Average of five numbers is -10, and the sum of three of the numbers is 16, wat is the average of the other 2 no's?  Choose the correct choice:	A) -33	B) 23	C) -34	D) -39	E) 32
Let the five numbers be a, b, c, d, e. Then their average is (a+b+c+d+e5)=10.(a+b+c+d+e5)=10.   Now three of the numbers have a sum of 16, say, a+b+c=16a+b+c=16.   So substitute 16 for a+b+ca+b+c in the average above: (16+d+e5)=10.(16+d+e5)=10.   Solving this equation for d+ed+e gives d+e=−66d+e=−66.   Finally, dividing by 2 (to form the average) gives (d+e2)=−33.(d+e2)=−33.   Hence, the answer is -33: -33
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Average of five numbers is -10, and the sum of three of the numbers is 16, wat is the average of the other 2 no's?