5 blue marbles, 3 red marbles and 4 purple marbles are placed in a bag. If 4 marbles are drawn without replacement, what is the probability that the resu lt will not be 2 blue and 2 purple marbles?	Choices
A) 4/33
B) (5/36)^2
C) 1/2
D) (31/36)^2
E) 29/33
Answer is 29/33.   The probability of 2 blue and 2 purple marbles selected is 5C2.4C2/12C4 =4/33.   Subtracting the above from 1 we get 29/33 29/33
<result>E</result>
5 blue marbles, 3 red marbles and 4 purple marbles are placed in a bag. If 4 marbles are drawn without replacement, what is the probability that the resu lt will not be 2 blue and 2 purple marbles?