The product of two fractions is 3/4 and their quotient is 6/18. If the denominator of one is 1/3 of the other's numerator, then find the pair of fractions?	Choose the correct choice from the following choices.
A) 1/3, 9/5
B) 1/2, 3/2
C) 1/2, 6/5
D) Data inadequate
E) None of these
Explanation:   Let A = x/y, and 1/2, 3/2 be two fractions   It is given that A*1/2, 3/2 = 3/4   Therefore x/y * 1/2, 3/2 = 3/4   1/2, 3/2 = 3y/4x   Therefore, A = x/y and 1/2, 3/2 = 3y/4x   It is given that A/1/2, 3/2 = (x/y) / (3y/4x) = 6/18   Therefore x/y * 4x/3y = 6 /18   Therefore 4x2/3y2 = 6/18   x2/y2 = 18/(4*18)   Therefore, x2/y2 = ¼   x/y = 1/2   1/2, 3/2 = 3y/4x = 3/4 (1/(x/y)) = 3/4 [1/(1/2)] = 6/4   Therefore A = 1/2 and 1/2, 3/2 = 3/2   ANSWER 1/2, 3/2
<result>B</result>
The product of two fractions is 3/4 and their quotient is 6/18. If the denominator of one is 1/3 of the other's numerator, then find the pair of fractions?