title: 2018 Irving Tennis Classic – Doubles
text: # 2018 Irving Tennis Classic – Doubles
  
  Marcus Daniell and Marcelo Demoliner were the defending champions but chose not to defend their title.
  
  Philipp Petzschner and Alexander Peya won the title after defeating Radu Albot and Matthew Ebden 6–2, 6–4 in the final.
  
  ## Seeds
  
  * Henri Kontinen / John Peers (first round)
  * Ben McLachlan / Julio Peralta (quarterfinals)
  * Dominic Inglot / Neal Skupski (first round)
  * Nicholas Monroe / Jackson Withrow (semifinals)
  
  ## Draw
  
  ### Key
  
  * Q = Qualifier
  * WC = Wild card
  * LL = Lucky loser
  * Alt = Alternate
  * SE = Special exempt
  * PR = Protected ranking
  * ITF = ITF entry
  * JE = Junior exempt
  * w/o = Walkover
  * r = Retired
  * d = Defaulted
  * SR = Special ranking
  
  | First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final |
  | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
  | 1 | H Kontinen J Peers | 5 | 5 | | | | | | | | | | | | | | |
  | | P Petzschner A Peya | 7 | 7 | | | P Petzschner A Peya | 6 | 4 | [10] | | | | | | | | |
  | WC | J Maginley Or Ram-Harel | 6 | 2 | [5] | | M Berrettini T Fabbiano | 3 | 6 | [6] | | | | | | | | |
  | | M Berrettini T Fabbiano | 4 | 6 | [10] | | | | | | | P Petzschner A Peya | 6 | 7 | | | | |
  | 3 | D Inglot N Skupski | 6 | 1 | [6] | | | | | | | W Koolhof A Sitak | 4 | 5 | | | | |
  | | W Koolhof A Sitak | 3 | 6 | [10] | | W Koolhof A Sitak | 6 | 6 | | | | | | | | | |
  | | M Fucsovics S Stakhovsky | 4 | 4 | | | A Krajicek L Lacko | 1 | 4 | | | | | | | | | |
  | | A Krajicek L Lacko | 6 | 6 | | | | | | | | | | | | P Petzschner A Peya | 6 | 6 |
  | | T Huey P Raja | 4 | $6^6$ | | | | | | | | | | | | R Albot M Ebden | 2 | 4 |
  | | S Lipsky D Sharan | 6 | $7^8$ | | | S Lipsky D Sharan | 3 | 2 | | | | | | | | | |
  | WC | H Hach Verdugo T Smyczek | 3 | $6^3$ | | 4 | N Monroe J Withrow | 6 | 6 | | | | | | | | | |
  | 4 | N Monroe J Withrow | 6 | $7^7$ | | | | | | | 4 | N Monroe J Withrow | 6 | 2 | [9] | | | |
  | | R Albot M Ebden | 6 | 6 | | | | | | | | R Albot M Ebden | 1 | 6 | [11] | | | |
  | WC | P Chrysochos Ian Dempster | 0 | 3 | | | R Albot M Ebden | 4 | 6 | [10] | | | | | | | | |
  | | J Erlich R Lindstedt | $6^6$ | 4 | | 2 | B McLachlan J Peralta | 6 | 2 | [4] | | | | | | | | |
  | 2 | B McLachlan J Peralta | $7^8$ | 6 | | | | | | | | | | | | | | |
  