<p>The price dependss roughly on material, machine hours, operator labour, profit and administrative overhead.
Some companies deduce the operator labour, machine hours and overhead to roughly 10 times the material cost. I think that is kind of fair. In your case I assume that you use PLA, the perabola is hollow (just a flat surface) and the company needs to construct the 3D model the parabola to a specific tolerance.
this model in PLA should not cost more than \$5 in filament, so about $ 50 should be an okay price for your parabola. The total price of \$147 leaves about \$97 for modeling the parabola. I think that's fair, given that a non-mathician has to find a way to construct a model and test the results.
If, for example, you want a metal print and you provide the 3D model I find the price of \$147 to be very normal. These metal printers are very expensive, labour intensive and eat up energy.
You can get instant quotes at the following sites: <a href="https://xometry.eu/" rel="nofollow noreferrer">https://xometry.eu/</a>, <a href="https://formalize-am.com/" rel="nofollow noreferrer">https://formalize-am.com/</a>
All above is just my best guess, given the data you provided. Expect a better answer when you provide more data.</p>

CC BY-SA 4.0
2021-05-19T08:49:46.057Z
yeah company told me that they use PLA, is there any cheaper material?
math boy
CC BY-SA 4.0
2021-05-19T08:58:25.180Z
Not really. PLA is about the cheapest stuff you could get. But the material is not the most expensive. having someone do the labour is the expensive part. Still assuming you have to get the parabole modeled by someone, you could try to find an online mathematical model generator or download a parabola from Thingiverse. Some models are in openscad, where you can easily code a math shape. If you'd live in the EU I could help you out printing it.
Hacky
CC BY-SA 4.0
2021-05-19T07:00:01.817Z
2021-05-19T07:00:01.817Z
Hacky
<p>So I wanted to print a 3D parabola, with a radius of 15 cm and a height of 4 cm.  I've told this company, they told me that they need 3.5 days and its price will be 147 USA dollars and 50 cents.</p>
<p>I just want to know what is the average price for this?</p>

CC BY-SA 4.0
2021-05-18T20:56:06.037Z
What material is this to be printed in? Are you supplying the model or is the company creating the model? There are other variables to consider to be able to supply a sufficient answer.
agarza
CC BY-SA 4.0
2021-05-18T21:18:20.300Z
company created model itself
math boy
CC BY-SA 4.0
2021-05-18T22:17:13.617Z
As a "Math boy" you would expect you do the math . If it is a plastic model, slice the model, note the filament length needed and deduce how many is on a spool at what price and add some extra for your time, energy and depreciation charge of the printer. I am guessing the object to be printed is in metal considering the price. This question is unanswerable without more details, please supply details by [edit]. Thanks.
0scar
CC BY-SA 4.0
2021-05-19T04:03:43.767Z
0scar, you have listed T&M costs only. Of course the designer's work adds to this. And note company overheads (like premises, management, communications, ...), and packaging, shipping, payment handling, and the taxes. Thus it would be cheaper when ordered on bulk ;)
octopus8
CC BY-SA 4.0
2021-05-19T13:30:56.430Z
Normally one thinks of a parabola as 2D. Are you thinking of the shape of a parabolic mirror on a reflecting telescope?
Perry Webb
CC BY-SA 4.0
2021-05-19T13:35:12.090Z
Maybe you are asking for a very smooth and accurate print.  They may be planning on a 0.1 mm step size with a 0.2 mm nozzle.  The model may also have smaller line segments than the default for the slicer.
Perry Webb
CC BY-SA 4.0
2023-12-03T08:54:41.033Z
Isn't the term for a '3D parabola' a 'paraboloid'?
Bob Ortiz
<diy-3d-printer>
What is average price for 3D parabola?
math boy
# What is average price for 3D parabola?

(Asked by: username_0 on 2021-05-18)

So I wanted to print a 3D parabola, with a radius of 15 cm and a height of 4 cm. I've told this company, they told me that they need 3.5 days and its price will be 147 USA dollars and 50 cents.

I just want to know what is the average price for this?

**Tags:** diy-3d-printer

> **Comments:**
> **username_1**: What material is this to be printed in? Are you supplying the model or is the company creating the model? There are other variables to consider to be able to supply a sufficient answer.  
> **username_0**: company created model itself  
> **username_2**: As a "Math boy" you would expect you do the math . If it is a plastic model, slice the model, note the filament length needed and deduce how many is on a spool at what price and add some extra for your time, energy and depreciation charge of the printer. I am guessing the object to be printed is in metal considering the price. This question is unanswerable without more details, please supply details by [edit]. Thanks.  
> **username_3**: username_2, you have listed T&M costs only. Of course the designer's work adds to this. And note company overheads (like premises, management, communications, ...), and packaging, shipping, payment handling, and the taxes. Thus it would be cheaper when ordered on bulk ;)  
> **username_4**: Normally one thinks of a parabola as 2D. Are you thinking of the shape of a parabolic mirror on a reflecting telescope?  
> **username_4**: Maybe you are asking for a very smooth and accurate print.  They may be planning on a 0.1 mm step size with a 0.2 mm nozzle.  The model may also have smaller line segments than the default for the slicer.  
> **username_5**: Isn't the term for a '3D parabola' a 'paraboloid'?  

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## 1 answers

### Answer by username_6 on 2021-05-19. Score: 1 | Accepted answer

The price dependss roughly on material, machine hours, operator labour, profit and administrative overhead.
Some companies deduce the operator labour, machine hours and overhead to roughly 10 times the material cost. I think that is kind of fair. In your case I assume that you use PLA, the perabola is hollow (just a flat surface) and the company needs to construct the 3D model the parabola to a specific tolerance.
this model in PLA should not cost more than \$5 in filament, so about $ 50 should be an okay price for your parabola. The total price of \$147 leaves about \$97 for modeling the parabola. I think that's fair, given that a non-mathician has to find a way to construct a model and test the results.
If, for example, you want a metal print and you provide the 3D model I find the price of \$147 to be very normal. These metal printers are very expensive, labour intensive and eat up energy.
You can get instant quotes at the following sites: <https://xometry.eu/>, <https://formalize-am.com/>
All above is just my best guess, given the data you provided. Expect a better answer when you provide more data.

> **Comments:**
> **username_0**: yeah company told me that they use PLA, is there any cheaper material?  
> **username_6**: Not really. PLA is about the cheapest stuff you could get. But the material is not the most expensive. having someone do the labour is the expensive part. Still assuming you have to get the parabole modeled by someone, you could try to find an online mathematical model generator or download a parabola from Thingiverse. Some models are in openscad, where you can easily code a math shape. If you'd live in the EU I could help you out printing it.  

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