1,345
1,354
1,435
.....
....
+5,431
The addition problem above shows four of the 24 different integers that can be formed by using each of the digits 1,3,4,5 exactly once in each integer. What is the sum of these 24 integers?	Answers:	A) 78,690	B) 82,240	C) 86,658	D) 90,240	E) 94,426
In each of the units, tens, hundreds, and thousands place, each digit will appear 6 times.   Then the sum equals 6(1111)+6(3333)+6(4444)+6(5555) = 86,658   The answer is 86,658.
<result>C</result>
1,345
1,354
1,435
.....
....
+5,431
The addition problem above shows four of the 24 different integers that can be formed by using each of the digits 1,3,4,5 exactly once in each integer. What is the sum of these 24 integers?