A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
Choose the correct choice.
A) 288  B) 200  C) 289  D) 267  E) 261
The number of ways to select two men and three women   = 5C2 * 6C3   = (5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)= 
<gadget id="calculator">(5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)</gadget>
<output>200</output>
200   Answer:200
<result>B</result>
A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?