In how many ways, a committee of 5 members can be selected from 8 men and 5 ladies, consisting of 3 men and 2 ladies?
Options: A) 75 B) 152 C) 175 D) 560 E) 612
(3 men out 8) and (2 ladies out of 5) are to be chosen   Required number of ways = (8C3 * 5C2) = 560   Answer is 560
<result>D</result>
In how many ways, a committee of 5 members can be selected from 8 men and 5 ladies, consisting of 3 men and 2 ladies?