The area of one square is x^2 + 10x + 25 and the area of another square is 4x^2 − 20x + 25. If the sum of the perimeters of both squares is 36, what is the value of x?  Choose the correct choice from the following answers:	A) 3	B) 5	C) 7	D) 9	E) 11
The areas are (x+5)^2 and (2x-5)^2.   The lengths of the sides are x+5 and 2x-5.   If we add the two perimeters:   4(x+5) + 4(2x-5) = 36   12x = 36   x = 3   The answer is 3.
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The area of one square is x^2 + 10x + 25 and the area of another square is 4x^2 − 20x + 25. If the sum of the perimeters of both squares is 36, what is the value of x?