In a box of 8 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective?
Choose the correct choice from the following choices
A) 1/12	B) 5/14	C) 2/13	D) 2/15	E) 1/17
First, there are 6C3 ways you can select 3 good pencils from 4 good ones.   Second, there are 8C3 ways you select 3 pencils from 6 ones in the box.   Then, the probability that neither pen will be defective is: 6C3/8C3=20/56 = 5/14   Answer is 5/14
<result>B</result>
In a box of 8 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective?