Of the female students at Barkely University, 5/6 are on the honor roll. Of the male students, 2/3 are on the honor roll. If 3/5 of the students are female, what fraction of all the students are on the honor roll?  Choose the correct choice.
A) 5/9
B) 3/15
C) 23/30
D) 43/60
E) 53/90
for total students take LCM OF FACTIONS=6*5= 
<gadget id="calculator">6*5</gadget>
<output>30</output>
30   Let female students=x,   so male students=30-x   Now,female stu. on honor roll=5/6(x) and male stu. on honor roll=2/3(30-x)   as given total female stu.=3/5(30)=18   female stu.=(5/6)*18= 
<gadget id="calculator">(5/6)*18</gadget>
<output>15</output>
15   and male stu.=(2/3)*12= 
<gadget id="calculator">(2/3)*12</gadget>
<output>8</output>
8   fraction of honor student=(15+8)/30=23/30.   23/30orrect answer is 23/30.
<result>C</result>
Of the female students at Barkely University, 5/6 are on the honor roll. Of the male students, 2/3 are on the honor roll. If 3/5 of the students are female, what fraction of all the students are on the honor roll?