Two positive integers differ by 4, and sum of their reciprocals is 6. Then one of the numbers is  Choose the correct choice from the following answers:
A) a) 3
B) b) 1
C) c) 5
D) 4
E) e) 28
Algebraic approach:   Let n be the smaller integer =&gt; 1/n + 1/(n+4) = 6   or ((n+4)+n)/n(n+4) =6 or (n^2+4n)*6 =2n+4 or n=2 as n cannot be -negative   Solve for n =&gt; n=4. Hence,   4
<result>D</result>
Two positive integers differ by 4, and sum of their reciprocals is 6. Then one of the numbers is