If the sum of two positive integers is 26 and the difference of their squares is 52, what is the product of the two integers? Choose the correct option: A) 108 B) 119 C) 128 D) 135 E) 168
Let the 2 positive numbers x and y   x+ y = 26 -- 1   x^2 - y^2 = 52   =&gt; (x+y)(x-y)=52 -- 2   Using equation 1 in 2 , we get   =&gt; x-y = 2 -- 3   Solving equation 1 and 3 , we get   x= 14   y= 12   Product = 14*12= 
<gadget id="calculator">14*12</gadget>
<output>168</output>
168   Answer 168
<result>E</result>
If the sum of two positive integers is 26 and the difference of their squares is 52, what is the product of the two integers?