A meeting has to be conducted with 6 managers. Find the number of ways in which the managers may be selected from among 9 managers, if there are 2 managers who refuse to attend the meeting together.
Choose one.
A) 36 B) 40 C) 42 D) 45 E) 49
The total number of ways to choose 6 managers is 9C6 = 84   We need to subtract the number of groups which include the two managers, which is 7C4 = 35.   84 - 35= 
<gadget id="calculator">84 - 35</gadget>
<output>49</output>
49   The answer is 49.
<result>E</result>
A meeting has to be conducted with 6 managers. Find the number of ways in which the managers may be selected from among 9 managers, if there are 2 managers who refuse to attend the meeting together.