Lee tried so hard to make a good div.2 D problem to balance his recent contest, but it still doesn't feel good at all. Lee invented it so tediously slow that he managed to develop a phobia about div.2 D problem setting instead. And now he is hiding behind the bushes...

Let's define a Rooted Dead Bush (RDB) of level n as a rooted tree constructed as described below.

A rooted dead bush of level 1 is a single vertex. To construct an RDB of level i we, at first, construct an RDB of level i-1, then for each vertex u: 

  * if u has no children then we will add a single child to it; 
  * if u has one child then we will add two children to it; 
  * if u has more than one child, then we will skip it. 

<image> Rooted Dead Bushes of level 1, 2 and 3.

Let's define a claw as a rooted tree with four vertices: one root vertex (called also as center) with three children. It looks like a claw:

<image> The center of the claw is the vertex with label 1.

Lee has a Rooted Dead Bush of level n. Initially, all vertices of his RDB are green.

In one move, he can choose a claw in his RDB, if all vertices in the claw are green and all vertices of the claw are children of its center, then he colors the claw's vertices in yellow.

He'd like to know the maximum number of yellow vertices he can achieve. Since the answer might be very large, print it modulo 10^9+7.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases.

Next t lines contain test cases — one per line.

The first line of each test case contains one integer n (1 ≤ n ≤ 2 ⋅ 10^6) — the level of Lee's RDB.

Output

For each test case, print a single integer — the maximum number of yellow vertices Lee can make modulo 10^9 + 7.

Example

Input


7
1
2
3
4
5
100
2000000


Output


0
0
4
4
12
990998587
804665184

Note

It's easy to see that the answer for RDB of level 1 or 2 is 0.

The answer for RDB of level 3 is 4 since there is only one claw we can choose: \{1, 2, 3, 4\}.

The answer for RDB of level 4 is 4 since we can choose either single claw \{1, 3, 2, 4\} or single claw \{2, 7, 5, 6\}. There are no other claws in the RDB of level 4 (for example, we can't choose \{2, 1, 7, 6\}, since 1 is not a child of center vertex 2).

<image> Rooted Dead Bush of level 4.
3
1234567
1268501
1268499

788765312
999997375
999999350

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String args[]) throws IOException {
        InOut inout = new InOut();
        Resolver resolver = new Resolver(inout);
        resolver.solve();
        inout.flush();
    }

    private static class Resolver {

        final long LONG_INF = (long) 1e18;
        final int INF = (int) (1e9 + 7);
        final int MOD = 998244353;
        long f[];
        InOut inout;

        Resolver(InOut inout) {
            this.inout = inout;
        }

        void initF(int n) {
            f = new long[n + 1];
            f[1] = 1;
            for (int i = 2; i <= n; i++) {
                f[i] = (f[i - 1] * i) % MOD;
            }
        }

        int d[] = {0, -1, 0, 1, 0};

        boolean legal(int r, int c, int n, int m) {
            return r >= 0 && r < n && c >= 0 && c < m;
        }

        void solve() throws IOException {
            long dp[] = new long[(int) (2e6 + 1)];
            dp[1] = dp[2] = 0;
            dp[3] = 1;
            dp[4] = 1;
            dp[5] = 3;
            dp[6] = 6;
            dp[7] = 12;
            dp[8] = 24;
            dp[9] = 49;
//            long dp2[] = dp.clone();
            for (int i = 10; i <= (int) 2e6; i++) {
                if (i % 3 != 0) {
                    dp[i] = (dp[i - 2] * 2 + dp[i - 1]) % INF;
                } else {
                    dp[i] = (1 + dp[i - 4] * 4 + dp[i - 3] * 4 + dp[i - 2]) % INF;
                }
//                dp2[i] = Math.max(dp2[i - 2] * 2 + dp2[i - 1], 1 + dp2[i - 4] * 4 + dp2[i - 3] * 4 + dp2[i - 2]);
            }
            int tt = 1;
            boolean hvt = true;
            if (hvt) {
                tt = nextInt();
            }
            for (int cs = 1; cs <= tt; cs++) {
                int n = nextInt();
                long rs = 0;
                format("%d", dp[n] * 4 % INF);

//                format("%d", rs);

                if (cs < tt) {
                    format("\n");
                }
//                flush();
            }
        }

        String next(int n) throws IOException {
            return inout.next(n);
        }

        String nextLine() throws IOException {
            return inout.nextLine();
        }

        int nextInt() throws IOException {
            return inout.nextInt();
        }

        long nextLong(int n) throws IOException {
            return inout.nextLong(n);
        }

        long[] anLong(int i, int j, int len) throws IOException {
            long a[] = new long[j + 1];
            for (int k = i; k <= j; k++) {
                a[i] = nextLong(len);
            }
            return a;
        }

        void print(String s, boolean nextLine) {
            inout.print(s, nextLine);
        }

        void format(String format, Object... obj) {
            inout.format(format, obj);
        }

        void flush() {
            inout.flush();
        }

        void swap(int a[], int i, int j) {
            a[i] ^= a[j];
            a[j] ^= a[i];
            a[i] ^= a[j];
        }

        int getP(int x, int p[]) {
            if (p[x] == 0 || p[x] == x) {
                return x;
            }
            return p[x] = getP(p[x], p);
        }

        void union(int x, int y, int p[]) {
            if (x < y) {
                p[y] = x;
            } else {
                p[x] = y;
            }
        }

        boolean topSort() {
            int n = adj.length - 1;
            int d[] = new int[n + 1];
            for (int i = 1; i <= n; i++) {
                for (int j = 0; j < adj[i].size(); j++) {
                    d[adj[i].get(j)[0]]++;
                }
            }
            List<Integer> list = new ArrayList<>();
            for (int i = 1; i <= n; i++) {
                if (d[i] == 0) {
                    list.add(i);
                }
            }
            for (int i = 0; i < list.size(); i++) {
                for (int j = 0; j < adj[list.get(i)].size(); j++) {
                    int t = adj[list.get(i)].get(j)[0];
                    d[t]--;
                    if (d[t] == 0) {
                        list.add(t);
                    }
                }
            }
            return list.size() == n;
        }

        class BinaryIndexedTree {

            int n = 1;
            long C[];

            BinaryIndexedTree(int sz) {
                while (n <= sz) {
                    n <<= 1;
                }
                C = new long[n];
            }

            int lowbit(int x) {
                return x & -x;
            }

            void add(int x, long val) {
                while (x < n) {
                    C[x] += val;
                    x += lowbit(x);
                }
            }

            long getSum(int x) {
                long res = 0;
                while (x > 0) {
                    res += C[x];
                    x -= lowbit(x);
                }
                return res;
            }

            int binSearch(long sum) {
                if (sum == 0) {
                    return 0;
                }
                int n = C.length;
                int mx = 1;
                while (mx < n) {
                    mx <<= 1;
                }
                int res = 0;
                for (int i = mx / 2; i >= 1; i >>= 1) {
                    if (C[res + i] < sum) {
                        sum -= C[res + i];
                        res += i;
                    }
                }
                return res + 1;
            }
        }

        //Binary tree
        class TreeNode {
            int val;
            int tier = -1;
            TreeNode parent;
            TreeNode left;
            TreeNode right;

            TreeNode(int val) {
                this.val = val;
            }
        }

        //binary tree dfs
        void tierTree(TreeNode root) {
            if (null == root) {
                return;
            }
            if (null != root.parent) {
                root.tier = root.parent.tier + 1;
            } else {
                root.tier = 0;
            }
            tierTree(root.left);
            tierTree(root.right);
        }

        //LCA start
        TreeNode[][] lca;
        TreeNode[] tree;

        void lcaDfsTree(TreeNode root) {
            if (null == root) {
                return;
            }
            tree[root.val] = root;
            TreeNode nxt = root.parent;
            int idx = 0;
            while (null != nxt) {
                lca[root.val][idx] = nxt;
                nxt = lca[nxt.val][idx];
                idx++;
            }
            lcaDfsTree(root.left);
            lcaDfsTree(root.right);
        }

        TreeNode lcaTree(TreeNode root, int n, TreeNode x, TreeNode y) throws IOException {
            if (null == root) {
                return null;
            }
            if (-1 == root.tier) {
                tree = new TreeNode[n + 1];
                tierTree(root);
            }
            if (null == lca) {
                lca = new TreeNode[n + 1][31];
                lcaDfsTree(root);
            }
            int z = Math.abs(x.tier - y.tier);
            int xx = x.tier > y.tier ? x.val : y.val;
            while (z > 0) {
                final int zz = z;
                int l = (int) binSearch(0, 31
                        , k -> zz < (1 << k));
                xx = lca[xx][l].val;
                z -= 1 << l;
            }
            int yy = y.val;
            if (x.tier <= y.tier) {
                yy = x.val;
            }
            while (xx != yy) {
                final int xxx = xx;
                final int yyy = yy;
                int l = (int) binSearch(0, 31
                        , k -> (1 << k) <= tree[xxx].tier && lca[xxx][(int) k] != lca[yyy][(int) k]);
                xx = lca[xx][l].val;
                yy = lca[yy][l].val;
            }
            return tree[xx];
        }
        //LCA end

        //graph
        List<int[]> adj[];

        void initGraph(int n, int m, boolean hasW, boolean directed) throws IOException {
            adj = new List[n + 1];
            for (int i = 1; i <= n; i++) {
                adj[i] = new ArrayList<>();
            }
            for (int i = 0; i < m; i++) {
                int f = nextInt();
                int t = nextInt();
                int w = hasW ? nextInt() : 0;
                adj[f].add(new int[]{t, w});
                if (!directed) {
                    adj[t].add(new int[]{f, w});
                }
            }
        }

        long binSearch(long l, long r, BinSearch sort) throws IOException {
            while (l < r) {
                long m = l + (r - l) / 2;
                if (sort.binSearchCmp(m)) {
                    l = m + 1;
                } else {
                    r = m;
                }
            }
            return l;
        }

        void getDiv(Map<Integer, Integer> map, int n) {
            int sqrt = (int) Math.sqrt(n);
            for (int i = sqrt; i >= 2; i--) {
                if (n % i == 0) {
                    getDiv(map, i);
                    getDiv(map, n / i);
                    return;
                }
            }
            map.put(n, map.getOrDefault(n, 0) + 1);
        }

        boolean[] generatePrime(int n) {
            boolean p[] = new boolean[n + 1];
            p[2] = true;

            for (int i = 3; i <= n; i += 2) {
                p[i] = true;
            }

            for (int i = 3; i <= Math.sqrt(n); i += 2) {
                if (!p[i]) {
                    continue;
                }
                for (int j = i * i; j <= n; j += i << 1) {
                    p[j] = false;
                }
            }
            return p;
        }

        boolean isPrime(long n) { //determines if n is a prime number
            int p[] = {2, 3, 5, 233, 331};
            int pn = p.length;
            long s = 0, t = n - 1;//n - 1 = 2^s * t
            while ((t & 1) == 0) {
                t >>= 1;
                ++s;
            }
            for (int i = 0; i < pn; ++i) {
                if (n == p[i]) {
                    return true;
                }
                long pt = pow(p[i], t, n);
                for (int j = 0; j < s; ++j) {
                    long cur = llMod(pt, pt, n);
                    if (cur == 1 && pt != 1 && pt != n - 1) {
                        return false;
                    }
                    pt = cur;
                }
                if (pt != 1) {
                    return false;
                }
            }
            return true;
        }

        long llMod(long a, long b, long mod) {
            return (a * b - (long) ((double) a / mod * b + 0.5) * mod + mod) % mod;
//        long r = 0;
//        a %= mod;
//        b %= mod;
//        while (b > 0) {
//            if ((b & 1) == 1) {
//                r = (r + a) % mod;
//            }
//            b >>= 1;
//            a = (a << 1) % mod;
//        }
//        return r;
        }

        long pow(long a, long n) {
            long ans = 1;
            while (n > 0) {
                if ((n & 1) == 1) {
                    ans = ans * a;
                }
                a = a * a;
                n >>= 1;
            }
            return ans;
        }

        long pow(long a, long n, long mod) {
            long ans = 1;
            while (n > 0) {
                if ((n & 1) == 1) {
                    ans = llMod(ans, a, mod);
                }
                a = llMod(a, a, mod);
                n >>= 1;
            }
            return ans;
        }

        private long[][] initC(int n) {
            long c[][] = new long[n][n];

            for (int i = 0; i < n; i++) {
                c[i][0] = 1;
            }

            for (int i = 1; i < n; i++) {
                for (int j = 1; j <= i; j++) {
                    c[i][j] = c[i - 1][j - 1] + c[i - 1][j];
                }
            }
            return c;
        }

        /**
         * ps: n >= m, choose m from n;
         */
        private int cmn(long n, long m) {
            if (m > n) {
                n ^= m;
                m ^= n;
                n ^= m;
            }
            m = Math.min(m, n - m);

            long top = 1;
            long bot = 1;
            for (long i = n - m + 1; i <= n; i++) {
                top = (top * i) % MOD;
            }
            for (int i = 1; i <= m; i++) {
                bot = (bot * i) % MOD;
            }

            return (int) ((top * pow(bot, MOD - 2, MOD)) % MOD);
        }

        long gcd(long a, long b) {
            if (a < b) {
                return gcd(b, a);
            }
            while (b != 0) {
                long tmp = a % b;
                a = b;
                b = tmp;
            }
            return a;
        }

        boolean isEven(long n) {
            return (n & 1) == 0;
        }

        interface BinSearch {
            boolean binSearchCmp(long k) throws IOException;
        }
    }

    private static class InOut {
        private BufferedReader br;
        private StreamTokenizer st;
        private PrintWriter pw;

        InOut() {
            br = new BufferedReader(new InputStreamReader(System.in));
            st = new StreamTokenizer(br);
            pw = new PrintWriter(new OutputStreamWriter(System.out));
            st.ordinaryChar('\'');
            st.ordinaryChar('\"');
            st.ordinaryChar('/');
        }

        private long[] anLong(int n) throws IOException {
            long a[] = new long[n];
            for (int i = 0; i < n; i++) {
                a[i] = nextInt();
            }
            return a;
        }

        private String next(int len) throws IOException {
            char ch[] = new char[len];
            int cur = 0;
            char c;
            while ((c = (char) br.read()) == '\n' || c == '\r' || c == ' ' || c == '\t') ;
            do {
                ch[cur++] = c;
            } while (!((c = (char) br.read()) == '\n' || c == '\r' || c == ' ' || c == '\t'));
            return String.valueOf(ch, 0, cur);
        }

        private int nextInt() throws IOException {
            st.nextToken();
            return (int) st.nval;
        }

        private long nextLong(int n) throws IOException {
            return Long.parseLong(next(n));
        }

        private double nextDouble() throws IOException {
            st.nextToken();
            return st.nval;
        }

        private String[] nextSS(String reg) throws IOException {
            return br.readLine().split(reg);
        }

        private String nextLine() throws IOException {
            return br.readLine();
        }

        private void print(String s, boolean newLine) {
            if (null != s) {
                pw.print(s);
            }
            if (newLine) {
                pw.println();
            }
        }

        private void format(String format, Object... obj) {
            pw.format(format, obj);
        }

        private void flush() {
            pw.flush();
        }
    }
}