A group of four women and two men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in two adjacent seats, how many possible different seating arrangements are there for these 6 theatre-goers?
Pick one:  A) 7! – 2!3!2!  B) 7! – 4!3!  C) 6! – 5!2!  D) 7 × 2!3!2!  E) 2!3!2!
6 people can sit in 6! different ways. But because 2 men cannot sit together, we take them as a unit.   This unit of men, among themselves can sit in 2! ways.   Hence, 6! - 2!.   This unit of men along with 4 women can sit in 5! different ways which also needs to be eliminated.   Hence 6! - 5!2!   6! – 5!2!
<result>C</result>
A group of four women and two men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in two adjacent seats, how many possible different seating arrangements are there for these 6 theatre-goers?