How many numbers can be formed by using digits 0 to 9, as the number should be divisible by 5 and it should be 4 digit one and no repitation is allowed on digits?	Options
A) 951 ways	B) 952 ways	C) 953 ways	D) 954 ways	E) 955 ways
For a number to be divisbly by 5 we have two choices 0 or 5   case 1 : when choice is 0   _ _ _ 0 first digt can be filled in 9ways , 2nd in 8 ways, 3rd in 7 ways so 9 * 8 *7= 
<gadget id="calculator">9 * 8 *7</gadget>
<output>504</output>
504   case 2 : when choice is 5   _ _ _ 5 first digi can be in 8 ways (since 0 cannot come ) , 2nd in 8 ,3rd in 7 so  8*8*7= 
<gadget id="calculator"> 8*8*7</gadget>
<output>448</output>
448   so it can be in  504 + 448= 
<gadget id="calculator"> 504 + 448</gadget>
<output>952</output>
952 ways   ANSWER:952 ways
<result>B</result>
How many numbers can be formed by using digits 0 to 9, as the number should be divisible by 5 and it should be 4 digit one and no repitation is allowed on digits?