Jim takes a seconds to swim t meters at a constant rate from point M to point N in a pool. Roger, who is faster than Jim, can swim the same distance in b seconds at a constant rate. If Jim leaves point M the same time that Roger leaves point N, how many fewer meters will Jim have swum than Roger when the two swimmers pass each other?	Choose the correct choice from the following answers:
A) c(b-a)/ a+b
B) c(a-b)/a+b
C) c(a+b)/a-b
D) t(a-b)/a+b
E) ab(b-a)/a+b
Both JimRoger are travelling at constant speedin opposite direction:   So, speed of Jim =t /a speed of Roger = t/b   Let say Jim travelled distance x from M where it met Roger, it means that Roger travelled (t-x) from point N   [x would be less than (t-x) as Jim is travelling slow]   From above, time taken by Jim to travel x = xa/t....................... (1)   Also, time taken by Roger to travel (t-x) = (t-x)b/t.....................(2)   Time taken by both JimRoger is same, so (1) = (2)   xa/t = (t-x)b/t,   Solving further, x = bt/(a+b).................... (3)   We require to find how many fewer meters will Jim have swum i.e   additional distance travelled by Roger = (t - x) - x   = t-2x   Substituting value of x from (3)solving the equation further, we get Answer = t(a-b)/a+b   Answer = (t(a-b)/a+b)
<result>D</result>
Jim takes a seconds to swim t meters at a constant rate from point M to point N in a pool. Roger, who is faster than Jim, can swim the same distance in b seconds at a constant rate. If Jim leaves point M the same time that Roger leaves point N, how many fewer meters will Jim have swum than Roger when the two swimmers pass each other?