If |x^2 − 6| = x, which of the following could be the value of x?  Choose the correct answer.
A) –3  B) –2  C) 0  D) 1  E) 2
The LHS is not negative, so the RHS is also not negative. Thus x &gt;= 0.   First, let's assume that x^2-6 is negative.   -(x^2 - 6) = x   x^2 + x - 6 = 0   (x+3)(x-2) = 0   x = 2 or x = -3 (However, x can not be negative.)   Then x=2 is a possible value for x.   The answer is 2.
<result>E</result>
If |x^2 − 6| = x, which of the following could be the value of x?