The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?	Pick one:
A) 7m
B) 6m
C) 5m
D) 2m
E) 4m
Let the sides of the rectangle be l and b respectively.   From the given data,   (√l2 + b2) = (1 + 108 1/3 %)lb   =&gt; l2 + b2 = (1 + 325/3 * 1/100)lb   = (1 + 13/12)lb   = 25/12 lb   =&gt; (l2 + b2)/lb = 25/12   12(l2 + b2) = 25lb   Adding 24lb on both sides   12l2 + 12b2 + 24lb = 49lb   12(l2 + b2 + 2lb) = 49lb   but 2(l + b) = 28 =&gt; l + b = 14   12(l + b)2 = 49lb   =&gt; 12(14)2 = 49lb   =&gt; lb = 48   Since l + b = 14, l = 8 and b = 6   l - b = 8 - 6= 
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
2m.   Answer: 2m
<result>D</result>
The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?