The weight of four dogs is determined to be 42 pounds, 38 pounds, 35 pounds and 41 pounds respectively. The weight of a fifth dog is determined to be y pounds. If the average (arithmetic mean) weight of the first four dogs is the same as that of all five dogs what is the value of y?  Select:
A) 31	B) 33	C) 35	D) 37	E) 39
Total weight of the 4 dogs = (42+38+35+41)= 
<gadget id="calculator">(42+38+35+41)</gadget>
<output>156</output>
156   Avg= 156/4= 
<gadget id="calculator">156/4</gadget>
<output>39</output>
39   Total weight of 5 dogs= 156+y or 4(39)+y   Average of 5 dogs as per Question = 39   Equation:   4(39) + y = 5 (39), or y = 39.   Choose 39
<result>E</result>
The weight of four dogs is determined to be 42 pounds, 38 pounds, 35 pounds and 41 pounds respectively. The weight of a fifth dog is determined to be y pounds. If the average (arithmetic mean) weight of the first four dogs is the same as that of all five dogs what is the value of y?