In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there Pick.
A) 109	B) 128	C) 138	D) 209	E) 176
Explanation:   In a group of 6 boys and 4 girls, four children are to be selected such that   at least one boy should be there.   So we can have   (four boys) or (three boys and one girl) or (two boys and two girls) or (one boy and three gils)   This combination question can be solved as   (6C4)+(6C3∗4C1)++(6C2∗4C2)+(6C1∗4C3)   =[6×5/2×1]+[(6×5×4/3×2×1)×4]+[(6×5/2×1)(4×3/2×1)]+[6×4]   =15+80+90+24= 
<gadget id="calculator">15+80+90+24</gadget>
<output>209</output>
209   Option 209
<result>D</result>
In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there