Thomas's age and Matt's age are in the ratio 2:3. Two years ago the ratio of their ages was 1:2. Find the ratio of their ages four years hence?	Pick
A) 1:2	B) 2:3	C) 3:4	D) 4:5	E) 5:6
Let ages of Thomas and Matt be x and y respectively.   x/y = 2/3 =&gt; x = 2/3 y   (x- 2)/(y - 2) = 1/2     ( - 2)/(  - 2)= 
<gadget id="calculator">  ( - 2)/(  - 2)</gadget>
<output>1</output>
1/2=&gt; 2x - 4 = y - 2 =&gt; 2x = y + 2= 
<gadget id="calculator">+ 2</gadget>
<output>2</output>
2/3 y   2 * 2/3 y= y + 2   4y = 3y + 6 =&gt; y = 6years   =&gt; x = 4 years   Ratio of their ages five years hence, (4 +4)/(6 + 4) = 8/10. =&gt; 4:5   Answer:4:5
<result>D</result>
Thomas's age and Matt's age are in the ratio 2:3. Two years ago the ratio of their ages was 1:2. Find the ratio of their ages four years hence?