111111
 100009
 10011
 1000000
 8
 10201
 102030
 908172
 123456
 415
 900000
 21
 909090
 314159
 999999
 909823
 987654
 1453
 1435
 98
 10
 2
 1

1
111111
 9
100001 1 1 1 1 1 1 1 1
 1
10011
 1
1000000
 8
1 1 1 1 1 1 1 1
 2
10101 100
 3
101010 1010 10
 9
101111 101011 101010 101010 101010 101010 101010 101000 100000
 6
111111 11111 1111 111 11 1
 5
111 101 101 101 1
 9
100000 100000 100000 100000 100000 100000 100000 100000 100000
 2
11 10
 9
101010 101010 101010 101010 101010 101010 101010 101010 101010
 9
111111 101011 101011 1011 11 1 1 1 1
 9
111111 111111 111111 111111 111111 111111 111111 111111 111111
 9
101111 101111 101101 101100 101100 101100 101100 101100 101000
 9
111111 111111 111111 111111 111110 111100 111000 110000 100000
 5
1111 111 111 110 10
 5
1111 111 111 101 1
 9
11 11 11 11 11 11 11 11 10
 1
10
 2
1 1
 1
1

#include <bits/stdc++.h>
using namespace std;
inline long long mod(long long n, long long m) {
  long long ret = n % m;
  if (ret < 0) ret += m;
  return ret;
}
long long gcd(long long a, long long b) { return (b == 0 ? a : gcd(b, a % b)); }
long long exp(long long a, long long b, long long m) {
  if (b == 0) return 1;
  if (b == 1) return mod(a, m);
  long long k = mod(exp(a, b / 2, m), m);
  if (b & 1) {
    return mod(a * mod(k * k, m), m);
  } else
    return mod(k * k, m);
}
vector<long long> resp;
void solve(long long &n) {
  string k = to_string(n);
  reverse(k.begin(), k.end());
  long long x = 0;
  for (long long i = 0; i < k.size(); i++) {
    if (k[i] >= '1') {
      x += exp(10, i, (long long)1000000000 * 1000000000);
    }
  }
  n -= x;
  resp.push_back(x);
}
int32_t main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  ;
  long long n;
  cin >> n;
  while (n) {
    solve(n);
  }
  cout << resp.size() << "\n";
  for (auto x : resp) {
    cout << x << " ";
  }
  cout << "\n";
}
