If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be: Pick:
A) 4 days  B) 5 days  C) 6 days  D) 8 days  E) 2 days
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.   Then, 6x + 8y =1/10	and 26x + 48y =1/2   Solving these two equations, we get : x =1/100 and y =1/200   (15 men + 20 boy)'s 1 day's work =(15/100+20/200)	=1/4	.   15 men and 20 boys can do the work in 4 days.   4 daysNSWER:4 days
<result>A</result>
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be: