<p>There is no hard and fast answer. To be treated as an idea gas (your title question), the particles in your gas should be point-like and they should be non-interacting if you are to use the ideal gas approximation.</p>

<p>This means you can take the mean separation ($\sim n^{-1/3}$) and compare that with the size of the particles - it should be much bigger. You can also compare the particle kinetic energies with the potential energy of their interactions at typical separations. eg The ratio of $kT$ to the Coulomb potential energy should be large.</p>

<p>The rest of your question is confused. You are asking about an adiabatic index, but that is a completely separate question from whether the gas is ideal. It depends on the equation of state, on interactions, on internal degrees of freedom, on the way energy is transported.</p>

<p>Relativistically degenerate gases <em>can</em> be ideal gases and are often assumed to be so. Do not confuse an ideal gas with a perfect gas (even though many do so).</p>

CC BY-SA 3.0
2015-12-08T16:22:04.800Z
@AtmosphericPrisonEscape The equation of state for a perfect gas is $P = nkT$. However, an adiabatic change in a gas will follow an "adiabat" defined by $PV^{\gamma} = const$ (the temperature will of course change). It is conceptually no different to saying an isothermal change implies $PV = constant$ (Boyle's law). In each case $P=nkT$ remains true.
ProfRob
CC BY-SA 3.0
2015-12-08T16:26:54.717Z
@Javier If you want to reformulate your question, then edit it. A photon gas is almost always considered an ideal gas. Metallicity affects the coulomb interactions only very slightly, even in white dwarfs. However it may affect the adiabatic index by determining whether convection or radiation is the dominant energy transport process.
ProfRob
CC BY-SA 3.0
2015-12-03T13:58:17.723Z
Hi, could you maybe elaborate a bit on the last part? In fact I'm one of those ppl confusing it. In my mind there is only one relation for the pressure towards the other fluid variables needed (fluid closure relation = equation of state?), so I'm strugglin a bit with the understanding how $P= n k_B T$ and $P = \rho^{\gamma}$ can be true at the same time.
AtmosphericPrisonEscape
CC BY-SA 3.0
2015-12-03T15:20:01.513Z
Thank you for your answer. I guess my question can now be reformulated as "How do the ideal gas hypotheses relate with typical processes and parameters of stars?" You mention the temperature, of course, but are there other important factors? (Maybe metallicity or radiation).
Javier
CC BY-SA 3.0
2015-12-03T06:04:29.363Z
2015-12-03T13:44:05.857Z
2015-12-03T13:44:05.857Z
ProfRob
<p>I am currently taking a first course on stellar astrophysics, and I noticed that in some cases we use the ideal gas equation of state for stars, so we also use $\gamma =5/3$. Of course it can only be applied where there is no nuclear reaction, so there is a limit in the temperature.</p>

<p>Also, if the radiation pressure if relevant, you have to consider the parameter $\beta$ to calculate the total pressure and the adiabatic coefficient $\gamma$. It is also incorrect (I think) if there are degeneration or relativistic considerations.</p>

<p>I don't know if I have to consider other factors before I can use this equation of state and value for $\gamma$, maybe it is important if it is a convective or radiative area, or other factors I didn't consider.</p>

<p>My question is: can anybody tell me the limits of the ideal gas approximation? (quantitative better than qualitative but any help will be well received)</p>

<star><astrophysics><gas><stellar-structure>
When is it a good aproximation to consider a star to be an ideal gas?
Javier
# When is it a good aproximation to consider a star to be an ideal gas?

(Asked by: username_0 on 2015-12-03)

I am currently taking a first course on stellar astrophysics, and I noticed that in some cases we use the ideal gas equation of state for stars, so we also use $\gamma =5/3$. Of course it can only be applied where there is no nuclear reaction, so there is a limit in the temperature.

Also, if the radiation pressure if relevant, you have to consider the parameter $\beta$ to calculate the total pressure and the adiabatic coefficient $\gamma$. It is also incorrect (I think) if there are degeneration or relativistic considerations.

I don't know if I have to consider other factors before I can use this equation of state and value for $\gamma$, maybe it is important if it is a convective or radiative area, or other factors I didn't consider.

My question is: can anybody tell me the limits of the ideal gas approximation? (quantitative better than qualitative but any help will be well received)

**Tags:** star, astrophysics, gas, stellar-structure

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## 1 answers

### Answer by username_1 on 2015-12-03. Score: 2

There is no hard and fast answer. To be treated as an idea gas (your title question), the particles in your gas should be point-like and they should be non-interacting if you are to use the ideal gas approximation.

This means you can take the mean separation ($\sim n^{-1/3}$) and compare that with the size of the particles - it should be much bigger. You can also compare the particle kinetic energies with the potential energy of their interactions at typical separations. eg The ratio of $kT$ to the Coulomb potential energy should be large.

The rest of your question is confused. You are asking about an adiabatic index, but that is a completely separate question from whether the gas is ideal. It depends on the equation of state, on interactions, on internal degrees of freedom, on the way energy is transported.

Relativistically degenerate gases *can* be ideal gases and are often assumed to be so. Do not confuse an ideal gas with a perfect gas (even though many do so).

> **Comments:**
> **username_2**: Hi, could you maybe elaborate a bit on the last part? In fact I'm one of those ppl confusing it. In my mind there is only one relation for the pressure towards the other fluid variables needed (fluid closure relation = equation of state?), so I'm strugglin a bit with the understanding how $P= n k_B T$ and $P = \rho^{\gamma}$ can be true at the same time.  
> **username_0**: Thank you for your answer. I guess my question can now be reformulated as "How do the ideal gas hypotheses relate with typical processes and parameters of stars?" You mention the temperature, of course, but are there other important factors? (Maybe metallicity or radiation).  
> **username_1**: @AtmosphericPrisonEscape The equation of state for a perfect gas is $P = nkT$. However, an adiabatic change in a gas will follow an "adiabat" defined by $PV^{\gamma} = const$ (the temperature will of course change). It is conceptually no different to saying an isothermal change implies $PV = constant$ (Boyle's law). In each case $P=nkT$ remains true.  
> **username_1**: @Javier If you want to reformulate your question, then edit it. A photon gas is almost always considered an ideal gas. Metallicity affects the coulomb interactions only very slightly, even in white dwarfs. However it may affect the adiabatic index by determining whether convection or radiation is the dominant energy transport process.  

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