In how many ways can the digit of the number 2233558888 be arranged so that the odd digits are placed in the even positions?  Choose the correct answer:
A) 380  B) 400  C) 430  D) 450  E) 480
odd place combination = 5!/2!*2!=30   even place combination= 6!/2!*4!=15   to total=30*15= 
<gadget id="calculator">30*15</gadget>
<output>450</output>
450   ANSWER:450
<result>D</result>
In how many ways can the digit of the number 2233558888 be arranged so that the odd digits are placed in the even positions?