Compound X contains elements A and B at an approximate ratio, by weight, of 2:10. Approximately how many grams of element B are there in 222 grams of compound X? Select the correct option:
A) 54 B) 185 C) 250 D) 270 E) 322
total number of fractions =2+10= 
<gadget id="calculator">2+10</gadget>
<output>12</output>
12   element B constitutes=10 out of 12 parts of X   So in 222 gms of X have 222*10/12= 
<gadget id="calculator">222*10/12</gadget>
<output>185</output>
185 gms of B   and  222-185= 
<gadget id="calculator"> 222-185</gadget>
<output>37</output>
37 gms of A.   cross check:- A/185= 37/185 =2/10 (as given)   Ans 185
<result>B</result>
Compound X contains elements A and B at an approximate ratio, by weight, of 2:10. Approximately how many grams of element B are there in 222 grams of compound X?