Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 35 percent ryegrass, what percent of the weight of this mixture is X ?
Choose the most appropriate option:
A) 10%
B) 33.33 %
C) 40%
D) 50%
E) 66.66 %
----------------&gt;Ryegrass   X--------------&gt;	40%   Y--------------&gt;	25%   M(mixture)----&gt;35%   0.4X + (M-X)0.25 = 0.35M   0.15X = 0.10M   X = 0.6666M   X = 66.66% of M   66.66 %
<result>E</result>
Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 35 percent ryegrass, what percent of the weight of this mixture is X ?