A box contains 4 chocobars and 4 ice creams. Tom eats 3 of them, by randomly choosing. What is the probability of choosing 2 chocobars and 1 icecream?
Choose the correct choice from the following choices:
A) 9/3
B) 1/7
C) 2/8
D) 2/7
E) 4/7
Probability of choosing 1 chocobar = 4/8 = 1/2   After taking out 1 chocobar, the total number is 7.   Probability of choosing 2nd chocobar = 3/7   Probability of choosing 1 icecream out of a total of 6 = 4/6 = 2/3   So the final probability of choosing 2 chocobars and 1 icecream = 1/2 * 3/7 * 2/3 = 1/7   1/7
<result>B</result>
A box contains 4 chocobars and 4 ice creams. Tom eats 3 of them, by randomly choosing. What is the probability of choosing 2 chocobars and 1 icecream?