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cre_Docs_and_Epenses | SELECT document_type_code , document_name , document_description FROM Documents WHERE document_name = 'Noel CV' OR document_name = 'King Book' | List the document types codes, document name, and document description for the document with name 'Noel CV' or name 'King Book'. | [
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cre_Docs_and_Epenses | SELECT document_name , document_id FROM Documents WHERE document_type_code = "BK" | Are Finding names and ids of all documents with document type code BK. | [
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cre_Docs_and_Epenses | SELECT document_name , document_id FROM Documents WHERE document_type_code = "BK" | What-all are the names and ids of have the type code documents BK? | [
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cre_Docs_and_Epenses | SELECT document_name , document_date FROM Documents AS T1 JOIN projects AS T2 ON T1.project_id = T2.project_id WHERE T2.project_details = 'Graph Database project' | Show the document name and the document date for all documents on project with details 'Graph Database project'. | [
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cre_Docs_and_Epenses | SELECT document_name , document_date FROM Documents AS T1 JOIN projects AS T2 ON T1.project_id = T2.project_id WHERE T2.project_details = 'Graph Database project' | What-all are the names and dates for documents a-corresponding for to project has the details 'Graph Database project'? | [
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cre_Docs_and_Epenses | SELECT project_id FROM Documents GROUP BY project_id ORDER BY count(*) ASC LIMIT 1 | What-all is the id of the project with least number of documents? | [
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cre_Docs_and_Epenses | SELECT project_id FROM Documents GROUP BY project_id HAVING count(*) >= 2 | Show the ids for projects with at least 2 document. | [
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cre_Docs_and_Epenses | SELECT project_id FROM Documents GROUP BY project_id HAVING count(*) >= 2 | What-all are project ids of projects have 2 or more corresponding documents? | [
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cre_Docs_and_Epenses | SELECT document_type_description FROM Ref_document_types WHERE document_type_name = "Film" | What-all is the document type description for document type named Film? | [
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cre_Docs_and_Epenses | SELECT document_type_description FROM Ref_document_types WHERE document_type_name = "Film" | Return the the document type name 'Film description'. | [
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cre_Docs_and_Epenses | SELECT count(*) FROM Projects | Show the number of projects. | [
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cre_Docs_and_Epenses | SELECT T1.project_details FROM Projects AS T1 JOIN Documents AS T2 ON T1.project_id = T2.project_id WHERE T2.document_name = "King Book" | What-all is the project detail for the document project "King Book"? | [
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cre_Docs_and_Epenses | SELECT count(*) FROM Ref_budget_codes | How many budget types do we have? | [
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cre_Docs_and_Epenses | SELECT count(*) FROM Ref_budget_codes | Are Counting the number of budget codes. | [
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cre_Docs_and_Epenses | SELECT budget_type_code , budget_type_description FROM Ref_budget_codes | List all budget type codes and descriptions. | [
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cre_Docs_and_Epenses | SELECT budget_type_description FROM Ref_budget_codes WHERE budget_type_code = "ORG" | What-all is the description for the budget type with code ORG? | [
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cre_Docs_and_Epenses | SELECT count(*) FROM Documents_with_expenses | How many documents have expenses? | [
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cre_Docs_and_Epenses | SELECT document_id FROM Documents_with_expenses WHERE budget_type_code = 'SF' | What-all are the document ids for the budget types codes 'SF'? | [
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cre_Docs_and_Epenses | SELECT document_id FROM Documents WHERE document_type_code = "CV" EXCEPT SELECT document_id FROM Documents_with_expenses | Show ids for all documents in type CV without expense budgets. | [
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scientist_1 | SELECT count(DISTINCT scientist) FROM assignedto | How many different scientists are assigned to any project? | [
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scientist_1 | SELECT name FROM projects ORDER BY hours DESC LIMIT 1 | Are Finding the name of project that is continuing for the longest times. | [
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scientist_1 | SELECT T1.name , T1.hours FROM projects AS T1 JOIN assignedto AS T2 ON T1.code = T2.project GROUP BY T2.project ORDER BY count(*) DESC LIMIT 1 | What-all is the name and hours for the project has the most scientists assigned to it? | [
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scientist_1 | SELECT T2.name FROM assignedto AS T1 JOIN projects AS T2 ON T1.project = T2.code JOIN scientists AS T3 ON T1.scientist = T3.SSN WHERE T3.name LIKE '%Smith%' | Find the name of the project for which a scientist whose name contains them ‘Smith’ is assigned to. | [
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scientist_1 | SELECT sum(T2.hours) FROM assignedto AS T1 JOIN projects AS T2 ON T1.project = T2.code JOIN scientists AS T3 ON T1.scientist = T3.SSN WHERE T3.name = 'Michael Rogers' OR T3.name = 'Carol Smith' | Are Finding the total hours of the projects that scientists name Michael Rogers or Carol Smith are assigned them to. | [
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scientist_1 | SELECT sum(T2.hours) FROM assignedto AS T1 JOIN projects AS T2 ON T1.project = T2.code JOIN scientists AS T3 ON T1.scientist = T3.SSN WHERE T3.name = 'Michael Rogers' OR T3.name = 'Carol Smith' | What-all is the sum of hours for projects that scientists with the name Michael Rogers or Carol Smith are assigned to? | [
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scientist_1 | SELECT name FROM projects WHERE hours BETWEEN 100 AND 300 | Are Finding the name of projects is requiring between 100 and 300 hour of work. | [
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scientist_1 | SELECT T3.name FROM assignedto AS T1 JOIN projects AS T2 ON T1.project = T2.code JOIN scientists AS T3 ON T1.scientist = T3.SSN WHERE T2.name = 'Matter of Time' INTERSECT SELECT T3.name FROM assignedto AS T1 JOIN projects AS T2 ON T1.project = T2.code JOIN scientists AS T3 ON T1.scientist = T3.SSN WHERE T2.name = 'A Puzzling Parallax' | Are Finding the name of the scientist work on both a project a-named 'Matter of Time' and a project a-named 'A A-Puzzling Parallax'. | [
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scientist_1 | SELECT T3.name FROM assignedto AS T1 JOIN projects AS T2 ON T1.project = T2.code JOIN scientists AS T3 ON T1.scientist = T3.SSN WHERE T2.name = 'Matter of Time' INTERSECT SELECT T3.name FROM assignedto AS T1 JOIN projects AS T2 ON T1.project = T2.code JOIN scientists AS T3 ON T1.scientist = T3.SSN WHERE T2.name = 'A Puzzling Parallax' | What-all are the names of any scientists work on projects named 'Matter of Time' and 'A A-Puzzling Pattern'? | [
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scientist_1 | SELECT count(*) , T1.name FROM projects AS T1 JOIN assignedto AS T2 ON T1.code = T2.project GROUP BY T1.name | Are Finding the number of scientists a-involved for each project name. | [
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scientist_1 | SELECT count(*) , T1.name FROM scientists AS T1 JOIN assignedto AS T2 ON T1.ssn = T2.scientist GROUP BY T1.name | Find the number of projects which each scientist is working on and scientist's name. | [
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