Ba ga Rre Smith ba ipaakanyetsa selemo mme ba tlhoka go tlatsa letsha la bone la go thuma. Kompone ya matsha e ba laetse gore ba lekanye bogolo jwa letsha, mme ba bo ba bo ntsifatsa ka 5.9 go bona gore ba tlhoka digalane di le kae tsa metsi. Kompone ya matsha e duedisiwa $0.10 ka galane go tla go tlatsa letsha. Rre Smith o lekantse letsha mme a fitlhela le le bophara jwa dikgato di le 14, boleele jwa dikgato di le 25, le boteng jwa dikgato di le 4. Go tla ja bokae go tlatsa letsha?

Peter has 4 boxes with the same number of chocolate bars in each, while Martha has 7 boxes with the same number of chocolate bars in each. If Peter and Martha have totals of 64 and 56 chocolate bars respectively, how many more chocolate bars does Peter have in each box than Martha?
Rre Smith o fitlhetse bogolo jwa letsha e le bophara jwa dikgato di le 14 x boleele jwa dikgato di le 25 x boteng jwa dikgato di le 4 = <<14*25*4=1400>>1,400 dikhubiki dikgato.
O latetse ditaelo tsa kompone ya matsha mme a fitlhela letsha la gagwe le tlhoka 1,400 x 5.9 = <<1400*5.9=8260>>8,260 digalane tsa metsi.
Go tlatsa letsha go tla ja $0.10 x 8,260 digalane = $<<0.10*8260=826>>826.
#### 826 

Peter has 64 chocolate bars in 4 equal boxes so there are 64/4 = <<64/4=16>>16 bars in each box
Martha has 56 chocolate bars in 7 equal boxes so there are 56/7 = <<56/7=8>>8 bars in each box
Peter has 16-8 = <<16-8=8>>8 bars more than Martha in each box
#### 8