In how many ways can be 5 boys and 5 girls sit around circular table so that no two boys sit next to each other?
Choose the correct choice from the following options:
A) (5!)^2  B) (6!)^2  C) 5!4!  D) 11!  E) (5!)^2*6!
first fix one boy and place other 4 in alt seats so total ways is 4!   now place each girl between a pair of boys... total ways of seating arrangement of girls 5!   total is 5!*4!   ANS 5!4!
<result>C</result>
In how many ways can be 5 boys and 5 girls sit around circular table so that no two boys sit next to each other?