If x, y, and z are positive integers such that x^2 + y^2 + z^2 = 64,470, which of the following could be the values of x, y, and z?
I)x=541 y=401 z=100
II)x=530 y=400 z=100
III)X=501 y=300 z=200	Choose the correct answer:	A) I only	B) II only	C) III only	D) I​ and II	E) I and III
10 sec answer if you know how to find the units digit of a number   The number given is of the form of square, so calculate the units digit - Here your objective is to find the sum where last digit is 0   x = 530, so x^2 will have units digit 0   y = 400, so y^2 will have units digit 0   z = 100, so z^2 will have units digit 0   Calculate the units digit , the units digit will be 0   Only option II will satisfy the condition , hence this will be our answer is option II only.
<result>B</result>
If x, y, and z are positive integers such that x^2 + y^2 + z^2 = 64,470, which of the following could be the values of x, y, and z?
I)x=541 y=401 z=100
II)x=530 y=400 z=100
III)X=501 y=300 z=200