A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?  Choose the correct choice from the following answers.
A) 10/21
B) 11/21
C) 2/7
D) 5/7
E) 3/7
Total number of balls = (2 + 3 + 2)= 
<gadget id="calculator">(2 + 3 + 2)</gadget>
<output>7</output>
7.   Let S be the sample space.   Then, n(S)= Number of ways of drawing 2 balls out of 7   = 7C2 `   =(7 x 6)/(2 x 1)   = 21.   Let E = Event of drawing 2 balls, none of which is blue.   n(E)	= Number of ways of drawing 2 balls out of (2 + 3) balls.   = 5C2   =(5 x 4)/(2 x 1)   = 10.   P(E) =n(E)/n(S)=10/21   10/21nswer :10/21
<result>A</result>
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?