A coin is weighted so that the probability of heads on any flip is 0.8, while the probability of tails is 0.2. If the coin is flipped 5 times independently, which of the following represents the probability that tails will appear no more than twice? Choose the correct choice from the following choices:
A) (0.8)^5 + 5(0.8)^4(0.2) + 10(0.8)^3(0.2)^2	B) (0.8)^5 + 4(0.8)^4(0.2) + 6(0.8)^3(0.2)^2	C) (0.6)^5 + 3(0.6)^4(0.4) + 2(0.6)^3(0.4)^2	D) (0.8)^5 + 2(0.8)^4(0.2) + (0.8)^3(0.2)^2	E) (0.6)^5 + (0.6)^4(0.4) + (0.6)^3(0.4)^2
Probability of Head, P(H) = 0.8   Probability of Tail, P(T) = 0.2   Tail will appear NO more than twice   i.e. favourable cases   2 Tails and 3 Heads, Probability = 5C2*(0.8)^3*(0.2)^2   1 Tail and 4 Heads, Probability = 5C1*(0.8)^4*(0.2)^2   0 Tail and 5 Heads, Probability = (0.8)^5   Required Probability = Sum of all Favourable cases = (0.8)^5 + 5(0.8)^4(0.2) + 10(0.8)^3(0.2)^2   (0.8)^5 + 5(0.8)^4(0.2) + 10(0.8)^3(0.2)^2nswer: option (0.8)^5 + 5(0.8)^4(0.2) + 10(0.8)^3(0.2)^2
<result>A</result>
A coin is weighted so that the probability of heads on any flip is 0.8, while the probability of tails is 0.2. If the coin is flipped 5 times independently, which of the following represents the probability that tails will appear no more than twice?