How many 4-digit numbers can be formed from the digits 0,2, 3, 5, 6, 7 and 9, which are divisible by 5 and if the repetition is not allowed?  Pick one:
A) 200
B) 240
C) 300
D) 360
E) 120
Since, each desired number is divisible by 5, so we must have either 0 or 5 at the unit place.   So , the tens place can now be filled by any of the remaining 6 digits (2, 3, 6, 7, 9, 0 or 5)   the hundreds place can now be filled by any of the remaining 5 digits   therefore the 3-digit no can be formed by   (4 * 5 * 6 * 2)= 
<gadget id="calculator">  (4 * 5 * 6 * 2)</gadget>
<output>240</output>
240 ways   Ans- 240
<result>B</result>
How many 4-digit numbers can be formed from the digits 0,2, 3, 5, 6, 7 and 9, which are divisible by 5 and if the repetition is not allowed?