A shop sells two variants of chocolates - one that costs $3 and the other that costs $5. If the shop sold $151 chocolates on a given day, how many different combinations of (number of $3 sold, number of $5 sold) exist?	Choices
A) 8	B) 10	C) 12	D) 14	E) 16
$151 = 29*$5 + 2*$3   We can find other combinations by reducing the $5 chocolates by 3 (which is -$15)and increasing the $3 chocolates by 5 (which is +$15).   The number of $5 chocolates can be 29, 26, 23, 20,...,2 for a total of 10 combinations.   The answer is 10.
<result>B</result>
A shop sells two variants of chocolates - one that costs $3 and the other that costs $5. If the shop sold $151 chocolates on a given day, how many different combinations of (number of $3 sold, number of $5 sold) exist?