In how many ways can 16 different gifts be divided among four children such that each child receives exactly three gifts?
Choose the correct choice from the following choices: A) 16^4 B) (4!)^4 C) 16!/(3!)^4 D) 16!/4! E) 4^16
Total 16 different Gifts, and 4 children.   Thus any one child gets 16C3 gifts,   then the other child gets 13C3 gifts(16 total - 3 already given),   then the third one gets 10C3 gifts,   and the last child gets 7C3 gifts.   Since order in which each child gets the gift is not imp, thus, ans :   1616!/(3!)^43 * 1316!/(3!)^43 * 1016!/(3!)^43 * 716!/(3!)^43 = 16! / (3!)^4   Ans : 16!/(3!)^4.
<result>C</result>
In how many ways can 16 different gifts be divided among four children such that each child receives exactly three gifts?