Find the area of a rhombus having each side equal to 13 cm and one of whose diagonal is 24 cm.	Select the correct option:
A) 150 sq.cm
B) 120 sq.cm
C) 130 sq.cm
D) 125 sq.cm
E) 110 sq.cm
Let ABCD is a rhombus with diagonals AC and BD which intersect each other at O.   AC = 24 ⇒ AO = 12   Let BO = x and AB = 13 cm (given)   By Pythagorean theorem   c 2 = a 2 + b 2   13 2 = 12 2 + x 2 169 = 144 + x 2   x 2 = 169 – 144   x 2 = 25   x = 5 cm   BO = 5 cm   Diagonal BD = 2 x 5 = 10 cm.   Area = ½ x [ product of diagonals]   = ½ x 24 x 10   Area = 120 sq.cm   Answer is 120 sq.cm
<result>B</result>
Find the area of a rhombus having each side equal to 13 cm and one of whose diagonal is 24 cm.