Two dice are thrown together .What is the probability that the sum of the number on the two faces is divided by 4 or 6 Pick one
A) 3/18  B) 5/18  C) 18/7  D) 18/5  E) 7/18
Clearly n(S)=6*6= 
<gadget id="calculator">6*6</gadget>
<output>36</output>
36   Let E be the event that the sum of the numbers on the two faces is divided by 4 or 6.Then   E={(1,3),(1,5),(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(5,1),(5,3),(6,2),   (6,6)}   n(E)=14.   Hence p(e)=n(e)/n(s)=14/36=7/18   Option: 7/18
<result>E</result>
Two dice are thrown together .What is the probability that the sum of the number on the two faces is divided by 4 or 6