Sadie o robetse diura di le 8 ka Mosupologo. Mo malatsing a mabedi a a latelang, o robetse diura di le pedi kwa tlase, letsatsi le letsatsi, ka gonne a ne a tshwanetse go fetsa tiro ya sekolo. Fa e le gore malatsi a mangwe a beke o robetse ura e le nngwe go feta malatsi ao a mabedi, o robetse diura di le kae ka palo mo bekeng yotlhe? 

Sadie slept 8 hours on Monday. For the next two days, she slept 2 hours less, each, because she had to complete some assignments. If the rest of the week she slept 1 hour more than those two days, how many hours did she sleep in total throughout the week?
Fa e le gore ka Mosupologo o robetse diura di le 8, go raya gore o robetse 8-2 = <<8-2=6>>6 diura ka letsatsi mo malatsing a mabedi a a latelang.
Palo yotlhe ya diura tse a di robertseng mo malatsing a mabedi e tla nna 6*2 = <<6*2=12>>12 diura.
Fa e le gore o robetse ura e le nngwe go feta mo malatsing a mangwe a beke, letsatsi le letsatsi, go raya gore o robetse 6+1 = <<6+1=7>>7 diura ka letsatsi.
Palo yotlhe ya diura tse a di robertseng mo malatsing a mangwe a beke e tla nna 4*7 = <<4*7=28>>28 diura.
Palo yotlhe ya diura tse a di robertseng mo bekeng yotlhe e tla nna 8+12+28 = <<8+12+28=48>>48 diura. 
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If on Monday she slept 8 hours, then she slept 8-2 = <<8-2=6>>6 hours on each of the next two days.
The total number of hours slept for the two days will be 6*2 = <<6*2=12>>12 hours.
If she slept 1 hour more for the rest of the week each day, then each day she slept 6+1 = <<6+1=7>>7 hours.
The total for the rest of the week will be 4*7 = <<4*7=28>>28 hours.
The total number of hours slept for the whole week will be 8+12+28 = <<8+12+28=48>>48 hours.
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