Walter fell from the eighth platform of some scaffolding and fell past David after falling 4 meters. If he fell for an additional three more times that depth before hitting the ground, and the platforms are evenly spaced out in height, what platform was David on?
Walter fell 4 meters and an additional three times that depth which is 3*4 = 12 meters.
He fell for a total of 4+12 = 
<gadget id="calculator">4+12</gadget>
<output>16</output>
16 meters.
The eighth platform is 16 meters high and the platforms are evenly spaced so each platform is 16/8 = 
<gadget id="calculator">16/8</gadget>
<output>2</output>
2 meters high.
David was located 4 meters below the 16 meter level which is 16-4 = 
<gadget id="calculator">16-4</gadget>
<output>12</output>
12 meters high.
Each platform is 2 meters high so 12 meters would mean the 12/2 = 
<gadget id="calculator">12/2</gadget>
<output>6</output>
6th platform.

<result>6</result>