A bakery currently has 9 pies and 2 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies?  Pick one:
A) 3/5
B) 4/7
C) 5/7
D) 2/11
E) 3/11
The total number of ways to choose 5 from 11 is 11C5 = 462.   The number of ways that include 3 pies is 9C3*2C2 = 84*1= 
<gadget id="calculator">84*1</gadget>
<output>84</output>
84   P(exactly 3 pies)= 84/462 = 2/11   The answer is 2/11.
<result>D</result>
A bakery currently has 9 pies and 2 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies?