The sum of 5 consecutive even numbers of set x is 440. Find the sum of a different set of five consecutive integers whose second least number is 121 less than double the least number of set x?
Choose the correct choice from the following choices:
A) 220 B) 230 C) 235 D) 236 E) 240
Let the five consecutive even numbers be 2(x - 2), 2(x - 1), 2x, 2(x + 1) and 2(x + 2)   Their sum = 10x = 440   x = 44 =&gt; 2(x - 2) = 84   Second least number of the other set = 2(84) - 121 = 47   This set has its least number as 46.   Sum of the numbers of this set = 46 + 47 + 48 + 49 + 50   = 48 - 2 + 48 - 1 + 48 + 48 + 1 + 48 + 2 =&gt; 5(48) = 240   240
<result>E</result>
The sum of 5 consecutive even numbers of set x is 440. Find the sum of a different set of five consecutive integers whose second least number is 121 less than double the least number of set x?