A tiger is 50 of its own leaps behind a deer. The tiger takes 5 leaps per minutes to deer’s 4. If the tiger and the deer cover 8 m and 5 m per leap respectively, what distance will the tiger have to run before it catches the deer ?	Choose the correct option.
A) 600m
B) 700m
C) 800m
D) 1000m
E) 1200m
Tiger takes 5 leaps /m and Deer takes 4 leaps/ m   Thus, tiger runs at the speed of 5 x 8 = 40 m/min   and deer runs at the speed of 4 x 5 = 20 m/min   Tiger is 50 leaps behind,which is 50 x 8 = 400 m   Relative speed of tiger and deer is = 20 m/min   Thus, 400/20 = 20 m   Thus,the tiger will catch deer = 20 x 40 =800 m   ANSWER:800m
<result>C</result>
A tiger is 50 of its own leaps behind a deer. The tiger takes 5 leaps per minutes to deer’s 4. If the tiger and the deer cover 8 m and 5 m per leap respectively, what distance will the tiger have to run before it catches the deer ?