A committee has 5 men and 6 women. What are the number of ways of selecting 3 men and 2 women from the given committee?	Choose the correct choice:
A) 150
B) 200
C) 250
D) 300
E) 350
The number of ways to select three men and two women = 5C3 * 6C2 = 10 * 15= 
<gadget id="calculator">10 * 15</gadget>
<output>150</output>
150   The answer is 150.
<result>A</result>
A committee has 5 men and 6 women. What are the number of ways of selecting 3 men and 2 women from the given committee?