Find the least number of candidates in an examination so that the percentage of successful candidates should be 76.8%:	Select:
A) 105	B) 115	C) 125	D) 135	E) 145
suppose no. of total candidates are 'y' and successful are 'x'.   (x/y)*(100)=76.8 or x/y=0.768   or y=x/0.768   here we need minimum value of y, which is obtained by minimum value of x.   if put x=768 then y=1000   now we will try decrease value of x than we will find less value of y. so factorized 768 by 2 further.   if put x=384 then y=500   if put x=192 then y=250   if put x=96 then y=125(answer)   if put x=48 then y=62.5(not integer)   so ans is 125   ANSWER:125
<result>C</result>
Find the least number of candidates in an examination so that the percentage of successful candidates should be 76.8%: