There are 6 orators A, B, C, D, E, F. In how many ways can the arrangements be made so that A always comes before B and B always comes before C.  Choose the correct choice from the following choices: A) 6! / 3! B) 8! / 6! C) 5! x 3! D) 8! / (5! x 3!) E) 8! / (5! x 4!)
Select any three places for A, B and C. They need no arrangement amongst themselves as A would always come before B and B would always come before C.   The remaining 3 people have to be arranged in 3 places.   Thus, 6C3 x 3! = 6! / 3!   6! / 3!NSWER:6! / 3!
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There are 6 orators A, B, C, D, E, F. In how many ways can the arrangements be made so that A always comes before B and B always comes before C.