how many 6 digit no. can be formed using digits 0 to 5,without repetition such that number is divisible by digit at its unit place?
Pick:
A) 420 B) 426 C) 432 D) 456 E) 485
when unit place is 1 then numbers which are divisible by 1 = 96 (4*4*3*2*1*1 ways)   when unit place is 2 then numbers which are divisible by 2 = 96 (4*4*3*2*1*1 ways)   when unit place is 3 then numbers which are divisible by 3 = 96 (4*4*3*2*1*1 ways)   when unit place is 3 then numbers which are divisible by 4 = 42 (3*3*2*1*1*1 ways when last two digits are 24 and 4*3*2*1*1*1 ways when last two digits are 04)   when unit place is 3 then numbers which are divisible by 5 = 96 (4*4*3*2*1*1 ways)   total=426   ANSWER:426
<result>B</result>
how many 6 digit no. can be formed using digits 0 to 5,without repetition such that number is divisible by digit at its unit place?