In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is: Select:
A) 21/46
B) 20/81
C) 50/90
D) 83/96
E) 24/81
Let S be the sample space and E be the event of selecting 1 girl and 2 boys.   Then, n(S)	= Number ways of selecting 3 students out of 25   = 25C3 `   =(25 x 24 x 23)   (3 x 2 x 1)   = 2300.   n(E)	= (10C1 x 15C2)   =[10 x(15 x 14)/(2 x 1)]   = 1050.   P(E) = n(E)/n(S) = 1050/2300 = 21/46.   21/46nswer:21/46
<result>A</result>
In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is: