Ha, sizning Haskell kodingizda `factorial` funksiyasining rekursiv ta'rifi bilan bog'liq muammo bor. Xususan, satr `factorial(n) = n*(n-1) * factorial(n-2) ` noto'g'ri, chunki u `n` funksiyasi har doim toq bo'lishini taxmin qiladi, bu `n` ning ko'pchilik qiymatlari uchun emas. Faktorial funksiyani to'g'ri aniqlash uchun siz quyidagi koddan foydalanishingiz mumkin: ``` factorial 0 = 1 factorial n = n * factorial (n - 1) ``` Ushbu kod faktorial funksiyani `n = 0 ` uchun asosni boshqaradigan rekursiv yondashuvdan foydalanib ta'riflaydi, so'ngra `n-1 `n uchun asosni hisoblaydi, shunda u asosga yet
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