A question paper has 2 parts, A & B, each containing 8 questions. If a student has to choose 8 from part A &4 from part B, in how many ways can he choose the questions?
Choose the correct choice from the following:  A) 110  B) 70  C) 120  D) 130  E) 140
There 8 questions in part A out of which 8 question can be chosen as = 8C8.   Similarly,4 questions can be chosen from 8 questions of Part B as = 8C4.   Hence, total number of ways,   =8C8*8C4   =[8!/(0!8!)]*[8!/(4!*4!)]   = {1}*{8*7*6*5/(4!)}   = 70.   70
<result>B</result>
A question paper has 2 parts, A & B, each containing 8 questions. If a student has to choose 8 from part A &4 from part B, in how many ways can he choose the questions?