A box contains 30 mangoes out of which 7 are spoilt. If seven mangoes are chosen at random, find the probability that A number is selected at random from first ninty natural numbers. What is the chance that it is a multiple of either 9 or 11?
Choices.
A) 1/5	B) 3/5	C) 2/5	D) 4/15	E) 7/5
The probability that the number is a multiple of 9 is 10/90. (Since 9*10= 
<gadget id="calculator">9*10</gadget>
<output>90</output>
90).   Similarly the probability that the number is a multiple of 11 is 8/90. {Since   11*8= 
<gadget id="calculator">  11*8</gadget>
<output>88</output>
88).   Neither 9 nor 11 has common multiple from 1 to 90. Hence these events are mutually exclusive events. Therefore chance that the selected number is a multiple of 9 or 11 is (10+8)/90= 1/5.   1/5NSWER:1/5
<result>A</result>
A box contains 30 mangoes out of which 7 are spoilt. If seven mangoes are chosen at random, find the probability that A number is selected at random from first ninty natural numbers. What is the chance that it is a multiple of either 9 or 11?