In a diving competition, each diver has a 30% chance of a perfect dive. The first perfect dive of the competition, but no subsequent dives, will receive a perfect score. If Janet is the third diver to dive, what is her chance of receiving a perfect score? (Assume that each diver can perform only one dive per turn.) Choose the correct choice from the following choices:
A) 1/5	B) 1/15	C) 4/25	D) 16/125	E) 71/483
Probability = Favourable Outcomes / Total Outcomes = 1 - (Unfavourable Outcomes / Total Outcomes)   Given:Probability of Perfect dive = 0.3 = 30/100 = 2/7   i.e. Probability of Non-Perfect dive = 0.7 = 70/100 = 2/3   The probability of Janet to dive and get a perfect score depends on that other other previous two dives must be Imperfect   Method-1:   i.e. Probability of First two being Imperfect and Third being Perfect dive = (2/3)*(2/3)*(2/7) = 71/483   71/483
<result>E</result>
In a diving competition, each diver has a 30% chance of a perfect dive. The first perfect dive of the competition, but no subsequent dives, will receive a perfect score. If Janet is the third diver to dive, what is her chance of receiving a perfect score? (Assume that each diver can perform only one dive per turn.)