A fair sided die labeled 1 to 6 is tossed three times. What is the probability the sum of the 3 throws is 16?
A)
B)
C)
D)
E)
Choose the correct choice from the following answers:
A) 1/6 B) 7/216 C) 1/36 D) 9/216 E) 11/216
The sum of 16 is obtained if the dices show: (6, 5, 5) or (6, 6, 4).   Each can occur in 3!/2!=3 ways, for example we can get (6, 5, 5) in 3 ways: (6, 5, 5), (5, 6, 5), (5, 5, 6), permutation of three items (6, 6, 5) out of which 2 5's are identical.   So, # of favorable outcomes is  2*3= 
<gadget id="calculator"> 2*3</gadget>
<output>6</output>
6;   Total # of outcomes is 6*6*6= 
<gadget id="calculator">6*6*6</gadget>
<output>216</output>
216;   P=favorable/total=6/216=1/36.   Answer: 1/36
<result>C</result>
A fair sided die labeled 1 to 6 is tossed three times. What is the probability the sum of the 3 throws is 16?
A)
B)
C)
D)
E)