20 balls are numbered 1 to 20. A ball is drawn and then another ball is drawn without replacement. What is the probability that both balls have even numbers?	Choose the correct option:
A) 7/30
B) 3/14
C) 9/38
D) 4/21
E) 5/26
P(1st ball is even) = 10/20   P(2nd ball is also even) = 9/19   P(both balls are even) = 10/20 * 9/19 = 9/38   The answer is 9/38.
<result>C</result>
20 balls are numbered 1 to 20. A ball is drawn and then another ball is drawn without replacement. What is the probability that both balls have even numbers?