If six boys sit in a row, then what is the probability that three particular boys are always together is?	Choose one:
A) 1/5 B) 1/4 C) 1/3 D) 1/7 E) 2/5
Six boys can be arranged in a row in 6! ways.   Treat the three boys to sit together as one unit then there 4 boys and they can be arranged in 4! ways.   Again 3 boys can be arranged among them selves in 3! ways.   Favorable outcomes = 3!4!   Required probability = 3!4!/6! = 1/5   1/5
<result>A</result>
If six boys sit in a row, then what is the probability that three particular boys are always together is?