At a reception, one-third of the guests departed at a certain time. Later two-fifths of the guests departed. Even later two-thirds of the remaining guests departed. If six people were left, how many were originally present at the party?  Choose the most appropriate option:	A) 28	B) 37	C) 20	D) 45 people	E) 27
Explanation:   Let Original members be x   First One third guest departed i.e x/3   Remaining guests = x – (x/3) = 2x/3   Now from the remaining (2x/3) two-fifths departed = 2/5(2x/3) = 4x/15   i.e. Now remaining guests will be (2x/3 – 4x/15) = 2x/5   Now from remaining (2x/5) two-thirds departed = 2/3(2x/5) = 4x/15   Now remaining guests = (2x/5 – 4x/15) = 2x/15   Given 2x/15 = 6 ⇒ x = 45   Answer: 45 people
<result>D</result>
At a reception, one-third of the guests departed at a certain time. Later two-fifths of the guests departed. Even later two-thirds of the remaining guests departed. If six people were left, how many were originally present at the party?