Exactly two sides of a certain 10-sided die are red. What is the probability that Kumar rolls the die 2 times and the die lands with a red side up for the first time on the second roll?
Answers
A) 0.16
B) 0.2
C) 0.3
D) 0.32
E) 0.56
Total no. of sides = 10   Sides that are red = 2   Probability that the die lands with red side up = 2/10   Therefore, Probability that the die does not land with red side up = 1 - 2/10 = 8/10   Probability that Kumar rolls the die 2 times and the die lands with a red side up for the first time on the second roll   = (1st roll - non red face) X (2nd roll - red face)   = 8/10 x2/10   = 16/100= 
<gadget id="calculator">16/100</gadget>
<output>4/25 = around 0.16</output>
0.16= 0.128   0.16
<result>A</result>
Exactly two sides of a certain 10-sided die are red. What is the probability that Kumar rolls the die 2 times and the die lands with a red side up for the first time on the second roll?