In a certain city , there are two football teams , 65 percent of the people prefer team (A) and the rest prefer team (B),
Team (A) is going to play against team (C) from another city. If 80 percent of people who prefer team (A) are going to attend the match , and 20 percent of the people who prefer team (B) are going to attend the match , what percent of city's people are going to attend the match ?  Choices:	A) 45%	B) 59%	C) 60%	D) 61%	E) 68%
say the population of the city is 100 person , so there are 65 persons prefer team (A) and 35 persons prefer team(B) .   65*0.8= 
<gadget id="calculator">65*0.8</gadget>
<output>52</output>
52 person who prefer team (A) are going to attend the match   35*0.2= 
<gadget id="calculator">35*0.2</gadget>
<output>7</output>
7 person who prefer team (B) are going to attend the match   Thus total of   52+7= 
<gadget id="calculator">  52+7</gadget>
<output>59</output>
59 persons are going to attend the match , which is 59 percent of population.   answer: 59%
<result>B</result>
In a certain city , there are two football teams , 65 percent of the people prefer team (A) and the rest prefer team (B),
Team (A) is going to play against team (C) from another city. If 80 percent of people who prefer team (A) are going to attend the match , and 20 percent of the people who prefer team (B) are going to attend the match , what percent of city's people are going to attend the match ?