You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 
import random
LI = lambda: list(map(int,input().split()))
MI = lambda: map(int,input().split())
yes = lambda: print("Yes")
no = lambda: print("No")
I = lambda: list(input())
J = lambda x: "".join(x)
II = lambda: int(input())
SI = lambda: input()
#---khan17---template
def compute_gcd(x, y):

   while(y):
       x, y = y, x % y
   return x

def compute_lcm(x, y):
   lcm = (x*y)//compute_gcd(x,y)
   return lcm
t = II()
for z in range(t):
	a,b,q = MI()
	c = max(a,b)
	mul = compute_lcm(a,b)
	ans = []
	for v in range(q):
		l,r = MI()
		count = 0
		if r<c:
			ans.append(0)
			continue
		elif l<c:
			left = c
		else:
			left = l
		count = (((r//mul)*mul)-left)//mul+1
		aaa = r-left+1-count*c
		gg = r-((r//mul)*mul)+1
		if gg<c:
			aaa+=c-gg
		ans.append(aaa)
	print(*ans)


