Let x be a positive integer, what is the remainder when 3^(3x+3)+3 is divided by 3?  Choose the correct answer:
A) 4 B) 2 C) 3 D) 1 E) 5
For: (3^(3x+3)+3)/3   Let n = 3x + 3   3^n   3^1 = 3   3^2 = 9   3^3 = 27   3^4 = 81   3^5 = 243, last digit pattern repeats 3, 9, 7, 1, 3, ....   Rule: x^(m+n) = (x^m)(x^n)   (3^(3x))(3^3)   Rule: x^(mn) = (x^m)^n   3^(3)(3^x)(3^3) =&gt; Now, (7)(3)(7) + 3 = (7) + 3 =&gt; Finally, 10/3 and remainder is 1.   Answer: 1
<result>D</result>
Let x be a positive integer, what is the remainder when 3^(3x+3)+3 is divided by 3?