In how many ways can be 8 boys and 8 girls sit around circular table so that no two boys sit next to each other? Select the correct option:
A) (5!)^2
B) (6!)^2
C) 7!8!
D) 11!
E) (5!)^2*6!
first fix one boy and place other 7 in alt seats so total ways is 7!   now place each girl between a pair of boys... total ways of seating arrangement of girls 8!   total is 7!*8!   ANS 7!8!
<result>C</result>
In how many ways can be 8 boys and 8 girls sit around circular table so that no two boys sit next to each other?