There are 12 balls in a bag; 8 are blue balls and the other 4 are yellow balls. If 3 balls are to be selected at random from the 12 balls, what is the probability that at least one of the yellow ball will be selected?	Pick one
A) 57/55  B) 56/55  C) 54/55  D) 53/55  E) 52/55
Total probability=1254/553=220   854/553 +854/552*454/551+854/551*454/552=56+112+48= 
<gadget id="calculator">56+112+48</gadget>
<output>216</output>
216   therefore the probability that at least one of the yellow ball will be selected= 216/220=54/55   answer is 54/55
<result>C</result>
There are 12 balls in a bag; 8 are blue balls and the other 4 are yellow balls. If 3 balls are to be selected at random from the 12 balls, what is the probability that at least one of the yellow ball will be selected?