Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age  Select: A) 77 B) 30 C) 66 D) 55 E) 44
Let the age of younger person is x,   Then elder person age is (x+16)   =&gt; 3(x-6) = (x+16-6) [6 years before]   =&gt; 3x-18 = x+10   =&gt; x = 14.   So other person age is x + 16 = 30   Answer:30
<result>B</result>
Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age