Mixture X contains 60% water and 40% chloride. If 120 gallons of Mixture Y is added to 80 gallons of mixture X in order to produce a solution that contains 75% water and 25% chloride, how many gallons of water must mixture Y contain?
Options
A) 100
B) 101
C) 102
D) 103
E) 104
80 gallons of Mix X containing 40% chloride + 120 gallons of Mix Y ----&gt; 25% chloride mixture   wA/wB = (cB - cAvg)/(cAvg - cA)   80/120 = (Y - 25)/(25 - 40)   2 * (-15) = 3 * (Y - 25)   Y = 15   So the concentration of chloride in Mix Y is 15%.   In 120 gallons of mix Y, you will have (85/100)*120= 
<gadget id="calculator">(85/100)*120</gadget>
<output>102</output>
102 gallons   ANSWER:102
<result>C</result>
Mixture X contains 60% water and 40% chloride. If 120 gallons of Mixture Y is added to 80 gallons of mixture X in order to produce a solution that contains 75% water and 25% chloride, how many gallons of water must mixture Y contain?