A student was asked to find the arithmetic mean of the numbers 13,31,78,92,115,103,68,10,57,21,34 and a. He found the mean to be 60. What should be the remainder in the place of a?	Select.
A) 98	B) 105	C) 120	D) 165	E) 132
We have (13+31+78+92+115+103+68+10+57+21+34+a) / 12 = 60   622+a= 720   a = 98   98nswer is 98
<result>A</result>
A student was asked to find the arithmetic mean of the numbers 13,31,78,92,115,103,68,10,57,21,34 and a. He found the mean to be 60. What should be the remainder in the place of a?