How many different combinations of outcomes can you make by rolling three standard (6-sided) dice if the order of the dice does not matter?
Options:
A) 24  B) 30  C) 56  D) 120  E) 216
1) All dice have the same number:   you have 6 possibilities.   2) 2 dice have the same number, but the 3rd is different:   you have 6*5   3) 3 dice are all different:   you have 6*5*4/3! = 20.   Because the question says the order does not matter, u have to divide it by 3!.   so totally you have 56.   ANS:C. 56.
<result>C</result>
How many different combinations of outcomes can you make by rolling three standard (6-sided) dice if the order of the dice does not matter?