Three dice are thrown together, Find the probability of getting a total of at least 5?
Choose the correct choice:
A) 2/7	B) 3/5	C) 51/52	D) 1/2	E) 53/54
Three different dice are thrown at the same time.   Therefore, total number of possible outcomes will be 63 = (6 × 6 × 6) = 216.   Number of events of getting a total of less than 5 = 4   i.e. (1, 1, 1), (1, 1, 2), (1, 2, 1) and (2, 1, 1).   Therefore, probability of getting a total of less than 5   P(53/54) = Number of favorable outcomes/Total number of possible outcome   = 4/216   = 1/54   Therefore, probability of getting a total of at least 5 = 1 - P(getting a total of less than 5)   = 1 - 1/54   = (54 - 1)/54   = 53/54
<result>E</result>
Three dice are thrown together, Find the probability of getting a total of at least 5?