A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 33 times, A has killed:  Options
A) 60 birds B) 72 birds C) 37 birds D) 80 birds E) 20 birds
Let the total number of shots be x. Then,   Shots fired by A =(5/8)x   Shots fired by B =(3/8)x   Killing shots by A =(1/3)of	(5/8)x=(5/24)x   Shots missed by B =(1/2) of (3/8)x	=(3/16)x   3x/16= 33 or x =(33 x 16)/3= 176.   Birds killed by A =(5x/24)	=(5/24*176)= 37.   Answer is 37 birds.
<result>C</result>
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 33 times, A has killed: