(1^2+2^2+3^2+.....+9^2)=?  Choose the correct choice from the following options.
A) 330  B) 285  C) 365  D) 385  E) None of them
formula is (1^2+2^2+3^2+....+n^2=1/6 n(n+1)(2n+1)   n=9   =(1/6x9x10x19)   =285   Answer is 285.
<result>B</result>
(1^2+2^2+3^2+.....+9^2)=?