How many numbers between 100 and 714 are divisible by 2, 3, and 7 together?
Choose the correct choice from the following options:
A) 112 B) 77 C) 267 D) 15 E) 99
Explanation:   As the division is by 2, 3, 7 together, the numbers are to be divisible by:  2*3*7= 
<gadget id="calculator"> 2*3*7</gadget>
<output>42</output>
42   The limits are 100 and 714   The first number divisible is 42*3= 
<gadget id="calculator">42*3</gadget>
<output>126</output>
126   To find out the last number divisible by 42 within 714:    714/42= 
<gadget id="calculator"> 714/42</gadget>
<output>17</output>
17   Hence, 42*14= 714 is the last number divisible by 42 within 714   Hence, total numbers divisible by 2, 3, 7 together are (17 â€“ 2) = 15   ANSWER: 15
<result>D</result>
How many numbers between 100 and 714 are divisible by 2, 3, and 7 together?