9 10
6 2 3 1 4 8 5 9 8
3 9
6 6
9 9
9 9
9 9
2 3
3 9
3 8
6 9
5 6
 10 10
5 10 9 2 9 3 5 5 6 5
5 10
2 2
3 10
4 8
1 3
1 5
5 5
10 10
8 9
6 10
 8 10
100 100 100 100 100 100 100 100
1 8
2 8
3 8
4 8
5 8
6 8
7 8
8 8
1 1
1 5
 5 15
103 45 103 67 45
1 1
1 2
1 3
1 4
1 5
2 2
2 3
2 4
2 5
3 3
3 4
3 5
4 4
4 5
5 5
 1 1
1000000
1 1
 10 5
10 9 8 7 6 5 4 3 2 1
4 8
1 10
3 9
2 2
5 10
 9 10
5 3 10 2 4 8 7 5 1
6 9
1 8
3 3
2 7
3 5
4 6
9 9
8 8
1 9
5 6
 9 10
10 2 6 2 4 6 6 4 1
4 8
8 9
2 3
8 9
9 9
4 5
1 7
6 6
6 8
1 1
 20 8
1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2
4 15
1 2
2 20
7 7
13 18
7 7
3 19
3 8
 1 2
1
1 1
1 1
 8 10
5 7 3 1 4 2 1 1
5 7
3 8
2 7
4 8
4 5
2 8
4 6
1 2
4 7
3 5

54
8
8
8
8
5
54
30
46
12
 63
10
92
34
24
53
9
5
11
54
 6400
4900
3600
2500
1600
900
400
100
100
2500
 103
148
457
524
659
45
148
215
350
103
170
215
67
112
45
 1000000
 25
55
35
9
21
 21
54
10
34
16
14
1
5
55
12
 42
5
8
5
1
6
76
6
28
10
 108
3
281
1
27
1
209
27
 1
1
 7
18
20
15
5
25
7
12
10
8

#include <bits/stdc++.h>
using namespace std;
long long int paw(long long int a, long long int b);
struct q {
  int l, r, in;
} quer[210000];
int arr[210000], coun[1100000], bl;
long long int sol[210000], ans = 0;
bool comp(const q& a, const q& b) {
  if (a.l / bl == b.l / bl) return a.r < b.r;
  return a.l / bl < b.l / bl;
}
int add(int ai) {
  ans -= (long long int)((long long int)coun[arr[ai]] *
                         (long long int)coun[arr[ai]] * (long long int)arr[ai]);
  coun[arr[ai]]++;
  ans += (long long int)((long long int)coun[arr[ai]] *
                         (long long int)coun[arr[ai]] * (long long int)arr[ai]);
  return 0;
}
int remove(int ai) {
  ans -= (long long int)((long long int)coun[arr[ai]] *
                         (long long int)coun[arr[ai]] * (long long int)arr[ai]);
  coun[arr[ai]]--;
  ans += (long long int)((long long int)coun[arr[ai]] *
                         (long long int)coun[arr[ai]] * (long long int)arr[ai]);
  return 0;
}
int main() {
  int n, d, i, sq, cl, cr;
  scanf("%d %d", &n, &d);
  for (i = 0; i < n; i++) scanf("%d", &arr[i]);
  bl = (int)sqrt(n);
  for (i = 0; i < d; i++) {
    scanf("%d %d", &quer[i].l, &quer[i].r);
    quer[i].l--;
    quer[i].r--;
    quer[i].in = i;
  }
  sort(quer, quer + d, comp);
  cl = 0;
  cr = 0;
  for (i = 0; i < d; i++) {
    while (cl < quer[i].l) {
      remove(cl);
      cl++;
    }
    while (cl > quer[i].l) {
      cl--;
      add(cl);
    }
    while (cr < quer[i].r + 1) {
      add(cr);
      cr++;
    }
    while (cr > quer[i].r + 1) {
      cr--;
      remove(cr);
    }
    sol[quer[i].in] = ans;
  }
  for (i = 0; i < d; i++) printf("%lld\n", sol[i]);
  return 0;
}
long long int paw(long long int a, long long int b) {
  long long int x = ((a) % 1000000007), ans = 1;
  while (b > 0) {
    if (b & 1) ans = (ans * x) % 1000000007;
    x = (x * x) % 1000000007;
    b >>= 1;
  }
  return ans;
}
