Two tains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 125 metres, in what time (in seconds) will they cross each other travelling in opposite direction?  Choose the correct choice from the following choices.
A) 6  B) 14  C) 16  D) 20  E) 18
Sol.   Speed of the first train = [150 / 10] m/sec = 15 m/sec.   Speed of the second train = [150 / 15] m/sec = 10 m/sec.   Relative speed = (15 + 10) = m/sec = 25 m/sec.   ∴ Required time = (125 + 125) / 25 secc = 6 sec.   6nswer 6
<result>A</result>
Two tains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 125 metres, in what time (in seconds) will they cross each other travelling in opposite direction?