If there are 5 pairs of twins, and a committee will be formed with 3 members. In how many ways this committee formed in a way that no siblings in a group? Choose the most appropriate option.
A) 32
B) 24
C) 56
D) 44
E) 80
Firstly, there are 5 ways to choose 3 groups from the 4 groups. Hence 5C3.   Next, with the 3 groups chosen, there are 2^3 choices of choosing either one of the siblings.   Hence, the total number of ways are 5C3 * (2^3) = 80   80
<result>E</result>
If there are 5 pairs of twins, and a committee will be formed with 3 members. In how many ways this committee formed in a way that no siblings in a group?