If x and y are integers such that (x+1)^2 is less than or equal to 16 and (y-1)^2 is less than 64, what is the sum of the maximum possible value of xy and the minimum possible value of xy? Select the correct option:
A) -16  B) -10  C) 0  D) 14  E) 16
(x+1)^2 &lt;= 16   x &lt;= 3   x &gt;= -5   (y-1)^2&lt; 64   y &lt; 9   y &gt; -7   Max possible value of xy is -5 × -6 = 30   minimum possible value of xy is -5 × 8 = -40   -40 + 30 = -10   Answer : -10
<result>B</result>
If x and y are integers such that (x+1)^2 is less than or equal to 16 and (y-1)^2 is less than 64, what is the sum of the maximum possible value of xy and the minimum possible value of xy?