In how many ways can five boys, three girls and a teacher sit in a row such that all boys sit together?	Options:
A) A)10000
B) B)12100
C) C)14400
D) D)1097
E) E)2781
Treat all boys as one unit. Now there are four students and a teacher and they can be arranged in 5! ways. Again five boys can be arranged among themselves in 5! ways.   Required number of arrangements   = 5! * 5! = 120 * 120= 
<gadget id="calculator">120 * 120</gadget>
<output>14_400</output>
14400.   Answer:14400
<result>C</result>
In how many ways can five boys, three girls and a teacher sit in a row such that all boys sit together?