A 30% solution of barium chloride is mixed with 10 grams of water to form a 20% solution. How many grams of original solution did we start with ?
I am trained to complete above problem as per following technique. Is it possible to solve in following manner.
30%_________100%
______20%
ratio is 100-20 : 20-30, which is wrong. There should not be 20. Instead, value in the middle should be in between 30% to 100%. Answers
A) 10	B) 15	C) 20	D) 25	E) 30
We're told that 10g of water are mixed with an unknown amount of 30% barium mixture to form a 20% barium final mixture. We're asked to figure out how much barium mixture we have....   Logically, if we had 10g of water mixed with 10g of barium mixture, we'd end up with a 15% overall mixture, so 10 is NOT the answer. We need MORE barium mixture to raise the final mixture up to 20%. Since the numbers in the prompt are allroundnumbers, it's highly likely that the correct answer will ALSO be a round number....   Let's TEST Answer C = 20g   (20g of barium mixture)(30% barium) = 6g barium   + 10g water.....   (6g barium)/(30g total liquid) = .2 = 20% final barium mixture.   So, the initial barium mixture MUST be 20g   ANSWER 20
<result>C</result>
A 30% solution of barium chloride is mixed with 10 grams of water to form a 20% solution. How many grams of original solution did we start with ?
I am trained to complete above problem as per following technique. Is it possible to solve in following manner.
30%_________100%
______20%
ratio is 100-20 : 20-30, which is wrong. There should not be 20. Instead, value in the middle should be in between 30% to 100%.