Consider the sequence of numbers beginning 23, 27, 28, 32, 33... It continues in such a way that by adding 5 to the nth term, one obtains the (n + 2)th term. What is the sum of the first 16 members of this sequence?	Choose the correct choice from the following answers: A) 878 B) 680 C) 788 D) 928 E) 1022
I would split them up like this.   23 28 33 and so on (8 terms)....the 10th term = 23+7*5= 
<gadget id="calculator">23+7*5</gadget>
<output>58</output>
58   27 32 37 and so on (8 terms)......the 9th term= 27+7*5= 
<gadget id="calculator">27+7*5</gadget>
<output>62</output>
62   Since the distance between any two numbers is the same we can use arithmetics   first+last/2 times no of numbers= the sum   (23+58)/2 * 8= 
<gadget id="calculator">(23+58)/2 * 8</gadget>
<output>324</output>
324   (27+62)/2 * 8= 
<gadget id="calculator">(27+62)/2 * 8</gadget>
<output>356</output>
356= 680   680
<result>B</result>
Consider the sequence of numbers beginning 23, 27, 28, 32, 33... It continues in such a way that by adding 5 to the nth term, one obtains the (n + 2)th term. What is the sum of the first 16 members of this sequence?