While playing a certain dice game, Chris wins if the sum of the two dice is 11, at which point the game is over. If the game allows Chris three rolls in an attempt to win, what is the probability that Chris will win?	Choose the correct choice from the following choices:
A) 1/2
B) 17/36
C) 26/165
D) 11/36
E) 25/216
Probability of winning game = 1- Probability of losing game   Probability of losing game = (Probability of not getting sum 7 in any of the three attempts)   Ways of getting sum 11 = (5,6)(6,5)= 2 ways   Total ways of getting outcome on two dice =6*6= 
<gadget id="calculator">6*6</gadget>
<output>36</output>
36   Probability of getting sum as 11 in any attempt=2/36=1/18   Probability of NOT getting sum as 11 in any attempt = 1-(1/18)= 17/18   Probability of losing game =(17/18)*(17/18)*(17/18)=139/165   I.e. Probability of wining game = 1-(139/165) =26/165   Answer : Option 26/165
<result>C</result>
While playing a certain dice game, Chris wins if the sum of the two dice is 11, at which point the game is over. If the game allows Chris three rolls in an attempt to win, what is the probability that Chris will win?