JATC's math teacher always gives the class some interesting math problems so that they don't get bored. Today the problem is as follows. Given an integer n, you can perform the following operations zero or more times:

  * mul x: multiplies n by x (where x is an arbitrary positive integer). 
  * sqrt: replaces n with √{n} (to apply this operation, √{n} must be an integer). 



You can perform these operations as many times as you like. What is the minimum value of n, that can be achieved and what is the minimum number of operations, to achieve that minimum value?

Apparently, no one in the class knows the answer to this problem, maybe you can help them?

Input

The only line of the input contains a single integer n (1 ≤ n ≤ 10^6) — the initial number.

Output

Print two integers: the minimum integer n that can be achieved using the described operations and the minimum number of operations required.

Examples

Input

20


Output

10 2

Input

5184


Output

6 4

Note

In the first example, you can apply the operation mul 5 to get 100 and then sqrt to get 10.

In the second example, you can first apply sqrt to get 72, then mul 18 to get 1296 and finally two more sqrt and you get 6.

Note, that even if the initial value of n is less or equal 10^6, it can still become greater than 10^6 after applying one or more operations.
#include <bits/stdc++.h>
using namespace std;
namespace fastIO{
	#define BUF_SIZE 100000
	#define OUT_SIZE 100000
	//fread->read
	bool IOerror=0;
//	inline char nc(){char ch=getchar();if(ch==-1)IOerror=1;return ch;} 
	inline char nc(){
		static char buf[BUF_SIZE],*p1=buf+BUF_SIZE,*pend=buf+BUF_SIZE;
		if(p1==pend){
			p1=buf;pend=buf+fread(buf,1,BUF_SIZE,stdin);
			if(pend==p1){IOerror=1;return -1;}
		}
		return *p1++;
	}
	inline bool blank(char ch){return ch==' '||ch=='\n'||ch=='\r'||ch=='\t';}
	template<class T> inline bool read(T &x){
		bool sign=0;char ch=nc();x=0;
		for(;blank(ch);ch=nc());
		if(IOerror)return false;
		if(ch=='-')sign=1,ch=nc();
		for(;ch>='0'&&ch<='9';ch=nc())x=x*10+ch-'0';
		if(sign)x=-x;
		return true;
	}
	inline bool read(double &x){
		bool sign=0;char ch=nc();x=0;
		for(;blank(ch);ch=nc());
		if(IOerror)return false;
		if(ch=='-')sign=1,ch=nc();
		for(;ch>='0'&&ch<='9';ch=nc())x=x*10+ch-'0';
		if(ch=='.'){
			double tmp=1; ch=nc();
			for(;ch>='0'&&ch<='9';ch=nc())tmp/=10.0,x+=tmp*(ch-'0');
		}
		if(sign)x=-x;
		return true;
	}
	inline bool read(char *s){
		char ch=nc();
		for(;blank(ch);ch=nc());
		if(IOerror)return false;
		for(;!blank(ch)&&!IOerror;ch=nc())*s++=ch;
		*s=0;
		return true;
	}
	inline bool read(char &c){
		for(c=nc();blank(c);c=nc());
		if(IOerror){c=-1;return false;}
		return true; 
	}
	template<class T,class... U>bool read(T& h,U&... t){return read(h)&&read(t...);}
	#undef OUT_SIZE
	#undef BUF_SIZE
};
using namespace fastIO;
/************* debug begin *************/
string to_string(string s){return '"'+s+'"';}
string to_string(const char* s){return to_string((string)s);}
string to_string(const bool& b){return(b?"true":"false");}
template<class T>string to_string(T x){ostringstream sout;sout<<x;return sout.str();}
template<class A,class B>string to_string(pair<A,B> p){return "("+to_string(p.first)+", "+to_string(p.second)+")";}
template<class A>string to_string(const vector<A> v){
	int f=1;string res="{";for(const auto x:v){if(!f)res+= ", ";f=0;res+=to_string(x);}res+="}";
	return res;
}
void debug_out(){puts("");}
template<class T,class... U>void debug_out(const T& h,const U&... t){cout<<" "<<to_string(h);debug_out(t...);}
#ifdef tokitsukaze 
#define debug(...) cout<<"["<<#__VA_ARGS__<<"]:",debug_out(__VA_ARGS__);
#else
#define debug(...) 233;
#endif
/*************  debug end  *************/
#pragma comment(linker, "/STACK:1024000000,1024000000")
#define mem(a,b) memset((a),(b),sizeof(a))
#define MP make_pair
#define pb push_back
#define fi first
#define se second
#define sz(x) (int)x.size()
#define all(x) x.begin(),x.end()
using namespace __gnu_cxx;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int> PII;
typedef pair<ll,ll> PLL;
typedef vector<int> VI;
typedef vector<ll> VL;
void go();
int main(){
	#ifdef tokitsukaze
		freopen("TEST.txt","r",stdin);
	#endif
	go();return 0;
}
const int INF=0x3f3f3f3f;
const ll LLINF=0x3f3f3f3f3f3f3f3f;
const double PI=acos(-1.0);
const double eps=1e-8;
const int MAX=1e6+10;
const ll mod=1e9+7;
/*********************************  head  *********************************/
int p[MAX],tot,prime[MAX];
void init(int n)
{
	int i,j;
	tot=0;
	mem(prime,0);
	prime[1]=1;
	for(i=2;i<=n;i++)
	{
		if(!prime[i]) prime[i]=p[tot++]=i;
        for(j=0;j<tot&&p[j]*i<=n;j++)
		{
			prime[i*p[j]]=p[j];
			if(i%p[j]==0) break;
		}
	}
}
map<int,int> mp;
void work(int x)
{
	int t;
	while(x>1)
	{
		t=prime[x];
		while(x%t==0&&x>1) x/=t,mp[t]++;
	}
}
void go()
{
	int n,i,ans,cnt,mx;
	init(MAX-10);
	while(read(n))
	{
		mp.clear();
		work(n);
		ans=1;
		mx=0;
		cnt=0;
		for(auto &it:mp)
		{
			ans*=it.fi;
			int tmp=0;
			while(it.se>1)
			{
				if(it.se&1) cnt=1,it.se++;
				it.se>>=1;
				tmp++;
			}
			mx=max(mx,tmp);
			if(it.se&1) cnt=1;
		}
		printf("%d %d\n",ans,cnt+mx);
	}
}