Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 30 percent ryegrass, what percent of the weight of this mixture is X ?
Select the correct option: A) 10% B) 33.33 % C) 40% D) 50% E) 66.66 %
Qnty.(cheaper)/Qty.(dearer)=(dearer-mean)/(mean-cheaper)   Thus Qy/Qx=(40-30)/(30-25)= 
<gadget id="calculator">(40-30)/(30-25)</gadget>
<output>2</output>
2   Therefore Qy=2 Qx and Qy+Qx = 100% (total). Hence Qx = 33.33%   ANSWER:33.33 %
<result>B</result>
Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 30 percent ryegrass, what percent of the weight of this mixture is X ?