What is the probability that a 3 person committee chosen at random from a group consisting of 6 men, 7 women, and 5 children contains exactly 1 woman?  Pick one
A) 77/204	B) 77/832	C) 11/77	D) 385/816	E) 22/832
Total possible selections = 3 out of 18 group members = 18C3   Favorable selections = 1 out of 7 women and 2 out of 11 (= 6 men + 5 children) = 7C1 * 11C2   Thus the required probability = 7C1*11C2 / 18C3 = 385/816. Thus 385/816 is the correct answer.
<result>D</result>
What is the probability that a 3 person committee chosen at random from a group consisting of 6 men, 7 women, and 5 children contains exactly 1 woman?