If 2^2n + 2^2n + 2^2n + 2^2n = 4^28, then n =  Options
A) 3 B) 6 C) 12 D) 27 E) 24
2^2n + 2^2n + 2^2n + 2^2n = 4^28   =&gt; 4 x 2^2n = 4^28 = 2^56   =&gt; 2^2 x 2^2n = 2^56   =&gt; 2^(2n+2) = 2^56   =&gt; 2n+2 = 56=&gt; n =27   So. Answer will be 27.
<result>D</result>
If 2^2n + 2^2n + 2^2n + 2^2n = 4^28, then n =