If x = 6 and y = −2, what is the value of (x − 2y)^y?  Answers.
A) −100
B) 0.01
C) 0.25
D) 4
E) 8
(x−2 y)^y=(6−2(−2))^−2 = 1/(6+4)^2= 1/100= 
<gadget id="calculator">1/100</gadget>
<output>1/100 = around 0.01</output>
0.01   ANSWER:0.01
<result>B</result>
If x = 6 and y = −2, what is the value of (x − 2y)^y?