You are given three strings A, B and C. Check whether they form a word chain.

More formally, determine whether both of the following are true:

* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.



If both are true, print `YES`. Otherwise, print `NO`.

Constraints

* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.

Input

Input is given from Standard Input in the following format:


A B C


Output

Print `YES` or `NO`.

Examples

Input

rng gorilla apple


Output

YES


Input

yakiniku unagi sushi


Output

NO


Input

a a a


Output

YES


Input

aaaaaaaaab aaaaaaaaaa aaaaaaaaab


Output

NO
import heapq
N,W=map(int,raw_input().split())
wv=[]

w_sum=0
for i in range(N):
	w,v=map(int,raw_input().split())
	w_sum+=w
	wv.append((w,v))


a=[ float("-inf") for i in range(w_sum*2) ]

i=0
i=1
q=[]
for ind_i, i in enumerate(wv):
	w=i[0]
	v=i[1]
	#Initialize
	if ind_i==0:
		a[0]=0
		a[w]=v
		continue
	#Put queue
	for ind_j, j in enumerate(a):
		if j!=float("-inf"):
			heapq.heappush(q,(ind_j,j))
	
	while len(q)!=0:
		ind_j, j=heapq.heappop(q)
		a[ind_j+w]=max(a[ind_j+w], a[ind_j]+v)
		
print max(a[:W+1])


