A box contains 3 white balls, 4 black balls and 5 yellow balls. In how many ways can 4 balls be drawn from the box, if at least one yellow ball is to be included in the draw?
Choose one.
A) 652	B) 547	C) 425	D) 356	E) 346
We may have (1 yellow and 3 others) or (2 yellow and 2 others) or (3 yellow and 1 others) or (4 yellow).   Therefore, Required number of ways= (4C1*8C3)+ (4C2*8C2)+ (4C3*8C1)+ (4C4)   = 4* 8*7*6/ 3*2*1 + 4*3/2*1 * 8*7/2*1 + (4C1*8) +1   = 224+168+32+1= 
<gadget id="calculator">224+168+32+1</gadget>
<output>425</output>
425.   ANSWER:425
<result>C</result>
A box contains 3 white balls, 4 black balls and 5 yellow balls. In how many ways can 4 balls be drawn from the box, if at least one yellow ball is to be included in the draw?