A hungry child reaches into a candy jar filled with 5 different candies; red, green, yellow, black, and white colored candies. If the child randomly picks three candies, what is the probability the child will pick the red and green colored candies as two of the three candies?
Choose the correct choice from the following
A) 3/10	B) 1/10	C) 1/15	D) 3/15	E) 2/5
Combination Formula: nCr = n!/(r!(n - r)!), where n is the population/set, and r is the sample/subset.   Total number possible = 5C3 = 5!/(3!(5 - 3)!) = 10   Number red possible = 1C1 = 1   Number green possible = 1C1 = 1   Number other possible = 3C1 = 3   Probability Formula: P(3/10) = (Number Favorable Outcomes)/(Total Number Possible Outcomes)   P(RG) = (1C1)(1C1)(3C1)/5C3 = 3/10   3/10nswer: 3/10
<result>A</result>
A hungry child reaches into a candy jar filled with 5 different candies; red, green, yellow, black, and white colored candies. If the child randomly picks three candies, what is the probability the child will pick the red and green colored candies as two of the three candies?