In how many ways can 5 boys be allotted four different study tables such that none of the study tables are empty and all the 5 boys are accommodated? Choose the correct choice:	A) 290	B) 280	C) 260	D) 240	E) 300
4 boys can be selected from 5 boys in 5C4 ways = 5   4 boys can be arranged in 4 rooms in 4! ways   and since 1 boy has to share a room with one of the 4 boys, therefore total ways = 2! = 2   Hence total number of ways in which allocation can be done = 5C4 * 4! * 2! = 5*2*4! =240   240
<result>D</result>
In how many ways can 5 boys be allotted four different study tables such that none of the study tables are empty and all the 5 boys are accommodated?