What is the probability that a 4-person committee chosen at random from a group consisting of 6 men, 7 women, and 5 children contains at least 1 woman? Choose the correct choice from the following choices:	A) 11/102	B) 77/204	C) 77/102	D) 91/102	E) 31/34
Total Members = 6+7+5= 
<gadget id="calculator">6+7+5</gadget>
<output>18</output>
18   Total ways of making 4 person committee= 18C4 = 3060   Total Members without women = 6+5= 
<gadget id="calculator">6+5</gadget>
<output>11</output>
11   Total ways of choosing e person committee without any women= (6+5)C4 = 330   favorable probability = 1- (330/3060) = 1- (11/102) = 91/102   Answer: option 91/102
<result>D</result>
What is the probability that a 4-person committee chosen at random from a group consisting of 6 men, 7 women, and 5 children contains at least 1 woman?