Three unbiased coins are tossed. What is the probability of getting at most two heads?  Choices
A) 3/4
B) 1/4
C) 7/8
D) 3/8
E) 2/8
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}   Let E = event of getting at most two heads.   Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.   P(E) =	n(E)	=	7	.   n(S)	8   Answer : 7/8.
<result>C</result>
Three unbiased coins are tossed. What is the probability of getting at most two heads?