If a and b are different values and a – b = 6(√a - √b), then in terms of b, a equals:	Choices:
A) √b B) b C) b - 12√b + 36 D) b + 2√b + 1 E) b^2 – 2b√b + b
(√a)^2 - (√b)^2 = 6(√a - √b) -----&gt; ( √a + √b) ( √a - √b) = 6(√a - √b) -------&gt; √a + √b = 6, so   √a = 6 - √b, square both sides and solve. Answer is b - 12√b + 36.
<result>C</result>
If a and b are different values and a – b = 6(√a - √b), then in terms of b, a equals: