Working together, Jose and Jane can complete an assigned task in 5 days. However, if Jose worked alone and complete half the work and then Jane takes over the task and completes the second half of the task, the task will be completed in 15 days. How long will Jose take to complete the task if he worked alone? Assume that Jane is more efficient than Jose Choose the correct answer: A) 26 days B) 15 days C) 60 days D) 65 days E) 36 days
Assume:   Jose does 1 job in x days, so Jose does 1/x job in a day   Jane does 1 job in y days, so Jane does 1/y job in a day   Together, they does (x+y)/xy job in a day. This is equals to 1/20. So   (x+y)/xy = 1/5   5(x+y) = xy   Next, we're told 1 job takes 15 days to complete if Jose and Jane each does half the work. So since Jose does 1 job in x days, he wil need x/2 days to do half the job. Jane similarly will need y/2 days to do the other half.   x/2 + y/2 = 15   x+y = 30   So   xy = 150   The answer choices are:   26 days   15 days   60 days   65 days   36 days   From the answer choices, So I'll go for 15 days for Jose and 10 days for Jane.   Answer : 15 days
<result>B</result>
Working together, Jose and Jane can complete an assigned task in 5 days. However, if Jose worked alone and complete half the work and then Jane takes over the task and completes the second half of the task, the task will be completed in 15 days. How long will Jose take to complete the task if he worked alone? Assume that Jane is more efficient than Jose