The arithmetic mean of the set S = {6, K, 5, 11, M, 6} is 7. If K and M are integers, and K ≠ M, what is the median of the numbers in the set?	Select the correct option:
A) 5 B) 5.5 C) 6 D) 6.5 E) 7
The sum of the numbers is 6*7= 
<gadget id="calculator">6*7</gadget>
<output>42</output>
42   K+M= 42 - 11 - 6 - 6 - 5= 
<gadget id="calculator">42 - 11 - 6 - 6 - 5</gadget>
<output>14</output>
14   Since K ≠ M, K and M do not equal 7.   Thus one of the two numbers is 6 or less and one is 8 or more.   Then middle two numbers in the set are 6 and 6.   The median is 6.   The answer is 6.
<result>C</result>
The arithmetic mean of the set S = {6, K, 5, 11, M, 6} is 7. If K and M are integers, and K ≠ M, what is the median of the numbers in the set?