A bakery currently has 6 pies and 5 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies? Select the correct option.
A) 100/231	B) 25/77	C) 5/11	D) 93/116	E) 50/147
The total number of ways to choose 5 from 11 is 11C5 = 462.   The number of ways that include 3 pies is 6C3*5C2 = 20*10= 
<gadget id="calculator">20*10</gadget>
<output>200</output>
200   P(exactly 3 pies)= 200/462 = 100/231   The answer is 100/231.
<result>A</result>
A bakery currently has 6 pies and 5 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies?