A jar contains only red, yellow, and orange marbles. If there are 3 red, 5 yellow, and 4 orange marbles, and 2 marbles are chosen from the jar at random without replacing any of them, what is the probability that 2 yellow, 1 red, and no orange marbles will be chosen? Choose the most appropriate option: A) 1/60 B) 1/45 C) 2/45 D) 3/22 E) 6/22
I started by finding the 2 probabilities, without calculation, like this:   P(YYR)   P(YRY)   P(RYY)   I calculated the first one and ended in 1/22. I looked at the answer choices at this point and saw answer D: 3/22.   This helped me realise that for the 6 possible orderings the probabbility is the same. So, it should be (1/22)*(6), which indeed is 6/22.   6/22
<result>E</result>
A jar contains only red, yellow, and orange marbles. If there are 3 red, 5 yellow, and 4 orange marbles, and 2 marbles are chosen from the jar at random without replacing any of them, what is the probability that 2 yellow, 1 red, and no orange marbles will be chosen?