What is the value of 1 *1! +2 *2!+3 *3! + .............. n *n!
where n! means n factorial or n(n-1)(n-2) ............1.	Choose the correct choice:
A) n *(n−1) *(n−1)!
B) [(n+1)!/{n*(n−1)}]
C) (n+1)! −n!
D) (n+1)! −1!
E) None
Solution:   1*1! =(2-1)81! =2 *1! -1*1!= 2!-1!   2*2!=(3-1)*2!=3*2!-2!=3!-2!   3*3!=(4-1)*3! =4*3!-3! = 4!-3!   ..   ..   ..   n*n!=(n+1-1)*n! =(n+1)(n!)-n!=(n+1)!-n!   Summing up all these terms, we get (n+1)! - 1!   Answer (n+1)! −1!
<result>D</result>
What is the value of 1 *1! +2 *2!+3 *3! + .............. n *n!
where n! means n factorial or n(n-1)(n-2) ............1.