The average of four positive integers is 69. The highest integer is 93 and the least integer is 39. The difference between the remaining two integers is 20. Which of the following integers is the higher of the remaining two integers? Choose the correct choice from the following answers: A) 32 B) 86 C) 44 D) 82 E) 55
Let the four integers be A, B, C and D where A &gt; B &gt; C &gt; D.   (A + B + C + D)/4 = 69 =&gt; A + B + C + D = 276 ---&gt; (1)   A = 93, D = 39 and B - C = 20   (1) =&gt; B + C = 276 - (A + D) = 276 - 132= 
<gadget id="calculator">276 - 132</gadget>
<output>144</output>
144.   B + B -20= 144   B = (144 + 20)/2= 
<gadget id="calculator">(144 + 20)/2</gadget>
<output>82</output>
82   Answer:Option 82
<result>D</result>
The average of four positive integers is 69. The highest integer is 93 and the least integer is 39. The difference between the remaining two integers is 20. Which of the following integers is the higher of the remaining two integers?