A toy store's revenue in November was 3/5 of its revenue in December and its revenue in January was 3/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January? Options
A) 1/4 B) 1/2 C) 2/3 D) 2 E) 4
Let 2ec rev =100   Then Nov rev is 3/5 (100) =&gt; 60   Therefore Jan rev = 3/4(Nov rev) = 3/4(60) =&gt; 45   Hence 2ec rev = x*( Nov rev+Jan rev)/2   100 = x* (60+45)/2   x = 100/52.5 =&gt; 1.90=2   Ans) 2
<result>D</result>
A toy store's revenue in November was 3/5 of its revenue in December and its revenue in January was 3/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?