Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.

Petya recently learned to determine whether a string of lowercase Latin letters is lucky. For each individual letter all its positions in the string are written out in the increasing order. This results in 26 lists of numbers; some of them can be empty. A string is considered lucky if and only if in each list the absolute difference of any two adjacent numbers is a lucky number. 

For example, let's consider string "zbcdzefdzc". The lists of positions of equal letters are:

  * b: 2
  * c: 3, 10
  * d: 4, 8
  * e: 6
  * f: 7
  * z: 1, 5, 9
  * Lists of positions of letters a, g, h, ..., y are empty.



This string is lucky as all differences are lucky numbers. For letters z: 5 - 1 = 4, 9 - 5 = 4, for letters c: 10 - 3 = 7, for letters d: 8 - 4 = 4. 

Note that if some letter occurs only once in a string, it doesn't influence the string's luckiness after building the lists of positions of equal letters. The string where all the letters are distinct is considered lucky.

Find the lexicographically minimal lucky string whose length equals n.

Input

The single line contains a positive integer n (1 ≤ n ≤ 105) — the length of the sought string.

Output

Print on the single line the lexicographically minimal lucky string whose length equals n.

Examples

Input

5


Output

abcda


Input

3


Output

abc

Note

The lexical comparison of strings is performed by the < operator in modern programming languages. String a is lexicographically less than string b if exists such i (1 ≤ i ≤ n), that ai < bi, and for any j (1 ≤ j < i) aj = bj.
import java.io.*;
import java.util.*;

public class Main {

    private  static void solver(InputReader sc, PrintWriter out) {

            int n = sc.nextInt();
            int x = n/4;
            n = n%4;

            StringBuilder sb = new StringBuilder("");
            for(int i=0; i<x; i++){
                    sb.append("abcd");
            }
            char ch = 'a';
            for(int i=0;i<n;i++){
                sb.append(ch+"");
                ch++;
            }
            out.println(sb);
    }
    private static int binarySearch(long arr[], int left, int right, long key){
        int mid = left + (right-left)/2;
        if(mid-1>=0) {
            if (arr[mid] > key && arr[mid - 1] <= key)
                return mid;
            if (arr[mid] > key && arr[mid - 1] > key)
                return binarySearch(arr, left, mid - 1, key);
        }
        if(arr[mid] <= key)
            return binarySearch(arr,mid+1,right,key);
        if(arr[arr.length-1]== -1 * key)
            return arr.length;
        else
            return 0;

    }
    public static void main(String[] args) throws Exception{
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);

        solver(in,out);
        out.close();
    }
    static class InputReader {
        public BufferedReader reader;
        public StringTokenizer tokenizer;

        public InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream), 32768);
            tokenizer = null;
        }

        public String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }
        public long nextLong(){
            return Long.parseLong(next());
        }

        public long[] readLongArr(int n){
            long arr[] = new long[n];
            for(int i=0; i<n; i++){
                arr[i] = nextLong();
            }
            return arr;
        }
        public int[] readIntArr(int n){
            int arr[] = new int[n];
            for(int i=0; i<n; i++){
                arr[i] = nextInt();
            }
            return arr;
        }
    }
}
class Pair{
    long x;
    boolean bool;
    Pair(long x, boolean bool){
        this.x = x;
        this.bool = bool;
    }
}