Three numbers are randomly selected, with replacement, from the set of integers {0, 1, 2, 3, 4, 5}. If the first number selected is w, the second number selected is x, and the third number is y, what is the probability that w < x < y ?
Choose the correct choice:
A) 5/18
B) 5/27
C) 7/36
D) 5/54
E) 7/108
The number of ways to select w, x, and y is:   6*6*6= 
<gadget id="calculator">  6*6*6</gadget>
<output>216</output>
216   The number of ways to choose three different numbers from the set is 6C3=20.   There are six permutations for each group of three different numbers, but only one permutation satisfies w &lt; x &lt; y.   P(w &lt; x &lt; y) = 20/216 = 5/54   The answer is 5/54.
<result>D</result>
Three numbers are randomly selected, with replacement, from the set of integers {0, 1, 2, 3, 4, 5}. If the first number selected is w, the second number selected is x, and the third number is y, what is the probability that w < x < y ?