Four different children have jelly beans: Aaron has 3, Bianca has 7, Callie has 8, and Dante has 11. How many jelly beans must Dante give to Aaron to ensure that no child has more than 1 fewer jelly beans than any other child?	Pick one:
A) 2	B) 3	C) 4	D) 5	E) 6
Since Bianca and Callie are both within 1 jelly bean of each other and Aaron has 5, Dante must provide 3 of his 11 jelly beans so each child has no more than 1 fewer jelly bean than any other child.   Dante + Aaron = 11+3= 
<gadget id="calculator">11+3</gadget>
<output>14</output>
14/2= 
<gadget id="calculator">14/2</gadget>
<output>7</output>
7   11-7= 
<gadget id="calculator">11-7</gadget>
<output>4</output>
4 so Dante must provide 3 jelly beans to Aaron.   Answer (4)
<result>C</result>
Four different children have jelly beans: Aaron has 3, Bianca has 7, Callie has 8, and Dante has 11. How many jelly beans must Dante give to Aaron to ensure that no child has more than 1 fewer jelly beans than any other child?