If the diameter of circle R is 60% of the diameter of circle S, the area of circle R is what percent of the area of circle S?
Select.
A) 50%	B) 46%	C) 36%	D) 26%	E) 38%
Let diameter of circle R , dr = 60   and diameter of circle S , ds = 100   Radius of circle R , Rr = 30   Radius of circle S , Rs = 50   Area of circle R/ Area of circle S = (pi * Rr ^2 ) /( pi * Rs^2 )   = (30/50)^2 = (6/10)^2   =36%   Answer :36%
<result>C</result>
If the diameter of circle R is 60% of the diameter of circle S, the area of circle R is what percent of the area of circle S?