If m^2-8m+1=0,then m^3+m^(-3)= ?  Choose the correct option:
A) 487	B) 488	C) 489	D) 457	E) 495
here from equation 1 we will get   m^2-8m+1=0   m^2=8m-1   m=(8m-1)/m.........(1)   m=8-1/m   so m+1/m=8   now in equation 2   m^3+1/m^3   (m+1/m)(m^2 - m*1/m + 1/m^2)   (m+1/m)(m^2 - 1 + 1/m^2)   (m+1/m)(m^2 + 1/m^2 - 1)   (m+1/m){(m+1/m)^2 - 2m*1/m - 1} {since a^2+b^2=(a+b)^2-2ab}   (m+1/m){(m+1/m)^2 - 2-1}   now putting the value of m from equation 1   8(8^2-2-1)   8(64-3)   =488   ANSWER:488
<result>B</result>
If m^2-8m+1=0,then m^3+m^(-3)= ?