Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
Choose the correct choice from the following answers.
A) 4 B) 6 C) 5 D) 7 E) 9
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)   = H.C.F. of 3360, 2240 and 5600 = 1120.   Sum of digits in N = ( 1 + 1 + 2 + 0 )= 
<gadget id="calculator">( 1 + 1 + 2 + 0 )</gadget>
<output>4</output>
4   4nswer: Option 4
<result>A</result>
Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: