Let a be a positive integer. If t is divisible by 2^a and t is also divisible by 3^(2a), then it is possible that t is NOT divisible by  Select:
A) 6  B) 3 × 2^a  C) 2 × 3^(2a)  D) 6^a  E) 6^(2a)
Since, t is divisible by 2^a and 3^(2a), it must be divisible by 6. As least value of a = 1   Only for 6^(2a), 6^(2a) doesn't satisfy, if a = 1 and t=18, it is not divisible by 6^2 (i.e 36)   Hence answer is 6^(2a)
<result>E</result>
Let a be a positive integer. If t is divisible by 2^a and t is also divisible by 3^(2a), then it is possible that t is NOT divisible by