If a number is 60% more than the another, how much % is the smaller number less than the first ? Choices
A) 32(1/3)%
B) 16(2/3)%
C) 37(1/2)%
D) 36(4/3)%
E) none of these
Take a number 100,   Then the other number is 160   % the smaller number is less than the first = [(60/(160)) x 100]% = 37(1/2)%.   ANSWER:37(1/2)%
<result>C</result>
If a number is 60% more than the another, how much % is the smaller number less than the first ?