On the first day of her vacation, Louisa traveled 160 miles. On the second day, traveling at the same average speed, she traveled 280 miles. If the 160-mile trip took 3 hours less than the 280-mile trip, what was the average speed, in miles per hour?  Select:
A) 40 B) 45 C) 46 D) 48 E) 50
(time)*(rate) = (distance)--&gt;(rate) = (distance)/(time)--&gt; given:(rate) = 160/t =280/(t+3)--&gt;4/t = 7/(t+3)--&gt;4t+12=7t ----&gt;3t= 12 . t= 4 ----&gt;(rate ) = 160/4= 
<gadget id="calculator">160/4</gadget>
<output>40</output>
40   40nswer: 40
<result>A</result>
On the first day of her vacation, Louisa traveled 160 miles. On the second day, traveling at the same average speed, she traveled 280 miles. If the 160-mile trip took 3 hours less than the 280-mile trip, what was the average speed, in miles per hour?