If n + 10 is a positive odd integer, which of the following must be true about the sum of the next four integers?	Options:
A) It is a multiple of 3
B) It is a multiple of 4
C) It is a prime number
D) It is a multiple of 5
E) It is a multiple of 2
n+10 is a positive odd integer. This means n will be an odd integer   The next 4 integers would be: n + 10, n + 11, n + 12, n + 13   Sum = 4n + 46   This sum will always be even.   Option It is a multiple of 2
<result>E</result>
If n + 10 is a positive odd integer, which of the following must be true about the sum of the next four integers?