From a group of 3 boys and 3 men, four are to be randomly selected. What is the probability that equal numbers of boys and men will be selected?	Choose one:
A) 1/5
B) 3/5
C) 4/5
D) 2/5
E) 6/10
Using the first example, here is the probability of THAT EXACT sequence occurring:   BBMM = (3/6)(2/5)(3/4)(2/3) = 36/360 = 1/10   Each of the other 5 options will yield the exact SAME probability....   eg   BMBM = (3/6)(3/5)(2/4)(2/3) = 36/360 = 1/10   So we have 6 different options that each produce a 1/10 chance of occurring.   6(1/10) = 6/10 = 3/5   Final Answer:   3/5
<result>B</result>
From a group of 3 boys and 3 men, four are to be randomly selected. What is the probability that equal numbers of boys and men will be selected?