An = 2An-1 + 4 and Qn = 4Qn-1 + 8 for all n > 1. If A5 = Q4 and A7 = 316, what is the first value of n for which Qn is an integer?	Choose the correct choice from the following: A) 1 B) 2 C) 3 D) 4 E) 5
Assuming I have understood the symbols used correctly answer is 3- 3   A7 = 2S6 +4 = 316   A6 = 312/2= 
<gadget id="calculator">312/2</gadget>
<output>156</output>
156= 2A5 + 4   A5 = 152/2= 
<gadget id="calculator">152/2</gadget>
<output>76</output>
76= Q4   Q4 = 4Q3 + 8 = 76   Q3 = 68/4= 
<gadget id="calculator">68/4</gadget>
<output>17</output>
17   Q3= 4Q2 + 8 = 17   Q2 = 9/4= 
<gadget id="calculator">9/4</gadget>
<output>9/4 = around 2.25</output>
2.25   Q2= 4Q1 + 8   Q1 will not be integer=3
<result>C</result>
An = 2An-1 + 4 and Qn = 4Qn-1 + 8 for all n > 1. If A5 = Q4 and A7 = 316, what is the first value of n for which Qn is an integer?