Answers.Body: <h1>Best solution</h1>
  <p><strong>If</strong> there is nothing wrong with my rather spaghettoid script (admittedly, a big if) then there is no complete solution. The best my computer finds is two cycles.
  It finds essentially three such solutions plus a few minor variations. Interestingly, the split is always 3-13.</p>
  <pre><code>[FEN &quot;1Q6/3R4/NB2P3/1P3P2/2P3P1/1N1P3P/P4KB1/R7 w - - 0 1&quot;]
  </code></pre>
  <p>.</p>
  <pre><code>[FEN &quot;R7/BP6/2PK4/6R1/2N3BP/1N1P2P1/P3PP2/Q7 w - - 0 1&quot;]
  </code></pre>
  <p>.</p>
  <pre><code>[FEN &quot;6R1/6BP/1N4P1/P4P2/BP2P1NK/2PP4/7Q/3R4 w - - 0 1&quot;]
  </code></pre>
  <h1>Strategy / computer implementation</h1>
  <p>From the assumptions follow a handful of constraints that enable an exhaustive search.</p>
  <ol>
  <li>There are no more than 4 chains of Ps. That is because Ps can only attack other Ps or Rs or Ns and each separate chain has a P at the base that is not available to be attacked by another P. Each chain is capped by a R or N.</li>
  <li>The major pieces each have a rank to themselves. That is because there is at least a P on their file, so they must spend their attack on that file. The Q, in particular, must also have her diagonals to herself.</li>
  <li>The Q must be attacked by a N.</li>
  <li>At least 1 chain of Ps must be capped off by a N. There are at least two Ps on the same rank and their respective chains cannot be both capped by Rs because then 1 chain would have to cross the private rank of the other chains R.</li>
  </ol>
  <p>Using these constraints makes the code rather verbose and ugly but keeps the number of candidates below a million or so.</p>
  <h1>Relaxing the rules</h1>
  <p>If we lift the one pawn per file rule it becomes untractable for my computer program, but we can solve manually</p>
  <pre><code>[FEN &quot;6R1/1R6/1BP3BN/3P2P1/2P2P2/1P4P1/P1N2K/Q7 w - - 0 1&quot;]
  </code></pre>
  <h1>Last word: The i files</h1>
  <p>We can actually achieve a full solution with no doubled pawns by ever so slightly bending the rules. All we need to do is rip out the f file but relax we are putting it right back: as the new i file. Job done:</p>
  <p><a href="https://i.sstatic.net/DDgO7.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/DDgO7.png" alt="enter image description here" /></a></p>
  
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2021-01-06T22:25:13.300Z
Answers.Text: Thank you! Can you get  a solution with one cycle if you allow doubled pawns?
Answers.UserDisplayName: bof
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2021-01-07T05:11:51.787Z
Answers.Text: @bof my computer can't but I can ;-)
Answers.UserDisplayName: Paul Panzer
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2021-01-07T06:24:19.290Z
Answers.Text: Well done. On the assumption that your computer program is correct and I've been suffering from a false memory of having seen a solution with one cycle and no doubled pawns, I'm awarding the check mark. Of course, I will have to move it if a solution to the puzzle as I stated it ever turns up.
Answers.UserDisplayName: bof
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2021-01-06T14:35:31.753Z
Answers.LastActivityDate: 2021-01-07T19:43:43.783Z
Answers.LastEditDate: 2021-01-07T19:43:43.783Z
Answers.UserDisplayName: Paul Panzer
Answers.Body: <p>This has several issues. It's missing a pawn on <code>c</code> and a bishop on the black diagonal, and the pawn on <code>d</code> doesn't attack anything, as well as nothing attacks the rook on <code>a3</code>, but this is as close as I can apparently get. Maybe someone can work off this and do better.</p>
  <p>However, there's a single cycle from <code>Ra3</code> to <code>d6</code>. Anything else I try ends up with at least one piece attacking multiple other pieces, and I still can't get all the pieces on the board without several of these multiple attacks.</p>
  <p>I put <s>baby</s> the queen in the corner to attempt to reduce the directions of her influence. Then I tried to put things in around her. I've been doing this manually, so I obviously haven't managed to try all combinations, but this methodology seems to have some merit, until it hits a wall.</p>
  <pre><code>[FEN &quot;5R2/N5P1/1P1P3P/PB2P3/5P2/R7/4KN2/7Q w - - 0 1&quot;]
  </code></pre>
  <p>There are so very many issues with this puzzle:</p>
  <ol>
  <li>The queen can only be attacked by a knight.</li>
  <li>The queen and both rooks require a whole rank to themselves, leaving only 5 ranks for the other 13 pieces.</li>
  <li>The queen needs the equivalent of at least one full diagonal.</li>
  <li>Pawns can't attack bishops or the king.</li>
  <li>Knights, bishops, and rooks can't attack like pieces.</li>
  <li>Because there's so many pawns, most major pieces are likely going to have to attack one.</li>
  </ol>
  
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2021-01-07T00:39:30.707Z
Answers.Text: @RewanDemontay, no. Unfortunately, I couldn't find places to put the one bishop or the last pawn that kept the cycle going without violating a bunch of puzzle rules.
Answers.UserDisplayName: computercarguy
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2021-01-06T23:37:52.903Z
Answers.LastActivityDate: 2021-01-06T23:45:32.973Z
Answers.LastEditDate: 2021-01-06T23:45:32.973Z
Answers.UserDisplayName: computercarguy
Body: <p>I saw this puzzle and a solution sometime in the previous century, I don't remember where, and I don't remember the solution.</p>
  <p>Place the 16 white men on an otherwise empty chessboard so that the following conditions are satisfied.</p>
  <ol>
  <li>Each man attacks one and only one other man.</li>
  <li>Each man is attacked by one and only one other man.</li>
  <li>The bishops are on opposite colors.</li>
  <li>One pawn on each file, no pawns on the first or last rank.</li>
  <li>There is one continuous cycle of attack, meaning that the men can be numbered from 1 to 16 so that #1 attacks #2, which attacks #3, which attacks #4, . . ., which attacks #15, which attacks #16, which attacks #1.</li>
  </ol>
  <p>What's the solution?</p>
  <p>Partial solutions (satisfying the first three conditions, but with doubled pawns or with two or more cycles of attack), will be appreciated and upvoted, but I'm hoping to accept an answer satisfying all five conditions.</p>
  
Comments.ContentLicense: CC BY-SA 4.0
Comments.CreationDate: 2021-01-03T00:53:56.170Z
Comments.Text: Interesting puzzle. If I had to guess I'd think it's not even possible... But if it is a puzzle, presumably there must be some solution.
Comments.UserDisplayName: koedem
Tags: <problems>
Title: Cyclic attack puzzle
ThreadText: # Cyclic attack puzzle
  
  (Asked by: username_0 on 2021-01-02)
  
  I saw this puzzle and a solution sometime in the previous century, I don't remember where, and I don't remember the solution.
  
  Place the 16 white men on an otherwise empty chessboard so that the following conditions are satisfied.
  
  1. Each man attacks one and only one other man.
  2. Each man is attacked by one and only one other man.
  3. The bishops are on opposite colors.
  4. One pawn on each file, no pawns on the first or last rank.
  5. There is one continuous cycle of attack, meaning that the men can be numbered from 1 to 16 so that #1 attacks #2, which attacks #3, which attacks #4, . . ., which attacks #15, which attacks #16, which attacks #1.
  
  What's the solution?
  
  Partial solutions (satisfying the first three conditions, but with doubled pawns or with two or more cycles of attack), will be appreciated and upvoted, but I'm hoping to accept an answer satisfying all five conditions.
  
  **Tags:** problems
  
  > **Comments:**
  > **username_1**: Interesting puzzle. If I had to guess I'd think it's not even possible... But if it is a puzzle, presumably there must be some solution.  
  
  ---
  
  ## 2 answers
  
  ### Answer by username_2 on 2021-01-06. Score: 5 | Accepted answer
  
  # Best solution
  
  **If** there is nothing wrong with my rather spaghettoid script (admittedly, a big if) then there is no complete solution. The best my computer finds is two cycles.
  It finds essentially three such solutions plus a few minor variations. Interestingly, the split is always 3-13.
  
  ```
  [FEN "1Q6/3R4/NB2P3/1P3P2/2P3P1/1N1P3P/P4KB1/R7 w - - 0 1"]
  
  ```
  
  .
  
  ```
  [FEN "R7/BP6/2PK4/6R1/2N3BP/1N1P2P1/P3PP2/Q7 w - - 0 1"]
  
  ```
  
  .
  
  ```
  [FEN "6R1/6BP/1N4P1/P4P2/BP2P1NK/2PP4/7Q/3R4 w - - 0 1"]
  
  ```
  
  # Strategy / computer implementation
  
  From the assumptions follow a handful of constraints that enable an exhaustive search.
  
  1. There are no more than 4 chains of Ps. That is because Ps can only attack other Ps or Rs or Ns and each separate chain has a P at the base that is not available to be attacked by another P. Each chain is capped by a R or N.
  2. The major pieces each have a rank to themselves. That is because there is at least a P on their file, so they must spend their attack on that file. The Q, in particular, must also have her diagonals to herself.
  3. The Q must be attacked by a N.
  4. At least 1 chain of Ps must be capped off by a N. There are at least two Ps on the same rank and their respective chains cannot be both capped by Rs because then 1 chain would have to cross the private rank of the other chains R.
  
  Using these constraints makes the code rather verbose and ugly but keeps the number of candidates below a million or so.
  
  # Relaxing the rules
  
  If we lift the one pawn per file rule it becomes untractable for my computer program, but we can solve manually
  
  ```
  [FEN "6R1/1R6/1BP3BN/3P2P1/2P2P2/1P4P1/P1N2K/Q7 w - - 0 1"]
  
  ```
  
  # Last word: The i files
  
  We can actually achieve a full solution with no doubled pawns by ever so slightly bending the rules. All we need to do is rip out the f file but relax we are putting it right back: as the new i file. Job done:
  
  [![enter image description here](https://i.sstatic.net/DDgO7.png)](https://i.sstatic.net/DDgO7.png)
  
  > **Comments:**
  > **username_0**: Thank you! Can you get  a solution with one cycle if you allow doubled pawns?  
  > **username_2**: @username_0 my computer can't but I can ;-)  
  > **username_0**: Well done. On the assumption that your computer program is correct and I've been suffering from a false memory of having seen a solution with one cycle and no doubled pawns, I'm awarding the check mark. Of course, I will have to move it if a solution to the puzzle as I stated it ever turns up.  
  
  ---
  
  ### Answer by username_3 on 2021-01-06. Score: 2
  
  This has several issues. It's missing a pawn on `c` and a bishop on the black diagonal, and the pawn on `d` doesn't attack anything, as well as nothing attacks the rook on `a3`, but this is as close as I can apparently get. Maybe someone can work off this and do better.
  
  However, there's a single cycle from `Ra3` to `d6`. Anything else I try ends up with at least one piece attacking multiple other pieces, and I still can't get all the pieces on the board without several of these multiple attacks.
  
  I put ~~baby~~ the queen in the corner to attempt to reduce the directions of her influence. Then I tried to put things in around her. I've been doing this manually, so I obviously haven't managed to try all combinations, but this methodology seems to have some merit, until it hits a wall.
  
  ```
  [FEN "5R2/N5P1/1P1P3P/PB2P3/5P2/R7/4KN2/7Q w - - 0 1"]
  
  ```
  
  There are so very many issues with this puzzle:
  
  1. The queen can only be attacked by a knight.
  2. The queen and both rooks require a whole rank to themselves, leaving only 5 ranks for the other 13 pieces.
  3. The queen needs the equivalent of at least one full diagonal.
  4. Pawns can't attack bishops or the king.
  5. Knights, bishops, and rooks can't attack like pieces.
  6. Because there's so many pawns, most major pieces are likely going to have to attack one.
  
  > **Comments:**
  > **username_3**: @RewanDemontay, no. Unfortunately, I couldn't find places to put the one bishop or the last pawn that kept the cycle going without violating a bunch of puzzle rules.  
  
  ---
  
  