You are given an array of integers a of length n. The elements of the array can be either different or the same. 

Each element of the array is colored either blue or red. There are no unpainted elements in the array. One of the two operations described below can be applied to an array in a single step:

  * either you can select any blue element and decrease its value by 1; 
  * or you can select any red element and increase its value by 1. 



Situations in which there are no elements of some color at all are also possible. For example, if the whole array is colored blue or red, one of the operations becomes unavailable.

Determine whether it is possible to make 0 or more steps such that the resulting array is a permutation of numbers from 1 to n?

In other words, check whether there exists a sequence of steps (possibly empty) such that after applying it, the array a contains in some order all numbers from 1 to n (inclusive), each exactly once.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of input data sets in the test.

The description of each set of input data consists of three lines. The first line contains an integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the length of the original array a. The second line contains n integers a_1, a_2, ..., a_n (-10^9 ≤ a_i ≤ 10^9) — the array elements themselves.

The third line has length n and consists exclusively of the letters 'B' and/or 'R': ith character is 'B' if a_i is colored blue, and is 'R' if colored red.

It is guaranteed that the sum of n over all input sets does not exceed 2 ⋅ 10^5.

Output

Print t lines, each of which contains the answer to the corresponding test case of the input. Print YES as an answer if the corresponding array can be transformed into a permutation, and NO otherwise.

You can print the answer in any case (for example, the strings yEs, yes, Yes, and YES will be recognized as a positive answer).

Example

Input


8
4
1 2 5 2
BRBR
2
1 1
BB
5
3 1 4 2 5
RBRRB
5
3 1 3 1 3
RBRRB
5
5 1 5 1 5
RBRRB
4
2 2 2 2
BRBR
2
1 -2
BR
4
-2 -1 4 0
RRRR


Output


YES
NO
YES
YES
NO
YES
YES
YES

Note

In the first test case of the example, the following sequence of moves can be performed:

  * choose i=3, element a_3=5 is blue, so we decrease it, we get a=[1,2,4,2]; 
  * choose i=2, element a_2=2 is red, so we increase it, we get a=[1,3,4,2]; 
  * choose i=3, element a_3=4 is blue, so we decrease it, we get a=[1,3,3,2]; 
  * choose i=2, element a_2=2 is red, so we increase it, we get a=[1,4,3,2]. 



We got that a is a permutation. Hence the answer is YES.
import java.io.*;
import java.util.*;

public class CodeForces{
    /*-------------------------------------------EDITING CODE STARTS HERE-------------------------------------------*/
    public static void main(String[] args) throws IOException{
        openIO();
        int testCase = 1;
        testCase = sc.nextInt();
        preCompute();
        for (int i = 1; i <= testCase; i++) solve(i);
        closeIO();
    }

    public static void solve(int tCase)throws IOException {
        int n = sc.nextInt();
        int[] arr = new int[n];
        List<Integer> red = new ArrayList<>();
        List<Integer> blue = new ArrayList<>();
        for(int i=0;i<n;i++) {
            arr[i] = sc.nextInt();
        }
        char[] color = sc.next().toCharArray();
        for(int i=0;i<n;i++){
            if(color[i]=='R')red.add(arr[i]);
            else blue.add(arr[i]);
        }

        for(int i=0;i<2;i++)
            for(int j=0;j<2;j++){
                if(isPossible(red,blue,i,j,n)){
                    out.println("YES");
                    return;
                }
            }
        out.println("NO");

    }
    private static boolean isPossible(List<Integer> red,List<Integer> blue,int a,int bb,int n){
        if(a==0)Collections.sort(red);
        else red.sort(Collections.reverseOrder());
        if(bb==0)Collections.sort(blue);
        else blue.sort(Collections.reverseOrder());
        int r = 0;
        int b = 0;
        boolean isPossible = true;
//        for(int i=1;i<=n;i++){
//            if(r<red.size() && red.get(r) <=i)r++;
//            else if(b<blue.size() && blue.get(b) >=i)b++;
//            else {
//               isPossible = false;
//               break;
//            }
//        }
//        if(isPossible)return true;
        isPossible = true;
        r = 0;
        b = 0;
        for(int i=1;i<=n;i++){
            if(b<blue.size() && blue.get(b) >=i)b++;
            else if(r<red.size() && red.get(r) <=i)r++;
            else {
                isPossible = false;
                break;
            }
        }
        return isPossible;
    }


    private static void  preCompute(){

    }
    /*-------------------------------------------EDITING CODE ENDS HERE-------------------------------------------*/
    static FastestReader sc;
    static PrintWriter out;
    private static void openIO() throws IOException{
        sc = new FastestReader();
        out = new PrintWriter(System.out);
    }

    /*------------------------------------------HELPER FUNCTION STARTS HERE------------------------------------------*/

    public static final int mod = (int) 1e9 +7;
    private static final int mod2 =  998244353;
    public static final int inf_int = (int) 2e9;
    public static  final long inf_long = (long) 4e18;

    // euclidean algorithm time O(max (loga ,logb))
    public static long _gcd(long a, long b) {
        if (a == 0)
            return b;
        return _gcd(b % a, a);
    }

    public static long _lcm(long a, long b) {
        // lcm(a,b) * gcd(a,b) = a * b
        return (a / _gcd(a, b)) * b;
    }


    // binary exponentiation time O(logn)
    public static long _power(long x, long n) {
        long ans = 1;
        while (n > 0) {
            if ((n & 1) == 1) {
                ans *= x;
                ans %= mod;
                n--;
            } else {
                x *= x;
                x %= mod;
                n >>= 1;
            }
        }
        return ans;
    }
    //sieve/first divisor time : O(mx * log ( log (mx) ) )
    public static int[]  _seive(int mx){
        int[] firstDivisor = new int[mx+1];
        for(int i=0;i<=mx;i++)firstDivisor[i] = i;
        for(int i=2;i*i<=mx;i++)
            if(firstDivisor[i] == i)
                for(int j = i*i;j<=mx;j+=i)
                    firstDivisor[j] = i;
        return firstDivisor;
    }

    private static boolean _isPrime(long x){
        for(long i=2;i*i<=x;i++)
            if(x%i==0)return false;
        return true;
    }


    /*------------------------------------------HELPER FUNCTION ENDS HERE-------------------------------------------*/

    /*-------------------------------------------FAST INPUT STARTS HERE---------------------------------------------*/

    public static void closeIO() throws IOException{
        out.flush();
        out.close();
        sc.close();
    }
    private static final class FastestReader {
        private static final int BUFFER_SIZE = 1 << 16;
        private final DataInputStream din;
        private final byte[] buffer;
        private int bufferPointer, bytesRead;

        public FastestReader() {
            din = new DataInputStream(System.in);
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
        }

        public FastestReader(String file_name) throws IOException {
            din = new DataInputStream(new FileInputStream(file_name));
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
        }

        private static boolean isSpaceChar(int c) { return !(c >= 33 && c <= 126); }

        private int skip() throws IOException {
            int b;
            //noinspection StatementWithEmptyBody
            while ((b = read()) != -1 && isSpaceChar(b)) {}
            return b;
        }

        public String next() throws IOException {
            int b = skip();
            final StringBuilder sb = new StringBuilder();
            while (!isSpaceChar(b)) { // when nextLine, (isSpaceChar(b) && b != ' ')
                sb.appendCodePoint(b);
                b = read();
            }
            return sb.toString();
        }

        public int nextInt() throws IOException {
            int ret = 0;
            byte c = read();
            while (c <= ' ') {
                c = read();
            }
            final boolean neg = c == '-';
            if (neg) { c = read(); }
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');

            if (neg) { return -ret; }
            return ret;
        }

        public long nextLong() throws IOException {
            long ret = 0;
            byte c = read();
            while (c <= ' ') { c = read(); }
            final boolean neg = c == '-';
            if (neg) { c = read(); }
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');
            if (neg) { return -ret; }
            return ret;
        }

        public double nextDouble() throws IOException {
            double ret = 0, div = 1;
            byte c = read();
            while (c <= ' ') { c = read(); }
            final boolean neg = c == '-';
            if (neg) { c = read(); }

            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');

            if (c == '.') {
                while ((c = read()) >= '0' && c <= '9') {
                    ret += (c - '0') / (div *= 10);
                }
            }

            if (neg) { return -ret; }
            return ret;
        }

        private void fillBuffer() throws IOException {
            bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
            if (bytesRead == -1) { buffer[0] = -1; }
        }

        private byte read() throws IOException {
            if (bufferPointer == bytesRead) { fillBuffer(); }
            return buffer[bufferPointer++];
        }

        public void close() throws IOException {
            din.close();
        }
    }
    /*---------------------------------------------FAST INPUT ENDS HERE ---------------------------------------------*/
}