If x is a positive integer, then the least value of x for which x! is divisible by 1,000,0000 is?
Can someone please explain intuitively what the question is asking?
Choose the most appropriate option:
A) 5 B) 9 C) 25 D) 15 E) 30
In order x! to be divisible by 1,000, it should have at least 3 trailing zeros. A trailing 0 in factorial of a number is produced by 2 and 5 in it:   2*5= 
<gadget id="calculator">  2*5</gadget>
<output>10</output>
10. So, we need 10 to be in x! at least in power of 3.   5!= 120 has 1 trailing zeros.   10! will have 2 trailing zeros.   15! will have 3 trailing zeros.   20! will have 5 trailing zeros.   25! will have 7 trailing zeros. 25
<result>C</result>
If x is a positive integer, then the least value of x for which x! is divisible by 1,000,0000 is?
Can someone please explain intuitively what the question is asking?