Three unbiased coins are tossed, what is the probability of geƫng at least 2 tails ? Select:
A) 1/3  B) 1/6  C) 1/2  D) 1/8  E) None of these
Explanation:   Total cases are = 2*2*2= 
<gadget id="calculator">2*2*2</gadget>
<output>8</output>
8, which are as follows   [TTT, HHH, TTH, THT, HTT, THH, HTH, HHT]   Favoured cases are= [TTH, THT, HTT, TTT] = 4   So required probability = 4/8 = 1/2   Answer: 1/2
<result>C</result>
Three unbiased coins are tossed, what is the probability of geƫng at least 2 tails ?