If the product of 3 consecutive integers is 210 then the sum of the two smaller integers is:
Pick one.
A) 17
B) 10
C) 11
D) 12
E) 13
let the numbers be x-1 , x , x+1   (x-1)(x)(x+1)=210   210=2*105   =2*3*35   =2*3*5*7   this can be written as 6*5*7   =&gt;x-1=5   x=6   x+1=7   sum of two smallest numbers=6+5= 
<gadget id="calculator">6+5</gadget>
<output>11</output>
11   ANSWER:11
<result>C</result>
If the product of 3 consecutive integers is 210 then the sum of the two smaller integers is: