A bag contains 7 red, 9 blue and 5 green balls. If 3 balls are picked at random, what is the probability that both are red?	Choose one:	A) 2/21	B) 3/41	C) 5/26	D) 1/38	E) 5/32
P(Both are red),   =7C3/21C3=(7*6*5)/21*20*19   =1/38   1/38
<result>D</result>
A bag contains 7 red, 9 blue and 5 green balls. If 3 balls are picked at random, what is the probability that both are red?