Five kilograms of oranges contained 90% of water. If the next day the concentration of water decreased by 10%, what was the new weight of the oranges, in kilograms?  Choose one:
A) 4.9
B) 4.8
C) 2.5
D) 2
E) 0.2
Five kilograms of oranges contained 90% of water. If the next day the concentration of water decreased by 10%, what was the new weight of the oranges, in kilograms?   (A) 4.9   (B) 4.8   (C) 2.5   (D) 2   (E) 0.2   If C is the answer, then the question means that the concentration of water the newt day became 80%.   Out of 5 kilograms 90%, or 4.5 kilograms was water and 0.5 kilograms was non-water.   The next day, after some water evaporated, oranges became 80% water and 20% of non-water, so the next day 0.5 kilograms of non-water composed 20% of oranges, which means that the new weight of the oranges was x*0.2=0.5 --&gt; x=2.5 kilograms.   Answer: 2.5.
<result>C</result>
Five kilograms of oranges contained 90% of water. If the next day the concentration of water decreased by 10%, what was the new weight of the oranges, in kilograms?