A drawer has six loose blue socks and six loose white socks. If four socks are removed from the drawer at random and without replacement. What is the probability that one pair of each color was selected?
Choose the correct answer.
A) 2/33
B) 5/66
C) 5/33
D) 5/11
E) 1/2
No of Loose blue socks = 6 (3 pairs)   No. of Loose white Socks = 6 (3 pairs)   total no. of blue and white socks = 12   Total no. of socks to be selected = 4   So we have C (12,4) = no of ways the socks can be selected = 495   No of ways One pair of blue socks is selected ( 2 blue socks) , C (6,2) , No of ways one pair of white socks can be selected C (6,2) ..Because we have to find a scenario where EXACTLY one pair of Blue socks and ONE pair of WHITE socks is selected we will multiply the two .. ie 15 x 15 ..   Filling the information in the Probability formula we get P (A) = (15 x 15) / 495 = 5 /11   ANSWER : (5/11)
<result>D</result>
A drawer has six loose blue socks and six loose white socks. If four socks are removed from the drawer at random and without replacement. What is the probability that one pair of each color was selected?