A basketball coach will select the members of a five-player team from among 10 players, including John and Peter. If the five players are chosen at random, what is the probability that the coach chooses a team that includes both John and Peter?	Choose the correct option
A) 1/9  B) 1/6  C) 2/9  D) 5/18  E) 1/3
straight forward way is to group J and P as always present on the team and as order does not matter so we just need to find the total number of ways to select rest three players = 8c3   total number of ways of selecting 5 players out of 10 = 10c5   probability = 8c3/10c5 =2/9   2/9
<result>C</result>
A basketball coach will select the members of a five-player team from among 10 players, including John and Peter. If the five players are chosen at random, what is the probability that the coach chooses a team that includes both John and Peter?