Three times the first of three consecutive odd integers is 8 more than twice the third. The third integer is:	Choose one:
A) 9
B) 11
C) 13
D) 15
E) 20
Let the three integers be x, x + 2 and x+ 4.   Then,   3x = 2(x + 4) + 8   x = 16   Third integer = x + 4 = 20.   ANSW20R:20
<result>E</result>
Three times the first of three consecutive odd integers is 8 more than twice the third. The third integer is: