The simple interest at z% for z years will be $z on a sum of  Choose the correct choice
A) $ (1000)/z B) $(100)z^2 C) $ z D) $ (100)/z E) $ 100z
Principal =$(100*z)/(z*z)=$(100/z).   Answer is $ (100)/z
<result>D</result>
The simple interest at z% for z years will be $z on a sum of