In how many different number of ways a combination of 3 men and 2 women can be selected from 6 men and 5 women.  Pick one
A) 10	B) 20	C) 30	D) 35	E) 40
6C3   = 6!/(3! . 3!)   = (6 × 5 × 4)/(3 × 2)   = 5 × 4 = 20.   20)
<result>B</result>
In how many different number of ways a combination of 3 men and 2 women can be selected from 6 men and 5 women.