In how many ways, a committee of 5 members can be selected from 9 men and 5 ladies, consisting of 3 men and 2 ladies?	Options
A) 75
B) 552
C) 775
D) 840
E) 912
(3 men out 9) and (2 ladies out of 5) are to be chosen   Required number of ways = (9C3 * 5C2) = 840   Answer is 840
<result>D</result>
In how many ways, a committee of 5 members can be selected from 9 men and 5 ladies, consisting of 3 men and 2 ladies?