Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $10 more than 1/4 of the fine and Peter paid $10 less than 1/3 of the fine, leaving pay $25 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay? Choose one.
A) $120	B) $125	C) $130	D) $135	E) $140
Call the fine F. Joe paid (1/4)F + 4 and Peter paid (1/3)F – 4, leaving (1/2)F – 5 left. If we add those three up, they should add up to F.   F = [(1/4)F + 10] + [(1/3)F – 10] + [(1/2)F – 25]   F = (1/4)F + (1/3)F + (1/2)F – 25   Multiply all terms by 12 to clear the fractions.   12F = 3F + 4F + 6F – 300   12F = 13 F – 300   –F = – 300   F = 300   Well, if the fine cost $300, then Sam paid the part not covered by Joe or Peter. Half the fine is $150, and Sam paid $25 less than this: $125   Answer = $125
<result>B</result>
Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $10 more than 1/4 of the fine and Peter paid $10 less than 1/3 of the fine, leaving pay $25 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?