The equation x = 2y^2 + 5y - 18, describes a parabola in the xy coordinate plane. If line l, with slope of 3, intersects the parabola in the upper-left quadrant at x = -5, the equation for l is
Select the correct option
A) 3x + y - 20 = 0  B) y - 3x - 11 = 0  C) -3x + y - 15 = 0  D) -2x - y - 7 = 0  E) -3x + y + 13.5 = 0
The question is made to look difficult though it is pretty simple if you focus on just the line and use process of elimination. (Remember that GMAT does not focus on parabolas so basically, the question should be quite do-able even if someone doesn't know how to handle parabolas.)   The line has a point (-5, y) on it where y is positive (since the point lies in upper left quadrant).   In options B ,C D and E, if you put x = -5, you get -ve value for y co-ordinate. So ignore them.   3x + y - 20 = 0nswer must be (3x + y - 20 = 0)
<result>A</result>
The equation x = 2y^2 + 5y - 18, describes a parabola in the xy coordinate plane. If line l, with slope of 3, intersects the parabola in the upper-left quadrant at x = -5, the equation for l is