The distance between stations A and B is 148 km. An express train left station A towards station B with the speed of 80 km/hr. At the same time, a freight train left station B towards station A with the speed of 36 km/hr. They met at station C at 12 pm, and by that time the express train stopped at at intermediate station for 10 min and the freight train stopped for 5 min. Find:
a) The distance between stations C and B.
b) The time when the freight train left station B.
Choose the correct choice from the following
A) 12.17  B) 10.35  C) 29.28  D) 12.32  E) 12.22
a) Let x be the distance between stations B and C. Then the distance from station C to station A is (148−x)(148−x) km. By the time of the meeting at station C, the express train travelled for 148−x80+1060148−x80+1060 hours and the freight train travelled for x36+560x36+560 hours. The trains left at the same time, so: 148−x80+16=x36+112148−x80+16=x36+112. The common denominator for 6, 12, 36, 80 is 720. Then   9(148−x)+120=20x+609(148−x)+120=20x+60   1332−9x+120=20x+601332−9x+120=20x+60   29x=139229x=1392   x=48x=48. Therefore the distance between stations B and C is 48 km.   b) By the time of the meeting at station C the freight train rode for 4836+5604836+560 hours, i.e. 11 hour and 2525 min.   Therefore it left station B at 12−(1+2560)=10+356012−(1+2560)=10+3560 hours, i.e. at 10:35 am.   Answer:10.35
<result>B</result>
The distance between stations A and B is 148 km. An express train left station A towards station B with the speed of 80 km/hr. At the same time, a freight train left station B towards station A with the speed of 36 km/hr. They met at station C at 12 pm, and by that time the express train stopped at at intermediate station for 10 min and the freight train stopped for 5 min. Find:
a) The distance between stations C and B.
b) The time when the freight train left station B.