N is the greatest number which divides 1305, 4665 and 6905 and gives the same remainder in each case. What is the sum of the digits in N? Choose one
A) 23	B) 28	C) 4	D) 1	E) 25
If the remainder is same in each case and remainder is not given, H4F of the differences of the numbers is the required greatest number    6905 - 1305= 
<gadget id="calculator"> 6905 - 1305</gadget>
<output>5_600</output>
5600   6905 - 4665= 
<gadget id="calculator">6905 - 4665</gadget>
<output>2_240</output>
2240   4665 - 1305= 
<gadget id="calculator">4665 - 1305</gadget>
<output>3_360</output>
3360   Hence, the greatest number which divides 1305, 4665 and 6905 and gives the same remainder, N= H4F of 5600, 2240, 3360   = 1120   Sum of digits in N   = Sum of digits in 1120   = 1 + 1 + 2 + 0= 
<gadget id="calculator">1 + 1 + 2 + 0</gadget>
<output>4</output>
4   Answer is 4
<result>C</result>
N is the greatest number which divides 1305, 4665 and 6905 and gives the same remainder in each case. What is the sum of the digits in N?