By using the numbers 1, 2, 5, 7 and 9 only once, how many five digit numbers can be made that are divisible by 25?
Select the correct option
A) 11
B) 12
C) 5
D) 10
E) 9
A number to be divisible by 25 must end with 00, 25, 50, or 75.   So, there are the following cases possible:   179-25 --&gt; the first three digits can be arranged in 3=6 ways.   129-75 --&gt; the first three digits can be arranged in 3=6 ways.   Total = 6 + 6= 
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
12.   Answer: 12.
<result>B</result>
By using the numbers 1, 2, 5, 7 and 9 only once, how many five digit numbers can be made that are divisible by 25?