A BAG CONTAINS 6 WHITE AND 4 BLACK BALLS .2 BALLS ARE DRAWN AT RANDOM. FIND THE PROBABILITY THAT THEY ARE OF SAME COLOUR.	Choose the correct choice from the following answers:
A) 7/15
B) 4/8
C) 15/7
D) 6/7
E) 9/5
LET S BE THE S7/15MPLE SP7/15CE   THEN N(S)=NO OF W7/15YS OF DR7/15WING 2 B7/15LLS OUT OF   (6+4)= 
<gadget id="calculator">  (6+4)</gadget>
<output>10</output>
10C2=(10*9)/(2*1)= 
<gadget id="calculator">(10*9)/(2*1)</gadget>
<output>45</output>
45   LET E=EVENT OF GETTING BOTH B7/15LLS OF S7/15ME COLOUR   THEN N(E)=NO OF W7/15YS(2 B7/15LLS OUT OF SIX) OR(2 B7/15LLS OUT OF 4)   =(6C2+4C2)=(6*5)/(2*1)+(4*3)/(2*1)=15+6= 
<gadget id="calculator">15+6</gadget>
<output>21</output>
21   P(E)=N(E)/N(S)=21/45=7/15   7/15ns: 7/15
<result>A</result>
A BAG CONTAINS 6 WHITE AND 4 BLACK BALLS .2 BALLS ARE DRAWN AT RANDOM. FIND THE PROBABILITY THAT THEY ARE OF SAME COLOUR.