If i equals the sum of the even integers from 2 to 200, inclusive, and k equals the sum of the even integers from 20 to 200, inclusive, what is the value of i - k?
Choose the correct choice from the following:	A) 10	B) 99	C) 9	D) 88	E) 90
Use following formulae for such problems:   Sum of evenly spaced integers = (# of integers)*(mean of integers)   # of integers = [(last - first)/2] + 1   Mean of integers = (last + first)/2   In above problem:   # of integers = [(200 - 2)/2] + 1= 100 and [(200-20)/2]+ 1 (200 - 2)/2  + 1= 
<gadget id="calculator">(200 - 2)/2  + 1</gadget>
<output>100</output>
100 and [(200-20)/2]+ 1 = 91   Mean of integers (200-20)/2 + 1= 
<gadget id="calculator">(200-20)/2 + 1</gadget>
<output>91</output>
91   Mean of integers= (200 + 2)/2= 
<gadget id="calculator">(200 + 2)/2</gadget>
<output>101</output>
101 and   (200 + 20)/2= 
<gadget id="calculator">  (200 + 20)/2</gadget>
<output>110</output>
110   Sum of integers= (100*101)= 
<gadget id="calculator">(100*101)</gadget>
<output>10_100</output>
10100 and   (91*110)= 
<gadget id="calculator">  (91*110)</gadget>
<output>10_010</output>
10010   Thus their difference i - k= 10100 - 10010= 
<gadget id="calculator">10100 - 10010</gadget>
<output>90</output>
90   ANSW90R:90
<result>E</result>
If i equals the sum of the even integers from 2 to 200, inclusive, and k equals the sum of the even integers from 20 to 200, inclusive, what is the value of i - k?