In a box, there are 3 blue, 7 white and 4 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?  Pick.
A) 4/14 B) 5/16 C) 8/32 D) 2/32 E) 9/32
Total number of bulbs = (3 + 7 + 4)= 
<gadget id="calculator">(3 + 7 + 4)</gadget>
<output>14</output>
14.   Let E= event that the bulb drawn is neither white nor blue = event that the bulb drawn is yellow.   Therefore, P(E)=4/14   4/14NSWER:4/14
<result>A</result>
In a box, there are 3 blue, 7 white and 4 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?