Annie has 100 cards numbered 1 through 100. If she deals nine cards to Alex, without replacing any of them, what is the probability that Alex will get five consecutive numbers?	Options: A) 95!/100! B) 9!/100! C) (92! X 9!)/100! D) (96! X 5!)/100! E) (97! X 4!)/100!
Alex to get 9 consecutive cards in ascending order, to have 9 consecutive at the end is good enough.   There are 92 consecutive numbers in 100: {1, 2, 3, 4, 5,6,7,8,9}, {2, 3, 4, 5, 6,7,8,9,10}, ..., {92,93,94,95,96, 97, 98, 99, 100};   Total ways to pick 9 cards out of 100 is {9!*92!}{100!}.   Answer: (92! X 9!)/100!.
<result>C</result>
Annie has 100 cards numbered 1 through 100. If she deals nine cards to Alex, without replacing any of them, what is the probability that Alex will get five consecutive numbers?