A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
Answers
A) 200	B) 350	C) 270	D) 874	E) 125
Explanation:   The number of ways to select two men and three women = 5C2 * 6C3   = (5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)= 
<gadget id="calculator">(5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)</gadget>
<output>200</output>
200   200nswer: 200
<result>A</result>
A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?