How many numbers between 100 and 798 are divisible by 2, 3, and 7 together?
Choose the most appropriate option:	A) 112	B) 77	C) 267	D) 17	E) 99
Explanation:   As the division is by 2, 3, 7 together, the numbers are to be divisible by:  2*3*7= 
<gadget id="calculator"> 2*3*7</gadget>
<output>42</output>
42   The limits are 100 and 798   The first number divisible is 42*3= 
<gadget id="calculator">42*3</gadget>
<output>126</output>
126   To find out the last number divisible by 42 within 798:    798/42= 
<gadget id="calculator"> 798/42</gadget>
<output>19</output>
19   Hence, 42*19= 798 is the last number divisible by 42 within 798   Hence, total numbers divisible by 2, 3, 7 together are (19 â€“ 2) = 17   ANSWER: 17
<result>D</result>
How many numbers between 100 and 798 are divisible by 2, 3, and 7 together?