3 women and a few men participated in a chess tournament. Each player played two matches with each of the other players. If the number of matches that men played among themselves is 78 more than those they played with the women, how many more men than women participated in the tournament?	Pick
A) 10 B) 11 C) 8 D) 9 E) 5
Let x be the number of men.   Number of matches men play among themselves is 2*(xC2)   Number of matches men play with women is 2*(3x)   2*(xC2) - 2*(3x) =78   x=13   Difference between men and women is 13-3= 
<gadget id="calculator">13-3</gadget>
<output>10</output>
10.   10NSWER 10
<result>A</result>
3 women and a few men participated in a chess tournament. Each player played two matches with each of the other players. If the number of matches that men played among themselves is 78 more than those they played with the women, how many more men than women participated in the tournament?