If x^2 = 161, which of the following is closest to a potential value of x?  Choose the correct choice from the following options: A) -127 B) -11 C) 12 D) 13 E) 131
Here the thing we must not forget is that X^even has two potential solutions   =&gt; x =+- √161 =&gt; +- 13 (approx)   this value is closer to 13   Hence 13 is correct.
<result>D</result>
If x^2 = 161, which of the following is closest to a potential value of x?