2 1
1 1
 4 1
2 2 1 1
 10 1
2 6 3 4 2 4 4 3 2 1
 2 1
999152 999153
 8 1000000
1 1 5 1000000 1000000 2 2 2
 9 2
1 6 1 5 5 8 6 8 7
 15 1
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
 1 4
8
 10 1
6 3 1 3 6 4 1 3 6 4
 10 1
1 2 3 5 6 8 10 11 9 4
 7 2
1 5 5 8 9 8 8
 2 1000000
1 1000000
 8 2
3 13 9 8 3 13 9 14
 1 1
1
 2 1
1 2

2
 2
 4
 1
 2
 4
 15
 1
 7
 2
 4
 1
 5
 1
 1

#include <bits/stdc++.h>
namespace IO {
template <typename T>
inline void read(T &x) {
  x = 0;
  int f = 1;
  char ch = getchar();
  while (ch > '9' || ch < '0') {
    if (ch == '-') f = -1;
    ch = getchar();
  }
  while (ch >= '0' && ch <= '9')
    x = (x << 3) + (x << 1) + ch - '0', ch = getchar();
  x *= f;
  return;
}
template <typename T>
inline void write(T x = 0) {
  T wr[51];
  wr[0] = 0;
  if (x < 0) putchar('-'), x = -x;
  if (!x) putchar(48);
  while (x) wr[++wr[0]] = x % 10, x /= 10;
  while (wr[0]) putchar(48 + wr[wr[0]--]);
  return;
}
}  // namespace IO
using IO::read;
using IO::write;
using namespace std;
const int N = 1e6 + 11;
int n, k, ans;
int a[N], b[N];
int main() {
  read(n), read(k);
  for (register int i = 1; i <= n; ++i) read(a[i]);
  sort(a + 1, a + n + 1);
  register int j = 0;
  for (register int i = 1; i <= n; ++i) {
    int p = lower_bound(a + 1, a + n + 1, a[i] - k) - a;
    if (a[p] >= a[i]) continue;
    ++b[p];
    --b[i];
  }
  for (register int i = 1; i <= n; ++i) {
    b[i] += b[i - 1];
    if (!b[i]) ++ans;
  }
  printf("%d\n", ans);
  return 0;
}
