Boston is 4 hr ahead of Frankfurt and 2 hr behind India. X leaves Frankfurt at 6 p.m. on Friday and reaches Boston the next day. After waiting there for 2 hr, he leaves exactly at noon and reaches India at 1 a.m. On his return journey, he takes the same route as before, but halts at Boston for 1hr less than his previous halt there. He then proceeds to Frankfurt.
What is X's average speed for the entire journey (to and fro)?	Pick.
A) 176 mph  B) 180 mph  C) 165 mph  D) Data insufficient  E) None of these
Explanation :   X reaches Boston at 10 AM. At the same moment, time in Frankfurt is 6 AM. Hence, the journey time was 12 hours.   X reaches India at 1 AM. At the same moment, time in Boston is 11 PM. Hence, the journey time was 11 hours.   Waiting time = 2 hours.   So, total time = 12 + 2 + 11= 
<gadget id="calculator">12 + 2 + 11</gadget>
<output>25</output>
25 hours.   Avg speed= 180 mph .   Answer : 180 mph
<result>B</result>
Boston is 4 hr ahead of Frankfurt and 2 hr behind India. X leaves Frankfurt at 6 p.m. on Friday and reaches Boston the next day. After waiting there for 2 hr, he leaves exactly at noon and reaches India at 1 a.m. On his return journey, he takes the same route as before, but halts at Boston for 1hr less than his previous halt there. He then proceeds to Frankfurt.
What is X's average speed for the entire journey (to and fro)?