x and y are positive integers. When x is divided by 15, the remainder is 2, and when x is divided by 10, the remainder is 7. When y is divided by 9, the remainder is 5, and when y is divided by 7, the remainder is 2. What is the least possible value of x * y?	Options
A) 389
B) 390
C) 388
D) 391
E) 392
When x is divided by 15, the remainder is 2: So, the possible values of x are: 2, 17, 32, 47, etc.   When x is divided by 10, the remainder is 7: So, the possible values of x are: 7,17... STOP. Since both lists include 17, the smallest possible value of x is 17.   When y is divided by 9, the remainder is 5: So, the possible values of y are: 5, 14, 23,32 etc.   When y is divided by 7, the remainder is 2: So, the possible values of y are: 2, 9, 16, 23 ...STOP. Since both lists include 23, the smallest possible value of y is 23   Since the smallest possible values of x and y are 17 and 23 respectively, the smallest possible value of x * y is 391. So,391 is the correct answer to the original question.
<result>D</result>
x and y are positive integers. When x is divided by 15, the remainder is 2, and when x is divided by 10, the remainder is 7. When y is divided by 9, the remainder is 5, and when y is divided by 7, the remainder is 2. What is the least possible value of x * y?