y =2x^2 +2bx + 512 cuts the x axis at (h, 0) and (k, 0). If h and k are integers, what is the least value of b?
Choose the correct choice from the following answers.
A) 256	B) -256	C) -128	D) -64	E) -257
As the curve cuts the x-axis at (h,0) and (k,0). Therefore h,k are the roots of the quadratic equation.   For the quadratic equation is in the form ofax^2+bx+c=0,   The product of the roots =c/a= 512/2= 
<gadget id="calculator">512/2</gadget>
<output>256</output>
256 and the sum of the roots=-b/a=-b   256 can be expressed as product of two numbers in the following ways:   1 * 256   2 * 128   4 * 64   8 * 32   16 * 16   The sum of the roots is maximum when the roots are 1 and 256 and the maximum sum is 1 + 256= 
<gadget id="calculator">1 + 256</gadget>
<output>257</output>
257.   The least value possible for b is therefore -257.   -257
<result>E</result>
y =2x^2 +2bx + 512 cuts the x axis at (h, 0) and (k, 0). If h and k are integers, what is the least value of b?