Mr. Kitayuta has just bought an undirected graph consisting of n vertices and m edges. The vertices of the graph are numbered from 1 to n. Each edge, namely edge i, has a color ci, connecting vertex ai and bi.

Mr. Kitayuta wants you to process the following q queries.

In the i-th query, he gives you two integers — ui and vi.

Find the number of the colors that satisfy the following condition: the edges of that color connect vertex ui and vertex vi directly or indirectly.

Input

The first line of the input contains space-separated two integers — n and m (2 ≤ n ≤ 100, 1 ≤ m ≤ 100), denoting the number of the vertices and the number of the edges, respectively.

The next m lines contain space-separated three integers — ai, bi (1 ≤ ai < bi ≤ n) and ci (1 ≤ ci ≤ m). Note that there can be multiple edges between two vertices. However, there are no multiple edges of the same color between two vertices, that is, if i ≠ j, (ai, bi, ci) ≠ (aj, bj, cj).

The next line contains a integer — q (1 ≤ q ≤ 100), denoting the number of the queries.

Then follows q lines, containing space-separated two integers — ui and vi (1 ≤ ui, vi ≤ n). It is guaranteed that ui ≠ vi.

Output

For each query, print the answer in a separate line.

Examples

Input

4 5
1 2 1
1 2 2
2 3 1
2 3 3
2 4 3
3
1 2
3 4
1 4


Output

2
1
0


Input

5 7
1 5 1
2 5 1
3 5 1
4 5 1
1 2 2
2 3 2
3 4 2
5
1 5
5 1
2 5
1 5
1 4


Output

1
1
1
1
2

Note

Let's consider the first sample. 

<image> The figure above shows the first sample. 

  * Vertex 1 and vertex 2 are connected by color 1 and 2. 
  * Vertex 3 and vertex 4 are connected by color 3. 
  * Vertex 1 and vertex 4 are not connected by any single color. 
2 1
1 2 1
1
1 2
 2 3
1 2 3
1 2 2
1 2 1
1
1 2
 2 5
1 2 1
1 2 2
1 2 3
1 2 4
1 2 5
1
1 2

1
 3
 5

import java.io.*;
import java.util.*;
 
public class Main {
	static class FastReader{ 
        BufferedReader br; 
        StringTokenizer st; 
        public FastReader(){br = new BufferedReader(new InputStreamReader(System.in));}
        String next(){while (st == null || !st.hasMoreElements()){try{st = new StringTokenizer(br.readLine());} 
        catch (IOException  e){e.printStackTrace();}}return st.nextToken();}
        int nextInt(){ return Integer.parseInt(next());}long nextLong(){return Long.parseLong(next());}double nextDouble(){return Double.parseDouble(next());}
        String nextLine(){String str = ""; try{str = br.readLine(); } catch (IOException e) {e.printStackTrace();} return str; } 
    }
	static FastReader sc = new FastReader();
	static List<pair> g[];
	public static void main (String[] args) throws Exception {
        PrintWriter out = new PrintWriter(System.out);
        int k = 1;
//        t = sc.nextInt();
        z : while(k-->0) {
        	int n = sc.nextInt();
    		int m = sc.nextInt();
    		g = new LinkedList[n+1];
    		for(int i=1;i<=n;i++) g[i] = new LinkedList<>();
    		while(m-->0) {
    			int u = sc.nextInt();
    			int v = sc.nextInt();
    			int c = sc.nextInt();
    			g[u].add(new pair(v,c));
    			g[v].add(new pair(u,c));
    		}
    		int q = sc.nextInt();
    		while(q-->0) {
    			int u = sc.nextInt();
    			int v = sc.nextInt();
    			int cnt = 0;
    			for(pair p : g[u]) {
        			boolean vis[] = new boolean[n+1];
        			vis[u] = true;
    				if(dfs(p.a,v,p.b,vis)) {
    					cnt++;
    				}
    			}
    			out.write(cnt+"\n");
    		}
      	}
		out.close();
	}
	private static boolean dfs(int u, int v, int b, boolean[] vis) {
		vis[u] = true;
		if(u == v) return true;
		
		for(pair p : g[u]) {
			if(!vis[p.a] && p.b == b)
				if(dfs(p.a,v,b,vis)) return true;
		}
		return false;
	}
}
class pair implements Comparable<pair>{
	int a;
	int b; 
	pair(int a,int b){
		this.a = a;
		this.b = b;
	}
	@Override
    public int compareTo(pair p){
        return this.b - p.b;
    }
}
