If X is to be chosen at random from the set {5,7,4,3,8} and Y is to be chosen at random from the set {6,3,4,2}, what is the probability that XY will be odd?	Choose one.
A) 12 B) 8 C) 11 D) 6 E) 1
Method-1   xy will be odd when   1) x is odd and y is even, Probability of x odd is (3/5) and Probability of y even is (3/4), so Probability of Case(1) = (3/5)*(3/4) = (15/20)=(3/4)   2) x is even and y is odd, Probability of x even is (2/5) and Probability of y odd is (1/4), so Probability of Case(2) = (2/5)*(1/4) = (2/20)   3) x is odd and y is odd, Probability of x odd is (3/5) and Probability of y odd is (1/4), so Probability of Case(1) = (3/5)*(1/4) = (3/20)   Total Favorable Probability = (15/20)+(2/20)+(3/20) = (20/20)= 
<gadget id="calculator">(20/20)</gadget>
<output>1</output>
1   Answer: option 1
<result>E</result>
If X is to be chosen at random from the set {5,7,4,3,8} and Y is to be chosen at random from the set {6,3,4,2}, what is the probability that XY will be odd?