A town's oldest inhabitant is x years older than the sum of the ages of the Lee triplets. If the oldest inhabitants is now J years old, how old will one of the triplets F be in 20 years?
J-X-40/3 is my answers.
J = X + L + L + L is the initial situation
After 20 years
J + 20 = X + L + L + L + 60 ...20 years for each triplet so 60 years totally.
J - X - 40/ 3 = L is my answer.
What wrong am i doing ? Since the age asked is after 20 years i also consider adding 20 years to J .	Choose the correct choice from the following answers:
A) (J - 50)/3	B) 3(J + 20)/x	C) (J + x - 50)/3	D) (J - x + 60)/3	E) (J + x - 20)/3
here it goes:   Oldest inhabitant = sum of age of triplets + X   J = 3L + X so L = (J - X)/3   After 20 years = L + 20   F= (J - X)/3 + 20   = (J - X + 60)/3=(J - x + 60)/3
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A town's oldest inhabitant is x years older than the sum of the ages of the Lee triplets. If the oldest inhabitants is now J years old, how old will one of the triplets F be in 20 years?
J-X-40/3 is my answers.
J = X + L + L + L is the initial situation
After 20 years
J + 20 = X + L + L + L + 60 ...20 years for each triplet so 60 years totally.
J - X - 40/ 3 = L is my answer.
What wrong am i doing ? Since the age asked is after 20 years i also consider adding 20 years to J .