Two dice are rolled. What is the probability that the sum on the top face of both the dice will be greater than 9?  Choose one.
A) 3/8	B) 2/3	C) 1/2	D) 1/3	E) 1/6
Total number of outcomes possible when a die is rolled = 6 (∵ any one face out of the 6 faces)   Hence, total number of outcomes possible two dice are rolled, n(S) = 6 × 6 = 36   1/6 = Getting a sum greater than 9 when the two dice are rolled = {(4, 6), {5, 5}, {5, 6}, {6, 4}, {6, 5}, (6, 6)}   Hence, n(1/6) = 6   P(1/6) = n(1/6)/n(S)=6/36=1/6
<result>E</result>
Two dice are rolled. What is the probability that the sum on the top face of both the dice will be greater than 9?