Three coins are tossed. What is the probability of getting at most two tails? Choose the most appropriate option:
A) 7/8	B) 1/8	C) 1/2	D) 1/7	E) 2/5
Total number of outcomes possible when a coin is tossed = 2 (∵ Head or Tail)   Hence, total number of outcomes possible when 3 coins are tossed, n(S) = 2 × 2 × 2 = 8   (∵ i.e., S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH})   E = event of getting at most two Tails = {TTH, THT, HTT, THH, HTH, HHT, HHH}   Hence, n(E) = 7   P(E) = n(E)/n(S)=7/8   7/8nswer is 7/8
<result>A</result>
Three coins are tossed. What is the probability of getting at most two tails?