A's speed is 20/13 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that B beats A by 60% of the length of the race?	Options:
A) 44%
B) 48%
C) 52%
D) 42%
E) 74%
First calculate the distance, B has covered with his speed in the time, in which A reached 40% of the race.   Then Add the remaining distance as head start for B to win the race.   Its best to apply Ratios concept here.   Since A's speed is 20/13 of B, therefore, B's speed is 13/20 of A   Distance covered by B = speed x time = (13/20) x (0.4) = 0.26   (Which means B would have covered 0.26 of the race length during the time in which A has covered 0.4 of the race length.   Therefore to win, B needs a headstart of (1 - 0.26 = ) 0.74 of the race length.   So the answer is 74%
<result>E</result>
A's speed is 20/13 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that B beats A by 60% of the length of the race?