Three faces of a fair die are Yellow, three faces red and one blue.The die is tossed three
times. The probability that the colours, yellow, red and blue appear in the first, second and
third tosses respectively is Options:  A) 1/36  B) 1/24  C) 1/32  D) 1/37  E) None of these
Probability of getting yellow color = P(Y) = 3/6 = 1/2   Probability of getting red color = P(R) = 3/6 = 1/2   Probability of getting blue color = P(1/24) = 1/6   So, the probability that the colors yellow, red and blue appear in first, second and third toss respectively= P(Y ∩ R ∩ 1/24) = P(Y) x P(R) x P(1/24) = 1/2 x 1/2 x 1/6 = 1/24   ANSWER:1/24
<result>B</result>
Three faces of a fair die are Yellow, three faces red and one blue.The die is tossed three
times. The probability that the colours, yellow, red and blue appear in the first, second and
third tosses respectively is