Let f(x) = ax2 - b|x|, where a and b are constant. Then at x =0, f(x) is
Select.
A) maximized whenever a>0, b>0  B) maximized whenever a>0, b<0  C) minimized whenever a>0, b>0  D) minimized whenever a>0, b<0  E) None of these
Explanation :   When a &gt; 0, b &lt; 0, ax2 and –b |x| are non negative for all x.   i.e. ax2 – b|x| ≥ 0.   ∴ ax2 – b |x| is minimum at x = 0 when a &gt; 0, b &lt; 0.   Answer : minimized whenever a&gt;0, b&lt;0
<result>D</result>
Let f(x) = ax2 - b|x|, where a and b are constant. Then at x =0, f(x) is