If logn48 = a and logn108 = b. What is the value of logn1296 in terms of a and b?	Choices
A) 2(2a + b)/5  B) (a + 3b)/5  C) 4(2a + b)/5  D) 2(a + 3b)/5  E) None of these
Given logn48 = 4logn2 + logn3 = a and   logn108 = 2.logn2 + 3logn3 = b   Let logn 2 = X and logn3 = Y.   =&gt; 4X + Y = a   2X +3Y = b.   2 x (ii) - (i) gives   6Y - Y = 2b - a   Y = (2b - a)/5   Similarly, X = (3a - b)/10.   logn1296 = 4(logn2 + logn3).   = 4[(2b - a)/5 + (3a - b)/10].   = 4[(a + 3b)/10] = 2(a + 3b)/5.   ANSWER:2(a + 3b)/5
<result>D</result>
If logn48 = a and logn108 = b. What is the value of logn1296 in terms of a and b?