If a number between 10 and 60 (inclusive) at random. What is the probability that the tens digit is greater than ones digit?
Pick one: A) 31/41 B) 1041 C) 14/41 D) 27/41 E) 16/51
If tens digi is 6 ---&gt; ones digit : 0   If tens digi is 5 ---&gt; ones digit : 0, 1, 2, 3, 4   If tens digi is 4 ---&gt; ones digit : 0, 1, 2, 3   If tens digi is 3 ---&gt; ones digit : 0, 1, 2   If tens digi is 2 ---&gt; ones digit : 0, 1   If tens digi is 1 ---&gt; ones digit : 0   So the number of numbers whose tens digit is greater than ones digit is 11.   The total number is   60-10+1= 
<gadget id="calculator">  60-10+1</gadget>
<output>51</output>
51.   So the probability is 16/51.   The answer is (16/51).
<result>E</result>
If a number between 10 and 60 (inclusive) at random. What is the probability that the tens digit is greater than ones digit?