The weight of four dogs is determined to be 25 pounds, 31 pounds, 43 pounds and 41 pounds respectively. The weight of a fifth dog is determined to be y pounds. If the average (arithmetic mean) weight of the first four dogs is the same as that of all five dogs what is the value of y?	Choose one
A) 31  B) 33  C) 35  D) 37  E) 39
Total weight of the 4 dogs = (25+31+43+41)= 
<gadget id="calculator">(25+31+43+41)</gadget>
<output>140</output>
140   Avg= 140/4= 
<gadget id="calculator">140/4</gadget>
<output>35</output>
35   Total weight of 5 dogs= 140+y or 4(35)+y   Average of 5 dogs as per Question = 35   Equation:   4(35) + y = 5 (35), or y = 35.   35hoose 35
<result>C</result>
The weight of four dogs is determined to be 25 pounds, 31 pounds, 43 pounds and 41 pounds respectively. The weight of a fifth dog is determined to be y pounds. If the average (arithmetic mean) weight of the first four dogs is the same as that of all five dogs what is the value of y?