Two digits in brother's age are the same as the digit in the sister's age, but in reverse order. In twenty nine years brother will be twice as old as sister will be then. what is the difference in their current age ?	Choose the correct option
A) 34
B) 50
C) 32
D) 28
E) 45
brother's age= 10x+y so sister's age= 10y+x..   after 29 years , 10x+y+29=2*(10y+x+29)....   so 29+19y=8x... check for odd values of y, y=1 satisfies the eqn with x=6... so ages are 61 and 16 and ans as found correctly by u is 45..45
<result>E</result>
Two digits in brother's age are the same as the digit in the sister's age, but in reverse order. In twenty nine years brother will be twice as old as sister will be then. what is the difference in their current age ?