If x = 147, which of the following numbers could be subtracted from x to create a sum that is divisible by 6?
Choose the correct choice from the following choices:	A) 1	B) 2	C) 3	D) 4	E) 5
Divisibility rule of 6: A number is divisible by 6 if it is divisible by both 2 and 3   Divisibility rule of 3: A number is divisible by 3 if the sum of the digits is divisible by 3   x = 147. We need to make this number even in order for it to be divisible by 2.   Hence we need to subtract an odd number from it.   Hence left over options are A, C, and E   147 - 1= 
<gadget id="calculator">147 - 1</gadget>
<output>146</output>
146. Sum of digits= 11.   This is not divisible by 3.   147 - 3= 
<gadget id="calculator">147 - 3</gadget>
<output>144</output>
144. Sum of digits= 9   This is divisible by 3.   Hence 3 should be subtracted from 147 to make the resultant a multiple of 6.   3orrect Option: 3
<result>C</result>
If x = 147, which of the following numbers could be subtracted from x to create a sum that is divisible by 6?