Let a be a positive integer. If n is divisible by 2^a and n is also divisible by 3^(2a), then it is possible that n is NOT divisible by  Select the correct option.
A) 6
B) 3 × 2^a
C) 2 × 3^(2a)
D) 6^a
E) 6^(2a)
Easiest method is to assume a value of a = 1   Given n is divisible by 2^2 ---&gt; n = 2^1*p ---&gt; n =2p   Also, n is also divisible by 3^(2a) ---&gt; n = 3^(2a) * q = 3^2*q = 9q   Lets look at a few numbers that are multiples of both 2 and 9 are 18,36,72....   Thus looking at the options , A-D divide the numbers 18,36,72.... while E (=6^(2) = 36 ) does not divide 18. Thus 6^(2a) is the correct answer.
<result>E</result>
Let a be a positive integer. If n is divisible by 2^a and n is also divisible by 3^(2a), then it is possible that n is NOT divisible by