What is the smallest number which when increased by 3 is divisible by 12, 15, 35, and 40?	Choose the correct option.
A) 837
B) 947
C) 1027
D) 1155
E) 1231
Factor each of the numbers 8, 15, 35, and 40 into primes:   12=2*2*3; 15=3*5; 35=5*7; 40=2*2*2*5   The smallest number divisible by all of them is thus   2*2*2*3*5*7= 
<gadget id="calculator">  2*2*2*3*5*7</gadget>
<output>840</output>
840   837 + 3= 
<gadget id="calculator">837 + 3</gadget>
<output>840</output>
840   837
<result>A</result>
What is the smallest number which when increased by 3 is divisible by 12, 15, 35, and 40?