The area of one square is x^2 + 4x + 4and the area of another square is 4x^2 − 12x + 9. If the sum of the perimeters of both squares is 32, what is the value of x?  Choose the correct choice from the following choices
A) 0
B) 2
C) 2.5
D) 4.67
E) 3
spotting the pattern of equations both are in form of (X+C)^2 so   A1= (x+2)^2A2= (2x-3)^2   L1= x+2L2= 2x-3   P1 = 4( x+2)P2=4(2x-3)   P1+P2=32   4( x+2) +4(2x-3)=32..............&gt; X=3   Answer: 3
<result>E</result>
The area of one square is x^2 + 4x + 4and the area of another square is 4x^2 − 12x + 9. If the sum of the perimeters of both squares is 32, what is the value of x?