When a natural number N is successively divided by 1,2,3,4 the remainders are 5,6,7,8. What will be the sum of the remainders if the order of the division is reversed?	Select the correct option:
A) 11
B) 12
C) 10
D) 2
E) 7
1 2 3 4   5 6 7 8   leave the top right- most number 8   start with bottom right-most number 5   8*3+7= 
<gadget id="calculator">8*3+7</gadget>
<output>31</output>
31   31*2+6= 
<gadget id="calculator">31*2+6</gadget>
<output>68</output>
68   68*1+5= 
<gadget id="calculator">68*1+5</gadget>
<output>73</output>
73   this is the number required   Now, do the successive division in the reverse order   The sum of the remainders is 10   Hence, the correct option is 10
<result>C</result>
When a natural number N is successively divided by 1,2,3,4 the remainders are 5,6,7,8. What will be the sum of the remainders if the order of the division is reversed?