From a group of 5 boys and 5 girls, 6 children are to be randomly selected. What is the probability that 3 boys and 3 girls will be selected? Choices
A) 4/15	B) 6/17	C) 8/19	D) 10/21	E) 12/23
The total number of ways to choose 6 children from 10 is 10C6 = 210   The number of ways to choose 3 boys and 3 girls is 5C3*5C3 = 10*10= 
<gadget id="calculator">10*10</gadget>
<output>100</output>
100   P(3 boys and 3 girls)= 100/210 = 10/21   The answer is 10/21.
<result>D</result>
From a group of 5 boys and 5 girls, 6 children are to be randomly selected. What is the probability that 3 boys and 3 girls will be selected?