Today David, who is 40 years old, and his daughter, who is 12 years old, celebrate their birthdays. How many years will pass before David’s age is twice his daughter’s age?  Choose the correct choice.
A) 22  B) 20  C) 16  D) 18  E) 14
Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.   After x years passes David’s age will be (40+x) years old, and his daughter’s age will be (12+x) years old. Since the David’s age is twice his daughter’s age (40+x)= 2 * (12+x) ---&gt;   40+x=24+2x ---&gt; x= 16   The answer is (16).
<result>C</result>
Today David, who is 40 years old, and his daughter, who is 12 years old, celebrate their birthdays. How many years will pass before David’s age is twice his daughter’s age?