Three unbiased coins are tossed. What is the probability of getting 1 heads, 1 Tail? Choose the correct choice from the following options:  A) 3/4  B) 1/4  C) 3/8  D) 7/8  E) 2/8
Let, H --&gt; Head , T --&gt; Tail   Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}   Let 2/8 = event of getting 3 heads   Then 2/8 = {THT, HTH}   P(2/8) = n(2/8)/n(S) =2/8   Answer is 2/8
<result>E</result>
Three unbiased coins are tossed. What is the probability of getting 1 heads, 1 Tail?