A number is selected at random from the first 30 natural numbers. What is the probability that the number is a multiple of either 2 or 19?
Choices:  A) 17/30  B) 2/5  C) 7/15  D) 8/15  E) 11/30
Number of Multiples of 2 from 1 through 30 = 30/2= 
<gadget id="calculator">30/2</gadget>
<output>15</output>
15   Number of Multiples of 19 from 1 through 30= 30/19 = 1   Number of Multiples of 2 and 19 both from 1 through 30 = Number of Multiples of 19*2(=38) = 0   Total favourable cases = 15 + 1- 0= 
<gadget id="calculator">15 + 1- 0</gadget>
<output>16</output>
16   Probability= 16 / 30 = 8/15   Answer: option 8/15
<result>D</result>
A number is selected at random from the first 30 natural numbers. What is the probability that the number is a multiple of either 2 or 19?