In three years, Janice will be three times as old as her daughter. Six years ago, her age was her daughter’s age squared. How old is Janice? Select
A) 18  B) 36  C) 40  D) 42  E) 45
Let Jane's age be J and daughters' age be D...   Given J   + 3= 
<gadget id="calculator">  + 3</gadget>
<output>3</output>
3(D + 3 )=&gt; J - 6 = 3D -&gt; Eq1.   Given J-6 = (D-6)^2 --&gt; Eq 2..   sub J-6 value in eq 2... 3D = D^2 - 12D + 36.   0 = D^2 - 15D + 36 =&gt; D = 12 or D = 3.   When D = 12 we get from eq 1... J+3 = 45 =&gt; J =42..   When D = 3 ..we get from eq 1.. J+3 = 18 =&gt; J = 15...   In the above options only 42 exits..   Answer: option 42 is correct answer..
<result>D</result>
In three years, Janice will be three times as old as her daughter. Six years ago, her age was her daughter’s age squared. How old is Janice?