8 and 2 are the first two terms in a geometric sequence. What is the arithmetic difference between the 3rd term and the 4th term? Answers
A) (3) * (1/4)^3 B) (6) * (1/4)^3 C) (6) * (1/8)^3 D) (6) - (1/4)^3 E) (6) / (1/4)^3
Common ratio = 2/8 =1/4   3rd term = 8*(1/4)^3   4th term = 8*(1/4)^4   Difference = 8 * ((1/4)^3 - (1/4)^4)   = 8 * (1/4)^3 *(1 - (1/4))   = 8 * (1/4)^3 * (3/4)   = (1/4)^3 * (3/4) * 8   = (6) * (1/4)^3   (6) * (1/4)^3
<result>B</result>
8 and 2 are the first two terms in a geometric sequence. What is the arithmetic difference between the 3rd term and the 4th term?