Lines y=√2·x+5 and y=3√2·x−1 intersect at what height above the x axis?	Pick:  A) -8√2  B) 0  C) 7√2  D) 8  E) 4√2
Solve two equations for y   y=√2·x+5   y=3√2·x−1   Set the two equations equal to each other and solve for x   √2·x+5 = 3√2·x−1   6 = 2√2·x   6/(2√2) = x   3/√2 = x   Plug x = 3/√2 into any one of the original equations to find the y value (height above x axis) where the two lines intersect   y=√2·x+5   y=√2·(3/√2)+5   y = 3 + 5= 
<gadget id="calculator">3 + 5</gadget>
<output>8</output>
8   Final answer:   8) 8
<result>D</result>
Lines y=√2·x+5 and y=3√2·x−1 intersect at what height above the x axis?