If the reciprocals of two consecutive positive integers are added together, what is the sum in terms of the greater integer x?
Pick.
A) x/3
B) x^2 - x
C) 2x - 1
D) (2x - 1)/(x^2 + x)
E) (2x - 1)/(x^2 - x)
Let two consecutive positive integers be x and x-1 (Greater integer is x)   So,   (1/x) + [1/(x-1)]   = (2x-1)/x(x-1)   =(2x-1)/(x^2- x)   Answer (2x - 1)/(x^2 - x)
<result>E</result>
If the reciprocals of two consecutive positive integers are added together, what is the sum in terms of the greater integer x?