If x, y, and z are positive integers such that x^2 - y^2 + z^2 = 36, which of the following could be the values of x, y, and z?
I)x=122,y=157,z=99
II)x=125,y=160,z=102
III)x=100,y=150,z=167	Choose the correct answer: A) I only B) II only C) III only D) I​ and II E) I and III
10 sec answer if you know how to find the units digit of a number   The number given is of the form of square, so calculate the units digit - Here your objective is to find the sum where last digit is 0   x = 122, so x^2 will have units digit 4   y = 157, so y^2 will have units digit 9   z = 99, so z^2 will have units digit 1   Calculate the units digit , the units digit will be 0   Test with options II and III, only option I will satisfy the condition , hence this will be our answer is option I only.
<result>A</result>
If x, y, and z are positive integers such that x^2 - y^2 + z^2 = 36, which of the following could be the values of x, y, and z?
I)x=122,y=157,z=99
II)x=125,y=160,z=102
III)x=100,y=150,z=167