Bill spends two days driving from Point A to Point B . On the first day, he drove 2 hours longer and at an average speed 5 miles per hour faster than he drove on the second day. If during the two days he drove a total of 680 miles over the course of 18 hours, what was his average speed on the second day, in miles per hour?  Select the correct option:
A) 20  B) 25  C) 28  D) 30  E) 35
First recognize that we have TWO pieces of information regarding the time Bill spent driving each day.   On day 1, Bill drove 2 hours longer than he drove on day 2.   So, let x = # of driving hours on day 2   Then x + 2 = # of driving hours on day 1   Bill drove a TOTAL of 18 hours   So, x + (x + 2) = 18   Simplify: 2x + 2 = 18   Solve, x = 8   So, Bill drove 10 hours on day 1 and he drove 8 hours on day 2   Now let's solve the question by starting with a word equation.   Let x = speed driven on day 2   So, x + 5 = speed driven on day 1   (Distance traveled on day 1) + (Distance traveled on day 2) = 680   Distance = (rate)(time)   We get: (x+ 5)(10) + (x)(8) = 680   35xpand: 10x + 50 + 8x = 680   Simplify: 18x + 50 = 680   18x = 630   x = 35 (mph)   ANSW35R:35
<result>E</result>
Bill spends two days driving from Point A to Point B . On the first day, he drove 2 hours longer and at an average speed 5 miles per hour faster than he drove on the second day. If during the two days he drove a total of 680 miles over the course of 18 hours, what was his average speed on the second day, in miles per hour?