In a room filled with 6 people, all 6 people have exactly 2 siblings in the room. If two individuals are selected from the room at random, what is the probability that those two individuals are NOT siblings?	Choose the correct option
A) 3/5 B) 3/7 C) 4/7 D) 5/6 E) 7/12
The 6 people consist of two sets of 3 siblings.   The number of ways to choose 2 people is 6C2 = 15.   The number of ways to choose 2 from the first group of siblings is 3C2 = 3.   The number of ways to choose 2 from the second group of siblings is 3C2 = 3.   The number of ways to choose 2 people who are siblings is  3+3= 
<gadget id="calculator"> 3+3</gadget>
<output>6</output>
6.   The number of ways to choose 2 people who are not siblings is   15-6= 
<gadget id="calculator">  15-6</gadget>
<output>9</output>
9.   P(the two people are not siblings)= 9/15 = 3/5   The answer is 3/5.
<result>A</result>
In a room filled with 6 people, all 6 people have exactly 2 siblings in the room. If two individuals are selected from the room at random, what is the probability that those two individuals are NOT siblings?