An alchemist discovered that the formula expressing the correct proportions needed to turn ordinary metal into gold is G = 3/2M + 25, where G is the number of gold bars and M is the number of metal bars. If a metal bar weighs twice as much as a gold bar, how many metal bars will yield an equal weight of gold?  Options: A) a.	A - 10 B) b.	B - 15 C) c.	C – 22.5 D) d.	D – 30 E) e.	E – 67.5
A --- 30/2 + 15 = 40 --- wrong   B --- 45/2 + 15 = not an integer --- wrong   C --- 22.5(3/2) + 15 = not an integer --- wrong   D --- 90/2+15 = 70 --- CORRECT   This is one of those problems that will probably be easiest to solve by plugging in numbers. The algebra is do-able, but it's not worth the effort (in my opinion). I was able to solve it in under 30 seconds total with this method.   a.	A - 10
<result>A</result>
An alchemist discovered that the formula expressing the correct proportions needed to turn ordinary metal into gold is G = 3/2M + 25, where G is the number of gold bars and M is the number of metal bars. If a metal bar weighs twice as much as a gold bar, how many metal bars will yield an equal weight of gold?