The sum of 2 numbers is 2000. Their L.C.M. is 21879. Their difference is?  Answers
A) 1845  B) 1978  C) 1945  D) 1862  E) 1789
Let the numbers be x and 2000-x   L.C.M. = x(200-x) = 21879   x^2 - 2000x + 21879 = 0   (x-1989) (x-11) = 0   x = 1989 and x = 11   Difference = 1989-11= 
<gadget id="calculator">1989-11</gadget>
<output>1_978</output>
1978   Answer is 1978
<result>B</result>
The sum of 2 numbers is 2000. Their L.C.M. is 21879. Their difference is?