A sphere is inscribed in a cube with an edge of 10. What is the shortest possible distance from one of the vertices of the cube to the surface of the sphere?  Select the correct option:
A) 10(√3-1)	B) 5	C) 10(√2-1)	D) 5(√3-1)	E) 5(√2-1)
As sphere is inscribed in cube then   =&gt;the edge of the cube equals to the diameter of a sphere --&gt; Diameter=10   Diagonal of a cube equals to Diagonal=square_root(10^2+10^2+10^2)=10√3.   half of 5(√3-1)iagonal-5(√3-1)iameter is gap between the vertex of a cube and the surface of the sphere = (10√3-10)/2   =5(√3-1)   ANSWER:5(√3-1)
<result>D</result>
A sphere is inscribed in a cube with an edge of 10. What is the shortest possible distance from one of the vertices of the cube to the surface of the sphere?