A teacher will pick a group of 9 students from a group of 14 students that includes Bart and Lisa. If one of all the possible 9-student groups is picked at random, what is the probability of picking a group that includes both Bart and Lisa?
Choose the correct choice from the following options.
A) 11/70 B) 36/91 C) 21/47 D) 121/390 E) 3/71
Probability = Favorable Outcomes / Total Outcomes   Total Outcomes= Total No. of ways of Picking Group of 9 out of 14 = 14C9 = 14! / (9! * 5!) = 2002   Favorable Outcomes= Total No. of ways of Picking Group of 9 out of 14 such that B and L are always in the group (i.e. we only have to pick remaining two out of remaining 12 as 36/91 and L must be there is group) = 12C7 = 792   Hence,Probability=792/2002=36/91   Answer: Option 36/91
<result>B</result>
A teacher will pick a group of 9 students from a group of 14 students that includes Bart and Lisa. If one of all the possible 9-student groups is picked at random, what is the probability of picking a group that includes both Bart and Lisa?