If two letters are chosen at random (without replacement) from the word EQUAL, what is the probability that none of the letters are vowels? Pick one.
A) 1/5 B) 2/5 C) 1/10 D) 3/10 E) 3/20
The number of ways to choose two letters is 5C2 = 10   The number of ways to choose two consonants is 2C2 = 1.   P(no vowels) = 1/10   The answer is 1/10.
<result>C</result>
If two letters are chosen at random (without replacement) from the word EQUAL, what is the probability that none of the letters are vowels?