An IT company wants to hire 500 candidate, and each candidate is either engineer, manager, or peon . If it wants to hire 300 more engineers than managers, and twice as many peons as managers. how many engineers does The company want to hire ? Choose the correct choice from the following.
A) 310  B) 320  C) 330  D) 340  E) 350
x = the number of engineers   y = the number of managers   z = the number of peons   From the first sentence we have   Equation #1: x + y + z = 500   ...It wants to hire 300 more engineers than managers...   Equation #2: x = 300 + y   ...twice as many peons as managers...   Equation #3: z = 2y   by reshuffling of equation #2 : x - y = 300   Now, we can replace z with y in Equation #1   equation #4 : x + y + 2y= 500   x+3y = 500   by adding equation #4 and equation #5 we get   y = 50   There are 50 managers.This is 300 less than the number of engineers, so x = 350. That's the answer. Just as a check, z = 100, and   350 + 50 + 100= 
<gadget id="calculator">  350 + 50 + 100</gadget>
<output>500</output>
500.   Answer= 350,(350)
<result>E</result>
An IT company wants to hire 500 candidate, and each candidate is either engineer, manager, or peon . If it wants to hire 300 more engineers than managers, and twice as many peons as managers. how many engineers does The company want to hire ?