20 litres of mixture contains 20% alcohol and the rest water. If 3litres of water be mixed with it, the percentage of alcohol in the new mixture would be?	Choose one.
A) 16.67%	B) 23%	C) 18.3%	D) 19.75%	E) 17.4%
Alcohol in the 20litres of mix. = 20% of 20litres = (20*20/100)= 
<gadget id="calculator">(20*20/100)</gadget>
<output>4</output>
4litres   water in it= 20-3= 
<gadget id="calculator">20-3</gadget>
<output>17</output>
17litres   new quantity of mix.= 20+3= 
<gadget id="calculator">20+3</gadget>
<output>23</output>
23 litres   Quantity of alcohol in it= 4litres   Percentage of alcohol in new mix. = 4*100/23 = 17.4%   Answer is 17.4%
<result>E</result>
20 litres of mixture contains 20% alcohol and the rest water. If 3litres of water be mixed with it, the percentage of alcohol in the new mixture would be?