If 6887 books need to be placed in boxes and each box can contain at most 9 books. How many books will be in the last unfilled box?  Choices
A) 1 books	B) 2 books	C) 3 books	D) 4 books	E) 5 books
The number of books that can be placed in boxes of 9 books is the first number that is divisible by 9 that occurs before 6887.   In order to divide the sum in 9 parts, the amount must be divisible by 9   Divisibility rule of 9: The sum of the digits must be divisible by 9   Sum of digits of 6887 = 29 and 27 is divisible by 9.   Hence, we need to remove 2 to this number for it to be divisible by 9   Correct Option: 2 books
<result>B</result>
If 6887 books need to be placed in boxes and each box can contain at most 9 books. How many books will be in the last unfilled box?