Of 5 employees, 3 are to be assigned an office and 2 are to be assigned a cubicle. If 3 of the employees are men and 2 are women, and if those assigned an office are to be chosen at random, what is the probability that the offices will be assigned to 2 of the men and 1 of the women?	Answers:
A) 1/3
B) 2/5
C) 1/2
D) 3/5
E) 2/3
probability = Desired Outcomes/Total Outcomes   Event = Selection of 3 employees to assign office from 5 such that 2 are men and 1 is woman   Total Outcomes = Selection of any 3 employees from 5 employees = 5 C 3 = 10   Desired Outcomes = Selection of 2 Men from 3 Men AND selection of 1 woman from 2 Women. = (3 C 2) * (2 C 1) = 3*2= 
<gadget id="calculator">3*2</gadget>
<output>6</output>
6   Probability= 6/10 --------&gt; 3/5   ANSWER:3/5
<result>D</result>
Of 5 employees, 3 are to be assigned an office and 2 are to be assigned a cubicle. If 3 of the employees are men and 2 are women, and if those assigned an office are to be chosen at random, what is the probability that the offices will be assigned to 2 of the men and 1 of the women?