in how many possible ways you can write 3240 as product of 3 positive integers a, b, c .	Choose the correct option.
A) 450 B) 420 C) 350 D) 320 E) 300
3240 =&gt; 2^3 * 3^4 * 5^1   a =&gt; 2^x1 * 3^y1 * 5^z1   b =&gt; 2^x2 * 3^y2 * 5^z2   c =&gt; 2^x3 * 3^y3 * 5^z3   a * b * c = 3240   x1 + x2 + x3 = 3 =&gt; 5C2   y1 + y2 + y3 = 4 =&gt; 6C2   z1 + z2 + z3 = 1 =&gt; 3C2   5C2 * 6C2 * 3C2 = 10 * 15 * 3= 
<gadget id="calculator">10 * 15 * 3</gadget>
<output>450</output>
450   450NSWER:450
<result>A</result>
in how many possible ways you can write 3240 as product of 3 positive integers a, b, c .