The number of sequences in which 7 boys can throw a apple, so that the youngest player may not be the last is Options:
A) 2300
B) 2400
C) 4320
D) 4500
E) 4550
The last ball can be thrown by any of the remaining 6 players.   The first 6 players can throw the ball in ⁶P₆ ways.   The required number of ways = 6(6!) = 4320   4320
<result>C</result>
The number of sequences in which 7 boys can throw a apple, so that the youngest player may not be the last is