10 years ago, the average age of a family of 4 members was 24 years. Two children having been born (with age diference of 2 years), the present average age of the family is the same. The present age of the youngest child is ?	Select the correct option.
A) 7 years  B) 5 years  C) 3 years  D) 4 years  E) 2 years
Explanation:   Total age of 4 members, 10 years ago = (24 x 4) years = 96 years.   Total age of 4 members now = [96 + (10 x 4)] years = 136 years.   Total age of 6 members now = (24 x 6) years = 144 years.   Sum of the ages of 2 children = (144 - 136)= 
<gadget id="calculator">(144 - 136)</gadget>
<output>8</output>
8 years.   Let the age of the younger child be years.   Then, age of the elder child= years.   So,   Age of younger child = 3 years.   Answer: 3 years
<result>C</result>
10 years ago, the average age of a family of 4 members was 24 years. Two children having been born (with age diference of 2 years), the present average age of the family is the same. The present age of the youngest child is ?