Walking at 5/6 of its usual speed, a train is 10 minutes too late. What is usual time to cover the journey?  Choose the correct option
A) 70 minutes B) 2 hours C) 2/3 hours D) 5/6 hours E) 85 minutes
et Speed be S and Time to cover the journey be T   S * T = D (distance of journey) --- 1   now as per the question stem we have   (5/6)S * (T + 10) = D ----2   Equating Value of D from (1) in (2) we get T = 50mins or 5/6hrs .   Answer: 5/6 hours
<result>D</result>
Walking at 5/6 of its usual speed, a train is 10 minutes too late. What is usual time to cover the journey?