What is the largest possible value of cc if 5c+(d−12)^2=235?
Choose the most appropriate option
A) 17
B) 25
C) 35
D) 42
E) 47
To maximize c, we should minimize (d-12)^2. (d-12)^2 is a square of a number, thus its smallest possible value is 0 (for d = 12).   In this case we'd have 5c + 0 = 235 --&gt; c = 47.   Answer: 47.
<result>E</result>
What is the largest possible value of cc if 5c+(d−12)^2=235?