If n is a natural number, then (6n^2 + 6n) is always divisible by?  Choose the most appropriate option: A) 6 only B) Both 6 and 12 C) 12 only D) 6 or 12 E) None
6n^2 + 6n = 6n(n + 1)   n(n + 1) is always even when n is a natural number   Hence 6n^2 + 6n is always divisible by 6 and 12   Both 6 and 12)
<result>B</result>
If n is a natural number, then (6n^2 + 6n) is always divisible by?