In three years, Janice will be three times as old as her daughter. Six years ago, her age was her daughter’s age squared. How old is Janice's Daughter? Options:
A) 12 B) 36 C) 40 D) 42 E) 45
Let Jane's age be J and daughters' age be D...   Given J   + 3= 
<gadget id="calculator">  + 3</gadget>
<output>3</output>
3(D + 3 )=&gt; J - 6 = 3D -&gt; Eq1.   Given J-6 = (D-6)^2 --&gt; Eq 2..   sub J-6 value in eq 2... 3D = D^2 - 12D + 36.   0 = D^2 - 15D + 36 =&gt; D = 12 or D = 3.   When D = 12 we get from eq 1... J+3 = 45 =&gt; J =42..   When D = 3 ..we get from eq 1.. J+3 = 18 =&gt; J = 15..   IMO option 12 is correct answer..
<result>A</result>
In three years, Janice will be three times as old as her daughter. Six years ago, her age was her daughter’s age squared. How old is Janice's Daughter?