(1^2+2^2+3^2+.....+11^2)=? Choose the correct choice from the following answers:  A) 506  B) 345  C) 365  D) 385  E) None of them
formula is (1^2+2^2+3^2+....+n^2=1/6 n(n+1)(2n+1)   n=11   =(1/6x11x12x23)   =506   506nswer is 506.
<result>A</result>
(1^2+2^2+3^2+.....+11^2)=?