Out of first 40 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is -. Choose one:	A) 1/2	B) 16/19	C) 4/5	D) 31/40	E) 3/5
n(S) = 40   n(Even no) = 20 = n(E)   n(Prime no) = 12 = n(P)   P(EᴜP) = 20/40 + 12/40 - 1/40 = 31/40   ANSWER:31/40
<result>D</result>
Out of first 40 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is -.