A coin is tossed 4 times. What is the probability z that the number of Heads is equal to the number of Tails?	Pick one.
A) 1/8	B) 1/4	C) 3/8	D) 1/2	E) 9/16
We have to find the probability that we get 2 heads and 2 tails in 4 tosses of the coin.   Using the binary formula and defining a head as a success,   P(2 heads in 4 tosses) = 43/82* (1/2)^2 * (1/2)^2   = 6/16   z= 3/8   The answer is therefore (3/8)
<result>C</result>
A coin is tossed 4 times. What is the probability z that the number of Heads is equal to the number of Tails?