If the sum of 5 consecutive integers is 125, what is sum of the 5 consecutive integers preceding the former sequence? Choose the most appropriate option:
A) 35 B) 25 C) 100 D) 105 E) 103
1) least of each will have a difference of 5 and next least too will have a difference of 5 and so on...   Therefore all 5 terms will have a term LESS by 5..   Sum = 125-(5*5)= 
<gadget id="calculator">125-(5*5)</gadget>
<output>100</output>
100   2.) if sum is 125, the average= median = 125/5= 
<gadget id="calculator">125/5</gadget>
<output>25</output>
25. The median of previous 5 will be 25-5= 
<gadget id="calculator">25-5</gadget>
<output>20</output>
20.   And sum would be   20*5= 
<gadget id="calculator">  20*5</gadget>
<output>100</output>
100   Answer: 100
<result>C</result>
If the sum of 5 consecutive integers is 125, what is sum of the 5 consecutive integers preceding the former sequence?