(2^2+4^2+6^2+.....+22^2)=?
Choices
A) 5578 B) 7996 C) 9964 D) 2024 E) 1346
=(1x2)^2+(2x2)^2,+(2x3)^3+......(2x11)^2   =2^2 x (1^2+2^2+3^2+.......+11^2)   formula is =1/6 n(n+1)(2n+1)   =(4x1/6x11x12x23)   =(4x506)=2024   Answer is 2024
<result>D</result>
(2^2+4^2+6^2+.....+22^2)=?