A bucket contains 2 mixtures A and B in the ratio 3:2. If 5 liters of the mixture is replaced by 5 liters of liquid B, then the ratio of the two liquids becomes 3:5. How much of the liquid A was there in the bucket?
Pick:
A) 8liters B) 10liters C) 12liters D) 15liters E) 18liters
1st ratio = 3:2   2nd ratio = 3:5   Difference of cross products ratio = 3*5-3*2= 
<gadget id="calculator">3*5-3*2</gadget>
<output>9</output>
9   common factor of the 1st ratio= (quantity replaced/sum of terms in 1st ratio) + (Quantity replaced*term 8liters in 2nd ratio/Difference)   = (5/5) + (5*3/9) = 1+5/3 = 2.67   Quantity of 8liters = 3*2.67 = 8liters approximately   8litersnswer is 8liters
<result>A</result>
A bucket contains 2 mixtures A and B in the ratio 3:2. If 5 liters of the mixture is replaced by 5 liters of liquid B, then the ratio of the two liquids becomes 3:5. How much of the liquid A was there in the bucket?