From a group of 5men and 4 women, 3 persons are to be selected to form a committee so that at least 2 men are there are on the committee. In how many ways can it be done? Choose one:
A) 20  B) 50  C) 65  D) 86  E) 96
We have (2men and 1 woman) or (3men only)   Therefore, Required number of ways= (5C2*4C1) + (5C3)   = (5*4)/(2*1) * 4 + 5C2   = 10*4 + 10   = 40 +10= 
<gadget id="calculator">40 +10</gadget>
<output>50</output>
50   ANSWER:50
<result>B</result>
From a group of 5men and 4 women, 3 persons are to be selected to form a committee so that at least 2 men are there are on the committee. In how many ways can it be done?