<p>It looks like the assumption regarding the 90° point is that the amount of the ecliptic visible is 180°. So the 90° direction is the halfway point.</p>

<p>The nonagesimal is on the ecliptic, so the altitude approximates the arc. The wording in the initial part has that correct, but then it goes on to say "the same as the angle" - this seems to be a mistake. The arc is directly related to the angle, yes, but it is not the angle.</p>

CC BY-SA 4.0
2019-02-14T17:06:56.010Z
thanks!. the thing is the visible ecliptic is not necessary $180^\circ$. but I think we can assume that is indeed the assumption. anyway, not sure I understand you last remark about the angle. 

unfortunately I still missing something with that paragraph.
d_e
CC BY-SA 4.0
2019-02-14T20:18:46.313Z
I read further on and now understand what you were saying - yes, the wording in the article is not correct
Rory Alsop
CC BY-SA 4.0
2019-02-13T22:11:21.160Z
2019-02-14T20:18:27.340Z
2019-02-14T20:18:27.340Z
Rory Alsop
<p>finally I think I grasped this.  As a novice, I did not understand some basic definitions that made that much harder for me to understand the paragraph. It might be a good idea to provide here an answer for reference to others that might encounter this issue. </p>

<p>1) parallax in this section refers to <strong>geocentric</strong> parallax. i.e where one point of observation is the surface of the earth and the second is it's center. Evidently, in the Zenith the geocentric parallax vanishes.</p>

<p>2) the longitude and latitude in this section refer to the lines in the <a href="https://en.wikipedia.org/wiki/Ecliptic_coordinate_system" rel="nofollow noreferrer">Ecliptic coordinate system</a> - where the ecliptic is of latitude 0 of course. [I'm still not sure as to <em>why</em> they used that system back then, instead of the more natural (at least to me ) Equatorial coordinate system. (maybe it was easier to calculate eclipses and plants transits using the ecliptic system)]</p>

<p>Now, for the nonagesimal - it is simply the highest point (closest to the Zenith) in the ecliptic at any given moment. it might be helpful here to note that nonagesimal is <em>not</em> the <a href="https://en.wikipedia.org/wiki/Midheaven" rel="nofollow noreferrer">Midheaven</a>. Simply because the highest point in the ecliptic does not necessarily intersect the meridian. </p>

<p>Making those definitions clear, the rest in that paragraph follows: the great circle drawn from the Zenith through the nonagesimal is simply a longitude line in the ecliptic coordinate system since it is perpendicular to a latitude line (the ecliptic being latitude 0). so since the the plane being defined by the earth's center, the observer point on the surface and the nonagesimal, is a plane of one longitude, then the parallax could not affect the longitude at all.   </p>

CC BY-SA 4.0
2019-03-06T19:24:18.703Z
2019-03-06T19:24:18.703Z
d_e
<p>I'm starting to learn Kepler's <strong><em>Astronomia Nova</em></strong> using William Donahue's translation . In the translator's introduction, it is demonstrated how Kepler did his parallax computation. I failed to understand the following paragraph:</p>

<p><a href="https://i.sstatic.net/eHYa3.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/eHYa3.png" alt="enter image description here"></a> </p>

<p>specifically: </p>

<p>1) nonagesimal's definition: there are 2 points of intersection between the ecliptic and the horizon: one in the East, the other in West. another ambiguity is the direction of the <span class="math-container">$90^\circ$</span></p>

<p>2) I can't see why the altitude of the nonagesimal is "the same as the angle between the ecliptic and the horizon". It does make sense to me, but I'm missing a kind of "proof" for that. </p>

<p>3) Actually I also failed to understand what follows in that paragraph - but maybe your explanation for the points above, will clarify that for me.</p>

<p>your help is very much appreciated</p>

<orbit><solar-system><astrophysics><kepler>
nonagesimal in Kepler's parallax computation
d_e
# nonagesimal in Kepler's parallax computation

(Asked by: username_0 on 2019-02-13)

I'm starting to learn Kepler's ***Astronomia Nova*** using William Donahue's translation . In the translator's introduction, it is demonstrated how Kepler did his parallax computation. I failed to understand the following paragraph:

[![enter image description here](https://i.sstatic.net/eHYa3.png)](https://i.sstatic.net/eHYa3.png)

specifically:

1) nonagesimal's definition: there are 2 points of intersection between the ecliptic and the horizon: one in the East, the other in West. another ambiguity is the direction of the $90^\circ$

2) I can't see why the altitude of the nonagesimal is "the same as the angle between the ecliptic and the horizon". It does make sense to me, but I'm missing a kind of "proof" for that.

3) Actually I also failed to understand what follows in that paragraph - but maybe your explanation for the points above, will clarify that for me.

your help is very much appreciated

**Tags:** orbit, solar-system, astrophysics, kepler

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## 2 answers

### Answer by username_1 on 2019-02-13. Score: 1

It looks like the assumption regarding the 90° point is that the amount of the ecliptic visible is 180°. So the 90° direction is the halfway point.

The nonagesimal is on the ecliptic, so the altitude approximates the arc. The wording in the initial part has that correct, but then it goes on to say "the same as the angle" - this seems to be a mistake. The arc is directly related to the angle, yes, but it is not the angle.

> **Comments:**
> **username_0**: thanks!. the thing is the visible ecliptic is not necessary $180^\circ$. but I think we can assume that is indeed the assumption. anyway, not sure I understand you last remark about the angle.   unfortunately I still missing something with that paragraph.  
> **username_1**: I read further on and now understand what you were saying - yes, the wording in the article is not correct  

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### Answer by username_0 on 2019-03-06. Score: 1

finally I think I grasped this. As a novice, I did not understand some basic definitions that made that much harder for me to understand the paragraph. It might be a good idea to provide here an answer for reference to others that might encounter this issue.

1) parallax in this section refers to **geocentric** parallax. i.e where one point of observation is the surface of the earth and the second is it's center. Evidently, in the Zenith the geocentric parallax vanishes.

2) the longitude and latitude in this section refer to the lines in the [Ecliptic coordinate system](https://en.wikipedia.org/wiki/Ecliptic_coordinate_system) - where the ecliptic is of latitude 0 of course. [I'm still not sure as to *why* they used that system back then, instead of the more natural (at least to me ) Equatorial coordinate system. (maybe it was easier to calculate eclipses and plants transits using the ecliptic system)]

Now, for the nonagesimal - it is simply the highest point (closest to the Zenith) in the ecliptic at any given moment. it might be helpful here to note that nonagesimal is *not* the [Midheaven](https://en.wikipedia.org/wiki/Midheaven). Simply because the highest point in the ecliptic does not necessarily intersect the meridian.

Making those definitions clear, the rest in that paragraph follows: the great circle drawn from the Zenith through the nonagesimal is simply a longitude line in the ecliptic coordinate system since it is perpendicular to a latitude line (the ecliptic being latitude 0). so since the the plane being defined by the earth's center, the observer point on the surface and the nonagesimal, is a plane of one longitude, then the parallax could not affect the longitude at all.


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