Jack, Jill, and Sandy each have one try to make a basket from half court. If their individual probabilities of making the basket are 1/6, 1/7, and 1/8 respectively, what is the probability that Jack and Sandy will make a basket but Jill will miss?
Select the correct option.
A) 1/8	B) 3/8	C) 3/28	D) 5/28	E) 1/56
The probability that Jack and Sandy will make a basket but Jill will miss is 1/6*6/7*1/8=1/56.   The answer is 1/56.
<result>E</result>
Jack, Jill, and Sandy each have one try to make a basket from half court. If their individual probabilities of making the basket are 1/6, 1/7, and 1/8 respectively, what is the probability that Jack and Sandy will make a basket but Jill will miss?