In a sequence of 12 numbers, each term, except for the first one, is 12^12 less than the previous term. If the greatest term in the sequence is 12^13, what is the smallest term in the sequence?
Thus, A12 = A1+12-1d
Where d is the difference between each pairs of consecutive terms. Since each term is 1211 less than the previous term, d=-1211Click individual answer choices for specific explanations.
From what I undersltand the formula for an arithmetic sequence represents
some-number-in-the-sequence= first-number-in-sequence +the-place-of-that-number - 1x the-difference-of-each-#-in-the-sequence
Choose the correct choice from the following choices
A) −12^11 B) 0 C) 12^11 D) 11·12^11 E) 12^12
there are total 12 terms. andgreatestterm is 12^13. Each term is 12^12 less than previous one. What does this signify? This shows it is an AP - a decreasing one. (NoticeEach term is 12^12 less than previous one')   Therefore, 12^13 is the first term of the AP and -12^11 is the difference between successive terms, the smallest term should be the last one.   Last term = First term + (n-1)*d   therefore, Last term = 12^13 + 11*(-12^12)   =&gt; Last term = 12^13 - 11*12^12   =&gt; Last term = 12^12 (12-11) = 12^12   Which is the smallest term.   Hence Ans 12^12 it is.
<result>E</result>
In a sequence of 12 numbers, each term, except for the first one, is 12^12 less than the previous term. If the greatest term in the sequence is 12^13, what is the smallest term in the sequence?
Thus, A12 = A1+12-1d
Where d is the difference between each pairs of consecutive terms. Since each term is 1211 less than the previous term, d=-1211Click individual answer choices for specific explanations.
From what I undersltand the formula for an arithmetic sequence represents
some-number-in-the-sequence= first-number-in-sequence +the-place-of-that-number - 1x the-difference-of-each-#-in-the-sequence