How many different arrangements of letters are possible if three letters are chosen from the letters A through J and the letters E and A must be among the letters selected? Choices:
A) 36 B) 39 C) 42 D) 45 E) 48
Besides A and E, there are 8 letters and we can choose one of them.   8C1 = 8   Three letters can be arranged in 3! ways.   The number of arrangements is 8*3! = 48   The answer is 48.
<result>E</result>
How many different arrangements of letters are possible if three letters are chosen from the letters A through J and the letters E and A must be among the letters selected?