Let a be a positive integer. If r is divisible by 2^a and r is also divisible by 3^(2a), then it is possible that r is NOT divisible by
Options
A) 6	B) 3 × 2^a	C) 2 × 3^(2a)	D) 6^a	E) 6^(2a)
Since, r is divisible by 2^a and 3^(2a), it must be divisible by 6. As least value of a = 1   Only for 6^(2a), 6^(2a) doesn't satisfy, if a = 1 and r=18, it is not divisible by 6^2 (i.e 36)   Hence answer is 6^(2a)
<result>E</result>
Let a be a positive integer. If r is divisible by 2^a and r is also divisible by 3^(2a), then it is possible that r is NOT divisible by