Three consecutive natural numbers from small to large are multiples of 7, 11, and 13. What is the smallest sum of these three natural numbers?
三个连续自然数从小到大依次是7，11，13的倍数，这三个自然数的和最小是多少？
<gadget id="calculator">143 * 5</gadget>
<output>715</output>

<gadget id="calculator">715 - 1</gadget>
<output>714</output>

<gadget id="calculator">77 + 714</gadget>
<output>791</output>

<gadget id="calculator">791 + 792 + 793</gadget>
<output>2_376</output>

<result>2_376</result>