If n is a natural number, then(6n^2+6n) is always divisible by?	Select
A) 6 only B) 6 and 12 C) 12 only D) by 18 only E) None of these
(6n^2+6n)=6n(n+1), which is always divisible by 6 and 12 both, since n(n+1) is always even.   Correct Option: 6 and 12
<result>B</result>
If n is a natural number, then(6n^2+6n) is always divisible by?