The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is? Select.
A) 22	B) 67	C) 40	D) 88	E) 11
Let the numbers be 2x and 3x.   Then, their L.C.M = 6x. So, 6x = 48 or x = 8.   The numbers are 16 and 24.   Hence, required sum = (16 + 24)= 
<gadget id="calculator">(16 + 24)</gadget>
<output>40</output>
40.   Answer:40
<result>C</result>
The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is?