find the terms which do not contain 7 between 1000 and 9999
Pick
A) 9000 B) 8000 C) 8500 D) 8800 E) 8900
Total number of four digit numbers =9000 (i.e 1000 to 9999 )   We try to find the number of numbers not having digit 2 in them.   Now consider the units place it can be selected in 9 ways (i.e 0,1,2,3,4,5,6,8,9)   Tens place it can be selected in 9 ways (i.e 0,1,2,3,4,5,6,8,9)   Hundreds place it can be selected in 9 ways (i.e 0,1,2,3,4,5,6,8,9)   Thousands place can be selected in 8 ways (i.e 1,2,3,4,5,6,,8,9) here '0' cannot be taken   Total number of numbers not having digit 7 in it =9 x 9 x 9 x 8 =5832   9000lso,Total number of numbers having digit 7 in it = 9000-5832= 
<gadget id="calculator">9000-5832</gadget>
<output>3_168</output>
3168   9000NSWER:9000
<result>A</result>
find the terms which do not contain 7 between 1000 and 9999