Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age	Choose one.
A) 12,28 B) 14,30 C) 16,32 D) 18,34 E) 19,32
Explanation:   Let the age of younger person is x,   Then elder person age is (x+16)   =&gt; 3(x-6) = (x+16-6) [6 years before]   =&gt; 3x-18 = x+10   =&gt; x = 14.   So other person age is x + 16 = 30   Answer: Option 14,30
<result>B</result>
Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age