What is the probability that when a hand of 6 cards is drawn from a well shuffled deck of 52 cards, It contains 2 Queen? Options:
A) 1/23445	B) 113/22434	C) 29187/1017926	D) 1017926/29187	E) None of these
nCr = n!/(n-r)!r!   Total number of possible hands = 52C6   52C6 = (52!)/((52-6)! × 6!)   52C6 = 61075560.   Number of hands with 2 Queen and 4 non-Queen cards = 4C2 × 48C4   4C2 = (4!)/(2! × 2!) = 6.   4829187/10179264 = (48!)/(44! × 4!) = 3 × 47 × 46 × 45 = 291870   (other 2 cards must be chosen from the rest 48 cards)   P (2 Queen) = (429187/10179262 × 4829187/10179264)/5229187/10179266 = 29187/1017926   29187/1017926
<result>C</result>
What is the probability that when a hand of 6 cards is drawn from a well shuffled deck of 52 cards, It contains 2 Queen?