What is theleast number should be added to 1056, so the sum of the number is completely divisible by 23?  Pick.
A) 1 B) 2 C) 3 D) 4 E) 5
(1056 / 23) gives remainder 21   21 + 2= 
<gadget id="calculator">21 + 2</gadget>
<output>23</output>
23, So we need to add 2   2
<result>B</result>
What is theleast number should be added to 1056, so the sum of the number is completely divisible by 23?