In a simultaneous throw of two dice, what is the probability of getting a total of 7? Pick one:	A) 1/6	B) 1/4	C) 2/3	D) 3/4	E) 4/5
We know that in simultaneous throw of two dice, n(S) = 6 x 6 = 36.   Let E = event of getting a total of 7 ={(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}   P(E) = n(E)/n(S) = 6/36 = 1/6.   1/6nswer 1/6.
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In a simultaneous throw of two dice, what is the probability of getting a total of 7?