A box contains2 blue marbles, 4 red marble, 3 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either green or yellow? Choose the correct choice from the following answers
A) 5/11 B) 4/11 C) 3/11 D) 2/11 E) 1/11
Given that there are 2 blue marbles, 4 red marbles, 3 green marbles and 2 yellow marbles. Probability that both marbles are green = 3Câ‚‚/11Câ‚‚ = 3/55   Probability that both are yellow = Â²Câ‚‚/11Câ‚‚ = 1/55   Probability that one green and other is yellow = (3Câ‚ * Â²Câ‚)/11Câ‚‚ = 6/55   Required probability = 3/55 + 1/55 + 6/55   = 10/55=2/11   Answer:2/11
<result>D</result>
A box contains2 blue marbles, 4 red marble, 3 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either green or yellow?