The present ages of three persons are in the proportion of 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages.
Answers:
A) 20,35,45
B) 8,20,28
C) 16,28,36
D) 16,28,46
E) None of these
Let the present ages of three persons be 4K,7K and 9K respectively.   (4K - 8) + (7K - 8) + (9K - 8) = 56   20K = 80   K = 4   Therefore, then present ages are 16,28,36.   ANSWER:16,28,36
<result>C</result>
The present ages of three persons are in the proportion of 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages.