Jane and Thomas are among the 7 people from which a committee of 3 people is to be selected. How many different possible committees of 3 people can be selected from these 7 people if at least one of either Jane or Thomas is to be selected?  Choose the most appropriate option:
A) 20 B) 25 C) 30 D) 35 E) 40
The total number of ways to choose 3 people from 7 is 7C3 = 35.   The number of committees without Jane or Thomas is 5C3 = 10.   There are  35-10= 
<gadget id="calculator"> 35-10</gadget>
<output>25</output>
25 possible committees which include Jane and/or Thomas.   The answer is 25.
<result>B</result>
Jane and Thomas are among the 7 people from which a committee of 3 people is to be selected. How many different possible committees of 3 people can be selected from these 7 people if at least one of either Jane or Thomas is to be selected?