The area of one square is x^2 + 8x + 16 and the area of another square is 4x^2 − 28x + 49. If the sum of the perimeters of both squares is 72, what is the value of x?  Choose the correct choice from the following options:
A) 3	B) 4	C) 5	D) 6	E) 7
The areas are (x+4)^2 and (2x-7)^2.   The lengths of the sides are x+4 and 2x-7.   If we add the two perimeters:   4(x+4) + 4(2x-7) = 72   12x = 84   x = 7   The answer is 7.
<result>E</result>
The area of one square is x^2 + 8x + 16 and the area of another square is 4x^2 − 28x + 49. If the sum of the perimeters of both squares is 72, what is the value of x?