A two digit number is 18 less than the sum of the squares of its digits. How many such numbers are there? Choose the correct choice from the following answers:
A) 1  B) 2  C) 3  D) 4  E) 5
suppose the digit 10x+y.   so, 10x+y=x^2+y^2-18   =&gt;(x-6)(x-4)=(y-7)(-y-6)   so conddition satisfied for x=6,4 and y=7 so no of digit 2. 67,47.   ANSWER:2
<result>B</result>
A two digit number is 18 less than the sum of the squares of its digits. How many such numbers are there?