The circumferences of the wheels of a carriage are 6 3/14 dm and 8 1/18 dm. What is the least distance in which both wheels simultaneously complete an integral number of revolutions ? How often will the points of the two wheels which were lowest at the time of starting touch the ground together in 1 kilometre ?	Choose the correct choice.
A) 47	B) 24	C) 45	D) 34	E) 56
LCM of 6 3/14 dm and 8 1/18 dm =435/2=217 1/2 dm   and the required no. of revolutions = 2*10000/435= 45.9   The required answer =45 times   Answer is 45
<result>C</result>
The circumferences of the wheels of a carriage are 6 3/14 dm and 8 1/18 dm. What is the least distance in which both wheels simultaneously complete an integral number of revolutions ? How often will the points of the two wheels which were lowest at the time of starting touch the ground together in 1 kilometre ?