1000000000000000
 994
 200385
 3842529393411
 8
 409477218238717
 2
 419477218238718
 909383000
 7
 999088000000000
 265
 415000000238718
 780869426483087
 9
 850085504652042
 567000123
 980123123123123
 409477218238719
 385925923480002
 999998169714888
 936302451686999
 114
 999999993700000
 108000000057
 409477218238716
 112
 1
 409477218238718
 999971000299999
 409477318238718
 735412349812385
 113
 999999999999999
 123830583943
 899990298504716
 936302451687000
 995
 990000000000000
 936302451687001
 999986542686123
 850085504652041

18 999999993541753
 12 941
 14 200355
 17 3842529383076
 7 7
 17 409477218238717
 2 2
 18 419466459294818
 16 909381874
 7 7
 18 999087986204952
 11 212
 18 414993991790735
 18 780869407920631
 7 7
 18 850085504652042
 16 566998782
 18 980123123116482
 18 409477218238718
 17 385925923479720
 18 999998150030846
 18 936302448662019
 11 114
 18 999999993541753
 17 107986074062
 17 409477218238710
 10 106
 1 1
 18 409477218238718
 18 999969994441746
 18 409477218238718
 18 735409591249436
 10 113
 18 999999993541753
 17 123830561521
 18 899973747835553
 18 936302448662019
 12 995
 18 989983621692990
 18 936302448662019
 18 999969994441746
 18 850085504650655

c = 2
s = 0
p = 0
temp = [0]
from math import *

for c in range(2, 100000):
    t = 0
    p = p + 1
    while s < c ** 3:
        s = s + p ** 3
        if s < c ** 3:
            t = t + 1
            temp.append(s)
        else:
            s = s - p ** 3
            break

            # s=s-p**3
            # t=t-1
            # if t>0:


def check(n):
    s = 0
    while n > 0:
        v = int(n ** (1 / 3.0))
        val = v ** 3
        n = n - val
        s = s + 1
    return s


# for i in range(1,1000):
#  print check(i),i
n = input()
l = len(temp)
s = 0
z2 = n
for i in range(0, l):
    s = temp[i]
    if s >= n:
        break
var = i - 1
var2 = i - 1
var3 = i - 1
ans2 = []
# print temp
fvv = []


def solve2(var, n):
    while var > 0:
        f1 = int(n ** (1 / 3.0)) + 1
        while f1 ** 3 > n or temp[var - 1] + (f1 ** 3) > n:
            if f1 ** 3 < n:
                n = f1 ** 3
            f1 = f1 - 1
        var = var - 1
        n = n - f1 ** 3
        # print f1
        ans2.append(f1 ** 3)
    return sum(ans2)


# print ans2
# print check(sum(ans2)
if z2 <= 7:
    print z2, z2
else:
    pv=-1
    tk=-1
    ans = solve2(var, z2)
    #print ans
    if ans>=0:
        if check(ans)>=pv:
            pv=ans
    #print ans
    ans2=solve2(var+1,z2)
    if ans2>=0:
        if check(ans2)>=pv:
            pv=ans2
    v=max(ans,ans2)
    print check(v),v