How many digits are in the number 50^8 × 8^3 × 11^2? Pick one:	A) 22	B) 20	C) 19	D) 18	E) 17
calculate the Number of 0's through the powers of 10   50^8 × 8^3 × 11^2 = (5^2*2)^8*2^9*11^2 = 5^16*2^17*11^2 = 2*11^2*10^16 = 242*10^16   Hence we would have 16 trailing 0's and the three digits from 242   Total digits = 3 + 16= 
<gadget id="calculator">3 + 16</gadget>
<output>19</output>
19   19orrect Option: 19
<result>C</result>
How many digits are in the number 50^8 × 8^3 × 11^2?