1*2+ 2*2^2+ 3*2^3+ 4*2^4……………………+2012*2^2012 Options
A) 8100312  B) 8100313  C) 8100412  D) 8200312  E) 8300312
take 2 outside as common   we get 2(1+2*1^2+3*1^3+.........2012*1^2012)   then 2(1+2+.....2012)   we get 8100312   8100312NSWER:8100312
<result>A</result>
1*2+ 2*2^2+ 3*2^3+ 4*2^4……………………+2012*2^2012