The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages.	Choices:
A) 20, 35, 55	B) 16, 28, 36	C) 20, 35, 45	D) None of these	E) 20, 15, 45
Answer: Option B   Let their present ages be 4x, 7x and 9x years respectively.   Then, (4x - 8) + (7x - 8) + (9x - 8) = 56   20x = 80 =&gt; x = 4   Their present ages are 16, 28 and 36 years respectively.
<result>B</result>
The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages.