If G is to be chosen at random from the set {5,8,7,1} and K is to be chosen at random from the set {14,8,3}, what is the probability that GK will be even?  Answers:
A) 1 B) 5 C) 8 D) 4 E) 3
Method-1   GK will be even when   1) G is even and K is odd, Probability of G even is (1/4) and Probability of K odd is (1/3), so Probability of Case(1) = (1/4)*(1/3) = (1/12)   2) G is Odd and K is Even, Probability of G Odd is (3/4) and Probability of K Even is (2/3), so Probability of Case(2) = (3/4)*(2/3) = (6/12)   3) G is even and K is Even, Probability of G even is (1/4) and Probability of K Even is (2/3), so Probability of Case(1) = (1/4)*(2/3) = (2/12)   Total Favorable Probability = (1/12)+(6/12)+(2/12) = (12/12)= 
<gadget id="calculator">(12/12)</gadget>
<output>1</output>
1   1nswer: option 1
<result>A</result>
If G is to be chosen at random from the set {5,8,7,1} and K is to be chosen at random from the set {14,8,3}, what is the probability that GK will be even?