The ages of two persons differ by 16 years. If 6 years ago, the elder one be 3 times as old as the younger one, find their present ages.	Choose the correct answer:
A) 14 years B) 17 years C) 24 years D) 29 years E) None
Solution   Let the age of the younger person be x years.   Then, age of the elder person	= (x + 16) years.   Therefore	‹=› 3 (x - 6) =(x + 16 - 6)   ‹=› 3x-18 = x+10   ‹=› 2x = 28   x= 14 years.   14 yearsnswer 14 years
<result>A</result>
The ages of two persons differ by 16 years. If 6 years ago, the elder one be 3 times as old as the younger one, find their present ages.