A man buys 12 lts of liquid which contains 10% of the liquid and the rest is water. He then mixes it with 10 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?
Select the correct option.
A) 80.91	B) 76.45	C) 77.45	D) 74.45	E) 73.45
10% in 12 lts is 1.2. So water = 12-1.2= 
<gadget id="calculator">12-1.2</gadget>
<output>10.8</output>
10.8 lts. 30% of 10 lts= 3. So water in 2nd mixture = 10-3= 
<gadget id="calculator">10-3</gadget>
<output>7</output>
7 lts. Now total quantity= 12 + 10= 
<gadget id="calculator">12 + 10</gadget>
<output>22</output>
22 lts. Total water in it will be 10.8 + 7= 
<gadget id="calculator">10.8 + 7</gadget>
<output>17.8</output>
17.8 lts. % of water= (100*17.8)/22 = 80.91. 80.91nswer:80.91
<result>A</result>
A man buys 12 lts of liquid which contains 10% of the liquid and the rest is water. He then mixes it with 10 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?