what is the minimum value of f(x) where
f(x)=(logax+logbx+logcx) and a>b>c>1..	Answers:  A) 3  B) 2  C) 1  D) 4  E) 5
here a,b,c are base for log..they aren't multiplied with x.   so logax=logex/logea;   f(x)= (logx/loga + logx/logb+ logx/logc);   = logx * (1/loga + 1/logb + 1/logc);   for minimum value of f(x) log values must me max 1   =1*3= 
<gadget id="calculator">1*3</gadget>
<output>3</output>
3   3NSWER:3
<result>A</result>
what is the minimum value of f(x) where
f(x)=(logax+logbx+logcx) and a>b>c>1..