Of the 14 members of a dancing group,10 can perform modern dancing, 8 can perform traditional dancing, and 4 can perform both type of dancing. If one member is chosen at random, what is the probability that the member chosen will be someone who can not perform neither type of dancing? Pick one:
A) a) 1/5
B) b) 1/10
C) c) 1/7
D) d) 1/4
E) e) 0
You know how to solve for Total number of people who can perform at least one type of dancing:   Total = n(A) + n(B) - n(A and B)   Total people who can use at least one machine = 10 + 8 - 4= 
<gadget id="calculator">10 + 8 - 4</gadget>
<output>14</output>
14   So all 14 people know how to perform at least one type of dancing. Hence, if you pick anyone, the probability is 0 that he/she wouldn't know how to perform any type of dancing   Answer (e) 0)
<result>E</result>
Of the 14 members of a dancing group,10 can perform modern dancing, 8 can perform traditional dancing, and 4 can perform both type of dancing. If one member is chosen at random, what is the probability that the member chosen will be someone who can not perform neither type of dancing?