A coin is tossed 4 times. What is the probability x that the number of Heads is equal to the number of Tails? Choose one.
A) 1/8
B) 1/4
C) 3/8
D) 1/2
E) 9/16
We have to find the probability that we get 2 heads and 2 tails in 4 tosses of the coin.   Using the binary formula and defining a head as a success,   P(2 heads in 4 tosses) = 43/82* (1/2)^2 * (1/2)^2   x= 6/16   = 3/8   The answer is therefore (3/8)
<result>C</result>
A coin is tossed 4 times. What is the probability x that the number of Heads is equal to the number of Tails?