If 4 people are selected from a group of 10 married couples, what is the probability that none of them would be married to each other? Choose the correct answer:	A) 1/33	B) 2/63	C) 1/3	D) 43/62	E) 11/12
If we are to select 4 people from 10 couples WITHOUT any restriction, how many ways can we make the selection? 20!/4!16! =4845   If we are to select 4 people from 10 couples WITH restriction that no married couple can both make it to the group, only a representative?   10!/4!6! = 210   But we know that to select a person from each couple, take 2 possibilities     210*2*2*2*2= 
<gadget id="calculator">  210*2*2*2*2</gadget>
<output>3_360</output>
3360   Probability= 43/62esired/All Possibilities =3360/4845 = 43/62   Answer: 43/62
<result>D</result>
If 4 people are selected from a group of 10 married couples, what is the probability that none of them would be married to each other?