A meeting has to be conducted with 5 managers.Find the number of ways in which the managers may be selected from among 9 managers,if 3 managers will not attend the meeting together. Choose the correct choice from the following:	A) 1.24	B) 2.91	C) 3.12	D) 4.126	E) 5.15
9 managers, but 3 of them cannot attend the meeting together.   We can split it into two cases.   1. Meeting without these 3 managers in it. That would mean selecting 5, from the remaining 6 which is 6C5 = 6   2. Meeting with one of the 3 managers. select 1 manager from 3, and then select 4 from the remaining 6, which is 3C1 + 6C4 = 18 + 6= 
<gadget id="calculator">18 + 6</gadget>
<output>24</output>
24.   1.24nswer : 1.24
<result>A</result>
A meeting has to be conducted with 5 managers.Find the number of ways in which the managers may be selected from among 9 managers,if 3 managers will not attend the meeting together.