In the junior basketball league there are 18 teams, 2/3 of them are bad and ½ are rich. What can't be the number of teams that are rich and bad? Select the correct option: A) 4. B) 6. C) 7. D) 8. E) 10
otal teams =18   bad teams=(2/3)*18= 
<gadget id="calculator">(2/3)*18</gadget>
<output>12</output>
12   rich teams=9   so maximum value that the both rich and bad can take will be 9. so E= 10 can not be that value.   ANSW10R:10
<result>E</result>
In the junior basketball league there are 18 teams, 2/3 of them are bad and ½ are rich. What can't be the number of teams that are rich and bad?