The arithmetic mean of the set S = {7, K, 6, 12, M, 7} is 8. If K and M are integers, and K ≠ M, what is the median of the numbers in the set?
Answers:
A) 6	B) 6.5	C) 7	D) 7.5	E) 8
The sum of the numbers is 6*8= 
<gadget id="calculator">6*8</gadget>
<output>48</output>
48   K+M= 48 - 12 - 7 - 7 - 6= 
<gadget id="calculator">48 - 12 - 7 - 7 - 6</gadget>
<output>16</output>
16   Since K ≠ M, K and M do not equal 8.   Thus one of the two numbers is 7 or less and one is 9 or more.   Then middle two numbers in the set are 7 and 7.   The median is 7.   The answer is 7.
<result>C</result>
The arithmetic mean of the set S = {7, K, 6, 12, M, 7} is 8. If K and M are integers, and K ≠ M, what is the median of the numbers in the set?