If the average of 8x and 8y is greater than 120, and x is twice y, what is the least integer value of x ?	Select the correct option.
A) 20
B) 25
C) 30
D) 32
E) 42
Substitution can be used in the following way:   Always start with the equation: x = 2y. It is more straight forward to manage as compared to the inequality.   Substitute y = x/2, not the other way because you need to find the minimum value of x. So you can get rid of y.   Now go on to the inequality. So 8y = 8x/2 = 4x   Now average of 8x and 4x is greater than 120. Average of 8x and 4x is 6x. So,   6x &gt; 120   x &gt; 20   20nswer : 208 /2= 
<gadget id="calculator">8 /2</gadget>
<output>4</output>
4x   Now average of 8x and 4x is greater than 120. Average of 8x and 4x is 6x. So,   6x &gt; 120   x &gt; 20   20nswer : 20
<result>A</result>
If the average of 8x and 8y is greater than 120, and x is twice y, what is the least integer value of x ?