If X and Y are positive integers such that (3X + 7Y) is a multiple of 11, then which of the following will be divisible by 11?	Options
A) 4X + 6Y  B) X + Y + 4  C) 9X + 4Y  D) 4X - 9Y  E) 9X - 4Y
by hit and trail, we put X = 5 and Y = 1 so that (3X + 7Y)   = ((3*5) + (7*1))= 
<gadget id="calculator">((3*5) + (7*1))</gadget>
<output>22</output>
22, which is divisible by 11   (4X + 6Y)= 4*5 + 6*1= 
<gadget id="calculator">4*5 + 6*1</gadget>
<output>26</output>
26, which is not divisible by 11   (X + Y + 4)= (5 + 1 + 4)= 
<gadget id="calculator">(5 + 1 + 4)</gadget>
<output>10</output>
10, which is not divisible by 11   (9X + 4Y)= (9*5 + 4*1)= 
<gadget id="calculator">(9*5 + 4*1)</gadget>
<output>49</output>
49 which is not divisible by 11   (4X - 9Y)= (4*5 - 9*1)= 
<gadget id="calculator">(4*5 - 9*1)</gadget>
<output>11</output>
11 which is divisible by 11   (9X - 4Y)= (9*5 - 4*1)= 
<gadget id="calculator">(9*5 - 4*1)</gadget>
<output>41</output>
41 which is not divisible by 11   So the Answer is 4X - 9Y
<result>D</result>
If X and Y are positive integers such that (3X + 7Y) is a multiple of 11, then which of the following will be divisible by 11?