Which of the following are roots of an equation (x^-2)+(3x^-1)-10=0 Pick one.
A) 1/5 and -1/2
B) -1/5 and 1/2
C) 1/5 and 1/2
D) -1/5 and -1/2
E) -5/2 and -1/2
Given: (x^-2) + (3x^-1) - 10 = 0   Rewrite as: 1/(x²) + 3/x - 10 = 0   Remove fractions by multiplying both sides by x² to get: 1 + 3x - 10x² = 0   Rearrange to get: 10x² - 3x - 1 = 0   Factor to get: (5x + 1)(2x - 1) = 0   So, EITHER 5x + 1 OR 2x - 1 = 0   If 5x + 1 = 0, then x = -1/5   If 2x - 1 = 0, then x = 1/2   So, the roots (solutions) are -1/5 and 1/2   The answer is -1/5 and 1/2.
<result>B</result>
Which of the following are roots of an equation (x^-2)+(3x^-1)-10=0