Let f(x) = x^2 + bx + c. If f(6) = 0 and f(-2) = 0, then b + c = Choose the correct answer: A) 18 B) 15 C) -16 D) -21 E) -24
f(x) = x^2 + bx + c. If f(6) = 0 and f(-2) = 0, then b + c =   f(6) = 0= 36+6b+c--- Taking 36 to the other side   -&gt; 6b+c= -36   f(-2) =0= 4-2b+c --- taking -2b+c to the other side   -&gt; 2b-c=4   When we add these 2 equations, we get 8b= -32---&gt; b= -4   And while substituting b= -4 we get c= -12.   b+c= -16--- Answer -16
<result>C</result>
Let f(x) = x^2 + bx + c. If f(6) = 0 and f(-2) = 0, then b + c =