Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 38 percent ryegrass, what percent of the weight of this mixture is X ?	Select
A) 10%	B) 33.33 %	C) 40%	D) 86.66%	E) 66.66 %
----------------&gt;Ryegrass   X--------------&gt;	40%   Y--------------&gt;	25%   M(mixture)----&gt;38%   0.4X + (M-X)0.25 = 0.38M   0.15X = 0.13M   X = 0.8666M   X = 86.66% of M   86.66%
<result>D</result>
Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 38 percent ryegrass, what percent of the weight of this mixture is X ?