Each of the squares above is to have exactly one letter and nothing else placed inside it. If 3 of the letters are to be the letter X, 2 of the letters are to be the letter Y, and 1 of the letters is to be the letter Z, in how many different arrangements can the squares have letters placed in them?	Choose the correct choice:
A) 30
B) 60
C) 108
D) 120
E) 150
take it as a alphabetical problem   XXXYYZ   since those are alphabets, they are identical....   so that's 6!/3!*2!*1! = 60   ANSWER:60
<result>B</result>
Each of the squares above is to have exactly one letter and nothing else placed inside it. If 3 of the letters are to be the letter X, 2 of the letters are to be the letter Y, and 1 of the letters is to be the letter Z, in how many different arrangements can the squares have letters placed in them?