A bowl was filled with 10 ounces of water, and 0.006 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period?
Choose the correct answer
A) 0.004%
B) 0.04%
C) 0.40%
D) 3%
E) 40%
Total amount of water evaporated each day during a 50-day period = .006 * 50   =.006 * 100/2   = .6/2= 
<gadget id="calculator">.6/2</gadget>
<output>0.3</output>
.3   percent of the original amount of water evaporated during this period= (.3/10) * 100= 
<gadget id="calculator">(.3/10) * 100</gadget>
<output>3</output>
3 %   Answer 3%
<result>D</result>
A bowl was filled with 10 ounces of water, and 0.006 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period?