If the radius of a sphere is increased by 50%, find the increase percent in
volume and the increase percent in the surface area.
Sol.  Options:
A) 100%	B) 120%	C) 90%	D) 115%	E) 125%
Let original radius = R. Then, new radius = (150/100)R=(3R/2)   Original volume = (4/3)R3, New volume = (4/3)(3R/2)3 =(9R3/2)   Increase % in volume=((19/6)R3)*(3/4R3)*100))% = 237.5%   Original surface area =4R2. New surface area = 4(3R/2)2=9R2   Increase % in surface area =(5R2/4R2) * 100) % = 125%.   ANSW125%R 125% 125%
<result>E</result>
If the radius of a sphere is increased by 50%, find the increase percent in
volume and the increase percent in the surface area.
Sol.