A bag contains 6 white and 4 black balls .2 balls are drawn at random. Find the probability that they are of same color? Choose the correct choice from the following choices:
A) 7/15
B) 7/17
C) 8
D) 8/15
E) 9
Let S be the sample space   Then n(S) = no of ways of drawing 2 balls out of   (6+4)= 
<gadget id="calculator">  (6+4)</gadget>
<output>10</output>
\inline {\color{Black}10C_{2}}= =45   Let E = event of getting both balls of same colour   Then,n(E) = no of ways (2 balls out of six) or (2 balls out of 4)   =\inline {\color{Black}6C_{2}+4C_{2}} = = 15+6= 
<gadget id="calculator">15+6</gadget>
<output>21</output>
21   Therefore, P(E)= n(E)/n(S) = 21/45 = 7/15   7/15)
<result>A</result>
A bag contains 6 white and 4 black balls .2 balls are drawn at random. Find the probability that they are of same color?