If the average (arithmetic mean) of the four numbers K, 2K + 3, 3K – 5 and 5K + 1 is 118, what is the value of K? Choose the correct choice from the following answers
A) 11	B) 15 3/4	C) 22	D) 118	E) 25 3/10
K + 2K +3 + 3K - 5 + 5K +1 = 11K -1   (11K -1)/4 = 118   11K = 118 * 4 +1 = 472 +1= 
<gadget id="calculator">472 +1</gadget>
<output>473</output>
473   K= 473 / 11= 
<gadget id="calculator">473 / 11</gadget>
<output>43</output>
43.   Answer 118.
<result>D</result>
If the average (arithmetic mean) of the four numbers K, 2K + 3, 3K – 5 and 5K + 1 is 118, what is the value of K?