If ‘n‘ integers taken at random and multiplied together, then what is the probability that the last digit of the product is 1, 3, 7 or 9 ?  Choose the correct answer:	A) (2/5)^n	B) (1/5)^n	C) (3/5)^n	D) (4/5)^n	E) (6/5)^n
Last digit may be 0,1,2,3,4,5,6,7,8,9 = 10   condition is 1,3,7,9 = 4   and n random no. so   probability is 4^n/10^n=(4/10)^n=(2/5)^n   (2/5)^nNSWER:(2/5)^n
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If ‘n‘ integers taken at random and multiplied together, then what is the probability that the last digit of the product is 1, 3, 7 or 9 ?