Machine–A produces 40% of the total output and Machine-B produces 60% of the total output. An average of nine units out of a thousand goods manufactured by Machine-A and one unit of 200 units produced by Machine-B prove to be defective. What is the probability that a unit chosen at random from the total daily output of the factory is defective?  Choose the correct option
A) 0.6	B) 0.06	C) 0.0066	D) 0.0006	E) 6.0e-05
Let total Production be 10000 units....   A produces 4000 units and 36 units are defective   B produces 6000 units and 30 units are defective   So, Out of total 10,000 units 66 units are defective...   So the required probability = 66/10000= 
<gadget id="calculator">66/10000</gadget>
<output>33/5_000 = around 0.0066</output>
&gt; 0.0066   Answer will be (0.0066)
<result>C</result>
Machine–A produces 40% of the total output and Machine-B produces 60% of the total output. An average of nine units out of a thousand goods manufactured by Machine-A and one unit of 200 units produced by Machine-B prove to be defective. What is the probability that a unit chosen at random from the total daily output of the factory is defective?