In a box of 12 pens, a total of 3 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?
Select the correct option
A) 1/6	B) 2/9	C) 6/11	D) 9/16	E) 3/4
# defective pens = 3   # good pens = 9   Probability of the 1st pen being good = # of favorable outcomes / # of total outcomes = 9/12   Probability of the 2nd pen being good = # of remaining favorable outcomes / # of total remaining outcomes = 8 / 11   Total probability = 9/12 * 8/11 = 6/11   answer will be 6/11
<result>C</result>
In a box of 12 pens, a total of 3 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?