What is the equation of a circle of radius 8 units centered at (3, 2)?  Choices:
A) x^2 + y^2 + 6x – 4y = 23	B) x^2 + y^2 - 6x + 4y = 23	C) x^2 + y^2 + 6x + 4y = 23	D) x^2 + y^2 - 6x – 4y = 51	E) x^2 + y^2 - 6x – 4y = - 23
the equation of a circle with center at (a,b) and radius R is (X-a)^2+(Y-b)^2=R^2   =&gt; answer = (X-3)^2+(Y-2)^2=8^2   solving,,we get the equation in answer choice x^2 + y^2 - 6x – 4y = 51
<result>D</result>
What is the equation of a circle of radius 8 units centered at (3, 2)?