Three unbiased coins are tossed. What is the probability of getting 2 Tails?	Choose one
A) 3/4
B) 1/4
C) 3/8
D) 7/8
E) 1/8
Let, H --&gt; Head , T --&gt; Tail   Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}   Let E = event of getting 2 Tails   Then E = {TTH, THT, HTT}   P(E) = n(E)/n(S) =3/8   Answer is 3/8
<result>C</result>
Three unbiased coins are tossed. What is the probability of getting 2 Tails?