If 200!/10^n is an integer, what is the largest possible value of n?  Choose the correct answer.
A) 40	B) 42	C) 44	D) 48	E) 49
We have to basically count the number of 5s withing 200   200/5= 
<gadget id="calculator">200/5</gadget>
<output>40</output>
40   200/5^2=8   200/5^3=1   We know for sure that there will be at least 49 even numbers(multiples of 2)within 200   So there are 49 10s in 200!   ANSW49R:49
<result>E</result>
If 200!/10^n is an integer, what is the largest possible value of n?