<p>It seems like there are two questions here:</p>
<h2>1: How could a moonless planet capture a single asteroid into a closed orbit around the planet?</h2>
<p>In a 2-body orbital system, a moonless planet couldn't capture an asteroid.  The asteroid would leave the planet's gravity well with the same relative speed that it entered.</p>
<p>However, a sun/planet/asteroid system is a 3-body orbital system.  If an asteroid is moving from perihelion to aphelion as it passes through a planet's gravity well, it may be slowing down due to the sun's gravitational pull.  If the asteroid's orbital velocity with respect to the planet drops enough, the asteroid will be captured.</p>
<p>Jupiter captures comets and asteroids all the time without significant interactions with its moons. There is a pretty good paper by <a href="https://www.scielo.br/j/cam/a/xFfB5ydsVZ9VdQSWF3Yp59m/?lang=en" rel="nofollow noreferrer">Prado and Broucke</a> called <em>The capture of comets by swing-by</em> describing Jupiter encounters that end up in closed Jupiter orbits.  They define a point <span class="math-container">$X_c$</span> and an angle <span class="math-container">$\theta$</span> for a Jupiter/Sun line crossing:</p>
<p><a href="https://i.sstatic.net/nIEA1.gif" rel="nofollow noreferrer"><img src="https://i.sstatic.net/nIEA1.gif" alt="enter image description here" /></a></p>
<p>Comets passing on points near Jupiter with low angles and low relative velocities with Jupiter have a higher probability of orbital capture.</p>
<h2>2: How can a highly elliptical orbit of an asteroid around a moonless planet become circularized?</h2>
<p><a href="https://en.wikipedia.org/wiki/Tidal_circularization" rel="nofollow noreferrer">Tidal Circularization</a> could decrease the eccentricity of a captured asteroid.</p>
<p><strong>Example:</strong> If tidal locked, the asteroid will rotate at (very close to) a uniform rate, but won't revolve around the planet at a uniform rate.  At it's fastest orbital speed at periapsis, the planet-side bulge pulls ahead and the opposite-side bulge lags behind.  The planet-side bulge has more gravitational force exerted on it, which decelerates the asteroid slightly, decreasing the next apoapsis.  A similar, but opposite effect occurs at apoapsis, increasing periapsis.  When periapsis and apoapsis meet, the orbit is circularized. This would happen to our Moon, in theory, if it wasn't for the Sun's gravitational influence.</p>
<p>More discussion of tidal circularization is here:
<a href="https://astronomy.stackexchange.com/questions/28962/is-the-moons-orbit-circularizing-why-does-tidal-heating-circularize-orbits">Is the moon&#39;s orbit circularizing? Why does tidal heating circularize orbits?</a></p>

CC BY-SA 4.0
2021-09-20T20:09:08.133Z
2021-09-20T20:09:08.133Z
Connor Garcia
<p>Ok, the simple answer would be through gravity assists from moons, taking a ballistic capture orbit into a circular orbit. I am wondering the chances of a ballistic orbit becoming a stable (on the order of tens of millions of years) orbit around a massive body? How would an asteroid be captured by a moonless body (like Venus)?</p>
<p>I know that a binary asteroid could transfer angular momentum to one component, causing one to be captured and the other to be ejected. Aerobraking won't work either because the orbit won't be stable and will impact the body in a short period of time. With these limited constraints in mind, would it be possible for a single, nonbinary asteroid to be captured by a celestial body without moons?</p>

CC BY-SA 4.0
2021-09-20T14:30:49.323Z
Related, or even a duplicate: https://astronomy.stackexchange.com/q/38320/31410
WarpPrime
CC BY-SA 4.0
2021-09-20T14:47:58.120Z
huh, I didn't realize the origins of Phobos and Deimos were controversial. How *does* a lone asteroid moon circularize around a planet??
BMF
CC BY-SA 4.0
2021-09-20T17:08:29.250Z
Maybe you could compare the asteroid-planet system's impact parameter [ https://en.wikipedia.org/wiki/Hyperbolic_trajectory#Impact_parameter ] with the Roche lobe radius of the planet?
Daddy Kropotkin
<planet><gravity><asteroids>
How could a captured asteroid enter a circularized orbit?
WarpPrime
# How could a captured asteroid enter a circularized orbit?

(Asked by: username_0 on 2021-09-20)

Ok, the simple answer would be through gravity assists from moons, taking a ballistic capture orbit into a circular orbit. I am wondering the chances of a ballistic orbit becoming a stable (on the order of tens of millions of years) orbit around a massive body? How would an asteroid be captured by a moonless body (like Venus)?

I know that a binary asteroid could transfer angular momentum to one component, causing one to be captured and the other to be ejected. Aerobraking won't work either because the orbit won't be stable and will impact the body in a short period of time. With these limited constraints in mind, would it be possible for a single, nonbinary asteroid to be captured by a celestial body without moons?

**Tags:** planet, gravity, asteroids
> **Comments:**
> **username_0**: Related, or even a duplicate: https://astronomy.stackexchange.com/q/38320/31410  
> **username_1**: huh, I didn't realize the origins of Phobos and Deimos were controversial. How *does* a lone asteroid moon circularize around a planet??  
> **username_2**: Maybe you could compare the asteroid-planet system's impact parameter [ https://en.wikipedia.org/wiki/Hyperbolic_trajectory#Impact_parameter ] with the Roche lobe radius of the planet?  

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## 1 answers

### Answer by username_3 on 2021-09-20. Score: 3 | Accepted answer

It seems like there are two questions here:

## 1: How could a moonless planet capture a single asteroid into a closed orbit around the planet?

In a 2-body orbital system, a moonless planet couldn't capture an asteroid. The asteroid would leave the planet's gravity well with the same relative speed that it entered.

However, a sun/planet/asteroid system is a 3-body orbital system. If an asteroid is moving from perihelion to aphelion as it passes through a planet's gravity well, it may be slowing down due to the sun's gravitational pull. If the asteroid's orbital velocity with respect to the planet drops enough, the asteroid will be captured.

Jupiter captures comets and asteroids all the time without significant interactions with its moons. There is a pretty good paper by [Prado and Broucke](https://www.scielo.br/j/cam/a/xFfB5ydsVZ9VdQSWF3Yp59m/?lang=en) called *The capture of comets by swing-by* describing Jupiter encounters that end up in closed Jupiter orbits. They define a point $X\_c$ and an angle $\theta$ for a Jupiter/Sun line crossing:

[![enter image description here](https://i.sstatic.net/nIEA1.gif)](https://i.sstatic.net/nIEA1.gif)

Comets passing on points near Jupiter with low angles and low relative velocities with Jupiter have a higher probability of orbital capture.

## 2: How can a highly elliptical orbit of an asteroid around a moonless planet become circularized?

[Tidal Circularization](https://en.wikipedia.org/wiki/Tidal_circularization) could decrease the eccentricity of a captured asteroid.

**Example:** If tidal locked, the asteroid will rotate at (very close to) a uniform rate, but won't revolve around the planet at a uniform rate. At it's fastest orbital speed at periapsis, the planet-side bulge pulls ahead and the opposite-side bulge lags behind. The planet-side bulge has more gravitational force exerted on it, which decelerates the asteroid slightly, decreasing the next apoapsis. A similar, but opposite effect occurs at apoapsis, increasing periapsis. When periapsis and apoapsis meet, the orbit is circularized. This would happen to our Moon, in theory, if it wasn't for the Sun's gravitational influence.

More discussion of tidal circularization is here:
[Is the moon's orbit circularizing? Why does tidal heating circularize orbits?](https://astronomy.stackexchange.com/questions/28962/is-the-moons-orbit-circularizing-why-does-tidal-heating-circularize-orbits)


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