Thomas o ntsha $1000 mo akhaontong ya banka ka dipampiri tsa $20.  O latlhegelwa ke dipampiri di le 10 a sa ntse a boela gae.  Morago ga moo, o dirisa halofo ya dipampiri tse di setseng go duela sekoloto.  Morago ga foo Thomas o menaganya madi a gagwe gararo.  Morago ga foo o fetola dipampiri tsotlhe tsa gagwe go nna tsa $5.  O na le dipampiri di le kae tsa $5?

Alice likes to count the puffs of clouds in the sky while she eats her lunch outside at school. On Monday she counts just 3 puffs of clouds. Each day after that through Friday, though, she sees double the number of clouds in the sky as the day before. At the end of the week, how many clouds will she have counted in the sky at lunch across all five days?
O ntshitse dipampiri di le 1000/20=<<1000/20=50>>50 
Ka jalo o setse ka dipampiri di le 50-10=<<50-10=40>>40
O dirisa halofo ya dipampiri go duela sengwe, ka jalo o sala ka dipampiri di le 40/2=<<40/2=20>>20
O menaganya madi a gagwe gararo mme seo se mo fa  20*3=<<20*3=60>>60 dipampiri.
Ka jalo o na le 60*20=$<<60*20=1200>>1200
Go fetolela mo go tsa $5 go raya gore o na le 1200/5=<<1200/5=240>>240 dipampiri
#### 240

On Monday Alice counts 3 puffs of clouds in the sky, and double that on Tuesday, 3 x 2 = <<3*2=6>>6 puffs of clouds.
On Wednesday she sees twice that amount, 6 x 2 = <<6*2=12>>12 puffs of clouds.
On Thursday she sees twice that amount, 12 x 2 = <<12*2=24>>24 puffs of clouds.
On Friday she sees twice the amount of the day before, 24 x 2 = <<24*2=48>>48 puffs of clouds.
In total, across all five days, she sees 3 + 6 + 12 + 24 + 48 = <<3+6+12+24+48=93>>93 total cloud puffs.
#### 93