Company A has 13 employees, 8 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?	Options.
A) 56 B) 231 C) 336 D) 350 E) 406
There are total of 13 employees, 8 of whom belong to the union and 5 doesn't. Out of 5 people working a shift at least 4 must belong to the union.   Now, at lest 4 out of 5 means that 4 or all 5 employees must belong to the union:   Out of 5 people working a shift 4 employees belong to the union and 1 doesn't: C48∗C15=3500;   Out of 5 people working a shift all 5 employees belong to the union: C58=56   Total # of ways:   350+56= 
<gadget id="calculator">  350+56</gadget>
<output>406</output>
406   Answer: 406.
<result>E</result>
Company A has 13 employees, 8 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?