Three boys are ages 4, 6 and 7 respectively. Three girls are ages 5, 8 and 9, respectively. If two of the boys and two of the girls are randomly selected and the sum of the selected children's ages is z, what is the difference between the probability that z is even and the probability that z is odd?  Choices:
A) 1/9	B) 1/6	C) 2/9	D) 1/4	E) 1/2
1/9ge of Boys:4, 6, 7   Sum of ages taken 2 at a time: 10,13,11   1/9ges of Girls:5, 8, 9   Sum of ages taken 2 at a time: 13,17,14   9 Combinations of sum between sets(10,12,11) &amp; (13,17,14)   =23,27,24- 16,30,17- 24,28,25   Prob(Even)= 5/9   Prob(Odd) =4/9   1/9nswer=5/9 - 4/9 = 1/9   1/9nswer:1/9
<result>A</result>
Three boys are ages 4, 6 and 7 respectively. Three girls are ages 5, 8 and 9, respectively. If two of the boys and two of the girls are randomly selected and the sum of the selected children's ages is z, what is the difference between the probability that z is even and the probability that z is odd?