Two identical circles intersect such that their centers and the points at which they intersect form a square of side 4 cm. What is the area of the region where the two circles intersect?	Pick
A) 16 - 4pi B) 4 - pi C) 2pi - 4 D) 8pi - 16 E) pi^2 - 4
Drawing a diagram, we see that the radius of the circle equals the side of the square.   The area of intersection is: pi*r^2/4 - (r^2-pi*r^2/4) = pi*r^2/2 - r^2 = 8pi - 16   The answer is 8pi - 16.
<result>D</result>
Two identical circles intersect such that their centers and the points at which they intersect form a square of side 4 cm. What is the area of the region where the two circles intersect?