2 years ago, the average age of a family of 5 members was 16 years. After a baby is born, the average age of family is the same today. Find the present age of the baby.  Select.
A) 4 years	B) 6 years	C) 8 years	D) 8 ½ years	E) 9 years
Hint: (1) First find total age of 5 members 2 years ago (2) Present age of 5 members (3) Total age of 6 members (4) Age of baby = Total age of 6 members - Present age of 5 members   We know that,   Average =Sum of Quantities / Number of Quantities   1) First calculate total age of 5 members 2 years ago = (Average age of 5 members x number of members)   First calculate total age of 5 members 2 years ago = (16 x 5) = 80 years   2) Calculate the present age of 5 members   2 years ago, their total age was 80 years. Present age can be calculated as follows:   Present age of 5 members = [80 + (2 x 5)] = 90 years   3) Calculate total age of 6 members considering baby = (16 x 6 ) = 96 years   4) Age of baby = (96 – 90) = 6 years   ANSWER IS 6 years
<result>B</result>
2 years ago, the average age of a family of 5 members was 16 years. After a baby is born, the average age of family is the same today. Find the present age of the baby.