48% of respondents to a survey consisted of those who used both M and N and those who used neither M nor N. 41% of respondents did not use M. 38% used N. What percent of respondents used only N? Choose one:
A) 19.5%
B) 21.5%
C) 20%
D) 15.5%
E) 17.5%
From the question, we can summarize the information as follows:   N Not N   M X   Not M Ans y 41   38 100   Then we can set a system of 3 equations 3 unknowns described below:   X + Y = 48   X + Ans = 38   Y + Ans = 41   Sum up all three equations to get 2X + 2Y + 2Ans = 127   15.5%ivide both sides by 2 to get X + Y + Ans = 63.5   Replace X + Y with 48 to get 48 + Ans = 63.5   Substract 48 from both sides to get Ans = 63.5 - 48= 
<gadget id="calculator">63.5 - 48</gadget>
<output>15.5</output>
15.5   The answer must be 15.5%.
<result>D</result>
48% of respondents to a survey consisted of those who used both M and N and those who used neither M nor N. 41% of respondents did not use M. 38% used N. What percent of respondents used only N?