Given A+B+C+D+E= FG. If FG is Maximum as possible and A,B,C,D,E,F,G all are distinct digits
(0-9) then what is the value of G.	Options.
A) 1
B) 2
C) 3
D) 4
E) 5
A+B+C+D+E=FG   9+8+7+6+5= 
<gadget id="calculator">9+8+7+6+5</gadget>
<output>35</output>
35 Here E=G, So it is not possible.   again 9+8+7+6+4= 
<gadget id="calculator">9+8+7+6+4</gadget>
<output>34</output>
34 Here also E=G, so it is also not possible   again 9+8+7+5+4= 
<gadget id="calculator">9+8+7+5+4</gadget>
<output>33</output>
33 Here F=G   Finally 9+8+6+5+4= 
<gadget id="calculator">9+8+6+5+4</gadget>
<output>32</output>
32 In this case condition is satisfies, so all are distinct and value of G=2.   ANSWER:2
<result>B</result>
Given A+B+C+D+E= FG. If FG is Maximum as possible and A,B,C,D,E,F,G all are distinct digits
(0-9) then what is the value of G.