The average price of 10 oranges is Rs. 12 while the average price of 8 of these oranges is Rs. 11.75. Of the remaining two oranges, if the price of one orange is 40% more than the price of the other, what is the price of each of these two oranges?	Select the correct option:	A) Rs 5, Rs 7.50	B) Rs 8, Rs 12	C) Rs 10, Rs 16	D) Rs 10.8, Rs 15.2	E) None of these
Explanation :   Total price of the two oranges = Rs. [(12 x 10) (11.75 x 8)]   = Rs. (120 - 94) = Rs. 26.   Let the price of one orange be Rs. x.   Then, the price of other orange = Rs. (x + 40% of x) = Rs. x + x2/5 = Rs. 7x/5   So, x + 7x/5 = 26   12x = 130   x = 10.8   The prices of the two oranges are Rs. 10.8 and Rs. 15.2   Answer : Rs 10.8, Rs 15.2
<result>D</result>
The average price of 10 oranges is Rs. 12 while the average price of 8 of these oranges is Rs. 11.75. Of the remaining two oranges, if the price of one orange is 40% more than the price of the other, what is the price of each of these two oranges?