A charitable woman gave one penny more than half pennies in her purse to a farmer .Afterwards she came across a beggar whom she gave 2 pennies more than half of what she had in her purse. In the end she gave 3 pennies more than half of what she had in her purse and left with a penny with her to a boy. Find what she had in the beginning?  Choose the correct choice from the following choices
A) 41  B) 42  C) 43  D) 44  E) 45
she gave 1 penny more than the half in the purse i.e (x/2 +1)   now she is left with:: (x-(x/2+1))=(x-2)/2   now to the beggar::   she gave 2 pennies more than the half in the purse i.e(x-2)/4 +2   and she is left with :: ((x-2)/2)-((x-2)/4 +2)= (x-10)/4   now at last   sh gave 3 pennies more then the half she was left with i.e ((x-10)/8+ 3)=A   so she is left with   (x-10)/4-A=(x-34)/8   now acc. to quest   (x-34)/8=1   hence x=42   ANSWER:42
<result>B</result>
A charitable woman gave one penny more than half pennies in her purse to a farmer .Afterwards she came across a beggar whom she gave 2 pennies more than half of what she had in her purse. In the end she gave 3 pennies more than half of what she had in her purse and left with a penny with her to a boy. Find what she had in the beginning?