A bowl was filled with 10 ounces of water, and 0.010 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period?	Choose the correct answer.
A) 0.004%
B) 0.04%
C) 0.40%
D) 5%
E) 40%
Total amount of water evaporated each day during a 50-day period = .008 * 50   =.010 * 100/2   = 1.0/2= 
<gadget id="calculator">1.0/2</gadget>
<output>0.5</output>
.5   percent of the original amount of water evaporated during this period= (.5/10) * 100= 
<gadget id="calculator">(.5/10) * 100</gadget>
<output>5</output>
5 %   Answer 5%
<result>D</result>
A bowl was filled with 10 ounces of water, and 0.010 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period?