Two different solutions of alcohol with respective proportions of alcohol to water of 3:1 and 2:3 were combined. What is the concentration of alcohol in the new solution if the first solution was 4.6 times the amount of the second solution?	Choose the correct choice from the following answers
A) 62.0	B) 65.25	C) 68.75	D) 70.15	E) 72.35
SOL:   Lets assume that 46L of sol1 was mixed with 10L of sol2.   Alcohol in Sol1: 46*3/4 = 34.5L   Alcohol in Sol2: 10*2/5 = 4L   Total Alcohol in the mixed solution of 56L = 34.5 + 4= 
<gadget id="calculator">34.5 + 4</gadget>
<output>38.5</output>
38.5L   Alcohol concentration in the new sol: (38.5/56)*100= 
<gadget id="calculator">(38.5/56)*100</gadget>
<output>68.75</output>
68.75%   ANSWER:68.75
<result>C</result>
Two different solutions of alcohol with respective proportions of alcohol to water of 3:1 and 2:3 were combined. What is the concentration of alcohol in the new solution if the first solution was 4.6 times the amount of the second solution?