A committee of three people is to be chosen from 6 married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?  Choices.
A) 167 B) 190 C) 140 D) 180 E) 160
Total no of ways of choosing a committee = 12C3 = 220   No of ways to choose first couple = 6C1 = 6   No of ways to choose 1 person from remaining 10 = 10C1 = 10   Total number of ways of choosing a married couple to be in the same committee = 6*10= 
<gadget id="calculator">6*10</gadget>
<output>60</output>
60   So, no of ways not choosing a married couple= 220-60= 
<gadget id="calculator">220-60</gadget>
<output>160</output>
160   ANS:E. 160
<result>E</result>
A committee of three people is to be chosen from 6 married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?