A certain musical scale has has 13 notes, each having a different frequency, measured in cycles per second. In the scale, the notes are ordered by increasing frequency, and the highest frequency is twice the lowest. For each of the 12 lower frequencies, the ratio of a frequency to the next higher frequency is a fixed constant. If the lowest frequency is 110 cycles per second, then the frequency of the 7th note in the scale is how many cycles per second?	Choose the correct option:  A) 110 * sqrt 2  B) 110 * sqrt (2^7)  C) 110 * sqrt (2^12)  D) 110 * the twelfth root of (2^7)  E) 110 * the seventh root of (2^12)
Let the constant be k.   F1 = 110   F2 = 110k   F3 = 110 k * k = 110 * k^2   F13= 110 * k^12   we know F13 = 2 *F1 = 2 * 1= 
<gadget id="calculator">2 * 1</gadget>
<output>2</output>
2 * 110= 
<gadget id="calculator">2 * 110</gadget>
<output>220</output>
220   220/110= k^12   k = twelfth root of 2   for F7...   F7 = 110 * k^6 ( as we wrote for F2 and F3)   F7 = 110 * (twelfth root of 2) ^ 6   F7 = 110 * sqrt (2)   The answer is 110 * sqrt 2.
<result>A</result>
A certain musical scale has has 13 notes, each having a different frequency, measured in cycles per second. In the scale, the notes are ordered by increasing frequency, and the highest frequency is twice the lowest. For each of the 12 lower frequencies, the ratio of a frequency to the next higher frequency is a fixed constant. If the lowest frequency is 110 cycles per second, then the frequency of the 7th note in the scale is how many cycles per second?