What are the last two digits of 43*25*23*72*51*31? Choose the correct option
A) 54
B) 75
C) 00
D) 45
E) 32
43*25*23*72*51*31=   We have to focus on the last two digits only, so 43*25=75*23=25*72=00   51*00= 
<gadget id="calculator">51*00</gadget>
<output>0</output>
00 therefore   31*00= 
<gadget id="calculator">  31*00</gadget>
<output>0</output>
00   Hence Answer is 00
<result>C</result>
What are the last two digits of 43*25*23*72*51*31?