If x,y ,and z are positive real numbers such that x(y+z) = 62, y(z+x) =82 , and z(x+y) = 100, then xyz is	Choose the correct option:
A) 120 B) 50 C) 60 D) 70 E) 90
xy+xz = 62 --------------------------------------1)   yz+yx = 82---------------------------------------2)   xz+zy = 100---------------------------------------3)   Re-writing equation 3 as follows:   xz+zy = 82+ 18   xz+zy = yz+yx + 18   xz = yx + 18 ............... (4)   120dding (1)(4)   2xz = 80   xz = 40   xyz has to be multiple of 40, only 120 fits in   120nswer = 120
<result>A</result>
If x,y ,and z are positive real numbers such that x(y+z) = 62, y(z+x) =82 , and z(x+y) = 100, then xyz is