In a certain game, a player begins with a bag containing tiles numbered 1 through 15, each of which has an equal probability of being selected. The player draws one tile. If the tile is even, the player stops. If not, the player draws another tile without replacing the first. If this second tile is even, the player stops. If not, the player draws a third tile—without replacing either of the first two tiles—and then stops. What is the probability that at the conclusion of the game, the sum of the tiles that the player has drawn is odd?	Select the correct option:
A) 5/18 B) 13/36 C) 3/8 D) 5/8 E) 23/36
player begins with containing tiles 1 to 10 and have equal probability of selecting means   Proabability of selecting one number =1/10. here 5 even numbers and 5 odd numbers are there.   Next , player draws one title , if number is even player stops or otherwise title is odd without replacement   player draws second title.   If second title is even , player stops or title is odd without replacement player draws third title.   in third title , without replacement of first and second title, player draws and stops it.   the sum of tilte probability is odd. here two conditions are possible.   1st condition is   1st title is odd+ 2nd title is even stops= probability of selecting one title is 1/10*5c1.   Here are we are not selecting 1st condition as even stops because sum of tile is odd.   Here 5 odd numbers are there we can select 1out of 5 odd numbers.   without replacement of fist we select second tilte is even. is 5/10*5c1/9c1.   here we are selecting one number out of remaining 9 numbers. so probability is 5/18.   we are selecting 1 even number out of 5.   2nd condition is 1stodd without replacement,2nd odd without replacement and 3rd one also odd to get odd as sum of title.   Then probability is 5/10*4/9*3/8=1/12.   Finally sum of probability of two conditions is 5/18+1/12   =23/36.   so option 23/36 is correct.
<result>E</result>
In a certain game, a player begins with a bag containing tiles numbered 1 through 15, each of which has an equal probability of being selected. The player draws one tile. If the tile is even, the player stops. If not, the player draws another tile without replacing the first. If this second tile is even, the player stops. If not, the player draws a third tile—without replacing either of the first two tiles—and then stops. What is the probability that at the conclusion of the game, the sum of the tiles that the player has drawn is odd?