From a theatre troupe of eight members, including Lou, one person will be randomly chosen to play Abel, another person will be randomly chosen to play Barry, and a third person will be randomly chosen to play Caine. What is the probability that Lou will NOT be chosen to play either Abel or Caine? Select the correct option
A) 1/168	B) 1/8	C) 1/4	D) 1/3	E) 3/4
"one person will be randomly chosen to play Abel, another person will be randomly chosen to play Barry, and a third person will be randomly chosen to play Caine"   The above statement is NOT clear   Still a solution:   For 8 students we have 3 posts   one post can be occupied by only one member   no two posts can be occupied by the same member   probability(P) for a member getting selected for particular 2 of the 3 posts=   probable outcomes=1(Caine)+1(Abel)=2   total outcomes=1(Caine)+1(Abel)+1(Barry)+5(non post positions)=8   =2/8=1/4   Probability required for the given case= 1-P=1-1/4=3/4   Answer: 3/4
<result>E</result>
From a theatre troupe of eight members, including Lou, one person will be randomly chosen to play Abel, another person will be randomly chosen to play Barry, and a third person will be randomly chosen to play Caine. What is the probability that Lou will NOT be chosen to play either Abel or Caine?