There are 16 cans in the refrigerator. 9 of them are red and 7 of them are blue. In how many ways we can remove 10 cans so that at least one red and at least one blue cans to remain the refrigerator. Select the correct option:  A) 460  B) 490  C) 833  D) 455  E) 445
Ways to pick 6 cans so that at least one red and at least one blue cans to remain the refrigerator =   total ways to pick 6 can out of 12 - ways to pick 6 red out of 7 red - ways to pick 6 blue out of 5 blue   128336âˆ’98336âˆ’78336=924âˆ’84âˆ’7=833   ANSWER:833
<result>C</result>
There are 16 cans in the refrigerator. 9 of them are red and 7 of them are blue. In how many ways we can remove 10 cans so that at least one red and at least one blue cans to remain the refrigerator.