If 6x^2 + x - 12 = (qx + b)(cx + d), then |q| + |b| + |c| + |d| =
For a complete solution and more practice problems, see this blog:
http://magoosh.com/gmat/2012/algebra-on ... to-factor/  Choose the correct option:
A) 10	B) 12	C) 15	D) 18	E) 20
6x^2+x-12 = 6x^2 + 9x -8x -12   =&gt; 3x(2x+3) -4(2x+3)   =&gt; (2x+3)(3x-4) = (qx+b)(cx+d)   Hence q=2, b=c=3, d=-4   So, 2+3+3+ |-4| = 2+3+3+4= 
<gadget id="calculator">2+3+3+4</gadget>
<output>12</output>
12   Answer 12.
<result>B</result>
If 6x^2 + x - 12 = (qx + b)(cx + d), then |q| + |b| + |c| + |d| =
For a complete solution and more practice problems, see this blog:
http://magoosh.com/gmat/2012/algebra-on ... to-factor/