a) Avtomobillarning eng tez harakatlanadigan vaqtini topish uchun v (t) funksiyaining maksimal qiymatini [2,6] intervalida topishimiz kerak. Buning uchun v (t) funksiyaining maksimal qiymatini [2,6] intervalida topishimiz kerak va tanqidiy nuqtalarni qidirishimiz kerak: v (t) = t3 - 15t2 + 72t + 8 v' (t) = 3t2 - 30t + 72 v' (t) ni nolga tenglashtirib va tenglamani hal qilish orqali quyidagilarni olamiz: 3t2 - 30t + 72t = 0 t2 - 10t + 24 = 0 t4 - 10t + 24 = 0 (t - 4) t - 6) = 0 Shuning uchun tanqidiy nuqtalar t = 4 va t = 06. Shu sababli, ushbu nuqtalarning har biri maksimal bo'lishini aniqlash uchun v (t) funksiyaining ikkinchi hosilasini aniqlaymiz
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