The present ages of three persons are in proportions 4:7:9 Eight years ago ,the sum of their ages was 56.Find their present ages (in years)	Options
A) 8,20,28
B) 16,28,36
C) 20,35,45
D) None of these
E) Cannot be determined
Solution   Let their present ages be 4x,7x and 9x years respectively.   Then,(4x-8)+(7x -8)+ (9x-8)=56 ⇔ 20x =80 ⇔ x=4.   ∴ Their present ages are 16 years ,28 years and 36 year respectively. Answer 16,28,36
<result>B</result>
The present ages of three persons are in proportions 4:7:9 Eight years ago ,the sum of their ages was 56.Find their present ages (in years)