What is the probability that a 5 person committee chosen at random from a group consisting of 6 men, 7 women, and 5 children contains exactly 1 woman?
Choose the correct choice
A) 55/204	B) 77/832	C) 11/77	D) 308/1411	E) 22/832
Total possible selections = 5 out of 18 group members = 18C5   Favorable selections = 1 out of 7 women and 4 out of 11 (= 6 men + 5 children) = 7C1 * 11C4   Thus the required probability = 7C1*11C4 / 18C5 = 55/204. Thus 55/204 is the correct answer.
<result>A</result>
What is the probability that a 5 person committee chosen at random from a group consisting of 6 men, 7 women, and 5 children contains exactly 1 woman?