If 200 lb of a mixture contain 80% husk and 20% sand. Then how much husk needs to be extracted in order to have 75% concentration of Husk? Choose one.
A) 1/4  B) 20/3  C) 1/2  D) 40  E) 60
We need to extract 40 lb of husk.   80 % of 200 = 160   20 % of 200 = 40   Now we have t remove husk to have 75 % of Husk ( key point sand is not supposed to be removed)   Let X be the new quantity after removing husk   So, 40 = 25 % of X   X = 160   Husk will 120 lbs , hence we need to remove 1/4 of the total husk or 40 lbs   ANSWER:40
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If 200 lb of a mixture contain 80% husk and 20% sand. Then how much husk needs to be extracted in order to have 75% concentration of Husk?