In how many ways can 5 boys and 3 girls sit around a table in such a way that no two girls sit together?
Choose the correct choice from the following choices
A) 1000
B) 1400
C) 1440
D) 1800
E) 1900
The 5 boys can be seated around a table in 4! Ways. In between them there are 5 places.   The 3 girls can be placed in the 5 places in 5P3 ways.   Therefore, Required number of ways= 4!* 5P3   =24*60= 
<gadget id="calculator">24*60</gadget>
<output>1_440</output>
1440   ANSWER:1440
<result>C</result>
In how many ways can 5 boys and 3 girls sit around a table in such a way that no two girls sit together?