A man drive his car to the office at 20miles/hr.
After reaching office, he realize that its a new year holiday so he went back home at a speed of 30miles/hr.
Discounting the time spent in the stoppage what was his average speed of his journey ? Answers.
A) 23miles/hr	B) 24miles/hr	C) 25miles/hr	D) 26miles/hr	E) None
Solution:   24miles/hr (not 25miles/hr which might be guessed by many)   D : distance traveled   T1 : time of going to office   T2 : time of returning back   Y : Average Speed   D = 20 * T1   T1 = D/20   D = 30 * T2   T2 = D/30   2D = Y(T2 + T1)   2D = Y(D/20 + D/30)   2D = Y(3D/60 + 2D/60)   2D = Y(5D/60)   Y = 120D/5D   =&gt; Y = 24   Answer 24miles/hr
<result>B</result>
A man drive his car to the office at 20miles/hr.
After reaching office, he realize that its a new year holiday so he went back home at a speed of 30miles/hr.
Discounting the time spent in the stoppage what was his average speed of his journey ?