Five kilograms of oranges contained 95% of water. If the next day the concentration of water decreased by 5%, what was the new weight of the oranges, in kilograms?	Select the correct option.
A) 30 B) 25 C) 15 D) 10 E) 5
Five kilograms of oranges contained 95% of water. If the next day the concentration of water decreased by 5%, what was the new weight of the oranges, in kilograms?   (A) 30   (B) 25   (C) 15   (D) 10   (E) 5   If B is the answer, then the question means that the concentration of water the newt day became 90%.   Out of 5 kilograms 95%, or 4.75 kilograms was water and 0.25 kilograms was non-water.   The next day, after some water evaporated, oranges became 90% water and 10% of non-water, so the next day 0.25 kilograms of non-water composed 10% of oranges, which means that the new weight of the oranges was x*0.10=0.25 --&gt; x=25 kilograms.   Answer: 25.
<result>B</result>
Five kilograms of oranges contained 95% of water. If the next day the concentration of water decreased by 5%, what was the new weight of the oranges, in kilograms?