A vessel is filled with liquid, 3 parts of which are water and 5 parts of syrup. How much of the
mixture must be drawn off and replaced with water so that the mixture may be half water and half
syrup?
Choose the correct choice from the following answers
A) 13
B) 14
C) 15
D) 16
E) 17
Explanation :   Let the quantity of the initial liquid in the vessel = 8 litre and quantity of water in the initial liquid = 3   litre andquantity of syrup in the initial liquid = 5 litreLet x litre of the mixture is drawn off and replaced   with waterQuantity of water in the new mixture = 3−3x8+xQuantity of syrup in the new mixture =   5−5x8Given that in the new mixture, quantity of water = quantity of   syrup⇒3−3x8+x=5−5x8⇒10x8=2⇒5x4=2⇒x=85⇒85litre   Initially we assumed that the quantity of the initial liquid in the vessel = 8 litre for   the ease of calculations. For that 8/5 litre of the mixture to be drawn off and replaced   with water so that the mixture may be half water and half syrup   Now, if the initial liquid in the vessel = 1 litre, quantity of the mixture to be drawn off   and replaced with water so that the mixture may be half water and half syrup   =85×18=15   It means 1/5 of the mixture has to be drawn off and replaced with water so that the mixture   may be half water and half syrup   Answer : Option 15
<result>C</result>
A vessel is filled with liquid, 3 parts of which are water and 5 parts of syrup. How much of the
mixture must be drawn off and replaced with water so that the mixture may be half water and half
syrup?