If the tens digit of positive integers h, y are 6, how many values of the tens digit of 2(h+y) can be there? Choose the most appropriate option.
A) 2	B) 3	C) 4	D) 5	E) 6
If the tens digit of positive integers h, y are 6, how many values of the tens digit of 2(h+y) can be there?   A. 2   B. 3   C. 4   D. 5   E. 6   -&gt; If h=y=60, 2(h+y)=240 is derived. If h=y=69, 2(h+y)=276 is derived, which makes 4,5,6,7 possible for the tens digit. Therefore, the answer is 4.
<result>C</result>
If the tens digit of positive integers h, y are 6, how many values of the tens digit of 2(h+y) can be there?