A meeting has to be conducted with 6 managers. Find the number of ways in which the managers be selected from among 10 managers, if 2 managers will not attend the meeting together?	Choose the most appropriate option.
A) 120	B) 110	C) 105	D) 140	E) 135
we can either choose all 6 people from 8 manager who have no problems or choose 5 from the 8 and 1 from the 2 managers who have a problem sitting together   so 8C6 + (8C5 * 2C1)   this is   28 + 112= 
<gadget id="calculator">  28 + 112</gadget>
<output>140</output>
140   Answer : 140
<result>D</result>
A meeting has to be conducted with 6 managers. Find the number of ways in which the managers be selected from among 10 managers, if 2 managers will not attend the meeting together?