Which is the least number that must be subtracted from 1828 so that the remainder when divided by 8, 12, 16 is 4? Answers
A) 0	B) 4	C) 8	D) 6	E) 2
First we need to figure out what numbers are exactly divisible by 8,12,16. This will be the set {LCM,LCMx2,LCMx3,...}   LCM(8,12,16) = 48 = 48   number is to be subtracted is 0   The largest such number less than or equal to 1828 is 48*38+4   0
<result>A</result>
Which is the least number that must be subtracted from 1828 so that the remainder when divided by 8, 12, 16 is 4?