A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?	Select
A) 4 litres, 8 litres B) 6 litres, 6 litres C) 5 litres, 7 litres D) 7 litres, 5 litres E) 8 litres, 6 litres
Explanation:   Let the cost of 1 litre milk be Re. 1   Milk in 1 litre mix. in 1st can =	3/4litre, C.P. of 1 litre mix. in 1st can Re.3/4   Milk in 1 litre mix. in 2nd can = 1/2litre, C.P. of 1 litre mix. in 2nd can Re.1/2   Milk in 1 litre of final mix. =	5/8litre, Mean price = Re.5/8   By the rule of alligation, we have:   C.P. of 1 litre mixture in 1st can C.P. of 1 litre mixture in 2nd can   Ratio of two mixtures =	1/8:1/8=1:1   So, quantity of mixture taken from each can =(1/2 x 12)=6 litres.   ANSWER IS 6 litres, 6 litres
<result>B</result>
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?