Answers.Body: <p>It should be easily possible to get 18 queens. If white captures four enemy pieces, that's enough to get doubled pawns on four files (a, c, e and g, for instance). And black captures four times to get his pawns on the b, d, f and h files. Then they can all advance and promote, and it should be easy to avoid mate by storing them all in some corner.</p>
  
  <p>Here, have the ugliest proof game ever :-)</p>
  
  <pre><code>[FEN ""]
  
  1.Nc3 Nc6 2.Nb5 Ne5 3.Nd4 Nc4 4.Nf5 Na3 5.bxa3 Nf6 6.Nh6 gxh6 7.Bb2 Ng4 8.
  Bf6 exf6 9.Nf3 Ne3 10.fxe3 Bb4 11.Nd4 Bc3 12.dxc3 Rg8 13.Nf5 Rg3 14.hxg3 
  h5 15.Nd6+ cxd6 16.Rb1 f5 17.Rb6 axb6 18.a4 h4 19.a5 h3 20.a6 h2 21.Rg1 
  h1=Q 22.a7 Rb8 23.a8=Q Qh6 24.Qa3 Qg7 25.Qb2 h5 26.a4 h4 27.a5 h3 28.a6 h2
  29.a7 h1=Q 30.a8=Q Qhh8 31.Qaa1 f4 32.g4 f3 33.g3 f2+ 34.Kd2 f5 35.Bg2 
  f1=Q 36.c4 Qf4 37.c5 d5 38.c6 d6 39.c7 Bd7 40.c8=Q Qfh6 41.Qcc3 f4 42.Qcb3
  f3 43.c4 f2 44.c5 f1=Q 45.c6 Qf5 46.c7 Qfh7 47.c8=Q d4 48.Ke1 d3 49.Kf2 d2
  50.Qf1 d1=Q 51.Qcc1 Qd5 52.g5 b5 53.g6 Qge7 54.g7 b4 55.g4 b5 56.Qd3 b3 
  57.Qbc3 b2 58.Kg3 b1=Q 59.g8=Q+ Qef8 60.g5 b4 61.Qgg7 b3 62.Qgd4 b2 63.g6 
  Qc2 64.g7 b1=Q 65.g8=Q Qdh5 66.Qda4 d5 67.e4 d4 68.Qda6 d3 69.Qga2 Qdf6 
  70.e5 Kd8 71.e6 d2 72.Qc3a3 Kc7 73.e7 d1=Q 74.e8=Q Qd8 75.Qef7 Rb7 76.e4 
  Rb8 77.e5 Rb7 78.e6 Rb8 79.e7 Rb7 80.e8=Q *
  </code></pre>
  
Answers.ContentLicense: CC BY-SA 3.0
Answers.CreationDate: 2014-11-05T09:05:50.733Z
Answers.Text: It indeed is ugly. Maybe you are interested in a more optimal way as dicussed here: http://chess.stackexchange.com/questions/4128/shortest-game-with-18-queens
Answers.UserDisplayName: Pablo S. Ocal
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2019-06-25T16:41:27.950Z
Answers.Text: Isn't it a mate in 1 with Qh2?
Answers.UserDisplayName: justhalf
Answers.ContentLicense: CC BY-SA 4.0
Answers.CreationDate: 2019-06-25T20:40:23.650Z
Answers.Text: Oh, sorry, I was responding to MikhailTal. Thanks Remco for your answer! =) (btw Qg4 and Qh4 is not mate, as can be captured by queen at a4)
Answers.UserDisplayName: justhalf
Answers.ContentLicense: CC BY-SA 3.0
Answers.CreationDate: 2014-08-09T14:16:30.350Z
Answers.Text: One question. Is this position a draw? :p
Answers.UserDisplayName: MikhailTal
Answers.ContentLicense: CC BY-SA 3.0
Answers.CreationDate: 2014-08-09T14:17:28.513Z
Answers.Text: It seems to be a mate in 4.
Answers.UserDisplayName: MikhailTal
Answers.ContentLicense: CC BY-SA 3.0
Answers.CreationDate: 2013-11-21T19:55:13.230Z
Answers.LastActivityDate: 2013-11-21T20:06:34.900Z
Answers.LastEditDate: 2013-11-21T20:06:34.900Z
Answers.UserDisplayName: RemcoGerlich
Body: <p>I was thinking about what the maximum number of queens can be on the board after only legal moves. The theoretical upper bound would be 18, the original 2 queens plus 16 promoted pawns. </p>
  
  <p>However, to have the pawns get past each other they would have to capture the opponent’s pieces. But they could not capture the opponents king or queen, so thats 2 less for each side (although a capture on one side would open for the other-so gets a bit tricker than that I realize). If so that would be 14, but with that many queens it would be easy to put the opponents king in check or checkmate I guess.</p>
  
  <p>Is it possible to get 14 queens on the board 
  in a legal game, and if not what is the maximum?</p>
  
Tags: <theory><problems><queens>
Title: Maximum number of queens possible
ThreadText: # Maximum number of queens possible
  
  (Asked by: username_0 on 2013-11-21)
  
  I was thinking about what the maximum number of queens can be on the board after only legal moves. The theoretical upper bound would be 18, the original 2 queens plus 16 promoted pawns.
  
  However, to have the pawns get past each other they would have to capture the opponent’s pieces. But they could not capture the opponents king or queen, so thats 2 less for each side (although a capture on one side would open for the other-so gets a bit tricker than that I realize). If so that would be 14, but with that many queens it would be easy to put the opponents king in check or checkmate I guess.
  
  Is it possible to get 14 queens on the board
  in a legal game, and if not what is the maximum?
  
  **Tags:** theory, problems, queens
  
  
  ---
  
  ## 1 answers
  
  ### Answer by username_1 on 2013-11-21. Score: 29 | Accepted answer
  
  It should be easily possible to get 18 queens. If white captures four enemy pieces, that's enough to get doubled pawns on four files (a, c, e and g, for instance). And black captures four times to get his pawns on the b, d, f and h files. Then they can all advance and promote, and it should be easy to avoid mate by storing them all in some corner.
  
  Here, have the ugliest proof game ever :-)
  
  ```
  [FEN ""]
  
  1.Nc3 Nc6 2.Nb5 Ne5 3.Nd4 Nc4 4.Nf5 Na3 5.bxa3 Nf6 6.Nh6 gxh6 7.Bb2 Ng4 8.
  Bf6 exf6 9.Nf3 Ne3 10.fxe3 Bb4 11.Nd4 Bc3 12.dxc3 Rg8 13.Nf5 Rg3 14.hxg3 
  h5 15.Nd6+ cxd6 16.Rb1 f5 17.Rb6 axb6 18.a4 h4 19.a5 h3 20.a6 h2 21.Rg1 
  h1=Q 22.a7 Rb8 23.a8=Q Qh6 24.Qa3 Qg7 25.Qb2 h5 26.a4 h4 27.a5 h3 28.a6 h2
  29.a7 h1=Q 30.a8=Q Qhh8 31.Qaa1 f4 32.g4 f3 33.g3 f2+ 34.Kd2 f5 35.Bg2 
  f1=Q 36.c4 Qf4 37.c5 d5 38.c6 d6 39.c7 Bd7 40.c8=Q Qfh6 41.Qcc3 f4 42.Qcb3
  f3 43.c4 f2 44.c5 f1=Q 45.c6 Qf5 46.c7 Qfh7 47.c8=Q d4 48.Ke1 d3 49.Kf2 d2
  50.Qf1 d1=Q 51.Qcc1 Qd5 52.g5 b5 53.g6 Qge7 54.g7 b4 55.g4 b5 56.Qd3 b3 
  57.Qbc3 b2 58.Kg3 b1=Q 59.g8=Q+ Qef8 60.g5 b4 61.Qgg7 b3 62.Qgd4 b2 63.g6 
  Qc2 64.g7 b1=Q 65.g8=Q Qdh5 66.Qda4 d5 67.e4 d4 68.Qda6 d3 69.Qga2 Qdf6 
  70.e5 Kd8 71.e6 d2 72.Qc3a3 Kc7 73.e7 d1=Q 74.e8=Q Qd8 75.Qef7 Rb7 76.e4 
  Rb8 77.e5 Rb7 78.e6 Rb8 79.e7 Rb7 80.e8=Q *
  
  ```
  
  > **Comments:**
  > **username_4**: One question. Is this position a draw? :p  
  > **username_4**: It seems to be a mate in 4.  
  > **username_2**: It indeed is ugly. Maybe you are interested in a more optimal way as dicussed here: http://chess.stackexchange.com/questions/4128/shortest-game-with-18-queens  
  > **username_3**: Isn't it a mate in 1 with Qh2?  
  > **username_3**: Oh, sorry, I was responding to username_4. Thanks Remco for your answer! =) (btw Qg4 and Qh4 is not mate, as can be captured by queen at a4)  
  
  ---
  
  