Anthony and Michael sit on the six-member board of directors for company R. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?
Choices.
A) 20%	B) 30%	C) 40%	D) 50%	E) 60%
Soln: Let the commitees be I and II   Assuming that Anthony and Michael R go into commitee I, there is just one more place left to be filled in that commitee and it can be taken by any of the 4 remaining people. Thus 4 ways.   Since the Anthony and Michael can also go into commitee II, we get 4 ways for that commitee also.   So in total = 8 ways   Now total number of ways of choosing 3 from 6 people is   = 640%3   = 6 * 5 * 4/3!   = 20 ways   Therefore Probability is = (8 /20) * 100= 
<gadget id="calculator">(8 /20) * 100</gadget>
<output>40</output>
40%
<result>C</result>
Anthony and Michael sit on the six-member board of directors for company R. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?