What is the remainder when 7^498 is divided by 5 ?  Choose the correct answer:
A) 4	B) 3	C) 2	D) 1	E) 0
7^0 = 1   7^1 = 7   7^2 = 49   7^3 = 343   7^4 = ...1   7^5 = ....7   7^6 = ......9   and so on in a recurring pattern of 1,7,9,3,1,7,9,3....   498/4 = 124 (with a remainder 2) so the last number is a 9.   so when 7^498 is divided by 5 the remainder is 4, 4NS = 4
<result>A</result>
What is the remainder when 7^498 is divided by 5 ?