26 +27+28+29=110. How many such 4 consecutive numbers are there less than 2500 when added gives a sum which is divisible by 10? Choose the correct choice from the following answers
A) 100	B) 200	C) 300	D) 400	E) 500
since 1+2+3+4= 
<gadget id="calculator">1+2+3+4</gadget>
<output>10</output>
10 &amp; 6+7+8+9= 
<gadget id="calculator">6+7+8+9</gadget>
<output>30</output>
30   any combination with these no be will give u desirable result...   so total no in 100 will be 20 &amp; that's why in in 2500,it will be 500   ANSW500R:500
<result>E</result>
26 +27+28+29=110. How many such 4 consecutive numbers are there less than 2500 when added gives a sum which is divisible by 10?