If two letters are chosen at random (without replacement) from the word HORSEBACK, what is the probability that none of the letters are vowels?  Choose the most appropriate option.
A) 4/9 B) 5/9 C) 5/12 D) 7/24 E) 11/36
The number of ways to choose two letters is 9C2 = 36   The number of ways to choose two consonants is 6C2 = 15.   P(no vowels) = 15/36 = 5/12   The answer is 5/12.
<result>C</result>
If two letters are chosen at random (without replacement) from the word HORSEBACK, what is the probability that none of the letters are vowels?