There are 9 magazines lying on a table; 4 are fashion magazines and the other 5 are sports magazines. If 3 magazines are to be selected at random from the 8 magazines, what is the probability that at least one of the fashion magazines will be selected?
Select: A) 1/2 B) 2/3 C) 32/35 D) 20/21 E) 13/14
answer is 20/21   Total probability=9C3=84   5C3 +5C2*4C1+5C1*4C2=10+40+30= 
<gadget id="calculator">10+40+30</gadget>
<output>80</output>
80   therefore the probability that at least one of the fashion magazines will be selected= 80/84=20/21   20/21
<result>D</result>
There are 9 magazines lying on a table; 4 are fashion magazines and the other 5 are sports magazines. If 3 magazines are to be selected at random from the 8 magazines, what is the probability that at least one of the fashion magazines will be selected?