The number of sequences in which 4 players can throw a ball, so that the youngest player may not be the last is ?	Options
A) 24  B) 22  C) 10  D) 16  E) 18
x Not younger   The last ball can be thrown by any of the remaining 4 players. The first 6 players can throw the ball in 3P3 ways.   The required number of ways = 3(3!)   = 18   Answer:18
<result>E</result>
The number of sequences in which 4 players can throw a ball, so that the youngest player may not be the last is ?