Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 % fescue. If a mixture of X and Y contains 30% ryegrass, what percent of the weight of the mixture is X?  Select the correct option:  A) 10%  B) 33 1/3%  C) 40%  D) 50%  E) 66 2/3%
Assuming the weight of the mixture to be 100g**, then the weight of ryegrass in the mixture would be 30g.   Also, assume the weight mixture X used in the mixture is Xg, then the weight of mixture Y used in the mixture would be (100-X)g.   So we can now equate the parts of the ryegrass in the mixture as:   0.4X + 0.25(100-X) = 30   0.4X + 25 - 0.25X = 30   0.15X = 5   X = 5/0.15 = 500/15 = 100/3   So the weight of mixture X as a percentage of the weight of the mixture   = (weight of X/weight of mixture) * 100%   = (100/3)/100 * 100%   = 33%   ANSWER:33 1/3%
<result>B</result>
Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 % fescue. If a mixture of X and Y contains 30% ryegrass, what percent of the weight of the mixture is X?