What is the units digit of 23^3 * 17^2 * 39^2?  Options: A) 9 B) 7 C) 5 D) 3 E) 1
The units digit of 23^3 is the units digit of   3*3*3= 
<gadget id="calculator">  3*3*3</gadget>
<output>27</output>
27 which is 7.   The units digit of 17^2 is the units digit of   7*7= 
<gadget id="calculator">  7*7</gadget>
<output>49</output>
49 which is 9.   The units digit of 39^2 is the units digit of   9*9= 
<gadget id="calculator">  9*9</gadget>
<output>81</output>
81 which is 1.   The units digit of  7*9*1= 
<gadget id="calculator"> 7*9*1</gadget>
<output>63</output>
63 is 3.   The answer is 3.
<result>D</result>
What is the units digit of 23^3 * 17^2 * 39^2?