A cylinder has a base with a circumference of 20pi meters and an equilateral triangle inscribed on the interior side of the base. A marker is dropped into the tank with an equal probability of landing on any point on the base. If the probability of the marker landing inside the triangle is (Sqrt 3)/4 , what is the length of a side of the triangle?  Select:
A) 3(sqrt 2pi) B) 3(sqrt 3pi) C) 10*sqrt (pi) D) 10(sqrt 3pi) E) 20 pi
Prob of marker landing in the triangle = area of triangle / area of base = sqrt(3)/4   10*sqrt (pi)ircumference of base = 20pi meters   =&gt; Radius of base = 10 meters   =&gt; Area of base = 100 pi sq m   Therefore area of the triangle = 100 pi * sqrt(3)/4   As the area of an equilateral triangle is sqrt(3)*(side^2)/4,   any side of the triangle = 10*sqrt(pi)   ANSWER:10*sqrt (pi)
<result>C</result>
A cylinder has a base with a circumference of 20pi meters and an equilateral triangle inscribed on the interior side of the base. A marker is dropped into the tank with an equal probability of landing on any point on the base. If the probability of the marker landing inside the triangle is (Sqrt 3)/4 , what is the length of a side of the triangle?