There are 10 students named alphabetically from A to J. What is the Probability that A and D do not sit together if all 10 sit around a circular table?	Select the correct option:	A) 2/9	B) 2/5	C) 7/9	D) 4/5	E) 8/9
Number of students = 10   Number of ways 10 students can sit around a circular table = (10 - 1)= 
<gadget id="calculator">(10 - 1)</gadget>
<output>9</output>
9!   Number of ways A and D sit together (consider A and D as one entity)= (9 - 1)= 
<gadget id="calculator">(9 - 1)</gadget>
<output>8</output>
8! * 2   Number of ways A and D do not sit together= 9! - (8! * 2)   Probability = (9! - (8! * 2))/9! = 1 - 2/9 = 7/9   Answer: 7/9
<result>C</result>
There are 10 students named alphabetically from A to J. What is the Probability that A and D do not sit together if all 10 sit around a circular table?