You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 
def gcd(x,y):
    while y:
        x,y =y,x % y
    return x



t = int(input())
for i in range(0,t):
    a , b , q = map(int,input().split())
    gatsu = max(a,b)
    gop = a*b//gcd(a,b)
    line = []
    for j in range(0,q):
        line.append(list(map(int,input().split())))
    sm = 0
    d = []
    for k in line:
        sm = 0
        start,end = (k[0]//gop)*gop,((k[1]//gop)+1)*gop
        sm += (end - start)//gop*gatsu
        if 0 <= k[0] % gop <= gatsu - 1:
            sm -= k[0] - start
        else:
            sm -= gatsu
        if 0 <= k[1] % gop <= gatsu -1:
            sm -= gatsu -1 - (k[1] % gop)
        else:
            sm -= 0
        d.append(k[1]-k[0]+1 - sm)
    for kk in d:
        print(kk,end=' ')
    print()
                
                
                
    
        