If logX/(a2 + ab + b2) = log Y/(b2 + bc + c2) = logZ/(c2 + ca + a2), then Xa - b.Yb - c. Zc - a =? Choose the correct option:  A) 0  B) -1  C) 1  D) 2  E) 3
Each ratio = k = log X = k(a2 + ab + b2)   =&gt; (a - b)logX = k(a3 - b3)   Similarly, Yb - c = ek(b3 - c3), Zc - a= ek(c3 - a3)   Therefore, Xa - b.Yb - c.Zc - a = e0 = 1.   ANSWER:1
<result>C</result>
If logX/(a2 + ab + b2) = log Y/(b2 + bc + c2) = logZ/(c2 + ca + a2), then Xa - b.Yb - c. Zc - a =?