A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 488. What is the sum of the last 8 of the even integers?  Choices
A) 598
B) 604
C) 610
D) 616
E) 622
The sum of the first 8 numbers is: x + (x+2) +...+ (x+14) = 488   The sum of the next 8 numbers is: (x+16) + (x+2+16) +...+ (x+14+16) =   488 + 8(16) = 488 + 128= 
<gadget id="calculator">488 + 128</gadget>
<output>616</output>
616   The answer is 616.
<result>D</result>
A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 488. What is the sum of the last 8 of the even integers?