Out of 6 fruits in a basket, 2 are rotten. If two fruits are drawn at random from the basket, the probability of both being rotten is
Choose the most appropriate option:	A) 1/15	B) 10/13	C) 21/15	D) 15/21	E) 2/21
The number of exhaustive events = 6C2 = 15.   Let E be event of the 2 fruits being rotten. The number of favourable cases are   2C2 = 1 way.   Required probability = 1/15.   1/15NSWER:1/15
<result>A</result>
Out of 6 fruits in a basket, 2 are rotten. If two fruits are drawn at random from the basket, the probability of both being rotten is