A number when divided by D leaves a remainder of 8 and when divided by 3D leaves a remainder of 21 . What is the remainder left, when twice the number is divided by 3D? Select.
A) 13	B) 12	C) 3	D) 2	E) 42
making eqn as per the question   a=Dx+8......1   a=3Dy+21....2   multiplying 3 in eqn 1 we get eqn 3   3a=3Dx+24....3   a=3Dy+21......2   now subtract 2 from 3 we get..   2a=3D(x-y)+3   so here's the remainder we got is 3   ANSWER:3
<result>C</result>
A number when divided by D leaves a remainder of 8 and when divided by 3D leaves a remainder of 21 . What is the remainder left, when twice the number is divided by 3D?