Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?	Choose the correct choice:	A) 2 times	B) 2 1/2 times	C) 2 3/4 times	D) 3 times	E) 4 times
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.   (4x + 8) = 5/2(x + 8)   8x + 16 = 5x + 40   3x = 24   x = 8.   Hence, required ratio = (4x + 16)/(x + 16)	= 48/24= 
<gadget id="calculator">48/24</gadget>
<output>2</output>
2.   2 timesNSWER:2 times
<result>A</result>
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?