If m > 1 and n = 2^(m−2), then 4^m =	Choose the correct answer:
A) 16n^2
B) 4n^2
C) n^2
D) n^2/4
E) n^2/16
n = 2^(m-2) = 2^m/4   2^m = 4n   4^m = (2^m)^2 = (4n)^2 = 16n^2   The answer is 16n^2.
<result>A</result>
If m > 1 and n = 2^(m−2), then 4^m =