Midas has boxes in three sizes: large, medium, and small. He puts 11 large boxes on a table. He leaves some of these boxes empty, and in all the other boxes he puts 8 medium boxes. He leaves some of these medium boxes empty, and in all the other medium boxes he puts 8 (empty) small boxes. Now, 102 of all the boxes on the table are empty.
How many boxes has Midas used in total?	Options:
A) 113	B) 114	C) 115	D) 116	E) 117
By keeping 8 boxes in a single box, the total number of empty boxes increases by  8-1= 
<gadget id="calculator"> 8-1</gadget>
<output>7</output>
7.   let x the number of times that 8 boxes have been kept in a box   now we know that 11 + 7x= 102   by solving we have x=13   finally 11 + 13 × 8 = 115   therefore totally 115 boxes have been used   ANSWER:115
<result>C</result>
Midas has boxes in three sizes: large, medium, and small. He puts 11 large boxes on a table. He leaves some of these boxes empty, and in all the other boxes he puts 8 medium boxes. He leaves some of these medium boxes empty, and in all the other medium boxes he puts 8 (empty) small boxes. Now, 102 of all the boxes on the table are empty.
How many boxes has Midas used in total?