An amount of Rs. 10000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 3/4 %, then the amount invested at 11% was? Select the correct option: A) 2377 B) 3750 C) 2997 D) 2677 E) 1987
Let the sum invested at 9% be Rs. x and that invested at 11% be Rs. (10000 - x). Then,   (x * 9 * 1)/100 + [(10000 - x) * 11 * 1]/100 = (10000 * 39/4 * 1/100)   (9x + 110000 - 11x)/100 = 3900/4= 
<gadget id="calculator">3900/4</gadget>
<output>975</output>
975   (9x + 110000 - 11x)= 97500   x = 6250   Sum invested at 9% = Rs. 6250   Sum invested at 11% = Rs. (10000 - 6250) = Rs. 3750.   Answer: 3750
<result>B</result>
An amount of Rs. 10000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 3/4 %, then the amount invested at 11% was?