When a=x+(2/x) and b=x-(2/x), (2^a^2)/(2^b^2)=? Choose one:
A) 2	B) 256	C) 8	D) 16	E) 32
--&gt; (2^a^2)/(2^b^2) ={(2)^(a^2-b^2)}=2^(a-b)(a+b).   Since a-b=4/x   and a+b=2x,   2^(a-b)(a+b)=2^(4/x)(2x)=2^8=256   Answer is 256
<result>B</result>
When a=x+(2/x) and b=x-(2/x), (2^a^2)/(2^b^2)=?