x and y are positive integers. When x is divided by 6, the remainder is 3, and when x is divided by 16, the remainder is 5. When y is divided by 9, the remainder is 5, and when y is divided by 7, the remainder is 4. What is the least possible value of x / y?	Choose the correct choice from the following options
A) 2.5
B) 3
C) 2
D) 1.3
E) 1.5
When x is divided by 6, the remainder is 3: So, the possible values of x are: 3, 9, 15, 21, etc.   When x is divided by 16, the remainder is 5: So, the possible values of x are: 5,21... STOP. Since both lists include 21, the smallest possible value of x is 21.   When y is divided by 9, the remainder is 5: So, the possible values of y are: 5, 14, 23,32 etc.   When y is divided by 7, the remainder is 4: So, the possible values of y are: 6, 14, ...STOP. Since both lists include 14, the smallest possible value of y is 14   Since the smallest possible values of x and y are 21 and 14 respectively, the smallest possible value of x / y is 1.5. So,1.5 is the correct answer to the original question.
<result>E</result>
x and y are positive integers. When x is divided by 6, the remainder is 3, and when x is divided by 16, the remainder is 5. When y is divided by 9, the remainder is 5, and when y is divided by 7, the remainder is 4. What is the least possible value of x / y?