The area of one square is x^2 + 8x + 16 and the area of another square is 4x^2 − 12x + 9. If the sum of the perimeters of both squares is 32, what is the value of x?  Choose the correct choice from the following:
A) 0  B) 2  C) 2.5  D) 7/3  E) 10
spotting the pattern of equations both are in form of (X+C)^2 so   A1= (x+4)^2A2= (2x-3)^2   L1= x+5L2= 2x-3   P1 = 4( x+4)P2=4(2x-3)   P1+P2=32   4( x+4) +4(2x-3)=32..............&gt; X=7/3   Answer: 7/3
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The area of one square is x^2 + 8x + 16 and the area of another square is 4x^2 − 12x + 9. If the sum of the perimeters of both squares is 32, what is the value of x?