A railroad running from west to east in Atcoder Kingdom is now complete.  There are N stations on the railroad, numbered 1 through N from west to east.  Tomorrow, the opening ceremony of the railroad will take place.  On this railroad, for each integer i such that 1≤i≤N-1, there will be trains that run from Station i to Station i+1 in C_i seconds. No other trains will be operated.  The first train from Station i to Station i+1 will depart Station i S_i seconds after the ceremony begins. Thereafter, there will be a train that departs Station i every F_i seconds.  Here, it is guaranteed that F_i divides S_i.  That is, for each Time t satisfying S_i≤t and t％F_i=0, there will be a train that departs Station i t seconds after the ceremony begins and arrives at Station i+1 t+C_i seconds after the ceremony begins, where A％B denotes A modulo B, and there will be no other trains.  For each i, find the earliest possible time we can reach Station N if we are at Station i when the ceremony begins, ignoring the time needed to change trains.
N = int(input())
ans = [0 for i in range(N)]

for i in range(N-1):
  C, S, F = map(int, input().split())
  for j in range(0, i+1):
    if ans[j] < S:
      ans[j] += S - ans[j]
    else:
      ans[j] += F - (ans[j]-S)%F
    ans[j] += C
    
for i in ans:
  print(i)


N = int(input())
ans = [0 for i in range(N)]

for i in range(N-1):
  C, S, F = map(int, input().split())
  for j in range(0, i+1):
    if ans[j] < S:
      ans[j] += S - ans[j]
    elif ans[j]%F != 0:
      ans[j] += F - ans[j]%F
    ans[j] += C
    
for i in ans:
  print(i)

