If (x^2 + 1)y=8, which of the following is not a possible value for y?
Choose the correct choice from the following answers:
A) 8/2
B) 2/5
C) 18/3
D) 3
E) 17/2
Its simple   equation is (x^2 +1)y = 8 ===&gt; x^2 = (8/y) - 1 . As , in LHS, it is x^2 the value has to be positive or zero in RHS.   Hence, (8/y) - 1&gt;= 0 ===&gt; y =&lt; 8. Now only option E has greater value of 'y' than 8.   Thus, correct ans is 17/2
<result>E</result>
If (x^2 + 1)y=8, which of the following is not a possible value for y?