In triangle XYZ, side XY, which runs perpendicular to side YZ, measures 24 inches in length. If the longest side of the the triangle is 26 inches, what is the area, in square inches, of triangle XYZ?	Options
A) 100 B) 120 C) 140 D) 150 E) 165
Okay we know we have a right triangle with hypotenuse 26.   Using Pythagoras theory I think: 24^2 + x^2 = 26^2   so 576 + x^2 = 676 ---&gt; x^2 = 100 ---&gt; x= 10   Areal of triangle = base* height / 2 so  24*10/2= 
<gadget id="calculator"> 24*10/2</gadget>
<output>120</output>
120   So answer choice 120
<result>B</result>
In triangle XYZ, side XY, which runs perpendicular to side YZ, measures 24 inches in length. If the longest side of the the triangle is 26 inches, what is the area, in square inches, of triangle XYZ?