Bu yerda Python dasturi foydalanuvchi tomonidan berilgan ma'lumotlarni so'rab, kvadrat tenglamasi uchun mumkin bo'lgan yechimlarni hisoblaydi ax^2 + bx + c = 0: ```python import cmath # A = float ((input)) " a = float ((input)) " a = float ((input b: ")) c = float ((input)) " c: " ()) # Diskriminantni hisoblash = cmath.sq ((rtb**2 - 4*a*c) # Diskriminantni hisoblash x1 = (-b + discriminant) / (2a*) x2 = (-b - discriminant) / (2a*) # Chiqarish yechimlarini bosib chiqarish f "potentsial yechimlar x1 = {x1} va x2 = {x2} ") ```python import cmath # Ushbu
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