Tavas is a cheerleader in the new sports competition named "Pashmaks".

<image>

This competition consists of two part: swimming and then running. People will immediately start running R meters after they finished swimming exactly S meters. A winner is a such person that nobody else finishes running before him/her (there may be more than one winner).

Before the match starts, Tavas knows that there are n competitors registered for the match. Also, he knows that i-th person's swimming speed is si meters per second and his/her running speed is ri meters per second. Unfortunately, he doesn't know the values of R and S, but he knows that they are real numbers greater than 0.

As a cheerleader, Tavas wants to know who to cheer up. So, he wants to know all people that might win. We consider a competitor might win if and only if there are some values of R and S such that with these values, (s)he will be a winner.

Tavas isn't really familiar with programming, so he asked you to help him.

Input

The first line of input contains a single integer n (1 ≤ n ≤ 2 × 105).

The next n lines contain the details of competitors. i-th line contains two integers si and ri (1 ≤ si, ri ≤ 104).

Output

In the first and the only line of output, print a sequence of numbers of possible winners in increasing order.

Examples

Input

3
1 3
2 2
3 1


Output

1 2 3 


Input

3
1 2
1 1
2 1


Output

1 3 
5
10 50
10 50
10 50
10 50
10 50
 2
10000 10000
10000 10000
 3
10000 10000
10000 10000
10000 10000
 3
1000 3000
1500 1500
3000 1000
 43
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 1
1 1
 2
1 1
1 1
 44
78 52
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 3
1000 3000
1499 1499
3000 1000
 5
50 50
49 50
50 49
49 49
50 1
 18
82 38
33 69
33 69
33 69
33 69
33 69
82 38
33 69
33 69
33 69
82 38
33 69
33 69
82 38
82 38
33 69
33 69
33 69
 1
10000 9999
 3
1000 3000
1501 1501
3000 1000
 2
1 2
2 1

1 2 3 4 5
 1 2
 1 2 3
 1 2 3
 1 3 16 24 29 31 32 37 41 42
 1
 1 2
 1
 1 3
 1
 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
 1
 1 2 3
 1 2 

#include <iostream>
#include <sstream>
#include <fstream>
#include <string>
#include <vector>
#include <deque>
#include <queue>
#include <stack>
#include <set>
#include <map>
#include <algorithm>
#include <functional>
#include <utility>
#include <bitset>
#include <cmath>
#include <cstdlib>
#include <ctime>
#include <cstdio>
#include <memory.h>
#include <iomanip>
#include <unordered_set>
#include <unordered_map>
using namespace std;

#define MP make_pair
#define FS first
#define SC second
#define LB lower_bound
#define PB push_back
#define lc p*2+1
#define rc p*2+2

typedef long long ll;
typedef pair<int,int> pi; 

const int Maxn=2e5+5;

class pnt{
	public:
		int x,y;
		int id;
		bool operator<(const pnt &o){
			return x<o.x||(x==o.x&&y<o.y);
		}
};

vector<pnt> hull;

bool check(pnt p1,pnt p2,pnt p3){
	ll d=(ll)p1.x*p3.y*(p2.y-p1.y)*(p3.x-p2.x)-(ll)p3.x*p1.y*(p3.y-p2.y)*(p2.x-p1.x);
	return d<0;
}

void insert(pnt o){
	if(hull.size()<2){
		hull.PB(o);
		return;
	}
	int m=hull.size()-1,l=m-1;
	while(m){
		if(check(hull[l],hull[m],o)){
			hull.pop_back();
			l--;m--;
		}
		else break;
	}
	hull.PB(o);
}

int n;
bool pw[Maxn];
pnt p[Maxn];

int main(){
	scanf("%d",&n);
	for(int i=1;i<=n;i++){
		scanf("%d%d",&p[i].x,&p[i].y);
		p[i].id=i;
	}
	sort(p+1,p+n+1);
	for(int i=1;i<=n;i++) insert(p[i]);
	int sz=hull.size(),it=0;
	while(it+1<sz&&hull[it+1].y>=hull[it].y) it++;
	for(int i=it;i<sz;i++) pw[hull[i].id]=true;
	for(int i=1;i<=n;i++) if(pw[i]) printf("%d ",i);
return 0;
}
