Three times the first of three consecutive odd integers is 6 more than twice the third. The third integer is:  Select
A) 9
B) 11
C) 13
D) 15
E) 18
Let the three integers be x, x + 2 and x+ 4.   Then,   3x = 2(x + 4) + 6   x = 14   Third integer = x + 4 = 18.   ANSW18R:18
<result>E</result>
Three times the first of three consecutive odd integers is 6 more than twice the third. The third integer is: