The number of ways in which six men and six women can be seated in a row, so that no two girls sit together is?  Pick one
A) 6! * ⁷P₆ B) 5! * 7 C) 6! * 7 D) 4! * 4 E) None
We can initially arrange the six boys in 6! ways.   Having done this, now three are seven places and six women to be arranged. This can be done in ⁷P₆ ways.   Hence required number of ways = 6! * ⁷P₆   6! * ⁷P₆
<result>A</result>
The number of ways in which six men and six women can be seated in a row, so that no two girls sit together is?