A gambler bought $3,000 worth of chips at a casino in denominations of $30 and $100. That evening, the gambler lost 16 chips, and then cashed in the remainder. If the number of $30 chips lost was 2 more or 2 less than the number of $100 chips lost, what is the largest amount of money that the gambler could have received back? Choices.
A) $2,040 B) $2,120 C) $1,960 D) $1,920 E) $2,030
In order to maximize the amount of money that the gambler kept, we should maximize # of $30 chips lost and minimize # of $100 chips lost, which means that # of $30 chips lost must be 2 more than # of $100 chips lost.   So, if # of $30 chips lost is x then # of $100 chips lost should be x-2. Now, given that total # of chips lost is 16: x+x-2=16 --&gt; x=9: 9 $30 chips were lost and 9-2= 
<gadget id="calculator">9-2</gadget>
<output>7</output>
7 $100 chips were lost.   Total worth of chips lost is   9*30+7*100= 
<gadget id="calculator">  9*30+7*100</gadget>
<output>970</output>
$970, so the gambler kept $3,000-$970=$2,030.   Answer: $2,030
<result>E</result>
A gambler bought $3,000 worth of chips at a casino in denominations of $30 and $100. That evening, the gambler lost 16 chips, and then cashed in the remainder. If the number of $30 chips lost was 2 more or 2 less than the number of $100 chips lost, what is the largest amount of money that the gambler could have received back?