Dinesh speaks truth in 3/4 cases and Abhishek lies in 1/5 cases. What is the percentage of cases in which both Dinesh and Abhishek contradict each other in stating a fact? Choose one: A) 60% B) 35% C) 20% D) 15% E) None of these
Explanation :   D and A will contradict each other when one speaks truth and other speaks lies.   Probability of D speak truth and A lies   =&gt;(3/4)×(1/5).   =&gt;3/20.   Probability of A speak truth and D lies   =&gt;(4/5)×(1/4).   =&gt;1/5.   The two probabilities are mutually exclusive. Hence, probabilities that D and A contradict each other:   =&gt;(3/20)+(1/5).   =&gt;7/20.= 
<gadget id="calculator">7/20.</gadget>
<output>0.35</output>
&gt;0.35×100%=&gt;35%   Answer : 35%
<result>B</result>
Dinesh speaks truth in 3/4 cases and Abhishek lies in 1/5 cases. What is the percentage of cases in which both Dinesh and Abhishek contradict each other in stating a fact?