From the third term,each term in the sequence a(1),a(2),a(3),a(4),a(5),a(6) is the sum of the preceding two terms that is a(n)=a(n-1)+a(n-2) for n=3,4,5,6.if a(5)=36 what is the sum of all the six terms?	Choose the correct choice from the following answers: A) 142 B) 143 C) 144 D) 145 E) 146
If x is the first term and y is second terem, then   terms are   x   y   x+y   x+2y...... equal to 36   2x+3y   3x+5y   sum of 6 terms = 8x+12 y = 4*(2x+3y)= 4*36= 
<gadget id="calculator">4*36</gadget>
<output>144</output>
144   ANSWER:144
<result>C</result>
From the third term,each term in the sequence a(1),a(2),a(3),a(4),a(5),a(6) is the sum of the preceding two terms that is a(n)=a(n-1)+a(n-2) for n=3,4,5,6.if a(5)=36 what is the sum of all the six terms?