If the perimeter of a rhombus is 52 cm and one of its
diagonals is 24 cm, then the area of the rhombus is	Choose the correct choice from the following answers.
A) 100 sq.cm
B) 110 sq.cm
C) 120 sq.cm
D) 130 sq.cm
E) 140 sq.cm
perimeter of rhombus = 4a (with side a)   4a=52 then a=13,   lets length of one diagonal p=24cm,   lenght of other diagonal is q;   area of rhombus = pq/2   using pythogorus theorem a^2= (p/2)^2 + (q/2)^2   we will get q=10.   then area=10*24/2= 
<gadget id="calculator">10*24/2</gadget>
<output>120</output>
120 sq.cm   ANSWER:120 sq.cm
<result>C</result>
If the perimeter of a rhombus is 52 cm and one of its
diagonals is 24 cm, then the area of the rhombus is