Find the numbers which are in the ratio 3:2:3 such that the sum of the first and the second added to the difference of the third and the second is 24?  Choose the correct choice
A) 4,3,22	B) 4,4,22	C) 9,3,32	D) 9,6,12	E) 18,12,18
Let the numbers be a, b and c.   a:b:c = 3:2:3   Given, (a + b) + (c - b) = 24   =&gt; a + c = 24   =&gt; 3x + 3x = 24 =&gt; x = 6   a, b, c are 3x, 2x, 3x   a, b, c are 18, 12, 18.   Answer:18,12,18
<result>E</result>
Find the numbers which are in the ratio 3:2:3 such that the sum of the first and the second added to the difference of the third and the second is 24?