A bag contains 2 yellow, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue? Choose the correct choice from the following choices
A) 10/21  B) 1/21  C) 9/11  D) 7/11  E) 6/11
Total number of balls = 2 + 3 + 2= 
<gadget id="calculator">2 + 3 + 2</gadget>
<output>7</output>
7   n(S)=Total number of ways 7 = 7C2   let E = event of drawing 2 balls, none of them is blue   n(E) = no of ways of drawing 2 balls, none of them is blue   =No of ways of drawing 2 balls from the total= 5C2   5*4/7*6 = 10/21   10/21NSWER 10/21
<result>A</result>
A bag contains 2 yellow, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?