Keling, eng kichik bos son bilan boshlaymiz, ya'ni P = 2. Endi N ning eng kichik qiymatini topamiz, ya'ni N! 2^M ga bo'linadi (M musbat butun son). Bu holatda N = 2. N ning faktoriyali N! = 2! = 2, ya'ni 2^1 ga bo'linadi (M = 1). Nihoyat, A va B ning eng kichik qiymatini topamiz, ya'ni A^B > P. Agar P = 2 bo'lsa, A va B ning eng kichik qiymati A = 2 va B = 2 bo'ladi, chunki 2^2 = 4 > 2. Shunday qilib, qiymatlari quyidagicha: P = 2 N = 2 (N! = 2! = 2) A^B = 2^2 = 4
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