A basketball player succeeds with 60% of her free throws. If she has a set of three free throws, what is the probability that she succeeds at least once?
Answers.
A) 0.856	B) 0.872	C) 0.936	D) 0.952	E) 0.985
P(missing all 3 free throws) = 0.4^3 = 0.064   P(succeeding at least once) = 1 - 0.064= 
<gadget id="calculator">1 - 0.064</gadget>
<output>0.936</output>
0.936   The answer is 0.936.
<result>C</result>
A basketball player succeeds with 60% of her free throws. If she has a set of three free throws, what is the probability that she succeeds at least once?