The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:	Pick:
A) 74  B) 94  C) 184  D) 364  E) 154
L.C.M. of 6, 9, 15 and 18 is 90. Let required number be 90k + 4, which is multiple of 7. Least value of k for which (90k + 4) is divisible by 7 is k = 4. Required number = (90 x 4) + 4 = 364. Answer :364
<result>D</result>
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: