How many positive three-digit integers are divisible by both 2 and 7?  Choose the correct choice from the following answers.
A) 40
B) 46
C) 52
D) 64
E) 70
A number to be divisible by both 2 and 7 should be divisible by the least common multiple of 2 and 7 so by 14.   Multiples of 14 between 100 and 999, inclusive is   (last-first)/multiple+1=(994-112)/14+1=63+1= 
<gadget id="calculator">63+1</gadget>
<output>64</output>
64   Answer: 64.
<result>D</result>
How many positive three-digit integers are divisible by both 2 and 7?