How many different number-plates for cars can be made if each number-plate contains four of the digits 0 to 9 followed by a letter A to Z, assuming that
(a) no repetition of digits is allowed?
Select.
A) 131040	B) 116700	C) 142369	D) 147225	E) 132547
we want 4 digit of cars and repetition is not allowed   1st digit can be fill with 0 to 9 i.e = 10   2nd digit can be fill with 0 to 9 except earlier selected i.e = 9   3rd digit can be fill with 0 to 9 except earlier selected i.e = 8   4th digit can be fill with 0 to 9 except earlier selected i.e = 7   No of ways = 10 * 9 * 8 * 7 * (total aplphabets)   = 5040 * 26   = 1,31,040   131040ns - 131040
<result>A</result>
How many different number-plates for cars can be made if each number-plate contains four of the digits 0 to 9 followed by a letter A to Z, assuming that
(a) no repetition of digits is allowed?