Two digits in father's age are the same as the digit in the son's age, but in reverse order. In five years father will be twice as old as son will be then. what is the difference in their current age ?  Pick one.
A) 18	B) 16	C) 34	D) 25	E) 12
Father's age= 10x+y   so son's age= 10y+x..   after 5 years , 10x+y+5=2*(10y+x+5)....   so 5+19y=8x... check for odd values of y, y=1 satisfies the eqn with x=3... so ages are 31 and 13 and ans as found correctly by u is 18..18
<result>A</result>
Two digits in father's age are the same as the digit in the son's age, but in reverse order. In five years father will be twice as old as son will be then. what is the difference in their current age ?