What is the least multiple of 7 which leaves a remainder of 4 when divided by 6, 9, 15 and 18 ?
Choose the correct choice from the following options:
A) 364  B) 350  C) 343  D) 371  E) 398
LCM of 6, 9, 15 and 18 = 90   Required Number = (90k + 4) which is a multiple of 7   Put k = 1. We get number as (90 × 1) + 4 = 94. But this is not a multiple of 7   Put k = 2. We get number as (90 × 2) + 4 = 184. But this is not a multiple of 7   Put k = 3. We get number as (90 × 3) + 4 = 274. But this is not a multiple of 7   Put k = 4. We get number as (90 × 4) + 4 = 364. This is a multiple of 7   Hence 364 is the answer. 364nswer: Option 364
<result>A</result>
What is the least multiple of 7 which leaves a remainder of 4 when divided by 6, 9, 15 and 18 ?