Divide 50 into two parts so that sum of the reciprocal is 1/12 ?	Choose one
A) 10,20 B) 20,20 C) 30,20 D) 40,20 E) 50,20
let two no be x,y   x+y=50 ....eq(1)   1/x+1/y=1/12...eq(2)   x+y/xy=1/12(using eq(1))   xy=600   now, (x-y)^2=(x+y)^2 -4xy   using above   x-y=10.....eq(3)   solving eq(1) &amp; eq(2)   x=30 &amp; y=20   ANSWER:30,20
<result>C</result>
Divide 50 into two parts so that sum of the reciprocal is 1/12 ?