A shipment of 250 smartphones contains 67 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?
Choose one:
A) 1/250  B) 1/14  C) 1/11  D) 1/9  E) 1/3
Probability of chosing one defective phone from a lot of 250 which ontains 67 defective phones is = (67/250)   Probability of chosing one defective phone from a lot of 249(we already picked one) which ontains 66(we already picked one) defective phones is = (66/249)   Combined probability of series of events = product of the probabilities = (67/250)*(66/249)   67/250 is close to (26/97) and (66/249)= (22/83)   so answer is (26/97)*(22/83) = (1/14)   So, answer will be 1/14
<result>B</result>
A shipment of 250 smartphones contains 67 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?