When a certain number X is divided by 143, the remainder is 45. Which of the following numbers, if added to X, would result in a number divisible by 12? Pick:
A) 7
B) 21
C) 34
D) 47
E) 6
So the number given is N = 143Q + 45   If this number is divided by 13, the remainder would be R[(143Q + 45)/13]   Since 143 is divisible by 13 , the product 143Q gives no remainder   This means the remainder of 45/13 should be the remainder of the entire number N   which is 6   To make it divisible by 13 , the smallest number that can be added = 12 - 6= 
<gadget id="calculator">12 - 6</gadget>
<output>6</output>
6   Correct Option : 6
<result>E</result>
When a certain number X is divided by 143, the remainder is 45. Which of the following numbers, if added to X, would result in a number divisible by 12?