Three unbiased coins are tossed. What is the probability of getting 1 heads and 1 Tail?	Options.
A) 3/4	B) 1/4	C) 3/8	D) 7/8	E) 1/8
Let, H --&gt; Head , T --&gt; Tail   Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}   Let E = event of getting 3 heads   Then E = {THT, HTH }   P(E) = n(E)/n(S) =2/8 = 1/4   Answer is 1/4
<result>B</result>
Three unbiased coins are tossed. What is the probability of getting 1 heads and 1 Tail?