Two painters 'P1' & 'P2' paint the bungalow in 3 days. If P1 alone can paint the bungalow in 12 days, in how many days can 'P2'' alone complete the same paint work?
Choose the correct choice from the following choices:
A) 4 days  B) 6 days  C) 9 days  D) 12 days  E) 15 days
EXPLANATION:   Hint:   If a person can do a part of work in 'n' days, then person's work in 1 day =	1/n   As painters P1 &amp; P2 paint the bungalows in 3 days, then work done by both painters =	1/3   As P1 paint it alone in 12 days, then work done by painter P1 =	1/12   Work done by painter P2 =	1/3	–	1/12	=	4 – 1/12	=	3/12	=	1/4   Therefore, same work will be completed by painter P2 in 4 days.   4 daysNSWER IS 4 days
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Two painters 'P1' & 'P2' paint the bungalow in 3 days. If P1 alone can paint the bungalow in 12 days, in how many days can 'P2'' alone complete the same paint work?