A shop sells two variants of chocolates - one that costs $3 and the other that costs $5. If the shop sold $112 chocolates on a given day, how many different combinations of (number of $3 sold, number of $5 sold) exist?  Answers.
A) 6	B) 7	C) 8	D) 12	E) 15
$112 = 20*$5 + 4*$3   We can find other combinations by reducing the $5 chocolates by 3 (which is -$15)and increasing the $3 chocolates by 5 (which is +$15).   The number of $5 chocolates can be 20, 17, 14,...,2 for a total of 7 combinations.   The answer is 7.
<result>B</result>
A shop sells two variants of chocolates - one that costs $3 and the other that costs $5. If the shop sold $112 chocolates on a given day, how many different combinations of (number of $3 sold, number of $5 sold) exist?