What is the area inscribed by the lines y =6, x = 3, y = 2x-4 on an xy-coordinate plane? Choose the correct choice from the following answers.
A) a) 1	B) b) 2	C) c) 4	D) d) 8	E) e) 16
First, let's graph the lines y = 6 and x = 3   At this point, we need to find the points where the line y = 2x-4 INTERSECTS the other two lines.   For the vertical line, we know that x = 3, so we'll PLUG x = 3 into the equation y = 2x-4 to get y = 2(3)-4 = 2   Perfect, when x = 3, y = 2, so one point of intersection is (3,2)   For the horizontal line, we know that y = 6, so we'll PLUG y = 6 into the equation y = 2x-4 to get 6 = 2x-4. Solve to get: x = 5   So, when y = 6, x = 5, so one point of intersection is (5,6)   Now add these points to our graph and sketch the line y = 2x-4   At this point, we can see that we have the following triangle.   The base has length 2 and the height is 4   Area = (1/2)(base)(height)   = (1/2)(2)(4)   = 4   Answer:   c) 4
<result>C</result>
What is the area inscribed by the lines y =6, x = 3, y = 2x-4 on an xy-coordinate plane?