A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 2, 4 and 3, which can be repeated. If the product of the digits in the area code must be even, how many different codes can be created?  Choose the correct choice
A) 20
B) 26
C) 24
D) 22
E) 30
Total # of codes possible is 3*3*3= 
<gadget id="calculator">3*3*3</gadget>
<output>27</output>
27. Oit of those 27 codes only the product of 333 will be odd, the remaining 26 will have either 2 or 4 in them, which ensures that their product will be even. Therefore the number of codes where the product of the digits is even= (total) - (restriction) = 27 - 1= 
<gadget id="calculator">27 - 1</gadget>
<output>26</output>
26.   Answer: 26
<result>B</result>
A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 2, 4 and 3, which can be repeated. If the product of the digits in the area code must be even, how many different codes can be created?