How many ways could two people sit at a table with four seats in which two of the four seats will remain empty?	Choose the correct option.
A) 60
B) 12
C) 112
D) 118
E) 120
ways in which 2 seats out 4 can be selected = 4C2   ways in which 2 people can be arranged in 2 seats = 2!   Total ways of arrangement = 4C2*2!   =4*3= 
<gadget id="calculator">4*3</gadget>
<output>12</output>
12   Ans= 12
<result>B</result>
How many ways could two people sit at a table with four seats in which two of the four seats will remain empty?