If P(A)=0.4, P(B)=0.6 and P(A ∪ B)=0.8. What is the value of P(A∩B')=? Pick one.
A) 0.1  B) 0.2  C) 0.3  D) 0.4  E) None
Solution:   P(A∪0.2) = P(A) + P(0.2) - P(A∩0.2') =&gt;   0.8=0.4 - P(A∩0.2) =&gt;P(A∩0.2)=0.2   P(A∩0.2') = P(A) - P(A∩0.2) = 0.4 - 0.2= 
<gadget id="calculator">0.4 - 0.2</gadget>
<output>0.2</output>
0.2   Answer 0.2
<result>B</result>
If P(A)=0.4, P(B)=0.6 and P(A ∪ B)=0.8. What is the value of P(A∩B')=?