<p>If you need a rough estimation, you can sample the positions of the stellar objects from their acceleration, using Newton's law. A full picture is drawn <a href="http://en.wikipedia.org/wiki/N-body_problem" rel="nofollow">on this Wikipedia page</a>, but basically, given N stellar objects at position P(i), with their respective mass M(i):</p>

<p>$$
M_i.\vec{acc_i} = -G\sum_{n \neq i}^N \frac {M_i.M_n.(\vec{pos_i}-\vec{pos_n})}{\begin{vmatrix} \vec{pos_i}-\vec{pos_n}\end{vmatrix}^3 }
$$</p>

<p>You can then derivate acceleration into speed, then into position using a small enough time delta. With initial positions and speed (which are the trickiest and also funniest to choose), you can simulate a rough N-body system.</p>

<p>On the fun and simulation side, this is what <a href="http://store.steampowered.com/app/72200/" rel="nofollow">Universe Sandbox</a> aims to present (in advance, sorry for linking to a commercial store, I'm not related to this studio).</p>

<p>Lagrangian points are also interesting to look at when simulating.</p>

<p>However, to simplify things, you may like to think nearly all stellar objects "close" to the binary system would have been eaten by the massive couple over time, and then consider only the barycenter of the pair of stars.</p>

<p><strong>EDIT:</strong> although OP was clear, my answer is for N objects. The simplification to N=2, with A and B being the positions of the two objects, results in:
$$
\vec{acc_A} = \frac{G.M_B}{AB^3}\vec{AB}
$$
$$
\vec{acc_B} = \frac{G.M_A}{BA^3}\vec{BA}
$$
And with an iterative process, once acceleration is computed for step k, using known initial conditions for speed and position:
$$
\vec{spd_{k+1}} = \vec{acc_k}.\Delta{t} + \vec{spd_k}
$$
$$
\vec{pos_{k+1}} = \vec{spd_k}.\Delta{t} + \vec{pos_k}
$$</p>

<p><strong>EDIT2:</strong> well, another rough estimation, for the period duration (which I misunderstood as "trajectory" from the question). I'd use cylindrical coordinates as reference, for their clean spatial representation, and for the single-angle conversion:</p>

<p>$$
\left( \begin{array}{c} R_k \\ \theta_k \\ h_k \end{array} \right) = \left( \begin{array}{c} \sqrt{pos_{x,k}^2+pos_{y,k}^2} \\ \arctan \left( \frac{pos_{y,k}}{pos_{x,k}} \right) \\ pos_{z,k} \end{array} \right)
$$</p>

<p>...with adequate precaution. Introduce part of that conversion at each iteration, and wait for theta to complete a rotation.</p>

<p>(in advance, sorry for the weird notation, which I just tried to make consistent from my previous posts)</p>

CC BY-SA 3.0
2017-04-21T13:25:51.553Z
This is far too complicated and not required in a binary system.
ProfRob
CC BY-SA 3.0
2014-02-21T18:31:16.427Z
That's a general answer for an n-body system. For the special case of a binary, the sum/integral can be solved explicitly, leading to orbits of the same period around the common barycenter. May be you could add a solution for this special case.
Gerald
CC BY-SA 3.0
2014-02-24T08:37:09.150Z
You're right, OP clearly stated the requirement but I provided a broader answer nonetheless. I'll edit the answer to match N=2.
TallFurryMan
CC BY-SA 3.0
2014-02-24T21:27:27.913Z
Ok, this isn't quite easy now: Can you turn the $\Delta$ to infinitisimals to get a differential equation, and find a connection to the 3rd Kepler law, like here: http://en.wikipedia.org/wiki/Gravitational_two-body_problem ?
Gerald
CC BY-SA 3.0
2014-02-25T13:12:40.707Z
@Gerald I'm afraid I won't :) my proposal is nothing but a simple iterative process, where additional perturbations may be introduced at each step. I avoided differentials because the problem doesn't require an exact solution (and partly because that would require me to reopen some books...). But based on your comment, it appears I misread the OP: I thought the question was about trajectories, but might be about the "period", as duration?
TallFurryMan
CC BY-SA 3.0
2014-02-25T17:57:38.357Z
It was worth a try :) . I've been understanding the question in the sense of duration. Nevertheless, your iterative solution is more robust regarding perturbations. By comparing the actual positions with the starting positions, it's easy to find out the period (duration) during a simulation run, if needed.
Gerald
CC BY-SA 3.0
2014-02-26T09:49:42.283Z
@Gerald well, edited another brute force proposal, using planar rotation as an easy way to detect full revolution.
TallFurryMan
CC BY-SA 3.0
2014-02-26T10:37:58.940Z
Assuming co-planar orbits is ok for binaries. In your formula for cylinder coordinates, take care about the ambiguity of arctan; math software libraries usually provide a version of arctan with two parameters to avoid this ambiguity.
Gerald
CC BY-SA 3.0
2014-02-21T17:21:47.373Z
2014-02-26T09:46:16.503Z
2014-02-26T09:46:16.503Z
TallFurryMan
<p>I have two stars, with known masses and known orbital radius. How do I calculate the orbital periods of both stars?</p>

CC BY-SA 3.0
2017-04-21T13:22:58.277Z
@ScottGriffiths Your answer was the correct one and the shortness of the answer was in keeping with the lack of research by the OP.
ProfRob
CC BY-SA 3.0
2014-02-21T14:19:18.487Z
Have you searched the web? I think you have not investigated enough. There are plenty of answers out there, like http://answers.yahoo.com/question/index?qid=20071225133716AA5gj9p and http://voyager.egglescliffe.org.uk/physics/gravitation/binary/binary.html
Envite
CC BY-SA 3.0
2014-02-21T14:25:47.123Z
@Envite I wouldn't blame the OP for not trusting yahoo answers, but the Egglescliffe School resource is a good one, even if they have poor site design.
called2voyage
CC BY-SA 3.0
2014-02-21T14:28:49.513Z
Just two results from the first page of Google for "Binary Stars Orbital Period"
Envite
CC BY-SA 3.0
2014-02-21T14:56:15.277Z
@Envite I did try searching the web several times; perhaps I used the wrong queries, and I habitually don't click yahoo answers links.
aaazalea
CC BY-SA 3.0
2014-02-21T16:28:07.997Z
Ok, but now that you have Egglescliffe document, please read it and answer your own question. Or if there is something specifically you do not understand of it, ask for that specific issue.
Envite
CC BY-SA 3.0
2014-02-21T17:31:24.600Z
@Envite I did, I understand but I haven't had time to write up an answer yet. Thanks for your help.
aaazalea
CC BY-SA 3.0
2014-02-23T20:27:20.577Z
Use Kepler's third law! In particular, use Newton's form of Kepler's third law. See [this page](http://astro.physics.uiowa.edu/ITU/glossary/keplers-third-law/) for the formula and an example.
Scott Griffiths
<orbit><gravity><binary-star>
How can I calculate the orbital periods in a binary star system?
aaazalea
# How can I calculate the orbital periods in a binary star system?

(Asked by: username_0 on 2014-02-21)

I have two stars, with known masses and known orbital radius. How do I calculate the orbital periods of both stars?

**Tags:** orbit, gravity, binary-star
> **Comments:**
> **username_2**: Have you searched the web? I think you have not investigated enough. There are plenty of answers out there, like http://answers.yahoo.com/question/index?qid=20071225133716AA5gj9p and http://voyager.egglescliffe.org.uk/physics/gravitation/binary/binary.html  
> **username_3**: @Envite I wouldn't blame the OP for not trusting yahoo answers, but the Egglescliffe School resource is a good one, even if they have poor site design.  
> **username_2**: Just two results from the first page of Google for "Binary Stars Orbital Period"  
> **username_0**: @Envite I did try searching the web several times; perhaps I used the wrong queries, and I habitually don't click yahoo answers links.  
> **username_2**: Ok, but now that you have Egglescliffe document, please read it and answer your own question. Or if there is something specifically you do not understand of it, ask for that specific issue.  
> **username_0**: @Envite I did, I understand but I haven't had time to write up an answer yet. Thanks for your help.  
> **username_4**: Use Kepler's third law! In particular, use Newton's form of Kepler's third law. See [this page](http://astro.physics.uiowa.edu/ITU/glossary/keplers-third-law/) for the formula and an example.  
> **username_1**: @ScottGriffiths Your answer was the correct one and the shortness of the answer was in keeping with the lack of research by the OP.  

---

## 1 answers

### Answer by username_5 on 2014-02-21. Score: 5

If you need a rough estimation, you can sample the positions of the stellar objects from their acceleration, using Newton's law. A full picture is drawn [on this Wikipedia page](http://en.wikipedia.org/wiki/N-body_problem), but basically, given N stellar objects at position P(i), with their respective mass M(i):

$$
M\_i.\vec{acc\_i} = -G\sum\_{n \neq i}^N \frac {M\_i.M\_n.(\vec{pos\_i}-\vec{pos\_n})}{\begin{vmatrix} \vec{pos\_i}-\vec{pos\_n}\end{vmatrix}^3 }
$$

You can then derivate acceleration into speed, then into position using a small enough time delta. With initial positions and speed (which are the trickiest and also funniest to choose), you can simulate a rough N-body system.

On the fun and simulation side, this is what [Universe Sandbox](http://store.steampowered.com/app/72200/) aims to present (in advance, sorry for linking to a commercial store, I'm not related to this studio).

Lagrangian points are also interesting to look at when simulating.

However, to simplify things, you may like to think nearly all stellar objects "close" to the binary system would have been eaten by the massive couple over time, and then consider only the barycenter of the pair of stars.

**EDIT:** although OP was clear, my answer is for N objects. The simplification to N=2, with A and B being the positions of the two objects, results in:
$$
\vec{acc\_A} = \frac{G.M\_B}{AB^3}\vec{AB}
$$
$$
\vec{acc\_B} = \frac{G.M\_A}{BA^3}\vec{BA}
$$
And with an iterative process, once acceleration is computed for step k, using known initial conditions for speed and position:
$$
\vec{spd\_{k+1}} = \vec{acc\_k}.\Delta{t} + \vec{spd\_k}
$$
$$
\vec{pos\_{k+1}} = \vec{spd\_k}.\Delta{t} + \vec{pos\_k}
$$

**EDIT2:** well, another rough estimation, for the period duration (which I misunderstood as "trajectory" from the question). I'd use cylindrical coordinates as reference, for their clean spatial representation, and for the single-angle conversion:

$$
\left( \begin{array}{c} R\_k \\ \theta\_k \\ h\_k \end{array} \right) = \left( \begin{array}{c} \sqrt{pos\_{x,k}^2+pos\_{y,k}^2} \\ \arctan \left( \frac{pos\_{y,k}}{pos\_{x,k}} \right) \\ pos\_{z,k} \end{array} \right)
$$

...with adequate precaution. Introduce part of that conversion at each iteration, and wait for theta to complete a rotation.

(in advance, sorry for the weird notation, which I just tried to make consistent from my previous posts)

> **Comments:**
> **username_6**: That's a general answer for an n-body system. For the special case of a binary, the sum/integral can be solved explicitly, leading to orbits of the same period around the common barycenter. May be you could add a solution for this special case.  
> **username_5**: You're right, OP clearly stated the requirement but I provided a broader answer nonetheless. I'll edit the answer to match N=2.  
> **username_6**: Ok, this isn't quite easy now: Can you turn the $\Delta$ to infinitisimals to get a differential equation, and find a connection to the 3rd Kepler law, like here: http://en.wikipedia.org/wiki/Gravitational_two-body_problem ?  
> **username_5**: @Gerald I'm afraid I won't :) my proposal is nothing but a simple iterative process, where additional perturbations may be introduced at each step. I avoided differentials because the problem doesn't require an exact solution (and partly because that would require me to reopen some books...). But based on your comment, it appears I misread the OP: I thought the question was about trajectories, but might be about the "period", as duration?  
> **username_6**: It was worth a try :) . I've been understanding the question in the sense of duration. Nevertheless, your iterative solution is more robust regarding perturbations. By comparing the actual positions with the starting positions, it's easy to find out the period (duration) during a simulation run, if needed.  
> **username_5**: @Gerald well, edited another brute force proposal, using planar rotation as an easy way to detect full revolution.  
> **username_6**: Assuming co-planar orbits is ok for binaries. In your formula for cylinder coordinates, take care about the ambiguity of arctan; math software libraries usually provide a version of arctan with two parameters to avoid this ambiguity.  
> **username_1**: This is far too complicated and not required in a binary system.  

---

