9 10
6 2 3 1 4 8 5 9 8
3 9
6 6
9 9
9 9
9 9
2 3
3 9
3 8
6 9
5 6
 10 10
5 10 9 2 9 3 5 5 6 5
5 10
2 2
3 10
4 8
1 3
1 5
5 5
10 10
8 9
6 10
 8 10
100 100 100 100 100 100 100 100
1 8
2 8
3 8
4 8
5 8
6 8
7 8
8 8
1 1
1 5
 5 15
103 45 103 67 45
1 1
1 2
1 3
1 4
1 5
2 2
2 3
2 4
2 5
3 3
3 4
3 5
4 4
4 5
5 5
 1 1
1000000
1 1
 10 5
10 9 8 7 6 5 4 3 2 1
4 8
1 10
3 9
2 2
5 10
 9 10
5 3 10 2 4 8 7 5 1
6 9
1 8
3 3
2 7
3 5
4 6
9 9
8 8
1 9
5 6
 9 10
10 2 6 2 4 6 6 4 1
4 8
8 9
2 3
8 9
9 9
4 5
1 7
6 6
6 8
1 1
 20 8
1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2
4 15
1 2
2 20
7 7
13 18
7 7
3 19
3 8
 1 2
1
1 1
1 1
 8 10
5 7 3 1 4 2 1 1
5 7
3 8
2 7
4 8
4 5
2 8
4 6
1 2
4 7
3 5

54
8
8
8
8
5
54
30
46
12
 63
10
92
34
24
53
9
5
11
54
 6400
4900
3600
2500
1600
900
400
100
100
2500
 103
148
457
524
659
45
148
215
350
103
170
215
67
112
45
 1000000
 25
55
35
9
21
 21
54
10
34
16
14
1
5
55
12
 42
5
8
5
1
6
76
6
28
10
 108
3
281
1
27
1
209
27
 1
1
 7
18
20
15
5
25
7
12
10
8

#include <bits/stdc++.h>
using namespace std;
const int maxn = 200020;
int a, b, ar[maxn], K;
long long yu[maxn * 5], ans[maxn], sq[maxn];
pair<pair<int, int>, int> bs[maxn];
bool cmp(const pair<pair<int, int>, int> &a,
         const pair<pair<int, int>, int> &b) {
  if ((a.first.first >> 9) != (b.first.first >> 9))
    return (a.first.first >> 9) < (b.first.first >> 9);
  if (a.first.second == b.first.second) return a.first.first < b.first.first;
  return a.first.second < b.first.second;
}
int main() {
  scanf("%d %d", &a, &b);
  K = sqrt(a) + 1;
  for (int i = 1; i <= a; i++) scanf("%d", &ar[i]), sq[i] = (long long)i * i;
  for (int i = 0, j, k; i < b; i++) {
    scanf("%d %d", &bs[i].first.first, &bs[i].first.second);
    bs[i].second = i;
  }
  sort(bs, bs + b, cmp);
  int l = 0, r = 0;
  long long res = 0;
  for (int i = 0; i < b; i++) {
    while (r < bs[i].first.second)
      r++, res -= sq[yu[ar[r]]] * ar[r], yu[ar[r]]++,
          res += sq[yu[ar[r]]] * ar[r];
    while (r > bs[i].first.second)
      res -= sq[yu[ar[r]]] * ar[r], yu[ar[r]]--, res += sq[yu[ar[r]]] * ar[r],
          r--;
    while (l < bs[i].first.first)
      res -= sq[yu[ar[l]]] * ar[l], yu[ar[l]]--, res += sq[yu[ar[l]]] * ar[l],
          l++;
    while (l > bs[i].first.first)
      l--, res -= sq[yu[ar[l]]] * ar[l], yu[ar[l]]++,
          res += sq[yu[ar[l]]] * ar[l];
    ans[bs[i].second] = res;
  }
  for (int i = 0; i < b; i++) printf("%lld\n", ans[i]);
  return 0;
}
