Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Child A has to sit next to both B & G, with these two children immediately adjacent to Child A on either side. The other four children can sit in any order in any of the remaining seats. How many possible configurations are there for the children?
Choose the correct choice from the following answers:
A) 240  B) 480  C) 720  D) 1440  E) 3600
First we can imagine the trio ABG as one item to arrange along with four other items: C , D, E, F.   This can be done in 5! = 120 ways   However the trio can be arranged in 2 ways: BAG or GAB.   So, total number of ways to sit the seven children is equal to 2*120= 
<gadget id="calculator">2*120</gadget>
<output>240</output>
240 (option 240)
<result>A</result>
Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Child A has to sit next to both B & G, with these two children immediately adjacent to Child A on either side. The other four children can sit in any order in any of the remaining seats. How many possible configurations are there for the children?