What will be the remainder of the following division:
(1234567....141516...20212223....404142)/43?  Choose the correct choice from the following.
A) 0
B) 1
C) 2
D) 3
E) 4
first add the digits   1+2+3+.........+42   =&gt;903   then 903 divided by 43   because it is the rule of division by 43( a prime number)   so 903%43=0   % is modulo operator it returns the remainder part   0NSWER:0
<result>A</result>
What will be the remainder of the following division:
(1234567....141516...20212223....404142)/43?