Jim is twice as old as Stephanie, who, four years ago, was three times as old as Kate. If, five years from now, the sum E of their ages will be 51, how old is Stephanie ?  Choose the correct choice from the following options:
A) 6
B) 10
C) 14
D) 20
E) 24
1) take C (14y.o.), so mean that S=14, J=28, their sum itself is 42+10 years from now is 52, it is over the 51,   so eliminate C,D,E   2) take B (10y.o.),E= meaning S=10,J=20, so  20+10+10= 
<gadget id="calculator"> 20+10+10</gadget>
<output>40</output>
40 and for K=10-4/3=2+9= 
<gadget id="calculator">2+9</gadget>
<output>11</output>
11, finally 40+11= 
<gadget id="calculator">40+11</gadget>
<output>51</output>
51. It is correct   10
<result>B</result>
Jim is twice as old as Stephanie, who, four years ago, was three times as old as Kate. If, five years from now, the sum E of their ages will be 51, how old is Stephanie ?