A certain bakery baked a batch of 450 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?	Options.
A) 166	B) 213	C) 413	D) 438	E) 511
Cookies which have both nuts and chocolate chips = 185   Let fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that   batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch = x   (185+x)/(450+x) = 6/10   =&gt;1850 + 10x = 2700 + 6x   =&gt; 4x = 850   =&gt; x = 212.5   Therefore x = 213   Answer 213
<result>B</result>
A certain bakery baked a batch of 450 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?