If a 4-digit integer is selected at random from the integers 6000 through 6999, inclusive, what is the probability that the first digit and the last digit of the integer are each equal to three times the tens digit and two times the hundreds digit?  Pick.
A) 1/999 B) 3/6000 C) 1/1000 D) 3/2000 E) 2/3000
Thousand digit has to be 6 . So units digit needs to 6 as well   Both Hundreds and Units digit needs to be 3 times the tens digit   6/3= 
<gadget id="calculator">6/3</gadget>
<output>2</output>
2   The tens digit is 2   Both Hundreds and Units digit needs to be 2 times the hundreds digit    6/2= 
<gadget id="calculator"> 6/2</gadget>
<output>3</output>
3   The hundreds digit is 3   The number is 6326   Total numbers between 6000 and 6999= (6999-6000)+1= 
<gadget id="calculator">(6999-6000)+1</gadget>
<output>1_000</output>
1000   Probability= 1/1000   Answer 1/1000
<result>C</result>
If a 4-digit integer is selected at random from the integers 6000 through 6999, inclusive, what is the probability that the first digit and the last digit of the integer are each equal to three times the tens digit and two times the hundreds digit?