If n is an integer greater than 5, which of the following must be divisible by 3? Pick one:
A) 1. n (n+1) (n-4)  B) 2. n (n+2) (n-1)  C) 3. n (n+3) (n-5)  D) 4. n (n+4) (n-2)  E) 5. n (n+5) (n-6)
We need to find out the number which is divisible by three,   In every 3 consecutive integers, there must contain 1 multiple of 3.   So n+4 and n+1 are same if we need to find out the 3's multiple. replace all the numbers which are more than or equal to three   1. n (n+1) (n-4) = &gt; n(n+1)(n-1) = &gt; (n-1)n(n+1)   2. n (n+2) (n-1) = &gt; n(n+2)(n-1) = &gt; (n-1)n(n+1)   3. n (n+3) (n-5) = &gt; n(n+0)(n-2) = &gt; (n-2)n(n)   4. n (n+4) (n-2) = &gt; n(n+1)(n-2) = &gt; (n-2)n(n+1)   5. n (n+5) (n-6) = &gt; n(n+2)(n-0) = &gt; (n)n(n+2)   from the above onlyoption Ais product of consecutive three numbers.   5. n (n+5) (n-6)
<result>E</result>
If n is an integer greater than 5, which of the following must be divisible by 3?