From a group of 3 CATS and 3 DOGS, 4 animals are to be randomly selected. What is the probability that equal numbers of cats and dogs will be selected?
Pick
A) 1/5  B) 2/5  C) 4/5  D) 3/5  E) 1
Using the first example, here is the probability of THAT EXACT sequence occurring:   CCDD = (3/6)(2/5)(3/4)(2/3) = 36/360 = 1/10   Each of the other 5 options will yield the exact SAME probability....   eg   CDCD = (3/6)(3/5)(2/4)(2/3) = 36/360 = 1/10   So we have 6 different options that each produce a 1/10 chance of occurring.   6(1/10) = 6/10 = 3/5   Final Answer:   3/5
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From a group of 3 CATS and 3 DOGS, 4 animals are to be randomly selected. What is the probability that equal numbers of cats and dogs will be selected?