How many ways could five people sit at a table with eight seats in which three of the eight seats will remain empty?
Choose the correct answer.
A) 6720  B) 6520  C) 56  D) 120  E) 40
ways in which 5 seats out 8 can be selected = 8C5   ways in which 5 people can be arranged in 5 seats = 5!   Total ways of arrangement = 8C5*5!   =(8!/(5!*3!))*5!   =56*120= 
<gadget id="calculator">56*120</gadget>
<output>6_720</output>
6720   6720ns= 6720
<result>A</result>
How many ways could five people sit at a table with eight seats in which three of the eight seats will remain empty?