A pack of baseball cards consists of 12 outfielder cards and 8 infielder cards. What is the lowest number of outfielder cards that would have to be removed from the pack so that no more than 40 percent of the pack would be outfielder cards? Choose the correct choice.
A) 4	B) 5	C) 6	D) 7	E) 8
Solution: Let x be the number of outfielder cards remaining of removal.   x &lt;= 0.4(8+x) ===&gt; 0.6x &lt;= 3.2 ==&gt; x &lt;= 5.33   S0, x = 5   So no. of cards to be removed is 12-5= 
<gadget id="calculator">12-5</gadget>
<output>7</output>
7.   Option 7
<result>D</result>
A pack of baseball cards consists of 12 outfielder cards and 8 infielder cards. What is the lowest number of outfielder cards that would have to be removed from the pack so that no more than 40 percent of the pack would be outfielder cards?