If a 3-digit integer is selected at random from the integers 300 through 349, inclusive, what is the probability that the first digit and the last digit of the integer are each equal to two more than the middle digit? Pick
A) 50/349  B) 1/313  C) 1/49  D) 1/100  E) 1/50
Hundreds digit has to be 3 . So units digit needs to 3 as well   And both Hundreds and Units digit needs to be 2 more than ten's digit   The number is 313   Total numbers between 300 and 349 = (349-300)+1= 
<gadget id="calculator">(349-300)+1</gadget>
<output>50</output>
50   Probability= 1/50   Answer 1/50
<result>E</result>
If a 3-digit integer is selected at random from the integers 300 through 349, inclusive, what is the probability that the first digit and the last digit of the integer are each equal to two more than the middle digit?