How many X ways can you group 3 people from 4 sets of twins if no two people from the same set of twins can be chosen? Choose one:
A) 3
B) 16
C) 28
D) 32
E) 56
Ways to select 3 people from 8 people (4 twins x 2) = 8C3 = 56   Ways to select 1 twin + 1 people = 4C1*6C1 = 24   Ways to select a group 3 people from 4 sets of twins if no two people from the same set of twins can be chosen X= 56 - 24= 
<gadget id="calculator">56 - 24</gadget>
<output>32</output>
32   Ans: 32
<result>D</result>
How many X ways can you group 3 people from 4 sets of twins if no two people from the same set of twins can be chosen?