The least number which when divided by 3, 4, 5 and 6 leaves a remainder 6, but when divided by 9 leaves no remainder, is Options: A) 117 B) 126 C) 252 D) 336 E) None of these
Explanation:   L.C.M of 3, 4, 5, 6 = 60   therefore Required Number is of the form 60k+6.   Least value of k for which (60k+6) is divisible by 9 is k = 2   therefore Required Number = (60 x 2+6)=126.   Answer: 126
<result>B</result>
The least number which when divided by 3, 4, 5 and 6 leaves a remainder 6, but when divided by 9 leaves no remainder, is