A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is: Choose the correct choice from the following choices.
A) 91/2 B) 3/6 C) 4/5 D) 2/91 E) 8/9
Let S be the sample space.   Then, n(S)	= number of ways of drawing 3 balls out of 15   = 15C3   =	(15 x 14 x 13)   (3 x 2 x 1)   = 455.   Let E = event of getting all the 3 red balls.   n(E) = 5C3 = 5C2 =	(5 x 4)/(2 x 1)= 10.   P(E) =	n(E)/n(S)=10/455=2/91.   Ans:2/91
<result>D</result>
A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is: