Khampani e duela mongwe le mongwe wa badiri ba yona R600 ka kgwedi. Khampani e na le molao wa go oketsa dituelo tsa badiri ba yona ka 10% ya tuelo ya ntlha ngwaga le ngwaga go bao ba feditseng dingwaga di le tlhano ba le mo khampaning. Fa Sylvie a sena go fetsa dingwaga di le tlhano mo khampaning ka Sedimonthole se se fetileng, a tuelo ya gagwe ya ngwaga le ngwaga e tla bo e le bokae morago ga dingwaga di le tharo?

A company pays each of its employees $600 in a month. The company has a policy of increasing the salaries of each of its employees by 10% of the initial salary every year for those who've stayed in the company for five years. If Sylvie just clocked 5 years in the company last December, what's her annual salary after three more years of service?
Mo kgweding, Sylvie o amogela R600.  seo se dirang  R600/kgwedi * 12 dikgwedi/ngwaga = R7200 ka ngwaga.
Dituelo tsa ga Sylvie di tla oketsega ka 10/100 * R7200/ngwaga = R<<10/100*7200=720>>720/ngwaga morago ga dingwaga di le tlhano.
Mo dingwageng di le tharo, koketsego ya tuelo ya gagwe e tla nna dingwaga di le 3 * R720/ngwaga = R<<3*720=2160>>2160
Morago ga dingwaga di le tharo, Sylvie o tla bo a duelwa R7200 + R2160 = R<<7200+2160=9360>>9360
#### 9360 

In a month, Sylvie earns $600. which totals $600/month * 12 months/year = $7200 in a year.
Sylvie earnings will increase by 10/100 * $7200/year = $<<10/100*7200=720>>720/year after 5 years.
In three years, the total increase in her salary will be 3 years * $720/year = $<<3*720=2160>>2160
After three years, Sylvie will be paid $7200 + $2160 = $<<7200+2160=9360>>9360
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