In the x-y plane, the area of the region bounded by the graph of |x+y| + |x-y| = 6 is	Choose the correct choice from the following options
A) 8 B) 12 C) 81 D) 20 E) 24
I've never seen such kind of question in GMAT before.   OK there can be 4 cases:   |x+y| + |x-y| = 4   A. x+y+x-y = 6 --&gt; x=3   B. x+y-x+y = 6 --&gt; y=3   C. -x-y +x-y= 6 --&gt; y=-3   D. -x-y-x+y=6 --&gt; x=-3   The area bounded by 4 graphs x=3, x=-3, y=3, y=-3 will be square with the side of 4 so the area will be 9*9= 
<gadget id="calculator">9*9</gadget>
<output>81</output>
81.   Answer: 81
<result>C</result>
In the x-y plane, the area of the region bounded by the graph of |x+y| + |x-y| = 6 is