If A speaks the truth 80% of the times, B speaks the truth 60% of the times. What is the probability that they tell the truth at the same time	Options:  A) 0.8  B) 0.48  C) 0.6  D) 0.14  E) 0.98
probability that A speaks truth is 80/100= 
<gadget id="calculator">80/100</gadget>
<output>4/5 = around 0.8</output>
0.8 probability that 0.48 speaks truth is   60/100= 
<gadget id="calculator">  60/100</gadget>
<output>3/5 = around 0.6</output>
0.6 since both A and 0.48 are independent of each other so PRO0.48A0.48ILITY OF A INTERSECTION 0.48= P(A) *P(0.48) =0.8 * 0.6= 
<gadget id="calculator">0.8 * 0.6</gadget>
<output>0.48</output>
0.48   ANSWER:0.48
<result>B</result>
If A speaks the truth 80% of the times, B speaks the truth 60% of the times. What is the probability that they tell the truth at the same time