A gambler bought $5,000 worth of chips at a casino in denominations of $20 and $100. That evening, the gambler lost 16 chips, and then cashed in the remainder. If the number of $20 chips lost was 2 more or 2 less than the number of $100 chips lost, what is the largest amount of money that the gambler could have received back?
Select.
A) $4,040
B) $4,120
C) $1,960
D) $4,920
E) $1,400
In order to maximize the amount of money that the gambler kept, we should maximize # of $20 chips lost and minimize # of $100 chips lost, which means that # of $20 chips lost must be 2 more than # of $100 chips lost.   So, if # of $20 chips lost is x then # of $100 chips lost should be x-2. Now, given that total # of chips lost is 16: x+x-2=16 --&gt; x=9: 9 $20 chips were lost and 9-2= 
<gadget id="calculator">9-2</gadget>
<output>7</output>
7 $100 chips were lost.   Total worth of chips lost is   9*20+7*100= 
<gadget id="calculator">  9*20+7*100</gadget>
<output>880</output>
$880, so the gambler kept $5,000-$880=$4,120.   Answer: $4,120.
<result>B</result>
A gambler bought $5,000 worth of chips at a casino in denominations of $20 and $100. That evening, the gambler lost 16 chips, and then cashed in the remainder. If the number of $20 chips lost was 2 more or 2 less than the number of $100 chips lost, what is the largest amount of money that the gambler could have received back?