A rectangular block has the dimensions 5x6x7 cm it is dropped into a cylindrical vessel of radius 6cm and height 10 cm. If the level of the fluid in the cylinder rises by 4 cm, What portion of the block is immersed in the fluid ?	Choices:
A) 22/7 x 24/35
B) 22/7 x 36 x 4
C) 22/7 x 36/5
D) 22/7 x 37/21
E) 22/7 x 32/21
Explanation:   Since level of water increased in cylinder by height 4.   This is because of the rectangular block .   Therefore , area of rectangular block immersed in water is = 22/7 x (6)^2 x 4   Thats why portion of block immersed in water is= (22/7 x 36 x 4) / total vol. of rectangle   = (22/7 x 36 x 4)/(7x5x6)   = 22/7 x 24/35.   22/7 x 24/35NSWER IS 22/7 x 24/35
<result>A</result>
A rectangular block has the dimensions 5x6x7 cm it is dropped into a cylindrical vessel of radius 6cm and height 10 cm. If the level of the fluid in the cylinder rises by 4 cm, What portion of the block is immersed in the fluid ?