If y = x^2 + mx + n, y is minimum when x is:	Choose the most appropriate option:
A) m/n B) -m/n C) -m/2 D) -n/2 E) n/m
We're given the equation Y = X^2 + mX + n.   IF.. we use a simple Classic Quadratic....   m = 2   n = 1   Y = X^2 + 2X + 1   We can then go about finding the answer that yields the MINIMUM result when X = ...   Answer A: m/n = 2/1= 
<gadget id="calculator">2/1</gadget>
<output>2</output>
2 --&gt; 4+4+1= +9   Answer B: -m/n = -2/1 = -2 --&gt; 4-4+1 = +1   Answer -m/2: -m/2 = -2/2 = -1 --&gt; 1-2+1 = 0   Answer D: -n/2 = -1/2 --&gt;(1/4)-1+1 = +1/4   Answer E: n/m = 1/2 --&gt; (1/4)+1+1 = +2 1/4   From these results, we can see the minimum result:   -m/2
<result>C</result>
If y = x^2 + mx + n, y is minimum when x is: