A little old lady lives in a house with only her children and the children each have pets. She has twice as many sons as daughters. Each son has a dog, and each daughter has a cat. If the total number of pets and children living with her are Y, then how many dogs live in the house, in terms of Y  Select:
A) Y/8	B) Y/2	C) 2*Y	D) 3*Y	E) Y/3
Since Y is the total of all children and pets, Y = Boys + Girls + Dogs + Cats   Since each boy has a dog then, Boys = Dogs. Since each Girl has a Cat then, Girls = Cats   Thus Y = 2*Boys + 2*Girls   Since there are twice as many boys as girls, Girls = Boys/2.   Thus Y = 2*Boys + 2*(Boys/2) Which simplifies to Y = 2*Boys + 1*Boy, or Y = 3*Boys   Since Boys = Dogs ... Y=3*Dogs   Which converts to Dogs = Y/3   Answer: Y/3
<result>E</result>
A little old lady lives in a house with only her children and the children each have pets. She has twice as many sons as daughters. Each son has a dog, and each daughter has a cat. If the total number of pets and children living with her are Y, then how many dogs live in the house, in terms of Y