There are N balls placed in a row. AtCoDeer the deer is painting each of these in one of the K colors of his paint cans. For aesthetic reasons, any two adjacent balls must be painted in different colors.

Find the number of the possible ways to paint the balls.

Constraints

* 1≦N≦1000
* 2≦K≦1000
* The correct answer is at most 2^{31}-1.

Input

The input is given from Standard Input in the following format:


N K


Output

Print the number of the possible ways to paint the balls.

Examples

Input

2 2


Output

2


Input

1 10


Output

10
#include <bits/stdc++.h>
using namespace std;
void __print(int x) { cout << x; }
void __print(long x) { cout << x; }
void __print(long long x) { std::cout << x; }
void __print(unsigned x) { std::cout << x; }
void __print(unsigned long x) { std::cout << x; }
void __print(unsigned long long x) { std::cout << x; }
void __print(float x) { std::cout << x; }
void __print(double x) { std::cout << x; }
void __print(long double x) { std::cout << x; }
void __print(char x) { cout << '\'' << x << '\''; }
void __print(const char *x) { cout << '\"' << x << '\"'; }
void __print(const string &x) { cout << '\"' << x << '\"'; }
void __print(bool x) { cout << (x ? "true" : "false"); }
template <typename T, typename V>
void __print(const pair<T, V> &x) {
  cout << '{';
  __print(x.first);
  cout << ',';
  __print(x.second);
  cout << '}';
}
template <typename T>
void __print(const T &x) {
  int f = 0;
  cout << '{';
  for (auto &i : x) cout << (f++ ? "," : ""), __print(i);
  cout << "}";
}
void _print() { cout << "]\n"; }
template <typename T, typename... V>
void _print(T t, V... v) {
  __print(t);
  if (sizeof...(v)) cout << ", ";
  _print(v...);
}
template <typename T>
inline void inp(T &any) {
  cin >> any;
}
template <typename T, typename... U>
inline void inp(T &a, U &...b) {
  cin >> a;
  inp(b...);
}
const int maxm = 1000000000 + 7;
const long long MOD = 1e9 + 7;
const int INF = 55;
long long dp[INF][INF * INF];
double startTime;
double getCurrentTime() {
  return ((double)clock() - startTime) / CLOCKS_PER_SEC;
}
int main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  ;
  int n, k;
  cin >> n >> k;
  long long ans = 1;
  for (int i = 0; i < n; i++) {
    ans *= (k - i);
  }
  cout << ans << "\n";
}
