When positive integer k is divided by 6 the remainder is 3. Which of the following CANNOT be an even integer? Choose the correct answer.
A) k + 1 B) k -11 C) 4k + 2 D) (k-3)/3 +2 E) k/3
First, because k/6 leaves a remainder of 3, we know k must be odd.   (k=6x+3 = 3(2x+1) = odd*odd = odd)   Knowing k is odd we can examine the answer choices:   a. k + 1 --&gt; odd + 1 --&gt; must be even   b. k -11 --&gt; odd - odd --&gt; must be even   c. 4k + 1 --&gt; 4*odd + 1 = even + 1 --&gt; must be odd   d. (k-3)/3 +2 --&gt; (6x+3-3)/3 + 2 = 2x + 2 --&gt; must be even   e. k/3 --&gt; (6x+3)/3 = 2x+1 = Must be odd   ANSWER:4k + 2
<result>C</result>
When positive integer k is divided by 6 the remainder is 3. Which of the following CANNOT be an even integer?