+= n / i;  return count;}[Original Python] =def count_trailing_zeroes_factorial_number(n):cnt = 0i = 5while ((n / i) >= 1):        cnt = (cnt + (n / i))        i *= 5return cnt[Simple Feedback] =The above Python translation does not do the same thing as the C++ code. Correct the Python translation.[UT Feedback] = The Python translation does not do the same thing as the C++ code. These are the results of failed unit tests that test whether the Python translation's outputs match the C++ program's outputs:Failed: assert count_trailing_zeroes_factorial_number(9) == 1Actual Result: 1.8Correct the translation.[Revised Python #n] = def count_trailing_zeroes_factorial_number(n):cnt = 0i = 5while ((n / i) >= 1):        cnt = (cnt + (n // i))        i *= 5return cnt[C++ Explanation] =The code is an implementation of counting the number of trailing zeroes in the factorial of a given number.int count = 0;The variable count is used to record the number of trailing zeroes.for ( int i = 5; n / i >=
Teaching Large Language Models to Self-Debug