In a box of 12 pens, a total of 6 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?	Choose the correct choice from the following options:
A) 1/6
B) 5/22
C) 6/11
D) 9/16
E) 3/4
Method- 1   There are 9 fine pieces of pen and 6 defective in a lot of 12 pens   i.e. Probability of first pen NOT being defective = (6/12)   i.e. Probability of Second pen NOT being defective = (5/11) [11 pen remaining with 5 defective remaining considering that first was defective]   Probability of 5/22oth pen being NON-defective = (6/12)*(5/11) = 5/22   Answer: option 5/22
<result>B</result>
In a box of 12 pens, a total of 6 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?