Solve the set of linear equations using subtraction:
4x-3y = 3
2x+6y = 4  Options:
A) x=1/3, y=2/3
B) x=1, y=2/3
C) x=3, y=1/3
D) x=2, y=2
E) x=1, y=1/3
Multiply the first equation by 2 so y will have a coefficient of 6 in both equations.   4x-3y = 3   Multiplying by 2: 8x-6y = 6   Add the new equation with the original second equation and solve for x.   8x-6y = 6   +2x+6y = 4   10x = 10   x=1   Substitute the solution for x into the first equation and solve for y.   4x-3y = 3   4(1)-3y = 3   -3y = -1   y=1/3   Substitute the solutions into the second equation to check the answer.   2*1+6*(1/3)= 
<gadget id="calculator">2*1+6*(1/3)</gadget>
<output>4</output>
4   2+(6/3)= 
<gadget id="calculator">2+(6/3)</gadget>
<output>4</output>
4   2+2= 
<gadget id="calculator">2+2</gadget>
<output>4</output>
4   4=4   x = 1 and y=1/3   Answer x=1, y=1/3
<result>E</result>
Solve the set of linear equations using subtraction:
4x-3y = 3
2x+6y = 4