If there are 6 pairs of twins, and a committee will be formed with 3 members. In how many ways this committee formed in a way that no siblings in a group? Options
A) 32	B) 24	C) 56	D) 144	E) 160
Firstly, there are 6 ways to choose 3 groups from the 4 groups. Hence 6C3.   Next, with the 3 groups chosen, there are 2^3 choices of choosing either one of the siblings.   Hence, the total number of ways are 6C3 * (2^3) = 160   160
<result>E</result>
If there are 6 pairs of twins, and a committee will be formed with 3 members. In how many ways this committee formed in a way that no siblings in a group?