Which of the following are roots of an equation (x^-2)-(2x^-1)-35=0	Choose the correct choice:
A) 1/5 and -1/7 B) -1/5 and 1/7 C) 1/5 and 1/7 D) -1/5 and -1/7 E) -5/2 and -1/7
Given: (x^-2) - (2x^-1) - 35 = 0   Rewrite as: 1/(x²) - 2/x - 35 = 0   Remove fractions by multiplying both sides by x² to get: 1 - 2x - 35x² = 0   Rearrange to get: 35x² + 2x - 1 = 0   Factor to get: (5x + 1)(7x - 1) = 0   So, EITHER 5x + 1 OR 7x - 1 = 0   If 5x + 1 = 0, then x = -1/5   If 7x - 1 = 0, then x = 1/7   So, the roots (solutions) are -1/5 and 1/7   The answer is -1/5 and 1/7.
<result>B</result>
Which of the following are roots of an equation (x^-2)-(2x^-1)-35=0