By using the numbers 1, 2, 3, 5 and 7 only once, how many five digit numbers can be made that are divisible by 25?	Answers
A) 10
B) 11
C) 12
D) 13
E) 14
A number to be divisible by 25 must end with 00, 25, 50, or 75.   So, there are the following cases possible:   137-25 --&gt; the first three digits can be arranged in 3=6 ways.   123-75 --&gt; the first three digits can be arranged in 3=6 ways.   Total = 6 + 6= 
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
12.   Answer: 12.
<result>C</result>
By using the numbers 1, 2, 3, 5 and 7 only once, how many five digit numbers can be made that are divisible by 25?