title: 2018 Shenzhen Longhua Open – Men's singles
text: # 2018 Shenzhen Longhua Open – Men's singles
  
  Radu Albot was the defending champion but lost in the first round to Zhang Ze.
  
  Miomir Kecmanović won the title after defeating Blaž Kavčič 6–2, 2–6, 6–3 in the final.
  
  ## Seeds
  
  * Radu Albot (first round)
  * Thomas Fabbiano (second round)
  * Ramkumar Ramanathan (second round)
  * Prajnesh Gunneswaran (first round)
  * Miomir Kecmanović (champion)
  * Yūichi Sugita (second round)
  * Go Soeda (first round)
  * Filip Peliwo (second round)
  
  ## Draw
  
  ### Key
  
  * Q = Qualifier
  * WC = Wild card
  * LL = Lucky loser
  * Alt = Alternate
  * SE = Special exempt
  * PR = Protected ranking
  * ITF = ITF entry
  * JE = Junior exempt
  * w/o = Walkover
  * r = Retired
  * d = Defaulted
  * SR = Special ranking
  
  ### Finals
  
  | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final | Final |
  | - | - | - | - | - | - | - | - | - |
  | | Aleksandr Nedovyesov | 5 | 4 | | | | | |
  | 5 | Miomir Kecmanović | 7 | 6 | | | | | |
  | 5 | Miomir Kecmanović | 7 | 6 | 5 | Miomir Kecmanović | 6 | 2 | 6 |
  | | | | | | Blaž Kavčič | 2 | 6 | 3 |
  | | Alejandro Davidovich Fokina | 5 | 4 | | Blaž Kavčič | 2 | 6 | 3 |
  | | Blaž Kavčič | 7 | 6 | | | | | |
  
  ### Top half
  
  | First round | First round | First round | First round | First round | Second round | Second round | Second round | Second round | Second round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals |
  | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
  | 1 | R Albot | 4 | 6 | 2 | | | | | | | | | | | | | | |
  | | Ze Zhang | 6 | 4 | 6 | | Ze Zhang | 6 | 1 | 6 | | | | | | | | | |
  | | D Wu | 4 | 4 | | | L Broady | 4 | 6 | 1 | | | | | | | | | |
  | | L Broady | 6 | 6 | | | | | | | | Ze Zhang | $6^3$ | $6^4$ | | | | | |
  | Q | G Oliveira | 3 | $6^2$ | | | | | | | | A Nedovyesov | $7^7$ | $7^7$ | | | | | |
  | | A Nedovyesov | 6 | $7^7$ | | | A Nedovyesov | $7^7$ | 6 | | | | | | | | | | |
  | | B Schnur | 3 | 2 | | 6 | Y Sugita | $6^4$ | 4 | | | | | | | | | | |
  | 6 | Y Sugita | 6 | 6 | | | | | | | | | | | | | A Nedovyesov | 5 | 4 |
  | 3 | R Ramanathan | 3 | 6 | $7^7$ | | | | | | | | | | | 5 | M Kecmanović | 7 | 6 |
  | Q | S Nagal | 6 | 4 | $6^2$ | 3 | R Ramanathan | $6^3$ | 4 | | | | | | | | | | |
  | WC | Mu Tao | 1 | 3 | | | M Safwat | $7^7$ | 6 | | | | | | | | | | |
  | | M Safwat | 6 | 6 | | | | | | | | M Safwat | 6 | 3 | $6^4$ | | | | |
  | | F Gaio | 6 | 3 | | | | | | | 5 | M Kecmanović | 1 | 6 | $7^7$ | | | | |
  | | D-h Lee | 1 | $0^r$ | | | F Gaio | 6 | 5 | 2 | | | | | | | | | |
  | | K Coppejans | 4 | 3 | | 5 | M Kecmanović | 4 | 7 | 6 | | | | | | | | | |
  | 5 | M Kecmanović | 6 | 6 | | | | | | | | | | | | | | | |
  
  ### Bottom half
  
  | First round | First round | First round | First round | Second round | Second round | Second round | Second round | Second round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals |
  | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
  | 8 | F Peliwo | 6 | $7^7$ | | | | | | | | | | | | |
  | WC | R Te | 3 | $6^4$ | 8 | F Peliwo | 4 | 7 | 3 | | | | | | | |
  | Q | S Mukund | $7^7$ | 6 | Q | S Mukund | 6 | 5 | 6 | | | | | | | |
  | WC | Y Wu | $6^4$ | 2 | | | | | | Q | S Mukund | 4 | 2 | | | |
  | | S-w Kwon | 5 | 3 | | | | | | | A Davidovich Fokina | 6 | 6 | | | |
  | | T-h Yang | 7 | 6 | | T-h Yang | $7^7$ | 4 | 2 | | | | | | | |
  | | A Davidovich Fokina | 6 | 6 | | A Davidovich Fokina | $6^1$ | 6 | 6 | | | | | | | |
  | 4 | P Gunneswaran | 3 | 4 | | | | | | | | | | A Davidovich Fokina | 5 | 4 |
  | 7 | G Soeda | 3 | 3 | | | | | | | | | | B Kavčič | 7 | 6 |
  | | B Kavčič | 6 | 6 | | B Kavčič | 6 | 6 | | | | | | | | |
  | | J Tatlot | 6 | 0 | | J Tatlot | 1 | 2 | | | | | | | | |
  | Q | S Myneni | 0 | $0^r$ | | | | | | | B Kavčič | 6 | 0 | | | |
  | | M Valkusz | 6 | 6 | | | | | | | M Valkusz | 2 | $0^r$ | | | |
  | | Z Li | 2 | 2 | | M Valkusz | $7^7$ | 7 | | | | | | | | |
  | WC | Xia Zihao | 3 | 2 | 2 | T Fabbiano | $6^5$ | 5 | | | | | | | | |
  | 2 | T Fabbiano | 6 | 6 | | | | | | | | | | | | |
  