If two numbers are in the ratio 2:3 and the numerator and denominator are added and subtracted by1 and 2 respectively, then the ratio becomes 6:2, then find the smallest number?	Choose the correct choice from the following choices:
A) 2	B) 1	C) 3	D) 4	E) 6
2:3   2x + 1 : 3x - 2 = 3 : 1   [2x + 1] = 3[3x - 2]   2x + 1 2  + 1= 
<gadget id="calculator"> 2  + 1</gadget>
<output>3</output>
3[3x - 2]   2x + 1= 9x -6   9x - 2x = 7   x 9  - 2= 
<gadget id="calculator">9  - 2</gadget>
<output>7</output>
7   x= 1   Then smallest number is = 2x   2x = 2   2
<result>A</result>
If two numbers are in the ratio 2:3 and the numerator and denominator are added and subtracted by1 and 2 respectively, then the ratio becomes 6:2, then find the smallest number?