Which of the following describes all values of x for which 36-x^2 ≥ 0 ?  Choose the most appropriate option
A) x ≥ 1
B) x ≤ -1
C) 0 ≤ x ≤ 1
D) x ≤ -1 or x ≥ 1
E) -6 ≤ x ≤ 6
36-x^2 &gt;= 0 ---&gt; x^2-36&lt;=0   --&gt; (x+6)(x-6)&lt;=0   Above equation true for   i) x+6&lt;=0 and x-6&gt;=0 ---&gt; x&lt;= -6 and x&gt;=6 ---&gt; this is not possible ---Strike out this solution   ii) x+6&gt;=0 and x-6&lt;=0 ---&gt; x&gt;=-6 and x&lt;=6 --&gt; -6&lt;=x&lt;=6   Answer -6 ≤ x ≤ 6
<result>E</result>
Which of the following describes all values of x for which 36-x^2 ≥ 0 ?