A question paper has 2 parts, A & B, each containing 7 questions. If a student has to choose 5 from part A & 4 from part B, in how many ways can he choose the questions?
Choose the correct choice from the following choices:
A) 1100
B) 1200
C) 1235
D) 1354
E) 735
There 7 questions in part A out of which 5 question can be chosen as = 7C5.   Similarly, 4 questions can be chosen from 7 questions of Part B as = 7C4.   Hence, total number of ways,   =7C5*7C4   =[7!/(2!5!)]*[7!/(3!*4!)]   = {21}*{7*6*5*4/(4*3*2*1)}   = 735.   73521 * 7*6*5*4/(4*3*2*1)= 
<gadget id="calculator">21 * 7*6*5*4/(4*3*2*1)</gadget>
<output>735</output>
735.   735
<result>E</result>
A question paper has 2 parts, A & B, each containing 7 questions. If a student has to choose 5 from part A & 4 from part B, in how many ways can he choose the questions?