If each digit in the set of A = (1,2,3,4,5) is exactly used once, in how many ways can the digits be arranged such that the 2 and 5 are not adjacent? Choose the correct choice from the following:
A) 6
B) 24
C) 72
D) 96
E) 112
The answer should be = total arrangements - arrangements when 2 and 5 are together.   = 5! - 4! * 2! = 120 -48= 
<gadget id="calculator">120 -48</gadget>
<output>72</output>
72   ANS:72
<result>C</result>
If each digit in the set of A = (1,2,3,4,5) is exactly used once, in how many ways can the digits be arranged such that the 2 and 5 are not adjacent?