The rhombus (AFCE) is inscribed in rectangle (ABCD). The length of BF = DE.
If the rectangle has a width of 20 yards and a length of 25 yards, what would be the total length (the perimeter) of a fence along the sides defined by AFCE?  Select.
A) 80 yards	B) 82 yards	C) 84 yards	D) 85 yards	E) 90 yards
The definition of a rhombus states that every side is of equal length. This definition is the key to solving this question.   1) We state that the hypotenuse of either side triangle is x. For this solution, I will be working with the left triangle.   2) We state that the bottom and top sides of the rhombus are also x, due to the definition of a rhombus.   3) We will define the bottom of the left triangle as y. That is, for the rectangle bottom itself, we can define it as 25 = y + x, where x is a side for the rhombus and y is the bottom part of the left triangle.   4) From (1), we know that x = 202+y2−−−−−−−√202+y2.   5) From (3), we know x = 25 - y.   6) From (4) and (5), we have the equation 202+y2−−−−−−−√=25−y202+y2=25−y   7) Solving for y, we get 4.5.   8) 25 - 4.5 = 20.5 = x   9) Since all sides of the rhombus are the same, 20.5 * 4 = 41 * 2= 
<gadget id="calculator">41 * 2</gadget>
<output>82</output>
82.   The answer is 82 yards, 82
<result>B</result>
The rhombus (AFCE) is inscribed in rectangle (ABCD). The length of BF = DE.
If the rectangle has a width of 20 yards and a length of 25 yards, what would be the total length (the perimeter) of a fence along the sides defined by AFCE?