A bag contains 12 white and 18 black balls.Two balls are drawn in succession without replacement. What is the probability that first is white and second is black? Options
A) 36/145 B) 29/145 C) 18/145 D) 20/145 E) 15/145
The probability that first ball is white=12C1/30C1=12/30=2/5   Since.the balls is not replaced; hence the number of balls left in bag=29.   Hence the probability of second ball is black is 18C1/29C1=18/29   Required probability =(2/5)*(18/29)=36/145   The answer is option 36/145
<result>A</result>
A bag contains 12 white and 18 black balls.Two balls are drawn in succession without replacement. What is the probability that first is white and second is black?