Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?  Choose the correct option.
A) 42, 33
B) 41, 33
C) 42, 35
D) 41, 35
E) 41, 37
Let the marks secured by them be x and (x + 9)   Then sum of their marks = x + (x + 9) = 2x + 9   Given that (x + 9) was 56% of the sum of their marks   =&gt;(x+9) = 56/100(2x+9)   =&gt;(x+9) = 14/25(2x+9)   =&gt; 25x + 225 = 28x + 126   =&gt; 3x = 99   =&gt; x = 33   Then (x + 9) = 33 + 9= 
<gadget id="calculator">33 + 9</gadget>
<output>42</output>
42   Hence their marks are 33 and 42   42, 33)
<result>A</result>
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?