A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?  Options.
A) 4:5	B) 9:1	C) 2:5	D) 3:4	E) 6:7
Milk = 3/5 * 20= 
<gadget id="calculator">3/5 * 20</gadget>
<output>12</output>
12 liters, water= 8 liters   If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.   Remaining milk = 12 - 6= 
<gadget id="calculator">12 - 6</gadget>
<output>6</output>
6 liters   Remaining water= 8 - 4= 
<gadget id="calculator">8 - 4</gadget>
<output>4</output>
4 liters   10 liters of pure milk are added, therefore total milk= (6 + 10)= 
<gadget id="calculator">(6 + 10)</gadget>
<output>16</output>
16 liters.   The ratio of milk and water in the new mixture= 16:4 = 4:1   If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10= 
<gadget id="calculator">4/5 * 10</gadget>
<output>8</output>
8 liters.   Amount of water removed= 2 liters.   Remaining milk = (16 - 8)= 
<gadget id="calculator">(16 - 8)</gadget>
<output>8</output>
8 liters.   Remaining water= (4 -2)= 
<gadget id="calculator">(4 -2)</gadget>
<output>2</output>
2 liters.   final mixture obtained= (8 + 10):2 = 18:2 = 9:1.   ANSWER 9:1
<result>B</result>
A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?