If X is to be chosen at random from the integers between 1 to 7, inclusive, and Y is to be chosen at random from the integers between 8 and 12, inclusive, what is the probability that X + Y will be even?	Choose the correct choice from the following answers:
A) 2/5  B) 3/7  C) 5/7  D) 17/35  E) 24/35
X+Y will be even if X and Y are both even or both odd.   P(X and Y are both even) = 3/7*3/5 = 9/35   P(X and Y are both odd) = 4/7*2/5 = 8/35   P(X+Y is even) = 9/35 + 8/35 = 17/35   The answer is 17/35.
<result>D</result>
If X is to be chosen at random from the integers between 1 to 7, inclusive, and Y is to be chosen at random from the integers between 8 and 12, inclusive, what is the probability that X + Y will be even?