what is the sum of all the 4 digit numbers that can be formed using all of the digits 2,3,5 and 7?  Choose one
A) 113323  B) 113322  C) 114322  D) 113321  E) 112322
Actually there is the direct formula for this kind of problems.   1. Sum of all the numbers which can be formed by using the n digits without repetition is: (n-1)!*(sum of the digits)*(111…..n times).   2. Sum of all the numbers which can be formed by using the n digits (repetition being allowed) is: n^{n-1}*(sum of the digits)*(111…..n times).   so as per question:(4-1)!*(2+3+5+7)*1111=113322   ANSWER:113322
<result>B</result>
what is the sum of all the 4 digit numbers that can be formed using all of the digits 2,3,5 and 7?