It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)),
when p=(a+b+c)/2, such that a, b, c are the lengths of sides of the triangle. If the triangle has 300, 300, and 300 as the side’s lengths, what is the triangle’s area?
Choose the correct choice from the following.
A) 34,200
B) 36,200
C) 38,200
D) 42,200
E) 38,971
It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)),   when p=(a+b+c)/2,   -&gt; P=(300+300+300)/2= 
<gadget id="calculator">(300+300+300)/2</gadget>
<output>450</output>
450, area=√(450(450-300)(450-300)(450-300))=38,971. Therefore, the answer is 38,971.
<result>E</result>
It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)),
when p=(a+b+c)/2, such that a, b, c are the lengths of sides of the triangle. If the triangle has 300, 300, and 300 as the side’s lengths, what is the triangle’s area?