Out of 4 fruits in a basket, 2 are rotten. If two fruits are drawn at random from the basket, the probability of both being rotten is	Choices:
A) 1/6
B) 10/21
C) 20/21
D) 11/16
E) 2/21
The number of exhaustive events = 4C2 =6.   Let E be event of the 2 fruits being rotten. The number of favourable cases are   2C2 = 1 way.   Required probability = 1/6   1/6NSWER:1/6
<result>A</result>
Out of 4 fruits in a basket, 2 are rotten. If two fruits are drawn at random from the basket, the probability of both being rotten is