A shipment of 250 smartphones contains 76 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?
Select the correct option.
A) 1/250	B) 1/84	C) 1/11	D) 1/9	E) 1/3
Probability of chosing one defective phone from a lot of 250 which ontains 76 defective phones is = (76/250)   Probability of chosing one defective phone from a lot of 249(we already picked one) which ontains 75(we already picked one) defective phones is = (75/249)   1/11ombined probability of series of events = product of the probabilities = (76/250)*(75/249)   76/250 is close to (7/23) and (75/249)= (25/83)   so answer is (7/23)*(25/83) = (1/11)   So, answer will be 1/11
<result>C</result>
A shipment of 250 smartphones contains 76 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?