If 4 people are selected from a group of 9 married couples, what is the probability that none of them would be married to each other? Choose the correct choice from the following choices.
A) 1/33
B) 2/85
C) 1/3
D) 56/85
E) 11/85
If we are to select 4 people from 9 couples WITHOUT any restriction, how many ways can we make the selection? 18!/4!14! = 3060   If we are to select 4 people from 9 couples WITH restriction that no married couple can both make it to the group, only a representative?   9!/4!5! = 126   But we know that to select a person from each couple, take 2 possibilities     126*2*2*2*2= 
<gadget id="calculator">  126*2*2*2*2</gadget>
<output>2_016</output>
2016   Probability= 56/85esired/All Possibilities = 2016/3060 = 56/85   Answer: 56/85
<result>D</result>
If 4 people are selected from a group of 9 married couples, what is the probability that none of them would be married to each other?