If m > 1 and n = 2^(m+1), then 4^m = Pick one:	A) 16n^2	B) 4n^2	C) n^2	D) n^2/4	E) n^2/16
n = 2^(m+1) = 2^m*2   2^m = n/2   4^m = (2^m)^2 = (n/2)^2 = n^2/4   The answer is n^2/4.
<result>D</result>
If m > 1 and n = 2^(m+1), then 4^m =