A , B and C are standing on a circular track of 4300m such that A and C are diametrically opposite and B is in between A and C .There clockwise order are ABC , B and C runs clockwise while A runs anti-clockwise .If the speed of A B and C are 5m/s , 8m/s and 10m/s respectively . They all start running at 10:00 AM. calculate the distance covered by B when A and C meet for the first time after 10:05AM .  Select the correct option.
A) 3240 metres	B) 3440 metres	C) 3640 metres	D) 4440 metres	E) 2440 metres
Relative speed of A &amp; C will be.. 15 m/s.. hence for first they will meet at   2150/15= 143.33 sec (around 2min 23sec).. so time will be 10:02:23..this case will not be considered as it is before 10:05.. Again they will meet at   4300/15=286.66 sec(around 4min 46sec).. time will be 10:07:10.. this case will be considered   Hence in 7min10 sec i.e 430   In 430sec 3440 metres will cover  430*8= 
<gadget id="calculator"> 430*8</gadget>
<output>3_440</output>
3440 metres   ANSWER:3440 metres
<result>B</result>
A , B and C are standing on a circular track of 4300m such that A and C are diametrically opposite and B is in between A and C .There clockwise order are ABC , B and C runs clockwise while A runs anti-clockwise .If the speed of A B and C are 5m/s , 8m/s and 10m/s respectively . They all start running at 10:00 AM. calculate the distance covered by B when A and C meet for the first time after 10:05AM .