Meg and Bob are among the 8 participants in a cycling race. If each participant finishes the race and no two participants finish at the same time, in how many different possible orders can the participants finish the race so that Meg finishes ahead of Bob?  Choose one:	A) 2400	B) 3000	C) 20160	D) 9000	E) 1200
Total # of ways the race can be finished is 8!. In half of the cases Meg finishes ahead of Bob and in other half Bob finishes ahead of Meg. So, ways Meg to finish ahead of Bob is 8!/2=20160.   Answer: 20160.
<result>C</result>
Meg and Bob are among the 8 participants in a cycling race. If each participant finishes the race and no two participants finish at the same time, in how many different possible orders can the participants finish the race so that Meg finishes ahead of Bob?