For every positive integer n, the nth term of a sequence is the total sum of three consecutive integers starting at n. What is the total sum of terms 1 through 60 of this series?
Choices:	A) 5330	B) 5670	C) 5990	D) 6240	E) 6550
Each term of the series has the form (n+n+1+n+2) = 3n+3   Since the series goes from 1 to 60, the sum of the series is:   3(1+2+...+60) + 60(3) ( + +1+ +2)= 
<gadget id="calculator">( + +1+ +2)</gadget>
<output>3</output>
3n+3   Since the series goes from 1 to 60, the sum of the series is:   3(1+2+...+60) + 60(3)=   3(60)(61)/2 + 60(3) =   90*61 + 180= 
<gadget id="calculator">90*61 + 180</gadget>
<output>5_670</output>
5670   The answer is 5670.
<result>B</result>
For every positive integer n, the nth term of a sequence is the total sum of three consecutive integers starting at n. What is the total sum of terms 1 through 60 of this series?