In how many E ways can 4 white and 3 black chess pieces be arranged in a row such that they occupy alternate places? Assume that the pieces are distinct.	Choose the correct choice from the following answers.
A) E=288
B) E=144
C) 12
D) 48
E) 96
4 white chess pieces can be arranged in 4! ways and 4 black pieces can be arranged in 3 ! ways.   W_W_W_W   Number of ways = 4!*3! = 24 * 6= 
<gadget id="calculator">24 * 6</gadget>
<output>144</output>
144   Answer E=144
<result>B</result>
In how many E ways can 4 white and 3 black chess pieces be arranged in a row such that they occupy alternate places? Assume that the pieces are distinct.