A group of three women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?	Choices
A) 7! – 2!3!2!	B) 6! – 4!3!	C) 7! – 5!3!	D) 7 × 2!3!2!	E) 2!3!2!
6 people can sit in 6! different ways. But because 3 men cannot sit together, we take them as a unit.   This unit of men, among themselves can sit in 3! ways.   Hence, 6! - 3!.   This unit of men along with3 women can sit in 4! different ways which also needs to be eliminated.   Hence 6! - 4!3!   6! – 4!3!
<result>B</result>
A group of three women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?