(1^2+2^2+3^2+.....+10^2)=?  Choose one
A) 330  B) 345  C) 365  D) 385  E) None of them
formula is (1^2+2^2+3^2+....+n^2=1/6 n(n+1)(2n+1)   n=10   =(1/6x10x11x21)   =385   Answer is 385.
<result>D</result>
(1^2+2^2+3^2+.....+10^2)=?