Jane and Thomas are among the 6 people from which a committee of 3 people is to be selected. How many different possible committees of 3 people can be selected from these 6 people if at least one of either Jane or Thomas is to be selected?
Choose the correct choice from the following answers:
A) 12	B) 14	C) 16	D) 18	E) 20
The total number of ways to choose 3 people from 6 is 6C3 = 20.   The number of committees without Jane or Thomas is 4C3 = 4.   There are  20-4= 
<gadget id="calculator"> 20-4</gadget>
<output>16</output>
16 possible committees which include Jane and/or Thomas.   The answer is 16.
<result>C</result>
Jane and Thomas are among the 6 people from which a committee of 3 people is to be selected. How many different possible committees of 3 people can be selected from these 6 people if at least one of either Jane or Thomas is to be selected?