In the junior basketball league there are 15 teams, 1/3 of them are bad and ½ are rich. What can't be the number of teams that are rich and bad?
Choose the correct choice from the following:  A) 4.  B) 6.  C) 7.  D) 8.  E) 9.
total teams =15   bad teams=(1/3)*15= 
<gadget id="calculator">(1/3)*15</gadget>
<output>5</output>
5   rich teams=8   so maximum value that the both rich and bad can take will be 8. so E= 9 can not be that value.   ans 9..
<result>E</result>
In the junior basketball league there are 15 teams, 1/3 of them are bad and ½ are rich. What can't be the number of teams that are rich and bad?