The equation x = 2y^2 + 5y - 16, describes a parabola in the xy coordinate plane. If line l, with slope of 3, intersects the parabola in the upper-left quadrant at x = -5, the equation for l is	Choose the correct choice from the following answers: A) 3x + y + 15 = 0 B) y + 3x - 1 = 0 C) -3x + y - 16.5 = 0 D) -2x - y - 7 = 0 E) -3x + y + 13.5 = 0
The line has a point (-5, y) on it where y is positive (since the point lies in upper left quadrant).   In options B , if you put x = -5, you get -ve value for y co-ordinate.   Answer must be (y + 3x - 1 = 0)
<result>B</result>
The equation x = 2y^2 + 5y - 16, describes a parabola in the xy coordinate plane. If line l, with slope of 3, intersects the parabola in the upper-left quadrant at x = -5, the equation for l is