In how many ways can 5 boys be allotted four different COTs such that none of the COTs are empty and all the 5 boys are accommodated?
Choose the correct answer.
A) 240  B) 260  C) 280  D) 290  E) 300
4 boys can be selected from 5 boys in 5C4 ways = 5   4 boys can be arranged in 4 COTS in 4! ways   and since 1 boy has to share a COT with one of the 4 boys, therefore total ways = 2! = 2   Hence total number of ways in which allocation can be done = 5C4 * 4! * 2! = 5*2*4!   240   240
<result>A</result>
In how many ways can 5 boys be allotted four different COTs such that none of the COTs are empty and all the 5 boys are accommodated?