In a railway station, there are two trains going. One in the harbor line and one in the main line, each having a frequency of 10 minutes. The main line service starts at 5 o'clock and the harbor line starts at 5.02 A.M. A man goes to the station every day to catch the first train that comes. What is the probability of the man catching the first train?  Pick one:
A) 0.9  B) 0.8  C) 0.6  D) 0.65  E) 1.5
For each 10 min interval, if man comes in first 2 min, he'll catch the 1st train, if he comes in next 8 min, he'll catch the 2nd train.   Hence, for harbor line = (2/10)= 
<gadget id="calculator">(2/10)</gadget>
<output>1/5 = around 0.2</output>
0.2 and for main line 0.8.   Answer:0.8
<result>B</result>
In a railway station, there are two trains going. One in the harbor line and one in the main line, each having a frequency of 10 minutes. The main line service starts at 5 o'clock and the harbor line starts at 5.02 A.M. A man goes to the station every day to catch the first train that comes. What is the probability of the man catching the first train?