If p is a natural number and p! ends with w trailing zeros, then the number of zeros that (5p)! ends with will be
Choices
A) a) (p+w) trailing zeros	B) b) (5p+y) trailing zeros	C) c) (5p+5y) trailing zeros	D) d) (p+5y) trailing zeros	E) e) none of them above
Let p = 1. p! = 1! = 1, which means w= 0   (5p)! = 5! = 120, trailing zeros = 1   1 = 1 + 0 = p + w   a) (p+w) trailing zerosnswer (a) (p+w) trailing zeros).
<result>A</result>
If p is a natural number and p! ends with w trailing zeros, then the number of zeros that (5p)! ends with will be