In a box, there are 6 blue, 7 white and 4 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?
Select the correct option
A) 3/16  B) 5/16  C) 8/32  D) 4/17  E) 6/17
Total number of bulbs = (6 + 7 + 4)= 
<gadget id="calculator">(6 + 7 + 4)</gadget>
<output>17</output>
17.   Let E= event that the bulb drawn is neither white nor blue = event that the bulb drawn is yellow.   Therefore, P(E)=4/17   ANSWER:4/17
<result>D</result>
In a box, there are 6 blue, 7 white and 4 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?