If sum of three numbers in A.P is 33 and sum of their squares id 491, then what are the three numbers. Answers.
A) 5,11,17
B) 7,11,15
C) 9,11,13
D) 3,11,19
E) 3,12,19
a + (a + d ) + ( a + 2d ) = 3( a + d ) = 33,   a + d = 11, or second term = 11 , first term = 11– d ,   Then ( 11- d ) 2 + 11 2 + ( 11 + d ) 2 = 491   2 d 2 = 491 - ( 3 * 121 ) = 491 - 363= 
<gadget id="calculator">491 - 363</gadget>
<output>128</output>
128   d 2= 64, d = 8, a = 3,   ANSWER:3,11,19
<result>D</result>
If sum of three numbers in A.P is 33 and sum of their squares id 491, then what are the three numbers.