Fa Rafaela a ne a le kwa tirong kwa resamong, mongwe le mongwe wa bareki ba le masome a mane ba ba neng ba tsile kwa resamong o ne a mo fa ntlha ya P20. Julieta o amogetse madi a le 10% kwa tlase mo dintlheng go na le Rafaela. Ke madi a a kana kang a Julieta le Rafaela ba a amogetseng botlhe mo dintlheng?

The amount of water passing through a river at one point in time is 4000 gallons. After a day of heavy rain, the amount of water passing through the river doubles at the same point. If the volume of water passing through the river at that point increases by 6000 gallons on the third day, calculate the total amount of water passing through the river at that point.
Palo-kakaretso ya madi a Rafaela a a amogetseng e le dintlha go tswa kwa bareking ba le masome a mane ke P20*40 = P<<40*20=800>>800
Julieta o bone madi a a kwa tlase ka 10% go na le a Rafaela mo dintlheng, a a kana ka 10/100*P800 = P<<10/100*800=80>>80
Palo-kakaretso ya madi a Julieta a a amogetseng e le dintlha ke P800-P80 = P<<800-80=720>>720
Botlhe fela, Julieta le Rafaela ba amogetse P720+P800 = P<<720+800=1520>>1520
#### 1520 

After a day of rain, the volume of water in the river passing at one point in time doubled to 2*4000 = <<2*4000=8000>>8000 gallons.
After more heavy rains, the volume of water passing through the river on the third day is 8000+6000 = <<8000+6000=14000>>14000 gallons.
#### 14000