A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are drawn what is the probability that one is yellow and two are red?
Choices
A) 12/429  B) 12/429  C) 12/455  D) 12/419  E) 12/492
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.   When three marbles are drawn, the probability that one is yellow and two are red   = (²12/455₁)(⁴12/455₂)/¹⁵12/455₃   = (2 * 4 * 3 * 3 * 2)/(1 * 2 * 15 * 14 * 13)   = 12/455   Answer: 12/455
<result>C</result>
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are drawn what is the probability that one is yellow and two are red?