In a box, there are 5 blue, 8 white and 3 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?  Choose one:
A) 3/16  B) 5/16  C) 8/32  D) 2/32  E) 9/32
Total number of bulbs = (5 + 8 + 3)= 
<gadget id="calculator">(5 + 8 + 3)</gadget>
<output>16</output>
16.   Let E= event that the bulb drawn is neither white nor blue = event that the bulb drawn is yellow.   Therefore, P(E)=3/16   3/16NSWER:3/16
<result>A</result>
In a box, there are 5 blue, 8 white and 3 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?