There are 4 girls and 4 boys. If they are to be seated in a row, what is the probability that no two girls sit together? Choose the correct choice from the following answers.
A) A)1/8!  B) B)6!5!/8!  C) C)2*4!4!/8!  D) D)2∗6!6!/12!  E) E)6!7!/12!
If girls are alternate, then only no 2 girls can be together.   So among 8 places, girls can be seated in 4 alternate places in 4! ways.   And boys can be seated in the remaining 4 places in 4! ways.   Therefore total number of ways = 4! * 4!   But there could be 2 such arrangements--&gt;   1. When first place is filled by a girl   2. When first place is filled by a boy   Therefore total number of ways = 2*4! * 4!   Also total number of ways to fill 8 places = 8!   Hence probability =2∗4!4!/8!   Answer:2*4!4!/8!
<result>C</result>
There are 4 girls and 4 boys. If they are to be seated in a row, what is the probability that no two girls sit together?