Utkarsh is forced to play yet another one of Ashish's games. The game progresses turn by turn and as usual, Ashish moves first.

Consider the 2D plane. There is a token which is initially at (0,0). In one move a player must increase either the x coordinate or the y coordinate of the token by exactly k. In doing so, the player must ensure that the token stays within a (Euclidean) distance d from (0,0).

In other words, if after a move the coordinates of the token are (p,q), then p^2 + q^2 ≤ d^2 must hold.

The game ends when a player is unable to make a move. It can be shown that the game will end in a finite number of moves. If both players play optimally, determine who will win.

Input

The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases.

The only line of each test case contains two space separated integers d (1 ≤ d ≤ 10^5) and k (1 ≤ k ≤ d).

Output

For each test case, if Ashish wins the game, print "Ashish", otherwise print "Utkarsh" (without the quotes).

Example

Input


5
2 1
5 2
10 3
25 4
15441 33


Output


Utkarsh
Ashish
Utkarsh
Utkarsh
Ashish

Note

In the first test case, one possible sequence of moves can be

(0, 0) \xrightarrow{Ashish } (0, 1) \xrightarrow{Utkarsh } (0, 2).

Ashish has no moves left, so Utkarsh wins.

<image>
import sys 
import time
start_time = time.time()
input = sys.stdin.readline
from collections import defaultdict
from collections import Counter
# sys.setrecursionlimit(10**5)
from itertools import permutations


for _ in range(int(input())):
	d, k = map(int, input().split())
	low = 0
	high = 10**5
	d = d * d
	ans = 0
	while low + 1 < high:
		mid = low + (high - low) // 2;
		check = mid * k * mid * k
		if check <= d:
			low = mid
			echo = low * low  * low * low
			low1 = 0
			high1 = 10**5
			while low1 + 1 < high1:
				mid = low1 + (high1 - low1 ) // 2;
				value = mid * k * mid * k
				check1 = echo + value
				if check1 <= d:
					low1 = mid
				else:
					high1 = mid

			need = low  + low1
			ans = max(need, ans)
				
		else:
			high = mid


	
	# print(ans)
	if ans % 2 == 0:
		print("Utkarsh")
	else:
		print("Ashish")
print('Execution time : {0:.9f} seconds'.format(time.time()-start_time), file = sys.stderr)

