Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?  Pick:	A) 42, 33	B) 42, 36	C) 44, 33	D) 44, 36	E) None of these
Explanation :   Let the marks secured by them be x and (x + 9)   Then sum of their marks = x + (x + 9) = 2x + 9   Given that (x + 9) was 56% of the sum of their marks   =&gt; (x + 9) = (56/100)(2x + 9)   =&gt; (x + 9) = (14/25)(2x + 9)   =&gt; 25x + 225 = 28x + 126   =&gt; 3x = 99   =&gt; x = 33   Then (x + 9) = 33 + 9= 
<gadget id="calculator">33 + 9</gadget>
<output>42</output>
42   Hence their marks are 33 and 42   42, 33nswer : Option 42, 33
<result>A</result>
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?