A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 6, 4 and 3, which can be repeated. If the product of the digits in the area code must be even, how many different codes can be created?  Pick one:	A) 20	B) 22	C) 26	D) 24	E) 30
Total # of codes possible is 3*3*3= 
<gadget id="calculator">3*3*3</gadget>
<output>27</output>
27. Oit of those 27 codes only the product of 333 and will be odd, the remaining 26 will have either 2 or 4 in them, which ensures that their product will be even. Therefore the number of codes where the product of the digits is even= (total) - (restriction) = 27 - 1= 
<gadget id="calculator">27 - 1</gadget>
<output>26</output>
26.   Answer: 26
<result>C</result>
A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 6, 4 and 3, which can be repeated. If the product of the digits in the area code must be even, how many different codes can be created?