The volume of the sphere QQ is (dfrac{37}{64}%)less than the volume of sphere PP and the volume of sphere RR is (dfrac{19}{27}%) less than that of sphere QQ. By what is the surface areaof sphere RR less than the surfacearea of sphere PP?  Options:
A) 56%	B) 68%	C) 75%	D) 85%	E) 95%
Let the volume of sphere PP be 64 parts.   Therefore volume of sphere QQ   =64−3764%=64−3764% of 6464   =64−37=27=64−37=27 parts.   The volume of RR   =27−1927×27=27−1927×27   =27−19=8=27−19=8 parts.   Volume ratio:   =P:Q:R=64:27:8=P:Q:R=64:27:8   Radius ratio:   =P:Q:R=4:3:2=P:Q:R=4:3:2   The surface area will be 16:9:516:9:5   Surface area of RR is less than the surface area of sphere PP   16k−4k=12k16k−4k=12k   Now,   =12k16k×100=12k16k×100   =75%=75%   Thus surface area of sphere RR is less than the surface area of sphere P by 75%   75%
<result>C</result>
The volume of the sphere QQ is (dfrac{37}{64}%)less than the volume of sphere PP and the volume of sphere RR is (dfrac{19}{27}%) less than that of sphere QQ. By what is the surface areaof sphere RR less than the surfacearea of sphere PP?