Santana has 7 brothers. 3 of them have birthdays in March, 1 of them has a birthday in October, 1 has a birthday in November, and another 2 of them were born in December. If Santana always buys each of her brothers a birthday present and a Christmas present, how many more presents does she have to buy in the second half of the year than the first half of the year?
Santana has 1 + 1 + 2 = 
<gadget id="calculator">1+1+2</gadget>
<output>4</output>
4 brothers with birthdays in the second half of the year.
She has 7 brothers - 4 brothers = 
<gadget id="calculator">7-4</gadget>
<output>3</output>
3 brothers with birthdays in the first half of the year.
Altogether, she has to buy 4 + 7 = 
<gadget id="calculator">4+7</gadget>
<output>11</output>
11 presents in the second half of the year.
Therefore, she has to buy 11 - 3 = 
<gadget id="calculator">11-3</gadget>
<output>8</output>
8 more presents in the second half of the year.

<result>8</result>