If x and y are non-zero integers, and 16x^4 – 4y^4 = 4x^2 + 2y^2, which of the following could be the value of x2 in terms of y?
Pick one.
A) 2y^2 B) 2y^2+3/4 C) 2y^2+1/4 D) 2y^2+1/2 E) 2y^2+1/6
16x^4 – 4y^4 = 4x^2 + 2y^2   (4x^2 + 2y^2) (4x^2 - 2y^2) = 4x^2 + 2y^2   4x^2 - 2y^2 = 1   4x^2 = 2y^2+1   x^2 = 2y^2+1/4   Answer : 2y^2+1/4
<result>C</result>
If x and y are non-zero integers, and 16x^4 – 4y^4 = 4x^2 + 2y^2, which of the following could be the value of x2 in terms of y?