Five farmers have 7,9,11,13 & 14 apple trees respectively in their orchards.last year each of them discovered that every tree in their own orchard bore exactly d same no of apples.further,if d 3rd farmer gives one apple to the 1st,& the 5th gives 3 to each of the 2nd & d 4th,they would all exactly have the same no of apples, what were d yields per tree in the orchards of d 3rd & 4th farmers?	Choose the correct choice: A) 8,9 B) 10,11 C) 11,12 D) 11,9 E) 11,8
Let a, b, c, d &amp; e be the number of apples bored last year in each farmer's tree.   Given that 7a + 1 = 9b + 3 = 11c - 1 = 13d + 3 = 14e - 6   But the question is to find the number of apples bored per tree in 3rd nd 4th orchard.It is enough to consider 11c - 1 = 13d + 3..   Therefore 11 c - 1 = 13 d + 3   By trial and error method, we get the value for c and d as 11 and 9.   5th nd 4th   14e - 6 = 13d + 3   14e - 13d = 9   here if u put e=d=1, result ll be 1, e=d=2 difference ll be 2, .... e=d=9 ,result ll be 9   so e=9 , d=9   So 5ht tree ll give  14 * 9= 
<gadget id="calculator"> 14 * 9</gadget>
<output>126</output>
126 no. of apples   4th tree ll give  13 * 9= 
<gadget id="calculator"> 13 * 9</gadget>
<output>117</output>
117 no. of apples   for 5th nd 2nd   14 * 9 -6= 9 * b + 3   120=9b + 3   b = 13   So 2nd tree ll give  9 * 13= 
<gadget id="calculator"> 9 * 13</gadget>
<output>117</output>
117   A= 119 , per tree = 17   B= 117 , per tree = 13   C= 121, per tree = 11   D= 117, per tree = 9   E = 126 , per tree = 9   3'rd farmer have 11 apples per tree and   4'th farmer have 9 apples per tree.   ANSWER:11,9
<result>D</result>
Five farmers have 7,9,11,13 & 14 apple trees respectively in their orchards.last year each of them discovered that every tree in their own orchard bore exactly d same no of apples.further,if d 3rd farmer gives one apple to the 1st,& the 5th gives 3 to each of the 2nd & d 4th,they would all exactly have the same no of apples, what were d yields per tree in the orchards of d 3rd & 4th farmers?