Car W and Car Y traveled the same 80-mile route. If Car W took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car W, how many hours did it take Car Y to travel the route?  Choose the correct choice from the following
A) 2/3	B) 1	C) 4/3	D) 8/5	E) 3
The speed of car W is (distance)/(time) = 80/2= 
<gadget id="calculator">80/2</gadget>
<output>40</output>
40 miles per hour.   The speed of car Y= 3/2*40= 
<gadget id="calculator">3/2*40</gadget>
<output>60</output>
60 miles per hour --&gt; (time)= (distance)/(speed) = 80/60 = 4/3 hours.   Answer: C.   Or: to cover the same distance at 3/2 as fast rate 2/3 as much time is needed --&gt; (time)*2/3 = 2*2/3 = 4/3 hours.   Answer: 4/3.
<result>C</result>
Car W and Car Y traveled the same 80-mile route. If Car W took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car W, how many hours did it take Car Y to travel the route?