If x = a/3 + b/3^2 + c/3^3, where a, b, and c are each equal to 0 or 1, then x could be each of the following EXCEPT:  Choose the correct choice from the following answers:
A) 1/27
B) 1/9
C) 4/27
D) 2/9
E) 4/9
x = a/3 + b/3^2 + c/3^3   = a/3 + b/9 + c/27   = (9a + 3b + c ) /27   2/9epending on whether a, b and c take 0 or 1 , the numerator can take 1 , 3 , 4 and 12   3/27 = 1/9   12/27 = 4/9   Answer 2/9
<result>D</result>
If x = a/3 + b/3^2 + c/3^3, where a, b, and c are each equal to 0 or 1, then x could be each of the following EXCEPT: