An instrument manufactured by a company consists of two parts A and B. In manufacturing part A, 9 out of 100 are likely to be defective and in manufacturing part B, 5 out of 100 are likely to be defective. Calculate the probability that the instrument will not be defective.
Choose the correct choice from the following options:
A) 0.86.	B) 0.91	C) 0.95	D) 0.97	E) None of these
Explanation :   Let, A ≡ event that part A is non- defective.   B ≡ event that part B is non- defective.   A and B are independent events.   AB ≡ event that part A and part B both are non-defective so that instrument is not defective.   =&gt; P(AB) = P(A) x P(B).   =&gt; [ 1 - P(~A)] x [ 1 - P(~B)].   Here, P(~A)= 9/100 = probability of part A being defective   and, P(~B) = 5 / 100 = probability of part B being defective.   =&gt; P(AB) = [1- (9 / 100 ) ] x [1- (5 / 100)].   =&gt; 0.91 x 0.95.   =&gt; 0.86.   Hence, the required probability is 0.86.   0.86.nswer : 0.86.
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An instrument manufactured by a company consists of two parts A and B. In manufacturing part A, 9 out of 100 are likely to be defective and in manufacturing part B, 5 out of 100 are likely to be defective. Calculate the probability that the instrument will not be defective.