Two numbers have a H.C.F of 11 and a product of two numbers is 1991. Find the L.C.M of the two numbers?  Pick one:  A) 140  B) 181  C) 160  D) 170  E) 180
L.C.M of two numbers is given by   (Product of the two numbers) / (H.C.F of the two numbers) = 1991/11= 
<gadget id="calculator">1991/11</gadget>
<output>181</output>
181.   ANSWER:181
<result>B</result>
Two numbers have a H.C.F of 11 and a product of two numbers is 1991. Find the L.C.M of the two numbers?