Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:	Answers:  A) 28 sec  B) 36 sec  C) 48 sec  D) 52 sec  E) 56 sec
Relative speed = (60+ 90) km/hr   = 150x5/18   = 120/3 m/sec   Distance covered = (1.10 + 0.9)= 
<gadget id="calculator">(1.10 + 0.9)</gadget>
<output>2</output>
2 km= 2000 m.   Required time = 2000 x 3/125 = 48 sec.   Answer : 48 sec.
<result>C</result>
Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: