Find the least number which when divided by 33 and 8 leaves a remainder of 2 in each case. Options:
A) 266
B) 268
C) 270
D) 272
E) 274
The least number which when divided by different divisors leaving the same remainder in each case   = LCM(different divisors) + remainder left in each case.   Hence the required least number   = LCM(33, 8) + 2 = 266.   266NSWER:266
<result>A</result>
Find the least number which when divided by 33 and 8 leaves a remainder of 2 in each case.