A larger cube has 64 cubic inch as a volume and in the cube there are 64 smaller cubes such that their volume is 1 cubic inch. What is the difference between the surface areas’ sum of the 64 smaller cubes and the surface area of the larger cube, in square inch?	Choose the correct choice from the following
A) 54  B) 64  C) 81  D) 288  E) 120
Volume of larger cube = 64 = 4^3   Side of larger cube = 4   Volume of smaller cube = 1 --&gt; Side of smaller cube = 1   Surface area of larger cube = 6 * 4^2 = 96   Surface area of 27 smaller cubes = 64 * 6 * 1= 
<gadget id="calculator">64 * 6 * 1</gadget>
<output>384</output>
384   288ifference= 384 - 96= 
<gadget id="calculator">384 - 96</gadget>
<output>288</output>
288   Answer: 288
<result>D</result>
A larger cube has 64 cubic inch as a volume and in the cube there are 64 smaller cubes such that their volume is 1 cubic inch. What is the difference between the surface areas’ sum of the 64 smaller cubes and the surface area of the larger cube, in square inch?