For integers x and y if x^2+x/y is always an odd integer then which of the following must be true?
Choose the correct choice from the following answers:
A) x is even ; y is odd
B) x is even ; y is even
C) x is odd ; y is odd
D) x is odd ; y is even
E) cannot be determined
Given x and y are integers...NOTE : While taking values, x/y must be properly divisible and the result has to integer itself..   x^2+x/y = odd always...   lets take x even (2) and y even (2)   4 + 2/2 = odd...   lets take x odd(3) and y odd(3)   9+3/3 = even...   So only x even and y even satisfies the equation..   If we take one even and other odd then we get x/y as non integer..which shouldn't be the case as per our question stem.   Option x is even ; y is even is correct...
<result>B</result>
For integers x and y if x^2+x/y is always an odd integer then which of the following must be true?