Find four consecutive even integers such that the sum of the second and fourth integers is one and a half times the sum of the first and third integers.
Choose the correct choice from the following choices.
A) n, 2n, 4n, 6n B) n, 2, 4, 6 C) n, 2n, 3n, 4n D) n, n+2, n+4, n+6 E) n, n^2, n^4, n^6
Sum of Second and Fourth Integers: (n + 2) + (n + 6) = 2n + 8   Sum of First and Third Integers: n + (n + 4) = 2n + 4   Since sum of the second and fourth integers is twice than the sum of the first and third integers, it follows that:   2n + 8 = 1.5(2n + 4)   2n + 8 = 3n + 6   3n − 2n = 8 − 6   n = 2   Answer: n, n+2, n+4, n+6
<result>D</result>
Find four consecutive even integers such that the sum of the second and fourth integers is one and a half times the sum of the first and third integers.