<p>To weigh a planet, scientists need to know two things:</p>
<ul>
<li><strong>How long it takes objects to orbit the planet</strong></li>
<li><strong>How far away those objects are from the planet.</strong></li>
</ul>
<p>The time it takes an object to orbit a planet depends on its distance from the planet and the planet’s mass.</p>
<p>NASA Space Place: <a href="https://spaceplace.nasa.gov/planets-weight/en/" rel="nofollow noreferrer">How Do We Weigh Planets?</a></p>

CC BY-SA 4.0
2020-09-27T09:52:13.230Z
You need to make it clearer that this only applies to planets (with satellites) in our own solar system.
ProfRob
CC BY-SA 4.0
2020-09-27T10:05:48.937Z
@RobJeffries Why should that not apply to exoplanets?
jng224
CC BY-SA 4.0
2020-09-27T10:36:04.567Z
@Jonas The mass of the star is necessary, as it's the dominant factor in Kepler's law relating the period with the semi-major axis.  Once you have the semi-major axis, the velocity amplitude of the star is then also needed to estimate the planet's mass.
zibadawa timmy
CC BY-SA 4.0
2020-09-27T13:32:29.147Z
So the suggested procedure for a planetary system identical to ours but orbiting a different star would not work because the other star is not the Sun? I find that hard to believe. Are you trying to make a subtle distinction for planets orbiting close to a star? If so, what is the exact distinction? Is the procedure inaccurate if the satellite's orbit is 1E-6 the distance between the exoplanet and star? 1E-3? 1E-1? Will such a difference make any sense to someone without a "science backgroung"?
JohnHoltz
CC BY-SA 4.0
2020-09-27T15:21:28.250Z
@Jonas We can't observe satellites going around exoplanets.
ProfRob
CC BY-SA 4.0
2020-09-27T15:43:56.503Z
@RobJeffries agreed, I just thought the theory would be the same (however, it is apparently a bit different as explained by zibadawa timmy)
jng224
CC BY-SA 4.0
2020-09-27T15:46:33.197Z
@Jonas Zibadawa is explaining that knowing the orbital period and semi-major axis of an exoplanet does not give you it's mass. It gives the mass of the star it is orbiting. The masses of exoplanets come from measuring velocities or from transit timing variations. For massive planets in wide orbits it is possible to estimate the planet mass with a very careful fit to the projected orbit (if the distance is known).
ProfRob
CC BY-SA 4.0
2020-09-27T16:15:23.830Z
@RobJeffries Strictly speaking, exoplanets are not planets. Per the current definition of "planet", there are only eight planets in the entire universe. Firstmost among the three characteristics of objects that qualify as planets is that they are objects that orbit the Sun.
David Hammen
CC BY-SA 4.0
2020-09-28T02:03:58.063Z
@RobJeffries all good points for sure. Then again, detecting exoplanets didn't used to be possible, nor did direct imaging of planetary systems, nor did making parallax measurements from the Kuiper belt, nor was the detection of gravitational waves... so I’ve just asked [What's still needed before we can observe orbits of exomoons thereby weighing expoplanets?](https://astronomy.stackexchange.com/q/39083/7982)
uhoh
CC BY-SA 4.0
2020-09-27T08:49:32.613Z
2020-09-28T02:11:08.013Z
2020-09-28T02:11:08.013Z
Sid110307
<p>The other answer posted is correct, but let me try to explain it a bit more fully, and actually correct you on your terms.  I did an interview on this topic for a podcast literally just two days ago, so it's fresh in my mind.</p>
<hr />
<p><strong>Answer: The way we determine an astronomical object's <em>mass</em> is through Newton's form of Kepler's Third Law, which relates the distance another object orbits the object in question to the distance it orbits from that object, and some fundamental math and physics constants.  Doing this <em>requires</em> that there be a smaller, &quot;test&quot; object in orbit of the object whose mass you want to measure.</strong></p>
<p>Conceptually, this means that we can only measure an object's mass via that mass's effect on another object.</p>
<hr />
<p>What does that mean?  Kepler's Third Law states that the time it takes one object to orbit another, squared, is <em>proportional</em> to the semi major axis of its orbit around that object, cubed.  We often use that in our solar system in units of distance in A.U. (1 A.U. = Earth's average distance from the Sun) and Earth years.  So, before we knew how big an A.U. is in km, we still knew that Jupiter was about 5.2 A.U., and it took 11.9 Earth years to go around the sun.</p>
<p>Kepler's Third Law was formed in 1619, but it took Newton's Law of Gravitation in 1687 to provide the physics behind it.  That physics changed the &quot;is proportional to&quot; to &quot;equals,&quot; and added 4π<sup>2</sup>/G*M into the formula.  We know what 4 means, we know what π means.  M is the mass of the big object that something is orbiting.  It's what we want to solve for.  And, assuming we can observe an orbiting object, we know its period and distance from the main object we want to solve for.</p>
<p>So then, all we have to do is figure out G, the gravitational constant.  Gravity is really weak, so it's really hard to measure, and it took nearly 100 years for it to be calculated kinda accurately, and the first real measurement that people like (done by Cavendish) didn't happen until 1798.</p>
<p>With a value for &quot;big G&quot; as it's often called in physics class, you can now calculate any object's mass, in space.  So long as it has another object orbiting it.  That smaller object is <em>required</em> so we can use Kepler's Third Law to observe that object's orbit around the big one we want to measure.  If we don't have that smaller object in orbit, we can't* measure the big one's mass.  So, our first reasonable measurements of Pluto's mass only came once its main satellite, Charon, was discovered.  Only asteroids with moons have reasonable mass estimates.</p>
<p>*There are slightly other ways to do this.  One is to put an artificial satellite in orbit, so once <em>Dawn</em> orbited Vesta, and then Ceres, we could get their masses.  Another way is a gravitational slingshot around an object, like sending a probe past Venus, we can watch how much Venus deflects the probe and get its mass.  We can also watch for gravitational perturbations in a system caused by smaller masses and figure out what those smaller masses must be to cause those perturbations, but this is much harder (but led to some early estimates of the mass of Venus).</p>
<p>The bottom-line is still that, conceptually, you can only do this by measuring the object's (mass's) effects on another object.</p>
<hr />
<p><strong>Terms</strong>:  Mass is a fundamental property of matter, it's a way to think of how much &quot;stuff&quot; is there.  It has the familiar units of grams (or kilograms) or pounds.  Weight is different.  Weight is how mass acts in the presence of an acceleration, like gravity.  It has the metric units of Newtons.</p>
<p>In the presence of a basically-the-same gravitational acceleration – Earth's surface – mass and weight are proportional because the gravitational acceleration is the same.  So my mass – which doesn't change (much) – is going to mean I weigh the same wherever I am on Earth's surface.  If my <em>mass</em> is 100 kg, then I will <em>weigh</em> about 1000 N on Earth.  If I go to the Moon, my <em>mass</em> is still 100 kg, but I will be in a different gravitational field and I will <em>weigh</em> about 160 N.</p>
<p>Because my weight and mass are proportional practically anywhere on Earth, we use the terms &quot;mass&quot; and &quot;weight&quot; completely interchangeably, but we still use them wrong.  In fact, when I did the podcast recording I mentioned above, we had to do up to seven takes of just one sentence because I kept using the terms wrong, even though I was explaining how to use them correctly!</p>
<p>This is important because your question is actually phrased wrong: The question is, &quot;How do we determine the <em>mass</em> of a planet?&quot;</p>

CC BY-SA 4.0
2020-09-27T18:15:24.017Z
2020-09-28T05:40:50.097Z
2020-09-28T05:40:50.097Z
Stuart Robbins
<p><strong>How do we weigh a planet?</strong></p>
<p>My friend asked me how do scientists weigh a planet. He is not from science background so I need to make him understand with simple analogy. How can I explain to him?</p>

CC BY-SA 4.0
2020-09-27T08:48:07.580Z
This might help: https://spaceplace.nasa.gov/planets-weight/en/
jng224
CC BY-SA 4.0
2020-09-27T20:19:23.723Z
Closely related, if not a duplicate: [How was the mass of Venus determined?](https://astronomy.stackexchange.com/questions/39077)
David Hammen
CC BY-SA 4.0
2020-09-28T01:47:15.383Z
In Space Exploration SE see [History of investigation of lunar and Martian surface gravity](https://space.stackexchange.com/q/44913/12102) and [Did the Mars rovers actually confirm the gravity of Mars?](https://space.stackexchange.com/q/14947/12102) and [Gravity Model measurement technique](https://space.stackexchange.com/q/26986/12102) for some discussions of "ground truth" measurements of gravity, which of course by itself isn't weighing the planet.
uhoh
<planet><solar-system>
How do we weigh a planet?
Sazzad Hissain Khan
# How do we weigh a planet?

(Asked by: username_0 on 2020-09-27)

**How do we weigh a planet?**

My friend asked me how do scientists weigh a planet. He is not from science background so I need to make him understand with simple analogy. How can I explain to him?

**Tags:** planet, solar-system
> **Comments:**
> **username_1**: This might help: https://spaceplace.nasa.gov/planets-weight/en/  
> **username_2**: Closely related, if not a duplicate: [How was the mass of Venus determined?](https://astronomy.stackexchange.com/questions/39077)  
> **username_3**: In Space Exploration SE see [History of investigation of lunar and Martian surface gravity](https://space.stackexchange.com/q/44913/12102) and [Did the Mars rovers actually confirm the gravity of Mars?](https://space.stackexchange.com/q/14947/12102) and [Gravity Model measurement technique](https://space.stackexchange.com/q/26986/12102) for some discussions of "ground truth" measurements of gravity, which of course by itself isn't weighing the planet.  

---

## 2 answers

### Answer by username_8 on 2020-09-27. Score: 9 | Accepted answer

The other answer posted is correct, but let me try to explain it a bit more fully, and actually correct you on your terms. I did an interview on this topic for a podcast literally just two days ago, so it's fresh in my mind.

---

**Answer: The way we determine an astronomical object's *mass* is through Newton's form of Kepler's Third Law, which relates the distance another object orbits the object in question to the distance it orbits from that object, and some fundamental math and physics constants. Doing this *requires* that there be a smaller, "test" object in orbit of the object whose mass you want to measure.**

Conceptually, this means that we can only measure an object's mass via that mass's effect on another object.

---

What does that mean? Kepler's Third Law states that the time it takes one object to orbit another, squared, is *proportional* to the semi major axis of its orbit around that object, cubed. We often use that in our solar system in units of distance in A.U. (1 A.U. = Earth's average distance from the Sun) and Earth years. So, before we knew how big an A.U. is in km, we still knew that Jupiter was about 5.2 A.U., and it took 11.9 Earth years to go around the sun.

Kepler's Third Law was formed in 1619, but it took Newton's Law of Gravitation in 1687 to provide the physics behind it. That physics changed the "is proportional to" to "equals," and added 4π2/G\*M into the formula. We know what 4 means, we know what π means. M is the mass of the big object that something is orbiting. It's what we want to solve for. And, assuming we can observe an orbiting object, we know its period and distance from the main object we want to solve for.

So then, all we have to do is figure out G, the gravitational constant. Gravity is really weak, so it's really hard to measure, and it took nearly 100 years for it to be calculated kinda accurately, and the first real measurement that people like (done by Cavendish) didn't happen until 1798.

With a value for "big G" as it's often called in physics class, you can now calculate any object's mass, in space. So long as it has another object orbiting it. That smaller object is *required* so we can use Kepler's Third Law to observe that object's orbit around the big one we want to measure. If we don't have that smaller object in orbit, we can't\* measure the big one's mass. So, our first reasonable measurements of Pluto's mass only came once its main satellite, Charon, was discovered. Only asteroids with moons have reasonable mass estimates.

\*There are slightly other ways to do this. One is to put an artificial satellite in orbit, so once *Dawn* orbited Vesta, and then Ceres, we could get their masses. Another way is a gravitational slingshot around an object, like sending a probe past Venus, we can watch how much Venus deflects the probe and get its mass. We can also watch for gravitational perturbations in a system caused by smaller masses and figure out what those smaller masses must be to cause those perturbations, but this is much harder (but led to some early estimates of the mass of Venus).

The bottom-line is still that, conceptually, you can only do this by measuring the object's (mass's) effects on another object.

---

**Terms**: Mass is a fundamental property of matter, it's a way to think of how much "stuff" is there. It has the familiar units of grams (or kilograms) or pounds. Weight is different. Weight is how mass acts in the presence of an acceleration, like gravity. It has the metric units of Newtons.

In the presence of a basically-the-same gravitational acceleration – Earth's surface – mass and weight are proportional because the gravitational acceleration is the same. So my mass – which doesn't change (much) – is going to mean I weigh the same wherever I am on Earth's surface. If my *mass* is 100 kg, then I will *weigh* about 1000 N on Earth. If I go to the Moon, my *mass* is still 100 kg, but I will be in a different gravitational field and I will *weigh* about 160 N.

Because my weight and mass are proportional practically anywhere on Earth, we use the terms "mass" and "weight" completely interchangeably, but we still use them wrong. In fact, when I did the podcast recording I mentioned above, we had to do up to seven takes of just one sentence because I kept using the terms wrong, even though I was explaining how to use them correctly!

This is important because your question is actually phrased wrong: The question is, "How do we determine the *mass* of a planet?"


---

### Answer by username_4 on 2020-09-27. Score: 3

To weigh a planet, scientists need to know two things:

* **How long it takes objects to orbit the planet**
* **How far away those objects are from the planet.**

The time it takes an object to orbit a planet depends on its distance from the planet and the planet’s mass.

NASA Space Place: [How Do We Weigh Planets?](https://spaceplace.nasa.gov/planets-weight/en/)

> **Comments:**
> **username_5**: You need to make it clearer that this only applies to planets (with satellites) in our own solar system.  
> **username_1**: @RobJeffries Why should that not apply to exoplanets?  
> **username_6**: @Jonas The mass of the star is necessary, as it's the dominant factor in Kepler's law relating the period with the semi-major axis.  Once you have the semi-major axis, the velocity amplitude of the star is then also needed to estimate the planet's mass.  
> **username_7**: So the suggested procedure for a planetary system identical to ours but orbiting a different star would not work because the other star is not the Sun? I find that hard to believe. Are you trying to make a subtle distinction for planets orbiting close to a star? If so, what is the exact distinction? Is the procedure inaccurate if the satellite's orbit is 1E-6 the distance between the exoplanet and star? 1E-3? 1E-1? Will such a difference make any sense to someone without a "science backgroung"?  
> **username_5**: @Jonas We can't observe satellites going around exoplanets.  
> **username_1**: @RobJeffries agreed, I just thought the theory would be the same (however, it is apparently a bit different as explained by zibadawa timmy)  
> **username_5**: @Jonas Zibadawa is explaining that knowing the orbital period and semi-major axis of an exoplanet does not give you it's mass. It gives the mass of the star it is orbiting. The masses of exoplanets come from measuring velocities or from transit timing variations. For massive planets in wide orbits it is possible to estimate the planet mass with a very careful fit to the projected orbit (if the distance is known).  
> **username_2**: @RobJeffries Strictly speaking, exoplanets are not planets. Per the current definition of "planet", there are only eight planets in the entire universe. Firstmost among the three characteristics of objects that qualify as planets is that they are objects that orbit the Sun.  
> **username_3**: @RobJeffries all good points for sure. Then again, detecting exoplanets didn't used to be possible, nor did direct imaging of planetary systems, nor did making parallax measurements from the Kuiper belt, nor was the detection of gravitational waves... so I’ve just asked [What's still needed before we can observe orbits of exomoons thereby weighing expoplanets?](https://astronomy.stackexchange.com/q/39083/7982)  

---

