If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a four-percent vinegar solution, what was the concentration of the original solution?  Select.
A) 19.3%	B) 17%	C) 20.67%	D) 15.5%	E) 12.5%
Let X be the quantity of non-vinegar in the strong vinegar solution   Thus vinegar quantity will be 12 - X   When 50 ounces of water were added the percentage of vinegar becomes 4%, thus (12 - X)/62 = 4/100   From this equation X = 9.52   Answer (12-9.52)/12 = 20.67%   ANSWER:20.67%
<result>C</result>
If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a four-percent vinegar solution, what was the concentration of the original solution?