4 shooters are hitting 1 out of 4 different targets. What is the probability that exactly one shooter will hit each target. Pick one.
A) 4/4^4
B) 4^4/4
C) 4!/4
D) 4!/4^4
E) 1/4!
Each shooter out of 4 has 4 options, hence total # of outcomes is 4^4;   Favorable outcomes will be 4!, which is # of ways to assign 4 different targets to 4 shooters:   1-2-3-4 (targets)   A-B-C-D (shooters)   B-A-B-C (shooters)   C-B-A-B (shooters)   ...   So basically # of arrangements of 4 distinct objects: 4!.   P=favorable/total=4!/4^4   Answer: 4!/4^4.
<result>D</result>
4 shooters are hitting 1 out of 4 different targets. What is the probability that exactly one shooter will hit each target.