If a sequence of 8 consecutive odd integers with increasing values has 9 as its 7th term, what is the sum of the terms of the sequence?
Choices:	A) 22	B) 32	C) 36	D) 40	E) 44
Seventh term, a7 = 9   Number of terms,n = 8   an= a1 + (n-1)d   a7= a1 + 6d   =&gt;9 = a1 + 12   =&gt;a1 = -3   8th term , a8 = 11   Sum of terms of the sequence = n/2[first term + last term]   = 4*[-3 + 11]   = 4*8= 
<gadget id="calculator">4*8</gadget>
<output>32</output>
32   Answer 32
<result>B</result>
If a sequence of 8 consecutive odd integers with increasing values has 9 as its 7th term, what is the sum of the terms of the sequence?