If y = x^2 + px + q, y is minimum when x is:	Choose the correct choice from the following:
A) p /q	B) -p/q	C) -p/2	D) -q/2	E) q/p
We're given the equation Y = X^2 + pX + q.   IF.. we use a simple Classic Quadratic....   p = 2   q = 1   Y = X^2 + 2X + 1   We can then go about finding the answer that yields the MINIMUM result when X = ...   Answer A: p/q = 2/1= 
<gadget id="calculator">2/1</gadget>
<output>2</output>
2 --&gt; 4+4+1= +9   Answer B: -p/q = -2/1 = -2 --&gt; 4-4+1 = +1   Answer -p/2: -p/2 = -2/2 = -1 --&gt; 1-2+1 = 0   Answer D: -q/2 = -1/2 --&gt;(1/4)-1+1 = +1/4   Answer E: q/p = 1/2 --&gt; (1/4)+1+1 = +2 1/4   From these results, we can see the minimum result:   -p/2
<result>C</result>
If y = x^2 + px + q, y is minimum when x is: