Elvis o simolola go kgweetsa go tswa kwa ntlong ya gagwe mme a ya bophirima diura di le 5. Morago ga moo, o a boela morago mme a ya botlhaba diura di le 8. Fa e le gore o ne a kgweetsa ka lobelo lo lo tlwaelegileng la dikilometara di le 18 ka ura mo dikarolong tse pedi tsa loeto, o bokgakala jo bo kae go tswa kwa ntlong ya gagwe jaanong?

A farm has 10 2-legged animals and 15 4-legged animals. If all animals are healthy, how many pairs of animal legs in total are on the farm?
Mo karolong ya ntlha ya loeto o kgweetsa bophirima diura di le 5 ka lobelo la dikilometara di le 18 ka ura ka jalo o ne a tsamaile sekgala sa 5*18 = <<5*18=90>> dikilometara di le 90
Morago ga moo o kgweetsa botlhaba ka lobelo le le lengwe diura di le 8 ka jalo o ne a tsamaile sekgala sa 8*18 = <<8*18=144>> dikilometara di le 144
Bogakala jwa gagwe go tswa kwa ntlong ya gagwe jaanong ke pharologanyo fa gare ga motsamao wa gagwe wa botlhaba le bophirima e leng dikilometara di le 144-90 = <<144-90=54>>54 
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2-legged animals have 2 legs. Therefore 10 2-legged animals will have 10*2=<<10*2=20>>20 legs
4-legged animals have 4 legs. Therefore 15 4-legged animals will have 15*4=<<15*4=60>>60 legs
In total there are 20+60= <<20+60=80>>80 legs
A pair of legs equals 2 legs. If there are 80 legs on the farm, there will be 80/2= <<80/2=40>>40 pairs of legs
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