What is the smallest no. which must be added to 25268 so as to obtain a sum which is divisible by 11?	Options:  A) 5  B) 10  C) 11  D) 20  E) 30
For divisibility by 11, the difference of sums of digits at even and odd places must be either zero or divisible by 11.   For 25268, Difference =(2+2+8) -(5+6)=12-11= 
<gadget id="calculator">12-11</gadget>
<output>1</output>
1.   The units digit is at odd place. So we add 10 to the number=&gt; 25268 +10= 
<gadget id="calculator">25268 +10</gadget>
<output>25_278</output>
25278   Now , (2+2+8) -(5+7)=12-12= 
<gadget id="calculator">12-12</gadget>
<output>0</output>
0=&gt;25268 is also divisible by 11   10
<result>B</result>
What is the smallest no. which must be added to 25268 so as to obtain a sum which is divisible by 11?