In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?	Select the correct option:
A) 8/21	B) 7/11	C) 5/27	D) 11/32	E) 1/4
Total number of balls = 8+7+6= 
<gadget id="calculator">8+7+6</gadget>
<output>21</output>
21   E= event that the ball drawn is neither red nor green   = event that the ball drawn is red   n(E) = 8   P(E) = 8/21   8/21nswer is 8/21
<result>A</result>
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?