A certain stock exchange designates each stock with a 1, 2 or 3 letter code, where each letter is selected from the 8 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order, constitute a different code, how many diff stocks is it possible to designate with these codes?	Choices
A) 258 B) 584 C) 774 D) 624 E) 523
Pretty simple actually   Number of 1 letter symbols = 8   Number of 2 letter symbols = 8*8   Number of 3 letter symbols = 8*8*8   The answer is sum of the 3. =584   So the answer is 584.
<result>B</result>
A certain stock exchange designates each stock with a 1, 2 or 3 letter code, where each letter is selected from the 8 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order, constitute a different code, how many diff stocks is it possible to designate with these codes?