In the coordinate plane, one of the vertices of a square is the point (-5, -4). If the diagonals of that square intersect at point (3, 2), what is the area of that square?	Pick one
A) 100	B) 225	C) 169	D) 256	E) 324
One point (-5-4), Intersection (3,2) so the distance from the first point -5-3=-8 is the midpoint of the square --&gt; whole side 16, 16*16=256   256
<result>D</result>
In the coordinate plane, one of the vertices of a square is the point (-5, -4). If the diagonals of that square intersect at point (3, 2), what is the area of that square?