A rectangular photograph is surrounded by a border that is 2 inch wide on each side. The total area of the photograph and the border is M square inches. If the border had been 4 inches wide on each side, the total area would have been (M + 94) square inches. What is the perimeter of the photograph, in inches?	Options.
A) 34	B) 36	C) 23	D) 40	E) 42
Let Length and Breadth of photograph be L and B respectively.   Perimeter is given by 2*(L+b) -----(1)   According to the question:   (L+4)(B+4) = m ----(2)   and   (L+8)(B+8) = m + 94 ---------&gt; (L+8)(B+8) - 94 = m ------(3)   Equating (2) and (3)   (L+4)(B+4) = (L+8)(B+8) - 94   LB + 4L + 4B + 16 = LB + 8L + 8B + 64 -94   Simplify   4L + 4B = 46 ------&gt; 2(L+B) =23 (23heck eq (1))   Answer is 23
<result>C</result>
A rectangular photograph is surrounded by a border that is 2 inch wide on each side. The total area of the photograph and the border is M square inches. If the border had been 4 inches wide on each side, the total area would have been (M + 94) square inches. What is the perimeter of the photograph, in inches?