If 183 is divisible by 11, find the value of the smallest natural no. N?
Choose the correct answer:
A) 5	B) 7	C) 9	D) 10	E) 12
In aptitude tests , we get questions on divisibility by 11.   A number is divisible by 11, when the difference between the sum of digits at even places and at odd places is 0 or multiple of 11   The given number is N183.   (Sum of digits at EVEN places) – (sum of digits at ODD places)=0   (8 + N)- (3+1)= 0   (8 + N) - 4 = 0   Here the value of N must be 7   7
<result>B</result>
If 183 is divisible by 11, find the value of the smallest natural no. N?