The sum of a 2digit no. & the no. obtained byreversing the order ofthe digit is 165. If the digits are differ by 3, find the original no.? Choices: A) 76 B) 86 C) 88 D) 90 E) 96
Let unit digit = x   Ten’s digit = x + 3   Original number = 10(x + 3) +x   = 10x + 30 + x   Original number = 11x +30   Reversing the digits :   Unit digit = x +3   Ten’s digit = x   New number = 10x + x + 3   New number = 11x + 3   As the sum of original number and the new number = 165   11x + 30 + 11x + 3 = 165   22x + 33 = 165   22x = 132   X = 6   Original number = 11 x + 30 = 11(6) +30   = 66 + 30= 
<gadget id="calculator">66 + 30</gadget>
<output>96</output>
96   96
<result>E</result>
The sum of a 2digit no. & the no. obtained byreversing the order ofthe digit is 165. If the digits are differ by 3, find the original no.?