If a number is 80% more than the another, how much % is the smaller number less than the first ?
Choose the correct answer:
A) 12(1/3)%  B) 44(2/3)%  C) 46(1/3)%  D) 16(4/3)%  E) 44(4/9)%
Take a number 100,   Then the other number is 180   % the smaller number is less than the first = [80/(180)) x 100]% = 44(4/9)%.   ANSW44(4/9)%R:44(4/9)%
<result>E</result>
If a number is 80% more than the another, how much % is the smaller number less than the first ?