Suppose f(x) is an odd function for which f(x + 2) = f(x) for all x, and
f(x) = x2 for x 2 (0, 1). Compute f(-3/2) + f(1).  Pick one
A) -1  B) -1/2  C) -1/4  D) 1/4  E) 1/2
Because f is periodic, we know that f(-3/2) = f(1/2) = (1/2)2 = 1=4. Because f   is odd, we know that f(1) = -f(/1), but because f is periodic, f(1) = f(-1). Therefore,   f(1) = 0 and the answer is 1=4.   correct answer 1/4
<result>D</result>
Suppose f(x) is an odd function for which f(x + 2) = f(x) for all x, and
f(x) = x2 for x 2 (0, 1). Compute f(-3/2) + f(1).