Meg and Bob are among the 5 participants in a cycling race. If each participant finishes the race and no two participants finish at the same time, in how many different possible orders can the participants finish the race so that Meg finishes ahead of Bob?  Choose the correct choice from the following answers
A) 24
B) 30
C) 60
D) 90
E) 120
Let me redeem myself:   JXXXX =&gt; Bob can be in any X...Total 4! = 24   XJXXX =&gt; Bob can be in the last 3 Xs...Total 3! = 6. However, since the first person can change too and it cannot be Bob, it can only be 3 other people. So Total = 6*3= 
<gadget id="calculator">6*3</gadget>
<output>18</output>
18   XXJBX=&gt; 3! = 6 total   XXJXB =&gt; 3! = 6 total   So this yields total of 12   XXXJB =&gt; 3! = 6   Ans = 24+18+12+6= 
<gadget id="calculator">24+18+12+6</gadget>
<output>60</output>
60   answer is 60
<result>C</result>
Meg and Bob are among the 5 participants in a cycling race. If each participant finishes the race and no two participants finish at the same time, in how many different possible orders can the participants finish the race so that Meg finishes ahead of Bob?