Tough and Tricky questions: Remainders.
1^1 + 2^2 + 3^3 + ... + 7^7 is divided by 7. What is the remainder?  Answers:  A) 0  B) 1  C) 2  D) 3  E) 4
a number is divisible by 5, if its last digit is divisible by 5   let's look into the sum of last digits of each term of the given expression   1^1=1   2^2=4   3^3=7   4^4=6   5^5=5   6^6=6   7^7=3   adding all these numbers we get 32 which gives a remainder of4 when divided by 7. so answer must be 4.   bunuel, can you please confirm the answer of this question.   Yes, the OA is C. Clicked the wrong button when posting. Edited. Thank you.   4
<result>E</result>
Tough and Tricky questions: Remainders.
1^1 + 2^2 + 3^3 + ... + 7^7 is divided by 7. What is the remainder?