If the mode of Set D is equal to the median of Set D, Set D could be Choose one:
A) [0, 1, 2, 2, 3, 4, 5, 6]
B) [2, 2, 5, 7, 9]
C) [x, x+1, x+2, x+2, x+3, x+3]
D) [10, 102, 105, 105]
E) [4, 7, 10, 11, 25/2, 13, 13, 17, 29, 51, 51, 51]
Correct Answer: (C)   Set D could be The mode is the most common number; the median is the middle number when the numbers are arranged from least to greatest. Any number plus an integer value is greater than the original number, so x + 1 is greater than x, x + 2 is greater than x + 1, etc., so set (C) is arranged from least to greatest. Its median is the average of (x+2) and (x+2), which must be (x+2). (x+2) is also the most common number, so the mode of set [x, x+1, x+2, x+2, x+3, x+3] is equal to the median of set [x, x+1, x+2, x+2, x+3, x+3].
<result>C</result>
If the mode of Set D is equal to the median of Set D, Set D could be