An urn contains 5 red, 6 blue and 8 green balls. 4 balls are randomly selected from the urn, find the probability that the drawn ball are 1 blue and 3 red?	Choices.
A) 1/969  B) 2/969  C) 4/969  D) 5/323  E) 21/789
Sample space = no. of ways 4 balls were drawn from urn = 19C4 = 3876   No. ways 1 blue balls and 3 red were drawn from bag = 6C1 * 5C3 = 60   Probability = 60 / 3876 = 5/323   Ans - 5/323
<result>D</result>
An urn contains 5 red, 6 blue and 8 green balls. 4 balls are randomly selected from the urn, find the probability that the drawn ball are 1 blue and 3 red?