There is a five digit code consist of letters and digit. the code can have one digit from 1,2,3 and any four letters from A,b,c,d,e. first and last code must be a letter and all letters can be repeated. How many combinations can be possible?	Choose the correct choice from the following answers:
A) 625  B) 3840  C) 5625  D) 11,520  E) 11,620
5c1*(5c1*5c1*3c1)*3!/2!*5c1=5625   First fix the 1st and last digit, that can be filled with any of the 5 letters in 5c1 ways   Remaining 3 digits includes a no which can be filled in 3c1 ways   Remaining 2 digits are again letters and can be filled in 5c1 ways   these 3 digits can be arranged among themselves in 3!/2! ways   5625 is the answer!   ANSWER:5625
<result>C</result>
There is a five digit code consist of letters and digit. the code can have one digit from 1,2,3 and any four letters from A,b,c,d,e. first and last code must be a letter and all letters can be repeated. How many combinations can be possible?