x3−ax2+3x−b=0x3−ax2+3x−b=0 has one factor as (x - 2). When the equation is divided by (x + 1), it leaves a remainder -12. What are the values of ‘a’ and ‘b’? Choose the correct choice from the following
A) 2,2  B) 2,6  C) 2,1  D) 2,9  E) 2,7
x3−ax2+3x−b=0x3−ax2+3x−b=0 has one factor as (x - 2). So for x = 2 the equation will satisfy or we can say if we substitute the value of x in the equation as 2 it will result into 0.   8 - 4a + 6 - b = 0 or 4a + b = 14 ....(i)   Now if we say that by dividing the equation by (x + 1) we get the remainder as -12 then if we put x = -1 in the equation then it will result in -12.   -1 - a - 3 - b = -12 or a + b = 8 ....(ii)   By solving (I) and (II) a = 2 and b = 6.   Answer:2,6
<result>B</result>
x3−ax2+3x−b=0x3−ax2+3x−b=0 has one factor as (x - 2). When the equation is divided by (x + 1), it leaves a remainder -12. What are the values of ‘a’ and ‘b’?