There are 5 girls and 5 boys. If they are to be seated in a row, what is the probability that no two girls sit together?	Choose the correct choice from the following answers:
A) A)1/10! B) B)2*5!5!/10! C) C)6!6!/10! D) D)6!6!/12! E) E)6!7!/12!
If girls are alternate, then only no 2 girls can be together.   So among 10 places, girls can be seated in 5 alternate places in 5! ways.   And boys can be seated in the remaining 5 places in 5! ways.   Therefore total number of ways = 5! * 5!   But there could be 2 such arrangements--&gt;   1. When first place is filled by a girl   2. When first place is filled by a boy   Therefore total number of ways = 2*5! * 5!   Also total number of ways to fill 10 places = 10!   Hence probability =2∗5!5!/10!   Answer:2*5!5!/10!
<result>B</result>
There are 5 girls and 5 boys. If they are to be seated in a row, what is the probability that no two girls sit together?