A shopkeeper first raises the price of Jewellery by x% then he decreases the new price by x%. After such up down cycle, the price of a Jewellery decreased by Rs. 21025. After a second up down cycle the Jewellery was sold for Rs. 484416. What was the original price of the jewellery.2 Choices.
A) Rs. 5,26,000  B) Rs. 6,00,625  C) Rs. 525625  D) Rs. 5,00,000  E) None of these
Solution: Let the initial price = Rs. 10000P   price after first increment = 10000P + 100xP.   price after first decrement = 10000P + 100xP - (100Px+Px2) = 10000P - Px2.   Now, total decrement,   Px2 = 21025 .............. (1)   price after second increment,   10000P - Px2 + 100xP - Px3/100   price after second increment,   10000P - P2 + 100xP - P3/100 - 100xP + Px3/100 - Px2 + Px4/10000   = 10000P -2Px2+Px2/10000 = 484416 ............... (2)   on solving equation equn (1) and (2), We get   x = 20.   substituting back we get,   P = 52.5625   Therefore   Answer: Option Rs. 525625
<result>C</result>
A shopkeeper first raises the price of Jewellery by x% then he decreases the new price by x%. After such up down cycle, the price of a Jewellery decreased by Rs. 21025. After a second up down cycle the Jewellery was sold for Rs. 484416. What was the original price of the jewellery.2