Dark is going to attend Motarack's birthday. Dark decided that the gift he is going to give to Motarack is an array a of n non-negative integers.

Dark created that array 1000 years ago, so some elements in that array disappeared. Dark knows that Motarack hates to see an array that has two adjacent elements with a high absolute difference between them. He doesn't have much time so he wants to choose an integer k (0 ≤ k ≤ 10^{9}) and replaces all missing elements in the array a with k.

Let m be the maximum absolute difference between all adjacent elements (i.e. the maximum value of |a_i - a_{i+1}| for all 1 ≤ i ≤ n - 1) in the array a after Dark replaces all missing elements with k.

Dark should choose an integer k so that m is minimized. Can you help him?

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases. The description of the test cases follows.

The first line of each test case contains one integer n (2 ≤ n ≤ 10^{5}) — the size of the array a.

The second line of each test case contains n integers a_1, a_2, …, a_n (-1 ≤ a_i ≤ 10 ^ {9}). If a_i = -1, then the i-th integer is missing. It is guaranteed that at least one integer is missing in every test case.

It is guaranteed, that the sum of n for all test cases does not exceed 4 ⋅ 10 ^ {5}.

Output

Print the answers for each test case in the following format:

You should print two integers, the minimum possible value of m and an integer k (0 ≤ k ≤ 10^{9}) that makes the maximum absolute difference between adjacent elements in the array a equal to m.

Make sure that after replacing all the missing elements with k, the maximum absolute difference between adjacent elements becomes m.

If there is more than one possible k, you can print any of them.

Example

Input


7
5
-1 10 -1 12 -1
5
-1 40 35 -1 35
6
-1 -1 9 -1 3 -1
2
-1 -1
2
0 -1
4
1 -1 3 -1
7
1 -1 7 5 2 -1 5


Output


1 11
5 35
3 6
0 42
0 0
1 2
3 4

Note

In the first test case after replacing all missing elements with 11 the array becomes [11, 10, 11, 12, 11]. The absolute difference between any adjacent elements is 1. It is impossible to choose a value of k, such that the absolute difference between any adjacent element will be ≤ 0. So, the answer is 1.

In the third test case after replacing all missing elements with 6 the array becomes [6, 6, 9, 6, 3, 6].

  * |a_1 - a_2| = |6 - 6| = 0; 
  * |a_2 - a_3| = |6 - 9| = 3; 
  * |a_3 - a_4| = |9 - 6| = 3; 
  * |a_4 - a_5| = |6 - 3| = 3; 
  * |a_5 - a_6| = |3 - 6| = 3. 



So, the maximum difference between any adjacent elements is 3.
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.InputMismatchException;
import java.util.TreeMap;

public class C {
	public static ArrayList<Integer>[] adj;
	public static StringBuilder ans;
	public static int[] vis;
	public static int flag;

	public static void main(String[] args) throws Exception {
		// TODO Auto-generated method stub
		InputReader s = new InputReader(System.in);
		PrintWriter p = new PrintWriter(System.out);
		int t = s.nextInt();
		while (t-- > 0) {
			int n = s.nextInt();
			int[] arr = new int[n];
			int[] arr2 = new int[n];
			for (int i = 0; i < n; i++) {
				arr[i] = s.nextInt();
				arr2[i] = arr[i];
			}
			TreeMap<Integer, Integer> map = new TreeMap<>();
			for (int i = 0; i < n; i++) {
				if (i == 0) {
					if (arr[i] != -1 && arr[i + 1] == -1) {
						map.put(arr[0], 1);
					}
					continue;
				} else if (i == n - 1) {
					if (arr[i] != -1 && arr[i - 1] == -1) {
						map.put(arr[i], 1);
					}
					continue;
				}
				if ((arr[i - 1] == -1 || arr[i + 1] == -1) && arr[i] != -1) {
					map.put(arr[i], 1);
				}
			}
			int sum = 0;
			int max = 0;
			if (map.size() == 0) {
				for (int i = 1; i < n; i++) {
					int temp = Math.abs(arr[i] - arr[i - 1]);
					max = Math.max(temp, max);
				}
				p.println(max + " " + "0");
				continue;
			}
			sum = (map.firstKey() + map.lastKey());
			int rep = (int) Math.ceil((double) sum / 2);
			int rep2 = (int) Math.floor((double) sum / 2);
			for (int i = 0; i < n; i++) {
				if (arr[i] == -1) {
					arr[i] = rep;
				}
			}
			int max2 = 0;
			for (int i = 1; i < n; i++) {
				int temp = Math.abs(arr[i] - arr[i - 1]);
				max = Math.max(temp, max);
			}
			for (int i = 0; i < n; i++) {
				if (arr2[i] == -1) {
					arr2[i] = rep2;
				}
			}
			for (int i = 1; i < n; i++) {
				int temp = Math.abs(arr2[i] - arr2[i - 1]);
				max2 = Math.max(temp, max2);
			}
			if (max < max2)
				p.println(max + " " + rep);
			else
				p.println(max2 + " " + rep2);
		}
		p.flush();
		p.close();
	}

	public static int onesComplement(int n) {
		int number_of_bits = (int) (Math.floor(Math.log(n) / Math.log(2))) + 1;
		return ((1 << number_of_bits) - 1) ^ n;
	}

	static class Pair<T, V> {
		T first; // maximum distance Node
		V second; // distance of maximum distance node

		// Constructor
		Pair(T first, V second) {
			this.first = first;
			this.second = second;
		}
	}

	public static ArrayList Divisors(long n) {
		ArrayList<Long> div = new ArrayList<>();

		for (long i = 1; i <= Math.sqrt(n); i++) {
			if (n % i == 0) {
				div.add(i);

				if (n / i != i)
					div.add(n / i);
			}
		}
		return div;
	}

	public static int BinarySearch(long[] a, long k) {
		int n = a.length;
		int i = 0, j = n - 1;
		int mid = 0;

		if (k < a[0])
			return 0;
		else if (k >= a[n - 1])
			return n;
		else {
			while (j - i > 1) {
				mid = (i + j) / 2;

				if (k >= a[mid])
					i = mid;
				else
					j = mid;
			}
		}

		return i + 1;
	}

	public static long GCD(long a, long b) {
		if (b == 0)
			return a;
		else
			return GCD(b, a % b);
	}

	public static long LCM(long a, long b) {
		return (a * b) / GCD(a, b);
	}

	static class InputReader {

		private final InputStream stream;
		private final byte[] buf = new byte[8192];
		private int curChar, snumChars;
		private SpaceCharFilter filter;

		public InputReader(InputStream stream) {
			this.stream = stream;
		}

		public int snext() {
			if (snumChars == -1)
				throw new InputMismatchException();
			if (curChar >= snumChars) {
				curChar = 0;
				try {
					snumChars = stream.read(buf);
				} catch (IOException e) {
					throw new InputMismatchException();
				}
				if (snumChars <= 0)
					return -1;
			}
			return buf[curChar++];
		}

		public int nextInt() {
			int c = snext();
			while (isSpaceChar(c)) {
				c = snext();
			}
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = snext();
			}
			int res = 0;
			do {
				if (c < '0' || c > '9')
					throw new InputMismatchException();
				res *= 10;
				res += c - '0';
				c = snext();
			} while (!isSpaceChar(c));
			return res * sgn;
		}

		public long nextLong() {
			int c = snext();
			while (isSpaceChar(c)) {
				c = snext();
			}
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = snext();
			}
			long res = 0;
			do {
				if (c < '0' || c > '9')
					throw new InputMismatchException();
				res *= 10;
				res += c - '0';
				c = snext();
			} while (!isSpaceChar(c));
			return res * sgn;
		}

		public int[] nextIntArray(int n) {
			int a[] = new int[n];
			for (int i = 0; i < n; i++) {
				a[i] = nextInt();
			}
			return a;
		}

		public String readString() {
			int c = snext();
			while (isSpaceChar(c)) {
				c = snext();
			}
			StringBuilder res = new StringBuilder();
			do {
				res.appendCodePoint(c);
				c = snext();
			} while (!isSpaceChar(c));
			return res.toString();
		}

		public String nextLine() {
			int c = snext();
			while (isSpaceChar(c))
				c = snext();
			StringBuilder res = new StringBuilder();
			do {
				res.appendCodePoint(c);
				c = snext();
			} while (!isEndOfLine(c));
			return res.toString();
		}

		public boolean isSpaceChar(int c) {
			if (filter != null)
				return filter.isSpaceChar(c);
			return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
		}

		private boolean isEndOfLine(int c) {
			return c == '\n' || c == '\r' || c == -1;
		}

		public interface SpaceCharFilter {
			public boolean isSpaceChar(int ch);
		}
	}

	static class CodeX {
		public static void sort(long arr[]) {
			merge_sort(arr, 0, arr.length - 1);
		}

		private static void merge_sort(long A[], long start, long end) {
			if (start < end) {
				long mid = (start + end) / 2;
				merge_sort(A, start, mid);
				merge_sort(A, mid + 1, end);
				merge(A, start, mid, end);
			}

		}

		private static void merge(long A[], long start, long mid, long end) {
			long p = start, q = mid + 1;
			long Arr[] = new long[(int) (end - start + 1)];
			long k = 0;

			for (int i = (int) start; i <= end; i++) {
				if (p > mid)
					Arr[(int) k++] = A[(int) q++];

				else if (q > end)
					Arr[(int) k++] = A[(int) p++];

				else if (A[(int) p] < A[(int) q])
					Arr[(int) k++] = A[(int) p++];

				else
					Arr[(int) k++] = A[(int) q++];
			}
			for (int i = 0; i < k; i++) {
				A[(int) start++] = Arr[i];
			}

		}

	}

}