If a number between 10 and 60 (inclusive) at random. What is the probability that the tens digit is greater than ones digit? Choices:
A) 31/41
B) 1041
C) 14/41
D) 16/51
E) 11/41
If tens digi is 6 ---&gt; ones digit : 0   If tens digi is 5 ---&gt; ones digit : 0, 1, 2, 3, 4   If tens digi is 4 ---&gt; ones digit : 0, 1, 2, 3   If tens digi is 3 ---&gt; ones digit : 0, 1, 2   If tens digi is 2 ---&gt; ones digit : 0, 1   If tens digi is 1 ---&gt; ones digit : 0   So the number of numbers whose tens digit is greater than ones digit is 11.   The total number is   60-10+1= 
<gadget id="calculator">  60-10+1</gadget>
<output>51</output>
51.   So the probability is 16/51. The answer is (16/51).
<result>D</result>
If a number between 10 and 60 (inclusive) at random. What is the probability that the tens digit is greater than ones digit?