A box contains 4 blue marbles, 3 red, 6 green marbles and two yellow marbles. If two marbles are picked at random, what is the probability that they are either blue or yellow?  Choose the correct choice from the following choices
A) 5/10  B) 4/10  C) 1/10  D) 2/10  E) 3/10
Given that there are 4 blue marbles, 3 red marbles, 6 green marbles and 2 yellow marbles. Probability that both marbles are blue = 41/10â‚‚/Â¹âµ1/10â‚‚ = (3 * 2)/(15 * 14) = 2/35   Probability that both are yellow = Â²1/10â‚‚/Â¹âµ1/10â‚‚ = (1)/(15 * 14) = 1/210   Probability that one blue and other is yellow = (41/10â‚ * Â²1/10â‚)/Â¹âµ1/10â‚‚ = (4*2)/(15 * 14) = 4/105   Required probability = 2/35 + 1/210 + 4/105   = 1/10   Answer:1/10
<result>C</result>
A box contains 4 blue marbles, 3 red, 6 green marbles and two yellow marbles. If two marbles are picked at random, what is the probability that they are either blue or yellow?