Mother is aged 3times more than her daughter Rose. After 8 years, she would be two and a 1/2times of Rose's age. After further 8 years, how many times would he be of Rose's age?  Options:
A) 1
B) 2
C) 4
D) 5
E) 6
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.   (4x + 8) = 5 (x + 8)   2   8x + 16 = 5x + 40   3x = 24   x = 8.   Hence, required ratio = (4x + 16)/(x + 16) = 48/24= 
<gadget id="calculator">48/24</gadget>
<output>2</output>
2.   2
<result>B</result>
Mother is aged 3times more than her daughter Rose. After 8 years, she would be two and a 1/2times of Rose's age. After further 8 years, how many times would he be of Rose's age?