Find the quotient when total no. Of divisors of 16! is divided by right most non-zero digit of 15! Choose the correct option:
A) 672	B) 682	C) 692	D) 745	E) 845
first find the factors of 16!   and then divide with non zero digit of 15!   factors of 16!   prime no below 16 are 2 3 5 7 11 13   now highest power of 2 in 16! is 15   3is 6,5 is 3,7 is 2,11,is 1,13 is 1   so no of factors is   16*7*4*3*2*2= 
<gadget id="calculator">  16*7*4*3*2*2</gadget>
<output>5_376</output>
5376   now last digit in 15!   it can be written as 2^11*3^6*5^3*7^2*11^1*13*1   5^3*2^3 gives 0 so remaining is 2^3=8   therefore  5376/8= 
<gadget id="calculator"> 5376/8</gadget>
<output>672</output>
672   672NSWER:672
<result>A</result>
Find the quotient when total no. Of divisors of 16! is divided by right most non-zero digit of 15!