If a number is 20% more than the another, how much % is the smaller number less than the first ? Select
A) 12(1/3)%	B) 16(2/3)%	C) 16(1/3)%	D) 16(4/3)%	E) none of these
Take a number 100,   Then the other number is 120   % the smaller number is less than the first = [(20/(120)) x 100]% = 16(2/3)%.   ANSWER:16(2/3)%
<result>B</result>
If a number is 20% more than the another, how much % is the smaller number less than the first ?