In how many ways, a committee of 5 members can be selected from 6 men and 5 ladies, consisting of 3 men and 2 ladies?	Choose the correct option.
A) 423  B) 456  C) 264  D) 200  E) 154
(3 men out 6) and (2 ladies out of 5) are to be chosen.   Required number of ways = (6c3x5c2)   = [6x5x4/3x2x1] x [5x4/2x1]   = 200.   Ans: 200
<result>D</result>
In how many ways, a committee of 5 members can be selected from 6 men and 5 ladies, consisting of 3 men and 2 ladies?