Given distinct positive integers 1, 10, 3, x, 2, and 9, which of the following could be the median?  Select the correct option:
A) 3
B) 4
C) 7
D) 8
E) 9
The median of a set with even number of terms is the average of two middle terms when arranged in ascending (or descending) order.   Arrange numbers in ascending order: 1, 2, 3, 9, 10, and x.   Now, x can not possibly be less than 3 as given that all integers are positive and distinct (and we already have 1, 2, and 3).   Next, if x is 3&lt;x&lt;9 then the median will be the average of 3 and x. As all answers for the median are integers, then try odd values for x:   If x=5, then median=(3+5)/2= 
<gadget id="calculator">(3+5)/2</gadget>
<output>4</output>
4 --&gt; OK;   Answer: B.   P.S. If x is more than 9 so 10 or more then the median will be the average of 3 and 9 so  (3+9)/2= 
<gadget id="calculator"> (3+9)/2</gadget>
<output>6</output>
6 (the maximum median possible).
<result>B</result>
Given distinct positive integers 1, 10, 3, x, 2, and 9, which of the following could be the median?