If the average (arithmetic mean) of the four numbers K, 2K + 3, 3K – 5 and 5K + 1 is 96, what is the value of K?  Choices:  A) 11  B) 15 3/4  C) 22  D) 35  E) 25 3/10
K + 2K +3 + 3K - 5 + 5K +1 = 11K -1   (11K -1)/4 = 96   11K = 96 * 4 +1 = 384 +1= 
<gadget id="calculator">384 +1</gadget>
<output>385</output>
385   K= 385 / 11= 
<gadget id="calculator">385 / 11</gadget>
<output>35</output>
35.   Answer 35.
<result>D</result>
If the average (arithmetic mean) of the four numbers K, 2K + 3, 3K – 5 and 5K + 1 is 96, what is the value of K?