The perimeters of two squares are 80 cm and 64 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.	Choices.
A) 42cm  B) 44cm  C) 46cm  D) 48cm  E) 49cm
Explanation:   Side of first square = (80/4)= 
<gadget id="calculator">(80/4)</gadget>
<output>20</output>
20 cm;   Side of second square= (64/4)= 
<gadget id="calculator">(64/4)</gadget>
<output>16</output>
16 cm.   Area of third square= [(20)2 - (16)2] cm2 = (400 - 256) cm2 = 144 cm2.   Side of third square = (144)(1/2) cm = 12 cm.   Required perimeter = (12 x 4) cm = 48 cm.   Answer: Option 48cm
<result>D</result>
The perimeters of two squares are 80 cm and 64 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.