When x is even, [x] = x/2 + 1, when x is odd [x] = 2x + 1 then [6]*[3] = ?  Select:
A) [22]
B) [44]
C) [45]
D) [28]
E) [10]
[6]*[3]=(6/2+1)(3*2+1)   =[28].   Ans-[28]
<result>D</result>
When x is even, [x] = x/2 + 1, when x is odd [x] = 2x + 1 then [6]*[3] = ?