In a village of 100 households, 75 have at least one DVD player, 80 have at least one cell phone, and 55 have at least one MP3 player. If x and y are respectively the greatest and lowest possible number of households that have all three of these devices, x – y Answers:
A) 55 B) 45 C) 65 D) 35 E) 25
x= (75+55+80-100-z)/2 for z=0 -&gt;55   y=the same for z=100 -&gt;10   Therefore x-y=45   ANSWER:45
<result>B</result>
In a village of 100 households, 75 have at least one DVD player, 80 have at least one cell phone, and 55 have at least one MP3 player. If x and y are respectively the greatest and lowest possible number of households that have all three of these devices, x – y