Utkarsh is forced to play yet another one of Ashish's games. The game progresses turn by turn and as usual, Ashish moves first.

Consider the 2D plane. There is a token which is initially at (0,0). In one move a player must increase either the x coordinate or the y coordinate of the token by exactly k. In doing so, the player must ensure that the token stays within a (Euclidean) distance d from (0,0).

In other words, if after a move the coordinates of the token are (p,q), then p^2 + q^2 ≤ d^2 must hold.

The game ends when a player is unable to make a move. It can be shown that the game will end in a finite number of moves. If both players play optimally, determine who will win.

Input

The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases.

The only line of each test case contains two space separated integers d (1 ≤ d ≤ 10^5) and k (1 ≤ k ≤ d).

Output

For each test case, if Ashish wins the game, print "Ashish", otherwise print "Utkarsh" (without the quotes).

Example

Input


5
2 1
5 2
10 3
25 4
15441 33


Output


Utkarsh
Ashish
Utkarsh
Utkarsh
Ashish

Note

In the first test case, one possible sequence of moves can be

(0, 0) \xrightarrow{Ashish } (0, 1) \xrightarrow{Utkarsh } (0, 2).

Ashish has no moves left, so Utkarsh wins.

<image>
#include <bits/stdc++.h>
using namespace std;
const int int_inf = 0x3f3f3f3f;
const long long int ll_inf = 0x3f3f3f3f3f3f3f3f;
const int max_n = 1e5 + 5;
int main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  int i, j;
  int t;
  cin >> t;
  while (t--) {
    double d, k;
    cin >> d >> k;
    double dd = d * d;
    int lim = d, add = k;
    bool flag = false;
    int max1 = -1;
    for (int i = 0; i <= lim; i += add) {
      int x = sqrt(d * d - i * i);
      int a = x / add;
      int b = i / add;
      if ((a + b) % 2 == 0 && (a + b) > max1) {
        max1 = (a + b);
        flag = false;
      }
      if ((a + b) % 2 == 1 && (a + b) > max1) {
        max1 = (a + b);
        flag = true;
      }
    }
    if (flag)
      cout << "Ashish" << endl;
    else
      cout << "Utkarsh" << endl;
  }
  return 0;
}
