The average of four positive integers is 69. The highest integer is 93 and the least integer is 39. The difference between the remaining two integers is 28. Which of the following integers is the higher of the remaining two integers?	Choose the most appropriate option:  A) 76  B) 86  C) 56  D) 45  E) 17
Let the four integers be A, B, C and D where A &gt; B &gt; C &gt; D.   (A + B + C + D)/4 = 69 =&gt; A + B + C + D = 276 ---&gt; (1)   A = 93, D = 39 and B - C = 28   (1) =&gt; B + C = 276 - (A + D) = 276 - 132= 
<gadget id="calculator">276 - 132</gadget>
<output>144</output>
144.   86 + 86 -28= 
<gadget id="calculator">86 + 86 -28</gadget>
<output>144</output>
144   86= (144 + 28)/2= 
<gadget id="calculator">(144 + 28)/2</gadget>
<output>86</output>
86   Answer: 86
<result>B</result>
The average of four positive integers is 69. The highest integer is 93 and the least integer is 39. The difference between the remaining two integers is 28. Which of the following integers is the higher of the remaining two integers?