Michael has some coins in his pocket consisting of dimes, nickels, and pennies. He has two
more nickels than dimes, and three times as many pennies as nickels. How many of each kind
of coin does he have if the total value is $0.52?	Choose the correct option.
A) 1 dimes, 2 nickels, and 4 pennies.	B) 2 dimes, 4 nickels, and 12 pennies.	C) 5 dimes, 5 nickels, and 6 pennies.	D) 7 dimes, 8 nickels, and 12 pennies.	E) 5 dimes, 4 nickels, and 3 pennies.
This problem involves money.   The question asks, “How many of each kind of coin”.   There is more than one unknown. So when doing the let statement, start with the   smallest quantity, in this case, the number of dimes.   Let x the number of dimes   x+2 the number of nickels   3x+2= the number of pennies   The value of all the dimes$0.10x plus the value of all the nickels$0.5(x+2) plus the   value of all the pennies$0.01(3)(x+2) equals the total value, $0.52.   Write the equation.   0.10x+0.05(x+2)+0.03(x+2)=0.52   10x+5(x+2)+3(x+2)=52   10x+5x+10+3x+6=52   18x=36   x=2   x+2=4   3(x+2)=12   The answer: Michael has 2 dimes, 4 nickels, and 12 pennies.   correct answer 2 dimes, 4 nickels, and 12 pennies.
<result>B</result>
Michael has some coins in his pocket consisting of dimes, nickels, and pennies. He has two
more nickels than dimes, and three times as many pennies as nickels. How many of each kind
of coin does he have if the total value is $0.52?