A certain series is defined by the following recursive rule: Sm=K(Sm-1) , where k is a constant. If the 1st term of this series is 64 and the 25th term is 192, what is the 9th term?	Pick:	A) ROOT 2	B) ROOT 3	C) 64*ROOT 3	D) 64*3^1/3	E) 64*3^24
Ans...D   No need for any GP formula here   The rule is that mth term is K times the (m-1)th term.   1st = 64   2nd = k.64   3rd = k^2.64   .   .   .   9th term = k^8 *64   .   .   .   so 25th = k^24*64   Using this solve for k and substitute k in the equation for the 9th term
<result>D</result>
A certain series is defined by the following recursive rule: Sm=K(Sm-1) , where k is a constant. If the 1st term of this series is 64 and the 25th term is 192, what is the 9th term?