Seed mixture X is 40% ryegrass and 60% bluegrass by weight; seed mixture Y is 25% ryegrass and 75% fescue. If a mixture of X and Y contains 30% ryegrass, what percent of the weight of the mixture is X? Select
A) 10% B) 33.33% C) 40% D) 50% E) 66.67%
x - wt of Mix X added   y - wt of Mix Y added   0.4x + 0.25y = 0.3(x+y)   0.1x = 0.05y   x/y = 5/10 = 1/2   y/x = 2   (y+x)/x = 3   =&gt; x/(y+x) * 100 = 100/3 = 33.33%   ANSWER:33.33%
<result>B</result>
Seed mixture X is 40% ryegrass and 60% bluegrass by weight; seed mixture Y is 25% ryegrass and 75% fescue. If a mixture of X and Y contains 30% ryegrass, what percent of the weight of the mixture is X?