A driver took a trip consisting of three segments at three different speeds. The driver drove a distance of (5D) at a speed of (2V), then a distance of (7D) at a speed of (3V), then a distance of D at a speed of (6V). In terms of D and V, what was the total time of the trip?	Answers: A) 3D/V B) 4D/V C) 5D/V D) 6D/V E) 7D/V
The total time of the trip was:   5D/2V + 7D/3V + D/6V =   30D/12V + 28D/12V + 2D/12V =   60D/12V = 5D/V   The answer is 5D/V.60 /12= 
<gadget id="calculator">60 /12</gadget>
<output>5</output>
5D/V   The answer is 5D/V.
<result>C</result>
A driver took a trip consisting of three segments at three different speeds. The driver drove a distance of (5D) at a speed of (2V), then a distance of (7D) at a speed of (3V), then a distance of D at a speed of (6V). In terms of D and V, what was the total time of the trip?