In how many ways can 6 boys and 4 girls sit around a table in such a way that no two girls sit together?
Pick:	A) 43200	B) 41100	C) 48500	D) 46500	E) 49600
The 6 boys can be seated around a table in 5! Ways. In between them there are 6 places.   The 4 girls can be placed in the 6 places in 6P4 ways.   Therefore, Required number of ways= 5!* 6P4   =120*360= 
<gadget id="calculator">120*360</gadget>
<output>43_200</output>
43200   43200NSWER:43200
<result>A</result>
In how many ways can 6 boys and 4 girls sit around a table in such a way that no two girls sit together?