If d=1/(2^3*5^9) is expressed as a terminating decimal, how many nonzero digits will d have?  Pick one
A) One	B) Two	C) Three	D) Seven	E) Ten
Another way to do it is :   We know x^a*y^a=(X*Y)^a   given = 1/(2^3*5^9)   = Multiply and divide by 2^4   =2^6/(2^3*2^6*5^9)   =2^6/10^9   =&gt; non zero digits are 64 =&gt; Ans Two
<result>B</result>
If d=1/(2^3*5^9) is expressed as a terminating decimal, how many nonzero digits will d have?