Mr. Thomas invested an amount of 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be 3508, what was the amount invested in Scheme B?
Answers:
A) 6400  B) 6500  C) 7200  D) 7500  E) None of these
Let the sum invested in Scheme A be x and that in Scheme B be (13900 – x).   Then, (x×14×2/100)+[(13900−x)×11×2/100]=3508   ⇒ 28x – 22x = 350800 – (13900 × 22) ⇒ 6x = 45000   ⇒ x = 7500.   So, sum invested in Scheme B = (13900 – 7500) = 6400.   6400nswer 6400
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Mr. Thomas invested an amount of 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be 3508, what was the amount invested in Scheme B?