Albatta! Bu safar, x^2 + 6x + 8 = 0 tenglamasini topish uchun kvadratlarni to'ldirish usulini qo'llayman: 1. Tenglamani (x^2 ± 2Ax + A^2) shaklida tartiblashamiz, natijada (x^2 + 2*3x + 3^2) - 1 = 0 2. Ikkala bo'g'inda qoldiq hadning qo'shma teskari qo'shamiz: (x^2 + 2*3x + 3^2) = 1 3. Birinchi bo'g'in ifodasi to'liq kvadratli trinomiy bo'lib, uni (x ± A) ^2 shakliga qisqartirish mumkin: (x + 3) ^2 = 1 4. Bu nuqtada, agar (x + 3) ifodasiga e'tibor bersak, uning kuchlanish darajasi bir juft ichida ekanligini tushunamiz. Shuning uchun (x + 3) ning eng
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