If the operation ∆ is defined by a ∆ b = (b - a)^2/a^2 for all numbers a and b, and a ≠ 0, then what is the result when we evaluate this expression: (-6) ∆ (6 ∆ −6) ?
Choices
A) 36/25	B) 81/4	C) 25/4	D) 49/9	E) 25/9
(-6) ∆ (6 ∆ −6) =   (-6) ∆ (12^2/6^2) =   (-6) ∆ (4) =   (-10^2) / (-6)^2 = 100/36 = 25/9   The answer is 25/9.
<result>E</result>
If the operation ∆ is defined by a ∆ b = (b - a)^2/a^2 for all numbers a and b, and a ≠ 0, then what is the result when we evaluate this expression: (-6) ∆ (6 ∆ −6) ?