What is the least value of integer N such that N! is divisible by 888 ?
Choose the correct choice from the following options
A) 13 B) 88 C) 31 D) 37 E) D) 888
888 = 8*111 = 3*8*37   Hence 888 is a multiple of 37 and we need at least one 37 in N!   Therefore least value of N! is 37!, which will contain all of 3, 8, and 37.   Correct Option: 37
<result>D</result>
What is the least value of integer N such that N! is divisible by 888 ?