A box contains 100 balls, numbered from 1 to 100. If three balls are selected at random and with replacement from the box, what is the probability D that the sum of the three numbers on the balls selected from the box will be odd?
Pick one:
A) 1/4
B) 3/8
C) 1/2
D) 5/8
E) 3/4
The sum of the three numbers on the balls selected from the box to be odd one should select either three odd numbered balls (Odd+Odd+Odd=Odd) or two even numbered balls and one odd numbered ball (Even+Even+Odd=Odd);   P(OOO)=(1/2)^3;   P(EEO)=3*(1/2)^2*1/2=3/8 (you should multiply by 3 as the scenario of two even numbered balls and one odd numbered ball can occur in 3 different ways: EEO, EOE, or OEE);   So finally D=1/8+3/8=1/2.   Answer: 1/2.
<result>C</result>
A box contains 100 balls, numbered from 1 to 100. If three balls are selected at random and with replacement from the box, what is the probability D that the sum of the three numbers on the balls selected from the box will be odd?