How many different 4 digit numbers can be formed from the number 1234 by re-arranging its digits so that the odd digits occupy even position
Pick one
A) 2  B) 8  C) 4  D) 7  E) 3
There are 2 odd numbers which have to be placed at 2 even places =2!=2 ways   There are 2 even numbers which have to be placed at 2 odd places. So 2! = 2 ways   so total number of ways of arranging all these numbers are  2 * 2= 
<gadget id="calculator"> 2 * 2</gadget>
<output>4</output>
4 ways   Answer:4
<result>C</result>
How many different 4 digit numbers can be formed from the number 1234 by re-arranging its digits so that the odd digits occupy even position