If A speaks the truth 40% of the times, B speaks the truth 20% of the times. What is the probability that at least one will tell the truth	Options
A) 1.8 B) 2.0 C) 1.52 D) 0.52 E) 1.3
probability of A speaks truth p(A)=4/10;false=6/10   probability of B speaks truth p(B)=2/10;false=8/10.For given qtn   Ans=1-(neither of them tell truth).Because A &amp; B are independent events   =1-[(6/10)*(8/10)]=1-48/100=1-0.48= 
<gadget id="calculator">1-0.48</gadget>
<output>0.52</output>
0.52   ANSWER:0.52
<result>D</result>
If A speaks the truth 40% of the times, B speaks the truth 20% of the times. What is the probability that at least one will tell the truth