The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 11 consecutive integers that start with (m + 2)?
Choose the correct choice from the following options:  A) m + 4  B) n + 6  C) n + 3  D) n + 5  E) n + 4
The average of consecutive numbers is the middle number.   Then n = m+2.   The average of 11 consecutive numbers starting from n is n+5.   The answer is n + 5.
<result>D</result>
The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 11 consecutive integers that start with (m + 2)?