Two trains, each 100 m long, moving in opposite directions, cross other in 15 sec. If one is moving twice as fast the other, then the speed of the faster train is?	Pick:	A) 76 km/hr	B) 66 km/hr	C) 60 km/hr	D) 67 km/hr	E) 32 km/hr
Let the speed of the slower train be x m/sec.   Then, speed of the train = 2x m/sec.   Relative speed = ( x + 2x) = 3x m/sec.   (100 + 100)/15 = 3x =&gt; x = 40/9.   So, speed of the faster train = 80/9 = 80/9 * 18/5= 
<gadget id="calculator">80/9 * 18/5</gadget>
<output>32</output>
32 km/hr.   Answer:32 km/hr
<result>E</result>
Two trains, each 100 m long, moving in opposite directions, cross other in 15 sec. If one is moving twice as fast the other, then the speed of the faster train is?