12 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played? Choose the correct choice from the following choices:
A) 190	B) 132	C) 210	D) 220	E) 225
Though 2*(12C2) is the correct approcah to do this, but for people like me who find Perm, Comb n Prob a nightmare, an easy approach can be used.   The first guy has to play 2 matches with the rest of 11, so he'll play 22 matches.   Similarly, second guy has to play with the rest of 10 as his 2 games with the first guy are already played. So he plays 20 matches.   This continues like this and the total matches are 22+20+18...+2   22+20+...+2 = 2(11+10+...+1) = 2((11*12)/2) = 11*12= 
<gadget id="calculator">11*12</gadget>
<output>132</output>
132.   ANSWER:132
<result>B</result>
12 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played?