Four different objects 1,2,3,4 are distributed at random in four places marked 1,2,3,4. What is probability that none of the objects occupy the place corresponding to it's number?
Choose one:
A) 17/24
B) 3/8
C) 1/2
D) 5/8
E) 1/3
Since, we know there are only 24 possible outcomes in TOTAL, it might not be a big deal just LIST the outcomes where no object is in right place.   We'll list the objects (1, 2, 3, and 4) in an order so that no number is in the correct place.   To begin, we'll place a 2 in the first position to get the following:   2134   2341   2413   There are 3 possible outcomes.   IF we place a 3 in the first position, we should also get 3 possible outcomes.   To confirm:   3142   3412   3421   Yep, 3 possible outcomes   IF we place a 4 in the first position, we should also get 4 possible outcomes.   To confirm:   4123   4312   4321   Yep, 3 possible outcomes   # of outcomes where no object is in right place = 3 + 3 + 3= 
<gadget id="calculator">3 + 3 + 3</gadget>
<output>9</output>
9   ---------------------------   So, P(no object is in the right place)= 9/24 = 3/8 = 3/8
<result>B</result>
Four different objects 1,2,3,4 are distributed at random in four places marked 1,2,3,4. What is probability that none of the objects occupy the place corresponding to it's number?