Fa Marcus a tsoga, ntlo ya gagwe e le 40 degrees. O fetsa diura di le 3 a baka, mme ura nngwe le nngwe fa onto e buletswe e oketsa themperetšha ya ntlo ka di degree di le 5. Morago ga foo Marcus o bula fensetere metsotso e le 30, mme ntlo e fola ka di degree di le 2 mo metsotsong e mengwe le e mengwe e le 10 e fensetere e butswe. Ke eng themperetšha ya bofelo ya ntlo?

The area of Billie's rectangular bedroom is 360 square feet. If the length of his room is 3 yards, what is the perimeter of the room in feet?
Sa ntlha, bona koketsego ya themperetšha ka kakaretso go tswa mo ontong: diura di le 3 * 5 degrees/ura = <<3*5=15>>15 degrees
Morago ga foo, tlhakanya palo eo le themperetšha ya kwa tshimologong: 15 degrees + 40 degrees = <<15+40=55>>55 degrees
Morago ga foo, aroganya nako e fensetere e butswe ka metsotso e le 10 go bona gore go na le phokotsego ya themperetšha ya 2-degree ga kae: metsotso e le 30 / metsotso e le 10 = <<30/10=3>>3
Morago ga foo, atisa palo ya diphkotsego ka selekanyo sa phokotsego nngwe le nngwe: 3 * 2 degrees = <<3*2=6>>6 degrees
Morago ga foo, ntsha palo eo go tswa mo themperetšheng ya ntlo morago ga go baka go bona themperetšha ya bofelo: 55 degrees - 6 degrees = <<55-6=49>>49 degrees
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The length of the room is 3 yards * (3 feet / 1 yard) = <<3*(3/1)=9>>9 feet.
The width of the room is 360 square feet / 9 feet = <<360/9=40>>40 feet.
The room's perimeter is 2(40+9) = 98
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