Set S contains exactly 10 numbers and has an average (arithmetic mean) of 6.2. If one of the numbers in Set S is increased by 3, while all other numbers remain the same, what is the new average of Set S? Answers:
A) 6.5	B) 6.7	C) 6.8	D) 6.85	E) 6.9
Old set S - Total is avg * no of elements = 6.2*10= 
<gadget id="calculator">6.2*10</gadget>
<output>62</output>
62   If one number is increased by 3 then total increased to  62+3= 
<gadget id="calculator"> 62+3</gadget>
<output>65</output>
65   New avg - 65/10= 6.5.   Hence answer is 6.5.
<result>A</result>
Set S contains exactly 10 numbers and has an average (arithmetic mean) of 6.2. If one of the numbers in Set S is increased by 3, while all other numbers remain the same, what is the new average of Set S?