What is the smallest no. which must be added to 8261955 so as to obtain a sum which is divisible by 11?
Choose the most appropriate option.
A) 8 B) 11 C) 13 D) 15 E) 16
For divisibility by 11, the difference of sums of digits at even and odd places must be either zero or divisible by 11.   For 8261955, Difference =(8+6+9+5) -(2+1+5)=28-8= 
<gadget id="calculator">28-8</gadget>
<output>20</output>
20.   The units digit is at odd place. So we add 2 to the number=&gt; 8261955 +2= 
<gadget id="calculator">8261955 +2</gadget>
<output>8_261_957</output>
8261957   Now , (8+6+9+7) -(2+1+5)=30-8= 
<gadget id="calculator">30-8</gadget>
<output>22</output>
22=&gt; 22 is a multiple of 11 and hence 8261957 is also divisible by 11   11
<result>B</result>
What is the smallest no. which must be added to 8261955 so as to obtain a sum which is divisible by 11?