If xy ≠ 0 and x^2y^2 − xy = 30, which of the following could be y in terms of x?
I. 6/x
II. -5/x
III. 3/x
Choose the correct choice from the following answers:
A) I only
B) II only
C) I and II only
D) I and III
E) II and III
(x^2)(y^2) – xy - 30 = 0   (xy – 6)(xy + 5) = 0   xy – 6 = 0 or xy + 5 = 0   xy = 6 or xy = -5   Since we need y in terms of x, we can isolate y in both of our equations.   y = 6/x or y = -5/x   Answer: I and II only
<result>C</result>
If xy ≠ 0 and x^2y^2 − xy = 30, which of the following could be y in terms of x?
I. 6/x
II. -5/x
III. 3/x