Henry solved a certain number of algebra problems in an hour, his older brother Frank solved
four times as many. Together they solved 80. How many were solved by each? Choose one:
A) H-12 F-49	B) H-30 F-83	C) H-20 F-90	D) H-16 F-64	E) H-40 F-100
I am looking for the number of problems solved by Henry (H) and Frank (F).   Who solved the least number of problems? Hopefully, you said Henry.   So let H = x   Frank solved four times as many, therefore   F = 4x   Read the problem again to find a relationship. Together they solved 80. That means that   H + F = 80 Substituting   x + 4x = 80 Solving for x   5x = 80   x = 16   Therefore Henry solved 16 and Frank solved 4 times 16 of 64 problems.   correct answer H-16 F-64
<result>D</result>
Henry solved a certain number of algebra problems in an hour, his older brother Frank solved
four times as many. Together they solved 80. How many were solved by each?