Two positive integers differ by 4, and sum of their reciprocals is 5 Then one of the numbers is	Pick one.
A) a) 3	B) b) 1	C) c) 5	D) d) 21	E) 4
Algebraic approach:   Let n be the smaller integer =&gt; 1/n + 1/(n+4) = 5   or ((n+4)+n)/n(n+4) =6 or (n^2+4n)*5 =2n+4 or n=2 as n cannot be -negative   Solve for n =&gt; n=4. Hence,   4
<result>E</result>
Two positive integers differ by 4, and sum of their reciprocals is 5 Then one of the numbers is