At 10 am 2 trains started travelling towards each other from station 287 miles apart they passed each other at 1:30 pmthe same dayy .if average speed of the faster train exceeded by 6 miles /hr what is speed of faster train in miles/hr
Select the correct option: A) 42 B) 43 C) 44 D) 45 E) 46
let the speed of slower train is x   then speed of faster train is=x+6   now, 287/x+x+6=7/2(3 and half hour)   after solving the equation we will get x=38   so faster train=x+6   38+6= 
<gadget id="calculator">38+6</gadget>
<output>44</output>
44   ANSWER:44
<result>C</result>
At 10 am 2 trains started travelling towards each other from station 287 miles apart they passed each other at 1:30 pmthe same dayy .if average speed of the faster train exceeded by 6 miles /hr what is speed of faster train in miles/hr