A bag contains 4 red balls, 5 green balls and 6 white balls. A ball is drawn at
random from the box. What is the probability that the ball drawn is either red or green?  Choose the most appropriate option:
A) 2/5
B) 3/5
C) 1/5
D) 7/15
E) 8/15
Total number of balls = (4 + 5 + 6)= 
<gadget id="calculator">(4 + 5 + 6)</gadget>
<output>15</output>
15.   Therefore, n(S)= 15.   Let E1 = event of drawing a red ball.   and E2 = event of drawing a green ball.   Then, E1 n E2 = f.   P (E1 n E2) = P(E1) + P(E2) = (4/15 + 5/15) = 9/15 = 3/5.   ANSWER:3/5
<result>B</result>
A bag contains 4 red balls, 5 green balls and 6 white balls. A ball is drawn at
random from the box. What is the probability that the ball drawn is either red or green?