You are given three strings A, B and C. Check whether they form a word chain.

More formally, determine whether both of the following are true:

* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.



If both are true, print `YES`. Otherwise, print `NO`.

Constraints

* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.

Input

Input is given from Standard Input in the following format:


A B C


Output

Print `YES` or `NO`.

Examples

Input

rng gorilla apple


Output

YES


Input

yakiniku unagi sushi


Output

NO


Input

a a a


Output

YES


Input

aaaaaaaaab aaaaaaaaaa aaaaaaaaab


Output

NO
#include <bits/stdc++.h>
using ll = long long;
#define FOR(i, k, n) for(ll i = (k); i < (n); i++)
#define FORe(i, k, n) for(ll i = (k); i <= (n); i++)
#define FORr(i, k, n) for(ll i = (k)-1; i > (n); i--)
#define FORre(i, k, n) for(ll i = (k)-1; i >= (n); i--)
#define REP(i, n) FOR(i, 0, n)
#define REPr(i, n) FORre(i, n, 0)
#define ALL(x) (x).begin(), (x).end()
#define ALLr(x) (x).rbegin(), (x).rend()
#define chmin(x, y) x = min(x, y)
#define chmax(x, y) x = max(x, y)
using namespace std;

const int INF = 1001001001;

int main(void){
  string a, b, c;
  cin >> a >> b >> c;
  if(a.back == b[0] && b.back == c[0]) cout << "YES" << endl;
  else cout << "NO" << endl;
  return 0;
}