The total circumference of two circles is 49. If the first circle has a circumference that is exactly twice the circumference of the second circle, then what is the approximate sum of their two radii?  Choices:
A) 7.8
B) 6.0
C) 6.7
D) 9.7
E) 18.0
Let r= Radius of smaller circle. Let R = Radius of larger circle   Therefore:   2πr + 2πR = 49   where 2r = R   Thus:   2πr + 4πr = 49   6πr = 49   r = approx 2.6   πR + 2Rπ = 49   3πR = 49   R = approx 5.2   r + R = approx 7.8   7.8nswer :7.8
<result>A</result>
The total circumference of two circles is 49. If the first circle has a circumference that is exactly twice the circumference of the second circle, then what is the approximate sum of their two radii?