How many different subset of the set of the 12 Calendar Month will not have the Month of March.  Choose the correct option
A) 1951	B) 1948	C) 1953	D) 1947	E) 1949
This is a combination solution   Since we have 11 different Month other than the Month of March we can take any Month from the set of 11 Months to make a subset.   11C1 +11C2 + 11C3 + 11C4 + 11C5 + 11C6 + 11C7 + 11C8 + 11C9 + 11C10 + 11C11 = 1948   Plus the one set that is null that is the Set having no element in it which is 11C0 =1   = 1948 + 1= 
<gadget id="calculator">1948 + 1</gadget>
<output>1_949</output>
1949   1949= 1949
<result>E</result>
How many different subset of the set of the 12 Calendar Month will not have the Month of March.