In a jar there are 3 red gumballs and 2 blue gumballs. What is the probability of drawing at least one red gumball when drawing two consecutive balls randomly? Select
A) 2/5
B) 16/20
C) 9/10
D) 3/5
E) 1/3
P(at least one red) = 1 - P(no red, so 2 blue) = 1- 2/5*1/4 = 9/10.   Answer: 9/10.
<result>C</result>
In a jar there are 3 red gumballs and 2 blue gumballs. What is the probability of drawing at least one red gumball when drawing two consecutive balls randomly?