The probability that a brand A widget is defective is x, the probability that a brand B widget is defective is 0.06, and the probability that a brand C widget is defective is 0.08. There are 40 brand A widgets, 35 brand B widgets, 25 brand C widgets, and nothing else in a container. If a widget is selected at random from the container, the probability that the widget selected is defective is 0.053. What is the value of x?
Choose the correct choice from the following:  A) 0.03  B) 0.04  C) 0.048  D) 0.05  E) 0.12
Probability of Brand A defective is x   Probability of Brand B defective is 0.06 which 6/100. Which tells you there are 2 defective piece in a lot of 33, for 35 lot it is approx - 2.12   Probability of Brand C defective is 0.08 which 8/100. Which tells you there are 2 defective piece in a lot of 25   Total = 40 + 25 + 25 = 100   Probability of having defective piece in a lot of 100 ( All brands ) = 0.053   Hence 5.3 defective piece out 100 lot.   So 40x + 2.12 + 2 = 5.3   x = 0.03   0.03NSWER :Opt 0.03.
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The probability that a brand A widget is defective is x, the probability that a brand B widget is defective is 0.06, and the probability that a brand C widget is defective is 0.08. There are 40 brand A widgets, 35 brand B widgets, 25 brand C widgets, and nothing else in a container. If a widget is selected at random from the container, the probability that the widget selected is defective is 0.053. What is the value of x?