In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term. What is the sum of the 15th, 17th, and 18th terms in the sequence?
Choose the correct choice from the following options: A) 2^18 B) 3(2^17) C) 7(2^16) D) 13(2^14) E) 7(2^15)
the sequence comes out to be 2^0,2^1,2^2,2^3 and so on...   so 15th term will be 2^14   17th term 2^16   18th term 2^17   adding all three   we get   2^14+(2^15)*4+(2^15)*8   so answer is 2^15(1+4+8)=&gt;13(2^15)   answer 13(2^14)
<result>D</result>
In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term. What is the sum of the 15th, 17th, and 18th terms in the sequence?