A box contains 4 red chips and 2 blue chips. If two chips are selected at random without replacement, what is the probability that the chips are different colors? Choose the correct choice from the following choices.
A) 1/2 B) 8/15 C) 7/12 D) 2/3 E) 7/10
Total selection ways: 6C2=6!/2!4!=15   Selecting one blue chip out of two: 2C1=2!/1!1!=2   Selecting one red chip out of four: 4C1=4!/1!3!=4   Thus, (2C1*4C1)/6C2=(2*4)/15=8/15   ANSWER:8/15
<result>B</result>
A box contains 4 red chips and 2 blue chips. If two chips are selected at random without replacement, what is the probability that the chips are different colors?