The length of a rectangle is three times of its width. If the length of the diagonal is 8√10 then find the perimeter of the rectangle.
Answers
A) 77 cm	B) 88 cm	C) 64 cm	D) 11 cm	E) 18 cm
Let Breadth = x cm,   then, Length = 3x cm   x2+(3x)2=(810−−√)2=&gt;10x2=640=&gt;x=8   x2+(3x)2=(810)2=&gt;10x2=640=&gt;x=8   So, length = 24 cm and breadth = 8 cm   Perimeter = 2(l+b)   = 2(24+8) = 64 cm   Answer:64 cm
<result>C</result>
The length of a rectangle is three times of its width. If the length of the diagonal is 8√10 then find the perimeter of the rectangle.