If a = 1 and b = -2, then (2a^2 + b)(m + y) + (a + b)(m - y) =	Options:  A) 0  B) 2x  C) y - m  D) x - y  E) x + y
Putting A=1 and B = -2 =&gt; 2A^2-B=0 ; so the first part of the term is zero   with second term =&gt; (1-2) *(m+y)=y-m =&gt; Smash y - m
<result>C</result>
If a = 1 and b = -2, then (2a^2 + b)(m + y) + (a + b)(m - y) =