A three-digit positive integer is chosen at random. What is the probability that the product of its digits is even? Pick
A) 1/2	B) 31/36	C) 49/54	D) 7/8	E) 11/12
P(three odd digits) = 5/9*5/10*5/10 = 5/36 (first digit cannot be 0, so we have a total of 9 digits, 4 even and 5 odd).   Therefore, P(at least one even digit) = 1 - 5/36 = 31/36.   Answer 31/36.
<result>B</result>
A three-digit positive integer is chosen at random. What is the probability that the product of its digits is even?