3
1 1 5
1 3 42
1 2 42
 2
42 23
1 2 10
 10
45792697 27183921 4791060 77070594 27286110 66957065 19283638 2944837 26775511 65379701
5 8 25
8 10 94
1 4 14
9 7 96
4 2 16
2 6 58
2 3 99
6 8 21
8 9 87
 5
3 1 2 6 5
1 2 3
2 3 1
4 3 9
5 3 1
 10
26 31 21 57 56 44 54 58 79 97
2 1 277
1 8 91
1 7 380
4 1 649
10 5 799
10 1 940
8 6 627
6 3 177
9 6 685
 10
8 100 62 38 26 51 26 23 77 32
6 8 29
4 1 82
7 8 66
7 10 67
8 9 98
6 1 14
1 5 48
3 1 58
2 9 90
 2
23 42
1 2 10
 1
42
 3
1 5 1
1 3 42
1 2 42
 10
1 1 1 1 1 1 1 1 1 1
1 2 5
1 3 5
1 4 5
1 5 5
1 6 5
1 7 5
1 8 5
1 9 5
1 10 5
 3
1 1 1
1 2 42
2 3 42
 3
5 1 1
1 3 42
1 2 24

3 1042.0638260857 1 727.3238618387 6 283959805416.40496826
 3 192.0000000000 1 13952642.4776933547 8 544327.1927847408 2 727.3238618387 1 0.0000000000 2 1042.0638260857 1 100.6230589875 2 544.3822186663 1 389.7666169867
#include <bits/stdc++.h>
using namespace std;
const int N = 2e5 + 3;
int n, sz[N], rt, ans, w[N], v[N];
double sum, val = 1e10, sumd, d[N];
vector<pair<int, int> > e[N];
void dfs(int x, int fz, int S) {
  sz[x] = 1;
  int Mx = 0;
  for (auto it : e[x])
    if (it.first != fz && !v[it.first])
      dfs(it.first, x, S), sz[x] += sz[it.first], Mx = max(Mx, sz[it.first]);
  Mx = max(Mx, S - sz[x]);
  if (Mx <= (S / 2)) rt = x;
}
void calc(int x, int fz, int o, long long len) {
  sum += len * sqrt(len) * w[x];
  d[o] += 1.5 * sqrt(len) * w[x];
  for (auto it : e[x])
    if (it.first != fz) calc(it.first, x, o, len + it.second);
}
void dfs(int x, int S) {
  dfs(x, 0, S), x = rt, dfs(x, 0, S);
  if (v[x]) return;
  v[x] = 1, sum = sumd = 0;
  for (auto it : e[x])
    d[it.first] = 0, calc(it.first, x, it.first, it.second),
    sumd += d[it.first];
  if (sum < val) ans = x, val = sum;
  for (auto it : e[x])
    if (sumd - 2 * d[it.first] < 0) {
      dfs(it.first, sz[it.first]);
      break;
    }
}
int main() {
  scanf("%d", &n);
  for (int i = 1; i <= n; i++) scanf("%d", &w[i]);
  for (int i = 1; i < n; i++) {
    int a, b, l;
    scanf("%d %d %d", &a, &b, &l);
    e[a].push_back({b, l}), e[b].push_back({a, l});
  }
  dfs(1, n);
  printf("%d %.20lf\n", ans, val);
  return 0;
}
