Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability V that Jane will be on the same committee as Albert? Select the correct option:
A) 12%
B) 20%
C) 33%
D) 40%
E) 50%
Total number of ways to choose 3 member committee - 6C3=(6!/3!3!)=20   No. of ways Albert n Jane are in same committee:- (4C1 * 2)= 8   Probability V= (8/20) *100= 
<gadget id="calculator">(8/20) *100</gadget>
<output>40</output>
40%.   +1 for me.. :40%
<result>D</result>
Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability V that Jane will be on the same committee as Albert?