Joseph has a bag with 2 red balls and 3 blue balls. If he pulls out two at random and simultaneously, what is the probability of him pulling one red and one blue ball?	Choices: A) 3/5 B) 2/3 C) 8/15 D) 4/12 E) 7/18
The probability is equal to the number of desired choices divided by the total number of possibilities.   Probability = Favorable/Total   Total = 5C2 = 5*4/2= 
<gadget id="calculator">5*4/2</gadget>
<output>10</output>
10   Favorable:   Pick 1 red ball out of 2 red balls   AND   Pick 1 blue ball out of 3 blue balls   2C1*3C1= 2*3= 
<gadget id="calculator">2*3</gadget>
<output>6</output>
6   P=6/10=3/5   When you use combination method, it is picking all possible cases and the order doesn't matter. Whereas, upon choosing probability method to solve, order matters.   Thus,   Total Probability:   Probability of choosing a red ball first 3/5ND Probability of choosing a blue ball   OR   Probability of choosing a blue ball first 3/5ND Probability of choosing a red ball   3/5nswer: 3/5
<result>A</result>
Joseph has a bag with 2 red balls and 3 blue balls. If he pulls out two at random and simultaneously, what is the probability of him pulling one red and one blue ball?