Tom and Marry each have a bag of marbles, each of which contains 4 Red marbles, 10 blue marbles, and 6 yellow marbles. If Tom and Marry each select one marble from their respective bags, what is the probability that either Tom or Marry select a blue marble? Select
A) 1/7 B) 2/4 C) 3/4 D) 1/8 E) 1/16
Probability that either selects a red marble,P(Either) = 1- probability that neither selects a blue marble, P(Neither)   Probability that Tom selects non blue = 10c1 / 20c1 = 1/2   Probability that Marry selects non blue = 10c1 / 20c1 = 1/2   =&gt; P(Either)=1- (1/2*1/2) = 1-1/4= 3/4.   3/4)
<result>C</result>
Tom and Marry each have a bag of marbles, each of which contains 4 Red marbles, 10 blue marbles, and 6 yellow marbles. If Tom and Marry each select one marble from their respective bags, what is the probability that either Tom or Marry select a blue marble?