Out of 7 fruits in a basket, 2 are rotten. If two fruits are drawn at random from the basket, the probability of both being rotten is Select the correct option:  A) 1/21  B) 10/21  C) 20/21  D) 11/21  E) 2/21
The number of exhaustive events = 7C2 = 21.   Let E be event of the 2 fruits being rotten. The number of favourable cases are   2C2 = 1 way.   Required probability = 1/21.   1/21NSWER:1/21
<result>A</result>
Out of 7 fruits in a basket, 2 are rotten. If two fruits are drawn at random from the basket, the probability of both being rotten is