4 Women & 6 men have to be seated in a row given that no two women can sit together. How many different arrangements are there.
Choose the correct choice from the following answers:	A) 6! x 7P4	B) 6! x 9P4	C) 6! x 5P4	D) 6! x 3P4	E) 6! x 2P4
Let us first sit all the 6 men in 6 positions in 6! ways. Now there are 7 gaps between them in which 4 women can sit in 7P47P4 ways.   So total ways are 6! x 7P4   6! x 7P4nswer:6! x 7P4
<result>A</result>
4 Women & 6 men have to be seated in a row given that no two women can sit together. How many different arrangements are there.