If (x-13)(x-3) < 0, which of the following must be true?
Select
A) x^2 + 5x + 6 < 0  B) x^2 + 5x + 6 > 0  C) 5 - x < 0  D) x - 5 < 0  E) 13 - x > 0
(x-13)(x-3)&lt;0 can be written as (13-x)(x-3)&gt;0   So,to inequality hold true multiple of (13-x) and (x-3) must be positive and if I let both elements positive/negative then the range becomes 3<x<13 -="" 13="" answer="" choice="" x=""> 0 matched which says 13-x&gt;0 or x&lt;13,which must be true (I started to look from 13 - x &gt; 0 to A for making easy decision first)   Correct Answer 13 - x &gt; 0</x<13>
<result>E</result>
If (x-13)(x-3) < 0, which of the following must be true?