A woman invested $1,000, part at 5% and the rest at 6%. Her total investment with interest at the end of the year was $1,055. How much did she invest at 5%? Choose the most appropriate option:
A) $500  B) $600  C) $700  D) $900  E) $950
et x be the portion invested at 5% and   Let (1-x) be the rest which is invested at 6%   The question states that the return after 1 year is (1055/1000)-1= 
<gadget id="calculator">(1055/1000)-1</gadget>
<output>11/200 = around 0.055</output>
0.055= 5.5%   We want to find the dollar amount invested in X   Using our defined variables, put together the equation and solve for x (the percentage of 1000 invested at 5%)   0.05x+0.06(1-x)= 0.055   (0.05)x +0.06 - (0.06)x = 0.055   -0.01x = -0.005   x= -0.005/-0.01 = 5/10 = 50%   So X = 50% of the 1000 which is 500   $500NSWER:$500
<result>A</result>
A woman invested $1,000, part at 5% and the rest at 6%. Her total investment with interest at the end of the year was $1,055. How much did she invest at 5%?