If x and y are numbers such that (x+6)(y-6)=0, what is the smallest possible value of x^2 + y^2	Choose the correct answer:
A) 0  B) 16  C) 25  D) 36  E) 49
From (x+6)(y-6)=0 it follows that either x=-6 or y=6. Thus either x^2=36 or y^2=36.   Now, if x^2=36, then the least value of y^2 is 0, so the least value of x^2 + y^2 = 36 + 0= 
<gadget id="calculator">36 + 0</gadget>
<output>36</output>
36.   Similarly if y^2=36, then the least value of x^2 is 0, so the least value of x^2 + y^2 = 0 + 36= 
<gadget id="calculator">0 + 36</gadget>
<output>36</output>
36.   Answer: 36.
<result>D</result>
If x and y are numbers such that (x+6)(y-6)=0, what is the smallest possible value of x^2 + y^2