Gus o dirisitse R20.00 kwa lebenkeleng la korosari. O rekile dikhipa di le 2 ka R2.00 se sengwe le se sengwe, kgamelo ya koko e gaisitsweng ka R8.00 le soda ka R1.00.  Phaenapole phae e ne e ja bokae?

Lee rears only sheep and geese on his farm.  If the total number of animal legs is 70, and the total number of animal heads is 20, how many sheep live on Lee's farm?
O rekile dikhipa di le 2 ka R2.00 se sengwe le se sengwe ka jalo di lopile 2*2 = R<<2*2=4.00>>4.00
O dirisitse R4.00 mo dikhipeng, R8.00 mo koko e gaisitsweng le R1.00 mo sodeng ka jalo o dirisitse 4+8+1 = R<<4+8+1=13.00>>13.00
O dirisitse R20.00 mme korosari yotlhe, ntle le phae e lopile R13.00  ka jalo phaenapole phae e lopile 20-13 = R<<20-13=7.00>>7.00
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Let g be the number of geese and let s be the number of sheep. The farm has g + s = 20 animals.
Therefore Lee has s = 20 - g sheep.
The animals have 2g + 4s = 70 legs.
Using the value of s above, 2g + 4(20-g) = 70.
2g + 80 - 4g = 70.
2g = 10.
There are therefore 10/2 = <<10/2=5>>5 geese.
There are 20 - 5 = <<20-5=15>>15 sheep remaining on the farm.
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