Three persons A, B and C divide a certain amount of money such that A's share is Rs.4 less than half of the total amount. B's share is Rs.8 more than half of what is left and finally C takes the which is Rs.14. Find the total amount they initially had with them?	Answers.
A) Rs.68 B) Rs.85 C) Rs.80 D) Rs.56 E) Rs.29
Let the total amount be Rs.P   Let shares of A and B be Rs.X and Rs.Y respectively.   Given, C's share was Rs.14.   X + Y + 14 = P --- (1)   From the given data, X = P/2 - 4 --- (2)   Remaining amount = P - (P/2 - 4) = P/2 + 4   Y = 1/2(P/2 + 4) + 8   =&gt; P/4 + 10 --- (3)   From (1), (2) and (3)   P/2 - 4 + P/4 + 10 + 14 = P   =&gt; 3P/4 + 20 = P   =&gt; P - 3P/4 = 20   =&gt; P/4 = 20 =&gt; P = Rs.80   Answer: Rs.80
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Three persons A, B and C divide a certain amount of money such that A's share is Rs.4 less than half of the total amount. B's share is Rs.8 more than half of what is left and finally C takes the which is Rs.14. Find the total amount they initially had with them?