Consider the sequence of numbers beginning 23, 27, 28, 32, 33... It continues in such a way that by adding 5 to the nth term, one obtains the (n + 2)th term. What is the sum of the first 17 members of this sequence? Pick one:
A) 878
B) 900
C) 743
D) 928
E) 1022
I would split them up like this.   23 28 33 and so on (9 terms)....the 9th term = 23+8*5= 
<gadget id="calculator">23+8*5</gadget>
<output>63</output>
63   27 32 37 and so on (8 terms)......the 8th term= 27+7*5= 
<gadget id="calculator">27+7*5</gadget>
<output>62</output>
62   Since the distance between any two numbers is the same we can use arithmetics   first+last/2 times no of numbers= the sum   (23+63)/2 * 9= 
<gadget id="calculator">(23+63)/2 * 9</gadget>
<output>387</output>
387   (27+62)/2 * 8= 
<gadget id="calculator">(27+62)/2 * 8</gadget>
<output>356</output>
356= 743   743
<result>C</result>
Consider the sequence of numbers beginning 23, 27, 28, 32, 33... It continues in such a way that by adding 5 to the nth term, one obtains the (n + 2)th term. What is the sum of the first 17 members of this sequence?