In how many ways can 5 boys and 3 girls be seated on 8 chairs so that no two girls are together?
Choose the correct choice from the following answers:
A) 5760 B) 14400 C) 480 D) 56 E) 40320
Consider the following arrangement:   *B*B*B*B*B*   Now, if girls occupy the places of 6 stars no girls will be together.   # of ways 3 girls can occupy the places of these 6 stars is C36=20;   # of ways 3 girls can be arranged on these places is 3!=6   # of ways 5 boys can be arranged is 5!=120   So total # of ways to arrange 3 Girls and 5 boys so that no girls are together is 20∗6∗120=14,400   ANS:14400
<result>B</result>
In how many ways can 5 boys and 3 girls be seated on 8 chairs so that no two girls are together?