Find the value of x which satisfies the relation
Log10 3+log10 (4x+1)=log10 (x+1)+1  Choose the correct option.
A) 2.5
B) 3.5
C) 3.2
D) 6.8
E) 9.8
[log10a + log10b = log10 ab]   and also 1 can be written as log10 10,   so question can be rewritten as: log10 (3(4x+1))=log10(10(x+1)),   this can be solved to get 12x+3=10x+10,   that gives x=7/2= 
<gadget id="calculator">7/2</gadget>
<output>7/2 = around 3.5</output>
3.5   ANSWER:3.5
<result>B</result>
Find the value of x which satisfies the relation
Log10 3+log10 (4x+1)=log10 (x+1)+1