The center of a circle lies on the origin of the coordinate plane. If a point (x, y) is randomly selected inside of the circle, what is the probability that y > 0 and y > x?	Choices:
A) 1/8	B) 1/6	C) 3/8	D) 1/2	E) 3/4
The line y=x divides the circle into two equal areas.   All the points above the line y=x satisfy the condition that y &gt; x.   All the points above the x-axis satisfy the condition that y &gt; 0.   The intersection of these two areas is 3/8 of the circle.   The answer is 3/8.
<result>C</result>
The center of a circle lies on the origin of the coordinate plane. If a point (x, y) is randomly selected inside of the circle, what is the probability that y > 0 and y > x?