Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case?	Choose the most appropriate option:	A) 3	B) 4	C) 5	D) 6	E) 7
Calculate the differences, taking two numbers at a time as follows:     (215-47)= 
<gadget id="calculator">  (215-47)</gadget>
<output>168</output>
168   (365-215)= 
<gadget id="calculator">(365-215)</gadget>
<output>150</output>
150   (365-47)= 
<gadget id="calculator">(365-47)</gadget>
<output>318</output>
318   HCF of 168, 150 and 318 we get 6, which is the greatest number, which while dividing 47, 215 and 365 gives the same remainder in each cases is 5.   ANSWER:5
<result>C</result>
Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case?