A couple decides to have 4 children. If they succeed in having 4 children and each child is equally likely to be a boy or a girl, what is the probability that they will have exactly 2 girls and 2 boys?	Choose the correct choice from the following choices
A) 3/8
B) 1/4
C) 3/16
D) 1/8
E) 1/16
no of ways of getting P(GGBB) is 4!/2!*2!;   Total no of ways is 2^n =2^4 =16;   6/16 = 3/8;   We can consider this question to a coin that is flipped for 4 times . what is the probability of getting exactly two heads .   P(all out comes) = 1/2 *1/2 *1/2 *1/2 =1/16;   P(favorable outcomes) = 4!/(2! * 2!) = 6/16 =3/8;   3/8NSWER:3/8
<result>A</result>
A couple decides to have 4 children. If they succeed in having 4 children and each child is equally likely to be a boy or a girl, what is the probability that they will have exactly 2 girls and 2 boys?