David decides to attend a base ball game with six friends. If the party of seven sits together in seven consecutive seats, and David must NOT sit in between two of his friends, how many ways can the seven friends be arranged? Choices:
A) 360
B) 180
C) 90
D) 720
E) 1440
David have to sit at either of the ends.   If David sits on the left most corner, then other 6 friends can be arranged in 6! = 720   David can also sit on the other end, then another 6! ways we can arrange.   So total number of ways = 720+720= 
<gadget id="calculator">720+720</gadget>
<output>1_440</output>
1440   Answer : 1440
<result>E</result>
David decides to attend a base ball game with six friends. If the party of seven sits together in seven consecutive seats, and David must NOT sit in between two of his friends, how many ways can the seven friends be arranged?