If n is a natural number, t hen 6n^2 + 6n is always divisible by?
Choose the correct option.
A) 6 only B) 6 and 12 C) 12 only D) 18 only E) 20 only
6n^2 + 6n = 6n(n+1), which is always divisible by 6 and 12 both, since n(n+1) is always even.   Answer is 6 and 12
<result>B</result>
If n is a natural number, t hen 6n^2 + 6n is always divisible by?