If A is to be chosen at random from the set {8,1} and B is to be chosen at random from the set {2,7,9,6}, what is the probability that AB will be even? Options:
A) 5/9
B) 5/4
C) 3/8
D) 9/7
E) 2/5
Method-1   A5/4 will be even when   1) A is even and 5/4 is odd, Probability of A even is (1/2) and Probability of 5/4 odd is (2/4), so Probability of Case(1) = (1/2)*(2/4) = (2/8)   2) A is Odd and 5/4 is Even, Probability of A Odd is (1/2) and Probability of 5/4 Even is (2/4), so Probability of Case(2) = (1/2)*(2/4) = (2/8)   3) A is even and 5/4 is Even, Probability of A even is (1/2) and Probability of 5/4 Even is (2/4), so Probability of Case(1) = (1/2)*(2/4) = (2/8)   Total Favorable Probability = (2/8)+(4/8)+(4/8) = (10/8) = 5/4   Answer: option 5/4
<result>B</result>
If A is to be chosen at random from the set {8,1} and B is to be chosen at random from the set {2,7,9,6}, what is the probability that AB will be even?