After harvest, out of a total of N apples from an orchard, if 1/4 of those tested had infection A and, of those with infection A, 1/2 also had infection B, how many apples did not have both infection A and B?
Select the correct option:
A) N/15  B) 7N/8  C) 14N/15  D) N/5  E) 4N/5
1/4 of tested had infection A, thus N/4 had infection A;   Of those with infection A, 1/2 also had infection B, thus 1/2*N/4 = N/8 had both infections A and B.   Therefore, N - N/8 = 7N/8 did not have both infection A and B.   Answer: 7N/8.
<result>B</result>
After harvest, out of a total of N apples from an orchard, if 1/4 of those tested had infection A and, of those with infection A, 1/2 also had infection B, how many apples did not have both infection A and B?