The sum of five consecutive odd numbers of set p is 435. What is the sum of five consecutive numbers of another set q. Whose largest number is 45 more than the largest number of set p? Choose the most appropriate option.
A) 530	B) 670	C) 730	D) 770	E) None of these
Let the five consecutive odd numbers of set p be 2n - 3, 2n - 1, 2n + 1, 2n + 3, 2n + 5.   Sum of these five numbers   = 2n - 3 + 2n - 1 + 2n + 1 + 2n + 3 + 2n + 5   = 10n + 5 = 435 =&gt; n = 43   Largest number of set p = 2(43) + 5 = 91   The largest number of set q = 91 + 45= 
<gadget id="calculator">91 + 45</gadget>
<output>136</output>
136=&gt; The five numbers of set q are 132, 133, 134, 135, 136.   Sum of above numbers = 132 + 133 + 134 + 135 + 136= 
<gadget id="calculator">132 + 133 + 134 + 135 + 136</gadget>
<output>670</output>
670.   ANSWER:670
<result>B</result>
The sum of five consecutive odd numbers of set p is 435. What is the sum of five consecutive numbers of another set q. Whose largest number is 45 more than the largest number of set p?