How many positive three-digit integers are divisible by both 5 and 7? Select the correct option
A) 10	B) 15	C) 18	D) 20	E) 26
A number to be divisible by both 5 and 7 should be divisible by the least common multiple of 5 and 7 so by 35.   Multiples of 35 between 100 and 999, inclusive is   (last-first)/multiple+1=(980-105)/35+1=25+1= 
<gadget id="calculator">25+1</gadget>
<output>26</output>
26   Answer: 26.
<result>E</result>
How many positive three-digit integers are divisible by both 5 and 7?