no.of zeros in 1*2^2*3^3*....49^49	Select:
A) 240
B) 250
C) 260
D) 270
E) 280
count the number of 5's   5^5 =&gt; 5 5's   10^10 = 2^10*5^10 =&gt; 10 5's   15^15 =&gt; 15 5's   20^20 =&gt; 20 5's   25^25 =(5^2)^25 = 5^50 =&gt; 50 5's   30^30 =&gt; 30 5's   35^35 =&gt; 35 5's   40^40 =&gt; 40 5's   45^45 -&gt; 45 5's   total no. of 5's = 5 + 10 + 15 + 20 + 50 + 30 + 35 + 40 + 45= 
<gadget id="calculator">5 + 10 + 15 + 20 + 50 + 30 + 35 + 40 + 45</gadget>
<output>250</output>
250   i.e. product has a term 5^250 , also no. of 2's is much more than 250   no.of zeros in 1*2^2*3^3*....49^49= 250   ANSWER:250
<result>B</result>
no.of zeros in 1*2^2*3^3*....49^49