Teams A, B, C,D and E were in a baseball tournament. Each team played each other team once. Team A beat team D. Teams A, B and C won the exact same number of games. How many games did team D lose?	Select the correct option.
A) 5 games  B) 4 games  C) 3 games  D) 2 games  E) 1 game
There are 4 teams and each team played each other team once. That tells us 2 facts:    Each team played 3 games    4 teams played a total of 6 games.   Since there are only 6 games, only 6 total wins are possible. Since A, B and C won the exact same number of games, they either all won 1 game or all won 2 games. Let’s examine both scenarios:   Scenario #1: A, B and C each won 1 game. In this scenario, D must have won all 3 games it played. That contradicts with the fact that A beat D. So, scenario 1 is not possible. So, it has to be scenario #2.   Scenario #2: A, B and C each 2 games. In this scenario, D won 0 games. That means D lost all 3 games it played.   correct answer 3 games
<result>C</result>
Teams A, B, C,D and E were in a baseball tournament. Each team played each other team once. Team A beat team D. Teams A, B and C won the exact same number of games. How many games did team D lose?