If two dice are thrown simultaneously, find the probability that the numbers appeared are equal?
Choices:	A) 2/6	B) 1/6	C) 3/6	D) 4/6	E) 5/6
The numbers appeared are equal.   Therefore, the required events are (1, 1), (2, 2), (3, 3), (4, 4), (5, 5) and (6, 6).   Therefore, n(E) = 6   Therefore, the required probability = n(E)/n(S) = 6/36   = 1/6   ANSWER:1/6
<result>B</result>
If two dice are thrown simultaneously, find the probability that the numbers appeared are equal?