If k^3 is divisible by 162, what is the least possible value of integer k?
Choose one
A) 12	B) 15	C) 18	D) 24	E) 36
k^3 = 162*x = 2*3^4*x   The factors of k must at minimum include 2*3^2 = 18.   The answer is 18.
<result>C</result>
If k^3 is divisible by 162, what is the least possible value of integer k?