If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case.What is the sum of the digits of N ?	Pick one.
A) 1	B) 2	C) 3	D) 5	E) 4
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)   = H.C.F. of 3360, 2240 and 5600 = 1120.   Sum of digits in N = ( 1 + 1 + 2 + 0 )= 
<gadget id="calculator">( 1 + 1 + 2 + 0 )</gadget>
<output>4</output>
4   ANSW4R:4
<result>E</result>
If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case.What is the sum of the digits of N ?