If q and d are both integers, q>d, and -3q>19, then the largest value of d would be?	Select the correct option:  A) -5  B) -6  C) -7  D) -8  E) -10
No, your thinking is incorrect. When we know that q&gt;d and q&lt;-6.33, the largest value of q can be -7 while if q=-7, then largest value of d &lt; -7 will be -8.For negative numbers, -7 &gt; -8 and -8&gt; -10.   You are right in saying that d can take any value less than -7 ---&gt; d could be -8, -9, -10 .... and out of all these values, -8 is the greatest.   Look at the numbers on the number line. For any 2 numbers, the ones on the right are greater than the ones on the left:   .......-11 -10 -9 -8 -7 -6 -5 ..... 0 1 2 3 4 5 6 ... (-11&lt; -10, -10&lt; -8, 4&lt; 5 etc).   So, as per the question if d&lt;q and q = -7 , then d's largest 'possible' value has to be -8.   -10 is smaller than -8=-8
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If q and d are both integers, q>d, and -3q>19, then the largest value of d would be?