Factor: 2x4y3 â€“ 32y3 Choose the correct choice from the following choices
A) A) 3y3(x2 + 4)(x + 2)(x -2)  B) B) 2y3(x2 + 4)(x + 2)(x -2)  C) C) 3y3(x2 + 4)(x + 2)(x -3)  D) D) 3y3(x2 + 4)(x + 3)(x -2)  E) E) 3y3(x2 + 4)(x + 2)(x -4)
2x4y3â€“ 32y3.   = 2y3(x4 â€“ 16).   = 2y3[(x2)2 - 42].   = 2y3(x2 + 4)(x2 - 4).   = 2y3(x2 + 4)(x2 - 22).   = 2y3(x2 + 4)(x + 2)(x -2).   Answer: (2y3(x2 + 4)(x + 2)(x -2)) 2y3(x2 + 4)(x + 2)(x -2)
<result>B</result>
Factor: 2x4y3 â€“ 32y3