<p>Almost, but each orbit corresponds to <em>its own</em> imaginary cone. Planets have different inclinations and directions of the plane.</p>
<p>The link between the angular momentum and energy of the planet and the size of the cone is somewhat involved but beautiful; see <a href="https://www.gregegan.net/SCIENCE/ConicSectionOrbits/ConicSectionOrbits.html#DS" rel="nofollow noreferrer">Greg Egan's explanation</a> of <a href="https://en.wikipedia.org/wiki/Dandelin_spheres" rel="nofollow noreferrer">Dandelin spheres</a>.</p>

CC BY-SA 4.0
2021-08-17T16:47:20.617Z
2021-08-17T22:30:50.627Z
2021-08-17T22:30:50.627Z
Anders Sandberg
<p>Yes and no.</p>
<p>What you seem to really asking is about the idea that the four types of orbits a body can have (circular, elliptical, parabolic, and hyperbolic) are also <a href="https://en.wikipedia.org/wiki/Conic_section" rel="nofollow noreferrer">conic sections</a>. In an ideal case where you use Newtonian physics and have just a single planet and single star, <em>yes you'll get those conic sections</em>. However, the planets in our solar system do not follow orbits which are perfect conic sections for a few reasons.</p>
<ol>
<li>Our solar system has several planets in it, all of which are affecting the orbit of the others. While the Sun is the predominant factor in any planet's orbital parameters, the other planets have non-zero, measurable effects. For the Earth, the perturbations from other planets (primarily Jupiter and Saturn) is described by the <a href="https://en.wikipedia.org/wiki/Milankovitch_cycles" rel="nofollow noreferrer">Milankovitch cycles</a> which are measured variabilities of the Earth's orbital parameters. What this means is that, at a fine scale, the Earth's orbit (as well as the other planets) is not a perfect, closed ellipse and does vary slightly from a conic section.</li>
<li>Newtonian physics is great for most scenarios, but in some cases, General Relativity starts applying. A specific example is Mercury. Mercury's orbit is greatly perturbed by the other planets, as described in point (1), however there are additional relativistic effects that cause Mercury to have an unclosed orbit. This effect is usually called the <a href="https://en.wikipedia.org/wiki/Tests_of_general_relativity#Perihelion_precession_of_Mercury" rel="nofollow noreferrer">perihelion precession of Mercury</a> and results in an orbit that differs quite significantly from a standard conic section.</li>
</ol>

CC BY-SA 4.0
2021-08-17T21:02:53.273Z
2021-08-18T13:25:43.730Z
2021-08-18T13:25:43.730Z
zephyr
<p>So that all the elliptic orbits can be seen as slices from the cone while the sun is a shared focus.</p>

CC BY-SA 4.0
2021-08-17T11:18:33.563Z
Given an ellipse with eccentricity $e$ and semi-major axis $a$ and a cone with aperture angle $\alpha$, there always exists a way to slice the cone such that the section is the ellipse. So the answer is trivially yes, if I interpret the question correctly
Prallax
CC BY-SA 4.0
2021-08-17T16:16:14.713Z
Is the question whether each of hte planetary orbits fit into an imaginary cone of its own, or whether all of the planetary orbits fit into one single imaginary cone?
M. A. Golding
<orbit><solar-system>
Do all the orbits of planets in the Solar system fit in a (imaginary) cone?
LIdbioe
# Do all the orbits of planets in the Solar system fit in a (imaginary) cone?

(Asked by: username_0 on 2021-08-17)

So that all the elliptic orbits can be seen as slices from the cone while the sun is a shared focus.

**Tags:** orbit, solar-system
> **Comments:**
> **username_1**: Given an ellipse with eccentricity $e$ and semi-major axis $a$ and a cone with aperture angle $\alpha$, there always exists a way to slice the cone such that the section is the ellipse. So the answer is trivially yes, if I interpret the question correctly  
> **username_2**: Is the question whether each of hte planetary orbits fit into an imaginary cone of its own, or whether all of the planetary orbits fit into one single imaginary cone?  

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## 2 answers

### Answer by username_3 on 2021-08-17. Score: 3

Almost, but each orbit corresponds to *its own* imaginary cone. Planets have different inclinations and directions of the plane.

The link between the angular momentum and energy of the planet and the size of the cone is somewhat involved but beautiful; see [Greg Egan's explanation](https://www.gregegan.net/SCIENCE/ConicSectionOrbits/ConicSectionOrbits.html#DS) of [Dandelin spheres](https://en.wikipedia.org/wiki/Dandelin_spheres).


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### Answer by username_4 on 2021-08-17. Score: 2

Yes and no.

What you seem to really asking is about the idea that the four types of orbits a body can have (circular, elliptical, parabolic, and hyperbolic) are also [conic sections](https://en.wikipedia.org/wiki/Conic_section). In an ideal case where you use Newtonian physics and have just a single planet and single star, *yes you'll get those conic sections*. However, the planets in our solar system do not follow orbits which are perfect conic sections for a few reasons.

1. Our solar system has several planets in it, all of which are affecting the orbit of the others. While the Sun is the predominant factor in any planet's orbital parameters, the other planets have non-zero, measurable effects. For the Earth, the perturbations from other planets (primarily Jupiter and Saturn) is described by the [Milankovitch cycles](https://en.wikipedia.org/wiki/Milankovitch_cycles) which are measured variabilities of the Earth's orbital parameters. What this means is that, at a fine scale, the Earth's orbit (as well as the other planets) is not a perfect, closed ellipse and does vary slightly from a conic section.
2. Newtonian physics is great for most scenarios, but in some cases, General Relativity starts applying. A specific example is Mercury. Mercury's orbit is greatly perturbed by the other planets, as described in point (1), however there are additional relativistic effects that cause Mercury to have an unclosed orbit. This effect is usually called the [perihelion precession of Mercury](https://en.wikipedia.org/wiki/Tests_of_general_relativity#Perihelion_precession_of_Mercury) and results in an orbit that differs quite significantly from a standard conic section.


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