A florist has 2 azaleas, 3 buttercups, and 7 petunias. The florist puts two flowers together at random in a bouquet. However, the customer calls and says that she does not want two of the same flower. What is the probability that the florist does not have to change the bouquet? Choose the correct choice:
A) 7/11 B) 17/22 C) 25/33 D) 41/66 E) 87/132
The probability that two of the same flowers were chosen:   P(AA) = 2/12 * 1/11 = 2/132   P(BB) = 3/12 * 2/11 = 6/132   P(PP) = 7/12 * 6/11 = 42/132   The sum of these probabilities is 25/66   P(two flowers are different) = 1 - 25/66 = 41/66   The answer is 41/66.
<result>D</result>
A florist has 2 azaleas, 3 buttercups, and 7 petunias. The florist puts two flowers together at random in a bouquet. However, the customer calls and says that she does not want two of the same flower. What is the probability that the florist does not have to change the bouquet?