If the operation @ is defined for all a and b by the equation a@b =(a-b)/5,then (3@-2)@6=?	Choose the correct answer:
A) 0 B) 1 C) 2 D) -2 E) -1
work within the parenthesis first so solve (3@-2) first   (3@-2)=(3-(-2))/5=(3+2)/5= 
<gadget id="calculator">(3+2)/5</gadget>
<output>1</output>
1   now take 1 plug back into equation and solve the rest   (1@6)=(1-6)/5=-5/5=-1   so -1 is the answer....this question is merely testing order of operations   remember P-1MDAS   Answer is option:-1
<result>E</result>
If the operation @ is defined for all a and b by the equation a@b =(a-b)/5,then (3@-2)@6=?