The product of two numbers is 2028 and their H.C.F is 13. The number of such pairs is:	Choose one:
A) 1 B) 2 C) 3 D) 4 E) 5
Let the numbers be 13a and 13b.   Then, 13a * 13b = 2028 =&gt; ab = 12.   Now, co-primes with product 12 are (1, 12) and (3, 4).   So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).   Clearly, there are 2 such pairs.   ANSWER:2
<result>B</result>
The product of two numbers is 2028 and their H.C.F is 13. The number of such pairs is: