A meeting has to be conducted with 4 managers. Find the number of ways in which the managers be selected from among 7 managers, if 2 managers will not attend the meeting together? Answers:  A) 25  B) 20  C) 35  D) 36  E) 38
we can either choose all 4 people from 5 manager who have no problems or choose 3 from the 5 and 1 from the 2 managers who have a problem sitting together   so 5C4 + (5C3 * 2C1)   this is   5 + 20= 
<gadget id="calculator">  5 + 20</gadget>
<output>25</output>
25   25nswer : 25
<result>A</result>
A meeting has to be conducted with 4 managers. Find the number of ways in which the managers be selected from among 7 managers, if 2 managers will not attend the meeting together?