In how many ways can a group of 15 friends be seated round 2 tables if one of the tables can seat 10 and the other can seat 5 people?	Pick
A) 15C5 * 9! *4!	B) 15C3 * 8! *3!	C) 15C4 * 9! *3!	D) 15C2 * 10! *3!	E) 16C5 * 10! *4!
10 people can be selected from 15 people in 15C10 ways.   Remaining 5 people can be selected from 5 people in 5C5 ways.   Now, arranging 10 people on a round table = (10-1)= 
<gadget id="calculator">(10-1)</gadget>
<output>9</output>
9!   15C5 * 9! *4!rranging 5 people on a round table= (5-1)= 
<gadget id="calculator">(5-1)</gadget>
<output>4</output>
4!   Hence, total number of ways= 15C10 * 9! * 5C5 * 4!   = 15C5 * 9! * 4!   15C5 * 9! *4!NSWER:15C5 * 9! *4!
<result>A</result>
In how many ways can a group of 15 friends be seated round 2 tables if one of the tables can seat 10 and the other can seat 5 people?