Go tsaya karolo mo letsholong la setšhaba la go jala ditlhare, Rre Julius o jwaile ditlhare di le masome a mabedi tsa White Oak le palo e menaganeng gabedi ya Lodgepole Pine go feta White Oak mo letsatsing la ntlha. Mo letsatsing la bobedi, o jwaile ditlhare tsa White Oak di le 10 go feta mme a oketsa palo ya ditlhare tsa Lodgepole Pine ka 1/4 go feta tse a di jetseng ka letsatsi la ntlha. Bala palogotlhe ya ditlhare tse di jetsweng ke Rre Julius mo malatsing a mabedi.

Alain's mom bought 5 packs of red pens and also bought twice the amount of black pens than the red. If each pack has 5 pens, how many pens does Alain have?
Rre Julius o jwaile ditlhare tsa phaene/eike * 20 tsa eike = <<2*20=40>>40 tsa Lodgepole Pine mo letsatsing la ntlha. 
Mo letsatsing la bobedi, o okeditse palo ya ditlhare tsa White Oak tse a di jetseng go nna ditlhare di le 20 + ditlhare di le 10 = <<20+10=30>>30.
Ka nako e e tshwanang, o okeditse palogotlhe ya ditlhare tsa Lodgepole Pine tse a di jetseng ka 1/4 * ditlhare di le 40 = <<1/4*40=10>>10 mo letsatsing la bobedi.
Palogotlhe ya ditlhare tsa Lodgepole Pine tse di jetsweng ke Rre Julius mo letsatsing la bobedi ke ditlhare di le 10 + ditlhare di le 40 = <<10+40=50>>50
Rre Julius o jwaile palogotlhe ya ditlhare di le 50 + ditlhare di le 30 + ditlhare di le 40 + ditlhare di le 20 = <<50+30+40+20=140>>140. 
#### 140 

Alain has a total of 5 x 5= <<5*5=25>>25 red pens.
And he has a total of 5 x 2 = <<5*2=10>>10 packs of black pens.
So, the total number of black pens he has is 10 x 5 = <<10*5=50>>50.
Therefore, the total number of pens he has is 50 + 25= <<50+25=75>>75.
#### 75