How many different arrangements of A, B, C, D, and E are possible where A is not adjacent to B ?  Choose the correct choice from the following.
A) 72
B) 48
C) 32
D) 30
E) 1
So you have 72,B,C,D,E   five possible ways to arrange it = 5! = 120   72B cannot be adjacents   (72B),C,D,E = 4! = 24 x 2(because it can be (72B) or (B72) ) = 48   120 -48- = 72 possible ways   72
<result>A</result>
How many different arrangements of A, B, C, D, and E are possible where A is not adjacent to B ?