'''
205. Isomorphic Strings Easy

Given two strings s and t, determine if they are isomorphic.

Two strings s and t are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character, but a character may map to itself.

 

Example 1:

Input: s = "egg", t = "add"
Output: true
Example 2:

Input: s = "foo", t = "bar"
Output: false
Example 3:

Input: s = "paper", t = "title"
Output: true
 

Constraints:

1 <= s.length <= 5 * 104
t.length == s.length
s and t consist of any valid ascii character.

'''
class Solution:
    def isIsomorphic(self, s: str, t: str) -> bool:

        '''
        ascii_map {
            s.letter : t.letter
            e: a
            g: d

        }
        '''
        index = 0
        s_map = {}
        t_map = {}
        while(index < len(s)):
            s_char = s[index]
            t_char = t[index]

            if s_char in t_map:
                if t_map[s_char] != t_char:
                    return False
            else:
                t_map[s_char] = t_char
      

            if t_char in s_map:
                if s_map[t_char] != s_char:
                    return False
            else:
                s_map[t_char] = s_char

            index+=1
        return True
