If n is a natural number, then (6n^2 + 6n) is always divisible by
Choose the correct choice from the following answers:	A) 6 only	B) 6 and 12 both	C) 12 only	D) 18 only	E) 12 and 18 both
(6n^2 + 6n) = 6n(n + 1), which is divisible by both 6 and 12, since n(n+1) is always even.   Answer 6 and 12 both.
<result>B</result>
If n is a natural number, then (6n^2 + 6n) is always divisible by