There are 5 married couples and a group of three is to be formed out of them; how many arrangements are there if a husband and wife may not be in the same group?
Choose one:
A) 70	B) 75	C) 80	D) 85	E) 90
Total ways of selecting 3 people out of 10 = 10C3 = 10*9*8/3*2 = 120   So final answer cannot be greater than 120.   In 3 people only 1 couple is possible. So way of selecting 1 couple out of 5 = 5801 = 5   Way of selecting 1 person out of remaining 8 = 8801 = 8   Total ways when there will be 1 couple and 1 different person = 8*5= 
<gadget id="calculator">8*5</gadget>
<output>40</output>
40   Total number of ways in which no people will be from same couple= 120 - 40= 
<gadget id="calculator">120 - 40</gadget>
<output>80</output>
80 ANS"80
<result>C</result>
There are 5 married couples and a group of three is to be formed out of them; how many arrangements are there if a husband and wife may not be in the same group?