If (2^x)(3^y) = 576, where x and y are positive integers, then (2^x-1)(3^y-2) equals:
Choices
A) 16	B) 24	C) 32	D) 96	E) 144
So I would start attacking this problem by quickly performing the prime factorization of 288. With that it is easy to count the 5 twos and the 2 threes that are the prime factors. So x=6, y=2. now quickly 2^5(3^0)=32. Than answer should be number 3.   32
<result>C</result>
If (2^x)(3^y) = 576, where x and y are positive integers, then (2^x-1)(3^y-2) equals: