Kevin, David, and Catherine each try independently to solve a problem. If their individual probabilities for success are 1/2, 2/9 and 3/4, respectively, what is the probability all three will solve the problem?	Select
A) 1/12 B) 1/8 C) 1/3 D) 1/4 E) 1/6
P(Kevin will solve)= 1/2   P(David will solve)= 2/9   P(Catherine will solve) = 3/4   P= (1/2)*(2/9)*(3/4) = 6/72 = 1/12   1/12nswer:1/12
<result>A</result>
Kevin, David, and Catherine each try independently to solve a problem. If their individual probabilities for success are 1/2, 2/9 and 3/4, respectively, what is the probability all three will solve the problem?