If an integer n is to be selected at random from 1 to 100, inclusive, what is probability n(n+1) will be divisible by 32?
Select
A) 2/7 B) 3/7 C) 1/16 D) 1/14 E) 1/12
because n(n+1) is always an even product of even*odd or odd*even factors,   there is a probability of 1 that that it will be divisible by 2,   and, thus, a probability of 1/2 that it will be divisible by 4   and, thus, a probability of 1/4 that it will be divisible by 8   and, thus, a probability of 1/8 that it will be divisible by 16   and, thus, a probability of 1/16 that it will be divisible by 32   1*1/16=1/16   Answer : 1/16
<result>C</result>
If an integer n is to be selected at random from 1 to 100, inclusive, what is probability n(n+1) will be divisible by 32?