A circular road runs round a circular ground. If the difference between the circumferences of the outer circle and inner circle is 66 metres, the width of the road is: Select the correct option:	A) 5.25m	B) 7m	C) 10.5m	D) 21m	E) 22m
2π(R-r)=60 =&gt; 2*22/7 * (R-r)=60.   Therefore, (R-r)= (66*7/44)= 
<gadget id="calculator">(66*7/44)</gadget>
<output>21/2 = around 10.5</output>
10.5m   ANSWER:10.5m
<result>C</result>
A circular road runs round a circular ground. If the difference between the circumferences of the outer circle and inner circle is 66 metres, the width of the road is: