When a random experiment is conducted, the probability that event A occurs is 1/3. If the random experiment is conducted 4 independent times, what is the probability that event A occurs exactly twice?	Pick one
A) 8/27	B) 10/31	C) 12/37	D) 14/41	E) 16/49
One case is: 1/3*1/3*2/3*2/3=4/81   The total number of possible cases is 4C2 = 6   P(event 8/27 occurs exactly twice) = 6*(4/81) = 8/27   The answer is 8/27.
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When a random experiment is conducted, the probability that event A occurs is 1/3. If the random experiment is conducted 4 independent times, what is the probability that event A occurs exactly twice?