In an interview , the probability of appointing Husband is 1/5 while that of wife is
¼.find probability that only one of them get selected in interview.  Choices:
A) 3/20 B) 4/20 C) 5/20 D) 6/20 E) 7/20
p(H)=1/5   p(w)=1/4   P(H bar)=1-1/5=4/5   p(w bar)=1-1/4=3/4   Required probability=p(H)*p(w bar)+p(w)*p(H bar)   1/5*3/4+1/4*4/5   7/20   ANSW7/20R:7/20
<result>E</result>
In an interview , the probability of appointing Husband is 1/5 while that of wife is
¼.find probability that only one of them get selected in interview.