Suppose that there is a rubber ball which has a property of bouncing back to the original height from which it was dropped and it keeps doing that until it is stopped by any external force.
Can you calculate the fraction of height to which the ball would have bounced if it has bounced four times after dropping from a certain height without being stopped?	Choose the most appropriate option: A) 16/81 B) 15/90 C) 18/88 D) 15/79 E) 13/85
A   16/81   Explanation:   It is a question of geometric progression but we can solve it step by step as well in case you are not aware of the formula.   At first bounce   The height at which the ball would have reached = 2/3 of the original height from which it was dropped.   At second bounce   The height at which the ball would have reached = 2/3 * 2/3 of the original height from which it was dropped.   At third bounce   The height at which the ball would have reached = 2/3 * 2/3 * 2/3 of the original height from which it was dropped.   At fourth bounce   The height at which the ball would have reached = 2/3 * 2/3 * 2/3 * 2/3 of the original height from which it was dropped.   Now, 2/3 * 2/3 * 2/3 * 2/3 = 16/81   Therefore, 16/81 of the original height from which the ball was dropped is the required fraction height.
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Suppose that there is a rubber ball which has a property of bouncing back to the original height from which it was dropped and it keeps doing that until it is stopped by any external force.
Can you calculate the fraction of height to which the ball would have bounced if it has bounced four times after dropping from a certain height without being stopped?