How many different 3 digit numbers can be formed from the number 891 by re-arranging its digits so that the odd digits occupy even position  Choose the correct choice
A) 5 B) 2 C) 8 D) 7 E) 6
There are 2 odd numbers which have to be placed at 2 even places =2!=2 ways   There are 1 even numbers which have to be placed at 1 odd places. So 1! = 1 ways   so total number of ways of arranging all these numbers are  1 * 2= 
<gadget id="calculator"> 1 * 2</gadget>
<output>2</output>
2 ways   Answer:2
<result>B</result>
How many different 3 digit numbers can be formed from the number 891 by re-arranging its digits so that the odd digits occupy even position