8 books are to be arranged in a shelf. Among these, 3 are copies of the same Math book, 3 are copies of the same Physics book and the remaining are copies of the same Chemistry book. How many different arrangements can be created?
Choose one:
A) 8!/{3!^3}  B) 8!/{3!3!2!2!}  C) 8!/{3!^2}  D) 8!/{(2!)(3!^2)}  E) 8!/{2!^3}
The total number of ways in which a total N items, out of which p are identical of one type, q are identical of another type and rest are different, can be arranged in a line is N!/{p!q!}   In the given problem, we have 8 books out of which 3 are identical Math books, 3 are identical Physics books and the remaining 2 are the same Chemistry books.   Hence the number of words that can be formed is 8!/{3!3!2!}   Ans 8!/{(2!)(3!^2)}
<result>D</result>
8 books are to be arranged in a shelf. Among these, 3 are copies of the same Math book, 3 are copies of the same Physics book and the remaining are copies of the same Chemistry book. How many different arrangements can be created?