7 people, A, B, C, D, E, F and H, go to a movie and sit next to each other in 8 adjacent seats in the front row of the theatre. In how many different arrangements will there be at least one person between A and F?
Choose the correct choice from the following options
A) 8! - 7!2	B) 5! - 7!2	C) 6! - 7!2	D) 8! - 6!2	E) 8! - 9!2
We need to find at least one person between A and F which is equal to Total ways - No one between A and F   Eight people can be arranged in 8! ways.   No one between A and F is equal to 7!*2! (consider A and F as one. 7 people can be arranged in 7! and 8! - 7!2 and F in 2!)   So, total ways = 8! - 7!2   8! - 7!2NS:8! - 7!2
<result>A</result>
7 people, A, B, C, D, E, F and H, go to a movie and sit next to each other in 8 adjacent seats in the front row of the theatre. In how many different arrangements will there be at least one person between A and F?