Can you please walk me through how to best approach this problem? Thanks
If #p# = ap^3+ bp – 1 where a and b are constants, and #-2# = 2, what is the value of #2#?	Pick.
A) 5	B) 0	C) -4	D) -3	E) -5
#p# = ap^3 + bp - 1   #-2# = 2   putting p = -2 in above equation   -8a -(2b +1) = 2 or   #-2# = (8a+2b+1) = -2   therefore 8a+2b = -3 .....(1   now putting p =2   #2# = 8 a+2b - 1   using equation 1(8a+2b = -3)   #5# = -3-1 = -4   hence -4
<result>C</result>
Can you please walk me through how to best approach this problem? Thanks
If #p# = ap^3+ bp – 1 where a and b are constants, and #-2# = 2, what is the value of #2#?