What is the probability of randomly selecting an arrangement of the letters of the word "MEDITERRANEAN" in which the first letter is E and the last letter is R? Choose one:  A) 1/13  B) 1/20  C) 1/26  D) 1/50  E) 1/100
There are 13 letters in MEDITERRANEAN, out of which E appears thrice, N appears twice, A appears twice, and R appears twice.   The number of arrangements of MEDITERRANEAN is therefore 13!/3!2!2!2!   The number of arrangements in which the first letter is E and the last letter is R is 11!/2!2!2! (we are left with 11 letters out of which E appears twice, N appears twice and A appears twice).   P=(11!/2!2!2!)/(13!/3!2!2!2!)=11/!2!2!2!∗3!2!2!2!/13!=3!/12∗13=1/26   Answer: 1/26.
<result>C</result>
What is the probability of randomly selecting an arrangement of the letters of the word "MEDITERRANEAN" in which the first letter is E and the last letter is R?