If (x-12)(x-3) < 0, which of the following must be true?
Answers:	A) x^2 + 5x + 6 < 0	B) x^2 + 5x + 6 > 0	C) 12 - x > 0	D) x - 5 < 0	E) 11 - x > 0
(x-12)(x-3)&lt;0 can be written as (12-x)(x-3)&gt;0   So,to inequality hold true multiple of (12-x) and (x-3) must be positive and if I let both elements positive/negative then the range becomes 3<x<12 -="" 12="" answer="" x=""> 0hoice E matched which says 12-x&gt;0 or x&lt;12,which must be true (I started to look from E to A for making easy decision first)   12 - x &gt; 0orrect Answer 12 - x &gt; 0</x<12>
<result>C</result>
If (x-12)(x-3) < 0, which of the following must be true?