In a box, there are 4 blue, 6 white and 5 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?  Choose one:  A) 3/16  B) 5/15  C) 8/32  D) 2/32  E) 9/32
Total number of bulbs = (4 + 6 + 5)= 
<gadget id="calculator">(4 + 6 + 5)</gadget>
<output>15</output>
15.   Let E= event that the bulb drawn is neither white nor blue = event that the bulb drawn is yellow.   Therefore, P(E)=5/15   ANSWER:5/15
<result>B</result>
In a box, there are 4 blue, 6 white and 5 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?