If xy ≠ 0 and x^2y^2 − 3xy = 28, which of the following could be y in terms of x?
I. 1/(2x)
II. -4/x
III. 7/x Select
A) I only	B) II only	C) I and II	D) I and III	E) II and III only
(x^2)(y^2) – 3xy - 28 = 0   (xy – 7)(xy + 4) = 0   xy – 7 = 0 or xy + 4 = 0   xy = 7 or xy = -4   Since we need y in terms of x, we can isolate y in both of our equations.   y = 7/x or y = -4/x   Answer: II and III only
<result>E</result>
If xy ≠ 0 and x^2y^2 − 3xy = 28, which of the following could be y in terms of x?
I. 1/(2x)
II. -4/x
III. 7/x