For the given equation x9+5x8−x3+7x+2=0,x9+5x8−x3+7x+2=0, how many maximum real roots are possible?  Choose the correct choice from the following:
A) 3  B) 7  C) 4  D) 0  E) 1
f(x) = x9+5x8−x3+7x+2=0x9+5x8−x3+7x+2=0   In f(x), there are 2 changes of sign. So, there are two positive roots.   f(-x) = - x9+5x8−x3+7x+2=0x9+5x8−x3+7x+2=0   In f(-x), there are 3 changes of sign. So, there are three negative roots.   So, in all there are 5 real roots possible (2 positive and 3 negative) and as degree of the given equation is 9, there are total 9 roots. So, remaining 4 roots will be imaginary.   Answer:4
<result>C</result>
For the given equation x9+5x8−x3+7x+2=0,x9+5x8−x3+7x+2=0, how many maximum real roots are possible?