If |x^2 − 12| = x, which of the following could be the value of x?  Select:  A) -4  B) -3  C) 1  D) 2  E) 3
|x2−12|=x|x2−12|=x   |x2−12||x2−12|cannot be negative; anything that comes out of mod is always positive   so |x2−12|&gt;0|x2−12|&gt;0   Out of our options A= -4 B= -3 cannot be the right answer because none of them are greater than 0   Now only Option C=1 or D=2 or E=3 are contenders for right answers.   A quick Cursory crude calculation will tell you that 3 is the right choice   |−32−12|=3|−32−12|=3   |9−12|=3|9−12|=3   |−3|=3|−3|=3   3=33=3   ANSW3R IS 3
<result>E</result>
If |x^2 − 12| = x, which of the following could be the value of x?