A bakery currently has 8 pies and 3 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies?  Choose the most appropriate option.
A) 3/7 B) 5/7 C) 4/11 D) 7/11 E) 23/33
The total number of ways to choose 5 from 11 is 11C5 = 462.   The number of ways that include 3 pies is 84/113*34/112 = 56*3= 
<gadget id="calculator">56*3</gadget>
<output>168</output>
168   P(exactly 3 pies)= 168/462 = 4/11   The answer is 4/11.
<result>C</result>
A bakery currently has 8 pies and 3 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies?