Into a bag there are 20 honey and 5 cherry candies. If a boy pick only two candies simultaneous and randomly, what is the probability that he picks one candy of each flavor?
Options
A) 2/25
B) 1/50
C) 1/12
D) 1/6
E) 1/3
We are told that we have 25 candies, 20 honey and 5 cherry candies. The candies are picked simultaneous and randomly, C1 and C2, in different flavors. There are two acceptable outcomes: 1) C1 is honey and C2 is cherry; 2) C1 is cherry and C2 is honey. Let's go: 1) C1 = (20/25)(5/24)= 1/6 chance of this happening. 2) C2 = (5/25)(20/24) = 1/6 chance of this happening. Then: (1/6)+(1/6)= 1/3, chance of getting the result that you wanted. Answer 1/3.
<result>E</result>
Into a bag there are 20 honey and 5 cherry candies. If a boy pick only two candies simultaneous and randomly, what is the probability that he picks one candy of each flavor?