There are 13 hearts in a full deck of 52 cards. In a certain game, you pick a card from a standard deck of 52 cards. If the card is a heart, you win. If the card is not a heart, the person replaces the card to the deck, reshuffles, and draws again. The person keeps repeating that process until he picks a heart, and the point is to measure how many draws it took before the person picked a heart and, thereby, won. What is the probability that one will pick the first heart on the third draw or later?  Answers.
A) 1/2	B) 9/16	C) 11/16	D) 13/16	E) 15/16
Here, we're told that 13 of the 52 cards are "hearts" - this is 1/4 of the deck. We're also told that after drawing a card, the card is PUT BACK in to the deck (so there will always be 52 cards to draw from).   To draw a heart for the first time on the 3rd draw (or later), the FIRST TWO draws MUST NOT be hearts....   Probability of NOT drawing a heart on the first draw = 3/4   Probability of NOT drawing a heart on the second draw = 3/4   (3/4)(3/4) = 9/16   From this point, you will eventually draw a heart (which is what the question is asking for), so the probability is 9/16.   ANSWER:9/16
<result>B</result>
There are 13 hearts in a full deck of 52 cards. In a certain game, you pick a card from a standard deck of 52 cards. If the card is a heart, you win. If the card is not a heart, the person replaces the card to the deck, reshuffles, and draws again. The person keeps repeating that process until he picks a heart, and the point is to measure how many draws it took before the person picked a heart and, thereby, won. What is the probability that one will pick the first heart on the third draw or later?