If an integer n is to be chosen at random from the integers 1 to 84, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8?	Choose the correct choice:  A) 9/14  B) 3/8  C) 1/2  D) 5/8  E) 3/4
n(n+1)(n+2) will be divisible by 8 when n is a multiple of 2 or when (n+1) is a multiple of 8.   Thus when n is even, this whole expression will be divisible by 8.   from 1 to 84, there are 42 even integers.   Now when (n+1) is multiple by 8, we have 12 such values for (n+1)   probability that n(n+1)(n+2) will be divisible by 8   = (42 + 12)/84   = 54/84   = 9/14   9/14ns is 9/14
<result>A</result>
If an integer n is to be chosen at random from the integers 1 to 84, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8?