Kyle, Devon, and Catherine each try independently to solve a problem. If their individual probabilities for success are 1/2, 1/3 and 5/9, respectively, what is the probability that Kyle but not Devon and Catherine will solve the problem?
Choices.
A) 13/29  B) 1/4  C) 15/21  D) 11/19  E) 4/27
P(Kyle will solve)=1/2   P(Devon will not solve)= 1 - 1/3 = 2/3   P(Catherine will not solve) = 1- 5/9 = 4/9   P= (1/2)*(2/3)*(4/9) = 8/54 = 4/27.   Answer:4/27
<result>E</result>
Kyle, Devon, and Catherine each try independently to solve a problem. If their individual probabilities for success are 1/2, 1/3 and 5/9, respectively, what is the probability that Kyle but not Devon and Catherine will solve the problem?