Anne and Beth will participate in a sack race (In a sack race, people hop to reach the finish line). In the time that Anne takes 3 hops, Beth takes 4 hops but the distance covered by Anne in 4 hops is equal to distance covered by Beth in 5 hops. What is the ratio of Anne’s speed: Beth’s speed? Choose the correct choice.
A) 3 : 5	B) 12 : 20	C) 15 : 16	D) 1 : 1	E) 5 : 3
The distance covered by Anne in 4 hops is equal to distance covered by Beth in 5 hops --&gt; 4*(distance of Ann's 1 hop) = 5*(distance of Beth's 1 hop).   The time that Anne takes 3 hops, Beth takes 4 hops --&gt; time for Ann to take 12 hops --&gt; 3*(time for Ann's 1 hop) = 4*(time for Beth's 1 hop).   Divide one by another:   4/3*(distance of Ann's 1 hop)/(time for Ann's 1 hop) = 5/4*(distance of Beth's 1 hop)/(time for Beth's 1 hop);   4/3*(Anne's speed) = 5/4*(Beth's speed);   4/3*(Anne's speed)/(Beth's speed) = 15/16.   Answer: 15 : 16.
<result>C</result>
Anne and Beth will participate in a sack race (In a sack race, people hop to reach the finish line). In the time that Anne takes 3 hops, Beth takes 4 hops but the distance covered by Anne in 4 hops is equal to distance covered by Beth in 5 hops. What is the ratio of Anne’s speed: Beth’s speed?