A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?  Choose the most appropriate option
A) 10/21 B) 10/29 C) 10/20 D) 10/22 E) 10/24
Explanation:   Total number of balls = (2 + 3 + 2)= 
<gadget id="calculator">(2 + 3 + 2)</gadget>
<output>7</output>
7.   Let S be the sample space.   Then, n(S)= Number of ways of drawing 2 balls out of 7 = = 21   Let E = Event of drawing 2 balls, none of which is blue.   n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls = = 10   Therefore, P(E) = n(E)/n(S) = 10/ 21.   10/21nswer: 10/21) 10/21
<result>A</result>
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?