There are 6 different travelers who each have a choice of vacationing at one of 10 different destinations. What is the probability that all 6 travelers will end up vacationing at the same destination?
Choose the correct answer
A) 0.1	B) 0.001	C) 0.0002	D) 1.0e-05	E) 0.0001
Prob that traveler 1 will choose 1st place(any particular place) out 10 places = 1/10   Prob that traveler 2 will choose same place out 10 places = 1/10   ......   Total = 1/10 * ... 1/10 (6 times)   = 1/10^6   But this can happen for all of the 10 places.   So Prob = 10/(10^6) = 1/10^(6-1)   =0.00001   Answer - 1.0e-05
<result>D</result>
There are 6 different travelers who each have a choice of vacationing at one of 10 different destinations. What is the probability that all 6 travelers will end up vacationing at the same destination?