Three coins are tossed. What is the probability of getting at most two tails?  Choose the correct choice.
A) 7/8 B) 1/8 C) 1/2 D) 1/7 E) 1/3
Total number of outcomes possible when a coin is tossed = 2 (âˆµ Head or Tail)   Hence, total number of outcomes possible when 3 coins are tossed, n(S) = 2 Ã— 2 Ã— 2 = 8   (âˆµ i.e., S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH})   E = event of getting at most two Tails = {TTH, THT, HTT, THH, HTH, HHT, HHH}   Hence, n(E) = 7   P(E) = n(E)/n(S)=7/8   7/8nswer:7/8
<result>A</result>
Three coins are tossed. What is the probability of getting at most two tails?