The average of five integers is 71, and none of these integers is greater than 100. If the average of three of the integers is 76, what is the least possible value of one of the other two integers? Choose the correct answer
A) 5	B) 15	C) 20	D) 21	E) 27
When it comes to averages, we know thataverage value = (sum of n values)/n   We can rewrite this into a useful formula:sum of n values = (average value)(n)   The average of five integers is 71   So, the sum of ALL 5 integers = (71)(5) =355   The average of three of the integers is 65   So, the sum of the 3 integers = (76)(3) =228   So, the sum of the 2 REMAINING integers =355-228= 
<gadget id="calculator">355-228</gadget>
<output>127</output>
127   If the sum of the 2 REMAINING integers=127, and we want to minimize one value, we must MAXIMIZE the other value.   100 is the maximum value so let 1 integer = 100, which means the other must equal 27   Answer: 27
<result>E</result>
The average of five integers is 71, and none of these integers is greater than 100. If the average of three of the integers is 76, what is the least possible value of one of the other two integers?