Jim and Reneey will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Reneey have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win?  Choose the correct choice from the following choices:
A) 5/6
B) 2/3
C) 1/2
D) 5/12
E) 1/3
1/3   probability of jim winning is basically the sum of three probabilities:   probability of jim picking rock and reneey picking scissors = 1/3*1/3 = 1/9   probability of jim picking scissors and reneey picking paper = 1/3*1/3=1/9   probability of jim picking paper and reneey picking rock = 1/3*1/3=1/9   1/9 + 1/9 + 1/9 = 3/9 = 1/3=1/3
<result>E</result>
Jim and Reneey will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Reneey have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win?