If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 4, respectively, what is the probability that b/a will not be an integer?
Choices:	A) 1/6	B) 1/4	C) 1/3	D) 1/2	E) 2/3
a is from the following set {1,2,3,4}   b is from the following set {4,6,8}   Total number of ways of choosing 2 integers, one from each set is = 4* 3= 
<gadget id="calculator">4* 3</gadget>
<output>12</output>
12 ways   Now the number of possibilities where b/a is not an integer is for the following outcomes   {b,a}=&gt; {4,3},{6,4},{8,3} = 3 ways   Hence probability is = 3/12 = 1/4   ans is 1/4
<result>B</result>
If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 4, respectively, what is the probability that b/a will not be an integer?