What is the sum of all possible solutions to |x - 3|^2 + |x - 3| = 12 ?	Pick one:
A) 5 B) 6 C) 7 D) 8 E) 9
Denote |x - 3| as y: y^2 + y = 12 --&gt; y = -4 or y = 3. Discard the first solution since y = |x - 3|, so it's an absolute value and thus cannot be negative.   y = |x - 3| = 3 --&gt; x = 6 or x = -1. The sum = 5.   5nswer: 5.
<result>A</result>
What is the sum of all possible solutions to |x - 3|^2 + |x - 3| = 12 ?