<p>I guess it depends on the type of Supernovae.</p>

<p>Type 1a supernovae are produced by a white dwarf star orbiting a companion close enough that matter transfers from the companion to the surface of the white dwarf.</p>

<p>Assuming only your star system of a 3M star and 6M star, the 6M star would become a white dwarf star first.  At the end of it's life, it would have been furiously converting hydrogen to helium, and helium to carbon via the C-N-O cycle and the triple alpha process (C-N-O being dominant in stars above 1.3M sol).  The highest reaction in this stars main sequence lifetime would have been the creation of oxygen, but oxygen is a catalyst in the C-N-O cycle, and therefore the last probable reaction in the star would be that of Helium in some form of shell burning in the outer core (more on that next).</p>

<p>The white dwarf, while orbting the companion, may siphon off hydrogen from the surface of the donor star.  This hydrogen will accumulate evenly over the surface of the dwarf star, slowly growing the mass of the dwarf.  Also, the hydrogen will be shell-burned into helium during this time increasing the density.</p>

<p>If sufficient mass can be accumulated, then the carbon within the white dwarf can ignite in a runaway reaction - literally blowing the entire star apart.  These supernovae produce every element up to Nickel (Ni-56).</p>

CC BY-SA 3.0
2016-04-20T12:55:38.873Z
2016-04-20T12:55:38.873Z
EastOfJupiter
<p>I understand that binary star systems may cause type Ia supernovae.</p>

<p>I have a question regarding supernova explosion in a binary system. What is the last nuclear reaction before massive explosion?</p>

<p>I am thinking of two 2 close stars of 3M and 6M. </p>

CC BY-SA 3.0
2016-04-19T12:34:33.963Z
Why a binary system in particular?
SE - stop firing the good guys
CC BY-SA 3.0
2016-04-19T15:10:51.023Z
it is the context. but i guess it does not matter
Mary.Lou
CC BY-SA 3.0
2016-04-19T15:54:03.837Z
I don't understand the question. Stars of 6 and 3 solar masses do not explode as supernovae. Nuclear reactions go on throughout the supernova explosion and afterwards, so there is no "last nuclear reaction".
ProfRob
CC BY-SA 3.0
2016-04-19T16:43:25.583Z
why they will not explode as supernova?
Mary.Lou
CC BY-SA 3.0
2016-04-19T16:55:42.793Z
Dear Rob, then i am confused. I thought that in binary stars even with the same mass the process is different. (cause i realize that 3M and 6M are not considered as massive stars to cause supernova). What evolutionary path then this binary system will follow?
Mary.Lou
CC BY-SA 3.0
2016-04-26T05:46:55.997Z
@Mary.Lou Generally, a star of 3 or 6 solar masses will lose much of their mass on their way to becoming a white dwarf, so the resulting white dwarf will be less than the roughly 1.4 solar masses needed to exceed the Chandrasekhar limit, which is what's required to go nova as the white dwarf adds mass in a binary system.   New questions can be asked rather than asking in comments, but there may already be answers to those so search first.
userLTK
<supernova>
What is the last nuclear reaction in a binary system before supernova?
Mary.Lou
# What is the last nuclear reaction in a binary system before supernova?

(Asked by: username_0 on 2016-04-19)

I understand that binary star systems may cause type Ia supernovae.

I have a question regarding supernova explosion in a binary system. What is the last nuclear reaction before massive explosion?

I am thinking of two 2 close stars of 3M and 6M.

**Tags:** supernova
> **Comments:**
> **username_1**: Why a binary system in particular?  
> **username_0**: it is the context. but i guess it does not matter  
> **username_2**: I don't understand the question. Stars of 6 and 3 solar masses do not explode as supernovae. Nuclear reactions go on throughout the supernova explosion and afterwards, so there is no "last nuclear reaction".  
> **username_0**: why they will not explode as supernova?  
> **username_0**: Dear Rob, then i am confused. I thought that in binary stars even with the same mass the process is different. (cause i realize that 3M and 6M are not considered as massive stars to cause supernova). What evolutionary path then this binary system will follow?  
> **username_3**: @Mary.Lou Generally, a star of 3 or 6 solar masses will lose much of their mass on their way to becoming a white dwarf, so the resulting white dwarf will be less than the roughly 1.4 solar masses needed to exceed the Chandrasekhar limit, which is what's required to go nova as the white dwarf adds mass in a binary system.   New questions can be asked rather than asking in comments, but there may already be answers to those so search first.  

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## 1 answers

### Answer by username_4 on 2016-04-20. Score: 2

I guess it depends on the type of Supernovae.

Type 1a supernovae are produced by a white dwarf star orbiting a companion close enough that matter transfers from the companion to the surface of the white dwarf.

Assuming only your star system of a 3M star and 6M star, the 6M star would become a white dwarf star first. At the end of it's life, it would have been furiously converting hydrogen to helium, and helium to carbon via the C-N-O cycle and the triple alpha process (C-N-O being dominant in stars above 1.3M sol). The highest reaction in this stars main sequence lifetime would have been the creation of oxygen, but oxygen is a catalyst in the C-N-O cycle, and therefore the last probable reaction in the star would be that of Helium in some form of shell burning in the outer core (more on that next).

The white dwarf, while orbting the companion, may siphon off hydrogen from the surface of the donor star. This hydrogen will accumulate evenly over the surface of the dwarf star, slowly growing the mass of the dwarf. Also, the hydrogen will be shell-burned into helium during this time increasing the density.

If sufficient mass can be accumulated, then the carbon within the white dwarf can ignite in a runaway reaction - literally blowing the entire star apart. These supernovae produce every element up to Nickel (Ni-56).


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