You are given two integers a and b, and q queries. The i-th query consists of two numbers l_i and r_i, and the answer to it is the number of integers x such that l_i ≤ x ≤ r_i, and ((x mod a) mod b) ≠ ((x mod b) mod a). Calculate the answer for each query.

Recall that y mod z is the remainder of the division of y by z. For example, 5 mod 3 = 2, 7 mod 8 = 7, 9 mod 4 = 1, 9 mod 9 = 0.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases. Then the test cases follow.

The first line of each test case contains three integers a, b and q (1 ≤ a, b ≤ 200; 1 ≤ q ≤ 500).

Then q lines follow, each containing two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ 10^{18}) for the corresponding query.

Output

For each test case, print q integers — the answers to the queries of this test case in the order they appear.

Example

Input


2
4 6 5
1 1
1 3
1 5
1 7
1 9
7 10 2
7 8
100 200


Output


0 0 0 2 4 
0 91 
# @oj: codeforces
# @id: hitwanyang
# @email: 296866643@qq.com
# @date: 2020-04-28 09:45
# @url:https://codeforces.com/contest/1342/problem/C
import sys,os
from io import BytesIO, IOBase
import collections,itertools,bisect,heapq,math,string
# region fastio

BUFSIZE = 8192

BUFSIZE = 8192

class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)


class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")


sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# ------------------------------
def main():
    t=int(input())
    i=0
    while i<t:
        abq=list(map(int,input().split()))
        a,b,q=abq[0],abq[1],abq[2]
        lcm=a*b//math.gcd(a,b)
        # print (a,b,q,lcm)
        ans=[]
        for j in range(q):
            lr=list(map(int,input().split()))
            l,r=lr[0],lr[1]
            # print (l,r)
            if r<=a:
                ans.append(0)
            else:
                mod=[]
                for k in range(min(lcm,r-l+1)):
                    mod1=((l+k)%a)%b
                    mod2=((l+k)%b)%a
                    mod.append((mod1,mod2))
                cnt=(r-l+1)//lcm
                m=(r-l+1)%lcm
                s=[x for x in mod if x[0]!=x[1]]
                ans.append(cnt*len(s)+len([x for x in s[0:m] if x[0]!=x[1]]))
        print (" ".join([str(a) for a in ans]))
        i+=1
if __name__ == "__main__":
    main()