A bag contains 2 red and 3 green balls. Another bag contains 4 red and 6 green balls. If one ball is drawn from each bag. Find the probability that one ball is red and one is green.  Answers
A) 19/20	B) 17/20	C) 21/25	D) 8/10	E) 9/40
Let A be the event that ball selected from the first bag is red and ball selected from second bag is green.   Let B be the event that ball selected from the first bag is green and ball selected from second bag is red.   P(A) = (2/5) x (6/10) = 6/25.   P(B) = (3/5) x (4/10) = 6/25.   Hence, the required probability is P(A) + P(B) which is nothing but 21/25.   ANSWER:21/25
<result>C</result>
A bag contains 2 red and 3 green balls. Another bag contains 4 red and 6 green balls. If one ball is drawn from each bag. Find the probability that one ball is red and one is green.