Polycarp often uses his smartphone. He has already installed n applications on it. Application with number i takes up a_i units of memory.

Polycarp wants to free at least m units of memory (by removing some applications).

Of course, some applications are more important to Polycarp than others. He came up with the following scoring system — he assigned an integer b_i to each application: 

  * b_i = 1 — regular application; 
  * b_i = 2 — important application. 



According to this rating system, his phone has b_1 + b_2 + … + b_n convenience points.

Polycarp believes that if he removes applications with numbers i_1, i_2, …, i_k, then he will free a_{i_1} + a_{i_2} + … + a_{i_k} units of memory and lose b_{i_1} + b_{i_2} + … + b_{i_k} convenience points.

For example, if n=5, m=7, a=[5, 3, 2, 1, 4], b=[2, 1, 1, 2, 1], then Polycarp can uninstall the following application sets (not all options are listed below): 

  * applications with numbers 1, 4 and 5. In this case, it will free a_1+a_4+a_5=10 units of memory and lose b_1+b_4+b_5=5 convenience points; 
  * applications with numbers 1 and 3. In this case, it will free a_1+a_3=7 units of memory and lose b_1+b_3=3 convenience points. 
  * applications with numbers 2 and 5. In this case, it will free a_2+a_5=7 memory units and lose b_2+b_5=2 convenience points. 



Help Polycarp, choose a set of applications, such that if removing them will free at least m units of memory and lose the minimum number of convenience points, or indicate that such a set does not exist.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

The first line of each test case contains two integers n and m (1 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 10^9) — the number of applications on Polycarp's phone and the number of memory units to be freed.

The second line of each test case contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^9) — the number of memory units used by applications.

The third line of each test case contains n integers b_1, b_2, …, b_n (1 ≤ b_i ≤ 2) — the convenience points of each application.

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.

Output

For each test case, output on a separate line: 

  * -1, if there is no set of applications, removing which will free at least m units of memory; 
  * the minimum number of convenience points that Polycarp will lose if such a set exists. 

Example

Input


5
5 7
5 3 2 1 4
2 1 1 2 1
1 3
2
1
5 10
2 3 2 3 2
1 2 1 2 1
4 10
5 1 3 4
1 2 1 2
4 5
3 2 1 2
2 1 2 1


Output


2
-1
6
4
3

Note

In the first test case, it is optimal to remove applications with numbers 2 and 5, freeing 7 units of memory. b_2+b_5=2.

In the second test case, by removing the only application, Polycarp will be able to clear only 2 of memory units out of the 3 needed.

In the third test case, it is optimal to remove applications with numbers 1, 2, 3 and 4, freeing 10 units of memory. b_1+b_2+b_3+b_4=6.

In the fourth test case, it is optimal to remove applications with numbers 1, 3 and 4, freeing 12 units of memory. b_1+b_3+b_4=4.

In the fifth test case, it is optimal to remove applications with numbers 1 and 2, freeing 5 units of memory. b_1+b_2=3.

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;

public class experiment
{
    static long M = 1000000009;
    static int INF = Integer.MAX_VALUE;
    static int[] a;
    static int[] b;
    static final FastScanner fs = new FastScanner();
    public static void main(String[] args) throws IOException
    {
        int T = fs.nextInt();

        while(T-->0) {
            int n = fs.nextInt();
            int m = fs.nextInt();

            a = fs.arrayIn(n);
            b = fs.arrayIn(n);

            ArrayList<Integer> cost1 = new ArrayList<>();
            ArrayList<Integer> cost2 = new ArrayList<>();

            for(int i=0; i<n; i++) {
                if(b[i] == 1) cost1.add(a[i]);
                else cost2.add(a[i]);
            }
            Collections.sort(cost1);
            Collections.reverse(cost1);
            Collections.sort(cost2);
            Collections.reverse(cost2);

            long ans = Long.MAX_VALUE;
            long totalm = 0;
            int cost = 0,p2=-1,count=0;

            while(p2+1<cost2.size() && totalm<m){
                p2++;
                totalm += cost2.get(p2);
                cost+=2;
            }
            for(int p1=0; p1<cost1.size(); p1++) {

                if(totalm>=m) ans = Math.min(ans,cost);

                totalm += cost1.get(p1);
                cost+=1;

                while(p2>=0 && totalm - cost2.get(p2)>=m) {
                    totalm -= cost2.get(p2);
                    cost-=2;
                    p2--;
                }
            }
            if(totalm>=m) ans = Math.min(ans,cost);

            if(ans == Long.MAX_VALUE) System.out.println(-1);
            else System.out.println(ans);
        }

    }
    static int count(int n , int m){
        if(m<=0) return 0;

        if(n>=0) {
            return Math.min(1+b[n]+count(n-1,m-a[n]),count(n-1,m));
        }
        return 0;
    }
    static long fact (int n) {

        long fact =1;
        for(int i=1; i<=n; i++) {
            fact = (fact*i)%M;
        }
        return fact%M;
    }

    static final Random random = new Random();

    static void ruffleSort(int arr[])
    {
        int n = arr.length;
        for(int i=0; i<n; i++)
        {
            int j = random.nextInt(n),temp = arr[j];
            arr[j] = arr[i];
            arr[i] = temp;
        }
        Arrays.sort(arr);
    }


    public static class Pairs implements Comparable<Pairs>
    {
        int value,index;
        Pairs(int value, int index)
        {
            this.value = value;
            this.index = index;
        }
        public int compareTo(Pairs p)
        {
            return Integer.compare(this.value, p.value);
        }
    }
}
class FastScanner
{
    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    StringTokenizer str = new StringTokenizer("");

    String next() throws IOException
    {
        while(!str.hasMoreTokens())
            str = new StringTokenizer(br.readLine());

        return str.nextToken();
    }

    char nextChar() throws IOException {
        return next().charAt(0);
    }

    int nextInt() throws IOException
    {
        return Integer.parseInt(next());
    }

    float nextfloat() throws IOException
    {
        return Float.parseFloat(next());
    }

    double nextDouble() throws IOException
    {
        return Double.parseDouble(next());
    }
    long nextLong() throws IOException
    {
        return Long.parseLong(next());
    }
    byte nextByte() throws IOException
    {
        return Byte.parseByte(next());
    }
    int [] arrayIn(int n) throws IOException
    {
        int  arr[] = new int[n];
        for(int i=0; i<n; i++)
        {
            arr[i] = nextInt();
        }
        return arr;
    }
}
