Utkarsh is forced to play yet another one of Ashish's games. The game progresses turn by turn and as usual, Ashish moves first.

Consider the 2D plane. There is a token which is initially at (0,0). In one move a player must increase either the x coordinate or the y coordinate of the token by exactly k. In doing so, the player must ensure that the token stays within a (Euclidean) distance d from (0,0).

In other words, if after a move the coordinates of the token are (p,q), then p^2 + q^2 ≤ d^2 must hold.

The game ends when a player is unable to make a move. It can be shown that the game will end in a finite number of moves. If both players play optimally, determine who will win.

Input

The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases.

The only line of each test case contains two space separated integers d (1 ≤ d ≤ 10^5) and k (1 ≤ k ≤ d).

Output

For each test case, if Ashish wins the game, print "Ashish", otherwise print "Utkarsh" (without the quotes).

Example

Input


5
2 1
5 2
10 3
25 4
15441 33


Output


Utkarsh
Ashish
Utkarsh
Utkarsh
Ashish

Note

In the first test case, one possible sequence of moves can be

(0, 0) \xrightarrow{Ashish } (0, 1) \xrightarrow{Utkarsh } (0, 2).

Ashish has no moves left, so Utkarsh wins.

<image>
#include <bits/stdc++.h>
 
#define mp make_pair
#define mt make_tuple
#define fi first
#define se second
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define forn(i, n) for (int i = 0; i < (int)(n); ++i)
#define for1(i, n) for (int i = 1; i <= (int)(n); ++i)
#define ford(i, n) for (int i = (int)(n) - 1; i >= 0; --i)
#define fore(i, a, b) for (int i = (int)(a); i <= (int)(b); ++i)
#define deb(x) cout<<#x<<" "<<endl;
 
using namespace std;
 
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<pii> vpi;
typedef vector<vi> vvi;
typedef long long ll;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef pair<ll, ll> pll;
typedef double ld;
 
template<class T> bool uin(T &a, T b) { return a > b ? (a = b, true) : false; }
template<class T> bool uax(T &a, T b) { return a < b ? (a = b, true) : false; }
//-------------------------------------------------------------------------------

double d;
double k;

double dist(ll x,ll y){
	ll g=x*x+y*y;
	return sqrt(g);
}
void solve(){
	cin>>d>>k;

	ll move=0;
	double tot=0;
	int x=0,y=0;

	while(tot<=d){
		if(move%2==0){
			x+=k;
			tot=dist(x,y);
			move++;
		}
		else{
			y+=k;
			tot=dist(x,y);
			move++;
		}
	}
	// cout<<move<<endl;
	if(move%2==1){
		cout<<"Utkarsh"<<'\n';
	}
	else{
		cout<<"Ashish"<<'\n';
	}

}


int main(){
	ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
	#ifndef ONLINE_JUDGE
	freopen("E:\\input-output\\input.txt","r",stdin);
	freopen("E:\\input-output\\output.txt","w",stdout);
	#endif
	ll t;cin>>t;
	while(t--){
		solve();
	}

}
 