A women paid $1650 a year in interest on a loan with an annual rate of 11%. How w\much more money could she have borrowed for the same amount of interest if she had been able to get a loan amount with an annual rate of 10%? Choose the correct choice from the following answers:  A) $165  B) $1500  C) $1815  D) $ 15000  E) $16500
Let P = Principal amount   R1 = Interest Rate for case 1   R2 = Interest Rate for case 2   Time = T = 1year   Now Interest = (P * R1* T)/ 100   We have 1650 = (P*11*1)/100 =&gt; we get P = 15000$   now Case 2 : P = 15000 R2= 10% T= 1year   Interest Amount is $1650( Interest Amount Remains same)   Now on $15000 with 10% Interest Amount is $1500.   We get, Difference in Interest Amount's is $ 150   Solve for   150 = (P * 10 * 1)/100   P = $ 1500 . So the women can borrow $1500 more.   Answer: $1500
<result>B</result>
A women paid $1650 a year in interest on a loan with an annual rate of 11%. How w\much more money could she have borrowed for the same amount of interest if she had been able to get a loan amount with an annual rate of 10%?