Which of the following CANNOT yield an integer when divided by 7 ?
Choose the most appropriate option:
A) The sum of three consecutive integers
B) An integer with only even prime factors
C) The product of two odd integers
D) An integer divisible by 8
E) An even integer
An integer to be divisible by 7, must have 7 in its prime factorization. Thus an integer with only even prime factors (2^n) CANNOT be divisible by 7.   As for the other options:   (A) The sum of three consecutive integers --&gt; if the three integers are {-1, 0, 1}, then their sum is 0 and 0 IS divisible by 7.   (C) The product of two odd integers --&gt; 1*7=7 --&gt; 7 is divisible by 7.   (D) An integer divisible by 8 --&gt; 0 is divisible by both 7 and 8.   (E) An even integer --&gt; 0--  1*7= 
<gadget id="calculator">--  1*7</gadget>
<output>7</output>
7 --&gt; 7 is divisible by 7.   (D) An integer divisible by 8 --&gt; 0 is divisible by both 7 and 8.   (E) An even integer --&gt; 0=even is divisible by 7.   Answer: An integer with only even prime factors.
<result>B</result>
Which of the following CANNOT yield an integer when divided by 7 ?