What is the greatest value of n such that 30!/6^n is an integer?	Select.
A) 11
B) 12
C) 13
D) 14
E) 15
30/2 + 30/(2^2)+30/(2^3)+30(2^4) = 15+7+3+1= 
<gadget id="calculator">15+7+3+1</gadget>
<output>26</output>
26   How many 3's are there ? so that the division leads to be an integer   30/3 + 30/(3^2)+30/(3^3)= 10+3+1= 
<gadget id="calculator">10+3+1</gadget>
<output>14</output>
14   How many 3's and 2's are there so that the division leads to be an integer   Minimum or common between 26 and 14.   Answer is 14.   ANSWER:14
<result>D</result>
What is the greatest value of n such that 30!/6^n is an integer?