Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?	Choose the correct choice from the following options.
A) 4.9
B) 4.8
C) 2.5
D) 2
E) 0.2
If C is the answer, then the question means that the concentration of water the newt day became 96%.   Out of 5 kilograms 98%, or 4.9 kilograms was water and 0.1 kilograms was non-water.   The next day, after some water evaporated, oranges became 96% water and 4% of non-water, so the next day 0.1 kilograms of non-water composed 4% of oranges, which means that the new weight of the oranges was x*0.04=0.1 --&gt; x=2.5 kilograms.   Answer: 2.5.
<result>C</result>
Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?