A jogger running at 9 kmph along side a railway track is 270 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger? Select
A) 3.6 sec	B) 18 sec	C) 36 sec	D) 39 sec	E) None of these
Speed of train relative to jogger   = (45 – 9) km/h = 36 km/h   = (36 × 5⁄18) m/sec = 10 m/sec   Distance to be covered = (270 + 120)= 
<gadget id="calculator">(270 + 120)</gadget>
<output>390</output>
390 m.   ∴ Time taken= (390⁄10) sec = 39 sec.   Answer 39 sec
<result>D</result>
A jogger running at 9 kmph along side a railway track is 270 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?