Find the smallest number of five digits exactly divisible by 32,40,56 and 64.
Choose the correct choice.
A) 11020  B) 11030  C) 11040  D) 11060  E) 11080
Smallest number of five digits is 10000.   Required number must be divisible by L.C.M. of 32,40,56,64 i.e 2240,   On dividing 10000 by 2240,we get 1200 as remainder.   Therefore, Required number = 10000 +( 2240 â€“ 1200 ) = 11040.   Answer is 11040.
<result>C</result>
Find the smallest number of five digits exactly divisible by 32,40,56 and 64.