How many three-digit numbers that do not contain the digits 2 or 5 are there?
Answers
A) 488
B) 996
C) 228
D) 456
E) 1986
We can have 7 digits ( 1,3,4,6,7,8,9) for the first place ( hundred's place).   and similarly 8 digits for tenth's and unit digit. ( 0,1,3,4,6,7,8,9)   So in total 7*8*8= 488   Hence 996
<result>B</result>
How many three-digit numbers that do not contain the digits 2 or 5 are there?