<p>Suppose two players in a game of poker (assume Texas Hold'em) have cards with the same values. For example, Player A and Player B have the cards 4 &amp; 9.
The board shows a 2,3,4,7, and 8 face up.</p>

<p>Who would be the winner, Player A or Player B?</p>

CC BY-SA 3.0
2015-11-05T19:39:24.403Z
This question is already answered on [Poker Stack Exchange](http://poker.stackexchange.com/a/4405/3340).
Rainbolt
CC BY-SA 3.0
2015-11-05T20:15:23.560Z
It is also already answered here.
bwarner
CC BY-SA 3.0
2015-11-13T22:39:04.467Z
... But to avoid sending people who found this question around to others, the short answer is that the two players tie and split the pot down the middle (any indivisible fraction remaining in the pot for the next hand).
KeithS
CC BY-SA 3.0
2015-12-16T21:10:08.280Z
That is incorrect.  The remaining dollar (or fraction of a dollar, if you're playing microstakes) is awarded to the player in worst position.
Stan Shaw
<poker>
In case of same card in both player
Ashraf
# In case of same card in both player

(Asked by: username_0 on 2015-11-05)

Suppose two players in a game of poker (assume Texas Hold'em) have cards with the same values. For example, Player A and Player B have the cards 4 & 9.
The board shows a 2,3,4,7, and 8 face up.

Who would be the winner, Player A or Player B?

**Tags:** poker

> **Comments:**
> **username_1**: This question is already answered on [Poker Stack Exchange](http://poker.stackexchange.com/a/4405/3340).  
> **username_2**: It is also already answered here.  
> **username_3**: ... But to avoid sending people who found this question around to others, the short answer is that the two players tie and split the pot down the middle (any indivisible fraction remaining in the pot for the next hand).  
> **username_4**: That is incorrect.  The remaining dollar (or fraction of a dollar, if you're playing microstakes) is awarded to the player in worst position.  

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