A BAG CONTAINS 6 RED AND 4 BLUE BALLS .2 BALLS ARE DRAWN AT RANDOM. FIND THE PROBABILITY THAT THEY ARE OF SAME COLOUR.
Answers
A) 4/15 B) 5/15 C) 6/15 D) 7/15 E) 8/15
LET S BE THE SAMPLE SPACE   THEN N(S)=NO OF WAYS OF 7/15RAWING 2 BALLS OUT OF   (6+4)= 
<gadget id="calculator">  (6+4)</gadget>
<output>10</output>
10C2=(10*9)/(2*1)= 
<gadget id="calculator">(10*9)/(2*1)</gadget>
<output>45</output>
45   LET E=EVENT OF GETTING BOTH BALLS OF SAME COLOUR   THEN N(E)=NO OF WAYS(2 BALLS OUT OF SIX) OR(2 BALLS OUT OF 4)   =(6C2+4C2)=(6*5)/(2*1)+(4*3)/(2*1)=15+6= 
<gadget id="calculator">15+6</gadget>
<output>21</output>
21   P(E)=N(E)/N(S)=21/45=7/15   Option: 7/15
<result>D</result>
A BAG CONTAINS 6 RED AND 4 BLUE BALLS .2 BALLS ARE DRAWN AT RANDOM. FIND THE PROBABILITY THAT THEY ARE OF SAME COLOUR.