10
abdcced
bdacdac
ecb
dc
eaeeebdd
adcdbadcac
eb
aadecccde
edbaeacad
accd
 100
d
a
e
eb
c
d
d
e
c
e
ac
d
c
aa
a
e
da
e
e
c
e
a
c
c
bc
bd
d
da
cc
be
b
a
ee
d
be
be
e
b
a
ed
cb
ab
a
ea
ac
aa
ed
d
b
eb
e
ed
c
ce
c
d
c
d
d
ee
e
b
ea
ea
da
ab
ba
ed
da
ec
ea
bd
ee
dc
d
bd
d
c
cc
ab
bd
a
ad
e
d
e
bc
bb
c
bc
a
a
e
ca
ac
c
ad
c
be
d
 3
ab
acb
ba
 10
a
b
a
c
b
a
b
a
a
a
 5
cab
bbc
caa
ccc
aca
 3
ac
abc
ca
 5
ab
bc
cd
de
ffffffffff
 16
ddgcb
fgbhgbdg
gha
dh
ddfb
fggbc
edb
hd
d
hfgcabf
hdaef
fhbcdgba
chee
cafeggc
f
ecb
 50
agecd
cghafi
fiide
iecc
jbdcfjhgd
diee
hfeg
ehc
gfijgjh
gacaifebg
dicbbddc
hjgciaei
jjcdh
g
gc
cf
hfdjhd
c
icidbec
ji
eeh
cgeejggc
acfd
jjg
ajefdj
eghhebiic
bih
gbb
jjaa
idc
gafi
ecg
dbigbjiehj
cedif
ahidfaaajg
hfhhiccbgb
dgegjgieif
hgjebhfdc
j
ahehd
ahdah
bijbhh
a
dabiggfhac
dedigbjbf
ihbdj
iihagchd
gfebhfdi
jbjdcggdh
f

0
 35
 5
 6
 9
 5
 10
 7
 37

#include <bits/stdc++.h>
using namespace std;
const int N = 500010;
const int C = 26;
int n, m[N], f[C][C] = {0};
pair<int, int> a[N];
char s[N];
int main() {
  int ans = 0;
  scanf("%d", &n);
  for (int i = 1; i <= n; ++i) {
    int u, v;
    scanf("%s", s + 1);
    m[i] = strlen(s + 1);
    u = s[1] - 'a';
    v = s[m[i]] - 'a';
    if (u == v) ans = max(ans, m[i]);
    for (int fi = 0; fi < C; ++fi)
      if (f[fi][u] > 0) f[fi][v] = max(f[fi][v], f[fi][u] + m[i]);
    f[u][v] = max(f[u][v], m[i]);
    ans = max(ans, f[v][v]);
  }
  cout << ans;
  return 0;
}
