A number is selected at random from the first 40 natural numbers. What is the probability that the number is a multiple of either 2 or 21? Choose the correct choice:
A) 21/40
B) 2/5
C) 7/15
D) 4/15
E) 11/30
Number of Multiples of 2 from 1 through 40 = 40/2= 
<gadget id="calculator">40/2</gadget>
<output>20</output>
20   Number of Multiples of 21 from 1 through 40= 40/21 = 1   Number of Multiples of 2 and 21 both from 1 through 40 = Number of Multiples of 21*2(=42) = 0   Total favourable cases = 20 + 1 - 0= 
<gadget id="calculator">20 + 1 - 0</gadget>
<output>21</output>
21   Probability= 21 / 40   21/40nswer: option 21/40
<result>A</result>
A number is selected at random from the first 40 natural numbers. What is the probability that the number is a multiple of either 2 or 21?