A box contains three red marbles and 1 green marble. If the marbles are removed from the box one at a time, in random order, what is the probability that all three red marbles are removed before the green marble?  Pick.
A) 1/64
B) 1/24
C) 1/12
D) 1/4
E) 1/2
There are 3 red marbles and 4 marbles total, so the probability of drawing a red marble on the first draw is 3/4 . On the second draw there are 2 red marbles and three marbles total so the probability of drawing a red marble is 2/3. On the third draw, there is only one red marble and one green marble, so the probability of drawing the red marble is 1/2. The probability of all three events happening is the product of the probabilities,3/4∗2/3∗1/2 or1/4   Answer 1/4
<result>D</result>
A box contains three red marbles and 1 green marble. If the marbles are removed from the box one at a time, in random order, what is the probability that all three red marbles are removed before the green marble?