If the average of 5 positive integers is 65 and the difference between the largest and the smallest of these 5 numbers is 10, what is the maximum value possible for the largest of these 5 integers? Choose one
A) 50  B) 52  C) 59  D) 68  E) 73
Sum of 5 Integer (a, b, c, d, e) = 5*65= 
<gadget id="calculator">5*65</gadget>
<output>325</output>
325   e - a= 10   i.e. e = a+10   For e to be maximum remaining 4 MUST be as small as possible   Since smallest of 5 numbers is a so to minimize other numbers we can take them equal to the smallest of 5 numbers   i.e. a+a+a+a+(a+10) = 325   i.e. 5a = 315   i.e. a = 63   i.e. Largest e = 63+10= 
<gadget id="calculator">63+10</gadget>
<output>73</output>
73   Answer: option 73
<result>E</result>
If the average of 5 positive integers is 65 and the difference between the largest and the smallest of these 5 numbers is 10, what is the maximum value possible for the largest of these 5 integers?