Jack, Jill, and Sandy each have one try to make a basket from half court. If their individual probabilities of making the basket are 1/6, 1/7, and 1/8 respectively, what is the probability that all three will miss? Select.
A) 3/8
B) 5/8
C) 7/16
D) 9/16
E) 23/32
The probability that all three will miss is 5/6*6/7*7/8=5/8.   The answer is 5/8.
<result>B</result>
Jack, Jill, and Sandy each have one try to make a basket from half court. If their individual probabilities of making the basket are 1/6, 1/7, and 1/8 respectively, what is the probability that all three will miss?