In how many ways can 4 boys and 3 girls sit around a table in such a way that no two girls sit together?
Choose the most appropriate option:  A) 100  B) 144  C) 155  D) 180  E) 190
The 4 boys can be seated around a table in 3! Ways. In between them there are 4 places.   The 3 girls can be placed in the 4 places in 4P3 ways.   Therefore, Required number of ways= 3!* 4P3   =6*24= 
<gadget id="calculator">6*24</gadget>
<output>144</output>
144   ANSWER:144
<result>B</result>
In how many ways can 4 boys and 3 girls sit around a table in such a way that no two girls sit together?