If Log2 x - 5 Log x + 6 = 0, then what would the value / values of x be?	Answers.
A) 5.3296
B) 6.3296
C) 7.3296
D) 8.3296
E) 9.3296
log(2x)-5log(x)+6=0 (given)   log(2x)-log(x^5)=-6   log(2x/x^5)=-6 [since log(a)-log(b)=log(a/b)]   apply anti log   2/(x^4)=e^-6   2/(x^4)=2.4788*10^-3   x^4=806.85   x=5.3296   5.3296NSWER:5.3296
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If Log2 x - 5 Log x + 6 = 0, then what would the value / values of x be?