Find the probability that a year chosen at random has 53 Mondays.	Pick one:  A) 5/28  B) 3/28  C) 1/28  D) 3/28  E) 3/27
Explanation :   There are 2 kinds of year   Leap year - probability = 1/4(out of 4 years one is a leap year)   Non leap year - probability = 3/4   So it's either this OR that   Now in non leap year, there are 365 days meaning 52 Weeks with one day extra   That one day can be Monday out of 7 possible days.Hence the probability = 1/7   Similarly in leap year, there are 366 days and so 366/7= 52 Weeks with 2 days Extra   Now probability of occurrence of Monday out of possible 7 days =2/7   So what we essentially want is   (5/28 non leap year 5/28ND Monday) OR ( 5/28 leap year 5/28ND Monday)   So it'll be [3/4*1/7] + [1/4*2/7] = 5/28   5/28nswer : 5/28
<result>A</result>
Find the probability that a year chosen at random has 53 Mondays.