A natural number has 43 divisors (excluding 1 and itself) . What is the maximum number of distinct prime factors it can have ? Options:
A) 2  B) 3  C) 4  D) 5  E) None of these
no. of total divisors=43+2= 
<gadget id="calculator">43+2</gadget>
<output>45</output>
45   If N=a^p*b^q*c^r.... then the number of factors of N = (p+1)(q+1)(r+1) ....   45=3*3*5   distinct prime factors are 3 and 5   2NSWER:2
<result>A</result>
A natural number has 43 divisors (excluding 1 and itself) . What is the maximum number of distinct prime factors it can have ?