The probability that B can shoot a target 3 out of 3 times is 0.25. What is the probability that the target will be missed by B immediately after such two shots? Pick one:	A) 0.25	B) 0.5	C) 0.4	D) 0.75	E) 0.8
Suppose there are total 'x' shots.   B shoots 3 out of 3 times. means out of x shots (x&gt;3)   therefore, 3/x = 0.25 (given)   the target will be missed by B immediately after such two shots : this means he can shot just twice ...the third shot cannot happen which means he missed (x-3) shots.   thus, the probabilty of missing just after 2 shots is (x-3)/x.   (x-3)/x = 1 - 3/x   = 1 - 0.25= 
<gadget id="calculator">1 - 0.25</gadget>
<output>0.75</output>
0.75   Answer : 0.75
<result>D</result>
The probability that B can shoot a target 3 out of 3 times is 0.25. What is the probability that the target will be missed by B immediately after such two shots?