Brady o bala madi a a mo segokeng sa gagwe sa madi. O na le di-pennies di le 100, di-nickel di le 40, di-dime di le 20, le dipampiri tsa dolara di le 40. Brady o na le bokae mo segokeng sa gagwe ka didolara? 

Ten stalls have 20 cows each. Mr. Sylas buys 40 cows and divides them equally, putting an equal number of the new cows into each of the twenty stalls. How many cows are in 8 of the stalls?
Ka ge penny e le sente e le 1, go raya gore di-pennies di le 100 di lekane le 100 x 1 sente = <<100=100>>100 sente.
Ka ge nickel e le disente di le 5, go raya gore di-nickel di le 40 di lekane le 40 x 5 = <<40*5=200>>200 sente.
Ka ge dime e lekane le disente di le 10, go raya gore di-dime di le 20 di lekane le 20 x 10 = <<20*10=200>>200 sente.
Jalo he, Brady o na le palogotlhe ya 100 + 200 + 200 = <<100+200+200=500>>500 sente.
Ka ge dolara e lekane le disente di le 100, go raya gore disente di le 500 di lekane le 500/100 = <<500/100=5>>5 didolara.
Jalo he, Brady o na le palogotlhe ya $40 + $5 = $<<40+5=45>>45 mo segokeng sa gagwe sa madi. 
#### 45

When Mr. Sylas puts an equal number of the cows he bought into the stalls, each stall gets 40/10 = <<40/10=4>>4 new cows.
Each of the stalls gets four cows, meaning a total of 8*4 = <<8*4=32>>32 cows are placed into eight of the stalls.
Since each stall had 20 cows before Mr. Sylas added four into each of the stalls, the total number of cows in eight of the stalls was 8*20= <<8*20=160>>160 cows.
There are 160+32 = <<160+32=192>>192 cows in eight stalls after Mr. Sylas adds four into each of the stalls.
#### 192