The present ages of three persons are in the proportion of 4 : 7 : 9. Eight years ago, the sum of their ages was 116. Find their present ages.	Choose the correct choice from the following options:
A) 20,35,45	B) 28,49,63	C) 16,28,36	D) 16,28,46	E) None of these
Let the present ages of three persons be 4K,7K and 9K respectively.   (4K - 8) + (7K - 8) + (9K - 8) = 116   20K = 140   K = 7   Therefore, then present ages are 28,49,63.   ANSWER:28,49,63
<result>B</result>
The present ages of three persons are in the proportion of 4 : 7 : 9. Eight years ago, the sum of their ages was 116. Find their present ages.