If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 3:4 then find the smallest number?	Choose the correct choice
A) 20 B) 22 C) 27 D) 28 E) 30
2:3   2x + 10 : 3x + 10 = 3 : 4   4[2x + 10] = 3[3x + 10]   8x + 40 = 9x + 30   9x - 8x = 40 - 30= 
<gadget id="calculator">40 - 30</gadget>
<output>10</output>
10   Then smallest number is= 2   2x = 20   Short cut method:   a:b = 2:3   c:d = 3:4   1.Cross multiplication with both ratios   a * d ~ b * c = 2 * 4 ~ 3 * 3 = 8 ~ 9 = 1   2. If 10 is added both the number means   10 * 3= 
<gadget id="calculator">  10 * 3</gadget>
<output>30</output>
30 and   10 * 4= 
<gadget id="calculator">  10 * 4</gadget>
<output>40</output>
40,   Then 30 ~ 40= 10   ===&gt; 1 -----&gt; 10   ===&gt; 2 -----&gt; 20   20
<result>A</result>
If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 3:4 then find the smallest number?