What is the probability of getting exactly 4 heads in a single throw of five fair coins? Select: A) 1/4 B) 3/8 C) 3/16 D) 5/32 E) 7/32
One possible case is HHHHT.   P(HHHHT) = 1/2*1/2*1/2*1/2*1/2 = 1/32   There are 5C4 = 5 possible cases.   P(4 heads) = 5*1/32 = 5/32   The answer is 5/32.
<result>D</result>
What is the probability of getting exactly 4 heads in a single throw of five fair coins?