For any 6 given numbers, which of the following is always equivalent to adding the 3 numbers together and then dividing the sum by 3?
I. Ordering the 3 numbers numerically, from highest to lowest, and then selecting the middle number.
II. Dividing each of the numbers by 3 and then adding the results together.
III. Multiplying each number by 6, adding the resulting products together, and then dividing the sum by 9. Options
A) I only B) II only C) I and II only D) II and III only E) None of the above
Let the 3 numbers be x, y and z.   Question: Which of the following is equivalent to (x + y + z)/3   I. Ordering the 3 numbers numerically, from highest to lowest, and then selecting the middle number. --&gt; Not always equivalent Eg: 111 and 141   II. Dividing each of the numbers by 3 and then adding the results together. --&gt; x/3 + y/3 + z/3 = (x + y + z)/3 --&gt; Equivalent   III. Multiplying each number by 6, adding the resulting products together, and then dividing the sum by 9. --&gt; (6x + 6y + 6z)/9 = 2(x + y + z)/3 --&gt; Not equivalent   Answer: II and III only
<result>D</result>
For any 6 given numbers, which of the following is always equivalent to adding the 3 numbers together and then dividing the sum by 3?
I. Ordering the 3 numbers numerically, from highest to lowest, and then selecting the middle number.
II. Dividing each of the numbers by 3 and then adding the results together.
III. Multiplying each number by 6, adding the resulting products together, and then dividing the sum by 9.