A woman invested $1,000, part at 5% and the rest at 6%. Her total investment with interest at the end of the year was $1,051. How much did she invest at 5%?	Select:
A) $500 B) $600 C) $700 D) $900 E) $950
et x be the portion invested at 5% and   Let (1-x) be the rest which is invested at 6%   The question states that the return after 1 year is (1051/1000)-1= 
<gadget id="calculator">(1051/1000)-1</gadget>
<output>51/1_000 = around 0.051</output>
0.051= 5.1%   We want to find the dollar amount invested in X   Using our defined variables, put together the equation and solve for x (the percentage of 1000 invested at 5%)   0.05x+0.06(1-x)= 0.051   (0.05)x +0.06 - (0.06)x = 0.051   -0.01x = -0.009   x= -0.009/-0.01 = 9/10 = 90%   So X = 90% of the 1000 which is 900   ANSWER:$900
<result>D</result>
A woman invested $1,000, part at 5% and the rest at 6%. Her total investment with interest at the end of the year was $1,051. How much did she invest at 5%?