P & Q sitting in a circular arrangement with 10 persons. What is the probability that P & Q will sit together?  Choose the correct choice from the following:
A) 1/13
B) 2/11
C) 3/14
D) 1/15
E) 2/17
n(S)= number of ways of sitting 12 persons at round table:   =(12-1)= 
<gadget id="calculator">(12-1)</gadget>
<output>11</output>
11!   Since two persons will be always together, then number of persons:=10+1= 
<gadget id="calculator">10+1</gadget>
<output>11</output>
11   So, 11 persons will be seated in (11-1)= 
<gadget id="calculator">(11-1)</gadget>
<output>10</output>
10! ways at round table and 2 particular persons will be seated in 2! ways.   n(A)= The number of ways in which two persons always sit together =10!×2   So probability = 10!*2!/11!= 2/11   2/11
<result>B</result>
P & Q sitting in a circular arrangement with 10 persons. What is the probability that P & Q will sit together?