Of the families in City X in 1991, 60 percent owned a personal computer. The number of families in City X owning a computer in 1993 was 20 percent greater than it was in 1991, and the total number of families in City X was 9 percent greater in 1993 than it was in 1991. what percent of the families in City X owned a personal computer in 1993?
Choose the correct answer:
A) 59%  B) 55%  C) 63%  D) 66%  E) 68%
Say a 100 families existed in 1991 then the number of families owning a computer in 1991 - 60   Number of families owning computer in 1993 = 60 * 120/100= 
<gadget id="calculator">60 * 120/100</gadget>
<output>72</output>
72   Number of families in 1993= 109   The percentage = 72/109 * 100 = 66%.   ANSWER:66%
<result>D</result>
Of the families in City X in 1991, 60 percent owned a personal computer. The number of families in City X owning a computer in 1993 was 20 percent greater than it was in 1991, and the total number of families in City X was 9 percent greater in 1993 than it was in 1991. what percent of the families in City X owned a personal computer in 1993?