In how many ways can a team of 5 persons be formed out of a total of 10 persons such that two particular persons should not be included in any team? Pick:  A) 56  B) 63  C) 69  D) 67  E) 23
Two particular persons should not be included in each team.   i.e., we have to select 5 persons from   10-2= 
<gadget id="calculator">  10-2</gadget>
<output>8</output>
8 persons.   Hence, required number of ways= 8C5   = 8*7= 
<gadget id="calculator">8*7</gadget>
<output>56</output>
56   56ns - 56
<result>A</result>
In how many ways can a team of 5 persons be formed out of a total of 10 persons such that two particular persons should not be included in any team?