In how many ways can 7 distinct objects be divided among three people so that either one or two of them do not get any object?	Choices.
A) 281
B) 304
C) 316
D) 381
E) 391
Case 1: Two guys don't get anything. All items go to 1 person. Hence, 3 ways.   Case 2: 1 guy doesn't get anything. Division of 7 items among 2 guys. Lets say they are called A &amp; B.   a) A gets 6. B gets 1. 7 ways.   b) A gets 5. B gets 2. 21 ways.   c) A gets 4. B gets 3. 35 ways.   d) A gets 3. B gets 4. 35 ways.   e) A gets 2. B gets 5. 21 ways.   f) A gets 1. B gets 6. 7 ways.   Total = 126 ways to divide 7 items between A &amp; B.   Total number of ways for case 2 = 126*3= 
<gadget id="calculator">126*3</gadget>
<output>378</output>
378 (Either A, or B, or C don't get anything).   Answer= Case 1 + Case 2 = 3 + 378= 
<gadget id="calculator">3 + 378</gadget>
<output>381</output>
381   ANSWER:381
<result>D</result>
In how many ways can 7 distinct objects be divided among three people so that either one or two of them do not get any object?