If 0 < a < b and k = (2a + 6b)/b , which of the following must be true? Pick.
A) k < 2
B) k < 7
C) k < 8
D) k > 9
E) k > 11
Here's another approach:   k = (2a + 6b)/b   = 2a/b + 6b/b   = 2(a/b) + 6   Since 0 &lt; a &lt; b, we know that a/b is less than 1, which means that 2(a/b) is some number less than 2.   So, we get k = (some number less than 2) + 6   From here, we can see that k must be less than 8   Answer: k &lt; 8
<result>C</result>
If 0 < a < b and k = (2a + 6b)/b , which of the following must be true?