A committee of 6 is chosen from 5 men and 5 women so as to contain at least 2 men and 3 women. How many different committees could be formed?  Choose the most appropriate option.
A) 150  B) 700  C) 1404  D) 2620  E) 3510
The only cases possible are :   1. 2 men and 4 women : 5C2 * 5C4 = 50   2. 3 men and 3 women: 5C3*5C3 = 100   Rest of the cases will either have 1 or 0 men (not allowed) or will have 1 or 2 or 0 women (not allowed)   Total possible combinations = 50+100= 
<gadget id="calculator">50+100</gadget>
<output>150</output>
150. Thus 150 is the correct answer.
<result>A</result>
A committee of 6 is chosen from 5 men and 5 women so as to contain at least 2 men and 3 women. How many different committees could be formed?