In a simultaneous throw of two coins, the probability of getting at least one head is	Choose one:
A) 1/2 B) 1/3 C) 2/3 D) 3/4 E) 3/5
Here S={HH, HT, TH, TT}   Let E = event of getting at least one head = {HT, TH, HH}   Therefore P(E) = n(E)/n(S) = 3/4   Answer 3/4.
<result>D</result>
In a simultaneous throw of two coins, the probability of getting at least one head is