A basketball player succeeds with 40% of her free throws. If she has a set of three free throws, what is the probability that she succeeds at least once?	Choices:  A) 0.343  B) 0.472  C) 0.555  D) 0.657  E) 0.784
P(missing all 3 free throws) = 0.6^3 = 0.216   P(succeeding at least once) = 1 - 0.216= 
<gadget id="calculator">1 - 0.216</gadget>
<output>0.784</output>
0.784   The answer is 0.784.
<result>E</result>
A basketball player succeeds with 40% of her free throws. If she has a set of three free throws, what is the probability that she succeeds at least once?