If the reciprocals of two consecutive positive integers are added together, what is the sum in terms of the greater integer b?
Answers:	A) b^2- b	B) 2b-1	C) (2b-1)/(b^2- b)	D) 2b-3	E) 2b-5
Let two consecutive positive integers be b and b-1 (Greater integer is b)   So,   (1/b) + [1/(b-1)]   = (2b-1)/b(b-1)   =(2b-1)/(b^2- b)   Answer : (2b-1)/(b^2- b)
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If the reciprocals of two consecutive positive integers are added together, what is the sum in terms of the greater integer b?