You are given three strings A, B and C. Check whether they form a word chain.

More formally, determine whether both of the following are true:

* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.



If both are true, print `YES`. Otherwise, print `NO`.

Constraints

* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.

Input

Input is given from Standard Input in the following format:


A B C


Output

Print `YES` or `NO`.

Examples

Input

rng gorilla apple


Output

YES


Input

yakiniku unagi sushi


Output

NO


Input

a a a


Output

YES


Input

aaaaaaaaab aaaaaaaaaa aaaaaaaaab


Output

NO
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

class Main {

    public static void main(String[] args) throws Exception {

        try {

            BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

            String[] inputWords = br.readLine().split(" ");
            String lastCharOfFirstWord = getLastCharacter(inputWords[0]);
            String firstCharOfSecondWord = getFirstCharacter(inputWords[1]);
            String lastCharOfSecondWord = getLastCharacter(inputWords[1]);
            String firstCharOfThirdWord = getFirstCharacter(inputWords[2]);

            if (lastCharOfFirstWord.equals(firstCharOfSecondWord)
                && firstCharOfSecondWord.equals(lastCharOfSecondWord)
                && lastCharOfSecondWord.equals(firstCharOfThirdWord)) {
                
                System.out.println("YES");
                
            } else {

                System.out.println("NO");

            }
            

        } catch (IOException | NumberFormatException e) {
            e.printStackTrace();
            System.exit(0);
        } catch (final Exception e) {
            e.printStackTrace();
            System.exit(0);
        }
    }

    private static String getFirstCharacter(String word) {
        return word.substring(0, 1);
    }

    private static String getLastCharacter(String word) {
        return word.substring(word.length() - 1, word.length());
    }
}
