How many five-digit numbers are there, if the two leftmost digits are even, the other digits are odd and the digit 4 cannot appear more than once in the number?	Answers:  A) 1375  B) 8451  C) 1546  D) 2375  E) 3215
Total five-digit numbers with two even leftmost digits and with three odd last digits: EEOOO - 4*5*5*5*5=4*5^4 (notice that we have only 4 choices for the first digit since we cannot use zero);   Total five-digit numbers with two 4's as leftmost digits and with three odd last digits: 44OOO - 5*5*5=5^3;   So, the answer is 4*5^4-5^3=5^3(4*5-1)=125*19= 
<gadget id="calculator">125*19</gadget>
<output>2_375</output>
2375.   Answer: 2375.
<result>D</result>
How many five-digit numbers are there, if the two leftmost digits are even, the other digits are odd and the digit 4 cannot appear more than once in the number?