A set consists of 12 numbers, all are even or multiple of 5. If 7 numbers are even and 14 numbers are multiple of 5, how many numbers is multiple of 10?
Select
A) 0 B) 1 C) 2 D) 3 E) 9
{Total} = {Even} + {Multiple of 5} - {Both} + {Nether}.   Since{Neither}=0(allare even or multiple of 5) then:   12 = 7 + 14 - {Both} + 0;   {Both}=9(so 1 number is both even AND multiple of 5, so it must be a multiple of 10).   Answer: 9.
<result>E</result>
A set consists of 12 numbers, all are even or multiple of 5. If 7 numbers are even and 14 numbers are multiple of 5, how many numbers is multiple of 10?