There are N balls placed in a row. AtCoDeer the deer is painting each of these in one of the K colors of his paint cans. For aesthetic reasons, any two adjacent balls must be painted in different colors.

Find the number of the possible ways to paint the balls.

Constraints

* 1≦N≦1000
* 2≦K≦1000
* The correct answer is at most 2^{31}-1.

Input

The input is given from Standard Input in the following format:


N K


Output

Print the number of the possible ways to paint the balls.

Examples

Input

2 2


Output

2


Input

1 10


Output

10
#include <bits/stdc++.h>
using namespace std;
const int mod = 1000000007;
int int_len(int n) {
  int s = 0;
  while (n != 0) s++, n /= 10;
  return s;
}
int int_sum(int n) {
  int m = 0, s = 0, a = n;
  while (a != 0) s++, a /= 10;
  for (int i = s - 1; i >= 0; i--)
    m += n / ((int)pow(10, i)) - (n / ((int)pow(10, i + 1))) * 10;
  return m;
}
int gcd(int a, int b) {
  int r, tmp;
  if (a < b) {
    tmp = a;
    a = b;
    b = tmp;
  }
  r = a % b;
  while (r != 0) {
    a = b;
    b = r;
    r = a % b;
  }
  return b;
}
int fac(int n) {
  int m = 1;
  while (n >= 1) m *= n, n--;
  return m;
}
int vec_sum(vector<int> v) {
  int n = 0;
  for (int i = 0; i < v.size(); i++) n += v[i];
  return n;
}
int main() {
  long long int n, k;
  cout << (long long int)pow(k - 1, n - 1) * k << endl;
}
