Of the 11 members of a football team in school, 9 are trained to play the offensive position, 6 can play defensive position, and 4 can play both position. If one member is chosen at random, what is the probability that the member chosen will be someone who play either position ?
Choose one
A) a) 3/11	B) b) 4/11	C) c) 0	D) d) 6/11	E) e) 7/11
You know how to solve for Total number of people who can play at one position:   Total = n(A) + n(B) - n(A and B)   Total people who can play at least one position = 9+6-4= 
<gadget id="calculator">9+6-4</gadget>
<output>11</output>
11   So all 11 people know how to play at least one position. Hence, if you pick anyone, the probability is 0 that he wouldn't know how to play any position   Answer (c) 0)
<result>C</result>
Of the 11 members of a football team in school, 9 are trained to play the offensive position, 6 can play defensive position, and 4 can play both position. If one member is chosen at random, what is the probability that the member chosen will be someone who play either position ?