How many 3 digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5 and none of the digits is repeated?
Answers.
A) 20	B) 16	C) 8	D) 24	E) 29
Explanation :   A number is divisible by 5 if the its last digit is a 0 or 5   We need to find out how many 3 digit numbers can be formed from the 6 digits (2,3,5,6,7,9)   which are divisible by 5.   Since the 3 digit number should be divisible by 5, we should take the digit 5   from the 6 digits(2,3,5,6,7,9) and fix it at the unit place.   There is only 1 way of doing this   1   Since the number 5 is placed at unit place, we have now five digits(2,3,6,7,9) remaining.   Any of these 5 digits can be placed at tens place   5 1   Since the digits 5 is placed at unit place and another one digits is placed at tens place,   we have now four digits remaining. Any of these 4 digits can be placed at hundreds place.   4 5 1   Required Number of three digit numbers = 4 x 5 x 1 = 20.. 20nswer : Option 20
<result>A</result>
How many 3 digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5 and none of the digits is repeated?