Two persons C & D started traveling from A and B which are 300 km apart, towards B and A respectively at 1.00 p.m. C travels at a constant speed of 30 kmph whereas D doubles his speed every hour. If D reaches A in 4 5/8 hours, at what time did C and D meet each other ?
Choose the correct choice from the following
A) 4:30 p.m.
B) 4:40 p.m.
C) 5:00 p.m.
D) 5:10 p.m.
E) 5:20 p.m.
Let speed of D in first hour = x   D’s speed = x+ 2x+ 4x+ 8x+ 16x*(5/8) = 25x   Given 25x=300 :. X = 12   At the end of four hours C traveled 120 (30 *4) kmph and D traveled 12 + 24+ 48 +96= 
<gadget id="calculator">12 + 24+ 48 +96</gadget>
<output>180</output>
180kmph   :. They meet each other after 4 hours ie at 5:00 p.m.   ANSWER:5:00 p.m.
<result>C</result>
Two persons C & D started traveling from A and B which are 300 km apart, towards B and A respectively at 1.00 p.m. C travels at a constant speed of 30 kmph whereas D doubles his speed every hour. If D reaches A in 4 5/8 hours, at what time did C and D meet each other ?