In how many different number of ways a combination of 3 men and 2 women can be selected from 6 men and 5 women?	Choose the correct choice from the following answers
A) 18  B) 20  C) 22  D) 24  E) 26
6C3   = 6!/(3! . 3!)   = (6 × 5 × 4)/(3 × 2)   = 5 × 4 = 20.   20)
<result>B</result>
In how many different number of ways a combination of 3 men and 2 women can be selected from 6 men and 5 women?