How many real solutions does the equation x5 + 2x3 + 8x2 + 16 = 0 have?
Pick:
A) 0 B) 1 C) 2 D) 3 E) 5
Note that x5+2x3+8x2+16 = (x3+8)(x2+2) = (x+2)(x2-2x+4)(x2+2).   Since the quadratic equations x2 - 2x + 4 = 0 and x2 + 2 = 0 have no real solutions, the   original equation has just one real solution, x = -2.   correct answer 1
<result>B</result>
How many real solutions does the equation x5 + 2x3 + 8x2 + 16 = 0 have?