The volume of the sphere QQ is (dfrac{37}{64}%)less than the volume of sphere PP and the volume of sphere RR is (dfrac{19}{27}%) less than that of sphere QQ. By what is the surface areaof sphere RR less than the surfacearea of sphere PP? Choose the correct choice from the following choices
A) 35% B) 65% C) 75% D) 90% E) 100%
Let the volume of sphere PP be 64 parts.   Therefore volume of sphere QQ   =64−3764%=64−3764% of 6464   =64−37=27=64−37=27 parts.   The volume of RR   =27−1927×27=27−1927×27   =27−19=8=27−19=8 parts.   Volume ratio:   =P:Q:R=64:27:8=P:Q:R=64:27:8   Radius ratio:   =P:Q:R=4:3:2=P:Q:R=4:3:2   The surface area will be 16:9:516:9:5   Surface area of RR is less than the surface area of sphere PP   16k−4k=12k16k−4k=12k   Now,   =12k16k×100=12k16k×100   =75%=75%   Thus surface area of sphere RR is less than the surface area of sphere P by 75%   75%
<result>C</result>
The volume of the sphere QQ is (dfrac{37}{64}%)less than the volume of sphere PP and the volume of sphere RR is (dfrac{19}{27}%) less than that of sphere QQ. By what is the surface areaof sphere RR less than the surfacearea of sphere PP?