A box contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the box, if atleast one black ball is to be included in the draw?  Pick:
A) 64  B) 36  C) 52  D) 86  E) 24
We may have (1 black and 2 non black) or (2 black and 1 non black) or (3 black)   Required number of ways = 3C1*6C2+3C2*6C1+3C3 = 64   64nswer is 64
<result>A</result>
A box contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the box, if atleast one black ball is to be included in the draw?