A woman takes certain sum of money at 10% p.a. simple interest. If she pays twice the amount takes, how many years has she been paying the interest?  Choices:
A) 5 years 7 months
B) 10 years
C) 15 years
D) 6 years
E) 20 years
Solution: simple interest question   B=A[1+ (tr/100)]; where A is principal amount, B final amount, t time in years and r interest rate   after putting the values 10   3= [1+(10t/100)]   t= 20 which is 20 years   Answer is 20 years
<result>E</result>
A woman takes certain sum of money at 10% p.a. simple interest. If she pays twice the amount takes, how many years has she been paying the interest?