What is the sum of the digits of integer k, if k = (10^30- 54) Choices.
A) 251	B) 261	C) 262	D) 269	E) 278
There are 31 digits in 10^30   When we subtract 54 from it, there will be 30 digits left.   10^30 can be written as 9999999....(30 times) + 1   So,   10^30 - 54 = 9999999....(30 times) + 1 - 54 = 9999999....(30 times) - 53   Consider the last 2 digits,   99-53= 
<gadget id="calculator">99-53</gadget>
<output>46</output>
46   The last 2 digits will be 46.   And our number would be 99999......99946 with 2 less 9s after subtraction.   Number of 9s left are 28 and the last two digits are 46   The sum of the digits will be     (28*9) + 4 + 6= 
<gadget id="calculator">  (28*9) + 4 + 6</gadget>
<output>262</output>
262   Answer:- 262
<result>C</result>
What is the sum of the digits of integer k, if k = (10^30- 54)