If 4b^4 − 41b^2 + 100 = 0, then what is the sum of the two greatest possible values of b ?  Choose the correct choice from the following:
A) 4	B) 9/2	C) 7	D) 41/4	E) 25
just forget about the value of b^4 for the moment and let b^2= X. (its better to work with power of 2 than 4)   now we have equation as 4x^2 -41x +100 =0, factoring them gives us 4X^2 -16x -25x +100 =0. which can be solved as (4x-25)(x-4) , so x= 4 and 25/4.   so b^2 = 4 and 25/4   so b= +2 and minus 2 and +5/2 and minus 5/2   The two greatest values are +2 and +5/2. so their sum 2+5/2 =9/2 = 9/2
<result>B</result>
If 4b^4 − 41b^2 + 100 = 0, then what is the sum of the two greatest possible values of b ?