What are the last two digits of 33*76*47*22*58*91? Choose one:
A) 16  B) 20  C) 18  D) 22  E) 24
33*76*47*22*58*91=   We have to focus on the last two digits only, so 33*76=08*47=76*22=72   72*58=76 therefore 76*91=16   Hence 16nswer is 16
<result>A</result>
What are the last two digits of 33*76*47*22*58*91?