Three (rather lazy) men A, B and C working together can do a work in 5 days. They start the work together and A works for 1 day and takes rest on the second day, B works for 2 days and takes rest on the next two days and C works for 2 days and takes rest on the next three days. In how many days will the work be completed ? (A, B, C work at the same rate) Select: A) 7 days B) 8 days C) 9 days D) 10 days E) 11 days
Total work is 3*5= 
<gadget id="calculator">3*5</gadget>
<output>15</output>
15 units.   A does 1 day of work every 2 days.   B does 2 days of work every 4 days.   C does 2 days of work every 5 days.   Test the options.   In 7 days:   A will do  1*3 + 1= 
<gadget id="calculator"> 1*3 + 1</gadget>
<output>4</output>
4 units (3 complete cycles and 1 day of work).   B will do  2*1+ 2= 
<gadget id="calculator"> 2*1+ 2</gadget>
<output>4</output>
4 units (1 complete cycle, 2 days of work, and 1 day of rest).   C will do  2*1 + 2= 
<gadget id="calculator"> 2*1 + 2</gadget>
<output>4</output>
4 units (1 complete cycle and 2 days of work).   Total= 4 + 4 + 4= 
<gadget id="calculator">4 + 4 + 4</gadget>
<output>12</output>
12 units.   In 8 days:   A will do  1*4= 
<gadget id="calculator"> 1*4</gadget>
<output>4</output>
4 units (4 complete cycles).   B will do  2*2= 
<gadget id="calculator"> 2*2</gadget>
<output>4</output>
4 units (2 complete cycles).   C will do  2*1 + 2= 
<gadget id="calculator"> 2*1 + 2</gadget>
<output>4</output>
4 units (1 complete cycle, 2 days of work, and 1 day of rest).   Total= 4 + 4 + 4= 
<gadget id="calculator">4 + 4 + 4</gadget>
<output>12</output>
12 units.   In 9 days:   A will do  1*4 + 1= 
<gadget id="calculator"> 1*4 + 1</gadget>
<output>5</output>
5 units (4 complete cycles and 1 day of work).   B will do 2*2+ 1= 4 units (2 complete cycles and 1 day of work).   C will do  2*1 + 2= 
<gadget id="calculator"> 2*1 + 2</gadget>
<output>4</output>
4 units (1 complete cycle, 2 days of work, and two days of rest).   Total= 5 + 5 + 4= 
<gadget id="calculator">5 + 5 + 4</gadget>
<output>14</output>
14 units.   In 10 days:   A will do  1*5= 
<gadget id="calculator"> 1*5</gadget>
<output>5</output>
5 units (5 complete cycles).   B will do  2*2+ 2= 
<gadget id="calculator"> 2*2+ 2</gadget>
<output>6</output>
6 units (2 complete cycle and 2 days of work).   C will do  2*2= 
<gadget id="calculator"> 2*2</gadget>
<output>4</output>
4 units (2 complete cycles).   Total= 5 + 6 + 4= 
<gadget id="calculator">5 + 6 + 4</gadget>
<output>15</output>
15 units.   Therefore, the answer is 10 days.
<result>D</result>
Three (rather lazy) men A, B and C working together can do a work in 5 days. They start the work together and A works for 1 day and takes rest on the second day, B works for 2 days and takes rest on the next two days and C works for 2 days and takes rest on the next three days. In how many days will the work be completed ? (A, B, C work at the same rate)