In how many ways a committee of 5 members can be selected from 6men and 5ladies, consisting of 3 men and 2 ladies?	Pick one:
A) 120	B) 115	C) 250	D) 160	E) 200
(3 men out 6) and (2 ladies out of 5) are to be chosen   Required number of ways = 6C3 * 5C2 = (6*5*4*5*4)/(3*2*1*2*1)= 
<gadget id="calculator">(6*5*4*5*4)/(3*2*1*2*1)</gadget>
<output>200</output>
200   Answer is 200
<result>E</result>
In how many ways a committee of 5 members can be selected from 6men and 5ladies, consisting of 3 men and 2 ladies?