There are 6 girls and 6 boys. If they are to be seated in a row, what is the probability that no two boys sit together?  Choose the correct choice from the following choices
A) A)1/12!
B) B)6!5!/12!
C) C)6!6!/12!
D) D)2∗6!/12!
E) E)none of these
If girls are alternate, then only no 2 boys can be together.   So among 12 places, boys can be seated in 6 alternate places in 6! ways.   And girls can be seated in the remaining 6 places in 6! ways.   Therefore total number of ways = 6! * 6!   But there could be 2 such arrangements--&gt;   1. When first place is filled by a girl   2. When first place is filled by a boy   Therefore total number of ways = 2*6! * 6!   Also total number of ways to fill 12 places = 12!   Hence probability =2∗6!6!/12!   Answer:none of these
<result>E</result>
There are 6 girls and 6 boys. If they are to be seated in a row, what is the probability that no two boys sit together?