Jill is dividing her six-person class into two teams of equal size for a basketball game. If no one will sit out, how many different match-ups between the two teams are possible?  Choices
A) 10 B) 25 C) 126 D) 252 E) 630
With 6 players, the process of figuring out how many groups of 3 can be formed is pretty straight-forward....   6C3 = 6!/(3!3!) = 20 possible groups of 3   Once forming that first group of 3, the remaining 3 players would all be placed on the second team by default.   The 'twist' is that the two teams of 3 canshow upin either order:   10
<result>A</result>
Jill is dividing her six-person class into two teams of equal size for a basketball game. If no one will sit out, how many different match-ups between the two teams are possible?