Find the number of trailing zeros in the product of (1^1)*(5^5)*(10^10)*(15^15) *(20^20)*(25^25)………. *(50^50).	Select:  A) 150  B) 200  C) 250  D) 245  E) 225
Looking at the numbers it looks like   (1x5)^5   (2x5)^10   ...   (10x5)^50   1. Determine the limiting factor. Is it 2 or is it 5? We know that all the numbers are multiple of 5 but not of 2. Thus, the limiting factor in this case is 2. Let's drop all the 5. Then, we count factors of 2 of even multiples.   2^10 = 10   4^20 = 20 + 20   6^30 = 30   8^40 = 40 + 40 + 40   10^50 = 50   250   Answer: 250
<result>C</result>
Find the number of trailing zeros in the product of (1^1)*(5^5)*(10^10)*(15^15) *(20^20)*(25^25)………. *(50^50).