Machine–A produces 40% of the total output and Machine-B produces 60% of the total output. An average of nine units out of a thousand goods manufactured by Machine-A and one unit of 300 units produced by Machine-B prove to be defective. What is the probability that a unit chosen at random from the total daily output of the factory is defective?  Answers:
A) a. 0.56
B) b. 0.056
C) c. 0.0056
D) d. 0.00056
E) e. 0.000056
Let total Production be 10000 units....   A produces 4000 units and 36 units are defective   B produces 6000 units and 20 units are defective   So, Out of total 10,000 units 56 units are defective...   So the required probability = 56/10000= 
<gadget id="calculator">56/10000</gadget>
<output>7/1_250 = around 0.0056</output>
&gt; 0.0056   Answer will be (c. 0.0056)
<result>C</result>
Machine–A produces 40% of the total output and Machine-B produces 60% of the total output. An average of nine units out of a thousand goods manufactured by Machine-A and one unit of 300 units produced by Machine-B prove to be defective. What is the probability that a unit chosen at random from the total daily output of the factory is defective?