Jack, Jill, and Sandy each have one try to make a basket from half court. If their individual probabilities of making the basket are 1/6, 1/7, and 1/8 respectively, what is the probability that Jack and Jill will make a basket but Sandy will miss?  Choose one:  A) 1/8  B) 1/16  C) 1/48  D) 1/96  E) 1/168
The probability that Jack and Jill will make a basket but Sandy will miss is 1/6*1/7*7/8=1/48.   The answer is 1/48.
<result>C</result>
Jack, Jill, and Sandy each have one try to make a basket from half court. If their individual probabilities of making the basket are 1/6, 1/7, and 1/8 respectively, what is the probability that Jack and Jill will make a basket but Sandy will miss?