A dishonest milk man tops up his bucket which is only 4/5 th full of milk with water. He again removes 5 liters of this mixture from the bucket and adds an equal quantity of water. If milk is now 60% of the mixture, what is the capacity of the bucket ?	Choose the most appropriate option:
A) 15 lit B) 20 lit C) 22.5 lit D) 25 lit E) 30 lit
Solution:   Let x be the capacity of the bucket.then, initial mixture has 80% milk.   then after 5 lt replaced with water----&gt;(80/100)∗(x−5)=(60/100)∗x(80/100)∗(x−5)=(60/100)∗x   x=20 lt.   Ans:- 20 lit.
<result>B</result>
A dishonest milk man tops up his bucket which is only 4/5 th full of milk with water. He again removes 5 liters of this mixture from the bucket and adds an equal quantity of water. If milk is now 60% of the mixture, what is the capacity of the bucket ?