In how many ways can the letters of word EMULATION be arranged such that NO two vowels appear together?  Choose the correct choice from the following.
A) 9!
B) 5!*4!
C) 4!*5!
D) 5!*4!*2!
E) 6!*4!
No 2 vowels together = the only arrangement possible will be V C V C V C V C V (with V=vowel, C=consonant). This is true as we have 5 vowels and 4 consonants and any other combination will force us to pair 2 vowels together.   Thus, the number of arrangements possible : 5 *4 *4 *3 *3 *2 *2*1 = 5!*4! ----&gt; 4!*5! is the correct answer.
<result>C</result>
In how many ways can the letters of word EMULATION be arranged such that NO two vowels appear together?