If n is a natural number, then (6n2 + 6n) is always divisible by: Choices:  A) 6 only  B) 6 and 12 both  C) 12 only  D) by 18 only  E) None
EXPLANATION   (6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.   Answer 6 and 12 both
<result>B</result>
If n is a natural number, then (6n2 + 6n) is always divisible by: