A 6-liter solution is 30% alcohol. How many liters of pure alcohol must be added to produce a solution that is 50% alcohol?	Pick:
A) 1.8	B) 2.1	C) 2.4	D) 2.7	E) 3.0
Let x be the amount of pure alcohol required.   0.3(6) + x = 0.5(x+6)   0.5x = 3 - 1.8   x = 2.4 liters   The answer is 2.4.
<result>C</result>
A 6-liter solution is 30% alcohol. How many liters of pure alcohol must be added to produce a solution that is 50% alcohol?