Three numbers are randomly selected, with replacement, from the set of integers {0, 1, 2, 3, 4, 5, 6, 7, 8}. If the first number selected is w, the second number selected is x, and the third number is y, what is the probability that w < x < y ?	Choose the most appropriate option
A) 28/243  B) 31/243  C) 35/729  D) 83/729  E) 101/729
The number of ways to select w, x, and y is:   9*9*9= 
<gadget id="calculator">  9*9*9</gadget>
<output>729</output>
729   The number of ways to choose three different numbers from the set is 9C3=84.   There are six permutations for each group of three different numbers, but only one permutation satisfies w &lt; x &lt; y.   The probability that w &lt; x &lt; y is 84/729 = 28/243   The answer is 28/243.
<result>A</result>
Three numbers are randomly selected, with replacement, from the set of integers {0, 1, 2, 3, 4, 5, 6, 7, 8}. If the first number selected is w, the second number selected is x, and the third number is y, what is the probability that w < x < y ?