A group of two women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?	Choose the correct answer.
A) 7! – 2!3!2!	B) 7! – 4!3!	C) 5! – 3!3!	D) 7 × 2!3!2!	E) 2!3!2!
5 people can sit in 5! different ways. But because 3 men cannot sit together, we take them as a unit.   This unit of men, among themselves can sit in 3! ways.   Hence, 5! - 3!.   This unit of men along with 2 women can sit in 3! different ways which also needs to be eliminated.   Hence 5! - 3!3!   5! – 3!3!
<result>C</result>
A group of two women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?