In a hotel, 60% had vegetarian lunch while 30% had non-vegetarian lunch and 15% had both type of lunch. If 96 people were present, how many did not eat either type of lunch ?
Options:  A) 27  B) 26  C) 25  D) 24  E) 20
Explanation:   n(A)=(60/100âˆ—96)=288/5   n(B)=(30/100âˆ—96)=144/5   n(Aâˆ©B)=(15100âˆ—96)=72/5   People who have either or both lunch n(AâˆªB)=288/5+144/5âˆ’72/5   =360/5= 
<gadget id="calculator">360/5</gadget>
<output>72</output>
72   So People who do no have either lunch were= 96 -72= 
<gadget id="calculator">96 -72</gadget>
<output>24</output>
24   ANSWER IS 24
<result>D</result>
In a hotel, 60% had vegetarian lunch while 30% had non-vegetarian lunch and 15% had both type of lunch. If 96 people were present, how many did not eat either type of lunch ?