<image>Given a finite sequence {a_{n}} with n_{0} terms (n_{0}≥4), if the following three conditions are satisfied simultaneously:
1. a_{1}=1, a=m (where m is a positive integer);
2. a_{i}-a_{i-1}=0 or 1, for i=2,3,…,n_{0};
3. For any two terms a_{p} and a_{q} (p≠q) from the sequence {a_{n}}, there must exist two terms a_{s} and a_{t} (s≠t) among the remaining n_{0}-2 terms such that a_{p}+a_{q}=a_{s}+a_{t}. 

Then the sequence {a_{n}} is called an Ω sequence.

(1) If the sequence {a_{n}} is an arithmetic sequence with the first term 1, a common difference of 1, and 6 terms, determine whether the sequence {a_{n}} is an Ω sequence, and explain the reason.
(2) When m=3, suppose that in the Ω sequence {a_{n}}, the number 1 appears d_{1} times, the number 2 appears d_{2} times, and the number 3 appears d_{3} times, with d_{1}, d_{2}, d_{3}∈N*. Prove that d_{1}≥4, d_{2}≥2, d_{3}≥4.
(3) When m=2019, find the minimum value of n_{0} for the Ω sequence {a_{n}}.