Three numbers are randomly selected, with replacement, from the set of integers {0, 1, 2, 3, 4, 5, 6}. If the first number selected is w, the second number selected is x, and the third number is y, what is the probability that w < x < y ?	Choose the correct choice from the following choices.
A) 2/7 B) 3/7 C) 5/49 D) 6/49 E) 30/343
The number of ways to select w, x, and y is:   7*7*7= 
<gadget id="calculator">  7*7*7</gadget>
<output>343</output>
343   The number of ways to choose three different numbers from the set is 7C3=35.   There are six permutations for each group of three different numbers, but only one permutation satisfies w &lt; x &lt; y.   P(w &lt; x &lt; y) = 35/343 = 5/49   The answer is 5/49.
<result>C</result>
Three numbers are randomly selected, with replacement, from the set of integers {0, 1, 2, 3, 4, 5, 6}. If the first number selected is w, the second number selected is x, and the third number is y, what is the probability that w < x < y ?