The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 15 consecutive integers that start with (m + 2)?
Choices.
A) m + 4  B) n + 6  C) n + 7  D) m + 5  E) n + 4
The average of consecutive numbers is the middle number.   Then n = m+2.   The average of 15 consecutive numbers starting from n is n+7.   The answer is n + 7.
<result>C</result>
The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 15 consecutive integers that start with (m + 2)?