Use (x) to represent the largest integer not exceeding x, remember {x}=x-(x), then the formula {((2012+1)/5)}+{((2012+2)/5)}+{ What is the value of ((2012+3)/5)}+…+{((2012+2012)/5)}.
用(x)表示不超过x的最大整数，记{x}=x-(x)，则算式{((2012+1)/5)}+{((2012+2)/5)}+{((2012+3)/5)}+…+{((2012+2012)/5)}的值为多少．
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>

<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>

<gadget id="calculator">2_012 - 2</gadget>
<output>2_010</output>

<gadget id="calculator">2_010 / 5</gadget>
<output>402</output>

<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>

<gadget id="calculator">0 + (1/5) + (2/5) + (3/5) + (4/5)</gadget>
<output>2</output>

<gadget id="calculator">402 * 2</gadget>
<output>804</output>

<gadget id="calculator">(3/5) + (4/5) + 804</gadget>
<output>4_027/5 = around 805.4</output>

<result>4_027/5 = around 805.4</result>