A runs 1 2/3 times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?
Pick:
A) 200 m B) 300m C) 270m D) 160m E) 150m
Explanation:   Ratio of the speeds of A and B =5 : 1 = 5 :3   Thus, in race of 5 m, A gains 2 m over B.   2 m are gained by A in a race of 5 m.   80 m will be gained by A in race of 5/2X80 m=200m   Winning post is 200 m away from the starting point.   200 mNSWER IS 200 m
<result>A</result>
A runs 1 2/3 times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?