If d=1/(2^3*5^10) is expressed as a terminating decimal, how many nonzero digits will d have?
Choose the most appropriate option.
A) One B) Two C) Three D) Seven E) Ten
Another way to do it is :   We know x^a*y^a=(X*Y)^a   given = 1/(2^3*5^10)   = Multiply and divide by 2^7   =2^7/(2^3*2^7*5^10)   =2^7/10^10   =&gt; non zero digits are 128 =&gt; Ans Three
<result>C</result>
If d=1/(2^3*5^10) is expressed as a terminating decimal, how many nonzero digits will d have?