If x = -5 and y = 8, what is the value of 2(x-y)^2 - xy ?
Select:
A) 358	B) 348	C) 368	D) 388	E) 378
x = -5 and y = 8   x-y = -5 - 8 = -13   x*y = -5 * 8 = -40   Now we apply it in the equation 2(x-y)^2 - xy =2(-13)^2-(-40)   ==&gt;2*169 +40 = 338+40= 
<gadget id="calculator">338+40</gadget>
<output>378</output>
378   Answer : 378
<result>E</result>
If x = -5 and y = 8, what is the value of 2(x-y)^2 - xy ?