If X = the product of four distinct prime numbers, how many factors does X have besides 1 and itself? Choose the correct choice from the following answers.
A) 10	B) 11	C) 12	D) 13	E) 14
Let's take the four primes: 2, 3, 5 and 7 --&gt; each of the 4 primes will be a factor of the product   All the possible combinations of the four primes will be factors (10 possible combinations):   2x3   2x5   2x7   3x5   3x7   5x7   2x3x5   2x3x7   2x5x7   3x5x7   Thus, in total there are   10 + 4= 
<gadget id="calculator">  10 + 4</gadget>
<output>14</output>
14 factors.   ANSW14R:14
<result>E</result>
If X = the product of four distinct prime numbers, how many factors does X have besides 1 and itself?