Alex o ipaakanyetsa go tshwara moletlo o o o rulagantseng mme o batla go tlhomamisa gore o na le ditulo tse di lekaneng batho botlhe. O romela taletso mo bathong ba le 100 ka imeile mme mongwe le mongwe wa bone a re o tla tla le ditsala tsa gagwe tse 2. Morago ga foo o founela ditsala tsa gagwe tse 10 go di laletsa mme ba le 8 ba re ba tla tla le balekane ba bone. Alex o tla tlhoka ditulo tse di kae?

Jared is trying to increase his typing speed. He starts with 47 words per minute (WPM). After some lessons the next time he tests his typing speed it has increased to 52 WPM. If he continues to increase his typing speed once more by 5 words, what will be the average of the three measurements?
Mongwe le mongwe wa batho ba ba rometsweng imeile o tla le ditsala tse 2, go raya gore ba tla nna ditlhopha tsa batho ba le 1 +2 = <<1+2=3>>3.
E re ka batho ba le 100 ba rometswe imeile, seno se dira palo yotlhe ya batho ba le 3 * 100 = <<3*100=300>>300.
Mo ditsalaneng tsa gagwe, batho ba le 8 ba rile ba tla tla le balekane ba bone, ka jalo palo yotlhe ke 10 + 8 = <<10+8=18>>18 batho.
Go akaretsa le setulo sa gagwe, Alex o tla tlhoka palo yotlhe ya ditulo di le  300 + 18 +1 = <<300+18+1=319>>319.
#### 319 

Jared types at 52 WPM and increases it by 5 WPM, 52 + 5 = <<52+5=57>>57 WPM.
His average over all his measured words-per-minute is 47 + 52 + 57 = <<47+52+57=156>>156.
His total is 156 / 3 typing speeds = <<156/3=52>>52 WPM as Jared's average typing speed.
#### 52