The weight of four dogs is determined to be 25 pounds, 31 pounds, 51 pounds and 41 pounds respectively. The weight of a fifth dog is determined to be y pounds. If the average (arithmetic mean) weight of the first four dogs is the same as that of all five dogs what is the value of y?
Choose the correct answer: A) 31 B) 33 C) 35 D) 37 E) 39
Total weight of the 4 dogs = (25+31+51+41)= 
<gadget id="calculator">(25+31+51+41)</gadget>
<output>148</output>
148   Avg= 148/4= 
<gadget id="calculator">148/4</gadget>
<output>37</output>
37   Total weight of 5 dogs= 148+y or 4(37)+y   Average of 5 dogs as per Question = 37   Equation:   4(37) + y = 5 (37), or y = 37.   Choose 37
<result>D</result>
The weight of four dogs is determined to be 25 pounds, 31 pounds, 51 pounds and 41 pounds respectively. The weight of a fifth dog is determined to be y pounds. If the average (arithmetic mean) weight of the first four dogs is the same as that of all five dogs what is the value of y?