What is the probability that the sum of two dice will yield a 7, and then when both are thrown again, their sum will again yield a 7? assume that each die has 6 sides with faces numbered 1 to 6.
Choose the correct answer:
A) 1/144
B) 1/36
C) 1/12
D) 1/6
E) 1/3
In order to get the sum of the two dices to be 7, there are six combinations that satisfy this requirement.   1+6= 
<gadget id="calculator">1+6</gadget>
<output>7</output>
7   2+5= 
<gadget id="calculator">2+5</gadget>
<output>7</output>
7   3+4= 
<gadget id="calculator">3+4</gadget>
<output>7</output>
7   4+3= 
<gadget id="calculator">4+3</gadget>
<output>7</output>
7   5+2= 
<gadget id="calculator">5+2</gadget>
<output>7</output>
7   6+1= 
<gadget id="calculator">6+1</gadget>
<output>7</output>
7   Each combination has 1/36 of probability of occurrence, or in total 6/36 for the six combinations, which is 1/6.   In order to get the probability of this occurring twice in a row we multiply 1/6 *1/6 and we get 1/36.   The answer is 1/36.
<result>B</result>
What is the probability that the sum of two dice will yield a 7, and then when both are thrown again, their sum will again yield a 7? assume that each die has 6 sides with faces numbered 1 to 6.