A gambler began playing blackjack with $110 in chips. After exactly 12 hands, he left the table with $320 in chips, having won some hands and lost others. Each win earned $100 and each loss cost $10. How many possible outcomes were there for the first 5 hands he played? (For example, won the first hand, lost the second, etc.)  Pick:
A) 10
B) 18
C) 26
D) 32
E) 64
If X is number of wins and Y num of losses then   100X - 10Y = 210   10X-Y = 21......only when Y = 9 and X = 3 it satisfies....so we have 3 wins and 9 losses.   for first 5, we can have the following:   0 wins 5 losses = 1 way   1 win and 4 losses = 5261 = 5   2 wins and 3 losses = 5262 = 10   3 wins and 2 losses = 5263 = 10   Add total ways = 26 ways   ANSWER:26
<result>C</result>
A gambler began playing blackjack with $110 in chips. After exactly 12 hands, he left the table with $320 in chips, having won some hands and lost others. Each win earned $100 and each loss cost $10. How many possible outcomes were there for the first 5 hands he played? (For example, won the first hand, lost the second, etc.)