From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?	Options:	A) 567	B) 564	C) 645	D) 735	E) 756
we have 3m and 2w   or   4m and 1w   or   5m   no of ways =(7C3 x 6C2) + (7C4 x 6C1) + (7C5)=	= (525 + 210 + 21)= 
<gadget id="calculator">(525 + 210 + 21)</gadget>
<output>756</output>
756.   ANSW756R:756
<result>E</result>
From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?