<p><a href="https://astronomy.stackexchange.com/questions/36488/is-venus-in-some-waytidally-locked-to-earth#comment72541_36488">@BMF's comment</a> links to (Gold &amp; Soter 1969) Icarus 11, (3), November 1969, pp 356-366 <a href="https://www.sciencedirect.com/science/article/pii/0019103569900682" rel="noreferrer">Atmospheric tides and the resonant rotation of Venus</a>. Since it is paywalled I'll add a short summary:</p>

<p>From the abstract:</p>

<blockquote>
  <p>The observed spin-orbit resonance of Venus, whereby the same side of Venus faces the Earth at each inferior conjunction, cannot be explained adequately by gravitational interaction with the Earth alone. The expected solar tidal drag on the solid body of Venus would easily overwhelm the Earth's couple upon any reasonable permanent deformation of Venus. If there exists, however, a solar atmospheric tide, partly thermally induced and similar to that known on the Earth, its torque may counteract that due to the solar solid body tide at a particular rotation period. The small interaction with the Earth is then sufficient to lock the period to one of the resonances in the vicinity of that angular velocity.</p>
</blockquote>

<p>The paper explains that if Venus' <span class="math-container">$J_{22}$</span> (transverse gravitational quadrupole moment) were about the same magnitude as Earth's it would be far too weak for this synchrony to be induced by gravitational interaction between these two planets because the tidal forces from the Sun would overwhelm the effect:</p>

<blockquote>
  <p>The spin-orbit resonance between the two planets is undoubtedly due to the action of the Earth upon the net permanent de- formation (or transverse quadrupole moment) of Venus. But in order for this rather weak torque, which is significant only near inferior conjunction, to overcome the constant drag of solar tidal friction on the body of Venus, the permanent quadrupole moment required for Venus would have to be at least an order of magnitude larger than comparison with the Earth would suggest. </p>
</blockquote>

<p>It then proposes that the tidal interaction with the Sun might be coincidentally cancelled by torque from Venus' atmospheric tidal effects. The paper discusses the history of understanding of transfer of angular momentum from a planets atmospheric tides to the planet itself:</p>

<blockquote>
  <p>It was first shown by Lord Kelvin (Thompson, 1882) that the Earth's atmospheric tides transfer angular momentum and energy from the orbit to the rotation and tend to accelerate the latter. Holmberg (1952) suggested that the associated production of mechanical energy might be sufficient to balance the dissipation of oceanic and solid body tides, so that the Earth's present rotation rate would be one of stable equilibrium over geological time. Subsequent studies, however, appear to confirm the older view that the Earth is in fact slowing down; i.e., that the energy loss in conventional tides exceeds the input through atmospheric tides. Nevertheless, the notion that a planet's rotation rate might be stabilized in the balance between the opposing two kinds of tides is perhaps the key to the resonant rotation of Venus.</p>
</blockquote>

<p>and concludes (in 1969) that this is probably what's happening. This is the extent of my answer, certainly in the fifty years since this paper it's been looked at in greater detail, but as far as I can tell there are no competing theories.</p>

<p><strong>Update:</strong> The problem was also addressed by (Ingersoll and Dobrovolskis  1978) in <a href="https://www.nature.com/articles/275037a0.pdf" rel="noreferrer">Venus' rotation and atmospheric tides</a> and by (Bills 2005) <a href="https://agupubs.onlinelibrary.wiley.com/doi/pdf/10.1029/2003JE002190" rel="noreferrer">Variations in the rotation rate of Venus due to orbital eccentricity modulation of solar tidal torques</a> J. Geophys. Res. 110, E11007</p>

<p>More recently Auclair-Desrotour, Laskar &amp; Mathis (2017) <a href="https://www.aanda.org/articles/aa/full_html/2017/07/aa28252-16/aa28252-16.html" rel="noreferrer">Atmospheric tides in Earth-like planets</a> A&amp;A 603, A107 have addressed the general topic in great detail and Venus is examined in great detail, but I can't tell if they address this subject directly or not. </p>

<hr>

<p>The paper also describes the rapidly evolving studies of Venus by Earth-based radar observation in the 1960's such that by 1969 Venus' apparent synchronicity became obvious at about the same time the Moon landings began. Radar studies of Venus started early, as discussed in </p>

<ul>
<li><a href="https://space.stackexchange.com/q/30346/12102">When did planetary scientists realize Venus' surface pressure was almost 100x that on Earth? How did they find out?</a></li>
<li><a href="https://space.stackexchange.com/q/30430/12102">How was the radius of Venus measured so accurately (± 3 km) via radar in the mid 1960's, before Venera 4 and Mariner 5?</a></li>
</ul>

<p><a href="https://i.sstatic.net/Dg3af.png" rel="noreferrer"><img src="https://i.sstatic.net/Dg3af.png" alt="Radar determination of the retrograde sidereal period of Venus"></a></p>

<blockquote>
  <p>FIG. 1. Radar determination of the retrograde sidereal period of Venus. With increasing accur- acy, the values have converged toward the reson- ant period of --243.16 days. The next nearest resonant periods are at -201 and -308 days. Figure adapted from Eshleman (1967); see also Shapiro (1967).</p>
</blockquote>

CC BY-SA 4.0
2020-06-10T06:00:04.897Z
2020-06-10T08:55:49.573Z
2020-06-10T08:55:49.573Z
uhoh
<p>This is a fun little problem that's remarkably close and the math is pretty easy when you use the right periods.</p>

<p>Venus' synodic period, relative to Earth, is 583.92 days on average.  He uses 584, but lets strive for accuracy.  Venus' solar day is 116.75 days, so 5 solar days is 583.75 days - Venus does 5 rotations in nearly the same amount of time that Earth and Venus line up together.  </p>

<p>More details below:</p>

<p>Eccentricity in this case, doesn't matter, so, even though Earth will move different amounts in those 218 days past the first full year, it's the average that matters.</p>

<p>A cool property of tidal locking is that the locked objects can move ahead or behind and it doesn't undo the locking.  For example, our Moon is tidally locked but its eccentricity still creates <a href="https://earthsky.org/astronomy-essentials/how-much-of-the-moon-can-we-see-from-earth-lunar-libration" rel="noreferrer">libration</a>.   Pluto can move ahead of or fall behind its 3/2 resonance with Neptune, but Neptune's gravity draws it back, so it never laps the 3/2 resonance.  It stays locked. All we need is the average synodic period, or 583.92 days.  </p>

<p>.03% is closer than many tidally locked objects' periods can be, but that doesn't mean they're tidally locked.  One can still lap the other.</p>

<p>We know it's coincidence because orbital periods, which determine the 583.92 ratio, are highly stable and Venus' orbital period might change very slowly, but only very slowly.   </p>

<p>The variation is a little under .03% or 3 parts in 10,000.   It's close enough that we might want to get more decimal points to get more accuracy, but that's where I run into some problems.    I can't find any more decimal points to Venus' solar day, just 116.75 days or 2802 hours.  No mention of fractions of hours.</p>

<p>His numbers on the video looked wrong to me at first, but he uses sidereal year, not the more familiar tropical year.  Most of us think of an Earth year as 365.2422 days, not 365.256 or 365.26 as he writes on his video.  I don't think it makes a big difference which we use, tropical or sidereal years.  That only changes the numbers slightly.  Both still fall to about 3 parts in 10,000.</p>

<p>His numbers posted on the video:</p>

<p>Earth Orbit:   365.26 days*<br>
Venus Orbit:   224.70 days<br>
Earth/Venus closest:   584 days</p>

<p>Venus Sidereal day:  243.03 days<br>
Venus Solar day:  116.75 days</p>

<p><a href="https://web.archive.org/web/20160304130722/http://nssdc.gsfc.nasa.gov/planetary/factsheet/venusfact.html" rel="noreferrer">Numbers I used</a></p>

<p>Footnote:   @BMF posted a research paper that says Earth may have an effect on Venus' rotation speed - <a href="https://www.sciencedirect.com/science/article/abs/pii/0019103569900682" rel="noreferrer">copied here</a>.   I'm going to leave my "it's coincidence" comments above, because it seems more likely to me that it's coincidence, but maybe I'm wrong.</p>

CC BY-SA 4.0
2020-06-10T06:15:17.213Z
It's appropriate to use sidereal years here, since we're comparing the positions of Venus & Earth relative to the "fixed" stars. We aren't concerned about the precession of the Earth's equinoxes.
PM 2Ring
CC BY-SA 4.0
2020-06-10T07:31:49.553Z
@PM2Ring Thank you for that.  I couldn't quite work it out, but that makes sense.
userLTK
CC BY-SA 4.0
2020-06-10T05:48:29.597Z
2020-06-11T20:49:22.527Z
2020-06-11T20:49:22.527Z
userLTK
<p>According to <a href="https://en.wikipedia.org/wiki/Orbital_resonance#Coincidental_%27near%27_ratios_of_mean_motion" rel="nofollow noreferrer">Wikipedia</a>, the orbital relationship between Venus and the Earth is coincidental and not because they are locked in a true orbital resonance, but it <em>may</em> be due to a true resonance in the past, or the system may be evolving toward a resonance in the future.</p>
<blockquote>
<p>A number of near-integer-ratio relationships between the orbital frequencies of the planets or major moons are sometimes pointed out (see list below). However, these have no dynamical significance because there is no appropriate precession of perihelion or other libration to make the resonance perfect (see the detailed discussion in the section above). Such near resonances are dynamically insignificant even if the mismatch is quite small because (unlike a true resonance), after each cycle the relative position of the bodies shifts. When averaged over astronomically short timescales, their relative position is random, just like bodies that are nowhere near resonance.</p>
<p>For example, consider the orbits of Earth and Venus, which arrive at almost the same configuration after 8 Earth orbits and 13 Venus orbits. The actual ratio is 0.61518624, which is only 0.032% away from exactly 8:13. The mismatch after 8 years is only 1.5° of Venus' orbital movement. Still, this is enough that Venus and Earth find themselves in the opposite relative orientation to the original every 120 such cycles, which is 960 years. Therefore, on timescales of thousands of years or more (still tiny by astronomical standards), their relative position is effectively random.</p>
<p>The presence of a near resonance may reflect that a perfect resonance existed in the past, or that the system is evolving towards one in the future.</p>
</blockquote>
<p>Here's a relevant diagram from the same article:</p>
<p><a href="https://i.sstatic.net/P4fyN.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/P4fyN.png" alt="Earth-Venus near-resonance" /></a></p>
<blockquote>
<p>Depiction of the Earth:Venus 8:13 near resonance. With Earth held stationary at the center of a nonrotating frame, the successive inferior conjunctions of Venus over eight Earth years trace a pentagrammic pattern (reflecting the difference between the numbers in the ratio).</p>
</blockquote>
<p>This &quot;near-resonance&quot; means that <a href="https://en.wikipedia.org/wiki/Transit_of_Venus" rel="nofollow noreferrer">transits of Venus</a> occur in a regular pattern:</p>
<blockquote>
<p>Transits of Venus are among the rarest of predictable astronomical phenomena. They occur in a pattern that generally repeats every 243 years, with pairs of transits eight years apart separated by long gaps of 121.5 years and 105.5 years. The periodicity is a reflection of the fact that the orbital periods of Earth and Venus are close to 8:13 and 243:395 commensurabilities.</p>
</blockquote>
<p>Here's a similar diagram, produced using my 3D orbit plotter script, which is linked at the end of <a href="https://astronomy.stackexchange.com/a/49823/16685">this answer</a>. It covers the timespan between the two most recent transits of Venus, in early June 2004 and 2012, with a 7 day timestep, and 1 year between numeric labels.</p>
<p><a href="https://i.sstatic.net/qCPvN.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/qCPvN.png" alt="Venus relative to Earth" /></a></p>
<hr />
<p>There <em>are</em> several examples of true orbital resonance in the solar system. The most well-known involves the Jovian moons, Ganymede, Europa, and Io.</p>
<p><a href="https://i.sstatic.net/VYajW.gif" rel="nofollow noreferrer"><img src="https://i.sstatic.net/VYajW.gif" alt="Galilean moon orbital resonance" /></a></p>
<blockquote>
<p>The three-body Laplace resonance exhibited by three of Jupiter's Galilean moons. Conjunctions are highlighted by brief color changes. There are two Io-Europa conjunctions (green) and three Io-Ganymede conjunctions (grey) for each Europa-Ganymede conjunction (magenta).</p>
</blockquote>
<p>Please see the Wikipedia article on <a href="https://en.wikipedia.org/wiki/Orbital_resonance" rel="nofollow noreferrer">orbital resonance</a> for further details.</p>

CC BY-SA 4.0
2020-06-10T05:50:19.497Z
I had to think about this one, but the 13:8 ratio doesn't matter for this question.   Only the 584 to 116.75 ratio of synodic period to Venus' solar day.    Basically 5 to 1.
userLTK
CC BY-SA 4.0
2020-06-10T06:10:13.820Z
@userLTK Yes, I'm only talking about the near-resonance between Earth & Venus's orbital period. The rotation period of Venus can't really be tidally locked to Earth if its orbit isn't resonant. Besides, the tidal force (which is proportional to $\frac1{r^3}$) between Earth & Venus is tiny.
PM 2Ring
CC BY-SA 4.0
2020-06-11T13:48:12.320Z
Just as an aside the almost but not quite 8:13 ratio of the Earth to venus's orbital periods explains why transits of Vednus normally occur in pair 8 years apart (e.g. there were transits 2004, 2012) but after the second transit in the pair there isn't a third (e.g there won't be transit in 2020)
John Davies
CC BY-SA 4.0
2020-06-12T16:35:39.810Z
@JohnDavies the actual reason that there's no third transit in each pair is that a pair contains two items.  (Cart, horse, sarcasm.)
phoog
CC BY-SA 4.0
2023-08-16T05:42:05.357Z
Here's a Sage script that plots the simplified trajectory of Venus relative to Earth, assuming that both orbits are circular, with the period ratio exactly 8/13 https://sagecell.sagemath.org/?z=eJxFkMFuwyAQRO-W_A8r9xAc0cRJpCiqxLH3qLV6bETxOiYiYK3X7u8X7ETlBDNv2IEX-LT33tnWYgOBfixDaOEL_TgAodNsJwQO8K6JuzybNIkVr8o8y7MGW-iDiwpJqMu3PIO4uAMFDFuolzMhj-SBYA0TGg4khAmD4K6UMFifNuV8XT3NQxWcYnh3yLOPp_BwvkHst4eZxdQmOsv4nYRdlJ_4Ii5p-QhHux29ie5CvQIuD8qzc4po0ndksubSu8AisRIES6gk7Ne9je1PpUwvMsEFUsWVEH0hIeGXPljPgzpW1YzoRvfp3y4cHJL2BlW1qaq9_HcIzUiDDV4dY7XzZujCr2hTCVXTiBKuZBtnPQ6quOtboKL8A7rqgPQ=&lang=sage
PM 2Ring
CC BY-SA 4.0
2020-06-10T04:08:46.220Z
2023-08-15T05:36:15.080Z
2023-08-15T05:36:15.080Z
PM 2Ring
<p>The video here demonstrates how Earth sees the same face of Venus every inferior conjunction (i.e., two planets are the closest to each other):</p>

<p><a href="https://www.youtube.com/watch?v=4m_ouMC61-w" rel="noreferrer">https://www.youtube.com/watch?v=4m_ouMC61-w</a> (or <a href="https://twitter.com/physicsJ/status/1263402883275386880" rel="noreferrer">https://twitter.com/physicsJ/status/1263402883275386880</a>)</p>

<p>This might be caused by some kind of tidal locking, or it might be a coincidence. Does this type of gravitational resonance exist, either in theory or in the wild (e.g., between moons of Jupiter or Saturn)?</p>

CC BY-SA 4.0
2020-06-09T23:17:23.097Z
I think it might be coincidence. Venus is way outside Earth's Hill sphere, so the Sun's gravity dominates. If it is a pure coincidence, it's a mighty strange one.
BMF
CC BY-SA 4.0
2020-06-09T23:30:19.053Z
Commenters on the tweet you link seem to think it has something to do with Earth's small gravitational torque at each inferior. Can't seem to find any supporting evidence or research though, besides maybe [this](https://www.sciencedirect.com/science/article/abs/pii/0019103569900682).
BMF
CC BY-SA 4.0
2020-06-10T13:46:35.600Z
I think the more general term for such phenomena is "resonance."
Ohm's Lawman
CC BY-SA 4.0
2023-06-16T19:13:19.920Z
Isn't this phenomenon because of very long (243 days) days on Venus? Well, Venus is so slow on its axis. May be this is responsible for it facing the same side at inferior conjuctions.
Snack Exchange
<venus><celestial-mechanics>
Is Venus in some way tidally locked to... Earth?
puzzlet
# Is Venus in some way tidally locked to... Earth?

(Asked by: username_0 on 2020-06-09)

The video here demonstrates how Earth sees the same face of Venus every inferior conjunction (i.e., two planets are the closest to each other):

<https://www.youtube.com/watch?v=4m_ouMC61-w> (or <https://twitter.com/physicsJ/status/1263402883275386880>)

This might be caused by some kind of tidal locking, or it might be a coincidence. Does this type of gravitational resonance exist, either in theory or in the wild (e.g., between moons of Jupiter or Saturn)?

**Tags:** venus, celestial-mechanics
> **Comments:**
> **username_1**: I think it might be coincidence. Venus is way outside Earth's Hill sphere, so the Sun's gravity dominates. If it is a pure coincidence, it's a mighty strange one.  
> **username_1**: Commenters on the tweet you link seem to think it has something to do with Earth's small gravitational torque at each inferior. Can't seem to find any supporting evidence or research though, besides maybe [this](https://www.sciencedirect.com/science/article/abs/pii/0019103569900682).  
> **username_2**: I think the more general term for such phenomena is "resonance."  
> **username_3**: Isn't this phenomenon because of very long (243 days) days on Venus? Well, Venus is so slow on its axis. May be this is responsible for it facing the same side at inferior conjuctions.  

---

## 3 answers

### Answer by username_4 on 2020-06-10. Score: 29

[@BMF's comment](https://astronomy.stackexchange.com/questions/36488/is-venus-in-some-waytidally-locked-to-earth#comment72541_36488) links to (Gold & Soter 1969) Icarus 11, (3), November 1969, pp 356-366 [Atmospheric tides and the resonant rotation of Venus](https://www.sciencedirect.com/science/article/pii/0019103569900682). Since it is paywalled I'll add a short summary:

From the abstract:

> The observed spin-orbit resonance of Venus, whereby the same side of Venus faces the Earth at each inferior conjunction, cannot be explained adequately by gravitational interaction with the Earth alone. The expected solar tidal drag on the solid body of Venus would easily overwhelm the Earth's couple upon any reasonable permanent deformation of Venus. If there exists, however, a solar atmospheric tide, partly thermally induced and similar to that known on the Earth, its torque may counteract that due to the solar solid body tide at a particular rotation period. The small interaction with the Earth is then sufficient to lock the period to one of the resonances in the vicinity of that angular velocity.

The paper explains that if Venus' $J\_{22}$ (transverse gravitational quadrupole moment) were about the same magnitude as Earth's it would be far too weak for this synchrony to be induced by gravitational interaction between these two planets because the tidal forces from the Sun would overwhelm the effect:

> The spin-orbit resonance between the two planets is undoubtedly due to the action of the Earth upon the net permanent de- formation (or transverse quadrupole moment) of Venus. But in order for this rather weak torque, which is significant only near inferior conjunction, to overcome the constant drag of solar tidal friction on the body of Venus, the permanent quadrupole moment required for Venus would have to be at least an order of magnitude larger than comparison with the Earth would suggest.

It then proposes that the tidal interaction with the Sun might be coincidentally cancelled by torque from Venus' atmospheric tidal effects. The paper discusses the history of understanding of transfer of angular momentum from a planets atmospheric tides to the planet itself:

> It was first shown by Lord Kelvin (Thompson, 1882) that the Earth's atmospheric tides transfer angular momentum and energy from the orbit to the rotation and tend to accelerate the latter. Holmberg (1952) suggested that the associated production of mechanical energy might be sufficient to balance the dissipation of oceanic and solid body tides, so that the Earth's present rotation rate would be one of stable equilibrium over geological time. Subsequent studies, however, appear to confirm the older view that the Earth is in fact slowing down; i.e., that the energy loss in conventional tides exceeds the input through atmospheric tides. Nevertheless, the notion that a planet's rotation rate might be stabilized in the balance between the opposing two kinds of tides is perhaps the key to the resonant rotation of Venus.

and concludes (in 1969) that this is probably what's happening. This is the extent of my answer, certainly in the fifty years since this paper it's been looked at in greater detail, but as far as I can tell there are no competing theories.

**Update:** The problem was also addressed by (Ingersoll and Dobrovolskis 1978) in [Venus' rotation and atmospheric tides](https://www.nature.com/articles/275037a0.pdf) and by (Bills 2005) [Variations in the rotation rate of Venus due to orbital eccentricity modulation of solar tidal torques](https://agupubs.onlinelibrary.wiley.com/doi/pdf/10.1029/2003JE002190) J. Geophys. Res. 110, E11007

More recently Auclair-Desrotour, Laskar & Mathis (2017) [Atmospheric tides in Earth-like planets](https://www.aanda.org/articles/aa/full_html/2017/07/aa28252-16/aa28252-16.html) A&A 603, A107 have addressed the general topic in great detail and Venus is examined in great detail, but I can't tell if they address this subject directly or not.

---

The paper also describes the rapidly evolving studies of Venus by Earth-based radar observation in the 1960's such that by 1969 Venus' apparent synchronicity became obvious at about the same time the Moon landings began. Radar studies of Venus started early, as discussed in

* [When did planetary scientists realize Venus' surface pressure was almost 100x that on Earth? How did they find out?](https://space.stackexchange.com/q/30346/12102)
* [How was the radius of Venus measured so accurately (± 3 km) via radar in the mid 1960's, before Venera 4 and Mariner 5?](https://space.stackexchange.com/q/30430/12102)

[![Radar determination of the retrograde sidereal period of Venus](https://i.sstatic.net/Dg3af.png)](https://i.sstatic.net/Dg3af.png)

> FIG. 1. Radar determination of the retrograde sidereal period of Venus. With increasing accur- acy, the values have converged toward the reson- ant period of --243.16 days. The next nearest resonant periods are at -201 and -308 days. Figure adapted from Eshleman (1967); see also Shapiro (1967).


---

### Answer by username_5 on 2020-06-10. Score: 16

This is a fun little problem that's remarkably close and the math is pretty easy when you use the right periods.

Venus' synodic period, relative to Earth, is 583.92 days on average. He uses 584, but lets strive for accuracy. Venus' solar day is 116.75 days, so 5 solar days is 583.75 days - Venus does 5 rotations in nearly the same amount of time that Earth and Venus line up together.

More details below:

Eccentricity in this case, doesn't matter, so, even though Earth will move different amounts in those 218 days past the first full year, it's the average that matters.

A cool property of tidal locking is that the locked objects can move ahead or behind and it doesn't undo the locking. For example, our Moon is tidally locked but its eccentricity still creates [libration](https://earthsky.org/astronomy-essentials/how-much-of-the-moon-can-we-see-from-earth-lunar-libration). Pluto can move ahead of or fall behind its 3/2 resonance with Neptune, but Neptune's gravity draws it back, so it never laps the 3/2 resonance. It stays locked. All we need is the average synodic period, or 583.92 days.

.03% is closer than many tidally locked objects' periods can be, but that doesn't mean they're tidally locked. One can still lap the other.

We know it's coincidence because orbital periods, which determine the 583.92 ratio, are highly stable and Venus' orbital period might change very slowly, but only very slowly.

The variation is a little under .03% or 3 parts in 10,000. It's close enough that we might want to get more decimal points to get more accuracy, but that's where I run into some problems. I can't find any more decimal points to Venus' solar day, just 116.75 days or 2802 hours. No mention of fractions of hours.

His numbers on the video looked wrong to me at first, but he uses sidereal year, not the more familiar tropical year. Most of us think of an Earth year as 365.2422 days, not 365.256 or 365.26 as he writes on his video. I don't think it makes a big difference which we use, tropical or sidereal years. That only changes the numbers slightly. Both still fall to about 3 parts in 10,000.

His numbers posted on the video:

Earth Orbit: 365.26 days\*  
Venus Orbit: 224.70 days  
Earth/Venus closest: 584 days

Venus Sidereal day: 243.03 days  
Venus Solar day: 116.75 days

[Numbers I used](https://web.archive.org/web/20160304130722/http://nssdc.gsfc.nasa.gov/planetary/factsheet/venusfact.html)

Footnote: @BMF posted a research paper that says Earth may have an effect on Venus' rotation speed - [copied here](https://www.sciencedirect.com/science/article/abs/pii/0019103569900682). I'm going to leave my "it's coincidence" comments above, because it seems more likely to me that it's coincidence, but maybe I'm wrong.

> **Comments:**
> **username_6**: It's appropriate to use sidereal years here, since we're comparing the positions of Venus & Earth relative to the "fixed" stars. We aren't concerned about the precession of the Earth's equinoxes.  
> **username_5**: @PM2Ring Thank you for that.  I couldn't quite work it out, but that makes sense.  

---

### Answer by username_6 on 2020-06-10. Score: 12

According to [Wikipedia](https://en.wikipedia.org/wiki/Orbital_resonance#Coincidental_%27near%27_ratios_of_mean_motion), the orbital relationship between Venus and the Earth is coincidental and not because they are locked in a true orbital resonance, but it *may* be due to a true resonance in the past, or the system may be evolving toward a resonance in the future.

> A number of near-integer-ratio relationships between the orbital frequencies of the planets or major moons are sometimes pointed out (see list below). However, these have no dynamical significance because there is no appropriate precession of perihelion or other libration to make the resonance perfect (see the detailed discussion in the section above). Such near resonances are dynamically insignificant even if the mismatch is quite small because (unlike a true resonance), after each cycle the relative position of the bodies shifts. When averaged over astronomically short timescales, their relative position is random, just like bodies that are nowhere near resonance.
>
> For example, consider the orbits of Earth and Venus, which arrive at almost the same configuration after 8 Earth orbits and 13 Venus orbits. The actual ratio is 0.61518624, which is only 0.032% away from exactly 8:13. The mismatch after 8 years is only 1.5° of Venus' orbital movement. Still, this is enough that Venus and Earth find themselves in the opposite relative orientation to the original every 120 such cycles, which is 960 years. Therefore, on timescales of thousands of years or more (still tiny by astronomical standards), their relative position is effectively random.
>
> The presence of a near resonance may reflect that a perfect resonance existed in the past, or that the system is evolving towards one in the future.

Here's a relevant diagram from the same article:

[![Earth-Venus near-resonance](https://i.sstatic.net/P4fyN.png)](https://i.sstatic.net/P4fyN.png)

> Depiction of the Earth:Venus 8:13 near resonance. With Earth held stationary at the center of a nonrotating frame, the successive inferior conjunctions of Venus over eight Earth years trace a pentagrammic pattern (reflecting the difference between the numbers in the ratio).

This "near-resonance" means that [transits of Venus](https://en.wikipedia.org/wiki/Transit_of_Venus) occur in a regular pattern:

> Transits of Venus are among the rarest of predictable astronomical phenomena. They occur in a pattern that generally repeats every 243 years, with pairs of transits eight years apart separated by long gaps of 121.5 years and 105.5 years. The periodicity is a reflection of the fact that the orbital periods of Earth and Venus are close to 8:13 and 243:395 commensurabilities.

Here's a similar diagram, produced using my 3D orbit plotter script, which is linked at the end of [this answer](https://astronomy.stackexchange.com/a/49823/16685). It covers the timespan between the two most recent transits of Venus, in early June 2004 and 2012, with a 7 day timestep, and 1 year between numeric labels.

[![Venus relative to Earth](https://i.sstatic.net/qCPvN.png)](https://i.sstatic.net/qCPvN.png)

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There *are* several examples of true orbital resonance in the solar system. The most well-known involves the Jovian moons, Ganymede, Europa, and Io.

[![Galilean moon orbital resonance](https://i.sstatic.net/VYajW.gif)](https://i.sstatic.net/VYajW.gif)

> The three-body Laplace resonance exhibited by three of Jupiter's Galilean moons. Conjunctions are highlighted by brief color changes. There are two Io-Europa conjunctions (green) and three Io-Ganymede conjunctions (grey) for each Europa-Ganymede conjunction (magenta).

Please see the Wikipedia article on [orbital resonance](https://en.wikipedia.org/wiki/Orbital_resonance) for further details.

> **Comments:**
> **username_5**: I had to think about this one, but the 13:8 ratio doesn't matter for this question.   Only the 584 to 116.75 ratio of synodic period to Venus' solar day.    Basically 5 to 1.  
> **username_6**: @userLTK Yes, I'm only talking about the near-resonance between Earth & Venus's orbital period. The rotation period of Venus can't really be tidally locked to Earth if its orbit isn't resonant. Besides, the tidal force (which is proportional to $\frac1{r^3}$) between Earth & Venus is tiny.  
> **username_7**: Just as an aside the almost but not quite 8:13 ratio of the Earth to venus's orbital periods explains why transits of Vednus normally occur in pair 8 years apart (e.g. there were transits 2004, 2012) but after the second transit in the pair there isn't a third (e.g there won't be transit in 2020)  
> **username_8**: @JohnDavies the actual reason that there's no third transit in each pair is that a pair contains two items.  (Cart, horse, sarcasm.)  
> **username_6**: Here's a Sage script that plots the simplified trajectory of Venus relative to Earth, assuming that both orbits are circular, with the period ratio exactly 8/13 https://sagecell.sagemath.org/?z=eJxFkMFuwyAQRO-W_A8r9xAc0cRJpCiqxLH3qLV6bETxOiYiYK3X7u8X7ETlBDNv2IEX-LT33tnWYgOBfixDaOEL_TgAodNsJwQO8K6JuzybNIkVr8o8y7MGW-iDiwpJqMu3PIO4uAMFDFuolzMhj-SBYA0TGg4khAmD4K6UMFifNuV8XT3NQxWcYnh3yLOPp_BwvkHst4eZxdQmOsv4nYRdlJ_4Ii5p-QhHux29ie5CvQIuD8qzc4po0ndksubSu8AisRIES6gk7Ne9je1PpUwvMsEFUsWVEH0hIeGXPljPgzpW1YzoRvfp3y4cHJL2BlW1qaq9_HcIzUiDDV4dY7XzZujCr2hTCVXTiBKuZBtnPQ6quOtboKL8A7rqgPQ=&lang=sage  

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