If n is an integer and 101n^2 is less than or equal to 8100, what is the greatest possible value of n?  Answers
A) 7
B) 8
C) 9
D) 10
E) 11
101 * n^2 &lt;=8100   n^2 &lt;=8100/101 which will be less than 81 since  8100/100= 
<gadget id="calculator"> 8100/100</gadget>
<output>81</output>
81 which is the square of 9   Next closest value of n where n^2&lt;=81 is 8   Ans 8
<result>B</result>
If n is an integer and 101n^2 is less than or equal to 8100, what is the greatest possible value of n?