In the number 11,0AB, A and B represent the tens and units digits, respectively. If 11,0AB is divisible by 55, what is the greatest possible value of B × A?
Select the correct option.
A) 0 B) 5 C) 10 D) 15 E) 25
You should notice that 55*2= 
<gadget id="calculator">55*2</gadget>
<output>110</output>
110 so 11,000 is divisible by 55: 55*200=11,000 (or you can notice that 11,000 is obviously divisible by both 5 and 11 so by 55) --&gt; B*A=0*0= 
<gadget id="calculator">0*0</gadget>
<output>0</output>
0.   Next number divisible by 55 is 11,000+55=11,055: B*A=5*5= 
<gadget id="calculator">5*5</gadget>
<output>25</output>
25 (next number won't have 110 as the first 3 digits so we have only two options 0 and 25).   Answer: 25
<result>E</result>
In the number 11,0AB, A and B represent the tens and units digits, respectively. If 11,0AB is divisible by 55, what is the greatest possible value of B × A?