A man walking at a constant rate of 6 miles per hour is passed by a woman traveling in the same direction along the same path at a constant rate of 12 miles per hour. The woman stops to wait for the man 10 minutes after passing him, while the man continues to walk at his constant rate. How many minutes must the woman wait until the man catches up?	Choices:
A) 5 B) 15 C) 10 D) 20 E) 25
When the woman passes the man, they are aligned (m and w). They are moving in the same direction. After 5 minutes, the woman (W) will be ahead the man (M):   m------M---------------W   w   In the 5 minutes, after passing the man, the woman walks the distance mW = wW, which is  10*12/60= 
<gadget id="calculator"> 10*12/60</gadget>
<output>2</output>
2 miles and the man walks the distance mM, which is  10*6/60= 
<gadget id="calculator"> 10*6/60</gadget>
<output>1</output>
1 mile.   The difference of 2 - 1= 
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
1 miles (MW) will be covered by the man in (1)/6= 1/6 of an hour, which is 10 minutes.   Answer 10.
<result>C</result>
A man walking at a constant rate of 6 miles per hour is passed by a woman traveling in the same direction along the same path at a constant rate of 12 miles per hour. The woman stops to wait for the man 10 minutes after passing him, while the man continues to walk at his constant rate. How many minutes must the woman wait until the man catches up?