111111
 100009
 10011
 1000000
 8
 10201
 102030
 908172
 123456
 415
 900000
 21
 909090
 314159
 999999
 909823
 987654
 1453
 1435
 98
 10
 2
 1

1
111111
 9
100001 1 1 1 1 1 1 1 1
 1
10011
 1
1000000
 8
1 1 1 1 1 1 1 1
 2
10101 100
 3
101010 1010 10
 9
101111 101011 101010 101010 101010 101010 101010 101000 100000
 6
111111 11111 1111 111 11 1
 5
111 101 101 101 1
 9
100000 100000 100000 100000 100000 100000 100000 100000 100000
 2
11 10
 9
101010 101010 101010 101010 101010 101010 101010 101010 101010
 9
111111 101011 101011 1011 11 1 1 1 1
 9
111111 111111 111111 111111 111111 111111 111111 111111 111111
 9
101111 101111 101101 101100 101100 101100 101100 101100 101000
 9
111111 111111 111111 111111 111110 111100 111000 110000 100000
 5
1111 111 111 110 10
 5
1111 111 111 101 1
 9
11 11 11 11 11 11 11 11 10
 1
10
 2
1 1
 1
1

#include <bits/stdc++.h>
using namespace std;
template <class T>
ostream& operator<<(ostream& stream, const vector<T> v) {
  stream << "[ ";
  for (int i = 0; i < (int)v.size(); i++) stream << v[i] << " ";
  stream << "]";
  return stream;
}
long long fpow(long long x, long long p, long long m) {
  long long r = 1;
  for (; p; p >>= 1) {
    if (p & 1) r = r * x % m;
    x = x * x % m;
  }
  return r;
}
long long inv(long long a, long long b) {
  return a < 2 ? a : ((a - inv(b % a, a)) * b + 1) / a % b;
}
int gcd(int a, int b) {
  if (!b) return a;
  return gcd(b, a % b);
}
long long gcd(long long a, long long b) {
  if (!b) return a;
  return gcd(b, a % b);
}
const int len = 7;
int N, K;
int reverse(int x) {
  int r = 0;
  while (x) {
    r = r * 10 + x % 10;
    x /= 10;
  }
  return r;
}
int main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cin >> N;
  vector<int> ans;
  while (N) {
    int r = 0, aux = N, i;
    vector<int> d;
    for (i = 0; i < len; i++) d.push_back(aux % 10), aux /= 10;
    for (i = len - 1; i >= 0; i--) r = r * 10 + (d[i] > 0);
    ans.push_back(r);
    N -= r;
  }
  cout << ans.size() << "\n";
  for (int x : ans) cout << x << " ";
  return 0;
}
