In a survey of 335 employees, 104 of them are uninsured, 54 work part time, and 12.5 percent of employees who are uninsured work part time. If a person is to be randomly selected from those surveyed, what is the probability that the person will neither work part time nor be uninsured? Choices.
A) 38/67
B) 8/41
C) 9/348
D) 1/8
E) 41/91
---------UI----------------NUI-------Total   PT ----(12.5/100)*104= 
<gadget id="calculator"> ----(12.5/100)*104</gadget>
<output>13</output>
13----------- --54   NPT---104-13-------------- x--------281   Total--104----------------------------335   we have to find not part time and not uninsured . in other words not part time and insured= x/335 = (281-104+13)/335   = 38/67   38/67nswer is 38/67.
<result>A</result>
In a survey of 335 employees, 104 of them are uninsured, 54 work part time, and 12.5 percent of employees who are uninsured work part time. If a person is to be randomly selected from those surveyed, what is the probability that the person will neither work part time nor be uninsured?