A meeting has to be conducted with 4 managers. Find the number of ways in which the managers may be selected from among 8 managers, if there are 2 managers who refuse to attend the meeting together. Pick one
A) 48
B) 55
C) 58
D) 62
E) 70
The total number of ways to choose 4 managers is 8C4 = 70   We need to subtract the number of groups which include the two managers, which is 6C2 = 15.   70 - 15= 
<gadget id="calculator">70 - 15</gadget>
<output>55</output>
55   The answer is 55.
<result>B</result>
A meeting has to be conducted with 4 managers. Find the number of ways in which the managers may be selected from among 8 managers, if there are 2 managers who refuse to attend the meeting together.