A woman invested $1,000, part at 5% and the rest at 6%. Her total investment with interest at the end of the year was $1,053. How much did she invest at 5%?
Options:	A) $500	B) $600	C) $700	D) $900	E) $950
et x be the portion invested at 5% and   Let (1-x) be the rest which is invested at 6%   The question states that the return after 1 year is (1053/1000)-1= 
<gadget id="calculator">(1053/1000)-1</gadget>
<output>53/1_000 = around 0.053</output>
0.053= 5.3%   We want to find the dollar amount invested in X   Using our defined variables, put together the equation and solve for x (the percentage of 1000 invested at 5%)   0.05x+0.06(1-x)= 0.053   (0.05)x +0.06 - (0.06)x = 0.053   -0.01x = -0.007   x= -0.007/-0.01 = 7/10 = 70%   So X = 70% of the 1000 which is 700   ANSWER:$700
<result>C</result>
A woman invested $1,000, part at 5% and the rest at 6%. Her total investment with interest at the end of the year was $1,053. How much did she invest at 5%?