A highway has its full length (1/8) repaired on the first day, and its full length (1/6) on the second day. On the third day, it is repaired the same amount as the second day, leaving a fraction of the total length How many have not been repaired?
一条公路第一天修了全长的(1/8)，第二天修了全长的(1/6)，第三天修的和第二天的同样多，还剩下全长的几分之几没有修？
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>

<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>

<gadget id="calculator">(1/6) * 2</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">1 - (1/8) - (1/3)</gadget>
<output>13/24 = around 0.541667</output>

<result>13/24 = around 0.541667</result>