The sum of the digits of [(10^x)^y]-64=279. What is the value of xy ?  Choose the correct choice from the following:	A) 28	B) 29	C) 30	D) 31	E) 32
1000−64=936. Whatever XY is you finish with 36==&gt;3+6= 
<gadget id="calculator">3+6</gadget>
<output>9</output>
9   Therefore, 279−9=270 and   270/9= 
<gadget id="calculator">  270/9</gadget>
<output>30</output>
30   Now you add the last two digits (3 and 6)   Answer is  30+2= 
<gadget id="calculator"> 30+2</gadget>
<output>32</output>
32   ANSW32R:32
<result>E</result>
The sum of the digits of [(10^x)^y]-64=279. What is the value of xy ?