Solve the equation:
A) |2x – (3x + 2)| = 1,
B) |x|/3 – 2|x|/2 = - 1,
C) |3x – 1| = 2|3x – 1| - 2	Choose the correct choice from the following options
A) -1, - 3/2, - 1/3
B) -2, - 3/2, - 1/3
C) -3, - 3/2, - 1/3
D) -1/2, - 3/2, - 1/3
E) None of these
Solution:   -1, - 3/2, - 1/3) |2x – 3x – 2| = 1 &lt;=&gt; |-x – 2| = 1 &lt;=&gt;   -x - 2 = 1 or –x - 2 = -1   From the first equation we get -2 - 1 = x &lt;=&gt; x = -3,   and from the second -2 + 1 = x &lt;=&gt; x = -1   B) |x|/3 – 2 |x|/2 = -1 We reduce to a common denominator and we get   2|x| – 3.2.|x| = - 6 &lt;=&gt;   2|x| - 6|x| = - 6 &lt;=&gt;   - 4|x| = -6 &lt;=&gt; |x| = 3/2 &lt;=&gt;   x = 3/2 or x = - 3/2   C) |3x – 1| = 2|3x – 1| – 2 &lt;=&gt;   2 = 2|3x – 1| – |3x – 1| &lt;=&gt;   2 = |3x – 1| &lt;=&gt;   3x - 1 = 2 or 3x - 1 3  - 1= 
<gadget id="calculator">3  - 1</gadget>
<output>2</output>
2 or 3x - 1= - 2,   from where 3x = 3 &lt;=&gt; x = 1 or 3x = - 1 &lt;=&gt; x = - 1/3   -1, - 3/2, - 1/3nswer -1, - 3/2, - 1/3
<result>A</result>
Solve the equation:
A) |2x – (3x + 2)| = 1,
B) |x|/3 – 2|x|/2 = - 1,
C) |3x – 1| = 2|3x – 1| - 2