A meeting has to be conducted with 5 managers. Find the number of ways in which the managers may be selected from among 7 managers, if there are 2 managers who refuse to attend the meeting together.  Choose the correct choice from the following choices
A) 6	B) 8	C) 10	D) 11	E) 15
The total number of ways to choose 5 managers is 7C5 = 21   We need to subtract the number of groups which include the two managers, which is 5C3 = 10.   21 - 10= 
<gadget id="calculator">21 - 10</gadget>
<output>11</output>
11   The answer is 11.
<result>D</result>
A meeting has to be conducted with 5 managers. Find the number of ways in which the managers may be selected from among 7 managers, if there are 2 managers who refuse to attend the meeting together.