In a committee there are 15 men and 10 women. If three members are selected randomly then what is the probability that 1 women and 2 men are selected? Choose the correct answer
A) 20/35	B) 21/31	C) 21/46	D) 11/21	E) 11/23
Let S be the sample space and E be the event of selecting 1 girl and 2 boys.   Then, n(S)	= Number ways of selecting 3 students out of 25   = 25C3 `   =	(25 x 24 x 23)   (3 x 2 x 1)   = 2300.   n(E)	= (10C1 x 15C2)   = 10 x	(15 x 14)   (2 x 1)   = 1050.   P(E) =	n(E)	=	1050	= 21/46   n(S)	2300   21/46
<result>C</result>
In a committee there are 15 men and 10 women. If three members are selected randomly then what is the probability that 1 women and 2 men are selected?