Two numbers when divided by a divisor leave remainders of 208 and 332 respectively. The remainder obtained when the sum of the numbers is divided by the same divisor is 68. Find the divisor.
Choose the correct choice from the following.
A) 335  B) 365  C) 387  D) 472  E) 516
Let x be the divisor.   N1 = xa + 208   N2 = xb + 332   N1 + N2 = x(a+b) + 540 = xc + 68   x(c-a-b) = 472 but we know that x &gt; 332, thus (c-a-b) must equal 1.   The answer is 472.
<result>D</result>
Two numbers when divided by a divisor leave remainders of 208 and 332 respectively. The remainder obtained when the sum of the numbers is divided by the same divisor is 68. Find the divisor.