A jogger running at 9 km/hr along side a railway track is 190 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?	Choices:
A) 88  B) 27  C) 36  D) 31  E) 12
Speed of train relative to jogger = 45 - 9= 
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
36 km/hr.= 36 * 5/18= 
<gadget id="calculator">36 * 5/18</gadget>
<output>10</output>
10 m/sec.   Distance to be covered= 190 + 120= 
<gadget id="calculator">190 + 120</gadget>
<output>310</output>
310 m.   Time taken= 310/10= 
<gadget id="calculator">310/10</gadget>
<output>31</output>
31 sec.   Answer: 31
<result>D</result>
A jogger running at 9 km/hr along side a railway track is 190 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?