A solution of 100 litres contains milk and water in the ratio 5:x. If ten litres of water is added to the solution, the ratio becomes 3:2, find the value of x?  Choose one.
A) 2.68
B) 2.55
C) 2.34
D) 2.57
E) 2.89
Exp. Total new quantity = original sol + water =100+10= 
<gadget id="calculator">100+10</gadget>
<output>110</output>
110   New ratio= 3:2, New quantity of milk =3/5*110= 
<gadget id="calculator">3/5*110</gadget>
<output>66</output>
66 Lit,   New quantity of water= 2/5*110= 
<gadget id="calculator">2/5*110</gadget>
<output>44</output>
44 Lit   Water present initially= (44-10)= 
<gadget id="calculator">(44-10)</gadget>
<output>34</output>
34 Lit   Ratio= 66/34 =5/x There for x = 2.57   Answer: 2.57
<result>D</result>
A solution of 100 litres contains milk and water in the ratio 5:x. If ten litres of water is added to the solution, the ratio becomes 3:2, find the value of x?