Suppose f(x) is an odd function for which f(x + 2) = f(x) for all x, and
f(x) = x2nd for xε2 (0,1). Compute f(-3/2) + f(1). Select the correct option.
A) -1 B) -1/2 C) -1/4 D) 1/4 E) 1/2
Because f is periodic, we know that f(-3/2) = f(1/2) = (1/2)2 = 1/4. Because f   is odd, we know that f(1) = -f(-1), but because f is periodic, f(1) = f(-1). Therefore,   f(1) = 0 and the answer is 1/4.   correct answer 1/4
<result>D</result>
Suppose f(x) is an odd function for which f(x + 2) = f(x) for all x, and
f(x) = x2nd for xε2 (0,1). Compute f(-3/2) + f(1).