How many 4 digit numbers can be formed with the digits 0, 1, 2, 3, 4, 5, 6, 7 and 6?  Select
A) a. 220	B) b. 249	C) c. 432	D) d. 216	E) e. 288
Taking Question with it's same language as given   To make number divisible by 5, the unit digit should be either 0 or 5 only   Case 1: If unit digit is fixed as zero   With two6s The choice to fill the remaining three digits = 3C2 x 5 = 15   With all remaining 3 digits different, The choice to fill the remaining three digits = 6 x 5 x 4= 120   Total Such cases = 120+15= 
<gadget id="calculator">120+15</gadget>
<output>135</output>
135   Case 2: If unit digit is fixed as Five   With two6s and one0The choice to fill the remaining three digits= 2 [6605 or 6065]   With two6s and without0The choice to fill the remaining three digits = 3C2 x 4 = 12   With all remaining 3 digits different, and one0The choice to fill the remaining three digits = 2 (ways to place zero) x 5 x 4= 40   With all remaining 3 digits different, and without0The choice to fill the remaining three digits = 3 x 5 x 4= 60   Total Such cases = 2+12+40+60= 
<gadget id="calculator">2+12+40+60</gadget>
<output>114</output>
114   Total numbers= 135+114 = 288   ANSWER OPTION d. 216
<result>D</result>
How many 4 digit numbers can be formed with the digits 0, 1, 2, 3, 4, 5, 6, 7 and 6?