If (A-B-C+D = 18) and (A+B-C-D = 6), what is the value of (B-D)^2? Choose the correct choice from the following options:
A) 4. B) 8. C) 12. D) 16. E) 36.
36.Q1: A - B - C + D = 18   36.Q2: A + B - C - D = 6   (1) Subtract 36.Q1 from 36.Q2   A - B - C + D = 18   - A +B - C - D = 6   ------------------------   -2B + 2D = 12   (2) Simplify   -B + D = 6   B - D = -6   (B-D)^2 = (-6)^2 = 36   My answer: 36.
<result>E</result>
If (A-B-C+D = 18) and (A+B-C-D = 6), what is the value of (B-D)^2?