476 ** 0 is divisible by both 3 and 11.The non zero digits in the hundred's and ten's places are respectively:
Select:
A) 8 and 8 B) 8 and 5 C) 8 and 7 D) 7 and 5 E) 8 and 3
Explanation:   Let the number be 476ab0   476ab0 is divisible by 3   =&gt; 4 + 7 + 6 + a + b + 0 is divisible by 3   =&gt; 17 + a + b is divisible by 3 ------------------------(i)   476ab0 is divisible by 11   [(4 + 6 + b) -(7 + a + 0)] is 0 or divisible by 11   =&gt; [3 + (b - a)] is 0 or divisible by 11 --------------(ii)   Substitute the values of a and b with the values given in the choices and select the values which satisfies both Equation 1 and Equation 2.   if a=6 and b=2,   17 + a + b = 17 + 6 + 2= 
<gadget id="calculator">17 + 6 + 2</gadget>
<output>25</output>
25 which is not divisible by 3 --- 7 and 5oes not meet equation(i).Hence this is not the answer   if a=8 and b=2,   17 + a + b = 17 + 8 + 2= 
<gadget id="calculator">17 + 8 + 2</gadget>
<output>27</output>
27 which is divisible by 3 --- Meet equation(i)   [3 + (b - a)]= [3 + (2 - 8)] = -3 which is neither 0 nor divisible by 11---7 and 5oes not meet equation(ii).Hence this is not the answer   if a=6 and b=5,   17 + a + b = 17 + 6 + 5= 
<gadget id="calculator">17 + 6 + 5</gadget>
<output>28</output>
28 which is not divisible by 3 --- 7 and 5oes not meet equation (i) .Hence this is not the answer   if a=8 and b=5,   17 + a + b = 17 + 8 + 5= 
<gadget id="calculator">17 + 8 + 5</gadget>
<output>30</output>
30 which is divisible by 3 --- Meet equation 1   [3 + (b - a)]= [3 + (5 - 8)= 
<gadget id="calculator">3 + (5 - 8)</gadget>
<output>0</output>
0 ---Meet equation 2   Since these values satisfies both equation 1 and equation 2, this is the answer   Answer: 7 and 5) 8 and 5
<result>D</result>
476 ** 0 is divisible by both 3 and 11.The non zero digits in the hundred's and ten's places are respectively: