In how many ways can the letters C, A, A, R, W, A be arranged so that the three A's are not next to each other?
Select:
A) 36	B) 48	C) 72	D) 96	E) 128
1 C   3 A   1 R   1 W   Number of ways these letters can be arranged = 6!/3! (3! to account 3 same As) = 120   Consider 3 As as 1 entity and thus the number of arrangements for (AAA)CRW = 4! = 24   Total allowed cases = 120-24= 
<gadget id="calculator">120-24</gadget>
<output>96</output>
96   96 is the correct answer.
<result>D</result>
In how many ways can the letters C, A, A, R, W, A be arranged so that the three A's are not next to each other?