There are 2 bars of gold-silver alloy; one piece has 2 parts of gold to 3 parts of silver and another has 3 parts of gold to 7 parts of silver. If both bars are melted into 8 kg bar with the final gold to silver ratio of 5:11. What was the weight of the first bar?  Choose the correct choice
A) 1 kg
B) 3 kg
C) 5 kg
D) 6 kg
E) 7 kg
irst bar is x kg, then second bar is (8-x)kg   First bar:   1 kgmt of gold = 2x/5kg   1 kgmt of silver = 3x/5 kg   Second bar:   1 kgmt of gold = 3(8-x)/10 kg   1 kgmt of silver = 7(8-x)/10 kg   Total amt of gold = 2x/5 + 3(8-x)/10 = (4x+24-3x)/10 = (x+24)/10 kg   Total amt of silver = 3x/5 + 7(8-x)/10 = (6x+56-7x)/10 = (56-x)/10 kg   Ratio of gold/silver = 5/11 = (x+24)/10 * 10/(56-x)   5/11 = (x+24)/(56-x)   5(56-x) = (x+24)(11)   x = 1kg   1 kgNSWER:1 kg
<result>A</result>
There are 2 bars of gold-silver alloy; one piece has 2 parts of gold to 3 parts of silver and another has 3 parts of gold to 7 parts of silver. If both bars are melted into 8 kg bar with the final gold to silver ratio of 5:11. What was the weight of the first bar?