You are given three strings A, B and C. Check whether they form a word chain.

More formally, determine whether both of the following are true:

* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.



If both are true, print `YES`. Otherwise, print `NO`.

Constraints

* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.

Input

Input is given from Standard Input in the following format:


A B C


Output

Print `YES` or `NO`.

Examples

Input

rng gorilla apple


Output

YES


Input

yakiniku unagi sushi


Output

NO


Input

a a a


Output

YES


Input

aaaaaaaaab aaaaaaaaaa aaaaaaaaab


Output

NO
import java.io.*;
import java.util.*;
public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
 
     String[] nyu=sc.nextLine().split(" ");

String[] nyuA=nyu[0].split("");
String[] nyuB=nyu[1].split("");
String[] nyuC=nyu[2].split("");

//     String nyu=sc.nextLine();
//int A=Integer.parseInt(nyu[0]);
//int B=Integer.parseInt(nyu[1]);
//int C=Integer.parseInt(nyu[2]);
//int D=Integer.parseInt(nyu);



//StringBuffer sb = new StringBuffer(nyu);
//		String dst = sb.reverse().toString();

//     String nyu2=sc.nextLine();
//int E=Integer.parseInt(nyu2);



//double A=Double.parseDouble(nyu[0]);
//double B=Double.parseDouble(nyu[1]);
/*
switch(C){
case 7:
case 5:
case 3:
System.out.println("YES") ;
break;
default:
System.out.println("NO") ;

break;
}
*/

//int res=Math.min((A*B),C);

//for(String tem:nyu){
//if(tem.equals("1"))res++;
//}
//int res=0;
//for(int i=0;i<300;i++){
//if(num[i]==1)res=i;
//}

//char[] c = nyu.toCharArray();


//System.out.println(nyu+"-"+line_r_2+"-"+nyu2+"-"+line_r_1);



if(nyuA[nyuA.length-1].equals(nyuB[0]) && nyuB[nyuB.length-1].equals(nyuC[0])){
//double res=Math.ceil((AB)/2);

System.out.println("Yes");
//}else if((C-B)<A){
//System.out.println("safe");

}else{
System.out.println("No");

}




	}
}