If the product of 8 integers is negative, at most how many of the integers can be negative?
Options.
A) 2  B) 3  C) 4  D) 5  E) 7
The product of 8 integers is negative   Thus an odd number of integers need to be negative to have a negative product   We are asked at most how many are required.   So, the highest odd integer before 6,i.e. 7   Correct Option : 7
<result>E</result>
If the product of 8 integers is negative, at most how many of the integers can be negative?