If the ratio of the roots of the equation x2+px+q=0 is equal to that of the roots x2+rx+s=0, then:
Pick
A) sq=pr
B) qp=sr
C) sq=p
D) ps=qr
E) none
x2+px+q=0 for this eqn... roots are R1=-p R2=-q   x2+rx+s=0 for this eqn... roots are R3=-r R4=-s   As per Question, -p/-q=-r/-s   =&gt; ps=qr   ANSWER:ps=qr
<result>D</result>
If the ratio of the roots of the equation x2+px+q=0 is equal to that of the roots x2+rx+s=0, then: