There are 360 balls in the ball pit. If a quarter of the balls in the ball pit are red and a fifth of the remaining balls are blue. How many of the balls are neither red nor blue?
A quarter of the balls are red and therefore there are 360 x (1 / 4) = 
<gadget id="calculator">360*(1/4)</gadget>
<output>90</output>
90 red balls.
When you remove the red balls from the ball pit there are 360 - 90 = 
<gadget id="calculator">360-90</gadget>
<output>270</output>
270 remaining balls.
A fifth of the remaining balls are blue, and therefore there are 270 x (1 / 5) = 
<gadget id="calculator">270*(1/5)</gadget>
<output>54</output>
54 blue balls.
The total of red and blue balls equals 90 + 54 = 
<gadget id="calculator">90+54</gadget>
<output>144</output>
144 balls.
When you remove the red and blue balls from the total there are 360 - 144 = 
<gadget id="calculator">360-144</gadget>
<output>216</output>
216 balls that are neither red nor blue.

<result>216</result>