Sure, here's an equivalent code in Rust:
```
fn print_int_or_char(input_string: &str, index: usize) {
    if let Some(c) = input_string.chars().nth(index) {
        if c.is_digit(10) {
            let num = c.to_digit(10).unwrap();
            println!("Integer: {}", num);
        } else if c.is_ascii_alphabetic() {
            println!("Character: {}", c);
        } else {
            println!("Invalid input");
        }
    } else {
        println!("Index out of bounds");
    }
}

fn main() {
    let input_string = "a1b2c3";
    let index = 2;

    print_int_or_char(input_string, index);
}
```
In Rust, we use references (&) instead of pointers to pass data around. The &str type is a reference to a string slice, which is similar to a C string.

The print_int_or_char function takes a reference to a string slice and an index as its arguments. We use the chars method on the input string to iterate over its characters, and use the nth method to get the character at the specified index. If the index is out of bounds, we print an error message.

We then use the is_digit method on the character to check if it's a digit, and the to_digit method to convert the digit character to an integer value. If the character is a letter, we print it directly. If the input is neither a digit nor a letter, we print an "Invalid input" message.

Note that Rust has a strong type system that helps prevent memory errors and other bugs that can arise from working with pointers in C. Therefore, while pointers are still used in Rust, they are less common than in C, and Rust code often relies on references and safe borrowing rules to manage memory.
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