In a recent survey at a local deli, it was observed that 3 out of 5 customers bought a bagel and 5 out of 7 customers bought a coffee. Some customers bought both. If 4 customers are selected, what are the chances that at least 1 customer bought a coffee and a bagel?	Choose the correct option.
A) 27/343  B) 3/7  C) 27/125  D) 271/340  E) 9/125
Let us take 7*5= 
<gadget id="calculator">7*5</gadget>
<output>35</output>
35 as the total number of customers. So  7*3= 
<gadget id="calculator"> 7*3</gadget>
<output>21</output>
21 customers bought a bagel and 5*5= 
<gadget id="calculator">5*5</gadget>
<output>25</output>
25 customers bought a coffee.   chances that at least 1 customer bought a coffee and a bagel= 1 - chances that no customer bought a coffee and a bagel   chances that no customer bought a coffee and a bagel= 24/35*23/34*22/33*21/32=69/340   chances that at least 1 customer bought a coffee and a bagel= 1 - 69/340 = 271/340   271/340
<result>D</result>
In a recent survey at a local deli, it was observed that 3 out of 5 customers bought a bagel and 5 out of 7 customers bought a coffee. Some customers bought both. If 4 customers are selected, what are the chances that at least 1 customer bought a coffee and a bagel?