If the operation @ is defined for all a and b by the equation a@b =(a/b)+(b/a) then (5@2)-3=? Options.
A) 0.5 B) 0.1 C) 0.4 D) 0.2 E) 0.3
work within the parenthesis first so solve (5@2) first   (5@2)=(5/2)+(2/5)=29/10= 
<gadget id="calculator">29/10</gadget>
<output>29/10 = around 2.9</output>
2.9   now take 2.9 plug back into equation and solve the rest    3-(2.9)= 
<gadget id="calculator"> 3-(2.9)</gadget>
<output>0.1</output>
0.1   so 0.1 is the answer....this question is merely testing order of operations   remember PEMDAS   Option 0.1
<result>B</result>
If the operation @ is defined for all a and b by the equation a@b =(a/b)+(b/a) then (5@2)-3=?