A tourist purchased a total of $3,500 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?  Options:
A) $1,430
B) $2,310
C) $2,290
D) $3,270
E) $4,150
Let the number of $10 checks cashed beT   Let the number of $50 checks cashed beF   7 checks cashed;   T+F=7   Now; T can be F+1 OR T can be F-1   Let's check both conditions;   T=F+1   T+F=7   F+1+F=7   2F=6   F=3   T=4   Value cashed = 3*50+4*10=150+40= 
<gadget id="calculator">150+40</gadget>
<output>190</output>
$190   Let's check the other condition as well;   T=F-1   T+F=7   F-1+F=7   2F=8   F=4   T=3   Value cashed = 4*50+3*10=200+30= 
<gadget id="calculator">200+30</gadget>
<output>230</output>
$230   The more money he cashes, the less loss he incurs. Thus, we must consider the latter case.   Value cashed= $230   Value lost = 3000-230 = $3270   Ans:$3,270
<result>D</result>
A tourist purchased a total of $3,500 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?