YouKn0wWho has an integer sequence a_1, a_2, … a_n. Now he will split the sequence a into one or more consecutive subarrays so that each element of a belongs to exactly one subarray. Let k be the number of resulting subarrays, and h_1, h_2, …, h_k be the lengths of the longest increasing subsequences of corresponding subarrays.

For example, if we split [2, 5, 3, 1, 4, 3, 2, 2, 5, 1] into [2, 5, 3, 1, 4], [3, 2, 2, 5], [1], then h = [3, 2, 1].

YouKn0wWho wonders if it is possible to split the sequence a in such a way that the [bitwise XOR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of h_1, h_2, …, h_k is equal to 0. You have to tell whether it is possible.

The longest increasing subsequence (LIS) of a sequence b_1, b_2, …, b_m is the longest sequence of valid indices i_1, i_2, …, i_k such that i_1 < i_2 < … < i_k and b_{i_1} < b_{i_2} < … < b_{i_k}. For example, the LIS of [2, 5, 3, 3, 5] is [2, 3, 5], which has length 3.

An array c is a subarray of an array b if c can be obtained from b by deletion of several (possibly, zero or all) elements from the beginning and several (possibly, zero or all) elements from the end.

Input

The first line contains a single integer t (1 ≤ t ≤ 10 000) — the number of test cases.

The first line of each test case contains a single integer n (2 ≤ n ≤ 10^5).

The second line of each test case contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^9).

It is guaranteed that the sum of n over all test cases doesn't exceed 3 ⋅ 10^5.

Output

For each test case, print "YES" (without quotes) if it is possible to split into subarrays in the desired way, print "NO" (without quotes) otherwise. You can print each letter in any register (upper or lower).

Example

Input


4
7
1 3 4 2 2 1 5
3
1 3 4
5
1 3 2 4 2
4
4 3 2 1


Output


YES
NO
YES
YES

Note

In the first test case, YouKn0wWho can split the sequence in the following way: [1, 3, 4], [2, 2], [1, 5]. This way, the LIS lengths are h = [3, 1, 2], and the bitwise XOR of the LIS lengths is 3 ⊕ 1 ⊕ 2 = 0.

In the second test case, it can be shown that it is impossible to split the sequence into subarrays that will satisfy the condition.
/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
public class Codechef
{static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() 
        { 
            br = new BufferedReader(new
                     InputStreamReader(System.in)); 
        } 
  
        String next() 
        { 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
  
        int nextInt() 
        { 
            return Integer.parseInt(next()); 
        } 
  
        long nextLong() 
        { 
            return Long.parseLong(next()); 
        } 
  
        double nextDouble() 
        { 
            return Double.parseDouble(next()); 
        } 
  
        String nextLine() 
        { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    } 
//    static int mod = 998244353 ;
//    static int N = 200005;
//    static long factorial_num_inv[] = new long[N+1];
//    static long natual_num_inv[] = new long[N+1];
//    static long fact[] = new long[N+1];
//    static void InverseofNumber() 
//{ 
//    natual_num_inv[0] = 1;
//    natual_num_inv[1] = 1; 
//    for (int i = 2; i <= N; i++) 
//        natual_num_inv[i] = natual_num_inv[mod % i] * (mod - mod / i) % mod; 
//} 
//static void InverseofFactorial() 
//{ 
//    factorial_num_inv[0] = factorial_num_inv[1] = 1; 
  
//    for (int i = 2; i <= N; i++) 
//        factorial_num_inv[i] = (natual_num_inv[i] * factorial_num_inv[i - 1]) % mod; 
//} 
//static long nCrModP(long N, long R) 
//{ 
//    long ans = ((fact[(int)N] * factorial_num_inv[(int)R]) % mod * factorial_num_inv[(int)(N - R)]) % mod; 
//    return ans%mod; 
//}
    //static boolean prime[];
    //static void sieveOfEratosthenes(int n)
    //{
    //    prime = new boolean[n+1];
        
    //    for (int i = 0; i <= n; i++)
    //        prime[i] = true;
 
    //    for (int p = 2; p * p <= n; p++)
    //    {
    //        // If prime[p] is not changed, then it is a
    //        // prime
    //        if (prime[p] == true)
    //        {
    //            // Update all multiples of p
    //            for (int i = p * p; i <= n; i += p)
    //                prime[i] = false;
    //        }
    //    }
 
        
    //}
    
	public static void main (String[] args) throws java.lang.Exception
	{
    //    InverseofNumber();
    //    InverseofFactorial();
    //   fact[0] = 1; 
    //   for (long i = 1; i <= 2*100000; i++)
    //   { 
    //       fact[(int)i] = (fact[(int)i - 1] * i) % mod; 
    //   }
    
		FastReader scan = new FastReader();
		PrintWriter pw = new PrintWriter(System.out);
        int t = scan.nextInt();
        while(t-->0){
            int n= scan.nextInt();
            int a[] = new int[n];
            for(int i=0;i<n;i++){
                a[i] = scan.nextInt();           
            }
            if(n%2==0){
                pw.println("YES");
            }
            else{
            int i=0;
            for(i = 1;i<n;i++){
                if(a[i]<=a[i-1])
                break;
            }
            if(i==n){
                pw.println("NO");
            }
            else{
                pw.println("YES");
            }
        }
            pw.flush();
        }
    }
    //static long bin_exp_mod(long a,long n){
	   
	//    long res = 1;
	   
	//    if(a==0)
	//    return 0;
	//    while(n!=0){
	//        if(n%2==1){
	//            res = ((res)*(a));
	//        }
	//           n = n/2;
	//            a = ((a)*(a));
	//    }
	   
	//    return res;
	//}
//   static long gcd(long a,long b){
//       if(a==0)
//       return b;
//       return gcd(b%a,a);
//   }
//   static long lcm(long a,long b){
//       return (a/gcd(a,b))*b;
//   }
}
//class Pair{
//    Integer x,y;
//    Pair(int x,int y){
//        this.x = x;
//        this.y = y;
//    }
//    public boolean equals(Object obj) {
//        // TODO Auto-generated method stub
//        if(obj instanceof Pair)
//        {
//            Pair temp = (Pair) obj;
//            if(this.x.equals(temp.x) && this.y.equals(temp.y))
//                return true;
//        }
//        return false;
//    }

//    @Override
//    public int hashCode() {
//        // TODO Auto-generated method stub
        
//        return (this.x.hashCode() + this.y.hashCode());        
//    }
//}
//class Compar implements Comparator<Pair>{
//    public int compare(Pair p1,Pair p2){
//        return p1.x-p2.x;
//    }
//}
