In how many ways can 5 different candies be distributed among 4 children? (Children could get 0 candies or more than one candy) Select.
A) 4^5 B) 5^4 C) 5! D) 4! E) 4!*5!
There are in total 5 candies. Let's say A,B,C,D and E.   Candy A can be distributed among any 4 children. So, there are 4 ways of distributing candy A.   similarly candy B,C,D and E can be distributed in 4 ways.   So total ways of distribution is   4*4*4*4*4 = 4^5.   4^5NS:4^5
<result>A</result>
In how many ways can 5 different candies be distributed among 4 children? (Children could get 0 candies or more than one candy)