How many different arrangements of letters are possible if three letters are chosen from the letters A through H and the letters E and A must be among the letters selected?  Choices:
A) 30
B) 33
C) 36
D) 39
E) 42
Besides A and E, there are 6 letters and we can choose one of them.   6C1 = 6   Three letters can be arranged in 3! ways.   The number of arrangements is 6*3! = 36   The answer is 36.
<result>C</result>
How many different arrangements of letters are possible if three letters are chosen from the letters A through H and the letters E and A must be among the letters selected?