In an increasing sequence of 8 consecutive even integers, the sum of the first 4 integers is 292. What is the sum of all the integers in the sequence?
Options:
A) 552	B) 616	C) 774	D) 886	E) 990
let the first term of the sequence be x   since it is consecutive even integers the terms be we x, x+2,x+4...x+14 (up to 8 terms)   now,   sum of first 4 terms =292   or,   4x+12=292   x=280/4= 
<gadget id="calculator">280/4</gadget>
<output>70</output>
70   Thus the answer can now be calculated by either summing up 70+72+74+... 8th term   or   s=n/2(2a+(n-1)d   =8/2(2*70+(7*2))   =4(140+14)=616   616
<result>B</result>
In an increasing sequence of 8 consecutive even integers, the sum of the first 4 integers is 292. What is the sum of all the integers in the sequence?