Mixture A, which is 20% oil, contains 20 gallons of water and mixture B is 80% oil. If the combination of mixture A and B has a 4.5 : 3 ratio of oil to water, how many gallons of water does mixture B have? Choose the correct choice from the following answers
A) 5  B) 10  C) 30  D) 40  E) 50
Combined mixture has oil: water = 4.5:3 ie. Oil = (4.5/7.5)*100= 
<gadget id="calculator">(4.5/7.5)*100</gadget>
<output>60</output>
60%   Now by Alligation Rule:   A . ......... B   20% . . . 80%   . . 60% . .   (80-60) . (60-20)=20 : =40   Qty A: Qty B = 1:2 ( A &amp; B are mixed in 1: 2 ration)   So if A contains 20 gallons water ie total Qty of A= 25 gallons (Since water is 80%)   So as per above ration Qty B mixed will be 50 gallons.   Qty of water in mixture B = 20% of 50 = 10 gallons.   ANSWER:10
<result>B</result>
Mixture A, which is 20% oil, contains 20 gallons of water and mixture B is 80% oil. If the combination of mixture A and B has a 4.5 : 3 ratio of oil to water, how many gallons of water does mixture B have?