The product of n consecutive positive integers is always divisible by	Choose the correct choice from the following choices.
A) n^2 -1  B) (n+1)!  C) 2n +1  D) n^2 + 1  E) n!
Product of first 2 number is 2*1   Product of first 3 number is 3*2*1   Product of first 4 number is 4*3*2*1   Product of first 5 number is 5*4*3*2*1   So, The product of first n natural numbers is always divisible by n! , answer will be (n!)
<result>E</result>
The product of n consecutive positive integers is always divisible by