The product of n^2 consecutive positive integers is always divisible by	Choose the correct choice:
A) n^2 -1 B) (n+1)! C) 2n +1 D) n^2 + 1 E) n!
Plug in some vlues and check -   Product of first 2 number is 2*1   Product of first 3 number is 3*2*1   Product of first 4 number is 4*3*2*1   Product of first 5 number is 5*4*3*2*1   So, The product of first n natural numbers is always divisible by n! , answer will be (n^2 -1)
<result>A</result>
The product of n^2 consecutive positive integers is always divisible by