There are 8 women and 7 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different such committees are possible? Choose the correct choice.
A) 332
B) 450
C) 362
D) 476
E) 588
8C2 * 7C2 = 28*21= 
<gadget id="calculator">28*21</gadget>
<output>588</output>
588   The answer is 588.
<result>E</result>
There are 8 women and 7 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different such committees are possible?