What was the day of the week on 4th April, 2006? Pick one.
A) Saturday  B) Thursday  C) Monday  D) Friday  E) Tuesday
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)   Odd days in 1600 years = 0   Odd days in 400 years = 0   5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days   Jan. Feb. March April   (31 + 28 + 31 + 4)= 
<gadget id="calculator">(31 + 28 + 31 + 4)</gadget>
<output>94</output>
94 days   94 days= (13 weeks + 3 day) 1 odd day.   Total number of odd days = (0 + 0 + 6 + 3)= 
<gadget id="calculator">(0 + 0 + 6 + 3)</gadget>
<output>9</output>
9 0 odd day.   Given day is Tuesday.   Answer: Option Tuesday
<result>E</result>
What was the day of the week on 4th April, 2006?