When a natural number N is successively divided by 11,12,13,14. the remainders are 15,16,17,18. What will be the sum of the remainders if the order of the division is reversed?
Select the correct option:  A) 16  B) 14  C) 12  D) 11  E) 9
11 12 13 14   15 16 17 18   leave the top right- most number 8   start with bottom right-most number 5   18*13+17= 
<gadget id="calculator">18*13+17</gadget>
<output>251</output>
251   251*12+16= 
<gadget id="calculator">251*12+16</gadget>
<output>3_028</output>
3028   3028*11+15= 
<gadget id="calculator">3028*11+15</gadget>
<output>33_323</output>
33323   this is the number required   Now, do the successive division in the reverse order   The sum of the remainders is 14   Hence, the correct option is 14
<result>B</result>
When a natural number N is successively divided by 11,12,13,14. the remainders are 15,16,17,18. What will be the sum of the remainders if the order of the division is reversed?