For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum of all the even integers between 1 and 100?  Choose the correct choice from the following answers:
A) 1250	B) 1530	C) 2120	D) 2540	E) 2550
Average of the set: (largest+smallest)/2=(100+2)/2= 
<gadget id="calculator">(100+2)/2</gadget>
<output>51</output>
51;   # of terms: (largest-smallest)/2+1=(100-2)/2+1= 
<gadget id="calculator">(100-2)/2+1</gadget>
<output>50</output>
50   The sum= 51*50= 
<gadget id="calculator">51*50</gadget>
<output>2_550</output>
2550   Answer: 2550
<result>E</result>
For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum of all the even integers between 1 and 100?