The sum of three consecutive integers is 93. What are the integers? Choices.
A) 20,21,22 B) 10,11,12 C) 30,31,32 D) 40,41,42 E) 30,31,32
First x Make the first number x   Second x+1 To get the next numberwe go up one or+1   Third x+2 Add another 1(2 total) to get the third   F +S +T =93 First (F) plus Second (S) plusThird (T) equals 93   (x)+(x+1)+(x+2)=93 Replace F with x, S with x+1, and T with x+2   x+x+1+x+2=93 Here the parenthesis aren′t needed.   3x+3=93 Combine like terms x+x+x and 2+1   −3 −3 Add 3 to both sides   3x=90 The variable ismultiplied by 3   3 3 Divide both sides by 3   x=30 Our solution for x   First 30 Replace x in our origional listwith 30   Second  (30)+1= 
<gadget id="calculator"> (30)+1</gadget>
<output>31</output>
31 The numbers are 30, 31, and 32   Third (30)+2= 
<gadget id="calculator">(30)+2</gadget>
<output>32</output>
32   correct answer 30,31,32
<result>E</result>
The sum of three consecutive integers is 93. What are the integers?