Exactly two sides of a certain 10-sided die are red. What is the probability that Kumar rolls the die 4 times and the die lands with a red side up for the first time on the fourth roll? Choose the correct choice from the following options
A) 0.1026 B) 0.01024 C) 0.02 D) 0.03 E) 0.04
Total no. of sides = 10   Sides that are red = 2   Probability that the die lands with red side up = 2/10   Therefore, Probability that the die does not land with red side up = 1 - 2/10 = 8/10   Probability that Kumar rolls the die 3 times and the die lands with a red side up for the first time on the third roll   = (1st roll - non red face) X (2nd roll - non red face) X (3rd roll - non red face)x (4th roll- red face)   = (8/10) X (8/10) X (8/10) x(2/10)   = 1024/10000   = 0.01024   0.01024
<result>B</result>
Exactly two sides of a certain 10-sided die are red. What is the probability that Kumar rolls the die 4 times and the die lands with a red side up for the first time on the fourth roll?