A division of a company consists of six men and six women. If two of these twelve employees are randomly selected as representatives of the division, what is the probability that both representatives will be female?  Choose the correct answer.
A) 5/22	B) 7/22	C) 5/33	D) 7/33	E) 5/66
The total number of ways to choose two representatives is 12C2=66.   The number of ways to choose two females is 6C2=15.   P(choosing two female representatives)=15/66=5/22   The answer is 5/22.
<result>A</result>
A division of a company consists of six men and six women. If two of these twelve employees are randomly selected as representatives of the division, what is the probability that both representatives will be female?