Find the sum of the number of combinations possible by using 1,2,3,4 such that no number is repeated(ex:- 1223,4322 are invalid 1234,4321 are valid)more than once. Pick one:
A) 66660	B) 66760	C) 66860	D) 66960	E) 67660
total no. formed = 4!=4*3*2*1= 
<gadget id="calculator">4*3*2*1</gadget>
<output>24</output>
24   each digit will be used at each positions, 6 times   sum of digits at unit place= 6*1+6*2+6*3+6*4 = 6*(1+2+3+4)= 
<gadget id="calculator">6*(1+2+3+4)</gadget>
<output>60</output>
60   this sum will be same for hundred, tens &amp; unit places   sum of all 4 digit numbers formed using digits 1,2,3,4= 1000*60+100*60+10*60+60   =60*(1000+100+10+1)   =60*1111= 
<gadget id="calculator">60*1111</gadget>
<output>66_660</output>
66660   66660NSWER:66660
<result>A</result>
Find the sum of the number of combinations possible by using 1,2,3,4 such that no number is repeated(ex:- 1223,4322 are invalid 1234,4321 are valid)more than once.