Find the least number which when divided by 31 and 9 leaves a remainder of 3 in each case. Choose the correct answer: A) 280 B) 282 C) 284 D) 286 E) 288
The least number which when divided by different divisors leaving the same remainder in each case   = LCM(different divisors) + remainder left in each case.   Hence the required least number   = LCM(31, 9) + 3 = 282.   ANSWER:282
<result>B</result>
Find the least number which when divided by 31 and 9 leaves a remainder of 3 in each case.