If m is an integer such that (-2)^2m=2^(6-m) then m=? Choices:  A) 1  B) 2  C) 3  D) 5  E) 6
(-2)^(2m) = 4^m   and   2^(6-m) = 4^((6-m)/2)   Therefore,   m = (6-m)/2   2m = 6 - m   m = 2   Answer 2
<result>B</result>
If m is an integer such that (-2)^2m=2^(6-m) then m=?