y =x^2 + bx + 128 cuts the x axis at (h, 0) and (k, 0). If h and k are integers, what is the least value of b?
Select the correct option
A) -129	B) -132	C) 32	D) 64	E) 128
As the curve cuts the x-axis at (h,0) and (k,0). Therefore h,k are the roots of the quadratic equation.   For the quadratic equation is in the form of ax^2+bx+c=0,   The product of the roots =c/a= 128/1 = 64 and the sum of the roots =-b/a=-b/1   128 can be expressed as product of two numbers in the following ways:   1 * 128   2 * 64   4 * 32   8 * 16   The sum of the roots is maximum when the roots are 1 and 128 and the maximum sum is 1 + 128= 
<gadget id="calculator">1 + 128</gadget>
<output>129</output>
129.   The least value possible for b is therefore -129.   a
<result>A</result>
y =x^2 + bx + 128 cuts the x axis at (h, 0) and (k, 0). If h and k are integers, what is the least value of b?