A convex polygon consisting of N vertices is given. The coordinates of each vertex are represented counterclockwise by (X1, Y1), (X2, Y2), ……, (XN, YN). No matter what straight line passes through the point P, find the coordinates of the point P so that the areas of the two convex polygons obtained after cutting are equal.

Constraints

* All inputs are integers

* 3 ≤ N ≤ 50

* 0 ≤ | Xi |, | Yi | ≤ 1000000

* The input polygon is a simple convex polygon.

* The output must satisfy max (| X-cX |, | Y-cY |) ≤ 0.0001 when the output coordinates are (X, Y) and the exact solution is (cX, cY).

Input

The input is given in the following format.

> N
> X1 Y1
> X2 Y2
> ……
> XN YN
>

Output

If there is a point that satisfies the condition of the problem statement, the coordinates of that point

> X Y
>

Output in the format of. If the point does not exist, output "NA" on one line.

Examples

Input

4
100 100
0 100
0 0
100 0


Output

50.00000 50.00000


Input

3
100 100
0 100
0 0


Output

NA
#include <stdio.h>
#include <string.h>
#include <algorithm>
#include <iostream>
#include <math.h>
#include <assert.h>
#include <vector>
#include <queue>
#include <string>
#include <map>
#include <set>

using namespace std;
typedef long long ll;
typedef unsigned int uint;
typedef unsigned long long ull;
static const double EPS = 1e-9;
static const double PI = acos(-1.0);

#define REP(i, n) for (int i = 0; i < (int)(n); i++)
#define FOR(i, s, n) for (int i = (s); i < (int)(n); i++)
#define FOREQ(i, s, n) for (int i = (s); i <= (int)(n); i++)
#define FORIT(it, c) for (__typeof((c).begin())it = (c).begin(); it != (c).end(); it++)
#define MEMSET(v, h) memset((v), h, sizeof(v))

#include <complex>

typedef complex<double> Point;
typedef vector<Point> Polygon;

static const double INF = 1e+10;

#define CURR(P, i) (P[i])
#define NEXT(P, i) (P[(i + 1) % P.size()])

struct Line : public vector<Point> {
  Line() {;}
  Line(Point a, Point b) { push_back(a); push_back(b); }
};

struct Circle {
  Point p;
  double r;
  Circle() {;}
  Circle(Point p, double r) : p(p), r(r) {;}
};

namespace std {
  bool operator<(const Point &lhs, const Point &rhs) {
    return lhs.real() == rhs.real() ? lhs.imag() < rhs.imag() : lhs.real() < rhs.real();
  }
}

inline double cross(const Point &a, const Point &b) {
  return imag(conj(a) * b);
}

inline double dot(const Point &a, const Point &b) {
  return real(conj(a) * b);
}

inline int ccw(Point a, Point b, Point c) {
  b -= a;
  c -= a;
  if (cross(b, c) > 0) { return 1; }
  if (cross(b, c) < 0) { return -1; }
  if (dot(b, c) < 0) { return 2; }
  if (norm(b) < norm(c)) { return -2; }
  return 0;
}


int n;
Polygon poly;
Point center;

int main() {
  while (scanf("%d", &n) > 0) {
    poly.clear();
    center = Point(0, 0);
    REP(i, n) {
      double x, y;
      scanf("%lf %lf", &x, &y);
      poly.push_back(Point(x, y));
      center += Point(x, y);
    }
    center /= (double)n;
    REP(i, n) {
      Point vect = poly[i] - center;
      Point need = center - vect;
      REP(j, n) {
        if (abs(poly[j] - need) <= EPS) { goto ok; }
      }
      puts("NA");
      goto end;
ok:;
    }
    printf("%.10f %.10f\n", center.real(), center.imag());
end:;
  }
}