In a mixture of milk and water, the proportion of milk by weight was 80%. If, in a 180 gm mixture, 36 gms of pure milk is added, what would be the percentage of milk in the mixture formed?  Choose the correct option:  A) 83.37%  B) 83.23%  C) 83.39%  D) 82.33%  E) 83.33%
Percentage of milk in the mixture formed   = [80/100 (180) + 36] / (180 + 36) * 100%   = (144 + 36)/216 * 100%   = 5/6 * 100%   = 83.33%   Answer: 83.33%
<result>E</result>
In a mixture of milk and water, the proportion of milk by weight was 80%. If, in a 180 gm mixture, 36 gms of pure milk is added, what would be the percentage of milk in the mixture formed?