What is the sum Y of all 3 digit numbers that leave a remainder of '2' when divided by 3?	Choices:  A) 897  B) 164,850  C) 164,749  D) 149,700  E) 156,720
The series is =&gt; 101+...998   Number of terms =&gt; 300   sum =&gt; 300/2 * [101+998]   hence sum Y=&gt; 164850 i.e. option 164,850
<result>B</result>
What is the sum Y of all 3 digit numbers that leave a remainder of '2' when divided by 3?