In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term. What is the sum of the 17th, and 18th terms in the sequence?
Answers.
A) 2^18 B) 3(2^16) C) 7(2^16) D) 3(2^16) E) 7(2^15)
the sequence comes out to be 2^0,2^1,2^2,2^3 and so on...   17th term 2^16   18th term 2^17   adding all three   we get   (2^16)+(2^16)*2   so answer is 2^16(1+2)=&gt;3(2^16)   answer 3(2^16)
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In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term. What is the sum of the 17th, and 18th terms in the sequence?