If F(x, n) be the number of ways of distributing "x" toys to "n" children so that each child receives at the most 2 toys then F(4, 3) =	Choose the correct option:
A) 3
B) 4
C) 6
D) 5
E) 7
Explanation :   We have to find the number of ways in which 4 toys can be distributed to 3 children so that each child receives at the most 2 toys.There are two possible cases:Case 1: Two of them receive 2 toys each and one of them doesn’t get any toy.There are 3 possible ways to distribute the toys in this case i.e., the three possible ways of selecting the child who will not get any toy.Case 2: Two of them receive 1 toy each and one of them receives 2 toys.Again there are 3 possible ways to distribute the toys in this case i.e., the three possible ways of selecting the child who will get 2 toys.So there are a total of 6 possible ways.   Answer : 6
<result>C</result>
If F(x, n) be the number of ways of distributing "x" toys to "n" children so that each child receives at the most 2 toys then F(4, 3) =