How many pounds of salt at 80 cents/lb must be mixed with 40 lbs of salt that costs 35 cents/lb so that a merchant will get 20% profit by selling the mixture at 48 cents/lb? Options.
A) 5
B) 15
C) 40
D) 50
E) 25
Selling price is 48 cents/lb   For a 20% profit, cost price should be 40 cents/lb (CP*6/5 = 48)   Basically, you need to mix 35 cents/lb (Salt 1) with 80 cents/lb (Salt 2) to get a mixture costing 40 cents/lb (Salt Avg)   weight of Salt1/weight of Salt2 = (Salt2 - SaltAvg)/(SaltAvg - Salt1) = (80 - 40)/(40 - 35)= 
<gadget id="calculator">(80 - 40)/(40 - 35)</gadget>
<output>8</output>
8/1   We know that weight of salt 1 is 40 lbs. Weight of salt 2 must be 5 lbs.   5nswer (5)
<result>A</result>
How many pounds of salt at 80 cents/lb must be mixed with 40 lbs of salt that costs 35 cents/lb so that a merchant will get 20% profit by selling the mixture at 48 cents/lb?