Find the number of ways in which four men, two women and a child can sit at a table if the child is seated between two women.	Choose the correct choice from the following:
A) 12 B) 24 C) 36 D) 48 E) 60
The number of arrangements of n distinct objects in a row is given by n!n!.   The number of arrangements of n distinct objects in a circle is given by (n−1)!(n−1)!.   We have M, M, M, M, W, W, C --&gt; glue two women and the child so that they become one unit and the child is between women: {WCW}. Now, these 5 units: {M}, {M}, {M}, {M}, {WCW} can be arranged around the table in  (5-1)= 
<gadget id="calculator"> (5-1)</gadget>
<output>4</output>
4! ways and the women within their unit can be arranged in 2 ways {W1, C, W2} or {W2, C, W1} so total # of arrangement is 4!*2=48.   Answer: 48. ANSWER:48
<result>D</result>
Find the number of ways in which four men, two women and a child can sit at a table if the child is seated between two women.