A division of a company consists of three men and seven women. If two of these ten employees are randomly selected as representatives of the division, what is the probability that both representatives will be female?	Answers.
A) 11/45	B) 7/45	C) 11/30	D) 7/30	E) 7/15
The total number of ways to choose two representatives is 10C2=45.   The number of ways to choose two females is 7C2=21.   P(choosing two female representatives)=21/45=7/15   The answer is 7/15.
<result>E</result>
A division of a company consists of three men and seven women. If two of these ten employees are randomly selected as representatives of the division, what is the probability that both representatives will be female?