David invested certain amount in three different schemes A, B and C with the rate of interest 10% p.a., 12% p.a. and 15% p.a. respectively. If the the total interest accrued in one year was 3200 and the amount invested in Scheme C was 150% of the amount invested in Scheme A and 240% of the amount invested in Scheme B, what was the amount invested in Scheme B?
Choose the most appropriate option:
A) 5000	B) 6500	C) 8000	D) cannot be determined	E) None of these
Let x, y and z be the amounts invested in schemes A, B and C respectively. Then,   (x×10×1/100)+(y×12×1/100)+(z×15×1/100)=3200   ⇒ 10x + 12y + 15z = 320000 ..... (i)   Now, z = 240% of y = 12⁄5y..... (ii)   And, z = 150% of x = 3⁄2x   ⇒ x = 2⁄3z = (2⁄3 × 12⁄5)y = 8⁄5y......(iii)   From (i),(ii) and (iii), we have :   16y + 12y + 36y = 320000 ⇒ 64y = 320000 ⇒ y = 5000.   ∴ Sum invested in Scheme B = 5000.   5000nswer 5000
<result>A</result>
David invested certain amount in three different schemes A, B and C with the rate of interest 10% p.a., 12% p.a. and 15% p.a. respectively. If the the total interest accrued in one year was 3200 and the amount invested in Scheme C was 150% of the amount invested in Scheme A and 240% of the amount invested in Scheme B, what was the amount invested in Scheme B?