Three students appear at an examination of Mathematics. The probability of their success are 1/3, 1/4, 2/5 respectively. Find the probability of success of at least two.	Select the correct option.
A) 1/4  B) 2/5  C) 3/4  D) 3/5  E) 4/5
The probability of success of at least two students will involve the following possibilities.   The first two students are successful, the last two students are successful, the first and third students are successful and all the three students are successful.   Therefore, the required probability = 1/3 x 1/4 x 3/5 + 1/4 x 2/5 x 2/3 + 1/3 x 2/5 x 3/4 + 1/3 x 1/4 x 2/5 = 1/4   1/4NSWER:1/4
<result>A</result>
Three students appear at an examination of Mathematics. The probability of their success are 1/3, 1/4, 2/5 respectively. Find the probability of success of at least two.