If P, Q, and R are distinct positive digits and the product of the two-digit integers PQ and PR is 221, what is the sum of the digits P, Q, and R?
Options.
A) 5
B) 11
C) 13
D) 21
E) 23
Factor out 221   221=13*17   Thus PQ=13 &amp; PR = 17 or vice versa   Thus P=1, Q=3 &amp; R=7   Sum=1+3+7= 
<gadget id="calculator">1+3+7</gadget>
<output>11</output>
11   Answer: 11
<result>B</result>
If P, Q, and R are distinct positive digits and the product of the two-digit integers PQ and PR is 221, what is the sum of the digits P, Q, and R?