The sum of three digits a number is 17. The sum of square of the digits is 109. If we substract 495 from the number, the number is reversed. Find the number.
Choose one.
A) 2,4,2 B) 8,3,6 C) 2,2,2 D) 3,3,4 E) 1,3,4
Let the number be abc.   Then a + b + c= 17 .....(1)   a2+b2+c2=109a2+b2+c2=109 .....(2)   100a+10b+c -495 = 100c+10b+a ......(3)   From 3, we get a - c = 5   So the possibilities for (a, c, b) are (6,1,10), (7,2,8), (8,3,6), (9,4,4)   From the above, (8,3,6) satisfies the condition.   Answer:8,3,6
<result>B</result>
The sum of three digits a number is 17. The sum of square of the digits is 109. If we substract 495 from the number, the number is reversed. Find the number.