A man buys 25 lts of liquid which contains 20% of the liquid and the rest is water. He then mixes it with 25 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?  Pick:
A) 55
B) 82
C) 73
D) 75
E) 85
20% in 25 lts is5. So water = 25-5= 
<gadget id="calculator">25-5</gadget>
<output>20</output>
20 lts. 30% of 25 lts=7.5. So water in 2nd mixture = 25-7.5= 
<gadget id="calculator">25-7.5</gadget>
<output>17.5</output>
17.5 lts. Now total quantity= 25 + 25= 
<gadget id="calculator">25 + 25</gadget>
<output>50</output>
50 lts. Total water in it will be 20 + 17.5= 
<gadget id="calculator">20 + 17.5</gadget>
<output>37.5</output>
37.5 lts. % of water= (100*37.5)/50= 
<gadget id="calculator">(100*37.5)/50</gadget>
<output>75</output>
75.   ANSWER:75
<result>D</result>
A man buys 25 lts of liquid which contains 20% of the liquid and the rest is water. He then mixes it with 25 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?