Four faces of a fair die are Yellow, two faces red and one blue.The die is tossed three
times. The probability that the colours, yellow, red and blue appear in the first, second and
third tosses respectively is	Choose the correct answer:
A) 1/36
B) 1/18
C) 1/32
D) 1/27
E) None of these
Probability of getting yellow color = P(Y) = 4/6 = 2/3   Probability of getting red color = P(R) = 2/6 = 1/3   Probability of getting blue color = P(B) = 1/6   So, the probability that the colors yellow, red and blue appear in first, second and third toss respectively= P(Y ∩ R ∩ B) = P(Y) x P(R) x P(B) = 2/3 x 1/3 x 1/6 = 1/27   ANSWER:1/27
<result>D</result>
Four faces of a fair die are Yellow, two faces red and one blue.The die is tossed three
times. The probability that the colours, yellow, red and blue appear in the first, second and
third tosses respectively is