The wheel of a car A is having a diameter of 40 inches is rotating at the rate of x inches/minute. The wheel of another car B is having a diameter of 20 inches and is rotating at the rate of y inches/minute. What is the value of x in terms of y if both the rims reach their starting positions at the same time after every rotation?  Choices:
A) 4y  B) 2y  C) 6y  D) 3y  E) 1y
t=S1/V1=S2/V2   or 40/x=20/y   or x=40y/20=2y   Answer is 2y40 /20= 
<gadget id="calculator">40 /20</gadget>
<output>2</output>
2y   Answer is 2y
<result>B</result>
The wheel of a car A is having a diameter of 40 inches is rotating at the rate of x inches/minute. The wheel of another car B is having a diameter of 20 inches and is rotating at the rate of y inches/minute. What is the value of x in terms of y if both the rims reach their starting positions at the same time after every rotation?