x varies inversely as square of y. Given that y = 2 for x = 1. The value of x for y = 6 will be equal to?	Pick one:
A) 1/5	B) 1/8	C) 1/3	D) 1/9	E) 1/2
Given x = k/y2, where k is a constant.   Now, y = 2 and x = 1 gives k = 4.   x = 4/y2 =&gt; x = 4/62, when   y = 6 =&gt; x = 4/36 = 1/9.   Answer: 1/9
<result>D</result>
x varies inversely as square of y. Given that y = 2 for x = 1. The value of x for y = 6 will be equal to?