You are given an H × W grid.
The squares in the grid are described by H strings, S_1,...,S_H.
The j-th character in the string S_i corresponds to the square at the i-th row from the top and j-th column from the left (1 \leq i \leq H,1 \leq j \leq W).
`.` stands for an empty square, and `#` stands for a square containing a bomb.

Dolphin is interested in how many bomb squares are horizontally, vertically or diagonally adjacent to each empty square.
(Below, we will simply say "adjacent" for this meaning. For each square, there are at most eight adjacent squares.)
He decides to replace each `.` in our H strings with a digit that represents the number of bomb squares adjacent to the corresponding empty square.

Print the strings after the process.

Constraints

* 1 \leq H,W \leq 50
* S_i is a string of length W consisting of `#` and `.`.

Input

Input is given from Standard Input in the following format:


H W
S_1
:
S_H


Output

Print the H strings after the process.
The i-th line should contain a string T_i of length W, where the j-th character in T_i corresponds to the square at the i-th row from the top and j-th row from the left in the grid (1 \leq i \leq H, 1 \leq j \leq W).

Examples

Input

3 5
.....
.#.#.
.....


Output

11211
1#2#1
11211


Input

3 5


Output




Input

6 6
.
.#.##
.#
.#..#.
.##..
.#...


Output

3
8#7##
5#
4#65#2
5##21
4#310
H, W = map(int, input().split())
#左右に'.'を余分に付けて標準入力からリストを作成
grid = [list('.'+input()+'.') for i in range(H)]
#上下にも付けてやる
grid.insert(0, list('.' * (W + 2)))　#上
grid.append(list('.' * (W + 2)))　#下
#答えを入れるリスト
ans = []

#付け足した行列はカウントしない
for i in range(1, H + 1):
  for j in range(1, W + 1):
    if grid[i][j] == '#':
      ans.append('#')
    else:
      #8方向にある'#'の数をカウント
      #付け足したのは'.'なので条件分岐は不要
      #str型で出力しなければjoinできない
      ans.append(str((grid[i-1][j-1:j+2]+grid[i][j-1:j+2]+grid[i+1][j-1:j+2]).count('#')))
  #一行終わったので改行を入れる
  ans.append('\n')
print(''.join(ans)) #リストをつないで出力