Four barrels of water have an average capacity of 8 gallons. What is the maximum possible capacity of the smallest barrel Q if the median is 10 gallons?  Select
A) 1 B) 2 C) 3 D) 4 E) 5
Suppose 4 barrels are B1, B2, B3, B4 in ascending capacity.   (B1+B2+B3+B4)/4 = 8   B1+B2+B3+B4=32   median is 10 ....... as the no. of terms are even i.e 4, median = (22+23)/2   ==&gt; 22+23 = 20   now we have 21+24 = 32-20= 
<gadget id="calculator">32-20</gadget>
<output>12</output>
12   Only the following possible cases can be there :   1,9,11,11   1,10,10,11   2,10,10,10   Max value of smallest barrel Q= 2
<result>B</result>
Four barrels of water have an average capacity of 8 gallons. What is the maximum possible capacity of the smallest barrel Q if the median is 10 gallons?