How many different arrangements of letters are possible if three letters are chosen from the letters A through I and the letters E and A must be among the letters selected? Pick
A) 36 B) 38 C) 40 D) 42 E) 44
Besides A and E, there are 7 letters and we can choose one of them.   7C1 = 7   Three letters can be arranged in 3! ways.   The number of arrangements is 7*3! = 42   The answer is 42.
<result>D</result>
How many different arrangements of letters are possible if three letters are chosen from the letters A through I and the letters E and A must be among the letters selected?