There are 12 cans in the refrigerator. 7 of them are red and 5 of them are blue. In how many ways we can remove 11 cans so that at least one red and at least one blue cans to remain the refrigerator.	Answers.
A) 4  B) 490  C) 493  D) 455  E) 445
Ways to pick 1 cans so that at least one red and at least one blue cans to remain the refrigerator =   total ways to pick 1 can out of 12 - ways to pick 1 red out of 7 red - ways to pick 1 blue out of 5 blue   12C1âˆ’7C1âˆ’5C1=12âˆ’7âˆ’1=4   4NSWER:4
<result>A</result>
There are 12 cans in the refrigerator. 7 of them are red and 5 of them are blue. In how many ways we can remove 11 cans so that at least one red and at least one blue cans to remain the refrigerator.