Find three consecutive odd integers so that the sum of twice the first, the second
and three times the third is 152.
Choose one
A) 20,23,25	B) 23,25,27	C) 25,28,31	D) 30,33,35	E) 29,31,35
First x Make the first x   Second x+2 Odd numbers sowe add 2(same as even!)   Third x+4 Add 2more (4 total) to get the third   2F +S +3T =152 Twicethefirstgives2F andthree times thethirdgives3T   2(x)+(x+2)+3(x+4)=152 Replace F , S, and T withwhatwe labled them   2x+x+2+3x+12=152 Distirbute through parenthesis   6x+14=152 Combine like terms 2x+x+3x and 2+14   −14 −14 Subtract 14 fromboth sides   6x=138 Variable ismultiplied by 6   6 6 Divide both sides by 6   x=23 Our solution for x   First 23 Replace xwith 23 in the original list   Second  (23)+2= 
<gadget id="calculator"> (23)+2</gadget>
<output>25</output>
25 The numbers are 23, 25, and 27   Third (23)+4= 
<gadget id="calculator">(23)+4</gadget>
<output>27</output>
27   correct answer 23,25,27
<result>B</result>
Find three consecutive odd integers so that the sum of twice the first, the second
and three times the third is 152.