If there are eight varieties of ice cream to be tasted and judged in a competition, what is the probability that black currant is tasted before Vanilla and Vanilla is tasted before chocolate, although not necessarily consecutively?	Options
A) 1/8!
B) 3!/8!
C) 5!/8!
D) 1/3!
E) 1/2!
8 flavors are too much. Lets try out only 3 flavors --&gt; Black Currant, Vanilla, Chocalate   We can get Black Currant before Vanilla and Vanilla before Chocolate in only 1 way.   Probability = Possible/Total = 1/3!   Now lets consider 4 flavors --&gt; BC, Van, Choc and X   Possibilities --&gt; 1) BC, X, Van, Choc   2) X, BC, Van, Choc   3) BC, Van, Choc, X   4) BC, Van, X, Choc   Probability = 4/24 = 1/3!   Since the probability remains the same for both the cases, the probability will mostly remain true for the 8 varieties too.   Answer: 1/3!
<result>D</result>
If there are eight varieties of ice cream to be tasted and judged in a competition, what is the probability that black currant is tasted before Vanilla and Vanilla is tasted before chocolate, although not necessarily consecutively?