By using the numbers 1, 2, 3, 5 and 9 only once, how many five digit numbers can be made that are divisible by 25?	Options.
A) 0
B) 1
C) 4
D) 8
E) 6
A number to be divisible by 25 must end with 00, 25, 50, or 75.   So, there are the following cases possible:   139-25 --&gt; the first three digits can be arranged in 3=6 ways.   Total = 6.   Answer: 6.
<result>E</result>
By using the numbers 1, 2, 3, 5 and 9 only once, how many five digit numbers can be made that are divisible by 25?