A committee has 5 men and 5 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
Choose one:
A) 127
B) 100
C) 882
D) 272
E) 323
The number of ways to select two men and three women   = ⁵C₂ * 5C₃   = (5 *4 )/(2 * 1) * (5 * 4 * 3)/(3 * 2)= 
<gadget id="calculator">(5 *4 )/(2 * 1) * (5 * 4 * 3)/(3 * 2)</gadget>
<output>100</output>
100   Answer: 100
<result>B</result>
A committee has 5 men and 5 women. What are the number of ways of selecting 2 men and 3 women from the given committee?