Of the three- digit integers greater than 700, how many have two digits W that are equal to each other and the remaining digit different from the other two?  Choose the most appropriate option.
A) 90 B) 82 C) 80 D) 45 E) 36
three-digit integers greater than 700: 701 to 999, inclusive.   possible values for hundreds-digit--&gt; 7,8,9   possible values for tens-digit and ones-digit --&gt; 0, 1,2,3,4,5,6,7,8,9   when hundreds-digit and tens-digit are the same: (3x1x10)-3=27 ---&gt; we minus three to exclude 777, 888 and 999   when hundreds-digit and ones-digit are the same: (3x10x1)-3=27 ---&gt; we minus three to exclude 777, 888 and 999   when tens-digit and hundreds-digit are the same:[(3x10x1)-3]-1=26 ---&gt; we minus three to exclude 777, 888 and 999; we minus one to exclude 700   W=27+27+26= 
<gadget id="calculator">27+27+26</gadget>
<output>80</output>
80   Answer: 80
<result>C</result>
Of the three- digit integers greater than 700, how many have two digits W that are equal to each other and the remaining digit different from the other two?