A bag holds 4 red marbles and 3 green marbles. If you removed two randomly selected marbles from the bag, without replacement, what is the probability that both would be red?  Answers.
A) 1/10	B) 1/5	C) 3/10	D) 2/7	E) 1/2
probability of selecting first red marble = 4/7   probability of selecting second red marble without replacement = 3/6   final probability = 4/7 * 3/6 = 2/7   The correct answer is 2/7.
<result>D</result>
A bag holds 4 red marbles and 3 green marbles. If you removed two randomly selected marbles from the bag, without replacement, what is the probability that both would be red?