Tavas is a cheerleader in the new sports competition named "Pashmaks".

<image>

This competition consists of two part: swimming and then running. People will immediately start running R meters after they finished swimming exactly S meters. A winner is a such person that nobody else finishes running before him/her (there may be more than one winner).

Before the match starts, Tavas knows that there are n competitors registered for the match. Also, he knows that i-th person's swimming speed is si meters per second and his/her running speed is ri meters per second. Unfortunately, he doesn't know the values of R and S, but he knows that they are real numbers greater than 0.

As a cheerleader, Tavas wants to know who to cheer up. So, he wants to know all people that might win. We consider a competitor might win if and only if there are some values of R and S such that with these values, (s)he will be a winner.

Tavas isn't really familiar with programming, so he asked you to help him.

Input

The first line of input contains a single integer n (1 ≤ n ≤ 2 × 105).

The next n lines contain the details of competitors. i-th line contains two integers si and ri (1 ≤ si, ri ≤ 104).

Output

In the first and the only line of output, print a sequence of numbers of possible winners in increasing order.

Examples

Input

3
1 3
2 2
3 1


Output

1 2 3 


Input

3
1 2
1 1
2 1


Output

1 3 
5
10 50
10 50
10 50
10 50
10 50
 2
10000 10000
10000 10000
 3
10000 10000
10000 10000
10000 10000
 3
1000 3000
1500 1500
3000 1000
 43
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 1
1 1
 2
1 1
1 1
 44
78 52
75 16
70 7
75 16
54 2
70 7
54 2
70 7
54 2
70 7
54 2
54 2
70 7
70 7
54 2
70 7
75 16
70 7
54 2
54 2
54 2
54 2
54 2
54 2
75 16
70 7
70 7
54 2
70 7
75 16
54 2
75 16
75 16
54 2
54 2
70 7
70 7
75 16
70 7
70 7
70 7
75 16
75 16
54 2
 3
1000 3000
1499 1499
3000 1000
 5
50 50
49 50
50 49
49 49
50 1
 18
82 38
33 69
33 69
33 69
33 69
33 69
82 38
33 69
33 69
33 69
82 38
33 69
33 69
82 38
82 38
33 69
33 69
33 69
 1
10000 9999
 3
1000 3000
1501 1501
3000 1000
 2
1 2
2 1

1 2 3 4 5
 1 2
 1 2 3
 1 2 3
 1 3 16 24 29 31 32 37 41 42
 1
 1 2
 1
 1 3
 1
 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
 1
 1 2 3
 1 2 

#include <bits/stdc++.h>
using namespace std;
const double eps = 1e-10;
const double PI = acos(-1.0);
const double BASE = 10000;
int dcmp(double x) {
  if (fabs(x) < eps)
    return 0;
  else
    return x > 0 ? 1 : -1;
}
struct Point {
  double x, y;
  int s, r;
  Point(double x = 0, double y = 0, int s = 0, int r = 0)
      : x(x), y(y), s(s), r(r) {}
};
Point operator+(Point A, Point B) { return Point(A.x + B.x, A.y + B.y); }
Point operator-(Point A, Point B) { return Point(A.x - B.x, A.y - B.y); }
Point operator*(Point A, double p) { return Point(A.x * p, A.y * p); }
Point operator/(Point A, double p) { return Point(A.x / p, A.y / p); }
bool operator==(const Point& A, const Point& B) {
  return dcmp(A.x - B.x) == 0 && dcmp(A.y - B.y) == 0;
}
bool operator<(const Point& A, const Point& B) {
  return A.x < B.x || (A.x == B.x && A.y < B.y);
}
double Dot(Point A, Point B) { return A.x * B.x + A.y * B.y; }
double Cross(Point A, Point B) { return A.x * B.y - A.y * B.x; }
vector<Point> LDConvexHull(vector<Point>& p) {
  sort(p.begin(), p.end());
  p.erase(unique(p.begin(), p.end()), p.end());
  int n = p.size();
  int m = 0;
  vector<Point> ch(n + 1);
  for (int i = 0; i < n; ++i) {
    if (m > 0 && ((ch[m - 1].y - p[i].y) * (ch[m - 1].x - p[i].x) > 0 ||
                  (dcmp(ch[m - 1].x == p[i].x) == 0 && ch[m - 1].y < p[i].y)))
      continue;
    while (m > 1 && dcmp(Cross(ch[m - 1] - ch[m - 2], p[i] - ch[m - 2])) <= 0)
      m--;
    ch[m++] = p[i];
  }
  ch.resize(m);
  return ch;
}
vector<Point> p;
map<pair<int, int>, vector<int> > Q;
int n;
int main() {
  scanf("%d", &n);
  p.clear(), Q.clear();
  for (int i = 1; i <= n; ++i) {
    int x, y;
    scanf("%d %d", &x, &y);
    p.push_back(Point((double)BASE / x, (double)BASE / y, x, y));
    Q[make_pair(x, y)].push_back(i);
  }
  vector<Point> temp = LDConvexHull(p);
  vector<int> res;
  for (int i = 0; i < temp.size(); ++i)
    for (int j = 0; j < Q[make_pair(temp[i].s, temp[i].r)].size(); ++j)
      res.push_back(Q[make_pair(temp[i].s, temp[i].r)][j]);
  sort(res.begin(), res.end());
  for (int i = 0; i < res.size(); ++i)
    printf("%d%c", res[i], (i == res.size() - 1) ? '\n' : ' ');
  return 0;
}
