If P(x) = ax^4+bx^3+cx^2+dx+e has roots at x = 1, 2, 3, 4 and P(0) = 48, what is P(5)? Choices:
A) 48
B) 24
C) 0
D) 50
E) 40
Roots are 1,2,3,4   So we can write this   equation As p(x)=   a(x-1)(x-2)(x-3)(x-4).....eq1   Put x=0here we p(0)=48=24a   TheN a=2   Now put a in eq1   And get the answer...   P(5)=a.4.3.2.1=48   48NSWER:48
<result>A</result>
If P(x) = ax^4+bx^3+cx^2+dx+e has roots at x = 1, 2, 3, 4 and P(0) = 48, what is P(5)?