Two trains, each 100 m long, moving in opposite directions, cross other in 10 sec. If one is moving twice as fast the other, then the speed of the faster train is?  Choices:  A) 22  B) 98  C) 48  D) 88  E) 12
Let the speed of the slower train be x m/sec.   Then, speed of the train = 2x m/sec.   Relative speed = ( x + 2x) = 3x m/sec.   (100 + 100)/10 = 3x =&gt; x = 20/3.   So, speed of the faster train = 40/3 = 40/3 * 18/5= 
<gadget id="calculator">40/3 * 18/5</gadget>
<output>48</output>
48 km/hr.   Answer:48
<result>C</result>
Two trains, each 100 m long, moving in opposite directions, cross other in 10 sec. If one is moving twice as fast the other, then the speed of the faster train is?