What is theleast number should be added to 1056, so the sum of the number is completely divisible by 23?	Pick one
A) 20	B) 23	C) 25	D) 27	E) 28
(1056 / 23) gives remainder 21   21 + 2= 
<gadget id="calculator">21 + 2</gadget>
<output>23</output>
23, So we need to add 2   23
<result>B</result>
What is theleast number should be added to 1056, so the sum of the number is completely divisible by 23?