After a long party Petya decided to return home, but he turned out to be at the opposite end of the town from his home. There are n crossroads in the line in the town, and there is either the bus or the tram station at each crossroad.

The crossroads are represented as a string s of length n, where s_i = A, if there is a bus station at i-th crossroad, and s_i = B, if there is a tram station at i-th crossroad. Currently Petya is at the first crossroad (which corresponds to s_1) and his goal is to get to the last crossroad (which corresponds to s_n).

If for two crossroads i and j for all crossroads i, i+1, …, j-1 there is a bus station, one can pay a roubles for the bus ticket, and go from i-th crossroad to the j-th crossroad by the bus (it is not necessary to have a bus station at the j-th crossroad). Formally, paying a roubles Petya can go from i to j if s_t = A for all i ≤ t < j. 

If for two crossroads i and j for all crossroads i, i+1, …, j-1 there is a tram station, one can pay b roubles for the tram ticket, and go from i-th crossroad to the j-th crossroad by the tram (it is not necessary to have a tram station at the j-th crossroad). Formally, paying b roubles Petya can go from i to j if s_t = B for all i ≤ t < j.

For example, if s="AABBBAB", a=4 and b=3 then Petya needs:

<image>

  * buy one bus ticket to get from 1 to 3, 
  * buy one tram ticket to get from 3 to 6, 
  * buy one bus ticket to get from 6 to 7. 



Thus, in total he needs to spend 4+3+4=11 roubles. Please note that the type of the stop at the last crossroad (i.e. the character s_n) does not affect the final expense.

Now Petya is at the first crossroad, and he wants to get to the n-th crossroad. After the party he has left with p roubles. He's decided to go to some station on foot, and then go to home using only public transport.

Help him to choose the closest crossroad i to go on foot the first, so he has enough money to get from the i-th crossroad to the n-th, using only tram and bus tickets.

Input

Each test contains one or more test cases. The first line contains the number of test cases t (1 ≤ t ≤ 10^4).

The first line of each test case consists of three integers a, b, p (1 ≤ a, b, p ≤ 10^5) — the cost of bus ticket, the cost of tram ticket and the amount of money Petya has.

The second line of each test case consists of one string s, where s_i = A, if there is a bus station at i-th crossroad, and s_i = B, if there is a tram station at i-th crossroad (2 ≤ |s| ≤ 10^5).

It is guaranteed, that the sum of the length of strings s by all test cases in one test doesn't exceed 10^5.

Output

For each test case print one number — the minimal index i of a crossroad Petya should go on foot. The rest of the path (i.e. from i to n he should use public transport).

Example

Input


5
2 2 1
BB
1 1 1
AB
3 2 8
AABBBBAABB
5 3 4
BBBBB
2 1 1
ABABAB


Output


2
1
3
1
6
/*
ID: davidzh8
PROG: subset
LANG: JAVA
 */

import java.io.*;
import java.util.*;
import java.lang.*;

public class homecoming {
    //Start Stub
    static long startTime = System.nanoTime();
    //Globals Go Here

    //Globals End
    public static void main(String[] args) throws IOException {
        FastScanner sc = new FastScanner("homecoming.in", true);
        FastWriter pw = new FastWriter("homecoming.out", true);
        int tcs= sc.ni();
        while (tcs-->0){
            int a= sc.ni();
            int b= sc.ni();
            int p= sc.ni();
            String line= sc.next();
            long[] dp= new long[line.length()];
            dp[line.length()-1]=0;
            int cur=-100000;
            for (int i = line.length()-2; i >=0 ; i--) {
                if (line.charAt(i)-'A'==cur){
                    dp[i]= dp[i+1];
                }
                else{
                    cur= line.charAt(i)-'A';
                    if (i!=line.length()-1){
                        dp[i]= dp[i+1];
                        if (cur==0) dp[i]+=a;
                        if (cur==1) dp[i]+=b;
                    }
                }
            }
            for (int i = 0; i < line.length(); i++) {
                if (p>=dp[i]){
                    System.out.println(i+1);
                    break;
                }
            }
        }





        /* End Stub */
        long endTime = System.nanoTime();
        //System.out.println("Execution Time: " + (endTime - startTime) / 1e9 + " s");
        pw.close();
    }


    static class Edge implements Comparable<Edge> {
        int w;
        int a;
        int b;

        public Edge(int w, int a, int b) {
            this.w = w;
            this.a = a;
            this.b = b;

        }

        public int compareTo(Edge obj) {
            if (obj.w == w) {
                if (obj.a == a) {
                    return b - obj.b;
                }
                return a - obj.a;
            } else return w - obj.w;
        }
    }

    static class Pair implements Comparable<Pair> {
        int a;
        int b;

        public Pair(int a, int b) {
            this.a = a;
            this.b = b;
        }

        public int compareTo(Pair obj) {
            if (obj.a == a) {
                return b - obj.b;
            } else return a - obj.a;
        }
    }

    static class SegmentTree {
        public long[] arr;
        public long[] tree;
        public int N;

        //Zero initialization
        public SegmentTree(int n) {
            N = n;
            arr = new long[N];
            tree = new long[4 * N + 1];
        }

        public long query(int treeIndex, int lo, int hi, int i, int j) {
            // query for arr[i..j]
            if (lo > j || hi < i)
                return 0;
            if (i <= lo && j >= hi)
                return tree[treeIndex];
            int mid = lo + (hi - lo) / 2;

            if (i > mid)
                return query(2 * treeIndex + 2, mid + 1, hi, i, j);
            else if (j <= mid)
                return query(2 * treeIndex + 1, lo, mid, i, j);

            long leftQuery = query(2 * treeIndex + 1, lo, mid, i, mid);
            long rightQuery = query(2 * treeIndex + 2, mid + 1, hi, mid + 1, j);

            // merge query results
            return merge(leftQuery, rightQuery);
        }

        public void update(int treeIndex, int lo, int hi, int arrIndex, long val) {
            if (lo == hi) {
                tree[treeIndex] = val;
                arr[arrIndex] = val;
                return;
            }

            int mid = lo + (hi - lo) / 2;

            if (arrIndex > mid)
                update(2 * treeIndex + 2, mid + 1, hi, arrIndex, val);
            else if (arrIndex <= mid)
                update(2 * treeIndex + 1, lo, mid, arrIndex, val);

            // merge updates
            tree[treeIndex] = merge(tree[2 * treeIndex + 1], tree[2 * treeIndex + 2]);
        }

        public long merge(long a, long b) {
            return (a + b);
        }
    }

    static class djset {
        int N;
        int[] parent;

        // Creates a disjoint set of size n (0, 1, ..., n-1)
        public djset(int n) {
            parent = new int[n];
            N = n;
            for (int i = 0; i < n; i++)
                parent[i] = i;
        }

        public int find(int v) {

            // I am the club president!!! (root of the tree)
            if (parent[v] == v) return v;

            // Find my parent's root.
            int res = find(parent[v]);

            // Attach me directly to the root of my tree.
            parent[v] = res;
            return res;
        }

        public boolean union(int v1, int v2) {

            // Find respective roots.
            int rootv1 = find(v1);
            int rootv2 = find(v2);

            // No union done, v1, v2 already together.
            if (rootv1 == rootv2) return false;

            // Attach tree of v2 to tree of v1.
            parent[rootv2] = rootv1;
            return true;
        }


    }

    static class FastScanner {
        public BufferedReader br;
        public StringTokenizer st;
        public InputStream is;

        public FastScanner(String name, boolean debug) throws IOException {
            if (debug) {
                is = System.in;
            } else {
                is = new FileInputStream(name);
            }
            br = new BufferedReader(new InputStreamReader(is), 32768);
            st = null;
        }


        public String next() {
            while (st == null || !st.hasMoreTokens()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return st.nextToken();
        }

        public int ni() {
            return Integer.parseInt(next());
        }

        public long nl() {
            return Long.parseLong(next());
        }

        public double nd() {
            return Double.parseDouble(next());
        }

        public String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
            return str;
        }
    }

    static class FastWriter {
        public PrintWriter pw;

        public FastWriter(String name, boolean debug) throws IOException {
            if (debug) {
                pw = new PrintWriter(System.out);
            } else {
                pw = new PrintWriter(new BufferedWriter(new FileWriter(new File(name))));
            }
        }

        public void println(Object text) {
            pw.println(text);
        }

        public void print(Object text) {
            pw.print(text);
        }

        public void close() {
            pw.close();
        }

        public void flush() {
            pw.flush();
        }
    }

}