Lorna invests $9000, with some at 6% annual interest and some at 11% annual interest. If she receives a total of $580 from these investments at the end of a year, how much was invested at the 6% interest rate?
Choose the correct choice from the following answers:  A) $160  B) $1,600  C) $2,200  D) $4,400  E) $1,800
We have that 'x' invested at 6%   We also have that '9000-x' invested at 11%   Now then 580/9000 is approx 10%   Therefore, -4x+9000-x=0   5x=9000   x=1800 approximately. Probably higher   Only $1,800 matches
<result>E</result>
Lorna invests $9000, with some at 6% annual interest and some at 11% annual interest. If she receives a total of $580 from these investments at the end of a year, how much was invested at the 6% interest rate?