Find the area of a triangle whose sides are 41 cm, 28 cm, 15 cm. Also, find the length of the altitude corresponding to the largest side of the triangle.  Choose one
A) 4.1 cm	B) 5.1 cm	C) 6.1 cm	D) 7.1 cm	E) 8.1 cm
Semi-perimeter of the triangle = (a + b + c)/2   = (41 + 28 + 15)/2   = 84/2= 
<gadget id="calculator">84/2</gadget>
<output>42</output>
42 cm   Therefore, area of the triangle= √(s(s - a) (s - b) (s - c))   = √(42 (42 - 41) (42 - 28) (42 - 15)) cm²   = √(42 × 1 × 27 × 14) cm²   = √(3 × 3 × 3 × 3 × 2 × 2 × 7 × 7) cm²   = 3 × 3 × 2 × 7 cm²   = 126 cm²   Now, area of triangle = 1/2 × b × h   Therefore, h = 2A/b   = (2 × 126)/41   = 252/41   = 6.1 cm   ANSWER : OPTION 6.1 cm
<result>C</result>
Find the area of a triangle whose sides are 41 cm, 28 cm, 15 cm. Also, find the length of the altitude corresponding to the largest side of the triangle.