What is the value of(a,y) in (13^-20-a*13^y)=168*13^-22? Options.
A) (1,2)
B) (0,1)
C) (-1,22)
D) (1,-22)
E) (1,-20)
(13^-20-a*13^y)=168*13^-22   Divide the LHS and RHS by 13^-22   13^2-a*13^(y+22) =168   168 can be expressed as 13^2 - 1   13^2-a*13^(y+22) =13^2 - 1   a*13^(y+22) =1   Now look at options and substitute .. Its easy for y=-22 . 13^0=1 a also = 1   ANSWER:(1,-22)
<result>D</result>
What is the value of(a,y) in (13^-20-a*13^y)=168*13^-22?