What is the absolute value of twice the difference of the roots of the equation F=5y^2 − 20y + 15 = 0 ?
Choose the correct choice from the following answers:
A) 0
B) 1
C) 2
D) 3
E) 4
F=5y^2 − 20y + 15 = 0 --&gt; y^2 − 4y + 3 = 0 --&gt; y=1 or y=3. The difference is 2, twice the difference is 4.   Answer: 4.
<result>E</result>
What is the absolute value of twice the difference of the roots of the equation F=5y^2 − 20y + 15 = 0 ?