In three years, Janice will be three times as old as her daughter. Six years ago, her age was her daughter’s age squared. What would be the age of Janice Daughter after 3 years
Choose one:
A) 18
B) 36
C) 40
D) 42
E) 45
Let Jane's age be J and daughters' age be D...   Given J   + 3= 
<gadget id="calculator">  + 3</gadget>
<output>3</output>
3(D + 3 )=&gt; J - 6 = 3D -&gt; Eq1.   Given J-6 = (D-6)^2 --&gt; Eq 2..   sub J-6 value in eq 2... 3D = D^2 - 12D + 36.   0 = D^2 - 15D + 36 =&gt; D = 12 or D = 3.   When D = 12 we get from eq 1... J+3 = 45 =&gt; J =42..   When D = 3 ..we get from eq 1.. J+3 = 18 =&gt; J = 15...   IMO option 18 is correct answer..
<result>A</result>
In three years, Janice will be three times as old as her daughter. Six years ago, her age was her daughter’s age squared. What would be the age of Janice Daughter after 3 years