Exactly three sides of a certain 10-sided die are red. What is the probability that Kumar rolls the die 3 times and the die lands with a red side up for the first time on the third roll?  Choose the correct choice from the following:
A) 0.184 B) 0.16 C) 0.18 D) 0.147 E) 0.148
Total no. of sides = 10   Sides that are red =3   Probability that the die lands with red side up = 3/10   Therefore, Probability that the die does not land with red side up = 1 - 3/10 = 7/10   Probability that Kumar rolls the die 3 times and the die lands with a red side up for the first time on the third roll   = (1st roll - non red face) X (2nd roll - non red face) X (3rd roll - red face)   = (7/10) X (7/10) X (3/10)   = 128/1000   = 0.147   0.147
<result>D</result>
Exactly three sides of a certain 10-sided die are red. What is the probability that Kumar rolls the die 3 times and the die lands with a red side up for the first time on the third roll?