The population of a town increases by 12% during first year and decreased by 10% during second year. If the present population is 50,400, what it was 2 years ago?
Options.
A) 40,000	B) 35,000	C) 50,000	D) 60,000	E) none of these
Here A = 50400, x = 12, y = - 10   Therefore, the population 2 years ago   = A /[( 1 + x/100) ( 1 + y/100)]   = 50400 / [( 1 + 12/100) ( 1 - 10/100)]   = (50400 x 100 x 100) / (112 x 90)   = 50,000.   ANSWER:50,000
<result>C</result>
The population of a town increases by 12% during first year and decreased by 10% during second year. If the present population is 50,400, what it was 2 years ago?