In a simultaneous throw of 2 dice, what is the probability of not getting a doublet?  Answers.
A) 2/3
B) 1/6
C) 4/7
D) 5/6
E) 4/9
n(S) = 6*6= 
<gadget id="calculator">6*6</gadget>
<output>36</output>
36   E= event of not getting a doublet = 36- event of getting a doublet= 36-6= 
<gadget id="calculator">36-6</gadget>
<output>30</output>
30   {(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}   Probability= 30/36 = 5/6   Answer is 5/6
<result>D</result>
In a simultaneous throw of 2 dice, what is the probability of not getting a doublet?