Out of 8 fruits in a basket, 2 are rotten. If two fruits are drawn at random from the basket, the probability of both being rotten is
Pick.
A) 1/28
B) 10/28
C) 20/28
D) 11/28
E) 2/28
The number of exhaustive events = 8C2 = 28.   Let E be event of the 2 fruits being rotten. The number of favourable cases are   2C2 = 1 way.   Required probability = 1/28.   1/28NSWER:1/28
<result>A</result>
Out of 8 fruits in a basket, 2 are rotten. If two fruits are drawn at random from the basket, the probability of both being rotten is