If the sum of three consecutive even numbers is 40 more than the average of these numbers, then the largest of these numbers is?	Options:
A) 20  B) 24  C) 22  D) 26  E) 27
Explanation:   Let the smallest of these number be x. The other two numbers are (x + 2) and (x + 4).   x + (x + 2) + (x + 4) = (X + (X+2) + (x+4)) / 3 + 40   3x + 3*(x + 2) + 3*(x + 4) = x + (x + 2) + (x + 4) + 120   9x + 18 = 3x + 126   6x = 108   x = 18   Therefore, the largest number is 22.   ANSWER 22
<result>C</result>
If the sum of three consecutive even numbers is 40 more than the average of these numbers, then the largest of these numbers is?