Diphiramiti tse dikgolo di eme ka sekhutlo sa di-degree tse 32 go tswa fa fatshe fa o eme kwa kgorong ya ntlo ya ga Sahir. Letsatsi le tlhatloga ka di-degree tse 5 ka ura go tswa kwa godimo ga phiramiti go ya kwa ntlong ya ga Sahir. Fa letsatsi le simolola kwa ntlheng ya phiramiti mme le tsamaya diura tse 10, go tla bo go na le di-degree tse kae go tswa fa fatshe go ya kwa letsatsing?

A pet shop had 6 cages of rodents. 3 of the cages have 10 hamsters and the other 3 have 5 guinea pigs. How many rodents did the pet shop have in total?
Di-degree tse 5 ka ura go ya diura tse 10 5*10=<<5*10=50>>di-degree tse 50
Phiramiti e di-degree tse 32 go tswa fa fatshe ka jalo 32+50=<<32+50=82>>di-degree tse 82
#### 82 

There are 3 cages x 10 hamsters/cage = <<3*10=30>>30 hamsters in the pet shop.
There are 3 cages x 5 guinea pigs/cage = <<3*5=15>>15 guinea pigs in the pet shop.
The pet shop has a total of 30 hamsters + 15 guinea pigs = <<30+15=45>>45 rodents.
#### 45