A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late . Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late. What is the speed W of the train. Choose the correct choice from the following answers:  A) a) 45  B) b) 33  C) c) 48  D) d) 55  E) e) 61
Let y be the balance distance to be covered and x be the former speed.   A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late   so, y/(3x/4) - y/x = 35/60   4y/3x - y/x = 7/12   y/x(4/3-1)=7/12   y/x*1/3=7/12   y/x=7/4   4y-7x=0 ........ 1   Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late   so, (y-24)/(3x/4) - (y-24)/x = 25/60   4(y-24)/3x - (y-24)/x = 5/12   (y-24)/x (4/3-1) = 5/12   (y-24)/x *1/3 = 5/12   (y-24)*12 = 3x*5   (y-24)*4 = 5x   4y-5x = 96 ....... 2   eq2 - eq1   2x=96   x=48=W   Ans = c) 48
<result>C</result>
A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late . Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late. What is the speed W of the train.