Out of first 30 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is ? Choices: A) 6/30 B) 2/30 C) 4/90 D) 24/30 E) 24/60
n(S) = 30   n(Even no) = 15 = n(E)   n(Prime no) = 10 = n(P)   P(EᴜP)   = 15/30 + 10/30 - 1/30   = 24/30   Answer:24/30
<result>D</result>
Out of first 30 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is ?