In how many ways 4 boys and 5 girls can be seated in a row so that they are alternate. Choose the correct answer:
A) 144	B) 288	C) 12	D) 256	E) 2880
Solution: Let the Arrangement be,   G B G B G B G B G   4 boys can be seated in 4! Ways.   Girl can be seated in 3! Ways.   Required number of ways,   = 4!*5! = 2880.   Answer: Option 2880
<result>E</result>
In how many ways 4 boys and 5 girls can be seated in a row so that they are alternate.