If m > 1 and n = 2^(m+3), then 4^m =
Answers:
A) 16n^2	B) 4n^2	C) 8n^2	D) n^2/64	E) n^2/16
n = 2^(m+3) = 2^m*8   2^m = n/8   4^m = (2^m)^2 = (n/8)^2 = n^2/64   The answer is n^2/64.
<result>D</result>
If m > 1 and n = 2^(m+3), then 4^m =