If X is to be chosen at random from the integers between 1 to 7, inclusive, and Y is to be chosen at random from the integers between 7 and 11, inclusive, what is the probability that X + Y will be even?
Choose the correct choice.
A) 3/5	B) 4/7	C) 5/7	D) 18/35	E) 23/35
X+Y will be even if X and Y are both even or both odd.   P(X and Y are both even) = 3/7*2/5 = 6/35   P(X and Y are both odd) = 4/7*3/5 = 12/35   P(X+Y is even) = 6/35 + 12/35 = 18/35   The answer is 18/35.
<result>D</result>
If X is to be chosen at random from the integers between 1 to 7, inclusive, and Y is to be chosen at random from the integers between 7 and 11, inclusive, what is the probability that X + Y will be even?