A number when divided by a divisor leaves a remainder of 27. When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor?  Choose the correct choice
A) 12	B) 13	C) 35	D) 40	E) 59
Let the number is N, the divisor = D,   I will make the two equations-   N = xD+27   2N = yD+11   where x and y are integers   Solving them: D(y-2x) = 40   as D is also integer and 40 is a prime number, the D should be 40 to satisfy the above equation.   Hence answer is '40'
<result>D</result>
A number when divided by a divisor leaves a remainder of 27. When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor?