The dimensions of a certain machine are 48*32*52,if the size of the machine is increased proportionally until sum of dimensions equals 156.
Options:  A) 56*40*50  B) 56*40*40  C) 56*40*30  D) 56*40*20  E) 56*40*60
Given dimensions of a machine are 48*32*52   if the size is raised proportionally untill the sum of dimensions   sum of given dimensions is   48+32+52= 
<gadget id="calculator">  48+32+52</gadget>
<output>132</output>
132   difference of actual and increased=156-132= 
<gadget id="calculator">156-132</gadget>
<output>24</output>
24   24/3= 
<gadget id="calculator">24/3</gadget>
<output>8</output>
8   this means each dimension has to raise for 8 units   thus the new dimensions are 56*40*60   ANSW56*40*60R:56*40*60
<result>E</result>
The dimensions of a certain machine are 48*32*52,if the size of the machine is increased proportionally until sum of dimensions equals 156.