The average price of 10 oranges is Rs. 12 while the average price of 8 of these oranges is Rs. 11.75. Of the remaining two oranges, if the price of one orange is 30% more than the price of the other, what is the price of each of these two oranges?
Answers:
A) Rs 5, Rs 7.50 B) Rs 11.1, Rs 14.9 C) Rs 10, Rs 16 D) Rs 12, Rs 14 E) None of these
Explanation :   Total price of the two oranges = Rs. [(12 x 10) (11.75 x 8)]   = Rs. (120 - 94) = Rs. 26.   Let the price of one orange be Rs. x.   Then, the price of other orange = Rs. (x + 30% of x) = Rs. x + 1/3x = Rs. 4x/3   So, x + 4x/3 = 26   7x = 78   x = 11.1   The prices of the two oranges are Rs. 11.1 and Rs. 14.9   Answer : Rs 11.1, Rs 14.9
<result>B</result>
The average price of 10 oranges is Rs. 12 while the average price of 8 of these oranges is Rs. 11.75. Of the remaining two oranges, if the price of one orange is 30% more than the price of the other, what is the price of each of these two oranges?