How many different arrangements of letters are possible if three letters are chosen from the letters A through F and the letters E and A must be among the letters selected?  Select.
A) 24  B) 28  C) 32  D) 36  E) 40
Besides A and E, there are 4 letters and we can choose one of them.   4C1 = 4   Three letters can be arranged in 3! ways.   The number of arrangements is 4*3! = 24   The answer is 24.
<result>A</result>
How many different arrangements of letters are possible if three letters are chosen from the letters A through F and the letters E and A must be among the letters selected?