There are 5 houses on a street: house A, B, C, D and E. The distance between any two adjacent houses is 100 feet. There are 2 children living in house A, 3 children living in house B, 4 children living in house C, 5 children living in house D and 6 children living in house E. If the school bus can only make one stop on that street, in front of which house should the bus stop so that the sum of walking distance among all children will be the least? Select the correct option.
A) house A  B) house B  C) house C  D) house D  E) house E
If we move the stop from house A to house B, 2 children (who live in house A) will have to walk 100 feet more each, but 18 children (who live in house B &amp; C &amp; D &amp; E) will walk 100 feet less each. Therefore, it will be 1800 – 200 =1600 feet less walk if we move the stop from house A to house B.   If we move the stop from house B to house C, 5 children (who live in house A &amp; B) will walk 100 feet more each, but 15 children (who live in house C &amp; D &amp; E) will walk 100 feet less each. Therefore, it will save a total of 1500 – 500 =1000 feet if we move the stop from house B to house C.   If we move the stop from house C to house D, 9 children (who live in house A &amp; B &amp; C) will walk 100 feet more each, but 11 children (who live in house D &amp; E) will walk 100 ft. less each. Therefore, it will be 1100 – 900 =200 feet less walk if we move the stop from house C to house D.   If we move the stop from house D to house E, 14 children (who live in house A &amp; B &amp; C &amp; D) will walk 100 feet more each, but 6 children (who live in house E ) will walk 100 feet less each. Therefore, it will be 1400 – 600 = 800 feet more walk if we move the stop from house D to house E.   Therefore, children will walk the least if the bus stop is at House D.   correct answer house D
<result>D</result>
There are 5 houses on a street: house A, B, C, D and E. The distance between any two adjacent houses is 100 feet. There are 2 children living in house A, 3 children living in house B, 4 children living in house C, 5 children living in house D and 6 children living in house E. If the school bus can only make one stop on that street, in front of which house should the bus stop so that the sum of walking distance among all children will be the least?