When we multiply a certain two digit number by the
sum of its digits 405 is achieved. If we multiply the
number written in reverse order of the same digits
by the sum of the digits,we get 486.Find the number?  Pick one
A) 40
B) 45
C) 50
D) 55
E) 60
Let the number be x y.   When we multiply the number by the sum of its digit   405 is achieved.   (10x+y)(x+y)=405....................1   If we multiply the number written in reverse order by its   sum of digits we get 486.   (10y+x)(x+y)=486......................2   dividing 1 and 2   (10x+y)(x+y)/(10y+x)(x+y) = 405/486.   10x+y / 10y+x = 5/6.   60x+6y = 50y+5x   55x=44y   5x = 4y.   From the above condition we conclude that the above   condition is satisfied by the second option i e b. 45.   ANSWER : 45 45
<result>B</result>
When we multiply a certain two digit number by the
sum of its digits 405 is achieved. If we multiply the
number written in reverse order of the same digits
by the sum of the digits,we get 486.Find the number?