Jack, Jill, and Sandy each have one try to make a basket from half court. If their individual probabilities of making the basket are 1/6, 1/7, and 1/8 respectively, what is the probability that Jill and Sandy will make a basket but Jack will miss? Pick one.
A) 3/168
B) 5/168
C) 7/168
D) 5/336
E) 7/336
The probability that Jill and Sandy will make a basket but Jack will miss is 5/6*1/7*1/8=5/336.   The answer is 5/336.
<result>D</result>
Jack, Jill, and Sandy each have one try to make a basket from half court. If their individual probabilities of making the basket are 1/6, 1/7, and 1/8 respectively, what is the probability that Jill and Sandy will make a basket but Jack will miss?