What is the sum of all possible 3-digit numbers that can be constructed using the digits 1, 3, and 4 if each digit can be used only once in each number?
Pick.
A) 1443	B) 1554	C) 1665	D) 1776	E) 1887
There are 6 possible arrangements of the three numbers.   Then each number will be in the hundreds, tens, and ones place two times each.   The sum is 2(111) + 2(333) + 2(444) = 1776   The answer is 1776.
<result>D</result>
What is the sum of all possible 3-digit numbers that can be constructed using the digits 1, 3, and 4 if each digit can be used only once in each number?