title: 2018 Oracle Challenger Series – Indian Wells – Women's doubles
text: # 2018 Oracle Challenger Series – Indian Wells – Women's doubles
  
  This was the first edition of the tournament.
  
  Taylor Townsend and Yanina Wickmayer won the title after defeating Jennifer Brady and Vania King 6–4, 6–4 in the final.
  
  ## Seeds
  
  * Raluca Olaru / Olga Savchuk (first round)
  * Barbora Krejčíková / Vera Lapko (semifinals)
  * Jennifer Brady / Vania King (final)
  * Duan Yingying / Wang Yafan (quarterfinals)
  
  ## Draw
  
  ### Key
  
  * Q = Qualifier
  * WC = Wild card
  * LL = Lucky loser
  * Alt = Alternate
  * SE = Special exempt
  * PR = Protected ranking
  * ITF = ITF entry
  * JE = Junior exempt
  * w/o = Walkover
  * r = Retired
  * d = Defaulted
  * SR = Special ranking
  
  ### Draw
  
  | First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final |
  | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
  | 1 | R Olaru O Savchuk | 3 | 5 | | | | | | | | | | | | | | | |
  | | S Chang A Mueller | 6 | 7 | | | S Chang A Mueller | 1 | 1 | | | | | | | | | | |
  | | C Dolehide A Riske | 6 | 6 | | | C Dolehide A Riske | 6 | 6 | | | | | | | | | | |
  | | N Broady E Hrdinová | 3 | 3 | | | | | | | | C Dolehide A Riske | 2 | 3 | | | | | |
  | 3 | J Brady V King | 6 | 6 | | | | | | | 3 | J Brady V King | 6 | 6 | | | | | |
  | | M Doi E Rodina | 4 | 3 | | 3 | J Brady V King | 6 | 6 | | | | | | | | | | |
  | | PC Gonçalves S Marand | 6 | $6^8$ | [1] | WC | J Elbaba I Neel | 1 | 3 | | | | | | | | | | |
  | WC | J Elbaba I Neel | 3 | $7^{10}$ | [10] | | | | | | | | | | | 3 | J Brady V King | 4 | 4 |
  | | V Golubic M Linette | 1 | 3 | | | | | | | | | | | | | T Townsend Y Wickmayer | 6 | 6 |
  | | T Townsend Y Wickmayer | 6 | 6 | | | T Townsend Y Wickmayer | 6 | $6^5$ | [10] | | | | | | | | | |
  | Alt | S Kenin A Weinhold | 1 | $6^3$ | | 4 | Y Duan Y Wang | 4 | $7^7$ | [6] | | | | | | | | | |
  | 4 | Y Duan Y Wang | 6 | $7^7$ | | | | | | | | T Townsend Y Wickmayer | 6 | $6^3$ | [10] | | | | |
  | | A Tomljanović V Zvonareva | 4 | 6 | [5] | | | | | | 2 | B Krejčíková V Lapko | 2 | $7^7$ | [6] | | | | |
  | | A Petkovic F Schiavone | 6 | 3 | [10] | | A Petkovic F Schiavone | 3 | 4 | | | | | | | | | | |
  | | K Bondarenko V Lepchenko | 0 | 0 | | 2 | B Krejčíková V Lapko | 6 | 6 | | | | | | | | | | |
  | 2 | B Krejčíková V Lapko | 6 | 6 | | | | | | | | | | | | | | | |
  