In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term. What is the sum of the 16th, 17th, and 19th terms in the sequence?
Choose the correct option
A) 2^18  B) 3(2^17)  C) 7(2^16)  D) 3(2^16)  E) 11(2^15)
the sequence comes out to be 2^0,2^1,2^2,2^3 and so on...   so 16th term will be 2^15   17th term 2^16   19th term 2^18   adding all three   we get   2^15+(2^15)*2+(2^15)*8   so answer is 2^15(1+2+8)=&gt;11(2^15)   answer 11(2^15)
<result>E</result>
In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term. What is the sum of the 16th, 17th, and 19th terms in the sequence?