Let N be the greatest number that divides 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:  Choose one: A) 4 B) 5 C) 6 D) 7 E) 8
HCF of (4665-1305) , ( 6905-4665) , (6905-1305)   = HCF of 3360 ,2240,5600   = 1120   sum of digits = 4   4NSWER:4
<result>A</result>
Let N be the greatest number that divides 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: