A train travels from station A to station B. If the train leaves station A and makes 75 km/hr, it arrives at station B 48 minutes ahead of scheduled. If it made 50 km/hr, then by the scheduled time of arrival it would still have 40 km more to go to station B. Find:
A) The distance between the two stations;
B) The time it takes the train to travel from A to B according to the schedule;
C) The speed of the train when it's on schedule.	Options.
A) 34  B) 27  C) 26  D) 28  E) 60
Let xx be the scheduled time for the trip from A to B. Then the distance between A and B can be found in two ways. On one hand, this distance equals 75(x−4860)75(x−4860) km. On the other hand, it is 50x+4050x+40 km. So we get the equation:   75(x−4860)=50x+4075(x−4860)=50x+40   x=4x=4 hr is the scheduled travel time. The distance between the two stations is 50⋅4+40=24050⋅4+40=240 km. Then the speed the train must keep to be on schedule is 2404=602404=60 km/hr.   Answer:60
<result>E</result>
A train travels from station A to station B. If the train leaves station A and makes 75 km/hr, it arrives at station B 48 minutes ahead of scheduled. If it made 50 km/hr, then by the scheduled time of arrival it would still have 40 km more to go to station B. Find:
A) The distance between the two stations;
B) The time it takes the train to travel from A to B according to the schedule;
C) The speed of the train when it's on schedule.