On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?  Select:
A) 33 1/3 %
B) 40%
C) 50%
D) 60%
E) 66 2/3%
Let the total # of passengers be 100.   Now, 20 passengers held round-trip tickets AND cars.   As 60% of the passengers with round-trip tickets did not take their cars then 40% of the passengers with round-trip tickets did take their cars, so # of passengers with round-trip tickets AND cars is 40% of the passengers with round-trip tickets.   If we take # of the passengers with round trip tickets to be xx then we'll have 0.4x=200.4x=20 --&gt; x=50x=50.   Answer: 50%.
<result>C</result>
On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?