9
 8
 6
 4
 7
 5
 2

1  2  3  4  5  6  7  8 
2  4  6  8 11 13 15 17 
3  6 10 13 16 20 23 26 
4  8 13 17 22 26 31 35 
5 11 16 22 27 33 38 44 
6 13 20 26 33 40 46 53 
7 15 23 31 38 46 54 62 
8 17 26 35 44 53 62 71 
 1  2  3  4  5  6  7 
2  4  6 10 12 14 16 
3  6 11 14 17 22 25 
4 10 14 20 24 30 34 
5 12 17 24 31 36 43 
6 14 22 30 36 44 52 
7 16 25 34 43 52 61 
 1  2  3  4  5 
2  4 10 12 14 
3 10 13 20 23 
4 12 20 24 32 
5 14 23 32 41 
 1  2  3 
2 10 12 
3 12 21 
 1  2  3  4  5  6 
2  4  6 11 13 15 
3  6 12 15 21 24 
4 11 15 22 26 33 
5 13 21 26 34 42 
6 15 24 33 42 51 
 1  2  3  4 
2  4 11 13 
3 11 14 22 
4 13 22 31 
 1 

#include <bits/stdc++.h>
using namespace std;
long long int inline power(long long int a, long long int b, long long int p) {
  a %= p;
  long long int ans = 1;
  while (b > 0) {
    if (b & 1) ans = (ans * a) % p;
    a = (a * a) % p;
    b >>= 1;
  }
  return ans;
}
long long int inv(long long int n, long long int p) {
  return power(n, p - 2, p);
}
bool inline isprime(long long int n) {
  if (n <= 1) return false;
  if (n <= 3) return true;
  if (n % 2 == 0 || n % 3 == 0) return false;
  for (long long int i = 5; i * i <= n; i = i + 6)
    if (n % i == 0 || n % (i + 2) == 0) return false;
  return true;
}
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
  long long int n, i, j;
  cin >> n;
  long long int a[n + 1][n + 1];
  for (i = 0; i < n + 1; i++) {
    for (j = 0; j < n + 1; j++) a[i][j] = 0;
  }
  for (i = 1; i < n; i++) {
    for (j = 1; j < n; j++) a[i][j] = i * j;
  }
  for (i = 1; i < n; i++) {
    for (j = 1; j < n; j++) cout << a[i][j] << " ";
    cout << "\n";
  }
  return 0;
}
