If (x/y)=(6/5), find the value (x^2+y^2)/(x^2-y^2)
Choose the correct choice from the following answers.
A) 61/11	B) 51/11	C) 41/11	D) 21/11	E) None of them
= (x^2+y^2)/(x^2-y^2) = ( x^2 /y^2+ 1)/ ( x^2 /y^2-1) = [(6/5)^2+1] / [(6/5)^2-1]   = [(36/25)+1] / [(36/25)-1] = (61*25)/(25*11) = 61/11   61/11nswer is 61/11.
<result>A</result>
If (x/y)=(6/5), find the value (x^2+y^2)/(x^2-y^2)