When a metallic ball bearing is placed inside a cylindrical container, of radius 2 cm, the height of the water, inside the container, increases by 0.6 cm. The radius, to the nearest tenth of a centimeter, of the ball bearing is	Choose the correct choice
A) 1 cm
B) 1.2 cm
C) 2 cm
D) 0.6 cm
E) None
Solution   When the ball was put in water, the volume of water increased by.   pi*22*0.6 = 2.4 pi cubic cm   The above volume is equal to the volume of the ball with radius r to find. Hence   (4/3)*pi*r3 = 2.4 pi   Solve the above for r   r = 1.2 cm   Answer 1.2 cm
<result>B</result>
When a metallic ball bearing is placed inside a cylindrical container, of radius 2 cm, the height of the water, inside the container, increases by 0.6 cm. The radius, to the nearest tenth of a centimeter, of the ball bearing is