A woman is 18 years older than her son. In two years, her age will be twice the age of her son. The present age of her son is: Choose the most appropriate option.
A) 20	B) 16	C) 22	D) 23	E) 24
Let the son's present age be x years. Then, woman's present age = (x + 18) years.   (x + 18) + 2 = 2(x + 2)   x + 20 = 2x + 4   x = 16.   Answer:16
<result>B</result>
A woman is 18 years older than her son. In two years, her age will be twice the age of her son. The present age of her son is: