Mo seriding sa ntlha sa motshameko wa kgwele ya dinao, setlhopha sa A se fitlheletse dinodi di le 4 fa setlhopha sa B se fitlheletse dinodi di le 2 kwa tlase ga setlhopha sa A.  Mo seriding sa bobedi, setlhopha sa A se fitlheletse 1/4 ya dinodi tse di fitlheletsweng ke setlhopha sa B, se se fitlheletseng dinodi di le 4 go feta tse se di fitlheletseng mo seriding sa ntlha.  Palo yotlhe ya dinodi tse di fitlheletsweng mo motshamekong ke efe? 

A regular box of 100 dishwasher pods costs $12. There's currently a special size box for the same price that has 20% more pods. How many dishwashing cycles with the new box can you run for $1 if you use 1 pod per cycle?
Mo seriding sa ntlha, setlhopha sa B se fitlheletse dinodi di le 4 - 2 = <<4-2=2>>2.
Palo yotlhe ya dinodi tse di fitlheletsweng mo seriding sa ntlha ke 2 + 4 = <<2+4=6>>6.
Mo seriding sa bobedi, setlhopha sa B se fitlheletse dinodi di le 4 * 2 = <<4*2=8>>8.
Setlhopha sa A se fitlheletse 1/4 * 8 = <<1/4*8=2>>2 mo seriding sa bobedi.
Palo yotlhe ya dinodi tse di fitlheletsweng mo seriding sa bobedi ke 8 + 2 = <<8+2=10>>10.
Palo yotlhe ya dinodi tse di fitlheletsweng mo motshamekong ke 6 + 10 = <<6+10=16>>16.
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If the regular box has 100 pods and the special one has 20% more, then the new box has 100 * 20% = 20 more pods
If the new one has 20 more pods than the regular one, the new box has a total of 20+100 = <<20+100=120>>120 pods
If the cost of the regular box ($12) is the same as the new box, then the new box also costs $12
If the new box has 120 pods and the price for the box is $12, then each pod costs $12/120 = $<<12/120=0.10>>0.10
If 1 pod costs $0.10 and is used in 1 cycle, then each cycle costs = $<<1*0.10=0.10>>0.10
If 1 cycle costs $0.10, then for $1 I could run $1/$0.1 = 10 cycles
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