After his wife's tragic death, Eurydice, Orpheus descended to the realm of death to see her. Reaching its gates was uneasy, but passing through them proved to be even more challenging. Mostly because of Cerberus, the three-headed hound of Hades. 

Orpheus, a famous poet, and musician plans to calm Cerberus with his poetry and safely walk past him. He created a very peculiar poem for Cerberus. It consists only of lowercase English letters. 

We call a poem's substring a palindrome if and only if it reads the same backwards and forwards. A string a is a substring of a string b if a can be obtained from b by deleting several (possibly zero or all) characters from the beginning and several (possibly zero or all) characters from the end.

Unfortunately, Cerberus dislikes palindromes of length greater than 1. For example in the poem abaa the hound of Hades wouldn't like substrings aba and aa.

Orpheus can only calm Cerberus if the hound likes his poetry. That's why he wants to change his poem so that it does not contain any palindrome substrings of length greater than 1.

Orpheus can modify the poem by replacing a letter at any position with any lowercase English letter. He can use this operation arbitrarily many times (possibly zero). Since there can be many palindromes in his poem, he may have to make some corrections. But how many, exactly? Given the poem, determine the minimal number of letters that have to be changed so that the poem does not contain any palindromes of length greater than 1.

Input

The first line of the input contains a single integer t (1 ≤ t ≤ 10^5) denoting the number of test cases, then t test cases follow.

The first and only line of each test case contains a non-empty string of lowercase English letters, Orpheus' poem.

The sum of the length of Orpheus' poems in all test cases will not exceed 10^5.

Output

You should output t lines, i-th line should contain a single integer, answer to the i-th test case.

Example

Input


7
babba
abaac
codeforces
zeroorez
abcdcba
bbbbbbb
a


Output


1
1
0
1
1
4
0

Note

In the first test case, we can replace the third character with c and obtain a palindrome-less poem bacba.

In the second test case, we can replace the third character with d and obtain a palindrome-less poem abdac.

In the third test case, the initial poem already doesn't contain any palindromes, so Orpheus doesn't need to change anything there.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Collections;
import java.util.StringTokenizer;

public class Main {

	public static void main(String[] args) throws Exception {
		Scanner sc = new Scanner();
		int t = sc.nextInt();
		while (t-- > 0) {
			String str = sc.next();
			int found = 0;
			int ans = 0;
			int i = 0;
			if (str.length() == 1) {
				System.out.println(0);
				continue;
			}
			for (; i < str.length();) {
				char ch = str.charAt(i);
				int same = 0;
				while (i < str.length() && str.charAt(i) == ch) {
					same++;
					i++;

				}
				if (same > 1) {
					ans += (same + 1) / 2;
					found = 1;
				}

			}

			if (found == 0) {
				System.out.println(isPalindrome(str) ? 1 : 0);
			} else
				System.out.println(ans);

		}

	}

	static boolean isPalindrome(String str) {

		// Pointers pointing to the beginning
		// and the end of the string
		int i = 0, j = str.length() - 1;

		// While there are characters toc compare
		while (i < j) {

			// If there is a mismatch
			if (str.charAt(i) != str.charAt(j))
				return false;

			// Increment first pointer and
			// decrement the other
			i++;
			j--;
		}

		// Given string is a palindrome
		return true;
	}

	static long nCrModp(int n, int r, int p) {
		if (r > n - r)
			r = n - r;

		// The array C is going to store last
		// row of pascal triangle at the end.
		// And last entry of last row is nCr
		int C[] = new int[r + 1];

		C[0] = 1; // Top row of Pascal Triangle

		// One by constructs remaining rows of Pascal
		// Triangle from top to bottom
		for (int i = 1; i <= n; i++) {

			// Fill entries of current row using previous
			// row values
			for (int j = Math.min(i, r); j > 0; j--)

				// nCj = (n-1)Cj + (n-1)C(j-1);
				C[j] = (C[j] + C[j - 1]) % p;
		}
		return C[r];
	}

	static void sort(int[] a) {
		ArrayList<Integer> l = new ArrayList<>();
		for (int i : a)
			l.add(i);
		Collections.sort(l);
		for (int i = 0; i < a.length; i++)
			a[i] = l.get(i);
	}

}

class Scanner {
	BufferedReader br;
	StringTokenizer st;

	Scanner() {
		br = new BufferedReader(new InputStreamReader(System.in));
	}

	String next() throws IOException {
		while (st == null || !st.hasMoreElements())
			st = new StringTokenizer(br.readLine());
		return st.nextToken();
	}

	int nextInt() throws NumberFormatException, IOException {
		return Integer.parseInt(next());
	}

	long nextLong() throws NumberFormatException, IOException {
		return Long.parseLong(next());
	}

	double nextDouble() throws NumberFormatException, IOException {
		return Double.parseDouble(next());
	}
}

//creating a hash table
//Hashtable<Integer, String> h = new Hashtable<Integer, String>();
//
//Hashtable<Integer, String> h1 = new Hashtable<Integer, String>();
//
//h.put(3, "Geeks");
//h.put(2, "forGeeks");
//h.put(1, "isBest");
//System.out.println(h.get(1));
//if (h.containsKey(1)) {
//	System.out.println(1111111);
//}
//if (h.containsValue("isBest")) {
//	System.out.println(1111111);
//}
//
//// create a clone or shallow copy of hash table h
//h1 = (Hashtable<Integer, String>) h.clone();
//
//// checking clone h1
////System.out.println("values in clone: " + h1);
//
//// clear hash table h
//h.clear();

//Creating object of the 
// class linked list 
//LinkedList<String> ll 
//    = new LinkedList<String>(); 
//
//// Adding elements to the linked list 
//ll.add("A"); 
//ll.add("B"); 
//ll.addLast("C"); 
//ll.addFirst("D"); 
//ll.add(2, "E"); 
//
//System.out.println(ll); 
//
//ll.remove("B"); 
//ll.remove(3); 
//ll.removeFirst(); 
//ll.removeLast(); 
//
//System.out.println(ll); 

//Set<Integer> set = new HashSet<Integer>();
//try {
//   for(int i = 0; i < 5; i++) {
//      set.add(count[i]);
//   }
//   System.out.println(set);
//
//   TreeSet sortedSet = new TreeSet<Integer>(set);
//   System.out.println("The sorted list is:");
//   System.out.println(sortedSet);
//
//   System.out.println("The First element of the set is: "+ (Integer)sortedSet.first());
//   System.out.println("The last element of the set is: "+ (Integer)sortedSet.last());
//}
//catch(Exception e) {}