A cask full of milk,'E' liters is removed and water is mixed. This process is repeated and now the ratio in milk to water is 16:9. Then what is the amount of milk in liter.
Choose the correct choice from the following.
A) E+9
B) 9E
C) 5E
D) 8E
E) cant be determined
After 'n' operations ,the amount of pure liquid remaining is = [x { ( 1-E/x )^n } ]...where x is original amount of liquid and E is amount of liquid removed..This is standard formula in RS aggarwal...   Now ,in our case the operations is performed twice...   Let the original milk be x liters..   E liters removed twice n = 2,   milk remaining (M) = [ x { (1-E/x)^2 } ]....water is (W) = x - [x { (1-E/x)^2 } ]   M/W = 16/9 Take (1-E/x)^2 = z   now solving we get z = 16/25 that is (1 - E/x)^2 = (4/5)^2   1 - E/x = 4/5   x = 5E   ANSWER:5E
<result>C</result>
A cask full of milk,'E' liters is removed and water is mixed. This process is repeated and now the ratio in milk to water is 16:9. Then what is the amount of milk in liter.