If x and y are integers such that x^2= 3y and xy = 36, then x – y = ?
Choose the correct choice from the following:  A) -30  B) -20  C) -5  D) 5  E) 0
here x and y are integers .   x^2=3y,xy =36.   substitute (x^2)/3=y in xy =&gt; x^3=36*3=&gt;x^3=108.   here x^3 is positive ,   x is also positive.   x=6 then y=6.   x-y=0   so option 0 is correct
<result>E</result>
If x and y are integers such that x^2= 3y and xy = 36, then x – y = ?