1/(2-√3)=?  Answers:
A) 9+4√5
B) 9-4√5
C) 9+2√5
D) 2+√3
E) 4+9√5
This question requires us to rationalize (fix) the denominator.   For more on this technique, seehttps://www.gmatprepnow.com/module/gmat ... video/1044   Given: 1/(2-√3)   Multiply top and bottom by the CONJUGATE of 2-√3, which is 2+√3   So, 1/(9-4√5) = (1)(9+4√5)/(9-4√5)(9+4√5)   2+√3
<result>D</result>
1/(2-√3)=?