The positive number z is divisible by 4. What is the remainder of dividing z(2+4+z)+3 by 2?
Select:
A) 0 B) 1 C) 2 D) 3 E) 4
When we solve any of these equations: 28+3 (z=4) or 56+3 (z=8) we end up with numbers to which we have to subtract 1 to end up with a number that is exactly divisible by 2. This is why we know that every result we get is going to have 1 as a remainder. Hence answer is 1.
<result>B</result>
The positive number z is divisible by 4. What is the remainder of dividing z(2+4+z)+3 by 2?