A black box contains eight marbles, of which three are red, and the rest are blue. A white box contains five marbles, of which two are red, and the rest are blue. If two marbles are chosen from the black box at random, and one marble is chosen from the white box at random, what is the probability that all marbles will be blue? Select the correct option:
A) 3/14	B) 3/8	C) 5/13	D) 8/13	E) 17/20
From the prompt we know about 2 boxes and the marbles within each:   The black box contains   3 red   5 blue   8 total   The white box contains   2 red   3 blue   5 total   We're told to pull 2 marbles from the black box and 1 marble from the white box. We're asked for the probability that ALL marbles pulled will be BLUE.   Let's start with the 1st marble you pull from the black box....   The probability that it's blue is 5/8   Once you pull that first marble, there's 1 fewer blue marble in the black box.   When you grab the 2nd marble from the black box....   The probability that it's blue is 4/7   For the 3rd marble, we pull from the white box.   The probability that it's blue is 3/5   Now, we multiply the results: (5/8)(4/7)(3/5) = 3/14   3/14
<result>A</result>
A black box contains eight marbles, of which three are red, and the rest are blue. A white box contains five marbles, of which two are red, and the rest are blue. If two marbles are chosen from the black box at random, and one marble is chosen from the white box at random, what is the probability that all marbles will be blue?