It is being given that (2^32 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
Choose one:
A) 16^2+1  B) 12  C) (2^96+1)  D) 24  E) 4^4+6
Explanation:   Let 2^32 = x. Then, (2^32 + 1) = (x + 1).   Let (x + 1) be completely divisible by the natural number N. Then,   (296 + 1) = [(2^32)3 + 1] = (x^3 + 1) = (x + 1)(x^2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.   (2^96+1)
<result>C</result>
It is being given that (2^32 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?