The ratio between a two-digit number and the sum of the digits of that
number is 4 : 1.If the digit in the unit's place is 3 more than the digit in the ten’s place, what is the number?	Choose the correct option.
A) 18	B) 36	C) 42	D) 24	E) 16
Let the ten's digit be x. Then, unit's digit = (x + 3).   Sum of the digits = x + (x + 3) = 2x + 3. Number   = l0x + (x + 3) = 11x + 3.   11x+3 / 2x + 3 = 4 / 1 =&gt; 11x + 3 = 4 (2x + 3) =&gt; 3x = 9 =&gt; x = 3.   Hence, required number = 11x + 3 = 36.   Answer 36)36.
<result>B</result>
The ratio between a two-digit number and the sum of the digits of that
number is 4 : 1.If the digit in the unit's place is 3 more than the digit in the ten’s place, what is the number?