Koa the Koala and her best friend want to play a game.

The game starts with an array a of length n consisting of non-negative integers. Koa and her best friend move in turns and each have initially a score equal to 0. Koa starts.

Let's describe a move in the game:

  * During his move, a player chooses any element of the array and removes it from this array, xor-ing it with the current score of the player.

More formally: if the current score of the player is x and the chosen element is y, his new score will be x ⊕ y. Here ⊕ denotes [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).

Note that after a move element y is removed from a.

  * The game ends when the array is empty. 



At the end of the game the winner is the player with the maximum score. If both players have the same score then it's a draw.

If both players play optimally find out whether Koa will win, lose or draw the game.

Input

Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 10^4) — the number of test cases. Description of the test cases follows.

The first line of each test case contains the integer n (1 ≤ n ≤ 10^5) — the length of a.

The second line of each test case contains n integers a_1, a_2, …, a_n (0 ≤ a_i ≤ 10^9) — elements of a.

It is guaranteed that the sum of n over all test cases does not exceed 10^5.

Output

For each test case print:

  * WIN if Koa will win the game. 
  * LOSE if Koa will lose the game. 
  * DRAW if the game ends in a draw. 

Examples

Input


3
3
1 2 2
3
2 2 3
5
0 0 0 2 2


Output


WIN
LOSE
DRAW


Input


4
5
4 1 5 1 3
4
1 0 1 6
1
0
2
5 4


Output


WIN
WIN
DRAW
WIN

Note

In testcase 1 of the first sample we have:

a = [1, 2, 2]. Here Koa chooses 1, other player has to choose 2, Koa chooses another 2. Score for Koa is 1 ⊕ 2 = 3 and score for other player is 2 so Koa wins.
'''
    Auther: ghoshashis545 Ashis Ghosh
    College: jalpaiguri Govt Enggineering College

'''
from os import path
import sys
from heapq import heappush,heappop,heapify
from functools import cmp_to_key as ctk
from collections import deque,defaultdict as dd 
from bisect import bisect,bisect_left,bisect_right,insort,insort_left,insort_right
from itertools import permutations
from datetime import datetime
from math import ceil,sqrt,log,gcd
def ii():return int(input())
def si():return input().rstrip()
def mi():return map(int,input().split())
def li():return list(mi())
abc='abcdefghijklmnopqrstuvwxyz'
mod=1000000007
# mod=998244353
inf = float("inf")
vow=['a','e','i','o','u']
dx,dy=[-1,1,0,0],[0,0,1,-1]

def bo(i):
    return ord(i)-ord('a')

file=1


def solve():

    for _ in range(ii()):


        n=ii()
        a=li()
        x=0
        for i in a:
            x^=i
        if(x==0):
            print("DRAW")
            continue

        for i in range(30,-1,-1):

            if x>>i&1:
                one=0
                zero=0
                for j in a:
                    if j>>i&1:
                        one+=1
                    else:
                        zero+=1

                # if ith bit of even number element are not set  
                # then her best friend forced Koa to chose (x*2 + 2)[x=one//4] no of elements
                # whose ith bit is set then Koa score ith bit will not set but her best
                # friend select (x*2 + 1) no of elements so her bestfriend score ith bit
                # will set. So,koa will lose.
                if(zero%2==0 and one%4==3):
                    print('LOSE')
                else:
                    print('WIN')
                break




   
        
    
    
    
    
    
    
    
    
        

        



    










        
if __name__ =="__main__":

    if(file):

        if path.exists('input.txt'):
            sys.stdin=open('input.txt', 'r')
            sys.stdout=open('output.txt','w')
        else:
            input=sys.stdin.readline
    solve()