The sum of first three terms of the Geometric sequence is 13/12 and their product is -1. Find the common ratio  Choices:
A) 3/4  B) -3/4  C) 4/3  D) 1/2  E) 1/8
We make the first three terms is of a/r, a, ar   Whose sum=a(1/r+1+r)=13/12   Their product = a3=-1   Hence, (3r+4)(4r+3)=0   r=-3/4 or -4/3   ANSWER -3/4 -3/4
<result>B</result>
The sum of first three terms of the Geometric sequence is 13/12 and their product is -1. Find the common ratio