What is the probability that you will get a sum of 8 when you throw three dice simultaneously? Options:	A) 21/6^3.	B) 23/6^3.	C) 25/6^3.	D) 27/6^3.	E) 29/6^3.
This sum of 8 can occur in the following cases:   1-1-6 --&gt; 3!/2!=3 ways;   1-2-5 --&gt; 3!=6 ways;   1-3-4 --&gt; 3!=6 ways;   2-2-4 --&gt; 3!/2!=3 ways;   2-3-3 --&gt; 3!/2!=3 ways.   Total of 3+6+6+3+3= 
<gadget id="calculator">3+6+6+3+3</gadget>
<output>21</output>
21 ways.   Now, since the total number of outcomes is 6^3, then the probability is 21/6^3.   21/6^3.NSWER:21/6^3.
<result>A</result>
What is the probability that you will get a sum of 8 when you throw three dice simultaneously?