What is the sum of the integers from -160 to 162, inclusive? Choose the correct answer:  A) 325  B) 327  C) 323  D) 330  E) 350
In an arithmetic progression,   the nth term is given by tn=a+(n-1)d   here tn=162, a=-160, d=1   hence, 162=-160+(n-1)   or n=323   Sum of n terms can be calculated by sn=n/2(a+l)   a=first term, l=last term, n=no. of terms   sn=323*(-160+162)/2= 
<gadget id="calculator">323*(-160+162)/2</gadget>
<output>323</output>
323*2/2= 
<gadget id="calculator">323*2/2</gadget>
<output>323</output>
323   Answer : 323
<result>C</result>
What is the sum of the integers from -160 to 162, inclusive?