Find the smallest number which when divided by 12 and 15 leaves respective remainders of 8 and 11.	Choose the correct answer.
A) 87  B) 97  C) 27  D) 21  E) 56
Let 'N' is the smallest number which divided by 12 and 15 leaves respective remainders of 8 and 11.   Required number = (LCM of 12 and 15) - (common difference of divisors and remainders) = (60) - (4)= 
<gadget id="calculator">(60) - (4)</gadget>
<output>56</output>
56.   ANSW56R:56
<result>E</result>
Find the smallest number which when divided by 12 and 15 leaves respective remainders of 8 and 11.