In a bag contains 8 White balls and 6 black balls from the bag two balls are taken out at random. Find the Probability that they are of the same color ?  Pick one.
A) 43/91
B) 45/91
C) 52/91
D) 61/91
E) 47/91
Here S be the sample space so,   n(S) = Number of ways of taken out balls of (8+6)= 
<gadget id="calculator">(8+6)</gadget>
<output>14</output>
14C2= (14X13)/(2X1)   = 182/2= 
<gadget id="calculator">182/2</gadget>
<output>91</output>
91   E= Event of getting both balls of the same color   Then,n (E) = Number of ways of drawing (2 balls out of 8) or (2 balls out of 6)   = (8C2 + 6C2) = 8 x 7/2 x1 + 6x5/2x1 = 56 /2 + 30/2 = 28 +15= 
<gadget id="calculator">28 +15</gadget>
<output>43</output>
43   P(E)= n(E) / n(S) = 43/91   43/91nswer is 43/91
<result>A</result>
In a bag contains 8 White balls and 6 black balls from the bag two balls are taken out at random. Find the Probability that they are of the same color ?