Set S is the prime integers between 0 and 30. If three numbers are chosen randomly from set S, what is the probability that the sum of these three numbers is odd?  Choose the correct choice from the following choices
A) 15/56	B) 3/8	C) 15/28	D) 7/10	E) 3/4
Total number of combinations=10C3=120...............(1)   Total number of combinations including2and two other numbers=9C2=36......................(2)   Therefore the difference ie. (1)-(2) is the set of 3 primes without 2=(120-36)= 
<gadget id="calculator">(120-36)</gadget>
<output>84</output>
84   So, probability=84/120=7/10   7/10
<result>D</result>
Set S is the prime integers between 0 and 30. If three numbers are chosen randomly from set S, what is the probability that the sum of these three numbers is odd?