What values of 'x' will be the solution to the inequality 15x - 2/x > 1?  Choices:
A) x > 0.4  B) x < 1/3  C) -1/3 < x < 0.4, x > 15/2  D) -1/3 < x < 0, x > 2/5  E) x < --1/3 or x > 2/5
Explanatory Answer   We can rewrite the above inequality as 15x - 2/x- 1 &gt; 0   i.e., 15x2−2−x/x&gt; 0   i.e., 15x2−6x+5x−2/x&gt; 0   Factorize the quadratic expression: (5x−2)(3x+1)/x &gt; 0   The above inequality will hold good if the numerator and denominator are both positive or are both negative.   Possibility 1: When (5x - 2)(3x + 1) &gt; 0 and x &gt; 0   This will hold true for values of 'x' that do not lie between -1/3 and 2/5 and for x &gt; 0.   Combining all these conditions, we get x &gt; 2/5   Possibility 2: When (5x - 2)(3x + 1) &lt; 0 and x &lt; 0.   This will hold true for the following values of 'x': -1/3 &lt; x &lt; 2/5 and x &lt; 0.   Combining, we get -1/3&lt; x &lt; 0.   Therefore, the range of values of x for which the above inequality will hold true is: -1/3 &lt; x &lt; 0 ∪∪ x &gt; 2/5   Choice -1/3 &lt; x &lt; 0, x &gt; 2/5
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What values of 'x' will be the solution to the inequality 15x - 2/x > 1?