The sum of three consecutive integers is 312. What is the sum of the next three consecutive integers?
Pick one:
A) 315	B) 321	C) 330	D) 415	E) 424
a+(a+1)+(a+2)=3a+3+( +1)+( +2)= 
<gadget id="calculator">+( +1)+( +2)</gadget>
<output>3</output>
3a+3=312   (a+3)+(a+4)+(a+5)=(3a+3)+9=312+9= 
<gadget id="calculator">312+9</gadget>
<output>321</output>
321   Answer: 321.
<result>B</result>
The sum of three consecutive integers is 312. What is the sum of the next three consecutive integers?