A bakery currently has 7 pies and 4 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies?
Choose the correct choice.
A) 3/11
B) 5/11
C) 14/33
D) 29/77
E) 36/77
The total number of ways to choose 5 from 11 is 11C5 = 462.   The number of ways that include 3 pies is 7C3*4C2 = 35*6= 
<gadget id="calculator">35*6</gadget>
<output>210</output>
210   P(exactly 3 pies)= 210/462 = 5/11   The answer is 5/11.
<result>B</result>
A bakery currently has 7 pies and 4 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies?