In the quadratic equation ax2 - 11x + 40 = 0, if the sum of two roots is 1.1, what is the product of the two roots?	Choices:
A) 4 B) 4.2 C) 8 D) 9 E) None of these
Explanation:   The sum of the roots of the quadratic equation ax2 - bx + c = 0 are (-b/a) and the product of the roots are (c/a).   Thus, in the equation ax2 - 11x + 40 = 0, where a = a, b = - 11 and c = 40.   we get, sum of the roots = - (- 11) / a = 1.1   a = 11 / 1.1= 
<gadget id="calculator">11 / 1.1</gadget>
<output>10</output>
10   Product of the roots= 40 / 10= 
<gadget id="calculator">40 / 10</gadget>
<output>4</output>
4   4NSWER: 4
<result>A</result>
In the quadratic equation ax2 - 11x + 40 = 0, if the sum of two roots is 1.1, what is the product of the two roots?