Find the greatest number of four digits which is perfectly divisible by 3 and when divided by 5, 7 and 9 leaves a remainder 3 in each case.
Select the correct option:
A) 1128
B) 1659
C) 2687
D) 1667
E) 1891
LCM of 3, 5, 7, 9 = 315. Greatest number of four digits which is divisible by 315 is 9765. The required number = 9765 + 3= 
<gadget id="calculator">9765 + 3</gadget>
<output>9_768</output>
9768. Ask doubt with Question Id: 1658 13) Find greatest number of four digits which when increased by 3568 is exactly divisible by 6, 8, 12, 20. a) 9992 b) 9785 c) 9840 d) None Explanation: Greatest number of 4 digits= 9999. 9999 + 3568 = 13567. LCM of 6, 8, 12 and 20 is 120.   ∴ Required number of 4 digits = 9999 – 7 = 9992 i.e. 9992 is the number to which if 3568 is added, then it is exactly divisible by 6, 8, 12, 20. Ask doubt with Question Id: 1659   Answer:1659
<result>B</result>
Find the greatest number of four digits which is perfectly divisible by 3 and when divided by 5, 7 and 9 leaves a remainder 3 in each case.