There are 7 cups placed on a table; 4 are juice cups and the other 3 are tea cups. If 2 cups are to be selected at random from the 7 cups, what is the probability that at least one of the juice cup will be selected?  Pick one
A) 6/7
B) 2/7
C) 3/7
D) 4/7
E) 5/7
Total probability=7C2=21   4C2 +4C1*3C1=6+12= 
<gadget id="calculator">6+12</gadget>
<output>18</output>
18   therefore the probability that at least one of the fashion magazines will be selected= 18/21=6/7   answer is 6/7
<result>A</result>
There are 7 cups placed on a table; 4 are juice cups and the other 3 are tea cups. If 2 cups are to be selected at random from the 7 cups, what is the probability that at least one of the juice cup will be selected?