2 students gave an examination. One of them scored 9 marks more than other and his marks were 56% of the sum of total of both their marks. What are their individual marks? Answers.
A) 42,38	B) 42,31	C) 42,32	D) 42,33	E) 42,34
Explanation:   Let marks of one of the students be X.   The marks of the other will be X+9   According to question, X+9 = 56% of X+ (X+9)   Solving, X + 9 = 56/100* (2X + 9)   =&gt; 25X + 225 = 28X + 126   =&gt; 3X = 99   =&gt; X = 33   Marks of one are 33, while of the other are 33+9= 
<gadget id="calculator">33+9</gadget>
<output>42</output>
42.   ANSWER: 42,33
<result>D</result>
2 students gave an examination. One of them scored 9 marks more than other and his marks were 56% of the sum of total of both their marks. What are their individual marks?