Two different solutions of alcohol with respective proportions of alcohol to water of 3:1 and 2:3 were combined. What is the concentration of alcohol in the new solution if the first solution was 6 times the amount of the second solution? Choose one:  A) 62  B) 65  C) 68  D) 70  E) 72
SOL:   Lets assume that 60L of sol1 was mixed with 10L of sol2.   Alcohol in Sol1: 60*3/4 = 45L   Alcohol in Sol2: 10*2/5 = 4L   Total Alcohol in the mixed solution of 70L = 45 + 4= 
<gadget id="calculator">45 + 4</gadget>
<output>49</output>
49L   Alcohol concentration in the new sol: (49/70)*100= 
<gadget id="calculator">(49/70)*100</gadget>
<output>70</output>
70%   ANSWER:70
<result>D</result>
Two different solutions of alcohol with respective proportions of alcohol to water of 3:1 and 2:3 were combined. What is the concentration of alcohol in the new solution if the first solution was 6 times the amount of the second solution?