Answers.Body: <p>Improving on Christian's answer:</p>
  <pre><code>    [Title &quot;2 Black Pawns&quot;]
      [FEN &quot;1R6/p1p1P2N/P1P1P3/2P4B/P1P1P2N/6R1/3Q4/B4k1K w - - 0 1&quot;]
  
  </code></pre>
  
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2022-12-13T16:19:11.383Z
Answers.Text: Haha, nice - that is what you get for writing software to come up with a solution and then not even taking two minutes to look over the solution :D
Answers.UserDisplayName: Christian
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2022-12-13T15:05:46.367Z
Answers.LastActivityDate: 2022-12-13T15:05:46.367Z
Answers.UserDisplayName: Brian Towers
Answers.Body: <p>My final suggestion is this:</p>
  <pre><code>[Title &quot;5 Black Pawns&quot;]
  [FEN &quot;1Q6/5PNP/P1P2ppp/3R4/P1p4P/P1p2P1B/4R3/K1k3BN w - - 0 1&quot;]
  
  </code></pre>
  <p>After letting my first program run for 20 hours and checking around 1.5 billion positions without finding another pawn I added a small improvement by defining the Queen's position explicitly and resigning on branches a bit quicker and - et voilà - after like three minutes of searching it found this solution:</p>
  
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2022-12-14T14:15:36.023Z
Answers.Text: The second diagram is much less good than the first or the third, because both bishops are on light squares, and this (plus the 8 pawns) makes the position illegal.
Answers.UserDisplayName: Evargalo
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2022-12-14T14:17:59.963Z
Answers.Text: Wow, thank you for the hint. I didn't even realize.
Answers.UserDisplayName: Christian
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2022-12-14T16:54:55.770Z
Answers.Text: I'm utterly surprised that Q and one B are not on the rim. P.S. I put the accept on hold in case your program finds a fourth. :-)
Answers.UserDisplayName: Hauke Reddmann
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2022-12-14T21:40:41.553Z
Answers.Text: Yeah - me too actually. Now I put some small optimization to look more for places for the pieces I guess are more likely to provide a solution and both bishops and the queen are on the rim ;) I'll continue to let it run tomorrow, but if until 4pm there is still no better solution, I think I'll have to quit it.
Answers.UserDisplayName: Christian
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2022-12-13T13:12:56.433Z
Answers.LastActivityDate: 2022-12-15T15:11:39.597Z
Answers.LastEditDate: 2022-12-15T15:11:39.597Z
Answers.UserDisplayName: Christian
Body: <p>Place the whole army of White and the black king on the board, such that no piece is attacked or defended. (Obviously you must use double pawns.) That's fairly easy, so tie breaker will be how many black pawns you can additionally smuggle in (again no piece being attacked or defended).</p>
  <p>Working example (I placed stuff random):</p>
  <pre><code>[FEN &quot;1K6/6NB/p7/3Q4/5R2/2R5/4P3/k3N1B1 w KQkq - 0 1&quot;]
  </code></pre>
  <p>As you can see, no more remaining White piece fits on the board (pawns on 1st/8th are illegal - please only legal positions, otherwise 32 knights would be the way to maximally &quot;fill&quot; a board). You <em>could</em> place a third knight on h8 but first try to get all White 8 pawns aboard...</p>
  
Comments.ContentLicense: CC BY-SA 4.0
Comments.CreationDate: 2022-12-15T15:12:31.670Z
Comments.Text: You already accepted, so I don't know whether you'll still check it, but actually I found another solution :)
Comments.UserDisplayName: Christian
Comments.ContentLicense: CC BY-SA 4.0
Comments.CreationDate: 2022-12-16T08:36:15.527Z
Comments.Text: I don't, but since I get auto-alerted to messages, I now know :-) (P.S. Unbelievable. 10 BP are an obvious hard maximum by row/col, now subtract diagonals - 3 with Q in the corner - and I think we are so >< close proving 5 pawns are indeed optimal.)
Comments.UserDisplayName: Hauke Reddmann
Tags: <problems>
Title: Piece Peace Puzzle
ThreadText: # Piece Peace Puzzle
  
  (Asked by: username_0 on 2022-12-12)
  
  Place the whole army of White and the black king on the board, such that no piece is attacked or defended. (Obviously you must use double pawns.) That's fairly easy, so tie breaker will be how many black pawns you can additionally smuggle in (again no piece being attacked or defended).
  
  Working example (I placed stuff random):
  
  ```
  [FEN "1K6/6NB/p7/3Q4/5R2/2R5/4P3/k3N1B1 w KQkq - 0 1"]
  
  ```
  
  As you can see, no more remaining White piece fits on the board (pawns on 1st/8th are illegal - please only legal positions, otherwise 32 knights would be the way to maximally "fill" a board). You *could* place a third knight on h8 but first try to get all White 8 pawns aboard...
  
  **Tags:** problems
  
  > **Comments:**
  > **username_1**: You already accepted, so I don't know whether you'll still check it, but actually I found another solution :)  
  > **username_0**: I don't, but since I get auto-alerted to messages, I now know :-) (P.S. Unbelievable. 10 BP are an obvious hard maximum by row/col, now subtract diagonals - 3 with Q in the corner - and I think we are so >< close proving 5 pawns are indeed optimal.)  
  
  ---
  
  ## 2 answers
  
  ### Answer by username_1 on 2022-12-13. Score: 5 | Accepted answer
  
  My final suggestion is this:
  
  ```
  [Title "5 Black Pawns"]
  [FEN "1Q6/5PNP/P1P2ppp/3R4/P1p4P/P1p2P1B/4R3/K1k3BN w - - 0 1"]
  
  ```
  
  After letting my first program run for 20 hours and checking around 1.5 billion positions without finding another pawn I added a small improvement by defining the Queen's position explicitly and resigning on branches a bit quicker and - et voilà - after like three minutes of searching it found this solution:
  
  > **Comments:**
  > **username_3**: The second diagram is much less good than the first or the third, because both bishops are on light squares, and this (plus the 8 pawns) makes the position illegal.  
  > **username_1**: Wow, thank you for the hint. I didn't even realize.  
  > **username_0**: I'm utterly surprised that Q and one B are not on the rim. P.S. I put the accept on hold in case your program finds a fourth. :-)  
  > **username_1**: Yeah - me too actually. Now I put some small optimization to look more for places for the pieces I guess are more likely to provide a solution and both bishops and the queen are on the rim ;) I'll continue to let it run tomorrow, but if until 4pm there is still no better solution, I think I'll have to quit it.  
  
  ---
  
  ### Answer by username_2 on 2022-12-13. Score: 3
  
  Improving on username_1's answer:
  
  ```
      [Title "2 Black Pawns"]
      [FEN "1R6/p1p1P2N/P1P1P3/2P4B/P1P1P2N/6R1/3Q4/B4k1K w - - 0 1"]
  
  ```
  
  > **Comments:**
  > **username_1**: Haha, nice - that is what you get for writing software to come up with a solution and then not even taking two minutes to look over the solution :D  
  
  ---
  
  