Which of the following values of x satisfies the inequality 2x2 – 3x + 1 > 0? Pick.
A) -1 < x < -1⁄2  B) 1⁄2 < x < 1  C) x > 1 or x < 1⁄2  D) -1⁄2 < x < 1  E) None of these
2x2 – 3x + 1 = 0.   or (2x – 1)(x – 1) = 0   Hence, α = 1⁄2 and β = 1   Now, the given inequality is 2x2 – 3x + 1 &gt; 0,   Hence, sign scheme will be as follows:   --------|---------------------|----------------   +ve 1⁄2 –ve 1 +ve   ∴ x &gt; 1 or x &lt; 1⁄2   [Note:If the inequality were 2x2 – 3x + 1 &lt; 0; the answer will be 1⁄2 &lt; x &lt; 1]   Answer x &gt; 1 or x &lt; 1⁄2
<result>C</result>
Which of the following values of x satisfies the inequality 2x2 – 3x + 1 > 0?