The number of ways in which ten candidates A1, A2, ...., A10 can be ranked so that A1 is always above A2 is Choose the correct choice from the following:  A) 10!⁄2  B) 10!  C) 9!  D) 8!⁄2  E) None of these
Ten candidates can be ranked in 10! ways. In half of these ways A1 is above A2 and in another half A2 is above A1.   So, required number of ways is 10!⁄2   10!⁄2nswer 10!⁄2
<result>A</result>
The number of ways in which ten candidates A1, A2, ...., A10 can be ranked so that A1 is always above A2 is