Find the least number which when divided by 38 and 3 leaves a remainder of 1 in each case. Choose the correct choice
A) 107	B) 109	C) 111	D) 113	E) 115
The least number which when divided by different divisors leaving the same remainder in each case   = LCM(different divisors) + remainder left in each case.   Hence the required least number   = LCM(38, 3) + 1 = 115.   ANSW115R:115
<result>E</result>
Find the least number which when divided by 38 and 3 leaves a remainder of 1 in each case.