In a vacant lot a man have 5 goat which eat in 2 days all the bush of 1/4 part of the lot, full of bushes. If the man added 10 goats to the lot and all of them will eat the weed at the same rate, how many days will take to all the goats eat all the bushes of the lot, since the first day?  Pick.
A) 8 days
B) 7 days
C) 6 days
D) 5 days
E) 4 days
We have that: 5 goats ----- 2 days, (5+10) G ----- X d, that is: (X d/ 5G) = (2 d/15G), then: X d = (2 d/15G)5G = (2/3)d. Is to say, the 15 goats eat the same quantity in 2/3 days; it is only 1/4 of the lot. Then, all the lot is: L = L1 + L2 + L3 + L4= 2 d + 3(2/3)d = (2 + 2)= 
<gadget id="calculator">(2 + 2)</gadget>
<output>4</output>
4 days. Answer 4 days.
<result>E</result>
In a vacant lot a man have 5 goat which eat in 2 days all the bush of 1/4 part of the lot, full of bushes. If the man added 10 goats to the lot and all of them will eat the weed at the same rate, how many days will take to all the goats eat all the bushes of the lot, since the first day?