what is the value of y if the greatest common divisor of (y-4)!,(y+1)!, and (y+2)! is 720.  Choose the correct option:  A) 12  B) 10  C) 9  D) 7  E) 8
GCD of (y-4)!,(y+1)!, and (y+2)! is 720. Find y.   Best way to find n is substitute each of the answer and find out the correct one.   Only option B gave the correct answer.   Option B: 10 and find GCD or 6!, 11! and 12!. 6! itself is 720 and 6! which is contained in the other two factorials. This satisfies the condition, hence answer is 10.   Answer is 10.
<result>B</result>
what is the value of y if the greatest common divisor of (y-4)!,(y+1)!, and (y+2)! is 720.