How many different positive integers can be formed using each digit in the set {0,1,3,3,3,7,8} exactly once?(Naturally, the number can't begin with 0)
.  Pick.
A) 160	B) 720	C) 1440	D) 4320	E) 5040
Since the first number can't be 0, then there are only 6 possible numbers than there could be. Then the following 6 number are a regular permutation, with 3 of the elements being the same   Number of integers will be 6*6!/3!= 720   ANS:720
<result>B</result>
How many different positive integers can be formed using each digit in the set {0,1,3,3,3,7,8} exactly once?(Naturally, the number can't begin with 0)
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