3 persons (1 couple and 1 single) are seated at random in a row of 5 chairs. What is the probability that the couple does not sit together?
Choose the correct choice: A) 5/7 B) 4/5 C) 2/5 D) 3/5 E) 11/18
The single person is no different from an empty chair :lol:   Thus, there are 202=10202=10 ways to pick two chairs for the couple, but only 4 in which they sit together (CCEEE, ECCEE, EECCE, EEECC).   1 - 4/10 = 3/5 is the answer.3/5   _
<result>D</result>
3 persons (1 couple and 1 single) are seated at random in a row of 5 chairs. What is the probability that the couple does not sit together?