A basketball player succeeds with 80% of her free throws. If she has a set of three free throws, what is the probability that she succeeds at least once?
Choose the correct choice from the following choices:
A) 0.972  B) 0.978  C) 0.984  D) 0.992  E) 0.998
P(missing all 3 free throws) = 0.2^3 = 0.008   P(succeeding at least once) = 1 - 0.008= 
<gadget id="calculator">1 - 0.008</gadget>
<output>0.992</output>
0.992   The answer is 0.992.
<result>D</result>
A basketball player succeeds with 80% of her free throws. If she has a set of three free throws, what is the probability that she succeeds at least once?