Can you please walk me through how to best approach this problem? Thanks
If #p# = ap^3+ bp – 1 where a and b are constants, and #-5# = 6, what is the value of #5#? Choose the correct answer: A) 5 B) 0 C) -8 D) -3 E) -5
#p# = ap^3 + bp - 1   #-5# = 6   putting p = -5 in above equation   -125a -(5b +1) = 6 or   #-5# = (125a+5b+1) = -6   therefore 125a+5b = -7 .....(1   now putting p = 5   #5# = 125 a+5b - 1   using equation 1(125a+5b = -7)   #5# = -7-1 = -8   hence -8
<result>C</result>
Can you please walk me through how to best approach this problem? Thanks
If #p# = ap^3+ bp – 1 where a and b are constants, and #-5# = 6, what is the value of #5#?