A five-person team is to be formed from a pool of 6 East All Stars and 6 West All Stars. What is the probability that the team will contain at least 2 East All Stars? Answers:	A) fraction of 29/33	B) 81/169	C) 57/120	D) 47/144	E) 119/720
The question with at- least can be easily tackled by   At least = Total cases - unwanted cases   So atleast 2 player = total cases - cases with no east all stars person - case with only one east all person   Total number of cases = 12C5 = 798   Cases with no east all person = 6C5(All person from west all stars) = 6   Cases with exactly one east all person = 6C4*6C1 (4from west all stars and 1 from east all stars)= 90   So total no. of cases with with at least two members = 798-6-90= 
<gadget id="calculator">798-6-90</gadget>
<output>702</output>
702   Probability= 702/798 = 29/33   answer:fraction of 29/33
<result>A</result>
A five-person team is to be formed from a pool of 6 East All Stars and 6 West All Stars. What is the probability that the team will contain at least 2 East All Stars?