Three positive integers a, b, and c are such that their average is 20 and a ≤ b ≤ c. If the median is (a + 13), what is the least possible value of c?	Answers.
A) 21 B) 22 C) 23 D) 24 E) 25
Solution:   We know that the average value is 20 therefore (a+b+c)/3 = 20   so a+b+c = 60   and b = a + 13   therefore a + (a + 13) + c = 60   The least value of c is when c = b   so take c = a + 13   hence, a + (a + 13) + (a + 13) = 60   i.e., a = 34/3 a non integer therefore c is not equal to b   so take c = b+1 therefore c = a+14   a + (a + 13) + (a + 14) = 60   i.e., a= 33/3= 
<gadget id="calculator">33/3</gadget>
<output>11</output>
11   hence, a= 11, b = 24, and c = 25   Answer: 25
<result>E</result>
Three positive integers a, b, and c are such that their average is 20 and a ≤ b ≤ c. If the median is (a + 13), what is the least possible value of c?