Let f(x) = x^2 + bx + c. If f(3) = 0 and f(-3) = 0, then b + c =
Pick one
A) 18 B) 15 C) -15 D) -21 E) -9
f(x) = x^2 + bx + c. If f(3) = 0 and f(-3) = 0, then b + c =   f(3) = 0= 9+3b+c--- Taking 9 to the other side   -&gt; 3b+c= -9   f(-3) = 0= 9-3b+c --- taking -3b+c to the other side   -&gt; 3b-c=9   When we add these 2 equations, we get 6b= 0---&gt; b= 0   And while substituting b= 0 we get c= -9.   b+c= -9--- Answer -9
<result>E</result>
Let f(x) = x^2 + bx + c. If f(3) = 0 and f(-3) = 0, then b + c =