Jane and Thomas are among the 9 people from which a committee of 4 people is to be selected. How many different possible committees of 4 people can be selected from these 9 people if at least one of either Jane or Thomas is to be selected? Choose the correct answer.
A) 67 B) 73 C) 79 D) 85 E) 91
The total number of ways to choose 4 people from 9 is 9C4 = 126.   The number of committees without Jane or Thomas is 7C4 = 35.   There are  126-35= 
<gadget id="calculator"> 126-35</gadget>
<output>91</output>
91 possible committees which include Jane and/or Thomas.   The answer is 91.
<result>E</result>
Jane and Thomas are among the 9 people from which a committee of 4 people is to be selected. How many different possible committees of 4 people can be selected from these 9 people if at least one of either Jane or Thomas is to be selected?