David decides to attend a base ball game with four friends. If the party of five sits together in five consecutive seats, and David must NOT sit in between two of his friends, how many ways can the five friends be arranged?	Choose the correct choice: A) 12 B) 24 C) 36 D) 6 E) 48
David have to sit at either of the ends.   If David sits on the left most corner, then other 5 friends can be arranged in 4! = 24   David can also sit on the other end, then another 4! ways we can arrange.   So total number of ways = 24+24= 
<gadget id="calculator">24+24</gadget>
<output>48</output>
48   Answer : 48
<result>E</result>
David decides to attend a base ball game with four friends. If the party of five sits together in five consecutive seats, and David must NOT sit in between two of his friends, how many ways can the five friends be arranged?