Lorna invests $5000, with some at 6% annual interest and some at 11% annual interest. If she receives a total of $580 from these investments at the end of a year, how much was invested at the 6% interest rate?	Choose one
A) $1,000	B) $1,600	C) $2,200	D) $4,400	E) $5,840
We have that 'x' invested at 6%   We also have that '6000-x' invested at 11%   Now then 580/5000 is approx 10%   Therefore, -4x+5000-x=0   5x=5000   x=1000 approximately. Probably higher   Only $1,000 matches
<result>A</result>
Lorna invests $5000, with some at 6% annual interest and some at 11% annual interest. If she receives a total of $580 from these investments at the end of a year, how much was invested at the 6% interest rate?