If the ratio of the roots of the equation 2x2-6x+q=0 is equal to that of the roots 3x2-6x+s=0, then:  Choose the correct choice from the following choices
A) 2s=q	B) s=q	C) 2q=s	D) 4s-q	E) None
2x2-6x+q=0 for this eqn... roots are R1=6/2= 
<gadget id="calculator">6/2</gadget>
<output>3</output>
3 R2=-q/2   3x2-6x+s=0 for this eqn... roots are R3=6/3= 
<gadget id="calculator">6/3</gadget>
<output>2</output>
2 R4=-s/3   As per Question, 3/(-q/2)=2/(-s/3)   =&gt; s=q   ANSWER:s=q
<result>B</result>
If the ratio of the roots of the equation 2x2-6x+q=0 is equal to that of the roots 3x2-6x+s=0, then: