If (10^20) – 65 is written as a base 10 integer, what is the sum of the digits in that integer?	Choose the correct choice from the following answers.
A) 200
B) 170
C) 180
D) 100
E) 210
We know that (10^20) is ending 00, so (10^20) – 65=9....9935   total number of digits in (10^20) – 65 is 20, or 18 digits of 9 and two digits 3 and 5.   answer choice is 18*9+(3+5)   18*9+8= 
<gadget id="calculator">18*9+8</gadget>
<output>170</output>
170   Answer is 170 170
<result>B</result>
If (10^20) – 65 is written as a base 10 integer, what is the sum of the digits in that integer?