The area of one square is x^2 + 12x + 36 and the area of another square is 4x^2 − 12x + 9. If the sum of the perimeters of both squares is 64, what is the value of x?	Select the correct option.
A) 0  B) 4.3  C) 2.5  D) 4.67  E) 10
spotting the pattern of equations both are in form of (X+C)^2 so   A1= (x+6)^2A2= (2x-3)^2   L1= x+6 L2= 2x-3   P1 = 4( x+6)P2=4(2x-3)   P1+P2=64   4( x+6) +4(2x-3)=64..............&gt; X=4.3   Answer: 4.3
<result>B</result>
The area of one square is x^2 + 12x + 36 and the area of another square is 4x^2 − 12x + 9. If the sum of the perimeters of both squares is 64, what is the value of x?