If x and y are numbers such that (x+3)(y-3)=0, what is the smallest possible value of x^2 + y^2	Choose the correct choice.
A) 0  B) 3  C) 6  D) 9  E) 12
From (x+3)(y-3)=0 it follows that either x=-3 or y=3. Thus either x^2=9 or y^2=9.   Now, if x^2=9, then the least value of y^2 is 0, so the least value of x^2 + y^2 = 9 + 0= 
<gadget id="calculator">9 + 0</gadget>
<output>9</output>
9.   Similarly if y^2=9, then the least value of x^2 is 0, so the least value of x^2 + y^2 = 0 + 9= 
<gadget id="calculator">0 + 9</gadget>
<output>9</output>
9.   Answer: 9.
<result>D</result>
If x and y are numbers such that (x+3)(y-3)=0, what is the smallest possible value of x^2 + y^2