You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 
import sys
def input():
	return sys.stdin.readline()[:-1]

t = int(input())
for _ in range(t):
	a, b, q = map(int, input().split())
	ans = [0 for _ in range(q)]
	res = [0 for _ in range(a*b)]
	for i in range(1, a*b):
		if (i%a)%b != (i%b)%a:
			res[i] = res[i-1] + 1
		else:
			res[i] = res[i-1]
	def func(x):
		quo, mod = x//(a*b), x%(a*b)
		return quo * res[-1] + res[mod]
	for i in range(q):
		l, r = map(int, input().split())
		ans[i] = func(r) - func(l-1)
	print(*ans)
