The average of six integers is 63, and none of these integers is greater than 100. If the average of three of the integers is 65, what is the least possible value of one of the other two integers? Choose the correct choice from the following.
A) 45
B) 62
C) 75
D) 83
E) 90
When it comes to averages, we know thataverage value = (sum of n values)/n   We can rewrite this into a useful formula:sum of n values = (average value)(n)   The average of five integers is 63   So, the sum of ALL 5 integers = (63)(6) =378   The average of three of the integers is 65   So, the sum of the 3 integers = (65)(3) =195   So, the sum of the 2 REMAINING integers =378-195= 
<gadget id="calculator">378-195</gadget>
<output>183</output>
183   If the sum of the 2 REMAINING integers=183, and we want to minimize one value, we must MAXIMIZE the other value.   100 is the maximum value so let 1 integer = 100, which means the other must equal 83   Answer: 83
<result>D</result>
The average of six integers is 63, and none of these integers is greater than 100. If the average of three of the integers is 65, what is the least possible value of one of the other two integers?