If log12 27 = a, then log6 16 is:
Choose one:  A) (3-a)/4(3+a)  B) (3+a)/4(3-a)  C) 4(3+a)/(3-a)  D) 4(3-a)/(3+a)  E) 5(3-a)/(3+a)
log12 27 = a =&gt; log 27/ log 12 = a   =&gt; log 33 / log (3 * 22) =a   =&gt; 3 log 3 / log 3 + 2 log 2 = a =&gt; (log 3 + 2 log 2)/ 3 log 3 = 1/a   =&gt; (log 3/ 3 log 3) + (2 log 2/ 3 log 3) = 1/3   =&gt; (2 log 2)/ (3 log 3) = 1/a – 1/3 = (3-a)/ 3a   =&gt; log 2/ log 3= (3-a)/3a =&gt; log 3 = (2a/3-a)log2   log16 16 = log 16/ log 6 = log 24/ log (2*3) = 4 log 2/ (log 2 + log 3)   = 4(3-a)/ (3+a)   ANSWER:4(3-a)/(3+a)
<result>D</result>
If log12 27 = a, then log6 16 is: