Given an array a of length n, find another array, b, of length n such that:

  * for each i (1 ≤ i ≤ n) MEX(\\{b_1, b_2, …, b_i\})=a_i. 



The MEX of a set of integers is the smallest non-negative integer that doesn't belong to this set.

If such array doesn't exist, determine this.

Input

The first line contains an integer n (1 ≤ n ≤ 10^5) — the length of the array a.

The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i ≤ i) — the elements of the array a. It's guaranteed that a_i ≤ a_{i+1} for 1≤ i < n.

Output

If there's no such array, print a single line containing -1.

Otherwise, print a single line containing n integers b_1, b_2, …, b_n (0 ≤ b_i ≤ 10^6)

If there are multiple answers, print any.

Examples

Input


3
1 2 3


Output


0 1 2 

Input


4
0 0 0 2


Output


1 3 4 0 

Input


3
1 1 3


Output


0 2 1 

Note

In the second test case, other answers like [1,1,1,0], for example, are valid.
import java.io.*;
import java.util.*;

public class C649C
{
    static PrintWriter out = new PrintWriter((System.out));

    public static void main(String args[]) throws IOException
    {
        Reader sc = new Reader();
        int n=sc.nextInt();
        int ar[]=new int[n];
        int b[]=new int[n];
        boolean has[]=new boolean[1_000_001];
        for(int x=0;x<n;x++)
        {
            ar[x]=sc.nextInt();
            has[ar[x]]=true;
        }
        int y=0;
        for(int x=0;x<n;x++)
        {
            if(x==0)
            {
                while(has[y])
                {
                    y++;
                }
                out.print(y+" ");
                y++;
            }
            else if(ar[x]!=ar[x-1])
            {
                out.print(ar[x-1]+" ");
            }
            else
            {
                while(has[y])
                {
                    y++;
                }
                out.print(y+" ");
                y++;
            }
        }
        out.close();
    }


    static class Reader
    {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st = new StringTokenizer("");

        public String next()
        {
            while (!st.hasMoreTokens())
            {
                try
                {
                    st = new StringTokenizer(br.readLine());
                }
                catch (Exception e)
                {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        public int nextInt()
        {
            return Integer.parseInt(next());
        }

        public long nextLong()
        {
            return Long.parseLong(next());
        }

        public double nextDouble()
        {
            return Double.parseDouble(next());
        }

        public String nextLine()
        {
            try
            {
                return br.readLine();
            }
            catch (Exception e)
            {
                e.printStackTrace();
            }
            return null;
        }

        public boolean hasNext()
        {
            String next = null;
            try
            {
                next = br.readLine();
            }
            catch (Exception e)
            {
            }
            if (next == null)
            {
                return false;
            }
            st = new StringTokenizer(next);
            return true;
        }
    }
}