A bag contains 3 red and 2 black ball. Another bag contains 4 red and 5 black balls. A ball is drawn from the first bag and is placed in the second. A ball is then drawn from the second. What is the probability that this draw of red ball is due to the drawing of red ball from the first bag ?
Select
A) 3/5
B) 2/5
C) 4/25
D) 3/10
E) 15/23
Probability of getting red ball from bag1 and then red from bag 2 = 3/5*5/10 = 15/50   Probability of getting black ball from bag1 and then red from bag 2 = 2/5*4/10 = 8/50   Now comes the condition, hence apply conditional probability:   P(Red)/ P(Red + Black)   (15/50)/(15/50+8/50) = 15/50 /23/50 = 15/23.   ANSW15/23R:15/23
<result>E</result>
A bag contains 3 red and 2 black ball. Another bag contains 4 red and 5 black balls. A ball is drawn from the first bag and is placed in the second. A ball is then drawn from the second. What is the probability that this draw of red ball is due to the drawing of red ball from the first bag ?