A coin is weighted so that the probability of heads on any flip is 0.2, while the probability of tails is 0.8. If the coin is flipped 5 times independently, which of the following represents the probability that tails will appear no more than twice?
Choose the correct choice from the following options: A) (0.2)^5 + 5(0.2)^4(0.8) + 10(0.2)^3(0.8)^2 B) (0.3)^5 + 4(0.3)^4(0.8) + 6(0.3)^3(0.8)^2 C) (0.3)^5 + 3(0.3)^4(0.8) + 2(0.3)^3(0.8)^2 D) (0.3)^5 + 2(0.3)^4(0.8) + (0.3)^3(0.8)^2 E) (0.6)^5 + (0.6)^4(0.4) + (0.6)^3(0.4)^2
Probability of Head, P(H) = 0.2   Probability of Tail, P(T) = 0.8   Tail will appear NO more than twice   i.e. favourable cases   2 Tails and 3 Heads, Probability = 5C2*(0.2)^3*(0.8)^2   1 Tail and 4 Heads, Probability = 5C1*(0.2)^4*(0.8)^2   0 Tail and 5 Heads, Probability = (0.2)^5   Required Probability = Sum of all Favourable cases = (0.2)^5 + 5(0.2)^4(0.8) + 10(0.2)^3(0.8)^2   (0.2)^5 + 5(0.2)^4(0.8) + 10(0.2)^3(0.8)^2nswer: option (0.2)^5 + 5(0.2)^4(0.8) + 10(0.2)^3(0.8)^2
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A coin is weighted so that the probability of heads on any flip is 0.2, while the probability of tails is 0.8. If the coin is flipped 5 times independently, which of the following represents the probability that tails will appear no more than twice?