In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit "5"?	Choose the correct choice from the following choices.
A) 180  B) 196  C) 286  D) 288  E) 324
let say number= XYZ   Z= units digit   Y= tenths digit   X= Hundredth's digit   For any 3 digit number to be odd, Unit digit must be odd   So Z can be filled with 1,3,7,9 (we are excluding digit 5) = 4 ways.   Y can be filled with 0,1,2,3,4,6,7,8,9 (we are excluding digit 5) = 9 ways   X can be filled with 1,2,3,4,6,7,8,9 (we are excluding digits 0 and 5..) = 8 ways   No of ways= 4*9*8= 
<gadget id="calculator">4*9*8</gadget>
<output>288</output>
288   Answer : 288
<result>D</result>
In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit "5"?