Solve the following system of equations:
x-y-z = 0
3x+4y+3z = 4
5x+2y+7z = 22  Pick one:
A) x=1, y=2, z=3	B) x=-1, y=-2, z=1	C) x=-2, y=3, z=1	D) x=1, y=-2, z=3	E) x=3, y=-1, z=2
Solve the first equation for x.   x-y-z = 0   x = y+z   Substitute the solution for x into the second and third equations.   3*(y+z)+4y+3z = 4   3y+3z+4y+3z = 4   7y+6z = 4   5*(y+z)+2y+7z = 22   5y+5z+2y+7z = 22   7y+12z = 22   Subtract the new second equation from the new third equation and solve for z.   7y+12z = 22   - (7y+6z = 4)   6z = 18   z=3   Substitute the solution for z back into 7y+6z = 4 and solve for y.   7y+6*3 = 4   7y+18 = 4   7y = -14   y=-2   Substitute the values for y and z back into x-y-z = 0.   x-(-2)-3 = 0   x-1 = 0   x=1   x=1, y=2, z=3nswer x=1, y=2, z=3
<result>A</result>
Solve the following system of equations:
x-y-z = 0
3x+4y+3z = 4
5x+2y+7z = 22