Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 15 ?	Choose the correct choice:
A) 9/10	B) 6/10	C) 2/10	D) 3/10	E) 5/10
Explanation:   Here, S = {1, 2, 3, 4, ...., 19, 20}=&gt; n(s) = 20   Let E = event of getting a multiple of 4 or 15   =multiples od 4 are {4, 8, 12, 16, 20}   And multiples of 15 means multiples of 3 and 5   = {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.   = the common multiple is only (15).   =&gt; E = n(E)= 6   Required Probability = P(E) = n(E)/n(S) = 6/20 = 3/10.   Answer is 3/10
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Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 15 ?