A car starts from X and moves towards Y. At the same time another car starts from Y and moves towards X. Both travel at a constant speed and meet after 6 hours. During that time, the faster car traveled 1/3 of the distance XY. How long would it take the slower car to travel the distance XY?  Options.
A) 6 hours
B) 9 hours
C) 10 hours
D) 12 hours
E) 15 hours
If one car travelled 1/3, then the other car must have travelled only 2/3, as they are meeting after 6 hours in a certain point. So:   (2/3)XY= 6*y --&gt; It took the car 6 hours to travel 2/3 of the distance at a constant speed y.   So if we solve this last equation:   2XY= 3*6*y= 9*y --&gt; It will take this car 9 hours in total to reach its final destination.   Answer: 9 hours
<result>B</result>
A car starts from X and moves towards Y. At the same time another car starts from Y and moves towards X. Both travel at a constant speed and meet after 6 hours. During that time, the faster car traveled 1/3 of the distance XY. How long would it take the slower car to travel the distance XY?