The sum of all two digit numbers divisible by 5 is Select
A) 945
B) 545
C) 745
D) 645
E) 845
Required numbers are 10,15,20 . . . . . 95   This is an A.P. in which a=10,d=5 and l=95.   Let the number of terms in it be n.Then t=95   So a+(n-1)d=95.   10+(n-1)*5=95,   10+5n-5=95   5+5n=95   5n=95-5= 
<gadget id="calculator">95-5</gadget>
<output>90</output>
90/5= 
<gadget id="calculator">90/5</gadget>
<output>18</output>
18.   Required sum=n/2(a+l)   =18/2(10+95)   =945   945nswer is 945.
<result>A</result>
The sum of all two digit numbers divisible by 5 is