Russell o otara di-bagel tse a di ratang mo inthaneteng.  Sepakete se le sengwe sa di-bagel se ja R10.00 mme se na le di-bagel di le 9 mo go sone.  Fa a otara dipakete di le 4 tsa di-bagel, o tla amogela theolelo ya 10%.  Morago ga go otara dikgetsana di le 4, a bagel e le nngwe e tla ja bokae?

Donny can only drink water if it's at least 40 degrees. He has two mugs of water. One mug is 33 degrees. The other is an unknown temperature. If he pours 4 ounces of water from the 33-degree mug into his water bottle and one ounce from the other bottle, he is now able to drink the water.  At least how many degrees is the second bottle?
O otara dipakete di le 4 tsa di-bagel mme sephuthelwana se le sengwe se ja R10.00 ka jalo seo ke 4*10 = R<<4*10=40.00>>40.00
O otara dipakete di le 4 ka R40.00 mme a amogela theolelo ya 10% ka jalo theolelo ya gagwe ke 40*.10 = R4.00
Di-bagel di ja R40.00 mme o na le theolelo ya R4.00 e dirang gore palogotlhe ya gagwe e nne 40-4 = R<<40-4=36.00>>36.00
Sepakete se le sengwe sa di-bagel se na le di-bagel di le 9 mo go sone mme o otara dipakete di le 4 ka jalo ke 9*4 = <<9*4=36>>36 bagels
Palogotlhe ya otara ya gagwe e ne e le R36.00 mme go na le di-bagel di le 36 ka jalo bagel e le nngwe e ja 36/36 = R<<36/36=1.00>>1.00
#### 1 

There are 5 total ounces of water because 4 + 1 = <<4+1=5>>5
The total temperatures is >=200 because 200 / 5 =<<200/5=40>>40
The 33 degree water contributes 132 points towards this because 4 x 33 = <<4*33=132>>132
The unknown temperature is at least 68 because 200 - 132 = <<200-132=68>>68
#### 68