There are 4 baskets. The first basket has 3 apples and 4 oranges, the second one has 4 apples and 5 mangoes, the third one has 6 Mangoes and 2 bananas and the last one has 7 bananas and 2 apples. If a fruit is randomly chosen from any basket and it comes out to be an apple, then what is the probability that it was taken out from the second basket?	Choose the correct choice from the following choices:
A) 27/69  B) 28/69  C) 29/69  D) 25/69  E) 28/64
P(A|1)=3/7   P(A|2)=4/9   P(A|3)=0/8   P(A|4)=2/9   Hence event 1,2,3,4 are the partitions of the sample space.   The probability of choosing an apple, by the law of total probability   P(A)=P(A|1)P(1)+P(A|2)P(2)+P(A|3)P(3)+P(A|4)P(4)   =3/7*1/4+4/9*1/4+0/8*1/4+2/9*1/4   =23/84   28/69y 28/69aye's theorem,   P(2|A)=P(A|2)*P(2)/P(A)   =4/9*(1/4)/(23/84)   =28/69   ANSWER:28/69
<result>B</result>
There are 4 baskets. The first basket has 3 apples and 4 oranges, the second one has 4 apples and 5 mangoes, the third one has 6 Mangoes and 2 bananas and the last one has 7 bananas and 2 apples. If a fruit is randomly chosen from any basket and it comes out to be an apple, then what is the probability that it was taken out from the second basket?