What is the probability of getting a sum 9 from two throws of a dice?
Choices.
A) 1/6  B) 1/9  C) 1/8  D) 5/8  E) 2/9
In two throws of a dice, n(S) = (6 x 6) = 36.   Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.   P(E)=n(E)/n(S)   =4/36   =1/9   The answer should be 1/9
<result>B</result>
What is the probability of getting a sum 9 from two throws of a dice?