You are given an integer n. In one move, you can either multiply n by two or divide n by 6 (if it is divisible by 6 without the remainder).

Your task is to find the minimum number of moves needed to obtain 1 from n or determine if it's impossible to do that.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow. 

The only line of the test case contains one integer n (1 ≤ n ≤ 10^9).

Output

For each test case, print the answer — the minimum number of moves needed to obtain 1 from n if it's possible to do that or -1 if it's impossible to obtain 1 from n.

Example

Input


7
1
2
3
12
12345
15116544
387420489


Output


0
-1
2
-1
-1
12
36

Note

Consider the sixth test case of the example. The answer can be obtained by the following sequence of moves from the given integer 15116544:

  1. Divide by 6 and get 2519424; 
  2. divide by 6 and get 419904; 
  3. divide by 6 and get 69984; 
  4. divide by 6 and get 11664; 
  5. multiply by 2 and get 23328; 
  6. divide by 6 and get 3888; 
  7. divide by 6 and get 648; 
  8. divide by 6 and get 108; 
  9. multiply by 2 and get 216; 
  10. divide by 6 and get 36; 
  11. divide by 6 and get 6; 
  12. divide by 6 and get 1. 
1
999838675

-1

import sys

def swap(x, y, a):
	temp = a[x]
	a[x] = a[y]
	a[y] = temp
	return a

def solve():
	return None

def main():
	q = []
	for line in sys.stdin.readlines():
		q.append(line)

	for i in range(len(q)):
		q[i] = int(q[i].rstrip().split(' ')[0])
		# q[i] = [int(x) for x in q[i]]

	for i in range(1, len(q)):
		num = q[i]
		if num == 1:
			print(0)
		else:
			total = 0
			while(num != 1):
				if num % 6 == 0:
					total +=1
					num /= 6
					continue
				if num % 3 == 0:
					total +=2
					num /= 3
					continue
				total = -1
				break
			print(total)

		# solve(q[i])

if __name__ == '__main__':
	main()