In the xy-plane, the points (c, d), (c, -d), and (-c, -d) are three vertices of a certain square. If c < 0 and d > 0, which of the following points R is in the same quadrant as the fourth vertex of the square?  Pick:
A) (-5, -3) B) (-5, 3) C) (5, -3) D) (3, -5) E) (3, 5)
The question:In the xy-plane, the points (c, d), (c, -d), and (-c, -d) are three vertices of a certain square.If c &lt; 0 and d &gt; 0,which of the following points R is in the same quadrant as the fourth vertex of the square?   I marked the tricky part in red. It seems c is anegativenumber and d is a positive number. This means   Vertex #1 = (c, d) is in QII (that is, negative x and positive y)   Vertex #2 = (c, -d) is in QIII (that is, both xy negative)   Vertex #3 = (-c, -d) is in QIV (that is y is negative, but x is positive)   That means the last vertex should be in the first quadrant --- the only first quadrant point is (5, 3), answer =(3, 5).
<result>E</result>
In the xy-plane, the points (c, d), (c, -d), and (-c, -d) are three vertices of a certain square. If c < 0 and d > 0, which of the following points R is in the same quadrant as the fourth vertex of the square?