Gita, Hussain, Inge, Jeong, Karen, and Leila are seated in a row of six chairs. How many seating arrangements are possible if Gita cannot sit next to Inge and Jeong must sit next to Leila?  Options
A) 288	B) 240	C) 144	D) 120	E) 96
taking he initials of each for reference... Since, J and L have to be together, lets combine them into 1. So, now we have 5 things which can be arranged in 5! ways. ALso, J and L can be arranged in two ways (JL, LJ) .   This gives total ways, 5! * 2 = 240   Now, we are given G and I can not be together, therefore subtract the cases when they (G and I) are together. Now, see we have 4 people (JL and GI) are combined as one. Total no of arrangement = 4!   But, J and L can be arranged internally in 2 ways (JL and LJ). Similarly, G and I can be internally arranged in two ways (GI and IG).   Therefore, total such cases will be 4! * 2 * 2 = 96. Subtract this from 240.   240 - 96= 
<gadget id="calculator">240 - 96</gadget>
<output>144</output>
144. Hence, 144
<result>C</result>
Gita, Hussain, Inge, Jeong, Karen, and Leila are seated in a row of six chairs. How many seating arrangements are possible if Gita cannot sit next to Inge and Jeong must sit next to Leila?