If Dave throws down a set dice twice, calculate the probability that one die would be an even while the other would be odd?	Select the correct option:
A) 1/6	B) 1/4	C) 1/2	D) 1	E) 1/3
The number of exhaustive outcomes for each throw is 36.   For both throws is= 64   Let E be the event of getting an even number on one die and an odd number on the other for each throw.   The event of getting either both even or both odd for each throw is = 18/36 = 1/2   The event of getting either both even or both odd for both throws is = 36/64 = 1/2   P(E) = 1 - 1/2   = 1/2.   Answer:c
<result>C</result>
If Dave throws down a set dice twice, calculate the probability that one die would be an even while the other would be odd?