SELECT DISTINCT COUNT(?uri) WHERE { ?x <http://dbpedia.org/ontology/otherParty> <http://dbpedia.org/resource/Janata_Party> . ?x <http://dbpedia.org/ontology/otherParty> ?uri }
Give the distinct number of other party of the people which have one of the party as Janata Party?
SELECT DISTINCT COUNT ( ?i ) WHERE { ?p property:other_party resource:Janata_Party . ?p property:other_party ?i }
54
There are [54] other parties of the people whose one other party is Janata Party.
There are [54] other popular parties, one of which is the Janata Party.