The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 9 consecutive integers that start with (m + 2)?	Select the correct option.
A) m + 4
B) n + 6
C) n + 3
D) m + 5
E) n + 4
Explanatory Answer   Approach: Work with a numerical example   The fastest way to solve problems of this kind is to take numerical examples.   Let the 5 consecutive integers be 1, 2, 3, 4, and 5.   The average of 5 consecutive integers from 1 to 5 is 3.   Therefore, the value of m is 1 and the value of n is 3.   9 consecutive integers starting from m + 2 will be 3, 4, ... , 11   The average of positive integers from 3 to 11 is 7.   We know n = 3. So, 7 has to be (n + 4)   Choice n + 4 is the correct answer.
<result>E</result>
The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 9 consecutive integers that start with (m + 2)?