For any 4 given numbers, which of the following is always equivalent to adding the 3 numbers together and then dividing the sum by 3?
I. Ordering the 3 numbers numerically, from highest to lowest, and then selecting the middle number.
II. Dividing each of the numbers by 3 and then adding the results together.
III. Multiplying each number by 6, adding the resulting products together, and then dividing the sum by 9.	Choose the correct choice from the following options:
A) I only B) II only C) I and II only D) II and III only E) None of the above
Let the 3 numbers be x, y and z.   Question: Which of the following is equivalent to (x + y + z)/3   I. Ordering the 3 numbers numerically, from highest to lowest, and then selecting the middle number. --&gt; Not always equivalent Eg: 111 and 141   II. Dividing each of the numbers by 3 and then adding the results together. --&gt; x/3 + y/3 + z/3 = (x + y + z)/3 --&gt; Equivalent   III. Multiplying each number by 6, adding the resulting products together, and then dividing the sum by 9. --&gt; (6x + 6y + 6z)/9 = 2(x + y + z)/3 --&gt; Not equivalent   I onlynswer: I only
<result>A</result>
For any 4 given numbers, which of the following is always equivalent to adding the 3 numbers together and then dividing the sum by 3?
I. Ordering the 3 numbers numerically, from highest to lowest, and then selecting the middle number.
II. Dividing each of the numbers by 3 and then adding the results together.
III. Multiplying each number by 6, adding the resulting products together, and then dividing the sum by 9.