How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?
Choose the correct choice from the following choices.
A) 20 B) 10 C) 5 D) 15 E) 25
Since, each desired number is divisible by 5, so we must have 5 at the unit place.   So , the tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9)   therefore the 3-digit no can be formed by   (5 * 4 * 1)= 
<gadget id="calculator">  (5 * 4 * 1)</gadget>
<output>20</output>
20 ways   20ns- 20
<result>A</result>
How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?