The number of diagonals of a polygon of n sides is given by the formula v=n(n-3)/2. If a polygon has twice as many diagonals as sides, how many sides does it have?	Choose the correct choice from the following answers
A) 3	B) 5	C) 6	D) 7	E) 8
v=n(n-3)   v=2*n   2n=n(n-3)   =&gt;2=n-3   =&gt;n=5   Answer 5
<result>B</result>
The number of diagonals of a polygon of n sides is given by the formula v=n(n-3)/2. If a polygon has twice as many diagonals as sides, how many sides does it have?