Let S be the set of permutations of the sequence 2, 3, 4, 5, 6 for which the first term is not 2. A permutation is chosen randomly from S. The probability that the second term is 5 is given by a/b (in lowest terms). What is a+b?	Choose the correct choice from the following options:
A) 5
B) 6
C) 11
D) 16
E) 19
The number of possible permutation without 2 in the first digit is   4X4X3X2X1=96 ways.   The number of possible permutations with 5 in the second term is= 3X3X2X1=18 ways.   18c1/96c1 = 18/96= 3/16= &gt; a+b=19.   ANSW19R:19
<result>E</result>
Let S be the set of permutations of the sequence 2, 3, 4, 5, 6 for which the first term is not 2. A permutation is chosen randomly from S. The probability that the second term is 5 is given by a/b (in lowest terms). What is a+b?