The rate of a certain chemical reaction is directly proportional to the square of the concentration of chemical A present and inversely proportional to the concentration of chemical B present. If the concentration of chemical B is increased by 100%, which of the following is closest to the percent change in the concentration of chemical A required to keep the reaction rate unchanged?	Answers.
A) 100% decrease B) 50% decrease C) 40% decrease D) 40% increase E) 50% increase
CA: Concentration A   CB: Concentration B   R: Reaction rate   Formula for reaction rate:   R = (CA^2) / CB   Thus if CB is increased by 100% &gt;&gt; means concentration doubles &gt;&gt; 2xCB   Thus, for R to remain the same (CA^2) also has to double.   &gt;&gt; 2 x (CA^2) &gt;&gt; to see what happens to CA, take the 2 into the bracket by taking its root   &gt;&gt; (SQRT 2 CA)^2   SQRT 2 is roughly 40% &gt;&gt; answer 40% increase
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The rate of a certain chemical reaction is directly proportional to the square of the concentration of chemical A present and inversely proportional to the concentration of chemical B present. If the concentration of chemical B is increased by 100%, which of the following is closest to the percent change in the concentration of chemical A required to keep the reaction rate unchanged?