An oratorical society consists of six members, and at an upcoming meeting, the members will present a total of four speeches. If no member presents more than two of the four speeches, in how many different orders could the members give speeches?	Pick one
A) 720	B) 1080	C) 1170	D) 1470	E) 1560
You need to remember that of the 3 people, 1 is going twice and two are going once. Since one of the 3 is going once, there are 3C1 possibilities for the double speaker.   So, to convert your work to the correct answer, you need to multiply:   240 * 3C1 = 240 * 3= 
<gadget id="calculator">240 * 3</gadget>
<output>720</output>
720. 720NS:720
<result>A</result>
An oratorical society consists of six members, and at an upcoming meeting, the members will present a total of four speeches. If no member presents more than two of the four speeches, in how many different orders could the members give speeches?