The average price of 10 oranges is Rs. 12 while the average price of 8 of these oranges is Rs. 11.75. Of the remaining two oranges, if the price of one orange is 50% more than the price of the other, what is the price of each of these two oranges?
Select the correct option:
A) Rs 5, Rs 7.50  B) Rs 10.4, Rs 15.6  C) Rs 10, Rs 16  D) Rs 12, Rs 14  E) None of these
Explanation :   Total price of the two oranges = Rs. [(12 x 10) (11.75 x 8)]   = Rs. (120 - 94) = Rs. 26.   Let the price of one orange be Rs. x.   Then, the price of other orange = Rs. (x + 50% of x) = Rs. x + 1/2x = Rs. 3x/2   So, x + 3x/2 = 26   5x = 52   x = 10.4   The prices of the two oranges are Rs. 10.4 and Rs. 15.6   Answer : Rs 10.4, Rs 15.6
<result>B</result>
The average price of 10 oranges is Rs. 12 while the average price of 8 of these oranges is Rs. 11.75. Of the remaining two oranges, if the price of one orange is 50% more than the price of the other, what is the price of each of these two oranges?