Revenues were recorded for Store A and Store B over a period of three months. In the first month, Store A's revenues were $45,000 higher than Store B's revenues. In the second month, Store A's revenues were $8,000 higher than Store B's revenues. If Store A's average (arithmetic mean) monthly revenue for the three months was $2,000 greater than Store B's average monthly revenue, then Store B's revenue in the third month was how much greater than Store A's revenue?  Choose the correct choice from the following answers:  A) $14,000  B) $15,000  C) $42,000  D) $47,000  E) $50,000
Answer: CIt may be tempting to come up with a lot of variables, one each for each month's revenue for each company. However, focus on the differences. In the first month, the difference was +45 in favor of A. (Note that we can drop the thousands since every number in the question is in terms of thousands.) In the second, the difference was +8 in favor of A. The average was +2 in favor of A. With these numbers, use the average formula to find the third month (T):   (45 + 8 + T)/3 = 2   53 + T = 6   T = -47   Since positive numbers indicate a difference in favor of A, negative numbers are in favor of B. -47 represents a $47,000 advantage in favor of Store B. Choice ($47,000) is correct.
<result>D</result>
Revenues were recorded for Store A and Store B over a period of three months. In the first month, Store A's revenues were $45,000 higher than Store B's revenues. In the second month, Store A's revenues were $8,000 higher than Store B's revenues. If Store A's average (arithmetic mean) monthly revenue for the three months was $2,000 greater than Store B's average monthly revenue, then Store B's revenue in the third month was how much greater than Store A's revenue?