9 10
6 2 3 1 4 8 5 9 8
3 9
6 6
9 9
9 9
9 9
2 3
3 9
3 8
6 9
5 6
 10 10
5 10 9 2 9 3 5 5 6 5
5 10
2 2
3 10
4 8
1 3
1 5
5 5
10 10
8 9
6 10
 8 10
100 100 100 100 100 100 100 100
1 8
2 8
3 8
4 8
5 8
6 8
7 8
8 8
1 1
1 5
 5 15
103 45 103 67 45
1 1
1 2
1 3
1 4
1 5
2 2
2 3
2 4
2 5
3 3
3 4
3 5
4 4
4 5
5 5
 1 1
1000000
1 1
 10 5
10 9 8 7 6 5 4 3 2 1
4 8
1 10
3 9
2 2
5 10
 9 10
5 3 10 2 4 8 7 5 1
6 9
1 8
3 3
2 7
3 5
4 6
9 9
8 8
1 9
5 6
 9 10
10 2 6 2 4 6 6 4 1
4 8
8 9
2 3
8 9
9 9
4 5
1 7
6 6
6 8
1 1
 20 8
1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2
4 15
1 2
2 20
7 7
13 18
7 7
3 19
3 8
 1 2
1
1 1
1 1
 8 10
5 7 3 1 4 2 1 1
5 7
3 8
2 7
4 8
4 5
2 8
4 6
1 2
4 7
3 5

54
8
8
8
8
5
54
30
46
12
 63
10
92
34
24
53
9
5
11
54
 6400
4900
3600
2500
1600
900
400
100
100
2500
 103
148
457
524
659
45
148
215
350
103
170
215
67
112
45
 1000000
 25
55
35
9
21
 21
54
10
34
16
14
1
5
55
12
 42
5
8
5
1
6
76
6
28
10
 108
3
281
1
27
1
209
27
 1
1
 7
18
20
15
5
25
7
12
10
8

#include <bits/stdc++.h>
using namespace std;
const long long MOD = 1e9 + 7;
const int N = 1e6 + 5;
int n, t, a[N], pl, pr;
long long c[N], hans;
vector<long long> ans;
vector<pair<pair<int, int>, int>> q;
bool mS(pair<pair<int, int>, int> x, pair<pair<int, int>, int> y) {
  if (x.first.first / 500 != y.first.first / 500)
    return x.first.first / 500 < y.first.first / 500;
  return x.first.second > y.first.second;
}
int main() {
  pr--;
  scanf("%d %d", &n, &t);
  for (int i = 0; i < n; i++) scanf("%d", &a[i]);
  q.resize(t);
  ans.resize(t);
  for (int i = 0; i < t; i++) {
    scanf("%d %d", &q[i].first.first, &q[i].first.second);
    q[i].first.first--;
    q[i].first.second--;
    q[i].second = i;
  }
  sort(q.begin(), q.end(), mS);
  for (auto i : q) {
    while (pl < i.first.first) {
      c[a[pl]]--;
      hans -= (1 + 2 * c[a[pl]]) * a[pl];
      pl++;
    }
    while (pl > i.first.first) {
      pl--;
      hans += (1 + 2 * c[a[pl]]) * a[pl];
      c[a[pl]]++;
    }
    while (pr > i.first.second) {
      c[a[pr]]--;
      hans -= (1 + 2 * c[a[pr]]) * a[pr];
      pr--;
    }
    while (pr < i.first.second) {
      pr++;
      hans += (1 + 2 * c[a[pr]]) * a[pr];
      c[a[pr]]++;
    }
    ans[i.second] = hans;
  }
  for (long long i : ans) printf("%lld\n", i);
  return 0;
}
