Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?	Pick one.
A) 24000	B) 25100	C) 25150	D) 25200	E) 25400
Explanation:   Number of ways of selecting 3 consonants from 7   = 7C3   Number of ways of selecting 2 vowels from 4   = 4C2   Number of ways of selecting 3 consonants from 7 and 2 vowels from 4   = 7C3 × 4C2   =   (   7   ×   6   ×   5   3   ×   2   ×   1   )   ×   (   4   ×   3   2   ×   1   )   =   210   =(7×6×53×2×1)×(4×32×1)=210   It means we can have 210 groups where each group contains total 5 letters (3 consonants and 2 vowels).   Number of ways of arranging 5 letters among themselves   =   5   !   =   5   ×   4   ×   3   ×   2   ×   1   =   120   =5!=5×4×3×2×1=120   Hence, required number of ways   =   210   ×   120   =   25200   25200)
<result>D</result>
Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?