Jackie has two solutions that are 2 percent sulfuric acid and 12 percent sulfuric acid by volume, respectively. If these solutions are mixed in appropriate quantities to produce 60 liters of a solution that is 10 percent sulfuric acid, approximately how many liters of the 12 percent solution will be required?
Answers.
A) 18 B) 20 C) 48 D) 36 E) 42
let a=amount of 2% acid and b= amount of 12% acid.   Now, The equation translates to,   0.02a + .12b = .1(a+b)   but a+b= 60   therefore .02a + .12b = .1(60)   =&gt; 2a + 12b = 600   but b=60-a   therefore   2a+ 12(60-a) = 600   =&gt; 10a = 120   hence a = 12. b = 60 -12= 
<gadget id="calculator">60 -12</gadget>
<output>48</output>
48.   Answer : 48
<result>C</result>
Jackie has two solutions that are 2 percent sulfuric acid and 12 percent sulfuric acid by volume, respectively. If these solutions are mixed in appropriate quantities to produce 60 liters of a solution that is 10 percent sulfuric acid, approximately how many liters of the 12 percent solution will be required?