Kvadratik tenglama quyidagicha: x^2 + 5x + 6 = 0 Ushbu tenglamani hal qilish uchun kvadrat formuladan foydalanamiz, ya'ni: x = (-b ± √(b^2 - 4ac)) / 2a a, b va c kvadrat tenglamaning koeffitsiyentlari bo'lgan joyda. Ushbu holatda a = 1, b = 5 va c = 6. Kvadratik formulada ushbu qiymatlarni almashtirish orqali biz quyidagilarni olamiz: x = (-5 ± √(5^2 - 41) 6))) / 2 x = (-5 ± √(25 - 24)) / 2 x = (-5 ± 1) / 2 Shuning uchun tenglamaning yechimlari quyidagicha: x1 (-5 = 1) + 2 = -2 x2 = (-5 - 1) / 2 = -3 x = -2 x = 1 va -2 x = 2 -3.
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