Morago ga go kwadisa thulaganyo ya gagwe ya go ikatisa mmele dibeke di le 8, Josh o ne a lemoga gore o feditse diura di le 4 a ikatisetsa mmele beke le beke ntle le ka dinako tse dingwe. Ka nako e nngwe, o feditse diura di le 5 beke le beke dibeke di le pedi tse di latelanang. Gape, o kile a fetsa diura di le 6 mo bekeng e le nngwe. Ke palogotlhe ya diura di le kae tse a di feditseng a ikatisetsa mmele mo dibekeng di le 8?

Ophelia and Jenna are living in the same apartment building. They each have 2 fewer sofas than chairs. Jenna has 3 times as many chairs as Ophelia. If Ophelia has 20 sofas, calculate the total number of sofas and chairs that they have.
Mo dibekeng di le 2, o feditse diura di le 5 beke le beke go dira palogotlhe ya diura di le 5*2 = <<5*2=10>>10
Mo bekeng e nngwe, o feditse diura di le 6; e e dirang palogotlhe ya diura di le 10+6 = <<10+6=16>>16
Go setse go balelwa dibeke di le 2+1 = <<2+1=3>>3
O ne a kwadisa dibeke di le 8 ka jalo go setse dibeke di le 8-3 = <<8-3=5>>5
O feditse diura di le 4 beke le beke mo dibekeng di le 5 go dira palogotlhe ya 4*5 = <<4*5=20>>20 diura
Palogotlhe mo dibekeng di le 8 ke: 16+20 = <<16+20=36>>36 diura
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If Ophelia has 20 sofas and 2 fewer sofas than chairs, she has 20+2 = <<20+2=22>>22 chairs.
Jenna has 3 times as many chairs as Ophelia, a total of 3*22 = <<3*22=66>>66 chairs
The total number of chairs Ophelia and Jenna have is 66+22 = <<66+22=88>>88
Since Jenna also has 2 fewer sofas than chairs, the total number of sofas she has is 66-2 = <<66-2=64>>64 sofas.
The total number of sofas Ophelia and Jenna have is 64+20 = <<64+20=84>>84 sofas
Together, they have 84 sofas+88 chairs = <<84+88=172>>172
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