If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:  Options:
A) 4 days
B) 5 days
C) 6 days
D) 7 days
E) 9 days
Explanation:   Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.   Then, 6x + 8y =	1/10and 26x + 48y =	1/2   Solving these two equations, we get : x =	1/100 and y =	1/200   (15 men + 20 boy)'s 1 day's work =15/100 + 20/200 = 1/4   15 men and 20 boys can do the work in 4 days.   4 daysNSWER IS 4 days
<result>A</result>
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be: