What is the greatest value of n such that 18^n is a factor of 17! ? Select:
A) 1 B) 2 C) 3 D) 4 E) 5
Another way to solve this question :   We know that 18 = 2 *3^2.   Hence, we need to find total number of 3s in 18! ( As out of 3 and 2 , we will have count of 3 least)   No. of 3s = 18/3= 
<gadget id="calculator">18/3</gadget>
<output>6</output>
6/3= 
<gadget id="calculator">6/3</gadget>
<output>2</output>
2.   Add the numbers in Bold, you will get total number of 3s= 8.   Hence, total number of 3^2 = 8/2= 
<gadget id="calculator">8/2</gadget>
<output>4</output>
4.   Hence, answer is 3. 3
<result>C</result>
What is the greatest value of n such that 18^n is a factor of 17! ?