What is the probability that a 4 person committee chosen at random from a group consisting of 3 men, 7 women, and 5 children contains exactly 1 woman?	Answers:
A) 56/195 B) 77/832 C) 11/77 D) 308/1411 E) 22/832
Total possible selections = 4 out of 15 group members = 15C4   Favorable selections = 1 out of 7 women and 3 out of 8 (= 3 men + 5 children) = 7C1 * 8C3   Thus the required probability = 7C1*8C3 / 15C4 = 56/195. Thus 56/195 is the correct answer.
<result>A</result>
What is the probability that a 4 person committee chosen at random from a group consisting of 3 men, 7 women, and 5 children contains exactly 1 woman?