Jean is wanted on 3 counts of arson, 2 burglary charges, and six times as many petty larceny as burglary charges. If each arson count has a 36-month sentence, each burglary charge is 18 months and each petty larceny charge is 1/3rd as long as a burglary charge, how many months in jail is Jean facing?
First find the total time for the burglary charges: 18 months/charge * 2 charges = 36 months.
Then find the total time for the arson charges: 3 counts * 36 months/count = 
<gadget id="calculator">3*36</gadget>
<output>108</output>
108 months.
Then find the time per larceny charge: 18 months / 3 = 
<gadget id="calculator">18/3</gadget>
<output>6</output>
6 months.
Then find the total number of larceny charges: 2 charges * 6 = 
<gadget id="calculator">2*6</gadget>
<output>12</output>
12 charges.
Then find the total time for the larceny charges: 6 months/charge * 12 charges = 72 months.
Then add up the time for all the charges to find the total jail time: 36 months + 72 months + 108 months = 
<gadget id="calculator">36+72+108</gadget>
<output>216</output>
216 months.

<result>216</result>