If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?  Choose one
A) 19.3%
B) 17%
C) 16.67%
D) 15.5%
E) 12.5%
Let X be the quantity of non-vinegar in the strong vinegar solution   Thus vinegar quantity will be 12 - X   When 50 ounces of water were added the percentage of vinegar becomes 3%, thus (12 - X)/62 = 3/100   From this equation X = 10.14   Answer (12-10.14)/12 = 15.5%   ANSWER:15.5%
<result>D</result>
If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?