The surface area of a sphere is 4πR^2, where R is the radius of the sphere. If the surface area of sphere A is eight times as large as the surface area of sphere B, then the radius of sphere A is how many times the radius of sphere B? Pick:
A) 2  B) 2√2  C) 4  D) 2π  E) π·√8
R1 : Radius of sphere A   R2 : Radius of sphere B   As per question,4πR1^2=8∗4πR2^2   or R12=8∗R2^2   or R1 = 2√2R2. Hence, 2√2
<result>B</result>
The surface area of a sphere is 4πR^2, where R is the radius of the sphere. If the surface area of sphere A is eight times as large as the surface area of sphere B, then the radius of sphere A is how many times the radius of sphere B?