Four kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?	Answers
A) 4.9	B) 4.8	C) 2.5	D) 2	E) 0.2
Four kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?   (A) 4.9   (B) 4.8   (C) 2.5   (D) 2   (E) 0.2   If D is the answer, then the question means that the concentration of water the newt day became 96%.   Out of 4 kilograms 98%, or 3.92 kilograms was water and 0.08 kilograms was non-water.   The next day, after some water evaporated, oranges became 96% water and 4% of non-water, so the next day 0.08 kilograms of non-water composed 4% of oranges, which means that the new weight of the oranges was x*0.04=0.08 --&gt; x=2 kilograms.   Answer:2.
<result>D</result>
Four kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?