A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?	Choose the correct option.
A) 66	B) 67	C) 68	D) 69	E) 70
Let the total volume of original bottle be x   Then question says 40% of x is oil.   Also question mentions that there is 8ml of oil in original bottle.   Set up equation--&gt; 40% of x = 8   40 * x /100 = 8   x=20.   Hence oil in original container is = 8mL (40 % of total volume)   vinegar in original container is = 4mL (20 % of total volume)   water in original container is = 8mL. (40 % of total volume)   Now we take a container which has 4 times volume of original container.   So, volume of new container = 4*20= 
<gadget id="calculator">4*20</gadget>
<output>80</output>
80   In this new container we pour oil, vinegar and water from original container.   Volume occupied in new container by oil, vinegar and water from original container= 8+4+8= 
<gadget id="calculator">8+4+8</gadget>
<output>20</output>
20mL   Hence volume left in new container= 80 - 20= 
<gadget id="calculator">80 - 20</gadget>
<output>60</output>
60mL   As per question, remaining space in the larger bottle is then filled with water. i.e 60mL is filled with water.   Hence total water in new container= 60 mL + 8mL(this one poured from old container)   =68mL   ANSWER:68
<result>C</result>
A full bottle contains 40% oil, 20% vinegar, and 40% water. The bottle is poured into a larger bottle, four times as big as original. The remaining space in the larger bottle is then filled with water. If there was 8 ml of oil in the original bottle, how much of water is in the final mixture?