At the beginning of a year ,the owner of a jewel shop raised the price of all the jewels in his shop by x% and lowered them by x%. The price of one jewel after this up and down cycle reduced by Rs.100.The owner carried out the same procedure after a month.After this second up-down cycle,the price of that jewel was Rs.2304.Find the original price of that jewel(in Rs.)  Pick one:	A) 2500	B) 550	C) 2600	D) 2650	E) None of these
Solution: Let the original price = y,   After first change, It becomes,   y * (1+(x/100))   After second change, It becomes   y *(1+(x/100))(1-(x/100)) = y(1-(x/100)^2 )   Thus,   x2*y = 106 ------- (1)   x2 = 106/y   Now,   y(1-(106/10000y))2 = 2304(similar to above)   y(1-100/y)2 = 2304   y = 2500.   2500nswer: Option 2500
<result>A</result>
At the beginning of a year ,the owner of a jewel shop raised the price of all the jewels in his shop by x% and lowered them by x%. The price of one jewel after this up and down cycle reduced by Rs.100.The owner carried out the same procedure after a month.After this second up-down cycle,the price of that jewel was Rs.2304.Find the original price of that jewel(in Rs.)