A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is	Select:
A) 40  B) 30  C) 55  D) 73  E) 52
A   40   Let distance = x km and usual rate = y kmph.   Then, x/y - x/(y+3) = 40/60 --&gt; 2y (y+3) = 9x ----- (i)   40lso, x/(y-2) - x/y = 40/60 --&gt; y(y-2) = 3x -------- (ii)   On dividing (i) by (ii), we get: x = 40.
<result>A</result>
A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is