Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Children A & B must sit next to each other, and child C must be somewhere to the right of A & B. How many possible configurations are there for the children?  Choose the correct choice from the following options.
A) 600	B) 720	C) 1440	D) 4320	E) 4800
First, consider the restriction of A &amp; B. As with problem #1 above, there are 12 possibilities for A &amp; B, counting both position and order.   Now, put the other five in any order — that’s 120 possibilities, for a total number of configurations of 1440. That number does not take into account the restriction with C.   Think about those 1440 configurations. In exactly half of them, C will be to the right of A &amp; B, and exactly half, C will be to the left of A &amp; B. Therefore, in  (1/2)*1440= 
<gadget id="calculator"> (1/2)*1440</gadget>
<output>720</output>
720 configurations, C will be to the right of A &amp; B.   Answer= 720
<result>B</result>
Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Children A & B must sit next to each other, and child C must be somewhere to the right of A & B. How many possible configurations are there for the children?