<p>As the right most eye does not have a solid chain it is still vulnerable.</p>

<p>This combined white's coverage on 8 means that when white takes E8 white will easily be able to move E9 into atari; after E8 white's next move would be F9, G8 or G9, which black cannot effectively block within the available two moves.</p>

CC BY-SA 4.0
2020-04-23T00:40:16.310Z
2020-04-23T00:40:16.310Z
KMR
<p>Just think about what happens when your stones get fully surrounded, as will eventually happen: The stone(s) at E9 will only retain a single liberty, the false eye, and you will need to fill that single liberty with a stone to connect E9 to the rest of the black group. And after that, only a single eye remains.</p>

<p>That is the point of false eyes: They are liberties which you will be forced to fill yourself, or suffer your stones being taken. As such, they do not count towards ensuring the life of a group.</p>

CC BY-SA 4.0
2020-05-19T07:25:21.783Z
2020-05-19T07:25:21.783Z
cmaster - reinstate monica
<p>I am an absolute beginner, trying to learn.</p>

<p>Let's consider that board (from a tutorial at <a href="http://playgo.to/iwtg/en/" rel="nofollow noreferrer">http://playgo.to/iwtg/en/</a>):</p>

<p><a href="https://i.sstatic.net/lv6xj.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/lv6xj.png" alt="enter image description here"></a></p>

<p>It's black's turn to play. The topic is to avoid a false eye at D9.</p>

<p>According to the tutorial, if I play at E8, I do not have a false eye:</p>

<p><a href="https://i.sstatic.net/Wb7zK.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/Wb7zK.png" alt="enter image description here"></a></p>

<p>But, if I play anywhere else and white plays at E8, I do have a false eye:</p>

<p><a href="https://i.sstatic.net/gd34e.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/gd34e.png" alt="enter image description here"></a></p>

<p>I do not understand how having a white stone, at the diagonal, would make a false eye.
Can anyone explain?</p>

<go>
in Go, why does this setup make a false-eye?
Thomas
# in Go, why does this setup make a false-eye?

(Asked by: username_0 on 2020-04-22)

I am an absolute beginner, trying to learn.

Let's consider that board (from a tutorial at <http://playgo.to/iwtg/en/>):

[![enter image description here](https://i.sstatic.net/lv6xj.png)](https://i.sstatic.net/lv6xj.png)

It's black's turn to play. The topic is to avoid a false eye at D9.

According to the tutorial, if I play at E8, I do not have a false eye:

[![enter image description here](https://i.sstatic.net/Wb7zK.png)](https://i.sstatic.net/Wb7zK.png)

But, if I play anywhere else and white plays at E8, I do have a false eye:

[![enter image description here](https://i.sstatic.net/gd34e.png)](https://i.sstatic.net/gd34e.png)

I do not understand how having a white stone, at the diagonal, would make a false eye.
Can anyone explain?

**Tags:** go


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## 2 answers

### Answer by username_1 on 2020-04-23. Score: 6 | Accepted answer

As the right most eye does not have a solid chain it is still vulnerable.

This combined white's coverage on 8 means that when white takes E8 white will easily be able to move E9 into atari; after E8 white's next move would be F9, G8 or G9, which black cannot effectively block within the available two moves.


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### Answer by username_2 on 2020-05-19. Score: 4

Just think about what happens when your stones get fully surrounded, as will eventually happen: The stone(s) at E9 will only retain a single liberty, the false eye, and you will need to fill that single liberty with a stone to connect E9 to the rest of the black group. And after that, only a single eye remains.

That is the point of false eyes: They are liberties which you will be forced to fill yourself, or suffer your stones being taken. As such, they do not count towards ensuring the life of a group.


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