From the top of a building, an object is thrown upward with an initial speed of 64 ft/sec. It touches the ground 5 seconds later. What is the height of the bulding
Choose one
A) 80 feet B) 70 feet C) 60 feet D) 50 feet E) 40 feet
The formula for the height H of a projectile thrown upward is given by   H(t) = -(1 / 2) g t 2 + Vo t + Ho   g is a constant and equal to 32. The initial speed Vo is known and also when t = 5 seconds H = 0 (touches the ground). Ho is the initial height or height of the building. Hence we can write   0 = -(1 / 2) (32) (5) 2 + (64) (5) + Ho   Solve the above for Ho to find the height of the building   Ho = 80 feet   80 feetnswer 80 feet
<result>A</result>
From the top of a building, an object is thrown upward with an initial speed of 64 ft/sec. It touches the ground 5 seconds later. What is the height of the bulding