If the sum of two numbers is 45 and the L.C.M and sum of the reciprocal of the numbers are 120 and 11/120 then HCF of numbers is equal to: Choices.
A) 55	B) 5	C) 10	D) 45	E) 4
Let the numbers be a and b and HCF is x,   Then, a + b = 45 and ab = x * 120 = 120x   Required sum = 1/a + 1/b = (a + b)/ab = 45/120x = 11/120.   x=5.   ANSWER:5
<result>B</result>
If the sum of two numbers is 45 and the L.C.M and sum of the reciprocal of the numbers are 120 and 11/120 then HCF of numbers is equal to: