A coin is tossed 7 times. Find the probability of getting more heads than tails in all 7 tosses? Options:  A) 1/2  B) 63/128  C) 4/7  D) 61/256  E) 63/64
Assuming the coin is fair - P(H)=P(T)=1/2   We can do as proposed by the explanation in your initial post:   Total outcomes: 2^7   Favorable outcomes:   4 heads --&gt; combination of HHHHTTT --&gt; 7!/(4!*3!)=35 (# of permutation of 7 letters out of which 4 H's and 3 T's are identical);   5 heads --&gt; combination of HHHHHTT --&gt; 7!/(5!*2!)=21;   6 heads --&gt; combination of HHHHHHT --&gt; 7!/(6!*1!)=7;   7 heads --&gt; combination of HHHHHHH --&gt; 1;   P(H&gt;T)=Favorable outcomes/Total outcomes=(35+21+7+1)/2^7=1/2.   1/2nswer:1/2
<result>A</result>
A coin is tossed 7 times. Find the probability of getting more heads than tails in all 7 tosses?