In a box, there are 10 red, 6 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither red nor blue?  Pick: A) 4/51 B) 10/21 C) 7/12 D) 6/21 E) 13/17
Total number of balls = 10+6+5= 
<gadget id="calculator">10+6+5</gadget>
<output>21</output>
21   E= event that the ball drawn is neither red nor blue   = event that the ball drawn is blue   n(E) = 6   P(E) = 6/21   Answer is 6/21
<result>D</result>
In a box, there are 10 red, 6 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither red nor blue?