Lorna invests $7000, with some at 6% annual interest and some at 11% annual interest. If she receives a total of $580 from these investments at the end of a year, how much was invested at the 6% interest rate? Options:
A) $160
B) $1,600
C) $2,200
D) $1,400
E) $5,840
We have that 'x' invested at 6%   We also have that '6000-x' invested at 11%   Now then 580/7000 is approx 10%   Therefore, -4x+7000-x=0   5x=7000   x=1400 approximately. Probably higher   Only $1,400 matches
<result>D</result>
Lorna invests $7000, with some at 6% annual interest and some at 11% annual interest. If she receives a total of $580 from these investments at the end of a year, how much was invested at the 6% interest rate?