Bug 38705 wizards should default with current editor selection [code manipulation]
Build 20030605 When using open-type wizard, or create class wizard, the initial type name should be using the current user editor selection if any, so as to ease the typing.
org.eclipse.jdt.ui/ui/org/eclipse/jdt/ui/wizards/NewContainerWizardPage.java
* @param name the wizard page's name
	 */
	public NewContainerWizardPage(String name) {
		super(name);
		fWorkspaceRoot= ResourcesPlugin.getWorkspace().getRoot();	
		ContainerFieldAdapter adapter= new ContainerFieldAdapter();
		
		fContainerDialogField= new StringButtonDialogField(adapter);
		fContainerDialogField.setDialogFieldListener(adapter);
		fContainerDialogField.setLabelText(NewWizardMessages.getString("NewContainerWizardPage.container.label")); 
		fContainerDialogField.setButtonLabel(NewWizardMessages.getString("NewContainerWizardPage.container.button")); 
		
		fContainerStatus= new StatusInfo();
		fCurrRoot= null;
	}
			
	/**
	 * Initializes the source folder field with a valid package fragement root.
	 * The package fragement root is computed from the given Java element.
	 * 
	 * @param elem the Java element used to compute the initial package
	 *    fragment root used as the source folder
	 */
	protected void initContainerPage(IJavaElement elem) {
		IPackageFragmentRoot initRoot= null;
		if (elem != null) {
			initRoot= JavaModelUtil.getPackageFragmentRoot(elem);
			if (initRoot == null || initRoot.isArchive()) {
				IJavaProject jproject= elem.getJavaProject();
				if (jproject != null) {