A box contains 20 balls, numbered from 1 to 20. If three balls are selected at random and with replacement from the box, what is the probability that the sum of the three numbers on the balls selected from the box will be odd?	Pick one.
A) 1/4 B) 3/8 C) 1/2 D) 5/8 E) 3/4
I don't think order matters in this case, because 2 + 2 + 1 = 2 + 1 + 2   My answer is: 1/4   1/4
<result>A</result>
A box contains 20 balls, numbered from 1 to 20. If three balls are selected at random and with replacement from the box, what is the probability that the sum of the three numbers on the balls selected from the box will be odd?