Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 2/3 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?
Choose one:
A) 1/16  B) 7/8  C) 9/64  D) 5/64  E) 3/64
P(Xavier will solve)=1/4   P(Yvonne will solve)=2/3   P(Zelda will NOT solve) = 1- 5/8 = 3/8.   Now, we need to multiply all this Ps to find an answer:   p= (1/4)*(2/3)*(3/8) = 1/16.   Ans. 1/16.
<result>A</result>
Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 2/3 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?