One ball is picked up randomly from a bag containing 8 yellow, 7 blue and 6 black balls. What is the probability that it is neither yellow nor black?	Pick one
A) 1/3 B) 1/4 C) 1/2 D) 3/4 E) 1/5
Total number of balls, n(S) = 8 + 7 + 6= 
<gadget id="calculator">8 + 7 + 6</gadget>
<output>21</output>
21   n(E)= Number of ways in which a ball can be selected which is neither yellow nor black   = 7 (∵ there are only 7 balls which are neither yellow nor black)   P(E) = n(E)/n(S)=7/21=1/3   1/3NSWER:1/3
<result>A</result>
One ball is picked up randomly from a bag containing 8 yellow, 7 blue and 6 black balls. What is the probability that it is neither yellow nor black?