A two digit number exceeds the sum of the digits of that number by 18. If the digit at the unit's place is double the digit in the ten's place, what is the number?	Choose the correct choice from the following.
A) 12  B) 24  C) 42  D) 48  E) 49
Let the ten's digit be x.   Then, unit's digit = 2x.   Number = 10x + 2x = 12x;   Sum of digits 10  + 2= 
<gadget id="calculator">10  + 2</gadget>
<output>12</output>
12x;   Sum of digits= x + 2x = 3x.   Therefore,  12x - 3x = 18   ‹=› 9x = 18   ‹=› x = 2.   Hence, required number = 12x = 24.   Answer 24
<result>B</result>
A two digit number exceeds the sum of the digits of that number by 18. If the digit at the unit's place is double the digit in the ten's place, what is the number?