If A speaks the truth 60% of the times, B speaks the truth 50% of the times. What is the probability that at least one will tell the truth
Pick one.
A) 0.8  B) 0.9  C) 1.0  D) 1.2  E) 1.3
probability of 0.8 speaks truth p(0.8)=6/10;false=4/10   probability of B speaks truth p(B)=5/10;false=5/10.For given qtn   0.8ns=1-(neither of them tell truth).Because 0.8 &amp; B are independent events   =1-[(4/10)*(5/10)]=4/5= 
<gadget id="calculator">4/5</gadget>
<output>4/5 = around 0.8</output>
0.8   0.8NSWER:0.8
<result>A</result>
If A speaks the truth 60% of the times, B speaks the truth 50% of the times. What is the probability that at least one will tell the truth