2 1
1 1
 4 1
2 2 1 1
 10 1
2 6 3 4 2 4 4 3 2 1
 2 1
999152 999153
 8 1000000
1 1 5 1000000 1000000 2 2 2
 9 2
1 6 1 5 5 8 6 8 7
 15 1
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
 1 4
8
 10 1
6 3 1 3 6 4 1 3 6 4
 10 1
1 2 3 5 6 8 10 11 9 4
 7 2
1 5 5 8 9 8 8
 2 1000000
1 1000000
 8 2
3 13 9 8 3 13 9 14
 1 1
1
 2 1
1 2

2
 2
 4
 1
 2
 4
 15
 1
 7
 2
 4
 1
 5
 1
 1

#Winners never quit, quiters never win............................................................................
from collections import deque as de
import math
from collections import Counter as cnt
from functools import reduce
from typing import MutableMapping

def factors(n):    
    return set(reduce(list.__add__, 
                ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0)))
class My_stack():
    def __init__(self):
        self.data = []
    def my_push(self, x):
        return (self.data.append(x))
    def my_pop(self):
        return (self.data.pop())
    def my_peak(self):
        return (self.data[-1])
    def my_contains(self, x):
        return (self.data.count(x))
    def my_show_all(self):
        return (self.data)
    def isEmpty(self):
      return len(self.data)==0

arrStack = My_stack()    
def decimalToBinary(n): 
    return bin(n).replace("0b", "")

def isPrime(n) : 
	if (n <= 1) : 
		return False
	if (n <= 3) : 
		return True

	
	if (n % 2 == 0 or n % 3 == 0) : 
		return False

	i = 5
	while(i * i <= n) : 
		if (n % i == 0 or n % (i + 2) == 0) : 
			return False
		i = i + 6

	return True

def get_prime_factors(number):
    prime_factors = []
    while number % 2 == 0:
        prime_factors.append(2)
        number = number / 2
    for i in range(3, int(math.sqrt(number)) + 1, 2):
        while number % i == 0:
            prime_factors.append(int(i))
            number = number / i

    if number > 2:
        prime_factors.append(int(number))

    return prime_factors
def get_frequency(list):
    dic={}
    for ele in list:
        if ele in dic:
            dic[ele] += 1
        else:
            dic[ele] = 1
    return dic
def Log2(x): 
    return (math.log10(x) / 
            math.log10(2)); 

def isPowerOfTwo(n): 
    return (math.ceil(Log2(n)) == math.floor(Log2(n))); 

   
#here we go......................
#winners never quit, quitters never win
n,k=map(int,input().split())
a=list(map(int,input().split()))
dic=get_frequency(a)
ss=sorted(list(set(a)))
tobesubtracttion=0
for i in range(len(ss)-1):
    if ss[i+1] <= ss[i]+k:
        tobesubtracttion+=dic[ss[i]]
print(n-tobesubtracttion)
    







        