Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is Options: A) 1 B) 3 C) 4 D) 0 E) 2
4 points are possible in which 1 point is the incentre of the circle and other 3 are excentres   ANSWER:4
<result>C</result>
Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is