How many different three-digit multiples of 5 can be composed of digits 1, 2, 3, 4, and 5 if none of the digits is repeated?  Pick:
A) 3
B) 6
C) 8
D) 12
E) 18
can you explain your method. i solved it differently   XYZ, where Z must be 5. therefore 1 variation of digit in Z.   Y can be any of the 4 possible choices.   X can be any of the 3 possible choices.   4+3+1= 
<gadget id="calculator">4+3+1</gadget>
<output>8</output>
8   8
<result>C</result>
How many different three-digit multiples of 5 can be composed of digits 1, 2, 3, 4, and 5 if none of the digits is repeated?