Two same class students appeared at an examination. One of them secured 9 marks more than the other and her marks was 56% of the sum of their marks. What are the marks obtained by them? Options.
A) 45,30
B) 42,33
C) 50,40
D) 55,45
E) 30,40
the marks secured by x =&gt; (x + 9)   Then sum of their = x + (x + 9) = 2x + 9   that (x + 9) was 56% of the sum of marks   =&gt;(x+9) = 56/100(2x+9)   =&gt;(x+9) = 14/25(2x+9)   =&gt; 25x + 225 = 28x + 126   =&gt; x = 33   =&gt; (x + 9) = 33 + 9= 
<gadget id="calculator">33 + 9</gadget>
<output>42</output>
42   -&gt;marks are 33 and 42   ANSWER 42,33
<result>B</result>
Two same class students appeared at an examination. One of them secured 9 marks more than the other and her marks was 56% of the sum of their marks. What are the marks obtained by them?