A jar contains a mixture of two liquids Acid( nitric acid) and Base(ammonium chloride) in the ratio 4 : 1. When 10 litres of the mixture is taken out and 10 litres of liquid Base is poured into the jar, the ratio becomes 2 : 3. How many litres of liquid Acid was contained in the jar?	Choose one.
A) 14 lts
B) 18 lts
C) 20 lts
D) 16 lts
E) 26 lts
%age of liquid Base in the original mixture   =1/5 x 100 = 20%   In the final mixture % of the liquid Base   = 3/5 x 100 = 60%   Now using the rule of allegation   Hence reduced quantity of the first mixture and the quantity of mixture B which is to be added are the same.   Total mixture = 10 + 10= 
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
20 liters and quantity of liquid A= 20/5 x 4 = 16 lts   ANSWER:16 lts
<result>D</result>
A jar contains a mixture of two liquids Acid( nitric acid) and Base(ammonium chloride) in the ratio 4 : 1. When 10 litres of the mixture is taken out and 10 litres of liquid Base is poured into the jar, the ratio becomes 2 : 3. How many litres of liquid Acid was contained in the jar?