A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money N did Bob receive?	Select:
A) 20
B) 22
C) 24
D) 26
E) 52
Notice that we need not consider Ann's portion in the solution. We can just let K = the money REMAINING after Ann has received her portion and go from there.   Our equation will use the fact that, once we remove Bob's portion, we have $32 for Chloe.   So, we getK - Bob's $ = 32   Bob received 4 dollars plus one-third of what remained   Once Bob receives $4, the amount remaining is K-4 dollars. So, Bob gets a 1/3 of that as well.   1/3 of K-4 is (K-4)/3   So ALTOGETHER, 22ob receives4 + (K-4)/3   So, our equation becomes:K -[4 + (K-4)/3 ]= 32   Simplify to get: K - 4 - (K-4)/3 = 32   Multiply both sides by 3 to get: 3K - 12 - K + 4 = 96   Simplify: 2K - 8 = 96   Solve: K = 52   Plug this K-value intoK - 22ob's $ = 32to get: 52 - 22ob's $ = 32   So, 22ob's $ N= 20   Answer:   22
<result>B</result>
A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money N did Bob receive?