Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 56, the three numbers in order are?	Select.
A) 48,96,24 B) 48,24,96 C) 96,24,48 D) 96,48,24 E) 98,48,24
Let the numbers be 2X, X and 4X   Average = (2X + X + 4X)/3   =&gt; 7X/3 = 56   =&gt; X = (3 x 56)/7 = 24   Hence, the numbers in order are 48, 24 and 96   ANSWER:48,24,96
<result>B</result>
Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 56, the three numbers in order are?