How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 2? Choose the correct answer
A) 15	B) 16	C) 17	D) 18	E) 19
18   All numbers divisible by two must be even, therefore the two digit number must end in 2, 4, or 6. There are three possibilities for each odd number first digit and two combinations for each even first number digit. 4x3 + 3x2 =18   Correct answer is 18.
<result>D</result>
How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 2?