Mark goes into the store to buy some groceries.  He buys 6 2$ cans of soup, 2 $5 loaves of bread, 2 3$ boxes of cereal, and 2 $4 gallons of milk.  When he gets to the register, he opens his wallet to pay and realizes he only has $10 bills in there.  How many $10 bills does he need to use to pay?
Mark buys 6 $2 cans of soup, meaning he spends 6*2= 
<gadget id="calculator">6*2</gadget>
<output>12</output>
12 dollars on soup.
Mark buys 2 $5 loaves of bread, meaning he spends 2*5= 
<gadget id="calculator">2*5</gadget>
<output>10</output>
10 dollars on bread.
Mark buys 2 $3 boxes of cereal, meaning he spends 2*3= 
<gadget id="calculator">2*3</gadget>
<output>6</output>
6 dollars on cereal.
Mark buys 2 $4 gallons of milk, meaning he spends 2*4= 
<gadget id="calculator">2*4</gadget>
<output>8</output>
8 dollars on milk.
All added together, this means Mark spends 12+10+6+8= 
<gadget id="calculator">12+10+6+8</gadget>
<output>36</output>
36 dollars.
Since Mark only has $10 bills, he spends 36/10= 
<gadget id="calculator">36/10</gadget>
<output>18/5 = around 3.6</output>
3.6 tens on it, which rounds up to 4 as you cannot spend .6 of an undividable item.

<result>4</result>