If the sum of two positive integers is 12 and the difference of their squares is 48, what is the product of the two integers? Pick one:
A) 32	B) 119	C) 128	D) 135	E) 143
Let the 2 positive numbers x and y   x+ y = 12 -- 1   x^2 - y^2 = 48   =&gt; (x+y)(x-y)=48 -- 2   Using equation 1 in 2 , we get   =&gt; x-y = 4 -- 3   Solving equation 1 and 3 , we get   x= 8   y= 4   Product = 8*4= 
<gadget id="calculator">8*4</gadget>
<output>32</output>
32   32nswer 32
<result>A</result>
If the sum of two positive integers is 12 and the difference of their squares is 48, what is the product of the two integers?