Sekolo se se botlana sa Cedar Falls se na le baithuti ba mophato wa 4 go ya go wa 7 mme ngwaga le ngwaga ba rotloediwa go bona maduo a a kwa godimo mo lenaneong la Accelerated Reader. Baithuti ba le 10 ba ba nang le maduo a a kwa godimo mo mophatong mongwe le mongwe ba a tle ba kgone go leka motshameko wa 'escape room' o o rulagantsweng ke barutabana. Ke baithuti ba le 8 fela ba ba ka kgonang go leka 'escape room' ka nako e le nngwe. Ba na le metsotso e le 45 go leka go tswa. Fa setlhopha sengwe le sengwe se dirisa metsotso ya sona e le 45 ka botlalo, go tla tsaya nako e kae gore mongwe le mongwe a leke 'escape room'? 

A bus has a capacity of 200 people. When it departed Chengli city, it had 20 people. On the first stop, 40 people entered the bus. On the second station, 3/4 of the total number of people who entered the bus at the first station entered the bus. If the number of passengers on the bus doubled at the third station, calculate the total number of people required to fill the remaining spaces on the bus.
Go na le mephato e le 4 mo sekolong se se botlana x baithuti ba le 10 = <<4*10=40>> baithuti ba le 40 ba ba tla kgonang go leka 'escape room'.
Go tla nna le baithuti ba le 40 / baithuti ba le 8 mo setlhopheng = <<40/8=5>> ditlhopha di le 5 tse di tla kgonang go leka 'escape room'.
Go tla tsaya ditlhopha di le 5 x metsotso e le 45 = <<5*45=225>> metsotso e le 225.
#### 225

If the number of passengers increased by 3/4 times the number that entered the bus on the first station, 3/4 * 40 people = <<3/4*40=30>>30 people entered the bus on the second station.
After the second station, the number of people on the bus was 20 people initially on the bus + 40 who entered at the first station + 30 who entered at the second station= <<20+40+30=90>>90 people.
The number of people doubled at the third station, which is 90 people * 2 = <<90*2=180>>180 people.
If the bus has a capacity of 200, the number of people required to fill the bus is 200 people - 180 people = <<200-180=20>>20 people
#### 20