In how many ways, a committee of 5 members can be selected from 6 men and 5 ladies, consisting of 3men and 2 ladies?  Answers.
A) 75
B) 152
C) 175
D) 200
E) 212
(3 men out 6) and (2 ladies out of 5) are to be chosen   Required number of ways = (6C3 * 5C2) = 200   Answer is 200
<result>D</result>
In how many ways, a committee of 5 members can be selected from 6 men and 5 ladies, consisting of 3men and 2 ladies?