A committee of three people is to be chosen from 7 married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?
Choose the correct choice from the following options.
A) 16  B) 39  C) 26  D) 30  E) 49
Total no of ways of choosing a committee = 7C3 = 35   No of ways to choose first couple = 7C1 = 7   No of ways to choose 1 person from remaining 12 = 12C1 = 12   Total number of ways of choosing a married couple to be in the same committee = 7*12= 
<gadget id="calculator">7*12</gadget>
<output>84</output>
84   So, no of ways not choosing a married couple= 84-35= 
<gadget id="calculator">84-35</gadget>
<output>49</output>
49   ANS:E. 49
<result>E</result>
A committee of three people is to be chosen from 7 married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?