A computer wholesaler sells six different computers and each is priced differently. If the wholesaler chooses three computers for display at a trade show, what is the probability (all things being equal) that the two most expensive computers will be among the three chosen for display?
Choose the correct choice from the following options:  A) 15/56  B) 3/28  C) 1/28  D) 1/5  E) 1/168
Since, two of the choices are prefixed, we are free to choose 1 from the rest of the 4 avilable. so 4C1 is the numerator.   Total no of ways we can choose 3 from 6 is 6c3, which is the denominator.   So, the probability: 4c1/6c3= 1/5 ans is 1/5.
<result>D</result>
A computer wholesaler sells six different computers and each is priced differently. If the wholesaler chooses three computers for display at a trade show, what is the probability (all things being equal) that the two most expensive computers will be among the three chosen for display?