If xy ≠ 0 and x^2y^2 − 2xy = 8, which of the following could be y in terms of x?
I. 4/x
II. -x/2
III. 3/x Choose the correct choice.
A) I only	B) II only	C) I and II	D) I and III	E) II and III
(x^2)(y^2) – 2xy - 8 = 0   (xy – 4)(xy + 2) = 0   xy – 4 = 0 or xy + 2 = 0   xy = 4 or xy = -2   Since we need y in terms of x, we can isolate y in both of our equations.   y = 4/x or y = -2/x   I onlynswer: I only
<result>A</result>
If xy ≠ 0 and x^2y^2 − 2xy = 8, which of the following could be y in terms of x?
I. 4/x
II. -x/2
III. 3/x