Three unbiased coins are tossed. What is the probability of getting at most two heads?
Choices: A) 3/4 B) 1/4 C) 3/8 D) 7/8 E) 5/8
Explanation:   Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}   Let E = event of getting at most two heads.   Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.   P(E) =n(E)/n(S)= 7/8	.   ANSWER : 7/8
<result>D</result>
Three unbiased coins are tossed. What is the probability of getting at most two heads?