What is the greatest of 3 consecutive integers whose sum is 33 ?
Pick.
A) 12
B) 7
C) 8
D) 9
E) 5
The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3   If the sum is 24, we need to solve the equation 3n + 3 + (  + 1) + (  + 2)= 
<gadget id="calculator">+ (  + 1) + (  + 2)</gadget>
<output>3</output>
3n + 3   If the sum is 24, we need to solve the equation 3n + 3= 33;   =&gt; 3n = 30;   =&gt; n = 10   The greatest of the three numbers is therefore   10+ 2= 
<gadget id="calculator">  10+ 2</gadget>
<output>12</output>
12 12nswer: 12
<result>A</result>
What is the greatest of 3 consecutive integers whose sum is 33 ?