There are 5 orators A, B, C, D, E. In how many ways can the arrangements be made so that A always comes before B and B always comes before C.  Choose the most appropriate option
A) 5! / 3!  B) 8! / 6!  C) 5! x 3!  D) 8! / (5! x 3!)  E) 8! / (5! x 4!)
Select any three places for A, B and C. They need no arrangement amongst themselves as A would always come before B and B would always come before C.   The remaining 2 people have to be arranged in 2 places.   Thus, 5C3 x 2! = 5! / 3!   5! / 3!NSWER:5! / 3!
<result>A</result>
There are 5 orators A, B, C, D, E. In how many ways can the arrangements be made so that A always comes before B and B always comes before C.