Gary o rata go tsamaya go dikologa paraka ya lefelo la bona, e e leng sekwere se se metara di le 1.5 ka boleele le di le 6 ka bophara. Fa a tsamaya ka lobelo lwa dikilometara di le 3 ka oura, o fetsa dioura di le kae a tsamaya?

Jerry has a flock of chickens. The red chickens produce 3 eggs a day, and the white chickens produce 5 eggs a day. Every day Jerry collects 42 eggs. If he has two more white chickens than red chickens, how many red chickens does he have?
Sa ntlha bona boleele jwa matlhakore a mabedi a maleele a paraka: dikilometara di le 6 * 2 = <<6*2=12>>12 dikilometara
Morago ga foo bona boleele jwa matlhakore a mabedi a makhutshwane a paraka: dikilometara di le 1.5 * 2 = <<1.5*2=3>>3 dikilometara
Morago ga foo tlhakanya boleele joo go bona boleele jotlhe go dikologa paraka: dikilometara di le 12 + dikilometara di le 3 = <<12+3=15>>15 dikilometara
Morago ga foo arola boleele jotlhe ka lobelo lwa ga Gary go bona gore o fetsa nako e e kana kang a tsamaya: dikilometara di le 15 / dikilometara di le 3 ka oura = <<15/3=5>>5 diura
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First, set up the equation for the number of eggs the chickens lay each day: 3r + 5w = 42, where r is the number of red chickens and w is the number of white chickens.
Then, express r in terms of w based on the information in the problem: w = r + <<+2=2>>2
Now substitute r + 2 for w in the equation for the number of eggs: 3r + 5(r + 2) = 42
Now multiply 5 through the parentheses: 3r + 5r + 10 = 42
Now add like terms to get 8r + 10 = 42
Now subtract 10 from both sides of the equation: 8r = 32
Finally, divide both sides of the equation by 8 to get r = 4
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