Karen places a bet with Tom that she will beat Tom in a car race by 4 miles even if Karen starts 4 minutes late. Assuming that Karen drives at an average speed of 60 mph and Tom drives at an average speed of 45 mph, how many Y miles will Tom drive before Karen wins the bet?  Choose the correct answer:
A) 15
B) 18
C) 21
D) 24
E) 27
Let K and T be the speeds of Karen and Tom respectively.   t be the time that Karen will travel ----&gt; t+4/60 will be the total time Tom will travel by the time the distance between Karen and Tom is 4 miles.   Thus, per the question , K(t) - T(t+4/60) = 4 ---&gt; t = 7/15 hours   Thus the distance traveled by Tom when Karen is 4 miles ahead of him Y: T*(t+4/60) = 45 (7/15+4/60) = 24 miles. 24 is the correct answer.
<result>D</result>
Karen places a bet with Tom that she will beat Tom in a car race by 4 miles even if Karen starts 4 minutes late. Assuming that Karen drives at an average speed of 60 mph and Tom drives at an average speed of 45 mph, how many Y miles will Tom drive before Karen wins the bet?