What is the probability of getting at least one six in a single throw of three unbiased dice?	Choose the correct choice from the following answers:	A) 1/6	B) 125/216	C) 1/36	D) 81/216	E) 91/216
Find the number of cases in which none of the digits show a '6'.   i.e. all three dice show a number other than '6', 5 * 5 *5 = 125 cases.   Total possible outcomes when three dice are thrown = 216.   The number of outcomes in which at least one die shows a '6' = Total possible outcomes when three dice are thrown - Number of outcomes in which none of them show '6'.   = 216 - 125= 
<gadget id="calculator">216 - 125</gadget>
<output>91</output>
91.   The required probability= 91/216.   ANSW91/216R:91/216
<result>E</result>
What is the probability of getting at least one six in a single throw of three unbiased dice?