The length of a rectangle is 5 more than the width. What are the dimensions of the rectangle if the perimeter is 34?  Choose the correct choice from the following choices:
A) 11  B) 12  C) 13  D) 14  E) None
Pretend width = 1, then length = 6 ( 1 + 5)   2 × 1 + 2 × 7 = 2 + 14= 
<gadget id="calculator">2 + 14</gadget>
<output>16</output>
16. Notice that 16 is far from a perimeter of 34   Try much bigger number.   How about if we...   Pretend width= 4, then length = 9 ( 4 + 5)   2 × 4 + 2 × 9 = 6 + 18= 
<gadget id="calculator">6 + 18</gadget>
<output>24</output>
24. We are getting closer to a perimeter of 34   Pretend width= 5, then length = 10 ( 5 + 5)   2 × 5 + 2 × 10 = 10 + 30 = 30.   Pretend width = 7, then length = 12 ( 7 + 5)   2 × 7 + 2 × 12 = 14 + 24= 
<gadget id="calculator">14 + 24</gadget>
<output>38</output>
38. This is higher than a perimeter of 34. So width should be higher than 5 and smaller than 7. May be a width of 6 will work.   Pretend width= 6, then length = 11 ( 6 + 5)   2 × 6 + 2 × 11 = 12 + 22= 
<gadget id="calculator">12 + 22</gadget>
<output>34</output>
34.   Use of algebra:   Let width= x   Let length = x + 5   P = 2 × L + 2 × W   34 = 2 × ( x + 5) + 2 × x   34 = 2x + 10 + 2x   34 = 4x + 10   34 - 10 = 4x + 10 - 10   24 = 4x   24/4 = 4x/4   6 = x   Therefore, width = 6 and length = x + 5 = 6 + 5= 
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
11   11nswer 11
<result>A</result>
The length of a rectangle is 5 more than the width. What are the dimensions of the rectangle if the perimeter is 34?