In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?  Choose the correct choice from the following.
A) 1/3 B) 1/9 C) 1/2 D) 1/7 E) 1/5
Explanation:   Total number of balls = (8 + 7 + 6)= 
<gadget id="calculator">(8 + 7 + 6)</gadget>
<output>21</output>
21.   Let E= event that the ball drawn is neither red nor green   = event that the ball drawn is blue.   n(E) = 7.   P(E) = n(E)/n(S) = 7/21 = 1/3.   1/3nswer: 1/3) 1/3
<result>A</result>
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?