X and Y run a 200 m race,where X beats Y by 20 m. To do a favor to Y, X starts 20 m behind the starting line in a second 200 m race. Both run at the same previous speed. Which of the following is true?  Options:
A) X Beats Y by 2m
B) Y Beats X by 10m
C) Y Beats X by 11m
D) Y Beats X by 1m
E) Y Beats X by 11m
Let's suppose that the speed of X is 20m/s and that the speed of Y is 18m/s.   So, in the first race, the results are the following:   X crosses the finish line in 10s. In other words, X has run 200m in 10 s.   In 10s, Y has run 180 meters.   Therefore, there is the difference of 20 meters mentioned in the question.   Now, let's review the second race.   In 11 seconds, X can complete the 200 meters race. We have to remember that X is 20 meters behind the starting line.   But in 11 seconds, Y has covered (180+18)= 
<gadget id="calculator">(180+18)</gadget>
<output>198</output>
198 meters. Also, it is important to notice that in 11 seconds Y cannot arrive to the finish line.   So, 200 - 198= 2 meter   X Beats Y by 2mnswer: X Beats Y by 2m
<result>A</result>
X and Y run a 200 m race,where X beats Y by 20 m. To do a favor to Y, X starts 20 m behind the starting line in a second 200 m race. Both run at the same previous speed. Which of the following is true?