For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum of all the even integers between 99 and 301?	Choose the correct choice from the following answers:	A) 10,100	B) 20,200	C) 22,650	D) 40,200	E) 45,150
Firstly calculate the number of even integers between 99 and 301:   No of even integers = (300 - 100)/2 + 1= 
<gadget id="calculator">(300 - 100)/2 + 1</gadget>
<output>101</output>
101   Avg of the even integers is  (100+300)/2= 
<gadget id="calculator"> (100+300)/2</gadget>
<output>200</output>
200.   The sum would be= no of even integers * Avg.   ==&gt; 101*202 = 20,200   Answer 20,200.
<result>B</result>
For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum of all the even integers between 99 and 301?