You have a bag of 9 letters: 3 Xs, 3 Ys and 3 Zs. You are given a box divided into 3 rows and 3 columns for a total of 9 areas. How many different E ways can you place one letter into each area such that there are no rows or columns with 2 or more of the same letter?	Choose the correct choice:
A) 5
B) 6
C) 9
D) 12
E) 18
Consider one particular arrangement of the first row: XYZ, then we can construct only two boxes with so that no rows or columns have 2 or more of the same letter:   XYZ   YZX   ZXY   And:   XYZ   ZXY   YZX   Now, the first row itself can be arranged in 3!=6 ways (since there are three distinct letter), hence the total number of boxes possible E is   2*6= 
<gadget id="calculator">  2*6</gadget>
<output>12</output>
12.   Answer: 12.
<result>D</result>
You have a bag of 9 letters: 3 Xs, 3 Ys and 3 Zs. You are given a box divided into 3 rows and 3 columns for a total of 9 areas. How many different E ways can you place one letter into each area such that there are no rows or columns with 2 or more of the same letter?