Find the probability that a leap year selected at random will not have 53 Sundays or Mondays. Choose the correct choice from the following answers
A) 6/7  B) 5/7  C) 4/7  D) 3/7  E) 2/7
There are 366 days in a leap year: 52 weeks and 2 more days. So, 52 Sundays, 52 Mondays and 2 days.   These 2 days can be: {Mon, Tue}, {Tue, Wed}, {Wed, Thu}, {Thu, Fri}, {Fri, Sat}, {Sat,Sun} and {Sun, Mon} (7 cases). In order to have 53 Sundays or 53 Mondays we should have either {Mon, Tue}   {Sat,Sun} or {Sun, Mon} case.   The probability of that is 3/7.   So probability of not having 53 Sundays or Mondays, probability is 1 - 3/7 = 4/7   Answer: 4/7.
<result>C</result>
Find the probability that a leap year selected at random will not have 53 Sundays or Mondays.