In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?  Choose the correct answer
A) 5/21	B) 5/29	C) 5/23	D) 5/24	E) 5/26
Number of ways of (selecting at least two couples among five people selected) = (5C2 * 6⁶C1)   As remaining person can be any one among three couples left.   Required probability = (5C2 * 6C1)/10C5   = (10 * 6)/252 = 5/21   5/21nswer:5/21
<result>A</result>
In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?