In how many ways can a group of 22 friends be seated round 2 tables if one of the tables can seat 12 and the other can seat 10 people?
Answers
A) 15C5 * 9! *4!	B) 15C3 * 8! *3!	C) 15C4 * 9! *3!	D) 22C2 * 11! *9!	E) 26C5 * 10! *4!
12 people can be selected from 22 people in 22C12 ways.   Remaining 10 people can be selected from 10 people in 10C10 ways.   Now, arranging 12 people on a round table = (12-1)= 
<gadget id="calculator">(12-1)</gadget>
<output>11</output>
11!   Arranging 10 people on a round table= (10-1)= 
<gadget id="calculator">(10-1)</gadget>
<output>9</output>
9!   Hence, total number of ways= 22C12 * 11! * 10C10 * 9!   = 22C2 * 11! * 9!   22C2 * 11! *9!
<result>D</result>
In how many ways can a group of 22 friends be seated round 2 tables if one of the tables can seat 12 and the other can seat 10 people?