What two-digit number is less than the sum of the square of its digits by 11 and exceeds their doubled product by 4?  Pick one:
A) 95	B) 99	C) 26	D) 73	E) None of the Above
Let the digits be x and y. The number would be 10x + y.   We are given that 2xy + 4 = 10x +y = x^2 y^2 -11   Thus 2xy +4 = x^2 + y^2 - 11   x^2 + y^2 -2xy = 16   (x-y)^2 = 16   (x-y) = 4 or -4   Substituting the values of (x-y) in the equation 2xy +5 = 10x + y   x comes out to be 1 or 9... thus the two numbers can be 26 or 98   Thus the answer is 26
<result>C</result>
What two-digit number is less than the sum of the square of its digits by 11 and exceeds their doubled product by 4?