The value of each of 5 numbers is at least 8. The average (arithmetic mean) of these 5 numbers is 24. If the average of two of the numbers is 18, what is the largest possible value that any of these 5 numbers can have? Choose the correct answer.
A) 28  B) 50  C) 68  D) 76  E) 84
Average =&gt; (a1+a2+a3+a4+a5)/5 =24   Thus =&gt; a1+a2+a3+a4+a5 = 120   now least value is 8, so let a1 = 8   average of 2 numbers is 18   thus , let (a2+a3) /2 =18   a2+a3 = 36   This tells that sum of last 2 numbers should be :     120 -8-36= 
<gadget id="calculator">  120 -8-36</gadget>
<output>76</output>
76   Then by elimination , eliminate 84 and 76   highest possible value of a5 should be 68 from the answer choice   Answer : 68
<result>C</result>
The value of each of 5 numbers is at least 8. The average (arithmetic mean) of these 5 numbers is 24. If the average of two of the numbers is 18, what is the largest possible value that any of these 5 numbers can have?