How many five digit numbers can be formed using digits 0,1,2,3,4,5, Which are divisible by 12, without any of the digits repeating?
Answers:
A) 100
B) 98
C) 81
D) 96
E) 72
0,1,2,3,4,5   One digit will have to remain out for all 5 digit numbers;   if 0 is out; Leftover digits will be 1,2,3,4,5 = Sum(1,2,3,4,5)=15. Ignore   if 1 is out; Leftover digits will be 0,2,3,4,5 = Sum(0,2,3,4,5)=14. Ignore   if 3 is out; Leftover digits will be 0,1,2,4,5 = Sum(0,1,2,4,5)=12.   4*4! = 4*24= 
<gadget id="calculator">4*24</gadget>
<output>96</output>
96   if 4 is out; Leftover digits will be 0,1,2,3,5= Sum(0,1,2,3,5)=11. Ignore   if 5 is out; Leftover digits will be 0,1,2,3,4 = Sum(0,1,2,3,4)=10. Ignore   Total count of numbers divisible by 12 = 96   Ans:96
<result>D</result>
How many five digit numbers can be formed using digits 0,1,2,3,4,5, Which are divisible by 12, without any of the digits repeating?