In how many ways can 12 different gifts be divided among four children such that each child receives exactly three gifts?  Select the correct option:
A) 16^3  B) (4!)^3  C) 12!/(3!)^4  D) 12!/4!  E) 4^12
Total 12 different Gifts, and 4 children.   Thus any one child gets 12C3 gifts,   then the other child gets 9C3 gifts(12 total - 3 already given),   then the third one gets 6C3 gifts,   and the last child gets 3C3 gifts.   Since order in which each child gets the gift is not imp, thus, ans :   1212!/(3!)^43 * 912!/(3!)^43 * 612!/(3!)^43 * 312!/(3!)^43 = 12! / (3!)^4   Ans : 12!/(3!)^4.
<result>C</result>
In how many ways can 12 different gifts be divided among four children such that each child receives exactly three gifts?