A meeting has to be conducted with 5 managers. Find the number of ways in which the managers be selected from among 8 managers, if 2 managers will not attend the meeting together?	Choose the most appropriate option.
A) 40	B) 36	C) 42	D) 45	E) 47
we can either choose all 5 people from 6 manager who have no problems or choose 4 from the 6 and 1 from the 2 managers who have a problem sitting together   so 6C5 + (6C4 * 2C1)   this is   6 + 30= 
<gadget id="calculator">  6 + 30</gadget>
<output>36</output>
36   Answer : 36
<result>B</result>
A meeting has to be conducted with 5 managers. Find the number of ways in which the managers be selected from among 8 managers, if 2 managers will not attend the meeting together?