Line Q has the equation 5y – 3x = 15. If Line S is perpendicular to Q, has an integer for its y-intercept, and intersects Q in the second quadrant, then how many possible Line S’s exist? (Note: Intersections on one of the axes do not count.)  Choose the correct choice from the following options
A) 9  B) 11  C) 13  D) 15  E) 17
5y - 3x = 15 and so y = 3x/5 + 3   When x = 0, then y = 3.   When y = 0, then x = -5   The slope is 3/5, so the slope of line S is -5/3.   Through the point (-5, 0), 0 = -5(-5)/3 + c   The y-intercept is c = -25/3 &lt; -8.   Thus the perpendicular line S can have y-intercepts from -8 up to 2.   The number of possible lines is   8 + 2 + 1= 
<gadget id="calculator">  8 + 2 + 1</gadget>
<output>11</output>
11   The answer is 11.
<result>B</result>
Line Q has the equation 5y – 3x = 15. If Line S is perpendicular to Q, has an integer for its y-intercept, and intersects Q in the second quadrant, then how many possible Line S’s exist? (Note: Intersections on one of the axes do not count.)