If the average (arithmetic mean) of five consecutive negative integers is 12k – 1, what is the difference between the greatest and least of the five integers?  Options.
A) 4K  B) 4k^2 -4k  C) 4-4k  D) 4  E) 4k+4
(n-2 + n - 1 + n + n + 1 + n + 2)/5 = 12k - 1   =&gt; n = 60k - 5   Greatest = n + 2 = 60k - 5 + 2 = 60k - 3   Least = n - 2 = 60k - 5 - 2   =&gt; 4ifference = 60k - 3 - (60k - 7)   = 4   Answer - 460  - 3 - (60  - 7)= 
<gadget id="calculator">60  - 3 - (60  - 7)</gadget>
<output>4</output>
4   Answer - 4
<result>D</result>
If the average (arithmetic mean) of five consecutive negative integers is 12k – 1, what is the difference between the greatest and least of the five integers?