How many possible integer values are there for x if |x - 3| < 6 ? Choose one
A) One	B) Two	C) Three	D) eleven	E) Five
Solution: |x-3| &lt; 6   let x=a therefore we have |a-3| &lt; 6 ==&gt; read this as origin is at +3 and we have to move +6 to the right and -6 to the left   (the less than sign represents that the a must be within boundaries )   (3-6)----------3----------(3+6)   now, we have -3&lt;a&lt;9   but a =x ==&gt; -3&lt;x&lt;9   Now question says Integer values (not rational ) therefore we have -2,-1,0,1,2,3,4,5,6,7,8   Hence 11 eleven
<result>D</result>
How many possible integer values are there for x if |x - 3| < 6 ?