if(x-10)(y-5)(z-2)=1000 then what is the least value of x+y+z? if x,y,z are all integer no.	Choices:
A) 7 B) 8 C) 9 D) 10 E) 11
(x-10)(y-5)(z-2)=1000   put x=0   y=-5   z=12   then   (0-10)(-5-5)(12-2)=1000   (-10)(-10)(10)=1000   1000=1000   7NSWER:7
<result>A</result>
if(x-10)(y-5)(z-2)=1000 then what is the least value of x+y+z? if x,y,z are all integer no.