3 men and 3 women need to be seated in 2 rows with 3 chairs in each row. All men have to be seated in the back row. How many ways can this be done?	Pick
A) 6  B) 12  C) 24  D) 36  E) 72
For one particular arrangement of men, say {m1, m2, m3} women in the front row can be arranged in 3!=6 ways, as total # of arrangements of men is 3!=6 then total # of arrangements of men and women is 3!*3!=36.   ANS:36
<result>D</result>
3 men and 3 women need to be seated in 2 rows with 3 chairs in each row. All men have to be seated in the back row. How many ways can this be done?