If x, y, and z are positive integers and 3x = 7y = 5z, then the least possible value of x + y + z is	Choose the correct choice from the following choices.
A) 15
B) 25
C) 71
D) 35
E) 45
given 3x=7y=5z   x+y+z in terms of x   = x+(3x/7)+(3x/5) = 71x/35   now checking with each of the answers and see which value gives a minimum integer value.   A x = 35/71*15 , not an integer   B,D,E can be ruled out similarly.   71 is minimum value as x = 71*35/71= 
<gadget id="calculator">71*35/71</gadget>
<output>35</output>
35   Answer is 71
<result>C</result>
If x, y, and z are positive integers and 3x = 7y = 5z, then the least possible value of x + y + z is