The batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. Find out the highest score of the player.	Choose the correct option:
A) 150  B) 174  C) 180  D) 166  E) 165
Explanation:   Total runs scored by the player in 40 innings = 40 × 50   Total runs scored by the player in 38 innings after excluding two innings = 38 × 48   Sum of the scores of the excluded innings = 40 × 50 - 38 × 48 = 2000 - 1824= 
<gadget id="calculator">2000 - 1824</gadget>
<output>176</output>
176   Given that the scores of the excluded innings differ by 172. Hence let's take   the highest score as x + 172 and lowest score as x   Now x + 172 + x= 176   =&gt; 2x = 4   =&gt; x =4/2= 
<gadget id="calculator">4/2</gadget>
<output>2</output>
2   Highest score= x + 172 = 2 + 172= 
<gadget id="calculator">2 + 172</gadget>
<output>174</output>
174   Answer: Option 174
<result>B</result>
The batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. Find out the highest score of the player.