How many ways could three people sit at a table with five seats in which two of the five seats will remain empty?  Choose the correct option:
A) 8	B) 12	C) 60	D) 118	E) 120
ways in which 3 seats out 5 can be selected = 5603   ways in which 3 people can be arranged in 3 seats = 3!   Total ways of arrangement = 5603*3!   =5*4/2*6   =10*6= 
<gadget id="calculator">10*6</gadget>
<output>60</output>
60   Ans= 60
<result>C</result>
How many ways could three people sit at a table with five seats in which two of the five seats will remain empty?