Sure, here's a Python code that should do what you described:

from PIL import Image

def rotate_record(image_path):
    image = Image.open(image_path)
    # Convert to grayscale for easier processing
    image = image.convert('L')
    # Rotate the image to all possible angles in increments of 1 degree
    for angle in range(0, 360, 1):
        rotated = image.rotate(angle)
        # Check if the label is at the top of the image
        label_top = rotated.crop((image.width/2-50, 0, image.width/2+50, 50))
        if label_top.getextrema()[0][0] == label_top.getextrema()[1][0]:
            # The label is at the top, so rotate the original image to this angle
            rotated_original = image.rotate(angle, expand=True)
            # Save the rotated image as a PNG file with the same name as the original file
            rotated_original.save(image_path[:-4] + '_rotated.png', 'PNG')
            return
    # If the label was not found, raise an exception
    raise ValueError('Label not found')

Here's how to use the function:
rotate_record('path/to/image.png')

This function uses the Python Imaging Library (PIL) to open and process the image. It rotates the image to all possible angles in increments of 1 degree and checks if the label is at the top of the image. If it finds the label, it rotates the original image to this angle and saves it as a PNG file with the same name as the original file. If it doesn't find the label, it raises a ValueError.

Note that this code assumes that the label is always at the top of the image and that it is a rectangular shape. If this is not the case, you may need to modify the code to check for a different region of the image or to use a different approach altogether.
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