CQXYM is counting permutations length of 2n.

A permutation is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2,3,1,5,4] is a permutation, but [1,2,2] is not a permutation (2 appears twice in the array) and [1,3,4] is also not a permutation (n=3 but there is 4 in the array).

A permutation p(length of 2n) will be counted only if the number of i satisfying p_i<p_{i+1} is no less than n. For example:

  * Permutation [1, 2, 3, 4] will count, because the number of such i that p_i<p_{i+1} equals 3 (i = 1, i = 2, i = 3).
  * Permutation [3, 2, 1, 4] won't count, because the number of such i that p_i<p_{i+1} equals 1 (i = 3). 



CQXYM wants you to help him to count the number of such permutations modulo 1000000007 (10^9+7).

In addition, [modulo operation](https://en.wikipedia.org/wiki/Modulo_operation) is to get the remainder. For example:

  * 7 mod 3=1, because 7 = 3 ⋅ 2 + 1, 
  * 15 mod 4=3, because 15 = 4 ⋅ 3 + 3. 

Input

The input consists of multiple test cases. 

The first line contains an integer t (t ≥ 1) — the number of test cases. The description of the test cases follows.

Only one line of each test case contains an integer n(1 ≤ n ≤ 10^5).

It is guaranteed that the sum of n over all test cases does not exceed 10^5

Output

For each test case, print the answer in a single line.

Example

Input


4
1
2
9
91234


Output


1
12
830455698
890287984

Note

n=1, there is only one permutation that satisfies the condition: [1,2].

In permutation [1,2], p_1<p_2, and there is one i=1 satisfy the condition. Since 1 ≥ n, this permutation should be counted. In permutation [2,1], p_1>p_2. Because 0<n, this permutation should not be counted.

n=2, there are 12 permutations: [1,2,3,4],[1,2,4,3],[1,3,2,4],[1,3,4,2],[1,4,2,3],[2,1,3,4],[2,3,1,4],[2,3,4,1],[2,4,1,3],[3,1,2,4],[3,4,1,2],[4,1,2,3].
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.*;

public class Practice {
	public static long mod = (long) Math.pow(10, 9) + 7;
	public static long mod2 = 998244353;
	public static int tt = 1;
	public static ArrayList<Integer> prime;

	public static void main(String[] args) throws Exception {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		PrintWriter pw = new PrintWriter(System.out);
		int t = Integer.parseInt(br.readLine());

		while (t-- > 0) {
			String[] s1 = br.readLine().split(" ");
			int n = Integer.valueOf(s1[0]);
			long ans = 1;
			for (int i = 1; i <= 2 * n; i++) {
				ans = (ans * i) % mod;
			}
			ans = (ans * (power(2, mod - 2))) % mod;
			pw.println(ans);
		}
		pw.close();
	}

	private static long power(long a, long p) {
		// TODO Auto-generated method stub
		long res = 1;
		while (p > 0) {
			if (p % 2 == 1) {
				res = (res * a) % mod;
			}
			p = p / 2;
			a = (a * a) % mod;
		}
		return res;
	}
}

//	private static void getFac(long n, PrintWriter pw) {
//		// TODO Auto-generated method stub
//		int a = 0;
//		while (n % 2 == 0) {
//			a++;
//			n = n / 2;
//		}
//		if (n == 1) {
//			a--;
//		}
//		for (int i = 3; i <= Math.sqrt(n); i += 2) {
//			while (n % i == 0) {
//				n = n / i;
//				a++;
//			}
//		}
//		if (n > 1) {
//			a++;
//		}
//		if (a % 2 == 0) {
//			pw.println("Bob");
//		} else {
//			pw.println("Alice");
//		}
//		//System.out.println(a);
//		return;
//	}

//	private static long power(long a, long p) {
//		// TODO Auto-generated method stub
//		long res = 1;
//		while (p > 0) {
//			if (p % 2 == 1) {
//				res = (res * a) % mod;
//			}
//			p = p / 2;
//			a = (a * a) % mod;
//		}
//		return res;
//	}
//
//	private static void fac() {
//		fac[0] = 1;
//		// TODO Auto-generated method stub
//		for (int i = 1; i < fac.length; i++) {
//			if (i == 1) {
//				fac[i] = 1;
//			} else {
//				fac[i] = i * fac[i - 1];
//			}
//			if (fac[i] > mod) {
//				fac[i] = fac[i] % mod;
//			}
//		}
//	}
//
//	private static int getLower(Long long1, Long[] st) {
//		// TODO Auto-generated method stub
//		int left = 0, right = st.length - 1;
//		int ans = -1;
//		while (left <= right) {
//			int mid = (left + right) / 2;
//			if (st[mid] <= long1) {
//				ans = mid;
//				left = mid + 1;
//			} else {
//				right = mid - 1;
//			}
//		}
//		return ans;
//	}

//	private static long getGCD(long l, long m) {
//
//		long t1 = Math.min(l, m);
//		long t2 = Math.max(l, m);
//		while (true) {
//			long temp = t2 % t1;
//			if (temp == 0) {
//				return t1;
//			}
//			t2 = t1;
//			t1 = temp;
//		}
//	}