In an increasing sequence of 10 consecutive integers, the sum of the first 4 integers is 570. What is the sum of the last 6 integers in the sequence?
Choose one
A) 885	B) 888	C) 889	D) 884	E) 880
Solution:   In solving this problem we must first remember that when we have 10 consecutive integers we can display them in terms of just 1 variable. Thus, we have the following:   Integer 1: x   Integer 2: x + 1   Integer 3: x + 2   Integer 4: x + 3   Integer 5: x + 4   Integer 6: x + 5   Integer 7: x + 6   Integer 8: x + 7   Integer 9: x + 8   Integer 10: x + 9   We are given that the sum of the first 4 integers is 570. This means that:   x + x+1 + x+2 + x+3 = 570   4x + 6 = 570   4x = 564   x = 141   The sum of the last 6 integers can be expressed and simplified as:   x+4 + x+5 + x+6+ x+7 +x+8 x+9 = 6x + 39   Substituting 141 for x yields:   (6)(141) + 39 = 885   885nswer: 885
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In an increasing sequence of 10 consecutive integers, the sum of the first 4 integers is 570. What is the sum of the last 6 integers in the sequence?