If a > 1, b > 1, and (a^2)b = a, then which of the following MUST be true?	Choices:
A) a > b
B) 2a > b
C) a^2< b^2
D) ab > b
E) a^3 < b^3
If b is positive, then we have that a&gt;b&gt;0.   If b is negative, then we have that a<b<0. a="" a)=""> b. Not necessarily true.   B) 2a &gt; b. Not necessarily true.   C) a^2&lt; b^2 then a&gt;b not necessarily true.   D) ab&gt;b If a&gt;b&gt;0, then ab&gt;b (the product of two positive integers is obviously greater than either one of them) and if a&lt;b&lt;0, then ab</b<0.>=positive&gt;negative=b. So,this statement is always true.   E)a^3&lt;b^3= axaxa&gt;bxbxb ,not necessarily true.   Therefore ab &gt; b is correct
<result>D</result>
If a > 1, b > 1, and (a^2)b = a, then which of the following MUST be true?