What is the lowest possible common multiple M of 2 distinct integers, each greater than 329? Answers: A) 330·331 B) 330^2 C) 33·331 D) 660 E) 330
Lowest possible common multiple M of 2 distinct integers will have to be multiple of the number greater than 329...which 330..   so one number will be 330...another one will be 660..   Ans is 660.
<result>D</result>
What is the lowest possible common multiple M of 2 distinct integers, each greater than 329?