In a box, there are 10 red, 8 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?	Choose the correct choice from the following options.
A) 4/51	B) 10/21	C) 8/23	D) 11/31	E) 13/17
Total number of balls = 10+8+5= 
<gadget id="calculator">10+8+5</gadget>
<output>23</output>
23   E= event that the ball drawn is neither red nor green   = event that the ball drawn is red   n(E) = 8   P(E) = 8/23   Answer is 8/23
<result>C</result>
In a box, there are 10 red, 8 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?