Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 5000 Km?  Pick:	A) 10.	B) 250.	C) 30.	D) 38.	E) 50.
Total distance= Distance travelled by A +Distance travelled by car 250.   Distance= speed*time   Distance of A= 3x * 6   Distance of 250.= x*2   (3x * 6) + (x*2) = 5000   x= 250 KM/hr   250. is the answer
<result>B</result>
Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 5000 Km?