Three unbiased coins are tossed. What is the probability of getting at most two heads?
Choose the correct choice from the following:	A) 3/4	B) 7/8	C) 3/8	D) 5/6	E) 9/11
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}   Let E = event of getting at most two heads.   Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.   P(E)=n(E)/n(S)   =7/8   The answer should be 7/8
<result>B</result>
Three unbiased coins are tossed. What is the probability of getting at most two heads?