A number, y is chosen at random from the set of positive integers from 1 to 9. What is the probability that (9/y) > y?  Choose the correct choice from the following options:
A) 2/9
B) 1/9
C) 1/3
D) 2/3
E) 7/9
Number x has to be chosen from numbers 1-9   (9/y) &gt; y   =&gt; 9 &gt; y^2   =&gt;y^2 - 9 &lt; 0   y can have 2 values only 1 , 2   Therefore , probability = 2 / 9   2/9nswer 2/9
<result>A</result>
A number, y is chosen at random from the set of positive integers from 1 to 9. What is the probability that (9/y) > y?