When positive integer R is divided by 6 the remainder is 3. Which of the following CANNOT be an even integer?	Choose the correct option:
A) a. k + 1
B) b. k -11
C) c. 4k + 2
D) d. (k-3)/3 +2
E) e. R/3
When positive integer R is divided by 6 the remainder is 3   So, R could equal 3, 9, 15, 21, etc   let's TEST R =3   a.3+ 1 = 4 (EVEN)   b.3-11 = -8 (EVEN)   c. 4(3) + 2 = 14 (EVEN)   d. (3-3)/3 +2 = 2 (EVEN)   At this point, we can already see the answer must be E.   Let's check e. R/3 forfun   e.3/3 = 1 (ODD)   Great!   Answer: e. R/3
<result>E</result>
When positive integer R is divided by 6 the remainder is 3. Which of the following CANNOT be an even integer?