A rock is dropped into a well and the distance traveled is 16 t 2 feet, where t is the time. If the water splash is heard 3 seconds after the rock was dropped, and that the speed of sound is 1100 ft / sec, approximate the height of the well	Select the correct option
A) 134.8 feet B) 136.2 feet C) 132.7 feet D) 132.2 feet E) 115.3 feet
Let T1 be the time it takes the rock to reach the bottom of the well. If H is the height of the well, we can write   H = 16 T1 2   Let T2 be the time it takes sound wave to reach the top of the well. we can write   H = 1100 T2   The relationship between T1 and T2 is   T1 + T2 = 3   Eliminate H and combine the equations H  1 +  2= 
<gadget id="calculator"> 1 +  2</gadget>
<output>3</output>
3   Eliminate H and combine the equations H= 16 T1 2 and H = 1100 T2 to obtain   16 T1 2 = 1100 T2   We now substitute T2 by 3 - T1 in the above equation   16 T1 2 = 1100 (3 - T1)   The above is a quadratic equation that may be written as   16 T1 2 + 1100 T1 - 3300 = 0   The above equations has two solutions and only one of them is positive and is given by   T1 = 2.88 seconds (2 decimal places)   We now calculate the height H of the well   H = 16 T1 2 = 16 (2.88) 2 = 132.7 feet   Answer 132.7 feet
<result>C</result>
A rock is dropped into a well and the distance traveled is 16 t 2 feet, where t is the time. If the water splash is heard 3 seconds after the rock was dropped, and that the speed of sound is 1100 ft / sec, approximate the height of the well