In a box, there are 6 red, 3 blue and 56 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green? Choices:
A) 2/3  B) 8/21  C) 6/14  D) 9/22  E) 10/21
Explanation:   Total number of balls = (6 + 3 + 5)= 
<gadget id="calculator">(6 + 3 + 5)</gadget>
<output>14</output>
14   Let E= event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.   Therefore, n(E) = 6.   P(E) = 6/14.   Answer: Option 6/14
<result>C</result>
In a box, there are 6 red, 3 blue and 56 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?