What is the area inscribed by the lines y = 10, x = 1, y = 3x+1 on an xy-coordinate plane? Choose the correct choice from the following answers.
A) a) 1	B) b) 2	C) c) 3	D) d) 6	E) e) 12
First, let's graph the lines y = 10 and x = 1   At this point, we need to find the points where the line y = 3x+1 INTERSECTS the other two lines.   For the vertical line, we know that x = 1, so we'll PLUG x = 1 into the equation y = 3x+1 to get y = 3(1)+1 = 4   Perfect, when x = 1, y = 5, so one point of intersection is (1,4)   For the horizontal line, we know that y = 10, so we'll PLUG y = 10 into the equation y = 3x+1 to get 10 = 3x+1. Solve to get: x = 3   So, when y = 10, x = 3, so one point of intersection is (3,10)   Now add these points to our graph and sketch the line y = 3x+1   At this point, we can see that we have the following triangle.   The base has length 2 and the height is 6   Area = (1/2)(base)(height)   = (1/2)(2)(6)   = 6   Answer:   d) 6
<result>D</result>
What is the area inscribed by the lines y = 10, x = 1, y = 3x+1 on an xy-coordinate plane?