The least number which when divided by 4, 6, 7 and 8 leaves a remainder 6, but when divided by 9 leaves no remainder, is Choices:
A) 340
B) 342
C) 523
D) 363
E) None of these
Explanation:   L.C.M of 4, 6, 7, 8 = 168   therefore Required Number is of the form 168k+6.   Least value of k for which (168k+6) is divisible by 9 is k = 2   therefore Required Number = (168 x 2+6)=342. Answer: 342
<result>B</result>
The least number which when divided by 4, 6, 7 and 8 leaves a remainder 6, but when divided by 9 leaves no remainder, is