A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 36 times, A has killed:
Options
A) 60 birds B) 72 birds C) 30 birds D) 80 birds E) 40 birds
Let the total number of shots be x. Then,   Shots fired by A =(5/8)x   Shots fired by B =(3/8)x   Killing shots by A =(1/3)of	(5/8)x=(5/24)x   Shots missed by B =(1/2) of (3/8)x	=(3/16)x   3x/16= 36 or x =(36 x 16)/3= 192.   Birds killed by A =(5x/24)	=(5/24*192)= 
<gadget id="calculator">(5/24*192)</gadget>
<output>40</output>
40.   Answer is 40 birds
<result>E</result>
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 36 times, A has killed: