Mr. Srinivas saves one coin of 5 on first day of the
week, three coins of 5 on the second day of the week.
Five coins of 5 on third day and so on. How much money will he has at the end of the week?
Options:
A) 238  B) 245  C) 2867  D) 987  E) 111
Number of   5 coins with him at the end of week = 5 × (1 + 3 + 5 + 7 + 9 + 11 + 13) = 5 × (sum of first 7 odd numbers) (By using the formula discussed earlier). ∴ Sum of all numbers = 5 × 72 = 245.   Answer:245
<result>B</result>
Mr. Srinivas saves one coin of 5 on first day of the
week, three coins of 5 on the second day of the week.
Five coins of 5 on third day and so on. How much money will he has at the end of the week?