Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 40 percent ryegrass, what percent of the weight of this mixture is X ?  Choose one
A) 100%  B) 33.33 %  C) 40%  D) 50%  E) 66.66 %
----------------&gt;Ryegrass   X--------------&gt;	40%   Y--------------&gt;	25%   M(mixture)----&gt;40%   0.4X + (M-X)0.25 = 0.4M   0.15X = 0.15M   X = 1M   X = 100% of M   100%
<result>A</result>
Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 40 percent ryegrass, what percent of the weight of this mixture is X ?