A alone finish a work in 12 days,where B finish same work in 15 days and C alone finish in 20 days.all three start work together but after 2 days A leave the work and B leave the work before 2 days of finishing the work.then in how many days work finished? Select:
A) 8  B) 45/6  C) 6  D) 58/7  E) 5
work of A in 1 day=1/12,work of B in 1 day=1/15 and work of C in 1 day=1/20   (A+B+C) Work in 2 days=2(1/12+1/15+1/20)=2×12/60=2/5   work of C in 2 days=1/10   remaining work=1-(2/5+1/10)=1-1/2=1/2   this work done by both B and C together   (B+C) work in 1 days=7/60   1/2 work done by (B+C)=[1*60/7*1/2]=30/7 days   total time taken to finish the work=[2+2+30/7]=58/7 days   Answer 58/7
<result>D</result>
A alone finish a work in 12 days,where B finish same work in 15 days and C alone finish in 20 days.all three start work together but after 2 days A leave the work and B leave the work before 2 days of finishing the work.then in how many days work finished?