There are 7 man and 5 women sitting in a circle, find the all possible way so that two women wont sit together?	Choose the correct choice from the following options:
A) 6!*7P5
B) 6!*7P4
C) 6!*7P3
D) 5!*7P5
E) 4!*7P5
7 men can sit in a circle in  (7-1)= 
<gadget id="calculator"> (7-1)</gadget>
<output>6</output>
6! ways   no two women sit together,so woman have to sit alternate to men   there will be 7 places,in which 5 women have to sit   so women can sit in 7 places as 7P5 ways   reqd ways= 6!*7P5   6!*7P5NSWER:6!*7P5
<result>A</result>
There are 7 man and 5 women sitting in a circle, find the all possible way so that two women wont sit together?