Go na le tlelase ya baithuti ba le 200 ba ba arogantsweng ka ditlhopha di le 3, mme di le 2 tsa tsone di lekana ka palo mme ya bofelo (e leng yenngwe e nnye go gaisa tsotlhe) e na le ba le 10 kwa tlase ga setlhopha se sengwe le se sengwe. Go na le baithuti ba le kae mo setlhopheng se sennye (se)?

Maria buys 8 shares of a stock for $8 each. The stock price increases 50% the first year Maria holds it, then decreases 25% in the second year. What is the final value of all Maria's shares?
Fa 10 e ka tsenngwa mo setlhopheng se sennye (ka jalo le mo palong yotlhe ya baithuti), go tla dira gore ditlhopha tsotlhe di le 3 di lekane ka palo ya (200+10)/3 = <<(200+10)/3=70>>70 mo setlhopheng sengwe le sengwe.
Jaanong fa re ntsha 10 mo setlhopheng se le sengwe re bona gore palo ya setlhopha se sennye ke 70-10 = <<70-10=60>>60 baithuti.
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First find the initial total value of Maria's purchase: 8 shares * $8/share = $<<8*8=64>>64
Then find the amount of the first price increase: $64 * .5 = $<<64*.5=32>>32
Add that amount to the initial value to find the value after the first year: $64 + $32 = $<<64+32=96>>96
Then multiply that amount by 25% to find the amount of the decrease in the second year: $96 * 25% = $<<96*25*.01=24>>24
Then subtract that amount from the value after the first year to find the final value: $96 - $24 = $<<96-24=72>>72
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