The sum of five consecutive odd numbers of set p is 435. What is the sum of five consecutive numbers of another set q. Whose largest number is 45 more than the largest number of set p?
Pick one:	A) 530	B) six hundred seventy	C) 730	D) 770	E) None of these
Let the five consecutive odd numbers of set p be 2n - 3, 2n - 1, 2n + 1, 2n + 3, 2n + 5.   Sum of these five numbers   = 2n - 3 + 2n - 1 + 2n + 1 + 2n + 3 + 2n + 5   = 10n + 5 = 435 =&gt; n = 43   Largest number of set p = 2(43) + 5 = 91   The largest number of set q = 91 + 45= 
<gadget id="calculator">91 + 45</gadget>
<output>136</output>
136=&gt; The five numbers of set q are 132, 133, 134, 135, 136.   Sum of above numbers = 132 + 133 + 134 + 135 + 136= 
<gadget id="calculator">132 + 133 + 134 + 135 + 136</gadget>
<output>670</output>
670.   ANSWER:six hundred seventy
<result>B</result>
The sum of five consecutive odd numbers of set p is 435. What is the sum of five consecutive numbers of another set q. Whose largest number is 45 more than the largest number of set p?