Machine–A produces 40% of the total output and Machine-B produces 60% of the total output. An average of nine units out of a thousand goods manufactured by Machine-A and one unit of 100 units produced by Machine-B prove to be defective. What is the probability that a unit chosen at random from the total daily output of the factory is defective?
Pick one
A) a. 0.96 B) b. 0.096 C) c. 0.0096 D) d. 0.00096 E) e. 0.000096
Let total Production be 10000 units....   A produces 4000 units and 36 units are defective   B produces 6000 units and 60 units are defective   So, Out of total 10,000 units 96 units are defective...   So the required probability = 96/10000= 
<gadget id="calculator">96/10000</gadget>
<output>6/625 = around 0.0096</output>
&gt; 0.0096   Answer will be (c. 0.0096)
<result>C</result>
Machine–A produces 40% of the total output and Machine-B produces 60% of the total output. An average of nine units out of a thousand goods manufactured by Machine-A and one unit of 100 units produced by Machine-B prove to be defective. What is the probability that a unit chosen at random from the total daily output of the factory is defective?