A shipment of 250 smartphones contains 84 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?
A.
B.
C.
D.
E.	Pick: A) 1/250 B) 1/84 C) 1/11 D) 1/9 E) 1/3
Probability of choosing one defective phone from a lot of 250 which ontains 84 defective phones is = (84/250)   Probability of choosing one defective phone from a lot of 249(we already picked one) which ontains 83(we already picked one) defective phones is = (83/249)   Combined probability of series of events = product of the probabilities = (84/250)*(83/249)   84/250 is close to (1/3) and (83/249)= (1/3)   so answer is (1/3)*(1/3) = (1/9)   ANSWER:1/9
<result>D</result>
A shipment of 250 smartphones contains 84 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?
A.
B.
C.
D.
E.