A railroad running from west to east in Atcoder Kingdom is now complete.  There are N stations on the railroad, numbered 1 through N from west to east.  Tomorrow, the opening ceremony of the railroad will take place.  On this railroad, for each integer i such that 1≤i≤N-1, there will be trains that run from Station i to Station i+1 in C_i seconds. No other trains will be operated.  The first train from Station i to Station i+1 will depart Station i S_i seconds after the ceremony begins. Thereafter, there will be a train that departs Station i every F_i seconds.  Here, it is guaranteed that F_i divides S_i.  That is, for each Time t satisfying S_i≤t and t％F_i=0, there will be a train that departs Station i t seconds after the ceremony begins and arrives at Station i+1 t+C_i seconds after the ceremony begins, where A％B denotes A modulo B, and there will be no other trains.  For each i, find the earliest possible time we can reach Station N if we are at Station i when the ceremony begins, ignoring the time needed to change trains.
n = int(input())
c = [0]*(n-1)
s = [0]*(n-1)
f = [0]*(n-1)

for i in range(n-1):
    c[i],s[i],f[i] = map(int,input().split())
for i in range(n-1):
    t = 0
    for j in range(i,n-1):
        if(t<s[j]):
            t = s[j]
        elif(t%f[j]):
            t += f[j]-(t%f[j])
        t += c[j]
    print(t)
n = int(input())
c = [0]*(n-1)
s = [0]*(n-1)
f = [0]*(n-1)

for i in range(n-1):
    c[i],s[i],f[i] = map(int,input().split())
for i in range(n):
    t = 0
    for j in range(i,n-1):
        if(t<s[j]):
            t = s[j]
        elif(t%f[j]):
            t += f[j]-(t%f[j])
        t += c[j]
    print(t)