A box contains 4 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either blue or red?
Select the correct option:  A) 8/10  B) 5/10  C) 9/10  D) 6/10  E) 7/10
Given that there are 4 blue marbles, 3 red marbles, 6 green marbles and 2 yellow marbles. Probability that both marbles are blue = 4Câ‚‚/Â¹âµCâ‚‚ = (3 * 2)/(15 * 14) = 2/35   Probability that both are red = 3Câ‚‚/Â¹âµCâ‚‚ = (1)/(15 * 14) = 1/35   Probability that one blue and other is red = (4Câ‚ * 3Câ‚)/Â¹âµCâ‚‚ = (4*2)/(15 * 14) = 4/35   Required probability = 2/35 + 1/35+ 4/35   = 7/10   Answer:7/10
<result>E</result>
A box contains 4 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either blue or red?