Lefelo la dintša le na le Dintša Tsa Jeremane di le 3 le Di-Bulldog di le 2. Fa Ntša ya Jeremane e ja dikilogerama di le 5 tsa dijo tsa dintša mme Bulldog e ja dikilogerama di le 3 tsa dijo tsa dintša ka letsatsi.  Ba tla tlhoka dikilogerama di le kae tsa dijo tsa dintša mo bekeng? 

Garrett is popping popcorn for a snack. As the pan of kernels heats up, the kernels start popping faster. Twenty pop in the first 30 seconds of cooking, then three times that amount in the next 30 seconds. The kernels increase to four times the initial popping rate in the next thirty seconds, but in the final 30 seconds, the popping slows down to half the rate as the past 30 seconds. After Garrett takes the pan off the heat, a quarter of the number of kernels that popped in the final 30 seconds of cooking also pop from the residual heat. How many pieces of popcorn does Garrett have to eat?
Dintša Tsa Jeremane di ja dikilogerama di le 3 x 5 = <<3*5=15>>15 tsa dijo tsa dintša ka letsatsi.
Di-Bulldog di ja dikilogerama di le 2 x 3 = <<2*3=6>>6 tsa dijo tsa dintša ka letsatsi.
Dintša tsotlhe di ka ja dikilogerama di le 15 + 6 = <<15+6=21>>21 tsa dijo tsa dintša ka letsatsi.
Ka jalo, di tlhoka dikilogerama di le 21 x 7 = <<21*7=147>>147 tsa dijo tsa dintša mo bekeng. 
#### 147 

In the second 30 seconds of cooking, 3 * 20 = <<3*20=60>>60 kernels pop.
In the third 30 seconds, 4 * 20 = <<4*20=80>>80 kernels pop.
In the final 30 seconds, 80 / 2 = <<80/2=40>>40 kernels pop.
After cooking, the residual heat makes 40 / 4 = <<40/4=10>>10 kernels pop.
Thus, Garrett has 20 + 60 + 80 + 40 + 10 = <<20+60+80+40+10=210>>210 pieces of popcorn to eat.
#### 210