A certain deck of cards contains 2 blue cards, 2 red cards, 2 yellow cards, and 2 green cards. If two cards are randomly drawn from the deck, what is the probability that they will both be not green? Choices:
A) 15/28
B) 1/4
C) 9/16
D) 1/32
E) 1/16
The question asks they will both be not green. Considering that these are draws without replacement there are following possibilities :   draw 1, draw 2   ===== =====   1) Not green, green;   2) green, Not green;   3) green, green;   4) Not green, not green;   The answer has to be either P(4) OR all exclusion of the 3 previous conditions i.e. 1- [P(1) + P(2) + P(3)] =&gt; neither of the draws are green   P(4) = 6/8*5/7=15/28   1- [P(1) + P(2) + P(3)] = 1 - [ (6/8 * 2/7) + (2/8*6/7) + (2/8*1/7)] = 1 - [26/8*7] = 1 - [13/28] = 15/28   15/28
<result>A</result>
A certain deck of cards contains 2 blue cards, 2 red cards, 2 yellow cards, and 2 green cards. If two cards are randomly drawn from the deck, what is the probability that they will both be not green?