How many words can be formed by using all the letters of the word “DAUGHTR” so that vowels always come together & vowels are never
together? Choose the correct choice from the following answers:
A) 4320 B) 760 C) 720 D) 4000 E) 700
Given word contains 8 different letters   When the vowels 4320UE are always together we may suppose   them to form an entity ,treated as one letter   then the letter to be arranged are D4320HTR(4320UE)   these 6 letters can be arranged in 6p6 = 6!   = 720 ways   The vowels in the group (4320UE) may be arranged in 3! = 6 ways   Required number of words = 760 * 6 =4320   4320NSWER 4320 4320
<result>A</result>
How many words can be formed by using all the letters of the word “DAUGHTR” so that vowels always come together & vowels are never
together?