The smallest 5 digit number exactly divisible by 41 is? Pick one.
A) 10003  B) 10004  C) 10007  D) 10009  E) 10010
The smallest 5-digit number = 10000.   41) 10000 (243   82   ---   180   164   ----   160   123   ---   37   ---   Required number = 10000 + (41 - 37)= 
<gadget id="calculator">10000 + (41 - 37)</gadget>
<output>10_004</output>
10004.   Option 10004
<result>B</result>
The smallest 5 digit number exactly divisible by 41 is?