1,235
1,253
1,325
.....
....
+5,321
The addition problem above shows four of the 24 different integers that can be formed by using each of the digits 1,2,3,5 exactly once in each integer. What is the sum of these 24 integers? Choose the correct option
A) 73,326
B) 78,524
C) 84,820
D) 89,918
E) 95,560
In each of the units, tens, hundreds, and thousands place, each digit will appear 6 times.   Then the sum equals 6(1111)+6(2222)+6(3333)+6(5555) = 73,326   The answer is 73,326.
<result>A</result>
1,235
1,253
1,325
.....
....
+5,321
The addition problem above shows four of the 24 different integers that can be formed by using each of the digits 1,2,3,5 exactly once in each integer. What is the sum of these 24 integers?