YouKn0wWho has two even integers x and y. Help him to find an integer n such that 1 ≤ n ≤ 2 ⋅ 10^{18} and n mod x = y mod n. Here, a mod b denotes the remainder of a after division by b. If there are multiple such integers, output any. It can be shown that such an integer always exists under the given constraints.

Input

The first line contains a single integer t (1 ≤ t ≤ 10^5) — the number of test cases.

The first and only line of each test case contains two integers x and y (2 ≤ x, y ≤ 10^9, both are even).

Output

For each test case, print a single integer n (1 ≤ n ≤ 2 ⋅ 10^{18}) that satisfies the condition mentioned in the statement. If there are multiple such integers, output any. It can be shown that such an integer always exists under the given constraints.

Example

Input


4
4 8
4 2
420 420
69420 42068


Output


4
10
420
9969128

Note

In the first test case, 4 mod 4 = 8 mod 4 = 0.

In the second test case, 10 mod 4 = 2 mod 10 = 2.

In the third test case, 420 mod 420 = 420 mod 420 = 0.
1
1000000000 1000000000

1000000000 

from __future__ import division, print_function
import math
import sys
import os
from io import BytesIO, IOBase
#from collections import deque, Counter, OrderedDict, defaultdict
#import heapq
#ceil,floor,log,sqrt,factorial,pow,pi,gcd
#import bisect
#from bisect import bisect_left,bisect_right

BUFSIZE = 8192


class FastIO(IOBase):
	newlines = 0

	def __init__(self, file):
		self._fd = file.fileno()
		self.buffer = BytesIO()
		self.writable = "x" in file.mode or "r" not in file.mode
		self.write = self.buffer.write if self.writable else None

	def read(self):
		while True:
			b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
			if not b:
				break
			ptr = self.buffer.tell()
			self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
		self.newlines = 0
		return self.buffer.read()

	def readline(self):
		while self.newlines == 0:
			b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
			self.newlines = b.count(b"\n") + (not b)
			ptr = self.buffer.tell()
			self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
		self.newlines -= 1
		return self.buffer.readline()

	def flush(self):
		if self.writable:
			os.write(self._fd, self.buffer.getvalue())
			self.buffer.truncate(0), self.buffer.seek(0)


class IOWrapper(IOBase):
	def __init__(self, file):
		self.buffer = FastIO(file)
		self.flush = self.buffer.flush
		self.writable = self.buffer.writable
		self.write = lambda s: self.buffer.write(s.encode("ascii"))
		self.read = lambda: self.buffer.read().decode("ascii")
		self.readline = lambda: self.buffer.readline().decode("ascii")


def print(*args, **kwargs):
	"""Prints the values to a stream, or to sys.stdout by default."""
	sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
	at_start = True
	for x in args:
		if not at_start:
			file.write(sep)
		file.write(str(x))
		at_start = False
	file.write(kwargs.pop("end", "\n"))
	if kwargs.pop("flush", False):
		file.flush()


if sys.version_info[0] < 3:
	sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
	sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)

input = lambda: sys.stdin.readline().rstrip("\r\n")

def I():
    return(int(input()))
def lint():
    return(list(map(int,input().split())))
def insr():
    s = input().strip()
    return(list(s[:len(s)]))
def invr():
    return(map(int,input().split()))
import itertools
from sys import maxsize, stdout, stdin,stderr
mod = int(1e9+7)
import sys
# def I(): return int(stdin.readline())
# def lint(): return [int(x) for x in stdin.readline().split()]
def S(): return list(map(str,input().strip()))
def grid(r, c): return [lint() for i in range(r)]
from collections import defaultdict, Counter, deque
import math
import heapq
from heapq import heappop , heappush
import bisect
from math import factorial, inf
from itertools import groupby
from itertools import permutations as comb

mod=1000000007
MOD = 998244353
def gcd(a,b): 
    while b:
        a %= b
        tmp = a
        a = b
        b = tmp
    
    return a
 
def lcm(a,b): 
    return a  // gcd(a, b) * b
 
def check_prime(n):
    for i in range(2, int(n ** (1 / 2)) + 1):
        if not n % i:
            return False
    return True

# def nCr(n, r):
 
#     return (fact(n) // (fact(r)
#                 * fact(n - r)))
 
# Returns factorial of n
# def fact(n):
 
#     res = 1
     
#     for i in range(2, n+1):
#         res = res * i
         
#     return res
def primefactors(n):
    num=0
    
    while n % 2 == 0:
        num+=1
        n = n / 2
    
    for i in range(3,int(math.sqrt(n))+1,2):
         
    
        while n % i== 0:
            num+=1
            n = n // i
               
    
    if n > 2:
        num+=1
    return num
'''
def iter_ds(src):
    store=[src]
    while len(store):
        tmp=store.pop()
        if not vis[tmp]:
            vis[tmp]=True
            for j in ar[tmp]:
                store.append(j)
'''
def ask(a,b,c):
    # print('? 1 {}'.format(a),flush=True)
    print(c,a,b,flush=True)
    n=I()
    
    return n
def linear_sieve(n):
    is_composite=[False]*n
    prime=[]
    for i in range(2,n):
        if not is_composite[i]:
            prime.append(i)
        for j in prime:
            is_composite[i*j]=True
            if i%prime==0:
                break
    return prime
 
def dfs(i,p,d):
    
    a,tmp=0,0
    for j in d[i]:
        if j!=p:
            a+=1
            tmp+=dfs(j,i)
    
    if a==0:
        return 0
    
    return tmp/a + 1 
def primeFactors(n):
    l=[]
    
    while n % 2 == 0:
        l.append(2)
        n = n // 2
    for i in range(3,int(math.sqrt(n))+1,2):
         
        
        while n % i== 0:
            l.append(i)
            n = n // i

    if n > 2:
        l.append(n)
    return l

def binpow(a,b,c):
    res=1
    a=a%c
    while b>0:
        if b&1:
            res=(res*a)%c

        b=b>>1
        a = (a*a)%c

    return res


    

#  Sieve
d=[]
primes=[]
prim=[0]*(10**5+1)
def sieve(n):
    
    for i in range(n):
        d.append(i)

    for i in range(2,n):

        if d[i]==i:
            prim[i]=1
            primes.append(i)
        j=0
        while j<len(primes) and primes[j]<=d[i] and primes[j]*i<n:
        
            d[i * primes[j]] = primes[j]
            j+=1

        
def primeFactors(n):
    factors=[]
    while n!=1:
        factors.append(d[n])
        n//=d[n]
    
    return factors




         
# t = 1    
# t = I()
# for _ in range(t):
#     n = I()
#     s = lint()
#     flag=True
#     tmp=0
#     for i in range(n):
#         if s[i]%2==1:
#             tmp+=1
#         else:
#             flag=False
#             for j in range(tmp+1):
#                 if s[i]%(i+2+j)!=0:
#                     tmp+=1
#                     flag=True
#                     break
#             if not flag:
#                 break
#     if flag:
#         print("YES")
#     else:
#         print("NO")
        
        
t = I()
for _ in range(t):
    x,y=lint()
    if y%x==0:
        ans=x
    elif x%y==0:
        ans=x+y
    else:
        if x>y:
            ans=x+y
        else:
            if y>2*x:
                ans=y-x
            else:
                ans=(y+x)//2
    
    print(ans)       



        
    
 

