4 people are sitting in a 4 seat row watching a football game. At halftime they all get up. When they return, they each randomly sit down on one of the 5 chairs. What is the likelihood that none of the 4 end up sitting in the same chair that they sat in during the first half?	Choose the correct choice from the following
A) 3/24
B) 3/4
C) 15/24
D) 18/24
E) 21/24
Originally seated A B C D   now when after they get up and when they sit back again .   1st- A has option to sit on 3 seats ( apart from his previous seat . thus he now sits on B's seat.)   2nd- Similarly B has option to sit on 3 seats ( because A has already occupied B's previous seat, thus B sits on a's seat.)   3rd- Now C has only 1 option to sit on D's seat . and similarly D also has one option to sit on C's seat.)   hence total favourable outcomes   3*3*2*1*1= 
<gadget id="calculator">  3*3*2*1*1</gadget>
<output>18</output>
18   and total possible outcomes=4!=24   probability of the favourable outcome= 3/4. 3/4
<result>B</result>
4 people are sitting in a 4 seat row watching a football game. At halftime they all get up. When they return, they each randomly sit down on one of the 5 chairs. What is the likelihood that none of the 4 end up sitting in the same chair that they sat in during the first half?