Fa kgetsi ya dimabole e ja $20 mme tlhotlhwa e tlhatloga ka 20% ya tlhotlhwa ya ntlha mo dikgweding dingwe le dingwe tse pedi, kgetsi ya dimabole e tla bo e ja bokae morago ga dikgwedi di le 36?

Anakin and Locsin went to the beach today. Anakin caught 10 starfish, 6 sea horses, and 3 clownfish. While Locsin caught 5 fewer starfish than Anakin, 3 fewer sea horses than Anakin, and 2 more clownfish than Anakin. How many fish were they able to catch?
Fa tlhotlhwa ya kgetsi ya dimabole e tlhatloga ka 20%, tlhotlhwa e tlhatloga ka 20/100*20 = $<<20/100*20=4>>4
Fa tlhotlhwa e tlhatloga morago ga dikgwedi dingwe le dingwe tse pedi, mo dikgweding di le 36, e tla bo e tlhatlogile makgetlo a le 36/2 = <<36/2=18>>18.
Fa koketsego nngwe le nngwe e le $4, palogotlhe ya tlhotlhwa ya kgetsi ya dimabole e tla bong e tlhatlogetse ka yone morago ga dikgwedi di le 36 ke 18*$4 = $<<18*4=72>>72
Morago ga koketsego yotlhe ya tlhotlhwa ya kgetsi ya dimabole morago ga dikgwedi di le 36, tlhotlhwa yotlhe e tla nna $20+$72 = $<<20+72=92>>92
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Locsin caught 10 - 5 = <<10-5=5>>5 starfishes.
They caught 10 + 5 = <<10+5=15>>15 starfishes.
Locsin caught 6 - 3 = <<6-3=3>>3 seahorses
They caught 6 + 3 = <<6+3=9>>9 seahorses
Locsin caught 3 + 2 = <<3+2=5>>5 clownfish.
So, they caught 3 + 5 = <<3+5=8>>8 clownfish.
Therefore, Anakin and Locsin were able to catch a total of 15 + 9 + 8 = <<15+9+8=32>>32 fish.
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