Two different solutions of alcohol with respective proportions of alcohol to water of 3:1 and 2:3 were combined. What is the concentration of alcohol in the new solution if the first solution was 9 times the amount of the second solution?	Answers: A) 62 B) 65.5 C) 68 D) 70 E) 71.5
SOL:   Lets assume that 90L of sol1 was mixed with 10L of sol2.   Alcohol in Sol1: 90*3/4 = 67.5L   Alcohol in Sol2: 10*2/5 = 4L   Total Alcohol in the mixed solution of 100L = 67.5 + 4= 
<gadget id="calculator">67.5 + 4</gadget>
<output>71.5</output>
71.5L   Alcohol concentration in the new sol: (71.5/100)*100= 
<gadget id="calculator">(71.5/100)*100</gadget>
<output>71.5</output>
71.5%   ANSW71.5R:71.5
<result>E</result>
Two different solutions of alcohol with respective proportions of alcohol to water of 3:1 and 2:3 were combined. What is the concentration of alcohol in the new solution if the first solution was 9 times the amount of the second solution?