Lorna invests $8000, with some at 6% annual interest and some at 11% annual interest. If she receives a total of $580 from these investments at the end of a year, how much was invested at the 6% interest rate? Choose the correct choice:
A) $160	B) $1,700	C) $2,200	D) $4,400	E) $5,840
We have that 'x' invested at 6%   We also have that '8000-x' invested at 11%   Now then 580/8000 is approx 10%   Therefore, -4x+8000-x=0   5x=8000   x=1600 approximately. Probably higher   Only $1,700 matches
<result>B</result>
Lorna invests $8000, with some at 6% annual interest and some at 11% annual interest. If she receives a total of $580 from these investments at the end of a year, how much was invested at the 6% interest rate?