The smallest number when increased by " 3 " is exactly divisible by 5,10,45,90,and 105 is:  Options
A) 630
B) 633
C) 150
D) 140
E) 627
LCM = 630   630-3= 
<gadget id="calculator">630-3</gadget>
<output>627</output>
627   ANSW627R:627
<result>E</result>
The smallest number when increased by " 3 " is exactly divisible by 5,10,45,90,and 105 is: