Jim has arrived late for his golf tee time with his friends. When he arrives at the course, he discovers that his friends have already walked 180 yards ahead on the course and that they are continuing to walk forward at a rate of 1.5 yards per second. A bystander with a golf cart takes pity on Jim and drives him to meet his friends at the rate of 4 yards per second. Once Jim meets his friends, he exits the cart and walks with them at their rate for the next 120 yards. What is Jim’s approximate average speed for his total trip?  Choose the correct answer:
A) 1.8 yards per second	B) 2.0 yards per second	C) 2.4 yards per second	D) 2.7 yards per second	E) 3.0 yards per second
Given Jim's friends has a lead of 180 yards and moving at 1.5 yards/sec speed   Jim on golf cart with speed 4 yards/sec has to meet this friends, assuming he meets them after "t" secs   So the total distance traveled by Jim and his friends should be same so as to meet them=&gt; 180+1.5t=4t   =&gt; 180=2.5t   =&gt;72 secs, so Jim meets his friends after traveling 72 secs at 4 yards/sec speed---First part of his journey (288 yards in 72 secs)   Now, Jim travels 120 yards with speed 1.5 yards/sec in  120/1.5= 
<gadget id="calculator"> 120/1.5</gadget>
<output>80</output>
80 secs---second part of his journey (120 yards in 80 secs)   So avg speed of Jim= total distance traveled/ total time   =&gt; (288+120)/(72+80)=408/152   =&gt;2.7 yards/sec approx   Answer: 2.7 yards per second
<result>D</result>
Jim has arrived late for his golf tee time with his friends. When he arrives at the course, he discovers that his friends have already walked 180 yards ahead on the course and that they are continuing to walk forward at a rate of 1.5 yards per second. A bystander with a golf cart takes pity on Jim and drives him to meet his friends at the rate of 4 yards per second. Once Jim meets his friends, he exits the cart and walks with them at their rate for the next 120 yards. What is Jim’s approximate average speed for his total trip?