In how many different number of ways a combination of 3 boys and 2 girls can be selected from 6 boys and 5 girls.
Choose the correct choice
A) 20  B) 40  C) 46  D) 48  E) 50
6C3   = 6!/(3! . 3!)   = (6 × 5 × 4)/(3 × 2)   = 5 × 4 = 20.   20)
<result>A</result>
In how many different number of ways a combination of 3 boys and 2 girls can be selected from 6 boys and 5 girls.