N is the greatest number which divides 1305, 4665 and 6905 and gives the same remainder in each case. What is the sum of the digits in N?  Select:
A) 4	B) 3	C) 6	D) 5	E) 2
6905 - 1305= 
<gadget id="calculator">6905 - 1305</gadget>
<output>5_600</output>
5600   6905 - 4665= 
<gadget id="calculator">6905 - 4665</gadget>
<output>2_240</output>
2240   4665 - 1305= 
<gadget id="calculator">4665 - 1305</gadget>
<output>3_360</output>
3360   Hence, the greatest number which divides 1305, 4665 and 6905 and gives the same remainder, N= HCF of 5600, 2240, 3360   = 1120   Sum of digits in N   = Sum of digits in 1120   = 1 + 1 + 2 + 0= 
<gadget id="calculator">1 + 1 + 2 + 0</gadget>
<output>4</output>
4 4nswer: Option 4
<result>A</result>
N is the greatest number which divides 1305, 4665 and 6905 and gives the same remainder in each case. What is the sum of the digits in N?