if x:y = 1:3, then find the value of
(7x+3y):(2x+y) Answers:
A) 14:5
B) 15:5
C) 16:5
D) 17:5
E) None of these
Explanation:   let x = 1k and y = 3k, so   =7(k)+3(3k)/ 2(k)+1(3k)   =16k/5k   =16:5   Option 16:5
<result>C</result>
if x:y = 1:3, then find the value of
(7x+3y):(2x+y)