Ages of two brothers differ by 14 years. If 12 years ago, the elder one was 3 times as old the younger one, find their present age	Choose the most appropriate option:
A) 12,26
B) 14,28
C) 16,30
D) 19,33
E) 21,35
Explanation:   Let the age of the younger brother be x,   Then the elder brother's age is (x+14)   =&gt; 3(x-12) = (x+14-12) [12 years before]   =&gt; 3x-36 = x+2   =&gt; x = 19.   So the elder brother's age is x + 14 = 33   Answer: Option 19,33
<result>D</result>
Ages of two brothers differ by 14 years. If 12 years ago, the elder one was 3 times as old the younger one, find their present age