Lori o batla go reka ditlhako tsa P320.00 le lebanta la P32.00 le tsamaisanang le tsone.  Tiro ya gagwe ya nakwana e mo duela P8.00 ka ura.  O tla tshwanela go bereka diura di le kae pele a ka kgona go reka dilo tse a di batlang?

Jerry has two pools, both with leaks emptying them out at 4 gallons/minute. 4 minutes ago, the big pool had twice as much water as the small pool. Now the big pool has four times as much water as the small pool. How much water does the small pool have now?
O batla go reka ditlhako tsa P320.00 le lebanta la P32.00 tse di dirang palogotlhe ya 320+32 = P<<320+32=352.00>>352.00
Dilo tse a di batlang di dira palogotlhe ya P352.00 mme o amogela P8.00 kwa tirong ya gagwe ya nakwana ka jalo o tla tshwanela go bereka diura di le 352/8 = <<352/8=44>>44
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First find how many gallons of water flow out of the pools in 4 minutes: 4 gallons/minute * 4 minutes = <<4*4=16>>16 gallons
Let b be the amount of water the big pool has now and s be the amount of water the small pool has. We know that b = 4s, and b + 16 = 2(s + 16)
Substituting the first equation into the second equation, we get 4s + 16 = 2(s + 16)
Multiplying through the parentheses, we get 4s + 16 = 2s + 32
Subtracting 2s from both sides, we get 2s + 16 = 32
Subtracting 16 from both sides, we get 2s = 16
Dividing both sides by 2, we get s = <<8=8>>8
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