A die is rolled twice. What is the probability of getting a sum equal to 9? Select:
A) 2/8  B) 1/9  C) 3/9  D) 7/4  E) 2/7
Explanation :   Total number of outcomes possible when a die is rolled =6   Hence, total number of outcomes possible when a die is rolled twice, n(S)=6*6= 
<gadget id="calculator">6*6</gadget>
<output>36</output>
36   E= Getting a sum of 9 when the two dice fall = {(3, 6), {4, 5}, {5, 4}, (6, 3)}   Hence, n(E) = 4   P(E) =n(E)/n(S)=4/36=1/9   1/9
<result>B</result>
A die is rolled twice. What is the probability of getting a sum equal to 9?