How many no.'s with 3 different digits, 2, 3, 5, 6, 7 and 9, which are divisible by 5?	Choose the correct choice:
A) 10
B) 20
C) 30
D) 40
E) 50
Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.   The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.   The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.   Required number of numbers = (1 x 5 x 4) = 20   20
<result>B</result>
How many no.'s with 3 different digits, 2, 3, 5, 6, 7 and 9, which are divisible by 5?