Tickets numbered from 1 to 26 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bears a number which is a multiple of 3?	Pick.
A) 1/5 B) 2/5 C) 3/10 D) 4/13 E) 1/7
Here, S = [1, 2, 3, 4, …., 19, 20, 21, 22, 23, 24, 25, 26]   Let E = event of getting a multiple of 3 = [3, 6, 9, 12, 15, 18, 21, 24]   P (E) = n (E) / n (S) = 8 / 26 = 4/13   The answer is 4/13.
<result>D</result>
Tickets numbered from 1 to 26 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bears a number which is a multiple of 3?