Jill is dividing her 12-person class into two teams of equal size for a basketball game. If no one will sit out, how many different match-ups between the two teams are possible?	Options
A) 10 B) 25 C) 462 D) 252 E) 630
With 12 players, the process of figuring out how many groups of 6 can be formed is pretty straight-forward....   12C6 = 12!/(6!6!) = 924 possible groups of 6   Once forming that first group of 6, the remaining 6 players would all be placed on the second team by default.   The 'twist' is that the two teams of 6 canshow upin either order:   462
<result>C</result>
Jill is dividing her 12-person class into two teams of equal size for a basketball game. If no one will sit out, how many different match-ups between the two teams are possible?