First, we need to determine the radius of the event horizon for an Earth-sized black hole. The Schwarzschild radius can be calculated as $$R = \frac{{2GM}}{{c^2 }}$$ where:
  - R is the radius of the evenet horizon in meters: $m$
  - G is the gravitational constant: $6.67 \cdot 10 ^ {-11} \frac{N{M^2}}{kg^2}$
  - M is the mass of Earth: $5.96 \cdot 10 ^ {24} kg$
  - c is the speed of light: $2.99 \cdot 10 ^ {8} \frac{m}{s}$

Here is the `python` code to calculate the Schwarzschild radius of Earth:
```python
G = 6.67e-11
M = 5.96e24
c = 2.99e8

def schwarzchild_rad(G, M, c):
    R = (2 * G * M) / (c ** 2)
    return R

radius = schwarzchild_rad(G, M, c)
print(round(myradius, 4), 'meters')
```
**Answer: The Earth-mass black hole's event horizon would be approximately 0.0089 meters in radius.**

Second, we need to calculate the lifetime of a black hole given its mass. This can be approximated as $$t_{evaporation} \approx {(\frac {M_{black hole}} {M_{solar mass}})} ^ {3} \cdot 10 ^ {66}$$ where time is given in years.

The `python` code to generate this is:
```python
# earth's mass in kg
M = 5.96e24

def evap_approx(M):
    sol_mass = 1.99e30
    evap = ((M/sol_mass)  ** 3) * 10 ** 66 # in years
    return evap 
    
evap_time = evap_approx(M)
print("{:e}".format(evap_time), 'years')
```
**Answer: The Earth-mass black hole would take approximately 2.7e49 years to evaporate.**
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