X and Y run a 100m race,where X beats Y by 20 m. To do a favor to Y, X starts 10m behind the starting line in a second 100m race. Both run at the same previous speed. Which of the following is true?	Choose the correct choice from the following answers:
A) X Beats Y by 2m B) X Beats Y by 0.5 m C) X Beats Y by 4 m D) Y Beats X by 10m E) Beats X by 11m
Let's suppose that the speed of X is 10m/s and that the speed of Y is 8m/s.   So, in the first race, the results are the following:   X crosses the finish line in 10s. In other words, X has run 100m in 10 s.   In 10s, Y has run 80 meters.   Therefore, there is the difference of 20 meters mentioned in the question.   Now, let's review the second race.   In 12 seconds, X can complete the 120 meters race. We have to remember that X is 20 meters behind the starting line.   But in 12 seconds, Y has covered (80+16)= 
<gadget id="calculator">(80+16)</gadget>
<output>96</output>
96 meters. Also, it is important to notice that in 12 seconds Y cannot arrive to the finish line.   So, 100 - 96= 4 meter   Answer: X Beats Y by 4 m
<result>C</result>
X and Y run a 100m race,where X beats Y by 20 m. To do a favor to Y, X starts 10m behind the starting line in a second 100m race. Both run at the same previous speed. Which of the following is true?