In how many ways can 16 different gifts be divided among four children such that each child receives exactly two gifts?
Choose one
A) 16^4
B) (4!)^4
C) 16!/(2!)^4
D) 16!/2!
E) 4^16
Total 16 different Gifts, and 4 children.   Thus any one child gets 16C2 gifts,   then the other child gets 14C2 gifts(16 total - 2 already given),   then the third one gets 12C2 gifts,   and the last child gets 10C2 gifts.   Since order in which each child gets the gift is not imp, thus, ans :   1616!/(2!)^42 * 1416!/(2!)^42 * 1216!/(2!)^42 * 1016!/(2!)^42 = 16! / (2!)^4   16!/(2!)^4
<result>C</result>
In how many ways can 16 different gifts be divided among four children such that each child receives exactly two gifts?