C and D work at a hospital with 4 other workers. For an internal review, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that C and D will both be chosen?  Choose the correct choice
A) A)1/3  B) B)1/4  C) C)1/15  D) D)3/8  E) E)2/3
Total number of people = 6   Probability of selecting 1/15 first and then D is 1/6∗1/5=1/30   Probability of selecting D first and then 1/15 is 1/6∗1/5=1/30   Therefore probability of selecting 1/15and D for the review is 1/30+1/30=1/15   Answer is 1/15
<result>C</result>
C and D work at a hospital with 4 other workers. For an internal review, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that C and D will both be chosen?