A division of a company consists of four men and eight women. If two of these twelve employees are randomly selected as representatives of the division, what is the probability that both representatives will be female?  Pick one:
A) 7/11	B) 7/33	C) 14/33	D) 7/66	E) 14/66
The total number of ways to choose two representatives is 12C2=66.   The number of ways to choose two females is 8C2=28.   P(choosing two female representatives)=28/66=14/33   The answer is 14/33.
<result>C</result>
A division of a company consists of four men and eight women. If two of these twelve employees are randomly selected as representatives of the division, what is the probability that both representatives will be female?