If (x^2 + 1)y=7, which of the following is not a possible value for y?
Choose the correct choice from the following answers:
A) 2  B) 2/3  C) 4/3  D) 4  E) 15/2
Its simple   equation is (x^2 +1)y = 7 ===&gt; x^2 = (7/y) - 1 . As , in LHS, it is x^2 the value has to be positive or zero in RHS.   Hence, (7/y) - 1&gt;= 0 ===&gt; y =&lt; 7. Now only option E has greater value of 'y' than 7.   Thus, correct ans is 15/2
<result>E</result>
If (x^2 + 1)y=7, which of the following is not a possible value for y?