After a long party Petya decided to return home, but he turned out to be at the opposite end of the town from his home. There are n crossroads in the line in the town, and there is either the bus or the tram station at each crossroad.

The crossroads are represented as a string s of length n, where s_i = A, if there is a bus station at i-th crossroad, and s_i = B, if there is a tram station at i-th crossroad. Currently Petya is at the first crossroad (which corresponds to s_1) and his goal is to get to the last crossroad (which corresponds to s_n).

If for two crossroads i and j for all crossroads i, i+1, …, j-1 there is a bus station, one can pay a roubles for the bus ticket, and go from i-th crossroad to the j-th crossroad by the bus (it is not necessary to have a bus station at the j-th crossroad). Formally, paying a roubles Petya can go from i to j if s_t = A for all i ≤ t < j. 

If for two crossroads i and j for all crossroads i, i+1, …, j-1 there is a tram station, one can pay b roubles for the tram ticket, and go from i-th crossroad to the j-th crossroad by the tram (it is not necessary to have a tram station at the j-th crossroad). Formally, paying b roubles Petya can go from i to j if s_t = B for all i ≤ t < j.

For example, if s="AABBBAB", a=4 and b=3 then Petya needs:

<image>

  * buy one bus ticket to get from 1 to 3, 
  * buy one tram ticket to get from 3 to 6, 
  * buy one bus ticket to get from 6 to 7. 



Thus, in total he needs to spend 4+3+4=11 roubles. Please note that the type of the stop at the last crossroad (i.e. the character s_n) does not affect the final expense.

Now Petya is at the first crossroad, and he wants to get to the n-th crossroad. After the party he has left with p roubles. He's decided to go to some station on foot, and then go to home using only public transport.

Help him to choose the closest crossroad i to go on foot the first, so he has enough money to get from the i-th crossroad to the n-th, using only tram and bus tickets.

Input

Each test contains one or more test cases. The first line contains the number of test cases t (1 ≤ t ≤ 10^4).

The first line of each test case consists of three integers a, b, p (1 ≤ a, b, p ≤ 10^5) — the cost of bus ticket, the cost of tram ticket and the amount of money Petya has.

The second line of each test case consists of one string s, where s_i = A, if there is a bus station at i-th crossroad, and s_i = B, if there is a tram station at i-th crossroad (2 ≤ |s| ≤ 10^5).

It is guaranteed, that the sum of the length of strings s by all test cases in one test doesn't exceed 10^5.

Output

For each test case print one number — the minimal index i of a crossroad Petya should go on foot. The rest of the path (i.e. from i to n he should use public transport).

Example

Input


5
2 2 1
BB
1 1 1
AB
3 2 8
AABBBBAABB
5 3 4
BBBBB
2 1 1
ABABAB


Output


2
1
3
1
6
import java.io.*;
import java.math.BigInteger;
import java.util.*;
import java.lang.*;
import java.util.stream.Collectors;
import java.util.stream.IntStream;
import java.util.stream.Stream;

public class Contest {
	//static ArrayList<Integer> prime=new ArrayList();
	
	   public static TreeMap<Long,Integer> t1=new TreeMap();
	    public static void solve()
	    {
	      long m=1;
	      for(int j=2;j<=1000;j++)
	      {
	         
	          if(isprime(j))
	          {
	              m=m*j;
	              if(m>1000000)
	              {
	                  break;
	              }else{
	                  t1.put(m,1);
	              }
	          }
	      }
	    }
	public static long gcd(long n1, long n2)
    {
        if (n2 != 0)
            return gcd(n2, n1 % n2);
        else
            return n1;
    }
	
//////////////////	
	public static class trie {
        int x,y,z;
        trie (int x,int y,int z){
            this.x=x;
            this.y=y;
            this.z=z;
        }
	
	} 
        
	public static class pair {
        int x,y;
        pair (int x,int y){
            this.x=x;
            this.y=y;
        }
        public boolean equals(Object o) {
        	if(o instanceof pair) {
        		pair p = (pair)o;
        		return (x == p.x && y == p.y);
        	}
        	return false;
        }
        public int hashCode() {
        	return (Integer.hashCode(x) * 3 + Integer.hashCode(y) );
        }
    }
	
//////////////////	
	
	static class Cmp implements Comparator<pair>
	{
		public int compare(pair a,pair b)
		{
			if(a.x==b.x)
			{
				return(a.y-b.y);
			}
			return(a.x-b.x);
		}
	}
	
	
//////////////////
	
	
	
	
//////////////////
	
	
	
	
	
	   static class FastReader
	   {
		   BufferedReader br;
		   StringTokenizer st;
		   public FastReader()
		   {
			   br = new BufferedReader(new InputStreamReader(System.in));
		   }
		   
		   
		   String next() 
	        { 
	            while (st == null || !st.hasMoreElements()) 
	            { 
	                try
	                { 
	                    st = new StringTokenizer(br.readLine()); 
	                } 
	                catch (IOException  e) 
	                { 
	                    e.printStackTrace(); 
	                } 
	            } 
	            return st.nextToken(); 
	        } 
		   
		   
		   int nextInt()
		   {
			   return Integer.parseInt(next());
		   }
		   long nextLong()
		   {
			   return Long.parseLong(next());
		   }
		   double nextDouble() 
	        { 
	            return Double.parseDouble(next()); 
	        } 
		   
		   String nextLine() 
	        { 
	            String str = ""; 
	            try
	            { 
	                str = br.readLine(); 
	            } 
	            catch (IOException e) 
	            { 
	                e.printStackTrace(); 
	            } 
	            return str; 
	        } 
	   }
	   
////////////////////// 
	//public static ArrayList<Integer> a=new ArrayList();
	   
	  public static ArrayList<Integer> Divisors(int n) 
	   { 
	       // Note that this loop runs till square root 
		  ArrayList<Integer> a=new ArrayList();
		   long sum=0;
	       for (int i=1; i*i<=(n); i++) 
	       { 
	           if (n%i == 0) 
	           { 
	               // If divisors are equal, print only one 
	               if (n/i == i) 
	               {
	                  // printf("%d ", i); 
	            	   sum=sum+1;
	            	   a.add(i);
	               }
	     
	               else // Otherwise print both 
	               {
	                   //printf("%d %d ", i, n/i); 
	            	   sum=sum+2;
	            	   a.add(i);
	            	   a.add(n/i);
	               }
	           } 
	       } 
	       return(a);
	   } 
	   
/////////////////////	  
	  
	  public static long SmallestPrimeDivisor(long n) 
	  { 
	      // if divisible by 2 
	      if (n % 2 == 0) 
	          return 2; 
	    
	      // iterate from 3 to sqrt(n) 
	      for (long i = 3; i * i <= n; i += 2) { 
	          if (n % i == 0) 
	              return i; 
	      } 
	    
	      return n; 
	  } 
	    
////////////////////	  
	   
	   public static boolean isprime(long n)
	    {
	        int count=0;
	     
	        for(long i=2;i*i<=n;i++)
	        {
	            if(n%i==0)
	            {
	                return(false);
	            }
	        }
	        return(true);
	    }
	
	   
//////////////////////
	   
	     //   (x^n)%1000000007
	   public static long modularExponentiation(long x,long n,long M)
	   {
	       if(n==0)
	           return 1;
	       else if(n%2 == 0)        //n is even
	           return modularExponentiation((x*x)%M,n/2,M);
	       else                             //n is odd
	           return (x*modularExponentiation((x*x)%M,(n-1)/2,M))%M;

	   }
	   
	   public static long nCr(int n,int k)
	   {
		  if(k==0)
			  return 1;
		  return(n*nCr(n-1,k-1)/k);
	   }
	   public static long factorial(int n)
	   {
		   if(n==1)
			   return 1;
		   return((n)*factorial(n-1));
	   }
	   
	   public static void debug(Object...o) {
		    System.out.println( Arrays.deepToString(o) );
	   }
	   
	   public static boolean prime[]=new boolean[100005];
	   //prime[j]==false means it's a prime.
	   public static void seive()
	   {
		   prime[0]=false;
		   prime[1]=false;
		   for(int i=2;i*i<=100005;i++)
		   {
			   if(!prime[i])
			   {
				   for(int j=i*i;i<=100005;j+=i)
				   {
					   prime[j]=true;
				   }
			   }
		   }
	   }
	    public static long AtMost(int k,char c[])
	    {
	    	long ans=0;
	    	int left=0,right=0;
	    	int n=c.length;
	    	HashMap<Character,Integer> h=new HashMap();
	    	h.put('1',0);
	    	while(right<n)
	    	{
	    		h.put(c[right],h.getOrDefault(c[right],0)+1);
	    		while(h.get('1')>k)
	    		{
	    			h.replace(c[left],h.get(c[left])-1);
	    			left++;
	    		}
	    		ans=ans+(right-left+1);
	    		right++;
	    	}
	    	return ans;
	    }
	 
	 
	    public static boolean equals(StringBuilder sb1, StringBuilder sb2){
	        
	        /*
	         * If both refer to the same object, they are equal
	         */
	        if(sb1 == sb2)
	            return true;
	 
	        /*
	         * If any of them is null, then they are not equal.
	         * We know both are not null at this point because of the previous
	         * condition which checks equality.
	         */
	        if(sb1 == null || sb2 == null)
	            return false;
	        
	        boolean isEqual = true;
	        
	        /*
	         * If both are not same length, they are not equal
	         */
	        if(sb1.length() == sb2.length()){
	            
	            /*
	             * Now, compare the characters one by one, and break the loop
	             * as soon as the characters at given position are different.
	             */
	            for(int i = 0 ; i < sb1.length(); i++){
	                
	                if(sb1.charAt(i) != sb2.charAt(i)){
	                    isEqual = false;
	                    break;
	                }
	            }
	            
	        }else{
	            isEqual = false;
	        }
	        
	        return isEqual;
	    }
	
	   
	   
	   
	   

		public static void main(String []args) throws Exception
		{
			
			
			 FastReader in =new FastReader();	
			 PrintWriter pw = new PrintWriter(System.out);
		    //Scanner sc=new Scanner(System.in)
			// int x=in.nextInt();
			//String a[]=in.nextLine().split(" ");
			//String b=in.nextLine();
			// StringBuilder s1=new StringBuilder(in.nextLine());
			// StringBuilder s2=new StringBuilder(in.nextLine());
			
			 int t=in.nextInt();
			 for(int i=0;i<t;i++)
			 {
				 int a=in.nextInt();
				 int b=in.nextInt();
				 int p=in.nextInt();
				 String s=in.nextLine();
				 int n=s.length();
				 int count=0,ans=1;
				 char c='*';
				 if(p<a && p<b)
				 {
					 ans=n;
				 }
				 else
				 {
				 for(int j=n-2;j>=0;j--)
				 {
					 char c1=s.charAt(j);
					 if(c1!=c)
					 {
						if(c1=='A')
						{
							if(p>=a)
							{
								p=p-a;
							}
							else
							{
								
								ans=j+2;
								break;
							}
						}
						else
						{
							if(c1=='B')
							{
								if(p>=b)
								{
									p=p-b;
								}
								else
								{
									ans=j+2;
									break;
								}
							}
						}
						c=c1;
					 }
				 }
				 }
				 pw.println(ans);
				 /*
				 if(ans>=n)
				 {
					 pw.println(ans);
				 }
				 else
				 {
				    char c1=s.charAt(ans-1);
				    for(int j=ans-1;j>=0;j--)
				    {
					 if(c1!=s.charAt(j))
					 {
						 ans=j+1;
						 break;
					 }
				    }
				 pw.println(ans);
				 }
				 */



			 }
			 
			 
		   	pw.flush();
			pw.close();
		   			
		}
			
	}	
		
		
		
		
		
		
		
		
		
		
	

