A computer wholesaler sells 7 different computers and each is priced differently. If the wholesaler chooses three computers for display at a trade show, what is the probability (all things being equal) that the two most expensive computers will be among the three chosen for display?  Choose the most appropriate option:
A) 5/35	B) 3/28	C) 1/28	D) 1/56	E) 1/168
Since, two of the choices are prefixed, we are free to choose 1 from the rest of the 5 avilable. so 5C1 is the numerator.   Total no of ways we can choose 3 from 7 is 7c3, which is the denominator.   So, the probability: 5c1/7c3= 5/35 ans is 5/35.
<result>A</result>
A computer wholesaler sells 7 different computers and each is priced differently. If the wholesaler chooses three computers for display at a trade show, what is the probability (all things being equal) that the two most expensive computers will be among the three chosen for display?