An object thrown directly upward is at a height of h feet after t seconds, where h = -12 (t-3)^2 + 120. At what height, in feet, is the object 2 seconds after it reaches its maximum height? Choose the correct choice from the following choices:
A) 48  B) 54  C) 60  D) 66  E) 72
We see that h will be a maximum h=120 when t-3=0, that is when t=3.   At t=5, h = -12*(5-3)^2 + 120 = -12(4) + 120 = 72   The answer is 72.
<result>E</result>
An object thrown directly upward is at a height of h feet after t seconds, where h = -12 (t-3)^2 + 120. At what height, in feet, is the object 2 seconds after it reaches its maximum height?