The average of 10 consecutive integers is 16. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average?
Choices:  A) 10.5  B) 11  C) 11.5  D) 12  E) 12.5
The total subtracted is (9+8+...+1) = (9*10) / 2= 
<gadget id="calculator">(9*10) / 2</gadget>
<output>45</output>
45   On average, each number will be reduced by   45/10= 
<gadget id="calculator">  45/10</gadget>
<output>9/2 = around 4.5</output>
4.5   Therefore, the overall average will be reduced by 4.5   The answer is 11.5.
<result>C</result>
The average of 10 consecutive integers is 16. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average?