An unbiased die is tossed .find the probability of getting a multiple of 3  Pick.
A) 1/3
B) 5/3
C) 2/3
D) 7/3
E) 3/7
Here S={1,2,3,4,5,6}   Let E be the event of getting the multiple of 3   then ,E={3,6}   P(E)=n(E)/n(S)=2/6=1/3   Option: 1/3
<result>A</result>
An unbiased die is tossed .find the probability of getting a multiple of 3