How many five-digit numbers are there, if the two leftmost digits are even, the other digits are odd and the digit 4 cannot appear more than once in the number?	Pick one
A) 1875  B) 2000  C) 2375  D) 2500  E) 3875
the five-digit number: abcde   a have 4 choice of even numbers: 2, 4, 6, 8   b have 4 choice of even numbers: 0, 2, 6, 8 because 4 cannot appear more than once   c, d and e each have 5 choice from 1, 3, 5, 7, 9   So total:  4*4*5*5*5= 
<gadget id="calculator"> 4*4*5*5*5</gadget>
<output>2_000</output>
2000 ANS:2000
<result>B</result>
How many five-digit numbers are there, if the two leftmost digits are even, the other digits are odd and the digit 4 cannot appear more than once in the number?