In a box, there are 6 red, 2 blue and 3 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?
Select the correct option
A) 6/11	B) 8/21	C) 3/7	D) 9/22	E) 10/21
Explanation:   Total number of balls = (6 + 2 + 3)= 
<gadget id="calculator">(6 + 2 + 3)</gadget>
<output>11</output>
11   Let E= event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.   Therefore, n(E) = 6.   P(E) = 6/11.   6/11nswer: Option 6/11
<result>A</result>
In a box, there are 6 red, 2 blue and 3 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?