Hannah o ne a felelwa ke tlhaloganyo fa a ntse a ithutela ditlhatlhobo tsa bofelo mme a simolola go thuba difensetere kwa makolotsaneng a sekolo se segolwane. O thubile kwatara ya difensetere tsa dikoloi tsa baithuti le 3/4 ya difensetere tsa dikoloi tsa barutabana. Fa go na le dikoloi tsa baithuti di le 64 tse nang le difensetere di le nne nngwe le nngwe le dikoloi tsa barutabana di le 32 tse nang le difensetere di le pedi nngwe le nngwe, ke difensetere di le kae tse di thubilweng ke Hannah?

A cat eats nine sausages in 30 minutes. A dog can eat the same number of sausages in 2/3 the amount of time the cat takes. Calculate the average time the two take the eat the sausages.
Sa ntlha, bona gore ke dikoloi di le kae tsa baithuti tse di thubilweng ke Hannah: 64 dikoloi * 1/4 = <<64*1/4=16>>16 dikoloi
Morago ga moo, bona gore ke dikoloi di le kae tsa barutabana tse di thubilweng ke Hannah: 32 dikoloi * 3/4 = <<32*3/4=24>>24 dikoloi
Morago ga moo, bona gore ke difensetere di le kae tsa dikoloi tsa baithuti tse di thubilweng: 16 dikoloi * 4 difensetere/koloi = <<16*4=64>>64 difensetere
Morago ga moo, bona gore ke difensetere di le kae tsa dikoloi tsa barutabana tse di thubilweng: 24 dikoloi * 2 difensetere/koloi = <<24*2=48>>48 difensetere
Go tswa foo, tlhakanya palo ya difensetere tsa baithuti le tsa barutabana tse di thubilweng go bona palogotlhe ya difensetere tse di thubilweng: 64 difensetere + 48 difensetere = <<64+48=112>>112 difensetere
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If the cat takes 30 minutes to eat the sausages, the dog takes 2/3*30 = <<30*2/3=20>>20 minutes.
The total amount of time the cat and the dog take to eat the sausages is 20+30 = <<20+30=50>>50 minutes.
The average time in minutes that the two take to eat the sausages is 50/2 = <<50/2=25>>25 minutes.
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