Out of a group of 10 contestants, 2 are to be selected at random. What is the maximum number of male contestants possible if the probability that both selected contestants are male is less than 60% ? Choose one.
A) 0
B) 1.66
C) 2.55
D) 1.22
E) 4.88
Let x be the number of males.   Total contestants = 10   Probability that the first contestant selected is a male = x/10   Probability that the second contestant selected is also a male = x-1/9   Total probability = x(x-1)/ 90 &lt; 1/60 (this probability is less than 60%)   Solving for x we get, x(x-1)&lt; 3/2. This implies that the maximum value of x can be 1.22.   Answer 1.22!
<result>D</result>
Out of a group of 10 contestants, 2 are to be selected at random. What is the maximum number of male contestants possible if the probability that both selected contestants are male is less than 60% ?