Go tsaya metsotso e le 240 go tsamaya ka ditlhapa tse dintšhwa go di tlwaetsa maoto. Jason o batla go leka go tsenela sehlopha sa mabelo mo dibekeng di le tharo.  Fa a kgona go tsamaya malatsi a le 4 mo bekeng go tlwaetsa ditlhapa, o tshwanetse go tsamaya lebaka le le kana kang letsatsi le letsatsi? 

Benny saw a 10-foot shark with 2 6-inch remoras attached to it. What percentage of the shark's body length is the combined length of the remoras?
Sa ntlha, bona gore Jason o na le malatsi a makae go ipaakanyetsa diteko:  dibeke di le 3 * malatsi a le 4/beke = <<3*4=12>>malatsi a le 12
Morago ga foo, arola nako e e tsayang go tlwaetsa ditlhapa ka nako e Jason a ka e dirisang letsatsi le letsatsi go bona gore o tshwanetse go tsamaya lebaka le le kana kang letsatsi le letsatsi:  metsotso e le 240 / malatsi a le 12 = <<240/12=20>>metsotso e le 20/letsatsi
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First, find the combined length of the remoras in inches: 6 inches/remora * 2 remoras = <<6*2=12>>12 inches
Then divide that number by 12 to convert it to feet: 12 inches / 12 inches/foot = <<1=1>>1 foot
Then divide the combined remora length in feet by the shark's length and multiply by 100% to express the answer as a percentage: 1 foot / 10 feet * 100% = 10%
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