What is the probability of getting a sum of 12 when rolling 3 dice simultaneously?
Choose the correct choice from the following choices:
A) 10/216
B) 12/216
C) 21/216
D) 23/216
E) 25/216
Sum of 12 can be achieved in following ways   6,5,1---Total cases = 3! = 6   6,4,2---Total cases = 3!= 6   6,3,3---Total cases = 3!/2! = 3   5,5,2---Total cases = 3!/2! = 3   5,4,3---Total cases = 3! = 6   4,4,4---Total cases = 3!/3! = 1   Total cases 3 /3= 
<gadget id="calculator">3 /3</gadget>
<output>1</output>
1   Total cases= 25   Probability = 25 * (1/6 * 1/6 * 1/6) = 25/216   ANSW25/216R:25/216
<result>E</result>
What is the probability of getting a sum of 12 when rolling 3 dice simultaneously?