If f(f(n)) + f(n) = 2n+3, f(0) = 1 then f(2014) = ? Choose the most appropriate option.
A) 2015  B) 2088  C) 270  D) 1881  E) 1781
f (f(0)) + f(0) = 2(0) + 3 ⇒⇒ f(1) = 3-1= 
<gadget id="calculator">3-1</gadget>
<output>2</output>
2, f(1)= 2   f(f(1)) + f(1) = 2(1) + 3 ⇒⇒ f(2)  ( (1)) +  (1)= 
<gadget id="calculator"> ( (1)) +  (1)</gadget>
<output>2</output>
2(1) + 3 ⇒⇒ f(2)= 5-2= 
<gadget id="calculator">5-2</gadget>
<output>3</output>
3, f(2)= 3   f(f(2)) + f(2) = 2(2) + 3 ⇒⇒ f(3) = 7-3= 
<gadget id="calculator">7-3</gadget>
<output>4</output>
4, f(3)= 4   ..............   f(2014) = 2015   2015ns: 2015
<result>A</result>
If f(f(n)) + f(n) = 2n+3, f(0) = 1 then f(2014) = ?