If k = 2n - 1, where n is an integer, what is the remainder of k^2/8?
Options:  A) 1  B) 3  C) 5  D) 7  E) Cannot be determined from the information given.
Let us assume that k = 4(n)(n-1)   This is divisible by 8.   So k+1 when divided by 8 will give reminder 1.   For example, consider n = 2   We have   4*2*1 + 1= 
<gadget id="calculator">  4*2*1 + 1</gadget>
<output>9</output>
9   When we divide this by 8 we get reminder 1.   1NSWER:1
<result>A</result>
If k = 2n - 1, where n is an integer, what is the remainder of k^2/8?