In a box, there are 9 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?
Pick.
A) 2/3
B) 8/21
C) 3/7
D) 9/22
E) 10/21
Explanation:   Total number of balls = (9 + 7 + 6)= 
<gadget id="calculator">(9 + 7 + 6)</gadget>
<output>22</output>
22   Let E= event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.   Therefore, n(E) = 8.   P(E) = 9/22.   Answer: Option 9/22
<result>D</result>
In a box, there are 9 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?