Working together, Jose and Jane can complete an assigned task in 30 days. However, if Jose worked alone and complete half the work and then Jane takes over the task and completes the second half of the task, the task will be completed in 45 days. How long will Jose take to complete the task if he worked alone? Assume that Jane is more efficient than Jose  Choose one:	A) 90 days	B) 30 days	C) 60 days	D) 65 days	E) 36 days
Assume:   Jose does 1 job in x days, so Jose does 1/x job in a day   Jane does 1 job in y days, so Jane does 1/y job in a day   Together, they does (x+y)/xy job in a day. This is equals to 1/20. So   (x+y)/xy = 1/30   30(x+y) = xy   Next, we're told 1 job takes 45 days to complete if Jose and Jane each does half the work. So since Jose does 1 job in x days, he wil need x/2 days to do half the job. Jane similarly will need y/2 days to do the other half.   x/2 + y/2 = 45   x+y = 90   So   xy = 30 *90= 
<gadget id="calculator">30 *90</gadget>
<output>2_700</output>
2700   The answer choices are:   90 days   30 days   60 days   65 days   36 days   From the answer choices, So I'll go for 90 days for Jose and 30 days for Jane.   90 daysnswer : 90 days
<result>A</result>
Working together, Jose and Jane can complete an assigned task in 30 days. However, if Jose worked alone and complete half the work and then Jane takes over the task and completes the second half of the task, the task will be completed in 45 days. How long will Jose take to complete the task if he worked alone? Assume that Jane is more efficient than Jose