Carter has a jar with 20 green M&Ms and 20 red M&Ms. He eats 12 of the green M&Ms, then his sister comes and eats half the red M&Ms and adds 14 yellow M&Ms. If Carter picks an M&M at random now, what is the percentage chance he'll get a green M&M?
First find the final number of green M&amp;Ms by subtracting 12 from the starting number: 20 M&amp;Ms - 12 M&amp;Ms = 
<gadget id="calculator">20-12</gadget>
<output>8</output>
8 green M&amp;Ms.
Then find the final number of red M&amp;Ms by dividing the starting number by half: 20 M&amp;Ms / 2 = 
<gadget id="calculator">20/2</gadget>
<output>10</output>
10 red M&amp;Ms.
Then find the total number of M&amp;Ms at the end by adding the number of red, green and yellow M&amp;Ms: 8 M&amp;Ms + 10 M&amp;Ms + 14 M&amp;Ms = 
<gadget id="calculator">8+10+14</gadget>
<output>32</output>
32 M&amp;Ms.
Then divide the number of green M&amp;Ms by the total number of M&amp;Ms and multiply by 100 to find the percentage chance Carter gets a green M&amp;M: 8 M&amp;Ms / 32 M&amp;Ms * 100 = 
<gadget id="calculator">8/32*100</gadget>
<output>25</output>
25%

<result>25</result>