Exactly four sides of a certain 10-sided die are red. What is the probability that Kumar rolls the die 3 times and the die lands with a red side up for the first time on the third roll?
Choices:
A) 0.3
B) 0.2
C) 0.01
D) 0.148
E) 0.144
Total no. of sides = 10   Sides that are red = 4   Probability that the die lands with red side up = 4/10   Therefore, Probability that the die does not land with red side up = 1 - 4/10 = 6/10   Probability that Kumar rolls the die 3 times and the die lands with a red side up for the first time on the third roll   = (1st roll - non red face) X (2nd roll - non red face) X (3rd roll - red face)   = (6/10) X (6/10) X (4/10)   = 144/1000= 
<gadget id="calculator">144/1000</gadget>
<output>18/125 = around 0.144</output>
0.144   0.144
<result>E</result>
Exactly four sides of a certain 10-sided die are red. What is the probability that Kumar rolls the die 3 times and the die lands with a red side up for the first time on the third roll?