A highway is to be divided into four lanes. For this purpose, three yellow stripes are painted so that stripes divide the highway into four lanes. If 3 gallons of paint cover an area of 5P square feet of highway, how many gallons of paint are needed to paint two stripes x inches wide on a stretch of highway m miles long? (1 mile = 5280 feet and 1 feet = 12 inches)
Answers.
A) 792mx/P  B) 264mx/P  C) 792P/mx  D) 264P/mx  E) 880mx/P
1 square foot needs 3/5P gallons of paint.   The width of each stripe is x/12 feet.   The length of each stripe is 5280m feet.   The area of each stripe is (5280m)(x/12) = 440mx square feet.   For three stripes, the total area is 1320mx square feet.   The number of gallons needed is (1320mx)*(3/5P) = 792mx/P gallons.   The answer is 792mx/P.  (1320  )*(3/5 )= 
<gadget id="calculator">  (1320  )*(3/5 )</gadget>
<output>792</output>
792mx/P gallons.   The answer is 792mx/P.
<result>A</result>
A highway is to be divided into four lanes. For this purpose, three yellow stripes are painted so that stripes divide the highway into four lanes. If 3 gallons of paint cover an area of 5P square feet of highway, how many gallons of paint are needed to paint two stripes x inches wide on a stretch of highway m miles long? (1 mile = 5280 feet and 1 feet = 12 inches)