In a box, there are 10 blue, 12 white and 10 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?	Choose the correct answer.
A) 3/16
B) 5/16
C) 8/32
D) 2/32
E) 9/32
Total number of bulbs = (10 + 12 + 10)= 
<gadget id="calculator">(10 + 12 + 10)</gadget>
<output>32</output>
32.   Let E= event that the bulb drawn is neither white nor blue = event that the bulb drawn is yellow.   Therefore, P(E)=10/32= 5/32   ANSWER:5/16
<result>B</result>
In a box, there are 10 blue, 12 white and 10 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?