A and B can finish 5 piece of work in 10 days each. C can do 40% faster than A and B.Approximately how many days would it take to finish 51 piece of work with all three working simultaneously?
Choices.
A) 38 B) 42 C) 46 D) 50 E) 51
since c is 40% faster , thus it will create 7 pieces of work in 10 days   in 10 days total number of work by all three will be :    5+5+7= 
<gadget id="calculator"> 5+5+7</gadget>
<output>17</output>
17   in 20 days:   17+17= 
<gadget id="calculator">17+17</gadget>
<output>34</output>
34   in 25 days:   34+17= 
<gadget id="calculator">34+17</gadget>
<output>51</output>
51   thus in all 51 days.   Ans:51
<result>E</result>
A and B can finish 5 piece of work in 10 days each. C can do 40% faster than A and B.Approximately how many days would it take to finish 51 piece of work with all three working simultaneously?