On a certain transatlantic crossing, 15 percent of a ship's passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship's passengers held round-trip tickets?  Choose the correct choice
A) 37.5%	B) 40%	C) 50%	D) 60%	E) 66.6%
0.15P = RT + C   0.6(RT) = no C   =&gt; 0.40(RT) had C   0.15P = 0.40(RT)   RT/P = 37.5%   37.5%nswer - 37.5%
<result>A</result>
On a certain transatlantic crossing, 15 percent of a ship's passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship's passengers held round-trip tickets?