Tavas is a cheerleader in the new sports competition named "Pashmaks".

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This competition consists of two part: swimming and then running. People will immediately start running R meters after they finished swimming exactly S meters. A winner is a such person that nobody else finishes running before him/her (there may be more than one winner).

Before the match starts, Tavas knows that there are n competitors registered for the match. Also, he knows that i-th person's swimming speed is si meters per second and his/her running speed is ri meters per second. Unfortunately, he doesn't know the values of R and S, but he knows that they are real numbers greater than 0.

As a cheerleader, Tavas wants to know who to cheer up. So, he wants to know all people that might win. We consider a competitor might win if and only if there are some values of R and S such that with these values, (s)he will be a winner.

Tavas isn't really familiar with programming, so he asked you to help him.

Input

The first line of input contains a single integer n (1 ≤ n ≤ 2 × 105).

The next n lines contain the details of competitors. i-th line contains two integers si and ri (1 ≤ si, ri ≤ 104).

Output

In the first and the only line of output, print a sequence of numbers of possible winners in increasing order.

Examples

Input

3
1 3
2 2
3 1


Output

1 2 3 


Input

3
1 2
1 1
2 1


Output

1 3 
5
10 50
10 50
10 50
10 50
10 50
 2
10000 10000
10000 10000
 3
10000 10000
10000 10000
10000 10000
 3
1000 3000
1500 1500
3000 1000
 43
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 1
1 1
 2
1 1
1 1
 44
78 52
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 3
1000 3000
1499 1499
3000 1000
 5
50 50
49 50
50 49
49 49
50 1
 18
82 38
33 69
33 69
33 69
33 69
33 69
82 38
33 69
33 69
33 69
82 38
33 69
33 69
82 38
82 38
33 69
33 69
33 69
 1
10000 9999
 3
1000 3000
1501 1501
3000 1000
 2
1 2
2 1

1 2 3 4 5
 1 2
 1 2 3
 1 2 3
 1 3 16 24 29 31 32 37 41 42
 1
 1 2
 1
 1 3
 1
 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
 1
 1 2 3
 1 2 

#include <bits/stdc++.h>
using namespace std;
inline void inp(int &n) {
  n = 0;
  int ch = getchar();
  int sign = 1;
  while (ch < '0' || ch > '9') {
    if (ch == '-') sign = -1;
    ch = getchar();
  }
  while (ch >= '0' && ch <= '9')
    n = (n << 3) + (n << 1) + ch - '0', ch = getchar();
  n = n * sign;
}
long long gcd(long long A, long long B) {
  return A > B ? gcd(B, A) : A ? gcd(B % A, A) : B;
}
long long lcm(long long A, long long B) { return A / gcd(A, B) * B; }
long long pow(long long A, long long B, long long P) {
  if (!B) return 1 % P;
  long long h = pow(A, B / 2, P);
  h *= h;
  h %= P;
  if (B % 2) h *= A;
  return h % P;
}
vector<int> z_function(string s) {
  int n = (int)s.length();
  vector<int> z(n);
  for (int i = 1, l = 0, r = 0; i < n; ++i) {
    if (i <= r) z[i] = min(r - i + 1, z[i - l]);
    while (i + z[i] < n && s[z[i]] == s[i + z[i]]) ++z[i];
    if (i + z[i] - 1 > r) l = i, r = i + z[i] - 1;
  }
  return z;
}
int tst;
void get_ready() { tst = 1; }
pair<pair<int, int>, int> P[262145];
int MX, a, b, n, i, j;
vector<int> ans;
bool READ() {
  cin >> n;
  for (i = 1; i <= n; i++) {
    scanf("%d%d", &a, &b);
    P[i].first = make_pair(a, b);
    P[i].second = i;
  }
  sort(P + 1, P + n + 1);
  reverse(P + 1, P + n + 1);
  for (i = 1; i <= n; i++) {
    j = i;
    while (j <= n && P[j].first.first == P[i].first.first) j++;
    for (int k = i; k < j; k++) MX = max(MX, P[k].first.second);
    for (int k = i; k < j; k++)
      if (MX <= P[k].first.second) ans.push_back(P[k].second);
    i = j - 1;
  }
  sort(ans.begin(), ans.end());
  for (j = 0; j < ans.size(); j++) cout << ans[j] << " ";
  return 1;
}
bool SOLVE() { return 1; }
bool PRINT() { return 1; }
bool CLEAR() { return 1; }
int main() {
  get_ready();
  while (tst--) {
    if (!READ()) {
      return 0;
    }
    if (!SOLVE()) {
      return 0;
    }
    if (!PRINT()) {
      return 0;
    }
    if (!CLEAR()) {
      return 0;
    }
  }
}
