<p>The mass of the Earth is about 81 times that of the Moon and the distance between their centres of mass is typically 384 400 km, so the centre of mass will be about 1/82 of this distance from the centre of mass of the Earth, which is about 4700km. </p>

<p>The orbits are not too far from circular, so the Earth travels about $2 \pi$ times that each month, so a little under 30000km.</p>

CC BY-SA 3.0
2018-03-05T13:11:43.473Z
Why is it 1/82, and not 1/81?
Strawberry
CC BY-SA 3.0
2018-03-05T13:26:36.387Z
@Strawberry because both the moon and Earth are off-center from the COM, but the Earth-Moon distance measurement is simply between bodies. So if you take the Earth's off-center distance as the baseline ("one unit") and the Moon's off-center distance is 81 times that, and the total of all 82 "units" is the Earth-Moon distance (center-to-center of course).
Asher
CC BY-SA 3.0
2018-03-05T14:21:09.080Z
It feels like everything is spinning. My head hurts.  I need to go lie down for a bit... ;-)
Strawberry
CC BY-SA 3.0
2018-03-05T14:44:29.747Z
For reference, the Earth's radius is ~6,371 km, which puts the center of mass about 1,671 km under the Earth's surface
Carl Kevinson
CC BY-SA 3.0
2018-03-05T15:50:36.897Z
@Strawberry, the fact that Earth wobbles that much is a little off-putting.  I feel like every "moon rotating around the Earth" model or animation I've ever seen is a lie.
JPhi1618
CC BY-SA 3.0
2018-03-05T16:34:57.743Z
@JPhi1618 It's even worse. It's not just orbiting the earth, we're both orbiting the Sun, and we do a little dance with each other as we're going.
Barmar
CC BY-SA 3.0
2018-03-05T17:21:23.410Z
There's a second lie in most of the figures you've seen that somewhat counteracts the failure to show the wobble of the earth. If you have seen an old LP record, the hole in the middle is roughly the size of the earth if the moon's orbit is the rim of the record. On that scale, the wobble would certainly be noticeable, but small compared to the whole scene.
Mark Foskey
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2018-03-05T17:57:45.300Z
@Strawberry Everything is spinning thanks to the law of conservation of angular momentum.
corsiKa
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2018-03-05T10:19:14.887Z
2018-03-05T10:19:14.887Z
Steve Linton
<p>I realize the Earth and the Moon both orbit around their shared center of mass, and that in the case of the Earth and Moon this center is "inside" the Earth. However, I'm looking for an approach to determine the distance the Earth travels in one "orbit around the moon" (as small as it may be).</p>

CC BY-SA 3.0
2018-03-05T11:45:28.643Z
The title of your question assumes that your frame of reference is fixed to Moon. Then, the *radius* of Earth's orbit around Moon is the same as that of Moon's orbit around Earth. Following from this, the *circumference* of Earth's orbit around Moon is also the same as that of Moon's orbit around Earth.

If you mean that your frame of reference is the centre of mass of Earth+Moon system, then [Steve Linton's answer][https://astronomy.stackexchange.com/a/25378] is adequate.
garyF
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2018-03-05T13:35:41.300Z
@garyF - Re-read the question.
Hot Licks
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2018-03-05T15:54:19.057Z
If anyone knows of an animation that shows the Earth and the moon both moving correctly, I'd love to see that.  Seems like the Earth is always stationary.
JPhi1618
CC BY-SA 3.0
2018-03-05T16:37:21.780Z
Found [this video](https://youtu.be/uGBANgbRkws?t=30) which shows the motion pretty well.  Also the [Wiki article](https://en.wikipedia.org/wiki/Barycenter#Gallery) on barycenter has some basic animations.
JPhi1618
CC BY-SA 3.0
2018-03-05T18:23:02.007Z
@JPhi1618 You'd need a pretty high resolution frame to show it clearly, as the scale of the Earth's motion is quite small compared to the separation.
dmckee --- ex-moderator kitten
CC BY-SA 3.0
2018-03-06T00:13:15.790Z
@JPhi1618 - That is a really good video and it's what I was _trying_ to imagine. Thanks for that!
MT.
CC BY-SA 3.0
2018-03-06T00:16:39.617Z
So I guess my question title is somewhat of a misnomer? When we say "the Moon orbits the Earth", that's just a simplification because the Earth is the dominant body involved between the two. It would be more accurate to say neither technically "orbits" the other, instead, they both orbit their barycenter. Is that correct?
MT.
<orbit><the-moon><earth>
What is the distance of the Earth's orbit around the Moon?
MT.
# What is the distance of the Earth's orbit around the Moon?

(Asked by: username_0 on 2018-03-05)

I realize the Earth and the Moon both orbit around their shared center of mass, and that in the case of the Earth and Moon this center is "inside" the Earth. However, I'm looking for an approach to determine the distance the Earth travels in one "orbit around the moon" (as small as it may be).

**Tags:** orbit, the-moon, earth
> **Comments:**
> **username_1**: The title of your question assumes that your frame of reference is fixed to Moon. Then, the *radius* of Earth's orbit around Moon is the same as that of Moon's orbit around Earth. Following from this, the *circumference* of Earth's orbit around Moon is also the same as that of Moon's orbit around Earth.  If you mean that your frame of reference is the centre of mass of Earth+Moon system, then [Steve Linton's answer][https://astronomy.stackexchange.com/a/25378] is adequate.  
> **username_2**: @garyF - Re-read the question.  
> **username_3**: If anyone knows of an animation that shows the Earth and the moon both moving correctly, I'd love to see that.  Seems like the Earth is always stationary.  
> **username_3**: Found [this video](https://youtu.be/uGBANgbRkws?t=30) which shows the motion pretty well.  Also the [Wiki article](https://en.wikipedia.org/wiki/Barycenter#Gallery) on barycenter has some basic animations.  
> **username_4**: @JPhi1618 You'd need a pretty high resolution frame to show it clearly, as the scale of the Earth's motion is quite small compared to the separation.  
> **username_0**: @JPhi1618 - That is a really good video and it's what I was _trying_ to imagine. Thanks for that!  
> **username_0**: So I guess my question title is somewhat of a misnomer? When we say "the Moon orbits the Earth", that's just a simplification because the Earth is the dominant body involved between the two. It would be more accurate to say neither technically "orbits" the other, instead, they both orbit their barycenter. Is that correct?  

---

## 1 answers

### Answer by username_5 on 2018-03-05. Score: 16 | Accepted answer

The mass of the Earth is about 81 times that of the Moon and the distance between their centres of mass is typically 384 400 km, so the centre of mass will be about 1/82 of this distance from the centre of mass of the Earth, which is about 4700km.

The orbits are not too far from circular, so the Earth travels about $2 \pi$ times that each month, so a little under 30000km.

> **Comments:**
> **username_6**: Why is it 1/82, and not 1/81?  
> **username_7**: @Strawberry because both the moon and Earth are off-center from the COM, but the Earth-Moon distance measurement is simply between bodies. So if you take the Earth's off-center distance as the baseline ("one unit") and the Moon's off-center distance is 81 times that, and the total of all 82 "units" is the Earth-Moon distance (center-to-center of course).  
> **username_6**: It feels like everything is spinning. My head hurts.  I need to go lie down for a bit... ;-)  
> **username_8**: For reference, the Earth's radius is ~6,371 km, which puts the center of mass about 1,671 km under the Earth's surface  
> **username_3**: @Strawberry, the fact that Earth wobbles that much is a little off-putting.  I feel like every "moon rotating around the Earth" model or animation I've ever seen is a lie.  
> **username_9**: @JPhi1618 It's even worse. It's not just orbiting the earth, we're both orbiting the Sun, and we do a little dance with each other as we're going.  
> **username_10**: There's a second lie in most of the figures you've seen that somewhat counteracts the failure to show the wobble of the earth. If you have seen an old LP record, the hole in the middle is roughly the size of the earth if the moon's orbit is the rim of the record. On that scale, the wobble would certainly be noticeable, but small compared to the whole scene.  
> **username_11**: @Strawberry Everything is spinning thanks to the law of conservation of angular momentum.  

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