The integer n is formed by writing the integers 1 through 333 in order as shown below.
n=123456789101112.......331332333
counting from the left, what is the 333rd digit of n?
Choose the correct choice from the following answers:
A) 0	B) 1	C) 3	D) 7	E) 8
the other way you can approach this is:   add zeroes as follows:   123456789....   make a pair of 3 by making each number a 3 digit number   000   001   002   003   004   005   006   007   008   009   010.... and so on   ....by doing this we can make that every other 30th digit will be a 9   and for doing this we are adding 1*3+2*9+1*90=112 zeroes...therefore 333rd digit now will be 333+111= 
<gadget id="calculator">333+111</gadget>
<output>444</output>
444 th digit   now 30*15=450....therefore 450th digit will be 9   and 15 th series will be of 141,142....149   so ........147148149.....in this 9 is the 450th digit therefore 444 th will be 7   hence the answer is 7 answer is 7
<result>D</result>
The integer n is formed by writing the integers 1 through 333 in order as shown below.
n=123456789101112.......331332333
counting from the left, what is the 333rd digit of n?