Integer d is the product of the integers a,b, and c and 1<a<b<c. If the remainder when 233 is divided by d is 79, what is the value of a+c?	Choose the correct option:
A) 7	B) 9	C) 13	D) 14	E) 18
79 is the remainder, therefore the number(a*b*c) or multiple of the number we need is 79 less than 233   Hence 233- 79= 
<gadget id="calculator">233- 79</gadget>
<output>154</output>
154   Therefore, 154 is either a number we want or it is a multiple of the number we want   But the largest factor of 154 is 77 because 77 * 2= 
<gadget id="calculator">77 * 2</gadget>
<output>154</output>
154   But 77 is less than 79 hence it can not be a number   Thus 154 is the number we want   a*b*c= 154   now factorize 154 =1*2*7*11 all are prime   Also we know 1&lt;a&lt;b&lt;c   thus a = 2 and c = 11   therefore a+c= 2+11= 
<gadget id="calculator">2+11</gadget>
<output>13</output>
13   ANSWER:13
<result>C</result>
Integer d is the product of the integers a,b, and c and 1<a<b<c. If the remainder when 233 is divided by d is 79, what is the value of a+c?