Teresa o rekisa diphologolo tse di tlhotshitsweng tse dikgolo ka tlhwatlhwa e e fetang ya tse dinnye gararo. Gompieno, o rekisitse diphologolo tse dinnye tse di tlhotshitsweng gabedi go feta tse dikgolo mme a bona P120 mo thekisong. Phologolo nngwe le nngwe e nnye e e tlhotshitsweng e ja P4. O rekisitse diphologolo di le kae tse dinnye tse di tlhotshitsweng?

John picks 4 bananas on Wednesday. Then he picks 6 bananas on Thursday. On Friday, he picks triple the number of bananas he did on Wednesday. How many bananas does John have?
A re re A ke palo ya diphologolo tse dikgolo tse di tlhotshitsweng tse Teresa a di rekisitseng.
Ka jalo, o rekisitse diphologolo tse dinnye tse di tlhotshitsweng tsa 2A. 
Diphologolo tse dikgolo tse di tlhotshitsweng di ja P3 * 4 = P<<3*4=12>>12.
O bonye P12A + 4 * 2A = 12A + 8A = 20A = P120 go tswa mo go rekiseng diphologolo tse di tlhotshitsweng gompieno.
Ka jalo, o rekisitse A = 120 / 20 = <<120/20=6>>6 ya diphologolo tse dikgolo tse di tlhotshitsweng gompieno.
Teresa o rekisitse diphologolo tse dinnye gabedi go feta tse dikgolo, ka jalo o rekisitse 6 * 2 = <<6*2=12>>12 tsa diphologolo tse dinnye tse di tlhotshitsweng gompieno.
#### 12 

Combining Wednesday and Thursday, John has 4 bananas + 6 bananas = <<4+6=10>>10 bananas.
On Friday, he picks 3 * 4 bananas = <<3*4=12>>12 bananas.
Altogether, John has 10 bananas + 12 bananas = <<10+12=22>>22 bananas.
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