A miniature roulette wheel is divided into 10 equal sectors, each bearing a distinct integer from 1 to 10, inclusive. Each time the wheel is spun, a ball randomly determines the winning sector by settling in that sector. If the wheel is spun five times, approximately what is the probability that the product of the five winning sectors’ integers will be even? Choose the correct choice:
A) 50%	B) 67%	C) 85%	D) 91%	E) 97%
The only way to have an odd product is if all 5 integers are odd.   P(odd product) = 1/2*1/2*1/2*1/2*1/2 = 1/32   P(even product) = 1 - 1/32 = 31/32 which is about 97%   The answer is 97%.
<result>E</result>
A miniature roulette wheel is divided into 10 equal sectors, each bearing a distinct integer from 1 to 10, inclusive. Each time the wheel is spun, a ball randomly determines the winning sector by settling in that sector. If the wheel is spun five times, approximately what is the probability that the product of the five winning sectors’ integers will be even?