The odds in favour of an event A are 3:4.The odds against anotehr independent event B are 7:4. What is the probability that at least one of the events will happen ?  Choose the correct answer:  A) 1/11  B) 7/11  C) 6/11  D) 8/11  E) None of these
Explanation :   The odds in favour of an event A are 3:4.   =&gt; Probability of A = P(A) = 3/(3+4) = 3/7.   The odds against an event B are 7 : 4.   =&gt; Probability of B = P(B) = 4/(7+4) = 4/11.   The probability of occurrence of at least one of the events A and B,   P(A+B) = P(A) + P(B) - P(AB).   =&gt;P(A+B) = P(A) + P(B) - P(A) x P(B).   =&gt; (3/7) + (4/11) - (3/7)(4/11).   =&gt; 7/11.   Hence, the required probability is 7/11.   Answer : 7/11
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The odds in favour of an event A are 3:4.The odds against anotehr independent event B are 7:4. What is the probability that at least one of the events will happen ?