If x,y ,and z are positive real numbers such that x+y-z = 62, y-z+x =82 , and z-x+y = 100, then find the x+y+z value?	Choices:
A) 80
B) 91
C) 62
D) 74
E) 82
x+y-z = 62, ------1)   y-z+x =82 , ------2)   z-x+y = 100------3)   from (1)&amp;(2)   2z=20   z=10   from (2)&amp;(3)   2y = 182   y=91   then x=62-81= -19   x+y+z = 82   correct option is 82
<result>E</result>
If x,y ,and z are positive real numbers such that x+y-z = 62, y-z+x =82 , and z-x+y = 100, then find the x+y+z value?