If two numbers are in the ratio 5:3. If 10 is Reduced to both of the numbers then the ratio becomes 2:1 then find the smallest number?
Choose the most appropriate option:	A) 15	B) 20	C) 30	D) 34	E) 36
5:3   5x - 10 : 3x - 10 = 2 : 1   1[5x - 10] = 2[3x - 10]   5x - 10 = 6x - 20   6x - 5x = 20 - 10= 
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
10   the small number is= 3   3x = 30 (Answer = 30)   Short cut method:   a:b = 5:3   c:d = 2:1   1.Cross multiplication with both ratios   a * d ~ b * c = 5 * 1 ~ 3 * 2 = 5 ~ 6 = 1   2. If 10 is reduced both the number means  10 * 2= 
<gadget id="calculator"> 10 * 2</gadget>
<output>20</output>
20 and   10 * 1= 
<gadget id="calculator">  10 * 1</gadget>
<output>10</output>
10,   Then 20 ~ 10= 10   ===&gt; 1 -----&gt; 10   ===&gt; 3 -----&gt; 30 (Answer is = 30)   30
<result>C</result>
If two numbers are in the ratio 5:3. If 10 is Reduced to both of the numbers then the ratio becomes 2:1 then find the smallest number?