What is the probability that a 4 person committee chosen at random from a group consisting of 6 men, 4 women, and 5 children contains exactly 1 woman?  Choose one: A) 44/91 B) 77/832 C) 11/77 D) 308/1411 E) 22/832
Total possible selections = 4 out of 15 group members = 15C4   Favorable selections = 1 out of 4 women and 3 out of 11 (= 6 men + 5 children) = 4C1 * 11C3   Thus the required probability = 4C1*11C3 / 15C4 = 44/91. Thus 44/91 is the correct answer.
<result>A</result>
What is the probability that a 4 person committee chosen at random from a group consisting of 6 men, 4 women, and 5 children contains exactly 1 woman?