Jake o tsamaya mo Ntlong-Bolaodi ya Ditshenekegi. O bona disenyane di le 80 tse nang le maoto a le 8 se sengwe le se sengwe, ditshenekegi di le 90 tse nang le maoto a le 6 se sengwe le se sengwe, le diphologolo tse tharo tse sa tlwaelegang tse nang le maoto a le 10 se sengwe le se sengwe. Ke maoto a makae a a a bonang ka kakaretso?

The marching band is ordering new uniforms. Each uniform comes with a hat that costs $25, a jacket that costs three times as much as the hat, and pants that cost the average of the costs of the hat and jacket. How much does each uniform cost total?
Sa ntlha, bona palo yotlhe ya maoto a disenyane: disenyane di le 80 * maoto a le 8/senyane = <<80*8=640>> maoto a le 640
Morago ga foo, bona palo yotlhe ya maoto a ditshenekegi: ditshenekegi di le 90 * maoto a le 6/setshenekegi = <<90*6=540>> maoto a le 540
Morago ga foo, bona palo yotlhe ya maoto a diphologolo tse sa tlwaelegang: diphologolo di le 3 tse sa tlwaelegang * maoto a le 10/phologolo e sa tlwaelegang = <<3*10=30>> maoto a le 30
Morago ga foo, tlhakanya palo ya mofuta mongwe le mongwe wa leoto go bona a a a boneng ka kakaretso: maoto a le 640 + maoto a le 540 + maoto a le 30 = <<640+540+30=1210>> maoto a le 1210
#### 1210 

First find the cost of the jacket: $25 * 3 = $<<25*3=75>>75
Then add the cost of the jacket and hat: $25 + $75 = $<<25+75=100>>100
Then divide that amount by 2 to find the average cost, which is the cost of the pants: $100 / 2 = $<<100/2=50>>50
Then add the cost of each item of clothing to find the total cost of the uniform: $25 + $75 + $50 = $<<25+75+50=150>>150
#### 150