For any positive integer n, the sum of the first n positive integers equals [n(n+1)]/2.
What is the sum of all the even integers between 99 and 161?  Choose the correct choice from the following answers:
A) 1090 B) 2060 C) 3080 D) 4030 E) 5040
100 + 102 +...+ 160 = 31*100 + (2+4...+60) = 31*100 + 2(1+2+...+30) =   31*100 + 2(30)(31)/2 = 130*31= 
<gadget id="calculator">130*31</gadget>
<output>4_030</output>
4030   The answer is 4030.
<result>D</result>
For any positive integer n, the sum of the first n positive integers equals [n(n+1)]/2.
What is the sum of all the even integers between 99 and 161?