If x+y=2 and x2y3 + y2x3=32, what is the value of xy? Options
A) 1 B) 2 C) 3 D) 4 E) 5
xy=4   As x+y=2   x2y3+y2x3=32   x2y2(y+x)=32   Substituting x+y   x2y2=16   xy=4   ANSWER:4
<result>D</result>
If x+y=2 and x2y3 + y2x3=32, what is the value of xy?