How can you get 81 using the digits 2, 3, 25, 50, 75, 100 only once using any of the arithmetic operators?
Choose the correct answer
A) 81	B) 82	C) 87	D) 98	E) 57
since 3^2 = 9 and 9^2 = 81,   ie , (3^2)^2 = 81   (3*3)^2 = 81   so,   [3*{(100+50-75)/25}]^2 = 81   81NSWER:81
<result>A</result>
How can you get 81 using the digits 2, 3, 25, 50, 75, 100 only once using any of the arithmetic operators?