If an integer x is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that x(x + 1)(x + 2) will be divisible by 8? Choose the correct choice from the following answers: A) 1/4 B) 3/8 C) 1/2 D) 5/4 E) 5/8
I get 5/8 as well   1 to 96 inclusive means we have 48 odd and 48 even integers   5/8 O 5/8 / 8 = Integer, therefore we have 48 / 96 numbers divisible by 8   O 5/8 O / 8 = Not Integer   We cannot forget multiples of 8 from 1 to 96   We have 12 numbers that are multiple of 8   Therefore, 48/96 + 12/96 = 60/96 = 5/8   answer : 5/8
<result>E</result>
If an integer x is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that x(x + 1)(x + 2) will be divisible by 8?