If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be: Options.
A) 3 days B) 4 days C) 5 days D) 6 days E) 7 days
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.   Then, (6x + 8y) = 1/10 and (26x + 48y) = 1/2.   Solving these two equations, we get : x = 1/100	and y = 1/200.   (15 men + 20 boy)'s 1 day's work = (15/100 + 20/200) = 1/4.   Therefore, 15 men and 20 boys can do the work in 4 days.   CORRECT OPTION: "4 days".
<result>B</result>
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be: