Two dogsled teams raced across a 300-mile course in Wyoming. Team A finished the course in 3 fewer hours than did team B. If team A’s average speed was 5 miles per hour greater than that of team B, what was team B’s average speed, in miles per hour?
Choose the correct choice from the following.
A) 12  B) 15  C) 18  D) 20  E) 25
Speed of B= S   Speed of A= S+5   Time taken by B=300/S Time Taken by A= 300/(S+5)   Difference in their time is 3 hrs.   300/S - 3 = 300/(S+5)   Plug in the values from the option   No need of choosing 12 &amp; 18 it won't satisfy   a) if we take 15 then   T(B) = 300/15= 
<gadget id="calculator">300/15</gadget>
<output>20</output>
20   T(A)= 300/20= 
<gadget id="calculator">300/20</gadget>
<output>15</output>
15. Hence from this option difference comes out to be 5 which is not correct   b) if we take 20 then   T(B)= 300/20= 
<gadget id="calculator">300/20</gadget>
<output>15</output>
15   T(A)= 300/25= 
<gadget id="calculator">300/25</gadget>
<output>12</output>
12   20ifference in timing is 3 hence Option 20 is correct
<result>D</result>
Two dogsled teams raced across a 300-mile course in Wyoming. Team A finished the course in 3 fewer hours than did team B. If team A’s average speed was 5 miles per hour greater than that of team B, what was team B’s average speed, in miles per hour?