The probability of rain showers in Barcelona on any given day is 0.4. What is the probability that it will rain on exactly one out of three straight days in Barcelona?
Choose the most appropriate option
A) 0.144	B) 0.072	C) 0.432	D) 0.72	E) 0.288
P(Rain) = 0.4 = 2/5   So, P(no rain) = 0.6 = 3/5   Let R represent Rain, and let N represent no rain   So, P(Rain exactly once) = P(R-N-N OR N-R-N OR N-N-R)   = P(R-N-N) + P(N-R-N) + P(N-N-R)   = (2/5)(3/5)(3/5) + (3/5)(2/5)(3/5) + (3/5)(3/5)(2/5)   = 18/125 + 18/125 + 18/125   = 54/125   NO DE0.432IMAL 0.432ONVERSION NEEDED   Notice that 62.5/125 = 1/2= 
<gadget id="calculator">1/2</gadget>
<output>1/2 = around 0.5</output>
0.5, so 54/125= a little less than 0.5   Answer:0.432
<result>C</result>
The probability of rain showers in Barcelona on any given day is 0.4. What is the probability that it will rain on exactly one out of three straight days in Barcelona?