Tough and Tricky questions: Combinations.
Six students - 3 Girls and 3 boys - are to sit side by side for a makeup exam. How many ways could they arrange themselves given that no two boys and no two girls can sit next to one another? Choose the correct choice:
A) 12
B) 72
C) 34
D) 240
E) 520
Six students - 3 boys and 3 girls - are to sit side by side for a makeup exam. How many ways could they arrange themselves given that no two boys and no two girls can sit next to one another?   A) 12   B) 36   C) 72   D) 240   E) 720   The boys (B) and girls(G) can either be arranged as BGBGBG or GBGBGB.   Within the arrangement BGBGBG or GBGBGB, the boys can be arranged 3! ways and girls can be arranged 3! ways.   Therefore total number of ways boys and girls can be arranged = 2*3!*3!= 72 ways   Answer:72
<result>B</result>
Tough and Tricky questions: Combinations.
Six students - 3 Girls and 3 boys - are to sit side by side for a makeup exam. How many ways could they arrange themselves given that no two boys and no two girls can sit next to one another?