The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the number. Yes, of course, n can be rather big, and one cannot find the power using a calculator, but we need people who are able to think, not just follow the instructions."

Could you pass the interview in the machine vision company in IT City?

Input

The only line of the input contains a single integer n (2 ≤ n ≤ 2·1018) — the power in which you need to raise number 5.

Output

Output the last two digits of 5n without spaces between them.

Examples

Input

2


Output

25
7
 2000000000000000000
 1000000000000000000
 987654321012345678

25
 25
 25
 25

import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintStream;
import java.util.ArrayList;
import java.util.InputMismatchException;
import java.util.Stack;

public class Main {

    static final File ip = new File("input.txt");
    static final File op = new File("output.txt");
    static InputReader in;

    static {
        try {
            System.setOut(new PrintStream(op));
            System.setIn(new FileInputStream(ip));
        } catch (Exception e) {
        }

        in = new InputReader(System.in);
    }

    /***
     * Write your code in this function! Input: Use InputReader "in" for reading
     * data. Output: Use System.out.println() to write output to file
     */
    private static void solve(int t1) {
        int n = in.readInt();
        System.out.println("25");
    }

    public static void main(String[] args) throws FileNotFoundException {

        // int t = in.readInt();
        // int t1 = 1;
        // while (t1 <= t) {
        //     solve(t1);
        //     t1++;
        // }
        solve(1);
    }

    /**
     * A class for Fast Input
     */
    static class InputReader {
        private InputStream stream;
        private byte[] buf = new byte[1024];
        private int curChar;
        private int numChars;
        private SpaceCharFilter filter;

        public InputReader(InputStream stream) {
            this.stream = stream;
        }

        public int read() {
            if (numChars == -1)
                throw new InputMismatchException();
            if (curChar >= numChars) {
                curChar = 0;
                try {
                    numChars = stream.read(buf);
                } catch (IOException e) {
                    throw new InputMismatchException();
                }
                if (numChars <= 0)
                    return -1;
            }
            return buf[curChar++];
        }

        public int readInt() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = read();
            }
            int res = 0;
            do {
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = read();
            } while (!isSpaceChar(c));
            return res * sgn;
        }

        public String readString() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            StringBuilder res = new StringBuilder();
            do {
                res.appendCodePoint(c);
                c = read();
            } while (!isSpaceChar(c));
            return res.toString();
        }

        public boolean isSpaceChar(int c) {
            if (filter != null)
                return filter.isSpaceChar(c);
            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }

        public String next() {
            return readString();
        }

    }

    public interface SpaceCharFilter {
        public boolean isSpaceChar(int ch);
    }
}
