What is the positive difference between the sum of the squares of the first 7 positive integers and the sum of the prime numbers between the first square and fourth square? Choose the correct choice from the following choices:
A) 11	B) 52	C) 83	D) 94	E) 99
Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.   the sum of the squares of the first 4 positive integers = 1^2 + 2^2 + 3^2 +...+7^2 = 140   the sum of the prime numbers between the first square(=1) and fourth square(=16) = 2+3+5+7+11+13= 
<gadget id="calculator">2+3+5+7+11+13</gadget>
<output>41</output>
41.   So the difference between 41 and 140 is 99.   So the answer is (99).
<result>E</result>
What is the positive difference between the sum of the squares of the first 7 positive integers and the sum of the prime numbers between the first square and fourth square?