50 is divided into two parts such that the sum of their reciprocals is 1/ 12.Find the two parts.	Choose one.
A) 27 and 23
B) 25 and 25
C) 10 and 40
D) 35 and 15
E) 30 and 20
Let the two parts be x and (50 - x).   Then, 1 / x + 1 / (50 – x) = 1 / 12 =&gt; (50 – x + x) / x ( 50 – x) = 1 / 12   =&gt; x2 – 50x + 600 = 0 =&gt; (x – 30) ( x – 20) = 0 =&gt; x = 30 or x = 20.   So, the parts are 30 and 20.   Answer is 30 and 20.
<result>E</result>
50 is divided into two parts such that the sum of their reciprocals is 1/ 12.Find the two parts.