The sum of all two digit numbers divisible by 6 is Select the correct option: A) 910 B) 510 C) 710 D) 610 E) 810
Required numbers are 12,18,24 . . . . . 96   This is an A.P. in which a=12,d=6 and l=96.   Let the number of terms in it be n.Then t=96   So a+(n-1)d=96.   12+(n-1)*6=96,   12+6n-6=96   6+6n=96   6n=96-6= 
<gadget id="calculator">96-6</gadget>
<output>90</output>
90/6= 
<gadget id="calculator">90/6</gadget>
<output>15</output>
15.   Required sum=n/2(a+l)   =15/2(12+96)   =810   Answer is 810.
<result>E</result>
The sum of all two digit numbers divisible by 6 is