If (x-14)(x-3) < 0, which of the following must be true?
Options:
A) x^2 + 5x + 6 < 0
B) 14-x > 0
C) 5 - x < 0
D) x - 5 < 0
E) 11 - x > 0
(x-14)(x-3)&lt;0 can be written as (14-x)(x-3)&gt;0   So,to inequality hold true multiple of (14-x) and (x-3) must be positive and if I let both elements positive/negative then the range becomes 3<x<14 14-x="" answer="" choice="" e="" matched="" says="" which="">0 or x&lt;14,which must be true (I started to look from E to A for making easy decision first)   Correct Answer 14-x &gt; 0</x<14>
<result>B</result>
If (x-14)(x-3) < 0, which of the following must be true?