A committee of 3 has to be formed randomly from a group of 6 people. If Tom and Mary are in this group of 6, what is the probability that Tom will be selected into the committee but Mary will not? Choices
A) .1	B) .2	C) 3/10	D) .4	E) .5
C (3,6) - all the possible arrangements   C(2,4) is the number of ways the committe with Tom and without Mary.   P = 3/10(2,4)/(3/10 3,6) = 3/10 3/10
<result>C</result>
A committee of 3 has to be formed randomly from a group of 6 people. If Tom and Mary are in this group of 6, what is the probability that Tom will be selected into the committee but Mary will not?