10
abdcced
bdacdac
ecb
dc
eaeeebdd
adcdbadcac
eb
aadecccde
edbaeacad
accd
 100
d
a
e
eb
c
d
d
e
c
e
ac
d
c
aa
a
e
da
e
e
c
e
a
c
c
bc
bd
d
da
cc
be
b
a
ee
d
be
be
e
b
a
ed
cb
ab
a
ea
ac
aa
ed
d
b
eb
e
ed
c
ce
c
d
c
d
d
ee
e
b
ea
ea
da
ab
ba
ed
da
ec
ea
bd
ee
dc
d
bd
d
c
cc
ab
bd
a
ad
e
d
e
bc
bb
c
bc
a
a
e
ca
ac
c
ad
c
be
d
 3
ab
acb
ba
 10
a
b
a
c
b
a
b
a
a
a
 5
cab
bbc
caa
ccc
aca
 3
ac
abc
ca
 5
ab
bc
cd
de
ffffffffff
 16
ddgcb
fgbhgbdg
gha
dh
ddfb
fggbc
edb
hd
d
hfgcabf
hdaef
fhbcdgba
chee
cafeggc
f
ecb
 50
agecd
cghafi
fiide
iecc
jbdcfjhgd
diee
hfeg
ehc
gfijgjh
gacaifebg
dicbbddc
hjgciaei
jjcdh
g
gc
cf
hfdjhd
c
icidbec
ji
eeh
cgeejggc
acfd
jjg
ajefdj
eghhebiic
bih
gbb
jjaa
idc
gafi
ecg
dbigbjiehj
cedif
ahidfaaajg
hfhhiccbgb
dgegjgieif
hgjebhfdc
j
ahehd
ahdah
bijbhh
a
dabiggfhac
dedigbjbf
ihbdj
iihagchd
gfebhfdi
jbjdcggdh
f

0
 35
 5
 6
 9
 5
 10
 7
 37

import java.util.*;
import java.io.*;
public class p1 {
    public static void main(String[] args) throws IOException
    {
        Scanner sc = new Scanner(System.in);
        PrintWriter out  = new PrintWriter((System.out));
        int[][] g = new int[26][26];
        int n = sc.nextInt();
        for(int i = 0; i<n; i++)
        {
            String s = sc.next();
            int start = s.charAt(0)-'a', end = s.charAt(s.length()-1)-'a';
            for(int j = 0; j<26; j++)
            {
                if(g[j][start] > 0 || j == start) g[j][end] = Math.max(g[j][end], g[j][start]+s.length());
            }
        }
        int max = 0;
        for(int i = 0; i<26; i++) max = Math.max(max, g[i][i]);
        out.println(max);
        out.close();
    }
}
