Kyle, David, and Catherine each try independently to solve a problem. If their individual probabilities for success are 1/3, 2/7 and 5/9, respectively, what is the probability that Kyle and Catherine, but not David will solve the problem? Select the correct option
A) 35/189 B) 33/129 C) 25/189 D) 24/113 E) 20/189
P(Kyle will solve)=1/3   P(David will not solve)= 1 - 2/7 = 5/7   P(25/189atherine will solve) = 5/9   P= (1/3)*(5/7)*(5/9) = 25/189   Answer:25/189
<result>C</result>
Kyle, David, and Catherine each try independently to solve a problem. If their individual probabilities for success are 1/3, 2/7 and 5/9, respectively, what is the probability that Kyle and Catherine, but not David will solve the problem?