Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Child A has to sit next to both B & G, with these two children immediately adjacent to here on either side. The other four children can sit in any order in any of the remaining seats. How many possible configurations are there for the children? Choose the correct answer.
A) 240  B) 480  C) 720  D) 1440  E) 3600
In order to sit together they become one entity that instead of having 7 students we have 4+ group of 3 = 4+1= 
<gadget id="calculator">4+1</gadget>
<output>5</output>
5 entities. In order to arrange 5= 5! and the group of 3 can be arranged in 2 ways G240B or B240G hence total possible configurations 240   answer is 240
<result>A</result>
Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Child A has to sit next to both B & G, with these two children immediately adjacent to here on either side. The other four children can sit in any order in any of the remaining seats. How many possible configurations are there for the children?