The bacteria have the probability of split into 3 and probability to die is 1/3rd of the total bacteria. Let the probability is P. Some of them survived with probability 1/5.Then which among the following relation is true?	Choose the correct choice from the following options.
A) P=1/3+1/5*3 B) P=1/3+1/5*4 C) P=1/3+1/5*2 D) P=1/8*(1/8-3) E) P=1/5*(1/4-3)
The bacteria have the probability of split into 3 and probability to die is 1/3rd of the total bacteria. Let the probability is P. Some of them survived with probability 1/5.Then which among the following relation is true?   a)P=1/3+1/5*3 b)P=1/5*(1/8-3)   P=1/3+1/5*3 is true.   P=1/3+1/5*3NSWER:P=1/3+1/5*3
<result>A</result>
The bacteria have the probability of split into 3 and probability to die is 1/3rd of the total bacteria. Let the probability is P. Some of them survived with probability 1/5.Then which among the following relation is true?