An art gallery owner is hanging paintings for a new show. Of the seven paintings she has to choose from, she can only hang three on the main wall of the gallery. Assuming that she hangs as many as possible on that wall, in how many ways can she arrange the paintings?	Choose one.
A) 18 B) 30 C) 64 D) 120 E) 210
Arrangment means permutations questions..   7P3 = 7!/3! = 210.   IMO option 210 is correct answer..
<result>E</result>
An art gallery owner is hanging paintings for a new show. Of the seven paintings she has to choose from, she can only hang three on the main wall of the gallery. Assuming that she hangs as many as possible on that wall, in how many ways can she arrange the paintings?