A bag contains 3 white balls, 3 black balls & 2 red balls. One by one three balls are drawn out without replacement. What is the probability that the third ball is red? Pick one:
A) 0.25 B) 0.15 C) 0.35 D) 0.45 E) 0.4
Favorable outcomes :   WWR -&gt; P(WWR)= 3/8 * 2/7 * 2/6 = 12/336   WRR -&gt; P(WRR)= 3/8 * 2/7 * 1/6 = 6/336   RWR -&gt; P(RWR)= 2/8 * 3/7 * 1/6 = 6/336   BBR -&gt; P(BBR)= 3/8 * 2/7 * 2/6 = 12/336   BRR -&gt; P(BRR)= 3/8 * 2/7 * 1/7 = 6/336   RBR -&gt; P(RBR)= 2/8 * 3/7 * 1/6 = 6/336   WBR -&gt; P(WBR)= 3/8 * 3/7 * 2/6 = 18/336   BWR -&gt; P(BWR)= 3/8 * 3/7 * 2/6 = 18/336   So, P(Total) = 84/336 = 1/4= 
<gadget id="calculator">1/4</gadget>
<output>1/4 = around 0.25</output>
0.25   0.25nswer is 0.25
<result>A</result>
A bag contains 3 white balls, 3 black balls & 2 red balls. One by one three balls are drawn out without replacement. What is the probability that the third ball is red?