If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a seven-percent vinegar solution, what was the concentration of the original solution? Choose the correct choice from the following:
A) 19.3%  B) 17%  C) 36.17%  D) 15.5%  E) 12.5%
Let X be the quantity of non-vinegar in the strong vinegar solution   Thus vinegar quantity will be 12 - X   When 50 ounces of water were added the percentage of vinegar becomes 7%, thus (12 - X)/62 = 7/100   From this equation X = 7.66   Answer (12-7.66)/12 = 36.17%   ANSWER:36.17%
<result>C</result>
If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a seven-percent vinegar solution, what was the concentration of the original solution?