Tavas is a cheerleader in the new sports competition named "Pashmaks".

<image>

This competition consists of two part: swimming and then running. People will immediately start running R meters after they finished swimming exactly S meters. A winner is a such person that nobody else finishes running before him/her (there may be more than one winner).

Before the match starts, Tavas knows that there are n competitors registered for the match. Also, he knows that i-th person's swimming speed is si meters per second and his/her running speed is ri meters per second. Unfortunately, he doesn't know the values of R and S, but he knows that they are real numbers greater than 0.

As a cheerleader, Tavas wants to know who to cheer up. So, he wants to know all people that might win. We consider a competitor might win if and only if there are some values of R and S such that with these values, (s)he will be a winner.

Tavas isn't really familiar with programming, so he asked you to help him.

Input

The first line of input contains a single integer n (1 ≤ n ≤ 2 × 105).

The next n lines contain the details of competitors. i-th line contains two integers si and ri (1 ≤ si, ri ≤ 104).

Output

In the first and the only line of output, print a sequence of numbers of possible winners in increasing order.

Examples

Input

3
1 3
2 2
3 1


Output

1 2 3 


Input

3
1 2
1 1
2 1


Output

1 3 
5
10 50
10 50
10 50
10 50
10 50
 2
10000 10000
10000 10000
 3
10000 10000
10000 10000
10000 10000
 3
1000 3000
1500 1500
3000 1000
 43
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 1
1 1
 2
1 1
1 1
 44
78 52
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 3
1000 3000
1499 1499
3000 1000
 5
50 50
49 50
50 49
49 49
50 1
 18
82 38
33 69
33 69
33 69
33 69
33 69
82 38
33 69
33 69
33 69
82 38
33 69
33 69
82 38
82 38
33 69
33 69
33 69
 1
10000 9999
 3
1000 3000
1501 1501
3000 1000
 2
1 2
2 1

1 2 3 4 5
 1 2
 1 2 3
 1 2 3
 1 3 16 24 29 31 32 37 41 42
 1
 1 2
 1
 1 3
 1
 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
 1
 1 2 3
 1 2 

#include <bits/stdc++.h>
using namespace std;
const int Maxn = 2e5 + 5;
class pnt {
 public:
  int x, y;
  int id;
  bool operator<(const pnt &o) const {
    return x < o.x || (x == o.x && y < o.y);
  }
};
vector<pnt> hull;
bool check(pnt p1, pnt p2, pnt p3) {
  long long d = (long long)p1.x * p3.y * (p2.y - p1.y) * (p3.x - p2.x) -
                (long long)p3.x * p1.y * (p3.y - p2.y) * (p2.x - p1.x);
  return d < 0;
}
void insert(pnt o) {
  if (hull.size() < 2) {
    hull.push_back(o);
    return;
  }
  int m = hull.size() - 1, l = m - 1;
  while (m) {
    if (check(hull[l], hull[m], o)) {
      hull.pop_back();
      l--;
      m--;
    } else
      break;
  }
  hull.push_back(o);
}
int n;
bool pw[Maxn];
pnt p[Maxn];
int main() {
  scanf("%d", &n);
  for (int i = 1; i <= n; i++) {
    scanf("%d%d", &p[i].x, &p[i].y);
    p[i].id = i;
  }
  sort(p + 1, p + n + 1);
  for (int i = 1; i <= n; i++) insert(p[i]);
  int sz = hull.size(), it = 0;
  while (it + 1 < sz && hull[it + 1].y > hull[it].y) it++;
  memset(pw, false, sizeof pw);
  for (int i = it; i < sz; i++) pw[hull[i].id] = true;
  for (int i = 1; i <= n; i++)
    if (pw[i]) printf("%d ", i);
  return 0;
}
