If xy > 0, 1/x + 1/y = 2, and 1/xy = 8, then (x+y)/4 = ?
Pick.
A) 1/16	B) 1/6	C) 1/5	D) 5	E) 6
(1/X+1/Y)=2 canbe solved as {(x+y)/xy}=8. Substituting for 1/xy=8, we get   x+y=2/8   ==&gt; (x+y)/4= 2/(8*4)=1/16.   1/16
<result>A</result>
If xy > 0, 1/x + 1/y = 2, and 1/xy = 8, then (x+y)/4 = ?