The average of 10 consecutive integers is 11. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average?  Choose one:
A) 5 B) 5.5 C) 6 D) 6.5 E) 7
The total subtracted is (9+8+...+1) = (9*10) / 2= 
<gadget id="calculator">(9*10) / 2</gadget>
<output>45</output>
45   On average, each number will be reduced by   45/10= 
<gadget id="calculator">  45/10</gadget>
<output>9/2 = around 4.5</output>
4.5   Therefore, the overall average will be reduced by 4.5   The answer is 6.5.
<result>D</result>
The average of 10 consecutive integers is 11. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average?