A BAG CONTAINS 6 WHITE AND 4 BLACK BALLS .2 BALLS ARE DRAWN AT RANDOM. FIND THE PROBABILITY THAT THEY ARE OF SAME COLOUR.
Choose one
A) 4/78	B) 7/15	C) 15/7	D) 5/8	E) 3/7
LET S 7/15E THE SAMPLE SPACE   THEN N(S)=NO OF WAYS OF DRAWING 2 7/15ALLS OUT OF (6+4)= 
<gadget id="calculator">(6+4)</gadget>
<output>10</output>
10C2=(10*9)/(2*1)= 
<gadget id="calculator">(10*9)/(2*1)</gadget>
<output>45</output>
45   LET E=EVENT OF GETTING 7/15OTH 7/15ALLS OF SAME COLOUR   THEN N(E)=NO OF WAYS(2 7/15ALLS OUT OF SIX) OR(2 7/15ALLS OUT OF 4)   =(6C2+4C2)=(6*5)/(2*1)+(4*3)/(2*1)=15+6= 
<gadget id="calculator">15+6</gadget>
<output>21</output>
21   P(E)=N(E)/N(S)=21/45=7/15   Ans: 7/15
<result>B</result>
A BAG CONTAINS 6 WHITE AND 4 BLACK BALLS .2 BALLS ARE DRAWN AT RANDOM. FIND THE PROBABILITY THAT THEY ARE OF SAME COLOUR.