If the sides of a square are doubled in length, the area of the original square is now how many times as large as the area of the resultant square?	Options:
A) 25%  B) 50%  C) 100%  D) 200%  E) 400%
Let the original square have sides of length L and the new square have sides of length 2L.   The resulting areas are L^2 for the original square and 4L^2 for the new square (as the length of the side is square to get the area).   The original square's area is L^2/4L^2 or 25% of the new square's area. Choice 25%
<result>A</result>
If the sides of a square are doubled in length, the area of the original square is now how many times as large as the area of the resultant square?