In a box of 12 pens, a total of 4 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?
Choose the correct choice: A) 1/6 B) 2/33 C) 14/33 D) 9/16 E) 3/44
Method- 1   There are 9 fine pieces of pen and 4 defective in a lot of 12 pens   i.e. Probability of first pen NOT being defective = (8/12)   i.e. Probability of Second pen NOT being defective = (7/11) [11 pen remaining with 8 defective remaining considering that first was defective]   Probability of Both pen being NON-defective = (8/12)*(7/11) = 14/33   Answer: option 14/33
<result>C</result>
In a box of 12 pens, a total of 4 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?