In how many different number of ways a combination of 3 persons can be selected from 4 men and 2 women?
Options
A) 160
B) 180
C) 200
D) 210
E) 220
6C3 × 5C2   6C3   = 6!/(3! . 3!)   = (6 × 5 × 4)/(3 × 2)   = 5 × 4 = 20.   5C2   = 5!/(3! . 2!)   = 5 × 2 = 10   = 20 × 10 = 200.   200)
<result>C</result>
In how many different number of ways a combination of 3 persons can be selected from 4 men and 2 women?