In a candy dish the ratio of red to yellow candies is 2:5, the ratio of red to green candies is 3:8, and the ratio of yellow ot blue candies is 9:2.what is the maximum total number Q of yellow and green candies combined if the maximum combined number of red and blue candies is fewer than 85?
Choose the correct choice from the following answers:
A) 144
B) 189
C) 234
D) 279
E) 309
Given that Red is to yellow is 2:5, Red is to green is 3:8 and Yellow is to blue is 9:2.   Therefore, the total number of red, yellow, blue and green balls will be 18x, 45x, 10x and 48x respectively, where x is a constant.   If the combined number of red and blue balls is fewer than 85, i.e. max 84 balls, then the maximum number of yellow and green balls will be 279.   (10x+18x) &lt; 85.   28x &lt; 85, i.e. 28x &lt;= 84 (Since number of balls cannot be in fraction). Thus, x&lt;=3.   (45x+48x) = 93x.   Max (93x) Q(45 +48 )= 
<gadget id="calculator">(45 +48 )</gadget>
<output>93</output>
93x.   Max (93x) Q= 279.   Answer is 279.
<result>D</result>
In a candy dish the ratio of red to yellow candies is 2:5, the ratio of red to green candies is 3:8, and the ratio of yellow ot blue candies is 9:2.what is the maximum total number Q of yellow and green candies combined if the maximum combined number of red and blue candies is fewer than 85?