What is the least possible value of expression E = (x-1)(x-3)(x-4)(x-6)+10 for real values of x? Choose the correct answer.
A) 1	B) 10	C) 9	D) 0	E) 8
Explanation :   E = (x-1)(x-6)(x-3)(x-4)+10   E = (x2-7x+6)(X2-7x+12)+10   Let x2-7x+6 = y   E = y2+6y+10   E = (y+3)2 + 1   Minimum value = 1 , when y = -3   1nswer : 1
<result>A</result>
What is the least possible value of expression E = (x-1)(x-3)(x-4)(x-6)+10 for real values of x?