The sum of three consecutive even numbers is 246. What are the numbers?
Options
A) 80,82,84
B) 65,68,71
C) 45,47,42
D) 100,102,49
E) 87,88,89
First x Make the first x   Second x+2 Even numbers, sowe add 2 to get the next   Third x+4 Add 2more (4 total) to get the third   F +S +T =246 SummeansaddFirst (F)plusSecond(S)plusThird(T)   (x)+(x+2)+(x+4)=246 Replace each F , S, and T withwhatwe labeled them   x+x+2+x+4=246 Here the parenthesis are not needed   3x+6=246 Combine like terms x+x+x and 2+4   −6 −6 Subtract 6 fromboth sides   3x=240 The variable ismultiplied by 3   3 3 Divide both sides by 3   x=80 Our solution for x   First 80 Replace x in the origional listwith 80.   Second  (80)+2= 
<gadget id="calculator"> (80)+2</gadget>
<output>82</output>
82 The numbers are 80, 82, and 84.   Third ( 80)+4= 
<gadget id="calculator">( 80)+4</gadget>
<output>84</output>
84   correct answer 80,82,84
<result>A</result>
The sum of three consecutive even numbers is 246. What are the numbers?