If 4 people are selected from a group of 6 married couples, what is the probability that none of them would be married to each other?	Choose the correct option:
A) 1/33 B) 2/33 C) 1/3 D) 16/33 probability E) 11/12
Each couple can send only one "representative" to the committee. We can choose 4 couples (as there should be 4 members) to send only one "representatives" to the committee in C46C64 # of ways.   But these 4 chosen couples can send two persons (either husband or wife): 2∗2∗2∗2=242∗2∗2∗2=24.   So # of ways to choose 4 people out 6 married couples so that none of them would be married to each other is: C46∗24C64∗24.   Total # of ways to choose 4 people out of 12 is C412C124.   P=C46∗24C412=1633P=C64∗24C124=1633   Answer: 16/33 probability.
<result>D</result>
If 4 people are selected from a group of 6 married couples, what is the probability that none of them would be married to each other?