In a watch, the minute hand crosses the hour hand for the third time exactly after every 3 hrs., 18 min., 15 seconds of watch time. What is the time gained or lost by this watch in one day? Choose the correct choice from the following answers:	A) 14 min. 10 seconds lost	B) 13 min. 50 seconds lost	C) 13 min. 20 seconds gained	D) 14 min. 40 seconds gained	E) None of these
In a watch than is running correct the minute hand should cross the hour hand once in every 65 + 5⁄11 min.   So they should ideally cross 3 times once in   3×(720/11)−2060/11min=196.36minutes   But in the watch under consideration, they meet after every 3 hr,18 min and 15 seconds,   i.e, (3 × 60 + 18 + 15⁄60) = 793⁄4 min.   Thus, our watch is actually losing time (as it is slower than the normal watch). Hence when our watch elapsed   (1440×196.36/198.25)=1426.27.   Hence the amount of time lost by our watch in one day = (1440 - 1426.27)= 
<gadget id="calculator">(1440 - 1426.27)</gadget>
<output>13.73</output>
13.73 i.e. 13 min and 50s (approx).   Answer 13 min. 50 seconds lost
<result>B</result>
In a watch, the minute hand crosses the hour hand for the third time exactly after every 3 hrs., 18 min., 15 seconds of watch time. What is the time gained or lost by this watch in one day?