The probability that B can shoot a target two out of two times is 0.45. What is the probability that the target will be missed by B immediately after such two shots?  Answers: A) 0.25 B) 0.5 C) 0.55 D) 0.4 E) 0.8
Suppose there are total 'x' shots.   B shoots 2 out of 2 times. means out of x shots (x&gt;2) B shots 2 out of 2 ----&gt; B shots at least 2 out of x.   therefore, 2/x = 0.25 (given)   the target will be missed by B immediately after such two shots : this means he can shot just twice ...the third shot cannot happen which means he missed (x-2) shots.   thus, the probabilty of missing just after 2 shots is (x-2)/x.   (x-2)/x = 1 - 2/x   = 1 - 0.45= 
<gadget id="calculator">1 - 0.45</gadget>
<output>0.55</output>
0.55   Answer : 0.55
<result>C</result>
The probability that B can shoot a target two out of two times is 0.45. What is the probability that the target will be missed by B immediately after such two shots?