If x is a positive, single-digit integer such that 4/3*x, 2x, x, and x + 2, and 4x – 2 form a non-ordered list of consecutive integers, which of the following could be the median of that list?  Answers
A) 3 B) 4 C) 5 D) 6 E) 8
The big hints are thatx is a 1-digit integerAND (4/3)x, 2x, x, and x + 2, and 4x – 2 are ALLintegers   For (4/3)x to be an integer, x MUST BE A MULTIPLE OF 3. So, x can equal 3, 6, or 9.   Now let's plug each possible value of x into the terms and see which one yields a list ofconsecutive integers   When x =3, we get the following terms: (4/3)(3), 2(3),3,3+ 2, and 3(3) – 2.   When we evaluate these terms we get: 4, 6, 3, 5 and 10   Rearrange to get: 3, 4, 5, 6, 10. So, when x = 3, we getconsecutive integers.   In this case, the MEDIAN = 5   Since 5 is among the answer choices, we need not test the other 2 values of x (i.e., x = 6 and x = 9)   Answer:   5
<result>C</result>
If x is a positive, single-digit integer such that 4/3*x, 2x, x, and x + 2, and 4x – 2 form a non-ordered list of consecutive integers, which of the following could be the median of that list?