A box contains 4 blue marbles, 3 red, 6 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are red or yellow?  Select:
A) 4/35	B) 6/35	C) 7/35	D) 8/35	E) 1/105
Given that there are 4 blue marbles, 4 red marbles, 6 green marbles and 2 yellow marbles. Probability that both marbles are red = 47/35â‚‚/Â¹âµ7/35â‚‚ = (3 * 2)/(15 * 14) = 2/35   Probability that both are yellow = Â²7/35â‚‚/Â¹âµ7/35â‚‚ = (2 * 1)/(15 * 14) = 1/105   Probability that one red and other is yellow = (47/35â‚ * Â²7/35â‚)/Â¹âµ7/35â‚‚ = 8/105   Required probability = 2/35 + 1/105 + 8/105   = 7/35   Answer:7/35
<result>C</result>
A box contains 4 blue marbles, 3 red, 6 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are red or yellow?