If two different solutions of alcohol with a respective proportion of water to alcohol of 3:1 and 2:3 were combined, what is the concentration of alcohol in the new solution if the original solutions were mixed in equal amounts?
Choose one.
A) 30.0%  B) 36.6%  C) 42.5%  D) 44.4%  E) 60.0%
Alcohol: Water   First mixture -- 3:1 -- 15:5   Second mixture -- 2:3 -- 8:12   Equal amounts of the mixture were combined, hence the final mixture will be in the ratio -- (15+8): (5+12) -- 23:17   % of alcohol -- 17/(23+17) * 100   = (17/40) * 100= 
<gadget id="calculator">(17/40) * 100</gadget>
<output>85/2 = around 42.5</output>
42.5   ANSWER:42.5%
<result>C</result>
If two different solutions of alcohol with a respective proportion of water to alcohol of 3:1 and 2:3 were combined, what is the concentration of alcohol in the new solution if the original solutions were mixed in equal amounts?