If an integer t is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that t(t + 1)(t + 2) will be divisible by 8?	Choose the correct choice from the following answers
A) 1/4	B) 3/8	C) 1/2	D) 5/8	E) 3/4
for t Total numbers 8*12   There are 12 numbers divisible by 8 -&gt; 3*12 (if 8 is an example - (6,7,8), (7,8,9), (8,9,10))   and 12 numbers divisible by 4 but not divisible by 8 -&gt; 2*12 (if 4 is an example (2,3,4) and (4,5,6))   The answer 5/8 -&gt; 5/8
<result>D</result>
If an integer t is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that t(t + 1)(t + 2) will be divisible by 8?