If x−log48+3log2=log125/3−log3, what is the value of x? Select the correct option.
A) 2  B) 1  C) 3  D) 5  E) 8
Explanation:   1/3 log 125= log (125^1/3) = log 5   3 log 2= log (2^3)= log 8   log a + log b= log (a*b)   Utilizing the same,   LHS= x -log 48 +log 8= x - log 6 - log 8 + log 8 = x - log 6   RHS= log 5 - log 3   =&gt; x= log 5 - log 3 + log 6 = log 5 - log 3 + log 2 + log 3   =&gt; x= log 10 = 1   Answer 1
<result>B</result>
If x−log48+3log2=log125/3−log3, what is the value of x?