In the sequence S, each term after the first is twice the previous term. If the first term of sequence S is 3, what is the sum of the 14th, 15th, 16th, 17th, 18th and 19th terms in sequence S?	Options:	A) 3(2^16)	B) 9(2^15)	C) 21(2^14)	D) 9(2^14)	E) 189(2^13)
The terms in the sequence can be shown as   a(n) = 2* a(n-1)   So, the sequence will look like: 3, 2*3, (2^2) *3,...   And the nth term will be given as 2^(n-1) *3   Therefore, a(14) = (2^13)*3, a(15) = (2^14) *3, a(16) = (2^15) *3, a(17) = (2^16) *3 , a(18) = (2^17) *3 and a(19) = (2^18) *3   So, a(14) + a(15) + a(16)+ a(17)+ a(18) = (2^13) *3 + (2^14) *3 + (2^15) *3+ (2^16) *3+ (2^17) *3+ (2^18) *3   = 3* (2^13) *(1+2+4+8+16+32) = 3* (2^13) *63   = 189 * (2^13)   Answer : 189(2^13)
<result>E</result>
In the sequence S, each term after the first is twice the previous term. If the first term of sequence S is 3, what is the sum of the 14th, 15th, 16th, 17th, 18th and 19th terms in sequence S?