Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/3, 1/2 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?
Choose the correct option:	A) 1/16	B) 7/8	C) 9/64	D) 5/64	E) 3/64
P(Xavier will solve)=1/3   P(Yvonne will solve)=1/2   P(Zelda will NOT solve) = 1- 5/8 = 3/8.   Now, we need to multiply all this Ps to find an answer:   p= (1/3)*(1/2)*(3/8) = 1/16.   Ans. 1/16.
<result>A</result>
Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/3, 1/2 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?