A man buys 12 lts of liquid which contains 20% of the liquid and the rest is water. He then mixes it with 10 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?  Options
A) 75.45  B) 76.45  C) 77.45  D) 74.45  E) 73.45
20% in 12 lts is 2.4. So water = 12-2.4= 
<gadget id="calculator">12-2.4</gadget>
<output>9.6</output>
9.6 lts. 30% of 10 lts= 3. So water in 2nd mixture = 10-3= 
<gadget id="calculator">10-3</gadget>
<output>7</output>
7 lts. Now total quantity= 12 + 10= 
<gadget id="calculator">12 + 10</gadget>
<output>22</output>
22 lts. Total water in it will be 9.6 + 7= 
<gadget id="calculator">9.6 + 7</gadget>
<output>16.6</output>
16.6 lts. % of water= (100*16.6)/22 = 75.45   75.45NSWER:75.45
<result>A</result>
A man buys 12 lts of liquid which contains 20% of the liquid and the rest is water. He then mixes it with 10 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?