3 years before age of A was double than age of B.after 7 years the sum of their ages will 83.calculate the age of A.	Options:  A) 24  B) 21  C) 40  D) 45  E) 42
Let 3 years before age of B=x year and age of A=2x year   present age of B=(x+3) and present age of A=(2x+3)   after 7 years age of B=(x+10) year and age of A=(2x+10) year   (x+10)+(2x+10)=83,3x=63,x=21.   present age of A=(2x+3)=45 years   answer 45
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3 years before age of A was double than age of B.after 7 years the sum of their ages will 83.calculate the age of A.