Sequence P is defined by pn=pn−1+3, p1=11, sequence Q is defined as qn=qn−1–4, q3=103. If pk>qk+2, what is the smallest value k can take?  Select the correct option.
A) 6  B) 9  C) 11  D) 14  E) 15
Set P = {11, 14, 17,.....}   Set Q = {110, 107, 103,....}   For Arithmetic progression a(n)=a(1)+(n−1)d   Started with C) 11 does not satisfy pk &gt; qk+2   and D) 14, pk = qk+2   So Answer is 15
<result>E</result>
Sequence P is defined by pn=pn−1+3, p1=11, sequence Q is defined as qn=qn−1–4, q3=103. If pk>qk+2, what is the smallest value k can take?