Given that N=a^3*b^4*c^5 where a, b and c are distinct prime numbers, what is the smallest number with which N should be multiplied such that it becomes a perfect square, a perfect cube as well as a perfect fifth power?	Choose the correct answer:
A) a^3*b^4*c^5
B) a^5*b^4*c^3
C) a^2*b^3*c^5
D) a^7*b^6*c^5
E) a^27*b^26*c^25
The powers of a, b and c have to be divisible by 2, 3 and 5 for N to be a perfect square, perfect cube and perfect 5th power.   LCM of 2, 3 and 5 is 30   The smallest integer N = (a^30)(b^30)(c^30)   Answer: a^27*b^26*c^25
<result>E</result>
Given that N=a^3*b^4*c^5 where a, b and c are distinct prime numbers, what is the smallest number with which N should be multiplied such that it becomes a perfect square, a perfect cube as well as a perfect fifth power?