Machine–A produces 40% of the total output and Machine-B produces 60% of the total output. An average of nine units out of a thousand goods manufactured by Machine-A and one unit of 50 units produced by Machine-B prove to be defective. What is the probability that a unit chosen at random from the total daily output of the factory is defective?	Options:
A) a. 0.156	B) b. 0.01506	C) c. 0.0156	D) d. 0.0001566	E) e. 0.00001566
Let total Production be 10000 units....   A produces 4000 units and 36 units are defective   B produces 6000 units and 120 units are defective   So, Out of total 10,000 units 156 units are defective...   So the required probability = 156/10000= 
<gadget id="calculator">156/10000</gadget>
<output>39/2_500 = around 0.0156</output>
&gt; 0.0156   Answer will be (c. 0.0156)
<result>C</result>
Machine–A produces 40% of the total output and Machine-B produces 60% of the total output. An average of nine units out of a thousand goods manufactured by Machine-A and one unit of 50 units produced by Machine-B prove to be defective. What is the probability that a unit chosen at random from the total daily output of the factory is defective?