function RxBrioUtils.toBrio()return Rx.map(function(H)if Brio.isBrio(H)then return H end return Brio.new(H)end)end
--[=[
	Takes a result and converts it to a brio if it is not one.

	@return (source: Observable<Brio<T> | T>) -> Observable<Brio<T>>
]=]
function RxBrioUtils.toBrio()
	return Rx.map(function(result)
		if Brio.isBrio(result) then
			return result
		end

		return Brio.new(result)
	end)
end
