Which is the least number that must be subtracted from 1856 so that the remainder when divided by 7, 12, 16 is 6?	Select the correct option:
A) 168	B) 172	C) 170	D) 174	E) 176
First we need to figure out what numbers are exactly divisible by 7,12,16. This will be the set {LCM,LCMx2,LCMx3,...}   LCM(7,12,16) = 48*7= 
<gadget id="calculator">48*7</gadget>
<output>336</output>
336   The numbers which will leave remainder 6 will be {336+6, 336x2 +6, 336x3 +6,...}   The largest such number less than or equal to 1856 is 336x5+6 or 1686   To obtain this you need to subtract 170.   170
<result>C</result>
Which is the least number that must be subtracted from 1856 so that the remainder when divided by 7, 12, 16 is 6?