A focus group is currently made up of x men and y women. If 2 men and 4 women are added to the group, and if one person is selected at random from the larger focus group, then what is the probability that a man is selected?
Select the correct option.
A) x/(x + 2)  B) x/(x + y)  C) (x + 2)/(x + y + 2)  D) (y + 4)/(x + y + 6)  E) (x + 2)/(x + y + 6)
x men   y women   x+2+y+4 is the total   =x+y+6   x+2 is the number of men   so (x + 2)/(x + y + 6)   E. (x + 2)/(x + y + 6)
<result>E</result>
A focus group is currently made up of x men and y women. If 2 men and 4 women are added to the group, and if one person is selected at random from the larger focus group, then what is the probability that a man is selected?