In a cricket match, five batsmen A, B, C, D and E scored an average of 36 runs. D Scored 5 more than E; E scored 8 fewer than A; B scored as many as D and E combined; and B and C scored 107 between them. How many runs did E score ?  Pick one
A) 62	B) 45	C) 28	D) 20	E) 25
Explanation:   Total runs scored = (36 x 5) = 180.   Let the runs scored by E be x.   Then, runs scored by D = x + 5; runs scored by A = x + 8;   runs scored by B = x + x + 5 = 2x + 5;   runs scored by C = (107 - B) = 107 - (2x + 5) = 102 - 2x.   So, total runs = (x + 8) + (2x + 5) + (102 - 2x) + (x + 5) + x = 3x + 120.   Therefore 3x + 120 =180 3X = 60 x = 20.   Answer: Option 20
<result>D</result>
In a cricket match, five batsmen A, B, C, D and E scored an average of 36 runs. D Scored 5 more than E; E scored 8 fewer than A; B scored as many as D and E combined; and B and C scored 107 between them. How many runs did E score ?