What are the last two digits of 36*28*61*83*73*62? Choose the correct choice from the following options
A) 11
B) 09
C) 07
D) 05
E) 04
36*28*61*83*73*62=   We have to focus on the last two digits only, so 36*28=08*61=88*83=04   04*73=92 therefore 92*62=04   Hence Answer is 04
<result>E</result>
What are the last two digits of 36*28*61*83*73*62?