A gambler bought $3,000 worth of chips at a casino in denominations of $20 and $100. That evening, the gambler lost 14 chips, and then cashed in the remainder. If the number of $20 chips lost was 2 more or 2 less than the number of $100 chips lost, what is the largest amount of money that the gambler could have received back?  Choose one:
A) $2,240 B) $2,120 C) $1,960 D) $1,920 E) $1,400
In order to maximize the amount of money that the gambler kept, we should maximize # of $20 chips lost and minimize # of $100 chips lost, which means that # of $20 chips lost must be 2 more than # of $100 chips lost.   So, if # of $20 chips lost is x then # of $100 chips lost should be x-2. Now, given that total # of chips lost is 14: x+x-2=14 --&gt; x=8: 8 $20 chips were lost and 8-2= 
<gadget id="calculator">8-2</gadget>
<output>6</output>
6 $100 chips were lost.   Total worth of chips lost is   8*20+6*100= 
<gadget id="calculator">  8*20+6*100</gadget>
<output>760</output>
$760, so the gambler kept $3,000-$760=$2,240.   $2,240nswer: $2,240.
<result>A</result>
A gambler bought $3,000 worth of chips at a casino in denominations of $20 and $100. That evening, the gambler lost 14 chips, and then cashed in the remainder. If the number of $20 chips lost was 2 more or 2 less than the number of $100 chips lost, what is the largest amount of money that the gambler could have received back?