Find the smallest number of five digits exactly divisible by 24,48,64 and 88. Options:
A) 11952	B) 11852	C) 11752	D) 11652	E) 11552
Smallest number of five digits is 10000.   Required number must be divisible by L.C.M. of 24,48,64,88 i.e 2012,   On dividing 10000 by 2012,we get 60 as remainder.   Therefore, Required number = 10000 +( 2012 â€“ 60 ) = 11952.   11952nswer is 11952.
<result>A</result>
Find the smallest number of five digits exactly divisible by 24,48,64 and 88.