A double decked bus can accomodate 120 passengers,50 in the upper deck and 70 in the lower deck.In how many ways can the passengers be accomodated if 15 refuse to be in the upper deck while 10 others refuse to be in the lower deck? Choose the correct answer:  A) 1. 95!/40!55!  B) 2. 85!/40!45!  C) 3. 110!/50!60!  D) 4. 110!50!60!/40!45!  E) 5. 110!/40!45!
120 passengers,50 in the upper deck and 70 in the lower deck.   25 passengers have issues as 15 refuse to be in the upper deck while 10 others refuse to be in the lower deck   So those 15 will be put in lower deck and 10 will be in upper deck   So from the rest 95 passengers(120-25), we need to find 40 people to put into upper deck and the rest go to lower deck   So the ways are: C(95,40) = 95!/40!55! . 1. 95!/40!55!nswer 1. 95!/40!55!
<result>A</result>
A double decked bus can accomodate 120 passengers,50 in the upper deck and 70 in the lower deck.In how many ways can the passengers be accomodated if 15 refuse to be in the upper deck while 10 others refuse to be in the lower deck?