What is the largest integer n such that 2^n is a factor of 20^8 ? Pick.
A) 1
B) 2
C) 4
D) 8
E) 16
20^8=(2^2∗5)^8=2^16 5^8 Therefore the largest integer n such that 2^n is a factor of 2^165^8 is 16.   Answer: 16.
<result>E</result>
What is the largest integer n such that 2^n is a factor of 20^8 ?