Suppose, the speed of any positive integer n is defined as follows:
seed(n) = n, if n < 10
= seed(s(n)), otherwise,
where s(n) indicates the sum of digits of n.For example, seed(7) = 7, seed(248) = seed(2 + 4 + 8) = seed(14) = seed(1 + 4) = seed(5) = 5 etc. How many positive integers n, such that n < 500, will have seed (n) = 9?	Options:
A) 39
B) 72
C) 81
D) 108
E) 55
Explanation :   We need to find out numbers less than 500, with sum of digits as 9.   We know that a number will be divisible by 9, if the sum of its digits is divisible by 9.   For eg : 18 has sum of digits 9.   198 has sum of digits 18, which has its sum of digits 9.   So, we need to find numbers less than 500 which are divisible by 9, or are multiples of 9 i.e 500/9 is 55.5555.   Hence, there are 55 numbers which are multiples of 9 less than 500.   Answer : 55
<result>E</result>
Suppose, the speed of any positive integer n is defined as follows:
seed(n) = n, if n < 10
= seed(s(n)), otherwise,
where s(n) indicates the sum of digits of n.For example, seed(7) = 7, seed(248) = seed(2 + 4 + 8) = seed(14) = seed(1 + 4) = seed(5) = 5 etc. How many positive integers n, such that n < 500, will have seed (n) = 9?