A fair coin is to be tossed twice and an integer is to be selected at random from one of the integers 3, 8, and 10. What is the probability that at least one head is tossed and an even integer is selected?  Select the correct option
A) 1/6 B) 1/4 C) 1/3 D) 1/2 E) 7/12
1) Let us simply state the possibilities. This method works for this problem due to the limited number of possibilities   Ways of getting at least a head and an even number =6   HT8   TH8   HT10   TH10   HH8   HH10   Ways of not getting at least one head and an even number=6   TT8   TT10   HT3   TH3   HH3   TT3   Total probability=6/12=1/2   Answer:1/2
<result>D</result>
A fair coin is to be tossed twice and an integer is to be selected at random from one of the integers 3, 8, and 10. What is the probability that at least one head is tossed and an even integer is selected?