If the numerator of a fraction is increased by 2 and the denominator is increased by 1, the fraction becomes 5⁄8 and if the numerator of the same fraction is increased by 3 and the denominator is increased by I the fraction becomes 3⁄4. What is the original fraction?	Choose the correct choice from the following choices:
A) Data inadequate
B) 2⁄7
C) 4⁄7
D) 3⁄7
E) None of these
Let the original fraction be x⁄y.   Then x+2y+1=58x+2y+1=58 or, 8x – 5y = – 11........ (i)   Again, x+3y+1=34x+3y+1=34 or, 4x – 3y = –9........ (ii)   Solving, (i) and (ii) we get x = 3 and y = 7   ∴ fraction = 3⁄7   Answer 3⁄7
<result>D</result>
If the numerator of a fraction is increased by 2 and the denominator is increased by 1, the fraction becomes 5⁄8 and if the numerator of the same fraction is increased by 3 and the denominator is increased by I the fraction becomes 3⁄4. What is the original fraction?