In the junior basketball league there are 18 teams, 1/3 of them are bad and ½ are rich. What can't be the number of teams that are rich and bad? Answers
A) 4.  B) 6.  C) 7.  D) 8.  E) 10.
total teams =18   bad teams=(1/3)*18= 
<gadget id="calculator">(1/3)*18</gadget>
<output>6</output>
6   rich teams=9   so maximum value that the both rich and bad can take will be 9. so E= 10 can not be that value.   ans 10..
<result>E</result>
In the junior basketball league there are 18 teams, 1/3 of them are bad and ½ are rich. What can't be the number of teams that are rich and bad?