Founu ya ga Jamal e kgona go tshola dinepe di le dintsi go menagane ga tse 6 go na le ya ga Brittany.  Palo e e kwa godimo ya dinepe tse founu ya ga Brittany e ka di tsholang ke di le dintsi go menagane ga tse 50 go na le palo ya dinonyane tse di mo setshwantshong sa ga Jamal sa matata kwa seralweng sa diphologolo.  Fa founu ya ga Jamal e kgona go tshola dinepe di le 1800, ke matata a makae a a bonalang mo setshwantshong sa ga Jamal sa matata kwa seralweng sa diphologolo?

Jamal's phone can hold 6 times more photographs than can Brittany's phone.  The maximum number of photographs that Brittany's phone can hold is 50 times more than the number of birds in Jamal's photograph of the ducks at the zoo.  If Jamal's phone can hold 1800 photographs, how many ducks can be seen in Jamal's photograph of ducks at the zoo?
E re ka founu ya ga Jamal e kgona go tshola dinepe di le 1800, e leng palo e e fetang ya ga Brittany ka makgetlo a le 6, founu ya ga Brittany e kgona go tshola dinepe di le `1800/6=<<1800/6=300>>300.
E re ka founu ya ga Brittany e kgona go tshola dinepe di le dintsi go menagane ga tse 50 go na le palo ya dinonyane tse di mo setshwantshong sa ga Jamal, go raya gore go na le matata a le 300/50=6 a a bonalang mo setshwantshong sa ga Jamal sa matata kwa seralweng sa diphologolo.
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Since Jamal's phone can hold 1800 photos, which is 6 times more than Brittany's phone can hold, Brittany's phone can hold `1800/6=<<1800/6=300>>300 photographs.
Since Brittany's phone can hold 50 times more photos than the number of birds in Jamal's photograph, then 300/50=6 ducks can be seen in Jamal's photograph of ducks at the zoo.
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