In a race of length L metres, Johnson beats Lewis by U metres and Greene by V metres, By how many metres does Lewis beat Greene in the same race ? (U<V)	Choose one:
A) L(L-V) / L-U	B) L(V-U) / L-U	C) L-V	D) U-V	E) U+V
As the time is constant, the ratio of distances will be the same as the ratio of speeds.   If Sj,Sl,Sg are the speeds of Johnson, Lewis, and Greene respectively, then   Sj/Sl = L/(L-U)   and Sj/Sg = L/(L-V)   =&gt; Sg/Sl = (L-V)/(L-U)   Therefore the speeds of Lewis and Greene are in the ratio (L-U)/(L-V)   When Lewis finishes the race, the time run by him and Greene are same   =&gt; The ratio of the speeds of Lewis and Greene will be the same as the ratio of distances run by them.   =&gt; Distance run by Greene when Lewis finishes the race = (L-V)/(L-U) * L   =&gt; Lewis beats Greene by L - L*(L-V)/(L-U) = L [ 1 - (L-V)/(L-U)] = L (V-U) / (L-U)   Option (L(V-U) / L-U) is therefore correct.
<result>B</result>
In a race of length L metres, Johnson beats Lewis by U metres and Greene by V metres, By how many metres does Lewis beat Greene in the same race ? (U<V)