Operation # is defined as: a # b = 4a^2 + 4b^2 + 8ab for all non-negative integers. What is the value of (a + b) + 4, when a # b = 100?	Choose the correct option
A) 5  B) 9  C) 10  D) 13  E) 17
OFFICIAL SOLUTION:   (B) We know that a # b = 100 and a # b = 4a² + 4b² + 8ab. So   4a² + 4b² + 8ab = 100   We can see that 4a² + 4b² + 8ab is a well-known formula for (2a + 2b)². Therefore   (2a + 2b)² = 100.   (2a + 2b) is non-negative number, since both a and b are non-negative numbers. So we can conclude that 2(a + b) = 10. (a + b) + 4 = 10/2 + 4= 
<gadget id="calculator">10/2 + 4</gadget>
<output>9</output>
9.   The correct answer is 9.
<result>B</result>
Operation # is defined as: a # b = 4a^2 + 4b^2 + 8ab for all non-negative integers. What is the value of (a + b) + 4, when a # b = 100?