A committee has 4 men and 6 women. What are the number of ways of selecting 2 men and 4 women from the given committee? Choose one:
A) 75
B) 90
C) 105
D) 120
E) 135
The number of ways to select two men and four women = 4C2 * 6C4 = 6 * 15= 
<gadget id="calculator">6 * 15</gadget>
<output>90</output>
90   The answer is 90.
<result>B</result>
A committee has 4 men and 6 women. What are the number of ways of selecting 2 men and 4 women from the given committee?