At a casino in Mumbai, there are 3 tables A, B and C. The payoffs at A is 10 : 1, at B is 20 : 1 and C is 30 :1. If a man bets Rs. 200 at each table and win at two of the tables, what is the maximum and minimum difference between his earnings can be ?
Pick
A) Rs. 4000  B) Rs. 4500  C) Rs. 2500  D) Rs. 2000  E) None of these
Solution: Maximum earning will be only possible when he will won on the maximum yielding table.   A → 10 :1   B → 20 :1   C → 30 :1   i.e., he won B and C but lost on A,   20 *200 +30 *200 - 1 *200= 
<gadget id="calculator">20 *200 +30 *200 - 1 *200</gadget>
<output>9_800</output>
9800   Minimum earnings will be when he won on table A and B and lose on table 3.   10 *200 + 20 *200 - 1 *200= 
<gadget id="calculator">10 *200 + 20 *200 - 1 *200</gadget>
<output>5_800</output>
5800   Therefore, difference= 9800-5800 = Rs. 4000.   Alternatively,   The difference,   = [(30 +20 -1) - (10 +20 -1)] * 200   = Rs. 4000.   Rs. 4000nswer: Option Rs. 4000
<result>A</result>
At a casino in Mumbai, there are 3 tables A, B and C. The payoffs at A is 10 : 1, at B is 20 : 1 and C is 30 :1. If a man bets Rs. 200 at each table and win at two of the tables, what is the maximum and minimum difference between his earnings can be ?