Fibonacci number f(i) appear in a variety of puzzles in nature and math, including packing problems, family trees or Pythagorean triangles. They obey the rule f(i) = f(i - 1) + f(i - 2), where we set f(0) = 1 = f(-1).

Let V and d be two certain positive integers and be N ≡ 1001 a constant. Consider a set of V nodes, each node i having a Fibonacci label F[i] = (f(i) mod N) assigned for i = 1,..., V ≤ N. If |F(i) - F(j)| < d, then the nodes i and j are connected.

Given V and d, how many connected subsets of nodes will you obtain?

<image>

Figure 1: There are 4 connected subsets for V = 20 and d = 100.

Constraints

* 1 ≤ V ≤ 1000
* 1 ≤ d ≤ 150

Input

Each data set is defined as one line with two integers as follows:

Line 1: Number of nodes V and the distance d.

Input includes several data sets (i.e., several lines). The number of dat sets is less than or equal to 50.

Output

Output line contains one integer - the number of connected subsets - for each input line.

Example

Input

5 5
50 1
13 13


Output

2
50
8
#include <cstdio>
#include <cstdlib>
#include <utility>
#include <typeinfo>
#include <cmath>
#include <numeric>
#include <algorithm>
#include <iostream>
#include <sstream>
#include <iomanip>
#include <vector>
#include <stack>
#include <map>
#include <string>
#define REP(i,n) for(int i=0;i<n;i++)
typedef long long ll;
using namespace std;
typedef vector<ll> vl;
typedef pair<ll,ll> pll;
typedef vector<pll> vpll;
typedef vector<string> vs;

int main() 
{
	int n,m;
	while(cin>>n>>m)
	{
		int fib[1002]={0};
		fib[0]=1;
		fib[1]=1;
		for(int i=2;i<n+2;i++){
			fib[i]=(fib[i-2]+fib[i-1])%1001;
		}
		sort(fib+2,fib+n+2);
		int ans=1;
		for(int i=3;i<n+2;i++){
			if(fib[i]-fib[i-1]>=m)ans++;
		}
		//REP(i,n+1)cout<<fib[i]<<" ";cout<<endl;
		cout<<ans<<endl;
	}
	return 0;
}