A group of 4 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the probability that Bob and Lisa will each sit next to only one of the three other students from the group?	Pick one:
A) 5.55%
B) 16.67%
C) 15.75%
D) 20.45%
E) 25%
The question basically asks about the probability that Bob and Lisa sit at the ends.   The total # of sitting arrangements is 4!.   Desired arrangement is either BYZL or LYZB. Now, YZ can be arranged in 2! ways, therefore total # of favorable arrangements is 2*2!.   P=(favorable)/(total)=(2*2!)/4!=1/6.   Answer: 16.67%.(2*2 )/4= 
<gadget id="calculator">(2*2 )/4</gadget>
<output>1</output>
1/6.   Answer: 16.67%.
<result>B</result>
A group of 4 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the probability that Bob and Lisa will each sit next to only one of the three other students from the group?