The sum of three prime numbers is 100. If one of them exceeds another by 36, then one of the numbers is:	Select the correct option
A) 7
B) 29
C) 41
D) 67
E) 76
x+(x+36)+y=100 =&gt; 2x+y=64   Therefore y must be even prime, which is 2.   Therefore 2x+2=64 =&gt; x=31   Third prime number= (x+36)= (31+36)= 
<gadget id="calculator">(31+36)</gadget>
<output>67</output>
67.   ANSWER:41
<result>C</result>
The sum of three prime numbers is 100. If one of them exceeds another by 36, then one of the numbers is: