Let exp(m,n) = m to the power n. If exp(10, m) = n exp(2, 2) where to and n are integers then n =
Options:
A) 27
B) 272
C) 98
D) 25
E) 72
Given 10m=n.2210m=n.22   ⇒⇒ 2m×5m=n.22⇒2m−2×5m=n2m×5m=n.22⇒2m−2×5m=n   For m = 2 we get least value of n = 25, and for m &gt; 2 we get infinite values are possible for n.   Answer:25
<result>D</result>
Let exp(m,n) = m to the power n. If exp(10, m) = n exp(2, 2) where to and n are integers then n =