f(1)=1,where f(x+y)=f(x)+f(y)+8xy-2.then f(7)=?	Choose the correct choice from the following.
A) 162 B) 163 C) 164 D) 165 E) 166
f(1)=1   f(2)= f(1+1)= 1+1+8-2= 
<gadget id="calculator">1+1+8-2</gadget>
<output>8</output>
8   f(3)= f(2+1)= 8+1+ (8*2*1)-2= 
<gadget id="calculator">8+1+ (8*2*1)-2</gadget>
<output>23</output>
23   f(6)= f(3+3)= 23+23+ (8*3*3)-2= 
<gadget id="calculator">23+23+ (8*3*3)-2</gadget>
<output>116</output>
116   f(7)= f(6+1)= 116+1+(8*6*1)-2= 
<gadget id="calculator">116+1+(8*6*1)-2</gadget>
<output>163</output>
163   thus ans is 163   ANSWER:163
<result>B</result>
f(1)=1,where f(x+y)=f(x)+f(y)+8xy-2.then f(7)=?