Consider the sequence of numbers beginning 23, 27, 28, 32, 33... It continues in such a way that by adding 5 to the nth term, one obtains the (n + 2)th term. What is the sum of the first 14 members of this sequence?
Choose the correct choice from the following options:
A) 878  B) 900  C) 560  D) 928  E) 1022
I would split them up like this.   23 28 33 and so on (7 terms)....the 7th term = 23+6*5= 
<gadget id="calculator">23+6*5</gadget>
<output>53</output>
53   27 32 37 and so on (7 terms)......the 7th term= 27+6*5= 
<gadget id="calculator">27+6*5</gadget>
<output>57</output>
57   Since the distance between any two numbers is the same we can use arithmetics   first+last/2 times no of numbers= the sum   (23+53)/2 * 7= 
<gadget id="calculator">(23+53)/2 * 7</gadget>
<output>266</output>
266   (27+57)/2 * 7= 
<gadget id="calculator">(27+57)/2 * 7</gadget>
<output>294</output>
294= 560   560
<result>C</result>
Consider the sequence of numbers beginning 23, 27, 28, 32, 33... It continues in such a way that by adding 5 to the nth term, one obtains the (n + 2)th term. What is the sum of the first 14 members of this sequence?