3/x + 3x = 3(x-9)
Choose one
A) -9
B) -1/6
C) -1/9
D) 1/9
E) 9
We can solve - expand the right side, multiply by x on both sides and then subtract away the 3x^2 terms:   (3/X) + 3x = 3(x-9)   (3/x) + 3x = 3x - 18   3 + 3x^2 = 3x^2 - 18x   3 = -18x   -1/6 = x   and to confirm, you can plug that answer back into the original equation to see that it makes the left and right sides equal.   -1/6
<result>B</result>
3/x + 3x = 3(x-9)