If p^2 – 12p + 36 = q, and p is a positive integer between 1 and 10, inclusive, what is the probability that q < 0?	Options: A) 1/10 B) 1/5 C) 2/5 D) 3/5 E) 3/10
(p-4)(p-8) = q   p = 5 ,6 or 7 for this to be true, so   3/10   Ans :3/10
<result>E</result>
If p^2 – 12p + 36 = q, and p is a positive integer between 1 and 10, inclusive, what is the probability that q < 0?