There are 3 teams each with 4 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?  Select:
A) 50 B) 23 C) 48 D) 28 E) 45
There are altogether three arrangements, which are we can select two members each from team A and B, each from team A and C, and each from team B and C. For each arrangement, there are altogether 16 possibilities (4*4) since each team has 4 players. So there are a total of 48 possibilities (16*3). I hope this method is easier for you to understand.
<result>C</result>
There are 3 teams each with 4 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?