If a certain toy store's revenue in November was 2/3 of its revenue in December and its revenue in January was 1/3 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?
Options:  A) 1/4  B) 1/2  C) 2/3  D) 2  E) 3
Let Dec rev =100   Then Nov rev is 2/3 (100) =&gt; 67   Therefore Jan rev = 1/3(Nov rev) = 1/3(67) =&gt; 23   Hence Dec rev = x*( Nov rev+Jan rev)/2   100 = x* (67+23)/2   x = 100/45 =&gt; 2.22=3   Ans) 3
<result>E</result>
If a certain toy store's revenue in November was 2/3 of its revenue in December and its revenue in January was 1/3 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?