If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a five-percent vinegar solution, what was the concentration of the original solution?	Select
A) 19.3%	B) 25.8%	C) 16.67%	D) 15.5%	E) 12.5%
Let X be the quantity of non-vinegar in the strong vinegar solution   Thus vinegar quantity will be 12 - X   When 50 ounces of water were added the percentage of vinegar becomes 5%, thus (12 - X)/62 = 5/100   From this equation X = 8.9   Answer (12-8.9)/12 = 25.8%   ANSWER:25.8%
<result>B</result>
If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a five-percent vinegar solution, what was the concentration of the original solution?