For any positive integer n, the sum of the first n positive integers equals [n(n+1)]/2.
What is the sum of all the even integers between 99 and 201?	Pick: A) 6540 B) 7650 C) 8760 D) 9870 E) 10,980
100 + 102 +...+ 200 = 51*100 + (2+4...+100) = 51*100 + 2(1+2+...+50) =   51*100 + 2(50)(51)/2 = 150*51= 
<gadget id="calculator">150*51</gadget>
<output>7_650</output>
7650   The answer is 7650.
<result>B</result>
For any positive integer n, the sum of the first n positive integers equals [n(n+1)]/2.
What is the sum of all the even integers between 99 and 201?