Let f(x) = x^2 + bx + c. If f(1) = 0 and f(-5) = 0, then f(x) crosses the y-axis at what y-coordinate? Choose the most appropriate option.
A) -5
B) -1
C) 0
D) 1
E) 5
When x = 1 and when x = -5, the expression f(x) = x² + bx + c equals 0.   Then f(x) = (x-1)(x+5)   f(0) = -5   The answer is -5.
<result>A</result>
Let f(x) = x^2 + bx + c. If f(1) = 0 and f(-5) = 0, then f(x) crosses the y-axis at what y-coordinate?