In a box, there are 8 red, 5 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?
Choose the correct choice from the following answers:	A) 2/3	B) 8/21	C) 3/7	D) 9/22	E) 8/19
Explanation:   Total number of balls = (8 + 5 + 6)= 
<gadget id="calculator">(8 + 5 + 6)</gadget>
<output>19</output>
19   Let E= event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.   Therefore, n(E) = 8.   P(E) = 8/19.   Answer: Option 8/19
<result>E</result>
In a box, there are 8 red, 5 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?