If M is the set of all consecutive multiples of 9 between 100 and 500, what is the median of M?  Pick one:
A) 300	B) 301	C) 301.5	D) 302.5	E) 306
Since 100/9 =11.11, 500/9=55.55, M can be written as {9*12, 9*13, ...., 9*54, 9*55}. The number of elements of M is, therefore, 44(=55-12+1). Since the number of elements is even number the median is the average of the 22nd element(=9*33) and 23rd element(=9*34). So the median is (9*33 + 9*34)/2 = 301.5. The answer is 301.5.
<result>C</result>
If M is the set of all consecutive multiples of 9 between 100 and 500, what is the median of M?