The present ages of A,B and C are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. What are their present ages (in years)?  Answers:
A) 20, 25 and 35 B) 21, 18 and 36 C) 18, 21 and 34 D) 12, 14 and 18 E) 16, 28 and 36
Sum of their present ages =56+3×8=80   Present age of A =80×420=16   Present age of B =80×720=28   Present age of C =80×920=36   Answer is 16, 28 and 36.
<result>E</result>
The present ages of A,B and C are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. What are their present ages (in years)?