If positive integers x is even and y is odd, which of the following must be odd?	Choose the correct choice from the following choices
A) 2xy B) 3x+y-1 C) x+y D) x + y -1 E) 3(x + y) - 3
Let x = 2 and y = 1   2xy = 2*2*1= 
<gadget id="calculator">2*2*1</gadget>
<output>4</output>
4   3x+y-1= 3*2 + 1 -1= 
<gadget id="calculator">3*2 + 1 -1</gadget>
<output>6</output>
6   x+y= 2+1= 
<gadget id="calculator">2+1</gadget>
<output>3</output>
3   x+y-1= 2+1-1= 
<gadget id="calculator">2+1-1</gadget>
<output>2</output>
2   3(x+y) - 3= 6+3-3= 
<gadget id="calculator">6+3-3</gadget>
<output>6</output>
6   Answer: x+y
<result>C</result>
If positive integers x is even and y is odd, which of the following must be odd?