5 blue marbles, 3 red marbles and 4 purple marbles are placed in a bag. If 4 marbles are drawn without replacement, what is the probability that the result will not be 2 blue and 2 purple marbles? Choose the correct choice from the following.
A) 4/33	B) (5/36)^2	C) 1/2	D) (31/36)^2	E) 29/33
Answer is 29/33.   The probability of 2 blue and 2 purple marbles selected is 5C2.4C2/12C4 =4/33.   Subtracting the above from 1 we get 29/33 29/33
<result>E</result>
5 blue marbles, 3 red marbles and 4 purple marbles are placed in a bag. If 4 marbles are drawn without replacement, what is the probability that the result will not be 2 blue and 2 purple marbles?