In a triangle ABC, AB = 6, BC = 8 and AC = 10. A perpendicular dropped from B, meets the side AC at D. A circle of radius BD (with centre B) is drawn. If the circle cuts AB and BC at P and Q respectively, then AP : QC is equal to  Choose the correct choice.
A) 1:1	B) 3:2	C) 4:1	D) 3:8	E) 2:5
Explanation :   Triangle ABC and Triangle A3:8B are similar,   AC/AB= BC/B3:8   10/6=8/r   r=24/5   BP=BQ=B3:8=r=24/5   AP=AB-r= 6-24/5 = 6/5   CQ=BC-r=8-24/5=16/5   AP:CQ= 6/16 = 3:8   Answer : 3:8
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In a triangle ABC, AB = 6, BC = 8 and AC = 10. A perpendicular dropped from B, meets the side AC at D. A circle of radius BD (with centre B) is drawn. If the circle cuts AB and BC at P and Q respectively, then AP : QC is equal to