A certain manufacturer of cake, muffin, and bread mixes has 80 buyers, of whom 50 purchases cake mix, 40 purchase muffin mix, and 20 purchase both cake mix and muffin mix. If a buyer is to be selected at random from the 100 buyers, what is the probability that the buyer selected will be one who purchases neither cake mix nor muffin mix?
Pick one.
A) a. 1/10 B) b. 3/8 C) c. 1/2 D) d. 7/10 E) e. 9/10
C+M+B-CM-MB-CB-2CMB = 80   C - cake buyers, M - muffin and B - Bread buyers. CM,MB,CB and CMB are intersecting regions.   the question asks for people who have bought only bread mixes = B-CB-MB-2CMB has to be found out.   50 + 40 + B-CB-MB-20-2CMB = 80   B-CB-MB-2CMB = 30   hence the probability = 30/80 = 3/8.   b. 3/8
<result>B</result>
A certain manufacturer of cake, muffin, and bread mixes has 80 buyers, of whom 50 purchases cake mix, 40 purchase muffin mix, and 20 purchase both cake mix and muffin mix. If a buyer is to be selected at random from the 100 buyers, what is the probability that the buyer selected will be one who purchases neither cake mix nor muffin mix?