It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number? Choose the correct choice from the following answers:
A) (2^96 + 1)
B) (2^16 + 1)
C) (2^95 + 1)
D) (2^95 - 1)
E) (2^75 + 1)
Let 232 = x. Then, (232 + 1) = (x + 1).   Let (x + 1) be completely divisible by the natural number N. Then,   (296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.   (2^96 + 1))
<result>A</result>
It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?