If (x + 2)(x - a) = px2x2 + qx + 8, what are the values of the constants a, p and q?  Choose the correct choice:
A) 299	B) 278	C) -4,1,6	D) 2378	E) 2771
(x + 2)(x - a) = px2px2 + qx + 8   ⇒x2⇒x2 + 2x - ax - 2a = px2px2 + qx + 8   ⇒x2⇒x2 + (2 - a) x - 2a = px2px2 + qx + 8   Equating the coefficients of x2x2 , x and constant terms on both sides.   p = 1; q = 2 - a   -2a = 8   Solving, we get a = -4, p = 1, q = 6   Answer:-4,1,6
<result>C</result>
If (x + 2)(x - a) = px2x2 + qx + 8, what are the values of the constants a, p and q?