Product M is produced by mixing chemical X and chemical Y in the ratio of 5 : 4. Chemical X is prepared by mixing two raw materials, A and B, in the ratio of 1 : 3. Chemical Y is prepared by mixing raw materials, B and C, in the ratio of 2 : 1. Then the final mixture is prepared by mixing 864 units of product M with water. If the concentration of the raw material B in the final mixture is 50%, how much water had been added to product M?  Choose the correct choice from the following.
A) 328 units  B) 368 units  C) 392 units  D) 616 units  E) None of the above
The final product is obtained by mixing 864 units of product M with water.   In 864 units of Product M, amount of B = 864×77/108 = 616   In the final mixture, concentration of B is 50%.   Therefore, the total quantity of final mixture = 616 × 2 = 1232   Water added = 1232 – 864 = 368   The correct answer is Choice 368 units.
<result>B</result>
Product M is produced by mixing chemical X and chemical Y in the ratio of 5 : 4. Chemical X is prepared by mixing two raw materials, A and B, in the ratio of 1 : 3. Chemical Y is prepared by mixing raw materials, B and C, in the ratio of 2 : 1. Then the final mixture is prepared by mixing 864 units of product M with water. If the concentration of the raw material B in the final mixture is 50%, how much water had been added to product M?