Vikas can cover a distance in 1 hr 24 min by covering (left(dfrac{2}{3}right)^{rd})of the distance at 4 kmph and the rest at 5kmph. The total distance is?  Choose the correct answer
A) 4 km	B) 5 km	C) 6 km	D) 9 km	E) 11 km
Let total distance be SS   total time = 1 hr 24 min = 84 min   = 8460=21158460=2115 hr   Let Vikas travels from A−&gt;T−&gt;SA−&gt;T−&gt;S   A ------------------------ T ------------ S   &lt;---------- (2S3)(2S3)---------&gt;&lt;----(S3)(S3)----&gt;   AA to TT :: speed = 4 kmph   Distance = (23)×S(23)×S   T to S :: speed = 5 km =   Distance = (1−23)S=13S(1−23)S=13S   Total time:   2115=2/3S4+1/3S42115=2/3S4+1/3S4   84=10S+4S84=10S+4S {Multiply both sides by 15×415×4}   S=8414=6S=8414=6 km   Option(6 km) is correct
<result>C</result>
Vikas can cover a distance in 1 hr 24 min by covering (left(dfrac{2}{3}right)^{rd})of the distance at 4 kmph and the rest at 5kmph. The total distance is?