A farmer divides his herd of x cows among his 4 sons so that one son gets one half of the herd, the second gets one-fourth, the third gets one-fifth and the fourth gets 7 cows. Then x is equal to
Select:  A) 100  B) 140  C) 180  D) 160  E) 120
no. of cows:: x   1st son: x/2   2nd son: x/4   3rd son: x/5   4th son: 7   (x)+(x/4)+(x/5)+7=x   =&gt; x - (19x/20)=7   =&gt; (20x-19x)/20=7   =&gt; x =140   ANSWER:140
<result>B</result>
A farmer divides his herd of x cows among his 4 sons so that one son gets one half of the herd, the second gets one-fourth, the third gets one-fifth and the fourth gets 7 cows. Then x is equal to