A group of 8 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the probability that Bob and Lisa will each sit next to only one of the seven other students from the group?	Choose the most appropriate option:
A) 5.67%	B) 3.57%	C) 15.17%	D) 2.07%	E) 2.57%
The question basically asks about the probability that Bob and Lisa sit at the ends.   The total # of sitting arrangements is 8!.   Desired arrangement is either BUVWXYZL or LUVWXYZB. Now, UVWXYZ can be arranged in 6! ways, therefore total # of favorable arrangements is 2*6!.   P=(favorable)/(total)=(2*6!)/8!=1/28.   Answer: 3.57%.
<result>B</result>
A group of 8 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the probability that Bob and Lisa will each sit next to only one of the seven other students from the group?