<p>I've asked this question to a couple of physicists a few days ago. Great minds think alike, huh?</p>

<p>First, bear in mind that Hawking radiation is only hypothetical. It is <em>not</em> theory. If we trust that hypothesis, this is what we can get.</p>

<p>In general relativity, black holes can be described through a number of approximations. For example, the Schwarzschild solution for a black hole describes it as an eternal object — not something that exists for some times, and doesn't exist for others. According to this solution, the event horizon must have always existed, and must remain existing eternally.</p>

<p>Schwarzschild black holes approximate black holes very accurately, but as you can tell, they fail to explain how a black hole can form, and (assuming Hawking radiation is real) they don't explain how one could eventually evaporate.</p>

<p>Of course, that solution won't help us. I've kept looking for one that accurately describes an evaporating, creatable black hole, but I've found nothing. The conclusion I've come to, along with those I've asked, is that our question has a major problem: Hawking radiation is explained via quantum field theory.</p>

<p>Thus, you can't simply use a GR solution for a black hole; you'd need some unholy mixture of quantum field theory and general relativity (keep in mind that both GR and QFT are incompatible in many situations).</p>

<p>In the end, it all comes down to how little we really know about black holes. It's not really possible to determine which solution is the best, and our inability to reconcile QFT with GR poses a big problem. The best answer I could give is "nobody really knows what would happen if you kept approaching a black hole".</p>

<p>We don't know if we would reach the event horizon, we don't know if the black hole will evaporate. We simply don't understand them well enough to know what solution would work, or how we would put QFT into it. If we somehow managed to find an approximation that properly combines GR and QFT, I assume (but don't quote me on this) the situation you described would be possible.</p>

<p>If it is possible, by the way, then we could confidently say that a black hole of any size could rip you apart through tidal forces. Tidal forces become weaker as the black hole's size increases, so one would assume a large enough black hole wouldn't rip you apart.</p>

<p>However, if we take Hawking radiation into account, and if your proposed scenario were indeed correct, the black hole would shrink as it evaporates. Since it would get smaller at a faster rate as we approach the event horizon, it would soon be small enough to rip us apart.</p>

CC BY-SA 3.0
2016-08-31T17:28:16.573Z
So assuming (BIG assumption) that all this works out this way and we can somehow survive tidal forces, would we then witness the event horizon constantly shrinking away from us as we approached until it vanished altogether? And then at that point, we would notice that in the few moments it took (from our perspective) for the black hole to vanish, the rest of the Universe aged billions of years?
called2voyage
CC BY-SA 3.0
2016-08-31T17:30:24.733Z
@called2voyage I suppose? God knows what would really happen, but my assumption is yes. But even if you somehow survived the ever-increasing strength of tidal forces, you'd have to deal with the extreme heat from the accretion disc and the incredibly strong magnetic fields.
Sir Cumference
CC BY-SA 3.0
2016-08-31T17:32:49.687Z
I ask because that solution sounds an awful lot like a one-way wormhole to the future.
called2voyage
CC BY-SA 3.0
2016-08-31T17:42:33.810Z
@called2voyage That's just how time dilation acts. It would be the same if you kept approaching the speed of light — your time would progress slower relative to the rest of the Universe, and the Universe's time would progress faster relative to you. A black hole doesn't have magic time-travel abilities, it just uses gravitational time dilation. All objects with gravity apply gravitational time dilation, but black holes will continue to dilate your time to infinity as you approach their event horizons.
Sir Cumference
CC BY-SA 3.0
2016-08-31T17:43:28.007Z
Right, but in this case you never cross the horizon, you just end up in the future.
called2voyage
CC BY-SA 3.0
2016-08-31T17:44:38.150Z
@called2voyage Again, no one really knows how to solve this, but perhaps. Remember that the black hole will keep shrinking and tidal forces will keep increasing, so even if you somehow survived the other deadly parts of a black hole, you'd still probably be ripped apart.
Sir Cumference
CC BY-SA 3.0
2016-08-31T17:48:39.427Z
I'm beginning to understand what Hawking meant when he said there are no black holes.
called2voyage
CC BY-SA 3.0
2016-09-01T16:28:40.270Z
@called2voyage: If it's true that you'd see the event horizon shrinking as you approach (due to time dilation), you'd also be bombarded by the Hawking radiation. The total amount of radiation that would hit you is finite, so it might be possible to shield against it, but it would be unpleasant.
Keith Thompson
CC BY-SA 4.0
2019-06-22T00:02:07.913Z
@called2voyage You don't need to try to dive through the event horizon of a black hole in order to get a trip to the far future. You can just plot a course that will take you  near the event horizon without actually going through it, and you your clock will end up having recored much less time than that belonging to an external viewer.

Traveling at close the the speed of light is probably a safer method of such time travel, however.
Douglas
CC BY-SA 4.0
2019-06-22T00:08:12.843Z
@Douglas I know, I was making a point about the apparent non-existence of the event horizon to the infalling observer.
called2voyage
CC BY-SA 4.0
2019-11-01T19:22:24.117Z
@called2voyage I don't believe what Sir Cumference has written. According to GR, you will pass through the event horizon in short order should you not be blocked by an accretion disk. What it looks like to an observer at infinity is a different matter than what it will look like to you. From your point of you, you will pass through the event horizon, and if it's a large enough black hole you won't be killed (yet) by tidal forces.

Of course, GR and QM haven't been resolved, so GR could be wrong. But until we resolve them, we won't know in what ways it will be wrong.
Douglas
CC BY-SA 4.0
2020-05-27T21:21:00.100Z
I am quite confused about your question, do you mean what happens to you if you fall in and the black hole dies right after?
Leo Pan
CC BY-SA 4.0
2023-01-26T16:40:31.957Z
@called2voyage billions of years?  Try at least $10^{67}$ years minimum and up to $10^{107}$ years for the really big black holes. Also note that the entire process would take between 10-20 seconds in proper time as seen by the infalling observer.  Personally I think that this scenario is much closer to the truth, the EH gets really close to forming but never fully finishes, and an infalling observer would see the EH shrink away and be bathed in a monstrous amount of Hawking radiation during their 10-20 second fall.
Aaron Hathaway
CC BY-SA 3.0
2016-08-31T05:43:04.827Z
2016-08-31T16:52:43.437Z
2016-08-31T16:52:43.437Z
Sir Cumference
<p>As it has been mentioned in a comment by @zephyr, the infinite time issue is actually a non-issue.</p>

<p>As you move closer to a black hole, the <em>relative</em> time to your point of view doesn't change in the same way that it does from a different reference frame. </p>

<p>Looking at your own situation, everything would happen in "real time" however, everything observed about you and your situation would take "and infinite amount of seconds for one second to pass."</p>

<p>This is also a contested <em>issue</em> because there have been measurements and possibly observations (I'd have to fact check this) of stars "falling" into black holes. So the infinite time from the outside observers perspective is also not possible.</p>

<p>In short, the best way to answer your question without going to much into theory, hypotheticals, or mad science, is simply to state: <strong>No, it does not mean that.</strong> </p>

CC BY-SA 3.0
2016-09-01T16:32:29.277Z
If we've observed a star falling into a black hole (I'd have to check that myself), that doesn't mean we've observed the star reaching the event horizon. We might just see the star being torn apart. It would appear to approach arbitrarily closely to the event horizon, to the point that it would seem to vanish, without ever actually reaching the event horizon from an outside frame of reference. All the mass/energy of anything falling into the black hole could seem to be "suspended" just above the event horizon, with its apparent speed asymptotically approaching zero. (Or I'm wrong.)
Keith Thompson
CC BY-SA 3.0
2016-08-31T14:37:15.190Z
2016-08-31T14:37:15.190Z
LaserYeti
<p>The event horizon never forms (nor does the singularity) because of general relativity which dictates gravitational time dilation. There is no universe within the black hole as some speculate. As the gravity becomes more and more intense time slows relative to the rest of the universe. A really large black hole radiates Hawking radiation at a temperature that is quite cool, for a supermassive black hole with millions of solar masses that temperature it's radiating at is <span class="math-container">$1.4*10^{-14}$</span> Kelvin or lower (it's about <span class="math-container">$10^{-7}$</span> or <span class="math-container">$10^{-8}$</span> for most stellar black holes). But here's the caveat, the Cosmic Microwave Background is at about 2.7 Kelvin so even accounting for the fact that black holes will only absorb CMB radiation that's a direct hit (otherwise it will orbit and miss being captured), it still means that all stellar mass or larger black holes are currently gaining more mass/energy from the CMB than they are losing to Hawking Radiation.</p>
<p>Since the universe continues to expand and is accelerating, the CMB will fall below <span class="math-container">$1 * 10^{-8}$</span> Kelvin in about <span class="math-container">$10^{29}$</span> years, at that point stellar mass black holes will start losing mass/energy and shrinking. Around <span class="math-container">$10^{36}$</span> years it'll fall below <span class="math-container">$10^{-14}$</span> and supermassive blackholes will start to shrink. The smallest stellar mass blackholes will finish evaporation around <span class="math-container">$10^{68}$</span> years from now and the largest around <span class="math-container">$10^{103}$</span> years. Another fun fact is that the Hawking radiation picks up in speed as the black hole evaporates and all black holes &quot;explode&quot; with the same amount of force calculated as the amount of radiation they release over the last second of their life, it equal to about 250,000 Tsar Bomba H-bombs or about 5 trillion tons of TNT. The only black holes that wouldn't explode with this much force would be microscopic ones which evaporate in less than a second.</p>
<p>So we've established that black holes will all eventually evaporate...it takes a ridiculous amount of time but it does happen in a finite amount of time. And as the matter falls in to form the singularity and event horizon general relativity shows that time dilation becomes greater and greater with respect to the rest of the universe. It becomes so dilated that if you were falling into a super massive black hole you would the hold get larger and larger, until a point when it took up half of your view then the rest of the cosmos would appear in a circle behind you, growing smaller and smaller as you got closer and close to the (not yet formed) event horizon. If you were to use a telescope and zoom in on that ever shrinking circle you would notice a few things. All the light falling into the black hole would get shifted bluer and bluer, time is going by much faster out there than where you are located. Before it blueshifted beyond visible light you might just be able to see starts actually moving in your host galaxy, if you had a computer with you and special detectors to see gamma rays (because light would continue to shift into harder and harder gamma rays) you would be able to watch trillions of years go by and it would keep speeding up faster and faster and faster, you could watch every star and galaxy in the universe go nova or super nova (that would be spectacular to see the stars popping like fireworks rapidly) and eventually that would stop and the sky would just be black, not because you've crossed the event horizon but because there are no more stars left. On the outside the majority of your fall towards the black hole would be in darkness with no stars or galaxies left, but from your point of view it would only a small part as your clock has slowed down so much that it would pass in moments. You will eventually arrive at where the event horizon should have been but the event horizon will have started shrinking at this point as the black hole has finally started radiating away more mass/energy than it's taking in from the CMB. You'll continue to move towards this new shrinking event horizon (this will all take mere moments form your point of view) until you get blasted with and explosion as described above. Actually the explosion will seem much greater to you, as the entire mass/energy of the black hole will seem to be released pretty much all at once due to your dilated frame of reference, for a super massive black hole. Calculated the force in megatons for a typical 50 million solar mass black hole, that's about <span class="math-container">$4 * 10^{40}$</span> megatons of TNT or <span class="math-container">$4*10^{38}$</span> Tsar Bomba's going off all at once from your reference frame.</p>
<p>You never cross the event horizon, it didn't have enough time to form as it would take infinite time and black holes eventually evaporate.</p>

CC BY-SA 4.0
2023-01-24T19:00:53.087Z
"All the light falling into the black hole would get shifted bluer and bluer, time is going by much faster out there than where you are located. Before it blueshifted beyond visible light you might just be able to see starts actually moving in your host galaxy, if you had a computer with..." None of this is correct. https://physics.stackexchange.com/questions/82678/does-someone-falling-into-a-black-hole-see-the-end-of-the-universe
ProfRob
CC BY-SA 4.0
2023-01-26T16:46:15.000Z
@ProfRob all this work to avoid a coordinate singularity is starting from a false assumption that the event horizon has fully formed.  GR time dilation is not just a trick of light alone, it's a very real thing that's necessary to take into account for our GPS satellites.  If you were to plot a course in a ship that took you close to a forming EH then back would you not arrive back to find that hundreds of years had passed relative to your distant starting point that's not in an intense gravity well?
Aaron Hathaway
CC BY-SA 4.0
2023-01-26T18:19:05.480Z
yes, if you lingered in the gravitational potential and then returned. Or even if you orbited close to the black hole. Neither of those is the scenario described in the question or in your answer, which are about inertial bodies falling into the black hole through the event horizon. I have given you a link where the correct physics is discussed both qualitatively and (exhaustingly) quantitatively.
ProfRob
CC BY-SA 4.0
2023-01-27T18:49:46.497Z
@ProfRob so by extension then let's imagine someone falling into a black hole that gets very close to the event horizon, if we integrate the GR time dilation as they approach we will eventually get a total time passed for a distant observer of $10^{87}$ years, yes?  And as we both know that's about the time frame needed for $10^6 M_{⊙}$ black hole to evaporate due to Hawking Radiation.  For any infalling matter a sufficient amount of time will pass for the black hole to evaporate will it not?
Aaron Hathaway
CC BY-SA 4.0
2023-01-27T19:06:18.787Z
you should read the correct answers to this problem that are in the link I gave. Or look at http://math.ucr.edu/home/baez/physics/Relativity/BlackHoles/fall_in.html You are now arguing about something I hadn't commented on (but your additional comments are irrelevant since the question is about whether the falling observer passes through the event horizon before the black hole evaporates, not what a distant observer sees).
ProfRob
CC BY-SA 4.0
2023-01-20T18:50:25.570Z
2023-01-24T16:01:06.223Z
2023-01-24T16:01:06.223Z
Aaron Hathaway
<p>It takes an infinite amount of time for something to fall past the event horizon of a black hole from the perspective of someone outside the event horizon. Black holes also evaporate after a finite amount of time from an outsider's perspective  due to Hawking radiation. </p>

<p>Does this mean that you would never actually reach the event horizon if you fell into a black hole because the black hole would evaporate?</p>

CC BY-SA 3.0
2016-08-31T11:48:37.160Z
Just to be clear, if you fell into a black hole, you'd fall into and meet the singularity long before it evaporated, what happens to the person falling in and what the person outside watching sees are 2 very different perspectives of the same event.
userLTK
CC BY-SA 3.0
2016-08-31T13:35:32.643Z
As userLTK indicates, the "infinite amount of time for something to fall past the event horizon" is only with respect to an observer watching an object fall in. The actual object doing the "falling" does not experience this so your question is moot. Besides, logic should indicate that if that were true, nothing could fall into a black hole and thus no black holes could every form or grow larger.
zephyr
CC BY-SA 3.0
2016-08-31T17:10:52.260Z
@zephyr This is a point of large confusion and no one is quite sure how to resolve it. It doesn't have a complete answer yet.
Sir Cumference
CC BY-SA 4.0
2019-01-30T10:46:29.937Z
Possible duplicate of [Infalling observer could never cross Black Hole event horizon?](https://astronomy.stackexchange.com/questions/29381/infalling-observer-could-never-cross-black-hole-event-horizon)
peterh
CC BY-SA 4.0
2019-01-31T05:43:26.993Z
I've voted to leave this question open - it's the other question that should be closed as a duplicate, given parts of it were *directly copied* from this one.
Chappo Hasn't Forgotten
CC BY-SA 4.0
2019-11-01T19:29:08.013Z
There's an existing FAQ for these sorts of questions: http://math.ucr.edu/home/baez/physics/Relativity/BlackHoles/fall_in.html For this particular question, the answer is no.
Douglas
CC BY-SA 4.0
2024-05-25T13:32:12.533Z
@zephyr I'm not following the "logic". Black holes could still grow larger from the perspective of an outside observer ─ just not from the perspective of an infalling object (since it would take an infinite amount of time for the object to gravitationally interact with more recent infalling objects).
Max
CC BY-SA 4.0
2024-05-25T13:33:54.070Z
@zephyr Also, why would the infalling object not experience time dilation? Clearly, satellites on Earth have to correct their clocks to account for time dilation, so why is the same not true for objects near a black hole?
Max
CC BY-SA 4.0
2024-05-25T14:40:56.943Z
@zephyr Moreover, now that I've thought more about this, the original infalling object A and the set of recent infalling objects B would be entangled: B can't be close enough to the event horizon to extend the Schwarzschild radius sufficiently to envelop A as this would imply the black hole would contain A ─ violating the no-hair theorem. So when B reaches a critical distance, A gets pushed back to the new event horizon. But A and B can't both be at the event horizon due to Pauli's exclusion principle, thus pushing one of A/B yet further out. I feel like this process explains Hawking radiation
Max
CC BY-SA 4.0
2024-05-25T15:24:18.090Z
More generally, the process could be described as follows: when a black hole forms, all of its contents get projected to the event horizon. But since the event horizon has fewer possible quantum states than the volume occupied by the black hole, a degeneracy pressure pushing the contents outward ─ equivalent to Hawking radiation ─ is created. As the contents spread out, the amount of mass at the event horizon decreases, reducing the Schwarzschild radius. If the pressure generated by infalling matter is greater than this degeneracy pressure, the black hole grows; otherwise, it shrinks.
Max
<black-hole><hawking-radiation>
Would a black hole evaporate via Hawking radiation before you fall past the event horizon?
Thomas
# Would a black hole evaporate via Hawking radiation before you fall past the event horizon?

(Asked by: username_0 on 2016-08-31)

It takes an infinite amount of time for something to fall past the event horizon of a black hole from the perspective of someone outside the event horizon. Black holes also evaporate after a finite amount of time from an outsider's perspective due to Hawking radiation.

Does this mean that you would never actually reach the event horizon if you fell into a black hole because the black hole would evaporate?

**Tags:** black-hole, hawking-radiation
> **Comments:**
> **username_1**: Just to be clear, if you fell into a black hole, you'd fall into and meet the singularity long before it evaporated, what happens to the person falling in and what the person outside watching sees are 2 very different perspectives of the same event.  
> **username_2**: As userLTK indicates, the "infinite amount of time for something to fall past the event horizon" is only with respect to an observer watching an object fall in. The actual object doing the "falling" does not experience this so your question is moot. Besides, logic should indicate that if that were true, nothing could fall into a black hole and thus no black holes could every form or grow larger.  
> **username_3**: @zephyr This is a point of large confusion and no one is quite sure how to resolve it. It doesn't have a complete answer yet.  
> **username_4**: Possible duplicate of [Infalling observer could never cross Black Hole event horizon?](https://astronomy.stackexchange.com/questions/29381/infalling-observer-could-never-cross-black-hole-event-horizon)  
> **username_5**: I've voted to leave this question open - it's the other question that should be closed as a duplicate, given parts of it were *directly copied* from this one.  
> **username_6**: There's an existing FAQ for these sorts of questions: http://math.ucr.edu/home/baez/physics/Relativity/BlackHoles/fall_in.html For this particular question, the answer is no.  
> **username_7**: @zephyr I'm not following the "logic". Black holes could still grow larger from the perspective of an outside observer ─ just not from the perspective of an infalling object (since it would take an infinite amount of time for the object to gravitationally interact with more recent infalling objects).  
> **username_7**: @zephyr Also, why would the infalling object not experience time dilation? Clearly, satellites on Earth have to correct their clocks to account for time dilation, so why is the same not true for objects near a black hole?  
> **username_7**: @zephyr Moreover, now that I've thought more about this, the original infalling object A and the set of recent infalling objects B would be entangled: B can't be close enough to the event horizon to extend the Schwarzschild radius sufficiently to envelop A as this would imply the black hole would contain A ─ violating the no-hair theorem. So when B reaches a critical distance, A gets pushed back to the new event horizon. But A and B can't both be at the event horizon due to Pauli's exclusion principle, thus pushing one of A/B yet further out. I feel like this process explains Hawking radiation  
> **username_7**: More generally, the process could be described as follows: when a black hole forms, all of its contents get projected to the event horizon. But since the event horizon has fewer possible quantum states than the volume occupied by the black hole, a degeneracy pressure pushing the contents outward ─ equivalent to Hawking radiation ─ is created. As the contents spread out, the amount of mass at the event horizon decreases, reducing the Schwarzschild radius. If the pressure generated by infalling matter is greater than this degeneracy pressure, the black hole grows; otherwise, it shrinks.  

---

## 3 answers

### Answer by username_3 on 2016-08-31. Score: 9

I've asked this question to a couple of physicists a few days ago. Great minds think alike, huh?

First, bear in mind that Hawking radiation is only hypothetical. It is *not* theory. If we trust that hypothesis, this is what we can get.

In general relativity, black holes can be described through a number of approximations. For example, the Schwarzschild solution for a black hole describes it as an eternal object — not something that exists for some times, and doesn't exist for others. According to this solution, the event horizon must have always existed, and must remain existing eternally.

Schwarzschild black holes approximate black holes very accurately, but as you can tell, they fail to explain how a black hole can form, and (assuming Hawking radiation is real) they don't explain how one could eventually evaporate.

Of course, that solution won't help us. I've kept looking for one that accurately describes an evaporating, creatable black hole, but I've found nothing. The conclusion I've come to, along with those I've asked, is that our question has a major problem: Hawking radiation is explained via quantum field theory.

Thus, you can't simply use a GR solution for a black hole; you'd need some unholy mixture of quantum field theory and general relativity (keep in mind that both GR and QFT are incompatible in many situations).

In the end, it all comes down to how little we really know about black holes. It's not really possible to determine which solution is the best, and our inability to reconcile QFT with GR poses a big problem. The best answer I could give is "nobody really knows what would happen if you kept approaching a black hole".

We don't know if we would reach the event horizon, we don't know if the black hole will evaporate. We simply don't understand them well enough to know what solution would work, or how we would put QFT into it. If we somehow managed to find an approximation that properly combines GR and QFT, I assume (but don't quote me on this) the situation you described would be possible.

If it is possible, by the way, then we could confidently say that a black hole of any size could rip you apart through tidal forces. Tidal forces become weaker as the black hole's size increases, so one would assume a large enough black hole wouldn't rip you apart.

However, if we take Hawking radiation into account, and if your proposed scenario were indeed correct, the black hole would shrink as it evaporates. Since it would get smaller at a faster rate as we approach the event horizon, it would soon be small enough to rip us apart.

> **Comments:**
> **username_8**: So assuming (BIG assumption) that all this works out this way and we can somehow survive tidal forces, would we then witness the event horizon constantly shrinking away from us as we approached until it vanished altogether? And then at that point, we would notice that in the few moments it took (from our perspective) for the black hole to vanish, the rest of the Universe aged billions of years?  
> **username_3**: @called2voyage I suppose? God knows what would really happen, but my assumption is yes. But even if you somehow survived the ever-increasing strength of tidal forces, you'd have to deal with the extreme heat from the accretion disc and the incredibly strong magnetic fields.  
> **username_8**: I ask because that solution sounds an awful lot like a one-way wormhole to the future.  
> **username_3**: @called2voyage That's just how time dilation acts. It would be the same if you kept approaching the speed of light — your time would progress slower relative to the rest of the Universe, and the Universe's time would progress faster relative to you. A black hole doesn't have magic time-travel abilities, it just uses gravitational time dilation. All objects with gravity apply gravitational time dilation, but black holes will continue to dilate your time to infinity as you approach their event horizons.  
> **username_8**: Right, but in this case you never cross the horizon, you just end up in the future.  
> **username_3**: @called2voyage Again, no one really knows how to solve this, but perhaps. Remember that the black hole will keep shrinking and tidal forces will keep increasing, so even if you somehow survived the other deadly parts of a black hole, you'd still probably be ripped apart.  
> **username_8**: I'm beginning to understand what Hawking meant when he said there are no black holes.  
> **username_9**: @called2voyage: If it's true that you'd see the event horizon shrinking as you approach (due to time dilation), you'd also be bombarded by the Hawking radiation. The total amount of radiation that would hit you is finite, so it might be possible to shield against it, but it would be unpleasant.  
> **username_6**: @called2voyage You don't need to try to dive through the event horizon of a black hole in order to get a trip to the far future. You can just plot a course that will take you  near the event horizon without actually going through it, and you your clock will end up having recored much less time than that belonging to an external viewer.  Traveling at close the the speed of light is probably a safer method of such time travel, however.  
> **username_8**: @Douglas I know, I was making a point about the apparent non-existence of the event horizon to the infalling observer.  
> **username_6**: @called2voyage I don't believe what Sir Cumference has written. According to GR, you will pass through the event horizon in short order should you not be blocked by an accretion disk. What it looks like to an observer at infinity is a different matter than what it will look like to you. From your point of you, you will pass through the event horizon, and if it's a large enough black hole you won't be killed (yet) by tidal forces.  Of course, GR and QM haven't been resolved, so GR could be wrong. But until we resolve them, we won't know in what ways it will be wrong.  
> **username_10**: I am quite confused about your question, do you mean what happens to you if you fall in and the black hole dies right after?  
> **username_11**: @called2voyage billions of years?  Try at least $10^{67}$ years minimum and up to $10^{107}$ years for the really big black holes. Also note that the entire process would take between 10-20 seconds in proper time as seen by the infalling observer.  Personally I think that this scenario is much closer to the truth, the EH gets really close to forming but never fully finishes, and an infalling observer would see the EH shrink away and be bathed in a monstrous amount of Hawking radiation during their 10-20 second fall.  

---

### Answer by username_12 on 2016-08-31. Score: 1

As it has been mentioned in a comment by @zephyr, the infinite time issue is actually a non-issue.

As you move closer to a black hole, the *relative* time to your point of view doesn't change in the same way that it does from a different reference frame.

Looking at your own situation, everything would happen in "real time" however, everything observed about you and your situation would take "and infinite amount of seconds for one second to pass."

This is also a contested *issue* because there have been measurements and possibly observations (I'd have to fact check this) of stars "falling" into black holes. So the infinite time from the outside observers perspective is also not possible.

In short, the best way to answer your question without going to much into theory, hypotheticals, or mad science, is simply to state: **No, it does not mean that.**

> **Comments:**
> **username_9**: If we've observed a star falling into a black hole (I'd have to check that myself), that doesn't mean we've observed the star reaching the event horizon. We might just see the star being torn apart. It would appear to approach arbitrarily closely to the event horizon, to the point that it would seem to vanish, without ever actually reaching the event horizon from an outside frame of reference. All the mass/energy of anything falling into the black hole could seem to be "suspended" just above the event horizon, with its apparent speed asymptotically approaching zero. (Or I'm wrong.)  

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### Answer by username_11 on 2023-01-20. Score: -1

The event horizon never forms (nor does the singularity) because of general relativity which dictates gravitational time dilation. There is no universe within the black hole as some speculate. As the gravity becomes more and more intense time slows relative to the rest of the universe. A really large black hole radiates Hawking radiation at a temperature that is quite cool, for a supermassive black hole with millions of solar masses that temperature it's radiating at is $1.4\*10^{-14}$ Kelvin or lower (it's about $10^{-7}$ or $10^{-8}$ for most stellar black holes). But here's the caveat, the Cosmic Microwave Background is at about 2.7 Kelvin so even accounting for the fact that black holes will only absorb CMB radiation that's a direct hit (otherwise it will orbit and miss being captured), it still means that all stellar mass or larger black holes are currently gaining more mass/energy from the CMB than they are losing to Hawking Radiation.

Since the universe continues to expand and is accelerating, the CMB will fall below $1 \* 10^{-8}$ Kelvin in about $10^{29}$ years, at that point stellar mass black holes will start losing mass/energy and shrinking. Around $10^{36}$ years it'll fall below $10^{-14}$ and supermassive blackholes will start to shrink. The smallest stellar mass blackholes will finish evaporation around $10^{68}$ years from now and the largest around $10^{103}$ years. Another fun fact is that the Hawking radiation picks up in speed as the black hole evaporates and all black holes "explode" with the same amount of force calculated as the amount of radiation they release over the last second of their life, it equal to about 250,000 Tsar Bomba H-bombs or about 5 trillion tons of TNT. The only black holes that wouldn't explode with this much force would be microscopic ones which evaporate in less than a second.

So we've established that black holes will all eventually evaporate...it takes a ridiculous amount of time but it does happen in a finite amount of time. And as the matter falls in to form the singularity and event horizon general relativity shows that time dilation becomes greater and greater with respect to the rest of the universe. It becomes so dilated that if you were falling into a super massive black hole you would the hold get larger and larger, until a point when it took up half of your view then the rest of the cosmos would appear in a circle behind you, growing smaller and smaller as you got closer and close to the (not yet formed) event horizon. If you were to use a telescope and zoom in on that ever shrinking circle you would notice a few things. All the light falling into the black hole would get shifted bluer and bluer, time is going by much faster out there than where you are located. Before it blueshifted beyond visible light you might just be able to see starts actually moving in your host galaxy, if you had a computer with you and special detectors to see gamma rays (because light would continue to shift into harder and harder gamma rays) you would be able to watch trillions of years go by and it would keep speeding up faster and faster and faster, you could watch every star and galaxy in the universe go nova or super nova (that would be spectacular to see the stars popping like fireworks rapidly) and eventually that would stop and the sky would just be black, not because you've crossed the event horizon but because there are no more stars left. On the outside the majority of your fall towards the black hole would be in darkness with no stars or galaxies left, but from your point of view it would only a small part as your clock has slowed down so much that it would pass in moments. You will eventually arrive at where the event horizon should have been but the event horizon will have started shrinking at this point as the black hole has finally started radiating away more mass/energy than it's taking in from the CMB. You'll continue to move towards this new shrinking event horizon (this will all take mere moments form your point of view) until you get blasted with and explosion as described above. Actually the explosion will seem much greater to you, as the entire mass/energy of the black hole will seem to be released pretty much all at once due to your dilated frame of reference, for a super massive black hole. Calculated the force in megatons for a typical 50 million solar mass black hole, that's about $4 \* 10^{40}$ megatons of TNT or $4\*10^{38}$ Tsar Bomba's going off all at once from your reference frame.

You never cross the event horizon, it didn't have enough time to form as it would take infinite time and black holes eventually evaporate.

> **Comments:**
> **username_13**: "All the light falling into the black hole would get shifted bluer and bluer, time is going by much faster out there than where you are located. Before it blueshifted beyond visible light you might just be able to see starts actually moving in your host galaxy, if you had a computer with..." None of this is correct. https://physics.stackexchange.com/questions/82678/does-someone-falling-into-a-black-hole-see-the-end-of-the-universe  
> **username_11**: @ProfRob all this work to avoid a coordinate singularity is starting from a false assumption that the event horizon has fully formed.  GR time dilation is not just a trick of light alone, it's a very real thing that's necessary to take into account for our GPS satellites.  If you were to plot a course in a ship that took you close to a forming EH then back would you not arrive back to find that hundreds of years had passed relative to your distant starting point that's not in an intense gravity well?  
> **username_13**: yes, if you lingered in the gravitational potential and then returned. Or even if you orbited close to the black hole. Neither of those is the scenario described in the question or in your answer, which are about inertial bodies falling into the black hole through the event horizon. I have given you a link where the correct physics is discussed both qualitatively and (exhaustingly) quantitatively.  
> **username_11**: @ProfRob so by extension then let's imagine someone falling into a black hole that gets very close to the event horizon, if we integrate the GR time dilation as they approach we will eventually get a total time passed for a distant observer of $10^{87}$ years, yes?  And as we both know that's about the time frame needed for $10^6 M_{⊙}$ black hole to evaporate due to Hawking Radiation.  For any infalling matter a sufficient amount of time will pass for the black hole to evaporate will it not?  
> **username_13**: you should read the correct answers to this problem that are in the link I gave. Or look at http://math.ucr.edu/home/baez/physics/Relativity/BlackHoles/fall_in.html You are now arguing about something I hadn't commented on (but your additional comments are irrelevant since the question is about whether the falling observer passes through the event horizon before the black hole evaporates, not what a distant observer sees).  

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