What are the last two digits of 63*35*37*82*71*41?  Choose the correct choice:
A) 10  B) 30  C) 40  D) 70  E) 80
First, multiplied 82 and 35, since 2 and 5 will give a 0 in the end. Got last 2 digits 70.   no need to multiply 70 by 41 and 71, since they wont change the last 2 digits (try if you want to, but effective multiplication in case of 41 and 71 is only with 1).   Now, 70 * 3(of 63) gives : last 2 digits as 10.   lastly, 10 * 7(of 37) gives : last 2 digits 70.   ANSWER:70
<result>D</result>
What are the last two digits of 63*35*37*82*71*41?