Three times the first of three consecutive odd integers is 5 more than twice the third. The third integer is:
Pick
A) 9	B) 11	C) 13	D) 15	E) 17
Let the three integers be x, x + 2 and x+ 4.   Then,   3x = 2(x + 4) + 5   x = 12   Third integer = x + 4 = 17.   ANSW17R:17
<result>E</result>
Three times the first of three consecutive odd integers is 5 more than twice the third. The third integer is: