B takes 12 more days than A to finish a task. B and A start this task and A leaves the task 12 days before the task is finished. B completes 60% of the overall task. How long would B have taken to finish the task if he had worked independently?	Answers:	A) 48 days	B) 36 days	C) 28 days	D) 32 days	E) 30 days
DETAILED SOLUTION   Let us say A and B split their share of the task and started doing their respective shares simultaneously.   Let’s say A takes A days to finish the task. Therefore, B takes A + 12 days to finish the entire task.   A has to finish 40% of the task, since B is doing the rest. So A will only take 2A/5 number of days.   B only has to finish 60% of the task, so B will take (3(A+12)/5) number of days.   But as we know, B starts working along with A and finishes 12 days after A stops working.   So, (3(A+12)/5) = ((2A)/5+12)   3A + 36 = 2A + 60   A = 24; B = 36 days.   Answer choice 36 days
<result>B</result>
B takes 12 more days than A to finish a task. B and A start this task and A leaves the task 12 days before the task is finished. B completes 60% of the overall task. How long would B have taken to finish the task if he had worked independently?