<p>This is because the summer and winter solstices (approx. June 21st and December 21st) do not correspond to the aphelion and perihelion (approx. July 5th and January 4th). Therefore, the average distance from the Sun is longer in the period from the Summer Solstice to Winter Solstice than vice versa, so the Earth is moving slower (on average) and it takes longer.</p>

<p>I think the values you mentioned are incorrect (switched around); 181.0 is a more likely value for Winter to Summer (February is a few days shorter than August).</p>

CC BY-SA 4.0
2018-10-17T19:01:15.787Z
@Glorifindel, you are correct. I have a spreadsheet with all the season dates. For this year (2018) winter to next summer (2019) is 181.77 days and summer to this coming winter is 183.47 days.
BillDOe
CC BY-SA 4.0
2018-10-17T14:12:15.517Z
2018-10-17T14:12:15.517Z
Glorfindel
<p>The diagram below illustrates the reason, which is that the earth moves at different speeds during it revolution around the sun and the distribution of those speeds is not equal because the solstices/equinoxes are not located at symmetrical points on the ellipse vis-a-vis the speed symmetries, which are centered on the aphelion and perihelion.</p>
<p><a href="https://i.sstatic.net/TcFKl.jpg" rel="nofollow noreferrer"><img src="https://i.sstatic.net/TcFKl.jpg" alt="Diagram of Earth's orbit around the Sun" /></a>
<br><em>Diagram by <a href="http://community.novacaster.com/showarticle.pl?id=11110" rel="nofollow noreferrer">Simon@Novacaster</a></em></p>
<p>In the case of the solstices only, this is because the tilt of the earth is such that it is not pointed towards the sun at aphelion/perihelion. If this was the case, then indeed both intervals would be the same. However, the equinoxes even in that case, they would not be the same.</p>

CC BY-SA 4.0
2020-09-22T08:43:29.200Z
2020-09-22T14:08:20.847Z
2020-09-22T14:08:20.847Z
Tyler Durden
<p>The path of the Earth around the sun is described as being an ellipse, with the Sun being at one of the foci of the ellipse.</p>
<p>Since an ellipse, by definition, is symmetrical with respect to the foci, I would expect the time for the earth to transit any two halves of the ellipse to be the same, so long as it moves at the same speed around the ellipse, or at least the speed characteristics are symmetrical as well.</p>
<p>However, this does not appear to be the case according to the following rounded figures for the time in days between equinoxes and solstices:</p>
<pre><code>Summer Solstice to Winter Solstice    184.3
Winter Solstice to Summer Solstice    181.0
Vernal Equinox to Autumnal Equinox    186.4
Autumnal Equinox to Vernal Equinox    178.9
</code></pre>
<p>These values can be found, for example, in astronomer Robert Newton's book of 1976.</p>
<p>Why are the values different?</p>

CC BY-SA 4.0
2018-10-17T17:27:00.547Z
Side note: use the "equal areas in equal time" law to check the elapsed time along any portion of the orbit.  In any case, I think Glorfindel's answer hits it.
Carl Witthoft
<orbit><ephemeris><equinox><solstice>
Why is the time between equinoxes different?
Tyler Durden
# Why is the time between equinoxes different?

(Asked by: username_0 on 2018-10-17)

The path of the Earth around the sun is described as being an ellipse, with the Sun being at one of the foci of the ellipse.
Since an ellipse, by definition, is symmetrical with respect to the foci, I would expect the time for the earth to transit any two halves of the ellipse to be the same, so long as it moves at the same speed around the ellipse, or at least the speed characteristics are symmetrical as well.
However, this does not appear to be the case according to the following rounded figures for the time in days between equinoxes and solstices:
Summer Solstice to Winter Solstice    184.3
Winter Solstice to Summer Solstice    181.0
Vernal Equinox to Autumnal Equinox    186.4
Autumnal Equinox to Vernal Equinox    178.9

These values can be found, for example, in astronomer Robert Newton's book of 1976.
Why are the values different?

**Tags:** orbit, ephemeris, equinox, solstice
> **Comments:**
> **username_1**: Side note: use the "equal areas in equal time" law to check the elapsed time along any portion of the orbit.  In any case, I think Glorfindel's answer hits it.  

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## 2 answers

### Answer by username_0 on 2020-09-22. Score: 5 | Accepted answer

The diagram below illustrates the reason, which is that the earth moves at different speeds during it revolution around the sun and the distribution of those speeds is not equal because the solstices/equinoxes are not located at symmetrical points on the ellipse vis-a-vis the speed symmetries, which are centered on the aphelion and perihelion.

[![Diagram of Earth's orbit around the Sun](https://i.sstatic.net/TcFKl.jpg)](https://i.sstatic.net/TcFKl.jpg)
  
*Diagram by [Simon@Novacaster](http://community.novacaster.com/showarticle.pl?id=11110)*

In the case of the solstices only, this is because the tilt of the earth is such that it is not pointed towards the sun at aphelion/perihelion. If this was the case, then indeed both intervals would be the same. However, the equinoxes even in that case, they would not be the same.


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### Answer by username_2 on 2018-10-17. Score: 14

This is because the summer and winter solstices (approx. June 21st and December 21st) do not correspond to the aphelion and perihelion (approx. July 5th and January 4th). Therefore, the average distance from the Sun is longer in the period from the Summer Solstice to Winter Solstice than vice versa, so the Earth is moving slower (on average) and it takes longer.

I think the values you mentioned are incorrect (switched around); 181.0 is a more likely value for Winter to Summer (February is a few days shorter than August).

> **Comments:**
> **username_3**: @Glorifindel, you are correct. I have a spreadsheet with all the season dates. For this year (2018) winter to next summer (2019) is 181.77 days and summer to this coming winter is 183.47 days.  

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