Of the families in City X in 1992, 30 percent owned a personal computer. The number of families in City X owning a computer in 1999 was 50 percent greater than it was in 1992, and the total number of families in City X was 5 percent greater in 1999 than it was in 1994. what percent of the families in City X owned a personal computer in 1999?  Choose one
A) 43%	B) 42.85%	C) 45.25%	D) 46.23%	E) 41.66%
Say a 100 families existed in 1992 then the number of families owning a computer in 1992 - 30   Number of families owning computer in 1999 = 30 * 150/100= 
<gadget id="calculator">30 * 150/100</gadget>
<output>45</output>
45   Number of families in 1999= 105   The percentage = 45/105 * 100 = 42.85%.   ANSWER:42.85%
<result>B</result>
Of the families in City X in 1992, 30 percent owned a personal computer. The number of families in City X owning a computer in 1999 was 50 percent greater than it was in 1992, and the total number of families in City X was 5 percent greater in 1999 than it was in 1994. what percent of the families in City X owned a personal computer in 1999?