On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is?	Pick one:
A) 8
B) 10
C) 12
D) 16
E) 18
Clearly, (2272 - 875) = 1397, is exactly divisible by N.   Now, 1397 = 11 x 127   The required 3-digit number is 127, the sum of whose digits is 10   Option 10
<result>B</result>
On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is?