If the tens digit of positive integer x is 2 and the tens digit of positive integer y is 2, how many possible values of the tens digit of 2(x+y) can there be? Choose the correct choice from the following choices
A) 2	B) 3	C) 4	D) 5	E) 6
We only need to consider the tens and ones digits of x and y, and the last two digits can be represented as 20 + p and 20 + q respectively.   2(20+p+20+q)= 80 + 2(p + q)   2(p+q) can range from 0 up to a maximum value of 36 when p=q=9.   Then the tens and ones digits of 2(x+y) can range from 80 up to 16.   That is, the tens digit can be 8, 9, 0, or 1.   There can be 4 possibilities for the tens digit.   The answer is 4.
<result>C</result>
If the tens digit of positive integer x is 2 and the tens digit of positive integer y is 2, how many possible values of the tens digit of 2(x+y) can there be?