log xy3 = a; log x2y = b then then value of log y /log x	Answers
A) 23  B) 277  C) 997  D) 1781  E) 123
log xy3 = logx + 3logy = a - - - (1)   log x2y = 2logx + logy = b - - - (2)   Multiplying (1) by 2 and subtracting (2) from it   5logy = 2a-b   logy = 2a−b52a−b5   Put the value of log y in equation (2),   2logx + 2a−b52a−b5 = b   logx = 3b−a53b−a5   logylogx=2a−b53b−a5log⁡ylog⁡x=2a−b53b−a5 = 2a−b3b−a   Answer:277
<result>B</result>
log xy3 = a; log x2y = b then then value of log y /log x