John and Karen begin running at opposite ends of a trail until they meet somewhere in between their starting points. They each run at their respective constant rates until John gets a cramp and stops. If Karen runs 50% faster than John, who is only able to cover 25% of the distance e before he stops, what percent longer would Karen have run than she would have had John been able to maintain his constant rate until they met. Select the correct option:
A) 25%  B) 50%  C) 75%  D) 100%  E) 200%
John and Karen begin running at opposite ends of a trail until they meet somewhere in between their starting points. They each run at their respective constant rates until John gets a cramp and stops. If Karen runs 50% faster than John, who is only able to cover 25% of the distance e before he stops, what percent longer would Karen have run than she would have had John been able to maintain his constant rate until they met.   Lets say the distance of the trail is 100 miles. Lets also say that J rate = 10 miles/hour and K rate = 15 miles/hour.   If John stops at the 25% mark that means he travels 25 miles in 2.5 hours. It would take Karen t=d/r t=75/15= 
<gadget id="calculator">75/15</gadget>
<output>5</output>
5 hours to reach john. If John had not stopped, their combined rate would 10+15= 
<gadget id="calculator">10+15</gadget>
<output>25</output>
25 miles/hour meaning they would have met in 4 hours. Therefore, she ran one hour longer (25%) longer than she would have needed to if John ran for the entire time.   25%NSWER: 25%) 25%
<result>A</result>
John and Karen begin running at opposite ends of a trail until they meet somewhere in between their starting points. They each run at their respective constant rates until John gets a cramp and stops. If Karen runs 50% faster than John, who is only able to cover 25% of the distance e before he stops, what percent longer would Karen have run than she would have had John been able to maintain his constant rate until they met.