If u > 1 and v = 2^(u −1), then 4^u =
Pick one.
A) 16v^2 B) 4v^2 C) v^2 D) v^2/4 E) v^2/16
If u &gt; 1 and v = 2^(u −1), then 4^u   Given u&gt;1, so let's assume u=2   v=2^(u-1) = 2^(2-1) = 2, so v=2   hence, 4^u = 4^2 = 16   only 1 ans. choice can satisfy this:   A) 16v^2 --&gt; clearly &gt; 16   B) 4v^2 --&gt; 4*2^2 = 16(we can stop after this as there can be only 1 right answer)   C) v^2 --&gt; clearly &lt; 16   D) v^2/4 --&gt; clearly &lt; 16   E) v^2/16 --&gt; clearly &lt; 16   Ans. 4v^2) 4v^2
<result>B</result>
If u > 1 and v = 2^(u −1), then 4^u =