(1^2+2^2+3^2+.....+7^2)=? Select
A) 330  B) 345  C) 365  D) 140  E) None of them
formula is (1^2+2^2+3^2+....+n^2=1/6 n(n+1)(2n+1)   n=7   =(1/6x7x8x15)   =140   Answer is 140.
<result>D</result>
(1^2+2^2+3^2+.....+7^2)=?