A bakery currently has 4 pies and 7 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies?
Pick:  A) 1/5  B) 2/7  C) 3/7  D) 1/11  E) 2/11
The total number of ways to choose 5 from 11 is 11C5 = 462.   The number of ways that include 3 pies is 4C3*7C2 = 4*21= 
<gadget id="calculator">4*21</gadget>
<output>84</output>
84   P(exactly 3 pies)= 84/462 = 2/11   The answer is 2/11.
<result>E</result>
A bakery currently has 4 pies and 7 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies?