If 12x = 16y = 28z, then what is a possible sum of positive integers x, y, and z?	Choose the correct choice
A) 52 B) 58 C) 122 D) 84 E) 168
12x = 16y = 28z   3x = 4y = 7z   3(4*7) = 4(3*7) = 7(3*4)   Addition = 28+21+12= 
<gadget id="calculator">28+21+12</gadget>
<output>61</output>
61   Answer would be multiple of 61 which is 122   Answer :122
<result>C</result>
If 12x = 16y = 28z, then what is a possible sum of positive integers x, y, and z?