A basketball player succeeds with 70% of her free throws. If she has a set of three free throws, what is the probability that she succeeds at least once?
Choose one
A) 0.952 B) 0.964 C) 0.973 D) 0.985 E) 0.992
P(missing all 3 free throws) = 0.3^3 = 0.027   P(succeeding at least once) = 1 - 0.027= 
<gadget id="calculator">1 - 0.027</gadget>
<output>0.973</output>
0.973   The answer is 0.973.
<result>C</result>
A basketball player succeeds with 70% of her free throws. If she has a set of three free throws, what is the probability that she succeeds at least once?