A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to 5^12 and 5^16, respectively, what is the value of A?	Choose the correct answer.
A) -24(5^12)
B) -27(5^12)
C) -24(5^6)
D) 23(5^12)
E) 24(5^12)
Ans : B   Assume that the numbers appear as shown below on the number line   A-----B-----C-----D-----E-----F-----G-----H   (5^12) (5^13)   As the values for G and H are given , we can calculate the difference between any two terms of the series .   Common Difference ,d = (5^13) - (5^12)   = (5^12) *[ 5-1 ]   = (5^12)*(4)   Also F + d = G as the terms are in equidistant and in increasing order.   So F + (5^12)*(4) = (5^12).   That is , F = (5^12) - (5^12)*(4)   = (5^12)[ 1-4]   = (5^12) (-3)   Similarly , E = F - d   = (5^12)[-3-4]   = (5^12)*(-7)   You can see a -4 getting added to the non-exponent part of the values . That is , according to the pattern , D SHOULD -27(5^12)E (5^12)*(-7-4)= (5^12)*(-11)   Following this pattern , A = (5^12)*(-27)   -27(5^12)
<result>B</result>
A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to 5^12 and 5^16, respectively, what is the value of A?