A bag contains 26 purple jellybeans, 15 green jellybeans, and 9 yellow jellybeans; these jellybeans are the only items in the bag. If a person reaches into the bag and picks out only purple jellybeans, how many jellybeans would the person have to pick out in order to double the probability that a jellybean picked out of the bag at random would be a green jellybean?	Select:	A) 5	B) 15	C) 19	D) 24	E) 25
Chances of picking a green at present = 15 / (26 + 15 + 9) = 15/50 = 3/10   So required is double that chance = 2 * 3/10 = 3/5   since only purple are removed, the new count be x, 3/5 = 15 (x + 15 + 9)   solving for x gives x = 1.   So 26 -1= 
<gadget id="calculator">26 -1</gadget>
<output>25</output>
25 purple jellybeans needs to be removed.   Answer is 25
<result>E</result>
A bag contains 26 purple jellybeans, 15 green jellybeans, and 9 yellow jellybeans; these jellybeans are the only items in the bag. If a person reaches into the bag and picks out only purple jellybeans, how many jellybeans would the person have to pick out in order to double the probability that a jellybean picked out of the bag at random would be a green jellybean?