A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?
Choose the correct choice from the following:
A) d/800  B) 5d/1000  C) 125d  D) d/1000 + 25  E) 125/(1000d)
Since you're choosing to approach this algebraically, I'm going to add some labeling to your work....   1,000 purchased for a total of D dollars.....   Each modem costs D/1,000 dollars....   Each modem is then sold for 25% ABOVE the cost:   (1.25)(D/1,000) = 1.25D/1,000   1.25D/1,000 = 125D/100,000   125/1,000 = 1/8 so....   125/100,000 = 1/800   So the sell price of each modem is D/800   Final d/800nswer:   d/800
<result>A</result>
A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?