The contents of a bag of candy consist of 11 green pieces of candy and 20 blue pieces of candy. How many blue pieces of candy must be eaten so that 55% of the candies in the bag will be green?
Pick:
A) 8
B) 10
C) 11
D) 13
E) 15
This question is rooted in basic arithmetic. Since the question asks how many marbles need to be removed and the answers ARE numbers, we can TEST THE ANSWERS until we find the one thatfits.   To start, we have a bag of candy....   11 green   20 blue   31 total   We're asked to eat enough blue candies until the green candies make up 55% of the bag....   Right now, green marbles make up 11/31 which equals about 35% of the bag, we need to eat blue candy to achieve green candies making up for 55% of the bag. We can test our answers   Let's TEST B....   IF 10 blue candies were eaten, then we'd have...   11 green candies   10 blue candies   21 total   11/21 is about 52%.   Let's TEST E...   IF 11 blue candies were eaten, then we'd have...   11 green candies   9 blue candies   20 total   11/20 IS 55%, so this MUST be the answer!   Final Answer:   11
<result>C</result>
The contents of a bag of candy consist of 11 green pieces of candy and 20 blue pieces of candy. How many blue pieces of candy must be eaten so that 55% of the candies in the bag will be green?