When positive integer n is divided by 5, the remainder is 1. When n is divided by 7, the remainder is 3. What is the smallest positive integer k such that k+n is a multiple of 36?  Choose the correct choice from the following answers.
A) 3
B) 4
C) 12
D) 32
E) 5
n = 5p + 1 = 6,11,16,21,26,31   n 5  + 1= 
<gadget id="calculator">5  + 1</gadget>
<output>6</output>
6,11,16,21,26,31   n= 7q + 3 = 3,10,17,24,31   =&gt;n = 36m + 31   To get this, we need to take LCM of co-efficients of p and q and first common number in series.   So we need to add 5 more to make it   36m + 36   Answer - 5
<result>E</result>
When positive integer n is divided by 5, the remainder is 1. When n is divided by 7, the remainder is 3. What is the smallest positive integer k such that k+n is a multiple of 36?