A person can walk at a constant rate of 8mph and can bike at a rate of 32mph. If he wants to travel 80 miles in 4 hours using bike and walking at their constant rates, how much distance would he require to walk? Pick
A) 20 B) 30 C) 48 D) 60 E) 72
Total distance = 80   Distance = Speed * Time   Walking speed = s1 = 8   Walking time = t1   Bike speed = s2 = 32   Time traveled in bike = t2   d1 + d2 = 80   s1t1 + s2t2 = 80   8*t1 + 32*t2 = 80   t1 + 4*t2 = 10 ----- (1)   Given: t1 + t2 =4 ----- (2)   (1) - (2) --&gt;3 t2 = 6 , t2=2 and t1 = 8 - 2= 
<gadget id="calculator">8 - 2</gadget>
<output>6</output>
6   Walking distance= s1*t1 = 8*6= 
<gadget id="calculator">8*6</gadget>
<output>48</output>
48   Answer: 48
<result>C</result>
A person can walk at a constant rate of 8mph and can bike at a rate of 32mph. If he wants to travel 80 miles in 4 hours using bike and walking at their constant rates, how much distance would he require to walk?