A miniature roulette wheel is divided into 9 equal sectors, each bearing a distinct integer from 1 to 9, inclusive. Each time the wheel is spun, a ball randomly determines the winning sector by settling in that sector. If the wheel is spun three times, approximately what is the probability that the product of the three winning sectors’ integers will be even?	Pick.
A) 50%	B) 67%	C) 83%	D) 90%	E) 96%
The only way to have an odd product is if all 3 integers are odd.   P(odd product) = 5/9*5/9*5/9 = 125/729   P(even product) = 1 - 125/729 = 604/729 which is about 83%   The answer is 83%.
<result>C</result>
A miniature roulette wheel is divided into 9 equal sectors, each bearing a distinct integer from 1 to 9, inclusive. Each time the wheel is spun, a ball randomly determines the winning sector by settling in that sector. If the wheel is spun three times, approximately what is the probability that the product of the three winning sectors’ integers will be even?