If (10^67) – 63 is written as a base 10 integer, which of the following options is the sum of the digits in that integer?
Choose the correct answer:
A) 598 B) 495 C) 590 D) 595 E) 695
We know that (10^67) is ending 00, so (10^67) – 63=9....9937   total number of digits in (10^20) – 63 is 67, or 65 digits of 9 and two digits 3 and 7.   answer choice is   65*9+10= 
<gadget id="calculator">  65*9+10</gadget>
<output>595</output>
595   Answer is 595 595
<result>D</result>
If (10^67) – 63 is written as a base 10 integer, which of the following options is the sum of the digits in that integer?