Let f(x) = x^2 + bx + c. If f(1) = 0 and f(-8) = 0, then f(x) crosses the y-axis at what y-coordinate? Choose the correct choice
A) -8	B) -1	C) 0	D) 1	E) 8
When x = 1 and when x = -8, the expression f(x) = x² + bx + c equals 0.   Then f(x) = (x-1)(x+8)   f(0) = -8   The answer is -8.
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Let f(x) = x^2 + bx + c. If f(1) = 0 and f(-8) = 0, then f(x) crosses the y-axis at what y-coordinate?