If (x^2 + 1)y=4, which of the following is not a possible value for y? Choose the correct answer: A) 3/2 B) 2 C) 4/3 D) 4 E) 9/2
Its simple   equation is (x^2 +1)y = 4 ===&gt; x^2 = (4/y) - 1 . As , in LHS, it is x^2 the value has to be positive or zero in RHS.   Hence, (4/y) - 1&gt;= 0 ===&gt; y =&lt; 4. Now only option E has greater value of 'y' than 4.   Thus, correct ans is 9/2
<result>E</result>
If (x^2 + 1)y=4, which of the following is not a possible value for y?