Imagine John has 2 blue balls, 3 green balls, 1 black ball and 4 red balls. How many ways can he arrange the balls lining them up?
Choose the correct choice from the following choices:
A) 10!/(2!)2 1!	B) 10!/2! 1! 3! 1!	C) 10!/4! 4!	D) 9!/4! 3! 2!	E) 10!/4! 3! 2!
n items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.   John has 10 balls which are 4 red balls, 3 green balls, 2 blue balls and 1 black ball.   Number of arrangements = 9!/(2!)2 3!   Answer: 10!/4! 3! 2!
<result>E</result>
Imagine John has 2 blue balls, 3 green balls, 1 black ball and 4 red balls. How many ways can he arrange the balls lining them up?