If 9 is a factor of 2k, then which of the following may not be an integer?	Choose the correct answer:	A) 6k/54 + 2k/3	B) (4k-18)/9	C) (2k+27)/9	D) (81-4k^2)/81	E) (2k-3)/3
I got the right answer A after plugging in 18 for k.   While going through Kaplan's explanation, I couldn't understand the part about choice A.   "6k/54 + 2k/3 = 3/6 * 2k/9 + 2k/3.   Since 9 is a factor of 2k, 3 is also factor of 2k. So 2k/3 is an integer, as is 2k/9. But 3/6 = 1/2, so if 2k/9 is not even, the expression 3/6 * 2k/9 will not be even."   But, isn't 2k/9 always even? 9 is a factor of 2k, which means that we could have 2(9), 2(2)(9), 2(3)(9), and so forth. The 9 in the denominator cancels out the 9 in the numerator. So we are left with 2 * something. So 2k/9 is even.6k/54 + 2k/3
<result>A</result>
If 9 is a factor of 2k, then which of the following may not be an integer?