Tavas is a cheerleader in the new sports competition named "Pashmaks".

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This competition consists of two part: swimming and then running. People will immediately start running R meters after they finished swimming exactly S meters. A winner is a such person that nobody else finishes running before him/her (there may be more than one winner).

Before the match starts, Tavas knows that there are n competitors registered for the match. Also, he knows that i-th person's swimming speed is si meters per second and his/her running speed is ri meters per second. Unfortunately, he doesn't know the values of R and S, but he knows that they are real numbers greater than 0.

As a cheerleader, Tavas wants to know who to cheer up. So, he wants to know all people that might win. We consider a competitor might win if and only if there are some values of R and S such that with these values, (s)he will be a winner.

Tavas isn't really familiar with programming, so he asked you to help him.

Input

The first line of input contains a single integer n (1 ≤ n ≤ 2 × 105).

The next n lines contain the details of competitors. i-th line contains two integers si and ri (1 ≤ si, ri ≤ 104).

Output

In the first and the only line of output, print a sequence of numbers of possible winners in increasing order.

Examples

Input

3
1 3
2 2
3 1


Output

1 2 3 


Input

3
1 2
1 1
2 1


Output

1 3 
5
10 50
10 50
10 50
10 50
10 50
 2
10000 10000
10000 10000
 3
10000 10000
10000 10000
10000 10000
 3
1000 3000
1500 1500
3000 1000
 43
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 1
1 1
 2
1 1
1 1
 44
78 52
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 3
1000 3000
1499 1499
3000 1000
 5
50 50
49 50
50 49
49 49
50 1
 18
82 38
33 69
33 69
33 69
33 69
33 69
82 38
33 69
33 69
33 69
82 38
33 69
33 69
82 38
82 38
33 69
33 69
33 69
 1
10000 9999
 3
1000 3000
1501 1501
3000 1000
 2
1 2
2 1

1 2 3 4 5
 1 2
 1 2 3
 1 2 3
 1 3 16 24 29 31 32 37 41 42
 1
 1 2
 1
 1 3
 1
 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
 1
 1 2 3
 1 2 

#include <bits/stdc++.h>
using namespace std;
const int INF = 1000000003;
int m;
int n;
int x[200001];
int y[200002];
int p[200002];
int l;
int s[200002];
bool cmp(int i, int j) { return x[i] > x[j] || (x[i] == x[j] && y[i] > y[j]); }
bool cross(int a, int b, int c) {
  long double xa = 1, xb = 1, xc = 1, ya = 1, yb = 1, yc = 1;
  xa /= x[a];
  xb /= x[b];
  xc /= x[c];
  ya /= y[a];
  yb /= y[b];
  yc /= y[c];
  long double ans = (xc - xa) * (yb - ya) - (yc - ya) * (xb - xa);
  if (abs(ans) < 1e-9) return false;
  return ans > 0;
}
int main(int argc, char *argv[]) {
  cin >> n;
  for (int i = 0; i < n; ++i) cin >> x[i] >> y[i];
  for (int i = 0; i < n; ++i) p[i] = i;
  sort(p, p + n, cmp);
  m = 1;
  s[0] = p[0];
  for (int i = 1; i < n; ++i) {
    int j = p[i];
    if (y[j] < y[s[m - 1]]) continue;
    while (m > 1 && cross(s[m - 2], s[m - 1], j)) --m;
    s[m++] = j;
  }
  sort(s, s + m);
  for (int i = 0; i < m; ++i) cout << s[i] + 1 << " ";
  cout << endl;
}
