In a box there are 5 red balls and 6 blue balls. What is the probability of drawing at least one red ball when drawing 3 consecutive balls randomly?
Choose the correct option
A) 201/202 B) 164/165 C) 256/259 D) 98/103 E) 115/217
P(at least one red) = 1 - P(no red, so 3 blue) = 1- 3/11*2/10*1/9 = 164/165.   Answer is 164/165
<result>B</result>
In a box there are 5 red balls and 6 blue balls. What is the probability of drawing at least one red ball when drawing 3 consecutive balls randomly?