What is the sum of all possible 3-digit numbers that can be constructed using the digits 2, 3, and 4 if each digit can be used only once in each number? Choose the correct choice from the following:  A) 1776  B) 1887  C) 1998  D) 2332  E) 2554
There are 6 possible arrangements of the three numbers.   Then each number will be in the hundreds, tens, and ones place two times each.   The sum is 2(222) + 2(333) + 2(444) = 1998   The answer is 1998.
<result>C</result>
What is the sum of all possible 3-digit numbers that can be constructed using the digits 2, 3, and 4 if each digit can be used only once in each number?