A coach placed 15 tennis balls and 5 soccer balls each into 5 baskets. He gave 5 of his students a short period of time to remove as many balls each from a basket as they could. 3 of them removed 8 balls each and the other 2 removed a certain number of balls each. If a total of 56 balls are still in the baskets, how many balls did the other 2 students each remove?
Combining the tennis and soccer balls, there are 15+5=
<gadget id="calculator">15+5</gadget>
<output>20</output>
20 balls in each basket.
There are 5 baskets, hence 5*20=
<gadget id="calculator">5*20</gadget>
<output>100</output>
100 balls in total
3 students removed 8 balls each, they removed 3*8=
<gadget id="calculator">3*8</gadget>
<output>24</output>
24 balls.
From the total number of balls, they left 100-24=
<gadget id="calculator">100-24</gadget>
<output>76</output>
76 balls.
There are 56 balls left so the other 2 students must have removed a total of 76-56=20 balls.
This means that each of these 2 students removed 20/2=
<gadget id="calculator">20/2</gadget>
<output>10</output>
10 balls.

<result>10</result>