How many no.'s with 3 different digits, 2, 3, 5, 6, 7 and 9, which are divisible by 5?	Choose the correct option
A) 18	B) 20	C) 25	D) 28	E) 31
Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.   The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.   The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.   Required number of numbers = (1 x 5 x 4) = 20   20
<result>B</result>
How many no.'s with 3 different digits, 2, 3, 5, 6, 7 and 9, which are divisible by 5?