If z is a multiple of 9402, what is the remainder when z^2 is divided by 9? Answers.
A) 0	B) 2	C) 4	D) 6	E) 8
The sum of the digits is 9+4+2= 
<gadget id="calculator">9+4+2</gadget>
<output>15</output>
15.   Thus 3 is a factor of 9402, so 3 is a factor of z.   Then 3^3= 9 is a factor of z^2.   Then the remainder when z^2 is divided by 9 is 0.   The answer is 0.
<result>A</result>
If z is a multiple of 9402, what is the remainder when z^2 is divided by 9?