What is the smallest of six consecutive odd integers whose average (arithmetic mean) is b + 2?  Choose the correct choice from the following answers
A) b -3 B) b- 6 C) b- 1 D) b E) b+ 1
Since the numbers are consecutive odd integers, mean = median = 3rd integer + 4th integer /2   b -3nd 1st integer= 3rd integer- 4   let's say 3rd integer = n and 4th integer = n+2   2n+2/2= b+2   n= b+1   1st integer= b+1-4= b-3   b -3 is the answer
<result>A</result>
What is the smallest of six consecutive odd integers whose average (arithmetic mean) is b + 2?