In a sequence of 12 numbers, each term, except for the first one, is 12^14 less than the previous term. If the greatest term in the sequence is 12^15, what is the smallest term in the sequence?
Thus, A12 = A1+12-1d
Where d is the difference between each pairs of consecutive terms. Since each term is 1211 less than the previous term, d=-1211Click individual answer choices for specific explanations.
From what I undersltand the formula for an arithmetic sequence represents
some-number-in-the-sequence= first-number-in-sequence +the-place-of-that-number - 1x the-difference-of-each-#-in-the-sequence	Choose the correct choice from the following.
A) 12^14 B) 0 C) 12^11 D) 11·12^11 E) 12^12
there are total 12 terms. andgreatestterm is 12^15. Each term is 12^14 less than previous one. What does this signify? This shows it is an AP - a decreasing one. (NoticeEach term is 12^14 less than previous one')   Therefore, 12^15 is the first term of the AP and -12^14 is the difference between successive terms, the smallest term should be the last one.   Last term = First term + (n-1)*d   therefore, Last term = 12^15 + 11*(-12^14)   =&gt; Last term = 12^15 - 11*12^14   =&gt; Last term = 12^14 (12-11) = 12^14   Which is the smallest term.   Hence 12^14ns 12^14 it is.
<result>A</result>
In a sequence of 12 numbers, each term, except for the first one, is 12^14 less than the previous term. If the greatest term in the sequence is 12^15, what is the smallest term in the sequence?
Thus, A12 = A1+12-1d
Where d is the difference between each pairs of consecutive terms. Since each term is 1211 less than the previous term, d=-1211Click individual answer choices for specific explanations.
From what I undersltand the formula for an arithmetic sequence represents
some-number-in-the-sequence= first-number-in-sequence +the-place-of-that-number - 1x the-difference-of-each-#-in-the-sequence