If 4 people are selected from a group of 5 married couples, what is the probability that none of them would be married to each other?  Choose the correct choice:
A) 1/33
B) 2/33
C) 1/3
D) 16/33
E) 8/21
If we are to select 4 people from 5 couples WITHOUT any restriction, how many ways can we make the selection? 10!/4!6! = 210   If we are to select 4 people from 5 couples WITH restriction that no married couple can both make it to the group, only a representative?   5!/4!1! = 5   But we know that to select a person from each couple, take 2 possibilities     5*2*2*2*2= 
<gadget id="calculator">  5*2*2*2*2</gadget>
<output>80</output>
80   Probability= Desired/All Possibilities = 80/210 = 8/21   Answer: 8/21
<result>E</result>
If 4 people are selected from a group of 5 married couples, what is the probability that none of them would be married to each other?