The digit at the ten’s place of a 2 digit no. is twice the digit at the unit’s place. If the sum of this no. and the no. formed by reversing the digits is 66. Find the no.
Choose the correct option:
A) 26 B) 28 C) 32 D) 42 E) 47
Let the unit place digit = x   Ten’s place digit = 2x   Number formed = 10(2x ) + x = 20 x + x = 21x   Reversing the digit :   Unit digit = 2x   Ten’s digit = x   New number formed = 10 (x) + 2x = 10x + 2x = 12x   As the sum of the number is 66.   21x + 12 x 10  + 2= 
<gadget id="calculator">10  + 2</gadget>
<output>12</output>
12x   As the sum of the number is 66.   21x + 12 x= 66   33x = 66   X = 2   So unit digit = 2   Number = 21x = 21(2)   =42   42
<result>D</result>
The digit at the ten’s place of a 2 digit no. is twice the digit at the unit’s place. If the sum of this no. and the no. formed by reversing the digits is 66. Find the no.