A group of 6 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the probability that Bob and Lisa will each sit next to only one of the five other students from the group? Select the correct option:
A) 5.6%
B) 6.7%
C) 15.5%
D) 20.4%
E) 25.7%
The question basically asks about the probability that Bob and Lisa sit at the ends.   The total # of sitting arrangements is 6!.   Desired arrangement is either BWXYZL or LWXYZB. Now, WXYZ can be arranged in 4! ways, therefore total # of favorable arrangements is 2*4!.   P=(favorable)/(total)=(2*4!)/6!=1/15.   Answer: 6.7%.
<result>B</result>
A group of 6 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the probability that Bob and Lisa will each sit next to only one of the five other students from the group?