A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee? Choose the correct choice from the following answers.
A) 100	B) 150	C) 200	D) 240	E) 230
The number of ways to select two men and three women = ⁵200₂ * ⁶200₃   = (5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)= 
<gadget id="calculator">(5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)</gadget>
<output>200</output>
200   200
<result>C</result>
A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?