What is the sum of the digits of integer k, if k = (10^30- 36)
Options:
A) 251
B) 260
C) 263
D) 269
E) 262
There are 31 digits in 10^30   When we subtract 36 from it, there will be 30 digits left.   10^30 can be written as 9999999....(30 times) + 1   So,   10^30 - 36 = 9999999....(30 times) + 1 - 36 = 9999999....(30 times) -35   Consider the last 2 digits,   99-35= 
<gadget id="calculator">99-35</gadget>
<output>64</output>
64   The last 2 digits will be 64.   And our number would be 99999......99964 with 2 less 9s after subtraction.   Number of 9s left are 28 and the last two digits are 64   The sum of the digits will be     (28*9) + 6 + 4= 
<gadget id="calculator">  (28*9) + 6 + 4</gadget>
<output>262</output>
262   Answer:- 262
<result>E</result>
What is the sum of the digits of integer k, if k = (10^30- 36)