The product of three consecutive numbers is 120. Then the sum of the smallest two numbers is ?	Select:	A) 9	B) 15	C) 20	D) 38	E) 56
Product of three numbers = 120   120 = 2*2*5*6 = 4*5*6   So, the three numbers are 4,5 and 6.   And Sum of smallest of these two = 4 + 5= 
<gadget id="calculator">4 + 5</gadget>
<output>9</output>
9.   9NSWER : OPTION 9
<result>A</result>
The product of three consecutive numbers is 120. Then the sum of the smallest two numbers is ?