An urn contains g green marbles and b blue marbles. If 3 green marbles and 7 blue marbles are added, and then one marble is selected at random from the urn, what is the probability that a blue marble will be drawn?
Choose one:
A) b/(b+g)
B) (b+5)/(g+3)
C) (b+5)/(b+g+8)
D) (b+5)/(b+g+3)
E) b+7/(b+g+10)
no of fav outcomes i.e. blue MArbles = b+5   Total no of outcomes i.e. total Marbles = (b+7)+(g+3)= b+g+10   probability = (b+7) /(b+g+10)   Answer b+7/(b+g+10)
<result>E</result>
An urn contains g green marbles and b blue marbles. If 3 green marbles and 7 blue marbles are added, and then one marble is selected at random from the urn, what is the probability that a blue marble will be drawn?