There are 8 red, 7 blue and 6 green balls, 1 ball is picked up randomly thenwhat is the probability that neither blue nor green? Choices.
A) 7/22	B) 7/25	C) 8/21	D) 8/23	E) 8/25
Total number of balls = (8 + 7 + 6)= 
<gadget id="calculator">(8 + 7 + 6)</gadget>
<output>21</output>
21   Let E= event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.   Therefore, n(E) = 8.   P(E) = 8/21.   8/21)
<result>C</result>
There are 8 red, 7 blue and 6 green balls, 1 ball is picked up randomly thenwhat is the probability that neither blue nor green?