Two representatives must be selected from each of two groups of students. One group consists of three men and one woman, and the other group consists of two women and one man. What is the probability that 2 men and 1 women will be selected ?
Choose the correct choice from the following options.
A) 1/6 B) 1/4 C) 2/7 D) 2/3 E) 1/2
Group 1: 3 Men and 1 Woman   Group 2: 1 Men and 2 Woman   Need: 2 Men and 2 women   Case 1: 2 Men from Group 1 and 1 women from group 2 - 3C2*2C1 = 6 ways   Case 2: 1 Men and 1 Woman from Group 1 and 1 Man and 1 women from group 2 - 3*1*1*2 = 6 ways   Total Favorable cases = 6+6= 
<gadget id="calculator">6+6</gadget>
<output>12</output>
12   Total Possible ways of selecting students 2 from each group= 4C2*3C2 = 6*3= 
<gadget id="calculator">6*3</gadget>
<output>18</output>
18   Probability= 12/18 = 2/3   Answer : Option 2/3
<result>D</result>
Two representatives must be selected from each of two groups of students. One group consists of three men and one woman, and the other group consists of two women and one man. What is the probability that 2 men and 1 women will be selected ?