If x is a positive integer, then the least value of x for which x! is divisible by 10 is?
Can someone please explain intuitively what the question is asking?  Choose the correct answer:
A) 5
B) 9
C) 12
D) 15
E) 30
In order x! to be divisible by 1,0, it should have at least 1 trailing zeros. A trailing 0 in factorial of a number is produced by 2 and 5 in it:   2*5= 
<gadget id="calculator">  2*5</gadget>
<output>10</output>
10. So, we need 10 to be in x! at least in power of 1.   5!= 120 has 1 trailing zeros.   5nswer: 5
<result>A</result>
If x is a positive integer, then the least value of x for which x! is divisible by 10 is?
Can someone please explain intuitively what the question is asking?