What is the probability that out of the combinations that can be made using all the letters of the word EXCESS, Jerome will randomly pick a combination in which the first letter is a vowel and the last letter is a consonant? Select
A) 96/320	B) 24/180	C) 33/100	D) 48/180	E) 96/180
lets see the possiblilties with the given restrictions..   lets put the starting letter as vowel E..   then remaining 5 places can be filled in 5!/2!= 60..   but this consists of second E as the last letter and we will have to subtract these ways from 60..   so when first and last places are occupied by E, the remaining 4 places can be filled by 4!/2!=12 ways..   so ways with the restrictions= 60-12= 48..   so prob= 48/180   ANSWER :48/180
<result>D</result>
What is the probability that out of the combinations that can be made using all the letters of the word EXCESS, Jerome will randomly pick a combination in which the first letter is a vowel and the last letter is a consonant?