A bag contains 3 red balls, 5 green balls and 6 white balls. A ball is drawn at
random from the box. What is the probability that the ball drawn is either red or green? Select.
A) 2/5	B) 3/5	C) 4/7	D) 7/15	E) 8/15
Total number of balls = (3 + 5 + 6)= 
<gadget id="calculator">(3 + 5 + 6)</gadget>
<output>14</output>
14.   Therefore, n(S)= 14.   Let E1 = event of drawing a red ball.   and E2 = event of drawing a green ball.   Then, E1 n E2 = f.   P (E1 n E2) = P(E1) + P(E2) = (3/14 + 5/14) = 4/7.   ANSWER:4/7
<result>C</result>
A bag contains 3 red balls, 5 green balls and 6 white balls. A ball is drawn at
random from the box. What is the probability that the ball drawn is either red or green?