In a 500 m race, Ravi beats Ramesh by 5 seconds or 100 m. They decide to run another race and this time Ravi gives Ramesh a head tart of 200 m. If Ravi’s speed is twice his previous speed and Ramesh’s speed is one and half times his previous speed, how far from the starting point should the winning post be so that they finish at the same time?
Choose the correct choice from the following options:
A) 500 m B) 1000 m C) 1500 m D) 2000 m E) 2500 m
Ravi beats ramesh by 5 sec or 100 mtr....means ramesh cover 100mtr in 5 sec....by this we can get ramesh speed in 20m/sec   20.............in 1 sec   500........in 500/20= 
<gadget id="calculator">500/20</gadget>
<output>25</output>
25 sec(Ramesh's time)   so ravi take 20 sec to cover 500 mtr......by this we can get that ravis speed is 25m/sec   now assume x be the distance from staring line where we need to put the winning post.   According to question ravi’s speed will be  25*2= 
<gadget id="calculator"> 25*2</gadget>
<output>50</output>
50m/sec &amp; ramesh’s speed will be   20*1.5= 
<gadget id="calculator">  20*1.5</gadget>
<output>30</output>
30 m/sec   now assume x be the distance from staring line where we need to put the winning post.   they will take same time to reach the wining post.   500 ms ravi gives Ramesh a 200 m ahead start so he has to accede x meter and Ramesh has to accede (x-200) meter   Hence we may write,   x/50=(x-200)/30   x=500 meter   500 mNSWER:500 m
<result>A</result>
In a 500 m race, Ravi beats Ramesh by 5 seconds or 100 m. They decide to run another race and this time Ravi gives Ramesh a head tart of 200 m. If Ravi’s speed is twice his previous speed and Ramesh’s speed is one and half times his previous speed, how far from the starting point should the winning post be so that they finish at the same time?