If a, b, c, d, e and f are integers and (ab + cdef) < 0, then what is the maximum number D of integers that can be negative?
Options: A) 2 B) 3 C) 4 D) 5 E) 6
Minimuum should be 1   Maximum should be 4:   1 out of a or b to make the multiplication negative   3 out of c, d, e or f to make the multiplication negative.   Negative+Negative&lt;0   Answer:C   maximum will be 5..   you dont require both the multiplicatin to be negative for entire equation to be negative...   any one a or b can be negative to make ab negative and it can still be more(away from 0) than the multiplication of 4 other -ve numbers...   actually by writing minimum required as 1 out of 6,you are actually meaning 5 out of 6 also possible as you will see D=5 or 1 will give you same equation..   ans 5
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If a, b, c, d, e and f are integers and (ab + cdef) < 0, then what is the maximum number D of integers that can be negative?