List R contains five numbers that have an average value of 60. If the median of the numbers in the list is equal to the mean and the largest number is equal to 20 more than two times the smallest number, what is the smallest possible value in the list?	Choose the correct choice:
A) 25
B) 28
C) 31
D) 34
E) 37
The middle number is 60.   Let the smallest number be x. Then the largest number is 2x+20.   To make x as small as possible, let's make the remaining numbers as large as possible.   So the second largest = the largest = 2x+20.   The second smallest should be equal to the median.   The numbers are x, 60, 60, 2x+20, 2x+20.   x + 60 + 60 + 2x + 20 + 2x + 20 = 5*60= 
<gadget id="calculator">5*60</gadget>
<output>300</output>
300   5x= 140   x = 28   The answer is 28.
<result>B</result>
List R contains five numbers that have an average value of 60. If the median of the numbers in the list is equal to the mean and the largest number is equal to 20 more than two times the smallest number, what is the smallest possible value in the list?