A and B play a series of 5 games in badminton. A's chance of winning s single game against B is 2/3. Find the chance that A wins exactly 3 games.  Select the correct option.
A) 64/81  B) 35/128  C) 80/243  D) None of these  E) cannot be determined
Explanation :   Here, each game is a trial and A's winning the game is a success. All games are independent , so, using the binomial distribution.   P(X) = nCx px(1 - p)n-x.   Where, x= wins exactly 3 games   =&gt; x = 3.   p= 2/3, 1-p=1/3, n=5.   P(3) = 5C3 (2/3)3(1/3)2 .   =&gt; 10 x (2(3)/3(5)).   =&gt; 80/243.   Answer : 80/243
<result>C</result>
A and B play a series of 5 games in badminton. A's chance of winning s single game against B is 2/3. Find the chance that A wins exactly 3 games.