Alex climbs a mountain peak and back from base. He takes the exact same route both ways. On the trip out he climbs up at an average speed of 5 miles per hour. On the trip back he climbs down at an average speed of 25 miles per hour. What is his approximate average speed for the round trip in miles per hour? Options:	A) 8.33	B) 18.3	C) 20	D) 22	E) 25
Average speed = total distance/total time   Here distance to peak and back is same as he takes the same route.   D = 5T1 and D=25T2   Therefore, T1 = D/5 and T2 = D/25   T1+T2 = 6d/25   Therefore, average speed = 2d/6d/25 =2d * 25/6d   8.33nswer is 8.3 Since, the options are far away we need not solve till the decimal points   So correct answer is option 8.33
<result>A</result>
Alex climbs a mountain peak and back from base. He takes the exact same route both ways. On the trip out he climbs up at an average speed of 5 miles per hour. On the trip back he climbs down at an average speed of 25 miles per hour. What is his approximate average speed for the round trip in miles per hour?