You are given three strings A, B and C. Check whether they form a word chain.

More formally, determine whether both of the following are true:

* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.



If both are true, print `YES`. Otherwise, print `NO`.

Constraints

* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.

Input

Input is given from Standard Input in the following format:


A B C


Output

Print `YES` or `NO`.

Examples

Input

rng gorilla apple


Output

YES


Input

yakiniku unagi sushi


Output

NO


Input

a a a


Output

YES


Input

aaaaaaaaab aaaaaaaaaa aaaaaaaaab


Output

NO
#include <bits/stdc++.h>
#include <math.h>
#define REP(i, n) for(int i = 0; i < (n); i++)
#define ALL(v) (v).begin(), (v).end()
using namespace std;
typedef long long ll;
typedef pair<int, int> P;
const int INF = 1001001001;
const int mINF = -1001001001;


int main() {
char a[10],b[10],c[10];
cin >> a >> b  >> c;
int a_num = strlen(a);
int b_num = strlen(b);
int ans ="NO";
if(a[a_num-1]==b[0]&&b[b_num-1]==c[0]) ans="YES";
cout << ans << endl;
return 0;
}
