What is the probability that their sum of two numbers, randomly selected from the set {3,6,9,12,15,18} will be greater than 9?  Choose one: A) 7/6 B) 7/9 C) 7/8 D) 7/10 E) 6/7
First7 problem is 6C2 = 12 .. Not 20..   Point 2, you sum should be greater than 9, so these are the following possibilities you have   ({3,9},{3,12},{3,15},{3,18},{6,9},{6,12},{6,15},{6,18},{9,12},{9,15},{9,18},{12,15},{12,18},{15,18}) which leads to 14 pairs   So the probability is 14 on 12 or 7/6..   7/6NSWER:7/6
<result>A</result>
What is the probability that their sum of two numbers, randomly selected from the set {3,6,9,12,15,18} will be greater than 9?