The sum of the squares of three numbers is 241, while the sum of their products taken two at a time is 100. Their sum is: Choose the correct option
A) 20 B) 11 C) 21 D) 41 E) None of these
x^+y^2+z^2=241   xy+yz+zx=100   as we know.. (x+y+z)^2=x^2+y^2+z^2+2(xy+yz+zx)   so (x+y+z)^2=241+(2*100)   (x+y+z)^2=441   so x+y+z=21   ANSWER:21
<result>C</result>
The sum of the squares of three numbers is 241, while the sum of their products taken two at a time is 100. Their sum is: