a, b, c and d are four consecutive numbers. If the sum of a and dis 113, what is the product of b and c?
Pick one.
A) 2652	B) 2578	C) 2534	D) 3192	E) 4234
Here d = a + 3   a + a + 3 = 113   2a = 110   a = 55   So, numbers are 55, 56, 57 and 58   ∴ b × c= 56 × 57 = 3192   3192
<result>D</result>
a, b, c and d are four consecutive numbers. If the sum of a and dis 113, what is the product of b and c?