When a natural number N is successively divided by 3,4,5,6 the remainders are 7,8,9,10. What will be the sum of the remainders if the order of the division is reversed? Answers:	A) 11	B) 78	C) 44	D) 19	E) 72
3 4 5 6   7 8 9 10   leave the top right- most number 8   start with bottom right-most number 5   10*5+9= 
<gadget id="calculator">10*5+9</gadget>
<output>59</output>
59   59*4+8= 
<gadget id="calculator">59*4+8</gadget>
<output>244</output>
244   244*3+7= 
<gadget id="calculator">244*3+7</gadget>
<output>739</output>
739   this is the number required   Now, do the successive division in the reverse order   The sum of the remainders is 19   Hence, the correct option is 19
<result>D</result>
When a natural number N is successively divided by 3,4,5,6 the remainders are 7,8,9,10. What will be the sum of the remainders if the order of the division is reversed?