Tavas is a cheerleader in the new sports competition named "Pashmaks".

<image>

This competition consists of two part: swimming and then running. People will immediately start running R meters after they finished swimming exactly S meters. A winner is a such person that nobody else finishes running before him/her (there may be more than one winner).

Before the match starts, Tavas knows that there are n competitors registered for the match. Also, he knows that i-th person's swimming speed is si meters per second and his/her running speed is ri meters per second. Unfortunately, he doesn't know the values of R and S, but he knows that they are real numbers greater than 0.

As a cheerleader, Tavas wants to know who to cheer up. So, he wants to know all people that might win. We consider a competitor might win if and only if there are some values of R and S such that with these values, (s)he will be a winner.

Tavas isn't really familiar with programming, so he asked you to help him.

Input

The first line of input contains a single integer n (1 ≤ n ≤ 2 × 105).

The next n lines contain the details of competitors. i-th line contains two integers si and ri (1 ≤ si, ri ≤ 104).

Output

In the first and the only line of output, print a sequence of numbers of possible winners in increasing order.

Examples

Input

3
1 3
2 2
3 1


Output

1 2 3 


Input

3
1 2
1 1
2 1


Output

1 3 
5
10 50
10 50
10 50
10 50
10 50
 2
10000 10000
10000 10000
 3
10000 10000
10000 10000
10000 10000
 3
1000 3000
1500 1500
3000 1000
 43
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 1
1 1
 2
1 1
1 1
 44
78 52
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 3
1000 3000
1499 1499
3000 1000
 5
50 50
49 50
50 49
49 49
50 1
 18
82 38
33 69
33 69
33 69
33 69
33 69
82 38
33 69
33 69
33 69
82 38
33 69
33 69
82 38
82 38
33 69
33 69
33 69
 1
10000 9999
 3
1000 3000
1501 1501
3000 1000
 2
1 2
2 1

1 2 3 4 5
 1 2
 1 2 3
 1 2 3
 1 3 16 24 29 31 32 37 41 42
 1
 1 2
 1
 1 3
 1
 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
 1
 1 2 3
 1 2 

#include <bits/stdc++.h>
using namespace std;
struct Point {
  double x, y;
  int id;
  Point() {}
  Point(double x, double y) {
    this->x = x;
    this->y = y;
  }
  void read(int id) {
    int s, b;
    scanf("%d%d", &s, &b);
    x = 1.0 / s;
    y = 1.0 / b;
    this->id = id;
  }
};
Point operator+(Point A, Point B) { return Point(A.x + B.x, A.y + B.y); }
Point operator-(Point A, Point B) { return Point(A.x - B.x, A.y - B.y); }
Point operator*(Point A, double p) { return Point(A.x * p, A.y * p); }
Point operator/(Point A, double p) { return Point(A.x / p, A.y / p); }
bool operator<(const Point& a, const Point& b) {
  return a.x < b.x || (a.x == b.x && a.y < b.y);
}
const double eps = 1e-8;
int dcmp(double x) {
  if (fabs(x) < eps)
    return 0;
  else
    return x < 0 ? -1 : 1;
}
bool operator==(const Point& a, const Point& b) {
  return dcmp(a.x - b.x) == 0 && dcmp(a.y - b.y) == 0;
}
double Dot(Point A, Point B) { return A.x * B.x + A.y * B.y; }
double Length(Point A) { return sqrt(Dot(A, A)); }
double Angle(Point A, Point B) {
  return acos(Dot(A, B) / Length(A) / Length(B));
}
double Cross(Point A, Point B) { return A.x * B.y - A.y * B.x; }
double Area2(Point A, Point B, Point C) { return Cross(B - A, C - A); }
struct Line {
  Point v, p;
  Line() {}
  Line(Point v, Point p) {
    this->v = v;
    this->p = p;
  }
  Point point(double t) { return v + p * t; }
};
Point Rotate(Point A, double rad) {
  return Point(A.x * cos(rad) - A.y * sin(rad),
               A.x * sin(rad) + A.y * cos(rad));
}
Point AngleBisector(Point p, Point v1, Point v2) {
  double rad = Angle(v1, v2);
  return Rotate(v1, dcmp(Cross(v1, v2)) * 0.5 * rad);
}
bool LineCoincide(Point p1, Point p2, Point p3) {
  return dcmp(Cross(p2 - p1, p3 - p1)) == 0;
}
bool LineParallel(Point v, Point w) { return Cross(v, w) == 0; }
bool LineVertical(Point v, Point w) { return Dot(v, w) == 0; }
Point GetLineIntersection(Point P, Point v, Point Q, Point w) {
  Point u = P - Q;
  double t = Cross(w, u) / Cross(v, w);
  return P + v * t;
}
double DistanceToLine(Point P, Point A, Point B) {
  Point v1 = B - A, v2 = P - A;
  return fabs(Cross(v1, v2)) / Length(v1);
}
double DistanceToSegment(Point P, Point A, Point B) {
  if (A == B) return Length(P - A);
  Point v1 = B - A, v2 = P - A, v3 = P - B;
  if (dcmp(Dot(v1, v2)) < 0)
    return Length(v2);
  else if (dcmp(Dot(v1, v3)) > 0)
    return Length(v3);
  else
    return fabs(Cross(v1, v2)) / Length(v1);
}
Point GetLineProjection(Point P, Point A, Point B) {
  Point v = B - A;
  return A + v * (Dot(v, P - A) / Dot(v, v));
}
bool SegmentProperIntersection(Point a1, Point a2, Point b1, Point b2) {
  double c1 = Cross(a2 - a1, b1 - a1), c2 = Cross(a2 - a1, b2 - a1),
         c3 = Cross(b2 - b1, a1 - b1), c4 = Cross(b2 - b1, a2 - b1);
  return dcmp(c1) * dcmp(c2) < 0 && dcmp(c3) * dcmp(c4) < 0;
}
bool SegmentProperIntersection2(Point a1, Point a2, Point b1, Point b2) {
  double c1 = Cross(a2 - a1, b1 - a1), c2 = Cross(a2 - a1, b2 - a1),
         c3 = Cross(b2 - b1, a1 - b1), c4 = Cross(b2 - b1, a2 - b1);
  return max(a1.x, a2.x) >= min(b1.x, b2.x) &&
         max(b1.x, b2.x) >= min(a1.x, a2.x) &&
         max(a1.y, a2.y) >= min(b1.y, b2.y) &&
         max(b1.y, b2.y) >= min(a1.y, a2.y) && dcmp(c1) * dcmp(c2) <= 0 &&
         dcmp(c3) * dcmp(c4) <= 0;
}
bool OnSegment(Point p, Point a1, Point a2) {
  return dcmp(Cross(a1 - p, a2 - p)) == 0 && dcmp(Dot(a1 - p, a2 - p)) < 0;
}
double PolygonArea(Point* p, int n) {
  double area = 0;
  for (int i = 1; i < n - 1; i++) area += Cross(p[i] - p[0], p[i + 1] - p[0]);
  return area / 2;
}
int isPointInPolygon(Point o, Point* p, int n) {
  int wn = 0;
  for (int i = 0; i < n; i++) {
    if (OnSegment(o, p[i], p[(i + 1) % n])) return -1;
    int k = dcmp(Cross(p[(i + 1) % n] - p[i], o - p[i]));
    int d1 = dcmp(p[i].y - o.y);
    int d2 = dcmp(p[(i + 1) % n].y - o.y);
    if (k > 0 && d1 <= 0 && d2 > 0) wn++;
    if (k < 0 && d2 <= 0 && d1 > 0) wn--;
  }
  if (wn != 0) return 1;
  return 0;
}
int ConvexHull(Point* p, int n, Point* ch) {
  sort(p, p + n);
  int m = 0;
  for (int i = 0; i < n; i++) {
    while (m > 1 && Cross(ch[m - 1] - ch[m - 2], p[i] - ch[m - 2]) < 0) m--;
    ch[m++] = p[i];
  }
  int k = m;
  for (int i = n - 2; i >= 0; i--) {
    while (m > k && Cross(ch[m - 1] - ch[m - 2], p[i] - ch[m - 2]) < 0) m--;
    ch[m++] = p[i];
  }
  if (n > 1) m--;
  return m;
}
const int N = 200005;
int n;
Point p[N], ch[N];
bool cmpx(Point a, Point b) {
  if (dcmp(a.x - b.x) == 0) return a.y > b.y;
  return a.x < b.x;
}
bool cmpy(Point a, Point b) {
  if (dcmp(a.y - b.y) == 0) return a.x > b.x;
  return a.y < b.y;
}
int vis[N];
int main() {
  scanf("%d", &n);
  for (int i = 0; i < n; i++) p[i].read(i + 1);
  int m = ConvexHull(p, n, ch);
  sort(ch, ch + m, cmpx);
  Point a[2];
  a[0] = ch[0];
  sort(ch, ch + m, cmpy);
  a[1] = ch[0];
  for (int i = 0; i < n; i++) {
    if (dcmp(Cross(a[0] - ch[i], a[1] - ch[i])) <= 0) vis[ch[i].id] = 1;
  }
  for (int i = 1; i <= n; i++)
    if (vis[i]) printf("%d ", i);
  return 0;
}
