How many four-digit numbers that do not contain the digits 2, 3, 4, 5, 6, or 7 are there?  Pick one: A) 168 B) 176 C) 184 D) 192 E) 200
The 1st digit can be filled up by the numbers: {1,8,9} = 3 ways   The 2nd digit can be filled up by the numbers: {0,1,8,9} = 4 ways   The 3rd digit can be filled up by the numbers: {0,1,8,9} = 4 ways   The 4th digit can be filled up by the numbers: {0,1,8,9} = 4 ways   The total number of such four-digit numbers is   3*4*4*4= 
<gadget id="calculator">  3*4*4*4</gadget>
<output>192</output>
192   The answer is 192.
<result>D</result>
How many four-digit numbers that do not contain the digits 2, 3, 4, 5, 6, or 7 are there?