A bag contains 50 tickets numbered 1,2,3,4......50 of which five are drawn at random and arranged in ascending order of magnitude.Find the probability that third drawn ticket is equal to 30.	Choose the correct choice:
A) 551/15134
B) 551/15139
C) 551/15132
D) 551/15196
E) 551/15766
Explanation:   Total number of elementary events = \inline {\color{Black}50C_{5}}   Given,third ticket =30   =&gt; first and second should come from tickets numbered 1 to 29 = \inline {\color{Black}29C_{2}} ways and remaining two in \inline {\color{Black}20C_{2}} ways.   Therfore,favourable number of events = \inline {\color{Black}29C_{2}\times 20C_{2}}   Hence,required probability = \inline {\color{Blue}(29C_{2}\times 20C_{2})/50C_{5}} =551 / 15134   551/15134nswer: 551/15134) 551/15134
<result>A</result>
A bag contains 50 tickets numbered 1,2,3,4......50 of which five are drawn at random and arranged in ascending order of magnitude.Find the probability that third drawn ticket is equal to 30.