In how many ways can the letters D, G, G, I, T be arranged so that the two I's are not next to each other?  Choose the correct choice:
A) 36  B) 48  C) 72  D) 96  E) 128
1 D   2 I   1 G   1 T   Number of ways these letters can be arranged = 5!/2! (2! to account 2 same Is) = 60   Consider 2 Is as 1 entity and thus the number of arrangements for (GG)DIT = 4! = 24   Total allowed cases = 60-24= 
<gadget id="calculator">60-24</gadget>
<output>36</output>
36   36 is the correct answer.
<result>A</result>
In how many ways can the letters D, G, G, I, T be arranged so that the two I's are not next to each other?