a^3 - b^3 - 3ab = 1,
a^3 - b^3 + ab = x! + 1,
where a,b,x are positive integers,x is least.
Find (a + b) ?	Choose the correct choice from the following answers: A) 2 B) 3 C) 4 D) 5 E) 6
a^3 - b^3 + ab = x! + 1,   a^3 - b^3 - 3ab = 1,   subtracting,   ab+3ab =x!   4ab=x!   if x=4   a=3   b=2   a+b=3+2= 
<gadget id="calculator">3+2</gadget>
<output>5</output>
5 and x=4.   ANSWER:5
<result>D</result>
a^3 - b^3 - 3ab = 1,
a^3 - b^3 + ab = x! + 1,
where a,b,x are positive integers,x is least.
Find (a + b) ?