if 6 coins are tossed simultaneously what is the probability of getting atleast four heads	Pick.
A) 11/32 B) 12/32 C) 13/32 D) 15/32 E) 19/32
n(S)= 2^6= 64   n(E)= 6C4 + 6C5 + 6C6 = 15+6+1= 
<gadget id="calculator">15+6+1</gadget>
<output>22</output>
22   p(E)= n(E)/n(S)= 22/64= 11/32   11/32NSWER:11/32
<result>A</result>
if 6 coins are tossed simultaneously what is the probability of getting atleast four heads