The sum of three consecutive multiples of 3 is 117. What is the largest number? Select:
A) 45 B) 48 C) 51 D) 42 E) 54
Let the numbers be 3x, 3x + 3 and 3x + 6.   Then,   3x + (3x + 3) + (3x + 6) = 117   9x = 108   x = 12   Largest number = 3x + 6 = 42   Answer : 42
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The sum of three consecutive multiples of 3 is 117. What is the largest number?