Can you please walk me through how to best approach this problem? Thanks
If #p# = ap^3+ bp – 1 where a and b are constants, and #-4# = 2, what is the value of #4#?  Choose the correct choice from the following:
A) -4
B) 0
C) -2
D) -3
E) -4
#p# = ap^3 + bp - 1   #-4# = 2   putting p = -4 in above equation   -64a -(4b +1) = 2 or   #-4# = (64a+4b+1) = -2   therefore 64a+4b = -3 .....(1   now putting p = 4   #4# = 64 a+4b - 1   using equation 1(64a+4b = -3)   #4# = -3-1 = -4   hence -4
<result>A</result>
Can you please walk me through how to best approach this problem? Thanks
If #p# = ap^3+ bp – 1 where a and b are constants, and #-4# = 2, what is the value of #4#?