In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?	Choose one:
A) 5/21	B) 5/22	C) 5/12	D) 5/29	E) 5/21
Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)   As remaining person can be any one among three couples left.   Required probability = (⁵C₂ * ⁶C₁)/¹⁰C₅   = (10 * 6)/252 = 5/21   5/21nswer: 5/21
<result>A</result>
In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?