a, b tunngaviussatit saniatitsinerit, a + 4i, b + 5i ilinniartitsisut z^2 - (10 + 9i) z + (4 + 46i) = 0.
(a, b) = (6, 4)
z^2 - (10 + 9i) z + (4 + 46i) = 0,

a + 4i, b + 5i roots iliorneq,

Vieta-formulerne matussaa:

(a + 4i) + (b + 5i) = 10 + 9i,

(a + 4i)(b + 5i) = 4 + 46i.

Peqataasut a + b + 9i = 10 + 9i, so a + b = 10.

Naguangat peqataasut, ab - 20 + (5a + 4b)i = 4 + 46i.

Ab = 24, 5a + 4b = 46.

A + b = 10, 5a + 4b = 46, a = 6, b = 4.

Ukiuni (a, b) (6, 4).