A bag contains 6 red balls, 5 green balls and 6 white balls. A ball is drawn at
random from the box. What is the probability that the ball drawn is either red or green?  Choose the correct choice from the following choices: A) 2/5 B) 3/5 C) 11/17 D) 7/15 E) 8/15
Total number of balls = (6 + 5 + 6)= 
<gadget id="calculator">(6 + 5 + 6)</gadget>
<output>17</output>
17.   Therefore, n(S)= 17.   Let E1 = event of drawing a red ball.   and E2 = event of drawing a green ball.   Then, E1 n E2 = f.   P (E1 n E2) = P(E1) + P(E2) = (6/17 + 5/17) = 11/17.   ANSWER:11/17
<result>C</result>
A bag contains 6 red balls, 5 green balls and 6 white balls. A ball is drawn at
random from the box. What is the probability that the ball drawn is either red or green?