The sum of the first 50 positive even integers is 2,000. What is the sum of the odd integers from 101 to 200, inclusive?  Answers:
A) 5,050	B) 7,500	C) 8,050	D) 15,000	E) 19,600
101+103+.......199   If we remove 100 from each of these it will be sum of 1st 100 odd numbers.   so 101+103+.......199 = 50 * 100 + (1+3+5+7+......)   sum of 1st 100 natural numbers = (100 * 101) / 2= 
<gadget id="calculator">(100 * 101) / 2</gadget>
<output>5_050</output>
5050   Sum of 1st 50 positive even integers= 2000   sum of 1st 100 odd numbers = 5050 - 2000= 
<gadget id="calculator">5050 - 2000</gadget>
<output>3_050</output>
3050   so 101+103+.......199= 50 * 100 + (1+3+5+7+......) = 5000 + 3050= 
<gadget id="calculator">5000 + 3050</gadget>
<output>8_050</output>
8050   8,050 is the answer.
<result>C</result>
The sum of the first 50 positive even integers is 2,000. What is the sum of the odd integers from 101 to 200, inclusive?