A man loses 1/3rd of his money, then wins Rs. 10 loses 1/3rd of what he has and wins Rs. 20 and finds that he has exactly what be had at the beginning. What was the amount he originally bad ?  Pick:
A) 25
B) 36
C) 10
D) 48
E) 45
let x be that amount   so accordind to question , eqn will be like:   (((x-x/3)+10)-(((x-x/3)+10)/3))+20=x   =&gt; ((2x/3+10)-((2x/3+10)/3))+20=x   =&gt;3x-4x/3=80   =&gt;x=48   ANSWER:48
<result>D</result>
A man loses 1/3rd of his money, then wins Rs. 10 loses 1/3rd of what he has and wins Rs. 20 and finds that he has exactly what be had at the beginning. What was the amount he originally bad ?