In how many ways can 4 boys and 2 girls sit around a table in such a way that no two girls sit together?	Choose the correct choice from the following answers: A) 74 B) 72 C) 78 D) 82 E) 68
The 4 boys can be seated around a table in 3! Ways. In between them there are 4 places.   The 2 girls can be placed in the 4 places in 4P2 ways.   Therefore, Required number of ways= 3!* 4P2   =6*12= 
<gadget id="calculator">6*12</gadget>
<output>72</output>
72   ANSWER:72
<result>B</result>
In how many ways can 4 boys and 2 girls sit around a table in such a way that no two girls sit together?