A quadilateral pqrs is inscribes in a circle of center o. PQ is parallel to RS and pq= 3rs,
also QR=PS. perimeter(pqrs)= perimeter of square whose area is 36sqm,then find the approx area of pqrs Pick one:
A) 6root(3) B) 12root(3) C) 9root(3) D) 18root(3) E) 12root(3)
Lets take, QR=PS= a m and RS=b m, So, PQ=3b m   now if are of a square is 36 sqm, then perimeter is 24   now perimeter of the inscribed quadrilateral is 4b+2a= 24   so, 2b+a=12   from this we can get set of solutions like (a,b)= (6,3), (8,2), (10,2)   Now, formula for area of inscribed quadrilater is root{(s-a)(s-b)(s-c)(s-d)}   Here s= 12   now by trial and error method we can get the solution   appprox area is 18root(3)   ANSWER:18root(3)
<result>D</result>
A quadilateral pqrs is inscribes in a circle of center o. PQ is parallel to RS and pq= 3rs,
also QR=PS. perimeter(pqrs)= perimeter of square whose area is 36sqm,then find the approx area of pqrs