Find the total no of 10 digits whose sum is 4.  Select the correct option:
A) 210	B) 220	C) 230	D) 240	E) 250
4=4+0(one 4 &amp; 9 zeroes)=&gt; 1   4=3+1(one 3,one 1 &amp; 8 zeroes)=&gt; 2*9!/8!=18   4=2+2(two 2's &amp; 8 zeroes)=&gt; 9   4=1+1+2(two 1's &amp; one 2)=&gt; 9!/7! + 9!/(7!*2!)=72+36= 
<gadget id="calculator">72+36</gadget>
<output>108</output>
108   4=1+1+1+1(four 1's)=&gt; 9!/(6!*3!)=84   total no. of 10 digits no. whose sum is 4 =1+18+9+108+84= 
<gadget id="calculator">1+18+9+108+84</gadget>
<output>220</output>
220   ans 220   ANSWER:220
<result>B</result>
Find the total no of 10 digits whose sum is 4.