Find the probability that a leap year selected at random will not have 53 Sundays Options
A) 6/7
B) 5/7
C) 4/7
D) 3/7
E) 2/7
There are 366 days in a leap year: 52 weeks and 2 more days. So, 52 Sundays and 2 days.   These 2 days can be: {Mon, Tue}, {Tue, Wed}, {Wed, Thu}, {Thu, Fri}, {Fri, Sat}, {Sat,Sun} and {Sun, Mon} (7 cases). In order to have 53 Sundays we should have either {Sat,Sun} or {Sun, Mon} case.   The probability of that is 2/7.   So, probability of not having 53 sundays is 1 - 2/7 = 5/7   Answer: 5/7.
<result>B</result>
Find the probability that a leap year selected at random will not have 53 Sundays