If n is a natural number, then (6n^2+6n) is always divisible by? Answers.
A) 6 only  B) 6 and 12  C) 12 only  D) by 18 only  E) None of these
(6n^2+6n)=6n(n+1), which is always divisible by 6 and 12 both, since n(n+1) is always even.   Correct Option: 6 and 12
<result>B</result>
If n is a natural number, then (6n^2+6n) is always divisible by?