Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $4 more than 1/4 of the fine and Peter paid $4 less than 1/3 of the fine, leaving pay $5 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?  Select.
A) $30	B) $25	C) $35	D) $40	E) $45
Call the fine F. Joe paid (1/4)F + 4 and Peter paid (1/3)F – 4, leaving (1/2)F – 5 left. If we add those three up, they should add up to F.   F = [(1/4)F + 4] + [(1/3)F – 4] + [(1/2)F – 5]   F = (1/4)F + (1/3)F + (1/2)F – 5   Multiply all terms by 12 to clear the fractions.   12F = 3F + 4F + 6F – 60   12F = 13 F – 60   –F = – 60   F = 60   Well, if the fine cost $60, then Sam paid the part not covered by Joe or Peter. Half the fine is $30, and Sam paid $5 less than this: $25.   Answer = $25
<result>B</result>
Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $4 more than 1/4 of the fine and Peter paid $4 less than 1/3 of the fine, leaving pay $5 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?