A 6-liter solution is 40% alcohol. How many liters of pure alcohol must be added to produce a solution that is 50% alcohol?  Select the correct option
A) 1.2  B) 1.5  C) 1.8  D) 2.1  E) 2.4
Let x be the amount of pure alcohol required.   0.4(6) + x = 0.5(x+6)   0.5x = 3 - 2.4   x = 1.2 liters   The answer is 1.2.
<result>A</result>
A 6-liter solution is 40% alcohol. How many liters of pure alcohol must be added to produce a solution that is 50% alcohol?