What is the area inscribed by the lines y =4, x = 2, y = 6-2x on an xy-coordinate plane?	Choose the correct choice from the following:
A) a) 1 B) b) 2 C) c) 4 D) d) 6 E) e) 8
First, let's graph the lines y = 4 and x = 2   At this point, we need to find the points where the line y = 6-2x INTERSECTS the other two lines.   For the vertical line, we know that x = 2, so we'll PLUG x = 2 into the equation y = 6-2x to get y = 6-2(2) = 2   Perfect, when x = 2, y = 2, so one point of intersection is (2,2)   For the horizontal line, we know that y = 4, so we'll PLUG y = 4 into the equation y = 6-2x to get 4 = 6-2x. Solve to get: x = 1   So, when y = 4, x = 1, so one point of intersection is (1,4)   Now add these points to our graph and sketch the line y = 6-2x   At this point, we can see that we have the following triangle.   The base has length 1 and the height is 2   a) 1rea = (1/2)(base)(height)   = (1/2)(1)(2)   = 1   a) 1nswer:   a) 1
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What is the area inscribed by the lines y =4, x = 2, y = 6-2x on an xy-coordinate plane?