(x + 5) is a factor in x^2 - mx - 40. What is the value of m?	Options:
A) 1	B) 2	C) 4	D) 3	E) 5
I solved the second degree equation and found it like this:   x^2 - mx - 40 = 0   (x-8)(x+5) = 0   x=8 or x= -5   Substituting both values for x in the equation we find:   x^2 - mx -40   =&gt; (-5)^2 - m(-5) = 40   =&gt; 25+ 5m= 40   =&gt; 5m = 40-25= 
<gadget id="calculator">40-25</gadget>
<output>15</output>
15=&gt; m = 3   And with 8, using a similar process we end up with:   (8)^2 - m(8) =40   -8m = 40-64= -24   m=3   Ao,ANS 3
<result>D</result>
(x + 5) is a factor in x^2 - mx - 40. What is the value of m?