Tuluit ikiortutik SANIILIAMIK ikiuuttoq.
Vektor A = (3, 4) 
Vektor B = (4, 3)
Kiitaussuseq: 
Vector A = (3, 4) 
Vector B = (4, 3)
A.B = 3*4 + 4*3 = 24
|A| = sqrt(3^2 + 4^2) = 5
|B| = sqrt(4^2 + 3^2) = 5
cos(θ) = (A.B) / (|A||B|) = 24 / (5*5) = 0.96
θ = arccos(0.96) = 16.26 degrees 
Kiitaussuseq Vector A, Vector B naapataaffik 16.26 degrees