(1^2+2^2+3^2+.....+12^2)=?
Choose one: A) 330 B) 345 C) 365 D) 385 E) 650
formula is (1^2+2^2+3^2+....+n^2=1/6 n(n+1)(2n+1)   n=12   =(1/6x12x13x25)   =650   Answer is 650.
<result>E</result>
(1^2+2^2+3^2+.....+12^2)=?