The average price of 10 oranges is Rs. 12 while the average price of 8 of these oranges is Rs. 11.75. Of the remaining two oranges, if the price of one orange is 60% more than the price of the other, what is the price of each of these two oranges?	Choose the correct option:
A) Rs 5, Rs 7.50  B) Rs 8, Rs 12  C) Rs 10, Rs 16  D) Rs 12, Rs 14  E) None of these
Explanation :   Total price of the two oranges = Rs. [(12 x 10) (11.75 x 8)]   = Rs. (120 - 94) = Rs. 26.   Let the price of one orange be Rs. x.   Then, the price of other orange = Rs. (x + 60% of x) = Rs. x + 3/5x = Rs. 8x/5   So, x + 8x/5 = 26   13x = 130   x = 10.   The prices of the two oranges are Rs. 10 and Rs. 16   Answer : Rs 10, Rs 16
<result>C</result>
The average price of 10 oranges is Rs. 12 while the average price of 8 of these oranges is Rs. 11.75. Of the remaining two oranges, if the price of one orange is 60% more than the price of the other, what is the price of each of these two oranges?