Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 91, the three numbers in order are?  Choose the correct choice from the following options.
A) 39, 78, and 156
B) 39, 156, and 78
C) 78, 39, and 156
D) 78, 156, and 39
E) 156, 39, and 78
Let the numbers be 2x, x and 4x   (2x + x + 4x)/3 = 91   7x/3 = 91   x = 39   The numbers in order are 78, 39, and 156   The answer is 78, 39, and 156.
<result>C</result>
Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 91, the three numbers in order are?