If d=1/(2^3*5^8) is expressed as a terminating decimal, how many nonzero digits will d have?	Choose the correct choice.
A) One
B) Two
C) Three
D) Seven
E) Ten
Another way to do it is :   We know x^a*y^a=(X*Y)^a   given = 1/(2^3*5^8)   = Multiply and divide by 2^5   =2^5/(2^3*2^5*5^8)   =2^5/10^8   =&gt; non zero digits are 32=&gt; Ans Two
<result>B</result>
If d=1/(2^3*5^8) is expressed as a terminating decimal, how many nonzero digits will d have?