About the number of pairs which have 18 as their HCF and 136 as their LCM, the conclusion can be  Options:
A) only one such pair exists
B) only two such pairs exist
C) such pair is not exists
D) no pairs
E) None of these
Explanation:   HCF is always a factor of LCM. ie., HCF always divides LCM perfectly.   such pair is not existsorrect Option: such pair is not exists
<result>C</result>
About the number of pairs which have 18 as their HCF and 136 as their LCM, the conclusion can be