Three unbiased coins are tossed. What is the probability of getting at most two heads?
Choose the correct option:
A) 3/4
B) 1/4
C) 3/8
D) 7/8
E) None of these
Explanation:   Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}   Let E = event of getting at most two heads.   Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.   P(E) =	n(E)	/ n(S) =7/8.   ANSWER IS 7/8
<result>D</result>
Three unbiased coins are tossed. What is the probability of getting at most two heads?