Let d(n) represent the sum of the digits of the integer n. For example,
d(2016) = 2 + 0 + 1 + 6 = 9:
For how many positive 3-digit integers k is it true that d(k) > d(k + 1)? Select.
A) 90	B) 100	C) 120	D) 140	E) 40
Note that d(k) &gt; d(k + 1) if and only if the units digit of k is 9, because if the units   digit of k is not 9, then d(k) = d(k + 1) - 1 &lt; d(k + 1). Since there are 9 possible hundreds   digits and 10 possible tens digits, there are   9 * 10= 
<gadget id="calculator">  9 * 10</gadget>
<output>90</output>
90 possible values of k.   correct answer 90
<result>A</result>
Let d(n) represent the sum of the digits of the integer n. For example,
d(2016) = 2 + 0 + 1 + 6 = 9:
For how many positive 3-digit integers k is it true that d(k) > d(k + 1)?