If after 300 grams of water were added to the 24%-solution of alcohol, the strength of the solution decreased by one-third, how much of the 24%-solution was used?  Pick one: A) 180 grams B) 220 grams C) 250 grams D) 350 grams E) 600 grams
I too think 600 grams should be the answer.   My reasoning is   The h20 content in 300 gms of water is 1   h20 content in 24% solution is 0.76   Resulting new solution's concentration decreases by one third means. Now it becomes 16% solution which means h20 content is 0.84   Let amount of solution be X   Then the equation can be set up   300*1 + 0.76X = 0.84 (X+300)   0.08X = 48   8X = 4800   X = 600 (ans 600 grams)
<result>E</result>
If after 300 grams of water were added to the 24%-solution of alcohol, the strength of the solution decreased by one-third, how much of the 24%-solution was used?