Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:  Answers:
A) 9
B) 11
C) 13
D) 15
E) 19
Let the three integers be x, x + 2 and x + 4.   Then, 3x = 2(x + 4) + 3 x = 11.   Third integer = x + 4 = 15.   Answer: 15
<result>D</result>
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is: