If x and y and z are two-digit integers such that x > 40, y<70, and z is > 80 and < 90, which of the following is closest to the maximum possible value of xyz ?	Pick
A) 700
B) 607,959
C) 4,000
D) 7,000
E) 28,000
To get the maximum possible value of xyz, we need maximize the value of x,y, and z.   max x can be = 99 (given x is a two-digit integer &gt; 40)   max y can be = 69 (given y is a two-digit integer &lt; 70)   max z can be = 89 (given z is a two-digit integer &gt; 80 and &lt; 90)   xy = 99*69*89 = 607,959   Answer (607,959)
<result>B</result>
If x and y and z are two-digit integers such that x > 40, y<70, and z is > 80 and < 90, which of the following is closest to the maximum possible value of xyz ?