Assume that a, b, and n are all positive integers. Let f (i) be the i-th fraction of the fraction a / b (0 ≤ f (i) ≤ 9). At this time, let s be the sum of f (i) from i = 1 to n.

s = f (1) + f (2) + ... + f (n)


Create a program that reads a, b, n, outputs s, and exits.



Input

The input consists of multiple datasets. For each dataset, three integers a (1 ≤ a ≤ 1000), b (1 ≤ b ≤ 10000), n (1 ≤ n ≤ 100) are given on one line, separated by blanks.

The number of datasets does not exceed 100.

Output

Prints s on one line for each dataset.

Example

Input

1 2 3
2 3 4
5 4 3
4 3 2


Output

5
24
7
6
import java.io.*;
import java.math.BigDecimal;

class Main{
public static void main(String[] args) throws IOException{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String line="";
while((line=br.readLine())!=null){
String[] values=line.split(" ");
BigDecimal a=BigDecimal.valueOf(Integer.parseInt(values[0]));
BigDecimal b=BigDecimal.valueOf(Integer.parseInt(values[1]));
int n=Integer.parseInt(values[2]);
while(true){
if(a.intValue()>=b.intValue()){
a.substract(b);
continue;
}
break;
}
BigDecimal c=a.devide(b);
int sum=0;
c=c.multiply(BigDecimal.valueOf(Math.pow(10,n)));
c=c.setScale(0,BigDecimal.ROUND_DOWN);
int d=c.intValue();
String str=String.valueOf(d);
for(int i=0;i<n;i++){
if(str.charAt(i)==null){
continue;
}
sum+=(int)(str.charAt(i)-'0');
}
System.out.println(sum);
}
}
}