A certain ball team has an equal number of right- and left-handed players. On a certain day, two-thirds of the players were absent from practice. Of the players at practice that day, one-third were right handed. What is the ratio of the number of right-handed players who were not at practice that day to the number of left handed players who were not at practice?  Choose the correct choice from the following answers:	A) 1/3	B) 2/3	C) 7/5	D) 5/7	E) 3/2
Say the total number of players is 18, 9 right-handed and 9 left-handed.   On a certain day, two-thirds of the players were absent from practice --&gt; 12 absent and 6 present.   Of the players at practice that day, one-third were right-handed --&gt; 6*1/3=2 were right-handed and 4 left-handed.   The number of right-handed players who were not at practice that day is 9-2 --  6*1/3= 
<gadget id="calculator"> --  6*1/3</gadget>
<output>2</output>
2 were right-handed and 4 left-handed.   The number of right-handed players who were not at practice that day is  9-2= 
<gadget id="calculator"> 9-2</gadget>
<output>7</output>
7.   The number of left-handed players who were not at practice that days is   9-4= 
<gadget id="calculator">  9-4</gadget>
<output>5</output>
5.   The ratio= 7/5.   Answer: 7/5.
<result>C</result>
A certain ball team has an equal number of right- and left-handed players. On a certain day, two-thirds of the players were absent from practice. Of the players at practice that day, one-third were right handed. What is the ratio of the number of right-handed players who were not at practice that day to the number of left handed players who were not at practice?