You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 
import sys
input=sys.stdin.readline
def gcd(a,b):
    if a>b:a,b=b,a
    while True:
        a,b=b%a,a
        if a==0:return b
def solve(l,r,a,b,lcm):
    mx=max(a,b)
    d1=l//lcm
    d2=r//lcm
    lr=l%lcm
    rr=r%lcm
    c=0
    if lr>mx:c+=(lcm-lr)
    else:c+=(lcm-mx)
    if rr>=mx:c+=(rr-mx+1)
    c+=(d2-d1-1)*(lcm-mx)
    return c
for i in ' '*int(input()):
    a,b,q=map(int,input().split())
    g=gcd(a,b)
    lcm=a*b//g
    mx=max(a,b)
    for j in ' '*q:
        l,r=map(int,input().split())
        print(solve(l,r,a,b,lcm),end=' ')
    print()
