A committee has 4 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
Choose the most appropriate option
A) 120 B) 160 C) 200 D) 240 E) 300
The number of ways to select two men and three women = 4C2 * 6C3 = 6 * 20= 
<gadget id="calculator">6 * 20</gadget>
<output>120</output>
120   The answer is 120.
<result>A</result>
A committee has 4 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?