In March, Kurt ran an average of 1.5 miles an hour. If by June he had increased his pace by 10 seconds per mile, then which of the following expresses the number of hours it would take Kurt to complete one mile in June?
Choose the correct choice:
A) 3590/60^2 B) 2410/60^2 C) 2390/60^2 D) 3586/60 E) 60^2/3590
1500 in 3600 sec   1000 in x sec   x = 2400   In june = 2400-10= 
<gadget id="calculator">2400-10</gadget>
<output>2_390</output>
2390   so 2390 / 60 * 60   2390/60^2   ANSWER:2390/60^2
<result>C</result>
In March, Kurt ran an average of 1.5 miles an hour. If by June he had increased his pace by 10 seconds per mile, then which of the following expresses the number of hours it would take Kurt to complete one mile in June?