Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution?  Choices.
A) 6:4
B) 6:14
C) 4:4
D) 4:6
E) 3:7
let:   x = ounces taken from solution A (20% salt)   y = ounces taken from solution B (80% salt)   to prepare 50 ounce 50% salt.   first equation is simple:   x + y = 50   to get another equation so as to be able to solve, compute salt contents.   20% of x + 80% of y = 50% of 50 or   x/5 + 4/5 * y = 25 or   x+4y = 125   solve two equations to get:   x = 25   y = 25   so solutions has to mix in   1:1 oops 4:4   ANSWER:4:4
<result>C</result>
Solution A is 20% salt and Solution B is 80% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution?