Patrick has three daughters named Avery, Bridget, & Catherine. He decides he wants to make a 3-letter password using the a combination of the each of their first initials (e.g. ABC, CBA, etc.). How many different permutations can he come up with?  Choose the correct choice from the following:  A) 3  B) 5  C) 6  D) 8  E) 11
Permutation calc is: n P r = n! / (n-r)! 3 P 3 = 3!/(3-3)! = 3x2x1/0!=6/1= 
<gadget id="calculator">6/1</gadget>
<output>6</output>
6 6orrect answer is 6 (6) ANSWER:6
<result>C</result>
Patrick has three daughters named Avery, Bridget, & Catherine. He decides he wants to make a 3-letter password using the a combination of the each of their first initials (e.g. ABC, CBA, etc.). How many different permutations can he come up with?