The area of one square is x^2 + 10x + 25 and the area of another square is x^2 − 6x + 9. If the sum of the perimeters of both squares is 32, what is the value of x? Answers:
A) 3
B) 2
C) 2.5
D) 4.67
E) 10
spotting the pattern of equations both are in form of (X+C)^2 so   31= (x+5)^232= (x-3)^2   L1= x+5L2= -3   P1 = 4( x+5)P2=4(x-3)   P1+P2=32   4( x+5) +4(x-3)=32.....3   3ns :3
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The area of one square is x^2 + 10x + 25 and the area of another square is x^2 − 6x + 9. If the sum of the perimeters of both squares is 32, what is the value of x?