Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil's age. After further 8 years, how many times would he be of Sunil's age? Choose the most appropriate option:
A) 4 times
B) 2 times
C) 3 times
D) 5 times
E) 1 times
Assume that Sunil's present age =x.   Then, father's present age =3x+x=4x   After 8 years, father's age =212 times of Sunils' age   ⇒(4x+8)=212(x+8)⇒4x+8=52(x+8)⇒8x+16=5x+40⇒3x=40−16=24⇒x=243=8   After further 8 years,   Sunil's age =x+8+8=8+8+8= 
<gadget id="calculator">8+8+8</gadget>
<output>24</output>
24   Father's age=4x+8+8=4×8+8+8=48   Father's age/Sunil's age =4824=2.   Answer is 2 times.
<result>B</result>
Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil's age. After further 8 years, how many times would he be of Sunil's age?