title: Fuglede−Kadison determinant
text: # Fuglede−Kadison determinant
  
  In mathematics, the Fuglede−Kadison determinant of an invertible operator in a finite factor is a positive real number associated with it. It defines a multiplicative homomorphism from the set of invertible operators to the set of positive real numbers. The Fuglede−Kadison determinant of an operator $A$ is often denoted by $\Delta (A)$.
  
  For a matrix $A$ in $M_{n}(\mathbb {C} )$, $\Delta (A)=\left|\det(A)\right|^{1/n}$ which is the normalized form of the absolute value of the determinant of $A$.
  
  ## Definition
  
  Let ${\mathcal {M}}$ be a finite factor with the canonical normalized trace $\tau$ and let $X$ be an invertible operator in ${\mathcal {M}}$. Then the Fuglede−Kadison determinant of $X$ is defined as
  
      $\Delta (X):=\exp \tau (\log(X^{*}X)^{1/2}),$
  
  (cf. Relation between determinant and trace via eigenvalues). The number $\Delta (X)$ is well-defined by continuous functional calculus.
  
  ## Properties
  
  * $\Delta (XY)=\Delta (X)\Delta (Y)$ for invertible operators $X,Y\in {\mathcal {M}}$,
  * $\Delta (\exp A)=\left|\exp \tau (A)\right|=\exp \Re \tau (A)$ for $A\in {\mathcal {M}}.$
  * $\Delta$ is norm-continuous on $GL_{1}({\mathcal {M}})$, the set of invertible operators in ${\mathcal {M}},$
  * $\Delta (X)$ does not exceed the spectral radius of $X$.
  
  ## Extensions to singular operators
  
  There are many possible extensions of the Fuglede−Kadison determinant to singular operators in ${\mathcal {M}}$. All of them must assign a value of 0 to operators with non-trivial nullspace. No extension of the determinant $\Delta$ from the invertible operators to all operators in ${\mathcal {M}}$, is continuous in the uniform topology.
  
  ### Algebraic extension
  
  The algebraic extension of $\Delta$ assigns a value of 0 to a singular operator in ${\mathcal {M}}$.
  
  ### Analytic extension
  
  For an operator $A$ in ${\mathcal {M}}$, the analytic extension of $\Delta$ uses the spectral decomposition of $|A|=\int \lambda \;dE_{\lambda }$ to define $\Delta (A):=\exp \left(\int \log \lambda \;d\tau (E_{\lambda })\right)$ with the understanding that $\Delta (A)=0$ if $\int \log \lambda \;d\tau (E_{\lambda })=-\infty$. This extension satisfies the continuity property
  
      $\lim _{\varepsilon \rightarrow 0}\Delta (H+\varepsilon I)=\Delta (H)$ for $H\geq 0.$
  
  ## Generalizations
  
  Although originally the Fuglede−Kadison determinant was defined for operators in finite factors, it carries over to the case of operators in von Neumann algebras with a tracial state ($\tau$) in the case of which it is denoted by $\Delta _{\tau }(\cdot )$.
  
  