If k is an integer and 2 < k < 7, for how many different values of k is there a triangle with sides of lengths 3, 6, and k?	Choose the correct answer:
A) 0	B) 1	C) 2	D) 3	E) 4
(6-3) &lt; k &lt; (6+3)   3 &lt; k &lt; 9   Thus k = 4, 5, 6, 7, 8   Since 2 &lt; k &lt; 7, then k can be 4, 5, or 6.   The answer is 3.
<result>D</result>
If k is an integer and 2 < k < 7, for how many different values of k is there a triangle with sides of lengths 3, 6, and k?