In how many ways can 8 Indians and, 4 American and 4 Englishmen can be seated in a row so that all person of the same nationality sit together? Choose one.
A) 8!*4!*4! Ways B) 3!*8!*4!*Ways C) 3!*4!*4! Ways D) 4!*4! Ways E) 3!*8!*4!*4! Ways
Taking all person of same nationality as one person, then we will have only three people.   These three person can be arranged themselves in 3! Ways.   8 Indians can be arranged themselves in 8! Way.   4 American can be arranged themselves in 4! Ways.   4 Englishman can be arranged themselves in 4! Ways.   Hence, required number of ways = 3!*8!*4!*4! Ways.   Ans 3!*8!*4!*4! Ways
<result>E</result>
In how many ways can 8 Indians and, 4 American and 4 Englishmen can be seated in a row so that all person of the same nationality sit together?