There are three departments having students 62,58,24 .In an exam they have to be seated in rooms such that each room has equal number of students and each room has students of one type only (No mixing of departments). Find the minimum number of rooms required? Select the correct option:  A) 72  B) 74  C) 75  D) 76  E) 77
WE NEED TO TAKE GCD WHICH IS 2   THUS ALL THE ROOMS WILL HAVE 2 STUDENTS OF THE SAME DEPT   1) 62/2 = 31   2) 58/2 = 29   3) 24/2 = 12   TOTAL NO. OF MIN ROOMS REQD = 31+12+29= 
<gadget id="calculator">31+12+29</gadget>
<output>72</output>
72   72NSWER:72
<result>A</result>
There are three departments having students 62,58,24 .In an exam they have to be seated in rooms such that each room has equal number of students and each room has students of one type only (No mixing of departments). Find the minimum number of rooms required?