Will decides to attend a basketball game with four friends.
If the party of five sits together in five consecutive seats, and Will must NOT sit in between two of his friends, how many ways
can the five friends be arranged? Choose the correct option: A) 24 B) 36 C) 48 D) 72 E) 120
Will have to sit at either of the ends.   If will sits on the left most corner, then other 4 friends can be arranged in 4! = 24   Will can also sit on the other end, then another 4! ways we can arrange.   So total number of ways = 24+24= 
<gadget id="calculator">24+24</gadget>
<output>48</output>
48   ANS:Option( 48)
<result>C</result>
Will decides to attend a basketball game with four friends.
If the party of five sits together in five consecutive seats, and Will must NOT sit in between two of his friends, how many ways
can the five friends be arranged?