Zain has 10 more of each coin than Emerie. If Emerie has six quarters, seven dimes, and five nickels, how many coins does Zain have?
If Emerie has six quarters, Zain has 6+10 = 
<gadget id="calculator">6+10</gadget>
<output>16</output>
16 quarters.
At the same time, Zain has 7+10 = 
<gadget id="calculator">7+10</gadget>
<output>17</output>
17 dimes, ten more than Emerie.
The total number of quarters and dimes Zain has is 17+16 = 
<gadget id="calculator">17+16</gadget>
<output>33</output>
33 coins.
Zain also has 10 more nickels than Emerie, a total of 10+5 = 
<gadget id="calculator">10+5</gadget>
<output>15</output>
15 nickels.
In total, Zain has 33+15 = 
<gadget id="calculator">33+15</gadget>
<output>48</output>
48 coins.

<result>48</result>