3 litre of water is added to 11 litre of a solution containing 42% of alcohol in the water. The
percentage of alcohol in the new mixture is  Choose the most appropriate option.
A) 25% B) 20% C) 30% D) 33% E) None of these
Explanation :   ----------------------------------------------------------Method-1 to solve the question--------------------------------------   --------------------We have a 11 litre solution containing 42% of alcohol in the water=&gt; Quantity of alcohol   in the solution= 11×42100Now 3 litre of water is added to the solution=&gt; Total Quantity of the new   solution = 11+3= 
<gadget id="calculator">11+3</gadget>
<output>14</output>
14Percentage of alcohol in the new solution=11×4210014×100=11×3100=33%-------------   ---------------------------------------------Method-2 to solve the question---------------------------------------------------   -------%Concentration of alcohol in pure water = 0%Concentration of alcohol in mixture = 42quantity of   water : Quantity of mixture = 3 : 11Let the %Concentration of alcohol in the new mixture = x   By the rule of alligation, we have   %Concentration of alcohol : 0   in pure water %Concentration of alcohol   in mixture : 42   Mean %Concentration   x   42 - x x - 0 = x   But (42 - x) : x = 3 : 11   ⇒42−xx=311⇒42−xx=311⇒42×11−11x=3x⇒14x=42×11⇒x=3×11=33=&gt; The percentage of alcohol in the   new mixture is 33%   Answer : Option 33%
<result>D</result>
3 litre of water is added to 11 litre of a solution containing 42% of alcohol in the water. The
percentage of alcohol in the new mixture is