Fa Sophie a tlhokometse motlogolo wa gagwe, o mo ntshetsa mefuta e e farologaneng ya ditshamekisi. Kgetsana ya dikgobokgobo e na le dikgobokgobo di le 31 mo go yone.  Katiba ya diphologolo tse di tutswetsweng e na le diphologolo di le 8 mo teng ga yone.  Tora ya go tlhatlaganetsa melelwane e na le melelwane e e mebalabala e le 9 mo go yone.  Sophie o sa tswa reka tube ya dibolo tse di tlhaping, tse di dirang gore palo ya gagwe yotlhe ya ditshamekisi tsa motlogolo wa gagwe e nne 62. Ke dibolo di le kae tse di tlhaping tse di neng di le mo teng ga tube?

Rita hand-picks Junebugs off of her plants every summer.  On Monday, she removed 39 Junebugs.  On both Tuesday and Wednesday, she removed twice as many Junebugs as she did on Monday.  Thursday she removed 48 and on Friday she removed 57.  What is the average number of Junebugs that she removes per day?
A re re T ke palo ya dibolo tse di tlhaping tse di mo teng ga tube.
Morago ga go reka tube ya dibolo, Sophie o na le 31 + 8 + 9 + T = 48 + T = 62 ditshamekisi tsa motlogolo wa gagwe.
Ka jalo, T = 62 - 48 = <<62-48=14>>14 dibolo tse di tlhaping di ne di le mo teng ga tube. 
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On both Tuesday and Wednesday, she removed twice as many as the 39 on Monday so she removed 2*39 = <<2*39=78>>78 Junebugs
All total she has removed 39+78+78+48+57 = <<39+78+78+48+57=300>>300 Junebugs
She has removed 300 Junebugs over 5 days so she has removed, on average 300/5 = <<300/5=60>>60 Junebugs per day
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