If (2^x)(3^y) = 216, where x and y are positive integers, then (2^x-1)(3^y-2) equals:	Select:
A) 12	B) 24	C) 48	D) 96	E) 144
So I would start attacking this problem by quickly performing the prime factorization of 288. With that it is easy to count the 5 twos and the 2 threes that are the prime factors. So x=3, y=3. now quickly 2^2(3^1)=12. Than answer should be number 1.   12
<result>A</result>
If (2^x)(3^y) = 216, where x and y are positive integers, then (2^x-1)(3^y-2) equals: