Snuke, who loves animals, built a zoo.  There are N animals in this zoo. They are conveniently numbered 1 through N, and arranged in a circle. The animal numbered i (2≤i≤N-1) is adjacent to the animals numbered i-1 and i+1. Also, the animal numbered 1 is adjacent to the animals numbered 2 and N, and the animal numbered N is adjacent to the animals numbered N-1 and 1.  There are two kinds of animals in this zoo: honest sheep that only speak the truth, and lying wolves that only tell lies.  Snuke cannot tell the difference between these two species, and asked each animal the following question: "Are your neighbors of the same species?" The animal numbered i answered s_i. Here, if s_i is `o`, the animal said that the two neighboring animals are of the same species, and if s_i is `x`, the animal said that the two neighboring animals are of different species.  More formally, a sheep answered `o` if the two neighboring animals are both sheep or both wolves, and answered `x` otherwise. Similarly, a wolf answered `x` if the two neighboring animals are both sheep or both wolves, and answered `o` otherwise.  Snuke is wondering whether there is a valid assignment of species to the animals that is consistent with these responses. If there is such an assignment, show one such assignment. Otherwise, print `-1`.
import itertools
n = int(input())
s = input()
t = [''] * n
for p in itertools.product(['o', 'x'], repeat=2):
  t[-2] = p[0]
  t[-1] = p[1]
  for i in range(n - 2):
    if (t[i - 2] + t[i - 1] + s[i - 1]).count('x') % 2 == 0:
      t[i] = 'o'
    else:
      t[i] = 'x'
  if (t[-3] + t[-2] + t[-1] + s[-2]).count('x') % 2 == 0 and (t[-2] + t[-1] + t[0] + s[-1]).count('x') % 2 == 0:
    ans = []
    for c in t:
      if c == 'o':
        ans.append('S')
      else:
        ans.append('W')
    print(*ans, sep='')
    break
else:
  print(-1)

import itertools
n = int(input())
s = input()
t = [''] * n
for p in itertools.product(['o', 'x'], repeat=2):
  t[-1] = p[0]
  t[0] = p[1]
  for i in range(1, n - 1):
    if (t[i - 2] + t[i - 1] + s[i - 1]).count('x') % 2 == 0:
      t[i] = 'o'
    else:
      t[i] = 'x'
  if (t[-3] + t[-2] + t[-1] + s[-2]).count('x') % 2 == 0 and (t[-2] + t[-1] + t[0] + s[-1]).count('x') % 2 == 0:
    ans = []
    for c in t:
      if c == 'o':
        ans.append('S')
      else:
        ans.append('W')
    print(*ans, sep='')
    break
else:
  print(-1)
