A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?
Select the correct option:
A) 60km/hr  B) 80km/hr  C) 100km/hr  D) 120km/hr  E) None of these
Explanation :   let distance between A and B be D km and real speed of the car be S km/hr   First time car takes 90 minutes more and second time car takes 75 minutes more than scheduled time.   So, T1 – T2 = 15/60 = 100   15/60 = [100/s + (D -100)/(3s/4)] – [160/s + (D – 160)/(3s/4)] Solve this D will be cancelled and S comes out to be 80km/hr   Answer –80km/hr
<result>B</result>
A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?