In how many ways can be 6 boys and 6 girls sit around circular table so that no two boys sit next to each other? Select the correct option: A) (5!)^2 B) (6!)^2 C) 5!6! D) 11! E) (5!)^2*6!
first fix one boy and place other 5 in alt seats so total ways is 5!   now place each girl between a pair of boys... total ways of seating arrangement of girls 6!   total is 5!*6!   ANS 5!6!
<result>C</result>
In how many ways can be 6 boys and 6 girls sit around circular table so that no two boys sit next to each other?