The sides of right triangle ABC are such that the length of side AC is 1.25 times the length of side AB, which itself is 4 units more than the length of side BC. If side AC = 20 units, what is the area of the triangle?  Options
A) 144 B) 69 C) 120 D) 160 E) 96
AC=1.25xAB, 20=1.25xAB, AB=16 units   AB=4+BC, BC=AB-4, BC=16-4= 
<gadget id="calculator">16-4</gadget>
<output>12</output>
12 units   Area= (AB*BC)/2 = 96   96 is the correct option.
<result>E</result>
The sides of right triangle ABC are such that the length of side AC is 1.25 times the length of side AB, which itself is 4 units more than the length of side BC. If side AC = 20 units, what is the area of the triangle?