Let f(x) = x^2 + bx + c. If f(1) = 0 and f(-7) = 0, then f(x) crosses the y-axis at what y-coordinate?
Choose the correct option:
A) -7  B) -1  C) 0  D) 1  E) 7
When x = 1 and when x = -7, the expression f(x) = x² + bx + c equals 0.   Then f(x) = (x-1)(x+7)   f(0) = -7   The answer is -7.
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Let f(x) = x^2 + bx + c. If f(1) = 0 and f(-7) = 0, then f(x) crosses the y-axis at what y-coordinate?