How many different numbers can we have by changing the position of the digits of the number 718844?	Options.
A) 15 B) 90 C) 180 D) 360 E) 720
Permutation in a group where there are repeated elements = n!/(p! * p2! *...*pn!); where p1, p2, .., pn are the number of times the element is repeated.   So, here required numbers = 6!/(2! * 2!) since we have 6 digits and 8 and 4 are each repeated twice.   = 180   Hence option 180
<result>C</result>
How many different numbers can we have by changing the position of the digits of the number 718844?