Two trains are moving in opposite direction @ 60 kmph and 90 kmph.Their lengths are 1.10 km and 0.9 km respectively.The time taken by the slower train to cross the faster train in seconds is Options
A) 36 B) 45 C) 48 D) 49 E) 50
R.S = (60+90)kmph =&gt; (150*5/18)m/sec =&gt; (125/3)m/sec   Distance covered = (1.10 + 0.9) km = (2*1000)= 
<gadget id="calculator">(2*1000)</gadget>
<output>2_000</output>
2000 m.   Required time= (2000 * 3/125)= 
<gadget id="calculator">(2000 * 3/125)</gadget>
<output>48</output>
48sec.   ANSWER:48
<result>C</result>
Two trains are moving in opposite direction @ 60 kmph and 90 kmph.Their lengths are 1.10 km and 0.9 km respectively.The time taken by the slower train to cross the faster train in seconds is