Hannah o tlhoka go nwa 60 ml ya metsi mo kilometareng nngwe le nngwe e a e tabogang. Fa morutabana wa gagwe wa mmele a mo laela go taboga ditilokwana di le 8 mme titilokwana nngwe le nngwe e le 0.25 km, Hannah o tla tlhoka go nwa metsi a le makae ka dimililitara?

For a New Year's resolution, Andy wants to lose 30 lbs. by his birthday, which is July 19th. Today is December 31st. If Andy needs to burn 3500 calories to lose a pound, how much of a calorie deficit (net amount of calories burned vs. calories consumed) does he need each day to reach his goal?
Sa ntlha, bona palo yotlhe ya dikilometara tse Hannah a di tabogang: ditilokwana di le 8 * .25 km/tilokwana = <<8*.25=2>>2 km
Morago ga foo, atise palo ya dikilometara tse a di tabogang ka selekanyo sa metsi a a a tlhokang mo kilometareng nngwe le nngwe go bona selekanyo sa metsi a a a tlhokang: 60 ml/km * 2 km = <<60*2=120>>120 ml
#### 120 

January, March, and May have 31 days, February has 28, and April and June have 30, and Andy's birthday is on the 19th day of July. So there are 3 * 31 days + 28 + 2 * 30 days + 19 days = 93 days + 28 + 60 days + 19 days = <<3*31+28+2*30+19=200>>200 days until Andy's birthday.
He wants to lose 30 lbs. At 3500 calories per pound, this is 30 * 3500 = <<30*3500=105000>>105,000 calories total,
To reach his goal, he will have to burn 105,000 calories / 200 days = <<105000/200=525>>525 calories per day more than he consumes.
#### 525