In a box, there are 3 blue, 4 white and 6 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?	Choose the correct choice from the following answers:
A) 3/16 B) 5/16 C) 6/13 D) 6/15 E) 9/32
Total number of bulbs = (3 + 4 + 6)= 
<gadget id="calculator">(3 + 4 + 6)</gadget>
<output>13</output>
13.   Let E= event that the bulb drawn is neither white nor blue = event that the bulb drawn is yellow.   Therefore, P(E)=6/13   ANSWER:6/13
<result>C</result>
In a box, there are 3 blue, 4 white and 6 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?