import math 
  
# A utility function that returns true if x is perfect square 
def isPerfectSquare(x): 
    s = int(math.sqrt(x)) 
    return s*s == x 
  
# Returns true if n is a Fibinacci Number, else false 
def isFibonacci(n): 
  
    # n is Fibinacci if one of 5*n*n + 4 or 5*n*n - 4 or both 
    # is a perferct square 
    return isPerfectSquare(5*n*n + 4) or isPerfectSquare(5*n*n - 4) 
     
n = int(input())
s = ""
for i in range(1,n+1):
    if isFibonacci(i)==True:
        s = s + "O"
    else:
        s = s + "o"
print(s)