A tank holds x gallons of a saltwater solution that is 20% salt by volume. One Fourth of the water is evaporated, leaving all of the salt. When 20 Gallons of water and 40 gallons of salt are added, the resulting mixture is 33 1/3 % salt by volume. What is the value of x?  Choose the correct choice from the following choices:  A) 300  B) 75  C) 100  D) 150  E) 175
Nope, 150. I can only get it by following PR's backsolving explanation. I hate that.   Original mixture has 20% salt and 80% water.   Total = x   Out of which Salt = 0.2x and water = 0.8x   Now, 1/4 water evaporates and all salt remains.   So what remains is 0.2x salt and 0.6x water.   Now 40 gallons salt is added and 20 gallons of water is added.   So salt now becomes -&gt; (0.2x + 40) and water --&gt; (0.6x+20)   Amount of salt is 33.33% of total. So amount of water is 66.66%. So salt is half of the volume of water.   So (0.2x+40) = (0.6x+20)/2 =&gt; 0.4x+80 =0.6x+20 =&gt;0.2x =60   Solving, x = 300   300nswer : 300
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A tank holds x gallons of a saltwater solution that is 20% salt by volume. One Fourth of the water is evaporated, leaving all of the salt. When 20 Gallons of water and 40 gallons of salt are added, the resulting mixture is 33 1/3 % salt by volume. What is the value of x?