Which of the following are roots of an equation (x^-2)+(4x^-1)-5=0 Choose the most appropriate option:	A) 1/5 and -1	B) -1/5 and 1	C) 1/5 and 1	D) -1/5 and -1	E) -5/2 and -1
Given: (x^-2) + (4x^-1) - 5 = 0   Rewrite as: 1/(x²) + 4/x - 5 = 0   Remove fractions by multiplying both sides by x² to get: 1 + 4x - 5x² = 0   Rearrange to get: 5x² - 4x - 1 1 + 4  - 5= 
<gadget id="calculator">1 + 4  - 5</gadget>
<output>0</output>
0   Rearrange to get: 5x² - 4x - 1= 0   Factor to get: (5x + 1)(x - 1) = 0   So, EITHER 5x + 1 OR x - 1 = 0   If 5x + 1 = 0, then x = -1/5   If x - 1 = 0, then x = 1   So, the roots (solutions) are -1/5 and 1   The answer is -1/5 and 1.
<result>B</result>
Which of the following are roots of an equation (x^-2)+(4x^-1)-5=0