Marie o otarile sejo se le seng sa koko se bitsang $12, diphaketse di le 5 tsa mashi tse bitsang $3 se le seng, diapole di le 4 tse bitsang $1.50 se le seng, le mabokose a pizza. Marie o duetse $50 ka kakaretso. O otarile mabokose a makae a pizza fa lebokoso le le leng le bitsa $8.50? 

Marie ordered one chicken meal that costs $12, 5 packs of milk that costs $3 each, 4 apples that cost $1.50 each, and some boxes of pizza. Marie paid a total of $50. How many boxes of pizza did Marie order if each box costs $8.50?
Diphaketse di le tlhano tsa mashi di bitsa $3 x 5 = $<<3*5=15>>15.
Diapole di le nne di bitsa $1.50 x 4 = $<<1.5*4=6>>6.
Palo ya kakaretso ya sejo sa koko, mashi, le diapole ke $12 + $15 + $6 = $<<12+15+6=33>>33.
Ka jalo, mabokose a pizza a bitsa $50 - $33 = $<<50-33=17>>17.
Jalo he, Marie o otarile mabokose a pizza a $17/$8.50 = <<17/8.5=2>>2. 
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Five packs of milk cost $3 x 5 = $<<3*5=15>>15.
Four apples cost $1.50 x 4 = $<<1.5*4=6>>6.
The total cost of the chicken meal, milk, and apples is $12 + $15 + $6 = $<<12+15+6=33>>33.
Thus, the boxes of pizza cost $50 - $33 = $<<50-33=17>>17.
Therefore, Marie ordered $17/$8.50 = <<17/8.5=2>>2 boxes of pizza.
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