You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 
import sys
import math


def count(sumg, n, r):
    res = sumg[n - 1] * (r // n)
    res += sumg[r % n]

    return res


def main():
    input = sys.stdin.readline
    t = int(input())
    while t > 0:
        t -= 1
        # read input

        a, b, q = (int(i) for i in input().split())
        n = a * b

        sumg = [0] * n

        for i in range(1, n):
            sumg[i] += sumg[i - 1]
            if (i % a) % b != (i % b) % a:
                sumg[i] += 1

        while q > 0:
            q -= 1
            l, r = (int(i) for i in input().split())
            res = count(sumg, n, r) - count(sumg, n, l - 1)

            if q:
                print(res, end=" ")
            else:
                print(res)


main()
