In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit 3?	Choose the correct choice.
A) 180  B) 288  C) 286  D) 284  E) 324
We have to find the total number of 3-digit odd numbers not having 3 as a digit.   Units digits will be among 1,5,7,9   Tenth digits will be among 0,1,2,5,4,6,7,8,9   Hundredth digits will be among 1,2,5,4,6,7,8,9   So total numbers = 4*9*8= 
<gadget id="calculator">4*9*8</gadget>
<output>288</output>
288   Answer : 288
<result>B</result>
In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit 3?