In a sequence of 11 numbers, each term, except for the first one, is 11^11 less than the previous term. If the greatest term in the sequence is 11^12, what is the smallest term in the sequence?
Thus, A12 = A1+12-1d
Where d is the difference between each pairs of consecutive terms. Since each term is 1211 less than the previous term, d=-1211Click individual answer choices for specific explanations.
From what I undersltand the formula for an arithmetic sequence represents
some-number-in-the-sequence= first-number-in-sequence +the-place-of-that-number - 1x the-difference-of-each-#-in-the-sequence Choose one:
A) −12^11	B) 0	C) 11^11	D) 11·12^11	E) 12^12
there are total 11 terms. andgreatestterm is 11^12. Each term is 11^11 less than previous one. What does this signify? This shows it is an AP - a decreasing one. (NoticeEach term is 11^11 less than previous one')   Therefore, 11^12 is the first term of the AP and -11^11 is the difference between successive terms, the smallest term should be the last one.   Last term = First term + (n-1)*d   therefore, Last term = 11^12 + 10*(-11^11)   =&gt; Last term = 11^12 - 10*11^11   =&gt; Last term = 11^11 (11-10) = 11^11   Which is the smallest term.   Hence Ans 11^11 it is.
<result>C</result>
In a sequence of 11 numbers, each term, except for the first one, is 11^11 less than the previous term. If the greatest term in the sequence is 11^12, what is the smallest term in the sequence?
Thus, A12 = A1+12-1d
Where d is the difference between each pairs of consecutive terms. Since each term is 1211 less than the previous term, d=-1211Click individual answer choices for specific explanations.
From what I undersltand the formula for an arithmetic sequence represents
some-number-in-the-sequence= first-number-in-sequence +the-place-of-that-number - 1x the-difference-of-each-#-in-the-sequence