A train starts from Delhi at 6.00 a.m. and reaches Meerut at 10 a.m. The other train starts from Meerut at 8 a.m. and reaches Delhi at 11.30 a.m. If the distance between Delhi and Meerut is 200 km, then at what time did the two trains meet each other?	Choose the correct choice from the following answers:
A) 8.56 a.m	B) 8.46 a.m	C) 7.56 a.m	D) 8.30 a.m	E) None of these
The Speed of the train starting from Delhi = 200/4= 
<gadget id="calculator">200/4</gadget>
<output>50</output>
50 km/h   The Speed of train starting from Meerut= 200/3.5 = 400/7 km/h   Suppose the two trains meet x hours after 6.00 am   Then x X 50 + (x - 2) x 400/7 = 200   or, 350x + 400x - 800 = 1400   or, 750x = 2200   or, x = 2200/750 = 2h 56 min   Hence, the required time = 8.56 am   8.56 a.mNSWER:8.56 a.m
<result>A</result>
A train starts from Delhi at 6.00 a.m. and reaches Meerut at 10 a.m. The other train starts from Meerut at 8 a.m. and reaches Delhi at 11.30 a.m. If the distance between Delhi and Meerut is 200 km, then at what time did the two trains meet each other?