At a conference, the only events scheduled for the day are seminars and breaks. All seminars are the same length and are 10 times as long as each break. A break must be between two consecutive seminars. If the first seminar begins at 9:00 a.m. and the third one ends at 12:40 a.m., how long will the conference last if there are a total of 6 seminars that day?  Choices:
A) hours and 15 minutes  B) hours and 20 minutes  C) hours and 25 minutes  D) hours and 30 minutes  E) hours and 35 minutes
Well its like this S B S B S B S B S B S   the interval between 9 am to 11:40 am is 160 min having 3 seminars and 2 breaks .If 1 break is of 5 min than time for 3 seminars = 160 - 2*5= 
<gadget id="calculator">160 - 2*5</gadget>
<output>150</output>
150   Time of 1 seminar=150 /3= 
<gadget id="calculator">150 /3</gadget>
<output>50</output>
50 min .   So calculating for 6 seminars and 5 breaks ,total time comes out to be 5 hrs and 20 min .   Answer is hours and 20 minutes.
<result>B</result>
At a conference, the only events scheduled for the day are seminars and breaks. All seminars are the same length and are 10 times as long as each break. A break must be between two consecutive seminars. If the first seminar begins at 9:00 a.m. and the third one ends at 12:40 a.m., how long will the conference last if there are a total of 6 seminars that day?