What is the greatest number of 4 digits that when divided by any of the numbers 6, 9, 12, 17 leaves a remainder of 2?	Pick one:
A) 9792
B) 9982
C) 9794
D) 9906
E) None of these
Apply hit and trial method at each option   9792/9= 0 remainder (failed)   9982/9= 1 remainder (failed)   9794/6= 2   9794/9= 2   9794/12=2   9793/17= 2   ANSWER:9794
<result>C</result>
What is the greatest number of 4 digits that when divided by any of the numbers 6, 9, 12, 17 leaves a remainder of 2?