If the average (arithmetic mean) of the four numbers K, 2K + 3, 3K – 5 and 5K + 1 is 41, what is the value of K?
Answers: A) 41 B) 15 3/4 C) 22 D) 23 E) 25 3/10
K + 2K +3 + 3K - 5 + 5K +1 = 11K -1   (11K -1)/4 = 41   11K = 41 * 4 +1 = 164 +1= 
<gadget id="calculator">164 +1</gadget>
<output>165</output>
165   K= 165 / 11= 
<gadget id="calculator">165 / 11</gadget>
<output>15</output>
15.   41nswer 41.
<result>A</result>
If the average (arithmetic mean) of the four numbers K, 2K + 3, 3K – 5 and 5K + 1 is 41, what is the value of K?