Set S contains exactly 10 numbers and has an average (arithmetic mean) of 6.2. If one of the numbers in Set S is increased by 8, while all other numbers remain the same, what is the new average of Set S?	Choices:
A) 6.6  B) 6.7  C) 6.8  D) 7.0  E) 6.9
Old set S - Total is avg * no of elements = 6.2*10= 
<gadget id="calculator">6.2*10</gadget>
<output>62</output>
62   If one number is increased by 8 then total increased to  62+8= 
<gadget id="calculator"> 62+8</gadget>
<output>70</output>
70   New avg - 70/10= 7.0.   Hence answer is 7.0.
<result>D</result>
Set S contains exactly 10 numbers and has an average (arithmetic mean) of 6.2. If one of the numbers in Set S is increased by 8, while all other numbers remain the same, what is the new average of Set S?