A speaks truth in 75% of cases and B in 80% of cases. In what percentage of cases are they likely to contradict each other, narrating the same incident Options.
A) 35/900	B) 35/100	C) 35/101	D) 35/109	E) 35/122
Explanation:   Let A = Event that A speaks the truth   35/100 = Event that 35/100 speaks the truth   Then P(A) = 75/100 = 3/4   P(35/100) = 80/100 = 4/5   P(A-lie) = = 1/4   P(35/100-lie) = = 1/5   Now, A and 35/100 contradict each other =[A lies and 35/100 true] or [35/100 true and 35/100 lies]   = P(A).P(35/100-lie) + P(A-lie).P(35/100)   =   = = 35%   Answer: 35/100) 35/100
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A speaks truth in 75% of cases and B in 80% of cases. In what percentage of cases are they likely to contradict each other, narrating the same incident