In a box there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?	Pick:
A) 7⁄19  B) 2⁄3  C) 3⁄4  D) 9⁄21  E) None of these
If the drawn ball is neither red nor green, then it must be blue, which can be picked in 7C1 = 7 ways. One ball can be picked from the total(8 + 7 + 6 = 21) in 21C1 = 21 ways.   ∴ Reqd probability = 7⁄21 = 1⁄3   Answer None of these
<result>E</result>
In a box there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?