A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, how many birds A has killed?	Choose the most appropriate option:  A) 10  B) 20  C) 30  D) 40  E) 50
Let the total number of shots=x   Shots fired by A=5x/8   Shots fired by B=3x/8   Killing shots by A=5x/8×1/3=5x/24   Missing shots by B=3x/8×1/2=3x/16   B has missed 27 times⇒3x/16=27   ⇒x=27×16/3=144   Hence, killing shots by A=5x/24=(5×144)/24=5×12/2=30   i.e., A has killed 30 birds   Answer is 30.
<result>C</result>
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, how many birds A has killed?