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Chemical compound
Iridium(III) bromide is a bromide of iridium(III), with the chemical formula of IrBr3.
Preparation.
Iridium(III) bromide can be formed by reacting iridium(II) bromide and bromine. Its tetrahydrate can be formed by reacting iridium dioxide dihydrate with hydrobromic acid. It can also be formed by the direct reaction of iridium and bromine at 8 atm and 570 °C.
Properties.
Iridium(III) bromide is a dark reddish-brown solid that is insoluble soluble in water, acids, and alkalis and decomposes to iridium(II) bromide on heating. It crystallizes in a highly disordered layered structure of aluminum(III) chloride or chromium(III) chloride type, where the monoclinic unit cell contains four formula units. As with rhenium(III) chloride, rhenium(III) bromide, α-iridium(III) chloride and α-ruthenium(III) chloride, the disorder is due to the different stacking of the metal layers. The light olive green tetrahydrate is slightly soluble in water but insoluble in ethanol and ether. When heated to 100 °C, it turns dark brown with release of water and decomposes to iridium and bromine at higher temperatures. It reacts with germanium dibromide in hydrobromic acid solution to form a compound containing Ir-Ge bond, and adding Cs+ to it can separate Cs3[Ir(GeBr3)nBr6−n] (n=1, 2, 3).
References.
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