The product of n-1 consecutive positive integers is always divisible by
Select:
A) n^2 -1
B) (n-1)!
C) 2n +1
D) n^2 + 1
E) n!
Plug in some vlues and check -   Product of first 2 number is 2*1   Product of first 3 number is 3*2*1   Product of first 4 number is 4*3*2*1   Product of first 5 number is 5*4*3*2*1   So, The product of first n natural numbers is always divisible by n! , answer will be ((n-1)!)
<result>B</result>
The product of n-1 consecutive positive integers is always divisible by