A man buys 100 lts of liquid which contains 25% of the liquid and the rest is water. He then mixes it with 90 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?
Select the correct option.
A) 81 B) 75 C) 72.63 D) 73 E) 76
25% in 100 lts is 25. So water = 100-25= 
<gadget id="calculator">100-25</gadget>
<output>75</output>
75 lts. 30% of 90 lts= 27. So water in 2nd mixture = 90-27= 
<gadget id="calculator">90-27</gadget>
<output>63</output>
63 lts. Now total quantity= 100 + 90= 
<gadget id="calculator">100 + 90</gadget>
<output>190</output>
190 lts. Total water in it will be 75 + 63= 
<gadget id="calculator">75 + 63</gadget>
<output>138</output>
138 lts. % of water= (100*138)/190 = 72.63   ANSWER:72.63
<result>C</result>
A man buys 100 lts of liquid which contains 25% of the liquid and the rest is water. He then mixes it with 90 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?