Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the game remainder in each case. Then sum of the digits in N is :	Choose the correct choice:  A) 4  B) 5  C) 6  D) 8  E) 9
Solution   N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)   = H.C.F. of 3360, 2240 and 5600 = 1120.   Sum of digits in N = (1 + 1 + 2 + 0)= 
<gadget id="calculator">(1 + 1 + 2 + 0)</gadget>
<output>4</output>
4. 4nswer 4
<result>A</result>
Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the game remainder in each case. Then sum of the digits in N is :