Given x = 20o, what is the value of log5(tan x)-log5(sin x)+log5(cos x)? Choose one.
A) 0 B) 1 /2 C) 1 D) log5 2 E) log2 5
One approach is to use that   A + F = (A+B) + (C +D) + (E +F)􀀀(B +C)􀀀(D+E) = 1 + 3 +5􀀀2􀀀4 = 3:   The answer can also be obtained by taking A = 1 and solving for the remaining variables.   Since A + B = 1, we get B = 0. Since B + C = 2, we get C = 2. Continuing, we get   D = 1, E = 3, and F = 2. Thus, A + F = 1 + 2= 
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
3 is a possibility. There are other   possibilities for the variables A;B; : : : ; F (just set A equal to something else), but in any   case the sum A + F will be 3.   correct answer 0
<result>A</result>
Given x = 20o, what is the value of log5(tan x)-log5(sin x)+log5(cos x)?