In a triangle ABC,point D is on side AB and point E is on side AC,such that BCED is a trapezium.DE:BC =3:5.Calculate the ratio of the area of triangle ADE and the trapezium BCED.
Choose the correct option:
A) 9/16  B) 8/16  C) 7/16  D) 6/16  E) 5/16
area of tri(9/16DE)/area of tri(9/16BC) = DE^2 / BC^2 since tri(9/16DE) -tri(9/16BC)   area of tri(9/16DE)/area of tri(9/16BC) = 9/25   area of tri(9/16BC)/area of tri(9/16DE) = 25/9   area of tri(9/16BC) = area of tri(9/16DE) + area of trap(BCDE)   (area of tri(9/16DE) + area of trap(BCDE))/area of tri(9/16DE) = 25/9   1 + area of trap(BCDE)/area of tri(9/16DE) = 25/9   take1on both sides   area of trap(BCDE)/area of tri(9/16DE) = (25/9) - 1 = 16/9   since question is asking for area of tri(9/16DE)/area of trap(BCDE) = 9/16   9/16NSWER:9/16
<result>A</result>
In a triangle ABC,point D is on side AB and point E is on side AC,such that BCED is a trapezium.DE:BC =3:5.Calculate the ratio of the area of triangle ADE and the trapezium BCED.