A box contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the box, if at least one black ball is to be included in the draw?	Choose the correct choice: A) 32 B) 48 C) 64 D) 96 E) None
We may have(1 black and 2 non-black) or (2 black and 1 non-black) or (3 black).   Required number of ways	= (3C1 x 6C2) + (3C2 x 6C1) + (3C3)   = 3 x((6 x 5)/(2x1))	+((3 x 2)/(2x1))x 6+ 1   = (45 + 18 + 1)= 
<gadget id="calculator">(45 + 18 + 1)</gadget>
<output>64</output>
64.   Option 64
<result>C</result>
A box contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the box, if at least one black ball is to be included in the draw?