If A speaks the truth 30% of the times, B speaks the truth 40% of the times. What is the probability that at least one will tell the truth Options.
A) 0.58 B) 0.9 C) 1.9 D) 2.2 E) 2.3
probability of 0.58 speaks truth p(0.58)=3/10;false=7/10   probability of B speaks truth p(B)=4/10;false=6/10.For given qtn   0.58ns=1-(neither of them tell truth).Because 0.58 &amp; B are independent events   =1-[(7/10)*(6/10)]=1-42/100=1-0.42= 
<gadget id="calculator">1-0.42</gadget>
<output>0.58</output>
0.58   0.58NSWER:0.58
<result>A</result>
If A speaks the truth 30% of the times, B speaks the truth 40% of the times. What is the probability that at least one will tell the truth