Find the minimum value of n such that 50! is perfectly divisible by 2520^n.  Answers.
A) 0
B) 1
C) 2
D) 3
E) 4
50!/2520^n   2520 -&gt; 2^3 * 3^2 * 5^1 * 7^1   Here 7 is the largest prime factor...   So in order to find the minimum value of "n", it is enough to find the minimum power of "7"... nd for maximum value of "n", find max power of 7...   For max. value of n, find   50/7^1 + 50/7^2 = 7 + 1= 
<gadget id="calculator">7 + 1</gadget>
<output>8</output>
8 [quotient only]   Max. value of n which is perfectly divisible by 2520^n is (8)   Min. value is 1   Max value : 8   Min Value : 1   ANSWER:1
<result>B</result>
Find the minimum value of n such that 50! is perfectly divisible by 2520^n.