If p is a natural number and p! ends with y trailing zeros, then the number of zeros that (5p)! ends with will be
Select the correct option:
A) (p+y) trailing zeros
B) (5p+y) trailing zeros
C) (5p+5y) trailing zeros
D) (p+5y) trailing zeros
E) none of them above
for p = 10 trailing 0's =   10/5= 
<gadget id="calculator">10/5</gadget>
<output>2</output>
2   for 5p,   50/5= 
<gadget id="calculator">50/5</gadget>
<output>10</output>
10, 50/25= 2 hence total is 12   Similarly,   for p = 20 trailing 0's = 20/5= 
<gadget id="calculator">20/5</gadget>
<output>4</output>
4   for 5p, trailing 0's= 50/5= 
<gadget id="calculator">50/5</gadget>
<output>10</output>
10, 50/25= 2 hence total is  10 + 2= 
<gadget id="calculator"> 10 + 2</gadget>
<output>12</output>
12   thus we observe,   number of 0's= p + y   example p = 20, y = 4 giving 24.   Hence (p+y) trailing zeros.
<result>A</result>
If p is a natural number and p! ends with y trailing zeros, then the number of zeros that (5p)! ends with will be