a goes to place x and b goes to place y.
after a travelled 180 km more than b they together meet at a point between xy. they together had their lunch for half an hour. after that a took 2 hrs to reach x and b took 4.5 hrs to reach y. find distance between x and y? Choose the correct choice from the following answers.
A) 900km
B) 540km
C) 720km
D) 820km
E) 920km
let speed of 900km be-------Sa   let speed of B be--------Sb   let the distance covered by B while going to position XY be-----------x   so distance covered by 900km in same time while going to XY is----------180 +x(it's given in the question)   so total distance b/w X and Y is=x+(x+180)   while going to position XY :-   time taken by 900km = time taken by B   (x+180)/Sa= x/Sb   Sa/Sb=(x+180)/x---------------------1   900kmfter lunch:-   900km.C.T(according to question)   Sa=x/2   Sb=(x+180)/4.5   dividing Sa/Sb=(x*4.5) / ((x+180)*2)--------------------2   equating equations 1 and 2   9/4 = (x+180)^2 / x^2   now taking square root on both sides we get   3/2 = (x+180) / x   x=360   therefore distance between x and y =x+(x+180)=900km   900kmNSWER:900km
<result>A</result>
a goes to place x and b goes to place y.
after a travelled 180 km more than b they together meet at a point between xy. they together had their lunch for half an hour. after that a took 2 hrs to reach x and b took 4.5 hrs to reach y. find distance between x and y?