About the number of pairs which have 20 as their HCF and 136 as their LCM, the conclusion can be  Pick.
A) only one such pair exists	B) only two such pairs exist	C) many such pairs exist	D) yes such pair exists	E) paid does not exists
Explanation:   HCF is always a factor of LCM. ie., HCF always divides LCM perfectly.   Correct Option: paid does not exists
<result>E</result>
About the number of pairs which have 20 as their HCF and 136 as their LCM, the conclusion can be