An object thrown directly upward is at a height of h feet after t seconds, where h = -15 (t-3)^2 + 150. At what height, in feet, is the object 2 seconds after it reaches its maximum height?
Select the correct option
A) 90	B) 98	C) 106	D) 120	E) 136
We see that h will be a maximum h=150 when t-3=0, that is when t=3.   90t t=5, h = -15(5-3)^2 + 150 = -15(4) + 150 = 90   The answer is 90.
<result>A</result>
An object thrown directly upward is at a height of h feet after t seconds, where h = -15 (t-3)^2 + 150. At what height, in feet, is the object 2 seconds after it reaches its maximum height?