A question paper has two parts, A and B, each containing 10 questions. If a student has to choose 8 from part A and 5 from part B, in how many ways can he choose the questions?
Choices.
A) 11340
B) 12750
C) 40
D) 320
E) None
Solution: There 10 questions in part A out of which 8 question can be chosen as = 10C8.   Similarly, 5 questions can be chosen from 10 questions of Part B as = 10C5.   Hence, total number of ways,   =10C8*10C5   =[10!/(2!8!)]*[10!/(5!*5)]   = {10*9/2}*{10*9*8*7*6/(5*4*3*2*1)}   = 1140.   11340nswer: Option 11340
<result>A</result>
A question paper has two parts, A and B, each containing 10 questions. If a student has to choose 8 from part A and 5 from part B, in how many ways can he choose the questions?