Two numbers when divided by a divisor leave remainders of 238 and 362 respectively. The remainder obtained when the sum of the numbers is divided by the same divisor is 68. Find the divisor.  Select.
A) 276	B) 552	C) 414	D) 1104	E) 2202
Let x be the divisor.   N1 = xa + 238   N2 = xb + 362   N1 + N2 = x(a+b) + 600 = xc + 68   x(c-a-b) = 532 but we know that x&gt;362, thus (c-a-b) must equal 1.   The answer is 552.
<result>B</result>
Two numbers when divided by a divisor leave remainders of 238 and 362 respectively. The remainder obtained when the sum of the numbers is divided by the same divisor is 68. Find the divisor.