A meeting has to be conducted with 5 managers. Find the number of ways in which the managers may be selected from among 8 managers, if there are 2 managers who refuse to attend the meeting together.
Choose the correct choice:
A) 36
B) 40
C) 45
D) 51
E) 56
The total number of ways to choose 5 managers is 8C5 = 56   We need to subtract the number of groups which include the two managers, which is 6C3 = 20.   56 - 20= 
<gadget id="calculator">56 - 20</gadget>
<output>36</output>
36   The answer is 36.
<result>A</result>
A meeting has to be conducted with 5 managers. Find the number of ways in which the managers may be selected from among 8 managers, if there are 2 managers who refuse to attend the meeting together.