A woman invested $1,000, part at 5% and the rest at 6%. Her total investment with interest at the end of the year was $1,052. How much did she invest at 5%?	Pick:
A) $500
B) $600
C) $700
D) $800
E) $950
et x be the portion invested at 5% and   Let (1-x) be the rest which is invested at 6%   The question states that the return after 1 year is (1052/1000)-1= 
<gadget id="calculator">(1052/1000)-1</gadget>
<output>13/250 = around 0.052</output>
0.052= 5.2%   We want to find the dollar amount invested in X   Using our defined variables, put together the equation and solve for x (the percentage of 1000 invested at 5%)   0.05x+0.06(1-x)= 0.052   (0.05)x +0.06 - (0.06)x = 0.052   -0.01x = -0.008   x= -0.008/-0.01 = 8/10 = 80%   So X = 80% of the 1000 which is 800   ANSWER:$800
<result>D</result>
A woman invested $1,000, part at 5% and the rest at 6%. Her total investment with interest at the end of the year was $1,052. How much did she invest at 5%?