The area of one square is x^2 + 8x + 16 and the area of another square is 4x^2 − 20x + 25. If the sum of the perimeters of both squares is 44, what is the value of x?  Choose the correct choice from the following answers:	A) 2	B) 4	C) 6	D) 8	E) 10
The areas are (x+4)^2 and (2x-5)^2.   The lengths of the sides are x+4 and 2x-5.   If we add the two perimeters:   4(x+4) + 4(2x-5) = 44   12x = 48   x = 4   The answer is 4.
<result>B</result>
The area of one square is x^2 + 8x + 16 and the area of another square is 4x^2 − 20x + 25. If the sum of the perimeters of both squares is 44, what is the value of x?