Fa Joanne a ntse a kgobokanya diapole mo tshimong ya lelwapa la gaabo, kgaitsadie o a tswa go tla go mo thusa. Joanne o kgobokanya diapole di le 30 go tswa mo ditlhareng tse di telele go gaisa, halofo ya palo e mo ditlhareng tse dikhutshwane go gaisa, le diapole tse dingwe mo ditlhareng tse di magareng. Fa re bapisa le Joanne, kgaitsadie o kgobokanya diapole tse di fetang tsa gagwe gabedi go tswa mo ditlhareng tse di telele go gaisa le diapole tse di fetang tsa gagwe gararo go tswa mo ditlhareng tse dikhutshwane go gaisa. Ga a tseye dipe mo ditlhareng tse di magareng. Fa bakaulengwe bano ba kgobokantse palo yotlhe ya diapole di le 500, Joanne o kgobokantse diapole di le kae go tswa mo ditlhareng tse di magareng?

Marcy makes homemade candles that she markets as 99% guaranteed not to explode. 5% of the more dangerous candles also have a defect that makes them smell like wet dog. If she makes 50000 candles, how many of them will both smell like wet dog and explode?
Joanna o kgobokantse diapole di le 30 / 2 = <<30/2=15>>15 go tswa mo ditlhareng tse di khutshwane.
Kgaitsadie o kgobokantse diapole di le 30 * 2 = <<30*2=60>>60 go tswa mo ditlhareng tse di telele.
Kgaitsadie gape o kgobokantse diapole di le 15 * 3 = <<15*3=45>>45 go tswa mo ditlhareng tse di khutshwane.
Ka kakaretso, kgaitsadie o kgobokantse diapole di le 60 + 45 = <<60+45=105>>105.
Go tswa mo ditlhareng tse di telele le tse di khutshwane, Joanna o kgobokantse diapole di le 30 + 15 = <<30+15=45>>45.
Go fitlha jaanong, bakaulengwe bano ba na le palo yotlhe ya diapole di le 105 + 45 = <<105+45=150>>150.
Ka jalo, Joanna o tshwanetse a bo a kgobokantse diapole di le 500 tsa paloyotlhe – diapole di le 150 tse ba nang le tsone go fitlha jaanong = <<500-150=350>>350 go tswa mo ditlhareng tse di magareng. 
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First find what percentage of the candles explode: 100% - 99% = 1%
Then multiply the odds of the candles exploding by the odds of them smelling like wet dog to find the probability of both events happening: 1% * 5% = 0.05%
Then multiply that percentage by the number of candles to find the number of them that have both defects: 0.05% * 50000 candles = <<0.05*.01*50000=25>>25 candles
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