Consider another example where a pack contains 4 blue, 2 red and 3 black pens. If a pen is drawn at random from the pack, replaced and the process repeated 2 more times, What is the probability of drawing 2 blue pens and 1 black pen? Pick.
A) 8/81 B) 9/81 C) 7/81 D) 6/81 E) None of these
EXPL8/81N8/81TION:   Here, total number of pens = 9   Probability of drawing 1 blue pen = 4/9   Probability of drawing another blue pen = 4/9   Probability of drawing 1 black pen = 3/9   Probability of drawing 2 blue pens and 1 black pen = 4/9 * 4/9 * 3/9 = 8/81   8/81NSWER IS 8/81
<result>A</result>
Consider another example where a pack contains 4 blue, 2 red and 3 black pens. If a pen is drawn at random from the pack, replaced and the process repeated 2 more times, What is the probability of drawing 2 blue pens and 1 black pen?