On a game show, there are three tables. Each table has three boxes (one Zonk!, one cash prize, and one Grand Prize). The contestant can choose one box from each table for a total of three boxes. If any of the boxes are a Zonk!, the contestant loses everything. What is the probability of getting NO Zonk! from any of the three boxes chosen?	Pick one:  A) 1/5  B) 1/3  C) 8/27  D) 1/27  E) 7/8
NO Zonk!:   1st box = No Zonk! = 2/3   2nd box = NO Zonk! = 2/3   3rd box = No Zonk! = 2/3   (2/3)(2/3)(2/3) = 8/27   8/27 is the probability of NO Zonk!, so...   Answer: 8/27
<result>C</result>
On a game show, there are three tables. Each table has three boxes (one Zonk!, one cash prize, and one Grand Prize). The contestant can choose one box from each table for a total of three boxes. If any of the boxes are a Zonk!, the contestant loses everything. What is the probability of getting NO Zonk! from any of the three boxes chosen?