A certain ball team has an equal number of right- and left-handed players. On a certain day, one-third of the players were absent from practice. Of the players at practice that day, one-third were right handed. What is the ratio of the number of right-handed players who were not at practice that day to the number of left handed players who were not at practice?	Options: A) 1/3 B) 5/1 C) 5/7 D) 7/5 E) 3/2
Say the total number of players is 18, 9 right-handed and 9 left-handed.   On a certain day, two-thirds of the players were absent from practice --&gt; 6 absent and 12 present.   Of the players at practice that day, one-third were right-handed --&gt; 12*1/3=4 were right-handed and 8 left-handed.   The number of right-handed players who were not at practice that day is 9-4 --  12*1/3= 
<gadget id="calculator"> --  12*1/3</gadget>
<output>4</output>
4 were right-handed and 8 left-handed.   The number of right-handed players who were not at practice that day is  9-4= 
<gadget id="calculator"> 9-4</gadget>
<output>5</output>
5.   The number of left-handed players who were not at practice that days is   9-8= 
<gadget id="calculator">  9-8</gadget>
<output>1</output>
1.   The ratio= 5/1.   Answer: 5/1
<result>B</result>
A certain ball team has an equal number of right- and left-handed players. On a certain day, one-third of the players were absent from practice. Of the players at practice that day, one-third were right handed. What is the ratio of the number of right-handed players who were not at practice that day to the number of left handed players who were not at practice?