Gary o tlhatswetsa diaparo gabedi ka beke. Tlhatswego nngwe le nngwe e dirisa dilitara di le 20 tsa metsi, mme litara ya metsi e ja P0.15. Gary o dirisa bokae mo metsing a tlhatswego ka ngwaga? 

The basketball team went to the steakhouse to eat dinner.  The first player ate a 6-ounce steak.  The second player ate beef tips, containing 8 beef tips, each an ounce in size.  The third player ate a one-pound steak.  And the fourth and fifth players ordered vegetarian meals.  In total, how many ounces of meat were consumed by the team?
Sa ntlha, atisa palo ya dinako tse Gary a tlhatswetsang diaparo ka beke ka palo ya dibeke mo ngwageng go bona gore o tlhatsweta ga kae ka ngwaga: ditlhatswego di le 2/beke * dibeke di le 52/ngwaga = <<2*52=104>>ditlhatswego di le 104/ngwaga
Morago ga foo, bona gore tlhatswego nngwe le nngwe e ja bokae: Dilitara di le 20/tlhatswego * P0.15/litara = P<<20*0.15=3.00>>3.00/tlhatswego
Morago ga foo, atisa tlhotlhwa ya tlhatswego nngwe le nngwe ka palo ya ditlhatswego go bona tlhotlhwa yotlhe: P3.00/tlhatswego * ditlhatswego di le 104 = P<<3*104=312>>312
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The second player consumed 8 1-ounce beef tips, for a total weight of 8*1=<<8*1=8>>8 ounces.
Thus, the total combined weight includes 6 ounces from the first player, 8 ounces from the second player, and 1 pound, which is 16 ounces, from the third player, for a combined total of 6+8+16=<<6+8+16=30>>30 ounces.
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