Two squares are chosen on a chessboard at random. What is the probability that they have a side in common?	Select
A) 1/18
B) 64/4032
C) 63/64
D) 1/9
E) 2/9
In 64 squares, there are:   (1) 4 at-corner squares, each has ONLY 2 squares each having a side in common with...   (2) 6*4 = 24 side squares, each has ONLY 3 squares such that each has a side in common with...   (3) 6*6 = 36 inner squares, each has 4 squares such that each has a side in common with...   So we have the calculation:   P = (4/64)*(2/63) + (24/64)*(3/63)+ (36/64)*(4/63)   P = 1/18   1/18NSWER:1/18
<result>A</result>
Two squares are chosen on a chessboard at random. What is the probability that they have a side in common?