An urn contains g green marbles and b blue marbles. If 3 green marbles and 4 blue marbles are added, and then one marble is selected at random from the urn, what is the probability that a blue marble will be drawn? Answers.
A) b/(b+g) B) (b+5)/(g+3) C) (b+5)/(b+g+8) D) (b+4)/(b+g+7) E) b/(b+g+5)
no of fav outcomes i.e. blue MArbles = b+4   Total no of outcomes i.e. total Marbles = (b+4)+(g+3)= b+g+7   probability = (b+4) /(b+g+7)   Answer (b+4)/(b+g+7)
<result>D</result>
An urn contains g green marbles and b blue marbles. If 3 green marbles and 4 blue marbles are added, and then one marble is selected at random from the urn, what is the probability that a blue marble will be drawn?