If the operation # is defined for all a and b by the equation a@b =(a*b)-1, then 2#(3#1) = Select the correct option
A) 4 B) 2 C) 3 D) 1 E) 5
work within the parenthesis first so solve (3#1) first   (3#1)=(3*1)-1= 
<gadget id="calculator">(3*1)-1</gadget>
<output>2</output>
2   now take 2 plug back into equation and solve the rest   (2#2)=(2*2)-1= 
<gadget id="calculator">(2*2)-1</gadget>
<output>3</output>
3   so 3 is the answer....this question is merely testing order of operations   remember PEMDAS   Option 3 is answer
<result>C</result>
If the operation # is defined for all a and b by the equation a@b =(a*b)-1, then 2#(3#1) =