You want to perform the combo on your opponent in one popular fighting game. The combo is the string s consisting of n lowercase Latin letters. To perform the combo, you have to press all buttons in the order they appear in s. I.e. if s="abca" then you have to press 'a', then 'b', 'c' and 'a' again.

You know that you will spend m wrong tries to perform the combo and during the i-th try you will make a mistake right after p_i-th button (1 ≤ p_i < n) (i.e. you will press first p_i buttons right and start performing the combo from the beginning). It is guaranteed that during the m+1-th try you press all buttons right and finally perform the combo.

I.e. if s="abca", m=2 and p = [1, 3] then the sequence of pressed buttons will be 'a' (here you're making a mistake and start performing the combo from the beginning), 'a', 'b', 'c', (here you're making a mistake and start performing the combo from the beginning), 'a' (note that at this point you will not perform the combo because of the mistake), 'b', 'c', 'a'.

Your task is to calculate for each button (letter) the number of times you'll press it.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases.

Then t test cases follow.

The first line of each test case contains two integers n and m (2 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5) — the length of s and the number of tries correspondingly.

The second line of each test case contains the string s consisting of n lowercase Latin letters.

The third line of each test case contains m integers p_1, p_2, ..., p_m (1 ≤ p_i < n) — the number of characters pressed right during the i-th try.

It is guaranteed that the sum of n and the sum of m both does not exceed 2 ⋅ 10^5 (∑ n ≤ 2 ⋅ 10^5, ∑ m ≤ 2 ⋅ 10^5).

It is guaranteed that the answer for each letter does not exceed 2 ⋅ 10^9.

Output

For each test case, print the answer — 26 integers: the number of times you press the button 'a', the number of times you press the button 'b', ..., the number of times you press the button 'z'.

Example

Input


3
4 2
abca
1 3
10 5
codeforces
2 8 3 2 9
26 10
qwertyuioplkjhgfdsazxcvbnm
20 10 1 2 3 5 10 5 9 4


Output


4 2 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 9 4 5 3 0 0 0 0 0 0 0 0 9 0 0 3 1 0 0 0 0 0 0 0 
2 1 1 2 9 2 2 2 5 2 2 2 1 1 5 4 11 8 2 7 5 1 10 1 5 2 

Note

The first test case is described in the problem statement. Wrong tries are "a", "abc" and the final try is "abca". The number of times you press 'a' is 4, 'b' is 2 and 'c' is 2.

In the second test case, there are five wrong tries: "co", "codeforc", "cod", "co", "codeforce" and the final try is "codeforces". The number of times you press 'c' is 9, 'd' is 4, 'e' is 5, 'f' is 3, 'o' is 9, 'r' is 3 and 's' is 1.
2
2 2
yz
1 1
2 2
yz
1 1
 1
11 2
thisisatest
3 5

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3 1 

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3 1 

 1 0 0 0 1 0 0 3 5 0 0 0 0 0 0 0 0 0 4 5 0 0 0 0 0 0 


import java.io.BufferedReader; 
import java.io.IOException; 
import java.io.InputStreamReader; 
import java.util.*; 
import java.util.StringTokenizer; 
import java.io.PrintWriter;
import java.io.*;
import java.util.stream.Collectors.*;
import java.lang.*;
import static java.util.stream.Collectors.*;
import static java.util.Map.Entry.*;
public class Ideo
{ 
    static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() 
        { 
            br = new BufferedReader(new
                     InputStreamReader(System.in)); 
        } 
  
        String next() 
        { 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
  
        int nextInt() 
        { 
            return Integer.parseInt(next()); 
        } 
  
        long nextLong() 
        { 
            return Long.parseLong(next()); 
        } 
  
        double nextDouble() 
        { 
            return Double.parseDouble(next()); 
        } 
  
        String nextLine() 
        { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    }
   
static int power(int x,int y) 
{ 
    int res = 1;      // Initialize result 
  
      // Update x if it is more than or  
                // equal to p 
  
    while (y > 0) 
    { 
        // If y is odd, multiply x with result 
        if (y%2==1) 
            res = (res*x); 
  
        // y must be even now 
        y = y>>1; // y = y/2 
        x = (x*x);   
    } 
    return res; 
} 
 
 static long gcd(long a,long b) 
    { 
        if (a == 0) 
            return b; 
        return gcd(b % a, a); 
    } 
 
 
  static boolean compareSeq(char[] S, int x, int y, int n) 
    { 
        for (int i = 0; i < n; i++)
         {
 
            if (S[x] < S[y]) 
               return true;
            else if (S[x] > S[y]) 
                return false; 
            x = (x + 1) % n; 
            y = (y + 1) % n; 
        } 
        return true; 
    } 
 
    static void build(long[] sum,int[] arr,int n)
    {
      for(int i=0;i<(1<<n);i++)
      {
        long total=0;
        for(int j=0;j<n;j++)
        {
          if((i & (1 << j)) > 0)
            total+=arr[j];
        }
 
        sum[i]=total;
      }
    }

 
       static int parity(int a)
       {
    a^=a>>16;
    a^=a>>8;
    a^=a>>4;
    a^=a>>2;
    a^=a>>1;
    return a&1;
  }
/*
  PriorityQueue<aksh> pq = new PriorityQueue<>((o1, o2) -> {
            if (o1.p < o2.p)
                return 1;
            else if (o1.p > o2.p)
                return -1;
            else
                return 0;
 
        });//decreasing order acc to p*/
static int power(int x, int y, int m)  
    { 
        if (y == 0) 
            return 1; 
          
        int p = power(x, y / 2, m) % m; 
        p = (p * p) % m; 
      
        if (y % 2 == 0) 
            return p; 
        else
            return (x * p) % m; 
    } 
/*static int modinv(int a, int m) 
    { 
        int g = gcd(a, m); 
        if (g != 1) 
            return 0;
        else 
        { 
           return power(a, m - 2, m); 
        } 
        //return 0;
    } */
 
static int[] product(int[] nums) {
    int[] result = new int[nums.length];
 
    int[] t1 = new int[nums.length];
    int[] t2 = new int[nums.length];
 
    t1[0]=1;
    t2[nums.length-1]=1;
 
    //scan from left to right
    for(int i=0; i<nums.length-1; i++){
        t1[i+1] = nums[i] * t1[i];
    }
 
    //scan from right to left
    for(int i=nums.length-1; i>0; i--){
        t2[i-1] = t2[i] * nums[i];
    }
 
    for(int i=0;i<nums.length;i++)
      {
        System.out.print(t1[i]+" "+t2[i]);
        System.out.println();
      }
 
    //multiply
    for(int i=0; i<nums.length; i++){
        result[i] = t1[i] * t2[i];
    }
 
    return result;
}
 
static int getsum(int[] bit,int ind)
{
  int sum=0;
  while(ind>0)
  {
    sum+=bit[ind];
    ind-= ind & (-ind);
  }
 
  return sum;
}
 
static void update(int[] bit,int max,int ind,int val)
{
  while(ind<=max)
  {
    bit[ind]+=val;
    ind+= ind & (-ind);
  }
}
 
    //static ArrayList<Integer>[] adj;
 
    static boolean check(long mid,long a,long b)
    {
      long count=1;
      while(count<=mid)
      {
        count++;
        if(a<b)
          a+=count;
        else
          b+=count;
 
        if(a==b)
          return true;
      }
        return false;
    }
 
    static class aksh implements Comparable<aksh>
    {
      int x;
      int y;
      public aksh(int x,int y)
      {
        this.x=x;
        this.y=y;
      }
      public int compareTo(aksh o)
      {
        if(x!=o.x)
          return x-o.x;
        else
          return y-o.y;
      }
    }
    static int get(int arr[], int n) 
    { 
        int result = 0; 
        int x, sum; 
          
        // Iterate through every bit 
        for(int i=0; i<32; i++) 
        { 
            // Find sum of set bits at ith position in all  
            // array elements 
            sum = 0; 
            x = (1 << i); 
            for(int j=0; j<n; j++) 
            { 
                if((arr[j] & x)!=0) 
                sum++; 
            }  
            if ((sum % 3)!=0) 
            result |= x; 
        } 
        return result; 
    }
 
    static boolean isPrime(int n)  
    {  
        // Corner cases  
        if (n <= 1) return false;  
        if (n <= 3) return true;  
          
        // This is checked so that we can skip  
        // middle five numbers in below loop  
        if (n % 2 == 0 || n % 3 == 0) return false;  
          
        for (int i = 5; i * i <= n; i = i + 6)  
            if (n % i == 0 || n % (i + 2) == 0)  
            return false;  
          
        return true;  
    }  
      
    static int nextPrime(int N)  
    {  
      
        // Base case  
        if (N <= 1)  
            return (2-N);  
      
        int prime = N;  
        boolean found = false;    
        while (!found)  
        {  
            if (isPrime(prime))  
                {
                  found = true;
                  break;
                }  
 
            prime++;
        }  
      
        return (prime-N);  
    }  
 
 
    static long product(long x) 
{ 
    long prod = 1; 
    while (x > 0)  
    { 
        prod *= (x % 10); 
        x /= 10; 
    } 
    return prod; 
} 
  
// This function returns the number having 
// maximum product of the digits 
static long findNumber(long l, long r) 
{ 
    // Converting both integers to strings 
    //string a = l.ToString(); 
    String b = Long.toString(r); 
  
    // Let the current answer be r 
    long ans = r; 
    for (int i = 0; i < b.length(); i++)  
    { 
        if (b.charAt(i) == '0') 
            continue; 
  
        // Stores the current number having 
        // current digit one less than current 
        // digit in b 
        char[] curr = b.toCharArray(); 
        curr[i] = (char)(((int)(curr[i] -  
                    (int)'0') - 1) + (int)('0')); 
  
        // Replace all following digits with 9 
        // to maximise the product 
        for (int j = i + 1; j < curr.length; j++) 
            curr[j] = '9'; 
  
        // Convert string to number 
        int num = 0; 
        for (int j = 0; j < curr.length; j++) 
            num = num * 10 + (curr[j] - '0'); 
  
        // Check if it lies in range and its product 
        // is greater than max product 
        if (num >= l && product(ans) < product(num)) 
            ans = num; 
    } 
  
    return product(ans); 
} 
 
static long mod=998244353;
 
static long pow(long in, long pow) {
    if(pow == 0) return 1;
    long out = pow(in, pow / 2);
    out = (out * out) % mod;
    if(pow % 2 == 1) out = (out * in) % mod;
    return out;
  }
  static long inv(long in) {
    return pow(in, mod - 2);
  }
 
  static void swap(int x,int y)
  {
    int temp=x;
    x=y;
    y=temp;
  }
 
  static int[] par;
  static int[] size;
  static int find(int i) 
  {
     if (par[i] == i)
      return i;
 
    return par[i] = find(par[par[i]]);
  }
 
  static void union(int x, int y) 
  {
      x = find(x);
      y = find(y);
      if (x == y)
        return;
      if (size[x] < size[y])
        swap(x, y);
 
      par[y] = x;
      size[x] += size[y];
    }
 
 
    static void multisourcebfs(long[] arr,int n,int m)
    {
      //HashSet<Long> vis=new HashSet<>();
      HashMap<Long,Long> dis=new HashMap<>();
      Queue<Long> q=new LinkedList<>();
 
      for(int i=0;i<arr.length;i++)
      {
        dis.put(arr[i],(long)0);
        q.add(arr[i]);
        //vis.add(arr[i]);
      }
 
      long[] res=new long[m];
      long ans=0;
      int k=0;
      while(!q.isEmpty())
      {
        if(k==m)
          break;
        long x=q.remove();
        if(dis.get(x)!=0)
        {
          ans+=dis.get(x);
          res[k]=x;
          k++;
        }
 
        if(dis.get(x-1)==null)
        {
          dis.put(x-1, dis.get(x)+1);
          q.add(x-1);
          //vis.add(x-1);
        }
 
        if(dis.get(x+1)==null)
        {
          dis.put(x+1, dis.get(x)+1);
          q.add(x+1);
          //vis.add(x+1);
        }
      }
 
      System.out.println(ans);
 
      for(int i=0;i<m;i++)
        System.out.print(res[i]+" ");
 
    }
 
    static int x; 
    static int maxcount=0;
    static void dfs(int node,int par,int dist)
    {
        if(dist>=maxcount)
        {
           maxcount=dist;
           x=node;
        }
 
        List<Integer> l = adj[node]; 
        for(Integer i: l)
        {
          if(i!=par)
          dfs(i,node,dist+1);
        }
    }

    

    static int h;
    static int w;
    static int bfs(char[][] ch,int i,int j)
    {
        Queue<aksh> q=new LinkedList<>();
        q.add(new aksh(i,j));

        int[][] dis=new int[h][w];
        int[][] vis=new int[h][w];
        vis[i][j]=1;
        dis[i][j]=0;
 
        while(!q.isEmpty())
        {
          aksh arr=q.poll();
          int x1=arr.x;
          int y1=arr.y;
 
          if((x1-1)>=0 && ch[x1-1][y1]!='#' && vis[x1-1][y1]==0)
          {
            vis[x1-1][y1]=1;
            q.add(new aksh(x1-1, y1));
            dis[x1-1][y1]=Math.max(dis[x1-1][y1],dis[x1][y1]+1);
          }
 
          if((x1+1)<h && ch[x1+1][y1]!='#' && vis[x1+1][y1]==0)
          {
            vis[x1+1][y1]=1;
            dis[x1+1][y1]=Math.max(dis[x1+1][y1],dis[x1][y1]+1);
            q.add(new aksh(x1+1, y1));
          }
 
          if((y1-1)>=0 && ch[x1][y1-1]!='#' && vis[x1][y1-1]==0)
          {
            vis[x1][y1-1]=1;
            dis[x1][y1-1]=Math.max(dis[x1][y1-1],dis[x1][y1]+1);
            q.add(new aksh(x1,y1-1));
          }
 
    
          if((y1+1)<w && ch[x1][y1+1]!='#' && vis[x1][y1+1]==0)
          {
            vis[x1][y1+1]=1;
            dis[x1][y1+1]=Math.max(dis[x1][y1+1],dis[x1][y1]+1);
            q.add(new aksh(x1,y1+1));
          }
        }
        int max=Integer.MIN_VALUE;

        for(int x=0;x<h;x++)
        {
          for(int y=0;y<w;y++)
            max=Math.max(dis[x][y],max);
        }

        return max;
    }

    static ArrayList<Integer> cnt;

    static void primefact(int n)
    {
 
          for (int i=2;i*i<=n;i++)
           {
              while ((n % i)==0)
              {
                cnt.add(i);
                n /= i;
              }
           }

          if(n>1)
             {
              cnt.add(n);
             }
    }

    static boolean hash[];
    static void sieve(int n)
    {
      Arrays.fill(hash, true);
    for (int p = 2; p * p < n; p++) 
        if (hash[p] == true) 
            for (int i = p * 2; i < n; i += p) 
                hash[i] = false; 
    }

    static long div(long n) 
  {
    long total = 1; 
    for (int p = 2; p <= n; p++)  
    { 
        if (hash[p]) 
        { 
            int count = 0; 
            if (n % p == 0)  
            { 
                while (n % p == 0)  
                { 
                    n = n / p; 
                    count++; 
                } 
                total = total * (count + 1); 
            } 
        } 
    } 
    return total; 
} 


    
    static  int upperbound(ArrayList<Integer> array, int length, int value) 
    {
        int low = 0;
        int high = length;
        while (low < high) {
            final int mid = (low + high) / 2;
            if (value >= array.get(mid)) 
            {
                low = mid + 1;
            } 
            else
            {
                high = mid;
            }
        }
        return low;
    }

     static int[][] dp;

    static void func(int[][] a,int n,int k,int p)
    {
              for (int i = 1; i < n; i++)
                for (int j = 1; j <= Math.min((i + 1) * k, p); j++)
                   for (int t2 = 0; t2 <= Math.min(k, Math.min(j, p)); t2++)
                     {
                         int aksh = 0;
                         if (t2!=0)
                         aksh = a[i][t2 - 1];

                         dp[i][j] = Math.max(dp[i][j], dp[i - 1][j - t2] + aksh);
                      }
    }


    static final long INF = Long.MAX_VALUE/5;
    static ArrayList<Integer>[] adj;
    static long binpow(long a, long b)
    {
       long res = 1;
       while (b > 0) 
       {
        if ((b & 1) !=0)
            res = res * a;
        a = a * a;
        b >>= 1;
        }
    return res;
    }

    static int upper(int[] array, int length, int value) {
        int low = 0;
        int high = length;
        while (low < high) {
            final int mid = (low + high) / 2;
            if (value >= array[mid]) {
                low = mid + 1;
            } else {
                high = mid;
            }
        }
        return low;
    }
    static int ans=0;
    static void bs(ArrayList<Integer> arr, int max, int k,int n)
    {
            int l= 1;
            int h= max;
            ans = h;

            while (l<=h)
           {
               int m = (l+h)/2;
               int r = 0;

               for (int i = 0; i < n; ++i)
                {
                  r += (arr.get(i) + m - 1) / m;
                  r--;
                }

               if(r <= k)
                  {
                    ans = m;
                    h = m - 1;
                  }
               else
                  l=m+1;
            }
    }
    static public void merge(int[][] arr) 
    {
        int n=arr[0].length;
        aksh[] a=new aksh[n];
        
        for(int i=0;i<n;i++)
            a[i]=new aksh(arr[i][0],arr[i][1]);
        
        Arrays.sort(a);
        Stack<aksh> s=new Stack<>();
        s.push(a[0]);
        
        for(int i=1;i<n;i++)
        {
            aksh temp=s.peek();
            if(temp.y>a[i].x)
            {
                temp.y=a[i].y;
                s.pop();
                s.push(temp);
            }
            else if(temp.y<a[i].x)
            {
                s.push(a[i]);
                System.out.println("hii");
            }
        }
        
        int size=s.size();
        int[][] ans=new int[size][2];
        int j=0;
        while(!s.isEmpty())
        {
            aksh temp=s.pop();
            ans[j][0]=temp.x;
            ans[j][1]=temp.y;
            j++;
        }  
        
    }

    static boolean pal(String s)
    {
      int n=s.length();
      int l=0;
      int r=n-1;
      int flag=0;
      while(l<r)
      {
        if(s.charAt(l)==s.charAt(r))
        {
          l++;
          r--;
        }
        else
          {
            flag=1;
            break;
          }
      }

      if(flag==1)
        return false;
      else
        return true;
    }    

    public static void main(String args[] ) throws Exception 
    {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT */
        FastReader sc=new FastReader();
        int t=sc.nextInt();

        while(t-->0)
        {
          int n=sc.nextInt();
          int m=sc.nextInt();
          String s=sc.next();
          int[][] c=new int[26][n];

          for(int i=0;i<n;i++)
          {
            int x=s.charAt(i)-'a';
            if(i==0)
              c[x][0]=1;
            else
              for(int j=0;j<26;j++)
                {
                  c[j][i]+=c[j][i-1];
                  if(j==x)
                    c[j][i]+=1;
                }
          }

          int[] ans=new int[26];
          for(int i=0;i<m;i++)
          {
            int x=sc.nextInt()-1;
            for(int j=0;j<26;j++)
              ans[j]+=c[j][x];
          }

          for(int i=0;i<n;i++)
            ans[s.charAt(i)-'a']++;

          for(int i=0;i<26;i++)
          System.out.print(ans[i]+" ");
          
          System.out.println();



          



        }
        


       
    }
 }
