If 170!/10^n is an integer, what is the largest possible value of n?  Choose the correct answer:
A) 47
B) 46
C) 41
D) 48
E) 45
The question actually asks the highest power of 10 which divides 300! ( For a number to be an integer - Without any remainder all the trailing zeroe's must be divided by the denominator)   10 = 2 x 5   170 factorial will have 41 as -   170/5= 
<gadget id="calculator">170/5</gadget>
<output>34</output>
34   34/5= 6   6/5 =1   So answer will be (41) 41
<result>C</result>
If 170!/10^n is an integer, what is the largest possible value of n?