A committee has 4 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?	Choose the correct choice from the following answers:  A) 127  B) 120  C) 882  D) 272  E) 323
The number of ways to select two men and three women   = 4C₂ * ⁶C₃   = (4*3 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)= 
<gadget id="calculator">(4*3 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)</gadget>
<output>120</output>
120   Answer: 120
<result>B</result>
A committee has 4 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?