On final examination a student's average (arithmetic mean) score on 4 subjects is 90. What must be his score on a 5th subject for his average score on the 5 subjects to be 92?
Choices: A) 60 B) 70 C) 80 D) 90 E) 100
(4*90+x)/5=92   x=(5*92)-(4*90)   x= 460 - 360= 
<gadget id="calculator">460 - 360</gadget>
<output>100</output>
100   Correct answer is 100
<result>E</result>
On final examination a student's average (arithmetic mean) score on 4 subjects is 90. What must be his score on a 5th subject for his average score on the 5 subjects to be 92?