Assistant: Here is a solution that assumes the filename is salaries.csv.

def max_salary(filename):

rows = DictReader(Path(filename).read_text().splitlines())
max_index = -1
for i, row in enumerate(rows):

if int(row[’Salary’]) > int(rows[max_index][’Salary’]):

max_index = i

return rows[max_index][’Name’]

print(max_salary(’salaries.csv’))
‘‘‘
-----

Human: What is the purpose of the code below ?

50

‘‘‘
def f(n, p):
if p == 0:

return 1

else :

return n*f(n, p-1)

-----

to 1 modulo 6.

‘‘‘
Assistant: This python function is designed to raise a base value n to a power p, that

is, computing the value nˆp where p is a positive integer.

Human: Write a program that returns the prime numbers less than 1000 that are congruent

Assistant : The method I will adopt to solve this problem is to go through all the
StarCoder_paper (1)