What is the smallest number which when increased by 7 is divisible by 25, 49, 15, and 21?	Pick:	A) 3,551	B) 3,668	C) 3,733	D) 3,822	E) 3,957
First factor each of 25, 49, 15, and 21 into primes:   25=5*5; 49=7*7; 15=3*5; 21=3*7   the smallest number divisible by each of the numbers is 3*5*5*7*7 = 3,675   3,675-7 = 3,668 thus 3,668 + 7 is the smallest number divisible by 25, 49, 15, and 21   3,668
<result>B</result>
What is the smallest number which when increased by 7 is divisible by 25, 49, 15, and 21?