Celery Worker - Consume from Queue matching a regex
Something along these lines would work: (\b(dev.)(\w+)).
Then refer to the second group for the stuff after "dev.".
You'll need to set it up to capturing repeated instances if you want to get multiple.
Background
Celery worker can be started against a set of queues using -Q flag. E.g. 

-Q dev.Q1,dev.Q2,dev.Q3

So far I have seen examples where all the queue names are explicitly listed as comma separated values. It is troublesome if I have a very long list.
Question
Is there a way I can specify queue names as a regex & celery worker will start consuming from all queues satisfying that regex.
E.g.

-Q dev.*

This should consume from all queuess starting with dev i.e. dev.Q1, dev.Q2, dev.Q3. But what I have seen is - it creates a queue dev..*
Also how can I tune the regex so that it doesn't pick ERROR queues e.g. dev.Q1.ERROR, dev.Q2.ERROR.