What was the day of the week on 17th June 1998?	Options
A) Monday	B) Sunday	C) Wednesday	D) Friday	E) Tuesday
Explanation:   17 Jun 1998 = (1997 years + period from 1-Jan-1998 to 17-Jun-1998)   We know that number of odd days in 400 years = 0   Hence the number of odd days in 1600 years = 0 (Since 1600 is a perfect multiple of 400)   Number of odd days in the period 1601-1900   = Number of odd days in 300 years   = 5 x 3 = 15 = 1   (As we can reduce perfect multiples of 7 from odd days without affecting anything)   Number of odd days in the period 1901-1997   = 73 normal years + 24 leap year   = 73 x 1 + 24 x 2 = 73 + 48= 
<gadget id="calculator">73 + 48</gadget>
<output>121</output>
121= (121 - 7 x 17) = 2 odd days   Number of days from 1-Jan-1998 to 17-Jun-1998   = 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 31(may) + 17(Jun)   = 168 = 0 odd day   Total number of odd days = (0 + 1 + 2 + 0)= 
<gadget id="calculator">(0 + 1 + 2 + 0)</gadget>
<output>3</output>
3   3 odd days= Wednesday   Hence 17th June 1998 is Wednesday.   Answer: Option Wednesday
<result>C</result>
What was the day of the week on 17th June 1998?