You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 
from math import gcd
def lcm(a,b):
    return a*b//gcd(a,b)
import sys
input = sys.stdin.buffer.readline
def print(val):
    sys.stdout.write(str(val) + '\n')
def quic():
    for _ in range(int(input().strip())):
        a,b,q = map(int,input().split())
        period = lcm(a,b)
        maxx = max(a,b)
        for _ in range(q):
            l,r = map(int,input().split())
            total = r - l + 1
            total_bad = 0 
            bottom = (l // period) + 1
            top = r // period
            x = l % period
            y = r % period
            if top < bottom:
                total_bad += max(0,min(maxx,y+1) - x)
                total -= total_bad
                print(total)
            else:
                total_bad += (top - bottom) * maxx
                total_bad += min(maxx,y+1)
                total_bad += max(0,maxx - x)
                total -= total_bad
                print(total)
quic()
                
        
        
