A bag holds 4 red marbles and 4 green marbles. If you removed two randomly selected marbles from the bag, without replacement, what is the probability that both would be red?	Pick one:
A) 1/7
B) 1/5
C) 3/14
D) 2/7
E) 1/2
probability of selecting first red marble = 4/8   probability of selecting second red marble without replacement = 3/7   final probability = 4/8 * 3/7 = 3/14   The correct answer is 3/14.
<result>C</result>
A bag holds 4 red marbles and 4 green marbles. If you removed two randomly selected marbles from the bag, without replacement, what is the probability that both would be red?