Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 1/3 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?  Choose the most appropriate option
A) 1/32
B) 7/8
C) 9/64
D) 5/64
E) 3/64
P(Xavier will solve)=1/4   P(Yvonne will solve)=1/2   P(Zelda will NOT solve) = 1- 5/8 = 3/8.   Now, we need to multiply all this Ps to find an answer:   p= (1/4)*(1/3)*(3/8) = 1/32.   Ans. 1/32.
<result>A</result>
Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 1/3 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?