Polycarp often uses his smartphone. He has already installed n applications on it. Application with number i takes up a_i units of memory.

Polycarp wants to free at least m units of memory (by removing some applications).

Of course, some applications are more important to Polycarp than others. He came up with the following scoring system — he assigned an integer b_i to each application: 

  * b_i = 1 — regular application; 
  * b_i = 2 — important application. 



According to this rating system, his phone has b_1 + b_2 + … + b_n convenience points.

Polycarp believes that if he removes applications with numbers i_1, i_2, …, i_k, then he will free a_{i_1} + a_{i_2} + … + a_{i_k} units of memory and lose b_{i_1} + b_{i_2} + … + b_{i_k} convenience points.

For example, if n=5, m=7, a=[5, 3, 2, 1, 4], b=[2, 1, 1, 2, 1], then Polycarp can uninstall the following application sets (not all options are listed below): 

  * applications with numbers 1, 4 and 5. In this case, it will free a_1+a_4+a_5=10 units of memory and lose b_1+b_4+b_5=5 convenience points; 
  * applications with numbers 1 and 3. In this case, it will free a_1+a_3=7 units of memory and lose b_1+b_3=3 convenience points. 
  * applications with numbers 2 and 5. In this case, it will free a_2+a_5=7 memory units and lose b_2+b_5=2 convenience points. 



Help Polycarp, choose a set of applications, such that if removing them will free at least m units of memory and lose the minimum number of convenience points, or indicate that such a set does not exist.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The first line of each test case contains two integers n and m (1 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 10^9) — the number of applications on Polycarp's phone and the number of memory units to be freed.

The second line of each test case contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^9) — the number of memory units used by applications.

The third line of each test case contains n integers b_1, b_2, …, b_n (1 ≤ b_i ≤ 2) — the convenience points of each application.

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.

Output

For each test case, output on a separate line: 

  * -1, if there is no set of applications, removing which will free at least m units of memory; 
  * the minimum number of convenience points that Polycarp will lose if such a set exists. 

Example

Input


5
5 7
5 3 2 1 4
2 1 1 2 1
1 3
2
1
5 10
2 3 2 3 2
1 2 1 2 1
4 10
5 1 3 4
1 2 1 2
4 5
3 2 1 2
2 1 2 1


Output


2
-1
6
4
3

Note

In the first test case, it is optimal to remove applications with numbers 2 and 5, freeing 7 units of memory. b_2+b_5=2.

In the second test case, by removing the only application, Polycarp will be able to clear only 2 of memory units out of the 3 needed.

In the third test case, it is optimal to remove applications with numbers 1, 2, 3 and 4, freeing 10 units of memory. b_1+b_2+b_3+b_4=6.

In the fourth test case, it is optimal to remove applications with numbers 1, 3 and 4, freeing 12 units of memory. b_1+b_3+b_4=4.

In the fifth test case, it is optimal to remove applications with numbers 1 and 2, freeing 5 units of memory. b_1+b_2=3.
import java.io.*;
import java.math.*;
import java.util.*;

// author : Multi-Thread

public class A {
	static int mod = (int) 1e9 + 7;

	public static void main(String[] args) {
		int test = fs.nextInt();
//		int test = 1;
		for (int cases = 0; cases < test; cases++) {
//			solve();
			System.out.println(solve());
		}
	}

	static long solve() {
		int n = fs.nextInt(), k = fs.nextInt();
		ArrayList<Integer> withOne = new ArrayList<Integer>();
		ArrayList<Integer> withTwo = new ArrayList<Integer>();
		Pair ar[] = new Pair[n];
		for (int i = 0; i < n; i++) {
			ar[i] = new Pair(-1, -1);
			ar[i].first = fs.nextInt();
		}
		for (int i = 0; i < n; i++) {
			ar[i].second = fs.nextInt();
			if (ar[i].second == 1) {
				withOne.add(ar[i].first);
			} else {
				withTwo.add(ar[i].first);
			}
		}
		Collections.sort(withOne, Collections.reverseOrder());
		Collections.sort(withTwo);
//		System.out.println(withOne);
//		System.out.println(withTwo);
		int start = 0, end = 0, A = 0, B = 0, cp = 0, ans = Integer.MAX_VALUE;
		if (withOne.isEmpty()) {
			int counter = 0;
			for (int i = withTwo.size() - 1; i >= 0; i--) {
				counter += 2;
				B += withTwo.get(i);
				if (B >= k) {
					break;
				}
			}
			if (B >= k) {
				ans = Integer.min(ans, counter);
			}
		} else {
			for (int i = 0; i < withOne.size(); i++) {
				A += withOne.get(i);
				int counter = i + 1;
				B = 0;
				int reqd = k - A;
				if (reqd > 0) {
					int z = Collections.binarySearch(withTwo, reqd);
					if (z < 0)
						z = ~z;
					if (z >= withTwo.size()) {
						z = withTwo.size() - 1;
					}
					B = 0;
//					System.out.println("IT1-->" + A + " " + B + " " + reqd + " " + z);
					while (z >= 0 && A + B < k) {
						counter += 2;
						B += withTwo.get(z);
						--z;
					}
//					System.out.println("IT2-->" + A + " " + B + " " + reqd + " " + z + " " + counter);
				}
				if (A + B >= k) {
					ans = Integer.min(ans, counter);
				}
			}
		}
		return ans == Integer.MAX_VALUE ? -1 : ans;
	}

	static void intSort(int[] a, boolean reverse) {
		ArrayList<Integer> al = new ArrayList<Integer>();
		for (int i : a)
			al.add(i);
		Collections.sort(al);
		if (reverse) {
			for (int i = 0; i < a.length; i++)
				a[i] = al.get(a.length - i - 1);
		} else {
			for (int i = 0; i < a.length; i++)
				a[i] = al.get(i);
		}
	}

	static void longSort(long[] a, boolean reverse) {
		ArrayList<Long> al = new ArrayList<>();
		for (long i : al)
			al.add(i);
		Collections.sort(al);
		if (reverse) {
			for (int i = 0; i < a.length; i++)
				a[i] = al.get(a.length - i - 1);
		} else {
			for (int i = 0; i < a.length; i++)
				a[i] = al.get(i);
		}
	}

	public static int[] radixSort(int[] f) {
		return radixSort(f, f.length);
	}

	public static int[] radixSort(int[] f, int n) {
		int[] to = new int[n];
		{
			int[] b = new int[65537];
			for (int i = 0; i < n; i++)
				b[1 + (f[i] & 0xffff)]++;
			for (int i = 1; i <= 65536; i++)
				b[i] += b[i - 1];
			for (int i = 0; i < n; i++)
				to[b[f[i] & 0xffff]++] = f[i];
			int[] d = f;
			f = to;
			to = d;
		}
		{
			int[] b = new int[65537];
			for (int i = 0; i < n; i++)
				b[1 + (f[i] >>> 16)]++;
			for (int i = 1; i <= 65536; i++)
				b[i] += b[i - 1];
			for (int i = 0; i < n; i++)
				to[b[f[i] >>> 16]++] = f[i];
			int[] d = f;
			f = to;
			to = d;
		}
		return f;
	}

	static class Pair {
		int first, second;

		public Pair(int first, int second) {
			this.first = first;
			this.second = second;
		}

		public String toString() {
			return "[" + first + "," + second + "]";
		}
	}

	static class LongPair {
		long first;
		long second;

		LongPair(long a, long b) {
			this.first = a;
			this.second = b;
		}

		public String toString() {
			return "[" + first + "," + second + "]";
		}
	}

	static boolean isPrime(long n) {
		// Corner cases
		if (n <= 1)
			return false;
		if (n <= 3)
			return true;
		if (n % 2 == 0 || n % 3 == 0)
			return false;

		long sq = (long) Math.sqrt(n);
		for (int i = 5; i <= sq; i = i + 6)
			if (n % i == 0 || n % (i + 2) == 0)
				return false;

		return true;
	}

	static class FastReader {
		BufferedReader br;
		StringTokenizer st;

		public FastReader() {
			br = new BufferedReader(new InputStreamReader(System.in));
		}

		String next() {
			while (st == null || !st.hasMoreElements()) {
				try {
					st = new StringTokenizer(br.readLine());
				} catch (IOException e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}

		int nextInt() {
			return Integer.parseInt(next());
		}

		long nextLong() {
			return Long.parseLong(next());
		}

		double nextDouble() {
			return Double.parseDouble(next());
		}

		String nextLine() {
			String str = "";
			try {
				str = br.readLine();
			} catch (IOException e) {
				e.printStackTrace();
			}
			return str;
		}
	}

	static class OutputWriter {
		private final PrintWriter writer;

		public OutputWriter(OutputStream outputStream) {
			writer = new PrintWriter(new BufferedWriter(new OutputStreamWriter(outputStream)));
		}

		public OutputWriter(Writer writer) {
			this.writer = new PrintWriter(writer);
		}

		public void print(Object... objects) {
			for (int i = 0; i < objects.length; i++) {
				if (i != 0)
					writer.print(' ');
				writer.print(objects[i]);
			}
		}

		public void println() {
			writer.print("\n");
		}

		public void printLine(Object... objects) {
			print(objects);
			writer.println();
		}

		public void close() {
			writer.close();
		}

		public void flush() {
			writer.flush();
		}

	}

	private static final FastReader fs = new FastReader();
	private static final OutputWriter out = new OutputWriter(System.out);
}