Assume that a, b, and n are all positive integers. Let f (i) be the i-th fraction of the fraction a / b (0 ≤ f (i) ≤ 9). At this time, let s be the sum of f (i) from i = 1 to n.

s = f (1) + f (2) + ... + f (n)


Create a program that reads a, b, n, outputs s, and exits.



Input

The input consists of multiple datasets. For each dataset, three integers a (1 ≤ a ≤ 1000), b (1 ≤ b ≤ 10000), n (1 ≤ n ≤ 100) are given on one line, separated by blanks.

The number of datasets does not exceed 100.

Output

Prints s on one line for each dataset.

Example

Input

1 2 3
2 3 4
5 4 3
4 3 2


Output

5
24
7
6
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main{
	public static void main(String[] args)throws IOException{
		InputStreamReader isr = new InputStreamReader(System.in);
		BufferedReader reader = new BufferedReader(isr);
		String string;
		while((string = reader.readLine()) != null){
			String[] str = string.split("[\\s]+");
			int[] n = new int[3];
			int sum = 0;
			for(int i = 0; i < 3; i++)
				n[i] = Integer.parseInt(str[i]);
			double x = (double)n[0] / n[1];
			String d = String.valueOf((x - (int)x) * Math.pow(10, n[2]));
			for(int i = 0; i < n[2]; i++){
				sum += Integer.parseInt(String.valueOf(d.charAt(i)));
			}
			System.out.println(sum);
		}
		reader.close();
	}
}