If two letters are taken at random from the word HOME, what is the probability that none of the letters would be vowels?	Choose one
A) 1/3	B) 1/2	C) 1/6	D) 1/8	E) 1/9
Explanation :   P(first letter is not vowel)=2/4P(second letter is not vowel)=1/3So,probability that none of letters would be vowels is =(2/4)x(1/3)=1/6   Answer : 1/6
<result>C</result>
If two letters are taken at random from the word HOME, what is the probability that none of the letters would be vowels?