There is a sequence A(n) such that A(n+1)=2A(n)-1 and A(1)=3, where n is a positive integer. What is the value of A(76)-A(75)?  Choose the correct option
A) 2^22+1	B) 2^23+1	C) 2^23+1	D) 2^24	E) 2^75
A1= 3   A2= 2*3-1= 
<gadget id="calculator">2*3-1</gadget>
<output>5</output>
5   A3= 2*5-1= 
<gadget id="calculator">2*5-1</gadget>
<output>9</output>
9   A4= 2*9-1= 
<gadget id="calculator">2*9-1</gadget>
<output>17</output>
17   We can notice that there is a squence   A2-A1= 2^1   A3-A2= 2^2   A4-A3= 2^3   Hence A76-A75= 2^75   2^75 is the answer
<result>E</result>
There is a sequence A(n) such that A(n+1)=2A(n)-1 and A(1)=3, where n is a positive integer. What is the value of A(76)-A(75)?