A computer wholesaler sells ten different computers and each is priced differently. If the wholesaler chooses three computers for display at a trade show, what is the probability (all things being equal) that the two most expensive computers will be among the three chosen for display?
Pick.
A) 15/56	B) 3/28	C) 1/28	D) 1/15	E) 1/168
Since, two of the choices are prefixed, we are free to choose 1 from the rest of the 8 avilable. so 8C1 is the numerator.   Total no of ways we can choose 3 from 10 is 10c3, which is the denominator.   So, the probability: 8c1/10c3= 1/15 ans is 1/15.
<result>D</result>
A computer wholesaler sells ten different computers and each is priced differently. If the wholesaler chooses three computers for display at a trade show, what is the probability (all things being equal) that the two most expensive computers will be among the three chosen for display?