A mirror 2 inches wide is placed around a rectangular paper with dimensions 8 inches by 12 inches. What is the area of the frame, in square inches? Choose the correct choice from the following:  A) 96  B) 94  C) 28  D) 44  E) 18
This question is an example of a 'punch out' question - we have to find the area of EVERYTHING, then 'punch out' the part that we don't want.   We're told that a mirror 2 inches wide is placed around a rectangular paper with dimensions 8 inches by 12 inches. We're asked for the area of the mirror , in square inches.   Area of a rectangle = (length)(width)   So the area of the paper is... (8)(12) = 96   The mrror 'adds' 2 inches to the top, bottom, left and right 'sides' of the picture, so the area of EVERYTHING is...   (8+2+2)(12+2+2) = (12)(16) = 196   When we 'punch out' the area of the paper, we'll be left with the area of the FR96ME:   192 - 96= 
<gadget id="calculator">192 - 96</gadget>
<output>96</output>
96   Final 96nswer:   96
<result>A</result>
A mirror 2 inches wide is placed around a rectangular paper with dimensions 8 inches by 12 inches. What is the area of the frame, in square inches?