What is the sum of all digits for the number 10^29 - 41?	Choices
A) 257
B) 242
C) 231
D) 202
E) 187
10^29 is a 30-digit number: 1 followed by 29 zeros.   10^29 - 41 is a 29-digit number: 27 9's and 59 at the end.   The sum of the digits is  27*9+5+9= 
<gadget id="calculator"> 27*9+5+9</gadget>
<output>257</output>
257.   The answer is 257.
<result>A</result>
What is the sum of all digits for the number 10^29 - 41?