Two identical circles intersect such that their centers and the points at which they intersect form a square of side 1 cm. What is the area of the region where the two circles intersect?	Choices.
A) pi/2 - 1  B) pi/4 - 1  C) 1 - pi/4  D) pi/8 + 1  E) 4 - pi
Drawing a diagram, we see that the radius of the circle equals the side of the square.   The area of intersection is: pi*r^2/4 - (r^2-pi*r^2/4) = pi*r^2/2 - r^2 = pi/2 - 1   The answer is pi/2 - 1.
<result>A</result>
Two identical circles intersect such that their centers and the points at which they intersect form a square of side 1 cm. What is the area of the region where the two circles intersect?