Which of the following leads to the correct mathematical solution for the number of ways that the letters of the word DATA could be arranged to create a four-letter code? Choose one:	A) 4!/2!	B) 6! − (3! + 2!)	C) 6! − (3! × 2!)	D) 6!/(3! + 2!)	E) 6!/(3! × 2!)
Number of letters in word 'DATA' = 4.   The letters 'A' appear 2 times in the word 'DATA'.   Therefore the mathematical solution for number of ways that the letters of the word D4!/2!T4!/2! can be arranged to create four-letter code   = 4!/2!   4!/2!nswer:4!/2!
<result>A</result>
Which of the following leads to the correct mathematical solution for the number of ways that the letters of the word DATA could be arranged to create a four-letter code?