You roll P (P > 1) number of Q (Q > 1) sided dice at once. What is the probability that at least two of the P dice will land on difference numbers. Choose the correct option
A) 1 - P/(Q^P)	B) 1 - Q/(P^Q)	C) 1 - 1/(P^(Q-1))	D) 1 - 1/(Q^(P-1))	E) 1 - 1/(Q-1)^P
This can be calculated by first finding the probability of all dice landing on the same number, and taking 1 - it:   The incorrect rolls are any Q-ples: 11...1, 22...2, ..., PP...P. This is makes Q possibilities. The P dice can roll Q*Q*...*Q (Q^P) number of ways. Thus the probability of landing on the same number is Q/(Q^P) = 1/(Q^(P-1)). Therefore, the probability of at least two of the P dice landing on different numbers is:   1 - 1/(Q^(P-1))   Answer: 1 - 1/(Q^(P-1)).
<result>D</result>
You roll P (P > 1) number of Q (Q > 1) sided dice at once. What is the probability that at least two of the P dice will land on difference numbers.