What is the probability that the sum of two dice will yield a 8, and then when both are thrown again, their sum will again yield a 8? assume that each die has 7 sides with faces numbered 1 to 7. Pick: A) 1/144 B) 1/36 C) 1/12 D) 1/6 E) 1/49
Solution -   Rolling dices is an independent event.   The combinations to get 8 are (1,7), (7,1), (2,6), (6,2), (3,5), (5,3), (4,,4) and total combinations of both dices is 49.   The probability of getting 8 in first attempt is 7/49=1/7.   Probability of getting 8 again in second attempt = (1/7)*(1/7) = 1/49. ANS 1/49
<result>E</result>
What is the probability that the sum of two dice will yield a 8, and then when both are thrown again, their sum will again yield a 8? assume that each die has 7 sides with faces numbered 1 to 7.