title: 2019 Maia Challenger – Doubles
text: # 2019 Maia Challenger – Doubles
  
  This was the first edition of the tournament.
  
  Andre Begemann and Daniel Masur won the title after defeating Guillermo García López and David Vega Hernández $7–6^{(7–2)},$ 6–4 in the final.
  
  ## Seeds
  
  * Romain Arneodo / Nicholas Monroe (first round)
  * Tomislav Brkić / Ante Pavić (quarterfinals)
  * Luca Margaroli / Andrea Vavassori (first round)
  * Scott Clayton / Purav Raja (first round)
  
  ## Draw
  
  ### Key
  
  * Q = Qualifier
  * WC = Wild card
  * LL = Lucky loser
  * Alt = Alternate
  * SE = Special exempt
  * PR = Protected ranking
  * ITF = ITF entry
  * JE = Junior exempt
  * w/o = Walkover
  * r = Retired
  * d = Defaulted
  * SR = Special ranking
  
  | First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final |
  | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
  | 1 | R Arneodo N Monroe | 3 | 7 | [8] | | | | | | | | | | | | |
  | | K Drzewiecki S Walków | 6 | 5 | [10] | | K Drzewiecki S Walków | $6^5$ | 7 | [7] | | | | | | | |
  | | T Gabashvili P Kotov | 6 | 3 | [10] | | T Gabashvili P Kotov | $7^7$ | 5 | [10] | | | | | | | |
  | WC | N Borges F Cabral | 4 | 6 | [4] | | | | | | T Gabashvili P Kotov | 3 | 4 | | | | |
  | 4 | S Clayton P Raja | 3 | 2 | | | | | | | G García López D Vega Hernández | 6 | 6 | | | | |
  | WC | Gonçalo Falcão P Sousa | 6 | 6 | | WC | G Falcão P Sousa | 1 | 4 | | | | | | | | |
  | Alt | A Çelikbilek V Kopřiva | 4 | 2 | | | G García López D Vega Hernández | 6 | 6 | | | | | | | | |
  | | G García López D Vega Hernández | 6 | 6 | | | | | | | | | | | G García López D Vega Hernández | $6^2$ | 4 |
  | WC | T Cação João Monteiro | $7^7$ | 3 | [10] | | | | | | | | | | A Begemann D Masur | $7^7$ | 6 |
  | | T Draganja Z Kolář | $6^4$ | 6 | [3] | WC | T Cação J Monteiro | $6^6$ | 4 | | | | | | | | |
  | | S Mukund VS Prashanth | 0 | 6 | [11] | | S Mukund VS Prashanth | $7^8$ | 6 | | | | | | | | |
  | 3 | L Margaroli A Vavassori | 6 | 4 | [9] | | | | | | S Mukund VS Prashanth | $7^7$ | 3 | [9] | | | |
  | | A Begemann D Masur | 6 | 4 | [10] | | | | | | A Begemann D Masur | $6^3$ | 6 | [11] | | | |
  | | S Martos Gornés S Puodziunas | 4 | 6 | [7] | | A Begemann D Masur | $7^7$ | 4 | [10] | | | | | | | |
  | | I Nedelko D Yevseyev | 1 | 4 | | 2 | T Brkić A Pavić | $6^4$ | 6 | [7] | | | | | | | |
  | 2 | T Brkić A Pavić | 6 | 6 | | | | | | | | | | | | | |
  