It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)),
when p=(a+b+c)/2, such that a, b, c are the lengths of sides of the triangle. If the triangle has 300, 300, and 360 as the side’s lengths, what is the triangle’s area? Choose the correct choice from the following answers.
A) 34,200
B) 36,200
C) 43,200
D) 42,200
E) 38,200
It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)),   when p=(a+b+c)/2,   -&gt; P=(300+300+360)/2= 
<gadget id="calculator">(300+300+360)/2</gadget>
<output>480</output>
480, area=√(480(480-300)(480-300)(480-360))=43,200. Therefore, the answer is 43,200.
<result>C</result>
It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)),
when p=(a+b+c)/2, such that a, b, c are the lengths of sides of the triangle. If the triangle has 300, 300, and 360 as the side’s lengths, what is the triangle’s area?