An urn contains 5 red, 6 blue and 8 green balls. 4 balls are randomly selected from the urn, find the probability that the drawn ball are 1 blue and 2 red and 1 green balls ?
Answers: A) 20/323 B) 40/323 C) 60/273 D) 50/373 E) 40/373
Sample space = no. of ways 4 balls were drawn from urn = 19C4 = 3876   No. ways 1 blue and 2 red and 1 green balls were drawn from bag = 6C1 * 5C2 * 8C1 = 480   Probability = 480 / 3876 = 40/323   Ans - 40/323
<result>B</result>
An urn contains 5 red, 6 blue and 8 green balls. 4 balls are randomly selected from the urn, find the probability that the drawn ball are 1 blue and 2 red and 1 green balls ?