If (|p|!)^p=|p|!, which of the following could be the value(s) of p ?
Options
A) -1 B) 0 C) 1 D) -1 and 1 E) -1, 0, and 1
Test Values   A. -1 ==&gt; |−1|−1=|−||! ==&gt; 1/1= 
<gadget id="calculator">1/1</gadget>
<output>1</output>
1==&gt; -1 is valid   B. 0 ==&gt; |0|!0=|0|! ==&gt; 1^0 ==&gt; 1=1 ==&gt; 0 is valid   C. 1 ==&gt; 1^1 ==&gt; 1 is valid   D. -1 and 1   E. -1, 0, and 1   Answer:-1, 0, and 1
<result>E</result>
If (|p|!)^p=|p|!, which of the following could be the value(s) of p ?