If x^2 – 3x = 18, then one possible value of x – 4 =	Pick one:
A) -9
B) -5
C) -3
D) -1
E) 2
x^2 – 3x = 18   i.e. x^2 – 3x - 18 = 0   i.e. x^2 –6x + 3x - 18 = 0   i.e. (x-6)(x+3) = 0   i.e. x = 6 or -3   i.e. x-4 = 6-4 or -3-4   i.e. x-4 = 2 or -7   Answer: Option 2
<result>E</result>
If x^2 – 3x = 18, then one possible value of x – 4 =