In 2 bags, there are to be put together 5 red and 12 white balls, neither bag being empty. How must the balls be divided so as to give a person who draws 1 ball from either bag- the least chance of drawing a red ball ?
Choose the correct choice from the following options:  A) 1/32  B) 2/32  C) 3/32  D) 4/32  E) 5/32
Least Chance.   P= 1/2 * 5/16 + 1/2 * 0 = 5/32   ANSW5/32R:5/32
<result>E</result>
In 2 bags, there are to be put together 5 red and 12 white balls, neither bag being empty. How must the balls be divided so as to give a person who draws 1 ball from either bag- the least chance of drawing a red ball ?