How many different 7 digit numbers can be formed from the number 3589463 by re-arranging its digits so that the odd digits occupy even position	Choose the correct choice.
A) 1  B) 5  C) 9  D) 72  E) 34
There are 4 odd numbers which have to be placed at 4 even places =4!/2!=12 ways   There are 3 even numbers which have to be placed at 3 odd places. So 3! = 6 ways   so total number of ways of arranging all these numbers are  12 * 6= 
<gadget id="calculator"> 12 * 6</gadget>
<output>72</output>
72 ways   Answer:72
<result>D</result>
How many different 7 digit numbers can be formed from the number 3589463 by re-arranging its digits so that the odd digits occupy even position