There are 8 girls and 8 boys. If they are to be seated in a row, what is the probability that no two girls sit together?
Select:
A) A)1/16!
B) B)6!5!/16!
C) C)6!6!/16!
D) D)2∗8!8!/16!
E) E)6!7!/12!
If girls are alternate, then only no 2 girls can be together.   So among 16 places, girls can be seated in 8 alternate places in 8! ways.   And boys can be seated in the remaining 8 places in 8! ways.   Therefore total number of ways = 8! * 8!   But there could be 2 such arrangements--&gt;   1. When first place is filled by a girl   2. When first place is filled by a boy   Therefore total number of ways = 2*8! * 8!   Also total number of ways to fill 16 places = 16!   Hence probability =2∗8!8!/16!   Answer:2∗8!8!/16!
<result>D</result>
There are 8 girls and 8 boys. If they are to be seated in a row, what is the probability that no two girls sit together?