What are the last two digits of (301*402*503*604*646*547*449*349)^2  Options
A) 96  B) 76  C) 56  D) 36  E) 24
((301*402*503*604*646)*(547*449*349))^2   If you observe above digits, last digit are: 1,2,3,4,6,7,9,9; 5&amp;9 are missing; so I have rearranged them so that multiplication will be easy for me as initial 4 digits have last two digits as 01,02,03,04,46 and final three as 47*49*49.   Solving for only last two digits and multiplying them we get:( (06*04*46)(47*01))^2 = (44*47)^2=68^2=24   Hence answer is 24
<result>E</result>
What are the last two digits of (301*402*503*604*646*547*449*349)^2