A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 2, 4 and 5, which can be repeated. If the product of the digits in the area code must be odd, how many different codes can be created?	Choose the correct choice:
A) 20 B) 22 C) 24 D) 1 E) 30
Total # of codes possible is 3*3*3= 
<gadget id="calculator">3*3*3</gadget>
<output>27</output>
27. Oit of those 27 codes only the product of 555 will be odd, the remaining 26 will have either 2 or 4 in them, which ensures that their product will be even. Therefore the number of codes where the product of the digits is even= (total) - (restriction) = 27 - 26= 
<gadget id="calculator">27 - 26</gadget>
<output>1</output>
1.   Answer: 1.
<result>D</result>
A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 2, 4 and 5, which can be repeated. If the product of the digits in the area code must be odd, how many different codes can be created?