If the reciprocals of two consecutive positive integers are added together, what is the sum in terms of the greater integer p?  Options
A) (2p-1)/(p^3- p) B) (2p-1)/(p^4- p) C) (2p-1)/(p^2- p) D) (2p-1)/(p^2- 2p) E) (2p-4)/(p^2- 3p)
Let two consecutive positive integers be p and p-1 (Greater integer is p)   So,   (1/p) + [1/(p-1)]   = (2p-1)/p(p-1)   =(2p-1)/(p^2- p)   Answer : (2p-1)/(p^2- p)
<result>C</result>
If the reciprocals of two consecutive positive integers are added together, what is the sum in terms of the greater integer p?