Revenues were recorded for Store A and Store B over a period of three months. In the first month, Store A's revenues were $40,000 higher than Store B's revenues. In the second month, Store A's revenues were $10,000 higher than Store B's revenues. If Store A's average (arithmetic mean) monthly revenue for the three months was $2,000 greater than Store B's average monthly revenue, then Store B's revenue in the third month was how much greater than Store A's revenue?	Choose the most appropriate option
A) $14,000 B) $15,000 C) $44,000 D) $46,000 E) $50,000
Answer: CIt may be tempting to come up with a lot of variables, one each for each month's revenue for each company. However, focus on the differences. In the first month, the difference was +40 in favor of A. (Note that we can drop the thousands since every number in the question is in terms of thousands.) In the second, the difference was +10 in favor of A. The average was +2 in favor of A. With these numbers, use the average formula to find the third month (T):   (40 + 10 + T)/3 = 2   50 + T = 6   T = -44   Since positive numbers indicate a difference in favor of A, negative numbers are in favor of B. -44 represents a $44,000 advantage in favor of Store B. $44,000hoice ($44,000) is correct.
<result>C</result>
Revenues were recorded for Store A and Store B over a period of three months. In the first month, Store A's revenues were $40,000 higher than Store B's revenues. In the second month, Store A's revenues were $10,000 higher than Store B's revenues. If Store A's average (arithmetic mean) monthly revenue for the three months was $2,000 greater than Store B's average monthly revenue, then Store B's revenue in the third month was how much greater than Store A's revenue?