A and B are two multiples of 14, and Q is the set of consecutive integers between A and B, inclusive. If Q contains 9 multiples of 14, how many multiples of 7 are there in Q? Choose one
A) 20  B) 19  C) 18  D) 17  E) 16
Lets Q's first number be 14   As per question, Q contains 9 multiples of 14 , so let Q's last number be 126. (14∗9)   We have,   a n = a+(n−1)d   Then   126 = 14 + (n-1)7   Solving for n , we get n = 17   ANSWER:17
<result>D</result>
A and B are two multiples of 14, and Q is the set of consecutive integers between A and B, inclusive. If Q contains 9 multiples of 14, how many multiples of 7 are there in Q?