In an increasing sequence of 12 consecutive even integers, the sum of the first 4 integers is 268. What is the sum of all the integers in the sequence?  Choose the correct choice: A) 552 B) 668 C) 774 D) 888 E) 990
let the first term of the sequence be x   since it is consecutive even integers the terms be we x, x+2,x+4...x+14 (up to 12 terms)   now,   sum of first 4 terms =268   or,   4x+16=268   x=252/4= 
<gadget id="calculator">252/4</gadget>
<output>63</output>
63   Thus the answer can now be calculated by either summing up 63+65+67+... 12th term   or   s=n/2(2a+(n-1)d   =12/2(2*63+(11*2))   =6(126+22)=888   888
<result>D</result>
In an increasing sequence of 12 consecutive even integers, the sum of the first 4 integers is 268. What is the sum of all the integers in the sequence?