The sum of all two digit numbers divisible by 4 is
Choices.
A) 1242
B) 1542
C) 1742
D) 1610
E) 1842
Required numbers are 12,16,20 . . . . . 96   This is an A.P. in which a=12,d=4 and l=96.   Let the number of terms in it be n.Then t=96   So a+(n-1)d=96.   12+(n-1)*6=96,   12+4n-4=96   4+4n=96   4n=96-4= 
<gadget id="calculator">96-4</gadget>
<output>92</output>
92/4= 
<gadget id="calculator">92/4</gadget>
<output>23</output>
23.   Required sum=n/2(a+l)   =23/2(12+96)   =1242   1242nswer is 1242
<result>A</result>
The sum of all two digit numbers divisible by 4 is