3 3 1
 300 2 300
 4000 4000 1
 4000 4000 100
 4 2 3
 3 300 300
 4000 100 4000
 3 300 1
 300 300 1
 4000 1000 3000
 3 2 4000
 4 3 2
 3 2 300
 4000 3998 2
 100 200 300
 300 300 300
 3 3 3
 10 10 10
 10 4 9
 239 300 231
 4000 2 3998
 200 100 300
 4000 2000 2000
 4000 4000 4000
 10 7 5
 4000 100 3900
 3 4000 4000

12
 775907030
 63263244
 994443885
 24
 496527918
 908339579
 828107078
 775907030
 876839920
 938379934
 48
 196174631
 296557186
 316471646
 375912430
 72
 318389383
 135283173
 774612666
 686088712
 949581532
 310481606
 997463324
 130636800
 221262673
 680114446

#include <bits/stdc++.h>
using namespace std;
const int mod = 1000000009, N = 4005;
int cal[N][N], fac[N];
inline int add(int a, int b) {
  if (a < 0) a += mod;
  if (b < 0) b += mod;
  int ret = a + b;
  if (ret >= mod)
    return ret %= mod;
  else
    return ret;
}
inline int mul(int a, int b) {
  if (a < 0) a += mod;
  if (b < 0) b += mod;
  long long ret = (long long)a * b;
  if (ret >= mod)
    return ret % mod;
  else
    return ret;
}
int main() {
  memset(cal, 0, sizeof(cal));
  cal[0][0] = 1;
  fac[0] = 1;
  for (int i = 1; i < N; i++) {
    fac[i] = mul(fac[i - 1], i);
    cal[i][0] = cal[i][i] = 1;
    for (int j = 1; j < i; j++) {
      cal[i][j] = add(cal[i - 1][j], cal[i - 1][j - 1]);
    }
  }
  int n, a, b, ans = 0;
  scanf("%d%d%d", &n, &a, &b);
  for (int i = 1; i < n - 1; i++) {
    for (int j = i + 2; j <= n; j++) {
      int cntb = j - i - 1, cnta = n - cntb;
      if (cntb > b) break;
      if (cnta > a) continue;
      ans = add(ans, mul(mul(cal[a - 1][cnta - 1], fac[a]),
                         mul(cal[b - 1][cntb - 1], fac[b])));
    }
  }
  printf("%d\n", ans);
  return 0;
}
