A and B have less than 6 diamonds each.What is the probability that the sum of diamonds they have is more than 3 but less than 7?
Choose the correct choice:
A) 3/5 B) 9/25 C) 4/9 D) 2/3 E) 3/2
A has 0, 1, 2, 3, 4, or 5 diamonds;   B has 0, 1, 2, 3, 4, or 5 diamonds.   More than 3 but less than 7 = 4, 5, or 6.   4:   {A, B}   {4, 0}   {3, 1}   {2, 2}   {1, 3}   {0, 4}   5:   {A, B}   {5, 0}   {4, 1}   {3, 2}   {2, 3}   {1, 4}   {0, 5}   6:   {A, B}   {5, 1}   {4, 2}   {3, 3}   {2, 4}   {1, 5}   Favorable = 5 + 6 + 5= 
<gadget id="calculator">5 + 6 + 5</gadget>
<output>16</output>
16.   Total= 6*6= 
<gadget id="calculator">6*6</gadget>
<output>36</output>
36   Probability= 16/36 = 4/9.   Answer: 4/9.
<result>C</result>
A and B have less than 6 diamonds each.What is the probability that the sum of diamonds they have is more than 3 but less than 7?