The weight of four dogs is determined to be 25 pounds, 31 pounds, 32 pounds and 28 pounds respectively. The weight of a fifth dog is determined to be y pounds. If the average (arithmetic mean) weight of the first four dogs is the same as that of all five dogs what is the value of y?	Pick: A) 31 B) 29 C) 35 D) 37 E) 39
Total weight of the 4 dogs = (25+31+32+28) = 132   Avg = 116/4= 
<gadget id="calculator">116/4</gadget>
<output>29</output>
29   Total weight of 5 dogs= 116+y or 4(29)+y   Average of 5 dogs as per Question = 29   Equation:   4(29) + y = 5 (29), or y = 29.   Choose 29
<result>B</result>
The weight of four dogs is determined to be 25 pounds, 31 pounds, 32 pounds and 28 pounds respectively. The weight of a fifth dog is determined to be y pounds. If the average (arithmetic mean) weight of the first four dogs is the same as that of all five dogs what is the value of y?