There is a road beside a river. Two friends started from a place A, moved to a temple situated at another place B and then returned to A again. One of them moves on a cycle at a speed of 12 km/hr, while the other sails on a boat at a speed of 10 km/hr. If the river flows at the speed of 4 km/hr, which of the two friends will return to place A first? Choose one
A) 5.4 km /hr B) 7.2 km /hr C) 8.4 km/hr D) 9.6 km /hr E) None
Solution   Clearly, the cyclist moves both ways at a speed of 12 km/hr.   So, average speed of the cyclist	= 12 km/hr.   Average speed	= (2x14x6/14+6) km/hr   = 42/5= 
<gadget id="calculator">42/5</gadget>
<output>42/5 = around 8.4</output>
8.4 kmph   Since the average speed of the cyclist is greater, he will return to A first.   Answer 8.4 km/hr
<result>C</result>
There is a road beside a river. Two friends started from a place A, moved to a temple situated at another place B and then returned to A again. One of them moves on a cycle at a speed of 12 km/hr, while the other sails on a boat at a speed of 10 km/hr. If the river flows at the speed of 4 km/hr, which of the two friends will return to place A first?