A container holds 4 quarts of diesel and 4 quarts of petrol. How many quarts of water must be added to the container to create a mixture that is 3 parts dieselto 5 parts water by petrol? Answers
A) 4/3	B) 5/3	C) 7/3	D) 8/3	E) 10/3
An alternate to the alligation method is the more direct/algebraic method:   Let x be the amount of petrol to be added.   New total amount of water = 4+x   Total amount of diesel= 4   New total = 4+4+x=8+x   Final ratio required (for petrol) = 5/(5+3)=5/8   Thus, (4+x)/(8+x) = 5/8 --&gt; solving for x you get x = 8/3.   8/3 is thus the correct answer.
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A container holds 4 quarts of diesel and 4 quarts of petrol. How many quarts of water must be added to the container to create a mixture that is 3 parts dieselto 5 parts water by petrol?