In how many ways can 7 people, A, B, C, D, E, F, G be seated in a row such that C and D are not seated next to each other as well as A and B are not seated next to each other?	Choose the correct choice from the following:
A) 384
B) 396
C) 576
D) 4944
E) 696
Number of total arrangements = 7!   Restriction 1= ABC4944 not next to each other --&gt; let say AB and C4944 are considered as one unit, respectively   Restriction 2= AB is not the same as BA + C4944 is not the same as 4944C --&gt; the number will increase by 2*2   Total number of arrangements - Number out of restrictions = Result   7! - (4!*2*2) = 5040 - (24*2*2)= 
<gadget id="calculator">5040 - (24*2*2)</gadget>
<output>4_944</output>
4944   Answer 4944
<result>D</result>
In how many ways can 7 people, A, B, C, D, E, F, G be seated in a row such that C and D are not seated next to each other as well as A and B are not seated next to each other?