If 4 people are selected from a group of 8 married couples, what is the probability that none of them would be married to each other?  Choose the correct choice from the following answers:	A) 1/33	B) 2/33	C) 8/13	D) 16/33	E) 11/12
If we are to select 4 people from 8 couples WITHOUT any restriction, how many ways can we make the selection? 16!/4!12! = 1820   If we are to select 4 people from 8 couples WITH restriction that no married couple can both make it to the group, only a representative?   8!/4!4! = 70   But we know that to select a person from each couple, take 2 possibilities     70*2*2*2*2= 
<gadget id="calculator">  70*2*2*2*2</gadget>
<output>1_120</output>
1120   Probability= Desired/All Possibilities = 1120/1820 = 8/13   Answer: 8/13
<result>C</result>
If 4 people are selected from a group of 8 married couples, what is the probability that none of them would be married to each other?