Two numbers when divided by a divisor leave remainders of 228 and 352 respectively. The remainder obtained when the sum of the numbers is divided by the same divisor is 68. Find the divisor.	Choose the correct choice from the following:
A) 512
B) 573
C) 634
D) 685
E) 736
Let x be the divisor.   N1 = xa + 228   N2 = xb + 352   N1 + N2 = x(a+b) + 580 = xc + 68   x(c-a-b) = 512 but we know that x &gt; 352, thus (c-a-b) must equal 1.   The answer is 512.
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Two numbers when divided by a divisor leave remainders of 228 and 352 respectively. The remainder obtained when the sum of the numbers is divided by the same divisor is 68. Find the divisor.