Of the 60 electronics components that a factory must manufacture, 80 percent would be most e¢ ciently manufactured by Machine A and the remaining 20 percent would be most efficiently manufactured by Machine B, though either machine could manufacture any of the 60 components. If 40 percent of the components were manufactured by Machine A and the remainder were manufactured by Machine B, what is thehighest possible number of components that were manufactured by the machine that would manufacture them the most efficiently? Choose the correct choice from the following answers
A) 30  B) 32  C) 33  D) 35  E) 36
A can manufacture 80 % of 60 efficiently, which is 48.   B can manufacure 20 % of 60 efficiently, which is 12.   Now 40 % of 60 are produced by A. This means 24 parts. Since A can produce 48 efficiently, all 24 are produced efficiently. Rest (36) is produced by B, which can produce max. 12 parts efficiently.   Hence parts that were produced efficiently = 12+24= 
<gadget id="calculator">12+24</gadget>
<output>36</output>
36. (36).
<result>E</result>
Of the 60 electronics components that a factory must manufacture, 80 percent would be most e¢ ciently manufactured by Machine A and the remaining 20 percent would be most efficiently manufactured by Machine B, though either machine could manufacture any of the 60 components. If 40 percent of the components were manufactured by Machine A and the remainder were manufactured by Machine B, what is thehighest possible number of components that were manufactured by the machine that would manufacture them the most efficiently?