How many different 9 digit numbers can be formed from the number 223355888 by re-arranging its digits so that the odd digits occupy even position?	Choose the correct choice from the following answers:
A) 22
B) 776
C) 26
D) 28
E) 60
Odd places are 4 and these are occupied by 3355. So this can be done in 4!/ (2! 2!) = 6   There are 5 even numbers which have to be placed at 5 odd places. So 5!/(2!3!) = 10 ways   so total number of ways of arranging all these numbers are  10 * 6= 
<gadget id="calculator"> 10 * 6</gadget>
<output>60</output>
60 ways   Answer:60
<result>E</result>
How many different 9 digit numbers can be formed from the number 223355888 by re-arranging its digits so that the odd digits occupy even position?