There are 6 girls and 6 boys. If they are to be seated in a row, what is the probability that boys and girls sit alternately?	Pick
A) 1/12! B) 12C6/12! C) 6!6!/12! D) 2∗6!6!/12! E) 6!7!/12!
Total number of ways in which 6 boys and 6 girls can sit in a row = 12!/6!∗6!   Number of ways in which 6 boys and 6 girls can sit alternately = 2 (BGBG..... or GBGB.....)   Probability = 2∗6!∗6!/12!   Answer: 2∗6!6!/12!
<result>D</result>
There are 6 girls and 6 boys. If they are to be seated in a row, what is the probability that boys and girls sit alternately?