A car starts from X and moves towards Y. At the same time another car starts from Y and moves towards X. Both travel at a constant speed and meet after 10 hours. During that time, the faster car traveled 2/3 of the distance XY. How long would it take the slower car to travel the distance XY?	Select:
A) 6 hours
B) 8 hours
C) 30 hours
D) 12 hours
E) 15 hours
If one car travelled 2/3, then the other car must have travelled only 1/3, as they are meeting after 10 hours in a certain point. So:   (1/3)XY= 10*y --&gt; It took the car 10 hours to travel 1/3 of the distance at a constant speed y.   So if we solve this last equation:   XY= 3*10*y= 30*y --&gt; It will take this car 30 hours in total to reach its final destination.   Answer: 30 hours
<result>C</result>
A car starts from X and moves towards Y. At the same time another car starts from Y and moves towards X. Both travel at a constant speed and meet after 10 hours. During that time, the faster car traveled 2/3 of the distance XY. How long would it take the slower car to travel the distance XY?