The average (arithmetic mean) of the even integers from 0 to 200 inclusive is how much greater than the average (arithmetic mean) of the even integers from 0 to 100 inclusive?
Select: A) 10 B) 25 C) 50 D) 100 E) 200
The sum of even numbers from 0 to N is 2 + 4 +...+ N   = 2(1 + 2 + ...+ N/2)   = 2(N/2)(N/2+1)/2 = (N/2)(N/2+1)   The average is (N/2)(N/2+1)/(N/2+1) = N/2   The average of the even numbers from 0 to 200 is  200/2= 
<gadget id="calculator"> 200/2</gadget>
<output>100</output>
100   The average of the even numbers from 0 to 100 is  100/2= 
<gadget id="calculator"> 100/2</gadget>
<output>50</output>
50   The answer is 50.
<result>C</result>
The average (arithmetic mean) of the even integers from 0 to 200 inclusive is how much greater than the average (arithmetic mean) of the even integers from 0 to 100 inclusive?