Two numbers when divided by a divisor leave remainders of 218 and 342 respectively. The remainder obtained when the sum of the numbers is divided by the same divisor is 68. Find the divisor.
Choose one.
A) 387  B) 423  C) 492  D) 512  E) 602
Let x be the divisor.   N1 = xa + 218   N2 = xb + 342   N1 + N2 = x(a+b) + 560 = xc + 68   x(c-a-b) = 492 but we know that x &gt; 342, thus (c-a-b) must equal 1.   The answer is 492.
<result>C</result>
Two numbers when divided by a divisor leave remainders of 218 and 342 respectively. The remainder obtained when the sum of the numbers is divided by the same divisor is 68. Find the divisor.