find the smallest number in GP whose sum is 38 and product is 1728  Answers:
A) 5  B) 6  C) 7  D) 8  E) 9
Let x,y,z be the numbers in geometric progression?   y^2=xz   x+y+z=38   xyz=1728   xyz = xzy = y^2y = y^3 = 1728   y = 12   y^2=xz=144   z=144/x   x+y+z = x+12+144/x = 38   x^2+12x+144=38x   x^2-26x+144=0   (x-18)(x-8)=0   x=8,18   If x =8, z = 38-8-12= 
<gadget id="calculator">38-8-12</gadget>
<output>18</output>
18   The numbers are 8,12, 18   Their sum is 38   Their product is 1,728   The smallest number is 8   ANSWER:8
<result>D</result>
find the smallest number in GP whose sum is 38 and product is 1728