What is the sum of natural numbers between 60 and 100
Choose one.
A) 4800
B) 4860
C) 5000
D) 5500
E) 3280
a = first number   l = last number   Sn = n/2[a + l]   between 60 and 100 numbers = 41 =&gt; 100 - 60= 
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
40 + 1= 
<gadget id="calculator">40 + 1</gadget>
<output>41</output>
41   Sn= 41/2 Ã— 160 = 41 Ã— 80 = 3280   Answer : 3280
<result>E</result>
What is the sum of natural numbers between 60 and 100