A box contains 40 balls, numbered from 1 to 40. If three balls are selected at random and with replacement from the box, what is the probability that the sum of the three numbers on the balls selected from the box will be odd? Pick:
A) 1/4
B) 3/8
C) 1/2
D) 5/8
E) 3/4
I don't think order matters in this case, because 2 + 2 + 1 = 2 + 1 + 2   My answer is: 1/4   1/4
<result>A</result>
A box contains 40 balls, numbered from 1 to 40. If three balls are selected at random and with replacement from the box, what is the probability that the sum of the three numbers on the balls selected from the box will be odd?