A number is selected at random from the first 30 natural numbers. What is the probability that the number is a multiple of either 3 or 17? Pick one
A) 17/30
B) 2/5
C) 7/15
D) 4/15
E) 11/30
Number of Multiples of 3 from 1 through 30 = 30/3= 
<gadget id="calculator">30/3</gadget>
<output>10</output>
10   Number of Multiples of 17 from 1 through 30= 30/17 = 1   Number of Multiples of 3 and 17 both from 1 through 30 = Number of Multiples of 17*3(=51) = 0   Total favourable cases = 10 + 1 - 0= 
<gadget id="calculator">10 + 1 - 0</gadget>
<output>11</output>
11   Probability= 11 / 30   Answer: option 11/30
<result>E</result>
A number is selected at random from the first 30 natural numbers. What is the probability that the number is a multiple of either 3 or 17?