A train travels from station A to station B. If it travels at a speed of 100 miles per hour, it ends up reaching the station 30 minutes late. If it travels at 120 miles per hour, it reaches the station 30 minutes early. What is the amount of time that the train is scheduled to take for the journey and what is the distance between the stations?	Choose the correct answer.
A) 2 hours, 225 miles B) 5.5 hours, 600 miles C) 4 hours, 450 miles D) 5 hours, 550 miles E) 6 hours, 650 miles
Let t be the usual time and x be the distance between AB. So we need to find t and Distance x. The question gives us 2 combinations of speedtime, but the distance remains the same for both condition.   Equation 1 - x= 100 (t+.5) (converted 30 mins into hr) added .5 hrs because it is late or took more time than usual.   Equation 2 - x= 120 (t-.5) subtracted .25 hrs because it is early or took less time than usual.   Now equating 12 we get 100(t+.5)=120(t-.5)   =&gt; 10t +5 = 12t - 6   =&gt; 2t=11 =&gt; t= 5.5 hrs.   Hence x= 100(5.5+.5) =&gt;100 X 6 =&gt; 600 miles.   Hence correct answer 5.5 hours, 600 miles
<result>B</result>
A train travels from station A to station B. If it travels at a speed of 100 miles per hour, it ends up reaching the station 30 minutes late. If it travels at 120 miles per hour, it reaches the station 30 minutes early. What is the amount of time that the train is scheduled to take for the journey and what is the distance between the stations?