8 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played?
Choose the most appropriate option:
A) 66
B) 52
C) 58
D) 55
E) 56
Though 2*(8C2) is the correct approcah to do this, but for people like me who find Perm, Comb n Prob a nightmare, an easy approach can be used.   The first guy has to play 2 matches with the rest of 7, so he'll play 14 matches.   Similarly, second guy has to play with the rest of 6 as his 2 games with the first guy are already played. So he plays 12 matches.   This continues like this and the total matches are 14+12+10...+2   14+12+...+2 = 2(7+6+...+1) = 2((7*8)/2) = 7*8= 
<gadget id="calculator">7*8</gadget>
<output>56</output>
56.   ANSW56R:56
<result>E</result>
8 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played?