If a and b are different values and a – b = 3(√a - √b), then in terms of b, a equals:  Pick:	A) √b	B) b	C) b - 2√b + 1	D) b - 6√b + 9	E) b^2 – 2b√b + b
(√a)^2 - (√b)^2 = 3(√a - √b) -----&gt; ( √a + √b) ( √a - √b) = 3(√a - √b) -------&gt; √a + √b = 3, so   √a = 3 - √b, square both sides and solve.   Answer is b - 6√b + 9.
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If a and b are different values and a – b = 3(√a - √b), then in terms of b, a equals: