A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:	Choose the correct choice:
A) 30 birds  B) 22 birds  C) 18 birds  D) 38 birds  E) 28 birds
Let total number of shots =x   Shots fired by 30 birds =5x/8   Shots fired by B =3x/8   Killing shots by 30 birds   =(5x/8)×(1/3)=5x/24   Missing shots by B   =(3x/8)×(1/2)=3x/16   B has missed 27 times   ⇒3x/16=27   ⇒x=(27×16)/3=144   Hence, killing shots by 30 birds   =5x/24=(5×144)/24=30   i.e., 30 birds has killed 30 birds   30 birdsnswer: 30 birds
<result>A</result>
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed: