Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?
Choose the correct choice from the following answers:	A) 44, 36	B) 42, 33	C) 43, 36	D) 42, 36	E) None
Let the marks secured by them be x and (x + 9)   Then sum of their marks = x + (x + 9) = 2x + 9   Given that (x + 9) was 56% of the sum of their marks   =&gt;(x+9) = 56/100(2x+9)   =&gt;(x+9) = 14/25(2x+9)   =&gt; 25x + 225 = 28x + 126   =&gt; 3x = 99   =&gt; x = 33   Then (x + 9) = 33 + 9= 
<gadget id="calculator">33 + 9</gadget>
<output>42</output>
42   Hence their marks are 33 and 42   42, 33
<result>B</result>
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?