A group of five women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 8 theatre-goers?  Pick
A) 7! – 2!3!2!
B) 7! – 4!3!
C) 8! - 6!3!
D) 7 × 2!3!2!
E) 2!3!2!
8 people can sit in 8! different ways. But because 3 men cannot sit together, we take them as a unit.   This unit of men, among themselves can sit in 3! ways.   Hence, 8! - 3!.   This unit of men along with 5 women can sit in 6! different ways which also needs to be eliminated.   Hence 8! - 6!3!   8! - 6!3!
<result>C</result>
A group of five women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 8 theatre-goers?