There are five thieves, each loot a bakery one after the other such that the first one takes 1/2 of the total no. of the breads plus 1/2 of a bread. Similarly 2nd, 3rd,4th and 5fth also did the same. After the fifth one no. of breads remained are 3. Initially how many breads were there?  Choose the correct choice
A) 124 B) 125 C) 126 D) 127 E) 128
Let the Number of Breads Initial be x   You Should Go in Reverse Order as left Bread is 3   i.e x=?   After 1st person ate A=x-(x/2)-(1/2)   i.e A=(2x-x)/2-(1/2)   i.e A=(x/2)-(1/2)   i.e A=(2x-2)/4   i.e A=(x-1)/2   like wise ----After 2nd person ate B=(A-1)/2   like wise ----After 3rd person ate C=(B-1)/2   like wise ----After 4th person ate 127=(C-1)/2   like wise ----After 5th person ate E=(127-1)/2   Now as after 5th person ate the Value of remaining Bread is ---3   therefore the value of E=3;   Now go Reverse from botom to top to get the value of X after calcuating   Value of 127=7   Value of C=15   Value of B=31   Value of A=63   Value of X=127   SO the Final answer is 127 breads were there   ANSWER:127
<result>D</result>
There are five thieves, each loot a bakery one after the other such that the first one takes 1/2 of the total no. of the breads plus 1/2 of a bread. Similarly 2nd, 3rd,4th and 5fth also did the same. After the fifth one no. of breads remained are 3. Initially how many breads were there?