Let f(x) = x^2 + bx + c. If f(1) = 0 and f(-6) = 0, then f(x) crosses the y-axis at what y-coordinate? Select:
A) -6 B) -1 C) 0 D) 1 E) 6
When x = 1 and when x = -6, the expression f(x) = x² + bx + c equals 0.   Then f(x) = (x-1)(x+6)   f(0) = -6   The answer is -6.
<result>A</result>
Let f(x) = x^2 + bx + c. If f(1) = 0 and f(-6) = 0, then f(x) crosses the y-axis at what y-coordinate?