<p>Since etymologically <em>sidereal</em> references the stars (Latin <em>sidus</em>), one might expect a sidereal day to correspond to the rotation of the Earth with respect to distant "fixed" stars. But this does not seem to be the case, and because the the difference is not significant, the two definitions are sometimes used interchangeably.</p>

<p>I don't know of an <em>explicit</em> IAU definition of <em>sidereal day</em>. However, since <strong>sidereal time</strong> is defined as the hour angle vernal equinox (which is a local definition, although Greenwich is conventional), defining the (mean) sidereal day in terms in reference to the equinox is practically the only sensible choice.</p>

<p>Effective 1985, UT1 is now computed using very long baseline interferometry of distant quasars, and so can be taken to be authoritative regarding the "fixed stars". The coordinated universal time (UTC) time approximates UT1 with atomic clocks. Anyway, UT1 derived the rotational period of the Earth as $p = 86164.09890369732\,\mathrm{s}$ of UT1 time and the mean sidereal day (in 2000) would be $86164.090530833\,\mathrm{s}$ of UT1 time, following the explanation:</p>

<blockquote>
  <p>The length of one sidereal day is defined by two successive transits of the mean equinox; while the Earth is rotating eastward, the mean equinox is moving westward due to precession. Therefore, one sidereal day is shorter than the Earth's rotational period by about $0.008\,\mathrm{s}$, the amount of precession in the right ascension in one day.</p>
</blockquote>

<p>See: Aoki, S., et al., <em>The new definition of universal time</em>, <a href="http://adsabs.harvard.edu/full/1982A%26A...105..359A" rel="nofollow">Astron. Astrophys. 105, 359-361 (1982)</a>.</p>

CC BY-SA 3.0
2014-10-14T15:55:16.110Z
Thank you Stan. I've been castrated more than once on English.SE for suggesting that a word's meaning could be inferred by its etymology. Apparently some people think that that term "living language" means "words mean whatever I want them to mean".
dotancohen
CC BY-SA 3.0
2014-10-14T15:40:17.010Z
2014-10-14T15:40:17.010Z
Stan Liou
<p>I notice that Wikipedia give two contradictory terms for the time period in which a planet rotates in relation to an infinitely-distant object. In one place this is called a "sidereal day" and in another "stellar day". <strong>Which of these are correct?</strong> For that point, is this an <a href="http://www.iau.org/" rel="nofollow">IAU</a> definition? I cannot find the definitions on the IAU website.</p>

<p>From the <a href="http://simple.wikipedia.org/wiki/Sidereal_day" rel="nofollow">Sidereal Day</a> page:</p>

<blockquote>
  <p>A sidereal day is the length of time it takes a planet to rotate from the perspective of a distant star.</p>
</blockquote>

<p>From the <a href="http://en.wikipedia.org/wiki/Day" rel="nofollow">Day</a> page:</p>

<blockquote>
  <ul>
  <li>stellar day - an entire rotation of a planet with respect to the distant stars</li>
  <li>sidereal day - a single rotation of a planet with respect to the vernal equinox</li>
  </ul>
</blockquote>

CC BY-SA 3.0
2014-10-16T12:05:00.760Z
Both are correct. Asserting that one must be correct and the other be incorrect creates a false dilemma.
David Hammen
CC BY-SA 3.0
2014-10-16T17:28:02.143Z
@DavidHammen: Thank you. What would be the case for objects whose vernal equinox precesses at an exaggerated pace?
dotancohen
CC BY-SA 3.0
2014-10-16T21:28:24.587Z
@dotancohen -- Precession is very slow. It's not a factor in this regard. The biggest distinction between a sidereal vs solar day is the simple fact that a planet orbits the Sun. This distinction is small for the Earth (roughly a factor of 366/365). It's rather large for Venus. A Venusian sidereal day is about 243 Earth days long, but thanks to Venus's retrograde rotation, A Venusian solar day is "only" 116.75 Earth days long.
David Hammen
<terminology>
Time period in which a planet rotates
dotancohen
# Time period in which a planet rotates

(Asked by: username_0 on 2014-10-14)

I notice that Wikipedia give two contradictory terms for the time period in which a planet rotates in relation to an infinitely-distant object. In one place this is called a "sidereal day" and in another "stellar day". **Which of these are correct?** For that point, is this an [IAU](http://www.iau.org/) definition? I cannot find the definitions on the IAU website.

From the [Sidereal Day](http://simple.wikipedia.org/wiki/Sidereal_day) page:

> A sidereal day is the length of time it takes a planet to rotate from the perspective of a distant star.

From the [Day](http://en.wikipedia.org/wiki/Day) page:

> * stellar day - an entire rotation of a planet with respect to the distant stars
> * sidereal day - a single rotation of a planet with respect to the vernal equinox

**Tags:** terminology
> **Comments:**
> **username_1**: Both are correct. Asserting that one must be correct and the other be incorrect creates a false dilemma.  
> **username_0**: @DavidHammen: Thank you. What would be the case for objects whose vernal equinox precesses at an exaggerated pace?  
> **username_1**: @dotancohen -- Precession is very slow. It's not a factor in this regard. The biggest distinction between a sidereal vs solar day is the simple fact that a planet orbits the Sun. This distinction is small for the Earth (roughly a factor of 366/365). It's rather large for Venus. A Venusian sidereal day is about 243 Earth days long, but thanks to Venus's retrograde rotation, A Venusian solar day is "only" 116.75 Earth days long.  

---

## 1 answers

### Answer by username_2 on 2014-10-14. Score: 3 | Accepted answer

Since etymologically *sidereal* references the stars (Latin *sidus*), one might expect a sidereal day to correspond to the rotation of the Earth with respect to distant "fixed" stars. But this does not seem to be the case, and because the the difference is not significant, the two definitions are sometimes used interchangeably.

I don't know of an *explicit* IAU definition of *sidereal day*. However, since **sidereal time** is defined as the hour angle vernal equinox (which is a local definition, although Greenwich is conventional), defining the (mean) sidereal day in terms in reference to the equinox is practically the only sensible choice.

Effective 1985, UT1 is now computed using very long baseline interferometry of distant quasars, and so can be taken to be authoritative regarding the "fixed stars". The coordinated universal time (UTC) time approximates UT1 with atomic clocks. Anyway, UT1 derived the rotational period of the Earth as $p = 86164.09890369732\,\mathrm{s}$ of UT1 time and the mean sidereal day (in 2000) would be $86164.090530833\,\mathrm{s}$ of UT1 time, following the explanation:

> The length of one sidereal day is defined by two successive transits of the mean equinox; while the Earth is rotating eastward, the mean equinox is moving westward due to precession. Therefore, one sidereal day is shorter than the Earth's rotational period by about $0.008\,\mathrm{s}$, the amount of precession in the right ascension in one day.

See: Aoki, S., et al., *The new definition of universal time*, [Astron. Astrophys. 105, 359-361 (1982)](http://adsabs.harvard.edu/full/1982A%26A...105..359A).

> **Comments:**
> **username_0**: Thank you Stan. I've been castrated more than once on English.SE for suggesting that a word's meaning could be inferred by its etymology. Apparently some people think that that term "living language" means "words mean whatever I want them to mean".  

---

