An object thrown directly upward is at a height of h feet after t seconds, where h = -14 (t-3)^2 + 140. At what height, in feet, is the object 2 seconds after it reaches its maximum height?	Choose the correct choice from the following options
A) 62
B) 68
C) 76
D) 84
E) 96
We see that h will be a maximum h=140 when t-3=0, that is when t=3.   At t=5, h = -14(5-3)^2 + 140 = -14(4) + 140 = 84   The answer is 84.
<result>D</result>
An object thrown directly upward is at a height of h feet after t seconds, where h = -14 (t-3)^2 + 140. At what height, in feet, is the object 2 seconds after it reaches its maximum height?