The perimeters of two squares are 40 cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.  Pick:
A) 24 cm
B) 17 cm
C) 14 cm
D) 10 cm
E) 12 cm
Side of first square = (40/4)= 
<gadget id="calculator">(40/4)</gadget>
<output>10</output>
10 cm;   Side of second square= (32/4)= 
<gadget id="calculator">(32/4)</gadget>
<output>8</output>
8 cm.   Area of third square= [(10) 2 - (8) 2] cm2 = (100 - 64) cm2 = 36 cm2.   Side of third square = (36)(1/2) cm = 6 cm.   Required perimeter = (6 x 4) cm = 24 cm.   24 cmNSWER 24 cm 24cm
<result>A</result>
The perimeters of two squares are 40 cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.