Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/5, 1/2 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?	Options: A) 11/8 B) 3/80 C) 9/64 D) 5/64 E) 3/64
P(Xavier will solve)=1/5   P(Yvonne will solve)=1/2   P(Zelda will NOT solve) = 1- 5/8 = 3/8.   Now, we need to multiply all this Ps to find an answer:   p= (1/5)*(1/2)*(3/8) = 3/80.   Ans. 3/80.
<result>B</result>
Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/5, 1/2 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?