Departments A, B, and C have 5 employees each, and department D has 20 employees. Departments A, B, C, and D have no employees in common. A task force is to be formed by selecting 1 employee from each of departments A, B, and C and 2 employees from department D. How many different task forces are possible? Options.
A) 19,000	B) 23,750	C) 100,000	D) 190,000	E) 400,000
5c1 * 5c1* 5c1*20c2 = 5*5*5*190=23,750. Hence 23,750 is the correct answer.
<result>B</result>
Departments A, B, and C have 5 employees each, and department D has 20 employees. Departments A, B, C, and D have no employees in common. A task force is to be formed by selecting 1 employee from each of departments A, B, and C and 2 employees from department D. How many different task forces are possible?