A committee has 6 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
Choose the correct choice from the following answers:
A) 127
B) 300
C) 882
D) 272
E) 323
The number of ways to select two men and three women   = 6C₂ * ⁶C₃   = (6*5)/(2 * 1) * (6 * 5 * 4)/(3 * 2)= 
<gadget id="calculator">(6*5)/(2 * 1) * (6 * 5 * 4)/(3 * 2)</gadget>
<output>300</output>
300   Answer: 300
<result>B</result>
A committee has 6 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?