One-sixth of the attendees at a certain convention are female students, two-thirds of the attendees are female, and one-third of the attendees are students. If 50 of the attendees are neither female nor students, what is the total number of attendees at the convention?  Options:  A) 600  B) 300  C) 400  D) 500  E) 700
Let no. of Attendee are A.   Now As per the condition of the problem stated above .   We have following population in the convention as Attendee.   Total no. of females = [2/3]*A   Total no. of females as student : [1/6]*A   Total no. of students = [1/3]*A   Total no. of male as student = [1/6]*A   Total no. of males = A - [2/3]*A = [1/3]A   No. of males which are not student = [1/3]A - [1/6]*A = 50   Hence A =300   Total no of males who are not student will be the answer as it states it should be neither female nor student   So Answer is 300
<result>B</result>
One-sixth of the attendees at a certain convention are female students, two-thirds of the attendees are female, and one-third of the attendees are students. If 50 of the attendees are neither female nor students, what is the total number of attendees at the convention?