In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?	Select the correct option:
A) 7/8
B) 4/5
C) 3/2
D) 2/3
E) 1/3
Total number of balls = (8 + 7 + 6)= 
<gadget id="calculator">(8 + 7 + 6)</gadget>
<output>21</output>
21.   Let E= event that the ball drawn is neither red nor green   = event that the ball drawn is blue.   n(E) = 7.   P(E) =n(E)/n(S)=7/21=1/3.   Ans: 1/3
<result>E</result>
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?