Set A of 8 positive integers may have the same element and have 40. And set B of 8 positive integers must have different elements and have 40. When m and n are the greatest possible differences between 40 and other elements’ sums in set A and set B, respectively, m-n=?	Choose the correct choice from the following choices.
A) 21  B) 29  C) 23  D) 25  E) 26
This is maximum-minimum. Hence, 40-(1+1+1+1+1+1+1)=32 and 40-(1+2+3+4+5+6+7)=11. So, 32-11=21. The correct answer is 21.
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Set A of 8 positive integers may have the same element and have 40. And set B of 8 positive integers must have different elements and have 40. When m and n are the greatest possible differences between 40 and other elements’ sums in set A and set B, respectively, m-n=?