The last digit of 12^12+13^13–14^14×15^15 = Choose one: A) 0 B) 1 C) 5 D) 8 E) 9
12^12+13^13–14^14∗15^15   =12^12+13^13–(14^14∗15^15)   Note that the answer would be -ve for this question   So, Just for the sake of last digit, I'm re-arranging the term as below   (14^14∗15^15)−(12^12+13^13)   (14^14∗15^15) &gt;&gt; As 4 &amp; 5 are at the units place, the units place would be 0 of the product. No need of further calculation   12^12&gt;&gt; Cyclicity is 2, 4, 8, 6... units digit = 6   13^13 &gt;&gt; Cyclicity is 3, 9, 7, 1... units digit = 3   0 - (6+3)   = 0 - 9 = 1 at the units place   Answer = 1 = 1
<result>B</result>
The last digit of 12^12+13^13–14^14×15^15 =