<p>Different places on the web imply that Schwarzschild's metric uses four components or separate equations, similar to how Einstein's full set requires 6 or 10, or they say only two are needed.  Is it 2 or 4?</p>
<p>P.S.:  Why does Friedmann's first equation only need one?  What does Schwarzschild include that Friedmann doesn't?</p>

CC BY-SA 4.0
2021-12-18T00:59:03.430Z
Remember that Schwarzschild solutions involve just about every kind of symmetry there is, reducing the amount of equations needed considerably.
Justin T
CC BY-SA 4.0
2021-12-18T01:03:59.027Z
Does this help? https://hepweb.ucsd.edu/ph110b/110b_notes/node75.html
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<gravity><general-relativity><theories><friedmann-equations>
Does the Schwarzschild metric solution require two (A and B, or g11 and g44) or four components (g11, g22, g33 and g44)?
Kurt Hikes
# Does the Schwarzschild metric solution require two (A and B, or g11 and g44) or four components (g11, g22, g33 and g44)?

(Asked by: username_0 on 2021-12-18)

Different places on the web imply that Schwarzschild's metric uses four components or separate equations, similar to how Einstein's full set requires 6 or 10, or they say only two are needed. Is it 2 or 4?

P.S.: Why does Friedmann's first equation only need one? What does Schwarzschild include that Friedmann doesn't?

**Tags:** gravity, general-relativity, theories, friedmann-equations
> **Comments:**
> **username_1**: Remember that Schwarzschild solutions involve just about every kind of symmetry there is, reducing the amount of equations needed considerably.  
> **username_2**: Does this help? https://hepweb.ucsd.edu/ph110b/110b_notes/node75.html  

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## 0 answers

