Utkarsh is forced to play yet another one of Ashish's games. The game progresses turn by turn and as usual, Ashish moves first.

Consider the 2D plane. There is a token which is initially at (0,0). In one move a player must increase either the x coordinate or the y coordinate of the token by exactly k. In doing so, the player must ensure that the token stays within a (Euclidean) distance d from (0,0).

In other words, if after a move the coordinates of the token are (p,q), then p^2 + q^2 ≤ d^2 must hold.

The game ends when a player is unable to make a move. It can be shown that the game will end in a finite number of moves. If both players play optimally, determine who will win.

Input

The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases.

The only line of each test case contains two space separated integers d (1 ≤ d ≤ 10^5) and k (1 ≤ k ≤ d).

Output

For each test case, if Ashish wins the game, print "Ashish", otherwise print "Utkarsh" (without the quotes).

Example

Input


5
2 1
5 2
10 3
25 4
15441 33


Output


Utkarsh
Ashish
Utkarsh
Utkarsh
Ashish

Note

In the first test case, one possible sequence of moves can be

(0, 0) \xrightarrow{Ashish } (0, 1) \xrightarrow{Utkarsh } (0, 2).

Ashish has no moves left, so Utkarsh wins.

<image>
import java.util.*;

public class Main
{
    public static void main(String [] args)
    {
        Scanner s = new Scanner(System.in);
        
        int t = s.nextInt();
        
        while(t-- != 0)
        {
            int d = s.nextInt();
            int k = s.nextInt();
            
            whoWon(0,0,d,k,true);
        }
    }
    
    //true-> Ashish
    //false->Utkarsh
    public static void whoWon(long x, long y, long d, long k, boolean player)
    {
        if(player && (x*x + (y+k)*(y+k) <= (d*d)))
        {
            whoWon(x, y+k, d, k, !player);
        }
        else if(!player && ((x+k)*(x+k) + y*y <= (d*d)))
            whoWon(x+k, y, d, k, !player);
        else
        {
            if(player)
                System.out.println("Utkarsh");
            else
                System.out.println("Ashish");
                
            return;
        }
    }
}