If X is to be chosen at random from the integers between 1 to 6, inclusive, and Y is to be chosen at random from the integers between 7 and 11, inclusive, what is the probability that X + Y will be even?
Choices.
A) 1/2	B) 2/3	C) 3/4	D) 4/5	E) 5/6
X+Y will be even if X and Y are both even or both odd.   P(X and Y are both even) = 3/6*2/5 = 1/5   P(X and Y are both odd) = 3/6*3/5 = 3/10   P(X+Y is even) = 1/5 + 3/10 = 1/2   The answer is 1/2.
<result>A</result>
If X is to be chosen at random from the integers between 1 to 6, inclusive, and Y is to be chosen at random from the integers between 7 and 11, inclusive, what is the probability that X + Y will be even?