A firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a $1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009?	Choose the most appropriate option:
A) 700  B) 1000  C) 1300  D) 1600  E) 2000
Profit=Revenue-Cost   2007:   -1000=R1-C1   2008:   0=(1+2X%)R1-(1+X%)C1   2009:   P3=(1+2 X%)^2*R1-(1+X%)^2*C1   we've already known that R3=1.44R1, so (1+2 X%)^2=1.44, X=10   we put X=10 back to the equation of 2008:   0=1.2R1-1.1C1, and we have 1.2R1=1.1C1, which we could combine with the equation of 2007.   Then we have 13001=12000, R1-11000   Finally, take 13001 and R1 into the equation of 2009 and we got P3=15840-14520= 
<gadget id="calculator">15840-14520</gadget>
<output>1_320</output>
1320 ;Answer: 1300
<result>C</result>
A firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a $1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009?