If two balls are randomly selected from a green urn containing 4 black and 4 white balls and placed into a yellow urn initially containing 5 black and 3 white balls. What is the probability that the yellow urn will contain an equal number of black and white balls after the change?
Options
A) A.3/14
B) B.4/9
C) C.5/9
D) D.1/3
E) E.1/9
To have equal number of black and white balls, the yellow urn must have 5 black and 5 white balls. So the balls we select out of the green urn must be both white.   Probability (first ball is white) = 4/8   Probability(second ball is white) = 3/7   Probability (both balls are white) = (4/8)*(3/7) = 3/14   A.3/14nswer A.3/14
<result>A</result>
If two balls are randomly selected from a green urn containing 4 black and 4 white balls and placed into a yellow urn initially containing 5 black and 3 white balls. What is the probability that the yellow urn will contain an equal number of black and white balls after the change?