A certain stock exchange designates each stock with a 1, 2 or 3 letter code, where each letter is selected from the 14 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order, constitute a different code, how many diff stocks is it possible to designate with these codes?	Pick one:
A) 2600  B) 2800  C) 2500  D) 3000  E) 2954
Pretty simple actually   Number of 1 letter symbols = 14   Number of 2 letter symbols = 14*14   Number of 3 letter symbols = 14*14*14   The answer is sum of the 3. = 14+14*14+14*14*14 =14(1+14+14*14)= 14*211= 
<gadget id="calculator">14*211</gadget>
<output>2_954</output>
2954   So the answer is 2954.
<result>E</result>
A certain stock exchange designates each stock with a 1, 2 or 3 letter code, where each letter is selected from the 14 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order, constitute a different code, how many diff stocks is it possible to designate with these codes?