In how many ways can be 4 boys and 4 girls sit around circular table so that no two boys sit next to each other?
Choose the correct choice from the following:
A) (5!)^2  B) (6!)^2  C) 3!4!  D) 11!  E) (5!)^2*6!
first fix one boy and place other 3 in alt seats so total ways is 3!   now place each girl between a pair of boys... total ways of seating arrangement of girls 4!   total is 4!*3!   ANS 3!4!
<result>C</result>
In how many ways can be 4 boys and 4 girls sit around circular table so that no two boys sit next to each other?