Of the 20 members of a kitchen crew in traditional Japanese, 17 can prepare sushi, 18 can prepare noodle, and 15 can prepare both. If one member is chosen at random, what is the probability that the member chosen will be someone who can not prepare either dish?
Choose the correct choice from the following choices:
A) a) 1/7  B) b) 1/5  C) c) 1/4  D) d) 0  E) e) 1/2
You know how to solve for Total number of people who can use at least one machine:   Total = n(A) + n(B) - n(A and B)   Total people who can prepare at least one dish = 17 + 18 - 15= 
<gadget id="calculator">17 + 18 - 15</gadget>
<output>20</output>
20   So all 20 people know how to prepare at least one dish. Hence, if you pick anyone, the probability is 0 that he/she wouldn't know how to prepare any dish   Answer (d) 0)
<result>D</result>
Of the 20 members of a kitchen crew in traditional Japanese, 17 can prepare sushi, 18 can prepare noodle, and 15 can prepare both. If one member is chosen at random, what is the probability that the member chosen will be someone who can not prepare either dish?