When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 4/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?  Pick one:
A) 10/9 n B) 4/3 n C) 3/2 n D) 9/4 n E) 7/3n
E is the answer.   To solve this problem, draw diagram or use algebra. I'm more comfortable with algebra.   Given   - tank was already 1/3 full.   - When n ltr added, it became 4/9   So 1/3 + n = 4/9   n = 4/9 - 3/9   n = 1/9   capacity of the tank is full fraction . i.e. 1 i.e. 9/9   so the question is 9/9 is how much times n   = 9/9= 
<gadget id="calculator">9/9</gadget>
<output>1</output>
1= xn   so x = 9/1= 
<gadget id="calculator">9/1</gadget>
<output>9</output>
9/1= 
<gadget id="calculator">9/1</gadget>
<output>9</output>
9n
<result>E</result>
When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 4/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?