Lebentlele la diaparo le na le dihempe tse 40 tse tsweu le dihempe tse 50 tsa diforelore.  Bofelong jwa dihempe tse tsweu di na le dikolara, mme dihempe tse 20 tsa diforelore di na le dikonopo.  Go na le dihempe tse dintsi tse di senang dikonopo tsa diforelore go feta dihempe tse tsweu tse di senang dikolara kae?

Vicki is planning a pop concert at her high school. The show will be 2 hours. She is allowing each group 2 minutes to get on stage, 6 minutes to perform, and then 2 minutes to exit the stage. If she allows a 10-minute intermission, how many groups can perform in the concert?
40/2 = <<40/2=20>>20 dihempe tse tsweu ga di na dikolara.
50 - 20 = <<50-20=30>>30 dihempe tsa diforelore ga di na dikonopo.
Go na le 30 - 20 = <<30-20=10>>10 dihempe tse di senang dikonopo tsa diforelore go feta dihempe tse tsweu tse di senang dikolara. 
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First, we should convert the 2 hours of showtime into minutes for our calculations. Since there are 60 minutes in 1 hour, the show will be 2 x 60 = <<2*60=120>>120 minutes.
Of those 120 minutes, 10 will be used for intermission, so 120 – 10 = <<120-10=110>>110 minutes for performances.
Each group will use 2 minutes to get on stage + 6 minutes to perform + 2 minutes to exit the stage = <<2+6+2=10>>10 minutes of show time.
Of the 110 minutes of performances, 10 are used per group, so 110 minutes / 10 = <<110/10=11>>11 groups can perform.
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