A shepherd has 1 million sheep at the beginning of Year 2010. The numbers grow by xx during the yr. A famine hits his village in the next year & many of his sheep die. The sheep population decreases by yy during 2001 and at the beginning of 2011 the shepherd finds that he is left with 1 million sheep. Which of the following is correct? Select the correct option:	A) x<y	B) x>y	C) x=y	D) x<=y	E) x>=y
Let us assume the value of xx to be 10%10%.   Therefore, the number of sheep in the herd at the beginning of year 2001 (end of 2000) will be 1 million + 10%10% of 1 million = 1.1 million   In 2001, the numbers decrease by y%y% and at the end of the year the number sheep in the herd = 1 million.   i.e., 0.1 million sheep have died in 2001.   In terms of the percentage of the number of sheep alive at the beginning of 2001,   it will be (0.1/1.1)×100%=9.09%(0.1/1.1)×100%=9.09%.   From the above illustration it is clear that x&gt;y   x&gt;y
<result>B</result>
A shepherd has 1 million sheep at the beginning of Year 2010. The numbers grow by xx during the yr. A famine hits his village in the next year & many of his sheep die. The sheep population decreases by yy during 2001 and at the beginning of 2011 the shepherd finds that he is left with 1 million sheep. Which of the following is correct?