A division of a company consists of three men and five women. If two of these employees are randomly selected as representatives of the division, what is the probability that both representatives will be female?  Choices.
A) 1/4  B) 2/9  C) 3/11  D) 5/14  E) 6/17
Total number of ways to select 2 members = 8C2 = 28   Total number of ways to select 2 females = 5C2 = 10   P(two females) = 10/28 = 5/14   The answer is 5/14.
<result>D</result>
A division of a company consists of three men and five women. If two of these employees are randomly selected as representatives of the division, what is the probability that both representatives will be female?