r = number of flags;n = number of poles;Any number of flags can be accommodated on any single pole.r= 5 n = 3 . If first pole has 2 flags ,third pole has 1 flag, how many ways the remaining can be arranged? Pick
A) 4 ways
B) 5 ways
C) 7 ways
D) 8 ways
E) 6 ways
2 flags are remaining and as it is given that 3 poles can have any no. of flags therefore   3p2=3!/(3-2)!   =3*23 /(3-2)= 
<gadget id="calculator">3 /(3-2)</gadget>
<output>3</output>
3*2= 
<gadget id="calculator">3*2</gadget>
<output>6</output>
6 ways   ANSW6 waysR:6 ways
<result>E</result>
r = number of flags;n = number of poles;Any number of flags can be accommodated on any single pole.r= 5 n = 3 . If first pole has 2 flags ,third pole has 1 flag, how many ways the remaining can be arranged?