You are given three strings A, B and C. Check whether they form a word chain.

More formally, determine whether both of the following are true:

* The last character in A and the initial character in B are the same.
* The last character in B and the initial character in C are the same.



If both are true, print `YES`. Otherwise, print `NO`.

Constraints

* A, B and C are all composed of lowercase English letters (`a` - `z`).
* 1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.

Input

Input is given from Standard Input in the following format:


A B C


Output

Print `YES` or `NO`.

Examples

Input

rng gorilla apple


Output

YES


Input

yakiniku unagi sushi


Output

NO


Input

a a a


Output

YES


Input

aaaaaaaaab aaaaaaaaaa aaaaaaaaab


Output

NO
# input
NW = [int(x) for x in input().split(" ")]
N = NW[0]
W = NW[1]

w = []
v = []

for _ in range(N):
	wv = [int(x) for x in input().split(" ")]
	w.append(wv[0])
	v.append(wv[1])

# 品物i-Nまでを使って容量Wのナップサックにいれられる品物の価値の総和の最大値
def rec(i, Wrec):
	if i >= N:
		return 0

	a = -1
	if Wrec - w[i] >= 0:
		a = v[i]+rec(i+1, Wrec-w[i])
	return max(
		a, #品物iを入れる
		rec(i+1, Wrec) #品物iを入れない
		)

print(rec(0,W))