If x is an integer that has exactly three positive divisors (these include 1 and x), how many positive divisors does x^3 have?
Choose the correct choice from the following answers
A) 4 B) 5 C) 6 D) 7 E) 8
Since factors of '4'are {1,2,4}   4^3=64   Number of factors/divisors of 64= 2^6   We know that when a number is expressed as a product of the prime factors as below:   N = a^x * b^y * c^z   Then no. of divisors = (x+1)*(y+1)*(z+1)   Then here  (6+1)= 
<gadget id="calculator"> (6+1)</gadget>
<output>7</output>
7   ANSWER:7
<result>D</result>
If x is an integer that has exactly three positive divisors (these include 1 and x), how many positive divisors does x^3 have?