3 balls are drawn randomly from a bag contains 3 black, 5 red and 4 blue balls. What is the probability that the balls drawn contain balls of different colors?
Choose the correct choice from the following options.
A) 1/3	B) 1/2	C) 2/11	D) 3/11	E) 11/13
Total number of balls = 3 + 5 + 4= 
<gadget id="calculator">3 + 5 + 4</gadget>
<output>12</output>
12   Let S be the sample space.   n(S)= Total number of ways of drawing 3 balls out of 12 = 12C3   Let E = Event of drawing 3 different coloured balls   To get 3 different coloured balls,we need to select one black ball from 3 black balls,   one red ball from 5 red balls, one blue ball from 4 blue balls   Number of ways in which this can be done = 3C1 × 5C1 × 4C1   i.e., n(E) = 3C1 × 5C1 × 4C1   P(E) = n(E)/n(S)=3C1×5C1×4C1/12C3   =3×5×4/(12×11×10/3×2×1)=3×5×4/2×11×10=3×4/2×11×2=3/11   ANSWER:3/11
<result>D</result>
3 balls are drawn randomly from a bag contains 3 black, 5 red and 4 blue balls. What is the probability that the balls drawn contain balls of different colors?