What is the absolute value of twice the difference of the roots of the equation W=5y^2 − 20y + 15 = 0 ?  Options.
A) 0 B) 1 C) 2 D) 3 E) 4
W=5y^2 − 20y + 15 = 0 --&gt; y^2 − 4y + 3 = 0 --&gt; y=1 or y=3. The difference is 2, twice the difference is 4.   Answer: 4.
<result>E</result>
What is the absolute value of twice the difference of the roots of the equation W=5y^2 − 20y + 15 = 0 ?