How many different three-digit multiples of 5 can be composed of digits 1, 3, 4, and 5 if none of the digits is repeated?  Choose the correct choice from the following options:  A) 3  B) 6  C) 10  D) 12  E) 18
= 3c2 x 2 = 6   can you explain your method. i solved it differently   XYZ, where Z must be 5. therefore 1 variation of digit in Z.   Y can be any of the 3 possible choices.   X can be any of the 2 possible choices.   2+3+1= 
<gadget id="calculator">2+3+1</gadget>
<output>6</output>
6   6
<result>B</result>
How many different three-digit multiples of 5 can be composed of digits 1, 3, 4, and 5 if none of the digits is repeated?