The length of each side of square A is increased by 100 percent to make square B. If the length of the side of square B is increased by 25 percent to make square C, by what percent is the area of square C greater than the sum of the areas of squares A and B?	Choose the correct choice from the following answers.
A) 75%  B) 25%  C) 10%  D) 45%  E) 180%
Let length of each side of square A be 10   Area of A = 10^2 = 100   Since , length of each side of square A is increased by 100 percent to make square B   length of each side of square B = 2*10= 
<gadget id="calculator">2*10</gadget>
<output>20</output>
20   Area of B= 20^2 = 400   Since , length of the side of square B is increased by 25 percent to make square C   length of each side of square C= 1.25*20= 
<gadget id="calculator">1.25*20</gadget>
<output>25</output>
25   Area of C= 25^2 = 625   45%ifference in areas of C and cummulative areas of A and B = 625 -(400+100) = 225   percent is the area of square C greater than the sum of the areas of squares A and B = (225/500) * 100= 
<gadget id="calculator">(225/500) * 100</gadget>
<output>45</output>
45%   Answer 45%
<result>D</result>
The length of each side of square A is increased by 100 percent to make square B. If the length of the side of square B is increased by 25 percent to make square C, by what percent is the area of square C greater than the sum of the areas of squares A and B?