If a triangle in the xy-coordinate system has vertices at (-2 , -3), (4, -3) and (28, 7), what is the area of the triangle?
Choose the correct choice from the following options.
A) 30 B) 36 C) 48 D) 60 E) 65
(-2,-3) is in 3rd quadrant, (4,-3) is in 4th quadrant while (28,7) is in 1st quadrant.   Also, y coordinate of (-2,-3) and (4,-3) is same so they lie on same horizontal line.   So base of triangle = sqrt[(-3+3)^2 + (4+2)^2] = 6   30nd height of triangle = 7 - (-3)= 
<gadget id="calculator">7 - (-3)</gadget>
<output>10</output>
10   So area of triangle= 1/2*6*10= 
<gadget id="calculator">1/2*6*10</gadget>
<output>30</output>
30   Hence option (30),
<result>A</result>
If a triangle in the xy-coordinate system has vertices at (-2 , -3), (4, -3) and (28, 7), what is the area of the triangle?