There are 8 balls in a bucket, 4 balls are blue and 4 balls are red. If two ball chosen randomly , how many chances there are at least one blue ball will present? Choose the correct choice from the following choices:
A) 21  B) 25  C) 16  D) 22  E) 20
Two ball will be chosen. At least 1 blue ball   Total ways = 8C2 = 28   Total without any blue ball = 4C2 = 6   Hence ways in which at least one blue will be present = 28 - 6= 
<gadget id="calculator">28 - 6</gadget>
<output>22</output>
22   Correct option: 22
<result>D</result>
There are 8 balls in a bucket, 4 balls are blue and 4 balls are red. If two ball chosen randomly , how many chances there are at least one blue ball will present?