In the xy-coordinate system, if (m, n) and (m + 2, n + k) are two points on the line with the equation x = 2y + 3, then k = Options.
A) 1/2 B) 1 C) 2 D) 5/2 E) 4
Since (m, n) and (m + 2, n + k) are two points on the line with the equation x = 2y + 5 they should satisfy m=2n +3 and m+2= 
<gadget id="calculator">+2</gadget>
<output>2</output>
2 *(n+k)+3.   By 1st equation we have m-2n=3 and by 2nd equation m-2n = 2k+1 ---&gt;3 =2k+1 ---&gt;k=1.   The answer is, therefore, (1).
<result>B</result>
In the xy-coordinate system, if (m, n) and (m + 2, n + k) are two points on the line with the equation x = 2y + 3, then k =