How many different 5 digit numbers can be formed from the number 28579 by re-arranging its digits so that the odd digits occupy even position Choose the correct choice from the following answers.
A) 12
B) 5
C) 7
D) 3
E) 1
There are 3 odd numbers which have to be placed at 3 even places =3!=6 ways   There are 2 even numbers which have to be placed at 2 odd places. So 2! = 2 ways   so total number of ways of arranging all these numbers are  6 * 2= 
<gadget id="calculator"> 6 * 2</gadget>
<output>12</output>
12 ways   12nswer:12
<result>A</result>
How many different 5 digit numbers can be formed from the number 28579 by re-arranging its digits so that the odd digits occupy even position