Which of the following is the lowest positive integer that is divisible by the first 6 positive integer multiples of 3?  Choices:	A) 90	B) 100	C) 120	D) 150	E) 180
The number must be divisible by 3, 2*3, 3^2, 2^2*3, 5*3, and 2*3^2.   The lowest such number is 2^2*3^2*5 = 180.   The answer is 180.
<result>E</result>
Which of the following is the lowest positive integer that is divisible by the first 6 positive integer multiples of 3?