Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 63, the three numbers in order are?  Choose the most appropriate option.
A) 27, 54, and 108	B) 54, 27, and 108	C) 108, 27, and 54	D) 108, 54, and 27	E) 54, 108, and 27
Let the numbers be 2x, x and 4x   (2x + x + 4x)/3 = 63   7x/3 = 63   x = 27   The numbers in order are 54, 27, and 108   The answer is 54, 27, and 108.
<result>B</result>
Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 63, the three numbers in order are?