It is being given that (2^32 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
Choices:
A) 2^16
B) 7 * 2^23
C) 7 * 2^33
D) 5 * 2^32
E) 2^96 + 1
Assume 2^32 = x   Therefore , (2^32 + 1) = (x + 1) --------eq. 1   2^96 + 1 = (2^32)^3 + 1   = x^3 + 1 = x^3 + 1^3   = (x + 1) (x^2 - x +1)---------eq. 2   From eq. 1 and 2   Option 2^96 + 1 is correct.
<result>E</result>
It is being given that (2^32 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?