(1^2 + 2^2 + 3^2 + ... + 10^2) = ?
Choose the correct choice from the following answers:
A) 385
B) 395
C) 375
D) 55
E) 58
Explanation :   1^2+2^2+3^2+⋯+n^2=∑n^2=n(n+1)(2n+1)/6   1^2+2^2+3^2+⋯+10^2=n(n+1)(2n+1)/6=(10(10+1)[(2×10)+1])/6=(10×11×21)/6=(10×11×7)/2=385   385nswer is 385
<result>A</result>
(1^2 + 2^2 + 3^2 + ... + 10^2) = ?