Combine all terms containing  𝑓
f
 .
(−2𝑘+3)𝑓=3𝑘
(
−
2
k
+
3
)
f
=
3
k
 
 The equation is in standard form.
(3−2𝑘)𝑓=3𝑘
(
3
−
2
k
)
f
=
3
k
 
 Divide both sides by  −2𝑘+3
−
2
k
+
3
 .
(3−2𝑘)𝑓3−2𝑘=3𝑘3−2𝑘
(
3
−
2
k
)
f
3
−
2
k
=
3
k
3
−
2
k
 
 Dividing by  −2𝑘+3
−
2
k
+
3
  undoes the multiplication by  −2𝑘+3
−
2
k
+
3
 .
𝑓=3𝑘3−2𝑘
f
=
3
k
3
−
2
k
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