#include <bits/stdc++.h>

using namespace std;

typedef unsigned uint;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ldbl;
typedef pair<int, int> pii;
typedef pair<uint, uint> puu;
typedef pair<ll, ll> pll;
typedef pair<ull, ull> pull;
typedef pair<double, double> pdd;
typedef vector<int> vi;
typedef vector<uint> vu;
typedef vector<ll> vll;
typedef vector<ull> vull;
typedef vector<pii> vpii;
typedef vector<puu> vpuu;
typedef vector<pll> vpll;
typedef vector<pull> vpull;
typedef vector<string> vstr;
typedef vector<double> vdbl;
typedef vector<ldbl> vldbl;
#define pb push_back
#define ppb pop_back
#define pfr push_front
#define ppfr pop_front
#define emp emplace
#define empb emplace_back
#define be begin
#define rbe rbegin
#define all(x) (x).be(), (x).end()
#define rall(x) (x).rbe(), (x).rend()
#define fir first
#define sec second
#define mkp make_pair
#define brif(cond) if (cond) break
#define ctif(cond) if (cond) continue
#define retif(cond) if (cond) return
void canhazfast() {ios_base::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);}
template<typename T> T gcd(T a, T b) {return b ? gcd(b, a%b) : a;}
template<typename T> T extgcd(T a, T b, T &x, T &y)
{
    T x0 = 1, y0 = 0, x1 = 0, y1 = 1;
    while (b) {
        T q = a/b; a %= b; swap(a, b);
        x0 -= q*x1; swap(x0, x1);
        y0 -= q*y1; swap(y0, y1);
    }
    x = x0; y = y0; return a;
}
int ctz(uint x) {return __builtin_ctz(x);}
int ctzll(ull x) {return __builtin_ctzll(x);}
int clz(uint x) {return __builtin_clz(x);}
int clzll(ull x) {return __builtin_clzll(x);}
int popcnt(uint x) {return __builtin_popcount(x);}
int popcntll(ull x) {return __builtin_popcountll(x);}
int bsr(uint x) {return 31^clz(x);}
int bsrll(ull x) {return 63^clzll(x);}

#define N 200016

int a[N];
pair<ll, int> hi[N];

void solve()
{
    int n, m, k = 0;
    ll sum = 0, smx = 0;

    cin >> n >> m;
    for (int i = 0; i < n; ++i) {
        cin >> a[i];
        sum += a[i];
        if (smx < sum) {
            smx = sum;
            hi[k++] = mkp(sum, i);
        }
    }
    for (; m; --m) {
        int x;
        ll ans = 0;
        cin >> x;
        if (x > smx) {
            if (sum <= 0) {
                cout << "-1 ";
                continue;
            }
            ll d = x-smx;
            int q = (d-1)/sum+1;
            ans = (ll)q*n;
            x -= q*sum;
        }
        ans += lower_bound(hi, hi+k, mkp((ll)x, 0))->sec;
        cout << ans << ' ';
    }
    cout << '\n';
}

int main()
{
    canhazfast();

    int t;
    cin >> t;
    for (; t; --t) solve();

    return 0;
}
