Snuke lives in another world, where slimes are real creatures and kept by some people. Slimes come in N colors. Those colors are conveniently numbered 1 through N. Snuke currently has no slime. His objective is to have slimes of all the colors together.

Snuke can perform the following two actions:

* Select a color i (1≤i≤N), such that he does not currently have a slime in color i, and catch a slime in color i. This action takes him a_i seconds.

* Cast a spell, which changes the color of all the slimes that he currently has. The color of a slime in color i (1≤i≤N-1) will become color i+1, and the color of a slime in color N will become color 1. This action takes him x seconds.




Find the minimum time that Snuke needs to have slimes in all N colors.

Constraints

* 2≤N≤2,000
* a_i are integers.
* 1≤a_i≤10^9
* x is an integer.
* 1≤x≤10^9

Input

The input is given from Standard Input in the following format:


N x
a_1 a_2 ... a_N


Output

Find the minimum time that Snuke needs to have slimes in all N colors.

Examples

Input

2 10
1 100


Output

12


Input

3 10
100 1 100


Output

23


Input

4 10
1 2 3 4


Output

10
n, x = map(int, input().split())
A = list(map(int, input().split()))

def segfunc(x, y):
    return min(x, y)

def init(init_val):
    # set_val
    for i in range(n):
        seg[i+num-1] = init_val[i]
    # built
    for i in range(num-2, -1, -1):
        seg[i] = segfunc(seg[2*i+1], seg[2*i+2])

def update(k, x):
    k += num - 1
    seg[k] = x
    while k:
        k = (k-1)//2
        seg[k] = segfunc(seg[2*k+1], seg[2*k+2])

def query(p, q):
    if q <= p:
        return ide_ele
    p += num - 1
    q += num - 2
    res = ide_ele
    while q-p>1:
        if p&1 == 0:
            res = segfunc(res, seg[p])
        if q&1 == 1:
            res = segfunc(res, seg[q])
            q -= 1
        p = p//2
        q = (q-1)//2
    if p == q:
        res = segfunc(res, seg[p])
    else:
        res = segfunc(segfunc(res, seg[p]), seg[q])
    return res

# identity element
ide_ele = 10**9+1

# num: n以上の最小の2のべき乗
num = 2**(n-1).bit_length()
seg = [ide_ele]*2*num

init(A)

ans = float('inf')
for k in range(n):
    t = k*x
    for i in range(n):
        if k <= i:
            t += query(i-k, i+1)
        else:
            t += min(query(0, i+1), query(n-(k-i), n))
    ans = min(t, ans)
print(ans)
