Father is aged three times more than his son Suresh. After 8 years, he would be two and a half times of Suresh's age. After further 8 years, how many times would he be of Suresh's age? Options: A) 2 times B) 2.(1/2)times C) 2(3/4) times D) 3 times E) 4 times
F=4s   F+8 = 2.5(S+*0   solving these, F =32, S=8   After further 8 yrs,   F= 32+8+8= 
<gadget id="calculator">32+8+8</gadget>
<output>48</output>
48   S=8+8+8= 
<gadget id="calculator">8+8+8</gadget>
<output>24</output>
24 yrs   so 2 times.   2 timesNSWER:2 times
<result>A</result>
Father is aged three times more than his son Suresh. After 8 years, he would be two and a half times of Suresh's age. After further 8 years, how many times would he be of Suresh's age?