Snuke lives in another world, where slimes are real creatures and kept by some people. Slimes come in N colors. Those colors are conveniently numbered 1 through N. Snuke currently has no slime. His objective is to have slimes of all the colors together.

Snuke can perform the following two actions:

* Select a color i (1≤i≤N), such that he does not currently have a slime in color i, and catch a slime in color i. This action takes him a_i seconds.

* Cast a spell, which changes the color of all the slimes that he currently has. The color of a slime in color i (1≤i≤N-1) will become color i+1, and the color of a slime in color N will become color 1. This action takes him x seconds.




Find the minimum time that Snuke needs to have slimes in all N colors.

Constraints

* 2≤N≤2,000
* a_i are integers.
* 1≤a_i≤10^9
* x is an integer.
* 1≤x≤10^9

Input

The input is given from Standard Input in the following format:


N x
a_1 a_2 ... a_N


Output

Find the minimum time that Snuke needs to have slimes in all N colors.

Examples

Input

2 10
1 100


Output

12


Input

3 10
100 1 100


Output

23


Input

4 10
1 2 3 4


Output

10
#include <bits/stdc++.h>
using namespace std;
long long read() {
  long long f = 1, x = 0;
  char c = getchar();
  while (c < '0' || '9' < c) {
    if (c == '-') f = -1;
    c = getchar();
  }
  while ('0' <= c && c <= '9') {
    x = x * 10 + c - '0';
    c = getchar();
  }
  return f * x;
}
long long a[2000 + 5], pre[2000 + 5];
int main() {
  long long n = read(), x = read(), ans = 10000000000000000ll;
  for (int i = 1; i <= n; i++) a[i] = read();
  for (int t = 1; t <= n + 1; t++) {
    long long tmp = 0;
    for (int i = 1; i <= n; i++) tmp += a[i], pre[i] = a[i];
    ans = min(ans, tmp + (t - 1) * x);
    for (int i = 1; i <= n; i++) a[i] = min(a[i], pre[(i + t - 1) % n + 1]);
  }
  printf("%lld\n", ans);
  return 0;
}
