You are given an H × W grid.
The squares in the grid are described by H strings, S_1,...,S_H.
The j-th character in the string S_i corresponds to the square at the i-th row from the top and j-th column from the left (1 \leq i \leq H,1 \leq j \leq W).
`.` stands for an empty square, and `#` stands for a square containing a bomb.

Dolphin is interested in how many bomb squares are horizontally, vertically or diagonally adjacent to each empty square.
(Below, we will simply say "adjacent" for this meaning. For each square, there are at most eight adjacent squares.)
He decides to replace each `.` in our H strings with a digit that represents the number of bomb squares adjacent to the corresponding empty square.

Print the strings after the process.

Constraints

* 1 \leq H,W \leq 50
* S_i is a string of length W consisting of `#` and `.`.

Input

Input is given from Standard Input in the following format:


H W
S_1
:
S_H


Output

Print the H strings after the process.
The i-th line should contain a string T_i of length W, where the j-th character in T_i corresponds to the square at the i-th row from the top and j-th row from the left in the grid (1 \leq i \leq H, 1 \leq j \leq W).

Examples

Input

3 5
.....
.#.#.
.....


Output

11211
1#2#1
11211


Input

3 5


Output




Input

6 6
.
.#.##
.#
.#..#.
.##..
.#...


Output

3
8#7##
5#
4#65#2
5##21
4#310
#include <bits/stdc++.h>
using namespace std;
using ll=long long;
using vb=vector<bool>;
using vvb=vector<vb>;
using vd=vector<double>;
using vvd=vector<vd>;
using vi=vector<int>;
using vvi=vector<vi>;
using vl=vector<ll>;
using vvl=vector<vl>;
using pll=pair<ll,ll>;
using tll=tuple<ll,ll>;
using tlll=tuple<ll,ll,ll>;
using vs=vector<string>;
#define all(a) a.begin(),a.end()
#define rall(a) a.rbegin(),a.rend()
#define rep(i,n) range(i,0,n)
#define rrep(i,n) for(ll i=((ll)n)-1;i>=0;i--)
#define range(i,a,n) for(ll i=((ll)a);i<((ll)n);i++)
#define LINF ((ll)1ll<<60)
#define INF ((int)1<<30)
#define EPS (1e-9)
#define MOD (1000000007ll)
#define fcout(a) cout<<setprecision(a)<<fixed
#define fs first
#define sc second
#define PI (3.1415926535897932384)

int dx[]={1,0,-1,0,1,-1,-1,1},dy[]={0,1,0,-1,1,1,-1,-1};
template<class T>bool chmax(T&a,T b){if(a<b){a=b; return true;}return false;}
template<class T>bool chmin(T&a,T b){if(a>b){a=b; return true;}return false;}
template<class S>S sum(vector<S>&a){return accumulate(all(a),S());}
template<class S>S max(vector<S>&a){return *max_element(all(a));}
template<class S>S min(vector<S>&a){return *min_element(all(a));}
ll max(int a,ll b){return max((ll)a,b);} ll max(ll a,int b){return max(a,(ll)b);}
int sgn(const double&r){return (r>EPS)-(r<-EPS);} // a>0  : sgn(a)>0
int sgn(const double&a,const double&b){return sgn(a-b);} // b<=c : sgn(b,c)<=0

template<class T>void puta(T&&t){cout<<t<<"\n";}
template<class H,class...T>void puta(H&&h,T&&...t){cout<<h<<' ';puta(t...);}
template<class S,class T>void tf(bool b,S t,T f){if(b)puta(t);else puta(f);}
void YN(bool b){tf(b,"YES","NO");}
void Yn(bool b){tf(b,"Yes","No");}
void yn(bool b){tf(b,"yes","no");}
template<class S,class T>ostream&operator<<(ostream&os,pair<S,T>p){os<<"["<<p.first<<", "<<p.second<<"]";return os;};
template<class S>auto&operator<<(ostream&os,vector<S>t){bool a=1;for(auto s:t){os<<(a?"":" ")<<s;a=0;}return os;}
template<class S>auto&operator>>(istream&is,vector<S>&t){for(S&a:t)cin>>a;return is;}

/*他のライブラリを入れる場所*/


int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);
    ll h,w;
    cin>>h>>w;
    vs f(h); cin>>f;
    vvl d(h,vl(w,0));
    rep(i,h)rep(j,w){
        if(f[i][j]=='#'){
            rep(v,8){
                ll ny=i+dy[v], nx=j+dx[v];
                if(ny<0 or nx<0 or ny>=h or nx>=w)continue;
                if(f[ny][nx]=='#')continue;
                d[ny][nx]++;
            }
        }
    }
    rep(i,h){
        rep(j,w)if(d[i][j]==0)cout<<"#"; else cout<<d[i][j];
        cout<<endl;
    }
    return 0;
}