How many different three-digit multiples of 5 can be composed of digits 2, 3, 4, and 5 if none of the digits is repeated?
Choose the correct option
A) 3 B) 6 C) 10 D) 12 E) 18
Available: 2, 3, 4, 5   You need to make 3 digit numbers which are multiples of 5.   ___ ___ ___   For the number to be a multiple of 5, it must end with either 0 or 5. We only have 5 available so the number must end with 5.   ___ ___ 5   Now you select 2 numbers out of the leftover 3 numbers (2, 3 and 4) in 3C2 ways and arrange them in the 2 places in 2! ways which gives you 3C2*2! = 6   or you can say that you can select a number for the hundreds place in 3 ways and select a number for the tens place in 2 ways (since numbers cannot be repeated). So you can make the number in  3*2= 
<gadget id="calculator"> 3*2</gadget>
<output>6</output>
6 ways   ANS:6
<result>B</result>
How many different three-digit multiples of 5 can be composed of digits 2, 3, 4, and 5 if none of the digits is repeated?