The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 5 consecutive integers that start with (m + 2)? Choices:
A) m + 3	B) n + 6	C) n + 3	D) m + 5	E) n + 2
The average of consecutive numbers is the middle number.   Then n = m+2.   The average of 5 consecutive numbers starting from n is n+2.   The answer is n + 2.
<result>E</result>
The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 5 consecutive integers that start with (m + 2)?