A box contains SEVEN bulbs out of which 4 are defective. If THREE bulbs are chosen at random, find the probability that atleast one bulb is good Options:	A) 5/38	B) 4/39	C) 4/31	D) 4/35	E) 6/35
Required probability = 1-4C3/7C3=1 - 4/35 = 31/35.
Answer:4/35
<result>D</result>
A box contains SEVEN bulbs out of which 4 are defective. If THREE bulbs are chosen at random, find the probability that atleast one bulb is good