There are 10 solid colored balls in a box, including 1 Green and 1 Yellow. If 3 of the balls in the box are chosen at random, without replacement, what is the probability that the 3 balls chosen will include the Green ball but not the yellow ball.
Choose the correct option: A) 1/6 B) 7/30 C) 1/4 D) 3/10 E) 4/15
But we ARE told that there is is only 1 green ball and only 1 yellow ball in the box, becausethere are 10 solid colored balls in a box,including 1 Green and 1 Yellowmeans exactly that. How else?   Would it make ANY sense if there were for example 2 green balls and we were told thatthere are 10 solid colored balls in a box,including 1 Green and 1 Yellow?   Hmm.. yeah, that does make sense. I'm a non-native English speaker so I tend to over-analyze simple things. In this case, since the wordonlywas missing i.e. there are 10 solid colored balls in a box, includingexactly/only1 Green and 1 Yellow . 7/30ut yeah, in retrospect this is a Quant question not a Verbal SCThanks for the explanation answer is 7/30
<result>B</result>
There are 10 solid colored balls in a box, including 1 Green and 1 Yellow. If 3 of the balls in the box are chosen at random, without replacement, what is the probability that the 3 balls chosen will include the Green ball but not the yellow ball.