Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 22 boys and 38 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad?	Choose the correct choice from the following answers
A) 2  B) 4  C) 6  D) 8  E) 10
Venn diagrams are useful for multiple values of a single variable e.g. State of mind - happy/sad/neither. When you have two or more variables such as here where you have gender - boy/girl too, it becomes unwieldy. In this case, either use the table or logic.   Table method is shown above; here is how you will use logic:   There are 6 happy boys.   There are 4 sad girls but total 10 sad children. So rest 6 sad children must be sad boys.   We have 6 happy boys and 6 sad boys. Total we have 22 boys. So  22 - 6 - 6= 
<gadget id="calculator"> 22 - 6 - 6</gadget>
<output>10</output>
10 boys must be neither happy nor sad.   Answer (10)
<result>E</result>
Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 22 boys and 38 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad?