On a counter of a donuts store, there are only 16 identical donuts, 11 filled with chocolate and 5 filled with jelly, but the seller tells me that the donuts are randomly placed on the counter. If would want to buy two, what is the probability that I choose one donuts of each flavor? Options:
A) 2/16
B) 1/32
C) 11/12
D) 11/48
E) 11/24
We are told that we have 16 donuts, 11 of chocolate and 5 of jelly. The donuts are picked simultaneous and randomly, D1 and D2, in different flavors. There are two acceptable outcomes: 1) D1 is chocolate and D2 is jelly; 2) D1 is jelly and D2 is chocolate. Let's go: 1) D1 = (11/16)(5/15)= 11/48 chance of this happening. 2) D2 = (5/16)(11/15) = 11/48 chance of this happening. Then: (11/48)+(11/48)= 11/24, chance of getting the result that you wanted. Answer 11/24.
<result>E</result>
On a counter of a donuts store, there are only 16 identical donuts, 11 filled with chocolate and 5 filled with jelly, but the seller tells me that the donuts are randomly placed on the counter. If would want to buy two, what is the probability that I choose one donuts of each flavor?