It is being given that (2^32 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
Choose the correct option:
A) (2^90 - 1)	B) (2^90 + 1)	C) (2^96 - 1)	D) (2^96 + 1)	E) (2^95 + 1)
Let 232 = x. Then, (232 + 1) = (x + 1).   Let (x + 1) be completely divisible by the natural number N. Then,   (296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.   (2^96 + 1))
<result>D</result>
It is being given that (2^32 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?