If after 600 grams of water were added to the 24%-solution of alcohol, the strength of the solution decreased by one-third, how much of the 24%-solution was used? Pick:
A) 180 grams
B) 220 grams
C) 250 grams
D) 350 grams
E) 1200 grams
I too think 1200 grams should be the answer.   My reasoning is   The h20 content in 200 gms of water is 1   h20 content in 24% solution is 0.76   Resulting new solution's concentration decreases by one third means. Now it becomes 16% solution which means h20 content is 0.84   Let amount of solution be X   Then the equation can be set up   600*1 + 0.76X = 0.84 (X+600)   0.08X = 96   8X = 9600   X = 1200 (ANS 1200 grams)
<result>E</result>
If after 600 grams of water were added to the 24%-solution of alcohol, the strength of the solution decreased by one-third, how much of the 24%-solution was used?