The sum of all two digit numbers divisible by 7 is Answers.
A) 910	B) 510	C) 728	D) 628	E) 810
Required numbers are 14,21,28 . . . . . 98   This is an A.P. in which a=14,d=7 and l=98.   Let the number of terms in it be n.Then t=98   So a+(n-1)d=98.   14+(n-1)*7=98,   14+7n-7=98   7+7n=98   7n=98-7= 
<gadget id="calculator">98-7</gadget>
<output>91</output>
91/7= 
<gadget id="calculator">91/7</gadget>
<output>13</output>
13.   Required sum=n/2(a+l)   =13/2(14+98)   =728   Answer is 728.
<result>C</result>
The sum of all two digit numbers divisible by 7 is