In a diving competition, each diver has a 40% chance of a perfect dive. The first perfect dive of the competition, but no subsequent dives, will receive a perfect score. If Janet is the third diver to dive, what is her chance of receiving a perfect score? (Assume that each diver can perform only one dive per turn.)	Select the correct option:
A) 1/5
B) 1/15
C) 4/25
D) 18/125
E) 61/125
Probability = Favourable Outcomes / Total Outcomes = 1 - (Unfavourable Outcomes / Total Outcomes)   Given:Probability of Perfect dive = 0.4 = 40/100 = 2/5   i.e. Probability of Non-Perfect dive = 0.6 = 60/100 = 3/5   The probability of Janet to dive and get a perfect score depends on that other other previous two dives must be Imperfect   Method-1:   i.e. Probability of First two being Imperfect and Third being Perfect dive = (3/5)*(3/5)*(2/5) =18/125   18/125
<result>D</result>
In a diving competition, each diver has a 40% chance of a perfect dive. The first perfect dive of the competition, but no subsequent dives, will receive a perfect score. If Janet is the third diver to dive, what is her chance of receiving a perfect score? (Assume that each diver can perform only one dive per turn.)