What are the maximum value and minimum values of f(x) = |2sin(2x - pi/3) - 5| + 3	Choose the correct choice: A) max10-min6 B) max11-min7 C) max12-min8 D) max13-min9 E) max14-min10
-1 &lt;= sin(2x - pi/3) &lt;= 1 : range of a sine function   -2 &lt;= 2sin(2x - pi/3) &lt;= 2 : mulitply all terms of the double inequality by 2   -2 - 5 &lt;= 2sin(2x - pi/3) - 5 &lt;= 2 - 5 : add -5 to all terms of the inequality.   -7 &lt;= 2sin(2x - pi/3) - 5 &lt;= -3   3 &lt;= |2sin(2x - pi/3) - 5| &lt;= 7 : change the above using absolute value.   3 + 3 &lt;= |2sin(2x - pi/3) - 5| + 3 &lt;= 7 + 3 : add 3 to all terms of the double inequality.   The maximum value of f(x) is equal to 10 and the minimum value of f(x) is equal to 6.   correct answer is max10-min6)max10-min6
<result>A</result>
What are the maximum value and minimum values of f(x) = |2sin(2x - pi/3) - 5| + 3