In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?
Answers: A) 5/21 B) 5/23 C) 5/29 D) 5/12 E) 5/92
Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)   As remaining person can be any one among three couples left.   Required probability   = (5C2 * 6C1)/10C5   = (10 * 6)/252 = 5/21   5/21nswer: 5/21
<result>A</result>
In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?