Let the least number of six digits,which when divided by 4,6,10 and 15 leaves in each case the same remainder of 2, be N. The sum of the digits in N is : Choose the correct choice from the following.
A) 3	B) 4	C) 5	D) 6	E) 7
Solution   Least number of 6 digital is 100000. L.C.M. of 4,6,10 and 15 = 60.   on dividing 100000 by 60, the remainder obtained is 40.   So, least number of 6 digits divisible by 4,6,10 and 15 = 100000 +(60 - 40)= 
<gadget id="calculator">100000 +(60 - 40)</gadget>
<output>100_020</output>
100020.   So, N= (100020 + 2)= 
<gadget id="calculator">(100020 + 2)</gadget>
<output>100_022</output>
100022. sum of digits in N= (1 + 2 + 2)= 
<gadget id="calculator">(1 + 2 + 2)</gadget>
<output>5</output>
5. Answer 5
<result>C</result>
Let the least number of six digits,which when divided by 4,6,10 and 15 leaves in each case the same remainder of 2, be N. The sum of the digits in N is :