Find four consecutive even integers so that the sum of the first two added to twice the sum of the last two is equal to 742.
Choose the correct answer:
A) 120 ,122 , 124 ,126  B) 120 ,122 , 124 ,128  C) 120 ,121 , 122 ,123  D) 123 ,125 , 127 ,129  E) None of these
Let x, x + 2, x + 4 and x + 6 be the four integers. The sum of the first two   x + (x + 2)   twice the sum of the last two is written as   2 ((x + 4) + (x + 6)) = 4 x + 20   sum of the first two added to twice the sum of the last two is equal to 742 is written as   x + (x + 2) + 4 x + 20 = 742   Solve for x and find all four numbers   x = 120 , x + 2 = 122 , x + 4 = 124 , x + 6 = 126   120 ,122 , 124 ,126nswer 120 ,122 , 124 ,126
<result>A</result>
Find four consecutive even integers so that the sum of the first two added to twice the sum of the last two is equal to 742.