10 years ago, the average age of a family of 4 members was 24 years. Two children having been born (with age diference of 2 years), the present average age of the family is the same. The present age of the youngest child is : Choose the correct choice from the following answers:  A) 1  B) 2  C) 3  D) 4  E) 5
Explanation:   Total age of 4 members, 10 years ago = (24 x 4) years = 96 years.   Total age of 4 members now = [96 + (10 x 4)] years = 136 years.   Total age of 6 members now = (24 x 6) years = 144 years.   Sum of the ages of 2 children = (144 - 136)= 
<gadget id="calculator">(144 - 136)</gadget>
<output>8</output>
8 years.   Let the age of the younger child be x years.   Then, age of the elder child= (X + 2)years.   So, x + (x + 2) = 8 ⇔ x = 3   Age of younger child = 3 years. Answer: 3
<result>C</result>
10 years ago, the average age of a family of 4 members was 24 years. Two children having been born (with age diference of 2 years), the present average age of the family is the same. The present age of the youngest child is :