As a treat for her two crying children, a mother runs to the freezer in which she has five cherry ice pops, three orange ice pops, and four lemon-lime ice pops. If she chooses two at random to bring outside to the children, but realizes as she runs out the door that she cannot bring them different flavors without one invariably being jealous of the other and getting even more upset, what is the probability that she has to return to the freezer to make sure that they each receive the same flavor? Options:
A) 1/9
B) 1/6
C) 5/18
D) 1/999
E) 5/6
Probability of not getting the same flavor -&gt;   Favourable -&gt; Cherry - orange [ 5C1 * 3C1 [or simply 5*3 ] or Cherry - lemon [ 5*4] or orange - lemon [3*4]   Prob = (5*3 + 5*4 + 3*4 ) / 9C2 = 47/47520 = 1/999   Answer -&gt; 1/999
<result>D</result>
As a treat for her two crying children, a mother runs to the freezer in which she has five cherry ice pops, three orange ice pops, and four lemon-lime ice pops. If she chooses two at random to bring outside to the children, but realizes as she runs out the door that she cannot bring them different flavors without one invariably being jealous of the other and getting even more upset, what is the probability that she has to return to the freezer to make sure that they each receive the same flavor?