What is the value of x^2yz − xyz^2, if x = − 2, y = 1, and z = 4? Answers:
A) 20  B) 24  C) 30  D) 32  E) 48
4*1*4 -(- 2*1*16)   =16+32= 
<gadget id="calculator">16+32</gadget>
<output>48</output>
48   Ans: 48
<result>E</result>
What is the value of x^2yz − xyz^2, if x = − 2, y = 1, and z = 4?