If a car went the first third of the distance at 80 kmh, the second third at 24 kmh, and the last third at 44 kmh, what was the average speed of the car for the entire trip? Choose the most appropriate option:
A) 39 kmh
B) 40 kmh
C) 42 kmh
D) 44 kmh
E) 50 kmh
39 kmhssume D/3 = 2640 (this number is convenient because it is divisible by 80, 24 and 44)   So:   2640 = 80*T1 = 33 hrs   2640 = 24*T2 = 110 hrs   2640 = 44*T3 = 60 hrs   T = T1 + T2 + T3 = 203 hrs   D = RT   (2640*3) = R*203   R = 39   39 kmhNSWER: 39 kmh
<result>A</result>
If a car went the first third of the distance at 80 kmh, the second third at 24 kmh, and the last third at 44 kmh, what was the average speed of the car for the entire trip?