In a simultaneous throw of 2 dice, what is the probability of getting a doublet?
Answers.
A) 1/3
B) 1/6
C) 1/2
D) 2/3
E) 1/5
n(S) = 6*6= 
<gadget id="calculator">6*6</gadget>
<output>36</output>
36   E= event of getting a doublet = {(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)} = 6   Probability = 6/36 = 1/6   Answer is 1/6
<result>B</result>
In a simultaneous throw of 2 dice, what is the probability of getting a doublet?