Given that p is a positive even integer with a positive units digit, if the units digit of p^3 minus the units digit of p^2 is equal to 0, what is the units digit of p - 3? Options.
A) 10 B) 8 C) 7 D) 3 E) 11
p is a positive even integer with a positive units digit--&gt; the units digit of p can be 2, 4, 6, or 8 --&gt;   In order the units digit of p^3 - p^2 to be 0, the units digit of p^3 and p^2 must be the same. Thus the units digit of p can be 0, 1, 5 or 6.   Intersection of values is 6, thus the units digit of p - 3 is  6 - 3= 
<gadget id="calculator"> 6 - 3</gadget>
<output>3</output>
3.   Answer: 3.
<result>D</result>
Given that p is a positive even integer with a positive units digit, if the units digit of p^3 minus the units digit of p^2 is equal to 0, what is the units digit of p - 3?