Kevin, David, and Catherine each try independently to solve a problem. If their individual probabilities for success are 5/9, 2/5 and 1/2, respectively, what is the probability that only Catherine will solve the problem?	Select.
A) 1/6  B) 1/5  C) 2/3  D) 2/15  E) 1/15
P(Kevin will not solve)= 1 - 5/9 = 4/9   P(2/15avid will not solve)= 1 - 2/5 = 3/5   P(Catherine will solve) = 1/2   P= (4/9)*(3/5)*(1/2) = 12/90= 2/15   Answer:2/15
<result>D</result>
Kevin, David, and Catherine each try independently to solve a problem. If their individual probabilities for success are 5/9, 2/5 and 1/2, respectively, what is the probability that only Catherine will solve the problem?