A man buys 20 lts of liquid which contains 30% of the liquid and the rest is water. He then mixes it with 20 lts of another mixture with 20% of liquid. What is the % of water in the new mixture?  Choose the correct choice from the following:
A) 59  B) 95  C) 80  D) 75  E) 65
30% in 20 lts is 6. So water = 20-6= 
<gadget id="calculator">20-6</gadget>
<output>14</output>
14lts.20% of 20 lts= 4. So water in 2nd mixture = 20-4= 
<gadget id="calculator">20-4</gadget>
<output>16</output>
16 lts. Now total quantity= 20 + 20= 
<gadget id="calculator">20 + 20</gadget>
<output>40</output>
40 lts. Total water in it will be 14 + 16= 
<gadget id="calculator">14 + 16</gadget>
<output>30</output>
30 lts. % of water= (100*30)/40= 
<gadget id="calculator">(100*30)/40</gadget>
<output>75</output>
75.   ANSWER:75
<result>D</result>
A man buys 20 lts of liquid which contains 30% of the liquid and the rest is water. He then mixes it with 20 lts of another mixture with 20% of liquid. What is the % of water in the new mixture?