Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day, she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many E kilometers per hour did Tammy walk on the second day?  Options.
A) 3	B) 3.5	C) 4	D) 4.5	E) 6
Ans: C   Total time = 14 hrs   Let time traveled during 1st day = x   Let time traveled during 2nd day = x-2   Total time =14   x+x-2 = 14   x=8   speed * time = distance   s*8 + (s+0.5)(8-2) = 52   solving s = 4.5   now speed for 2nd day is 0.5 less than the 1st day which is 4.5   Thus speed for 2nd day = 4   Its simple algebra for s*8 + (s+0.5)(8-2) = 52 but for some reason Im getting 3.5 and not 4.5.   8s+6s+3=52   14s=49   s=3.5
<result>C</result>
Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day, she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many E kilometers per hour did Tammy walk on the second day?