Three unbiased coins are tossed. What is the probability of getting all tails?	Choose the correct choice
A) 7/8	B) 1/2	C) 3/8	D) 1/4	E) 1/8
Let, H --&gt; Head , T --&gt; Tail   Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}   Let 1/8 = event of getting two heads   Then 1/8 = {TTT}   P(1/8) = n(1/8)/n(S) =1/8
<result>E</result>
Three unbiased coins are tossed. What is the probability of getting all tails?