A certain population of bacteria doubles every 10 minutes. If the number of bacteria in the population initially was 10^5, then what was the number in the population 80 minutes later?  Options:
A) 2(10^5) B) 8(10^5) C) (2^8)(10^5) D) (10^8)(10^5) E) (10^5)^8
Every 10 minutes, the population is double the previous population.   In 80 minutes, the population doubles 8 times.   The population then is 2^8*10^5.   The answer is (2^8)(10^5).
<result>C</result>
A certain population of bacteria doubles every 10 minutes. If the number of bacteria in the population initially was 10^5, then what was the number in the population 80 minutes later?