The sum of the squares of two consecutive positive integers exceeds their product by 91. Find the integers?	Choose one:
A) 6,5	B) 5,8	C) 2,3	D) 9,8	E) 9,10
Explanation:   Let the two consecutive positive integers be x and x + 1   x2 + (x + 1)2 - x(x + 1) = 91   x2 + x - 90 = 0   (x + 10)(x - 9) = 0 =&gt; x = -10 or 9.   As x is positive x = 9   Hence the two consecutive positive integers are 9 and 10.   Answer 9,10
<result>E</result>
The sum of the squares of two consecutive positive integers exceeds their product by 91. Find the integers?