A committee of three people is to be chosen from four married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?  Pick
A) 16
B) 24
C) 26
D) 30
E) 32
The committee could have   0 men and 3 women = 4 possibilities ( 4c3 )   1 man and 2 women = 12 possibilities ( no couple should be in the team : 4 * 3c2 )   2 men and 1 woman = 12 possibilities ( no couple should be in the team : 4c2 *2c1 )   3 men and 0 women = 4 possibilities ( 4c3 )   Therefore  4+12+12+4= 
<gadget id="calculator"> 4+12+12+4</gadget>
<output>32</output>
32   Answer 32 32
<result>E</result>
A committee of three people is to be chosen from four married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?