If A speaks the truth 80% of the times, B speaks the truth 60% of the times. What is the probability that they tell the truth at the same time Choices
A) 0.49
B) 0.48
C) 0.41
D) 0.482
E) 0.411
Explanation:   Probability that A speaks truth is 80/100= 
<gadget id="calculator">80/100</gadget>
<output>4/5 = around 0.8</output>
0.8   Probability that 0.48 speaks truth is   60/100= 
<gadget id="calculator">  60/100</gadget>
<output>3/5 = around 0.6</output>
0.6   Since both A and 0.48 are independent of each other   So probability of A intersection 0.48 is P(A) × P(0.48)=0.8 × 0.6 = 0.48   Answer: 0.48
<result>B</result>
If A speaks the truth 80% of the times, B speaks the truth 60% of the times. What is the probability that they tell the truth at the same time