1,236
1,263
1,326
.....
....
+6,321
The addition problem above shows four of the 24 different integers that can be formed by using each of the digits 1,2,3,6 exactly once in each integer. What is the sum of these 24 integers?  Options: A) 63,332 B) 67,772 C) 71,112 D) 75,552 E) 79,992
In each of the units, tens, hundreds, and thousands place, each digit will appear 6 times.   Then the sum equals 6(1111)+6(2222)+6(3333)+6(6666) = 79,992   The answer is 79,992.
<result>E</result>
1,236
1,263
1,326
.....
....
+6,321
The addition problem above shows four of the 24 different integers that can be formed by using each of the digits 1,2,3,6 exactly once in each integer. What is the sum of these 24 integers?