In how many ways can 8 Indians and, 4 American and 4 Englishmen can be seated in a row so that all person of the same nationality sit together?  Choose the correct choice from the following choices:	A) 3!*8!*4!*4! Ways	B) 8!*4!*4! Ways	C) 8!*3!*4! Ways	D) 3!*4!*4! Ways	E) 4!*4! Ways
Taking all person of same nationality as one person, then we will have only three people.   These three person can be arranged themselves in 3! Ways.   8 Indians can be arranged themselves in 8! Way.   4 American can be arranged themselves in 4! Ways.   4 Englishman can be arranged themselves in 4! Ways.   Hence, required number of ways = 3!*8!*4!*4! Ways.   Option 3!*8!*4!*4! Ways
<result>A</result>
In how many ways can 8 Indians and, 4 American and 4 Englishmen can be seated in a row so that all person of the same nationality sit together?