Jo o ntse a dira dimaseke tsa sefatlhego.  A ka dira dimaseke di le 4 tse dinnye ka materiyale a dimetara di le 2 mme a dire dimaseke di le 3 tse ditona ka materiyale a dimetara di le 2.25.  O tla tlhoka materiyale a a kana kang go direla tlelase ya gagwe dimaseke di le 20 tse dinnye le di le 8 tse ditona? 

Calvin is making soup for his family for dinner. He has a pot with enough soup to fill four adult's bowls or eight child's bowls. He is an adult and will be eating with his adult wife and their two children. If everyone eats one bowl at a meal, how many times will each child be able to have a bowl of soup for lunch from the leftover soup?
Go tsaya dimetara di le 2 tsa materiyale / dimaseke di le 4 tse dinnye = <<2/4=0.5>>dimetara di le 0.5 tsa materiyale mo masekeng mangwe le mangwe. 
Go tsaya dimetara di le 2.25 tsa materiyale / dimaseke di le 3 tse ditona = <<2.25/3=0.75>>dimetara di le 0.75 tsa materiyale mo masekeng mangwe le mangwe. 
Go dimaseke tse dinnye, go tla tsaya dimaseke di le 20 x dimetara di le 0.5 =  <<20*0.5=10>>dimetara di le 10 tsa materiyale.
Go dimaseke tse ditona, go tla tsaya dimaseke di le 8 x dimetara di le 0.75 = <<8*0.75=6>>dimetara di le 6 tsa materiyale.
Ka kakaretso, go tla tsaya dimetara di le 10 + dimetara di le 6 = <<10+6=16>>dimetara di le 16 tsa materiyale.
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Four adult bowls equal eight children’s bowls, so each adult bowl is 8 / 4 = <<8/4=2>>2 children’s bowls.
Calvin and his wife will eat two adult bowls, so they will eat the equivalent of 2 * 2 = <<2*2=4>>4 children’s bowls.
Thus, he, his wife, and their children will eat 4 + 2 = <<4+2=6>>6 children’s bowls at dinner.
After dinner, there will be 8 - 6 = <<8-6=2>>2 children’s bowls left over.
There are 2 children, so each child will be able to eat a bowl of leftover soup for lunch 2 / 2 = <<2/2=1>>1 time.
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