If the reciprocals of two consecutive positive integers are added together, what is the sum in terms of the greater integer d?	Choose the correct choice:  A) (3d-1)/(d^2- d)  B) (2d-1)/(d^4- d)  C) d^2- d  D) 2d-1  E) (2d-1)/(d^2- d)
Let two consecutive positive integers be d and d-1 (Greater integer is d)   So,   (1/d) + [1/(d-1)]   = (2d-1)/d(d-1)   =(2d-1)/(d^2- d)   Answer : (2d-1)/(d^2- d)
<result>E</result>
If the reciprocals of two consecutive positive integers are added together, what is the sum in terms of the greater integer d?