If the length of a rectangle is increased by 10% and the area is unchanged , then its corresponding breadth must be decreased by?	Choose the correct option:
A) 9 1/19
B) 9 1/15
C) 9 1/16
D) 9 1/11
E) 9 1/10
Suppose length = 100m and breadth = x m   Area = 100 m   New length = 110m and breadth = (x-y% of x)   Then, \inline 110\times (x-\frac{y}{100}x)=100\times x   \inline \Rightarrow \inline 110\times (1-\frac{y}{100})=100   \inline \Rightarrow \inline 1-\frac{y}{100}=\frac{100}{110}   \inline \Rightarrow \frac{y}{100}=1-\frac{100}{110}=\frac{1}{11}   \inline y=\frac{100}{11}=9\frac{1}{10}%   Answer:9 1/10
<result>E</result>
If the length of a rectangle is increased by 10% and the area is unchanged , then its corresponding breadth must be decreased by?