At an elite baseball camp, 60% of players can bat both right-handed and left-handed. If 1/3 of the players who bat left-handed do not bat right-handed, what is the probability that a player selected at random does not bat left-handed?  Choose the correct choice from the following options:
A) 10%
B) 20%
C) 25%
D) 30%
E) 40%
2/3 of players who bat left-handed also bat right-handed.   Then 3/2(60%) = 90% of all players can bat left-handed.   P(a player does not bat left-handed) = 1 - 90% = 10%   The answer is 10%.
<result>A</result>
At an elite baseball camp, 60% of players can bat both right-handed and left-handed. If 1/3 of the players who bat left-handed do not bat right-handed, what is the probability that a player selected at random does not bat left-handed?