If x= (10^50) - 57, what is the sum of all the digits of x? Pick one:
A) 390 B) 418 C) 420 D) 439 E) 449
10^2 100-57=43 (result of two digits number)   10^3 1000-57=943 (result of three digits number)   10^4 10000-57=9943 (result of four digits number)   and so on... until 10^50   The result of the subtraction becomes a 50 digits number composed by 48 pairs of 9 followed by a 4 and 5. Therefore   48*9= 
<gadget id="calculator">  48*9</gadget>
<output>432</output>
432 and 432+(4+5)=439   The correct answer is 439.
<result>D</result>
If x= (10^50) - 57, what is the sum of all the digits of x?