Bug 92564 [Viewers] (doc only) incorrect use of html in javadoc of BackgroundContentProvider
Version: 3.1.0 Build id: I20050419-1200 The section that is explaining the information flow is not correctly defining the ordered list. Each item should be wrapped in a 'li', not an 'ol'. Index: BackgroundContentProvider.java =================================================================== RCS file: /home/eclipse/org.eclipse.jface/src/org/eclipse/jface/viewers/deferred/BackgroundContentProvider.java,v retrieving revision 1.4 diff -u -r1.4 BackgroundContentProvider.java --- BackgroundContentProvider.java 28 Mar 2005 14:57:36 -0000 1.4 +++ BackgroundContentProvider.java 25 Apr 2005 11:13:00 -0000 @@ -38,12 +38,12 @@ * <p> * Information flow is like this: * </p> - * <ol>IConcurrentModel sends unordered elements to BackgroundContentProvider (in a background thread)</ol> - * <ol>BackgroundContentProvider sorts, filters, and sends element/index pairs to - * ConcurrentTableUpdator (in a background thread)</ol> - * <ol>ConcurrentTableUpdator batches the updates and sends them to an AbstractVirtualTable - * (in the UI thread)</ol> - * <li> + * <ol> + * <li>IConcurrentModel sends unordered elements to BackgroundContentProvider (in a background thread)</li> + * <li>BackgroundContentProvider sorts, filters, and sends element/index pairs to + * ConcurrentTableUpdator (in a background thread)</li> + * <li>ConcurrentTableUpdator batches the updates and sends them to an AbstractVirtualTable + * (in the UI thread)</li> * </ol> * * <p>
bundles/org.eclipse.jface/src/org/eclipse/jface/viewers/deferred/BackgroundContentProvider.java
order = sortOrder;
        		 
        		LazySortedCollection newCollection = new LazySortedCollection(order);
        		
        		Object[] items = collection.getItems(false);
        		for (int j = 0; j < items.length && order == sortOrder; j++) {
					Object item = items[j];
					
					newCollection.add(item);
				}
        		
        		
				if (order != sortOrder) {
					continue;
				}
				collection = newCollection;
				continue;
        	} 
        	
        	
        	if (f != filter) {
        		dirty = true;
        		f = filter;
        		
        		Object[] items = collection.getItems(false);
        		
        		
        		for (int j = 0; j < items.length && f == filter; j++) {
					Object toTest = items[j];