A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken?  Choices:
A) 1 hour
B) 1/3 hour
C) 2/3 hour
D) 3/4 hour
E) 1/4 hour
Let the original speed and time is S and T   then distance =S*T   Now the speed changes to 2/3S and T is T+20   As the distance is same   S*T=2/3S*(T+20)   solving this we get t=40 minutes   =40/60=2/3 hour   ANSWER:2/3 hour
<result>C</result>
A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken?