What is the value of X, if
1/(log442/441 X) + 1/(log443/442 X) + 1/(log444/443 X) +…+ 1/(log899/898 X) +1/(log900/899 X) = 2?  Choose the correct choice
A) 2/21	B) 1	C) 7/100	D) 10/7	E) None of these
The given equation   = 1/(log442/441 X) = (log442/441)/logX = logX 442/441.   = logX 442/441 + logX 443/442 + logX 444/443 +......+ logX 899/898 + logX 900/899 = 2.   = logX 900/441 = 2   =&gt;X2 = 900/441   =&gt;X = 30/21 = 10/7.   ANSWER:10/7
<result>D</result>
What is the value of X, if
1/(log442/441 X) + 1/(log443/442 X) + 1/(log444/443 X) +…+ 1/(log899/898 X) +1/(log900/899 X) = 2?