A certain bakery baked a batch of 400 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch? Choose the correct choice from the following answers
A) 13	B) 27	C) 41	D) 43	E) 51
Cookies which have both nuts and chocolate chips = 235   Let fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that   batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch = x   (235+x)/(400+x) = 6/10   =&gt;2350 + 10x = 2400 + 6x   =&gt; 4x = 50   =&gt; x = 12.5   Therefore x = 13   13nswer 13
<result>A</result>
A certain bakery baked a batch of 400 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?