What is the sum of the digits of integer k, if k = (10^40- 46)	Select.
A) 351 B) 360 C) 363 D) 369 E) 378
There are 41 digits in 10^4   When we subtract 46 from it, there will be 40 digits left.   10^4 can be written as 9999999....(40 times) + 1   So,   10^40 - 46 = 9999999....(40 times) + 1 - 46 = 9999999....(40 times) -45   Consider the last 2 digits,   99-45= 
<gadget id="calculator">99-45</gadget>
<output>54</output>
54   The last 2 digits will be 54.   And our number would be 99999......99954 with 2 less 9s after subtraction.   Number of 9s left are 38 and the last two digits are 54   The sum of the digits will be     (38*9) + 5 + 4= 
<gadget id="calculator">  (38*9) + 5 + 4</gadget>
<output>351</output>
351   351nswer:- 351
<result>A</result>
What is the sum of the digits of integer k, if k = (10^40- 46)