Given two sets X = {1,1,8,8,9,9} and Y = {0,1}, if one number is chosen from each set at random, what is the probability that the sum of both numbers is an even number  Choose one.
A) 1/5	B) 1/3	C) 1/6	D) 1/4	E) 1/2
One way to look at it:   The number from set X can be ANYTHING.   The number selected from set Y will determine whether the sum is odd or even.   For example, if a 8 is selected from set X, we need a 0 from set Y to get an even sum.   If a 9 is selected from set X, we need a 1 from set Y to get an even sum.   And so on.   So, P(sum is even) = P(select ANY number from set X ANDselect the number from set Y that makes the sum even)   = P(select ANY number from set X)xP(select the number from set Y that makes the sum even)   = 1x1/2   = 1/2   = 1/2
<result>E</result>
Given two sets X = {1,1,8,8,9,9} and Y = {0,1}, if one number is chosen from each set at random, what is the probability that the sum of both numbers is an even number