You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 
import math
def fun(num, a, b):
    chk = math.floor(num/(a*b))
    ans = 0
    
    ans += chk*b
    
    ans += min(num-(chk*a*b)+1,b)
    return ans    

t = int(input())

for _ in range(t):
    
    a, b, q = list(map(int,input().split()))
    
    if(a>b):
        a, b = b, a
    ans = []
    for i in range(q):
        l, r = list(map(int,input().split()))
        
        ans = fun(r,a,b) - fun(l,a,b)
        
        if((l%a)%b == (l%b)%a):
            ans += 1
        
        #print(cnt)
        print(r-l+1 - ans,end=' ')
    print()