If y = x^2 + rx + s, y is minimum when x is: Pick one
A) r/s
B) -r/s
C) -r/2
D) -s/2
E) s/r
We're given the equation Y = X^2 + rX + s.   IF.. we use a simple Classic Quadratic....   r = 2   s = 1   Y = X^2 + 2X + 1   We can then go about finding the answer that yields the MINIMUM result when X = ...   Answer A: r/s = 2/1= 
<gadget id="calculator">2/1</gadget>
<output>2</output>
2 --&gt; 4+4+1= +9   Answer B: -r/s = -2/1 = -2 --&gt; 4-4+1 = +1   Answer -r/2: -r/2 = -2/2 = -1 --&gt; 1-2+1 = 0   Answer D: -s/2 = -1/2 --&gt;(1/4)-1+1 = +1/4   Answer E: s/r = 1/2 --&gt; (1/4)+1+1 = +2 1/4   From these results, we can see the minimum result:   -r/2
<result>C</result>
If y = x^2 + rx + s, y is minimum when x is: