How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and if the repetition is allowed? Choose the correct choice from the following
A) 20	B) 5	C) 10	D) 36	E) 25
Since, each desired number is divisible by 5, so we must have 5 at the unit place.   So , the tens place can now be filled by any of the remaining 6 digits (2, 3, 6, 7, 9, 5)   therefore the 3-digit no can be formed by   (6 * 6 * 1)= 
<gadget id="calculator">  (6 * 6 * 1)</gadget>
<output>36</output>
36 ways ------(since repetition is allowed)   Ans- 36
<result>D</result>
How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and if the repetition is allowed?