What is the largest number that will divide 90207, 232585 and 127986 without leaving a
remainder?	Select:
A) 257  B) 905  C) 351  D) 498  E) 398
HCF is the best solution. bit its time taking.   see the numbers 90207 , 232585 , 127986.   choose 905. but its not possible because last digit must be 0 or 5.   choose 498. it is also not possible because last dight must be an even number.   only 2 left now.   its easy now to get the answer by division method   ans is 257.   257NSWER:257
<result>A</result>
What is the largest number that will divide 90207, 232585 and 127986 without leaving a
remainder?