x, a, z, and b are single digit positive integers. x = 1/3a. z = ¼3b. (10a + b) – (10x + z) could NOT equal
Answers.
A) 31 B) 32 C) 46 D) 64 E) 68
a=3x , b =3z therefore(3x.10+3z) - (10x +z) = (3-1) (10x+z) =2.(10x+Z)   number should be divisible by 2   31
<result>A</result>
x, a, z, and b are single digit positive integers. x = 1/3a. z = ¼3b. (10a + b) – (10x + z) could NOT equal