In a box, there are 12 red, 6 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?	Pick one
A) 12/23	B) 10/21	C) 7/12	D) 11/31	E) 13/17
Total number of balls = 10+6+5 = 23   E = event that the ball drawn is neither red nor green   = event that the ball drawn is red   n(E) = 12   P(E) = 12/23   12/23nswer is 12/23
<result>A</result>
In a box, there are 12 red, 6 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?