Divide 71 into 2 parts such that 1 part exceeds the other by 8. What are the 2 no.'s in that part?
Pick.
A) 27	B) 29	C) 31	D) 32	E) 37
Let $let n$ be the smaller and 71 - n be the larger number. Now, since the larger number exceeds the smaller number by 7, we can form the equation   larger number – smaller number = 7   which is equivalent to   Simplifying, we have 71 - 2n = 7. This gives us 2n = 78 which implies that the larger number is . The smaller is 71-39=31.   31
<result>C</result>
Divide 71 into 2 parts such that 1 part exceeds the other by 8. What are the 2 no.'s in that part?