What is the smallest no. which must be added to 3245613 so as to obtain a sum which is divisible by 11?
Pick one
A) 1 B) 2 C) 4 D) 9 E) 3
For divisibility by 11, the difference of sums of digits at even and odd places must be either zero or divisible by 11.   For 3245613 , Difference =(3+4+6+3) -(2+5+1)=16-8= 
<gadget id="calculator">16-8</gadget>
<output>8</output>
8.   The units digit is at odd place. So we add 3 to the number=&gt; 3245613+3= 
<gadget id="calculator">3245613+3</gadget>
<output>3_245_616</output>
3245616   Now , (3+4+6+6) -(2+5+1)=19-8= 
<gadget id="calculator">19-8</gadget>
<output>11</output>
11=&gt;11 is a multiple of 11 and hence 3245616 is also divisible by 11   3
<result>E</result>
What is the smallest no. which must be added to 3245613 so as to obtain a sum which is divisible by 11?