A six faced die is so biased that it is twice as likely to show an even number as an odd. It is thrown twice. What is the probability that the sum of the numbers is even?	Pick.
A) 1/3 B) 2/3 C) 5/9 D) 6/11 E) 7/11
Probability of getting an even number = 2/3   Probability of getting an odd number = 1/3   since the dice is biased.   The sum is even if   (even,even) or (odd,odd)   [P(even).P(even)] + [P(odd).P(odd)]   2/3 * 2/3 + 1/3 * 1/3 = 4/9 + 1/9 = 5/9   ANSWER:5/9
<result>C</result>
A six faced die is so biased that it is twice as likely to show an even number as an odd. It is thrown twice. What is the probability that the sum of the numbers is even?