If (x^2 + 1)y=5, which of the following is not a possible value for y?	Choose the correct choice from the following answers
A) 1/2  B) 2  C) 4/3  D) 3  E) 13/2
Its simple   equation is (x^2 +1)y = 5 ===&gt; x^2 = (5/y) - 1 . As , in LHS, it is x^2 the value has to be positive or zero in RHS.   Hence, (5/y) - 1&gt;= 0 ===&gt; y =&lt; 5. Now only option E has greater value of 'y' than 5.   Thus, correct ans is 13/2
<result>E</result>
If (x^2 + 1)y=5, which of the following is not a possible value for y?