Polycarp often uses his smartphone. He has already installed n applications on it. Application with number i takes up a_i units of memory.

Polycarp wants to free at least m units of memory (by removing some applications).

Of course, some applications are more important to Polycarp than others. He came up with the following scoring system — he assigned an integer b_i to each application: 

  * b_i = 1 — regular application; 
  * b_i = 2 — important application. 



According to this rating system, his phone has b_1 + b_2 + … + b_n convenience points.

Polycarp believes that if he removes applications with numbers i_1, i_2, …, i_k, then he will free a_{i_1} + a_{i_2} + … + a_{i_k} units of memory and lose b_{i_1} + b_{i_2} + … + b_{i_k} convenience points.

For example, if n=5, m=7, a=[5, 3, 2, 1, 4], b=[2, 1, 1, 2, 1], then Polycarp can uninstall the following application sets (not all options are listed below): 

  * applications with numbers 1, 4 and 5. In this case, it will free a_1+a_4+a_5=10 units of memory and lose b_1+b_4+b_5=5 convenience points; 
  * applications with numbers 1 and 3. In this case, it will free a_1+a_3=7 units of memory and lose b_1+b_3=3 convenience points. 
  * applications with numbers 2 and 5. In this case, it will free a_2+a_5=7 memory units and lose b_2+b_5=2 convenience points. 



Help Polycarp, choose a set of applications, such that if removing them will free at least m units of memory and lose the minimum number of convenience points, or indicate that such a set does not exist.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The first line of each test case contains two integers n and m (1 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 10^9) — the number of applications on Polycarp's phone and the number of memory units to be freed.

The second line of each test case contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^9) — the number of memory units used by applications.

The third line of each test case contains n integers b_1, b_2, …, b_n (1 ≤ b_i ≤ 2) — the convenience points of each application.

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.

Output

For each test case, output on a separate line: 

  * -1, if there is no set of applications, removing which will free at least m units of memory; 
  * the minimum number of convenience points that Polycarp will lose if such a set exists. 

Example

Input


5
5 7
5 3 2 1 4
2 1 1 2 1
1 3
2
1
5 10
2 3 2 3 2
1 2 1 2 1
4 10
5 1 3 4
1 2 1 2
4 5
3 2 1 2
2 1 2 1


Output


2
-1
6
4
3

Note

In the first test case, it is optimal to remove applications with numbers 2 and 5, freeing 7 units of memory. b_2+b_5=2.

In the second test case, by removing the only application, Polycarp will be able to clear only 2 of memory units out of the 3 needed.

In the third test case, it is optimal to remove applications with numbers 1, 2, 3 and 4, freeing 10 units of memory. b_1+b_2+b_3+b_4=6.

In the fourth test case, it is optimal to remove applications with numbers 1, 3 and 4, freeing 12 units of memory. b_1+b_3+b_4=4.

In the fifth test case, it is optimal to remove applications with numbers 1 and 2, freeing 5 units of memory. b_1+b_2=3.
//package Codeforces;
import java.util.*;
import java.awt.List;
import java.io.*;
public class D
{
   static final int mod = (int) 1e9 + 7;
   static final int inf = (int) 1e9;
   static final long INF = (long) 1e18;static int n,cost;
   static int first[]=new int[(int)2e5+7],second[]=new int[first.length];
   static ArrayList<Integer> ones = new ArrayList<Integer>();
   static ArrayList<Integer> two = new ArrayList<Integer>();
   static long pref[]=new long[first.length];
   public static void main(String[] args) throws IOException 
   {
		FastScanner fs = new FastScanner();
		PrintWriter out = new PrintWriter(System.out);
		int T=fs.nextInt();
		while(T-->0)
		{
			n=fs.nextInt();cost=fs.nextInt();
			for(int i=1;i<=n;i++)first[i]=fs.nextInt();
			for(int i=1;i<=n;i++)second[i]=fs.nextInt();
			for(int i=1;i<=n;i++)
			{
				if(second[i]==1)ones.add(first[i]);
				else two.add(first[i]);
			}
			Collections.sort(ones,Collections.reverseOrder());
			Collections.sort(two,Collections.reverseOrder());
			///System.out.println(ones+" "+two);
			for(int i=0;i<two.size();i++)
			{	pref[i+1]=pref[i]+two.get(i);}
			int ans=inf;long sum=0;
			for(int i=0;i<=ones.size();i++)
			{
				if(i==0)
				{
					long needed=cost;
					int ind=bin_search(pref,two.size(),needed);
					//System.out.println(ind+" "+i+" "+needed);
					if(ind!=-1)
						ans=Math.min(ans,ind*2);
				}
				else
				{
					sum+=ones.get(i-1);
					long needed=cost-sum;
					int ind=bin_search(pref,two.size(),needed);
					//System.out.println(ind+" "+i+" "+needed);
					if(ind!=-1)
						ans=Math.min(ans,(ind*2)+(i));
				}
			}
			out.println(ans==inf ? -1:ans);ones.clear();two.clear();
		}
		out.close();
   }
   public static int bin_search(long arr[],int len,long key)
   {
	   int left=0,right=len;int ans=-1;
	   while(left<=right)
	   {
		   int mid=(left+right)/2;
		   if(arr[mid]>=key) {ans=mid;right=mid-1;}
		   else left=mid+1;
	   }
	   return ans;
   }
	public static int upper_bound(int arr[],int key)
	{
		int index=inf,num=0;
		int left=0,right=arr.length-1;
		while(left<=right)
		{
			int mid=left+(right-left)/2;
			if(arr[mid]<=key) {index=mid;num=arr[mid];left=mid+1;}
			else 
				right=mid-1;
		}
		return index==inf ? arr.length:index;
	}
}
class FastScanner {
	BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
	StringTokenizer st = new StringTokenizer("");

	public String next() {
		while (!st.hasMoreTokens())
			try {
				st = new StringTokenizer(br.readLine());
			} catch (IOException e) {
				e.printStackTrace();
			}
		return st.nextToken();

	}

	public String nextLine() throws IOException {
		return br.readLine();
	}

	int[] sort(int arr[]) {
		ArrayList<Integer> list = new ArrayList<Integer>();
		for (int i : arr)
			list.add(i);
		Collections.sort(list);
		for (int i = 0; i < arr.length; i++) {
			arr[i] = list.get(i);
		}
		return arr;
	}

	char[] charsort(char arr[]) {
		ArrayList<Character> list = new ArrayList<>();
		for (char c : arr)
			list.add(c);
		Collections.sort(list);
		for (int i = 0; i < list.size(); i++) {
			arr[i] = list.get(i);
		}
		return arr;
	}

	long[] longsort(long arr[]) {
		ArrayList<Long> list = new ArrayList<Long>();
		for (long i : arr)
			list.add(i);
		Collections.sort(list);
		for (int i = 0; i < arr.length; i++) {
			arr[i] = list.get(i);
		}
		return arr;
	}

	public int nextInt() {
		return Integer.parseInt(next());
	}

	public int[] readArray(int n) {
		int[] arr = new int[n];
		for (int i = 0; i < n; i++)
			arr[i] = nextInt();
		return arr;
	}

	public long nextLong() {
		return Long.parseLong(next());
	}

	public long[] longreadArray(int n) {
		long[] a = new long[n];
		for (int i = 0; i < n; i++)
			a[i] = nextLong();
		return a;
	}
}
