How many ways could four cars can be parked at a parking lot with seven parking empty parking spots in which three of the seven spots will remain empty? Answers:
A) 840
B) 28
C) 7
D) 920
E) 838
ways in which 4 spots out 7 can be selected = 7C4   ways in which 4 cars can be arranged in 4 seats = 4!   Total ways of arrangement =7C4*4!   =(7*6*5/3*2)*24   =35*24= 
<gadget id="calculator">35*24</gadget>
<output>840</output>
840   840ns= 840
<result>A</result>
How many ways could four cars can be parked at a parking lot with seven parking empty parking spots in which three of the seven spots will remain empty?