Three unbiased coins are tossed. What is the probability of getting 3 heads? Options.
A) 3/4	B) 1/4	C) 3/8	D) 7/8	E) 1/8
Let, H --&gt; Head , T --&gt; Tail   Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}   Let 1/8 = event of getting 3 heads   Then 1/8 = {HHH}   P(1/8) = n(1/8)/n(S) =1/8
<result>E</result>
Three unbiased coins are tossed. What is the probability of getting 3 heads?