title: 2016 French Open – Legends over 45 doubles
text: # 2016 French Open – Legends over 45 doubles
  
  Guy Forget and Henri Leconte were the defending champions; however, Forget decided not to participate in the tournament this year. Leconte teamed up with Arnaud Boetsch, but they were eliminated during the round-robin competition.
  
  Sergi Bruguera and Goran Ivanišević emerged as the champions, defeating Yannick Noah and Cédric Pioline in the final with a score of 6–3, $7–6^{(7–2)}.$
  
  ## Draw
  
  ### Key
  
  * Q = Qualifier
  * WC = Wild card
  * LL = Lucky loser
  * Alt = Alternate
  * SE = Special exempt
  * PR = Protected ranking
  * ITF = ITF entry
  * JE = Junior exempt
  * w/o = Walkover
  * r = Retired
  * d = Defaulted
  * SR = Special ranking
  
  ### Final
  
  | Finals | Finals | Finals | Finals | Finals |
  | - | - | - | - | - |
  | | Sergi Bruguera Goran Ivanišević | 6 | $7^7$ | |
  | | Yannick Noah Cédric Pioline | 3 | $6^2$ | |
  
  ### Group C
  
  | | | A Boetsch H Leconte | P Cash J McEnroe | S Bruguera G Ivanišević | RR W–L | Set W–L | Game W–L | Standings |
  | - | - | - | - | - | - | - | - | - |
  | C1 | Arnaud Boetsch Henri Leconte | | 4–6, 2–6 | 3–6, 3–6 | 0–2 | 0–4 | 12–24 | 3 |
  | C2 | Pat Cash John McEnroe | 6–4, 6–2 | | 1–6, 6–3, [5–10] | 1–1 | 3–2 | 19–16 | 2 |
  | C3 | Sergi Bruguera Goran Ivanišević | 6–3, 6–3 | 6–1, 3–6, [10–5] | | 2–0 | 4–1 | 22–13 | 1 |
  
  Standings are determined by: 1. number of wins; 2. number of matches; 3. in three-players-ties, percentage of sets won, or of games won; 4. steering-committee decision.
  
  ### Group D
  
  | | | Y Noah C Pioline | M Pernfors M Wilander | M Bahrami R Krajicek | RR W–L | Set W–L | Game W–L | Standings |
  | - | - | - | - | - | - | - | - | - |
  | D1 | Yannick Noah Cédric Pioline | | 6–4, 6–4 | $7–6^{(7–5)},$ 2–6, [10–8] | 2–0 | 4–1 | 22–20 | 1 |
  | D2 | Mikael Pernfors Mats Wilander | 4–6, 4–6 | | $6–7^{(2–6)},$ 4–6 | 0–2 | 0–4 | 18–25 | 3 |
  | D3 | Mansour Bahrami Richard Krajicek | $6–7^{(5–7)},$ 6–2, [8–10] | $7–6^{(6–2)},$ 6–4 | | 1–1 | 3–2 | 25–20 | 2 |
  
  Standings are determined by: 1. number of wins; 2. number of matches; 3. in three-players-ties, percentage of sets won, or of games won; 4. steering-committee decision.
  
  