SELECT DISTINCT COUNT(?uri) WHERE { ?x <http://dbpedia.org/ontology/ingredient> <http://dbpedia.org/resource/Agaricus_bisporus> . ?x <http://dbpedia.org/ontology/ingredient> ?uri }
Find the total number of ingredients of the recepies whose ingredient is common Mushroom ?
SELECT DISTINCT COUNT ( ?g ) WHERE { ?x property:ingredient resource:Agaricus_bisporus . ?x property:ingredient ?g }
26
There are [26] ingredients on the foods whose one ingredient is Agaricus bisporus.
The products contain [26] ingredients, one of which is Agaricus bisporus.
There are [26] ingredient of the the recepies whose ingredient is common mushroom.
There are [26] ingredients of an recepies whose ingredient is Agaricus bisporus.