In how many ways can 5 GIRLS and 3 BOYS be seated on 8 chairs so that no two BOYS are together? Choose the correct option
A) A)5760 B) B)14400 C) C)480 D) D)56 E) E)40320
Consider the following arrangement:   *G*G*G*G*G   Now, if BOYS occupy the places of 6 stars no BOYS will be together.   # of ways 3 14400OYS can occupy the places of these 6 stars is C36=20;   # of ways 3 14400OYS can be arranged on these places is 3!=6   # of ways 5 GIRLS can be arranged is 5!=120   So total # of ways to arrange 3 14400OYS and 5 GIRLS so that no 14400OY are together is 20∗6∗120=14,400   ANS:14400
<result>B</result>
In how many ways can 5 GIRLS and 3 BOYS be seated on 8 chairs so that no two BOYS are together?