The L.C.M of two numbers is 48. The numbers are in the ratio 4:3. The sum of numbers is:	Options.
A) 28 B) 30 C) 40 D) 50 E) 60
Let the numbers be 4x and 3x.   Then, their L.C.M = 12x. So, 12x = 48 or x = 4.   The numbers are 16 and 12.   Hence, required sum = (16 + 12)= 
<gadget id="calculator">(16 + 12)</gadget>
<output>28</output>
28.   28NSWER:28
<result>A</result>
The L.C.M of two numbers is 48. The numbers are in the ratio 4:3. The sum of numbers is: