Consider the sets Tn= {n, n + 1, n + 2, n + 3, n + 4), where n = 1, 2, 3, … , 96. How many of these sets contain 6 or any integral multiple thereof (i.e., any one of the numbers 6, 12, 18, …)?  Choose the correct choice from the following choices:
A) 80
B) 81
C) 82
D) 83
E) 84
Explanation :   If n = 1, then the set T1 = {1,2,3,4,5}, and it does not have 6 or any multiples.   n = 2 to n = 6 has 6 in the set.   n = 7, has the set T7 = {7,8,9,10,11}, and no 6 or multiples.   So 1 in every 6 members do not have 6 or multiples of 6.   So, till n = 96, there are 16 sets of “6 members” (16*6 = 96) and 16 sets do not have 6 or its multiples, while the remaining 80 sets have.   80nswer : 80
<result>A</result>
Consider the sets Tn= {n, n + 1, n + 2, n + 3, n + 4), where n = 1, 2, 3, … , 96. How many of these sets contain 6 or any integral multiple thereof (i.e., any one of the numbers 6, 12, 18, …)?