Tavas is a cheerleader in the new sports competition named "Pashmaks".

<image>

This competition consists of two part: swimming and then running. People will immediately start running R meters after they finished swimming exactly S meters. A winner is a such person that nobody else finishes running before him/her (there may be more than one winner).

Before the match starts, Tavas knows that there are n competitors registered for the match. Also, he knows that i-th person's swimming speed is si meters per second and his/her running speed is ri meters per second. Unfortunately, he doesn't know the values of R and S, but he knows that they are real numbers greater than 0.

As a cheerleader, Tavas wants to know who to cheer up. So, he wants to know all people that might win. We consider a competitor might win if and only if there are some values of R and S such that with these values, (s)he will be a winner.

Tavas isn't really familiar with programming, so he asked you to help him.

Input

The first line of input contains a single integer n (1 ≤ n ≤ 2 × 105).

The next n lines contain the details of competitors. i-th line contains two integers si and ri (1 ≤ si, ri ≤ 104).

Output

In the first and the only line of output, print a sequence of numbers of possible winners in increasing order.

Examples

Input

3
1 3
2 2
3 1


Output

1 2 3 


Input

3
1 2
1 1
2 1


Output

1 3 
5
10 50
10 50
10 50
10 50
10 50
 2
10000 10000
10000 10000
 3
10000 10000
10000 10000
10000 10000
 3
1000 3000
1500 1500
3000 1000
 43
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 1
1 1
 2
1 1
1 1
 44
78 52
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 3
1000 3000
1499 1499
3000 1000
 5
50 50
49 50
50 49
49 49
50 1
 18
82 38
33 69
33 69
33 69
33 69
33 69
82 38
33 69
33 69
33 69
82 38
33 69
33 69
82 38
82 38
33 69
33 69
33 69
 1
10000 9999
 3
1000 3000
1501 1501
3000 1000
 2
1 2
2 1

1 2 3 4 5
 1 2
 1 2 3
 1 2 3
 1 3 16 24 29 31 32 37 41 42
 1
 1 2
 1
 1 3
 1
 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
 1
 1 2 3
 1 2 

#include <bits/stdc++.h>
#pragma warning(disable : 4996)
#pragma comment(linker, "/STACK:36777216")
using namespace std;
const long long int inf = 100000000000000000LL;
struct Node {
  long long int p, b;
  long long int col;
  bool operator<(const Node& other) const {
    return p < other.p || p == other.p && b < other.b;
  }
};
struct pt {
  long long int x, y;
  long long int index;
};
bool bad(pt a, pt b) {
  return a.x < b.x && a.y <= b.y || a.x <= b.x && a.y < b.y;
}
bool cmp(pt a, pt b) { return a.x < b.x || a.x == b.x && a.y < b.y; }
bool my(pt a, pt b) { return a.index < b.index; }
bool cw(pt a, pt b, pt c) {
  return a.x * (b.y - c.y) + b.x * (c.y - a.y) + c.x * (a.y - b.y) <= 0;
}
bool ccw(pt a, pt b, pt c) {
  return a.x * (b.y - c.y) + b.x * (c.y - a.y) + c.x * (a.y - b.y) >= 0;
}
void convex_hull(vector<pt>& a) {
  if (a.size() == 1) return;
  sort(a.begin(), a.end(), &cmp);
  pt p1 = a[0], p2 = a.back();
  vector<pt> up;
  for (size_t i = 0; i < a.size(); ++i) {
    if (i == a.size() - 1 || cw(p1, a[i], p2)) {
      while (up.size() >= 2 && !cw(up[up.size() - 2], up[up.size() - 1], a[i]))
        up.pop_back();
      up.push_back(a[i]);
    }
  }
  a.clear();
  for (size_t i = 0; i < up.size(); ++i) {
    up[i].x *= -1;
    while (a.size() && bad(a.back(), up[i])) {
      a.pop_back();
    }
    if (a.size() == 0 || !bad(up[i], a.back())) a.push_back(up[i]);
  }
}
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout << fixed << setprecision(15);
  srand(23);
  int n;
  cin >> n;
  vector<pt> arr(n);
  for (int i = 0; i < n; ++i) {
    cin >> arr[i].x >> arr[i].y;
    arr[i].x *= -1;
    arr[i].index = i + 1;
  }
  convex_hull(arr);
  sort(arr.begin(), arr.end(), &my);
  for (int i = 0; i < arr.size(); ++i) {
    cout << arr[i].index << " ";
  }
  return 0;
}
