Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old his son. Then the sum of the present ages of the son and the father is:	Pick: A) 108 B) 75 C) 80 D) 110 E) 101
Let the present ages of the father and son be 2x and x years respectively.   Then, (2x - 18) = 3(x - 18) =&gt; x = 36   Required sum = (2x + x) = 108 years.   108NSWER 108
<result>A</result>
Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old his son. Then the sum of the present ages of the son and the father is: