If grapes are 93% water and raisins are 16% water, then how many kilograms did a quantity of raisins, which currently weighs 8 kilograms, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.) Choices: A) 92 B) 96 C) 100 D) 104 E) 108
Let x be the original weight.   The weight of the grape pulp was 0.07x.   Since the grape pulp is 84% of the raisins, 0.07x = 0.84(8).   Then x = 12*8= 
<gadget id="calculator">12*8</gadget>
<output>96</output>
96 kg.   The answer is 96.
<result>B</result>
If grapes are 93% water and raisins are 16% water, then how many kilograms did a quantity of raisins, which currently weighs 8 kilograms, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.)