If n is a natural number, then(6n^2+6n) is always divisible by?	Choose the correct choice from the following choices
A) 6 only
B) 6 and 12 both
C) 12 only
D) by 18 only
E) None of these
(6n^2+6n)=6n(n+1), which is always divisible by 6 and 12 both, since n(n+1) is always even.   Correct Option: 6 and 12 both
<result>B</result>
If n is a natural number, then(6n^2+6n) is always divisible by?