Of the three-digit integers greater than 700, how many have two digits that are equal to each other and the remaining digit different from the other two?	Pick one
A) 90 B) 82 C) 80 D) 45 E) 36
Three digit number can have only following 3 patterns:   A. all digits are distinct;   B. two digits are alike and third is different;   C. all three digits are alike.   We need to calculate B. B=Total - A - C   Total numbers from 700 to 999 = 299 (3-digit numbers greater than 700);   A. all digits are distinct = 3*9*8= 
<gadget id="calculator">3*9*8</gadget>
<output>216</output>
216 (first digit can have only three values 7, 8, or 9);   C. all three are alike= 3 (777, 888, 999).   So, 299-216-3=80.   Answer: 80.
<result>C</result>
Of the three-digit integers greater than 700, how many have two digits that are equal to each other and the remaining digit different from the other two?