Let R1 and R2 respectively denote the maximum and minimum possible remainders when (276)n is divided by 91 for any natural number n , n>= 144. Find R1+R2.
Select
A) 90  B) 82  C) 84  D) 64  E) None
Explanation :   The remainder when 276 divided by 91 is 3 hence   remainder of (276)n/91 = remainder 3n/91   Taking n = 1,2,3,4,5   We get the possible remainders as 3, 9, 27, 81, 61, 1 respectively.   For n&gt;5, the pattern repeats   Hence R1 = 81 and R2 = 1   R1+R2 = 81+1= 
<gadget id="calculator">81+1</gadget>
<output>82</output>
82   Answer : 82
<result>B</result>
Let R1 and R2 respectively denote the maximum and minimum possible remainders when (276)n is divided by 91 for any natural number n , n>= 144. Find R1+R2.