If a and b are digits, and the number a99,99b/88 = an integer, what are the values of a and b?
Options.
A) a = b = 7 B) a = b = 6 C) a = b = 3 D) a = b = 1 E) a = b = 2
a99,99b, divisible by 88.   Factors of 88 = (8)(11)   Divisible by 8: if the last 3 digits of the number are divisible by 8.   99b/8 =&gt; 992/8= 
<gadget id="calculator">992/8</gadget>
<output>124</output>
124=&gt; b = 2   Divisibe by 11: subtract the last digit from the number, over and over again, as necessary. If the remaining number is divisible by 11, the original number is divisible by 11.   a9999-2 =&gt; a999-7 =&gt; a99-2 =&gt; a9-7= 
<gadget id="calculator">9-7</gadget>
<output>2</output>
&gt; a2=&gt; 22/11= 
<gadget id="calculator">22/11</gadget>
<output>2</output>
2.   So a= 2.   Answer: a = b = 2
<result>E</result>
If a and b are digits, and the number a99,99b/88 = an integer, what are the values of a and b?