9x^2+3px+6q divided by 3x+1 leave reminder -3/4 and qx^2+4px+7 is exactly divisible by x+1, then find the values of p and Q
Choose the correct choice from the following options
A) 7/4,0  B) 8/4,0  C) 9/4,0  D) 7/4,1  E) 7/4,2
1st quadration eqn gives remainder -3/4 on dividing by 3x+1.so, eqn-(-3/4) is divisible by 3x+1 means eqn+3/4 has a roo x=-1/3.so,on putting x=-1/3 in the 1st eqn,1-p+6q+3/4=0 that is 6q-p=-7/4.2nd quad eqn is divisible by x+1.so x=-1 is root of that eqn.on putting x=-1,eqn=0.so,   q-4p+7=0.on comparing two linear eqns in p and 2,we get p=7/4 and q=0.   7/4,0NSWER:7/4,0
<result>A</result>
9x^2+3px+6q divided by 3x+1 leave reminder -3/4 and qx^2+4px+7 is exactly divisible by x+1, then find the values of p and Q