You are given an array of integers a of length n. The elements of the array can be either different or the same. 

Each element of the array is colored either blue or red. There are no unpainted elements in the array. One of the two operations described below can be applied to an array in a single step:

  * either you can select any blue element and decrease its value by 1; 
  * or you can select any red element and increase its value by 1. 



Situations in which there are no elements of some color at all are also possible. For example, if the whole array is colored blue or red, one of the operations becomes unavailable.

Determine whether it is possible to make 0 or more steps such that the resulting array is a permutation of numbers from 1 to n?

In other words, check whether there exists a sequence of steps (possibly empty) such that after applying it, the array a contains in some order all numbers from 1 to n (inclusive), each exactly once.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of input data sets in the test.

The description of each set of input data consists of three lines. The first line contains an integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the length of the original array a. The second line contains n integers a_1, a_2, ..., a_n (-10^9 ≤ a_i ≤ 10^9) — the array elements themselves.

The third line has length n and consists exclusively of the letters 'B' and/or 'R': ith character is 'B' if a_i is colored blue, and is 'R' if colored red.

It is guaranteed that the sum of n over all input sets does not exceed 2 ⋅ 10^5.

Output

Print t lines, each of which contains the answer to the corresponding test case of the input. Print YES as an answer if the corresponding array can be transformed into a permutation, and NO otherwise.

You can print the answer in any case (for example, the strings yEs, yes, Yes, and YES will be recognized as a positive answer).

Example

Input


8
4
1 2 5 2
BRBR
2
1 1
BB
5
3 1 4 2 5
RBRRB
5
3 1 3 1 3
RBRRB
5
5 1 5 1 5
RBRRB
4
2 2 2 2
BRBR
2
1 -2
BR
4
-2 -1 4 0
RRRR


Output


YES
NO
YES
YES
NO
YES
YES
YES

Note

In the first test case of the example, the following sequence of moves can be performed:

  * choose i=3, element a_3=5 is blue, so we decrease it, we get a=[1,2,4,2]; 
  * choose i=2, element a_2=2 is red, so we increase it, we get a=[1,3,4,2]; 
  * choose i=3, element a_3=4 is blue, so we decrease it, we get a=[1,3,3,2]; 
  * choose i=2, element a_2=2 is red, so we increase it, we get a=[1,4,3,2]. 



We got that a is a permutation. Hence the answer is YES.
import java.util.*;

import java.io.*;
import java.math.*;


/**
 * @author Naitik
 * 
 */
public class Main

{ 
	 static FastReader sc=new FastReader(); 
	 static int dp[][][];
	 //static int v[][];
	 static int mod=998244353;;
//	 static int mod=1000000007;
	 static long max;
	 static long bit[];
	 //static long bit1[];
//	 static long seg[];
	 //static long fact[];
//	 static long A[];
	// static TreeMap<Integer,Integer> map;
	 //static StringBuffer sb=new StringBuffer("");
	 static TreeMap<Long,Integer> map;
	   static PrintWriter out=new PrintWriter(System.out);
	   
	  public static void main(String[] args)
	  {
		 //  StringBuffer sb=new StringBuffer("");
		  int ttt=1;
		      ttt =i();			   
	        outer :while (ttt-- > 0) 
			{
	        	int n=i();
	        	int A[]=input(n);
	        	char B[]=s().toCharArray();
	        	for(int i=0;i<n;i++) {
	        		if(A[i]<1 && B[i]=='B') {
	        			System.out.println("NO");
	        			continue outer;
	        		}
	        		if(A[i]>n && B[i]=='R') {
	        			System.out.println("NO");
	        			continue outer;
	        		}
	        		
	        	}
	        	PriorityQueue<Integer> q1=new PriorityQueue<Integer>();
	        	PriorityQueue<Integer> q2=new PriorityQueue<Integer>();
	        	for(int i=0;i<n;i++) {
	        		if(B[i]=='R') {
	        			q1.add(A[i]);
	        		}
	        		else {
	        			q2.add(A[i]);
	        		}
	        	}
	        	for(int i=1;i<=n;i++) {
	        		if(q1.isEmpty()) {
	        			int p=q2.peek();
	        			if(p<i) {
	        				System.out.println("NO");
	        				continue outer;
	        			}
	        			q2.remove();
	        			continue;
	        		}
	        		if(q2.isEmpty()) {
	        			int p=q1.peek();
	        			if(p>i) {
	        				System.out.println("NO");
	        				continue outer;
	        			}
	        			q1.remove();
	        			continue;
	        		}
	        		int p1=q1.peek();
	        		int p2=q2.peek();
	        		if(p1>i && p2<i) {
	        			System.out.println("NO");
	        			continue outer;
	        		}
	        		if(p2>=i) {
	        			q2.remove();
	        		}
	        		else {
	        			q1.remove();
	        		}
	        	}
	        	System.out.println("YES");

	        	
	        	
	  
	        	
	        }
	        //System.out.println(sb.toString());
		     out.close();
	     
	     
	    //CHECK FOR N=1                    //CHECK FOR M=0
        //CHECK FOR N=1                    //CHECK FOR M=0
       	//CHECK FOR N=1
       	
		        
		     
    } 
 
	
static class Pair implements Comparable<Pair>
     {
    	 long x;
    	 int y;
    	 int z;
    	 Pair(long x,int y){
    		 this.x=x;
    		 this.y=y;
    		// this.z=z;
    		 
    	 }
		@Override
		public int compareTo(Pair o) {
			if(this.x>o.x)
				return +1;
			else if(this.x<o.x)
				return -1;
			else {
				if(this.y>o.y)
					return 1;
				else if(this.y<o.y)
					return -1;
				else
					return 0;
			}
		}
//		public int hashCode() 
//		{ 
//			final int temp = 14; 
//			int ans = 1; 
//			ans =x*31+y*13; 
//			return ans; 
//		} 
//		@Override
//		public boolean equals(Object o) 
//		{ 
//			if (this == o) { 
//				return true; 
//			} 
//			if (o == null) { 
//				return false; 
//			} 
//			if (this.getClass() != o.getClass()) { 
//				return false; 
//			} 
//			Pair other = (Pair)o; 
//			if (this.x != other.x || this.y!=other.y) { 
//				return false; 
//			} 
//			return true; 
//		} 	
//		
		/* FOR TREE MAP PAIR USE */
		
//		public int compareTo(Pair o) {
// 			if (x > o.x) {
// 				return 1;
// 			}
// 			if (x < o.x) {
// 				return -1;
// 			}
// 			if (y > o.y) {
// 				return 1;
// 			}
// 			if (y < o.y) {
// 				return -1;
// 			}
// 			return 0;
// 		}
		
     }

//static int find(int A[],int a) {
//	  if(A[a]<0)
//		  return a;
//	  return A[a]=find(A, A[a]);
//}
static int find(int A[],int a) {
	  if(A[a]==a)
		  return a;
	  return find(A, A[a]);
}
//FENWICK TREE
static void update(int i, int x){
	for(; i < bit.length; i += (i&-i))
		bit[i] += x;
}

static int sum(int i){
	int ans = 0;
	for(; i > 0; i -= (i&-i))
		ans += bit[i];
	return ans;
}
//END
static void add(long v) {
	if(!map.containsKey(v)) {
		map.put(v, 1);
	}
	else {
		map.put(v, map.get(v)+1);
	}
}
static void remove(long v) {
	if(map.containsKey(v)) {
		map.put(v, map.get(v)-1);
		if(map.get(v)==0)
			map.remove(v);
	}
}
public static int upper(int A[],int k,int si,int ei)
{
	int l=si;
	int u=ei;
	int ans=-1;
	while(l<=u) {
		int mid=(l+u)/2;
		if(A[mid]<=k) {
			ans=mid;
			l=mid+1;
		}
		else {
			u=mid-1;
		}
	}
	return ans;
}
public static int lower(int A[],int k,int si,int ei)
{
	int l=si;
	int u=ei;
	int ans=-1;
	while(l<=u) {
		int mid=(l+u)/2;
		if(A[mid]<=k) {
			l=mid+1;
		}
		else {
			ans=mid;
			u=mid-1;
		}
	}
	return ans;
	
    
}
static int[] copy(int A[]) {
	int B[]=new int[A.length];
	for(int i=0;i<A.length;i++) {
		B[i]=A[i];
	}
	return B;
}
static long[] copy(long A[]) {
	long B[]=new long[A.length];
	for(int i=0;i<A.length;i++) {
		B[i]=A[i];
	}
	return B;
}
static int[] input(int n) {
	int A[]=new int[n];
	   for(int i=0;i<n;i++) {
		   A[i]=sc.nextInt();
	   }
	   return A;
   }
static long[] inputL(int n) {
	long A[]=new long[n];
	   for(int i=0;i<n;i++) {
		   A[i]=sc.nextLong();
	   }
	   return A;
   }
static String[] inputS(int n) {
	String A[]=new String[n];
	   for(int i=0;i<n;i++) {
		   A[i]=sc.next();
	   }
	   return A;
   }
static long sum(int A[]) {
	long sum=0;
	for(int i : A) {
		sum+=i;
	}
	return sum;
}
static long sum(long A[]) {
	long sum=0;
	for(long i : A) {
		sum+=i;
	}
	return sum;
}
static void reverse(long A[]) {
	int n=A.length;
	long B[]=new long[n];
	for(int i=0;i<n;i++) {
		B[i]=A[n-i-1];
	}
	for(int i=0;i<n;i++)
		A[i]=B[i];
	
}
static void reverse(int A[]) {
	int n=A.length;
	int B[]=new int[n];
	for(int i=0;i<n;i++) {
		B[i]=A[n-i-1];
	}
	for(int i=0;i<n;i++)
		A[i]=B[i];
	
}
static void input(int A[],int B[]) {
	   for(int i=0;i<A.length;i++) {
		   A[i]=sc.nextInt();
		   B[i]=sc.nextInt();
	   }
}
static int[][] input(int n,int m){
	int A[][]=new int[n][m];
	for(int i=0;i<n;i++) {
		for(int j=0;j<m;j++) {
			A[i][j]=i();
		}
	}
	return A;
}
static char[][] charinput(int n,int m){
	char A[][]=new char[n][m];
	for(int i=0;i<n;i++) {
		String s=s();
		for(int j=0;j<m;j++) {
			A[i][j]=s.charAt(j);
		}
	}
	return A;
}
static int nextPowerOf2(int n)
{
    n--;
    n |= n >> 1;
    n |= n >> 2;
    n |= n >> 4;
    n |= n >> 8;
    n |= n >> 16;
    n++;
     
    return n;
}
static int highestPowerof2(int x)
{
   
    x |= x >> 1;
    x |= x >> 2;
    x |= x >> 4;
    x |= x >> 8;
    x |= x >> 16;
     
    return x ^ (x >> 1); 
 
}
static long highestPowerof2(long x)
{
   
    x |= x >> 1;
    x |= x >> 2;
    x |= x >> 4;
    x |= x >> 8;
    x |= x >> 16;
    return x ^ (x >> 1); 
 
}

static int max(int A[]) {
	int max=Integer.MIN_VALUE;
	for(int i=0;i<A.length;i++) {
		max=Math.max(max, A[i]);
	}
	return max;
}
static int min(int A[]) {
	int min=Integer.MAX_VALUE;
	for(int i=0;i<A.length;i++) {
		min=Math.min(min, A[i]);
	}
	return min;
}
static long max(long A[]) {
	long max=Long.MIN_VALUE;
	for(int i=0;i<A.length;i++) {
		max=Math.max(max, A[i]);
	}
	return max;
}
static long min(long A[]) {
	long min=Long.MAX_VALUE;
	for(int i=0;i<A.length;i++) {
		min=Math.min(min, A[i]);
	}
	return min;
}
static long [] prefix(long A[]) {
	long p[]=new long[A.length];
	p[0]=A[0];
	for(int i=1;i<A.length;i++)
		p[i]=p[i-1]+A[i];
	return p;
}
static long [] prefix(int A[]) {
	long p[]=new long[A.length];
	p[0]=A[0];
	for(int i=1;i<A.length;i++)
		p[i]=p[i-1]+A[i];
	return p;
}
static long [] suffix(long A[]) {
	long p[]=new long[A.length];
	p[A.length-1]=A[A.length-1];
	for(int i=A.length-2;i>=0;i--)
		p[i]=p[i+1]+A[i];
	return p;
}
static long [] suffix(int A[]) {
	long p[]=new long[A.length];
	p[A.length-1]=A[A.length-1];
	for(int i=A.length-2;i>=0;i--)
		p[i]=p[i+1]+A[i];
	return p;
}
static void fill(int dp[]) {
	Arrays.fill(dp, -1);
}
static void fill(int dp[][]) {
	for(int i=0;i<dp.length;i++)
	Arrays.fill(dp[i], -1);
}
static void fill(int dp[][][]) {
	for(int i=0;i<dp.length;i++) {
		for(int j=0;j<dp[0].length;j++) {
			Arrays.fill(dp[i][j],-1);
		}
	}
}
static void fill(int dp[][][][]) {
	for(int i=0;i<dp.length;i++) {
		for(int j=0;j<dp[0].length;j++) {
			for(int k=0;k<dp[0][0].length;k++) {
			Arrays.fill(dp[i][j][k],-1);
			}
		}
	}
}
static void fill(long dp[]) {
	Arrays.fill(dp, -1);
}
static void fill(long dp[][]) {
	for(int i=0;i<dp.length;i++)
	Arrays.fill(dp[i], -1);
}
static void fill(long dp[][][]) {
	for(int i=0;i<dp.length;i++) {
		for(int j=0;j<dp[0].length;j++) {
			Arrays.fill(dp[i][j],-1);
		}
	}
}
static void fill(long dp[][][][]) {
	for(int i=0;i<dp.length;i++) {
		for(int j=0;j<dp[0].length;j++) {
			for(int k=0;k<dp[0][0].length;k++) {
			Arrays.fill(dp[i][j][k],-1);
			}
		}
	}
}
static int min(int a,int b) {
	return Math.min(a, b);
}
static int min(int a,int b,int c) {
	return Math.min(a, Math.min(b, c));
}
static int min(int a,int b,int c,int d) {
	return Math.min(a, Math.min(b, Math.min(c, d)));
}
static int max(int a,int b) {
	return Math.max(a, b);
}
static int max(int a,int b,int c) {
	return Math.max(a, Math.max(b, c));
}
static int max(int a,int b,int c,int d) {
	return Math.max(a, Math.max(b, Math.max(c, d)));
}
static long min(long a,long b) {
	return Math.min(a, b);
}
static long min(long a,long b,long c) {
	return Math.min(a, Math.min(b, c));
}
static long min(long a,long b,long c,long d) {
	return Math.min(a, Math.min(b, Math.min(c, d)));
}
static long max(long a,long b) {
	return Math.max(a, b);
}
static long max(long a,long b,long c) {
	return Math.max(a, Math.max(b, c));
}
static long max(long a,long b,long c,long d) {
	return Math.max(a, Math.max(b, Math.max(c, d)));
}

static long power(long x, long y, long p)
{

	if(y==0)
		return 1;
	if(x==0)
		return 0;
    long res = 1;
    x = x % p;

    while (y > 0) {

        if (y % 2 == 1)
            res = (res * x) % p;

        y = y >> 1; 
        x = (x * x) % p;
    }

    return res;
}
static long power(long x, long y)
{

	if(y==0)
		return 1;
	if(x==0)
		return 0;
    long res = 1;

    while (y > 0) {

        if (y % 2 == 1)
            res = (res * x);

        y = y >> 1; 
        x = (x * x);
    }

    return res;
}
static void print(int A[]) {
	for(int i : A) {
		System.out.print(i+" ");
	}
	System.out.println();
}
static void print(long A[]) {
	for(long i : A) {
		System.out.print(i+" ");
	}
	System.out.println();
}
static long mod(long x) {
	  return ((x%mod + mod)%mod);
}
static String reverse(String s) {
	StringBuffer p=new StringBuffer(s);
	p.reverse();
	return p.toString();
}

     static int i() {
    	 return sc.nextInt();
     }
     static String s() {
    	 return sc.next();
     }
     static long l() {
    	 return sc.nextLong();
     }  
     static void sort(int[] A){
        int n = A.length;
        Random rnd = new Random();
        for(int i=0; i<n; ++i){
            int tmp = A[i];
            int randomPos = i + rnd.nextInt(n-i);
            A[i] = A[randomPos];
            A[randomPos] = tmp;
        }
        Arrays.sort(A);
     }
     static void sort(long[] A){
	        int n = A.length;
	        Random rnd = new Random();
	        for(int i=0; i<n; ++i){
	            long tmp = A[i];
	            int randomPos = i + rnd.nextInt(n-i);
	            A[i] = A[randomPos];
	            A[randomPos] = tmp;
	        }
	        Arrays.sort(A);
	     }
  static String sort(String s) {
 	 Character ch[]=new Character[s.length()];
 	 for(int i=0;i<s.length();i++) {
 		 ch[i]=s.charAt(i);
 	 }
 	 Arrays.sort(ch);
 	 StringBuffer st=new StringBuffer("");
 	 for(int i=0;i<s.length();i++) {
 		 st.append(ch[i]);
 	 }
 	 return st.toString();
  }
  static HashMap<Integer,Integer> hash(int A[]){
	  HashMap<Integer,Integer> map=new HashMap<Integer, Integer>();
	  for(int i : A) {
		  if(map.containsKey(i)) {
			  map.put(i, map.get(i)+1);
		  }
		  else {
			  map.put(i, 1);
		  }
	  }
	  return map;
  }
  static HashMap<Long,Integer> hash(long A[]){
	  HashMap<Long,Integer> map=new HashMap<Long, Integer>();
	  for(long i : A) {
		  if(map.containsKey(i)) {
			  map.put(i, map.get(i)+1);
		  }
		  else {
			  map.put(i, 1);
		  }
	  }
	  return map;
  }
  static TreeMap<Integer,Integer> tree(int A[]){
	  TreeMap<Integer,Integer> map=new TreeMap<Integer, Integer>();
	  for(int i : A) {
		  if(map.containsKey(i)) {
			  map.put(i, map.get(i)+1);
		  }
		  else {
			  map.put(i, 1);
		  }
	  }
	  return map;
  }
  static TreeMap<Long,Integer> tree(long A[]){
	  TreeMap<Long,Integer> map=new TreeMap<Long, Integer>();
	  for(long i : A) {
		  if(map.containsKey(i)) {
			  map.put(i, map.get(i)+1);
		  }
		  else {
			  map.put(i, 1);
		  }
	  }
	  return map;
  }
     static boolean prime(int n) 
	    { 
	        if (n <= 1) 
	            return false; 
	        if (n <= 3) 
	            return true; 
	        if (n % 2 == 0 || n % 3 == 0) 
	            return false; 
	        double sq=Math.sqrt(n);
	  
	        for (int i = 5; i <= sq; i = i + 6) 
	            if (n % i == 0 || n % (i + 2) == 0) 
	                return false; 
	        return true; 
	    } 
     static boolean prime(long n) 
	    { 
	        if (n <= 1) 
	            return false; 
	        if (n <= 3) 
	            return true; 
	        if (n % 2 == 0 || n % 3 == 0) 
	            return false; 
	        double sq=Math.sqrt(n);
	  
	        for (int i = 5; i <= sq; i = i + 6) 
	            if (n % i == 0 || n % (i + 2) == 0) 
	                return false; 
	        return true; 
	    } 
     static int gcd(int a, int b) 
     { 
         if (a == 0) 
             return b; 
         return gcd(b % a, a); 
     } 
     static long gcd(long a, long b) 
     { 
         if (a == 0) 
             return b; 
         return gcd(b % a, a); 
     } 
     
        
    static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() 
        { 
            br = new BufferedReader(new
                     InputStreamReader(System.in)); 
        } 
  
        String next() 
        { 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
  
        int nextInt() 
        { 
            return Integer.parseInt(next()); 
        } 
  
        long nextLong() 
        { 
            return Long.parseLong(next()); 
        } 
  
        double nextDouble() 
        { 
            return Double.parseDouble(next()); 
        } 
  
        String nextLine() 
        { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    } 
} 



