The number of arrangement of letters of the word BANANA in which the two N's do not appear adjacently is:	Choose the correct choice from the following answers:
A) 40
B) 50
C) . 60
D) 80
E) 100
Total # of arrangements of BANANA is 6!/(3!2!) = 60 (arrangement of 6 letters {B}, {A}, {N}, {A}, {N}, {A}, where 3 A's and 2 N's are identical).   The # of arrangements in which the two N's ARE together is 5!/3!=20 (arrangement of 5 units letters {B}, {A}, {A}, {A}, {NN}, where 3 A's are identical)..   The # of arrangements in which the two N's do not appear adjacently is {total} - {restriction} = 60 - 20= 
<gadget id="calculator">60 - 20</gadget>
<output>40</output>
40.   40nswer: 40.
<result>A</result>
The number of arrangement of letters of the word BANANA in which the two N's do not appear adjacently is: