Utkarsh is forced to play yet another one of Ashish's games. The game progresses turn by turn and as usual, Ashish moves first.

Consider the 2D plane. There is a token which is initially at (0,0). In one move a player must increase either the x coordinate or the y coordinate of the token by exactly k. In doing so, the player must ensure that the token stays within a (Euclidean) distance d from (0,0).

In other words, if after a move the coordinates of the token are (p,q), then p^2 + q^2 ≤ d^2 must hold.

The game ends when a player is unable to make a move. It can be shown that the game will end in a finite number of moves. If both players play optimally, determine who will win.

Input

The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases.

The only line of each test case contains two space separated integers d (1 ≤ d ≤ 10^5) and k (1 ≤ k ≤ d).

Output

For each test case, if Ashish wins the game, print "Ashish", otherwise print "Utkarsh" (without the quotes).

Example

Input


5
2 1
5 2
10 3
25 4
15441 33


Output


Utkarsh
Ashish
Utkarsh
Utkarsh
Ashish

Note

In the first test case, one possible sequence of moves can be

(0, 0) \xrightarrow{Ashish } (0, 1) \xrightarrow{Utkarsh } (0, 2).

Ashish has no moves left, so Utkarsh wins.

<image>
#include <bits/stdc++.h>
#define ll long long int
#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL);
#define pb push_back 
#define mp make_pair
#define ff first
#define ss second
#define pii pair<int,int> 
#define pll pair<ll,ll> 
#define vi vector<int> 
#define endl '\n'
#define vll vector<ll> 
#define MAX 1000000

using namespace std;

int main() 
{
	// your code goes here
	fastio ;
	int t ; 
	cin>>t ; 
	while(t--)
	{
	    ll d,k ; 
	    cin>>d>>k ; 
	    ll state =1  ; 
	    ll x = 0 ; 
	    ll y = 0  ; 
	    while(x*x + y*y <= d*d)
	    {
	        if(x<y)
	        {
	            x = x + k  ; 
	        }
	        else
	        {
	            y = y + k ; 
	        }
	        state = 1-state ; 
	    }
	    if(state == 0)
	    {
	        cout<<"Utkarsh"<<endl; 
	    }
	    else
	    {
	        cout<<"Ashish"<<endl;
	    }
	    
	}
	
	
	return 0;
}