A packet of 10 electronic components is known to include 3 defectives. If 4 components are randomly chosen and tested, what is the probability of finding among them not more than one defective component. Select the correct option:
A) 0.6517
B) 0.868
C) 0.4483
D) None of these
E) Cannot be determined
Explanation :   Here, the trials are independent , since the probability of defective component in any trial is not affected by the occurrence or non-occurrence of a defective component in any other trial. So, it is a case of binomial distribution.   No. of trials = n = 4.   Occurrence of a defective component is a success.   Then, the probability of success = p = 3/10.   the probability of failure = 1- p = 7/10.   Components not more than one defective one means x ≤ 1 i.e x = 0.   Using the formula,   P(x) = ncxPx(1-P)n-x.   Since,   =&gt; P(x ≤ 1) = P(x = 0) or P(x = 1)   = P(0) + P(1) .   = 4c0(3/10)0 x (7/10)4 + 4c1(3/10)1x (7/10)3 .   = (7/10)4 + 4 x (3/10) x (7/10)3.   = 0.6517   Hence, the required probability is 0.6517.   0.6517nswer : 0.6517
<result>A</result>
A packet of 10 electronic components is known to include 3 defectives. If 4 components are randomly chosen and tested, what is the probability of finding among them not more than one defective component.