From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:  Options:	A) 149 m	B) 156 m	C) 173 m	D) 200 m	E) none
Solution   Let AB be the tower.   Then, &lt;APB =30° and AB= 100 m   AB/AP= tan30°   = 1 / √3   AB = (AB x √3)= 100√3 m.   = (100 x 1.73) m = 173 m.   Answer 173 m
<result>C</result>
From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is: