Which of the following describes all values of x for which 16-x^2 ≥ 0 ?
Choose one.
A) x ≥ 1	B) x ≤ -1	C) 0 ≤ x ≤ 1	D) x ≤ -1 or x ≥ 1	E) -4 ≤ x ≤ 4
16-x^2 &gt;= 0 ---&gt; x^2-16&lt;=0   --&gt; (x+4)(x-4)&lt;=0   Above equation true for   i) x+4&lt;=0 and x-4&gt;=0 ---&gt; x&lt;= -4 and x&gt;=4 ---&gt; this is not possible ---Strike out this solution   ii) x+4&gt;=0 and x-4&lt;=0 ---&gt; x&gt;=-4 and x&lt;=4 --&gt; -4&lt;=x&lt;=4   answer -4 ≤ x ≤ 4
<result>E</result>
Which of the following describes all values of x for which 16-x^2 ≥ 0 ?