A die is rolled twice. What is the probability of getting a sum equal to 9?  Choose one:
A) 2/3  B) 2/9  C) 1/3  D) 1/9  E) 2/5
Total number of outcomes possible when a die is rolled = 6 (∵ any one face out of the 6 faces)   Hence, total number of outcomes possible when a die is rolled twice, n(S) = 6 × 6 = 36   2/5 = Getting a sum of 9 when the two dice fall = {(3, 6), {4, 5}, {5, 4}, (6, 3)}   Hence, n(2/5) = 4   P(2/5) = n(2/5)/n(S)=4/36=1/9   Answer is 2/5
<result>E</result>
A die is rolled twice. What is the probability of getting a sum equal to 9?