You are given three strings A, B and C. Check whether they form a word chain.

More formally, determine whether both of the following are true:

* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.



If both are true, print `YES`. Otherwise, print `NO`.

Constraints

* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.

Input

Input is given from Standard Input in the following format:


A B C


Output

Print `YES` or `NO`.

Examples

Input

rng gorilla apple


Output

YES


Input

yakiniku unagi sushi


Output

NO


Input

a a a


Output

YES


Input

aaaaaaaaab aaaaaaaaaa aaaaaaaaab


Output

NO
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, W;
  long long dp[105][105];
  int w[105], v[105];
  cin >> n >> W;
  for (int i = 0; i < n; i++) {
    cin >> w[i] >> v[i];
  }
  for (int i = n - 1; i >= 0; i--) {
    for (int j = 0; j <= W; j++) {
      if (j < w[i])
        dp[i][j] = dp[i + 1][j];
      else
        dp[i][j] = max(dp[i + 1][j], dp[i + 1][j - w[i]] + v[i]);
    }
  }
  cout << dp[0][W] << endl;
  return 0;
}
