In a room with 10 people, 6 people have exactly 1 friend in the room and 5 people have exactly 2 friends in the room (Assuming that friendship is a mutual relationship, i.e. if Jane is Paul's friend, Paul is Jane's friend). If two individuals are selected from the room at random, what is the probability that those two individuals are NOT friends?	Choose the correct choice from the following answers:	A) 5/21	B) 3/7	C) 4/5	D) 5/7	E) 16/21
(6/10)(7/9) + (5/10)(6/9) if you choose one of the 6 with one other friend, then you have a 7/9 chance of not picking their friend 2nd. If you choose one of the 5 with 2 friends, you have a 6/9 chance of not picking one of their friends second. Add them up.   42/90 + 30/90   72/90 = 4/5   C. 4/5
<result>C</result>
In a room with 10 people, 6 people have exactly 1 friend in the room and 5 people have exactly 2 friends in the room (Assuming that friendship is a mutual relationship, i.e. if Jane is Paul's friend, Paul is Jane's friend). If two individuals are selected from the room at random, what is the probability that those two individuals are NOT friends?