Three numbers are randomly selected, with replacement, from the set of integers {0, 1, 2, 3, 4}. If the first number selected is w, the second number selected is x, and the third number is y, what is the probability that w < x < y ?  Answers
A) 7/125  B) 4/125  C) 4/25  D) 3/25  E) 2/25
The number of ways to select w, x, and y is:   5*5*5= 
<gadget id="calculator">  5*5*5</gadget>
<output>125</output>
125   The number of ways to choose three different numbers from the set is 5C3=10.   There are six permutations for each group of three different numbers, but only one permutation satisfies w &lt; x &lt; y.   P(w &lt; x &lt; y) = 10/125 = 2/25   The answer is 2/25.
<result>E</result>
Three numbers are randomly selected, with replacement, from the set of integers {0, 1, 2, 3, 4}. If the first number selected is w, the second number selected is x, and the third number is y, what is the probability that w < x < y ?