A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 456. What is the sum of the last 8 of the even integers?  Choose the correct answer:
A) 580 B) 584 C) 588 D) 592 E) 596
The sum of the first 8 numbers is: x + (x+2) +...+ (x+14) = 456   The sum of the next 8 numbers is: (x+16) + (x+2+16) +...+ (x+14+16) =   456 + 8(16) = 456 + 128= 
<gadget id="calculator">456 + 128</gadget>
<output>584</output>
584   The answer is 584.
<result>B</result>
A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 456. What is the sum of the last 8 of the even integers?