Bob bikes to school every day at a steady rate of x miles per hour. On a particular day, Bob had a flat tire exactly halfway to school. He immediately started walking to school at a steady pace of y miles per hour. He arrived at school exactly t hours after leaving his home. How many miles is it from the school to Bob's home?	Select.
A) (x + y) / t
B) 2(x + t) / xy
C) 2xyt / (x + y)
D) 2(x + y + t) / xy
E) x(y + t) + y(x + t)
Say the distance to school is 10 miles, x=5 miles per hour and y=1 miles per hour, then:   Time Bob spent biking would be  5/5= 
<gadget id="calculator"> 5/5</gadget>
<output>1</output>
1 hour, and time he s pent walking would be  5/1= 
<gadget id="calculator"> 5/1</gadget>
<output>5</output>
5 hours, so t=1+5= 
<gadget id="calculator">1+5</gadget>
<output>6</output>
6 hours.   Now, plug x=5, y=1, and t=6 into the answer choices to see which one yields the distance of 10 miles. Only answer choice C fits.   Answer: 2xyt / (x + y).
<result>C</result>
Bob bikes to school every day at a steady rate of x miles per hour. On a particular day, Bob had a flat tire exactly halfway to school. He immediately started walking to school at a steady pace of y miles per hour. He arrived at school exactly t hours after leaving his home. How many miles is it from the school to Bob's home?