There are 9 books on a shelf that consist of 4 paperback books and 5 hardback books. If 4 books are selected at random without replacement, how many different combinations are there which include at least one paperback book?	Choose the correct choice:
A) 88
B) 99
C) 110
D) 121
E) 132
The total number of ways to select 4 books is 9C4 = 126   The number of ways which do not include any paperbacks is 5C4 = 5   The number of combinations with at least one paperback is  126-5= 
<gadget id="calculator"> 126-5</gadget>
<output>121</output>
121   The answer is 121.
<result>D</result>
There are 9 books on a shelf that consist of 4 paperback books and 5 hardback books. If 4 books are selected at random without replacement, how many different combinations are there which include at least one paperback book?