Let f(x) = x^2 + bx + c. If f(4) = 0 and f(-3) = 0, then b + c =
Choose one.
A) 18 B) 15 C) -13 D) -21 E) -24
f(x) = x^2 + bx + c. If f(4) = 0 and f(-3) = 0, then b + c =   f(4) = 0= 16+4b+c--- Taking 16 to the other side   -&gt; 4b+c= -16   f(-3) = 0= 9-3b+c --- taking -3b+c to the other side   -&gt; 3b-c=9   When we add these 2 equations, we get 7b= -7---&gt; b= -1   And while substituting b= -1 we get c= -12.   b+c= -13--- Answer -13
<result>C</result>
Let f(x) = x^2 + bx + c. If f(4) = 0 and f(-3) = 0, then b + c =