In a simultaneous throw of a pair of dice, find the probability of getting a total more than 11
Answers:
A) 11/25  B) 7/12  C) 5/13  D) 5/12  E) 6/17
Total number of cases = 10*10= 
<gadget id="calculator">10*10</gadget>
<output>100</output>
100   Favourable cases= [(2,10),(3,9),(3,10),(4,8),(4,9),(4,10),(5,7),(5,8),(5,9),(5,10),(6,6),(6,7),(6,8),(6,9),(6,10),(7,5),(7,6),(7,7),(7,8),(7,9),(7,10),(8,4),(8,5),(8,6),(8,7),(8,8),(8,9),(8,10),(9,3),(9,4),(9,5),(9,6),(9,7),(9,8),(9,10),(10,2),(10,3),(10,4),(10,5),(10,6),(10,7),(10,8),(10,9),(10,10)] = 44   So Probability = 44/100 = 11/25   11/25nswer is 11/25
<result>A</result>
In a simultaneous throw of a pair of dice, find the probability of getting a total more than 11