import math 
  
# A utility function that returns true if x is perfect square 
def isPerfectSquare(x): 
    s = int(math.sqrt(x)) 
    return s*s == x 
  
# Returns true if n is a Fibinacci Number, else false 
def isFibonacci(n): 
  
    # n is Fibinacci if one of 5*n*n + 4 or 5*n*n - 4 or both 
    # is a perferct square 
    return isPerfectSquare(5*n*n + 4) or isPerfectSquare(5*n*n - 4) 
    

n = int(input())

ans = ""

for i in range(1,n+1) :
    
    if isFibonacci(i) :
        
        ans = ans + "O"
        
    else :
        ans = ans + "o"
        
print(ans)