A basketball coach will select the members of a five-player team from among 8 players, including John and Peter. If the five players are chosen at random, what is the probability that the coach chooses a team that includes both John and Peter? Choose the correct answer:	A) 1/9	B) 1/6	C) 2/9	D) 5/14	E) 1/3
you can but that will require more cases and will be time consuming.   straight forward way is to group J and P as always present on the team and as order does not matter so we just need to find the total number of ways to select rest three players = 6c3   total number of ways of selecting 5 players out of 8 = 8c5   probability = 6c3/8c5 = 5/14   5/14
<result>D</result>
A basketball coach will select the members of a five-player team from among 8 players, including John and Peter. If the five players are chosen at random, what is the probability that the coach chooses a team that includes both John and Peter?