A raffle is being held at a party with 25 guests. Each guest has a numbered ticket (1 through 25). Three numbers will be randomly chosen and prizes given out. Paul and Jane have numbers 22 and 23. What is the probability both will win a prize? Choose the correct choice from the following options:	A) 1/2	B) 1/3	C) 1/100	D) 1/10	E) 3/25
Combination Formula: nCr = n!/(r!(n - r)!), where n is the population/set, and r is the sample/subset.   Total number possible = 251/1003 - 5!/(3!(5 - 3)!) = 2,300   Number 22 possible = 11/1001 = 1   Number 23 possible = 11/1001 = 1   Number other possible = 231/1001 = 23   Probability Formula: P(A) = (Number Favorable Outcomes)/(Total Number Possible Outcomes)   P(22, 23) = (11/1001)(11/1001)(231/1001)/251/1003 = 23/2,300 = 1/100   Answer: 1/100
<result>C</result>
A raffle is being held at a party with 25 guests. Each guest has a numbered ticket (1 through 25). Three numbers will be randomly chosen and prizes given out. Paul and Jane have numbers 22 and 23. What is the probability both will win a prize?