The average (arithmetic man) of three integers a, b, and c is exactly four times the median. If a < b < c and a = 0, what is the value of c/b?
Options:
A) 2	B) 3	C) 4	D) 11	E) Cannot be determined from the information given.
The average of three integers a, b, and c is exactly twice the median --&gt; (a+b+c)/3=4b --&gt; since a=0, then (0+b+c)/3=4b --&gt; c=11b --&gt; c/b=11.   Answer: 11.
<result>D</result>
The average (arithmetic man) of three integers a, b, and c is exactly four times the median. If a < b < c and a = 0, what is the value of c/b?