What is the greatest prime factor of 6^8−3^8 ?	Choose the correct answer:
A) 3 B) 11 C) 17 D) 19 E) 31
6⁸ − 3⁸ is a DIFFERENCE OF SQUARES. So we can factor it.   6⁸ − 3⁸ = (6⁴ + 3⁴)(6⁴ - 3⁴)   = (6⁴ + 3⁴)(6² + 3²)(6² - 3²)   = (6⁴ + 3⁴)(6² + 3²)(6 + 3)(6 - 3)   = (6⁴ + 3⁴)(45)(9)(3)   = (6⁴ + 3⁴)(3)(3)(5)(3)(3)(3)   Hmmmm, we can see that the correct answer is "hiding" in the first number (6⁴ + 3⁴)   Let's factor out the 3⁴, to get:   6⁴ + 3⁴ = 3⁴(2⁴ + 1)   = 3⁴(16 + 1)   = 3⁴(17)   = (3)(3)(3)(3)(17)   So, 6⁸ − 3⁸ = (3)(3)(3)(3)(17)(3)(3)(5)(3)(3)(3)   So the correct answer is 17
<result>C</result>
What is the greatest prime factor of 6^8−3^8 ?