For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum of all the integers between 100 and 200? Choose the correct choice from the following:
A) 4545  B) 5050  C) 6525  D) 4352  E) 4652
sum = 100*101/2 = 50*101= 
<gadget id="calculator">50*101</gadget>
<output>5_050</output>
5050   Answer is 5050
<result>B</result>
For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum of all the integers between 100 and 200?