You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 
import java.util.Scanner;

public class C1342 {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int T = in.nextInt();
        for (int t=0; t<T; t++) {
            int A = in.nextInt();
            int B = in.nextInt();
            int M = A*B;
            int[] count = new int[M+1];
            for (int r=1; r<=M; r++) {
                count[r] = count[r-1] + (((r%A)%B == (r%B)%A) ? 0 : 1);
            }
            int Q = in.nextInt();
            StringBuilder sb = new StringBuilder();
            for (int q=0; q<Q; q++) {
                long L = in.nextLong();
                long R = in.nextLong();
                long answer = R/M*count[M]+count[(int)(R%M)]-(L-1)/M*count[M]-count[(int)((L-1)%M)];
                sb.append(answer).append(' ');
            }
            System.out.println(sb);
        }
    }

}
