The larger of two negative consecutive even integers 2t and 2(t-1) is multiplied by 4 and then added to the smaller of the two original integers. Which of the following represents this operation? Choose the correct choice from the following:
A) 6t-2
B) 10t-2
C) -2
D) 3
E) -2-4t^2
larger of 2t-2, 2t (when they are negative) is 2t. the smallest of 2t and 2t-2 when they are positive is 2t-2.   therefore 4* 2t + 2t-2 = 10t-2.   option 10t-2.
<result>B</result>
The larger of two negative consecutive even integers 2t and 2(t-1) is multiplied by 4 and then added to the smaller of the two original integers. Which of the following represents this operation?