In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term. What is the sum of the 13th, 13th, and 15th terms in the sequence?  Choose the correct choice:
A) 2^18  B) 3(2^17)  C) 7(2^16)  D) 3(2^16)  E) 7(2^12)
the sequence comes out to be 2^0,2^1,2^2,2^3 and so on...   so 13th term will be 2^12   14th term 2^13   15th term 2^14   adding all three   we get   2^12+(2^12)*2+(2^12)*4   so answer is 2^15(1+2+4)=&gt;7(2^12)   answer 7(2^12)
<result>E</result>
In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term. What is the sum of the 13th, 13th, and 15th terms in the sequence?