John decides to attend a basketball game with six friends. If the party of seven sits together in seven consecutive seats, and John must NOT sit in between two of his friends, how many ways can the seven friends be arranged? Choose the correct choice from the following options
A) 1220	B) 1000	C) 540	D) 1440	E) 720
John have to sit at either of the ends.   If John sits on the left most corner, then other 6 friends can be arranged in 6! = 720   John can also sit on the other end, then another 6! ways we can arrange.   So total number of ways = 720+720= 
<gadget id="calculator">720+720</gadget>
<output>1_440</output>
1440   Answer : 1440
<result>D</result>
John decides to attend a basketball game with six friends. If the party of seven sits together in seven consecutive seats, and John must NOT sit in between two of his friends, how many ways can the seven friends be arranged?