Given distinct positive integers 1, 11, 5, x, 2, and 9, which of the following could be the median?  Choose the correct choice from the following answers.
A) 3	B) 5	C) 6	D) 8	E) 9
The median of a set with even number of terms is the average of two middle terms when arranged in ascending (or descending) order.   Arrange numbers in ascending order: 1, 2, 5, 9, 11, and x.   Now, x can not possibly be less than 3 as given that all integers are positive and distinct (and we already have 1, 2, and 5).   Next, if x is 5&lt;x&lt;9 then the median will be the average of 5 and x. As all answers for the median are integers, then try odd values for x:   If x=6, then median=(5+6)/2= 
<gadget id="calculator">(5+6)/2</gadget>
<output>11/2 = around 5.5</output>
5.5 --&gt; not among answer choices;   If x=7, then median=(5+7)/2= 
<gadget id="calculator">(5+7)/2</gadget>
<output>6</output>
6 --&gt; OK;   Answer: 6.
<result>C</result>
Given distinct positive integers 1, 11, 5, x, 2, and 9, which of the following could be the median?