A circular metal plate of even thickness has 12 holes of radius 1 cm drilled into it. As a result the plate lost 1/6th its original weight. The radius of the circular plate is
Options
A) 16sqrt2	B) 8sqrt2	C) 32sqrt2	D) sqrt72	E) sqrt82
Area of 12 holes=12*Pi*1^2=12*Pi   As 12*Pi=(1/6)th weight,so total Area of Plate=12*Pi/(1/6)=72*Pi   If r=radius of the plate,then its Area=Pi*r^2=72*Pi, So r=Sqrt72   ANSWER:sqrt72
<result>D</result>
A circular metal plate of even thickness has 12 holes of radius 1 cm drilled into it. As a result the plate lost 1/6th its original weight. The radius of the circular plate is