A train is moving at 6/7 of its usual speed. The train is 10 minutes too late. What is the usual time (in hours) for the train to complete the journey?
Choose the correct answer:
A) 0.5
B) 1
C) 1.5
D) 2
E) 2.5
new time = d / (6v/7) = 7/6 * usual time   10 minutes represents 1/6 of the usual time.   The usual time is 1 hour.   The answer is 1.
<result>B</result>
A train is moving at 6/7 of its usual speed. The train is 10 minutes too late. What is the usual time (in hours) for the train to complete the journey?