water is continuously poured from a reservoir to a locality at the steady rate of 10,000 liters per hour. When delivery exceeds demand the excess water is stored in a tank. If the demand for 8 consecutive three-hour periods is 10000,10000,45000,25000,40000,15000,60000 and 35000 liters respectively, what will be the minimum capacity required of the water tank (in 1000 litres) to meet the demand?  Options
A) 20 B) 30 C) 40 D) 50 E) 60
in the period of first 3 hrs, the demand of water = 10000.   but the water poured by 10000 per hour.   Thus the end of 3 hours it will poured 30000 ltr then the excess of water = 20000.   Similarly at the end of 2nd 3 hr period the excess of water  20000+20000= 
<gadget id="calculator"> 20000+20000</gadget>
<output>40_000</output>
40000.   Third, 3 hrs water poured= 30000   already we have 40000 of excess water and demand 45000.   Then the excess water at the end of 3rd 3 hrs   = 40000+30000–45000   = 25000   Fourth 3 hrs. water = 25000+30000–25000   = 30000   Fifth = 30000+30000–40000   = 20000   Sixth = 20000+30000–15000=35000   Seventh = 35000+30000–60000   = 5000   Eighth = 5000+30000–35000   = 0   By analyzing the above results, we have 40000 ltrs is the highest measure of excess water.   So the minimum capacity of water tank = 40000 litres = 40   i.e. = 40   ANSWER:40
<result>C</result>
water is continuously poured from a reservoir to a locality at the steady rate of 10,000 liters per hour. When delivery exceeds demand the excess water is stored in a tank. If the demand for 8 consecutive three-hour periods is 10000,10000,45000,25000,40000,15000,60000 and 35000 liters respectively, what will be the minimum capacity required of the water tank (in 1000 litres) to meet the demand?