If n is a natural number, then (6n^2 + 6n) is always divisible by:
Choices
A) 6 B) 12 C) 24 D) 6 only E) 6 and 12 both
Explanation:   (6n^2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.   6 and 12 both
<result>E</result>
If n is a natural number, then (6n^2 + 6n) is always divisible by: