If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 8, respectively, what is the probability that b/a will not be an integer?
Choose the correct choice from the following choices
A) 2/12 B) 3/12 C) 4/12 D) 1/2 E) 2/3
a is from the following set {1,2,3,4}   b is from the following set {8,10,12}   The total number of ways of choosing 2 integers, one from each set is  4*3= 
<gadget id="calculator"> 4*3</gadget>
<output>12</output>
12 ways.   The possibilities where b/a is not an integer is for the following outcomes:   {b,a}= {8,3},{10,3},{10,4} = 3 ways   Thus the probability is 3/12 = 1/4   The answer is 3/12.
<result>B</result>
If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 8, respectively, what is the probability that b/a will not be an integer?