How many 3 digit numbers are completely divisible 6 ? Choose the correct choice from the following choices:
A) 146  B) 148  C) 150  D) 152  E) None of these
Explanation :   100/6 = 16, remainder = 4. Hence 2 more should be added to 100 to get the minimum   3 digit number divisible by 6.   =&gt; Minimum 3 digit number divisible by 6 = 100 + 2= 
<gadget id="calculator">100 + 2</gadget>
<output>102</output>
102   999/6= 166, remainder = 3. Hence 3 should be decreased from 999 to get the maximum   3 digit number divisible by 6.   =&gt; Maximum 3 digit number divisible by 6 = 999 - 3= 
<gadget id="calculator">999 - 3</gadget>
<output>996</output>
996   Hence, the 3 digit numbers divisible by 6 are 102, 108, 114,... 996   This is Arithmetic Progression with a= 102 ,d = 6, l=996   Number of terms = (l−a)/d + 1 = (996 − 102)/6 + 1 = 894/6 + 1 = 149 + 1= 
<gadget id="calculator">149 + 1</gadget>
<output>150</output>
150. Answer : Option 150
<result>C</result>
How many 3 digit numbers are completely divisible 6 ?