A shipment of 240 smartphones contains 84 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?  Choices.
A) 1/250	B) 9/74	C) 1/11	D) 1/9	E) 1/3
Probability of chosing one defective phone from a lot of 240 which ontains 84 defective phones is = (84/240)   Probability of chosing one defective phone from a lot of 239(we already picked one) which ontains 83(we already picked one) defective phones is = (83/239)   Combined probability of series of events = product of the probabilities = (84/240)*(83/239)   84/240 is close to (7/20) and (83/239)= (25/72)   so answer is (7/20)*(25/72) (9/74)   So, answer will be 9/74
<result>B</result>
A shipment of 240 smartphones contains 84 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?