In how many different number of ways a Committee of 3 person of can be selected from 5 men and 3 women such that atleast 1 women is included in the committee?	Choose the correct choice
A) 38 B) 40 C) 42 D) 46 E) 49
1W 2M 2W 1M 3W   = 3C1 × 5C2 + 3C2 × 5C1 + 3C3s   = 3 × (5 × 4)/2 + 3 × 5 + 1   = 30 + 15 + 1= 
<gadget id="calculator">30 + 15 + 1</gadget>
<output>46</output>
46   Total 5M 3W   8C3= 56   5C3 = 10   Atleast one women = total - with out women   Atleast one women = 56 - 10= 
<gadget id="calculator">56 - 10</gadget>
<output>46</output>
46   46)
<result>D</result>
In how many different number of ways a Committee of 3 person of can be selected from 5 men and 3 women such that atleast 1 women is included in the committee?