If 22^n is a divisor of 97!+98! ,what is the maximum possible value of integer n?	Choices:
A) 8 B) 9 C) 10 D) 11 E) 12
22^n means power of 11 as 2 would surely have more power than 11 in a factorial..   97!+98!=97!(1+98)=97!*99....   99 will have ONE 11 and 97! will have 97/11 or 8..   Total 1+8= 
<gadget id="calculator">1+8</gadget>
<output>9</output>
9   ANSWER:9
<result>B</result>
If 22^n is a divisor of 97!+98! ,what is the maximum possible value of integer n?