If five boxes of fruit contain six different fruit in each box, and a fruit is randomly selected from each box, what is the probability of getting at least one pair of the same fruit?	Select the correct option:
A) 31/32	B) 4/9	C) 1/2	D) 5/49	E) 49/54
AT LEAST one pair of matching fruit.   First solve for NO matching fruit:   1st box = any fruit = 6/6   2nd box = not a match to the first = 5/6   3rd box = not a match to the 1st or 2nd = 4/6   4th box = not a match to the 1st, 2nd or 3rd = 3/6   5th box = not a match to the 1st, 2nd, 3rd or 4th = 2/6   (6/6)(5/6)(4/6)(3/6)(2/6) =   (1)(5/6)(2/3)(1/2)(1/3) = 60/648   5/54   5/54 is the probability of NO matching fruit, so...   1 - 5/54 = 49/54 = the probability of getting at least one matching pair of fruit.   Answer: 49/54
<result>E</result>
If five boxes of fruit contain six different fruit in each box, and a fruit is randomly selected from each box, what is the probability of getting at least one pair of the same fruit?