There are 12 cans in the refrigerator. 7 of them are red and 5 of them are blue. In how many ways we can remove 10 cans so that at least one red and at least one blue cans to remain the refrigerator.	Choose the correct choice from the following answers.
A) 460 B) 490 C) 493 D) 35 E) 445
Ways to pick 2 cans so that at least one red and at least one blue cans to remain the refrigerator =   total ways to pick 2 can out of 12 - ways to pick 2 red out of 7 red - ways to pick 2 blue out of 5 blue   12C2âˆ’7C2âˆ’5C2=66âˆ’21âˆ’10=35   ANSWER:35
<result>D</result>
There are 12 cans in the refrigerator. 7 of them are red and 5 of them are blue. In how many ways we can remove 10 cans so that at least one red and at least one blue cans to remain the refrigerator.