The perimeter of a rectangle is 44. The length is 5 less than double the width.
Find the dimensions Choose the correct choice: A) 6 by 10 B) 7 by 11 C) 8 by 12 D) 9 by 13 E) 10 by 14
Length x Wewillmake the length x   Width 2x−5 Width is five less than two times the length   P =2L+2W The formula for perimeter of a rectangle   (44)=2(x)+2(2x−5) Replace P , L, andW with labeled values   44=2x+4x−10 Distribute through parenthesis   44=6x−10 Combine like terms 2x+4x   +10 +10 Add 10 to both sides   54=6x The variable ismultiplied by 6   6 6 Divide both sides by 6   9=x Our solution for x   Length 9 Replace xwith 9 in the origional list of sides   Width 2(9)−5=13 The dimensions of the rectangle are 9 by 13.   correct answer 9 by 13
<result>D</result>
The perimeter of a rectangle is 44. The length is 5 less than double the width.
Find the dimensions