Hilbert's Hotel is a very unusual hotel since the number of rooms is infinite! In fact, there is exactly one room for every integer, including zero and negative integers. Even stranger, the hotel is currently at full capacity, meaning there is exactly one guest in every room. The hotel's manager, David Hilbert himself, decides he wants to shuffle the guests around because he thinks this will create a vacancy (a room without a guest).

For any integer k and positive integer n, let kmod n denote the remainder when k is divided by n. More formally, r=kmod n is the smallest non-negative integer such that k-r is divisible by n. It always holds that 0≤ kmod n≤ n-1. For example, 100mod 12=4 and (-1337)mod 3=1.

Then the shuffling works as follows. There is an array of n integers a_0,a_1,…,a_{n-1}. Then for each integer k, the guest in room k is moved to room number k+a_{kmod n}.

After this shuffling process, determine if there is still exactly one guest assigned to each room. That is, there are no vacancies or rooms with multiple guests.

Input

Each test consists of multiple test cases. The first line contains a single integer t (1≤ t≤ 10^4) — the number of test cases. Next 2t lines contain descriptions of test cases.

The first line of each test case contains a single integer n (1≤ n≤ 2⋅ 10^5) — the length of the array.

The second line of each test case contains n integers a_0,a_1,…,a_{n-1} (-10^9≤ a_i≤ 10^9).

It is guaranteed that the sum of n over all test cases does not exceed 2⋅ 10^5.

Output

For each test case, output a single line containing "YES" if there is exactly one guest assigned to each room after the shuffling process, or "NO" otherwise. You can print each letter in any case (upper or lower).

Example

Input


6
1
14
2
1 -1
4
5 5 5 1
3
3 2 1
2
0 1
5
-239 -2 -100 -3 -11


Output


YES
YES
YES
NO
NO
YES

Note

In the first test case, every guest is shifted by 14 rooms, so the assignment is still unique.

In the second test case, even guests move to the right by 1 room, and odd guests move to the left by 1 room. We can show that the assignment is still unique.

In the third test case, every fourth guest moves to the right by 1 room, and the other guests move to the right by 5 rooms. We can show that the assignment is still unique.

In the fourth test case, guests 0 and 1 are both assigned to room 3.

In the fifth test case, guests 1 and 2 are both assigned to room 2.
/*
Some say the world will end in fire,
Some say in ice.
From what I've tasted of desire
I hold with those who favor fire.
But if it had to perish twice,
I think I know enough of hate
To say that for destruction ice
Is also great
And would suffice.
*/
import java.io.*;
import java.util.*;
 
public final class Main{
    
    static class DSU{
        int[] parent;
        int[] size;
        DSU(int n){
            parent = new int[n + 1];
            size = new int[n + 1];
            for(int i = 0; i <= n; i++){
                parent[i] = i;
                size[i] = 1;
            }
        }
        int getRoot(int i){
            while(i != parent[i]){
                parent[i] = parent[parent[i]];
                i = parent[i];
            }
            return i;
        }
        boolean find(int i, int j){
            return (getRoot(i) == getRoot(j)) ? true : false;
        }
        void union(int i, int j){
            if(find(i, j))  return;
            int rooti = getRoot(i);
            int rootj = getRoot(j);
            if(size[rooti] > size[rootj]){
                parent[rootj] = rooti;
                size[rooti] += size[rootj];
            }
            else{
                parent[rooti] = rootj;
                size[rootj] += size[rooti];
            }
        }
    }
    
    public static final long MOD = 1000000007;
    public static final int limit = 200005;
    
    public static void main(String[] args) {
        InputReader in = new InputReader(System.in);
        PrintWriter w = new PrintWriter(System.out);
 
        int t = in.nextInt();
        //int t=1;
        while (t-- > 0) {
            int n = in.nextInt();
            long[] A = new long[n];
            for(int i = 0; i < n; i++){
                A[i] = in.nextLong();
            }
            
            boolean[] isPresent = new boolean[n];
            for(int i = 0; i < n; i++){
                long index = (A[i] + i) % n;
                if(index < 0)   index += n;
                isPresent[ (int) index] = true;
            }
            
            boolean isValid = true;
            for(int i = 0; i < n; i++){
                if(!isPresent[i]){
                    isValid = false;
                    break;
                }
            }
            w.println( (isValid)? "YES" : "NO");
        }
        w.close();
    }
    
    static class InputReader {
 
        private final InputStream stream;
        private final byte[] buf = new byte[8192];
        private int curChar, snumChars;
        private SpaceCharFilter filter;
 
        public InputReader(InputStream stream) {
            this.stream = stream;
        }
 
        public int snext() {
            if (snumChars == -1)
                throw new InputMismatchException();
            if (curChar >= snumChars) {
                curChar = 0;
                try {
                    snumChars = stream.read(buf);
                } catch (IOException e) {
                    throw new InputMismatchException();
                }
                if (snumChars <= 0)
                    return -1;
            }
            return buf[curChar++];
        }
 
        public int nextInt() {
            int c = snext();
            while (isSpaceChar(c)) {
                c = snext();
            }
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = snext();
            }
            int res = 0;
            do {
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = snext();
            } while (!isSpaceChar(c));
            return res * sgn;
        }
 
        public long nextLong() {
            int c = snext();
            while (isSpaceChar(c)) {
                c = snext();
            }
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = snext();
            }
            long res = 0;
            do {
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = snext();
            } while (!isSpaceChar(c));
            return res * sgn;
        }
 
        public int[] nextIntArray(int n) {
            int a[] = new int[n];
            for (int i = 0; i < n; i++) {
                a[i] = nextInt();
            }
            return a;
        }
 
        public String readString() {
            int c = snext();
            while (isSpaceChar(c)) {
                c = snext();
            }
            StringBuilder res = new StringBuilder();
            do {
                res.appendCodePoint(c);
                c = snext();
            } while (!isSpaceChar(c));
            return res.toString();
        }
 
        public String nextLine() {
            int c = snext();
            while (isSpaceChar(c))
                c = snext();
            StringBuilder res = new StringBuilder();
            do {
                res.appendCodePoint(c);
                c = snext();
            } while (!isEndOfLine(c));
            return res.toString();
        }
 
        public boolean isSpaceChar(int c) {
            if (filter != null)
                return filter.isSpaceChar(c);
            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }
 
        private boolean isEndOfLine(int c) {
            return c == '\n' || c == '\r' || c == -1;
        }
 
        public interface SpaceCharFilter {
            public boolean isSpaceChar(int ch);
        }
    }
}