An urn contains 5 red, 6 blue and 8 green balls. 4 balls are randomly selected from the urn, find the probability that the drawn ball are 1 blue and 1 red and 2 green balls ?
Choose the correct choice.
A) 70/323
B) 50/323
C) 52/969
D) 60/323
E) 25/321
Sample space = no. of ways 4 balls were drawn from urn = 19C4 = 3876   No. ways 1 blue and 1 red and 2 green balls were drawn from bag = 6C1 * 5C1 * 8C2 = 840   Probability = 840 / 3876 = 70/323   70/323ns - 70/323
<result>A</result>
An urn contains 5 red, 6 blue and 8 green balls. 4 balls are randomly selected from the urn, find the probability that the drawn ball are 1 blue and 1 red and 2 green balls ?