In a class of 10 students, a group of 4 will be selected for a trip. How many different groups are possible, if 2 of those 10 students are a married couple and will only travel together?  Choose the correct choice from the following answers.
A) 98
B) 115
C) 122
D) 126
E) 165
We need to break the grouping down to 2 scenarios : with the married couple or without the married couple in the group of 4 people for the trip   1) With the married couple in the group, we have to find the number of possibilities for the other 2 spots in the group from the left 8 people = 8!/(2!*6!) = 28   2) Without the married couple in the group, we have to find the number of possibilities for picking 4 people from the 8 unmarried people from the group = 8!/(4! * 4! ) = 70   Total number of possibilities = 28 + 70= 
<gadget id="calculator">28 + 70</gadget>
<output>98</output>
98 (98)
<result>A</result>
In a class of 10 students, a group of 4 will be selected for a trip. How many different groups are possible, if 2 of those 10 students are a married couple and will only travel together?