Two numbers when divided by a divisor leave remainders of 198 and 322 respectively. The remainder obtained when the sum of the numbers is divided by the same divisor is 68. Find the divisor. Options:
A) 365
B) 398
C) 412
D) 435
E) 452
Let x be the divisor.   N1 = xa + 198   N2 = xb + 322   N1 + N2 = x(a+b) + 520 = xc + 68   x(c-a-b) = 452 but we know that x &gt; 322, thus (c-a-b) must equal 1.   The answer is 452.
<result>E</result>
Two numbers when divided by a divisor leave remainders of 198 and 322 respectively. The remainder obtained when the sum of the numbers is divided by the same divisor is 68. Find the divisor.