2 identical circles intersect so that their centre and point at which they intersect form a square of 1 cm.the area of portion that is common two circles is
4 Choose the correct option.
A) π2-1	B) 4	C) √2-1	D) √5	E) π/2-1
the area of the sector is pi*r^2*90/360 (as it is a square, so the angle is 90)   =pi*r^2/4   =pi/4 (as the area of the square is 1cm^2, so the sides are 1 cm each. the sides of the square are the radii of the circle)   now, the area of the triangle formed by two radii and a line which joins the point of intersection of the two circles = 0.5*1*1= 
<gadget id="calculator">0.5*1*1</gadget>
<output>0.5</output>
0.5   So, half of the portion of our desired area= (pi/4 - 0.5)   therefore, the area of our desired portion is 2* (pi/4 - 0.5)   = pi/2 - 1   ANSWπ/2-1R:π/2-1
<result>E</result>
2 identical circles intersect so that their centre and point at which they intersect form a square of 1 cm.the area of portion that is common two circles is
4