Out of the three numbers A, B and C, A exceeds B by 20 and C exceeds A by 55. If the sum of all the numbers is 230, What is the difference between the largest and the smallest number?	Answers
A) 52
B) 58
C) 63
D) 75
E) 76
Explanation:   We have , A = B + 20 &amp; C = A + 55 = B + 75   Thus, (B + 20) + (B) + (B + 75) = 230   B = 45   Thus, A = 65 &amp; C = 120. Hence, (C) – (B) = 120 – 45 = 75   Short-Cut Method : Since C is larger than A by 55 and A is larger than B by 20, we get, the Required difference = 55 + 20= 
<gadget id="calculator">55 + 20</gadget>
<output>75</output>
75 (without calculating the actual values of A, B and C).   ANSWER 75
<result>D</result>
Out of the three numbers A, B and C, A exceeds B by 20 and C exceeds A by 55. If the sum of all the numbers is 230, What is the difference between the largest and the smallest number?