A family consisting of one mother, one father, two daughters and a son is taking a road trip in a sedan. The sedan has two front seats and three back seats. If one of the parents must drive and the two daughters refuse to sit next to each other, how many possible seating arrangements are there?
Answers:  A) 28  B) 32  C) 48  D) 60  E) 120
Sisters can sit separately in two ways:   1. one of them is on the front seat (2 ways). Others (including second sister) can be arranged in: 2 (drivers seat)*3! (arrangements of three on the back seat)=12 ways. Total for this case:  2*12= 
<gadget id="calculator"> 2*12</gadget>
<output>24</output>
24   Or   2. both by the window on the back seat (2 ways). Others can be arranged in: 2 (drivers seat)*2 (front seat)*1(one left to sit between the sisters on the back seat)=4 ways. Total for this case:  2*4= 
<gadget id="calculator"> 2*4</gadget>
<output>8</output>
8.   Total=24+8= 
<gadget id="calculator">24+8</gadget>
<output>32</output>
32. ANS:32
<result>B</result>
A family consisting of one mother, one father, two daughters and a son is taking a road trip in a sedan. The sedan has two front seats and three back seats. If one of the parents must drive and the two daughters refuse to sit next to each other, how many possible seating arrangements are there?