(1^2+2^2+3^2+.....+8^2)=?	Choose the correct choice from the following options:
A) 330
B) 345
C) 204
D) 385
E) None of them
formula is (1^2+2^2+3^2+....+n^2=1/6 n(n+1)(2n+1)   n=8   =(1/6x8x9x17)   =204   Answer is 204.
<result>C</result>
(1^2+2^2+3^2+.....+8^2)=?