In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit "5"?
A.
B.
C
D.
E.  Choose the correct answer.
A) 180 B) 196 C) 286 D) 288 E) 324
Should be 288.   We have to find the total number of 3-digit odd numbers not having 5 as a digit.   Units digits will be among 1,3,7,9   Tenth digits will be among 0,1,2,3,4,6,7,8,9   Hundredth digits will be among 1,2,3,4,6,7,8,9   So total numbers = 4*9*8= 
<gadget id="calculator">4*9*8</gadget>
<output>288</output>
288   ANSWER:288
<result>D</result>
In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit "5"?
A.
B.
C
D.
E.