If A is to be chosen at random from the set {56,85,41} and B is to be chosen at random from the set {1,2,3,4,5}, what is the probability that AB will be odd? Pick one
A) 4/15  B) 13/15  C) 56/15  D) 6/15  E) 8/15
Method-1   A13/15 will be odd when   1) A is odd and 13/15 is even, Probability of A odd is (2/3) and Probability of 13/15 even is (2/5), so Probability of Case(1) = (2/3)*(2/5) = (4/15)   2) A is even and 13/15 is odd, Probability of A even is (1/3) and Probability of 13/15 odd is (3/5), so Probability of Case(2) = (1/3)*(3/5) = (3/15)   3) A is odd and 13/15 is odd, Probability of A odd is (2/3) and Probability of 13/15 odd is (3/5), so Probability of Case(1) = (2/3)*(3/5) = (6/15)   Total Favorable Probability = (4/15)+(3/15)+(6/15) = (13/15)   Answer: option 13/15
<result>B</result>
If A is to be chosen at random from the set {56,85,41} and B is to be chosen at random from the set {1,2,3,4,5}, what is the probability that AB will be odd?