If -1<x<0, what is the median J of these six numbers listed below
1/x^3,1/x^2, 1/x,x, x^2,x^3  Choices:
A) 1/x	B) x^2	C) x^2(x+1)/2	D) J=x(x^2+1)/2	E) x^2/2x
My approach: Put any value between -1 and 0. you will get the answer. lets say 0.5. so the list will be as follows:   -8,-2,-0.5,-0.125 and last two numbers will be positive so need to see that.   median will be between -0.5 and -0.125.   So, (x^3+x)/2 (J=x(x^2+1)/2).
<result>D</result>
If -1<x<0, what is the median J of these six numbers listed below
1/x^3,1/x^2, 1/x,x, x^2,x^3