E re ka Octavia a tlhokomela boitekanelo jwa gagwe thata, o nwa seripa sa kopi tsa kofi tse di akantshiwang ka letsatsi. Mme monna wa ga Octavia e bong Juan o nwa kofi e e fetang ya ga Octavia ka makgetlo a le 10. Ngaka ya ga Juan e mo kopile go fokotsa go nwa kofi go lekana le dikopi di le 4 tse di akantshiwang ka letsatsi. Juan o tshwanetse go fokotsa kofi ya gagwe ka dikopi di le kae ka letsatsi?

A bag of buttons had 21 buttons in it. Seven buttons had two holes and the rest had four holes. How many holes were in all the buttons in the bag?
Ka ge dikopi tsa kofi tse di akantshiwang ka letsatsi ele 4, Octavia o nwa 4/2 = <<4/2=2>>2 dikopi.
Juan o nwa kofi e e fetang ya ga Octavia ka makgetlo a le 10, e leng selo se se dirang 10 * 2 = <<10*2=20>>20 dikopi.
Fa re ntsha palo ya dikopi tse di akantshiwang ka letsatsi mo palong ya dikopi tse di nowang ke Juan, re sala le 20 - 4 = <<20-4=16>>16 dikopi.
Ka jalo he, Juan o tshwanetse go fokotsa kofi ya gagwe ka dikopi di le 16 ka letsatsi.
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There were 21 - 7 = <<21-7=14>>14 buttons with four holes.
The four-holed buttons had 14 * 4 = <<14*4=56>>56 holes.
The two-holed buttons had 7 * 2 = <<7*2=14>>14 holes.
Thus, there were 56 + 14 = <<56+14=70>>70 holes in all the buttons in the bag.
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