There is a escalator and 2 persons move down it.A takes 50 steps and B takes 75 steps while the escalator is moving down.Given that the time taken by A to take 1 step is equal to time taken by B to take 3 steps.Find the no. of steps in the escalator while it is staionary?	Choose the correct choice
A) 60  B) 70  C) 80  D) 90  E) 100
If A takes 1 step in one second, then B takes 3 steps in one second. If A takes t1 seconds to   take 50 steps, then B takes 150 steps in t1 seconds.   For B, to take 150 steps he requires t1 seconds,   then to take 75 steps he requires t1/2 seconds.   now use relative velocity   L - v*t1=50 (for first person)   L-v*t1/2=75(for second person)   S(escalator w.r.t ground)-s(person w.r.t escalator)=s1(person w.r.t ground)   S,s,s1 are the steps   now put the v*t1 from 1 into the second equation and u get   L- (L-50)/2=75   L+50=150   L=100   ANSW100R:100
<result>E</result>
There is a escalator and 2 persons move down it.A takes 50 steps and B takes 75 steps while the escalator is moving down.Given that the time taken by A to take 1 step is equal to time taken by B to take 3 steps.Find the no. of steps in the escalator while it is staionary?