Each of 7 workers will pick a day of the week as his vacation day. What is the probability that exactly one worker will pick a different day? Answers.
A) 7!/7^7
B) 1/7!
C) 1/7^7
D) 7/7!
E) 7/7^7
Each worker out of 7 has 7 options (Sunday, Monday, Tuesday,.., Saturday), hence total # of outcomes is 7^7;   Favorable outcomes will be 7!, which is # of ways to assign 7 different day to 7 workers.   P=favorable/total=7!/7^7   7!/7^7nswer: 7!/7^7.
<result>A</result>
Each of 7 workers will pick a day of the week as his vacation day. What is the probability that exactly one worker will pick a different day?