A number was divided successively in order by 4,5,6 the remainder was respectively 2,3,4 the numbers are? Choose the correct choice from the following answers:
A) 1	B) 2	C) 3	D) 4	E) 8
let x=6q+3   then x^2=(6q+3)^2=6(6q^2+6q+1)+3   thus the remainder is 3   The Answer is(3)
<result>C</result>
A number was divided successively in order by 4,5,6 the remainder was respectively 2,3,4 the numbers are?