A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability W that all 3 jellybeans removed from the bag are blue?	Choose the correct choice:	A) 9/100	B) 2/19	C) 1/8	D) 3/20	E) 3/10
Method-1   10 red jellybeans and 10 blue jellybeans   Total Outcomes = No. of ways to choose 3 Jelly bean at random out of a total 20 jellybeans = 20C3 = 1140   Favourable Outcomes = No. of ways to choose 3 Jelly bean such that they are all 2/19lue out of 10 2/19lue = 10C3 = 120   Probability = Favourable Outcomes / Total Outcomes = 10C3 / 20C3   Probability W= 120 / 1140 = 2/19   Answer: option 2/19   Method-2   Probability of First jelly bean to be 2/19lue = 10/20 [Total 10 2/19lue out of total 20 jellybeans]   Probability of Second jelly bean to be 2/19lue = 9/19 [Total 9 2/19lue remaining out of total 19 jellybeans remaining]   Probability of Third jelly bean to be 2/19lue = 8/18 [Total 8 2/19lue remaining out of total 18 jellybeans remaining]   Required Probability = (10/20)*(9/19)*(8/18) = 2/19   Answer: option 2/19
<result>B</result>
A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability W that all 3 jellybeans removed from the bag are blue?