Three coins are tossed. What is the probability of getting at most two tails?  Pick one:
A) 2
B) 6/7
C) 7/8
D) 25
E) 5/1
Explanation :   Total number of outcomes possible when a coin is tossed = 2   Hence, total number of outcomes possible when 3 coins are tossed, n(S) = 2 × 2 × 2 = 8   E = event of getting at most two Tails = {TTH, THT, HTT, THH, HTH, HHT, HHH}   Hence, p(E)=n(E)/n(S)=7/8   7/8
<result>C</result>
Three coins are tossed. What is the probability of getting at most two tails?