The sum of 3 consecutive numbers is definitely:
Select.
A) Positive  B) Divisible by 2.  C) Divisible by 3  D) Divisible by 4.  E) Divisible by 5
If 1st term is x:   x+(x+1)+(x+2)=3x+3---&gt;Always divisible by 3   If 2nd term is x:   (x-1)+x+(x+1)  +( +1)+( +2)= 
<gadget id="calculator">  +( +1)+( +2)</gadget>
<output>3</output>
3x+3---&gt;Always divisible by 3   If 2nd term is x:   (x-1)+x+(x+1)=3x---&gt;Always divisible by 3   If 3rd term is x:   (x-2)+(x-1)+x=3x-3---&gt;Always divisible by 3   Answer: Divisible by 3
<result>C</result>
The sum of 3 consecutive numbers is definitely: