What is the equation of a circle of radius 5 units centered at (3, 2)?	Choices:
A) x^2 + y^2 + 6x – 4y = 23
B) x^2 + y^2 - 6x + 4y = 23
C) x^2 + y^2 + 6x + 4y = 23
D) x^2 + y^2 - 6x – 4y = - 12
E) x^2 + y^2 - 6x – 4y = 12
the equation of a circle with center at (a,b) and radius R is (X-a)^2+(Y-b)^2=R^2   =&gt; answer = (X-3)^2+(Y-2)^2=5^2   solving,,we get the equation in answer choice x^2 + y^2 - 6x – 4y = 12.
<result>E</result>
What is the equation of a circle of radius 5 units centered at (3, 2)?