What are the maximum value and minimum values of f(x) = |2sin(2x - pi/3) - 5| + 3	Choose one.
A) max 8-min 2	B) max 9-min 1	C) max 10-min 6	D) max 11-min 5	E) max 12-min 3
-1 &lt;= sin(2x - pi/3) &lt;= 1 : range of a sine function   -2 &lt;= 2sin(2x - pi/3) &lt;= 2 : multiply all terms of the double inequality by 2   -2 - 5 &lt;= 2sin(2x - pi/3) - 5 &lt;= 2 - 5 : add -5 to all terms of the inequality.   -7 &lt;= 2sin(2x - pi/3) - 5 &lt;= -3   3 &lt;= |2sin(2x - pi/3) - 5| &lt;= 7 : change the above using absolute value.   3 + 3 &lt;= |2sin(2x - pi/3) - 5| + 3 &lt;= 7 + 3 : add 3 to all terms of the double inequality.   The maximum value of f(x) is equal to 10 and the minimum value of f(x) is equal to 6.   correct answer max 10-min 6
<result>C</result>
What are the maximum value and minimum values of f(x) = |2sin(2x - pi/3) - 5| + 3