If each side of a right triangle is increased by 10% and the base(b) is half of the height, find the percentage change in its area? Select:	A) 26%	B) 21%	C) 15%	D) 18%	E) 12%
a =1/2 x b x h or 1/2 x 2a x a(for simplification)   New h = 220a / 100 = 22a / 10   New b =(110a x 100) ==11a/10   New area = 1/2 (22a x 11a) / (10 x 10) = (121a²/100)   increased area== (121a²/100) - a²   Increase %= [(21a²/100 ) x (1/a² ) x 100]% = 21%   answer :21%
<result>B</result>
If each side of a right triangle is increased by 10% and the base(b) is half of the height, find the percentage change in its area?