Andy o batla go fokotsa boima jwa gagwe ka diponto di le 30 pele ga letsatsi la gagwe la botsalo, e leng Phukwi 19, e le maikemisetso a Ngwaga o Mosha. Gompieno ke Sedimonthole 31. Fa Andy a tlhoka go fisa di-calorie di le 3500 go fokotsa ponto e le nngwe, o tlhoka go nna le tlhaelo ya di-calorie e e kana kang (palo ya di-calorie tse di fisitsweng go feta tse di jewang) letsatsi le letsatsi gore a fitlhelele mokgele wa gagwe?

The farm has 30 cows and the zoo has 20 sheep.  The zoo has twice as many cows as the farm does.  The farm has half as many sheep as the zoo does.  How many animals do the farm and zoo have combined?
Ferikgong, Mopitlwe, le Motsheganong di na le malatsi a le 31, Tlhakole a na le a le 28, mme Moranang le Seetebosigo di na le a le 30, mme letsatsi la botsalo la ga Andy ke la bo 19 la Phukwi. Ka jalo go na le malatsi a le 3 * 31 + 28 + 2 * 30 + 19 = 93 + 28 + 60 + 19 = <<3*31+28+2*30+19=200>>200 pele ga letsatsi la botsalo la ga Andy.
O batla go fokotsa diponto di le 30. Ka di-calorie di le 3500 mo pontong e le nngwe, seno ke 30 * 3500 = <<30*3500=105000>>105,000 di-calorie ka kakaretso.
Go fitlhelela mokgele wa gagwe, o tla tshwanela ke go fisa 105,000 di-calorie / malatsi a le 200 = <<105000/200=525>>525 di-calorie ka letsatsi go feta tse a di jang.
#### 525 

The zoo has 2 * 30 cows = <<2*30=60>>60 cows.
The farm has 1/2 * 20 sheep = <<1/2*20=10>>10 sheep.
Combined the zoo and farm have 30 cows + 10 sheep + 60 cows + 20 sheep = <<30+10+60+20=120>>120 animals.
#### 120