Ages of two persons differ by 14 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age  Pick
A) 12,28	B) 13,27	C) 16,32	D) 18,34	E) 19,34
Explanation:   Let the age of younger person is x,   Then elder person age is (x+14)   =&gt; 3(x-6) = (x+14-6) [6 years before]   =&gt; 3x-18 = x+8   =&gt; x = 13   So other person age is x + 14 = 27   Answer: Option 13,27
<result>B</result>
Ages of two persons differ by 14 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age