What is the equation of the line that goes through (–2, 3) and (5, –4)?  Choices.
A) y = –x + 1	B) y = x + 5	C) y = –3x/7 + 15/7	D) y = –4x/3 + 1/3	E) y = 9x/5 + 33/5
Here, we will follow the procedure we demonstrated in the last section. Call (–2, 3) the “first” point and (5, –4), the “second.” Rise = –4 – 3 = –7. Run = 5 – (–2) = 7. Slope = rise/run = –7/7= 
<gadget id="calculator">7/7</gadget>
<output>1</output>
–1.   Yes, it makes sense that the slope is negative. We have the slope, so plug m= –1 and (x, y) = (–2, 3) into y = mx + b:   3 = (–1)*(–2) + b   3 = 2 + b   1 = b   So, plugging in m = –1 and b = 1, we get an equation y = –x + 1. y = –x + 1nswer = y = –x + 1
<result>A</result>
What is the equation of the line that goes through (–2, 3) and (5, –4)?