Three consecutive odd integers are in increasing order such that the sum of the last two integers is 17 more than the first integer. Find the three integers?
Options.
A) 11,13,15 B) 7, 2, 10 C) 7, 9, 10 D) 7, 9, 11 E) 7, 9, 29
Explanation:   Let the three consecutive odd integers be x, x + 2 and x + 4 respectively.   x + 4 + x + 2 = x + 17 =&gt; x = 11   Hence three consecutive odd integers are 11, 13 and 15   11,13,15nswer: 11,13,15
<result>A</result>
Three consecutive odd integers are in increasing order such that the sum of the last two integers is 17 more than the first integer. Find the three integers?