In how many ways can 5 boys be allotted four different wadrobe such that none of the wadrobe are empty and all the 5 boys are accommodated?	Select:
A) 300	B) 290	C) 240	D) 260	E) 280
4 boys can be selected from 5 boys in 52404 ways = 5   4 boys can be arranged in 4 rooms in 4! ways   and since 1 boy has to share a room with one of the 4 boys, therefore total ways = 2! = 2   Hence total number of ways in which allocation can be done = 52404 * 4! * 2! = 5*2*4! =240   240
<result>C</result>
In how many ways can 5 boys be allotted four different wadrobe such that none of the wadrobe are empty and all the 5 boys are accommodated?