At a certain fruit stand, the price of each apple is 40 cents and the price of each orange is 60 cents. Mary selects a total of 15 apples and oranges from the fruit stand, and the average (arithmetic mean) price of the 15 pieces of fruit is 48 cents. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is 45 cents?  Choose one.
A) 1  B) 2  C) 3  D) 8  E) 9
Let number of Apples = A   number of oranges = B   A+B=15 --- 1   .48 =(.4A + .6 B)/15   =&gt; 48 = 4A + 6B ----2   Solving 1 and 2, we get   A= 9   B= 6   Let the number of oranges put back = 3   45*(15-c) = 40*9 + 60(6-3)   =&gt; 3= 3   Answer 3
<result>C</result>
At a certain fruit stand, the price of each apple is 40 cents and the price of each orange is 60 cents. Mary selects a total of 15 apples and oranges from the fruit stand, and the average (arithmetic mean) price of the 15 pieces of fruit is 48 cents. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is 45 cents?