How many integerskgreater than 100 and less than 1100 are there such that if the hundreds and the units digits ofkare reversed, the resulting integer is k+99?  Choose the correct choice:	A) 50	B) 60	C) 70	D) 80	E) 90
Numbers will be like 102 =&gt; 201 = 102 + 99   203 =&gt; 302 = 103 + 99   so the hundereth digit and units digit are consecutive where unit digit is bigger than hundred digit.   There will be ninet pairs of such numbers   for every pair there will 10 numbers like for 12 =&gt; 102, 112,132,142,152, 162,172,182,192.   Total = 9 *10= 
<gadget id="calculator">9 *10</gadget>
<output>90</output>
90 hence 90.
<result>E</result>
How many integerskgreater than 100 and less than 1100 are there such that if the hundreds and the units digits ofkare reversed, the resulting integer is k+99?