In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green? Choose the correct choice from the following choices:  A) 2/3  B) 3/4  C) 7/19  D) 8/21  E) None
Solution   Total number of balls	= (8 + 7 + 6)= 
<gadget id="calculator">(8 + 7 + 6)</gadget>
<output>21</output>
21.   Let E= event that the ball drawn is neither red nor green   =event that the ball drawn is red.   Therefore, n(E) = 8.   P(E) = 8/21.   Answer 8/21
<result>D</result>
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?