For which of the following functions f is f(b) = f(1-b) for all b?
Options:  A) f (x) = 1 - x  B) f (b) = 1 - b^2  C) f (b) = b^2 - (1 - b)^2  D) f (b) = b^2*(1 - b)^2  E) f (x) = x/(1 - x)
I remember seeing this problem in a GMATprep test. I think choice D should be F(b)=(b^2) (1-b)^2. If that is true then substituting (1-b) for will give us the same function back and the answer choice is f (b) = b^2*(1 - b)^2, where the function is multiplicative
<result>D</result>
For which of the following functions f is f(b) = f(1-b) for all b?