If B and C are digits and 8BC is a 3-digit number that is divisible by 5, which of the following is a possible product of B and C?
Pick one:  A) 1  B) 2  C) 5  D) 7  E) 14
Try with the options -   A. If BC = 1 , both B and C must be 1   B. If BC = 2 , either B or C must be 1 or 2 ; In that case sum of the digits will be 8 + 1 + 2= 
<gadget id="calculator">8 + 1 + 2</gadget>
<output>11</output>
11 which is not divisible by 3   C. If BC= 5 , either B or C must be 1 or 5 ; In that case sum of the digits will be 8 + 1 + 5= 
<gadget id="calculator">8 + 1 + 5</gadget>
<output>14</output>
14 which is not divisible by 3   D. If BC= 6 , then we can have the following possibilities   i. Either B or C must be 2 or 3 ; In that case sum of the digits will be 8 + 2 + 3= 
<gadget id="calculator">8 + 2 + 3</gadget>
<output>13</output>
13 which is not divisible by 3   ii. Either B or C must be 1 or 6 ; In that case sum of the digits will be 8 + 1 + 6= 
<gadget id="calculator">8 + 1 + 6</gadget>
<output>15</output>
15 which is divisible by 3   E. If BC= 14 , then either B or C must be 2 or 7 ; In that case sum of the digits will be 8 + 2 + 7= 
<gadget id="calculator">8 + 2 + 7</gadget>
<output>17</output>
17 which is not divisible by 5   Thus answer is (7)
<result>D</result>
If B and C are digits and 8BC is a 3-digit number that is divisible by 5, which of the following is a possible product of B and C?