If two dice are thrown simultaneously, then find the probability that the sum of numbers appeared on the dice is 6 or 7?  Answers:	A) 5/6	B) 7/36	C) 5/36	D) 11/36	E) 12/36
The sum of numbers appeared is 6 or 7. Therefore, the required sums are 6 or 7, i.e., the required events are (1,5), (5,1), (2,4), (4,2), (3,3), (1,6), (6,1), (2,5), (5,2), (3,4), (4,3)   i.e., for 6, n(E) = 5 and for 7, n(E) = 6   Therefore, the required probability = n(E)/n(S) = 11/36.   ANSWER:11/36
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If two dice are thrown simultaneously, then find the probability that the sum of numbers appeared on the dice is 6 or 7?