Three times the first of three consecutive odd integers is 7 more than twice the third. The third integer is: Select: A) 9 B) 11 C) 13 D) 15 E) 19
Let the three integers be x, x + 2 and x+ 4.   Then,   3x = 2(x + 4) + 7   x = 15   Third integer = x + 4 = 19.   ANSW19R:19
<result>E</result>
Three times the first of three consecutive odd integers is 7 more than twice the third. The third integer is: