$T(n) ={15n}^3+n^2+4 \\ {15n}^3+n^2+4 \le {15n}^3+n^3+{4n}^3, qachon \; x>1\\{15n}^3+n^2+4 saqlaydi \le {20n}^3 saqlaydi \\ Shunday qilib \; c=20, n_0=1$
spam fails_task lang_mismatch pii not_appropriate hate_speech sexual_content quality toxicity humor helpfulness creativity violence