A four-digit code can consist of the digits 0 ~ 9 except that it does not contain the digits 1, 2, 4, and 6 at all. If repeated digits are allowed, what is the probability that it has at least one even digit?  Choose the correct choice:
A) 23/24  B) 31/36  C) 55/64  D) 65/81  E) 75/121
P(no even digits) = 2/3*2/3*2/3*2/3 = 16/81   P(at least one even digit) = 1 - 16/81 = 65/81   The answer is 65/81.
<result>D</result>
A four-digit code can consist of the digits 0 ~ 9 except that it does not contain the digits 1, 2, 4, and 6 at all. If repeated digits are allowed, what is the probability that it has at least one even digit?