It is being given that (2^32 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?	Choose the correct choice from the following choices
A) (2^16 + 1) B) (2^16 - 1) C) (7 x 2^23) D) (2^96 + 1) E) (2^98 + 1)
Let 2^32 = x. Then, (2^32 + 1) = (x + 1).   Let (x + 1) be completely divisible by the natural number N. Then,   (2^96 + 1) = [(2^32)^3 + 1] = (x^3 + 1) = (x + 1)(x^2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.   Answer:(2^96 + 1)
<result>D</result>
It is being given that (2^32 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?