In how many ways can the letters D, I, G, I, T, K be arranged so that the two I's are not next to each other?
Choose the correct choice from the following answers:
A) 36  B) 48  C) 72  D) 96  E) 240
1 D   2 I   1 G   1 T   1 K   Number of ways these letters can be arranged = 6!/2! (2! to account 2 same Is) = 360   Consider 2 Is as 1 entity and thus the number of arrangements for (II)DGT = 5! = 120   Total allowed cases = 360-120= 
<gadget id="calculator">360-120</gadget>
<output>240</output>
240   240 is the correct answer.
<result>E</result>
In how many ways can the letters D, I, G, I, T, K be arranged so that the two I's are not next to each other?