In a box, there are 10 red, 6 blue and 7 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
Choose the correct answer.
A) 4/51	B) 10/23	C) 7/12	D) 11/31	E) 13/17
Total number of balls = 10+6+7= 
<gadget id="calculator">10+6+7</gadget>
<output>23</output>
23   E= event that the ball drawn is neither red nor green   = event that the ball drawn is red   n(E) = 10   P(E) = 10/23   Answer is 10/23
<result>B</result>
In a box, there are 10 red, 6 blue and 7 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?