In a jar there are balls in different colors: blue, red, green and yellow.
The probability of drawing a blue ball is 1/8.
The probability of drawing a red ball is 1/5.
The probability of drawing a green ball is 1/7.
If a jar cannot contain more than 50 balls, how many yellow balls are in the Jar?	Select:
A) 27
B) 26
C) 24
D) 23
E) 21
answer of 1st   just add the given probabilities p(blue)+p(red)+p(green) i.e   1/8+1/5+1/7=35+56+40/280 =131/280   now we know p(blue)+p(red)+p(green)+p(yellow)=1   131/280+p(yellow)=1   p(yellow)= 149/280 =21/40   i.e why yellow balls are 21.   21
<result>E</result>
In a jar there are balls in different colors: blue, red, green and yellow.
The probability of drawing a blue ball is 1/8.
The probability of drawing a red ball is 1/5.
The probability of drawing a green ball is 1/7.
If a jar cannot contain more than 50 balls, how many yellow balls are in the Jar?