You are given three strings A, B and C. Check whether they form a word chain.

More formally, determine whether both of the following are true:

* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.



If both are true, print `YES`. Otherwise, print `NO`.

Constraints

* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.

Input

Input is given from Standard Input in the following format:


A B C


Output

Print `YES` or `NO`.

Examples

Input

rng gorilla apple


Output

YES


Input

yakiniku unagi sushi


Output

NO


Input

a a a


Output

YES


Input

aaaaaaaaab aaaaaaaaaa aaaaaaaaab


Output

NO
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll INF = 1e18;
const ll MOD = 1e9 + 7;
#define all(v) v.begin(), v.end()
#define repi(i, n, init) for (ll i = init; i < (n); i++)
#define repd(i, n, init) for (ll i = (n); i >= init; i--)
#define repm(i, m) for (auto i = m.begin(); i != m.end(); i++)

int main()
{
    string A, B, C;
    cin >> A >> B >> C;
    cout << (A.at(A.length() - 1) == B.at(0) && B.at(B.length() - 1) == C.at(0)) ? "YES" : "NO" << endl;
    return 0;
}