A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
Pick.
A) 89  B) 20  C) 36  D) 88  E) 34
Speed of train relative to jogger = 45 - 9= 
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
36 km/hr.= 36 * 5/18= 
<gadget id="calculator">36 * 5/18</gadget>
<output>10</output>
10 m/sec.   Distance to be covered= 240 + 120= 
<gadget id="calculator">240 + 120</gadget>
<output>360</output>
360 m.   Time taken= 360/10= 
<gadget id="calculator">360/10</gadget>
<output>36</output>
36 sec.   Answer: Option 36
<result>C</result>
A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?