If in a cricket one day match, there were no wide balls, no wides, no extras and no overthrows.
What is the maximum number of runs that a batsman can score in 40 overs in an ideal case scenario?
Choices.
A) 1652  B) 1651  C) 1653  D) 1323  E) None
Solution:   1323   Explanation:   For an ideal case, the batsman will hit a six on each ball. But if he hits six on the last ball of the over, the strike will change in the next over. Thus, the best he can do in the last ball is run 3 runs so that he retains the strike even in the next over. Thus the total runs that he can score in each over:    6 * 5 + 3= 
<gadget id="calculator"> 6 * 5 + 3</gadget>
<output>33</output>
33   But this will have to go like it only till the 39th over. In the 40th over, he can hit a six in the last ball as well as that will be the last ball of his destination.   Thus runs for the 40th over will be  6 * 6= 
<gadget id="calculator"> 6 * 6</gadget>
<output>36</output>
36.   Hence the maximum runs= 33 * 39 + 36= 
<gadget id="calculator">33 * 39 + 36</gadget>
<output>1_323</output>
1323   Answer 1323
<result>D</result>
If in a cricket one day match, there were no wide balls, no wides, no extras and no overthrows.
What is the maximum number of runs that a batsman can score in 40 overs in an ideal case scenario?