The sum of the squares of three numbers is 100, while the sum of their products taken two at a time is 48. Their sum is: Select:
A) 20 B) 30 C) 40 D) 50 E) None of these
x^+y^2+z^2=100   xy+yz+zx=48   as we know.. (x+y+z)^2=x^2+y^2+z^2+2(xy+yz+zx)   so (x+y+z)^2=100+(2*48)   (x+y+z)^2=196   so x+y+z=14   ANSWNone of theseR:None of these
<result>E</result>
The sum of the squares of three numbers is 100, while the sum of their products taken two at a time is 48. Their sum is: