The 3 digits of a number add up to 11. The number is divisible by 5. The leftmost digit is double the middle digit. What is the product of the 3 digits?	Choose one:  A) 38  B) 40  C) 78  D) 88  E) 125
xyz is a 3 digit integer divisible by 5. So z can take only 0 or 5. We are also given that x = 2y   This means x+y (2y+y) must be a multiple of 3   xy5 or xy0   CASE 1   x+y+0 = 11   x+y=11   This can't be the case because 11 is not a multiple of 3   CASE 2   x+y+5 = 11   x+y=6   solving we get, x=4y=2   So the 3 digit number is 425   Thus the product of the digits will be = 4 x 2 x 5 = 40   Answer 40
<result>B</result>
The 3 digits of a number add up to 11. The number is divisible by 5. The leftmost digit is double the middle digit. What is the product of the 3 digits?