A shop produces sarongs. The daily average production is given by 5n + 20, where n is the number of workers aside from the owner. In the first k days, 500 units are produced, and then 5 workers are added to the team. After another k days, the cumulative total is 1200. How many workers were part of the latter production run?	Pick one:
A) A)6
B) B)14
C) C)11
D) D)15
E) E)23.5
The daily average production is given by 5n + 20- given   In the first k days, 500 units are produced   = (5n+20)K =500   k = 500/5n+20...................................1   5 workers were added = 5(n+5)+20 = 5n +45   cumulative is 1200 .. thus for the current period = 1200 -500= 
<gadget id="calculator">1200 -500</gadget>
<output>700</output>
700   (5n+45)K= 700   k = 700/5n+45........................................2   equate 1 and 2   500/5n+20 = 700 /5n+45   500(5n+45) = 700(5n+20)   25n + 225 = 35n + 140   -10n = -85   n = 8.5   thus n+5 = 14   hence 14
<result>B</result>
A shop produces sarongs. The daily average production is given by 5n + 20, where n is the number of workers aside from the owner. In the first k days, 500 units are produced, and then 5 workers are added to the team. After another k days, the cumulative total is 1200. How many workers were part of the latter production run?