A meeting has to be conducted with 4 managers. Find the number of ways in which the managers may be selected from among 7 managers, if there are 2 managers who refuse to attend the meeting together.	Select: A) 18 B) 21 C) 25 D) 30 E) 35
The total number of ways to choose 4 managers is 7C4 = 35   We need to subtract the number of groups which include the two managers, which is 5C2 = 10.   35 - 10= 
<gadget id="calculator">35 - 10</gadget>
<output>25</output>
25   The answer is 25.
<result>C</result>
A meeting has to be conducted with 4 managers. Find the number of ways in which the managers may be selected from among 7 managers, if there are 2 managers who refuse to attend the meeting together.