Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 27 percent ryegrass, what percent of the weight of this mixture is X ?
Choose the correct choice:
A) 10% B) 13.33 % C) 40% D) 50% E) 66.66 %
----------------&gt;Ryegrass   X--------------&gt;	40%   Y--------------&gt;	25%   M(mixture)----&gt;27%   0.4X + (M-X)0.25 = 0.27M   0.15X = 0.02M   X = 0.1333M   X = 13.33% of M   13.33 %
<result>B</result>
Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 27 percent ryegrass, what percent of the weight of this mixture is X ?