If n is a natural number, then (6n2 + 6n) is always divisible by:  Choose the correct choice from the following answers:  A) 6 only  B) 12 only  C) 6 and 12 both  D) by 18 only  E) 15 only
(6n^2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.   Answer 6 and 12 both) 6 and 12 both.
<result>C</result>
If n is a natural number, then (6n2 + 6n) is always divisible by: