The sequence a(1), a(2), …, a(n), … is such that a(n)=4a(n–1) –3 for all integers n>1. If a(3)=x, then a(1)=?
Select:
A) 4x–3	B) 16x–15	C) (x+3)/4	D) (x+3)/16	E) (x+15)/16
Since we know a(3) we can find a(2),   if we can find a(2) we can find a(1).   a(3)=4a(2)-3 ---&gt; x=4a(2)-3 ---&gt; a(2)=(x+3)/4   a(2)=4a(1)-3 ---&gt; (x+3)/4=4a(1)-3 ---&gt; 4a(1)=(x+15)/4 ---&gt; a(1)=(x+15)/16   The answer is (x+15)/16.
<result>E</result>
The sequence a(1), a(2), …, a(n), … is such that a(n)=4a(n–1) –3 for all integers n>1. If a(3)=x, then a(1)=?