The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
Choose the correct choice from the following options.
A) 74	B) 94	C) 184	D) 364	E) 375
L.C.M. of 6, 9, 15 and 18 is 90.   Let required number be 90k + 4, which is multiple of 7.   Least value of k for which (90k + 4) is divisible by 7 is k = 4.   Required number = (90 x 4) + 4 = 364. Answer: Option 364
<result>D</result>
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: