Let p be a prime number greater than 2, and let N = 32p. How many odd divisors does N have?	Answers:
A) 1 B) 2 C) 3 D) 4 E) 5
The answer is A, there is exactly one. Since is the largest (and only) even prime number, any p larger than 2 is odd. Then since 32 = 2*2*2*2, all of which are even, this means that p must be the only odd prime factor.
<result>A</result>
Let p be a prime number greater than 2, and let N = 32p. How many odd divisors does N have?