(212 + 222 + 232 + ... + 302) = ?	Choose the correct option
A) 385
B) 2485
C) 2570
D) 3255
E) none
Solution   (212 + 222 + 232 + ... + 302) = a+(n-1)d=last number .....so 212+(n-1)10=302.....so n=10. so sum= n/2(2a+(n-1)d) = 10/2(2*212+9*10) = 2570.   Answer 2570
<result>C</result>
(212 + 222 + 232 + ... + 302) = ?