For any four digit number, abcd, *abcd*= (3^a)(5^b)(7^c)(11^d). What is the value of (n – m) if m and n are four digit numbers for which *m* = (3^r)(5^s)(7^t)(11^u) and *n* = (25)(*m*)?	Select the correct option:
A) 2000
B) 200
C) 25
D) 20
E) 2
bcd is a four digit number where a, b, c and d are the 4 digits.   *abcd*= (3^a)(5^b)(7^c)(11^d). The '**' act as an operator.   Given: *m* = (3^r)(5^s)(7^t)(11^u)   So m = rstu where r, s, t, and u are the 4 digits of m.   Say, r = 1 and s = 0, t = 0 and u = 0   m = 1000   Then *m* = 3   Now,   *n* = (25)(*m*) = 25(3) = (3^1)(5^2)(7^0)(11^0)   n = 1200   n - m = 1200 - 1000= 
<gadget id="calculator">1200 - 1000</gadget>
<output>200</output>
200   ANSWER:200
<result>B</result>
For any four digit number, abcd, *abcd*= (3^a)(5^b)(7^c)(11^d). What is the value of (n – m) if m and n are four digit numbers for which *m* = (3^r)(5^s)(7^t)(11^u) and *n* = (25)(*m*)?