Of the five-digit positive integers that have no digits equal to zero, how many have two digits that are equal to each other and the remaining digit different from the other two?	Choose the most appropriate option
A) 24440	B) 36440	C) 72440	D) 181440	E) 216440
Of the five-digit positive integers that have no digits equal to zero, how many have two digits that are equal to each other and the remaining digit different from the other two?   A. 24   B. 36   C. 72   D. 144   E. 216   Choosing the digit for p - 9 ways;   Choosing the digit for q - 8 ways;   Choosing the digit for r - 7 ways;   Choosing the digit for s - 6ways;   # of permutations of 3 digits in ppqrs - 5!/2!   Total: 9*8*7*6*5!/2!=181440.   Answer: 181440.
<result>D</result>
Of the five-digit positive integers that have no digits equal to zero, how many have two digits that are equal to each other and the remaining digit different from the other two?