If y = x^2 + ux + v, y is minimum when x is:  Select the correct option
A) u/u B) -u/u C) -u/2 D) -v/2 E) v/u
We're given the equation Y = X^2 + uX + v.   IF.. we use a simple Classic Quadratic....   u = 2   v = 1   Y = X^2 + 2X + 1   We can then go about finding the answer that yields the MINIMUM result when X = ...   Answer A: u/v = 2/1= 
<gadget id="calculator">2/1</gadget>
<output>2</output>
2 --&gt; 4+4+1= +9   Answer B: -u/v = -2/1 = -2 --&gt; 4-4+1 = +1   Answer -u/2: -u/2 = -2/2 = -1 --&gt; 1-2+1 = 0   Answer D: -v/2 = -1/2 --&gt;(1/4)-1+1 = +1/4   Answer E: v/u = 1/2 --&gt; (1/4)+1+1 = +2 1/4   From these results, we can see the minimum result:   -u/2
<result>C</result>
If y = x^2 + ux + v, y is minimum when x is: