Seven different objects must be divided among three people. In how many ways can this be done if one or two of them must get no objects?
Choose the correct choice from the following answers:  A) 381  B) 36  C) 84  D) 180  E) 190
Let the three people be A, B, and C.   If 1 person gets no objects, the 7 objects must be distributed such that each of the other two get 1 object at least.   This can be done as 6 &amp; 1, 5 &amp; 2, 4 &amp; 3 and their rearrangements.   The answer would be ( 7C6 + 7C5 + 7C4 ) x 3! = 378   Also, two people getting no objects can be done in 3 ways.   Thus, the answer is 378 + 3= 
<gadget id="calculator">378 + 3</gadget>
<output>381</output>
381   381NSWER:381
<result>A</result>
Seven different objects must be divided among three people. In how many ways can this be done if one or two of them must get no objects?