If (A-B-C+D = 13) and (A+B-C-D = 5), what is the value of (B-D)^2? Choose the correct choice from the following options
A) 4.  B) 8.  C) 12.  D) 16  E) 64
A-B-C+16 = 13 -- equation 1   A+B-C-16 = 5 -- equation 2   Adding 1 and 2 , we get   2A - 2C = 18   =&gt; A-C = 9 -- equation 3   Using equation 3 in 2 , we get   B-16 = 5 - 9 = -4   =&gt;(B-16)^2 = 16   Answer 16
<result>D</result>
If (A-B-C+D = 13) and (A+B-C-D = 5), what is the value of (B-D)^2?