Nicole cycles at a constant rate of 20 kilometers per hour, and is passed by Jessica, who cycles at a constant rate of 40 kilometers per hour. If Jessica cycles at her constant rate for x minutes after passing Nicole, then stops to wait for her, how many minutes will Jessica have to wait for Nicole to catch up to her?  Select:
A) a) x minutes B) b) x/2 minutes C) c) 2x/3 minutes D) d) 3x/2 minutes E) e) 2x minutes
Speed of nicole = 20km/h or 20/60 km/min = 1/3 km/min.   Once jessica passed the nicole, the distance between the nicole and jessica will increase at the rate of   (30-20)= 
<gadget id="calculator">  (30-20)</gadget>
<output>10</output>
10km/h or 1/6 km/min   now jessica is cycling for x minutes after passing the nicole, so in those x minutes distance between jessica and nicole would be (1/6)*x= x/6 km.   So, the time taken by nicole to travel x/6 km = (x/6)/(1/3) = 3x/2. hence answer should be d) 3x/2 minutes.
<result>D</result>
Nicole cycles at a constant rate of 20 kilometers per hour, and is passed by Jessica, who cycles at a constant rate of 40 kilometers per hour. If Jessica cycles at her constant rate for x minutes after passing Nicole, then stops to wait for her, how many minutes will Jessica have to wait for Nicole to catch up to her?