A bag contains 21 toys numbered 1 to 21. A toy is drawn and then another toy is drawn without replacement. Find the probability that both toys will show even numbers.	Choose the correct option:
A) 5/21
B) 9/42
C) 6/22
D) 4/21
E) 3/21
Since there are 10 even numbers in the given range, the probability that the first toy shows an even number = 10/21   Since the toy is not replaced, there are now 9 even numbered toys and total 20 toys left.   Hence, probability that the second toy shows an even number = 9/20.   Required probability = 10/21 x 9/20 = 9/42.   ANSWER:9/42
<result>B</result>
A bag contains 21 toys numbered 1 to 21. A toy is drawn and then another toy is drawn without replacement. Find the probability that both toys will show even numbers.