a natural numbr has exactly 10 divisors including 1 and itself.how many distint prime factors this natural numbr will have? Choices:	A) 1 or2	B) 1 or3	C) 1 or 2or 3	D) 2 or 3	E) 2 or 5
Here it is given that the number has exactly 10 divisor including 1 and itself.   So the number may be (any one prime factors)power 9 .....I.e (2)pow 9, (3)pow 9....etc.total 10 factor=(9+1)= 
<gadget id="calculator">(9+1)</gadget>
<output>10</output>
10.   Also the number may be as (any one prime factors)pow 1*(any one prime factors)pow 4........I.e...(2)pow 1*(3)pow 4...etc= total 10 factor ((1+1)*(4+1))= 
<gadget id="calculator"> ((1+1)*(4+1))</gadget>
<output>10</output>
10.   Hence either 1 or 2 is correct   1 or2NSWER:1 or2
<result>A</result>
a natural numbr has exactly 10 divisors including 1 and itself.how many distint prime factors this natural numbr will have?