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 200
 6
 246
 220
 108
 6
 334
 280
 20
 266
 60
 10
 142
 58
 120
 134
 172
 400
 186
 60
 230
 8
 190
 46
 74
 54
 400
 12
 2
 86

import java.util.Scanner;

public class CF253_B_Tandem {

	public static void main(String[] args) {

		Scanner in = new Scanner(System.in);

		char[] str = in.nextLine().toCharArray();
		int lAdded = in.nextInt();
		
		// Find the largest tandem repeat in the original string
		int origRepLen = 0;
		outerLoop:
		for(int repLen = str.length / 2; repLen > 0; repLen--) {
			innerLoop:
			for(int repStart = 0; repStart < str.length; repStart++) {
				int ind1 = repStart;
				int ind2 = repStart + repLen;
				for(int i = 0; i < repLen; i++) {
					if(ind1 >= str.length || ind2 >= str.length) {
						continue outerLoop;
					}
					if(str[ind1] != str[ind2]) {
						continue innerLoop;
					}
					ind1++;
					ind2++;
				}
				origRepLen = 2*repLen;
				break outerLoop;
			}
			
		}
		
		// Consider a tandem repeat of length 2*repLen in the concatenated string
		int nMax = 0;
		mainLoop:
		for(int repLen = (str.length + lAdded)/2; repLen > 0; repLen--) {
		
			// We can append anything on the
			if(str.length <= repLen) {
				nMax = 2*repLen;
				break;
			}
			
			// We need an overlap, check if there's a repeating sequence from the end
			for(int overSize = 0; overSize < (repLen - lAdded); overSize++) {
				int ind1 = str.length-overSize-1;
				int ind2 = ind1-repLen;
				if(ind2 < 0) {
					continue mainLoop;
				}
				if(str[ind1] != str[ind2]) {
					continue mainLoop;
				}
			}
			
			nMax = 2*repLen;
			break;
		}
		
		System.out.println(Math.max(nMax, origRepLen));
	}

}
