A jogger running at 9 km/hr along side a railway track is 270 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?	Pick: A) 67 sec B) 89 sec C) 39 sec D) 87 sec E) 45 sec
Speed of train relative to jogger = 45 - 9= 
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
36 km/hr.= 36 * 5/18= 
<gadget id="calculator">36 * 5/18</gadget>
<output>10</output>
10 m/sec.   Distance to be covered= 270 + 120= 
<gadget id="calculator">270 + 120</gadget>
<output>390</output>
390 m.   Time taken= 390/10= 
<gadget id="calculator">390/10</gadget>
<output>39</output>
39 sec.   Answer: 39 sec
<result>C</result>
A jogger running at 9 km/hr along side a railway track is 270 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?