we have two cubes which are joined to each other covering one face of each. and remaining faces of both are colored with the different colors.then the first cube is cut into 8 smaller cubes and another in 27 smaller cubes. what is the total number of faces having no color?	Choose one
A) 141 B) 142 C) 143 D) 144 E) 145
each cube having 6 faces   for each cube 5 faces has color and one face for each has not   1st cube divided into 8 smaller cubes so num of faces = 8*6= 
<gadget id="calculator">8*6</gadget>
<output>48</output>
48   in this 48 faces  5*4= 
<gadget id="calculator"> 5*4</gadget>
<output>20</output>
20 faces having the color and 28 don't   because if we divided a cube into 2^n smaller cubes (2^3= 8) then each face of original cube is divided into 2^(n-1) smaller faces (2^2 = 4) [and inner faces also there]   similarly 2nd cube divided into 27 smaller cubes so num of faces = 27*6= 
<gadget id="calculator">27*6</gadget>
<output>162</output>
162   in tiis 162 faces  5*9= 
<gadget id="calculator"> 5*9</gadget>
<output>45</output>
45 faces having color and 117 don't   total no of faces having no color= 28+117= 
<gadget id="calculator">28+117</gadget>
<output>145</output>
145   ANSW145R:145
<result>E</result>
we have two cubes which are joined to each other covering one face of each. and remaining faces of both are colored with the different colors.then the first cube is cut into 8 smaller cubes and another in 27 smaller cubes. what is the total number of faces having no color?