In an election contested by two parties, Party D secured 12% of the total votes more than Party R. If party R got 132,000 votes, by how many votes did it lose the election?
Choose the correct option
A) 240,000	B) 300,000	C) 168,000	D) 36,000	E) 24,000
Explanatory Answer   Let the percentage of the total votes secured by Party D be x%   Then the percentage of total votes secured by Party R = (x - 12)%   As there are only two parties contesting in the election, the sum total of the votes secured by the two parties should total up to 100%   i.e., x + x - 12 = 100   2x - 12 = 100   or 2x = 112 or x = 56%.   If Party D got 56% of the votes, then Party got  (56 - 12)= 
<gadget id="calculator"> (56 - 12)</gadget>
<output>44</output>
44% of the total votes.   44% of the total votes= 132,000   i.e., 44/100*T = 132,000   =&gt; T = 132000*100/44 = 300,000 votes.   The margin by which Party R lost the election = 12% of the total votes   = 12% of 300,000 = 36,000.   The correct choice is (36,000)
<result>D</result>
In an election contested by two parties, Party D secured 12% of the total votes more than Party R. If party R got 132,000 votes, by how many votes did it lose the election?