A committee has 5 men and 4 women. What are the number of ways of selecting 2 men and 3 women from the given committee?	Options
A) 127  B) 40  C) 882  D) 272  E) 323
The number of ways to select two men and three women   = ⁵C₂ * 4C₃   = (5 *4 )/(2 * 1) * (4 * 3 * 2)/(3 * 2)= 
<gadget id="calculator">(5 *4 )/(2 * 1) * (4 * 3 * 2)/(3 * 2)</gadget>
<output>40</output>
40   Answer: 40
<result>B</result>
A committee has 5 men and 4 women. What are the number of ways of selecting 2 men and 3 women from the given committee?