An alloy of copper and zinc contains copper and zinc in the ratio 8 : 2. Another alloy of copper and zinc contains copper and zinc in the ratio 4 : 6. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc? Pick one:	A) 5 : 1	B) 4 : 1	C) 3 : 1	D) 6 : 1	E) 8 : 1
Let Alloy_1 be x units, and let Alloy_2 be y units.   So, fraction of copper in Alloy_1 = 8x/10, and fraction of zinc in Alloy_1 = 2x/10   Similarly, fraction of copper in Alloy_2 = 4y/10, and fraction of zinc in Alloy_2 = 6y/10.   Mixing them, we get   copper = 8x/10 +4y/10; zinc = 2x/10 + 6y/10   So, 8x+4y = 2x+6y   -&gt; 6x = 2y   -&gt; x/y =6/2= 
<gadget id="calculator">6/2</gadget>
<output>3</output>
3/1   So, they must be mixed in the ratio 3 : 1   Answer : 3 : 1
<result>C</result>
An alloy of copper and zinc contains copper and zinc in the ratio 8 : 2. Another alloy of copper and zinc contains copper and zinc in the ratio 4 : 6. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc?