Three dice are thrown together, Find the probability of getting a total of atmost 6?
Pick.
A) 1/3
B) 1/8
C) 3/13
D) 2/25
E) 5/54
Three different dice are thrown at the same time.   Therefore, total number of possible outcomes will be 63 = (6 × 6 × 6) = 216.   Number of events of getting a total of atmost 6 = 20   i.e. (1, 1, 1), (1, 1, 2), (1, 2, 1), (2, 1, 1), (1, 1, 3), (1, 3, 1), (3, 1, 1), (2, 2, 1), (1, 2, 2), (1, 1, 4), (1, 4, 1), (4, 1, 1), (1, 2, 3), (1, 3, 2), (2, 1, 3), (2, 3, 1), (3, 1, 2), (3, 2, 1) and (2, 2, 2).   Therefore, probability of getting a total of atmost 6   P(5/54) = Number of favorable outcomes/Total number of possible outcome   = 20/216   = 5/54
<result>E</result>
Three dice are thrown together, Find the probability of getting a total of atmost 6?