A meeting has to be conducted with 5 managers. Find the number of ways in which the managers be selected from among 9 managers, if 2 managers will not attend the meeting together? Pick:	A) 35	B) 91	C) 120	D) 126	E) 150
we can either choose all 5 people from 7 manager who have no problems or choose 4 from the 7 and 1 from the 2 managers who have a problem sitting together   so 7C5 + (7C4 * 2C1)   this is 21 + 70   91 ANS:91
<result>B</result>
A meeting has to be conducted with 5 managers. Find the number of ways in which the managers be selected from among 9 managers, if 2 managers will not attend the meeting together?