Three coins are tossed. Find the probability of at least 1 head and 1 tail ?  Pick one.
A) 1/2 B) 1/4 C) 3/4 D) 7/8 E) 1/8
n(s) = 2^3 = 8 ....(3 coins tossed)   let E is the event of getting at least 1 head and 1 tail   n(E) = TTH , HTT, THT, HHT, HTH, THH = 6   P(E) = n(E) / n(s)   = 6/8   = 3/4   Ans- 3/4
<result>C</result>
Three coins are tossed. Find the probability of at least 1 head and 1 tail ?