If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 10, respectively, what is the probability that b/a will not be an integer?  Choices:
A) 1/2
B) 1/3
C) 1/4
D) 1/6
E) 1/8
a is from the following set {1,2,3,4}   b is from the following set {10,12,14}   The total number of ways of choosing 2 integers, one from each set is  4*3= 
<gadget id="calculator"> 4*3</gadget>
<output>12</output>
12 ways.   The possibilities where b/a is not an integer is for the following outcomes:   {b,a}= {10,3},{10,4},{14,3},{14,4} = 4 ways   Thus the probability is 4/12 = 1/3   The answer is 1/3.
<result>B</result>
If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 10, respectively, what is the probability that b/a will not be an integer?