Solution X is 20% chemical A and 80% chemical B by volume; Solution Y is 30% chemical A and 70% chemical B. If a mixture of X and Y is 22% chemical A, what percent of the mixture is Solution X?	Options:  A) 20%  B) 44%  C) 50%  D) 80 percent  E) 90%
22% of chemical A in X+Y grams of solution comes from 20% chemical A in solution X and 30% chemical A in solution Y, thus:   0.22(X + Y) = 0.2X + 0.3Y --&gt; X = 4Y --&gt; X/(X+Y)=4/5=0.8.   Answer: 80 percent.
<result>D</result>
Solution X is 20% chemical A and 80% chemical B by volume; Solution Y is 30% chemical A and 70% chemical B. If a mixture of X and Y is 22% chemical A, what percent of the mixture is Solution X?