Andrew o baka dirolwana tsa sinamone di le 200 le dimafene a di-blueberry a mannye a le 300. Rolorwana e e tlwaelegileng ya sinamone e na le di-calories di le 600 mme mafene a a tlwaelegileng a blueberry a na le di-calories di le 450. Fa pastry e nnye e na le 1/3 ya di-calories tsa pastry e e tlwaelegileng, di-pastry tse a di besitseng di na le di-calories di le kae? 

There are 10000 gallons of water in a pool. Using a water pump, Anthony and his father fill a tank with half the amount of water in the pool. They use water from the tank to water their vegetable garden. If the tank is emptied at a rate of 500 gallons of water per day, how many gallons of water will be remaining in the tank after 6 days?
Sa ntlha bona palo ya di-calories mo rolorwaneng e nnye ya sinamone: 600 calories / 3 = <<600/3=200>>200 calories
Morago ga moo atisa palo eo ka palo ya dirolwana tse di nnye tsa sinamone: 200 calories/roll * 200 rolls = <<200*200=40000>>40000 calories
Morago ga moo bona palo ya di-calories mo mafeneng a mannye a blueberry: 450 calories / 3 = <<450/3=150>>150 calories
Morago ga moo atisa palo eo ka palo ya mafene a mannye a di-blueberry: 150 calories/muffin * 300 muffins = <<150*300=45000>>45000 calories
Morago ga moo tlhakanya palo ya di-calories go tswa mo mofuteng mongwe le mongwe wa pastry go bona palogotlhe ya di-calories:  45000 calories + 40000 calories = <<45000+40000=85000>>85000 calories
#### 85000 

The water pump takes 1/2 *10000 = <<5000=5000>>5000 gallons of the pool's water into the tank.
If 500 gallons of water is used daily for six days, the total amount of water used after six days is 500*6 = <<500*6=3000>>3000 gallons.
The total amount of water remaining in the tank will be 5000-3000 = <<5000-3000=2000>>2000 gallons
#### 2000