If x≠0 and x=√4xy−4y^2, then, in terms of y, x =	Pick
A) 2y  B) y  C) y/2  D) -(4y^2)/(1-2y)  E) -2y
Well it means :   Squaring we get:   x^2 =4y(x-y)   Assume X^2=m &gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;1   Than ,m=4y(m^1/2-y)   on solving:m-4y(m)^1/2+4y^2=0 &gt;&gt; quadratic in y s solve for y.   Y comes out to be =(m^1/2)/2   Hence,put m =x^2 from 1.   So x=2y   2yNSWER:2y
<result>A</result>
If x≠0 and x=√4xy−4y^2, then, in terms of y, x =