In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?  Choices:
A) 1/3	B) 2/3	C) 1/4	D) 1/5	E) 2/5
Total number of balls = (8 + 7 + 6)= 
<gadget id="calculator">(8 + 7 + 6)</gadget>
<output>21</output>
21.   Let E= event that the ball drawn is neither red nor green   = event that the ball drawn is blue.   n(E) = 7   =&gt;7/21 = 1/3   1/3NSWER 1/3
<result>A</result>
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?