The last digit of 12^12+13^13–14^14×15^15=	Choose the correct option:
A) 0
B) 1
C) 5
D) 8
E) 9
This question tests the cyclicity concept.   2 has a cyclicity of 4 i.e. 5th power of 2 has same unit digit as 1st power of 2 .   3 also has cyclicity of 4   4 has cycling of 2   5 has 0.   So this complicated calculation boils down to   2^12 +3^13 - 4^14 ×5^15   6+3-6×0=9 as unit digit is answer.   Answer 9
<result>E</result>
The last digit of 12^12+13^13–14^14×15^15=