The sum of the squares of two consecutive positive integers exceeds their product by 91. Find the integers?
Choose the correct choice from the following choices:  A) 9, 10  B) 10, 11  C) 11, 12  D) 12, 13  E) None of these
Let the two consecutive positive integers be x and x + 1   x2 + (x + 1)2 - x(x + 1) = 91   x2 + x - 90 = 0   (x + 10)(x - 9) = 0 =&gt; x = -10 or 9.   As x is positive x = 9   Hence the two consecutive positive integers are 9 and 10.   9, 10NSWER:9, 10
<result>A</result>
The sum of the squares of two consecutive positive integers exceeds their product by 91. Find the integers?