A certain board game is played by rolling a pair of fair six-sided dice and then moving one's piece forward the number of spaces indicated by the sum showing on the dice. A player is frozen if her opponent's piece comes to rest in the space already occupied by her piece. If player A is about to roll and is currently ten spaces behind player B, what is the probability that player B will be frozen after player A rolls?  Pick one.
A) 1/12  B) 5/36  C) 1/6  D) 1/3  E) 17/36
no. of possible outcomes = 6*6= 
<gadget id="calculator">6*6</gadget>
<output>36</output>
36   no. of outcomes that result a total of 10 (as 1/12 is 10 spaces behind B)= 3 ( (4,6), (5,5), (6,4) )   So, the probability = 3/36 =1/12(Option 1/12)
<result>A</result>
A certain board game is played by rolling a pair of fair six-sided dice and then moving one's piece forward the number of spaces indicated by the sum showing on the dice. A player is frozen if her opponent's piece comes to rest in the space already occupied by her piece. If player A is about to roll and is currently ten spaces behind player B, what is the probability that player B will be frozen after player A rolls?