If f(f(n))+f(n)=2n+3 and f(0)=1, what is the value of f(2012)?	Choose the correct choice from the following answers:
A) 222
B) 2787
C) 2013
D) 2778
E) 10222
Put n = 0   Then f(f(0))+f(0) = 2(0) + 3 ⇒⇒ f(1) + 1 = 3 ⇒⇒ f(1) = 2   Put n = 1   f(f(1)) + f(1) = 2(1) + 3 ⇒⇒ f(2) + 2  ( (1)) +  (1)= 
<gadget id="calculator"> ( (1)) +  (1)</gadget>
<output>2</output>
2(1) + 3 ⇒⇒ f(2) + 2= 5 ⇒⇒f(2) = 3   Put n = 2   f(f(2)) + f(2) = 2(2) + 3 ⇒⇒ f(3) + 3 = 7 ⇒⇒ f(3) = 4   ......   f(2012) = 2013   Answer:2013
<result>C</result>
If f(f(n))+f(n)=2n+3 and f(0)=1, what is the value of f(2012)?