Find the least which when divided y 16,18,20, and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder. Choose one
A) 17004
B) 18000
C) 18002
D) 18004
E) 18005
Solution   L.C.M. of 16,18,20,25 = 3600. required number is of the form 3600 k + 4.   Least value of k for which (3600 k + 4 ) is divisible by 7 is k = 5.   So, Required number = (3600 × 5 + 4) = 18004. Answer 18004
<result>D</result>
Find the least which when divided y 16,18,20, and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.