If the sum of two positive integers is 18 and the difference of their squares is 36, what is the product of the two integers?	Pick:
A) 108
B) 80
C) 128
D) 135
E) 143
Let the 2 positive numbers x and y   x+ y = 18 -- 1   x^2 - y^2 = 36   =&gt; (x+y)(x-y)=36 -- 2   Using equation 1 in 2 , we get   =&gt; x-y = 2 -- 3   Solving equation 1 and 3 , we get   x= 10   y= 8   Product = 10*8= 
<gadget id="calculator">10*8</gadget>
<output>80</output>
80   Answer 80
<result>B</result>
If the sum of two positive integers is 18 and the difference of their squares is 36, what is the product of the two integers?