In how many ways can 8 Indians and, 4 American and 4 Englishmen can be seated in a row so that all person of the same nationality sit together?
Choose the correct choice from the following options:
A) 3!*8!*4!*4! ways B) 8!*4!*4! ways C) 3!4! ways D) 3!*5! ways E) 3!*6! ways
Taking all person of same nationality as one person, then we will have only three people.   These three person can be arranged themselves in 3! Ways.   8 Indians can be arranged themselves in 8! Way.   4 American can be arranged themselves in 4! Ways.   4 Englishman can be arranged themselves in 4! Ways.   Hence, required number of ways = 3!*8!*4!*4! Ways.   3!*8!*4!*4! waysNSWER 3!*8!*4!*4! ways
<result>A</result>
In how many ways can 8 Indians and, 4 American and 4 Englishmen can be seated in a row so that all person of the same nationality sit together?