What is the remainder when 123456789101112131415161718192021222324252627282930313233343536373839404142434481 is divided by 45? Select
A) 26 B) 36 C) 16 D) 06 E) 40
Explanation :   Let's call : A = 123456789101112131415161718192021222324252627282930313233343536373839404142434481   =&gt; A = B * 100 + 81 [with B = 1234567 ..... 424344]   We have:   B x 100 is divisible by 45   Because:   - Sum of all digits in B   = 1+2+3 + .... +44 = (1+44) + (2+43) + ....+ (22+23) (22 pairs)   = 22*45 =&gt; 36 divisible for 9   Since 36 is divisible by 9, 36 * 100 will be divisible by  9*5= 
<gadget id="calculator"> 9*5</gadget>
<output>45</output>
45   81 divided 45 gives a remainder of 36   Therefore, A divided by 45 reminder 36   Answer : 36
<result>B</result>
What is the remainder when 123456789101112131415161718192021222324252627282930313233343536373839404142434481 is divided by 45?