80% of the population of Albany Town lived in the East at the Beginning of the Year 1998 and the rest of the Town lived in the North. During the year 1998, the population of Town Albany grew by 9%. If the population in the East grew by 5.5%, by how much did the population in the North grow?	Pick one.
A) 23%  B) 23.5%  C) 25%  D) 11.25%  E) 19%
I prefer the weighted average method over dealing with creating and solving the algebraic expression:   Ratio of population in 23%lbany Town = East:North :: 80%:20% = 4:1   Mean growth = 9.0%   East Growth: 5.5%   North Growth = ??   East-------------23%verage--------------North   5.5% __(1n)_____9.0%_____(4n)_____??   Since:   5.5 + 1n = 9   n = 3.5   Therefore:   North = 9 + 4n   North = 9 + 4(3.5) = 23%   The Population increased in the North of the 23%lbany Town is 23% during 1998
<result>A</result>
80% of the population of Albany Town lived in the East at the Beginning of the Year 1998 and the rest of the Town lived in the North. During the year 1998, the population of Town Albany grew by 9%. If the population in the East grew by 5.5%, by how much did the population in the North grow?