A thief steels a car at 6a.m. and drives it at 40kmph. The theft is discovered at 7a.m. and the owner sets off in another car at 60 kmph. When will he overtake the thief?
Options
A) 9a.m.	B) 9.30a.m.	C) 10a.m.	D) 11.45a.m.	E) 10.15a.m.
Suppose the thief overtakes x hours after 6a.m.   Distance covered by the thief in x hrs = distance covered by the owner in (x-1 hours)   40x = 60(x-1)   20x = 60   x = 3 hrs   Thief is overtaken at 9 a.m.   9a.m.nswer is 9a.m.
<result>A</result>
A thief steels a car at 6a.m. and drives it at 40kmph. The theft is discovered at 7a.m. and the owner sets off in another car at 60 kmph. When will he overtake the thief?