Only a single rail track exists between stations A and B on a railway line. One hour after the north bound super fast train N leaves station A for station B, a south-bound passenger train S reaches
station A from station B. The speed of the super fast train is twice that of a normal express train E, while the speed of a passenger train S is half that of E. On a particular day, N leaves for B from A, 20 min behind the normal schedule. In order to maintain the schedule, both N and S increased their speeds. If the super fast train doubles its speed, what should be the ratio (approximately) of the speeds of passenger train to that of the super fast train so that the passenger train S reaches exactly at the scheduled time at A on that day?  Choices.
A) 1 : 3	B) 1 : 4	C) 1 : 5	D) 1 : 6	E) 1 : 7
Explanation :   If speed of N = 4, speed of S = 1.   =&gt; Average speed = (2 X 4 x 1) / ( 4 + 1) = 1.6.   Because time available is 2/3, speed = 3/2.   Now Average speed = 2.4   Now speed of N = 8.   Speed of S = y.   =&gt; (2 x 8 x y) / (8+y) = 2.4   =&gt; y = 1.3   The required ratio is 1.3 : 8 i.e 1 : 6.   Answer : 1 : 6
<result>D</result>
Only a single rail track exists between stations A and B on a railway line. One hour after the north bound super fast train N leaves station A for station B, a south-bound passenger train S reaches
station A from station B. The speed of the super fast train is twice that of a normal express train E, while the speed of a passenger train S is half that of E. On a particular day, N leaves for B from A, 20 min behind the normal schedule. In order to maintain the schedule, both N and S increased their speeds. If the super fast train doubles its speed, what should be the ratio (approximately) of the speeds of passenger train to that of the super fast train so that the passenger train S reaches exactly at the scheduled time at A on that day?