Suppose that the angle between the minute hand and hour hand of a
clock is 60o. If the minute hand is 16 inches long and the hour hand is
10 inches long, then what is the distance between the tip ends of the
hands in inches? Choose the correct answer:
A) 10 B) 11 C) 12 D) 13 E) 14
This is a direct application of the Law of Cosines with two sides of a triangle   having lengths 10 inches and 16 inches and the angle between them being 60. If x denotes   the distance between the tips of the hands in inches, then   x2&lt;-(square) = 102 +16-2&lt;-(square)-2*10*16cos(60o)= 100 + 256-160= 
<gadget id="calculator">100 + 256-160</gadget>
<output>196</output>
196   Hence, x= 14.   correct answer 14
<result>E</result>
Suppose that the angle between the minute hand and hour hand of a
clock is 60o. If the minute hand is 16 inches long and the hour hand is
10 inches long, then what is the distance between the tip ends of the
hands in inches?