What is the area inscribed by the lines y =2, x = 2, y = 10-x on an xy-coordinate plane?	Choose the correct choice from the following answers:
A) a) 8
B) b) 10
C) c) 12
D) d) 14
E) e) 18
First, let's graph the lines y = 2 and x = 2   At this point, we need to find the points where the line y = 10-x INTERSECTS the other two lines.   For the vertical line, we know that x = 2, so we'll PLUG x = 2 into the equation y = 10-x to get y = 10-2= 
<gadget id="calculator">10-2</gadget>
<output>8</output>
8   Perfect, when x= 2, y = 8, so one point of intersection is (2,8)   For the horizontal line, we know that y = 2, so we'll PLUG y = 2 into the equation y = 10-x to get 2 = 10-x. Solve to get: x = 8   So, when y = 2, x = 8, so one point of intersection is (8,2)   Now add these points to our graph and sketch the line y = 10-x   At this point, we can see that we have the following triangle.   The base has length 6 and the height is 6   Area = (1/2)(base)(height)   = (1/2)(6)(6)   = 18   Answer:   e) 18
<result>E</result>
What is the area inscribed by the lines y =2, x = 2, y = 10-x on an xy-coordinate plane?