Assume that a, b, and n are all positive integers. Let f (i) be the i-th fraction of the fraction a / b (0 ≤ f (i) ≤ 9). At this time, let s be the sum of f (i) from i = 1 to n.

s = f (1) + f (2) + ... + f (n)


Create a program that reads a, b, n, outputs s, and exits.



Input

The input consists of multiple datasets. For each dataset, three integers a (1 ≤ a ≤ 1000), b (1 ≤ b ≤ 10000), n (1 ≤ n ≤ 100) are given on one line, separated by blanks.

The number of datasets does not exceed 100.

Output

Prints s on one line for each dataset.

Example

Input

1 2 3
2 3 4
5 4 3
4 3 2


Output

5
24
7
6
#include <bits/stdc++.h>
using namespace std;
static const double EPS = 1e-10;
static const double PI = acos(-1.0);
static const int mod = 10007;
static const int INF = 1 << 25;
static const long long LL_INF = 1152921504606846976;
static const int dx[] = {-1, 0, 1, 0, 1, -1, 1, -1};
static const int dy[] = {0, -1, 0, 1, 1, 1, -1, -1};
int a, b, n;
int f(double a, int b, int n) {
  double a_b = a / b;
  int res = 0;
  for (int i = 0; i < n; i++) {
    a_b *= 10;
    res += (int)a_b % 10;
  }
  return res;
}
int main() {
  while (~scanf("%d %d %d", &a, &b, &n)) {
    int ans = f(a, b, n);
    printf("%d\n", ans);
  }
  return 0;
}
