Which of the following CANNOT be the median of the 3 positive integers x, y, and z?  Select
A) x
B) z
C) x+z
D) (x+z)/2
E) (x+z)/3
The median of a set with odd number of terms is justa middle term, so it's x, y or z. Eliminate A and B right away. Now, the median can also be (x+z)/2 and (x+z)/3 (for example: {1, 2, 3} and {1, 2, 5}).   But since x, y, and z arepositiveintegers then it no way can be x+z. Why? Because a middle term (the median) cannot possibly be greater than two terms (x and z) in a set with 3 terms.   Answer: x+z.
<result>C</result>
Which of the following CANNOT be the median of the 3 positive integers x, y, and z?