A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 472. What is the sum of the last 8 of the even integers? Choose the correct answer.
A) 588 B) 594 C) 600 D) 606 E) 612
The sum of the first 8 numbers is: x + (x+2) +...+ (x+14) = 472   The sum of the next 8 numbers is: (x+16) + (x+2+16) +...+ (x+14+16) =   472 + 8(16) = 472 + 128= 
<gadget id="calculator">472 + 128</gadget>
<output>600</output>
600   The answer is 600.
<result>C</result>
A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 472. What is the sum of the last 8 of the even integers?