Jim and Reneeh will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Reneeh have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win?	Options:
A) 5/6
B) 2/3
C) 1/2
D) 5/12
E) 1/3
1/3   probability of jim winning is basically the sum of three probabilities:   probability of jim picking rock and reneeh picking scissors = 1/3*1/3 = 1/9   probability of jim picking scissors and reneeh picking paper = 1/3*1/3=1/9   probability of jim picking paper and reneeh picking rock = 1/3*1/3=1/9   1/9 + 1/9 + 1/9 = 3/9 = 1/3=1/3
<result>E</result>
Jim and Reneeh will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Reneeh have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win?