David has s pairs of shoes, which is 1/4 as many as Mary and twice as many as Jones. In terms of s, how many pairs of shoes do the three of them have combined?  Options
A) 9/2*s	B) 7/2*s	C) 3s	D) 11/2*s	E) 5/2*s
== s +4s + s/2 ==&gt; 5s + 1/2 s = 11/2*s   Ans .11/2*s
<result>D</result>
David has s pairs of shoes, which is 1/4 as many as Mary and twice as many as Jones. In terms of s, how many pairs of shoes do the three of them have combined?