How many numbers with 3 different digits can be formed using only the even-numbered digit?  Answers:	A) 10	B) 24	C) 40	D) 60	E) 120
Odd digits are 2, 4, 6, 8.   We want 3 different digits.   First digit can be chosen in 4 ways.   Second digit can be chosen in 3 ways.   Third digit can be chosen in 2 ways.   Total ways = 4*3*2= 
<gadget id="calculator">4*3*2</gadget>
<output>24</output>
24   Hence option (24).
<result>B</result>
How many numbers with 3 different digits can be formed using only the even-numbered digit?