Out of three given numbers, the first one is twice the second and three times the third. If the average of these numbers is 88, then the difference between first and third is. Choose one:
A) 92
B) 39
C) 87
D) 96
E) None
Sum of three number is=88*3= 
<gadget id="calculator">88*3</gadget>
<output>264</output>
264   Let three numbers are a, b,c and a is the highest and c is the lowest   Then,   2b=a so b=a/2 and 3c=a so c=a/3   we can write,   a+b+c=264   a+a/2+a/3=264   11a/6=264   a=144   So, c=144/3= 
<gadget id="calculator">144/3</gadget>
<output>48</output>
48   So there difference is=144-48= 
<gadget id="calculator">144-48</gadget>
<output>96</output>
96   Answer 96
<result>D</result>
Out of three given numbers, the first one is twice the second and three times the third. If the average of these numbers is 88, then the difference between first and third is.