Find a 5-digit integer whose value is equal to the sum of the factorials of its own digits. Options
A) 40585	B) 41585	C) 42585	D) 44585	E) 30585
factorial values from 0 to 9   0!=1   1!=1   2!=2   3!=6   4!=24   5!=120   6!=720   7!=5040   8!=40320   9!=362880 now given that it is a 5 digit number   so we can eliminate 9! from the count.   but   0-9 numbers can be arranged in 5 digit numbers in 9x9x9x9x9=59049(if repetition)   If not:   9x8x7x6x5=15120   by crosscheck we can eliminate numbers with 1,2,3,6,7,8,9 numbers in twice or thrice or more   40585   4!+0!+5!+8!+5!= 24 + 1 + 120 + 40320 + 120= 
<gadget id="calculator">24 + 1 + 120 + 40320 + 120</gadget>
<output>40_585</output>
40585   40585NSWER:40585
<result>A</result>
Find a 5-digit integer whose value is equal to the sum of the factorials of its own digits.