The larger of two negative consecutive even integers 2t and 2(t-1) is multiplied by 7 and then added to the smaller of the two original integers. Which of the following represents this operation?
Choose the most appropriate option:
A) 16t-2
B) 8t-2
C) -2
D) 3
E) -2-4t^2
larger of 2t-2, 2t (when they are negative) is 2t. the smallest of 2t and 2t-2 when they are positive is 2t-2.   therefore 7* 2t + 2t-2 = 16t-2.   option 16t-2.
<result>A</result>
The larger of two negative consecutive even integers 2t and 2(t-1) is multiplied by 7 and then added to the smaller of the two original integers. Which of the following represents this operation?