The sum of all two digit numbers divisible by 8 is
Pick:	A) 910	B) 510	C) 611	D) 616	E) 810
Required numbers are 16,24 . . . . . 96   This is an A.P. in which a=16,d=8 and l=96.   Let the number of terms in it be n.Then t=96   So a+(n-1)d=96.   16+(n-1)*8=96   16+8n-8=96   8+8n=96   8n=96-8= 
<gadget id="calculator">96-8</gadget>
<output>88</output>
88/8= 
<gadget id="calculator">88/8</gadget>
<output>11</output>
11.   Required sum=n/2(a+l)   =11/2(16+96)   =616   Answer is 616
<result>D</result>
The sum of all two digit numbers divisible by 8 is