If both 5^2 and 3^3 are factors of n x (2^5) x (6^2) x (7^3), what is the smallest possible positive value of n?
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Choose the correct choice:  A) 25  B) 27  C) 45  D) 75  E) 125
If both 5^2 &amp; 3^3 are factors, then they must be present in the number.   Leaving rest of the prime factors and splitting 6^2 into 3^2 * 2^3.   The number is lacking 5^2 &amp; a 3, so that 5^2 and 3^3 is a factor.   Hence the smallest number is 5^2 * 3 = 75   ANSWER:75
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If both 5^2 and 3^3 are factors of n x (2^5) x (6^2) x (7^3), what is the smallest possible positive value of n?
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