Eric throws 2 dice,and his score is the sum of the values shown.Sandra throws one dice and her score is the square of the value shown. what is the probabilty that Sandras score will be strictly higher than Erics score??	Options.
A) 117/216
B) 127/126
C) 137/126
D) 147/126
E) 157/126
sandra score can be like 1,4,9,16,25,36   eric score less then 1--&gt;0   eric score less then 4=(1,1),(1,2)(2,1)--&gt;3   eric score less then 9 are (1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(4,1)(4,2)(4,3)(4,4)(5,1)(5,2)(5,3)(6,1)(6,2)--&gt;26   eric score will always be less then 16---&gt;36   eric score will always be less then 25---&gt;36   eric score will always be less then 36---&gt;36   total favorable outcomes=3+26+36+36+36= 
<gadget id="calculator">3+26+36+36+36</gadget>
<output>137</output>
137   total possible outcomes=216(36*6)   probability=137/216   ANSWER:137/126
<result>C</result>
Eric throws 2 dice,and his score is the sum of the values shown.Sandra throws one dice and her score is the square of the value shown. what is the probabilty that Sandras score will be strictly higher than Erics score??