If four fair dice are thrown simultaneously, what is the probability of getting at least one pair?  Options.
A) 1/6	B) 5/18	C) 1/2	D) 2/3	E) 13/18
1st roll = any number = 6/6   2nd roll = not a match to the first = 5/6   3rd roll = not a match to the 1st or 2nd = 4/6   4th roll = not a match to the 1st or 2nd or 3rd = 3/6   (6/6)(5/6)(4/6)(3/6) =   (1)(5/6)(2/3)(1/2) =   10/36   10/36 is the probability of rolling 0 matching numbers, so...   1 - 10/36 = 26/36 = the probability of rolling at least one matching pair of numbers   26/36 = 13/18   Answer:13/18
<result>E</result>
If four fair dice are thrown simultaneously, what is the probability of getting at least one pair?