The ages of two persons differ by 16 years. If 6 years ago , the elder one be 3 times as old as the younger one, find their present ages .
Choose the correct answer:
A) 10 years and 18 years B) 18 years and 26 years C) 20 years and 28 years D) 14 years and 30 years E) 16 years and 25 years
Explanation :   Sol. Let the age of the younger person be xx years   Then , age of the elder person = (x+16)(x+16) years   âˆ´âˆ´ 3(xâˆ’6)=(x+16âˆ’6)3(x-6)=(x+16-6)   â‡” 3x âˆ’18=x+10â‡” 3x -18=x+10   â‡” 2x=28â‡” 2x=28   â‡” x=14â‡” x=14   Hence, their present age are 14 years and 30 years .   ANSWER IS 14 years and 30 years
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The ages of two persons differ by 16 years. If 6 years ago , the elder one be 3 times as old as the younger one, find their present ages .