What is the greater of the two numbers whose product is 2560, given that the sum of the two numbers exceeds their difference by 32? Pick: A) A)90 B) B)100 C) C)160 D) D)70 E) of these
Let the greater and the smaller number be g and s respectively.   gs = 2560   g + s exceeds g - s by 32 i.e., g + s - (g - s) = 32   i.e., 2s = 32 =&gt; s = 16   g = 2560/s = 160.   ANSWER:160
<result>C</result>
What is the greater of the two numbers whose product is 2560, given that the sum of the two numbers exceeds their difference by 32?