While playing a certain dice game, Chris wins if the sum of the two dice is 8, at which point the game is over. If the game allows Chris three rolls in an attempt to win, what is the probability that Chris will win?
Choose the correct choice from the following answers.
A) 1/2  B) 17/36  C) 137/379  D) 11/36  E) 25/216
Probability of winning game = 1- Probability of losing game   Probability of losing game = (Probability of not getting sum 7 in any of the three attempts)   Ways of getting sum 8 = (2,6)(3,5)(4,4)(5,3)(6,2)= 5 ways   Total ways of getting outcome on two dice =6*6= 
<gadget id="calculator">6*6</gadget>
<output>36</output>
36   Probability of getting sum as 8 in any attempt=5/36   Probability of NOT getting sum as 8 in any attempt = 1-(5/6)= 31/36   Probability of losing game =(31/36)*(31/36)*(31/36)=242/379   I.e. Probability of wining game = 1-(242/379) = 137/379   Answer : Option 137/379
<result>C</result>
While playing a certain dice game, Chris wins if the sum of the two dice is 8, at which point the game is over. If the game allows Chris three rolls in an attempt to win, what is the probability that Chris will win?