#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using P = pair<int, int>;
ll gcd(ll a, ll b) {
  if (a % b == 0) {
    return b;
  } else {
    return (gcd(b, a % b));
  }
}
const int mod = 1000000007;
struct mint {
  ll x;
  mint(ll x = 0) : x((x % mod + mod) % mod) {}
  mint operator-() const { return mint(-x); }
  mint& operator+=(const mint a) {
    if ((x += a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator-=(const mint a) {
    if ((x += mod - a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator*=(const mint a) {
    (x *= a.x) %= mod;
    return *this;
  }
  mint operator+(const mint a) const { return mint(*this) += a; }
  mint operator-(const mint a) const { return mint(*this) -= a; }
  mint operator*(const mint a) const { return mint(*this) *= a; }
  mint pow(ll t) const {
    if (!t) return 1;
    mint a = pow(t >> 1);
    a *= a;
    if (t & 1) a *= *this;
    return a;
  }
  mint inv() const { return pow(mod - 2); }
  mint& operator/=(const mint a) { return *this *= a.inv(); }
  mint operator/(const mint a) const { return mint(*this) /= a; }
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x; }
ostream& operator<<(ostream& os, const mint& a) { return os << a.x; }
int main(int argc, const char* argv[]) {
  int n;
  cin >> n;
  int zero = 0;
  map<pair<ll, ll>, P> mp;
  for (int i = 0; i < (n); ++i) {
    ll x, y;
    cin >> x >> y;
    if (x == 0 && y == 0) {
      zero++;
      continue;
    }
    ll g = gcd(x, y);
    x /= g;
    y /= g;
    if (y < 0) {
      x = -x;
      y = -y;
    }
    if (y == 0 && x < 0) {
      x = -x;
      y = -y;
    }
    bool rot90 = (x <= 0);
    if (rot90) {
      ll tmp = x;
      x = y;
      y = -tmp;
    }
    if (rot90)
      mp[{x, y}].first++;
    else
      mp[{x, y}].second++;
  }
  mint ans = 1;
  for (auto p : mp) {
    int s = p.second.first;
    int t = p.second.second;
    mint now = 1;
    now += mint(2).pow(s) - 1;
    now += mint(2).pow(t) - 1;
    ans *= now;
  }
  ans -= 1;
  ans += zero;
  cout << ans << endl;
  return 0;
}
