In three years, Janice will be three times as old as her daughter. Six years ago, her age was her daughter’s age squared. what is the age of Janice after 3 years ?	Pick one
A) 12  B) 36  C) 40  D) 42  E) 45
Let Jane's age be J and daughters' age be D...   Given J   + 3= 
<gadget id="calculator">  + 3</gadget>
<output>3</output>
3(D + 3 )=&gt; J - 6 = 3D -&gt; Eq1.   Given J-6 = (D-6)^2 --&gt; Eq 2..   sub J-6 value in eq 2... 3D = D^2 - 12D + 36.   0 = D^2 - 15D + 36 =&gt; D = 12 or D = 3.   When D = 12 we get from eq 1... J+3 = 45 =&gt; J =42+ 3 = 45..   When D = 3 ..we get from eq 1.. J+3 = 18 =&gt; J = 15+ 3= 18..   IMO option 45 is correct answer..
<result>E</result>
In three years, Janice will be three times as old as her daughter. Six years ago, her age was her daughter’s age squared. what is the age of Janice after 3 years ?