In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term. What is the sum of the 16th, 17th terms in the sequence?
Options:	A) 2^18	B) 3(2^17)	C) 7(2^16)	D) 3(2^15)	E) 7(2^15)
the sequence comes out to be 2^0,2^1,2^2,2^3 and so on...   so 16th term will be 2^15   17th term 2^16   adding all three   we get   2^15+(2^15)*2   so answer is 2^15(1+2)=&gt;3(2^15)   answer 3(2^15)
<result>D</result>
In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term. What is the sum of the 16th, 17th terms in the sequence?