A hostess must seat 10 people around 2 circular tables. Table 1 can hold 6 people, table 2 can hold 4 people. If the hostess always seats people at Table 1 first and 2 seating arrangements are said to be different only when the positions of people are different relative to each other at the table, how many seating arrangements are possible?	Choose the correct choice from the following answers.
A) 5*210
B) 15!*210
C) 120*3!
D) 5!*3!*210
E) 5!*5!*3!
1)since there are two tables, the hostess has to choose 6 out of 10 and the remaining 4 will go to other table..   so WAYS= 10C6=10!/6!4!=210..   2)now 6 on the Table 1 can be seated in (6-1)! ways   3)and 4 on the Table 1 can be seated in (4-1)! ways   TOTAL ways=210*5!*3!   5!*3!*210
<result>D</result>
A hostess must seat 10 people around 2 circular tables. Table 1 can hold 6 people, table 2 can hold 4 people. If the hostess always seats people at Table 1 first and 2 seating arrangements are said to be different only when the positions of people are different relative to each other at the table, how many seating arrangements are possible?