In how many ways can 6 boys and 3 girls sit around a table in such a way that no two girls sit together?
Choose the correct choice from the following answers:
A) 10000  B) 14000  C) 14400  D) 18000  E) 19000
The 6 boys can be seated around a table in 5! Ways. In between them there are 6 places.   The 3 girls can be placed in the 6 places in 6P3 ways.   Therefore, Required number of ways= 5!* 6P3   =120*120= 
<gadget id="calculator">120*120</gadget>
<output>14_400</output>
14400   ANSWER:14400
<result>C</result>
In how many ways can 6 boys and 3 girls sit around a table in such a way that no two girls sit together?