There are six different models that are to appear in a fashion show. Two are from Europe, two are from South America, and two are from North America. If all the models from the same continent are to stand next to each other, how many ways can the fashion show organizer arrange the models? Select the correct option.
A) 72  B) 48  C) 64  D) 24  E) 8
Let's say that Models of Europe are represented by E1 and E2 respectively   Let's say that Models of South America are represented by S1 and S2   Let's say that Models of North America are represented by Na and N2   So we have to define the total ways of entries of E1 E2 S1 S2 N1 N2   We have to keep E1 E2 together and similarly N1 N2 together and similarly S1 S2 together so make three groups of two models from same region each   Arrangement of these three Group can be done in 3! ways   Arrangement of Models within Group can be done in 2!x2!x2! ways   i.e. Total Ways of Arranging the models so that they are grouped as per region together = (3!)*(2!x2!x2!) = 6*8= 
<gadget id="calculator">6*8</gadget>
<output>48</output>
48   Answer: Option 48
<result>B</result>
There are six different models that are to appear in a fashion show. Two are from Europe, two are from South America, and two are from North America. If all the models from the same continent are to stand next to each other, how many ways can the fashion show organizer arrange the models?