In how many ways can 7 different object be divided among three persons so that either one or two of them do not get any object?	Choose one:
A) 351  B) 361  C) 371  D) 391  E) 381
Case 1: Two guys don't get anything. All items go to 1 person. Hence, 3 ways.   Case 2: 1 guy doesn't get anything. Division of 7 items among 2 guys. Lets say they are called A &amp; B.   a) A gets 6. B gets 1. 7 ways.   b) A gets 5. B gets 2. 21 ways.   c) A gets 4. B gets 3. 35 ways.   d) A gets 3. B gets 4. 35 ways.   e) A gets 2. B gets 5. 21 ways.   f) A gets 1. B gets 6. 7 ways.   Total = 126 ways to divide 7 items between A &amp; B.   Total number of ways for case 2 = 126*3= 
<gadget id="calculator">126*3</gadget>
<output>378</output>
378 (Either A, or B, or C don't get anything).   Answer= Case 1 + Case 2 = 3 + 378= 
<gadget id="calculator">3 + 378</gadget>
<output>381</output>
381   ANSW381R:381
<result>E</result>
In how many ways can 7 different object be divided among three persons so that either one or two of them do not get any object?