5 cats are about to jump on 5 different mice. What is the probability that exactly one cat will jump on a single mouse?  Choose the correct answer:
A) 5*5
B) 1/5!
C) 5!/5^5
D) 5!/5^2
E) 1/5^5
Each cat out of 5 has 5 options, hence total # of outcomes is 5^5;   Favorable outcomes will be 5!, which is # of ways to assign 5 different mice to 5 cats:   1-2-3-4-5 (mice)   A-B-C-D-E (cats)   B-A-C-D-E (cats)   B-C-A-D-E (cats)   ...   So basically # of arrangements of 5 distinct objects: 5!.   P=favorable/total=5!/5^5   Answer: 5!/5^5.
<result>C</result>
5 cats are about to jump on 5 different mice. What is the probability that exactly one cat will jump on a single mouse?