27 is a perfect cube. When x is perfect cube which is added to the prime factor of 27, the result is not a prime number. What is the square root of x? Choose the correct choice.
A) 2
B) 4
C) 6
D) 8
E) 10
27 is 3*3*3   2*2= 
<gadget id="calculator">2*2</gadget>
<output>4</output>
4, 3+4=7   4*4= 
<gadget id="calculator">4*4</gadget>
<output>16</output>
16, 3+16=17   6*6= 
<gadget id="calculator">6*6</gadget>
<output>36</output>
36, 3+36=39   8*8= 
<gadget id="calculator">8*8</gadget>
<output>64</output>
64, 3+64=67   10*10= 
<gadget id="calculator">10*10</gadget>
<output>100</output>
100, 3+100=103   here C is the only addition that is not a prime number.   so the answer is 6
<result>C</result>
27 is a perfect cube. When x is perfect cube which is added to the prime factor of 27, the result is not a prime number. What is the square root of x?