It is given that 2^32 + 1 is exactly divisible by a certain number. Which one of the following is also divisible by the same number X?
Select:	A) a. 2^96 + 1	B) b. 2^16 - 1	C) c. 2^16 + 1	D) d. 7 * 2^33	E) e. 2^64 + 1
a³ + b³ =(a+b)(a² -ab +b²)   Now, let (2^32 + 1) be (a+b)   a³ + b³ = (2^96 + 1)   Now, as mentioned in formula above,   a³ + b³ is always divisible by (a+b)   So any factor of X=(a+b) is a factor of (a³ + b³)   Henca a. 2^96 + 1
<result>A</result>
It is given that 2^32 + 1 is exactly divisible by a certain number. Which one of the following is also divisible by the same number X?