An object thrown directly upward is at a height of h feet after t seconds, where h = -15 (t-2)^2 + 150. At what height, in feet, is the object 2 seconds after it reaches its maximum height?  Choose the correct choice from the following options:
A) 72	B) 90	C) 124	D) 132	E) 140
We see that h will be a maximum h=150 when t-2=0, that is when t=2.   At t=4, h = -15(4-2)^2 + 150 = -15(4) + 150 = 90   The answer is 90.
<result>B</result>
An object thrown directly upward is at a height of h feet after t seconds, where h = -15 (t-2)^2 + 150. At what height, in feet, is the object 2 seconds after it reaches its maximum height?