Ms. Barton has four children. You are told correctly that she has at least two girls but you are not told which two of her four children are those girls. What is the probability that she also has two boys? (Assume that the probability of having a boy is the same as the probability of having a girl.
Select.
A) 1/4
B) 3/8
C) 5/11
D) 1/2
E) 6/11
Assume that there are 4 Ms. Barton's children in a row: 1-2-3-4. Let show all possible combinations of them being girl(G) or boy(B) giving that there at least two girls. We are seeing each child 1,2,3,4 a s a unique(so, we distinguish between them)   BBGG   BGBG   GBBG   BGGB   GBGB   GGBB   BGGG   GBGG   GGBG   GGGB   GGGG   Overall 11 variants. 6 of them satisfy the condition of 2 boys exactly (they are highlighted in bold)   Therefore the probability is 6/11   Answer:6/11
<result>E</result>
Ms. Barton has four children. You are told correctly that she has at least two girls but you are not told which two of her four children are those girls. What is the probability that she also has two boys? (Assume that the probability of having a boy is the same as the probability of having a girl.