John & Mary go for an interview for 2 vacancies. The probability for the selection of John is 1/3 & whereas the probability forthe selection of Mary is 1/5. What is the probabilitynone of them are selected?	Pick one.
A) 2/11 B) 3/14 C) 8/15 D) 7/13 E) 8/11
Let A = the event that John is selected and B = the event that Dani is selected.   Given that P(A) = 1/3 and P(B) = 1/5   We know that A¯ is the event that A does not occur and B¯ is the event that B does not occur   Probability that none of them are selected   =P(A¯∩B¯)(∵ Reference : Algebra of Events)   =P(A¯).P(B¯) (∵ Here A and B are Independent Events and refer theorem on independent events)   =[ 1 - P(A) ][ 1 - P(B)]   =(1−13)(1−15)   =23×45=8/15   8/15
<result>C</result>
John & Mary go for an interview for 2 vacancies. The probability for the selection of John is 1/3 & whereas the probability forthe selection of Mary is 1/5. What is the probabilitynone of them are selected?