find the remainder (32)^33^34 when divided by 11?
Pick one.
A) 9 B) 10 C) 11 D) 12 E) 13
unit digit of 33^34 = 9 i.e odd no.   (32)^33^34 / 11   = (11*3-1)^(-------9) / 11   = (-1)^(odd) / 11   = -1/10   =&gt; rem = -1+11= 
<gadget id="calculator">-1+11</gadget>
<output>10</output>
10   ANSWER:10
<result>B</result>
find the remainder (32)^33^34 when divided by 11?