If p^2 – 13p + 40 = d, and p is a positive integer between 1 and 10, inclusive, what is the probability that d < 0?	Choose the most appropriate option:  A) 1/10  B) 1/5  C) 2/5  D) 3/5  E) 3/10
p2 – 13p + 40 = d   so (p – 8)(p – 5) = d   For q to be negative, the expressions (p – 8) and (p – 5) must have opposite signs. Which integers on the number line will yield opposite signs for the expressions (p – 8) and (p – 5)? Those integers in the range 5 &lt; p &lt; 8 (notice 5 and 8 are not included because they would both yield a value of zero and zero is a nonnegative integer). That means that there are only two integer values for p, 6 and 7, that would yield a negative q. With a total of 10 possible p values, only 2 yield a negative q, so the probability is 2/10 or 1/5.   The correct answer is 1/5.
<result>B</result>
If p^2 – 13p + 40 = d, and p is a positive integer between 1 and 10, inclusive, what is the probability that d < 0?