int main(void){

  int n,a[10000],i,j,count=0;

  scanf("%d",&n);
  for(i=0; i < n; i++){
    scanf("%d",&a[i]);
        if(a[i]==2 || a[i] == 3) count++;
        else {

          for(j = a[i] - 1; j > 1; j--){
            if(a[i] % j == 0){
              count++;
              break;
            }
          }
        }
  }
  printf("%d\n",count);
  return 0;
}