Each student at a certain university is given a four-character identification code, the rest two characters of which are digits between 0 and 9, inclusive, and the last two characters of which are selected from the 26 letters of the alphabet. If characters may be repeated and the same characters used in a different order constitute a different code, how many different identification codes can be generated following these rules?
Pick:
A) 135,200
B) 67,600
C) 64,000
D) 60,840
E) 58,500
First two parts for the code, are digits between 0-9, therefore, 10 options for the first part of the code,   and as characters may be repeated, 10 options for the second part as well   Therefore, we have 10 X 10 possibilities for the first and second part of the code   Last two parts of the code, are characters selected from the 26 letters of the alphabet, therefore, 26 options for the third part of the code,   and as characters may be repeated, 26 options for the fourth part as well   Therefore, we have 26 X 26 possibilities for the third and fourth part of the code   so, in all total no. of different identification codes generated following these rules   = 10 X 10 X 26 X 26 = 67600   Answer 67,600
<result>B</result>
Each student at a certain university is given a four-character identification code, the rest two characters of which are digits between 0 and 9, inclusive, and the last two characters of which are selected from the 26 letters of the alphabet. If characters may be repeated and the same characters used in a different order constitute a different code, how many different identification codes can be generated following these rules?