As a treat for her two children, a mother runs to the freezer in which she has three cherry ice pops, three orange ice pops, and five lemon ice pops. She chooses two at random to bring outside to the children, but realizes as she runs out the door that she cannot bring them different flavors without one being jealous of the other and getting even more upset. What is the probability that she has to return to the freezer to make sure that they each receive the same flavor? Choose one
A) 7/11 B) 9/22 C) 19/33 D) 29/44 E) 39/55
P(2 cherry) = 3/11 * 2/10 = 6/110   P(2 orange) = 3/11 * 2/10 = 6/110   P(2 lemon) = 5/11 * 4/10 = 20/110   P(2 of the same flavor) = 32/110   P(2 different flavors) = 1 - 32/110 = 78/110 = 39/55   The answer is 39/55.
<result>E</result>
As a treat for her two children, a mother runs to the freezer in which she has three cherry ice pops, three orange ice pops, and five lemon ice pops. She chooses two at random to bring outside to the children, but realizes as she runs out the door that she cannot bring them different flavors without one being jealous of the other and getting even more upset. What is the probability that she has to return to the freezer to make sure that they each receive the same flavor?