In a local election, 2400 people were to vote for Party A or Party B. Party A was bound to win the election. However, on Election Day, 33% of the voters of Party A were kidnapped. Party B was also able to influence the remaining Party A voters and thus double the strength of its voters. In this way, Party A lost by a majority which was half of that by which it would have won had the elections been fair. How many people finally voted for Party A and Party B?	Choose the most appropriate option
A) 600(A), 1200(B)	B) 300(A), 600(B)	C) 450(A), 900(B)	D) 600(A), 900(B)	E) None of these
DETAILED SOLUTION   Easiest way to solve this question is through options:   a) If 600 voted for A and 1200 voted for B then   Before influencing, A –   600 + 600= 
<gadget id="calculator">  600 + 600</gadget>
<output>1_200</output>
1200, B – 1200 – 600= 600(As half of B’s vote were through influencing)   Before kidnapping, A – 1200 + a∗12 of 1200 = 1800 (As 1/3 of A’s voters were kidnapped which is half of the 2/3 that remained)   Thus, total voter initially = 1800 (A) + 600 (B) = 2400   Thus option a) fits the scenario given in the question completely.   Therefore,   600(, 1200(B)nswer – (a)   Correct 600(, 1200(B)nswer:600(, 1200(B)
<result>A</result>
In a local election, 2400 people were to vote for Party A or Party B. Party A was bound to win the election. However, on Election Day, 33% of the voters of Party A were kidnapped. Party B was also able to influence the remaining Party A voters and thus double the strength of its voters. In this way, Party A lost by a majority which was half of that by which it would have won had the elections been fair. How many people finally voted for Party A and Party B?