Lorna invests $6000, with some at 6% annual interest and some at 11% annual interest. If she receives a total of $580 from these investments at the end of a year, how much was invested at the 6% interest rate?  Select the correct option.
A) $160
B) $1,600
C) $2,200
D) $4,400
E) $5,840
11+6= 
<gadget id="calculator">11+6</gadget>
<output>17</output>
17%, therefore   17/100*6000= 
<gadget id="calculator">  17/100*6000</gadget>
<output>1_020</output>
1020, now add 1020 + 580= 
<gadget id="calculator">1020 + 580</gadget>
<output>1_600</output>
1600. ($1,600)
<result>B</result>
Lorna invests $6000, with some at 6% annual interest and some at 11% annual interest. If she receives a total of $580 from these investments at the end of a year, how much was invested at the 6% interest rate?