In how many ways can the letters of the word SPENCER be arranged if the S and P must always be together and the N and C must always be together?
Select.
A) 12 B) 24 C) 60 D) 120 E) 240
There are 7 letters in the word SP240NC240R are 2240 , SP , NC , R   We will consider SP and NC as a group and there are 2 240's   No of arrangements in which S and P must always be together and the N and C must always be together   = (5! *2 *2)/2!   = 5!*2   = 120 *2= 
<gadget id="calculator">120 *2</gadget>
<output>240</output>
240   Answer 240
<result>E</result>
In how many ways can the letters of the word SPENCER be arranged if the S and P must always be together and the N and C must always be together?