If x,y ,and z are positive real numbers such that x+y-z =100 , y-z+x =120 , and z-x+y = 50, then find the x+y+z value?  Choose the correct choice from the following choices.
A) 100	B) 120	C) 150	D) 200	E) 160
x+y-z =100, ------1)   y-z+x =120 , ------2)   z-x+y = 50------3)   from (1)&amp;(2)   2z=20   z=10   from (2)&amp;(3)   2y = 170   y=85   then x=100-75= 
<gadget id="calculator">100-75</gadget>
<output>25</output>
25   x+y+z= 120   correct option is 120
<result>B</result>
If x,y ,and z are positive real numbers such that x+y-z =100 , y-z+x =120 , and z-x+y = 50, then find the x+y+z value?