The units digit of (35)^(87) + (93)^(49) is: Pick:	A) 2	B) 4	C) 6	D) 8	E) 0
The units digit of powers of 3, cycles in a group of 4: {3, 9, 7, 1}   49 has the form 4k+1, so the units digit of 93^49 is 3.   The units digit of powers of 5 is always 5.   3+5= 
<gadget id="calculator">3+5</gadget>
<output>8</output>
8, so the units digit is 8.   The answer is 8.
<result>D</result>
The units digit of (35)^(87) + (93)^(49) is: