Three small cruise ships, each carrying 6 passengers, will dock tomorrow. One ship will dock at Port A, another at Port B, and the third at Port C. At Port A, two passengers will be selected at random and each winner will receive one gift certificate worth $50. At Port B, one passenger will be selected at random to receive a gift certificate worth $35, and at Port C, one passenger will be selected at random to receive a gift certificate worth $25. How many different ways can the gift certificates be given out?
Choose the correct choice from the following answers.
A) 1520 B) 2260 C) 2870 D) 3240 E) 4590
The number of ways for the ships to go to the ports is 3! = 6.   At Port A, the number of ways to choose two winners is 6C2 = 15.   At Port B, the number of ways to choose one winner is 6.   At Port C, the number of ways to choose one winner is 6.   The total number of ways to give out gift certificates is  6*15*6*6= 
<gadget id="calculator"> 6*15*6*6</gadget>
<output>3_240</output>
3240   The answer is 3240.
<result>D</result>
Three small cruise ships, each carrying 6 passengers, will dock tomorrow. One ship will dock at Port A, another at Port B, and the third at Port C. At Port A, two passengers will be selected at random and each winner will receive one gift certificate worth $50. At Port B, one passenger will be selected at random to receive a gift certificate worth $35, and at Port C, one passenger will be selected at random to receive a gift certificate worth $25. How many different ways can the gift certificates be given out?