In a box carrying one dozen of oranges, one-third have become bad. If 3 oranges are taken out from the box at random, what is the probability that at least one orange out of the three oranges picked up is good? Pick:
A) 1⁄55	B) 54⁄55	C) 45⁄55	D) 3⁄55	E) None of these
n(S) = 12C3 = 12×11×10 /3×2=2×11×10=220   No. of selection of 3 oranges out of the total 12 oranges   = 12C3 = 2 × 11 × 10 = 220   No. of selection of 3 bad oranges out of the total 4 bad oranges = 4C3 = 4   \n(E) = no. of desired selection of oranges   = 220 – 4 = 216   \ P(E) = n(E)/n(S)=216/220=54/55   Answer 54⁄55
<result>B</result>
In a box carrying one dozen of oranges, one-third have become bad. If 3 oranges are taken out from the box at random, what is the probability that at least one orange out of the three oranges picked up is good?