In how many different ways can 2 identical blue balls and 2 identical red balls be shared among 4 children such that each child receives a ball? Select the correct option:
A) 10  B) 24  C) 34  D) 20  E) 21
GGG RRR   Therefore total number of ways is   4! but there are two groups of 2 identical things.   Therefore total number of "different" ways is   4!/ (2!) (2!) = 24 ANS:24
<result>B</result>
In how many different ways can 2 identical blue balls and 2 identical red balls be shared among 4 children such that each child receives a ball?