The 323rd term of the series a, b , b, c, c, c, d, d, d, d, e, e, e, e, e, .... is
Select the correct option
A) u
B) v
C) w
D) y
E) z
a is one time, b,2 times so on...   so 323=n(n+1)/2..   0r n(n+1)= 646... now 25*26=650...24*25&lt;646 so n= 25. and 25th alphabet is Y. ans y
<result>D</result>
The 323rd term of the series a, b , b, c, c, c, d, d, d, d, e, e, e, e, e, .... is