Can you please walk me through how to best approach this problem? Thanks
If #p# = ap^3+ bp – 1 where a and b are constants, and #-3# = 2, what is the value of #3#?	Choose one.
A) -4 B) 0 C) -2 D) -3 E) -5
#p# = ap^3 + bp - 1   #-3# = 2   putting p = -3 in above equation   -27a -(3b +1) = 2 or   #-5# = (27a+3b+1) = -2   therefore 27a+3b = -3 .....(1   now putting p = 3   #3# = 27 a+3b - 1   using equation 1(27a+3b = -3)   #3# = -3-1 = -4   hence -4
<result>A</result>
Can you please walk me through how to best approach this problem? Thanks
If #p# = ap^3+ bp – 1 where a and b are constants, and #-3# = 2, what is the value of #3#?