Two equilateral triangles of side 12cm are placed one on top of another, such that a 6 pointed star is formed .if the six verticals lie on a circle what is the area of the circle not enclosed by the star ?
Select the correct option.
A) 68 B) 83 C) 57 D) 61 E) 62
area of star = √3/4 * (12)^2 + 3* √3/4 *(12/3)^2 = 48√3   if r be radius of circle then r=6/cos30 =&gt; r=12/√3 =&gt; r^2=48   area of circle = pi*48   area of the circle not enclosed by the star = 48*pi - 48√3 =48(3.14-1.732)= 68(approax)   68NSWER:68
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Two equilateral triangles of side 12cm are placed one on top of another, such that a 6 pointed star is formed .if the six verticals lie on a circle what is the area of the circle not enclosed by the star ?