If a refrigerator contains 12 cans such that there are 7 blue cans and 5 red cans. In how many ways can we remove 8 cans so that at least 1 blue can and 1 red can remains in the refrigerator. Choose the correct choice:	A) 452	B) 453	C) 454	D) 455	E) 456
The possible cases of (b,r) draws are (6,2) (5,3) (4,4)   6 2----&gt;7c6*5c2---&gt;7*10=70   5 3----&gt;7c5*5c3---&gt;21*10=210   4 4----&gt;7c4*5c4---&gt;35*5=175   70+210+175= 
<gadget id="calculator">70+210+175</gadget>
<output>455</output>
455   ANSWER:455
<result>D</result>
If a refrigerator contains 12 cans such that there are 7 blue cans and 5 red cans. In how many ways can we remove 8 cans so that at least 1 blue can and 1 red can remains in the refrigerator.