The population of cities A and B is equal. The population of city A increases in two successive years by 20% and 15% respectively and that of city B increases successively by 20% and 10% respectively. If the difference in the population of two cities after 2 years is 768, then what was the total population of the two cities initially?	Pick one:
A) 12,800
B) 26,500
C) 24,600
D) 25,600
E) 27,600
Population of city A = Population of city B = A   M . F of A = 120/100*115/100 = 138/100   M . F of B = 120/100*110/100 =132/100   Population of A after 2 years = A*138/100   Population of B after 2 years = A*132/100   25,600ifference = A/100( 138 –132 ) = 768   A = 768*100/6= 
<gadget id="calculator">768*100/6</gadget>
<output>12_800</output>
12800   Total initial population= 12800+12800 = 25,600   ANSWER:25,600
<result>D</result>
The population of cities A and B is equal. The population of city A increases in two successive years by 20% and 15% respectively and that of city B increases successively by 20% and 10% respectively. If the difference in the population of two cities after 2 years is 768, then what was the total population of the two cities initially?