An urn contains g green marbles and b blue marbles. If 3 green marbles and 6 blue marbles are added, and then one marble is selected at random from the urn, what is the probability that a blue marble will be drawn? Answers:
A) b+6/(b+g+9)	B) (b+5)/(g+3)	C) (b+5)/(b+g+8)	D) (b+5)/(b+g+3)	E) b/(b+g+5)
no of fav outcomes i.e. blue MArbles = b+6   Total no of outcomes i.e. total Marbles = (b+6)+(g+3)= b+g+9   probability = (b+6) /(b+g+9)   b+6/(b+g+9)nswer b+6/(b+g+9)
<result>A</result>
An urn contains g green marbles and b blue marbles. If 3 green marbles and 6 blue marbles are added, and then one marble is selected at random from the urn, what is the probability that a blue marble will be drawn?