How many methods are possible for arranging 5 boys and 4 girls in such a way that no 2 girls could sit together?	Choose the correct choice from the following answers.
A) 43200  B) 43700  C) 44200  D) 53200  E) 33200
The arrangement can be done as below   X..B..X..B...X..B...X..B...X..B..X   where b is the position of Boys and 4 girls can be placed at any of 6 positions marked as X.   so Number of arrangements will be   5! * 6p4 = 120*360= 
<gadget id="calculator">120*360</gadget>
<output>43_200</output>
43200   43200NSWER:43200
<result>A</result>
How many methods are possible for arranging 5 boys and 4 girls in such a way that no 2 girls could sit together?