In how many ways can the letters L, I, M, I, T, S be arranged so that the two I's are not next to each other?	Choose one
A) 36
B) 48
C) 240
D) 296
E) 428
1 L   2 I   1 M   1 T   1 S   Number of ways these letters can be arranged = 6!/2! (2! to account 2 same Is) = 360   240onsider 2 Is as 1 entity and thus the number of arrangements for (II)LMTS = 5! = 120   Total allowed cases = 360-120= 
<gadget id="calculator">360-120</gadget>
<output>240</output>
240   240 is the correct answer.
<result>C</result>
In how many ways can the letters L, I, M, I, T, S be arranged so that the two I's are not next to each other?