what is the remainder when 30^72^87 is divided by 11. Choose the correct answer.
A) 5  B) 7  C) 1  D) 3  E) 4
let us take N=72^87   eq is..30^N/11=8^N/11   here cyclicity of 8 is 10   then N/10=72^87/10=2^87/10   here cyclicity of 2 is   then 87%4=3(3rd cycle of 2)....i.e2^3%10=8(8th cycle of8)   therefore final ans is 8^8%11=5   5NSWER:5
<result>A</result>
what is the remainder when 30^72^87 is divided by 11.