Find the least number which when divided by 37 and 7 leaves a remainder of 2 in each case. Choose the correct option:
A) 259	B) 261	C) 263	D) 265	E) 267
The least number which when divided by different divisors leaving the same remainder in each case   = LCM(different divisors) + remainder left in each case.   Hence the required least number   = LCM(37, 7) + 2 = 261.   ANSWER:261
<result>B</result>
Find the least number which when divided by 37 and 7 leaves a remainder of 2 in each case.