Out of first 40 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is ?
Select.
A) 11/40  B) 17/29  C) 17/40  D) 31/40  E) 17/27
n(S) = 40   n(Even no) = 20 = n(E)   n(Prime no) = 12 = n(P)   P(EᴜP)   = 20/40 + 12/40 - 1/40   = 31/40   Answer:31/40
<result>D</result>
Out of first 40 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is ?