The area of one square is x^2 + 10x + 25 and the area of another square is 4x^2 − 12x + 9. If the sum of the perimeters of both squares is 32, what is the value of x?  Select the correct option:
A) 0 B) 2 C) 2.5 D) 4.67 E) 10
spotting the pattern of equations both are in form of (X+C)^2 so   A1= (x+5)^2 &amp; A2= (2x-3)^2   L1= x+5 &amp; L2= 2x-3   P1 = 4( x+5) &amp; P2=4(2x-3)   P1+P2=32   4( x+5) +4(2x-3)=32..............&gt; X=2   Answer: 2
<result>B</result>
The area of one square is x^2 + 10x + 25 and the area of another square is 4x^2 − 12x + 9. If the sum of the perimeters of both squares is 32, what is the value of x?