The sum of the squares of the fifth and the eleventh term of an AP is 3 and the product of the second and fourteenth term is equal to P.Find the product of the first and the fifteenth term of the AP.	Choose the correct choice from the following answers.
A) (58P-39)/45 B) (98P+39)/72 C) (116P-39)/90 D) (98P+39)/90 E) None of these
(T5)^2+(T11)^2=3   T2*T14=P   T1*T15=?   (a+4d)^2+(a+10d)^2=3   2a^2+28ad+116d^2=3.....(1)   (a+d)(a+13d)=P   a^2+14ad+13d^2=P   a^2+14ad = P- 13d^2   1.5-45d^2=P   2P=3-90d^2...........(2)   a^2+14ad=?   =P-13d^2   =P-13(3-2P)/90   =(116P-39)/90   ANSWER:(116P-39)/90
<result>C</result>
The sum of the squares of the fifth and the eleventh term of an AP is 3 and the product of the second and fourteenth term is equal to P.Find the product of the first and the fifteenth term of the AP.