Three dice are thrown together, Find the probability of getting a total of atmost 5?	Choose the most appropriate option:  A) 2/35  B) 1/8  C) 3/31  D) 2/9  E) 5/108
Three different dice are thrown at the same time.   Therefore, total number of possible outcomes will be 63 = (6 × 6 × 6) = 216.   Number of events of getting a total of atmost 5 = 10   i.e. (1, 1, 1), (1, 1, 2), (1, 2, 1), (2, 1, 1), (1, 1, 3), (1, 3, 1), (3, 1, 1), (2, 2, 1) and (1, 2, 2).   Therefore, probability of getting a total of atmost 5   P(5/108) = Number of favorable outcomes/Total number of possible outcome   = 10/216   = 5/108
<result>E</result>
Three dice are thrown together, Find the probability of getting a total of atmost 5?