If d=1/(2^3*5^11) is expressed as a terminating decimal, how many nonzero digits will d have?  Choose the correct choice from the following choices.
A) One	B) Two	C) Three	D) Seven	E) Ten
Another way to do it is :   We know x^a*y^a=(X*Y)^a   given = 1/(2^3*5^11)   = Multiply and divide by 2^8   =2^8/(2^3*2^8*5^11)   =2^8/10^11   =&gt; non zero digits are 256=&gt; Ans Three
<result>C</result>
If d=1/(2^3*5^11) is expressed as a terminating decimal, how many nonzero digits will d have?