A tourist purchased a total of $1,500 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was three more or three less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
Choose one:
A) $1,230
B) $1,310
C) $1,290
D) $1,270
E) $1,150
Let the number of $10 checks cashed beT   Let the number of $50 checks cashed beF   7 checks cashed;   T+F=7   Now; T can be F+3 OR T can be F-3   Let's check both conditions;   T=F+3   T+F=7   F+3+F=7   2F=4   F=2   T=5   Value cashed = 2*50+5*10= 
<gadget id="calculator">2*50+5*10</gadget>
<output>150</output>
$150   Let's check the other condition as well;   T=F-3   T+F=7   F-3+F=7   2F=10   F=5   T=2   Value cashed = 5*50+2*10= 
<gadget id="calculator">5*50+2*10</gadget>
<output>270</output>
$270   The more money he cashes, the less loss he incurs. Thus, we must consider the latter case.   Value cashed= $270   Value lost = 1500-270= 
<gadget id="calculator">1500-270</gadget>
<output>1_230</output>
$1230   $1,230ns:$1,230
<result>A</result>
A tourist purchased a total of $1,500 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was three more or three less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?