A person jogged 10 times along the perimeter of a rectangular field at the rate of 12 kilometers per hour for 30 minutes. If field has a length that is twice its width, find the area of the field in square meters. Pick
A) 56,000 square meters
B) 32,000 square meters
C) 65,000 square meters
D) 20,000 square meters
E) 43,000 square meters
Let us first find the distance d jogged   distance = rate * time = (12 km / hr)* 30 minutes   = (12 km/hr) * 0.5 hr = 6 km   The distance of 6 km corresponds to 10 perimeters and therefore 1 perimeter is equal to   6 km / 10 = 0.6 km = 0.6 * 1000= 
<gadget id="calculator">0.6 * 1000</gadget>
<output>600</output>
600 meters   Let L and W be the length and width of the field. The length is twice the width. Hence   L= 2 W   The perimeter is 600 meters and is given by   2 (L + W) = 600   Substitute L by 2 W   2 (2 W + W) = 600   Simplify and solve for W   4 W + 2 W = 600   6 W = 600   W = 100   Find L   L = 2 W = 200   Find the area A of the rectangle   A = L * W = 200 * 100 = 20,000 square meters correct answer 20,000 square meters
<result>D</result>
A person jogged 10 times along the perimeter of a rectangular field at the rate of 12 kilometers per hour for 30 minutes. If field has a length that is twice its width, find the area of the field in square meters.