Of the 80 electronics components that a factory must manufacture, 60 percent would be most e¢ ciently manufactured by Machine A and the remaining 40 percent would be most efficiently manufactured by Machine B, though either machine could manufacture any of the 80 components. If 60 percent of the components were manufactured by Machine A and the remainder were manufactured by Machine B, what is thehighest possible number of components that were manufactured by the machine that would manufacture them the most efficiently?
Select the correct option:	A) 80	B) 32	C) 33	D) 35	E) 36
A can manufacture 60 % of 80 efficiently, which is 48.   B can manufacure 40 % of 80 efficiently, which is 32.   Now 60 % of 80 are produced by A. This means 48 parts. Since A can produce 48 efficiently, all 48 are produced efficiently. Rest (32) is produced by B, which can produce max. 32 parts efficiently.   Hence parts that were produced efficiently = 32+48= 
<gadget id="calculator">32+48</gadget>
<output>80</output>
80. (80).
<result>A</result>
Of the 80 electronics components that a factory must manufacture, 60 percent would be most e¢ ciently manufactured by Machine A and the remaining 40 percent would be most efficiently manufactured by Machine B, though either machine could manufacture any of the 80 components. If 60 percent of the components were manufactured by Machine A and the remainder were manufactured by Machine B, what is thehighest possible number of components that were manufactured by the machine that would manufacture them the most efficiently?