Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability taht the ticket drawn has a number which is a multiple of 3 or 5? Choose the correct choice from the following options.
A) 1/2
B) 2/5
C) 8/15
D) 9/20
E) None
Solution   Here S=(1,2,3,4,5,...,19,20).   Let E=event of getting a multiple of 3 or 5   = (3,6,9,12,15,18,5,10,20)   P(E)= n(E) / n(S)   = 9/20.   Answer 9/20
<result>D</result>
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability taht the ticket drawn has a number which is a multiple of 3 or 5?