<p>By knowing the position and velocity of the Sun relative to the centre of the Milky Way, and the galactic longitude/latitude of the object we are observing (in our galaxy), and the radial velocity vector, we can obtain the vector tangential to the orbit of that body by correcting for the Sun's velocity and seeing which vector projects to the measured one. You may draw a simplified model and see this is possible via some trigonometric formulae.<br> Similarly, we can correct for more velocitites and obtain the same data for other galaxies.</p>

CC BY-SA 4.0
2019-12-10T14:48:36.977Z
2019-12-10T14:48:36.977Z
Tosic
<p>A galactic rotation curve shows the speed of stars as of function of their distance to the center of the galaxy. </p>

<p>The Doppler shift data is obtained for many many stars in the galaxy. From this, you can deduce the speed of each star. You can then trace the plot with their speed compared to their distance to the center of the galaxy. If you do this, you will find that there is a general trend to the data points, where the speed of stars far from the galactic center go faster than expected. </p>

CC BY-SA 4.0
2019-12-12T15:59:07.633Z
2019-12-12T15:59:07.633Z
usernumber
<p>What do you mean by rotation curve? The orbit?</p>

<p>You can derive the theoretical tangential velocity of a body 2 on a circular orbit around body 1. For that you only need the mass of body 1 and the distance. If you know the mass of the galaxy core, you can check if the measured velocities match with it.</p>

<p>The radial velocity of a arm of a galaxy will tell you exactly the tangential velocity to the galaxy core if you look from the side of it, for example.</p>

CC BY-SA 4.0
2019-12-12T15:48:21.783Z
The rotation curve typically designates the speed of stars (or galaxies) are a function of their distance to the center of the galaxy (or galaxy cluster).
usernumber
CC BY-SA 4.0
2019-12-09T22:58:49.023Z
2019-12-09T22:58:49.023Z
Andres Huster
<p>Imagine a spiral galaxy where the rotation of gas and stars within the disk is close to circular (generally true for gas clouds, though less true for stars) in a single plane (the disk), and imagine that it is tilted at some intermediate angle with respect to your line of sight. A circular disk galaxy will then project to form an apparent ellipse, with a major axis and a minor axis (see figure).</p>

<p><a href="https://i.sstatic.net/3yFcr.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/3yFcr.png" alt="enter image description here"></a></p>

<p>If you look at points which lie along the minor axis (say, points b1 or b2), you will see stars and clouds which are moving <em>perpendicular</em> to your line of sight, so they have <em>zero</em> radial velocity relative to you, and there will be <em>no</em> Doppler shift.</p>

<p>If, instead, you look at points which lie along the <em>major</em> axis (say, points a1 or a2), your line of sight will intersect gas clouds and stars which are moving (mostly) <em>along</em> your line of sight (either towards you or away from you), so you will observe the maximum possible radial velocity and thus the maximum possible Doppler shift (either positive = velocities away from you, or negative = velocities toward you).</p>

<p>There's one further factor, which is the effect of inclination. If the galaxy is genuinely <em>face-on</em> (inclination <span class="math-container">$i = 0$</span>), then you won't seem any Doppler shifts, because all the motion is in the plane of the sky, perpendicular to your line of sight. (In practice there will really be <em>some</em> motions up and down with respect to the galaxy plane, but this won't tell you about the rotation curve.) If the galaxy is <em>edge-on</em>, then you get the maximum possible Doppler shift, which gives you the rotation velocity <span class="math-container">$V$</span> directly. If the galaxy has an in-between inclination, then the radial velocity is the part of the cloud/star velocity in the direction of your line of sight, which is <span class="math-container">$V \sin i$</span>. So if you can determine the galaxy's inclination, you can divide the <em>observed</em> velocity along the major axis by <span class="math-container">$\sin i$</span> to get <span class="math-container">$V$</span>.</p>

<p>Up until relatively recently, the practice (in optical astronomy) was to use a long-slit spectrograph and orient it so that the slit lies along the galaxy's major axis. Then at each point along the major axis, from the center outward, you measure the Doppler shift, apply the <span class="math-container">$\sin i$</span> inclination correction, and then you have the rotation curve: <span class="math-container">$V$</span> as a function of radius <span class="math-container">$r$</span> along the major axis.</p>

<p>If you have fully two-dimensional spectroscopy (e.g., from a radio telescope interferometric array observing emission from atomic hydrogen or molecular gas, or an optical or infrared integral field spectrograph), then you can use the data at intermediate locations within the disk (not just along the major axis), where the observed velocity is <span class="math-container">$= V \sin i \cos \alpha$</span>, where <span class="math-container">$\alpha$</span> is the angle between the major axis and the location you're looking at (so for locations <em>on</em> the major axis, the observed velocity is just <span class="math-container">$V \sin i$</span>). Then you can fit a model to the set of observed velocities (which you get from the Doppler shifts) and work out <span class="math-container">$V$</span> as a function of radius. (The standard approach is called a "tilted ring" model, where you assume the velocity is a simple function of radius, but allow for the possibility that the disk might be warped, so that the orientation -- including the inclination -- might change with radius.)</p>

CC BY-SA 4.0
2020-03-02T09:43:29.767Z
fyi I've just asked [Is there still a red shift when moving perpendicular to the direction of incidence?](https://astronomy.stackexchange.com/q/35382/7982)
uhoh
CC BY-SA 4.0
2019-12-16T15:23:50.583Z
2020-01-13T13:19:09.993Z
2020-01-13T13:19:09.993Z
Peter Erwin
<p>I have been reading about the deviation of galactic rotation curves from the predicted Keplerian curve to a flat curve at large galactocentric distances.</p>

<p>They were the first indicators of the existence of dark matter but I do not understand how the curve is obtained from Doppler shift data (as mentioned by some papers as the method of determination for the curve.)</p>

<p>Doppler shift data would allow measurement of radial velocity but how can that alone be enough to extrapolate the rotation curve?</p>

<galaxy><rotation><dark-matter>
How are galactic rotation curves determined from radial velocity measurements?
Khurana
# How are galactic rotation curves determined from radial velocity measurements?

(Asked by: username_0 on 2019-12-09)

I have been reading about the deviation of galactic rotation curves from the predicted Keplerian curve to a flat curve at large galactocentric distances.

They were the first indicators of the existence of dark matter but I do not understand how the curve is obtained from Doppler shift data (as mentioned by some papers as the method of determination for the curve.)

Doppler shift data would allow measurement of radial velocity but how can that alone be enough to extrapolate the rotation curve?

**Tags:** galaxy, rotation, dark-matter

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## 4 answers

### Answer by username_4 on 2019-12-16. Score: 5 | Accepted answer

Imagine a spiral galaxy where the rotation of gas and stars within the disk is close to circular (generally true for gas clouds, though less true for stars) in a single plane (the disk), and imagine that it is tilted at some intermediate angle with respect to your line of sight. A circular disk galaxy will then project to form an apparent ellipse, with a major axis and a minor axis (see figure).

[![enter image description here](https://i.sstatic.net/3yFcr.png)](https://i.sstatic.net/3yFcr.png)

If you look at points which lie along the minor axis (say, points b1 or b2), you will see stars and clouds which are moving *perpendicular* to your line of sight, so they have *zero* radial velocity relative to you, and there will be *no* Doppler shift.

If, instead, you look at points which lie along the *major* axis (say, points a1 or a2), your line of sight will intersect gas clouds and stars which are moving (mostly) *along* your line of sight (either towards you or away from you), so you will observe the maximum possible radial velocity and thus the maximum possible Doppler shift (either positive = velocities away from you, or negative = velocities toward you).

There's one further factor, which is the effect of inclination. If the galaxy is genuinely *face-on* (inclination $i = 0$), then you won't seem any Doppler shifts, because all the motion is in the plane of the sky, perpendicular to your line of sight. (In practice there will really be *some* motions up and down with respect to the galaxy plane, but this won't tell you about the rotation curve.) If the galaxy is *edge-on*, then you get the maximum possible Doppler shift, which gives you the rotation velocity $V$ directly. If the galaxy has an in-between inclination, then the radial velocity is the part of the cloud/star velocity in the direction of your line of sight, which is $V \sin i$. So if you can determine the galaxy's inclination, you can divide the *observed* velocity along the major axis by $\sin i$ to get $V$.

Up until relatively recently, the practice (in optical astronomy) was to use a long-slit spectrograph and orient it so that the slit lies along the galaxy's major axis. Then at each point along the major axis, from the center outward, you measure the Doppler shift, apply the $\sin i$ inclination correction, and then you have the rotation curve: $V$ as a function of radius $r$ along the major axis.

If you have fully two-dimensional spectroscopy (e.g., from a radio telescope interferometric array observing emission from atomic hydrogen or molecular gas, or an optical or infrared integral field spectrograph), then you can use the data at intermediate locations within the disk (not just along the major axis), where the observed velocity is $= V \sin i \cos \alpha$, where $\alpha$ is the angle between the major axis and the location you're looking at (so for locations *on* the major axis, the observed velocity is just $V \sin i$). Then you can fit a model to the set of observed velocities (which you get from the Doppler shifts) and work out $V$ as a function of radius. (The standard approach is called a "tilted ring" model, where you assume the velocity is a simple function of radius, but allow for the possibility that the disk might be warped, so that the orientation -- including the inclination -- might change with radius.)

> **Comments:**
> **username_5**: fyi I've just asked [Is there still a red shift when moving perpendicular to the direction of incidence?](https://astronomy.stackexchange.com/q/35382/7982)  

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### Answer by username_1 on 2019-12-10. Score: 1

By knowing the position and velocity of the Sun relative to the centre of the Milky Way, and the galactic longitude/latitude of the object we are observing (in our galaxy), and the radial velocity vector, we can obtain the vector tangential to the orbit of that body by correcting for the Sun's velocity and seeing which vector projects to the measured one. You may draw a simplified model and see this is possible via some trigonometric formulae.  
 Similarly, we can correct for more velocitites and obtain the same data for other galaxies.


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### Answer by username_2 on 2019-12-12. Score: 1

A galactic rotation curve shows the speed of stars as of function of their distance to the center of the galaxy.

The Doppler shift data is obtained for many many stars in the galaxy. From this, you can deduce the speed of each star. You can then trace the plot with their speed compared to their distance to the center of the galaxy. If you do this, you will find that there is a general trend to the data points, where the speed of stars far from the galactic center go faster than expected.


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### Answer by username_3 on 2019-12-09. Score: -1

What do you mean by rotation curve? The orbit?

You can derive the theoretical tangential velocity of a body 2 on a circular orbit around body 1. For that you only need the mass of body 1 and the distance. If you know the mass of the galaxy core, you can check if the measured velocities match with it.

The radial velocity of a arm of a galaxy will tell you exactly the tangential velocity to the galaxy core if you look from the side of it, for example.

> **Comments:**
> **username_2**: The rotation curve typically designates the speed of stars (or galaxies) are a function of their distance to the center of the galaxy (or galaxy cluster).  

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