If a and n are integers, and a^3=360n, then n must be divisible by which of the following?	Choose the correct choice from the following answers:
A) 2
B) 6
C) 25
D) 27
E) 60
a^3=360n = 2^3*3^2*5*n   and a^3 is a perfect cube due to a being an integer   hence 360n must have powers of each prime number as multiple of 3   hence 360n = 2^3*3^2*5*(3*5^2) for least value of n   i.e. n must have 5^2   Answer: Option 25
<result>C</result>
If a and n are integers, and a^3=360n, then n must be divisible by which of the following?