A bag contains 8 red, 7 blue and 6 green dress. If one dress is picked up randomly then ewhat is the probability that it is neither red nor green?
Choose the correct option:
A) 1/3
B) 2/3
C) 2/5
D) 3/7
E) None of these
Total number of dress = (8 + 7 + 6)= 
<gadget id="calculator">(8 + 7 + 6)</gadget>
<output>21</output>
21.   Let E= event that the dress drawn is neither red nor green   = event that the dress drawn is blue.   n(E) = 7.   P(E) =	n(E)	=	7	=	1/3   n(S) 21   1/3
<result>A</result>
A bag contains 8 red, 7 blue and 6 green dress. If one dress is picked up randomly then ewhat is the probability that it is neither red nor green?