In March, Kurt ran an average of 2 miles an hour. If by June he had increased his pace by 10 seconds per mile, then which of the following expresses the number of hours it would take Kurt to complete one mile in June? Options.
A) 3590/60^2
B) 2410/60^2
C) 1790/60^2
D) 3586/60
E) 60^2/3590
Kurt ran at an average of 2 miles/hour in march. So to run 1 mile he would take 1/2 hours = (60 * 60)/2= 
<gadget id="calculator">(60 * 60)/2</gadget>
<output>1_800</output>
1800 seconds.   If he increases his speed by 10 seconds, he will complete a mile in 1790 seconds. 1790/60^2onverting in hours= 1790/(60 * 60) = 1790/(60^2)   ANSWER: 1790/60^2
<result>C</result>
In March, Kurt ran an average of 2 miles an hour. If by June he had increased his pace by 10 seconds per mile, then which of the following expresses the number of hours it would take Kurt to complete one mile in June?