Adams, Smith, Derek, Alex and Bob bought movie tickets in one row next to each other. What is the probability that Bob and Adams will each sit next to each other?  Choose one
A) 5%
B) 10%
C) 15%
D) 20%
E) 25%
Possible sitting position is 5! = 120   10%ob and Adams Sitting next to each other is 5 Combination 2   =5!/2!(5-2)!   =120/2(6)   =120/12= 
<gadget id="calculator">120/12</gadget>
<output>10</output>
10   Answer= 10%
<result>B</result>
Adams, Smith, Derek, Alex and Bob bought movie tickets in one row next to each other. What is the probability that Bob and Adams will each sit next to each other?