How many different arrangements of A, B, C, D, and E are possible where B and D is not adjacent to E?  Choose the correct choice
A) 96  B) 72  C) 32  D) 30  E) 1
So you have A,72,C,D,E   five possible ways to arrange it = 5! = 120   A,72,C,(DE) = 4! = 24 x 2 = 48   120 -48= 
<gadget id="calculator">120 -48</gadget>
<output>72</output>
72 possible ways   72
<result>B</result>
How many different arrangements of A, B, C, D, and E are possible where B and D is not adjacent to E?