For a finite sequence of non zero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 3, -3, 2, 5, -4, -6 ? Choose one
A) 1
B) 2
C) 3
D) 4
E) 5
Given sequence: {1, -3, 2, 5, -4, -6}   The questions basically asks: how manypairs of consecutive termsare there in the sequence such that the product of these consecutive terms is negative.   1*(-3)=-3=negative;   -3*2=-6=negative;   2*5= 
<gadget id="calculator">2*5</gadget>
<output>10</output>
10=positive;   5*(-4)=-20=negative;   (-4)*(-6)= 
<gadget id="calculator">(-4)*(-6)</gadget>
<output>24</output>
24=positive.   So there are 3 pairs of consecutive terms of the sequence for which the product is negative.   1nswer: 1.
<result>A</result>
For a finite sequence of non zero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 3, -3, 2, 5, -4, -6 ?