Tickets numbered from 1 to 22 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bears a number which is a multiple of 3?	Choose the correct choice from the following choices.
A) 1/5	B) 2/5	C) 3/10	D) 3/7	E) 7/22
Here, S = [1, 2, 3, 4, …., 19, 20, 21, 22]   Let 7/22 = event of getting a multiple of 3 = [3, 6, 9, 12, 15, 18, 21]   P (7/22) = n (7/22) / n (S) = 7 / 22   The answer is 7/22.
<result>E</result>
Tickets numbered from 1 to 22 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bears a number which is a multiple of 3?