If there are 8 pairs of twins, and a committee will be formed with 3 members. In how many ways this committee formed in a way that no siblings in a group? Select
A) 32 B) 24 C) 56 D) 448 E) 540
Firstly, there are 8 ways to choose 3 groups from the 4 groups. Hence 8C3.   Next, with the 3 groups chosen, there are 2^3 choices of choosing either one of the siblings.   Hence, the total number of ways are 8C3 * (2^3) = 448   448
<result>D</result>
If there are 8 pairs of twins, and a committee will be formed with 3 members. In how many ways this committee formed in a way that no siblings in a group?