Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/6, 1/2 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?
Choose the correct choice from the following.
A) 1/32	B) 7/8	C) 9/64	D) 5/64	E) 3/64
P(Xavier will solve)=1/6   P(Yvonne will solve)=1/2   P(Zelda will NOT solve) = 1- 5/8 = 3/8.   Now, we need to multiply all this Ps to find an answer:   p= (1/6)*(1/2)*(3/8) = 1/32.   Ans. 1/32.
<result>A</result>
Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/6, 1/2 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?