A number when divided by a divisor leaves a remainder of 24.
When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor?  Answers:	A) 35	B) 37	C) 41	D) 43	E) 44
Let the original number be 'a'   Let the divisor be 'd'   Let the quotient of the division of aa by dd be 'x'   Therefore, we can write the relation as a/d = x and the remainder is 24.   i.e., a=dx+24 When twice the original number is divided by d, 2a is divided by d.   We know that a=dx+24. Therefore, 2a = 2dx + 48   The problem states that (2dx+48)/d leaves a remainder of 11.   2dx2dx is perfectly divisible by d and will therefore, not leave a remainder.   The remainder of 11 was obtained by dividing 48 by d.   When 48 is divided by 37, the remainder that one will obtain is 11.   Hence, the divisor is 37.   37
<result>B</result>
A number when divided by a divisor leaves a remainder of 24.
When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor?