A certain bakery baked a batch of 470 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?  Choose one:	A) 166	B) 293	C) 413	D) 438	E) 511
Cookies which have both nuts and chocolate chips = 165   Let fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that   batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch = x   (165+x)/(470+x) = 6/10   =&gt;1650 + 10x = 2820 + 6x   =&gt; 4x = 1170   =&gt; x = 292.5   Therefore x = 293   Answer 293
<result>B</result>
A certain bakery baked a batch of 470 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?