A feed shop sells two varieties of birdseed: Product A, which is 40% millet and 60% sunflower, and Product B, which is 65% millet and 35% safflower. If a customer purchases a mix of the both types of birdseed that is 50% millet, what percent of the mix is Product A?	Choose the correct answer
A) 50%	B) 55%	C) 60%	D) 40%	E) 45 %
Yes there is a simple method :   Consider the following method   Product A : 40% millet and 60% sunflower   Product B : 65% millet and 35% safflower   Mix : 50% millet   Here the weighted average is 50%,   Now Product A has 40% millet, which is 10% less than the weighted average of mix = - 0.10 A --------------- I   Similarly, Product B has 65 % millet, which is 15 % more than the weighted average of mix = + 0.15 B ------------ II   Now, both Product A and Product B are combined to give a 50% mix containing millet, so equate I and II   implies, 0.10 A = 0.15 B   Therefore A/B = 0.15/0.10 = 3/2   A : B : (A + B) = 3 : 2 : (3+2) = 3 : 2 : 5   We have to find, percent of the mix is Product A i.e. A : (A + B) = 3 : 5 = (3 / 5) * 100= 
<gadget id="calculator">(3 / 5) * 100</gadget>
<output>60</output>
60 %   Here is a pictorial representation :   Product A= 40%------------------------10% or 0.10 below average, A times-----------------Total below = - 0.10 A   ----------------------------------------------------------------------------------------Average = 50% or 0.50   Product B = 65 %--------------------------15% or 0.15 above average, B times-----------------Total above = + 0.15 B   Since the amount below the average has to equal the average above the average; therefore,   0.10 A = 0.15 B   A/B = 3/2   A:B: Total = 3:2:5   A/Total = 3:5 = 60 %   Answer: 60%
<result>C</result>
A feed shop sells two varieties of birdseed: Product A, which is 40% millet and 60% sunflower, and Product B, which is 65% millet and 35% safflower. If a customer purchases a mix of the both types of birdseed that is 50% millet, what percent of the mix is Product A?