If 6000209× 6111209× K^20 is divisible by 3, which of the following could be the value of K? Options.
A) 6000209 B) 6111209 C) 6123309 D) 6111109 E) 6111309
The first two terms are not divisible by 3, so we need the third term to be divisible by 3. The only way that (k^2) is going to be a multiple of 3 is if k is a multiple of 3. Therefore, we need the single answer that is a multiple of 3.   Answer =(6111309)
<result>E</result>
If 6000209× 6111209× K^20 is divisible by 3, which of the following could be the value of K?