The code you provided looks like a recursive implementation of the factorial function in Haskell. However, it appears that you have missed a base case for the recursion. When n=1, the recursive call will be factorial(n-2), which will cause an infinite recursion.

To fix this, you need to provide a base case for n=0 or n=1, which should return 1. Here's a corrected version of your code:
"factorial(0) = 1
factorial(1) = 1
factorial(n) = n * factorial(n-1)
"
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