8+88+888+.....+8888........8888. There are 21 “8” digits in the last term of the series.
Find the last three digits of the sum.  Choose the correct choice from the following answers:
A) 384	B) 584	C) 784	D) 968	E) 768
21*8= 
<gadget id="calculator">21*8</gadget>
<output>168</output>
168 carry 16   20*8= 
<gadget id="calculator">20*8</gadget>
<output>160</output>
160+16= 
<gadget id="calculator">160+16</gadget>
<output>176</output>
176 carry 17   19*8= 
<gadget id="calculator">19*8</gadget>
<output>152</output>
152+17= 
<gadget id="calculator">152+17</gadget>
<output>169</output>
169   the value is 968   ANSWER:968
<result>D</result>
8+88+888+.....+8888........8888. There are 21 “8” digits in the last term of the series.
Find the last three digits of the sum.