Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.
Choose the correct answer.
A) 1683  B) 1753  C) 1523  D) 1433  E) None of them
L.C.M. of 5,6,7,8 = 840.   Therefore, Required number is of the form 840k + 3   Least value of k for which (840k + 3) is divisible by 9 is k = 2.   Therefore, Required number = (840 X 2 + 3)=1683   1683nswer is 1683.
<result>A</result>
Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.