If 853,845 bars of chocolate need to be placed in little boxes and each box can contain at most 9 bars of chocolate. How many bars of chocolate will be in the last unfilled box? Choose one
A) 1  B) 3  C) 5  D) 6  E) 7
The number of bars of chocolate that can be placed in the little boxes of 9 bars is the first number that is divisible by 9 that occurs before 853,845.   In order to divide the sum in 9 parts, the amount must be divisible by 9   Divisibility rule of 9: The sum of the digits must be divisible by 9   Sum of digits of 853,845 = 33 and 27 is divisible by 9.   Hence, we need to remove 6 to this number for it to be divisible by 9   Correct Option: 6
<result>D</result>
If 853,845 bars of chocolate need to be placed in little boxes and each box can contain at most 9 bars of chocolate. How many bars of chocolate will be in the last unfilled box?