There are N balls placed in a row. AtCoDeer the deer is painting each of these in one of the K colors of his paint cans. For aesthetic reasons, any two adjacent balls must be painted in different colors.

Find the number of the possible ways to paint the balls.

Constraints

* 1≦N≦1000
* 2≦K≦1000
* The correct answer is at most 2^{31}-1.

Input

The input is given from Standard Input in the following format:


N K


Output

Print the number of the possible ways to paint the balls.

Examples

Input

2 2


Output

2


Input

1 10


Output

10
#include <bits/stdc++.h>
using namespace std;
typedef struct edge_ {
  long long to;
  long long cost;
} edge;
typedef struct point_ {
  long long x, y;
  point_(long long x = 0, long long y = 0) : x(x), y(y) {}
} point;
template <typename T>
using mat2d = vector<vector<T>>;
constexpr double PI = 3.14159265358979323846;
constexpr long long INF = 1 << 15;
constexpr long long MOD = (long long)1e9 + 7;
constexpr double EPS = 1e-7;
constexpr int dy4[4] = {0, 1, 0, -1};
constexpr int dx4[4] = {1, 0, -1, 0};
constexpr int dy8[8] = {0, 1, 1, 1, 0, -1, -1, -1};
constexpr int dx8[8] = {1, 1, 0, -1, -1, -1, 0, 1};
template <typename T>
istream& operator>>(istream& is, vector<T>& vec) {
  for (T& x : vec) is >> x;
  return is;
}
template <typename T>
ostream& operator<<(ostream& os, const vector<T>& vec) {
  for (const T& x : vec) os << x << " ";
  return os;
}
template <typename S, typename T>
istream& operator>>(istream& is, pair<S, T>& p) {
  is >> p.first >> p.second;
  return is;
}
istream& operator>>(istream& is, point& p) {
  is >> p.x >> p.y;
  return is;
}
template <typename S, typename T>
ostream& operator<<(ostream& os, const pair<S, T>& p) {
  os << "{" << p.first << " : " << p.second << "}";
  return os;
}
template <typename T>
ostream& operator<<(ostream& os, const set<T>& s) {
  for (const T& x : s) os << x << " ";
  return os;
}
ostream& operator<<(ostream& os, const edge e) {
  os << "{to: " << e.to << ", cost: " << e.cost << "}";
  return os;
}
ostream& operator<<(ostream& os, const point& p) {
  os << "(" << p.x << " " << p.y << ")";
  return os;
}
int main() {
  int N, K;
  cin >> N >> K;
  cout << K * pow(K - 1, N - 1) << endl;
  return 0;
}
