Today John, who is 38 years old, and his daughter, who is 13 years old, celebrate their birthdays. How many years will pass before John’s age is twice his daughter’s age?	Choose the correct answer
A) 13
B) 14
C) 15
D) 16
E) 12
Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.   After x years passes John’s age will be (38+x) years old, and his daughter’s age will be (13+x) years old. Since the John’s age is twice his daughter’s age (38+x)= 2 * (13+x) ---&gt;   38+x=26+2x ---&gt; x= 12   The answer is (12).
<result>E</result>
Today John, who is 38 years old, and his daughter, who is 13 years old, celebrate their birthdays. How many years will pass before John’s age is twice his daughter’s age?