What is the greater of the two numbers whose product is 1280, given that the sum of the two numbers exceeds their difference by 32? Pick.
A) A)90 B) B)100 C) C)110 D) D)70 E) 80
Let the greater and the smaller number be g and s respectively.   g*s = 1288   g + s exceeds g - s by 32 i.e., g + s - (g - s) = 32   i.e., 2s = 32 =&gt; s = 16.   g = 1280/s = 80.   ANSW80R:80
<result>E</result>
What is the greater of the two numbers whose product is 1280, given that the sum of the two numbers exceeds their difference by 32?