A circular road runs around a circular garden. If the sum of the circumferences of the inner and outer circles is 88 metres and the radius of the inner circle is one-third of the outer circle, then the width of the road is :  Choose the correct option
A) 4 metres	B) 5 metres	C) 7 metres	D) 6 metres	E) 8 metres
let radius of inner circle=r1   radius of outer circle=r2   Also r1=1/3*r2   3*r1=r2   circumference of inner circle=2*pi*r1   circumference of outer circle=2*pi*r2   2*  * 1= 
<gadget id="calculator">2*  * 1</gadget>
<output>2</output>
2*pi*r2=6*pi*r1 (since r2=3*r1)   2*pi*r1 + 6*pi*r1 =88 (as per question)   r1=3.5 m   r2=3*3.5= 
<gadget id="calculator">3*3.5</gadget>
<output>10.5</output>
10.5 m   width of road=10.5 - 3.5= 
<gadget id="calculator">10.5 - 3.5</gadget>
<output>7</output>
7 m Ans.   ANSWER:7 metres
<result>C</result>
A circular road runs around a circular garden. If the sum of the circumferences of the inner and outer circles is 88 metres and the radius of the inner circle is one-third of the outer circle, then the width of the road is :