What is the sum of all possible 3-digit numbers that can be constructed using the digits 1, 2, and 4 if each digit can be used only once in each number?
Choose the correct choice from the following options:
A) 1210  B) 1221  C) 1332  D) 1443  E) 1554
There are 6 possible arrangements of the three numbers.   Then each number will be in the hundreds, tens, and ones place two times each.   The sum is 2(111) + 2(222) + 2(444) = 1554   The answer is 1554.
<result>E</result>
What is the sum of all possible 3-digit numbers that can be constructed using the digits 1, 2, and 4 if each digit can be used only once in each number?