Two prime numbers are considered consecutive if no other prime lies between them on the number line. If p1p1 and p2p2 are consecutive primes, with |p1–p2|>2, what is the smallest possible absolute value of the coefficient of the x term in the distributed form of the expression (x–p1)(x–p2)?  Choose the correct choice from the following answers:  A) 5  B) 8  C) 12  D) 18  E) 24
(x−p1)∗(x−p2)=x2−(p1+p2)x+p1p2   Value of (p1+p2) will be min. for the min consecutive primes which satisfy |p1-p2|&gt;2   So the min. value p1 &amp; p2 can take = 7, 11   p1+p2= 7+11= 
<gadget id="calculator">7+11</gadget>
<output>18</output>
18   Answer. 18
<result>D</result>
Two prime numbers are considered consecutive if no other prime lies between them on the number line. If p1p1 and p2p2 are consecutive primes, with |p1–p2|>2, what is the smallest possible absolute value of the coefficient of the x term in the distributed form of the expression (x–p1)(x–p2)?