L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is :  Pick
A) -2	B) -1	C) 1	D) 2	E) 0
Explanation:   H. C. F of two prime numbers is 1. Product of numbers = 1 x 161 = 161.   Let the numbers be a and b . Then , ab= 161.   Now, co-primes with product 161 are (1, 161) and (7, 23).   Since x and y are prime numbers and x &gt;y , we have x=23 and y=7.   inline fn_jvn therefore 3y-x = (3 x 7)-23 = -2 . -2nswer: -2
<result>A</result>
L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is :