Find value of X: (422+404)^2−(4×422×404)=X. Select
A) 234 B) 267 C) 324 D) 356 E) 577
Given Equation is in the form (a+b)2−4ab where a=422 and b=404   Hence answer   =(a+b)2−4ab=(a−b)2=(422−404)2=182=324   324
<result>C</result>
Find value of X: (422+404)^2−(4×422×404)=X.