When a natural number N is successively divided by 12,13,14,15. the remainders are 16,17,18,19. What will be the sum of the remainders if the order of the division is reversed?	Choose one:
A) 16  B) 19  C) 12  D) 11  E) 9
12 13 14 15   16 17 18 19   leave the top right- most number 8   start with bottom right-most number 5   19*14+18= 
<gadget id="calculator">19*14+18</gadget>
<output>284</output>
284   284*13+17= 
<gadget id="calculator">284*13+17</gadget>
<output>3_709</output>
3709   3709*12+16= 
<gadget id="calculator">3709*12+16</gadget>
<output>44_524</output>
44524   this is the number required   Now, do the successive division in the reverse order   The sum of the remainders is 19   Hence, the correct option is 19
<result>B</result>
When a natural number N is successively divided by 12,13,14,15. the remainders are 16,17,18,19. What will be the sum of the remainders if the order of the division is reversed?