Lines y=√2·x+2 and y=3√2·x−1 intersect at what height above the x axis? Choose the correct choice from the following answers: A) (13√2)/2 B) 13/2 C) 13 D) 2 E) 0
Solve two equations for y   y=√2·x+2   y=3√2·x−1   Set the two equations equal to each other and solve for x   √2·x+2 = 3√2·x−1   3 = 2√2·x   3/(2√2) = x   Plug x = 3/(2√2) into any one of the original equations to find the y value (height above x axis) where the two lines intersect   y=√2·x+2   y=√2·(3/(2√2))+2   y = 3/2 + 5   y = 3/2 + 10/2   y = 13/2   Final answer:   13/2) 13/2
<result>B</result>
Lines y=√2·x+2 and y=3√2·x−1 intersect at what height above the x axis?