A, B, C, D and E play a game of cards. A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has." A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?  Pick one:	A) 22	B) 23	C) 25	D) 35	E) 30
Explanation:   Clearly, we have :   B-3 = E ...(i)   B + 3 = D ...(ii)   A+B = D + E+10 ...(iii)   B = C + 2 ...(iv)   A+B + C + D + E= 133 ...(v)   From (i) and (ii), we have : 2 B = D + E ...(vi)   From (iii) and (vi), we have : A = B + 10 ...(vii)   Using (iv), (vi) and (vii) in (v), we get:   (B + 10) + B + (B - 2) + 2B = 133 =&gt; 5B = 125=&gt; B = 25.   ANSWER IS 25
<result>C</result>
A, B, C, D and E play a game of cards. A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has." A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?