The equation of line m is y = 4/3*x - 100. What is the smallest possible distance in the xy-plane from the point with coordinates (0, 0) to any point on line m?	Choose the correct choice from the following answers.
A) 48  B) 50  C) 60  D) 75  E) 100
This can be solve in two steps and without any complex calculation.   Given : equation of line m as y=(4/3)x -100. So the line intercept the axes at (0,-100) and (75,0).   This can be considered a right angle triangle with right angle at (0,0) . So Base=100 , Height=75 and Hypotenuse =125 (By Pythagoras triplet)   So a perpendicular from the (0,0) to hypotenuse will be the answer.   Area of triangle= 0.5*100*75=0.5*125* x   =&gt; x=60;   SO answer is 60=60
<result>C</result>
The equation of line m is y = 4/3*x - 100. What is the smallest possible distance in the xy-plane from the point with coordinates (0, 0) to any point on line m?