Factor: x4y3 â€“ 16y3	Choose one.
A) A) 3y3(x2 + 4)(x + 2)(x -2)
B) B) y3(x2 + 4)(x + 2)(x -2)
C) C) 3y3(x2 + 4)(x + 2)(x -3)
D) D) 3y3(x2 + 4)(x + 3)(x -2)
E) E) 3y3(x2 + 4)(x + 2)(x -4)
x4y3â€“ 16y3.   = y3(x4 â€“ 16).   = y3[(x2)2 - 42].   = y3(x2 + 4)(x2 - 4).   = y3(x2 + 4)(x2 - 22).   = y3(x2 + 4)(x + 2)(x -2).   Answer: (y3(x2 + 4)(x + 2)(x -2)) y3(x2 + 4)(x + 2)(x -2)
<result>B</result>
Factor: x4y3 â€“ 16y3