The present ages of A,B & C are in proportions 4:7:9. 8 years ago, the sum of their ages was 56. What are their present ages? Choose the correct choice from the following answers:
A) 10,20 and 36
B) 16,22 and 36
C) 16,28 and 36
D) 14,18 and 36
E) None
Let present age of A,B and C be 4x,7x and 9x respectively.   (4x−8)+(7x−8)+(9x−8)=56⇒20x=80⇒x=4   Hence present age of A, B and C are   4×4, 7×4 and 9×4 respectively.   i.e., 16,28 and 36 respectively.   16,28 and 36
<result>C</result>
The present ages of A,B & C are in proportions 4:7:9. 8 years ago, the sum of their ages was 56. What are their present ages?