In how many ways 3 boys and 3 girls can be seated in a row so that they are alternate.	Choose the correct answer.
A) 144 B) 288 C) 36 D) 256 E) None
Solution: Let the Arrangement be,   B G B G B G B   34 boys can be seated in 3! Ways.   Girl can be seated in 3! Ways.   Required number of ways,   = 3!*3! = 36.   Answer: Option 36
<result>C</result>
In how many ways 3 boys and 3 girls can be seated in a row so that they are alternate.