There are 10 magazines lying on a table; 6 are sports magazines and the other 4 are current affairs magazines. If 4 magazines are to be selected at random from the 10 magazines, what is the probability that at least one of the current affairs magazines will be selected?	Select the correct option.
A) 2/5	B) 3/5	C) 4/5	D) 6/5	E) 7/5
Total probability=10C4=210   4C4 +4C3*6C1+4C2*6C2+4C1*6C3=1+24+21+80= 
<gadget id="calculator">1+24+21+80</gadget>
<output>126</output>
126   therefore the probability that at least one of the current affairs magazines will be selected= 126/210=3/5   answer is 3/5
<result>B</result>
There are 10 magazines lying on a table; 6 are sports magazines and the other 4 are current affairs magazines. If 4 magazines are to be selected at random from the 10 magazines, what is the probability that at least one of the current affairs magazines will be selected?