Let f(x) = x^2 + bx + c. If f(6) = 0 and f(-1) = 0, then b + c =	Choose the correct choice from the following
A) 18
B) 15
C) -15
D) -11
E) -24
f(x) = x^2 + bx + c. If f(6) = 0 and f(-1) = 0, then b + c =   f(6) = 0= 36+6b+c--- Taking 36 to the other side   -&gt; 6b+c= -36   f(-1) = 0= 1-b+c --- taking -b+c to the other side   -&gt; b-c=1   When we add these 2 equations, we get 7b= -35---&gt; b= -5   And while substituting b= -5 we get c= -6.   b+c= -11--- Answer -11
<result>D</result>
Let f(x) = x^2 + bx + c. If f(6) = 0 and f(-1) = 0, then b + c =