A 48 lts container containing liquid A and B contains 25% liquid A. a few lts of the mixture is released and replaced with equal amount of Liquid B. If this process is repeated once, the cylinder is found to contain 16% liquid A .How many lts of the mixture was released each time.?	Options:
A) 4.8	B) 9.6	C) 7.68	D) 9	E) None of the Above
25% of mixture is liquid A =&gt; 12 ltrs of liquid A and 36 ltrs of liquid B together form 48 ltrs of the mixture.   This implies that the ratio of liquids A and B in the mixture is is 1:3   Let the amount of liquid removed i x ltrs =&gt; x/4 ltrs of liquid A and 3x/4 ltrs of liquid B is removed.   Given that the x liters of mixture removed is added with same quantity of liquid B =&gt;   12-(x/4) + {36-(3x/4) + x} = 48   =&gt; {12 -(x/4)} + {36 + x/4} = 48   The ratio of liquid A to total mixture after first time the process is done = 16% =&gt;   {12- (x/4)} / 48 = 16/100   12- (x/4) = 7.68   x/4 = 4.32 =&gt; x= 17.28   ANSWER:7.68
<result>C</result>
A 48 lts container containing liquid A and B contains 25% liquid A. a few lts of the mixture is released and replaced with equal amount of Liquid B. If this process is repeated once, the cylinder is found to contain 16% liquid A .How many lts of the mixture was released each time.?