Out of a group of 10 contestants, 2 are to be selected at random. What is the maximum number of male contestants possible if the probability that both selected contestants are male is less than 20% ?
Select
A) 0  B) 1.51  C) 2  D) 2.12  E) 4
Let y be the number of males.   Total contestants = 10   Probability that the first contestant selected is a male = y/10   Probability that the second contestant selected is also a male = y-1/9   Total probability = y(y-1)/ 90 &lt; 1/20 (this probability is less than 20%)   Solving for y we get, y(y-1)&lt; 9/2. This implies that the maximum value of y can be 2.12.   Answer 2.12!
<result>D</result>
Out of a group of 10 contestants, 2 are to be selected at random. What is the maximum number of male contestants possible if the probability that both selected contestants are male is less than 20% ?