In the coordinate plane, one of the vertices of a square is the point (-6, -4). If the diagonals of that square intersect at point (3, 2), what is the area of that square?  Answers:  A) 100  B) 169  C) 324  D) 196  E) 225
One point (-6-4), Intersection (3,2) so the distance from the first point -6-3=-9 is the midpoint of the square --&gt; whole side 18, 18*18=324   324
<result>C</result>
In the coordinate plane, one of the vertices of a square is the point (-6, -4). If the diagonals of that square intersect at point (3, 2), what is the area of that square?