The length of each side of square A is increased by 100 percent to make square B. If the length of the side of square B is increased by 75 percent to make square C, by what percent is the area of square C greater than the sum of the areas of squares A and B?  Choose the correct choice from the following:
A) 75% B) 80% C) 145% D) 150% E) 180%
Let length of each side of square A be 10   Area of A = 10^2 = 100   Since , length of each side of square A is increased by 100 percent to make square B   length of each side of square B = 2*10= 
<gadget id="calculator">2*10</gadget>
<output>20</output>
20   Area of B= 20^2 = 400   Since , length of the side of square B is increased by 75 percent to make square 145%   length of each side of square 145%= 1.75*20= 
<gadget id="calculator">1.75*20</gadget>
<output>35</output>
35   Area of 145%= 35^2 = 1225   Difference in areas of 145% and cummulative areas of A and B = 1225 -(400+100)= 
<gadget id="calculator">1225 -(400+100)</gadget>
<output>725</output>
725   percent is the area of square 145% greater than the sum of the areas of squares A and B= (725/500) * 100= 
<gadget id="calculator">(725/500) * 100</gadget>
<output>145</output>
145%   Answer 145%
<result>C</result>
The length of each side of square A is increased by 100 percent to make square B. If the length of the side of square B is increased by 75 percent to make square C, by what percent is the area of square C greater than the sum of the areas of squares A and B?