You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 

import math
t = int(input())
while t!=0:

        a,b,q= map(int,input().split())
        lcm = (a*b)//math.gcd(a,b)

        arr = [0]*(lcm)
        for i in range(lcm):
                if ((i+1)%a)%b != ((i+1)%b)%a:
                        arr[i]=1
        prefixsum = [arr[0]]
        for i in range(1,len(arr)):
                prefixsum.append(arr[i]+prefixsum[-1])
        sum1 = prefixsum[-1]

        list1 = []
        for i in range(q):

            l,r = map(int,input().split())
            l-=2
            r-=1
            div = r//(lcm)
            mod = r%(lcm)
            t1 = div*sum1 + prefixsum[mod]

            div2 = l//(lcm)
            mod2 = l%(lcm)

            t2 = div2*sum1 + prefixsum[mod2]
            list1.append(t1-t2)
        print(*list1)




        t-=1
