A coin has two sides. One side has the number 1 on it and the other side has the number 2 on it. If the coin is flipped three times what is the probability that the sum of the numbers on the landing side of the coin will be greater than 3?
Choose the correct choice from the following.
A) 3/8	B) 1/16	C) 7/8	D) 1/2	E) 1/4
One approach to solve the problem is to list the different possibilities for a toss of coin three times. Because there are two outcomes and the coin is tossed three times, the table will have 2*2*2 or 8 rows.   Next add the resulting rows together to find the sum (the fourth column in the table below).   Toss 1 | Toss 2 | Toss 3 | Sum   1 ---------- 1 -------- 1 ------ 3   1 ---------- 1 -------- 2 ------ 4   1 ---------- 2 -------- 1 ------ 4   1 ---------- 2 -------- 2 ------ 5   2 ---------- 1 -------- 1 ------ 4   2 ---------- 1 -------- 2 ------ 5   2 ---------- 2 -------- 1 ------ 5   2 ---------- 2 -------- 2 ------ 6   From the table we see that there are 7 situations where the sum of the tosses will be greater than 3. And there are 8 possible combinations resulting in a probability of   7/8 or a probability of 7/8.   SO the correct answer is 7/8.
<result>C</result>
A coin has two sides. One side has the number 1 on it and the other side has the number 2 on it. If the coin is flipped three times what is the probability that the sum of the numbers on the landing side of the coin will be greater than 3?