xy+yz=63
xz+yz=23
find x+y+z ?  Choose the correct choice from the following.
A) 23
B) 24
C) 25
D) 26
E) 27
take z as common term in second equation   ie z(x+y)=23   now as 23 is prime no therefore its factors must be 1 and 23.   now as x,y,z is integer no therefore z= 1 as sum of two integer cannot be equal to 1.   =&gt; z= 1 and x + y = 23   therefore x+y+z = 1 + 23= 
<gadget id="calculator">1 + 23</gadget>
<output>24</output>
24.   ANSWER:24
<result>B</result>
xy+yz=63
xz+yz=23
find x+y+z ?