The probability of Bob picking two white balls from the bowl is:

(number of ways to choose 2 white balls from 3) / (number of ways to choose 2 balls from 8) = (3C2) / (8C2) = (3!) / ((8!) / (2! * 6!)) = 3 / 28 = 1/9.

So the probability that both balls are white is 1/9.
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