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64
 200
 6
 246
 220
 108
 6
 334
 280
 20
 266
 60
 10
 142
 58
 120
 134
 172
 400
 186
 60
 230
 8
 190
 46
 74
 54
 400
 12
 2
 86

import java.util.Scanner;

public class Main {
  public static String s;
  
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    s = sc.next();
    int k = sc.nextInt();
    int maxLength = 2;
    
    // The general idea is that for every possible substring of even length, we check if it can be
    // a tandem repeat. However, we only need to check substrings that are longer than the longest
    // tandem repeat that we have already found.
    for (int start = 0; start + maxLength + 1 < s.length() + k; ++start) {
      for (int end = start + maxLength + 1; end < s.length() + k; end += 2) {
        if (isPossibleTandemRepeat(start, end)) {
          maxLength = Math.max(maxLength, end - start + 1);
        }
      }
    }
    
    System.out.println(maxLength);
  }
  
  public static boolean isPossibleTandemRepeat(int start, int end) {
    int n = (end - start + 1) / 2;  // guaranteed that end and start are of opposite parity
    for (int i = start; i < start + n; ++i) {
      if (i + n >= s.length()) {
        return true;
      } else if (s.charAt(i) != s.charAt(i + n)) {
        return false;
      }
    }
    return true;
  }
}