Sehlopha sa kgwele ya dinao se bapetse metshameko e le 22.  Se fentse metshameko e le 8 go feta e se e latlhegetseng. Se fentse metshameko e mekae?

A football team played 22 games. They won 8 more than they lost. How many did they win?
A re re L ke palo ya metshameko e se e latlhegetseng.
Palo ya metshameko e se e fentseng ke L + <<+8=8>>8.
Sehlopha se bapetse (L+8) + L = 2L + 8 = 22 ya metshameko.
Jalo he, 2L = 22 - 8 = 14
Ka jalo L = 14/2 = <<14/2=7>>7 ya metshameko e se e latlhegetseng.
Ka jalo he, sehlopha se fentse  22 – 7 = <<22-7=15>>15 ya metshameko.
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Let L be the number of losses.
The number of wins is L + <<+8=8>>8.
The team played (L+8) + L = 2L + 8 = 22 games.
So, 2L = 22 - 8 = 14
So L = 14/2 = <<14/2=7>>7 losses.
Therefore, the team won 22 – 7 = <<22-7=15>>15 games.
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