How much space, in cubic units, is left vacant when maximum number of 3x3x3 cubes are fitted in a rectangular box measuring 6x9x11 ?  Choose the correct choice from the following answers:
A) 112
B) 111
C) 110
D) 109
E) 108
No of cubes that can be accommodated in box = (6*9*11)/(3*3*3)   6*9 in numerator can be perfectly divided by 3*3 in denominator.   side with length 11 can't be perfectly divided by 3 and hence is the limiting factor. Closet multiple of 3 less that 11 is 9. so vacant area in cube =   =6*9*(11-9)   =6*9*2= 
<gadget id="calculator">6*9*2</gadget>
<output>108</output>
108   Ans - 108
<result>E</result>
How much space, in cubic units, is left vacant when maximum number of 3x3x3 cubes are fitted in a rectangular box measuring 6x9x11 ?