<p>Yes, gravitational waves can be redshifted. The answer of this question explains why: <a href="https://physics.stackexchange.com/questions/137292/can-gravitational-waves-be-red-shifted">https://physics.stackexchange.com/questions/137292/can-gravitational-waves-be-red-shifted</a>
The answer to the question above basicly states that doppler effect applies to any wave that propagates at light speed.</p>

<p>Actualy measuring the redshift is much more difficult, because neither redshift nor rest-frame mass can be extracted from the signal. Only the combination of the two can be obtained - M(1+z). This is called the redshifted mass. Deriving actual redshift from redshifted mass is quite complicated as this problem is relatively new and no efficient solution exists yet. This article here describes the derivation of the redshift in detail:
<a href="http://arxiv.org/pdf/1312.1862v2.pdf" rel="noreferrer">http://arxiv.org/pdf/1312.1862v2.pdf</a>
From it you can see that it is indeed possible to derive redshift from redshifted mass, but the method is really imprecise as it has a massive 10 - 20% uncertanity.</p>

CC BY-SA 3.0
2017-10-24T08:14:57.567Z
Also, see [this paper](https://arxiv.org/abs/1107.5725), which describes being able to break the mass-redshift degeneracy through the measurement of of tidal effects in the gravitational wave signal waveforms of merging neutron stars. However, this method requires some constraints on the neutron star equation of state to have already been measured.
Matt Pitkin
CC BY-SA 3.0
2016-03-17T22:22:14.570Z
2016-03-17T22:22:14.570Z
2017-04-13T12:40:15.377Z
Err403
<p>Yes, the formula is :</p>
<p><span class="math-container">$$z=\frac{H}{c} \mathrm{d}L$$</span>
where:</p>
<p><span class="math-container">$z$</span>: red shift<br />
<span class="math-container">$H$</span>: hubble constant<br />
<span class="math-container">$c$</span>: speed of light<br />
<span class="math-container">$\mathrm{d}l$</span>: amount of strain</p>
<p>for more information look at this link ( see time after 27:30 )</p>
<p><div class="youtube-embed"><div>
                <iframe width="640px" height="395px" src="https://www.youtube.com/embed/Ak0ZB3nIUHk?start=0"></iframe>
            </div></div></p>

CC BY-SA 4.0
2023-05-25T20:57:32.127Z
2023-05-26T19:39:59.900Z
2023-05-26T19:39:59.900Z
Hamidreza Abdollahi
<p>According to general relativity, would gravitational waves experience the same sort of redshift that electromagnetic waves experience due to the expansion of the universe?</p>

<p>And are there astrophysical processes that would be expected to have a characteristic 'frequency signature' analogous to the lyman or balmer series of hydrogen which would enable a measurement gravitational wave redshift. </p>

<p>I'm thinking of processes like baryon accoustic oscillations, certain types of supernovae, neutron star mergers, etc.</p>

CC BY-SA 3.0
2016-01-22T21:29:14.813Z
See https://physics.stackexchange.com/questions/137292/can-gravitational-waves-be-red-shifted.
HDE 226868
<expansion><gravitational-waves>
Redshift for gravitational waves?
dualredlaugh
# Redshift for gravitational waves?

(Asked by: username_0 on 2016-01-22)

According to general relativity, would gravitational waves experience the same sort of redshift that electromagnetic waves experience due to the expansion of the universe?

And are there astrophysical processes that would be expected to have a characteristic 'frequency signature' analogous to the lyman or balmer series of hydrogen which would enable a measurement gravitational wave redshift.

I'm thinking of processes like baryon accoustic oscillations, certain types of supernovae, neutron star mergers, etc.

**Tags:** expansion, gravitational-waves
> **Comments:**
> **username_1**: See https://physics.stackexchange.com/questions/137292/can-gravitational-waves-be-red-shifted.  

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## 2 answers

### Answer by username_2 on 2016-03-17. Score: 6

Yes, gravitational waves can be redshifted. The answer of this question explains why: <https://physics.stackexchange.com/questions/137292/can-gravitational-waves-be-red-shifted>
The answer to the question above basicly states that doppler effect applies to any wave that propagates at light speed.

Actualy measuring the redshift is much more difficult, because neither redshift nor rest-frame mass can be extracted from the signal. Only the combination of the two can be obtained - M(1+z). This is called the redshifted mass. Deriving actual redshift from redshifted mass is quite complicated as this problem is relatively new and no efficient solution exists yet. This article here describes the derivation of the redshift in detail:
<http://arxiv.org/pdf/1312.1862v2.pdf>
From it you can see that it is indeed possible to derive redshift from redshifted mass, but the method is really imprecise as it has a massive 10 - 20% uncertanity.

> **Comments:**
> **username_3**: Also, see [this paper](https://arxiv.org/abs/1107.5725), which describes being able to break the mass-redshift degeneracy through the measurement of of tidal effects in the gravitational wave signal waveforms of merging neutron stars. However, this method requires some constraints on the neutron star equation of state to have already been measured.  

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### Answer by username_4 on 2023-05-25. Score: 1

Yes, the formula is :

$$z=\frac{H}{c} \mathrm{d}L$$
where:

$z$: red shift  
$H$: hubble constant  
$c$: speed of light  
$\mathrm{d}l$: amount of strain

for more information look at this link ( see time after 27:30 )


---

