Place a number in each of the following empty
boxes so that the sum of the numbers in any 3
consecutive boxes is 2015. What is the number
that should go in the box with the question
mark?	Pick one:	A) 684	B) 567	C) 892	D) 431	E) 999
To help illustrate the problem, we will label a few boxes as shown below.   Since the sum of the numbers in any 3 consecutive boxes is the same,   607 + A + B = A + B + C.   After taking away both A and B from the above equation we get 607 = C   Therefore, the number in box C should be 607.   Since the sum of the numbers in any 3 consecutive boxes is 2015,   C + 724 +? = 607 + 724 +? = 2015   Therefore, ? = 684   correct answer 684
<result>A</result>
Place a number in each of the following empty
boxes so that the sum of the numbers in any 3
consecutive boxes is 2015. What is the number
that should go in the box with the question
mark?