From a box containing 10 orange balls and 6 yellow balls, a child takes out two balls simultaneously and at random. What is the probability that he picks one ball of each color?	Choose the correct option.
A) 1/8	B) 1/30	C) 1/16	D) 1/4	E) 1/2
We are told that we have 16 balls, 10 orange and 6 yellow. The balls are drawn simultaneous and randomly, B1 and B2, in different colors. There are two acceptable outcomes: 1) B1 is orange and B2 is yellow; 2) B1 is yellow and B2 is orange. Let's go: 1) B1 = (10/16)(6/15)= 1/4 chance of this happening. 2) B2 = (6/16)(10/15) = 1/4 chance of this happening. Then: (1/4)+(1/4)= 1/2, chance of getting the result that you wanted. Answer 1/2.
<result>E</result>
From a box containing 10 orange balls and 6 yellow balls, a child takes out two balls simultaneously and at random. What is the probability that he picks one ball of each color?