100 identical coins each with probability 'pp' showing up heads & tossed. If 0<p<10<p<1 and the probabilityof heads showing on 50coins is equal tothat of heads on 51 coins, then the value of pp is?  Pick:
A) 50/107  B) 53/103  C) 51/101  D) 65/101  E) 89/101
Let aa be the number of coins showing heads   Then, P(A=50)=P(A=51)P(A=50)=P(A=51)   ⇒10051/10150×P50×(1−P)50⇒10051/10151×P51×(1−P)49⇒10051/10150×P51×(1−P)50=10051/10151×P⇒51(1âˆ′P)=50P⇒P=51/101   51/101
<result>C</result>
100 identical coins each with probability 'pp' showing up heads & tossed. If 0<p<10<p<1 and the probabilityof heads showing on 50coins is equal tothat of heads on 51 coins, then the value of pp is?