In a box, there are 7 red, 3 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green? Pick.
A) 2/3	B) 8/21	C) 3/7	D) 7/15	E) 10/21
Explanation:   Total number of balls = (7 + 3 + 5)= 
<gadget id="calculator">(7 + 3 + 5)</gadget>
<output>15</output>
15.   Let E= event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.   Therefore, n(E) = 7.   P(E) = 7/15.   Answer: Option 7/15
<result>D</result>
In a box, there are 7 red, 3 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?