An unbiased cubic die is thrown.What is the probabiltiy of getting a multiple of 3 or 4?
Select the correct option:
A) 1/12
B) 1/2
C) 3/4
D) 1/6
E) 1/9
S={1,2,3,4,5,6}   P(E)=n(E)/n(S)   n(s)=Total numbers in a die=6   Let E be the event of getting the multiple of 3   then ,E={3,6}   P(mutliple of 3) = 2/6 = 1/3   Let E be the event of getting the multiple of 4   then ,E={4}   P(multiple of 4) = 1/6   P(multiple of 3 or 4) = 1/3 + 1/6 = 1/2   ans 1/2
<result>B</result>
An unbiased cubic die is thrown.What is the probabiltiy of getting a multiple of 3 or 4?