<p><strong>tl;dr:</strong> </p>

<p>The synodic period would be the same. For this object it will be about:</p>

<p><span class="math-container">$$\left( \frac{1}{365.25} - \frac{1}{557} \right)^{-1} \approx 1061 \ days.$$</span></p>

<p>You can confirm that by reading this new ArXiv preprint about Roadster: <a href="https://arxiv.org/abs/1802.04718" rel="nofollow noreferrer">The random walk of cars and their collision probabilities with planets</a>. In the 2nd paragraph of Section 3 it says:</p>

<blockquote>
  <p>The bodies reach the same orbital longitude on their synodic timescale of ∼ 2.8 yrs.</p>
</blockquote>

<p>There's a slight difference, since the Roadster's orbit continues to be refined, and the paper is about evolution over long timescales.</p>

<p>However, I think what you really want to know are <em>the times of closest approach</em> when (at least) one orbit is significantly eccentric, and <em>those  will not be periodic</em> or come at regular intervals.</p>

<hr>

<p>Well the Roadster is quite far away now and moving farther rapidly. See <a href="https://space.stackexchange.com/a/25121/12102">this answer</a> for some details and some nice images from medium-sized tracking telescopes. It's already dimmer than +22 magnitude as seen from Earth, and as far as I know there won't be any really close approaches to Earth for a long time.</p>

<p><a href="https://i.sstatic.net/fQXGo.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/fQXGo.png" alt="enter image description here"></a></p>

<p>But to answer your question, the period is about 557 days. You can see this for example if you go to JPL's <a href="https://ssd.jpl.nasa.gov/horizons.cgi" rel="nofollow noreferrer">Horizons</a> and look at the osculating elements. If you look a few weeks in the future when the Roadster is sufficiently far away from Earth not to be perturbed, the period around the Sun flattens out to 557 days.</p>

<p><a href="https://i.sstatic.net/TYEzA.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/TYEzA.png" alt="enter image description here"></a></p>

<p><a href="https://i.sstatic.net/CViZK.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/CViZK.png" alt="enter image description here"></a></p>

<p><strong>above x2:</strong> Top: Distance data from JPL's <a href="https://ssd.jpl.nasa.gov/horizons.cgi" rel="nofollow noreferrer">Horizons</a> plotted using Python <a href="https://space.stackexchange.com/a/25079/12102">from here</a>. Bottom: Estimated apparent magnitude using distances from Horizons plus math shown in the text of <a href="https://space.stackexchange.com/a/25121/12102">this answer</a>. Your milage may vary, but probably within +/-2 magnitudes of "official" predictions when they come out.</p>

<hr>

<p>A really cool GIF can be seen in the Space.com article <a href="https://www.space.com/39647-spacex-tesla-roadster-spotted-in-space.html" rel="nofollow noreferrer">Observatory Spots Elon Musk's Tesla Roadster Zooming Through Space (Video)</a>. It is over 7 MB so I can't add it here. However, here are ten frames from somewhere in the middle. Still, you should go see the whole thing.</p>

<p>GIF:</p>

<p><a href="https://i.sstatic.net/vyp79.gif" rel="nofollow noreferrer"><img src="https://i.sstatic.net/vyp79.gif" alt="enter image description here"></a></p>

<hr>

<p>DEMIOS image below, from <a href="http://www.elecnor-deimos.com/deimos-sky-survey-spacex-starman-tesla/" rel="nofollow noreferrer">here</a> as also <a href="https://twitter.com/planet4589/status/961700958030966784" rel="nofollow noreferrer">tweeted</a> by Jonathan McDowell. The little dot near the center moving to the right and up is Roadster in reflected sunlight, probably mostly from the white FH 2nd stage still attached.</p>

<p>GIF:</p>

<p><a href="https://i.sstatic.net/fjvSZ.gif" rel="nofollow noreferrer"><img src="https://i.sstatic.net/fjvSZ.gif" alt="enter image description here"></a></p>

CC BY-SA 3.0
2018-02-12T02:54:20.217Z
Why is it not periodic, does it not follow an elliptical orbit with that period of 557 days? Are there a lot of perturbations? Lastly that synodic period equation assumes circular orbits, does it really still apply to elliptical ones as well?
Rithwik Sudharsan
CC BY-SA 3.0
2018-02-12T05:03:44.780Z
@hawaii12 Both Earth's and Roadster's elliptical orbits are periodic. But a plot of the *distance between the two* will only be periodic if the two orbits are circular. You can always calculate a synodic period using your equation, but the more that one or both orbits are elliptical, it is less useful it is because the idea of "appears in the same position" is less and less correct. It's the *usefulness* of the synodic period that requires nearly-circular orbits, not the definition. There won't be a different equation for elliptical orbits.
uhoh
CC BY-SA 3.0
2018-02-13T06:05:31.397Z
So, the more elliptical the orbits are, the farther the synodic period will be from a true intersection of the two objects? Is there any place I can go to see why the distances between two elliptical orbits is not periodic;  [this](http://www.pa.uky.edu/~shlosman/anim/double_star_ellips.gif) is the visual I am seeing (the distance seems to be periodic).
Rithwik Sudharsan
CC BY-SA 3.0
2018-02-13T11:53:16.687Z
@hawaii12 Oh, your visual is of two bodies orbiting around a common center of mass. That's totally different than two bodies *orbiting around a third body* such as the Sun in the case of your question. That little green dot in the visual linked in your comment is the location of the center of mass of the two, but there isn't anything there physically. They are orbiting around each other. Mathematically you can see it as a single orbit. The smaller body's orbit is exactly 3.6 times larger than the heavier body, they both have identical eccentricity, and they both lie in a single plane.
uhoh
CC BY-SA 3.0
2018-02-13T11:59:55.907Z
Your graphic is the same as the others shown in Wikipedia's article about the [two body problem](https://en.wikipedia.org/wiki/Two-body_problem). In these figures, there's a red dot in the middle, but there is no physical body or mass at that point. But with Earth and Roadster both orbiting around a third, things are very different, so Earth and Roadster's orbits around the Sun are mostly independent.
uhoh
CC BY-SA 4.0
2018-02-11T03:48:28.690Z
2018-10-31T13:13:21.457Z
2018-10-31T13:13:21.457Z
uhoh
<p>For example, when would someone with a telescope be able to see Starman and his Roadster (when will the Tesla roadster's elliptical orbit cross ours again, and how would that be calculated?) </p>

<p>For two circular orbits, I understand this is given by $$\frac{1}{S} = \frac{1}{T_2} - \frac{1}{T_1} $$ .</p>

<orbit><orbital-migration><eccentric-orbit>
How would one calculate the synodic period of the Earth and an elliptical orbit?
Rithwik Sudharsan
# How would one calculate the synodic period of the Earth and an elliptical orbit?

(Asked by: username_0 on 2018-02-10)

For example, when would someone with a telescope be able to see Starman and his Roadster (when will the Tesla roadster's elliptical orbit cross ours again, and how would that be calculated?)

For two circular orbits, I understand this is given by $$\frac{1}{S} = \frac{1}{T\_2} - \frac{1}{T\_1} $$ .

**Tags:** orbit, orbital-migration, eccentric-orbit

---

## 1 answers

### Answer by username_1 on 2018-02-11. Score: 1

**tl;dr:**

The synodic period would be the same. For this object it will be about:

$$\left( \frac{1}{365.25} - \frac{1}{557} \right)^{-1} \approx 1061 \ days.$$

You can confirm that by reading this new ArXiv preprint about Roadster: [The random walk of cars and their collision probabilities with planets](https://arxiv.org/abs/1802.04718). In the 2nd paragraph of Section 3 it says:

> The bodies reach the same orbital longitude on their synodic timescale of ∼ 2.8 yrs.

There's a slight difference, since the Roadster's orbit continues to be refined, and the paper is about evolution over long timescales.

However, I think what you really want to know are *the times of closest approach* when (at least) one orbit is significantly eccentric, and *those will not be periodic* or come at regular intervals.

---

Well the Roadster is quite far away now and moving farther rapidly. See [this answer](https://space.stackexchange.com/a/25121/12102) for some details and some nice images from medium-sized tracking telescopes. It's already dimmer than +22 magnitude as seen from Earth, and as far as I know there won't be any really close approaches to Earth for a long time.

[![enter image description here](https://i.sstatic.net/fQXGo.png)](https://i.sstatic.net/fQXGo.png)

But to answer your question, the period is about 557 days. You can see this for example if you go to JPL's [Horizons](https://ssd.jpl.nasa.gov/horizons.cgi) and look at the osculating elements. If you look a few weeks in the future when the Roadster is sufficiently far away from Earth not to be perturbed, the period around the Sun flattens out to 557 days.

[![enter image description here](https://i.sstatic.net/TYEzA.png)](https://i.sstatic.net/TYEzA.png)

[![enter image description here](https://i.sstatic.net/CViZK.png)](https://i.sstatic.net/CViZK.png)

**above x2:** Top: Distance data from JPL's [Horizons](https://ssd.jpl.nasa.gov/horizons.cgi) plotted using Python [from here](https://space.stackexchange.com/a/25079/12102). Bottom: Estimated apparent magnitude using distances from Horizons plus math shown in the text of [this answer](https://space.stackexchange.com/a/25121/12102). Your milage may vary, but probably within +/-2 magnitudes of "official" predictions when they come out.

---

A really cool GIF can be seen in the Space.com article [Observatory Spots Elon Musk's Tesla Roadster Zooming Through Space (Video)](https://www.space.com/39647-spacex-tesla-roadster-spotted-in-space.html). It is over 7 MB so I can't add it here. However, here are ten frames from somewhere in the middle. Still, you should go see the whole thing.

GIF:

[![enter image description here](https://i.sstatic.net/vyp79.gif)](https://i.sstatic.net/vyp79.gif)

---

DEMIOS image below, from [here](http://www.elecnor-deimos.com/deimos-sky-survey-spacex-starman-tesla/) as also [tweeted](https://twitter.com/planet4589/status/961700958030966784) by Jonathan McDowell. The little dot near the center moving to the right and up is Roadster in reflected sunlight, probably mostly from the white FH 2nd stage still attached.

GIF:

[![enter image description here](https://i.sstatic.net/fjvSZ.gif)](https://i.sstatic.net/fjvSZ.gif)

> **Comments:**
> **username_0**: Why is it not periodic, does it not follow an elliptical orbit with that period of 557 days? Are there a lot of perturbations? Lastly that synodic period equation assumes circular orbits, does it really still apply to elliptical ones as well?  
> **username_1**: @hawaii12 Both Earth's and Roadster's elliptical orbits are periodic. But a plot of the *distance between the two* will only be periodic if the two orbits are circular. You can always calculate a synodic period using your equation, but the more that one or both orbits are elliptical, it is less useful it is because the idea of "appears in the same position" is less and less correct. It's the *usefulness* of the synodic period that requires nearly-circular orbits, not the definition. There won't be a different equation for elliptical orbits.  
> **username_0**: So, the more elliptical the orbits are, the farther the synodic period will be from a true intersection of the two objects? Is there any place I can go to see why the distances between two elliptical orbits is not periodic;  [this](http://www.pa.uky.edu/~shlosman/anim/double_star_ellips.gif) is the visual I am seeing (the distance seems to be periodic).  
> **username_1**: @hawaii12 Oh, your visual is of two bodies orbiting around a common center of mass. That's totally different than two bodies *orbiting around a third body* such as the Sun in the case of your question. That little green dot in the visual linked in your comment is the location of the center of mass of the two, but there isn't anything there physically. They are orbiting around each other. Mathematically you can see it as a single orbit. The smaller body's orbit is exactly 3.6 times larger than the heavier body, they both have identical eccentricity, and they both lie in a single plane.  
> **username_1**: Your graphic is the same as the others shown in Wikipedia's article about the [two body problem](https://en.wikipedia.org/wiki/Two-body_problem). In these figures, there's a red dot in the middle, but there is no physical body or mass at that point. But with Earth and Roadster both orbiting around a third, things are very different, so Earth and Roadster's orbits around the Sun are mostly independent.  

---

