If the operation @ is defined for all a and b by the equation a@b =(a^2*b)*3, then 2@(3@-1) = Choose the most appropriate option: A) -324 B) 223 C) 324 D) -223 E) -410
work within the parenthesis first so solve (3@-1) first   (3@-1)= ((3^2)*-1)*3 = (9*-1)*3= -9*3=-27   now take -3 plug back into equation and solve the rest   2@(-27)=((2^2)*-3)*3 = (4*-27)*3= -324   so -324 is the answer....this question is merely testing order of operations   remember PEMD-324S   Option -324
<result>A</result>
If the operation @ is defined for all a and b by the equation a@b =(a^2*b)*3, then 2@(3@-1) =