The altitude drawn to the base of an isosceles triangle is 8 cm and the perimeter is 32 cm. The area of the triangle is
Choose the correct choice from the following answers:
A) 72 cm2 B) 60 cm2 C) 66 cm2 D) 65 cm2 E) None of these
Let ABC be the isosceles triangle and AD be the altitude.   Let AB = AC = x. Then, BC = (32 – 2x).   Since, in an isosceles triangle, the altitude bisects the base. So, BD = DC = (16 – x).   In ΔADC, AC2 = AD2 + DC2   ⇒ x2 = (8)2 + (16 – x)2   ⇒ 32x = 320 ⇒ x = 10.   ∴ BC = (32 – 2x) = (32 – 20) cm = 12 cm.   Hence, required area = (1⁄2 × 60 cm2C × AD)   = (1⁄2 × 12 × 10) cm2 = 60 cm2   Answer 60 cm2
<result>B</result>
The altitude drawn to the base of an isosceles triangle is 8 cm and the perimeter is 32 cm. The area of the triangle is