C++da quyidagicha amalga oshirish mumkin: int countNodes(Node* root) { if (root == NULL) return 0; return 1 + countNodes(root->left) + countNodes(root->right); } Ishtirokchiligini sinab ko'rish uchun, siz funksiyalarni minglab takrorlashlar bilan bir for-qazoqida ishga tushirishingiz mumkin, keyin sizga ish vaqtini sarflashingiz mumkin. Pythonda bspw shunday ko'rinadi: from time import perfcounter n_iter = 1000 root =... # tree #... t0 = perfcounter(for _ in range(n_iter): count_nodes(root) printf{_niter} iterations: { tookf{percounter-t0} ")
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