In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?  Answers:  A) 101  B) 209  C) 301  D) 405  E) 91
Required number of ways = 6C1*4C3 + 6C2*4C2 + 6C6*4C1 + 6C4   = 24+90+80+15= 
<gadget id="calculator">24+90+80+15</gadget>
<output>209</output>
209   Answer is 209
<result>B</result>
In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?