In how many ways can 10 different gifts be divided among four children such that each child receives exactly two gifts? Pick
A) 16^4 B) (4!)^4 C) 10!/(2!)^4 D) 16!/4! E) 4^16
Total 10 different Gifts, and 4 children.   Thus any one child gets 10C2 gifts,   then the other child gets 8C2 gifts(10 total - 2 already given),   then the third one gets 6C2 gifts,   and the last child gets 4C2 gifts.   Since order in which each child gets the gift is not imp, thus, ans :   1010!/(2!)^42 * 810!/(2!)^42 * 610!/(2!)^42 * 410!/(2!)^42 = 10! / (2!)^4   Ans : 10!/(2!)^4.
<result>C</result>
In how many ways can 10 different gifts be divided among four children such that each child receives exactly two gifts?