Tough and Tricky questions: Exponents.
If 7^(3x-1)*3^(4y-3) = 49^x*27^y, then x + y =  Choose the most appropriate option.
A) 3 B) 4 C) 2 D) 1 E) 5
Here is my solution.   7^(3x-1)*3^(4y-3) = 49^x*27^y   Here RHS 49^x*27^y= 7^(2x)*3^(3y)   Equating powers on both sides--&gt;   3x-1=2x , thus x 3 -1= 
<gadget id="calculator"> 3 -1</gadget>
<output>2</output>
2x , thus x=1 and   4y-3=3y giving y=3   So, x+y=4   Option: 4
<result>B</result>
Tough and Tricky questions: Exponents.
If 7^(3x-1)*3^(4y-3) = 49^x*27^y, then x + y =