6 boys and 4 girls appeared in a exam. If 4 students are failed how many chances at least one girl is failed?
Select the correct option
A) 198
B) 200
C) 190
D) 195
E) 180
4 girls and 6 boys. Four students is failed   It is always better to subtract the total from none in case of at least one problems.   Total ways = 10C4 = 210   Total ways without any girls = 6C4 = 15   Hence ways in which at least one man will be present = 210 - 15= 
<gadget id="calculator">210 - 15</gadget>
<output>195</output>
195   Correct option: 195
<result>D</result>
6 boys and 4 girls appeared in a exam. If 4 students are failed how many chances at least one girl is failed?