A question paper has 2 parts, A & B, each containing 5 questions. If a student has to choose 3 from part A & 4 from part B, in how many ways can he choose the questions?	Options
A) 50	B) 100	C) 152	D) 150	E) 55
There 3 questions in part A out of which 4 question can be chosen as = 5C3.   Similarly, 5 questions can be chosen from 10 questions of Part B as = 5C4.   Hence, total number of ways,   =5C3*5C4   =[5!/(2!3!)]*[5!/(4!*1)]   = {10}*{5*4!/(4!)}   = 10*5= 
<gadget id="calculator">10*5</gadget>
<output>50</output>
50.   50
<result>A</result>
A question paper has 2 parts, A & B, each containing 5 questions. If a student has to choose 3 from part A & 4 from part B, in how many ways can he choose the questions?