Kayla o tshwara moletlo wa letsatsi la matsalo kwa lebaleng la dibaesekopo. Thuelo ya go hira lefelo la dibaesekopo ke R125 go fitlha batho ba le 20, mme go tlalelelwa ka R6 go moeng mongwe le mongwe yo o tlaleletsang. Kayla o memile bana ba a tsenang le bone ba le 25 le basetsana ba le 7 ba a tantshang nabo, mmogo le maloko a lelapa a le 13. Ke batho ba le 4 fela ba ba rileng ba ka se kgone go tla. Moletlo o tla ja bokae?

Mr Hezekiah had 20 trucks from his store supplying fertiliser to different farmers in his hometown dispatched for delivery on a particular day. Each truck was carrying 20 tons of fertiliser packed in bags. Two hours after the trucks had departed for delivery, Mr Hezekiah got the news that a quarter of the number of lorries dispatched for delivery had mechanical failures on the road and could not deliver the fertilisers to the farmers. Calculate the total number of tons of fertiliser that reached the farmers that day?
Kayla o memile bana ba a tsenang le bone ba le 25 + ditsala tsa tanse ba le 7 + maloko a lelapa a le 13 = <<25+7+13=45>>45 batho ba ba memilweng.
Mo bathong ba le 45 ba ba memilweng – batho ba le 4 ga ba kake ba tla = <<45-4=41>>41 batho ba tla tsenang moletlo.
Mo bathong ba le 41 ba ba tsenang – ba le 20 ba akarediwa mo thuelong = <<41-20=21>>21 baeng ba ba tlaleletsang ba ba sa akarediwang mo thuelong.
Thuelo ya baeng ba ba tlaleletsang ba le 21 ke 21 x R6 = R<<21*6=126>>126.
Thuelo yotlhe ya moletlo ke R125 ya thuelo + R126 ya baeng ba ba tlaleletsang = R<<125+126=251>>251.
#### 251

If there were 20 trucks dispatched for delivery, and 1/4 of the total number had mechanical failures, there were 1/4*20 = <<20*1/4=5>>5 failed deliveries.
Out of the 20 trucks dispatched to deliver fertiliser, 20-5 = <<20-5=15>>15 trucks delivered to the farmers.
Since each truck carried 20 tons of fertiliser, the total amount of tons of fertiliser delivered that day was 15*20 = <<15*20=300>>300 tons.
#### 300