Albatta! Keling, f ((x) = sin (((3x ^ 2 + 2) funksiyasini ko'rib chiqaylik. Ushbu holatda g ((x) = sin ((x) va h ((x) = 3x ^ 2 + 2. zanjir qoidasidan foydalanib, f ((x) ning hosilasini quyidagicha topishimiz mumkin: f'((x) = g' (((h)) * h' ((x) = cos ((3x ^ 2 + 2) * (6x) Shunday qilib, f ((x) ning hosilasi f ((x) = 6x cos ((3 ((x ^ 2 + 2)). Bu erda biz birinchi navbatda tashqi funksiyaning hosilasini topamiz g ((x) h ((x) da baholanadi), bu cos ((3 ((x ^ 2) + 2) Keyin, biz uni x ga nisbatan h ((x) funksiyasining hosilasi bilan ko'paytiramiz, bu 6x
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