In an increasing sequence of 8 consecutive even integers, the sum of the first 4 integers is 284. What is the sum of all the integers in the sequence?  Choose the correct choice from the following options
A) 552
B) 568
C) 574
D) 586
E) 600
let the first term of the sequence be x   since it is consecutive even integers the terms be we x, x+2,x+4...x+14 (up to 8 terms)   now,   sum of first 4 terms =284   or,   4x+12=284   x=272/4= 
<gadget id="calculator">272/4</gadget>
<output>68</output>
68   Thus the answer can now be calculated by either summing up 68+70+72+... 8th term   or   s=n/2(2a+(n-1)d   =8/2(2*68+(7*2))   =4(136+14)=600   600
<result>E</result>
In an increasing sequence of 8 consecutive even integers, the sum of the first 4 integers is 284. What is the sum of all the integers in the sequence?