The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 13 consecutive integers that start with (m + 2)?	Choose one:	A) m + 6	B) n + 6	C) n + 3	D) m + 5	E) n + 4
The average of consecutive numbers is the middle number.   Then n = m+2.   The average of 13 consecutive numbers starting from n is n+6.   The answer is n + 6.
<result>B</result>
The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 13 consecutive integers that start with (m + 2)?