A shepherd has 1million sheep at the beginning of Year 2010. The no's grow by xx during the yr. A famine hits his village in the next year & many of his sheep die. The sheep population decreases by yy during 2001 and at the beginning of 2011 the shepherd finds that he is left with 1million sheep. Which of the following is correct? Choose the correct choice from the following answers.
A) x<y
B) x>y
C) x=y
D) x<=y
E) x>=y
Let us assume the value of xx to be 10%10%.   Therefore, the number of sheep in the herd at the beginning of year 2001 (end of 2000) will be 1 million + 10%10% of 1 million = 1.1 million   In 2001, the numbers decrease by y%y% and at the end of the year the number sheep in the herd = 1 million.   i.e., 0.1 million sheep have died in 2001.   In terms of the percentage of the number of sheep alive at the beginning of 2001,   it will be (0.1/1.1)×100%=9.09%(0.1/1.1)×100%=9.09%.   From the above illustration it is clear that x&gt;y   x&gt;y
<result>B</result>
A shepherd has 1million sheep at the beginning of Year 2010. The no's grow by xx during the yr. A famine hits his village in the next year & many of his sheep die. The sheep population decreases by yy during 2001 and at the beginning of 2011 the shepherd finds that he is left with 1million sheep. Which of the following is correct?