What is the smallest of six consecutive odd integers whose average (arithmetic mean) is x + 2?
Pick.
A) x - 5 B) x - 3 C) x - 1 D) x E) x + 1
Assume the integers to be   n - 5, n - 3, n- 1, n+1, n + 3, n + 5   AM = 6n/6 = n   Given n = x + 2   Therefore, smallest term = n - 5 = x + 2 - 5 = x - 3   Correct Option: x - 3
<result>B</result>
What is the smallest of six consecutive odd integers whose average (arithmetic mean) is x + 2?