What is the positive difference between the sum of the squares of the first 6 positive integers and the sum of the prime numbers between the first square and fourth square?
Options:
A) 11	B) 12	C) 13	D) 14	E) 50
Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.   the sum of the squares of the first 4 positive integers = 1^2 + 2^2 + 3^2 +4^2+5^2+6^2 = 91   the sum of the prime numbers between the first square(=1) and fourth square(=16) = 2+3+5+7+11+13= 
<gadget id="calculator">2+3+5+7+11+13</gadget>
<output>41</output>
41.   So the difference between 41 and 91 is 50.   So the answer is (50).
<result>E</result>
What is the positive difference between the sum of the squares of the first 6 positive integers and the sum of the prime numbers between the first square and fourth square?