A man buys 10 lts of liquid which contains 20% of the liquid and the rest is water. He then mixes it with 15 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?	Choose the most appropriate option:	A) 74	B) 84	C) 94	D) 49	E) 47
20% in 10 lts is 2. So water = 10-2= 
<gadget id="calculator">10-2</gadget>
<output>8</output>
8 lts. 30% of 15 lts= 4.5. So water in 2nd mixture = 15-4.5= 
<gadget id="calculator">15-4.5</gadget>
<output>10.5</output>
10.5 lts. Now total quantity= 10 + 15= 
<gadget id="calculator">10 + 15</gadget>
<output>25</output>
25 lts. Total water in it will be 8 + 10.5= 
<gadget id="calculator">8 + 10.5</gadget>
<output>18.5</output>
18.5 lts. % of water= (100*18.5)/25= 
<gadget id="calculator">(100*18.5)/25</gadget>
<output>74</output>
74   74NSWER:74
<result>A</result>
A man buys 10 lts of liquid which contains 20% of the liquid and the rest is water. He then mixes it with 15 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?