Tn = 2Tn-1 + 4 and Qn = 4Qn-1 + 8 for all n > 1. If T5 = Q4 and T7 = 316, what is the first value of n for which Qn is an integer?	Choose the correct choice from the following answers
A) 1  B) 2  C) 3  D) 4  E) 5
Assuming I have understood the symbols used correctly answer is 3- 3   T7 = 2S6 +4 = 316   T6 = 312/2= 
<gadget id="calculator">312/2</gadget>
<output>156</output>
156= 2T5 + 4   T5 = 152/2= 
<gadget id="calculator">152/2</gadget>
<output>76</output>
76= Q4   Q4 = 4Q3 + 8 = 76   Q3 = 68/4= 
<gadget id="calculator">68/4</gadget>
<output>17</output>
17   Q3= 4Q2 + 8 = 17   Q2 = 9/4= 
<gadget id="calculator">9/4</gadget>
<output>9/4 = around 2.25</output>
2.25   Q2= 4Q1 + 8   Q1 will not be integer
<result>C</result>
Tn = 2Tn-1 + 4 and Qn = 4Qn-1 + 8 for all n > 1. If T5 = Q4 and T7 = 316, what is the first value of n for which Qn is an integer?