A jar contains only red, yellow, and orange marbles. If there are 3 red, 7 yellow, and 4 orange marbles, and 3 marbles are chosen from the jar at random without replacing any of them, what is the probability that 2 yellow, 1 red, and no orange marbles will be chosen?
Select.
A) 1/60	B) 1/45	C) 2/45	D) 3/22	E) 5/22
I started by finding the 2 probabilities, without calculation, like this:   P(YYR)   P(YRY)   P(RYY)   I calculated the first one and ended in 1/22. I looked at the answer choices at this point and saw answer D: 5/22.   This helped me realise that for the 3 possible orderings the probabbility is the same. So, it should be (1/22)*(5), which indeed is 5/22.   5/22
<result>E</result>
A jar contains only red, yellow, and orange marbles. If there are 3 red, 7 yellow, and 4 orange marbles, and 3 marbles are chosen from the jar at random without replacing any of them, what is the probability that 2 yellow, 1 red, and no orange marbles will be chosen?