A train running at 1/5 of its own speed reached a place in 10hours. How much time could be saved if the train would have run at its own speed?	Answers.
A) 8hrs  B) 10hrs  C) 12hrs  D) 15hrs  E) 6hrs
New speed = 1/5 of usual speed   New time = 5/1 of usual time   5/1 of usual time = 10 hrs   Usual time = 10*1/5= 
<gadget id="calculator">10*1/5</gadget>
<output>2</output>
2 hrs   Time saved= 10-2= 
<gadget id="calculator">10-2</gadget>
<output>8</output>
8 hrs   8hrsnswer is 8hrs
<result>A</result>
A train running at 1/5 of its own speed reached a place in 10hours. How much time could be saved if the train would have run at its own speed?