The average of four positive integers is 69. The highest integer is 93 and the least integer is 39. The difference between the remaining two integers is 28. Which of the following integers is the higher of the remaining two integers? Choose the correct choice:
A) 65 B) 48 C) 37 D) 23 E) 12
Let the four integers be A, B, C and D where A &gt; B &gt; C &gt; D.   (A + B + C + D)/4 = 69 =&gt; A + B + C + D = 276 ---&gt; (1)   A = 93, D = 39 and B - C = 28   (1) =&gt; B + C = 276 - (A + D) = 276 - 132= 
<gadget id="calculator">276 - 132</gadget>
<output>144</output>
144.   48 + 48 -28= 144   48 = (144 + 28)/2= 
<gadget id="calculator">(144 + 28)/2</gadget>
<output>86</output>
86   Answer:48
<result>B</result>
The average of four positive integers is 69. The highest integer is 93 and the least integer is 39. The difference between the remaining two integers is 28. Which of the following integers is the higher of the remaining two integers?