If 6 different numbers are to be selected from integers 0 to 6, how many 6-digit even integers greater than 300,000 can be composed?  Pick:
A) 1080	B) 1180	C) 1280	D) 1480	E) 1680
Starting with number n &gt;= 3and last number = {0,2,4,6}   case I :   1680ven number   4 or 6 in 100 thousands digit   the units digit can be any one of {0,2,4(if 6 is considered), 6 (if 4 is considered)}   so IF 4 is considered in 100 thousands digit    1*5*4*3*2*3= 
<gadget id="calculator"> 1*5*4*3*2*3</gadget>
<output>360</output>
360   So if 6 is considered in 100 thousands digit    1*5*4*3*2*3= 
<gadget id="calculator"> 1*5*4*3*2*3</gadget>
<output>360</output>
360   Hence in Case I we have 720   Case II   3 or 5 in 100 thousands digit   So if 3 is considered in 100 thousands digit    1*5*4*3*2*4= 
<gadget id="calculator"> 1*5*4*3*2*4</gadget>
<output>480</output>
480   So if 5 is considered in 100 thousands digit    1*5*4*3*2*4= 
<gadget id="calculator"> 1*5*4*3*2*4</gadget>
<output>480</output>
480   Hence For case II we have   480+480= 
<gadget id="calculator">  480+480</gadget>
<output>960</output>
960   Total we have   960+720= 
<gadget id="calculator">  960+720</gadget>
<output>1_680</output>
1680 cases:   Final Answer:1680
<result>E</result>
If 6 different numbers are to be selected from integers 0 to 6, how many 6-digit even integers greater than 300,000 can be composed?