The total circumference of two circles is 88. If the first circle has a circumference that is exactly twice the circumference of the second circle, then what is the approximate sum of their two radii?	Pick one:
A) 5.7  B) 6.0  C) 6.7  D) 9.7  E) 14.0
Let r= Radius of smaller circle. Let R = Radius of larger circle   Therefore:   2πr + 2πR = 88   where 2r = R   Thus:   2πr + 4πr = 88   6πr = 88   r = approx 4.7   πR + 2Rπ = 88   3πR = 88   R = approx 9.3   r + R = approx 14.0   Answer : 14.0
<result>E</result>
The total circumference of two circles is 88. If the first circle has a circumference that is exactly twice the circumference of the second circle, then what is the approximate sum of their two radii?