Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 32 percent ryegrass, what percent of the weight of this mixture is X ?
Options:
A) 10%
B) 33.33 %
C) 46.66%
D) 50%
E) 66.66 %
----------------&gt;Ryegrass   X--------------&gt;	40%   Y--------------&gt;	25%   M(mixture)----&gt;32%   0.4X + (M-X)0.25 = 0.32M   0.15X = 0.07M   X = 0.4666M   X = 46.66% of M   46.66%
<result>C</result>
Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 32 percent ryegrass, what percent of the weight of this mixture is X ?