A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 440. What is the sum of the last 8 of the even integers? Choose the correct option.
A) 568 B) 584 C) 596 D) 604 E) 612
The sum of the first 8 numbers is: x + (x+2) +...+ (x+14) = 440   The sum of the next 8 numbers is: (x+16) + (x+2+16) +...+ (x+14+16) =   440 + 8(16) = 440 + 128= 
<gadget id="calculator">440 + 128</gadget>
<output>568</output>
568   The answer is 568.
<result>A</result>
A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 440. What is the sum of the last 8 of the even integers?