After a long party Petya decided to return home, but he turned out to be at the opposite end of the town from his home. There are n crossroads in the line in the town, and there is either the bus or the tram station at each crossroad.

The crossroads are represented as a string s of length n, where s_i = A, if there is a bus station at i-th crossroad, and s_i = B, if there is a tram station at i-th crossroad. Currently Petya is at the first crossroad (which corresponds to s_1) and his goal is to get to the last crossroad (which corresponds to s_n).

If for two crossroads i and j for all crossroads i, i+1, …, j-1 there is a bus station, one can pay a roubles for the bus ticket, and go from i-th crossroad to the j-th crossroad by the bus (it is not necessary to have a bus station at the j-th crossroad). Formally, paying a roubles Petya can go from i to j if s_t = A for all i ≤ t < j. 

If for two crossroads i and j for all crossroads i, i+1, …, j-1 there is a tram station, one can pay b roubles for the tram ticket, and go from i-th crossroad to the j-th crossroad by the tram (it is not necessary to have a tram station at the j-th crossroad). Formally, paying b roubles Petya can go from i to j if s_t = B for all i ≤ t < j.

For example, if s="AABBBAB", a=4 and b=3 then Petya needs:

<image>

  * buy one bus ticket to get from 1 to 3, 
  * buy one tram ticket to get from 3 to 6, 
  * buy one bus ticket to get from 6 to 7. 



Thus, in total he needs to spend 4+3+4=11 roubles. Please note that the type of the stop at the last crossroad (i.e. the character s_n) does not affect the final expense.

Now Petya is at the first crossroad, and he wants to get to the n-th crossroad. After the party he has left with p roubles. He's decided to go to some station on foot, and then go to home using only public transport.

Help him to choose the closest crossroad i to go on foot the first, so he has enough money to get from the i-th crossroad to the n-th, using only tram and bus tickets.

Input

Each test contains one or more test cases. The first line contains the number of test cases t (1 ≤ t ≤ 10^4).

The first line of each test case consists of three integers a, b, p (1 ≤ a, b, p ≤ 10^5) — the cost of bus ticket, the cost of tram ticket and the amount of money Petya has.

The second line of each test case consists of one string s, where s_i = A, if there is a bus station at i-th crossroad, and s_i = B, if there is a tram station at i-th crossroad (2 ≤ |s| ≤ 10^5).

It is guaranteed, that the sum of the length of strings s by all test cases in one test doesn't exceed 10^5.

Output

For each test case print one number — the minimal index i of a crossroad Petya should go on foot. The rest of the path (i.e. from i to n he should use public transport).

Example

Input


5
2 2 1
BB
1 1 1
AB
3 2 8
AABBBBAABB
5 3 4
BBBBB
2 1 1
ABABAB


Output


2
1
3
1
6
/*
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 */

import java.io.*;
import java.util.*;
public class B1315 
{
    public static void main(String args[])throws IOException
        {
            Scanner sc=new Scanner(System.in);
            int t=sc.nextInt();
            for(int z=1;z<=t;z++)
            {
                int bus=sc.nextInt();
                int tram=sc.nextInt();
                int p=sc.nextInt();
                String s=sc.next();
                int n=s.length();
                s=" "+s;
                long cost[]=new long[n+1];
                int i=1,j=2;long curr=0;
                while(j<=n)
                {
                    if(s.charAt(j)==s.charAt(i))
                        j++;
                    else
                    {
                        if(s.charAt(i)=='A')
                        {
                            cost[j]=curr+bus;
                            curr+=bus;
                        }
                        else
                        {
                            cost[j]=curr+tram;
                            curr+=tram;
                        }
                        i=j;
                        j++;
                    }
                }
                if(i!=n)
                {
                    if(s.charAt(i)=='A')
                        cost[n]=curr+bus;
                    else
                        cost[n]=curr+tram;
                }
                for(i=1;i<=n;i++)
                {
                    if(cost[n]-cost[i] <=p)
                    {
                        System.out.println(i);
                        break;
                    }
                }
            }
        }

}
