Walking at 5/6 of her normal speed, a worker is 12 minutes later than usual in reaching her office. The usual time (in minutes) taken by her to cover the distance between her home and her office is Select the correct option:
A) 36 B) 42 C) 48 D) 54 E) 60
Let V be her normal speed and let T be her normal time.   D = (5/6)V * (T+12)   Since the distance is the same we can equate this to a regular day which is D = V*T   V*T = (5/6)V * (T+12)   T/6 = 10   T=60   The answer is 60.
<result>E</result>
Walking at 5/6 of her normal speed, a worker is 12 minutes later than usual in reaching her office. The usual time (in minutes) taken by her to cover the distance between her home and her office is