The sum of the 5 consecutive two digit odd numbers when divided by 10 becomes a perfect square, which of the following can be one of these 5 numbers?	Answers.
A) 47	B) 91	C) 41	D) 67	E) 44
perfect square:- 1,4,9,16,25,36   sum=square*10=10,40,90,160,250,360   sum of 4 odd consecutive numbers is multiple of 4   so the only number left are 40,160,360   sum/4=40/4= 
<gadget id="calculator">40/4</gadget>
<output>10</output>
10 is not possible   sum/4=360/4= 
<gadget id="calculator">360/4</gadget>
<output>90</output>
90 is not possible   sum/4=160/4= 
<gadget id="calculator">160/4</gadget>
<output>40</output>
40 is the only option available i.e 41   ANSWER:41
<result>C</result>
The sum of the 5 consecutive two digit odd numbers when divided by 10 becomes a perfect square, which of the following can be one of these 5 numbers?