9 people will pick a number between 1 and 9. What is the probability that exactly one person will pick a different number?
Pick:
A) 1/9	B) 1/9*9	C) 1/9!	D) 9!/9	E) 9!/9^9
Each person out of 9 has 9 options, hence total # of outcomes is 9^9;   Favorable outcomes will be 9!, which is # of ways to assign 9 different number to 9 people.   P=favorable/total=9!/9^9   Answer: 9!/9^9.
<result>E</result>
9 people will pick a number between 1 and 9. What is the probability that exactly one person will pick a different number?