You are given three strings A, B and C. Check whether they form a word chain.

More formally, determine whether both of the following are true:

* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.



If both are true, print `YES`. Otherwise, print `NO`.

Constraints

* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.

Input

Input is given from Standard Input in the following format:


A B C


Output

Print `YES` or `NO`.

Examples

Input

rng gorilla apple


Output

YES


Input

yakiniku unagi sushi


Output

NO


Input

a a a


Output

YES


Input

aaaaaaaaab aaaaaaaaaa aaaaaaaaab


Output

NO
#include <bits/stdc++.h>
int main(void) {
  int i;
  char A[10], B[10], C[10], d, e;
  scanf("%s %s %s", A, B, C);
  for (i = 0; i < 10; i++) {
    if (A[i] == '\0') {
      d = A[i - 1];
      break;
    }
  }
  for (i = 0; i < 10; i++) {
    if (B[i] == '\0') {
      e = B[i - 1];
      break;
    }
  }
  if (d == B[0] && e == C[0]) {
    printf("YES\n");
  } else {
    printf("NO\n");
  }
  return 0;
}
