For a given polygon g, print "1" if g is a convex polygon, "0" otherwise. Here, in a convex polygon, all interior angles are less than or equal to 180 degrees.

g is represented by a sequence of points p1, p2,..., pn where line segments connecting pi and pi+1 (1 ≤ i ≤ n-1) are sides of the polygon. The line segment connecting pn and p1 is also a side of the polygon.

Constraints

* 3 ≤ n ≤ 100
* -10000 ≤ xi, yi ≤ 10000
* No point of the polygon will occur more than once.
* Two sides of the polygon can intersect only at a common endpoint.

Input

g is given by coordinates of the points p1,..., pn in the following format:


n
x1 y1
x2 y2
:
xn yn


The first integer n is the number of points. The coordinate of a point pi is given by two integers xi and yi. The coordinates of points are given in the order of counter-clockwise visit of them.

Output

Print "1" or "0" in a line.

Examples

Input

4
0 0
3 1
2 3
0 3


Output

1


Input

5
0 0
2 0
1 1
2 2
0 2


Output

0
#include <cstdio>
#include <utility>
#include <vector>
#include <complex>
#include <cmath>

using namespace std;

static const double EPS=1e-12;
static const double INF=1e24;

using Point=complex<double>;
using Plane=vector<Point>;
using Polygon=vector<Point>;

bool operator<(const Point &a, const Point &b) {
    return real(a)!=real(b)? real(a)<real(b) : imag(a)<imag(b);
}

double cross_prod(const Point &a, const Point &b) {
    return imag(conj(a)*b);
}

double dot_prod(const Point &a, const Point &b) {
    return real(conj(a)*b);
}

enum {
    ONLINE_FRONT=-2,
    CLOCKWISE,
    ON_SEGMENT,
    COUNTER_CLOCKWISE,
    ONLINE_BACK,
};

int ccwise(Point a, Point b, Point c) {
    b -= a; c -= a;

    if (cross_prod(b, c) > 0) {
        return COUNTER_CLOCKWISE;
    } else if (cross_prod(b, c) < 0) {
        return CLOCKWISE;
    } else if (dot_prod(b, c) < 0) {
        return ONLINE_BACK;
    } else if (norm(b) < norm(c)) {
        return ONLINE_FRONT;
    } else {
        return ON_SEGMENT;
    }
}

bool is_convex(Polygon g) {
    size_t V=g.size();
    for (size_t i=0; i<V; ++i) {
        int state=ccwise(g[i], g[(i+1)%V], g[(i+2)%V]);
        if (state == CLOCKWISE)
            return false;
    }

    return true;
}

int main() {
    size_t n;
    scanf("%zu", &n);

    Polygon g(n);
    for (size_t i=0; i<n; ++i) {
        double x, y;
        scanf("%lf %lf", &x, &y);
        g[i] = Point(x, y);
    }

    printf("%d\n", is_convex(g));
    return 0;
}