If an integer e is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that e(e + 1)(e + 2) will be divisible by 8?
Choose one: A) 1/4 B) 3/8 C) 1/2 D) 5/8 E) 3/4
for e Total numbers 8*12   There are 12 numbers divisible by 8 -&gt; 3*12 (if 8 is an example - (6,7,8), (7,8,9), (8,9,10))   and 12 numbers divisible by 4 but not divisible by 8 -&gt; 2*12 (if 4 is an example (2,3,4) and (4,5,6))   The answer 5/8 -&gt; 5/8
<result>D</result>
If an integer e is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that e(e + 1)(e + 2) will be divisible by 8?