Of the three numbers, the first is twice as second and three times the third. The average of the three numbers is 33, and the three numbers in order are?
Choose the correct choice from the following choices:  A) 54,27,18  B) 98,49,33  C) 126,63,36  D) 108,54,36  E) None of these
Explanation :   Solution: Let A =x,   B =x/2, C = x/3.   =x + x/2 + x/3 / 3 = 33   By solving we will get x = 54.   Hence 54,27,18= 54   B= 54/2= 
<gadget id="calculator">54/2</gadget>
<output>27</output>
27   C= 54/3= 
<gadget id="calculator">54/3</gadget>
<output>18</output>
18   54,27,18nswer : 54,27,18
<result>A</result>
Of the three numbers, the first is twice as second and three times the third. The average of the three numbers is 33, and the three numbers in order are?