Three cards are drawn successively, without replacement from a pack of 52 well shuffled cards.
What is the probability that first two cards are queens and the third card drawn is an ace?
Pick:
A) 2/5521  B) 2/5529  C) 5525/2  D) 1/5525  E) 2/5525
Let Q denote the event that the card drawn is queen and A be the event that   the card drawn is an ace. Clearly, we have to find P (QQA)   Now P(Q) = 4/52   Also, P (Q|Q) is the probability of second queen with the condition that one queen has   already been drawn. Now there are three queen in (52 - 1)= 
<gadget id="calculator">(52 - 1)</gadget>
<output>51</output>
51 cards.   Therefore P(Q|Q)= 3/51   P(A|QQ) is the probability of third drawn card to be an ace, with the condition   that two queens have already been drawn. Now there are four aces in left 50 cards.   Therefore P(A|QQ) = 4/50   By multiplication law of probability, we have   P(QQA) = P(Q) P(Q|Q) P(A|QQ)   = 4/52 × 3/51 × 4/50   = 2/5525.   2/5525
<result>E</result>
Three cards are drawn successively, without replacement from a pack of 52 well shuffled cards.
What is the probability that first two cards are queens and the third card drawn is an ace?