A certain board game is played by rolling a pair of fair six-sided dice and then moving one's piece forward the number of spaces indicated by the sum showing on the dice. A player is frozen if her opponent's piece comes to rest in the space already occupied by her piece. If player A is about to roll and is currently nine spaces behind player B, what is the probability that player B will be frozen after player A rolls?	Choose the correct choice from the following answers:	A) 1/12	B) 5/36	C) 1/9	D) 1/3	E) 17/36
no. of possible outcomes = 6*6= 
<gadget id="calculator">6*6</gadget>
<output>36</output>
36   no. of outcomes that result a total of 9 (as A is 9 spaces behind B)= 4 ( (3,6), (4,5), (5,4), (6,3) )   So, the probability = 4/36=1/9 (Option 1/9)
<result>C</result>
A certain board game is played by rolling a pair of fair six-sided dice and then moving one's piece forward the number of spaces indicated by the sum showing on the dice. A player is frozen if her opponent's piece comes to rest in the space already occupied by her piece. If player A is about to roll and is currently nine spaces behind player B, what is the probability that player B will be frozen after player A rolls?