Ages of two persons differ by 18 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age  Pick one:  A) 12,28  B) 15,33  C) 16,32  D) 18,34  E) 19,34
Explanation:   Let the age of younger person is x,   Then elder person age is (x+18)   =&gt; 3(x-6) = (x+18-6) [6 years before]   =&gt; 3x-18 = x+12   =&gt; x = 15.   So other person age is x + 18 = 33   Answer: Option 15,33
<result>B</result>
Ages of two persons differ by 18 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age