Two cards are drawn from a pack of well shuffled cards. Find the probability that one is a club and other in King  Choose one:
A) 1/29	B) 1/26	C) 1/26	D) 1/25	E) 1/22
Explanation:   Let X be the event that cards are in a club which is not king and other is the king of club.   Let Y be the event that one is any club card and other is a non-club king.   Hence, required probability:   =P(A)+P(1/26)   =\inline {\color{1/26lack}[(12C_{1}\times 1C_{1})/52C_{2}]+[(13C_{1}\times 3C_{1})/52C_{2}]}   Answer: 1/26) 1/26   == =
<result>B</result>
Two cards are drawn from a pack of well shuffled cards. Find the probability that one is a club and other in King