If a,b and c are consecutive positive integers and a>b>c. What can be the value of (a^2-b^2)(b^2-c^2)?  Pick.
A) 21  B) 79  C) 143  D) 231  E) 450
Since a,b and c are consecutive positive integers and a&gt;b&gt;c, we can write them as (x + 1), x and (x - 1) respectively   (a^2-b^2)(b^2-c^2) can be simplified into (2x + 1)(2x - 1) = 4x^2 - 1   using the options to find the product,   only C. 143 satisfactorily gives us x as an integer   ANSWER:143
<result>C</result>
If a,b and c are consecutive positive integers and a>b>c. What can be the value of (a^2-b^2)(b^2-c^2)?