From a well shuffled deck of cards, what would be the probability that you would draw a two or a spade?  Choose the correct answer
A) 4 in 12 B) 4 in 10 C) 4 in 13 D) 4 in 8 E) 4 in 16
P(4 in 13)+P(2)-P(4 in 13n2)   P(4 in 13u2)=13/52 + 4/52 - 1/52 = 4/13
<result>C</result>
From a well shuffled deck of cards, what would be the probability that you would draw a two or a spade?