a sixth grade teacher asked her students to draw rectangles with positive integer length and a perimeter of 42.the difference between the largest and smallest possible ares of the rectangles that the students could have come up with is?
Choose the correct choice:
A) 50 sq units B) 60 sq units C) 70 sq units D) 80 sq units E) 90 sq units
sum of length and breadth will be 21 units . 42/2=21   area will be max when lxb = 11x10=110 sq units   area will be min when lxb = 20x1=20 sq units.   .the difference between the largest and smallest possible ares of the rectangles that the students could have come up with= 110-20= 
<gadget id="calculator">110-20</gadget>
<output>90</output>
90 sq units   ANSW90 sq unitsR:90 sq units
<result>E</result>
a sixth grade teacher asked her students to draw rectangles with positive integer length and a perimeter of 42.the difference between the largest and smallest possible ares of the rectangles that the students could have come up with is?