A straight pipe 1 meter in length was marked off in fourths and also in thirds. If the pipe was then cut into separate pieces at each of these markings, which of the following gives all the different lengths of the pieces, in fractions of a meter?
Choose the correct choice from the following
A) 1/6 and 1/4 only  B) 1/4 and 1/3 only  C) 1/12, 1/6 and 1/4  D) 1/6, 1/4, and 1/3  E) 1/12, 1/6, and 1/3
Generally fast way to solve such problem is writing the different marks in ascending/descending order with same denominator:   Here 4th : 0/4, 1/4, 2/4, 3/4, 4/4   and 3rd : 0/3, 1/3, 2/3, 3/3   Now with understood common denominator 12 write the numbers : for 4th : 0,3,6,9,12 and for 3rd : 0,4,8,12   Now comine : 0,3,4,6,8,9,12   Now find the cut with denominator 12 (Substracrt adjacent terms : 3/12, 1/12, 2/12, 1/12,3/12 i.e. 1/4, 1/12 and 1/6 after removing duplicates.   Answer - 1/12, 1/6 and 1/4
<result>C</result>
A straight pipe 1 meter in length was marked off in fourths and also in thirds. If the pipe was then cut into separate pieces at each of these markings, which of the following gives all the different lengths of the pieces, in fractions of a meter?