You are given an integer n. In one move, you can either multiply n by two or divide n by 6 (if it is divisible by 6 without the remainder).

Your task is to find the minimum number of moves needed to obtain 1 from n or determine if it's impossible to do that.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow. 

The only line of the test case contains one integer n (1 ≤ n ≤ 10^9).

Output

For each test case, print the answer — the minimum number of moves needed to obtain 1 from n if it's possible to do that or -1 if it's impossible to obtain 1 from n.

Example

Input


7
1
2
3
12
12345
15116544
387420489


Output


0
-1
2
-1
-1
12
36

Note

Consider the sixth test case of the example. The answer can be obtained by the following sequence of moves from the given integer 15116544:

  1. Divide by 6 and get 2519424; 
  2. divide by 6 and get 419904; 
  3. divide by 6 and get 69984; 
  4. divide by 6 and get 11664; 
  5. multiply by 2 and get 23328; 
  6. divide by 6 and get 3888; 
  7. divide by 6 and get 648; 
  8. divide by 6 and get 108; 
  9. multiply by 2 and get 216; 
  10. divide by 6 and get 36; 
  11. divide by 6 and get 6; 
  12. divide by 6 and get 1. 
1
999838675

-1

import math
def gcd(a,b): 
    if (b == 0): 
         return a 
    return gcd(b, a%b) 

def lcm(a,b): 
    return (a*b) / gcd(a,b) 

def bs(arr, l, r, x): 
    while l <= r: 
        mid = l + (r - l)//2; 
        if(arr[mid]==x): 
            return arr[mid]
        elif(arr[mid]<x): 
            l = mid + 1
        else: 
            r = mid - 1
    return -1

def swap(list, pos1, pos2): 
      
    list[pos1], list[pos2] = list[pos2], list[pos1] 
    return list

t = int(input())
for _ in range(t):
    n = int(input())
    x = n/3
    if(n==1):
        print(0)
        continue
    # print(x,y)
    if(n==3):
        print(2)
    elif(x%1!=0):
        print(-1)
    else:
        i3 = 0
        nn = n
        while(nn%3==0):
            nn=nn/3
            i3+=1
        i2 = 0
        while(nn%2==0):
            nn=nn/2
            i2+=1
        # print(i3,i2)
        if(i3>=i2):
            z = n*pow(2,i3-i2)
            x = 0
            while(z%6==0):
                z=z/6
                x+=1
            if(z!=1):
                print(-1)
            else:
                print(i3-i2+x)
        else:
            print(-1)